4281 problem(s) found in 407 milliseconds (displaying 100 problem(s)).

1 - P0000003
Nikita M. Plaksin
(4) Die Schwalbe 97 02/1986
Spezialpreis
P0000003
(12+14)
#1
Der letzte B-Zug war g7-g5
1. e3 Sxc3# (1. Ke1??)
play all play one stop play next play all
Mario Richter: The position can be reached from the initial game array in less than 50 moves, with bPg7 playing Pg7-g6-g5, so something must be completely wrong here. (2009-4-23)
Mario Richter: As D.Baibikov informed me, I misinterpreted the stipulation: "Der letzte B-Zug war g7-g5" is part of the stipulation, so the position should be analyzed under the assumption, that the last pawn move in the game leading to the diagram was Pg7-g5. This makes my earlier comment of course obsolete ... (2010-4-25)
hans: 1. Sxc3#/Sa3#/Sd2#/Sg3# (not fxg1Q/R# for g7-g5 is last B-move.)
R: 1. d4xRe5 Bh6-g7 2. Bg7-f8 Re6-e5 (R to b8, Q to d8, K to e8, B to f8)Wb makes tempomoves, and after g7-g5 can Black retract the other pawns. (2010-4-26)
A.Buchanan: Smallest used probid number in PDB. All the early numbers are retros, because that's where Gerd's interest initially lay, I guess. (2017-10-5)
Henrik Juel: Hans's retroplay does not work, because last pawn move was g7-g5, not d4xTe5, and his forward play argument is invalid
White captured [Lc6] and dxTe
Black captured [Lf1], a7xb6, hxLg, and g3xf2
White has no last move, so he has the move; but he cannot mate, so the stipulation must refer to Black, who mates with fxg1=DT, Sg3, or bS~, depending on what White plays
The retroplay is something like
-1... Lh6 -2.Lg7, retract Kg8 via a7 and f5 to d1, Sa3-b1, Ta1 out, Kd1 to h7, Ta1 to b8, Dc5 to d8, Kh7 to e8, Lf8-h6, and g7-g5 is just in time, if my counting is correct
The En passant Keyword makes little sense; White could capture hxg6ep, but did not (2017-10-5)
Henrik Juel: tiny typo: Black captured hxg, not hxLg (2017-10-6)
A.Buchanan: I agree with your count :D (2017-10-6)
comment
Keywords: 50 move rule, Conditional problem
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-10-6 more...
2 - P0000033
S. N. Ravishankar
5467v Die Schwalbe 98 04/1986
P0000033
(5+3) cooked
#1 vor 14
VRZ, Typ friedlich
R: 1. Tg1-f1 2. Tf2-f3 Te2- 3. Te1-g1 4. Te2-f2 Ta2- 5. Ta1-e1 Tb2-a2 6. Tb1-a1 Tc2-b2 7. Tc1-b1 Td2-c2 8. Tg1-c1 Tc2-d2 9. Td2-e2 Tb2-c2 10. Tc2-d2 Ta2-b2 11. Tb2-c2 g3-g2 12. Lg2-h3+, dann 1. Th1#
play all play one stop play next play all
Cook: Kurzlösung:
R: 1. Tg1-f1 droht 2. Tf1-f3, dann 1. Th1#
R: 1. Tg1-f1 Tf2-g2 2. Tf1-g1, dann 1. T3xf2#
(Mario Richter)
Mario Richter: So wie abgebildet, sollte die Problemno. nicht '5467v' sein.
Die Verbesserung (also das 'v') scheint erst später erschienen zu sein.
Das Diagramm ist kurzlösig durch: R: 1. Tg1-f1 (dr. 2. Tf1-f3, dann 1. Th1#) Tf2-g2 2. Tf1-g1, dann 1. Tf3xf2#. (2011-8-18)
Alfred Pfeiffer: Dies ist schon eine Veränderung des Originals. Wo die (in der LB bereits erwähnte) "Korrekturfassung" erschien, ist unklar. (2018-1-16)
comment
Keywords: Defensive Retractor, Type Pacific
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-1-17 more...
3 - P0000067
Karlheinz Bachmann
5821 Die Schwalbe 104 04/1987
P0000067
(11+15) cooked
BP in 48,0
1. Sf3 a5 2. Sd4 a4 3. Sb3 axb3 4. a3 Ta4 5. Ta2 bxa2 6. Tg1 axb1=S 7. Th1 Sc3 8. Tg1 Sd5 9. Th1 Sb6 10. Tg1 Sa8 11. Th1 b6 12. Tg1 La6 13. Th1 Dc8 14. Tg1 Db7 15. Th1 Df3 16. gxf3 h5 17. Lh3 h4 18. Le6 h3 19. La2 Lc4 20. Lb1 La2 21. b3 Sa6 22. Lb2 Sc5 23. Lf6 gxf6 24. Kf1 Lh6 25. Kg1 Lf4 26. Df1 Sh6 27. Dg2 hxg2 28. h4 0-0 29. Th3 Kh7 30. Tg3 Sg8 31. Kh2 g1=S 32. Kg2 Kh6 33. Tg4 Lh2 34. Tb4 Kh5 35. f4 Sf3 36. Tb5 Sd4 37. Ta5 Sb5 38. Kf3 Lg1 39. Ke3 Kg4 40. Ta7 Kh3 41. Tb7 Kg2 42. Tb8 Kf1 43. Kf3 Ke1 44. Kg2 Kd1 45. Kf1 Kc1 46. Ke1 Kb2 47. Kd1 Ka1 48. Kc1 Ta6
play all play one stop play next play all
Cook: 1. a3 b5 2. Ta2 b4 3. h4 b3 4. Th3 bxa2 5. Tb3 axb1=S 6. Tb4 Sa6 7. Sf3 Sc5 8. Se5 La6 9. Tb5 Dc8 10. Tb6 Db7 11. Tb4 Df3 12. gxf3 h5 13. Lh3 Th6 14. Le6 Sc3 15. La2 Lc4 16. Lb1 La2 17. b3 S3a4 18. Sg4 hxg4 19. Lb2 g3 20. Tb7 Ta6 21. Lf6 gxf6 22. Dc1 Lh6 23. Db2 Kf8 24. Dc3 Kg7 25. Db4 Tf8 26. Db5 Sb6 27. Dc6 Sa8 28. Dd6 g2 29. De6 g1=S 30. Dd6 Lf4 31. Dc6 Lh2 32. f4 Sf3+ 33. Kf1 Sd4 34. Kg2 Sb5 35. Kf3 Kh6 36. Ke3 Kh5 37. Dd6 Kg4 38. Dc6 Kh3 39. Dd6 Kg2 40. Db6 Kf1 41. Kf3 Ke1 42. Kg2 Kd1 43. Kf1 Kc1 44. Ke1 Kb2 45. Kd1 Ka1 46. Kc1 axb6 47. Tb8 Lg1
paul: See P0002277 as a correction. (2018-3-3)
more ...
comment
Keywords: Unique Proof Game, Length Record, Non-standard material, Castling
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-3-3 more...
4 - P0000078
Leonid M. Borodatow
Evgeny V. Kharichev

5949 Die Schwalbe 106 08/1987
P0000078
(13+10)
#3
b) sBd3 nach d4
New version P1347269
Yoav Ben-Zvi: Intended solution in a is 1.R-e4+ but cooked by 1.Rxb7 because castling is met by R-g4#.
Correction: Place WRs on c3 and c4, move BRa1 to c1.
Solution: a) 1.Rxc7? 0-0! 1.R-e4+! K-f8 2.N-d6 b) 1.Rxc7! (threat 2.R-c8#) 0-0?
To see if Black castling rights can be preserved assume BK and BRh8 never moved. [BRa8] could not escape the back row so BRc1 is promoted on g1 by [BPf7] after capturing the third missing White piece on g2. One of WBa2, WBh2 is promoted since the first of [WBc1], [WBf1] to be released requires that the other is prevented from reaching a2 or h2 by the advance of [WPb2] or [WPg2]. The promotion to WB by [WPa2] could not be on e8 or g8 (requires move by BK) so it was on d8 or f8, the promoted bishop moving from there to h2. The path of [WPa2] to promotion requires capture of all 5 missing Black pieces, other than [BBc8], including [BRa8] so the last capture by White must be WPe7xBRd8=B ([BBc8] captured earlier by WN). The position when this capture and promotion was played has WP on g2 (waiting for arrival of promoted bishop to h2) which means [WBf1] was locked at home which means WP stood on b2 (waiting for arrival of [WBf1] to a2) and [WBc1] was also locked at home. With the original WBs both locked at home White's central cage is locked so the White king and queen are also locked at home and [WRh1] is locked in its corner cage. All Black missing pieces have been captured, BKe8 and BRh8 both stand at home (under the assumption) and [BPe7] must have advanced to e6 to vacate e7 for the promoting WP. At this point Black has only pawn moves to make until the promotion to rook while White must get the promoted bishop to h2 to allow the advance of [WPg2] to g3. Starting from 3rk2r/ppppPppp/4p2N/2R5/8/4N2P/1PPPPPP1/2BQKB1R play continues 1.WPe7xRd8=B Pe6-e5 2.Bd8-h4 Pf7-f6 3.Bh4-g3 Pf6-f5 4.Bg3-h2 Pf5-f4 5.Pg2-g3 Pf4-f3 6.Ne3-g2 Pf3xNg2 7.Nh6-f7 Pg2-g1=R 8.xx Rg1-g2 9.Bh2-g1 Rg2-h2 10.Bf1-g2 Pe5-e4! 11.Bg2-f3 Rh2-g2 and from here WBf3 continues to a2 followed by WPb2-b3 releasing WBc1 to be captured on h6, WQd1 to be captured on d3, WKe1 to move to f6 and the rooks c5,h1 and g2 to take their place on c3,c4 and c1. This works for the diagram position (so Black retains the right to castle) but not for b (since BP ends up on d3). (2017-10-5)
A.Buchanan: @Yoav: my proof is *almost* identical to yours. I felt I needed experiment to justify that wQ didn't have enough time to develop to g2 & it could only be wN captured there. Therefore beP & bgP had not captured anything until the cage opened on queenside.
For setting up the pieces for the forward play, I prefer wRa3 instead of c3, because b) has no non-trivial dual. (2017-10-5)
A.Buchanan: with wTc4a3 sTc1h8:
a) 1. Te4+ Kf8 2. Txa7 ~ 3. Ta8#
b) 1. Txa7 droht 2. Ta8# 1. ... d5 (d6) 2. Txc7 ~ 3. Ta8# (2017-10-6)
Yoav Ben-Zvi: The difficulty in refuting the capture of WQ on g2 arises when the Solution is visualized by the standard technique of long range retraction. By doing a "Fast retraction/rewind" to the critical position (when White plays his last capture) and then looking forward it is easily seen that White needs to get a piece very quickly to g2 while WQ is locked at d1 so a WN stands on e3 or h4 ready to move to g2 (after it is vacated by WP) in 1 move.
The suggested transfer of WRc3 to a3 results not only in the elimination of duals but also in new thematic content. In b, there is now reciprocal change, betwen Try and Solution, of the key (1.Rxc7?, 1.Rxa7!) and the second move continuation (1...P-d6/d5 2.Rxa7, 1...Pd6/d5 2.Rxc7). In a, Rxa7 is the second move continuation in the Solution and the key of a Try refuted by 1...BP-d6/d5! (not 1...0-0? 2.R-g4#) 2.Rxc7 0-0!.
This is not enough for an independent modern #3 but it is impressive for one in which the Solution is justified by extensive Retro-Analysis. (2017-10-10)
comment
Keywords: Castling (sk), Cant Castler (sk)
Genre: Retro, 3#
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-26 more...
5 - P0000121
Tivadar Kardos
12552 Schweizerische Schachzeitung 12/1984
P0000121
(2+2) C+
-1(w+s), dann h#1
2 Lösungen
1) R: 1. h4xLg5 Le3xDg5, dann 1. La7 Dd8#
2) R: 1. Kb1xTa1 Ta7xDa1+, dann 1. Ka8 Dh8#
play all play one stop play next play all
Doppelt veröffentlicht!
Sally: Als Vier-Steiner ganz beachtlich und als Abwechslung willkommendes, hübsches und interessantes Retrorätsel. (2018-6-25)
comment
Keywords: Help retractor, Kindergarten Problem
Genre: Retro
Computer test: rawbats
Reprints: 6512 Die Schwalbe 115 02/1989
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-6-26 more...
6 - P0000136
Dmitri W. Pronkin
Andrey Frolkin

6631v Die Schwalbe 117 06/1989
Preis
P0000136
(14+14)
BP in 57,5
1. a4 h5 2. a5 h4 3. a6 h3 4. axb7 hxg2 5. h4 d5 6. h5 d4 7. h6 d3 8. h7 dxc2 9. d4 a5 10. Lh6 c1=T 11. e4 Tc5 12. Se2 Th5 13. e5 c5 14. e6 Sc6 15. b8=T a4 16. Tb4 a3 17. Ta4 c4 18. b4 c3 19. b5 c2 20. b6 c1=T 21. b7 Tc4 22. b8=T Da5+ 23. Tbb4 Lb7 24. S1c3 0-0-0 25. exf7 e5 26. Tc1 Lc5 27. f8=T a2 28. Tf3 a1=T 29. Sa2 g1=T 30. Tfa3 Tg6 31. f4 Te6 32. f5 g5 33. f6 g4 34. f7 g3 35. f8=T g2 36. Tf5 g1=T 37. Lf8 Tg7 38. Sg3 e4 39. Ld3 e3 40. 0-0 e2 41. Tcc3 e1=T 42. Lc2 T1e3 43. d5 Tdd7 44. d6 Tdf7 45. d7+ Kb8 46. Dd6+ Ka8 47. Dc7 Sge7 48. d8=T+ Sc8 49. Tdd3 Thg8 50. h8=T Tae1 51. Th6 T1e2 52. T1f2 Tce4 53. Kf1 Ld4 54. Tfc5 Se5 55. Sf5 Sc4 56. Sd6 Sb2 57. Tbc4 Sb6 58. Db8+
play all play one stop play next play all
Der absolute KBP-Längenrekord.
See P1338946 cooked.
paul: Compare with P0002278 & P0002279 (2010-4-30)
Mu-Tsun Tsai: This one is by far the toughest retro I've ever solved. Very little certain information can be determined by structural consideration alone, even with long and complicated argument. It took me five days to complete solving this. (2012-7-22)
A.Buchanan: @Mu-Tsun: that's an interesting data point - thanks for posting. (2017-9-7)
Henrik Juel: The current record is 58.5 moves in a proof game problem by the authors + Keym, Die Schwalbe 2017 (2017-9-7)
Henrik Juel: I just learned that the 58.5 move proof game has been cooked... (2017-9-7)
more ...
comment
Keywords: Unique Proof Game, Length Record, Non-standard material (TTTTTTtttttt), Castling, Superseded by (P1338946), Aristocrat
Genre: Retro
Reprints: 584 Ukrainisches Album 1986-1990
86 Shortest Proof Games 11/1991
(6) diagrammes 103 10-12/1992
H18 FIDE Album 1989-1991 1997
feenschach 137, p. 368, 08-09/2000
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-9-19 more...
7 - P0000138
Wolfgang Dittmann
6633v Die Schwalbe 117 06/1989
P0000138
(15+14)
BP in 14,5
Schlagschach
1. Sh3 Sf6 2. Sf4 g5 3. Sd3 e6 4. Tg1 Ke7 5. Sb4 Se8 6. g4 e5 7. h4 gxh4 8. Tg2 h3 9. Tg3 h2 10. d3 h1=L 11. Sd2 Le4 12. dxe4 Lg7 13. Lg2 Kf8 14. Th3 h5 15. gxh5
play all play one stop play next play all
paul: The first 12.5 moves checked by Jacobi, with blackmustcapture and whitemustcapture. (2018-2-27)
A.Buchanan: @Paul: I still don't understand why you don't set kings not royal. You might miss a solution/cook. (2018-2-27)
paul: @Andrew: in the first instance, I wanted to show that the solution also works with orthodox Kings. (2018-2-28)
comment
Keywords: Ceriani-Frolkin Theme (l), Unique Proof Game, Losing Chess, Loss of tempo
Genre: Retro, Fairies
Reprints: (B2) Quartz 35 08/2010
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2015-1-9 more...
8 - P0000140
Narajan Shankar Ram
6686 Die Schwalbe 118 08/1989
P0000140
(3+3) C+
#1 vor 2
VRZ, Typ friedlich
R: 1. Te8-e6? Sg5-h3!
R: 1. Tf8-f6 droht 2. Kb5-c4, dann 1. Te7#
R: 1. Tf8-f6 a6-a5 2. Kc5-c4, dann 1. Te7#
R: 1. Tf8-f6 Ka8-b7,Kb8-b7,Kc8-b7 2. Tf7-f8+, dann 1. Te8#
R: 1. Tf8-f6 Kc7-b7 2. Kc5-c4, dann 1. Te7#
R: 1. Tf8-f6 Kc6-b7,Kb6-b7,Ka6-b7 2. Te7-e6+, dann 1. Tf6#
play all play one stop play next play all
Henrik Juel: Solution
-1.Tf8 thr./Ka8,Kb8,Kc8/a6,Kc7 -2.Kb5/Tf7/Kc5, 1.Te7/Te8/Te7 (2012-8-30)
shankar ram: Try 1.Te8? (2.Kb5 & Tf7#) Sg5! with reciprocal change after 1...K~8/K~6 (2018-1-16)
more ...
comment
Keywords: Defensive Retractor, Type Pacific
Genre: Retro
Computer test: rawbats
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-12 more...
9 - P0000324
Josef Haas
8259 Die Schwalbe 143 10/1993
P0000324
(7+5)
a) Wer setzt in 1 Zug matt?
b) Auf welchem Feld muß ein schwarzer Bauer eingefügt werden, damit die andere Partei als in a) mattsetzt?
b) (+sBc7) 1. ... Lg8xe6#
a) 1. Tg6#
1) R: 1. ... Kg6xBf6! 2. g5xf6ep++ f7-f5 3. La2-b1+
play all play one stop play next play all
"Vermutlich aus der Kleinkunstkiste des Autors hervorgekramt.
a) sollte einfach formuliert sein: 'Matt in 1 Zug' - denn wie es hier heißt, klingt es als ob nur einer mattsetzen kann. Das aber ist nicht der Fall, denn beide können's: 1. ... Lxe6# und 1. Tg6#. Üblicherweise hat Weiß das Prae und kann darauf pochen, den Schwarz hat einen altklassischen letzten Zug: 1. ... Kg6xBf6! (nebst 2. Bg5xBf6ep++ Bf7-f5 3. La2-(x)b1)" (HHS);
also ist Weiß am Zug und setzt matt mit 1. Tg6#.
b) Nach Einfügen eines sBc7 geht die o.g. Rückzugfolge nicht, weil der wK nicht auf die 8. Reihe gelangen kann. Also Schwarz am Zuge und 1. ... Lxe6#
"Allzubekanntes - kein Problem für Schwalbelöser" (HHS)
Wenn das alles so bekannt ist, erstaunt doch sehr, daß nur drei Löser die Autorintention nachvollziehen konnten. Alle anderen Löser (5) kamen zu genau entgegengesetzten Erkenntnissen (in a) setzt Schwarz matt, in b) Weiß), was wohl durch die nicht ganz konventionelle Formulierung suggeriert wurde. Ich find's ein interessantes Beispiel für Massenhypnose! (GL) 2/I/3L.
Brassaud: La solution proposée 1/Tg6# est possible
Mais il y a aussi le rétro jeu -1) Fa2-b1, Rg5g6 -2) Ta4-a5+, Rf4-f5 etc … et avec le trait aux noirs : 1) Fxe6 # est possible (2017-8-30)
A.Buchanan: @Brassaud: yes I agree. There is no reason why White should not have moved last. So both players can mate, but part (b) implies that the intended solution in (a) is 1 player. If the published stipulation for (a) was maybe just "#1", which by default is white to move, then there is a unique solution.
For (b) I am wondering about +sBg6, which would also stop the en passant trick, both by blocking sK from retreating there and also by locking sL in an impossible cage with sBf7. (2017-8-31)
Henrik Juel: Adding a black pawn on g6 of course prevents a black last move by Kf6, but it allows f7xg6 as last move; Lg8 is not locked, because Ph7 is white (2017-8-31)
A.Buchanan: Yes (2017-8-31)
more ...
comment
Keywords: Add pieces, No legal last move for Black
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-9-4 more...
10 - P0000383
Unto Heinonen
8492 Die Schwalbe 146 04/1994
P0000383
(14+15)
BP in 22,5
1. e4 a6 2. Lb5 axb5 3. f4 Ta3 4. Sf3 Tc3 5. dxc3 e5 6. Dd4 exd4 7. a4 d3 8. a5 d2+ 9. Ke2 d1=T 10. a6 Td6 11. a7 Ta6 12. a8=D c6 13. Da7 Da5 14. Dg1 Lc5 15. e5 Ke7 16. e6 Kd6 17. e7 Lb6 18. Dd1+ Kc5 19. e8=L d6 20. Ld7 Ta8 21. Lh3 Ld7 22. g4 Le8 23. Lf1
play all play one stop play next play all
paul: The first 19 moves tested (Euclide 1.11) (2017-12-26)
Henrik Juel: .. and I tested the remaining 3.5 moves (by hand)
These partial tests do not guarantee C+, of course
For clarity, the DTL in Keywords might be replaced by DtL or DLt (2017-12-26)
comment
Keywords: Unique Proof Game, Pronkin Theme (DTL)
Genre: Retro
Reprints: (42a) Die Schwalbe 232 08/2008
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2009-1-7 more...
11 - P0000547
Tivadar Kardos
Werner Frangen

