change log for P0008808 (close)
date | time | user | object | table | field | type | old | new |
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2018-06-27 | 5:28:13 | Alfred Pfeiffer | P0008808 | problems | stip | update | #1 vor 2 VRZ, Typ Høeg | #1 vor 2 VRZ, Typ Hoeg |
2014-08-05 | 22:58:20 | Alfred Pfeiffer | P0008808 | problems | soltxt | update | In the first variation white might legally supplement a pawn, but then his final retraction would lead to an illegal pawn position, R: 1. ... Ka8xBa7? 2. b6-b7+?? comment: This is the first published type Høeg defensive retractor. The above may not be the best way of presenting the solution, because it suppresses the timing of white's and black's decisions: 1. White chooses a white man and decides from where it came, 2. Black decides which black man (if any) white just captured, 3. Black chooses a man and decides from where it came, 4. White decides which white man (if any) black just captured, 5. White chooses a white man and decides from where it came, 6. Black decides which black man (if any) white just captured, 7. White can mate with a forward move. (In this problem black has no choice in step 2). Variations arise from the various possibilities in steps 2, 3, and perhaps 6. Duals (if any) arise from more than one possibility in steps 4, 5, and perhaps 7. (Høeg felt that white had won the retraction game after step 6, if white now could mate). For a problem in 3 moves four more steps are added before step 7. Here is an alternative presentation of the solution: -1 b7 Ka8(L) -2 b6, 1 Lc6 [not -1 - Ka8(B?)], -1 - Kb8(T) -2 Lc6(any), 1 Ta8, -1 - Ka6(L) -2 b6, 1 Lc8, -1 - Kb6(T) -2 c2, 1 b8DT. | In the first variation white might legally supplement a pawn, but then his final retraction would lead to an illegal pawn position, R: 1. ... Ka8xBa7? 2. b6-b7+?? comment: This is the first published type Høeg defensive retractor. The above may not be the best way of presenting the solution, because it suppresses the timing of white's and black's decisions: 1. White chooses a white man and decides from where it came, 2. Black decides which black man (if any) white just captured, 3. Black chooses a man and decides from where it came, 4. White decides which white man (if any) black just captured, 5. White chooses a white man and decides from where it came, 6. Black decides which black man (if any) white just captured, 7. White can mate with a forward move. (In this problem black has no choice in step 2). Variations arise from the various possibilities in steps 2, 3, and perhaps 6. Duals (if any) arise from more than one possibility in steps 4, 5, and perhaps 7. (Høeg felt that white had won the retraction game after step 6, if white now could mate). For a problem in 3 moves four more steps are added before step 7. Here is an alternative presentation of the solution: -1 b7 Ka8(L) -2 b6, 1 Lc6 [not -1 - Ka8(B?)], -1 - Kb8(T) -2 Lc6(any), 1 Ta8, -1 - Ka6(L) -2 b6, 1 Lc8, -1 - Kb6(T) -2 c2, 1 b8D. |
2014-08-05 | 22:53:34 | Alfred Pfeiffer | P0008808 | problems | solution | update | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+, dann 1. Lc6# R: 1. b7-b8=T Kb8xTa7 2. Lc6xBd7, dann 1. Ta8# R: 1. b7-b8=T Ka6xLa7 2. b6-b7, dann 1. Lc8# R: 1. b7-b8=T Kb6xTa7 2. c2-c3, dann 1. b8=D# | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+, dann 1. Lc6# R: 1. b7-b8=T Kb8xTa7 2. Lc6xBd7,Lc6x~d7, dann 1. Ta8# R: 1. b7-b8=T Ka6xLa7 2. b6-b7, dann 1. Lc8# R: 1. b7-b8=T Kb6xTa7 2. c2-c3, dann 1. b8=D# |
2014-08-05 | 22:49:46 | Alfred Pfeiffer | P0008808 | problems | solution | update | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+, dann 1. Lc6# R: 1. b7-b8=T Kb8xTa7 2. Lc6xd7, dann 1. Ta8# R: 1. b7-b8=T Ka6xLa7 2. b6-b7, dann 1. Lc8# R: 1. b7-b8=T Kb6xTa7 2. c2-c3, dann 1. b8=D,T# | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+, dann 1. Lc6# R: 1. b7-b8=T Kb8xTa7 2. Lc6xBd7, dann 1. Ta8# R: 1. b7-b8=T Ka6xLa7 2. b6-b7, dann 1. Lc8# R: 1. b7-b8=T Kb6xTa7 2. c2-c3, dann 1. b8=D# |
