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2 problem(s) found in 7204 milliseconds (displaying 2 problem(s)). [PROBID='P0002686' OR PROBID='P0006310'] [download as LaTeX]

1 - P0002686
Shankar Ram
4154 feenschach 70 08/1984
P0002686
(1+1) cooked
Ergänze wT, wS und wB zu einem IC!
Madrasi

play all play one stop play next play all
Verführung: wTd1 wSc3 wBe4, aber Stellung ist legal, zuletzt wBd3xsSe4+

Lösung: wTb5 wSb6 wBc4!
Cook: - wTc5 wSc7 wBc6
- wTe5 wSe7 wBe6
- wTd6 wSb6 wBc6
- wTd6 wSf6 wBe6
jeweils illegales Doppelschach, ohne T bzw. S legales Einfachschach, ohne wB jeweils Doppelschach erklärbar durch SxT++

Duplicate Diagram: P0006310

Autor: Td4/Sb4/Bc4 or Td4/Sf4/Be4 are not cooks, since after removing wT, w's last move can be SxBb4 or SxBf4, but after this, there no last move for Black!
Twin: I later added a twin - a)Orthodox, b)Madrasi
The solution to the Orthodox twin is Te5/Se4/Be6.
[Der orthodoxe Zwilling ist C+]
paul: The try is here wTd1 wSc3 wBe4 (legal position -1.d3xSe4+) (2011-09-22)
Henrik Juel: Why are wTd4 wSb4 wBc4 or wTd4 wSf4 wBe4 cooks? The positions seem still illegal without the T.
This looks like a cook: wTe5, wSe4, wBe6 (with no Madrasi effects). (2011-09-22)
hpr: I am no expert here, but my 2 cents anyway:
wTe5, wSe4, wBe6; the position is legal, last move: Sg3xTe4. Right? (2011-09-23)
Henrik Juel: Yes, you are right, of course. Last move could even be KxTf5+. (2011-09-23)
paul: wTd4 wSb4 wBc4 seems to be a cook. Without Td4 the last moves where -1.Sa2xBb4++ Bb2-c4 (2011-09-25)
Henrik Juel: But the last moves should be a white and a black move, not the two white moves Sa2xBb4 and Bb2-c4. (2011-09-25)
paul: Right, Henrik! Then the problem has unique solution. (2011-09-25)
shankar ram: Td4/Sb4/Bc4 or Td4/Sf4/Be4 are not cooks, since after removing wT, w's last move can be SxBb4 or SxBf4, but after this, there no last move for Black!

Twin: I later added a twin - a)Orthodox, b)Madrasi
The solution to the Orthodox twin is Te5/Se4/Be6. (2018-01-16)
Mario Richter: The tries Td4/Sb4/Bc4 or Td4/Sf4/Be4 are interesting (for me: much more than the official wTd1 wSc3 wBd3), because they make use of a strange Madrasi en passant effect ...
In these two tries an illegal triple check is used, but to cook the problem is suffices to construct an illegal double check:
- wTc5 wSc7 wBc6
- wTe5 wSe7 wBe6
- wTd6 wSb6 wBc6
- wTd6 wSf6 wBe6 (2018-01-16)
more ...
comment
Keywords: Illegal cluster, Madrasi, only Kings
Genre: Retro, Fairies
FEN: 8/8/8/3k1K2/8/8/8/8
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2018-01-17 more...
2 - P0006310
Albert Heinrich Kniest
7328 FEENSCHACH 06/1965
P0006310
(1+1)
-1s, dann h=6
Ohneschach
b) Alles eine Reihe höher
c) Alles zwei Reihen höher
d) Alles drei Reihen höher

Duplicate Diagram: P0002686

Mario Richter: Stimmt hier alles (Position,Forderung)? Wenn ja, wie sieht die AL aus? (2018-01-17)
Henrik Juel: Something must be wrong, otherwise an obvious cook in part a) is
-1... Kc2xTd3, 1.Kc1 Ta3 2.Kd1 Ta2 .. 6.Kh1 Tg2= (2018-01-17)
Henrik Juel: ... or even faster
1.Kb1 Ke3 2.Ka2 Tb3 3.Ka1 Kd3 4.Ka2 Kc3 5.Ka1 Tb2= (2018-01-17)
Mario Richter: I thought that the stipulation might have been: -1s, dann ser-h=6, but in this case I do not see any solution in a) (2018-01-17)
Alfred Pfeiffer: Noch schneller:
a) R: 1. ... Kc2xTd3 , dann 1. Kb1 Ke2 2. Ka1 Kd1 3. Ka2 Kc1 4. Ka1 Td2=, oder
a) R: 1. ... Kc3xLd3, dann 1. Kb2 Ke3 2. Ka1 Kd4 3. Ka2 Kc3 4. Ka1 Kb3=, oder
a) R: 1. ... Kc2xSd3, dann 1. Kb1 KKe2 2. Ka1 Kd1 3. Ka2 Kc2 4. Ka1 Sb4= (2018-01-17)
comment
Keywords: Help retractor, Checkless, Twin by board shift, only Kings
Genre: Retro, Fairies
FEN: 8/8/8/8/8/3k1K2/8/8
Input: Gerd Wilts, 1995-08-26
Last update: A.Buchanan, 2024-01-13 more...
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