3462 Die Schwalbe 68 04/1981
P0000547
(14+9) C+
BP in 8,5
1. Sc3 d5 2. Sxd5 Sc6 3. Sxe7 Sd4 4. Sxg8 De7 5. Sxe7 Sxe2 6. Sxc8 Sxg1 7. Sb6 Ke7 8. Sxa8 b6 9. Txg1
play all play one stop play next play all
Sally: Parforce-Tour des w. Springers, verführungsreich, aber nicht so schwierig und im Lösungsverlauf so phantasievoll, wie manch anders Stück. (2017-9-6)
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Natch 2.1 Copyright (C) 1997,98,99,2001,2002 Pascal Wassong
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-11-13 more...
12 - P0000555
Leonid M. Borodatow
3531v Die Schwalbe 69 06/1981
P0000555
(5+9) cooked
Letzter Zug?
R: 1. Bh7xDg8=L
play all play one stop play next play all
Cook: R: 1. Ke4xDd5
Brassaud: Autre possibilité : rétro 1/ Ca6xDb8 ou Ca6xTb8 etc.. (2017-8-31)
comment
Keywords: Last Move? (BxD=L), Type A, Promotion (L), Non-standard material, Superseded by (P0000618)
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2015-12-3 more...
13 - P0000577
Tivadar Kardos
3742 Die Schwalbe 72 12/1981
P0000577
(8+12)
BP in 11,5
1. d4 e5 2. Lg5 Dxg5 3. Sf3 Dxg2 4. Sxe5 Dxh1 5. Sxd7 Dd5 6. Sxf8 Dxa2 7. Sg6 Dxa1 8. Sxh8 Da6 9. Sg6 Dxg6 10. Dd3 Dxd3 11. e3 Dxf1+ 12. Kd2
play all play one stop play next play all
paul: C+ pour les premiers dix coups (Popeye). (2011-9-17)
Sally: Die Reihenfolge der Züge ist festgelegt, aber eine bestimmte Thematik wird nicht gezeigt. Dieser Sachverhalt scheint sehr zur Schwierigkeut der Aufgabe beigetragen zu haben. Es gab nur 2 Löser! (2017-9-6)
comment
Keywords: Unique Proof Game
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2005-12-27 more...
14 - P0000676
Werner Keym
2477 Die Schwalbe 51 06/1978
P0000676
(5+5)
Welches war der letzte Zug?
R: 1. Lf8xDg7+
play all play one stop play next play all
Henrik Juel: -1.Lf8xDg7 Dg8 -2.Kd3 Dg7
-3.Lg8 h7 etc. (2004-8-12)
A.Buchanan: I think Willcocks deserved a co-author for P1012630 (2018-4-2)
Henrik Juel: Werner probably thought that saving a man was sufficiently original (2018-4-2)
A.Buchanan: Willcocks would have been young enough to have opined: maybe he just said: "it's yours!" (2018-4-2)
Mario Richter: There are several articles flying around discussing the sense or nonsense of "after" and "version of" labels in the domain of record constructions, maybe in 'Die Schwalbe' or 'feenschach', and I think one even by our problem friend M. Caillaud. IIRC the majoriy was in the "makes no sense-party" ... (2018-4-2)
A.Buchanan: As far as I know, there has never been versioning or after for any economy record construction. I kind of like these problems where there are more composers than pieces on the board, and that would be impractical unless all are equal co-authors. And PDB doesn't support versioning/after properly anyway. (2018-4-2)
comment
Keywords: Type C, Last Move? (LxD), Economy record
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2012-4-15 more...
15 - P0000715
Leonid M. Borodatow
2814 Die Schwalbe 57 06/1979
P0000715
(11+5)
Welcher Stein wurde zuletzt auf f8 geschlagen?
siehe Neufassung 2814v!
Brassaud: Rétro jeu : 1) Tf6f8+, Rf7xCg8 2) Tb6f6+, Rf8f7 3) Fb2g7+, Rf7f8 4) g7g8=C+, Rg8f7+ 5) g6g7, Rf8g8 6) b5xa6, Rg8f8 6) Re7d8, a7a6 7) Rf6e7 etc ..
Les pions noirs de e7, f7, g7 et h7 ont été promus après 3 prises de pièces blanches. Les pions blancs ont pris 10 pièces noires, le Fou de c8 a été pris en c8. Il n’y a pas eu de prise en f8, mais un Cavalier blanc (de promotion) été pris en g8 (2017-8-31)
comment

Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2002-10-12 more...
16 - P0000723
Reto List
Markus Ott

2870 Die Schwalbe 58 08/1979
P0000723
(12+10)
#2
1. 0-0-0? illegal
1. Kd2! ... 2. Tg1#

R: 1. ... Kh3xSg2 2. Sh4xLg2+ Lf1-g2
play all play one stop play next play all
Mit W am Zug zuletzt nur R: 1. ... Kh3xSg2 2. Sh4xLg2+ Lf1-g2 möglich. In der resultierenden Stellung haben die wBB am K-Flügel viermal geschlagen, hinzu kommt der sLf8, der von einem weißen Offizier eliminiert wurde. Damit sind alle fehlenden sSteine erklärt, die wBBa2+c2 haben ihre PAS-Linie nie verlassen und konnten auch nicht umwandeln, standen als Bauernschlagobjekte also nicht zur Verfügung. sBh7 schlug auf g6 den wLf1. Der weißfeldrige sUW-L kann also nur durch schlaglose UW des sBd7 auf d1 entstanden sein (für die UW auf b1 fehlt ein Schlagobjekt!), die w0-0-0 ist damit unmöglich.
Brassaud: Les blancs ont pris 5 fois (D,T,T,C, et pion de d7). Le FN f8 n’est pas sorti. Il n’y a pas de pièce noire à rendre pour dénouer la position du roi noir.
Avec le trait au blanc le rétro jeu possible serait : 1) …, Rh3xCg2 2) Ch4g2+ et il y a un rétro pat noir. 1) o-o puis 2) Tg1# ne va pas.
Si j’ai bien compris il s’agit de « No legal last move for Black »
Le trait est aux noirs.
Le rétro jeu est : 1) Th4h7, Rh3g2 2) Tg4h4+, Rg2h3 etc .. Le o-o blanc est possible.
0) .., RxCh1 1) Re2+, Rg2 2) Tg1 #
mais sur 0) …, Fxb5 il n’y a pas de mat en 2 coups (2017-9-1)
Henrik Juel: I believe this is the intention:
-1... Kh3xSg2 -2.Sh4xLg2 etc.
Now White has captured [Lf8], d2xe3, e2xf3, hxgxf
And Black has captured h7xLg6 and [Pa2,Pc2] on their files
[Pa2] must have been captured by an officer, so [Pd7] has promoted on d1 without capturing; hence Ke1 has moved, so White may not castle
1.Kd2 any 2.Tg1# (2017-9-1)
comment
Keywords: Castling (wg), Cant Castler (wg), under-promotion (l)
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2017-9-2 more...
17 - P0000736
Tivadar Kardos
2935 Die Schwalbe 59 10/1979
P0000736
(10+14) C+
BP in 7,0
1. Sc3 Sf6 2. Se4 Sxe4 3. g3 Sxg3 4. Sf3 Sxh1 5. Se5 Sxf2 6. Sxd7 Sxd1 7. Sxb8 Txb8
play all play one stop play next play all
Sally: Eine eindeutige Zugfolge, was bei solchen Aufgaben nicht oft zutrifft. Nicht ganz leicht. Der Rekord steht bei 41,5 Zügen.
(BS). (2017-9-6)
Henrik Juel: 41.5 moves is a very old record
The current record length for proof games is 58.5 moves in a problem by Pronkin, Frolkin & Keym, problem C, p.7 in Die Schwalbe, heft 283, February 2017
The former record was 57.5 moves in a problem by Pronkin & Frolkin, Die Schwalbe, 1989 (V) (2017-9-6)
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: (Natch 2.2Beta1 Copyright (C) 1997,98,99,2001,2002,2003 Pascal Wassong)
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-11-13 more...
18 - P0000739
Nikita M. Plaksin
Alexandr A. Klibanski

2981 Die Schwalbe 60 12/1979
P0000739
(15+11)
#2
1. ... Txc5 dxc5 etc
1. ... Txd4 Txd4 etc
1. ... fxe3 Lxe3 etc
1. ... fxg3ep De6 etc
R: 1. g2-g4 f5-f4 2. Dg3-h3 f6-f5 3. Dg8xBg3 f7-f6 4. Da8-g8 g4-g3 5. a7-a8=D g5-g4 6. a6-a7 g6-g5 7. a5-a6 g7-g6 8. a4-a5 a5xDb4 9. Da3-b4+ etc
play all play one stop play next play all
Henrik Juel: Black has the move. 0... Rxc5/Rxd4/fxe3 1.dxc5/Rxd4/Bxe3 etc. -1.g2 f5 -2.Qg3 f6 -3.Qg8:P f7 -4.Qa8 g4 -5.Q=a7 g5 -6.a6 g6 -7.a5 g7 -8.a4 a5:Q -9.Qa3 etc. (2003-12-10)
Brassaud: et pour justifier le mot-clé : 0)...f4xg3ep 1)De6 etc. (2017-9-4)
A.Buchanan: Very original problem: with lots of forward and backward play. A minor retro transposition is possible (Black's 3rd & 4th moves), and there is a dual in one line after e.p., but I really like this. (2017-9-4)
comment
Keywords: En passant, No legal last move for Black, Phoenix
Genre: Retro, 2#
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-9-5 more...
19 - P0000781
Josef Haas
1467 Die Schwalbe 31 02/1975
F. Schützhold gewidmet
1. Lob
P0000781
(11+6)
Weiß nimmt 1 Zug zurück, dann #1
R: 1. Tg8xSh8, dann 1. cxb6ep#
play all play one stop play next play all
Brassaud: 1) cxb6ep # est correct. Le coup blanc à retirer peut être 1) TxCh8, mais également 1) Th8 ou encore un coup de pion vers e5 ou g6 Avec le rétro jeu -1)…, b7 b5 -2) Cf2, f2xg1=T etc .. (2017-9-10)
Henrik Juel: I believe that the retraction must be -1.Tg8xSh8
otherwise Ka7 might have made the last move (2017-9-10)
A.Buchanan: Yes I remember writing about this many years ago here: https://www.janko.at/Retros/Glossary/EnPassant.htm. It all depends on exact capture-counting to refute the possibility that wR is the third promoted rook in the diagram. (2017-9-11)
comment
Keywords: Help retractor, En passant
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-9-11 more...
20 - P0000783
Luis Alberto Garaza
1469 Die Schwalbe 31 02/1975
P0000783
(13+15)
Wer ist am Zug?
hans: Black to move
R:-1.Th8-h7 Sc7-e8 -2.Th7-h8 Sa6-c7 -3.Th8-h7 Sb8-a6 -4.Th7-h8 Sd7-b8 -5.Tg7-h7 Sf8-d7 -6.Tg5-g7 Sh7-f8 -7.Tg7-g5 Sg5-h7 -8.Th7-g7 a4-a3! -9.Th8-h7 Kg7-f6 -10.Se3-f5+ etc. (2012-5-17)
Brassaud: Trait noir avec le rétro-jeu suivant :
-1) Th8-h7, Cc7-e8 -2) Th7-h8, Rg7-f6 -3) Th8-h7+, Rf8-g7 4) Th7-h8, Ca6-c7 5) Th8-h7, Cb8-a6 6) Th7-h8, Cd7-b8 7) Th8-h7, Df6-e5 8) Ce3-f5, Ce5-d7+ 9) Ff5-g4, Re8-f8 10) Rg4-h5, Cd7-e5+ etc …
Trait blanc possible :
-1) …, h4-h3 -2) Th8-h7,Cc7-e8 etc .. avec le rétro-jeu précédent. (2017-9-10)
Henrik Juel: -2... Kg7?? exposes the king to an illegal double check (2017-9-10)
Yoav Ben-Zvi: Try White-to-move? R: -1...BNc7-e8 -2.Rg7-h7 Na6-c7 -3.Rh7-g7 Nb8-a6 -4.Rg7-h7 Nd7-b8 -5.Rh7-g7 Nf8-d7 -6.Rg7-h7 (not Rh8-h7 Nh7-f8 -7.??) Nh7-f8 -7.Rg5-g7 Pa4-a3 -8.Rg7-g5 Ng5-h7 -9.Rh7-g7 ?? This shows first a Retro-opposition by BN on h7 which either smothers the WR (if it stands on h8) or forces it to retract to g5 (from g7) creating a second Retro-opposition that forces Black to use his only tempo retraction (a4-a3) prematurely. The solution shows Retro-unpin of WNf5 by BN retracting to g5. (2017-9-11)
comment
Keywords: Non-standard material, Whose move?
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-9-11 more...
21 - P0000803
Gerd Rinder
1646 Die Schwalbe 35 10/1975
P0000803
(8+10)
Remis
VL: Patt unless the PRA-logic is applied (the Buridan ass-like collision)!

Nachdruck: The Problemist, v.19, No.6, 11/2003. (2008-10-15)
A.Buchanan: This is designed to be Retro Strategy, although the subsequent convention changes which set PRA to be the default would cook it. (2017-10-21)
comment
Keywords: En passant, Retro Strategy
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-10-21 more...
22 - P0000847
Norbert Ringeltaube
182 Die Schwalbe 4 04/1970
W. Schröder gewidmet
P0000847
(13+13) C+
#56
Doppellängstzüger
1. Lg8 Ta8 2. La2 Th8 3. Lg8 Txe2 4. La2 Ta8 5. Lg8 Ta1 6. La2 Th2 7. Lg8 Ta8 8. La2 Th8 9. Lg8 Txd2 10. La2 Ta8 11. Lg8 Ta1 12. La2 Th2 13. Lg8 Ta8 14. La2 Th8 15. Lg8 Txc2 16. La2 Ta8 17. Lg8 Ta1 18. La2 Th2 19. Lg8 Ta8 20. La2 Th8 21. Lg8 Txb2+ 22. Lb3 Ta8 23. Ta7 Th8 24. Ta1 Ta8 25. Txa8 Th2 26. Lg8 Ta2 27. Lxa2 Lf1 28. Lg8 Lc4 29. Ta1 Lxg8 30. Ta8 La2 31. Th8 Lg8 32. Lb8 La2 33. Tc8 Lg8 34. Lxe5 La2 35. Th8 Lg8 36. Lb8 La2 37. Lf4+ Sxf4 38. Ta8 Lg8 39. Ta1 La2 40. Txf5 Lg8 41. Ta8 La2 42. Th8 Lg8 43. Txb5 La2 44. Ta8 Lg8 45. Ta1 La2 46. Th5+ Sxh5 47. gxh5 Lg8 48. Ta8 La2 49. Th8 Lg8 50. hxg6 La2 51. Ta8 Lg8 52. Ta1 La2 53. gxh7 Lg8 54. Ta8 La2 55. Th8 Lg8 56. hxg8=D,T#
play all play one stop play next play all
Henrik Juel: Solution
1.Lg8 Ta8 2.La2 Th8 3.Lg8 Txe2 4.La2 Ta8 5.Lg8 Ta1 6.La2 Th2 .. 9.Lg8 Txd2 .. 15.Lg8 Txc2 .. 21.Lg8 Txb2+ 22.Lb3 Ta8 23.Ta7 Th8 24.Ta1 Ta8 25.Txa8 Th2 26.Lg8 Ta2 27.Lxa2 Lf1 28.Lg8 Lc4 29.Ta1 Lxg8 30.Ta8 La2 31.Th8 Lg8 32.Lb8 La2 33.Tc8 Lg8 34.Lxe5 La2 35.Th8 Lg8 36.Lb8 La2 37.Lf4+ Sxf4 38.Ta8 Lg8 39.Ta1 La2 40.Txf5 Lg8 .. 43.Txb5 La2 .. 46.Th5+ Sxh5 47.gxh5 Lg8 48.Ta8 La2 49.Th8 Lg8 50.hxg6 La2 .. 53.gxh7 Lg8 .. 56.hxg8=DT#
C+ by Popeye 4.61, except for the promotion mate dual
I see no retro content (2017-11-24)
comment
Keywords: Maximummer, Sea Snake
Genre: Fairies
Computer test: Popeye 4.61
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-11-26 more...
23 - P0000872
Josef Kutscher
497 Die Schwalbe 10 08/1971
P0000872
(12+12)
legal?
b) Ergänze die sD, so daß die Stellung legal ist!
Brassaud: Ajouter une dame noire en b1, seule case possible, et la position devient légale
Rétro jeu
1) Re5-f5+, e4xd3 ep+ 2) d2-d4, b2-b1 =D+ etc ..
Excellente présentation du thème : Ergänze Steine (2017-9-19)
Henrik Juel: a)
The position is legal, with this retroplay
-1.Ke5xSf5 e4xPd4ep -2.d2 Sd4 etc.
b)
After addition of sD, Ke5xSf5 is illegal because all white captures were now made by pawns, but as Brassaud mentions, adding sD on b1 allows
-1.Ke5 e4xPd4ep -2.d2 D=b2 etc. (2017-9-19)
comment
Keywords: Add pieces
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-10-25 more...
24 - P0000965
Thomas R. Dawson
(86.) The Fairy Chess Review 7, p. 78, 08/1937
P0000965
(3+8)
Letzter Zug?
R: 1. b6xLa7
play all play one stop play next play all
Henrik Juel: A possible retroplay is
-1.b6xLa7 Lb8 -2.a5xSb6 Sd5xSb6 -3.Sc4,
then extract the kings via b6, etc. (2018-4-2)
comment
Keywords: Type A, Last Move? (BxL), Economy record, Type B (a fortiori)
Genre: Retro
Reprints: A/30 feenschach 159, p. 78, 04-06/2005
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-4-3 more...
25 - P0000972
Vilhelm Röpke
Albrecht Brandis
Hugo August
Thomas R. Dawson
Richard Steinweg
Hugo Rohr
Valerian Onitiu

1) Skakbladet 08/1924
P0000972
(6+1)
Letzter Zug?
R: 1. Kd1xSc1
play all play one stop play next play all
Henrik Juel: This position was actually submitted by V. Røpke only, according to the comment by tournament director Niels Høeg (p.88); the other authors had a black DTL on a1, but Høeg liked this position best, and it is the most well-known from the tourney
V. Røpke was an actuary and the strongest Danish solver for many years, and he never used his first name, so in talk others did not either, but called him Røpke; I was 15 when I met him, so I called him Mr. Røpke... (2018-4-2)
more ...
comment
Keywords: Last Move? (KxS), Type A
Genre: Retro
Reprints: Rund um das Schachbrett 1955
385 Arbeiter-Zeitung (Wien) 05/04/1959
RA17 diagrammes 16 08/1975
A7b Length Records in Last Single Moves? , p. 4, 11/2009
1429 Problemskak 30, p. 20, 04-06/2015
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2015-7-8 more...
26 - P0001162
Luigi Ceriani
36 Europe Echecs 24 08/1960
P0001162
(11+15) cooked
Löse die Stellung auf!
Brassaud: Les pions noirs en b3-b5 et c4 ont fait 3 prises, le Fou blanc a été pris en f1 et un pion blanc pris colonne h. Intention de l’auteur : rétro jeu 1) d4xDe5+, Dg3 2) d3, Te6 3) d2, Te4 4) Th4, Tg4e4+ 5) Th5, h7 6) Th4, Ta4 7) Th5, Ta1 8)Th4, Tc1 9) Th5, Tc3 10) Th4, Te3 11) Th5, Te6 12) Th4, Tg6 13) Th6, Te6 14) Tg6, b4 15) Tg8, Th6 16) Tf8 Tg6xh6 17) Th8, Tg8 18) h5, Td8 19) Tg8, Td7 20) Th8, Tc7 21) Fb8, Ca7 22) Tc8, Td7 23) Tc7c8+, Cc8 24) Fa7, Td8 25) Tb7, Td7 26) Tb8, Tb7 27) Ta8, Tc7 28) Fb8, Ca7 29) h4, Cc8 30) Ta3, Ca7 31) Td3, Cc8 32) Td4, Da3 33) Tf4d4+
La dame blanche peut sortir, la Tour noire en c7 peut regagner la case h8 et le Fou noir la case f8. On peut alors reprendre g7-g5 etc …
Une bien belle balade de tours, mais qu’elle est la démolition ? (2017-10-17)
Henrik Juel: Cook:
-1.d4xDe5 Dg3 -2.d3 Te6 -3.d2 Te3 -4.Th4 Tg4, retract Tb4 to g6, -12... h7 -13.Th6 Te6 -14.Tg6 Te3! -15.Tg8 Te6 -16.Tf8 Th6 -17.Tg8 Tg6xPh6 -18.Th8 Tg8 -19.h5 Td8 -20.Tg8 Td7 -21.Tf8 Tc7 -22.Lb8 Sa7 -23.Tc8 Td7 -24.Tc7 Sc8, retract Tc7 to a8, Td7 to c7, -28.Lc8 Sa7 -29.h4 Sc8
In the intended solution Black wasted b4-b3 at -14., forcing White to retract Ta8 to f4 to release the SE corner, but in the cook this also works:
-30.T=a7 b4 -31.a6 Sa7 -31.a5 a6xTSb5 etc. (2017-10-17)
Mario Richter: A much more simple cook is:
R: 1. d4xDe5+ Dg3-e5+ 2. d3-d4 Tg7-g6 3. d2-d3 Dh4-g3! 4. Kf4-f5 g6-g5+
which completely avoids the retro-opposition trouble in the north-west corner, so we first should check, if the given position is correctly typed into the PDB. Is it eg. in one of the Ceriani-books? (2017-10-17)
Brassaud: Remerciements pour ces explications ! (2017-10-17)
Gerald Ettl: Korrekturversuch:
Weiss:Bb6c6d3a2e2f2g2 La7 Tc5g4 Dh2 Kf5 Schwarz:Be7f7h6b5d5g5c4a3 Sc8h1 Lh3g1 Te6g6 De5 Kd6
R: 1.Dg3e5+ d2d3 2.Te4e6 Th4g4 3.Tg4e4+ Th5h4 4.h7h6 Th6h5 5.Te6g6 Tg6h6 6.Te3e6 Tg8g6 7.Te6e3 Tf8g8 8.Th6e6 Te8f8 9.Tg6xBh6 Th8e8 10.Tg8g6 h5h6 11.Td8g8 Tf8h8 12.Td7d8 Th8f8 13.Tc7d7 Lb8a7 14.Sa7c8 Tc8h8 15.Td7c7 Tc7c8+ 16.Sc8a7 La7b8 17.Td8d7 Tb7c7 18.Td7d8 Tb8b7 19.Tb7d7 Ta8b8 20.Tc7b7 Lb8a7 21.Sa7c8 h4h5 22.Sc8a7 Ta4a8 23.Sa7c8 Tb4a4
wT nach f4 (2018-6-24)
comment