2014-08-05 | 22:46:43 | Alfred Pfeiffer | P0008808 | problems | solution | update | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+, dann 1. Lc6# R: 1. ... Kb8xTa7 2. Lc6xd7, dann 1. Ta8# R: 1. ... Ka6xLa7 2. b6-b7, dann 1. Lc8# R: 1. ... Kb6xTa7 2. c2-c3, dann 1. b8=D,T# | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+, dann 1. Lc6# R: 1. b7-b8=T Kb8xTa7 2. Lc6xd7, dann 1. Ta8# R: 1. b7-b8=T Ka6xLa7 2. b6-b7, dann 1. Lc8# R: 1. b7-b8=T Kb6xTa7 2. c2-c3, dann 1. b8=D,T# |
2014-08-05 | 22:45:27 | Alfred Pfeiffer | P0008808 | problems | solution | update | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+ dann Lc6# R: 1. ... Kb8xTa7 2. Lc6xd7 dann Ta8# R: 1. ... Ka6xLa7 2. b6-b7 dann Lc8# R: 1. ... Kb6xTa7 2. c2-c3 dann b8=D,T# | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+, dann 1. Lc6# R: 1. ... Kb8xTa7 2. Lc6xd7, dann 1. Ta8# R: 1. ... Ka6xLa7 2. b6-b7, dann 1. Lc8# R: 1. ... Kb6xTa7 2. c2-c3, dann 1. b8=D,T# |
2014-08-05 | 22:44:03 | Alfred Pfeiffer | P0008808 | problems | solution | update | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+ and Lc6#, 1. ... Kb8xTa7 2. Lc6xd7 and Ta8#, 1. ... Ka6xLa7 2. b6-b7 and Lc8#, 1. ... Kb6xTa7 2. c2-c3 and b8=D(T)#. In the first variation white might legally supplement a pawn, but then his final retraction would lead to an illegal pawn position, R: 1. ... Ka8xBa7? 2. b6-b7+?? comment: This is the first published type Hoeg defensive retractor. The above may not be the best way of presenting the solution, because it suppresses the timing of white's and black's decisions: 1. White chooses a white man and decides from where it came, 2. Black decides which black man (if any) white just captured, 3. Black chooses a man and decides from where it came, 4. White decides which white man (if any) black just captured, 5. White chooses a white man and decides from where it came, 6. Black decides which black man (if any) white just captured, 7. White can mate with a forward move. (In this problem black has no choice in step 2). Variations arise from the various possibilities in steps 2, 3, and perhaps 6. Duals (if any) arise from more than one possibility in steps 4, 5, and perhaps 7. (Hoeg felt that white had won the retraction game after step 6, if white now could mate). For a problem in 3 moves four more steps are added before step 7. Here is an alternative presentation of the solution: -1 b7 Ka8(L) -2 b6, 1 Lc6 [not -1 - Ka8(B?)], -1 - Kb8(T) -2 Lc6(any), 1 Ta8, -1 - Ka6(L) -2 b6, 1 Lc8, -1 - Kb6(T) -2 c2, 1 b8DT. | R: 1. b7-b8=T Ka8xLa7 2. b6-b7+ dann Lc6# R: 1. ... Kb8xTa7 2. Lc6xd7 dann Ta8# R: 1. ... Ka6xLa7 2. b6-b7 dann Lc8# R: 1. ... Kb6xTa7 2. c2-c3 dann b8=D,T# |
2014-08-05 | 22:42:10 | Alfred Pfeiffer | P0008808 | problems | stip | update | #1 vor 2 VRZ, Typ Hoeg | #1 vor 2 VRZ, Typ Høeg |
2014-08-05 | 22:41:42 | Alfred Pfeiffer | P0008808 | problems | soltxt | update | In the first variation white might legally supplement a pawn, but then his final retraction would lead to an illegal pawn position, R: 1. ... Ka8xBa7? 2. b6-b7+?? comment: This is the first published type Høeg defensive retractor. The above may not be the best way of presenting the solution, because it suppresses the timing of white's and black's decisions: 1. White chooses a white man and decides from where it came, 2. Black decides which black man (if any) white just captured, 3. Black chooses a man and decides from where it came, 4. White decides which white man (if any) black just captured, 5. White chooses a white man and decides from where it came, 6. Black decides which black man (if any) white just captured, 7. White can mate with a forward move. (In this problem black has no choice in step 2). Variations arise from the various possibilities in steps 2, 3, and perhaps 6. Duals (if any) arise from more than one possibility in steps 4, 5, and perhaps 7. (Høeg felt that white had won the retraction game after step 6, if white now could mate). For a problem in 3 moves four more steps are added before step 7. Here is an alternative presentation of the solution: -1 b7 Ka8(L) -2 b6, 1 Lc6 [not -1 - Ka8(B?)], -1 - Kb8(T) -2 Lc6(any), 1 Ta8, -1 - Ka6(L) -2 b6, 1 Lc8, -1 - Kb6(T) -2 c2, 1 b8DT. |