Genre: Retro
Input: Gerd Wilts, 1995-6-3
27 - P0001220
Luigi Ceriani
93 Europe Echecs 49 01/1963
P0001220
(14+14)
Welches waren die letzten 7 Einzelzüge?
R: 1. ... Da1-c3+ 2. b6xSa7 Lh8-d4 3. c5xTb6! Dg7-a1 4. Kb2-c2 Tf6-b6+!
play all play one stop play next play all
Gerald Ettl: Ich sehe ehrlich gesagt nur (vermutlich) die AL:
R: 1.Da1c3+ 2.b6xSa7 3.Lh8d4 4.c5xTb6! 5.Dg7a1 6.Kb2c2 7.Tf6b6+
Kann dazu näher Angaben machen, wie etwa der cook aussehen sollte. (2017-1-19)
Henrik Juel: I see no other retroplay, either
Maybe the problem is not cooked after all? (2017-1-19)
Gerald Ettl: Henrik, dasgleiche denke ich auch. (2017-1-19)
A.Buchanan: I agree. I will remove the cook mark, but let's keep this conversation unhidden, for the record. (2017-1-20)
Mario Richter: The main point of the problem is the fact that to explain White's two pawn captures, black pawn h7 had to promote on g1 (Ph7-h3xg2-g1), therefore wPb2-b3 and wPg2-g3 cannot be soon retracted, and the retraction of bPh7/6xYg6/5 is illegal. I computer-checked the problem with this constraints, and my program rawbats only found the solution given by Gerald. (2017-1-20)
Yoav Ben-Zvi: What Mario calls "the main point of the problem" I consider as a mechanism not the primary thematic content. This can be seen in the solution retraction that contains a "Retro-Bristol" retraction by BBd4 crossing g7 for the BQ followed by a Retro-Critical retraction by BQc3 crossing f6 for BRb6 (a Retro-Indian). Looking at the same move sequence going forward the move BQg7-a1 is a Bristol clearance of d4 for BBh8. The BQ does not remain on a1, retreating back to c3, so that the clearance move does not contain the impurity of an arrival effect. A similar BQ,BB maneuver is shown in Baibikov's P1342072. (2017-10-30)
comment
Keywords: Last Moves? (7)
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2017-1-20 more...
28 - P0001238
Filip S. Bondarenko
111 Europe Echecs 65 04/1964
P0001238
(15+15)
#1 (wer?)
1. ... Sbxc2#!
1. Sxc7? (illegal)
play all play one stop play next play all
H. Juel: White has made an even number of moves. Black has made an odd number of moves. So Black has the move!
more ...
comment
Keywords: Parity Argument, Whose move?
Genre: Retro
Reprints: Problemas 18, p. 479, 04/2017
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-9-19 more...
29 - P0001243
Aleksey A. Troitzky
Vladimir Korolkov

(1) Problem 41-44 03/1957
1. Preis
P0001243
(9+12)
Ist die Stellung legal?
Die Stellung ist legal:

R: 1. Kf8-e8 2. Kg8-f8 3. Kh7-g8 4. Kg6-h7 5. Kf5-g6 6. Ke5-f5 7. Kd5-e5 8. Kc4-d5 9. Kb3-c4 10. Kc2-b3 11. Kd1-c2 12. Ke1-d1 13. Kf2-e1 14. Kg1-f2 15. Kf2xTg1
play all play one stop play next play all
Henrik Juel: The long march by black king to uncapture [Th1] was shown in 1930 by Niels Høeg, P0001754 (2018-2-23)
Henrik Juel: ...
But there might exist an even earlier problem by Troitzky, who died in 1942, so this problem must be a version by Korolkov (2018-2-23)
Mario Richter: In his article in 'Problem (Zagreb)' Korolkov mentiones, that in the last years of Troitzky's life, when he lived in Leningrad, Korolkov often visited him and they "not only dealed with the construction of endgame studies, but also of retrograde analysis problems."
Someone with better knowledge of the russian language might perhaps provide more details ... (2018-2-24)
Henrik Juel: So this problem may be a joint composition, although it seems strange that it was published 15 years after Troitzky's death (2018-2-24)
A.Buchanan: According to Wikipedia sadly, Troitsky died of starvation in 1942 in the siege of Leningrad. With all the disruption, perhaps not surprising that publication of this problem was delayed. What was the story of Korolkov's life? Did he leave Leningrad before the siege, or did he survive it? (2018-2-24)
VL: Well, Andrew, VK worked (for appr. 50 years) as an electrical engineer at the famous Kirov plant. Afaik, during the WWII he evacuated together with the plant to Ural (to the so-called Tank City near Chelyabinsk). (2018-2-25)
A.Buchanan: Thank you, Valery. That's quite moving. (2018-2-25)
comment
Keywords: Promenade (k), Non-standard material, Promotion (t), Volet Pawn (extended)
Genre: Retro
Reprints: Problem 61-64 07/1959
528 FIDE Album 1956-1958 1961
116 Europe Echecs 67-68 08/1964
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-24 more...
30 - P0001304
Luigi Ceriani
176 Europe Echecs 102 07/1967
P0001304
(11+14)
Löse die Stellung auf!
Alfred Pfeiffer: Zwei wK, Diagrammfehler? (2009-12-1)
TBr: Bei dem sBe7 tippe ich mal auf sKd6, auch ohne die Quelle nachschlagen zu können. (2009-12-1)
Henrik Juel: With black king on d6 (and count 11+14):
White captured [Ph7] with an officer and Lb8xTc7+, and promoted on a8.
Black captured [Pf2] with an officer and a6xb5, b6xc5, c5xd4, and dxPe.
-1.Lb8xTc7 Tb7 -2.La7 Tc7 -3.Sd7 Tb7 -4.Sb8 Tc7 ... -9.Sh3 Tb7 -10.Sf4xPh3 Tb8 ... -13.Sa6 Ta8 -14.Sc7 h4 -15.Lb8 Ta1 -16.La7 Tf1 -17.Lb8 Tf4 -18.La7 Tf1xPf4 -19.Lb8 Ta1 -20.La7 Ta2 -21.Lb8 Ta8 -22.La7 Tb8 -23.Sa8 Tb7 -24.f3 Tc7 -25.Lb8 Sa7 -26.f2 Sc8 -27.S=Pa7 h5 -28.a6 Sa7 -29.a5 a6xb5 etc. (2009-12-4)
Brassaud: Il semble exister une autre possibilité : -1) Fb8xTc7+, Fd7e6 2) Ce6f8+, Fe8d7 3) Fa7b8, Df8f7 4) Tf7g7, Fg7h6 5) Fb8a7, Th6g6 6) Tg6f6, Th4h6 7) Th6g6, Tf4h4 8) Th3h6, Th4f4 9) Ta3h3, Tf4h4 10) Ta8a3, Th4f4 11) a7a8=T, Tf4h4 12) a6a7, Th4f4 13) a5a6, a6xXb5 etc .. (pion h7 pris en h7 et pion f2 pris en f2) (2017-11-5)
Henrik Juel: I agree; with my abbreviated German notation
-1.Lb8xTc7 Ld7 -2.Se6 Le8 -3.La7 Df8 -4.Tf7-g7 Lg7 -5.Lb8 Th6
and the position opens easily, so there is no need for fancy uncaptures of [Pf2,Ph7]
This must be an unintended cook, if the diagram is correct (2017-11-5)
comment

Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: TBr, 2009-12-5 more...
31 - P0001317
Luigi Ceriani
189 Europe Echecs 109 02/1968
5. Preis
P0001317
(11+15)
Löse die Stellung auf!
Henrik Juel: Thanks for leaving this for me, Hans.
Black captured [Pa2 and Pf2], bxc, cxb, and dxe, and promoted on h1; White captured h6xg7, and promoted on d8.
-1... Sc4 -2.b6 Sa5 -3.e3 Sb7 -4.Dc8 Sb8! -5.Dd7 Lg8 -6.Dc8 Sa5 -7.Dd7 Sc4xPa5 -8.e2 Se3 -9.a4 Sf5 -10.a3 Sg3xPf5 -11.a2 Sh1 -12.f4 S=h2 -13.f3 h3 -14.f2 h4 -15.g4 h5 -16.g3 h7 -17.h6xSg7 Sf5 -18.h5 Sd4 -19.h4 Sb3 -20.h3 Sa5 -21.h2 Sb7 -22.Dc8, etc.
As I recall, Sam Loyd named a problem 'Stuck Steinitz'; sans comparaison, I shall name this fine retro 'Held Hans'... (2012-8-21)
Brassaud: Avec le rétro trait aux blancs, il y a une solution plus rapide. Un gain de 3 coups.
-1) Dc8 Lg8 -2) Db8 Sc4 -3) b6 Sa5 -4) e3 Sc4xa5 -5) e2 Se3 6) a4 Sf5 etc avec la suite comme Henrik. (2017-11-7)
Henrik Juel: It is quite possible that your solution is the intended one, Francois, althought I like the uncheck -7.Dd7 in mine
Some years ago Hans Nieuwhart and I started to provide solutions to the many retros entered by Gerd Wilts; most of those solutions were never checked, so your current work is much appreciated (2017-11-7)
Henrik Juel: typo: although, not althought, of course (2017-11-7)
Brassaud: thank you, Henrik, for your appreciation that goes straight to my heart (2017-11-8)
comment

Genre: Retro
Input: Gerd Wilts, 1995-6-3
32 - P0001359
Luigi Ceriani
233 Europe Echecs 134 03/1970
1. Preis
P0001359
(10+15)
Welche Züge hat der wBf gemacht?
R: 1. ... Dh6xSg6+ 2. g2-g3 Sc8-a7 3. La7-b8 g5xBf4 4. Lb8-a7 Ld8-c7 5. La7-b8+ Sc7-e8 6. Lb8-a7 Sa6-c7 7. La7-b8+ Lc7-d8 8. f2-f4! Sb4-a6 9. Lb8-a7 Sd3-b4 10. La7-b8 Sf4-d3 11. Lb8-a7 Sh3-f4 12. La7-b8 Sf4xBh3 13. Sh4-g6 Sg6-f4+ 14. Sf3-h4 Ld8-c7 15. Se1-f3 Lc7-d8 16. Sc2-e1 Ld8-c7 17. Sb4-c2 Lc7-d8 18. Sa6-b4 Lb8-c7 19. Sc7-a6 d3-d2 20. Sa8-c7 Lc7-b8 21. Lb8-a7 Sa7-c8 22. h2-h3 Sc8-a7 23. a7-a8=S d4-d3 24. a6-a7 Sa7-c8 25. a5-a6 a6xSb5
play all play one stop play next play all
hans: The move made is f2-f4 (not f2-f3)

R: -1. ... Dh6xSg6 -2. g2-g3 Sc8-a7 -3. La7-b8 g5xf4 -4. Lb8-a7 Ld8-c7 -5. La7-b8+ Sc7-e8 -6. Lb8-a7 Sa6-c7 -7. La7-b8+ Lc7-d8 -8. f2-f4!!!! Sb4-a6 -9. Lb8-a7 Sa2-b4 -10. La7-b8 Sc3-a2 -11. Lb8-a7 Se2-c3 -12. La7-b8 Sg1-e2 -13. Lb8-a7 Sh3-g1 -14. La7-b8 Sf4xh3!! -15. Sh4-g6 Sg6-f4+ -16. Sf3-h4 Lb8-c7 -17. Se1-f3 Lc7-b8 -18. Sc2-e1 Lb8-c7 -19. Sb4-c2 Lc7-b8 -20. Sa6-b4 Lb8-c7 -21. Sc7-a6 d3-d2 -22. Sa8-c7 Lc7-b8 -23. Lb8-a7 Sa7-c8 -24. h2-h3 Sc8-a7 -25. a7-a8=S d4-d3 -26. a6-a7 Sa7-c8 -27. a5-a6 a6xYb5 etc.
wCap: dxe,
sCap: axb, bxc, cxd, gxf, Sxh3, Dxg6, (2013-2-9)
Brassaud: A shorter solution is :
-1. ... Dh6xSg6 -2. g2-g3 Sc8-a7 -3. La7-b8 g5xf4 -4. Lb8-a7 Ld8-c7 -5. La7-b8+ Sc7-e8 -6. Lb8-a7 Sa6-c7 -7. La7-b8+ Lc7-d8 -8. Lb8-a7 Sb4-a6 -9. La7-b8 Sd3-b4 -10. Lb8-a7 Sf2-d3 -11. La7-b8 Sh3-f2 -12. f2-f4 !!!! Sf4xh3 -13. Sh4-g6 Sg6-f4+ etc … (2017-11-12)
comment

Genre: Retro
Reprints: feenschach 13 02/1973
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2017-11-12 more...
33 - P0001360
Max Lange
885 Deutsche Schachzeitung , p. 61, 02/1858
P0001360
(8+5) C+
#3
1. dxc6ep+! Kd5 2. Sf2 droht 3. Sc7#
2. ... bxc6+ 3. Lxc6#
play all play one stop play next play all
Originalforderung: Weiß zieht und soll auf die kürzeste Weise matt setzen. Matt in wieviel Zügen?

See also P0002092.
VL: The very first retro problem...
The author is presumably Max Lange,
as John Beasley (jointly with Hanspeter Suwe)
determined. See his article on the â??en passant keyâ?�
in The Problemist, May 2004 (pp. 391-392) and
Sept 2004 (p. 459). See also Chess Note 4417 (June 2006) in
http://www.chesshistory.com/winter/ . (2008-11-30)
Mario Richter: The list of contents (p.VIII) for the year 1858 explicitely gives Max Lange as the author of this problem. So could we really say, that the author is 'anonym'? (2010-12-9)
Henrik Juel: Only possible last move is c7-c5
C+ by Popeye 4.61 (2017-9-9)
Henrik Juel: A direct link to Chess Note 4417 is
http://www.chesshistory.com/winter/winter23.html#4417._Zukertort_problem_C.N._4042
But is does not provide new information (2017-11-9)
Henrik Juel: Without the ep key, the shortest mate is in 4 moves
unfortunately with many possible keys 1.Le8,Lc8,Sf6,Se5,Lxc5+
e.g., 1.Sf6 exf6 2.Lf5 Kxd5 3.Sc7+ Kd6 4.Lxc5#
or 1.Lxc5+ Kxd7 2.Txe7+ Kd8 3.Sf6 Kc8 4.Te8# (2018-3-1)
comment
Keywords: En passant, En passant as key
Genre: Retro
Computer test: Popeye 4.61
Reprints: Deutsche Schachzeitung , p. 313, 10/1906
53 Retrograde Analysis 1915
234 Europe Echecs 140-141 10/1970
RA1 diagrammes 11 10/1974
(A) feenschach 154 2004
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-9-12 more...
34 - P0001373
Aleksey A. Troitzky
95A Retrograde Analysis 1915
P0001373
(13+13)
#4
1. dxe6ep Txb8+ 2. Kxb8 ... 3. Dxf7+ Kd8 4. Dd7+
UWF: Lb8 und ein sT.
Umwandlung des wBh2 auf h8, weiße Schlagfälle: cxd, f2xe3, gxf; schwarze Schlagfälle: wLc1, hxg, gxh. R: 1. e7-e5 f2xD(S)e3
play all play one stop play next play all
Henrik Juel: -1... e7 -2.f2xSe3 Sc2 -3.Kc7 Sb4 -4.Kc8 Sc6 -5.Le5 Sb8 -6.Kc7 Sc6 etc., not -1... e6? with wrong tempo. (2004-3-8)
AV: Cook : 1 Dxf7+ ... 3# (2006-4-1)
VL: Apparently, a misprint in the original position: BQ should
stand on h8 instead of R. Among the other 199 problems in
this classic book, none contains non-standard material!
Anyway, BPc7 promoted on c1. The parity (odd-even) effect. (2006-4-7)
VL: No, sorry, Qh8 doesn't repair the problem...
Moreover, there is a dual: 2.Kxb8 or Kc7. (2006-4-8)
Yoav Ben-Zvi: The #4 cannot be salvaged so the stipulation needs to be changed. "White to move. Last move?" is simplest. To retain the e.p. element requires something like "White to move. How many of the BPs can be captured on the first move?".
With such a stipulation BRh8 can (and should) be replaced by BQ. Without a BR obviously promoted on c1 it needs to be shown that White cannot break the tempo by retracting either WPc4xBd5, since then [BPc7] must but cannot unpromote on c1, or WPc4xPd5 since Black captured WB on c1 and the WNs by BPhxg (allowing [WPh2] to promote without capture on h8) followed by BPgxh so it cannot play BPcxd. (2017-12-27)
comment
Keywords: En passant, En passant as key, Non-standard material, Promotion
Genre: Retro
Reprints: 247 Europe Echecs 150 07/1971
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-8-10 more...
35 - P0001393
Luis Alberto Garaza
267 Europe Echecs 171 02/1973
P0001393
(13+16)
Die Rochade ist zulässig. Welches war der letzte Zug?
Brassaud: Letzte zug -1) …, g6g5 Le roque étant légal et le cavalier blanc ne pouvant venir de f6, le dernier coup a été joué par les noirs, pion g5 (venant de h6 ou de g6)
Décompte des coups joués jusqu’à la position finale :
Blancs : pions = impair, tours = impair, cavaliers = pair soit un total pair
Noirs avec dernier coup h6xCg5 : pions = impair, tour de a8 = impair, tour de h8 = impair, cavaliers = pair soit un total impair. Cet essai n’est pas légal.
Avec le dernier coup joué g6g5, la parité noire est changée : la tour de h8 a pu jouer un nombre pair de coups (via colonne h) (2017-11-14)
comment
Keywords: Castling (wk), Parity Argument
Genre: Retro
Input: Gerd Wilts, 1995-6-3
36 - P0001452
Jean Claude Dumont
Jean-Claude Gandy

326 Europe Echecs 225/226 10/1977
P0001452
(7+3)
#2
1. Lf5 b5+ 2. cxb5#
1. ... b6,bxc6 2. Lc8#
R: 1. ... Kb6xSa6 2. b5xc6ep+ c7-c5 3. Sc5xSa6 ...
play all play one stop play next play all
AV: 1 Ff5!. Derniers coups 1...Cb8-a6 2 Cc5xCa6+ c7-c5 3 b5xc6e.p.+ Rb6xCa6. (2005-6-26)
Brassaud: Je propose une autre solution ?
Rétro jeu : -1) Tb3b4, Rb5a5 -2) bxc6ep+, c7c5 -3) Te3b3+, Rc5b6 etc …
Trait noir. 0) … b6 1) Fb1, b5+ 2) cxb5# (2017-11-22)
Henrik Juel: Clever idea, Francois, but I believe the convention is that White has the move in a #2 problem, unless it can be proved that Black has no last move
With germanic notation the intended solution is
1.Lf5 b5+/b6,bxc6 2.cxb5/Lc8#
with retroplay
-1... Kb6xSa6 -2.b6xc5ep c7 -3.Sc5xSa6 etc. (2017-11-22)
comment
Keywords: Last Moves?
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-11-23 more...
37 - P0001464
Claude Wiedenhoff
338 Europe Echecs 237/238 10/1978
P0001464
(12+11)
#1
Brassaud: 1) Ta1# not 1) Fxg6 ? Le trait est aux noirs.
Blancs : h2=h8, gxfxexdxcxb b8=fou
Noirs : b7xa=a1, h7h6xg5, g7xf6
-1) Th3h5, f7xCg6 -2) Ch4g6+, a6a5 -3) Fg6h7, Rh7h8 -4) Fh5g6+ etc …
L’essai avec le dernier coup joué par les noirs -1).. a6a5 -2) Th3h5, f7xCg6 -3) Ch4g6+, a7a6 .. ne va pas car le fou promu en b8 ne peut revenir en h2 (2017-11-23)
Henrik Juel: White could not capture [Pb7] on b7, because [Lc8,Dd8] need to get out early; so [Pb7] promoted on a1 or captured b7xc6
Nowadays we would probably write the stipulation as '#1 (who?)' for clarity (2017-11-23)
comment
Keywords: Whose move?, Last Moves?
Genre: Retro
Input: Gerd Wilts, 1995-6-3
38 - P0001485
P. Debreu
359 Europe Echecs 253 01/1980
2. ehrende Erwähnung
P0001485
(14+8)
Weiß ist am Zug
Wo wurde die schwarze Dame geschlagen?
hans: White last move is capture the sD and this can be done on several places LxDe1, TxDc3, SxDd5, SxDa7, LxDc8 cxDb5! (2011-2-15)
Henrik Juel: There must be some diagram error. (2011-2-15)
AV: We must add "White to move" to the stipulation. Therefore, the last move is ...Kb1xLb2 and the sD must have been captured on her original square d8. And the sLc8 has been captured in b3 (axb3+ Ka1-b1).

1.Sf3 h5 2.Se5 h4 3.Sc6 h3 4.Sxd8 At home ! 4...hxg2 5.Sc6 Th3 6.Se5 Te3 7.fxe3 g1T 8.Kf2 Tg6 9.Lg2 Te6 10.h4 Tg6 11.h5 Te6 12.h6 Tg6 13.h7 Te6 14.h8T Tg6 15.T1h3 Sc6 16.Dh1 Sd4 17.exd4 Sf6 18.Ke3 Se4 19.Kd3 Sc5+ 20.dxc5 Tb6 21.cxb6 Tb8 22.bxa7 Kd8 23.axb8L Ke8 24.La7 Kd8 25.Lg1 b6 26.b4 Lb7 27.Sc3 Ld5 28.La3 Le6 29.Tb1 Kc8 30.Sc6 Kb7 31.Sa7+ Ka6 32.b5+ Ka5 33.Ld6 Lb3 34.Lb7 Le6 35.Lc8 Lg4 36.Sd5 Ka4 37.Tb4+ Ka3 38.Ta4+ Kb2 39.La3+ Ka1 40.Lc1 Le6 41.Lf2 Lg4 42.Kc4 Le6 43.Kb4 Lf5 44.Tha3 Ld3 45.Th3 Lc4 46.Thc3 Lb3 47.Dd1 Kb1 48.Le1 Ka1 49.axb3+ Kb1 50.Lb2+ Kxb2 (2014-11-24)
Brassaud: L’idée de la prise de la dame noire en d8 afin de donner du temps aux noirs (Re8-d8 et Rd8-e8) se trouvait déjà dans les problèmes P0001301 et P0001329 de Luigi Ceriani (2017-11-26)
Henrik Juel: In fact Ceriani made a number of problems with this idea
His early P0005010 is one of my favorite retros (2017-11-26)
comment
Keywords: Non-standard material
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2014-11-24 more...
39 - P0001506
Michel Caillaud
379 Europe Echecs 265 01/1981
Dr L. Ceriani zum Gedenken
1.-2. Preis e.a.
P0001506
(14+10)
#1 (wer?)
Henrik Juel: With stipulation '#1 (who?)' the solution is: 1... Sg5#, not 1.Re1??, because Black has the move. -1.Sc3 Sf6 ... -5.Sb6 Sa1 -6.Sc8 S=a2 -7.Sb6 a3 -8.Sc8 a4 -9.S=c7 a5 -10.b6xP a6 -11.a5xQ Qb3 -12.a4 Qd1 -13.c2xP d4 -14.g5 e5xS -15.Sb3 Qe1 -16.Sc5 Qd1 -17.Sd3 a7 -18.Se1 e6 -19.Sg2 Qf1 -20.Re1 e7 -21.fRe2 Rf2 etc. To open the cage we need a man on f1; the only possibility is a bQ, uncaptured on b6. But then we also need a man to screen on g2; uncapturing a bS on d3 and retracting it to g2 is too slow, so on d3 we uncapture a bP, which in turn on d4 uncaptures a wS, which screens on g2. A very good and difficult retro. (2003-4-25)
Yoav Ben-Zvi: The side-to-move is determined by the Retro opposition that occurs when the uncaptured WN needs to retract to e1 (on its way to g2) while the uncaptured BQ shuffles between e1 and d1. (2018-4-3)
comment
Keywords: Whose move?, Retro Opposition
Genre: Retro
Reprints: 970 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2006-10-22 more...
40 - P0001517
Michel Caillaud
389v Europe Echecs 271 07/1981
Lob
P0001517
(12+9)
h#2
Henrik Juel: Solution: 1.g5 hxg8=QR 2.gxf4 Kd2#, not 2... 0-0-0??.
Only if White had the move would he be entitled to castle: -1... h5 -2.Sf2 h6 -3.Sd3 Kh1 -4... Bg1 -5... Kh2 .. -8... Kh5 -9... Bh2 -10.Sf2 Bg3 -11.h2 Bh4 -12.Sd3 Bf6 etc. (2003-3-31)
Yoav Ben-Zvi: The need for a tempo move (by WK or WR) arises because WN needs to stand on f2 when Black retracts Bg3-h2. I dont think this is Retro opposition because the role of the WN is positive (Retro Shield) rather than negative. (2018-4-3)
Henrik Juel: Now I notice that Ph7 is a so-callet Volet pawn (coming diagonally from c2)
The definition of Retro Opposition in the latest Album (2010-12, p.620) is:
'In a particular phase of the retro-play it can be proved which side is to play, despite there being mobile units on both sides.' (2018-4-3)
Mario Richter: The position can also be easily resolved by an early retraction of f3-f4, in this case wK had to move earlier in the game not because of RO but to let original wRook h1 out ... (2018-4-5)
Yoav Ben-Zvi: The FIDE Album Theme Index tries to save space so the definitions contain only what is deemed to be the essential core of the theme. In some cases, such as the definition for Retro Opposition, this is carried too far and an essential characteristic is left out. To see this note that the definition (given above) does not distinguish Retro Opposition from the Parity Argument theme. Unless Parity is considered to be a particular type of Retro Opposition, the FIDE Album definition must be rejected.
I think that any satisfactory definition of RO will state that a thematic retraction is prevented (not enabled) by certain circumstances. If this is the case then I see no Retro Opposition here. (2018-4-9)
comment
Keywords: Cant Castler, Retro Opposition, Castling (wg), Volet Pawn
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-4-3 more...
41 - P0001524
Michel Caillaud
396 Europe Echecs 261/262 09/1981
1.-2. Preis e.a.
P0001524
(14+11)
Wer ist am Zug?
R: 1. Sa2-c1 h7xSg6 2. Sf8-g6 Lc1-d2 3. Se6-f8 Ld2-c1 4. Sc5-e6 Lc1-d2 5. Sb7xBc5 Ld2-c1 6. Sd6-b7 Lc1-d2 7. Sb5-d6 Ld2-c1 8. Sa3-b5 Lc1-d2 9. Sb1-a3 Kh2-h1 10. Sd2-b1 Kh3-h2 11. Kg1-f1 c6-c5 12. Sf1-d2 Ld2-c1 13. Sh2-f1 Lc1-d2 14. Tf1-e1 c7-c6 15. 0-0 Dg2-f3 16. Tf3-e3 Le3-c1 17. Sc1-a2 Ld4-e3 18. Te3-f3 Lg7-d4 19. f3-f4
play all play one stop play next play all
Weiße Schläge: hxg; gxf; dxe; axb. Schwarze Schläge: hxg; dxc. Schwarzer Bc7 wurde auf seiner Linie geschlagen, sBa7 wandelt sich auf a1 um. Schwarz ist am Zug.
Yoav Ben-Zvi: The side-to-move is determined by 2 Retro oppositions: The BB is prevented from retracting to d2 when the WN stands there on its way to h2 and White un-castling is prevented with BB standing on d2. The 2 tempo moves provided by a BP that is uncaptured on c5 are not enough to overcome both oppositions if the diagram position is White-to-move. (2018-4-3)
comment
Keywords: Retro Opposition, Castling (wk), Whose move?
Genre: Retro
Reprints: 972 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-4-3 more...
42 - P0001535
Michel Caillaud
407 Europe Echecs 286 10/1982
Roger Diot zum Gedenken
3. ehrende Erwähnung
P0001535
(13+11)
#1
R: 1. Se6-g5 Sc6-b8 2. Sc7-e6 Sd4-c6 3. Sa8-c7 Sb3-d4 4. a7-a8=S Sc1-b3 5. a6-a7 Sb3-c1 6. a5-a6 Sc1-b3 7. a4-a5 Sb3-c1 8. Se6-f8 Sc1-b3 9. Sc7-e6 Sb3-c1 10. Sa8-c7 Sc1-b3 11. a7-a8=S Kg6-h6 12. a6-a7 c2-c1=S 13. a5-a6 c3-c2 14. b4xBa5 c4-c3 15. c3xLb4 Ld6-b4 16. c2-c3 Lf4-d6 17. a3-a4 Lh6-f4 18. a2-a3 Lf8-h6 19. h6-h7 g7xSf6
play all play one stop play next play all
Schwarz Schläge: gxf6; hxgxf. Weiße Schläge: dxe3; exf3; fxg; cxbxa. Der schwarze Bauer a7 wurde auf seiner Linie geschlagen. Um die Stellung aufzulösen, muß der sLf8 über h6 auf sein Ausgangsfeld zurückgespielt werden. Schwarz ist am Zug.
Yoav Ben-Zvi: When the second unpromoted WP uncaptures a BB on b4 it must retreat in all haste to f8 so that BK must stand on g6 (not h6) and unpromoted BP must stand on c4 (not c5). This determines the side-to-move in the diagram position. Is it justified to consider a conflict between pieces of the same color a Retro opposition? (2018-4-3)
comment
Keywords: Retro Opposition, Promotion
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-4-3 more...
43 - P0001547
Andrey Frolkin
Andrej N. Kornilow

418 Europe Echecs 292 04/1983
dedicated to K P Q N N P B R
1. ehrende Erwähnung
P0001547
(27+0)
Das Brett ist nicht gefärbt.
1) Färbe das Brett,
2) Bestimme die Art und Farbe der Steine,
3) Welches war der letzte Zug?
4) Wem ist das Problem gewidmet?
hans: Turn board 90°
Last move 0-0+
White:Kg1,Tf1,Te1,Lb6,Sf7,a5,b4,c3,d2,d7,f2,g2,g7, (13)
Black:Kc1,Da8,Ta4,Lb2,Sa2,Sb3,a7,b7,c5,d4,e5,f4,g3,(14)
captures White: exd hxg Black: fxe gxf hxg (5)
A=Bauer C=König D=Toren I-Dame L=Springer U=Laufer
For 4) probably a name with those six letters A-C-D-I-L-U (2012-2-22)
Henrik Juel: The answer to part 4) is, I think, Michel Caillaud, as his last name only uses the six letters in the problem (2012-2-22)
Alain Brobecker: Dedication was given with pieces symbols. This eases things a lot! (2012-2-22)
Brassaud: Wem ist das problem gewidmet ? My ‘april fool ‘solution.
Probably a name with those six letters : KPQNNPBR … for King, Pawn, Queen etc … Which suggests: ACDILU and so Michel CAILLAUD. But this is a code, and there is no reason to say that it is not the coding of other letters.Chess problem Data Base Server contains several ' retro ' problem authors whose names contain 6 different letters.
When classifying by number of published problems, we can find : M. Caillaud, L. Ceriani, T. Dawson, W. Dittmann, T. Steudel, A. Kisljak, A. Buchanan, G. Donati, T. Kardos, N. Dupont, W. Frangen, D. Baibikow, E. Bartel, P. Kniest, M. Richter etc. .. (and even, but very far behind : F. Brassaud)- So everyone has to make a choice. (2017-12-9)
Henrik Juel: Curious that so many well-known composers happen to have exactly six different letters in their last names (2017-12-9)
Olaf Jenkner: Footballers have eleven different letters in their last names. (2017-12-9)
comment
Keywords: Last Move?, Castling (wk)
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alain Brobecker, 2012-2-22 more...
44 - P0001555
Philippe Serfati
426 Europe Echecs 301 01/1984
P0001555
(12+14)
#1
Welches war der letzte Zug des weißen Königsläufers?
Brassaud: White : dxe, hxg - Black : exdxcxbxa
White checkmate : Qe5#
Rétro : 1)… a2=S 2) b2, b3xa2 3) De4, cxSb3 3) Td2, dxLc4 4) Lf1 (last move), d6 5) e2, Ld4 …. (2017-12-11)
comment
Keywords: Last move of a specific piece?, Non-standard material
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-8-10 more...
45 - P0001566
Andrey Frolkin
436 Europe Echecs 307 07-08/1984
Lob
P0001566
(22+0)
Färbe die Steine! Welches war der letzte Zug?
Henrik Juel: White: Kg8, Qh8, Bf8,g3, Pa2,a6,b3,c2,d2,f2,h7 (11+11). -1.B=g7:S. (2003-11-20)
Brassaud: The solution proposed by Henrik does not seem appropriate. White: Kg8, Qh8, Bf8,g3, Pa2,a6,b3,c2,d2,f2,h7. So : Queen g8 and one of the two bishops are promotions, and seven pawns ?
Whatever the color of the pieces : on the diagram there are eleven pawns, at least three queens promotion and two bishops promotion (four bishops on black fields). Total sixteen pawns (or equivalents after promotion). So there is the necessary presence of the two originals queens.
The queen in g8 is a white promotion (last move g7xh8 = D +)
If the king f6 is black: the queens d6 d8 f4 and h6 are black. The white queen from e1 is absent.
If the king f6 is white: the queens d6 d8 f4 and h6 are white. This is the black queen from e8 who is absent.
Could this be a diagram error (2017-12-13)
Brassaud: erratum : queen in h8 (2017-12-13)
Mario Richter: Henrik's solution is absolutely legal - wQh8 is the original wQueen and last move was: g7xSf8=L+. (2017-12-13)
Brassaud: Sorry I had not understood the last move B=g7:S, it's easier with g7xSf8=L+. Thank you Mario. (2017-12-13)
Henrik Juel: In my uninformed youth I wrote in English, also for the men (S=knight), with very abbreviated notation in retroplay
-1.B=g7:S reads 'bishop unpromotes (=) to g7, uncapturing (:) a knight' (this is sufficient, as there is no bishop on h8)
Nobody else thought this was a good idea, and now I use KDTLSP for the men and full notation for uncaptures, e.g., -1.g7xSf8=L
Sorry about the confusion, Francois (2017-12-13)
Henrik Juel: For this enjoyable problem I should also have written the pawn play, like
White: e2xd3x..xa6, g7xSf8=L
Black: c3xb2, dxe, fxe, e1=D three times, gxh, hxg, g1=L (2017-12-13)
comment
Keywords: Last Move?, Coloring problem, Promotion
Genre: Retro
Input: Gerd Wilts, 1995-6-3
46 - P0001568
Michel Caillaud
438 Europe Echecs 310 10/1984
Lob
P0001568
(12+13)
h#1,5*
* 1. ... ... 2. 0-0-0 Tb8#
1. ... d6 2. Lf7 (nicht 0-0-0?) Tb8#
play all play one stop play next play all
Schlagfälle und Umwandlungen: axb, bxc, cxd, h=; dxc, exf, fxe, hxg, a=
Henrik Juel: Maybe the stipulation should be h#1: 1.0-0-0 Rb8#. The castling is preserved by -1.Bb8 Ba5 -2.Kg1 Bb6 ... -10.Kb4 Bb6 -11.Ka5 Ba7 -12.Ka6 g4 -13.Kb7 Bb6 -14.Kc6 Ba5 -15.Rb6 Ba6 etc. (2003-4-14)
Michel Caillaud: Correct stipulation : h#1,5*
Set : 1.0-0-0 Rb8#
Play : 1...d6 2.Bf7 (not 0-0-0?) Rb8# (2003-4-15)
Yoav Ben-Zvi: Release of the position without moving BK and BRa8 requires that WK retracts to c6 (to shield the BK from WBa4) via a3,b4,a5,a6,b7. When WK is retracted from a5 to a6, BB must be standing on a7 (to shield WK from BRa8) and Black must respond with retraction of BPg4-g3. This implies that, when WK is retracted from b4 to a5, BB cannot stand on a7 (as Black would then need to use his only tempo retraction too early) so it stands on b6 while WB stands on b8 (WB cannot stand on a7 as this would be a Retro-opposition preventing Black's following retraction BBa7-b6). WK does not have a triangulation available on the retro-path from h1 to b4 so the configuration of WKb4, WBb8, BBb6, BPg3 with White to play the next retraction can only be achieved, under the assumption of Black retaining castling rights, if it is Black to move in the diagram position. This means 0-0-0 is available in the set play but not in the solution (reversed because of the H#1.5 stipulation). (2018-4-5)
comment
Keywords: Cant Castler, Retro Opposition, Castling (sg)
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-4-6 more...
47 - P0001598
Michel Caillaud
468 Europe Echecs 334 10/1986
P0001598
(15+11)
#1 (wer?)
1. ... c1=S# (1. Sxb3#??)
R: 1. Sg2-e1 La2-b1 2. Sh4-g2 Lb1-a2 3. Sg6-h4 La2-b1 4. Sh8-g6 Lb1-a2 5. Sf7-h8 La2-b1 6. Sd8-f7 Lb1-a2 7. Sc6-d8 La2-b1 8. Sb4-c6 Lb1-a2 9. Sa2-b4 b4-b3 10. Sc1-a2 ... 11. Se2-c1 ... 12. Sg3-e2 ... 13. Sh5-g3 ... 14. Sg7-h5 ... 15. Se8-g7 ... 16. Sc7-e8 ... 17. Sa8-c7 ... 18. a7-a8=S ... 19. a6-a7 ... 20. a5-a6 ... 21. a4-a5
play all play one stop play next play all
Springerkreisel
Henrik Juel: Black has the move; the retroplay is -1.Sg2 Ba2 ... -8.Sb4 Bb1 -9.Sa2 b4 -10.Sc1 Ba2 ... -17.Sa8 ... -18.S=a7 etc. (2003-4-22)
Renny Bosch: Aside from that sensational 1 5/8 full circle Knight tour, this composition has some additional challenges. One never really knows one has seen all of a composition's beauty until one has actually produced a proof game. In this case a pawn analysis shows that white Pawns h and g have captured on g and f, exd, dxc, cxb6, bxc3, and a has promoted, black Pawn a has captured on b, and h has promoted. The question is, what happened to the piece that the black h Pawn promoted to? It cannot be one of the pieces still on the board, so it must have been one of the white Pawn capturees, but which one? The only way to unlock the central cluster is to uncapture a white Knight on b5, then walk the bK to b5 and the wQ to d4, after which the wPd6 can uncapture from e5.

Here is a PG (as pretty as I could make it) that shows the whole thing: 1. a4 b5 2. c4 c6 3. c5 Qb6 4. cxb6 c5 5. Ra3 c4 6. Re3 c3 7. Re6 c2 8. e4 Na6 9. e5 Nc5 10. a5 Na4 11. h4 Nc3 12. bxc3 Bb7 13. Ba3 Bd5 14. Bc5 Bb3 15. Be3 b4 16. g4 Rc8 17. g5 Rc4 18. Qe2 Re4 19. Qd3 Kd8 20. Qd4 Kc8 21. Bc4 Kb7 22. Bd5+ Ka6 23. Ke2 Kb5 24. Kd3 f5 25. Rh2 f4 26. Rg2 f3 27. Rg3 h5 28. Rg4 Nf6 29. gxf6 g5 30. Rf4 g4 31. Ne2 Rg8 32. Ng1 Rg5 33. Ne2 Rf5 34. Ng1 Bh6 35. Ne2 Bg5 36. hxg5 h4 37. Ng1 h3 38. Ne2 h2 39. Ng1 h1=Q 40. Ne2 Qh8 41. Ng1 Qb8 42. Ne2 Qd6 43. exd6 a6 44. Qe5 Ba2 45. Nd4+ Kc5 46. Na3 Bb1 47. Nab5 axb5 48. a6 Ba2 49. a7 Bb1 50. a8=N Ba2 51. Nc7 Bb1 52. Ne8 Ba2 53. Ng7 Bb1 54. Nh5 Ba2 55. Ng3 Bb1 56. Nge2 Ba2 57. Nc1 Bb1 58. Na2 b3 59. Nb4 Ba2 60. Nbc6 Bb1 61. Nd8 Ba2 62. Nf7 Bb1 63. Nh8 Ba2 64. Ng6 Bb1 65. Nh4 Ba2 66. Ng2 Bb1 67. Ne1 (2007-12-11)
Brassaud: Fantastic ride of the white knight, bravo Michel Caillaud. Yes we can unpromote rook e4 still present on the board. PG 1) c4, f5 2) Sh3, f4 3) Sg1, c6 4) Dc2, b5 5) Db3, Sa6 6) Da4, Sc5 7) Dd1, Se4 8) c5, Sd6 9) g4, Sf6 10) g5, Tg8 11) g5xSf6, g5 12) e4, g4 13) e5, Lb7 14) Se2, Db6 15) c5xDb6, c5 16) e5xSd6, c4 17) a4, Tg5 18) h4, Tf5 19) Th3, Lh6 20) Te3, Lg5 21) Te6, Le4 22) Sc3, Lb1 23) Sd5, c3 24) Sg3, c2 25) a5, O-O-O 26) Sc7, Kb7 27) Sa8, Tc8 28) h4xLg5, Tc3 29) b2xTc3, h5 30) Lg2+, Ka6 31) Ld5, h4 32) Ke2, f3+ 33) Kd3, h3 34) Ta4, h2 35) Tf4, h1=T 36) De2, Th8 37) De5, Tc8 38) Se2, Tc4 39) La3, Te4 40) Lc5, b4 41) Le3, Kb5 42) Sd4+, Kc5 43) Sc7, a6 44) Sb5, a6xSb5 (the cage is closed) 45) a6, La2 46) a7, Lb1 47) a8=S, La2 48) Sc7, Lb1 49) Se8, La2 50) Sg7, Lb1 51) Sh5, La2 52) Sg3, Lb1 53) Se2, La2 54) Sc1, Lb1 55) Sa2, b3! 56) Sb4, La2 57) Sc6, Lb1 58) Sd8, La2 59) Sf7, Lb1 60) Sh8, La2 61) Sg6, Lb1 62) Sh4, La2 63) Sg2, Lb1 64) Se1, … c1=S# (2017-12-16)
Yoav Ben-Zvi: A similar concept appears in P0001979. (2017-12-18)
more ...
comment
Keywords: Whose move?, Retro Opposition, Promotion, under-promotion (S)
Genre: Retro
Reprints: Die Schwalbe 120 12/1989
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-18 more...
48 - P0001599
Leonid M. Borodatow
469 Europe Echecs 334 10/1986
A. Hazebrouck gewidmet
P0001599
(10+15)
#1
AV: Les Noirs ont le trait et matent par ...g3#. Derniers coups : 1 e3-e4 (ou d3xCe4) Ce5-d7+ 2 e4-e5 Cd7-f6 3 b2-b3 Cf6-e8 4 a2-a3 Tc3-f3+ 5 Rf4-e4 Tf3xb3+ 6 Re4-f4 Tb3-f3+ 7 Rf4-e4 Tf3xa3+ 8 Re4-f4 Ta3-f3+ 9 Rf4-e4. (2005-6-27)
Brassaud: Alain Villeneuve proposes : 1)Kf4e4, Ta3f3+ 2)Ke4f4, Tf3xa3+ 3)Kf4e4, Tb3f3+ 4)Ke4f4, Tf3xb3+ 5)Kf4e4, Tc3f3+ 6)a2a3, Sf6e8 7)b2b3, Sd7f6 8)e4e5, Se5d7+ Then he proposes d3xSe4 or e3e4. I think that the sequence d3xSe4 is not legal : 9) d3xSe4, Sf6e4 ? 10) d2d3 What else? and the white bishop can not go back to c1. The only possibility is 9)e3e4, Ta3c3 10)Ke4f4, Sf3e5+ 11)Tf5d5 … (2017-12-17)
Henrik Juel: I think that both of Alain's suggestions work
-9.d3xSe4 Sd2! -10.Ke4 Sf3-d2 -11.Kf4 Tb3 -12.Ke4 and, e.g., -12... Sc6 -13.Tf5, and there is no more time pressure (2017-12-17)
Brassaud: Agree with you Henrik, it's an oversight on my part for the shield 10 Cd2f3 (I progress slowly taking advantage of my mistakes) (2017-12-17)
comment
Keywords: Whose move?, Uncapture of pieces by pieces
Genre: Retro
Input: Gerd Wilts, 1995-6-3
49 - P0001605
Dmitri W. Pronkin
Andrey Frolkin

475 Europe Echecs 337 01/1987
P0001605
(1+16) C+
BP in 17,0
1. d3 h6 2. Lg5 hxg5 3. h4 Txh4 4. a4 Txa4 5. Th6 Sxh6 6. g4 Sxg4 7. Lg2 Sxf2 8. Lc6 Sxc6 9. d4 Sxd4 10. c4 Sxe2 11. c5 Sxg1 12. c6 dxc6 13. Dd4 Dxd4 14. Ta3 Dxb2 15. Th3 Lxh3 16. Sc3 0-0-0 17. Sd5 Txd5= patt!
play all play one stop play next play all
Henrik Juel: Black makes 15 captures.
The first 13.0 moves are correct by Euclide 1.0, but it takes some 4 minutes, so a complete test would probably take more than a day (2014-12-9)
paul: Jacobi checked the last 16 moves (in about 20 min). (2018-5-10)
Mario Richter: I would like to label this problem as a "Massacre PG", but the current definition of that term only knows of two-sided MPGs. Perhaps we could make the same differentiation as for "Homebase"?!
Btw., wasn't "popeye" best for such massacres?
rawbats confirms complete correctness of the problem after approx. 25 minutes. (2018-5-11)
Henrik Juel: Yes, Mario, Popeye is fairly good at this type
C+ by Popeye 4.61 in 57 minutes (2018-5-11)
A.Buchanan: @Mario: yes I agree it would be good to make massacre more specific. There are 69 massacres currently, almost all 2-sided, but maybe also some series-movers (unique or non-unique) which are currently not counted? (2018-5-12)
comment
Keywords: Unique Proof Game, Castling, Homebase (w)
Genre: Retro
Computer test: rawbats
Reprints: 116 Shortest Proof Games 11/1991
20a 64 Proof Games 2012
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-5-11 more...
50 - P0001631
Francois Brassaud
500 Europe Echecs 358 10/1988
P0001631
(14+10)
#1
b) alles ein Feld nach links
a) 1. gxf6ep#!
b) 1. bxc6ep#!
play all play one stop play next play all
Henrik Juel: In part a) Black has captured [Lf1] on f1 and [Lc1] on a dark square, so last move was neither c6xd5 nor g6xf5
Nor was last move d7-d5, because this would entail that Le4 were [Pa7] promoted on b1; this promotion is feasible with a3xLb2, but then the promoted bishop could not reach e4
So last move was f7-f5, allowing 1.gxf6ep#
Part b) is analogous, 1.bxc6ep# (2017-11-22)
comment
Keywords: En passant, Symmetrical position, Twin by board shift
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-11-23 more...
51 - P0001641
Francois Brassaud
510 Europe Echecs 367/368 07/1989
A. Hazebrouck gewidmet
P0001641
(13+14) cooked
KBP?
1. h4 e5 2. h5 Ke7 3. h6 Kd6 4. hxg7 Kc5 5. Th6 Kb4 6. Tc6 h5 7. e4 h4 8. Ke2 h3 9. Kf3 Th4 10. Le2 Sh6 11. g8=L f6 12. Lb3 h2 13. c4 h1=S 14. Dc2 Sg3 15. fxg3 a5 16. g4 a4 17. g5 axb3 18. g6 bxc2 19. g7 cxb1=T 20. g8=D
play all play one stop play next play all
Cook: 1. c2-c4 a7-a6 2. e2-e4 e7-e6 3. f2-f4 h7-h5 4. Dd1xh5 Ke8-e7 5. Dh5-b5 Th8-h4 6. Ke1-e2 Th4-g4 7. h2-h4 a6xb5 8. h4-h5 b5-b4 9. h5-h6 Ke7-d6 10. h6-h7 Kd6-c5 11. Th1-h6 Tg4-h4 12. h7-h8=D g7-g6 13. Dh8-c3 b4xc3 14. Ke2-f3 c3-c2 15. f4-f5 c2xb1=T 16. f5xg6 Kc5-b4 17. g6-g7 e6-e5 18. Th6-c6 f7-f6 19. Lf1-e2 Sg8-h6 20. g7-g8=D (H. Juel)
Henrik Juel: Cooked acc. to Euclide 1.01, e.g.,
1. Bc2-c4 Ba7-a6 2. Be2-e4 Be7-e6 3. Bf2-f4 Bh7-h5 4. Dd1xh5 Ke8-e7 5. Dh5-b5 Th8-h4 6. Ke1-e2 Th4-g4 7. Bh2-h4 Ba6xb5 8. Bh4-h5 Bb5-b4 9. Bh5-h6 Ke7-d6 10. Bh6-h7 Kd6-c5 11. Th1-h6 Tg4-h4 12. Bh7-h8=D Bg7-g6 13. Dh8-c3 Bb4xc3 14. Ke2-f3 Bc3-c2 15. Bf4-f5 Bc2xb1=T 16. Bf5xg6 Kc5-b4 17. Bg6-g7 Be6-e5 18. Th6-c6 Bf7-f6 19. Lf1-e2 Sg8-h6 20. Bg7-g8=D (2017-11-22)
comment
Keywords: Allumwandlung, Ceriani-Frolkin Theme (Ls), Unique Proof Game, Non-standard material
Genre: Retro
Computer test: Euclide 1.01
Reprints: 135 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-11-23 more...
52 - P0001654
Andrey Frolkin
523 Europe Echecs 373 01/1990
M. Caillaud gewidmet
P0001654
(11+6)
#1 vor 8
VRZ, Typ Proca
Alex Levit: It looks like here is the short solution in a 5 moves. So may be there is a typo in the stipulation.

Black pawns where made 4 captures on the white squares, so only the dark-squared bishop could be uncaptured by a black officer.

R. 1.Be8xRh5 Rh3-h5+ 2.g5xh6 e.p. (2.Kd4-e5? Bd2xBe3+ and forward 1.Bc3#) h7-h5 3.Rf3xBf4 Bh2xBf4+ 4.Kd4-e5 Bd2-e3+
5.Sc4-b6 and forward 1.a3# or 4...Bc1-e3+ 5.Sc4-b6 and forward 1.c3# (2018-2-10)
comment
Keywords: Defensive Retractor, Type Proca
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-8-28 more...
53 - P0001664
Leonid M. Borodatow
533 Europe Echecs 373 10/1990
P0001664
(8+9)
Wer gewinnt?
Beispielauflösung (mri)
R: 1. Sa3-b1 e3xBd2 2. Sb5-a3 f4xLe3 3. Lc5-e3 g5xSf4 4. La3-c5 h6xDg5 5. Lc1-a3 h7-h6 6. b2xTc3 Tf3-c3 7. Sg6-f4 c3-c2 8. Lb3-d1 Tf8-f3 9. Lg8-b3 Ta8-f8 10. f7xDg8=L Dd8-g8 11. Df4-g5 Kd1-e1 12. Sd6-b5 Kc2-d1 13. Sc8-d6 Kb3-c2 14. Df1-f4 Kc4-b3 15. Dd1-f1 Kd5-c4 16. f6-f7 Ke6-d5 17. Kf1-g1 d4xBc3 18. c2-c3 Kf7-e6 19. Ke1-f1 d5-d4 20. Sb6xLc8 e6xBd5 21. c4xSd5 Se3-d5 22. b3xTc4 Sf1-e3 23. f5-f6 Ke8-f7 24. f4-f5 Se3xLf1 25. f2-f4 Tf4-c4 26. Sc4-b6 Tf8-f4 27. Sa3-c4 f7xTe6 28. Sb1-a3 Tg8-f8 29. Ta6-e6 Sd5-e3 30. Ta1-a6 Sf6-d5 31. a2xSb3 Sc5-b3 32. Sf8-g6 Th8-g8 33. Se6xLf8 Sg8-f6 34. Sf4-e6 Sa6-c5 35. Sh3-f4 Sb8-a6 36. Sg1-h3
play all play one stop play next play all
AV: Les Noirs ont le trait et gagnent. Derniers coups : 1 bxT(D,C)c3 h7-h6 2 Fc1-a3 hxT(D)g5 3 Fa3-c5 gxD(T)f4 4 Fc5-e3 fxFe3 5 Cb5(c4)-a3 exPd2 6 Ca3-b1. (2005-6-28)
hans: Dont think this solution is correct (Ld1 is promoted pawn on g- or e-line) (2018-5-24)
Henrik Juel: Good to hear from you again, Hans
I think that the AV solution is OK
With German-like notation the retroplay could be
-1.Sa3 e3xPd2 -2.Sb5 f4xLe3 -3.Lc6 g5xSf4 -4.La3 h6xTg5 -5.Lc1 h7 -6.b2xTc3
The other captures by White pawns were: a2xb3xc4xd5 and, e.g., f7xe8=L
[Pf7] went something like f7xDe6xPd5xPc4-c3-c2 (2018-5-24)
Henrik Juel: ... more precisely: a2xb3xc4 and cxd (2018-5-24)
Henrik Juel: ... and -3.Lc5, not Lc6 (2018-5-24)
comment
Keywords: Retro Opposition, Whose move?, Promoted material on the board
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-5-25 more...
54 - P0001681
Michel Caillaud
Jacques Rotenberg

550 Europe Echecs 382 07-08/1991
2. ehrende Erwähnung
P0001681
(15+15) C+
KBP?
1) Weiß am Zug
2) Schwarz am Zug
1) 1. Sf3 f5 2. Se5 f4 3. Sxd7 Kf7 4. Se5+ Kf6 5. Sf3 Lg4 6. Sg1 Lxe2 7. f3 De8
2) 1. e4 f5 2. e5 Kf7 3. e6+ Kf6 4. exd7 De8 5. d8=D f4 6. Dd3 Lg4 7. D3e2 Lxe2 8. f3
play all play one stop play next play all
Jacques Rotenberg: .
a) Switchback of the knight
b) Switchback of the pawn (2017-11-28)
more ...
comment
Keywords: Unique Proof Game, Switchback (S), Promotion, Rückkehr nach Umwandlung
Genre: Retro
Computer test: Euclide 0.93
Reprints: 8 Shortest Proof Games 11/1991
(11) diagrammes 15 07-09/1994
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-11-28 more...
55 - P0001722
Thomas R. Dawson
Charles Edward Kemp

5677 The Fairy Chess Review 8 10/1943
P0001722
(8+12)
h=Retropatt in 3
R: 1. Kf7xSe7 Sc8-e7 2. Kg8xTf7 Tc7-f7! 3. 0-0 Td7-c7 Retropatt
play all play one stop play next play all
Henrik Juel: Stipulation should be 'help-retrostalemate in 3'. -0... Kf7xSe7 -1.Sc8 Kg8xTf7 -2.Tc7! 0-0 -3.Td7 and Black is retrostalemate. Not a defensive retractor, but a help retractor with a weird aim. (2004-3-18)
Sally: Zurück:
1. Kd7xSe7? - Sg8-e7,
2. Kc8xTd7? - Tg7-d7,
3. O O O??? - Tfg7!
In der Verführung wäre die Rücknahme der langen Rochade illegal, da der w. Bauer a2 als Schlagobjekt im Osten gebraucht wurde und sich auf "a8" umwandelte. Somit musste der
schwarze Turm auf "a8" bereits gezogen haben! (2018-6-5)
comment
Keywords: Help retractor, Symmetrical position, Asymmetrical solution, Castling
Genre: Retro
Reprints: 336 FIDE Album 1914-1944/III 1975
H28 ASymmetrie 2013
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-5 more...
56 - P0001736
Harold Holgate Cross
2455 The Fairy Chess Review 10/1936
P0001736
(13+15)
Wer gewinnt?
1. ... Lg2#?
1. Sc3+! b1=D,T,L,S 2. Txb1#
play all play one stop play next play all
Brassaud: 0) …, Lh3 1) Tc1, Sg6 2) Td1, Sf4 3) Tc1, Sd3 4) Td1, Sc1 5) Sc3, Lf1 6) Sd5, Lh3 7) Sf4, Lf1 8) Sg6, Lh3 9) Sh8, Lf1 10) h7=S, Lh3 11) h6, Lf1 12) h5, Lh3 13) h4, Lf1 14) h3!, h4xDg3 15) Dd6, h5 16) g2, g3xSf2 17) Se4, Tf2 … retract black bishop on c8 and b6b7. Retract wK via g3 … (with 14) h2 ? the black king can’t escape from the south-west cage) (2018-1-31)
Henrik Juel: The problem appeared as no.2455, p.17, FCR Oct. 1936
The solution on p.25, FCR Feb. 1937 has this comment by TR Dawson
'.. an excellent double opposition, Sh4 and Bf1 v. Rcd1, followed by white S from b1 v. Bf1,h3'
(B,R are L,T in German) (2018-1-31)
comment
Keywords: Whose move?, Retro Opposition
Genre: Retro
Reprints: 221 FIDE Album 1914-1944/III 1975
(40) Die Schwalbe 72 12/1981
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-2-1 more...
57 - P0001737
Harold Holgate Cross
The Fairy Chess Review 1939
T.R. Dawson gewidmet
P0001737
(14+14)
Darf Schwarz ep schlagen?
R: 1. d2-d4 d5xSe4 ­2. Sg5-e4 Tg2-g1 ­3. Sf3-g5 Tg1-f1 ­4. Tf1-e1 d6-d5 ­5. Se1-f3 h7-h6 ­6. Lc2-d1 Kd1-c1 ­7. L~c2+.
R: 1. d3-d4? fails to Retro­ Opposition. So Black can capture e.p.
play all play one stop play next play all
Henrik Juel: At first sight the further resolution seems difficult, but this would seem to work:
Retract Pc3 to c2, Tb3 to f3, and Pb4 to b3, while the black king spends time on c1 and d1
The everything (but the kitchen sink, Se1) can be extracted via the a-file (2017-9-16)
comment
Keywords: En passant, Retro Opposition
Genre: Retro
Reprints: 223 FIDE Album 1914-1944/III 1975
(39) Die Schwalbe 72 12/1981
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-9-16 more...
58 - P0001739
Karl Fabel
9561 The Fairy Chess Review 06/1953
P0001739
(14+14)
Welches waren die letzten Züge?
R: 1. Tf1-h1 f6xSe5 2. Sf3-e5 Kh1-g2 3. Sg1-f3 Kg2-h1 4. Lc3-b2 Kh1-g2 5. Tb2-b1 Kg2-h1 6. Ta2-b2 Kh1-g2 7. Ta3-a2 Kg2-h1 8. Tb1-c1 Kh1-g2 9. Tb2-b1 Kg2-h1 10. Ta2-b2 Kh1-g2 11. Tb1-d1 Kg2-h1 12. Kd1-e1 Kh1-g2 13. Kc1-d1 Kg2-h1 14. Td1-f1 Kh1-g2 15. Kb2-c1 Kg2-h1 16. Tc1-b1 Kh1-g2 17. Kb1-b2 Kg2-h1 18. Tb2-a2 Kh1-g2 19. Ka2-b1 Kg2-h1 20. Tb1-b2 Kh1-g2 21. Kb2-a2 Kg2-h1 22. Ta2-a3 Kh1-g2 23. Ka3-b2 Kg2-h1 24. Kb4-a3 Kh1-g2 25. Ta3-a2 Kg2-h1 26. Tb2-b1 Kh1-g2 27. Ta2-b2 Kg2-h1 28. Tb1-c1 Kh1-g2 29. Tb2-b1 Kg2-h1 30. Sf3-g1 d5-d4 31. Th1-d1 Kf1-g2 32. Sg1-f3 Ke1-f1 33. Le5-c3 Kd1-e1 34. Kc3-b4 Kc1-d1 35. Kd3-c3 Kd1-c1 36. Ke3-d3 Kc1-d1 37. Kf3-e3 Kd1-c1 38. Kg2-f3 Kc1-d1 39. Kf1-g2 Kd1-c1 40. Sf3-g1 Kc1-d1 41. Tg1-h1 Kd1-c1 42. Tg8-g1 Kc1-d1 43. Kg2-f1 Kd1-c1 44. Kg3-g2 Ke1-d1 45. Sh4-f3 Kf1-e1 46. Kg4-g3 Kg2-f1 47. Sf3-h4 Kh1-g2 48. Th8-g8 Kg2-h1 49. Tb1-b2 d6-d5 50. Th1-b1 Kf1-g2 51. Sg1-f3 Ke1-f1 52. Kg3-g4 Kd1-e1 53. Kg2-g3 Kc1-d1 54. Kf1-g2 Kd1-c1 55. Sf3-g1 Kc1-d1 56. Tg1-h1 Kd1-c1 57. Tg8-g1 Kc1-d1 58. Kg2-f1 Kd1-c1 59. Kg3-g2 Ke1-d1 60. Sh4-f3 Kf1-e1 61. Kg4-g3 Kg2-f1 62. Sf3-h4 Kh1-g2 63. Tb2-a2 Kg2-h1 64. Tb1-b2 d7-d6 65. Th1-b1 Kf1-g2 66. Sg1-f3 Ke1-f1 67. Kg3-g4 Kd1-e1 68. Kg2-g3 Kc1-d1 69. Kf1-g2 Kd1-c1 70. Sf3-g1 Kc1-d1 71. Tg1-h1 Kd1-c1 72. Tg7-g1 Kc1-d1 73. Kg2-f1 Kd1-c1 74. Kg3-g2 Ke1-d1 75. Sh4-f3 Kf1-e1 76. Kg4-g3 Kg2-f1 77. Sf3-h4 Kh1-g2 78. Ta2-a3 Kg2-h1 79. Tb2-a2 Kh1-g2 80. Lf4-e5 Kg2-h1 81. Tb1-b2 f7-f6 82. Th1-b1 Kf1-g2 83. Sg1-f3 Ke1-f1 84. Kh4-g4 Kd1-e1 85. Tg3-g7 Kc1-d1 86. g7-g8=T Kb2-c1 87. g6-g7 Ka3-b2 88. Le5-f4 Kb4-a3 89. Lb2-e5 Kc5-b4 90. Lc1-b2 Kd6-c5 91. b2-b3
play all play one stop play next play all
weiter: Bg2xLh3, sLh3 nach c8, wT entwandelt auf a8, sBa6/7xS, wBhxsBg
hans: R: -1. Rf1-h1 f6xSe5 -2. Sf3-e5 Kh1-g2 -3. Sg1-f3+ Kg2-h1 -4. Bc3-b2 K -5.Rb2-b1 K -6. Ra2-b2 K -7. Ra3-a2 K -8.Rb1-c1 K -9. Rb2-b1 K -10. Ra2-b2 K -11. Rc1-d1 K -12. Rb1-c1 K -13. Kd1-e1 K -14. Kc1-d1 K -15. Kb2-c1 K -16. Re1-b1 K -17.Kb1-b2 K -18. Rb2-a2 K -19. Ka2-b1 K -20. Rb1-b2 K -21. Kb2-a2 K -22. Ra2-a3 K -23. Ka3-b2 K -24. Rb2-b1 K -25. Rb1-e1 K -26. Kb4-a3 K -27. Ra3-a2 K -28. Ra2-b2 K -29. Rb2-b1 Kg2-h1 -30. Sf3-g1 d5-d4 -31. Rh1-f1 Kf1-g2 -32. Sg1-f3+ Kg2-f1 -33. Bd4-c3 Kf1-g2 -34. Kc3-b4 Kg2-f1 -35. Kd3-c3 Kf1-g2 -36. Ke3-d3 Ke2-f1 -37. Kf3-e3 Kd1-e1 -38. Kg2-f3 Kc1-d1 -39. Kf1-g2 Kd1-c1 -40. Sf3-g1 Kc1-d1 -41. Se5-f3 Kd1-c1 -42. Rg1-h1 Kc1-d1 -43. Rg8-g1 etc.
Kd1-c1 -44. Rh8-g8 -45. Kg3-g2 Kc1-d1 -46. Kg2-gf1 Kd1-c1 -47. Kf3-g2 Ke1-d1 -48. Kf4-f3 Kf1-e1 -49. Sf3-e5 Kg2-f1 -50. Rb1-b2 d6-d5 -51. Rh1-d1 Kf1-g2 -52. Sg1-f3+ Ke1-f1 -53. Kf3-f4 Kd1-e1 -54. Kg2-f3 Kc1-d1 -55. Kf1-g2 Kd1-c1 -56. Sf3-g1 Kc1-d1 -57. Rg1-h1 Kd1-c1 -58. Rg7-g1 ------------ -95. ... Kb4-a3 -96. Bb2-e5 Kc5-b4 -97. Bc1-b2 Kd6-c5 -98. b2-b3 etc.
(wK and wS manoeuvre to let wRooks pass the bK, with the necessary bPawn tempo-moves) (2011-12-8)
Brassaud: A theme widely explored by Karl Fabel, confer problems P0001383 (1972) and P0001419 (1975) (2018-2-1)
comment
Keywords: Last Moves?, Castling (wk), Promotion (TT), Promoted material on the board, under-promotion
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-2-2 more...
59 - P0001759
Nikita M. Plaksin
The Problemist 1980
4. ehrende Erwähnung
P0001759
(8+6)
Welches war der letzter Zug?
Monochromes Schach
Brassaud: Last moves :
1) Kd5c4, e5xDf6 2) Df4f6 b3xTa4 3) Dg3 (e3) f4 a2xDb3 4) DxTg3(Tf3) …
Proof game :
1) c4, e5 2) Dc2, a5 3) Dxh7, Ta6 4) DxSg8, Tg6 5) Dh7, Le7 6) Dh3, f5 7) Dxf5, Lh4 8) De4, Lg3 9) h2xLg3, Tg4 10) Th5, De7 11) Tf5, Db4 12) Dc6, Dc3 13) Da4, DxLc1+ 14) Dd1, Dc3 15) Tf3, De3 16) Dc2, Dh6 17) Td3, Dh2 18) Dd1, DxSg1 19) Dc2, Dh2 20) Dd1, b5 21) Dc2, b5xc4 22) Dd1, c4xTd3 23) Dc2, Ta4 24) Dc4, d5 25) Dxd5, c5 26) Dc4, Th4 27) Dc2, Tf4 28) Dd1, g5 29) Dc2, d3xDc2 30) g3xTf4, c2xSb1=D 31) f4xe5, Df5 32) Tc1, Dh4 33) Tc3, Dh3 34) Ta3, Dh1 35) Tc3, DxLf1 36) Ta3, Dh1 37) Tc3, Dh3 38) Tc1, Db3 39) Tc3, Kd7 40) Tc1, Kc6 41) Tc3, Kd5 42) Tc1, Lf5 43) Tc3, Lg6 44) Tg3, DxTg3 45) a2xDb3, Df4 46) b3xTa4, Df6 47) e5xDf6, Kc4 (2018-2-3)
comment
Keywords: Last Move?, Monochrome
Genre: Retro
Reprints: RA158 diagrammes 73 09-10/1985
984 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2003-12-20 more...
60 - P0001848
Thomas R. Dawson
The Chess Amateur 1918
P0001848
(12+10)
Ergänze einen wT, dann #1
+wTb1? +wTc3!: 1. b3#
play all play one stop play next play all
Sally: Die w. Bauern haben 6 mal geschlagen, und zwar auch Bb7 nach Umwandlung Bb7 hat auf a2 einen w. Turm geschlagen.
Nr. 3 : Schach ohne Grenzen (Fabel & Kemp 1969). (2012-2-21)
Henrik Juel: Here is a detailed solution
White pawns captured all six missing black men by c2xd3x..xh7 (on light squares) and h2xLg3
Black captured [Lf1] at home and the remaining two missing white men by b3xa2 (to promote to D or S on a1) and g7xf6
The forward sequence was gxf6 before hxg3 before [Th1] could exit; but it could not reach a2, so [Th1] is still on the board (and the black pawns captured g7xSf6 and [Ta1] on a2 )
The only possible #1 is with [Th1] added on c3, as it could not reach b1 (2018-1-6)
Mario Richter: Henrik's analysis shows that it would suffice to stipulate: "Add a Piece, then #1". I would prefer this version since it gives the solver the chance to detect some more RA issues by himself (e.g. that the Piece to add can only be a White rook). (2018-1-16)
comment
Keywords: Promotion, Add pieces
Genre: Retro
Reprints: 107 Caissa's Wild Roses in Clusters 1937
3 Chess unlimited , p. 37, 1969
35 Die Schwalbe 71, p. 326, 10/1981
1 feenschach 143, p. 225, 08-10/2001
(F) The Problemist 07/2010
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-1-16 more...
61 - P0001863
Nikita M. Plaksin
Rex Multiplex 1985
3. Preis
P0001863
(13+12)
#1
hans: 1. e6-e7# (not 1. … Dxh5#)
R: -1. … Sd5-b6 -2. d7-d8=L Se3-d5 -3. c6xLd7 Sg4-e3 -4. c5-c6 Sh6-g4 -5. b4xLc5 Lg1-c5 -6. a3xLb4 g2-g1=L -7. a2-a3 g3-g2 -8. c3-c4 g4-g3 -9. c2-c3 g5-g4 -10. g4xSh5 De1-e2 -11. g2-g4 Sg3-h5 -12. Kh5-g6 Se2-g3+ -13. Kg6-h5 Ke7-f8 -14. Kh5-g6 Kd6-e7 -15. Tg6-g7 Tg7-h7 -16. Lh7-g8 and cage is open.
captures black: exf, fxe [Lc1] (2012-9-14)
Brassaud: Agree with Hans untill 12) .. Se2g3+ and then 13) Tg6f6, Tf6f5 and cage is open. (2018-3-2)
comment
Keywords: Promotion, Whose move?
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: hpr, 2001-3-18 more...
62 - P0001899
Fritiof Lindgren
Eskilstuna-Kuriren 1937
P0001899
(4+8)
#1 vor 5
VRZ, Typ Hoeg
R: 1. Kg8xTh8 Th3-h8+ 2. Kf8xDg8 Dh7-g8+ 3. Ke8xTf8 Tf3-f8+ 4. Kd8xDe8 Df7-e8+ 5. b6xSc7, dann 1. b7#
play all play one stop play next play all
Henrik Juel: The problem seems cooked as stated, so the type probably should be Høeg, where the opponent chooses which man (if any) to supplement on the abandoned square:
-1.Kg8:R Rh3 -2.Kf8:Q Qh7
-3.Ke8:R Rf1 -4.Kd8:Q Qf7
-5.b6:S (supplementing Q, R or B is now illegal), 1.b7#
If Black doesn't keep supplementing a checking man, he is mated at once with 1.c8=QR#. -2.Kf7?:B! (2003-2-24)
paul: Probably, this problem is by Fritiof LINDGREN (1997-1957), because Bo Lindgren was born in 1927. (2018-2-3)
paul: Of course, Fritiof was born in 1897, not 1997. (2018-2-3)
comment
Keywords: Defensive Retractor, Type Høeg
Genre: Retro
Reprints: 335 FIDE Album 1914-1944/III 1975
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-27 more...
63 - P0001901
Thomas R. Dawson
The Pittsburgh Gazette Times 1915
P0001901
(9+12)
Ergänze eine wD, dann #1
+wDe8: 1. Sc3#
R: 1. Ka3-a2 e7-e8=D
play all play one stop play next play all
Henrik Juel: Analysis
White pawns captured all four missing black men by axb, bxa, and cxbxa, and he promoted [Ph2] on h8 (and possibly [Pe2] on e8)
Black pawns captured all five (after addition) missing white men by e7xf6 and h7xPg6x...xc2
-1... Ka1 -2.Tb2 Kb1 -3.Ta2 Ka1 -4.Tb2 Ka2 -5.Tb1 leads nowhere, so -5... Ka3 D=Pe7 must happen sooner or later (2018-2-23)
Henrik Juel: all six, not five, of course (2018-2-23)
comment
Keywords: Add pieces, Promotion, Promotion in the retro play
Genre: Retro
Reprints: Arnhemsche Courant 24/12/1926
103 Caissa's Wild Roses in Clusters 1937
344 FIDE Album 1914-1944/III 1975
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-2-23 more...
64 - P0001917
Camil Seneca
L'Echiquier de Paris 1950
Lob
Mémorial Lazard
P0001917
(12+2)
#2
b) -sBf5
a) 1. Sc3! (Zugzwang) Kxb3 2. La4#
1. ... Kxd3 2. 0-0-0#
b) 1. Le8! (Zugzwang) Kxb3 2. Sd4#
1. ... Kxd3 2. Lg6#
play all play one stop play next play all
In a) last black move could be f-pawn. (castling possible)
In b) last black move is Kb1-c2 after Ta2-a1+ (no castling)
Mémorial Lazard
more ...
comment
Keywords: Cant Castler, Castling (wg)
Genre: Retro
Reprints: RA6 diagrammes 12/1974
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-9-12 more...
65 - P0001970
Thomas R. Dawson
26 Kongreßbuch Teplitz-Schönau 1923
P0001970
(13+13)
h#1
1. exf3ep Lc2#
play all play one stop play next play all
1.exf3e.p. Bc2# is the only possible solution, but this necessitates R: 1.f2-f4. Can we prove this?

(13+13) with 1+2 pawn captures. Bf8 captured at home, so to satisfy White appetite, the missing Black pawn (a or b) must have promoted via c2 on c1. Two more White units must be captured to allow this.

The kings cage can only be unlocked by retracting WPc2. But the clock is ticking as there are only 6 black moves which can be retracted.

The promoted piece was captured on e3 or h3. If either capture is undone, then a White bishop square is cut off, so WB must be replaced prior to this.

Now the order of the early moves is: WdP moves, WQB & WQR escape, BP promotes on c1 to X (capturing WR at some point), X captured by WP.

So the first White capture must be dxNe3 and the second White capture releases gxXh3. The second White capture releases WKB & WKR. WKR captured by original BfP.

The clock starts ticking with gxh3. Black has 6 pawn moves. WKB has 3 moves to reach h7. WR has 3 if it goes via d file, or 2 if it starts on g1 (in which case WfP or WQB must also move once). So certainly at least 6 White moves. Last move was therefore White (even if the stipulation didn't tell us), and it can only have been WfP coming from f3 or f4. If it had been coming from f3 it would have blocked WKB in its progress, so the last White move was indeed R: 1.f2-f4.

WKR did therefore move from g1-g4-e4, and R: 1. ... fxRe5 2. Rg4-e4. Prior to that, move order not unique, but counting still exact.

Note that WN loitering on b4, pretending to be part of the cage, is present on the board just to make up the numbers.
Jeliss: "Obstruction of passage square f3 to Bishop of same colour."

"Version 'Pittsburgh Leader' 08.06.1913"
Henrik Juel: -1.f2 f5xTe4 -2.Tg4 f6 -3.Tg1 f7 -4.Le4 h5 -5.Lg2 h6 -6.Lf1 h7 -7.g2xDTSh3, unpromote DTS on c1, etc. (2004-3-18)
Henrik Juel: Nice analysis, Andrew, but your last comment seems incorrect.
Without Sb4, 1.b4 Txb4+ is not mate because of 2.Txb4#! (2013-7-26)
A.Buchanan: Thanks Henrik, I have fixed the solution. Forward chess is even harder than retro chess. And because Rb7 is retro-pinned, I overlooked that it's not forward-pinned! (2013-7-27)
Yoav Ben-Zvi: Appears as the first problem (D445) in the booklet on Dawson's RA problems by G.P. Jellis. The obstruction that occurs in the Try -1.Pf3-f4?, by WP of WB, is described as "obstruction of passage square". It is not considered by Dawson and his disciples to be a Retro opposition. Dawson's conception of RO was quite broad, it included cases where the interference was not by occupation of the target square, so the only valid reason that I can see to exclude this case is that the 2 pieces involved are both of the same color. Fabel's definition explicitly excludes "Monochrome RO". I conclude that it would be preferrable to interpret RO as a bi-chromatic interference. The keyword Retro opposition should be removed. (2018-4-7)
comment
Keywords: Last Moves?, En passant as key
Genre: h#, Retro
Reprints: D445 Retro-Opposition [Jelliss] 1989
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-4-9 more...
66 - P0001974
Thomas R. Dawson
Eskilstuna-Kuriren 1917
P0001974
(11+15)
#3
Henrik Juel: 1.Tb5 Txg6+ 2.Lxg6. -1... d5 -2.Lf4 Tf8 -3.Dg3 Dh3 -4.Dh2 Sg3 -5.Dh1 Lh2 etc. (2004-3-18)
Erich Bartel: Nachdrucke:
1) Retro Opposition, 1989.---
2) Problemkiste (66) XII 1989.--- (2007-4-15)
Yoav Ben-Zvi: Might be the earliest publication of a sound problem showing Retro-Opposition (on g3 after -1...BPd5-d4 -2.Bf4-g3) It may also be the first instance of "Sliding Block" (Verschiebepuzzle) without conditions. Appears as D918 in Dawson's booklet on Retro-Opposition. (2017-12-5)
comment
Keywords: Cant Castler, Castling (sk)
Genre: Retro
Reprints: Problemkiste (66) 12/1989
Input: Gerd Wilts, 1995-6-3
Last update: Erich Bartel, 2013-7-27 more...
67 - P0001978
Thomas R. Dawson
Eskilstuna-Kuriren 1918
P0001978
(11+13)
Ergänze einen schwarzen Springer in einer Ecke, so daß Weiß in einem Zug mattsetzen kann!
Henrik Juel: Add sSh8. 1.Sxh3#. -1... Sg6 -2.Lc2 Sf4 -3.Ld1 Se2 -4.Lc2 Sc1 -5.Ka1 Sa2 -6.Lb1 Dc1 etc. (2004-3-18)
Yoav Ben-Zvi: Not +BNa8?: Black is to move due to Parity Argument.
Not +BNa1?: Illegal position due to Retro-Opposition between BN and WB on c2.
An alternative stipulation: "If the position is legal: #1 (who?)" with a)BN on a1 (illegal), b)BNa1 to b2 (1.WNg1xh3#! not 1...BQa3-a2#?), c)BNa1 to c2 (illegal).
Appears as D1089 in Dawson's "Seventy Five Retros", 1928. (2017-12-21)
Henrik Juel: I just discovered that an edited version of Dawson's 1928 manuscript can be found at
www.theproblemist.org/trd-retop.html (2017-12-21)
Henrik Juel: Just for the record:
This problem did not appear in Dawson's 1928 manuscript, but was added by the editor G. P. Jelliss
In the edited version the manuscript retros are marked by ¤

On the RO discussion:
Now we have not only Dawson's notion of RO, but also Jelliss's interpretation of Dawson's notion... (2017-12-21)
comment
Keywords: Retro Opposition, Add pieces
Genre: Retro
Input: Gerd Wilts, 1995-6-3
68 - P0001979
Thomas R. Dawson
Svenska Dagbladet 1923
P0001979
(11+14)
#2
1. gxh6 ... 2. g8=D,T#
play all play one stop play next play all
"Blundering Horsemen"
Henrik Juel: 1.gxh6 (2.g8DT#). Black could castle, only if he had the move: -1.Sc2 Sf7 ... -9.Sg8 Sf7 -10.Sh6 Sd8 -11.Sf7 d4 -12.Sh8 Sf7 -13.S=h7 etc. (2004-3-18)
Henrik Juel: The stipulation implies that White has the move, so Black starts the retroplay
Assume (for contradiction) that Black may castle; then Ta8 and Ke8 may not retract, and Black is left to retract Sh6 (because e4-e3 is needed at the end of the retroplay), which must pendle on f7, d8, h8, h6, reaching f7 every other retraction
The only way to release the position is to unpromote Sa1 on h8; one route is a1-c2-e3-d1 and then c3-a4-b6-c8-e7-g8-h6-f7-h8
The retroplay goes -0... Sf7 -1.Sc2 Sh6 .. -9.Sg8 Sd8 -10.Sh6 and now we are stuck: -10... e4 is premature (-11.Sf7 occupies the square Black wants to go to), and -10... Sf7 occupies the square White wants to retract to
We conclude that Black may not castle, allowing 1.gxh6 thr. 2.g8=DT#
In a 1928 manuscript Dawson called the theme Retro Opposition, and this has been the accepted terminology ever since; for this situation I prefer the more descriptive term Retro Collision, as the white and black knights collide on f7 (2017-12-20)
Henrik Juel: corrections: not e4-e3, but d4-d3, and later -10... d4 (2017-12-20)
Yoav Ben-Zvi: Dawson did not attempt a definition of "Retrograde Opposition" in the 1928 manuscript. His conception of the theme was broad as seen by examples such as P0001982 (D1141 in the manuscript). Fabel narrowed things down to a contest over occupation of a square between opposite-colored pieces which Henrik prefers to call "Retro-Collision". The Themes Index of the FIDE Albums defines Retro Opposition as "In a particular phase of the retro-play it can be proved which side is to play, despite there being mobile pieces on both sides." ignoring entirely the characteristic contested square. According to this definition the problem asking "Whose move?" for a position identical to the initial array would qualify although it is an elementary example of "Parity Argument" rather than RO. (2017-12-21)
Henrik Juel: What a mess!
According to Yoav we have three notions of RO, so whenever we use these words we really should add: according to Fabel, Dawson, or FIDE Albums
In the PDB Gerd entered lots of RO problems, but he (wisely?) neglected to define RO (2017-12-21)
comment
Keywords: Cant Castler, Retro Opposition, Castling (sg)
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-21 more...
69 - P0001995
Thomas R. Dawson
Birmingham Post 14/07/1911
P0001995
(6+7)
#2
1. Sd4
1. ... bxa6 2. Db1#
1. ... b6 2. Sc6#
1. ... d5 2. Dg3#
1. ... fxg6 2. Tf8#
1. ... gxf6 2. Dg8#
play all play one stop play next play all
Schwarz hat keinen letzten Zug!
Sally: (Verwackelt)
1. Sb5-d4?
mit 5 Varianten, entsprechend den s. Bauernzügen :
Db1, Sc6, Dg3, Tf8, Dg8#. Aber :
Der w. König kann unmöglich die s. Bauernkette durchgebrochen haben, um nach d7 zu gelangen! Auch bei den 2 Zurücknahmen
c7, d6, oder e7, d6 bleibt diese Frage offen im Sinne der retrograden Analyse. Die Stellung des w. Königs ist partieunmöglich - das Problem ist verwackelt! (2017-8-9)
Henrik Juel: The problem is not of the 'Whose move?' type, and the specification 'Weiss am Zug' does not appear in 'Retrograde Analysis'
In 'RA' the problem is unclearly lumped together with two problems that have legal positions, but are incorrect as Black has no possible last move
This problem has an illegal position (because wK could not reach d7), so it is meaningless to ask for last move
I suggest that the Keyword 'Whose move?' is replaced by 'Joke' (2017-8-9)
Yoav Ben-Zvi: It seems to me this is a legitimate "Whose move?" problem since WK on d7 is illegal only if it is White to move. However after 0...BPb7xa6 White plays either 1.Nxd6 or 1.Q-b1 so the #2 is cooked. Correction: Move WNb5 to b3 and WPc3 to c4, add WPa5, WPc5, BPc6. (2017-8-22)
Thomas Volet: Surely Dawson knew that for the position to be legal it must Black's move in the diagram. Perhaps the joke is that the forward play is to continue with Black moving, particularly as it seems that White will be able to mate no later than it's second move no matter what Black does. I like the variation 1…. PxP, 2.Q-b1, but it has been a long time since this writer moved chess pieces in forward time, so no assurances. (2017-8-23)
Henrik Juel: My above comment is not well formulated...
In 'Retrograde Analysis' the problem appears in the chapter on illegal positions with the comment 'The present group is illegal, because it is White's turn to move, and Black could not have played last.'
It has the stipulation Mate in two, and the solution is stated as 1.Sd4; there is no indication that TRD was interested in 'Whose move?' or in the forward play after a first move by Black (2017-8-23)
A.Buchanan: In January 1911, Hjorth's accidental P0001996 had appeared, but July of that year was I think too early for the Article 15 theme to be established. Although Dawson here has accidentally created a very pretty position of Black pawns and White King, there is no indication that he is profiting from it by having new or interesting play after Black plays a zeroth move. In particular 0... b6 has many responses, which are also not defeated by Yoav's version.

I tried to find this newspaper in an archive, but 1911 seems not be stored.

@Henrik: what is the book 'Retrograde Analysis'? (2017-8-26)
Henrik Juel: Alain C. White published a book on chess problems each year for many years, and sent it to his friends for Christmas.
In 1915 the book was 'Retrograde Analysis' by Dawson and Hundsdorfer. It contains almost 300 problems, many by the authors, and includes many originals, like the Høeg classic with three e.p. captures. The Hjorth problem appeared as No. 2, on which the authors write:
'We remember our surprise at finding No. 2 reproduced by a careful editor with an added White Pawn at a2 and a Black Pawn at a3. Their remoteness from the field of action drew attention quaintly to the grave illegality they were intended to correct.' (2017-8-26)
A.Buchanan: OK I see. I will add this as a reprint. If Dawson himself said the problem simply had an illegal position, then that ends the discussion. Does anyone have a copy of L.N.de Jong's earlier "Onmogelijke Standen" in "Op de Hoogte" referred to on page 9? (2017-8-27)
Mario Richter: The date given for the de Jong article in the Dawson/Hundsdorfer book is wrong, correct is 09/1911.
The "Onmogelijke Standen" articles can befound at http://resolver.kb.nl/resolve?urn=dts:399009:mpeg21:0085 and http://resolver.kb.nl/resolve?urn=dts:399012:mpeg21:0074

The oldest problem I could find so far, which uses the "no legal last black move" Argument intentionally, is P1338137. (2017-8-27)
A.Buchanan: @Mario: thanks very much for the links. Page 41 of D&H also mentions a revolutionary pamphlet "On the Nature of Chess Problems" by A.Gehlert in 1903. I am curious about this, and I wonder if there is a copy of that extant? (2017-8-27)
Yoav Ben-Zvi: P0002016 is a #1 example from 1870. This contains a unique solution for every 'zero' move by Black, obviously an advantage although in case there is one Black move that leads to a unique solution then multiple solutions in other 'variations' can be tolerated as duals. This problem lacks a 'Try' that is refuted because it is Black's move. For a #2 that includes a 'Try' see P1012013 (noted by Andrew in comment to P0001996). (2017-8-27)
comment
Keywords: Illegal position
Genre: Retro
Reprints: 1770 Wiener Hausfrauen-Zeitung 51, p. 615, 15/12/1912
1B Retrograde Analysis , p. 7, 1915
479 Hamburger Problem-Nachrichten 09-10/1949
Im Wunderland des Schachproblems , p. 36, 1958
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-8-27 more...
70 - P0001996
H. H. Hjorth
707 Skakbladet 01/1911
P0001996
(3+2)
#3
1. f8=S? g6 2. Kh6 g5 3. Sg6# but Black has no last move!
0. ... g6 1. Kh6! g5 2. f8=D/T# short solution
0. ... Kxh7 1. f8=D! g6 2. Kf6 g5 3. Dg7#
play all play one stop play next play all
Henrik Juel: Orig. stipulation was just '#3'. 0... Kxh7 1.f8D g6 2.Kf6 g5 3.Dg7#, not 1.f8S? g6 2.Kh6 g5 3.Sg6, because Black has the move. (2004-3-8)
A.Buchanan: I think the original stipulation worked fine, with the convention that Black must play a defensive zeroth move. (2013-7-20)
Frank Müller: Die Autorabsicht ist 1. f8=S.
Im Maiheft 1911 (Seite 128) weist H. Hannemann auf die Illegalität hin und gibt an, dass die Autorabsicht durch wBa2/sBa3 gerettet werden kann.
Also kein Retro, sondern ein normaler Dreizüger. (2013-9-6)
A.Buchanan: @Frank: I didn't know this. Werner Keym in his book "Eigenartige Schachprobleme" treats this as an early (the earliest?) deliberate example of "Der 'falsche' Anzug". The fact that one of the two Black defences leads to a short mate suggests that it was accidental. But maybe this was how this theme (now enshrined in Article 15 of the Codex) was stumbled across. Knut Hannemann (not Harald, his father) provided a real example in 1929 (P1012013) but the most amazing early example for me was Axel Akerblom 1925 (P0005625). (2017-8-26)
comment
Keywords: No legal last move for Black
Genre: Retro, 3#
Reprints: 2 Retrograde Analysis 1915
(IV) Problem 37-40 09/1956
1428 Problemskak 30, p. 19, 04-06/2015
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-8-26 more...
71 - P0002016
William A. Shinkman
1 Dubuque Chess Journal , p. 105, 15/11/1870
P0002016
(6+4)
#1
1. ... Kxd5 Dc5#
1. ... Kxf5 Dg5#
1. ... f6 Dxe6#
play all play one stop play next play all
Schwarz hat keinen letzten Zug.

Lösung in Heft 12, Februar 1871, S. 33:
"It will be seen that it must have been White's last move, if now Black move P-B3 or if K takes S Q mates."
'The Chess Journal' listet dann noch einige alternative Lösungsideen der Leser auf:
"To this Carpenter adds turn the board and Q takes B mates. Courtenay says -- Remove the KB from the Board. Davis thinks the Springers fell off and should have been placed on d6 and f6, whence a stalemate is easily effected."
Publiziert als "Chess Puzzle No. 1"
Originalforderung: "Suppose we find such a position at the end of a game; White's next move will effect a mate. How is it done?"
A.Buchanan: I would replace sL with sB, and have wK on d7 instead of wL, but what do I know compared to the "Wizard of Grand Rapids"? :-) (2017-8-28)
Henrik Juel: Maybe the Wizard wanted a cross-like position rather than a T-like one
C+ by Popeye 4.61 (2017-8-28)
Henrik Juel: ... or possibly the author wanted a pictorial warning that the unwary solver was about to be double-crossed (2017-8-28)
more ...
comment
Keywords: No legal last move for Black
Genre: Retro
Reprints: 12 Retrograde Analysis 1915
(I) Problem 79-82 01/1962
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2017-8-28 more...
72 - P0002092
Karl Portius
35 Leipziger Illustrirte Zeitung 24/08/1844
P0002092
(5+6)
#2
1. gxf6ep+ Ke8 2. Sd6#
Der En passant-Schlag kann nicht begründet werden.
play all play one stop play next play all
Erschien mit folgendem Begelttext:
In einem Club spielten zwei mittelmäßige Spieler mit einander, als derjenige, der die Weißen hatte, ausrief: "Wenn Sie so ziehen, werden Sie gleich Matt." Bei diesen Worten trat der Präsident des Clubs, ein berühmter Meister, an das Schachbrett und erklärte: Weiß könne unmöglich Matt geben. Weiß ließ sich aber nicht stören, zog und setzte mit dem zweiten Zuge Matt; und der Herr Präsident konnte weiter nichts sagen als "Ah, so!"
from Dawson & Hunsdorfer, 1915:
"The actual origin of the en passant analytic is not certain. Way back in 1944, a year before the publication of the Indian problem, old Portius, the genial editor of the Leipzig Illustrated, published No. 53A [this problem] in connection with one of his chess tales. It is simply a trick problem, quite free of any thought of analysis, but we quote it for its historical significant. It set solvers' brains in action, and suggested the possibility of an analytic en passant key. [...] No. 53 [P0001360, 1858] fourteen years after No. 53A, is analytically sound, but unfortunately unidentified." [Author now known to be Max Lange.]
So this is a joke rather than cooked.
Henrik Juel: From the story we know that White can mate in two
this is possible only if last move was f7-f5
then C+ by Popeye 4.61 (2017-9-9)
comment
Keywords: En passant, Joke (en passant)
Genre: Retro
Reprints: 53A Retrograde Analysis 1915
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2017-9-9 more...
73 - P0002098
Max Lange
Handbuch der Schachaufgaben [Lange] 1862
P0002098
(6+9)
#1
1. axb6ep#
play all play one stop play next play all
Eine sehr frühe (erste?) Darstellung des retroanalytisch begründeten en passant Schlages. (\eb)
ML schreibt dazu: "In dieser Position läßt sich die Voraussetzung des exceptionellen Zuges begründen...".
TBr: Nein, nicht erste Darstellung, siehe P0001360 (ebenfalls von Max Lange), das wohl das erste korrekte Retro überhaupt zu sein scheint. (2015-9-6)
Yoav Ben-Zvi: WBe2, WPd5 and BPg7 can be removed. (2018-3-1)
A.Buchanan: I think wPd5 is needed so that bK can’t unmove with check from b7 (2018-3-1)
more ...
comment
Keywords: En passant, En passant as key
Genre: Retro
Reprints: 57A Retrograde Analysis 1915
K588 Problemkiste (110) 04/1997
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2015-9-10 more...
74 - P0002107
Rudolf Behal
Neues Illustrirtes Blatt 1897
P0002107
(12+3) C+
#3
1. exd6ep Kxg3 2. Dg1+ Kh4 3. Sf3#
1. ... Kxg4 2. De5 Kh4 3. Df4#
1. ... Kxg5 2. Dg7+ Kh4 3. Sf5#
play all play one stop play next play all
für eine ökonomisierte Version s. P1012712
more ...
comment
Keywords: En passant as key, Model mate (3x)
Genre: Retro, 3#
Computer test: Popeye 4.61
Reprints: 62 Retrograde Analysis 1915
(X) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-1-26 more...
75 - P0002122
Wolfgang Hundsdorfer
Deutsches Wochenschach 03/10/1909
P0002122
(13+12)
#3
1. fxe6ep! Txe6+ 2. Lxe6+ Kxh5 3. Dg4#
1. ... Lh7+ 2. Lf5+ Kxh5 3. Dg4#
R: 1. ... e7-e5 2. Ke5-e4 Tf6-d6
play all play one stop play next play all
Yoav Ben-Zvi: The 4 missing BPs are all needed to account for 4 WP captures. [BPa7] and [BPb7] capture all 3 missing White pieces to promote on c1 so [BPc7] does not capture and also promotes on c1. Therefore White's last move could not be -2.WPc4xd5 or -2.WKe3-e4 (forcing -2...BPc5xd4) as, in both cases, the path to promotion of [BPc7] is closed off. This implies that White's last move was WKe5-e4 preceded by BRf6-d6.
The e.p. key opens up 2 checks for Black but closes off the threatened mate on d5. The skill shown by the pioneers of RA in dressing up their problems with an orthodox stipulation is to be admired but also shows why it was neccessary to shed this practice in order to make further progress. (2018-3-22)
Henrik Juel: C+ by Popeye 4.61 (after analysis) (2018-3-22)
more ...
comment
Keywords: En passant
Genre: Retro
Reprints: 69B Retrograde Analysis 1915
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-3-22 more...
76 - P0002139
Aleksey A. Troitzky
Bohemia 1910
P0002139
(14+14)
#2
Henrik Juel: 1.bxc6ep+. -1... c7 -2.Tc6 etc.
Not -1... c6? -2.Lc7 and the tempo is wrong. (2004-3-8)
Yoav Ben-Zvi: -1...BPc6-c5? -2.Bc7-b8 leads to a Retro-opposition between the bishops on b8 which cannot be resolved by switching the side to move due to the Parity Argument (for the moves of the bishops) and lack of a tempo retraction for either side. This part was shown in P0002141. The WB must stand on b8 when Black retracts BPc7-c6/c5 (releasing WRb6 and opening the North-West cage) because standing on d8,e7,f8 it cannot be released from the back rows before BBa4 is retracted home to c8 (to allow retraction of BPd7-d8) but the release of BBa4 from the South cage awaits the retraction of WB home to c1 (to allow retraction of WPd2-d3) causing a deadlock (the release of WBc1 and BBc8 must each precede the other so neither can come first).
Retro-opposition (supported by the Parity argument) combined with a clever deadlock argument, refute a Try thus justifying the En Passant key of a #2. An impressive achievement at the time that remains beautifull when viewed today. (2018-2-18)
A.Buchanan: In the world of chess problems, it amazes me that (1) so many different ideas can be conceived (2) so many of those can be realized. (2018-2-19)
comment
Keywords: En passant, Retro Opposition
Genre: Retro, 2#
Reprints: 79 Retrograde Analysis 1915
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-19 more...
77 - P0002141
Wolfgang Hundsdorfer
Münchner Neueste Nachrichten 1908
P0002141
(9+12)
#5
1. bxc6ep Lxb6 2. De5! dxe5 3. Lxe5 Ld4+ 4. Lxd4 ... 5. Lb2#
play all play one stop play next play all
Henrik Juel: 1.bxc6ep Lxb6 2.De5! dxe5 3.Lxe5 Ld4+ 4.Lxd4. -1... c7 -2.Tc6 Lg1 -3.La7 h2xg1=L -4.Db6 a5xb4 etc. Not -1... c6? -2.Lc7, and perpetual repetition by movable wLc7 and sDLS! Very good. (2004-2-26)
Yoav Ben-Zvi: BBa7 is promoted by [BPh7] playing BPh2xg1=B. all 7 missing White pieces were captured by BPs. This means [WPh2] accounts for one of the captures by BPs so it must have captured 2 Black pieces, one on the g file to clear the way for [BPh7] and the other to promote on f8 or h8. This leaves only 1 missing Black piece that can be captured by other WPs so WPb5 came from the a file not from the c file and WBb8 could not promote on d8.
The last move of the game was by Black (determined by the stipulation). It was not -1...BPd7-d6? (BBa6 also promoted but not enough BPs to promote). Also not BPc7xd6? (too many captures by BPs).
Not -1...Pc6-c5? -2.Bc7-b8 (not -2.Pc4xb5? since WP captured only once) Bb8-a7 (or -2...Qb8-a8 -3.Bd8-c7 Qa8-b8 repeats while Pc7-c6/Qc7-b8 locks WBd8 which cannot unpromote) -3.Bd8-c7 Na7-c8/Qa7-a8/Ba7-b8/ (not -3...Pc7-c6/Bc7-b8 as WBd8 cannot unpromote) -4.Bc7-d8 and retro-stalemate or forced repetition.
The main Try is refuted by Retro-opposition on b8 between WB and both BB and BQ with no way to switch the side-to-move due to the Parity argument and lack of tempo retractions for either side. This problem is considered to be the earliest implementation of Retro-opposition. (2018-2-12)
A.Buchanan: Very clean retro play... and nice forward play with double sacrifice for the win. (2018-2-12)
comment
Keywords: En passant as key, Retro Opposition
Genre: Retro
Reprints: 116 150 exzentrische Schachaufgaben 1910
79B Retrograde Analysis 1915
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-2-12 more...
78 - P0002257
Ulrich Ring
5674 feenschach 93 11-12/1989
P0002257
(13+15) cooked
BP in 23,5
1. e4 h5 2. Dg4 hxg4 3. d4 Th3 4. d5 Tb3 5. Le3 b5 6. Lb6 axb6 7. h4 Ta4 8. h5 La6 9. h6 Dc8 10. h7 Db7 11. Th6 Da7 12. Tc6 dxc6 13. e5 Kd7 14. e6+ Kd6 15. exf7 Kc5 16. d6 e5 17. d7 e4 18. d8=D e3 19. Dd1 Ld6 20. f8=L g6 21. Lh6 e2 22. Lc1 Tf4 23. h8=T Kb4 24. Th1
play all play one stop play next play all
Cook: 1. e4 h5 2. Dg4 hxg4 3. d4 Th3 4. d5 Tb3 5. Le3 b5 6. Lb6 axb6 7. h4 Ta4 8. h5 La6 9. h6 Dc8 10. h7 Db7 11. Th6 Da7 12. Tc6 dxc6 13. e5 Kd7 14. e6+ Kd6 15. exf7 Kc5 16. d6 e5 17. d7 e4 18. d8=D g6 19. Dd1 Ld6 20. f8=L e3 21. Lh6 e2 22. Lc1 Tf4 23. h8=T Kb4 24. Th1
Alfred Pfeiffer: Die Korrekturfassung 5674v mit gleicher Forderung (fs-99, S.38): 1ss5/d1b5/lbb1b1b1/1bl5/k2t2b1/2t5/BBB2BB1/TSLDKLST soll die Duale der Urfassung (4-fach mögliches Ziehen von g7-g6) nicht mehr enthalten. (2014-11-6)
Henrik Juel: The correction mentioned by Alfred is still cooked, acc. to Euclide 1.01 (2017-11-24)
comment
Keywords: Unique Proof Game, Homebase (W), Pronkin Theme (DTL)
Genre: Retro
Reprints: 42 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2014-11-6 more...
79 - P0002277
Karlheinz Bachmann
v Die Schwalbe 104, p. 217, 04/1987
1. ehrende Erwähnung
P0002277
(11+15)
BP in 48,0
1. Sf3 a5 2. Sd4 a4 3. Sb3 axb3 4. a3 Ta4 5. Ta2 bxa2 6. Tg1 axb1=S 7. Th1 Sc3 8. Tg1 Sd5 9. Th1 Sb6 10. Tg1 Sa8 11. Th1 b6 12. Tg1 La6 13. Th1 Dc8 14. Tg1 Db7 15. Th1 Df3 16. gxf3 h5 17. Lh3 h4 18. Le6 h3 19. La2 Lc4 20. Lb1 La2 21. b3 Sa6 22. Lb2 Sc5 23. Lf6 gxf6 24. Kf1 Lh6 25. Kg1 Kf8 26. Df1 Kg7 27. Dg2+ hxg2 28. h4 Kg6 29. Kh2 g1=S 30. Kg2 Lf4 31. h5+ Kg5 32. h6 Lg3 33. h7 Sh6 34. Th4 Tb8 35. Tb4 Tb7 36. f4+ Kh4 37. h8=T Sf3 38. Tg8 Se5 39. Tg5 Sg6 40. Kf3 Kh3 41. Ke3 Kg2 42. Te5 Kf1 43. Kf3 Ke1 44. Kg2 Kd1 45. Kf1 Kc1 46. Ke1 Kb2 47. Kd1 Ka1 48. Kc1 Sh8
play all play one stop play next play all
paul: Correction of P0000067. (2018-3-3)
comment
Keywords: Unique Proof Game, Length Record, Non-standard material, Promotion (Tss)
Genre: Retro
Reprints: 82 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2006-1-10 more...
80 - P0002307
Jacques Rotenberg
Rex Multiplex 1983
P0002307
(16+14) C+
BP in 6,5
1. e3 h6 2. Ld3 Th7 3. Lxh7 a5 4. Ld3 Ta6 5. Lxa6 h5 6. Lf1 Sa6 7. e4
play all play one stop play next play all
Jacques Rotenberg: .
Round trip of the bishop (2017-11-28)
comment
Keywords: Unique Proof Game, Round Trip (L)
Genre: Retro
Computer test: Natch 2.1 Copyright (C) 1997,98,99,2001,2002 Pascal Wassong
Reprints: 137 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-11-28 more...
81 - P0002313
Yaakov Mintz
The Problemist 1987-1988
3.-5. ehrende Erwähnung e.a.
P0002313
(12+11)
BP in 17,5
1. f3 e5 2. Kf2 e4 3. De1 e3+ 4. Kxe3 Ke7 5. Dg3 De8 6. Kf2 Kd8 7. Ke1 Lc5 8. Kd1 Lxg1 9. De1 Lxh2 10. Txh2 d6 11. Txh7 Le6 12. Txg7 Th1 13. Th7 Lxa2 14. Th8 Lxb1 15. Txa7 b5 16. Tb7 Ta1 17. Ta7 b4 18. Ta8
play all play one stop play next play all
Cook: NL
1. f3 e5 2. Kf2 e4 3. De1 e3+ 4. Kxe3 b5 5. Dg3 b4 6. Kf2 Lc5+ 7. Ke1 Lxg1 8. Kd1 Lxh2 9. Txh2 d6 10. Txh7 Le6 11. Txg7 Th1 12. Th7 Lxa2 13. Th8 Lxb1 14. Txa7 Ke7 15. Tb7 Ta1 16. Ta7 De8 17. Ta8 Kd8 18. De1 (Mario Richter)
paul: C+ (Euclide 1.11) for the first 13 moves (in about 51 hours). I do not dare to check for 13.5 moves. (2018-3-8)
Henrik Juel: Tiny typo in Mario's cook: 10.Txh7 (2018-3-8)
Mario Richter: The typo comes from a "by hand conversion" of the output of several tools I'm using (here: rawbats and chessbase) - unfortunately each tool has it's own output format, incl. the PDB solution field format ... (2018-3-9)
A.Buchanan: I have a janitor's tool which allows me to change the representation of positions & solutions.
Try to copy the file here: https://www.dropbox.com/sh/ld64s00zm0f9tx8/AAA7r8BsA0vuLcZOOKNvKkmua?dl=0
Click on it, and then hit the download button on the right.
The most useful is the one which converts from FEN to PDB "pieces" format.
Stick the input string in the yellow cell, and pick up the result from the green cell.
If you want to see how it's done, unhide the hidden rows and columns: no VBA just simple Excel.
Only 1% as clever as rawbats, but it still saves me a lot of time.
Feel free to use and to improve. (2018-3-9)
Mario Richter: @Andrew: Thanks for your offer - but I have such tools myself. My fault was not to use them (I thought that I'll be able to transform such a short PG by hand without errors ...)
Would be nice if the PDB-System would be more helpful with respect to language support.
I've decided to use 'english' in the language settings, but that doesn't help here, since solutions still have to be given in german piece notation.
Might be difficult to change this, especially when thinking of fairy piece names, so I can live with that, but there are other aspect which sometimes drive me crazy, e.g. the handling of source names in different languages ... (2018-3-9)
A.Buchanan: I thought you might have such a tool, but I thought it was a nice opportunity to announce it for others who might find it useful. (2018-3-9)
more ...
comment
Keywords: Unique Proof Game, Interchange, Belfort
Genre: Retro
Reprints: 144 Shortest Proof Games 11/1991
Best Problems 47 07/2008
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-3-9 more...
82 - P0002380
Vladimir Korolkov
Prawda 1929
1. Preis
P0002380
(12+6)
Gewinn
1. Lxh3? Lf3!+ 2. Lg2 f1=D#
1. Tc1+? Sxc1 2. La4+ b3 Schwarz gewinnt
1. Td2+! Kc1 2. Td1+ Kxd1 3. La4+ b3! 4. Lxb3+ Ke1 5. Lb4+ Sc3! 6. Lxc3+ Kf1
7. Lc4 Lxc4 8. Dc5! Ld3 9. Db5! Lxb5 10. b8=S! Ld3 11. a8=L! Le2 13. f8=T! Gewinn
11. a8=D? Le4+ 12. Dxe4 Patt
8. ... Le2 9. f8=T
2. ... Kxb2 3. Lxh3
2. Tc2+? Kb1! 3. Tc1+ Sxc1 4. Lf5+ Sd3 5. Lxd3+ Lxd3 Schwarz gewinnt
1. ... Ke1 2. Txe2+ Kxe2 3. Lxh3 Gewinn
play all play one stop play next play all
Yoav Ben-Zvi: A fine study with 3 underpromotions. This is not a Retro and none of the promoted pieces are captured so there is no Ceriani-Frolkin. (2018-2-7)
more ...
comment
Keywords: Promotion (SLT), under-promotion
Genre: Studies
Reprints: 43 Int. GM und M für Schachkompositionen 1988
A. Die Schwalbe 127, p. 373, 02/1991
Rochade Europa , p. 24, 04/1997
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-2-7 more...
83 - P0002461
S. N. Ravishankar
Rex Multiplex 1986
P0002461
(2+3)
#1 vor 15
VRZ, Typ friedlich
R: 1. Kg6-h5 Lg8-h7+ 2. Kf7-g6 Lh7-g8+ 3. Ke7-f7 Lg7-f8+ 4. Kf6-e7 Lf8-g7+ 5. Kf5-f6 Lg8-h7+ 6. Ke6-f5 Lh7-g8+ 7. Kd6-e6 Lg7-f8+ 8. Ke5-d6 Lf8-g7+ 9. Ke4-e5 Lg8-h7+ 10. Kd5-e4 Lh7-g8+ 11. Kc5-d5 Lg7-f8+ 12. Kd4-c5 Lf8-g7+ 13. Kd3-d4 Lg8-h7+ 14. Kc4-d3 Lh7-g8+ 15. Kb3-c4, dann 1. Th6-h1#
play all play one stop play next play all
more ...
comment
Keywords: Defensive Retractor, Type Pacific, Aristocrat, Minimal, Staircase (K)
Genre: Retro
Reprints: 4 Die Schwalbe 104, p. 214, 04/1987
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-1-16 more...
84 - P0002611
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 26, 1979
P0002611
(3+1)
Ergänze einen wL auf e3 oder e4!
Monochromes Schach
+wLe3
play all play one stop play next play all
Forderungs-Alternative: Einfarben-Schach. Auf dem Brett steht ein unsichtbarer Läufer. Steht er auf einem schwarzen oder einem weißen Feld?
Yoav Ben-Zvi: In the book (page 26) the WB is placed between e3 and e4. It seems simpler to represent this with WB on e4, the stipulation "Monochrome chess. Is the position legal?" and a Twin b) WBe4 to e3. Proof of illegality with WB on e4: There is no piece that could perform the last capture on a dark square since no piece on the board is capable of a dark-squared capture and it could not be a piece that is missing since such a piece would itself have been captured later on a dark square. Smullyan's version uses poetic language including the metaphor of a Bear and a Lion fighting until each has entirely devoured the other. Essentially the argument uses the well-known mathemtical technique of "Infinite descent" leading to "Reductio ad Absurdum": It can be shown that assuming the existence of a "minimal" instance that has some property (such as most recent capture on a dark square) leads to the conclusion that it is not really minimal (there is a more recent capture on a dark square) so the assumption leads to self contradiction and is therefore not true. A formal definition of this method was developed by Fermat (17th Century) but it was used as far back as Euclid's "Elements" (300 B.C.). (2017-12-14)
Henrik Juel: It might be simpler to consider the retroplay:
With Le4 there is no way of producing a dark-squared man by uncapture (2017-12-14)
Brassaud: With Le4 it seems possible to producing a dark-squared man with the retroplay : 1) Lc2-e4, Kd7-e8 2) Ld3xPc2, b3xPc2 3) Ld3-e4, a4xb3 ep 4) b2-b4... But the position remains illegal as shown with the metaphor of the lion and the bear. (2017-12-15)
Henrik Juel: Good point, Francois
But the en passant trick still cannot create a full retroplay back to the initial position with 32 men
I should have written 'officer' instead of 'man' (2017-12-15)
Yoav Ben-Zvi: Henrik's modified claim that "with WBe4 there is no way of producing a dark-squared officer by uncapture" is correct but I do not see a simple way to prove it directly. A "lion and bear" type argument with retroplay could ask "Which of the pieces that move on the dark squares was the first to uncapture?". It should be noted that this piece could not be a pawn that was itself uncaptured e.p. (since the history of such a pawn does not include an uncapture) and that proving that such a piece does not exist proves illegality (since it implies that dark-squared officers such as BQd8 could not be uncaptured). A similar clarification is needed when applying the argument to forward moves.
The Homebase position of the diagram is an IC. It could be presented (optionally adding a WB on f1 and/or a BB on c8) with the stipulation "Is the position legal?" and the Twin b)-WPf2. (2017-12-17)
comment
Keywords: Monochrome, Add pieces (L), Homebase (2)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-28 more...
85 - P0002619
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002619
(15+13)
Darf Weiß noch rochieren?
Yoav Ben-Zvi: Appears on page 54 of the Book. WPb4 and BPg5 both captured Rooks. Neither BR could have escaped from the bottom rows, to be captured by [WPa2], before capture of the WR cleared the h column. It follows that the WR was captured first with WP still on column a and therefore the captured WR could not have come from a1 and was originally from h1 escaping through the h column. WRh1 is a "Sibling Impostor" and White "Can't Castle". (2018-3-15)
Henrik Juel: It seems that Lc1 is unnecessary
Even without it, White cannot castle, by a very similar argument; the only difference is that Th1 might be [Th1], but if so, it must have moved to make way for [Ta1] (2018-3-15)
comment
Keywords: Castling (wk), Cant Castler, Impostor (T)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
(A) Probleme für Tiger 4 04/1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-15 more...
86 - P0002624
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 66, 1979
P0002624
(12+13)
Ergänze einen wB auf f4 oder f5!
1) +wBf5
play all play one stop play next play all
Henrik Juel: The dark-squared bishops were captured by officers, so the pawn captures were c7xSb6, d7xLc6 by Black and exLf, f2xSg3 by White (when the pawn has been added)
The forward sequence was e2-e3 (or e2-e4) before d7xLc6 before exLf on a light square, so [Pe2] could not reach f4, and the undetermined capture was e4xLf5.
This simple idea was later shown more elegantly in P1012384.
more ...
comment
Keywords: Add pieces
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
R5 Phénix 275-276, p. 10810, 07-08/2017
R5 Phénix 275-276, p. 10812, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-9 more...
87 - P0002628
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002628
(3+2)
#1
Aprilscherz!
1. b8=sS#
play all play one stop play next play all
vgl. P1349637
Mario Richter: Could be, inspired by P1349637, presented as twin: a) diagram, b) +sSb8 (2018-5-2)
Ladislav Packa: Mario: Position b) would be enough. H#1*: 1...bxa8=R#, 1.Sd7 b8=S# (2018-5-2)
comment
Keywords: Joke, Joke promotion (s)
Genre: Fairies
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-5-2 more...
88 - P0002686
Narajan Shankar Ram
4154 feenschach 70 08/1984
P0002686
(1+1) cooked
Ergänze wT, wS und wB zu einem IC!
Madrasi

play all play one stop play next play all
Verführung: wTd1 wSc3 wBe4, aber Stellung ist legal, zuletzt wBd3xsSe4+

Lösung: wTb5 wSb6 wBc4!
Cook: - wTc5 wSc7 wBc6
- wTe5 wSe7 wBe6
- wTd6 wSb6 wBc6
- wTd6 wSf6 wBe6
jeweils illegales Doppelschach, ohne T bzw. S legales Einfachschach, ohne wB jeweils Doppelschach erklärbar durch SxT++

Duplicate Diagram: P0006310

Autor: Td4/Sb4/Bc4 or Td4/Sf4/Be4 are not cooks, since after removing wT, w's last move can be SxBb4 or SxBf4, but after this, there no last move for Black!
Twin: I later added a twin - a)Orthodox, b)Madrasi
The solution to the Orthodox twin is Te5/Se4/Be6.
[Der orthodoxe Zwilling ist C+]
paul: The try is here wTd1 wSc3 wBe4 (legal position -1.d3xSe4+) (2011-9-22)
Henrik Juel: Why are wTd4 wSb4 wBc4 or wTd4 wSf4 wBe4 cooks? The positions seem still illegal without the T.
This looks like a cook: wTe5, wSe4, wBe6 (with no Madrasi effects). (2011-9-22)
hpr: I am no expert here, but my 2 cents anyway:
wTe5, wSe4, wBe6; the position is legal, last move: Sg3xTe4. Right? (2011-9-23)
Henrik Juel: Yes, you are right, of course. Last move could even be KxTf5+. (2011-9-23)
paul: wTd4 wSb4 wBc4 seems to be a cook. Without Td4 the last moves where -1.Sa2xBb4++ Bb2-c4 (2011-9-25)
Henrik Juel: But the last moves should be a white and a black move, not the two white moves Sa2xBb4 and Bb2-c4. (2011-9-25)
paul: Right, Henrik! Then the problem has unique solution. (2011-9-25)
shankar ram: Td4/Sb4/Bc4 or Td4/Sf4/Be4 are not cooks, since after removing wT, w's last move can be SxBb4 or SxBf4, but after this, there no last move for Black!

Twin: I later added a twin - a)Orthodox, b)Madrasi
The solution to the Orthodox twin is Te5/Se4/Be6. (2018-1-16)
Mario Richter: The tries Td4/Sb4/Bc4 or Td4/Sf4/Be4 are interesting (for me: much more than the official wTd1 wSc3 wBd3), because they make use of a strange Madrasi en passant effect ...
In these two tries an illegal triple check is used, but to cook the problem is suffices to construct an illegal double check:
- wTc5 wSc7 wBc6
- wTe5 wSe7 wBe6
- wTd6 wSb6 wBc6
- wTd6 wSf6 wBe6 (2018-1-16)
more ...
comment
Keywords: Illegal cluster, Madrasi, only Kings
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-1-17 more...
89 - P0003126
Nissim Shirin
2189 Shahmat 04/1986
P0003126
(8+13)
h#2
1. fxe3ep Txc5 2. Le4 Sxb3#
play all play one stop play next play all
Der ep-Schlüssel ist nicht gerechtfertigt, weil zuletzt auch f3xTe4 geschehen sein kann.
Mario Richter: Something must be wrong here: White's last move might have been f3xTe4, so ep-key is not justified (2018-3-26)
comment
Keywords: En passant as key
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-3-29 more...
90 - P0003178
Tivadar Kardos
10575 The Fairy Chess Review 08/1956
P0003178
(5+15) C+
h#4
1. gxf3ep+ Kxh4 2. Tg7 hxg7 3. 0-0-0 g8=D 4. Kb8 Dxd8#
play all play one stop play next play all
Sally: Zuletzt geschach:
f2 - f4, Te3 - g3+! (2017-9-6)
Henrik Juel: Last move was not e3xf4, because the only capture by White was b2xa3; and not f3-f4, because then the check from Lc1 would be unexplainable (2017-9-6)
comment
Keywords: En passant as key, Castling (sg), Promotion (D), Valladao Task
Genre: h#, Retro
Computer test: Popeye C-Version 3.52 (2048 KB)
Reprints: 25 Die Schwalbe 217, p. 360, 02/2006
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-2-14 more...
91 - P0003179
Tivadar Kardos
10421 The Fairy Chess Review 02/1956
P0003179
(9+11) C+
h#3
1. fxg3ep Lxe2 2. Sa3 0-0-0 3. Sd2 Th1#
play all play one stop play next play all
Henrik Juel: for clarity: 1... Lxe2
White captured all missing black men by bxa, dxcxb, and exdxc, so Pg4 is [Pg2] and last move was g2-g4
C+ by Popeye 4.61 (2017-9-12)
more ...
comment
Keywords: En passant as key, Castling
Genre: h#, Retro
Computer test: C+ by Popeye 4.61 (2017-9-12) subject to manual proof of e.p. viability
Reprints: 141 200 Ausgewählte Schachaufgaben 1983
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-9-13 more...
92 - P0003396
Tivadar Kardos
Festgrüße 1956
P0003396
(8+16) C+
h#2
1. Kd4! bxc5 2. Ke5 d4#
1. axb3ep? Txe1 2. Sd3 Txe4# (illegal)
play all play one stop play next play all
1. axb3ep? ist illegal, weil zuletzt R: 1. g7-g8=S geschehen sein konnte
vgl. P1348363
Henrik Juel: C+ by Popeye 4.61
The possibility of a promotion as last move shows that the ep capture cannot be legitimized
But the ep capture also seems illegal, as Black pawns captured all missing white men, including [Lc1] (2018-3-22)
A.Buchanan: Perhaps this is deliberate: to construct an e.p. problem which does not rely on the e.p. convention. (2018-3-22)
Yoav Ben-Zvi: This differs from P1348363 by the addition of the WP on a5 and removal of the Twin that shows the e.p. in the solution. In the present version the promotion to WN is uniquely determined to be White's last move. The Twin can be replaced with: b) -WNg8 leading to model mates. I think the idea of an illusionary e.p. used to trap the sophisticated solver was attempted in P1346195. (2018-3-24)
A.Buchanan: I made P1261604 to have illusionary en passant hxg to distract from the real en passant action elsewhere. (2018-3-24)
A.Buchanan: There's a set of problem in W.Keym's Eigenartige Schachprobleme (a section called "Bosheiten im Einzüger") 308-324, pages 100-105) which explore castling, en passant and the move in various combinations of real and try play, within the context of #1 problems. Most are by Keym himself, but Fabel makes a few appearances. Not sure if these problems are all in PDB yet. (2018-3-25)
Olaf Jenkner: Would it be possible to improve the retro content by moving bPh6 to h7 and replacing Ng8 by Bh8? (2018-3-25)
Olaf Jenkner: I overlooked Bg7-h8 so nothing would be changed. (2018-3-26)
more ...
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: Popeye 4.61
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-26 more...
93 - P0003405
Laszlo Lindner
Magyar Sakkvilag 1943
3. Preis
P0003405
(4+16) C+
h#2
b) sBf3 nach e3
a) 1. Lxd4 Txb3 2. Tc5 Sd2#
R: 1. Kg3-h4 2. gxf3ep+

b)
R: 1. d2-d4, dann 0. ... d2-d4
1. e4xd3ep Kxh3 2. d4 Sa3#
play all play one stop play next play all
Ob der Zwilling b) schon im Original vorhanden war, ist nicht sicher, im Nachdruck in 'Problem [Zagreb]' fehlt er, dafür kommt er in einem Artikel von . Petrovici zum "Thema Than" von 03/2016 vor.
Mario Richter: @Alfred: Wieso funktioniert Abspiel-Button für b) nicht?? (2018-3-22)
A.Buchanan: @Mario, @Alfred: the problem is that the b solution follows the retro bit, and the parser think that it's retro too. If I remove the retro part, b) works fine. I don't know how to reset the parser so it's going forwards again. Normally I just put the R part after the forwards part, but that won't work here because there's twins. (2018-3-22)
Alfred Pfeiffer: Keine Ahnung, warum das Nachspielen von b) nach dem Retro-Part von a) nicht funktioniert. Evtl. ein Bug im Proramm. Das sollte Gerd Wilts prüfen.
Ein Tausch der Lösungen b) und a) in der Textreihenfolge erlaubt das Nachspielen, (2018-3-22)
comment
Keywords: En passant as key, En passant in the retro play, Than theme
Genre: h#, Retro
Reprints: (II) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-3-22 more...
94 - P0003438
Antti Gottfried Ojanen
3977 Stella Polaris 06/1971
4. -6. Platz
P0003438
(3+7) C+
h#3 (AP)
2.1...
1. Tb5 0-0-0 2. Tb3 Kc2 3. T3xb4 Ta1#
1. cxb3ep Tc1 2. Ta5 Txc3 3. Sb5 Tc4#
play all play one stop play next play all
Nordisches Turnier
Jakob Leck: Jahresangabe müsste vermutlich 1971 lauten. Vergleiche Urdrucknummern 3978 (P0003446) und 3979 (P0003436). (2018-2-11)
Henrik Juel: The given theme was a variation on AP:
ep capture in one solution is justified by castling in the other one (2018-2-11)
A.Buchanan: I would prefer sTh5 on d5, allowing remowal of wBd4. (2018-2-11)
more ...
comment
Keywords: a posteriori (AP), En passant as key, Castling (wg)
Genre: h#, Retro
Computer test: C+ by Popeye 4.61
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-12 more...
95 - P0003447
Gerd Rinder
(O) Die Schwalbe 16, p. 393, 10/1972
P0003447
(14+13) C+
h#2 (pRA)
1. Txg3 Sxg3+ 2. Kf3 0-0#
1. cxd3ep Lxg1 2. e2 Sd2#
1. gxf3ep Lxg1 2. Dd3 Txh4#
play all play one stop play next play all
VL: This problem was first published in the article entitled "Konstruktive Kritik am Kodex von Piran" (by W.Keym; H.16). The author is a strong opponent of the retro-synthese (including AP a la Keeble--Petrovic = "Typ Petrovic"). Here we meet a retro-situation resembling that of AP, which, however, is interpreted and resolved purely in the framework of pRA. Namely, the problem contains three retro-variants: (a) 0-0; (b) 0-0-0 & cxd3 ep; (c) 0-0-0 & gxf3 ep. Each of them results in a unique (partial) solution (see above), so that the problem is sound. The absence of 0-0-0 in the latter two solutions is a witty feature that emphasizes a fundamental distinction from AP (where only actual castling can legalize the ep-key). Judging from the article "PRA oder Kodex" by B.Pavlovic in the "Problem", 152-6, where this problem is reproduced, it was initially stipulated "h#2, PRA-Typ Rinder" (this is presently known under the name "Typ Keym"). It is reproduced also in the book "Eigenartige Schachprobleme" by W.Keym, 2010, Pr.385. (2012-8-26)
Sally: Hier schlugen die w. Bauern dreimal, unter anderem eine UW-Figur von "h1 oder "a1",(entweder ist 000 oder 00 zulässig).
Der letzte Zug war 1. K-e1, oder T-a1, oder "d2-d4". oder
"f2-f4". Falls 000 zulässig ist, dann ist 00 unzulässig und jeweils einer der E.-P.-Schläge erlaubt, Also löst entweder:
1. Bg4xf3 E.p.! - Lxg1, 2. Dd3 - Txh4#. oder :
1. Bc4xd3 E.p.! - Lxg1, 2. Be2 - Sd2#.
Beide Male wird das Zugrecht 000 anerkannt, aber nicht aufgeführt! Falls 00 zulässig ist, dann ist 000 unzulässig;
in diesem Fall war zuletzt der Zug "T-a1" möglich, daher kein E.p.-Schlag erlaubt. Also löst :
1. Txg3! - Sxg3+, 2. Kf3 - 00 #. (2018-6-15)
Henrik Juel: C+ by Popeye 4.61, after analysis (2018-6-15)
more ...
comment
Keywords: Castling, En passant as key, a posteriori (AP)
Genre: h#, Retro
Computer test: Popeye 4.61
Reprints: (II) Problem 152-156 04/1973
XI Caissas Schloßbewohner 1 1983
(13) Die Schwalbe 241 02/2010
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-16 more...
96 - P0003451
Knud Harald Hannemann
3823 Stella Polaris 03/1971
P0003451
(6+8) cooked
h#2 (AP)
2.1...
1) 1. gxf3ep 0-0-0 2. Te7 Th4#
2) 1. cxd3ep 0-0 2. Da4 Txa4#
play all play one stop play next play all
AB: I think this is cooked. I don't see how AP castling can justify earlier ep here.
1. Kf3 Bf5 2. Kg2 Be4#
1. Kf3 Bxd7 2. Kg2 Bc6#
1. cxd3 Rf1 2. Qa4 Rxa4#
1. gxf3ep Ra5 2. Kf4 Rh4#
1. gxf3ep Rd1 2. Re7 Rh4#
Also, second solution given has typos 1. *c*xd3ep & 2. Q*a*4. (2002-3-21)
V.Liskovets: Indeed this problem is cooked, and I
failed to correct it preserving symmetry.
Here is a possible correction:
W: Ke1 Ra1 Rh1 Be6 Pd4 Pf4
B: Ke4 Qd7 Rf7 Pc3 Pc4 Pe3 Pg3 Pg4 Bh7 Rb2 Pb3

Another story, justifying its contents (e.p.).
In my opinion, all published treatments are
insatisfactory (the same concerns P0004295
(corrected) by Werner Kuntsche as well).
There is a way to make it sound under the
sophisticated HYBRID stipulation 'AP, pRA':
2 partial solutions legalized JOINTLY by
both castlings (details to be published). (2002-4-2)
more ...
comment
Keywords: Castling (wkwg), En passant as key, a posteriori (AP)
Genre: h#, Retro
Reprints: (65) Problem 144-147 12/1971
(8) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-12 more...
97 - P0003463
Tivadar Kardos
1581 Problemista 03/1967
P0003463
(9+16)
h#4
1. 0-0-0?? 0-0 2. Kb8 Txc1 3. Ka8 Txb1 4. Tb8 Ta1# (0-0-0 ist illegal)
1. De6! h4 2. 0-0 h5 3. Kh8 hxg6 4. Tg8 Txh7#
play all play one stop play next play all
1. 0-0-0? ist nicht gestattet, da wegen der schwarzen Bauernstellung der weiße Bauer a2 auf a8 umgewandelt wurde!
more ...
comment
Keywords: Cant Castler, Castling (wksg)
Genre: h#, Retro
Reprints: 144 200 Ausgewählte Schachaufgaben 1983
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-9-6 more...
98 - P0003518
Oskar E. Vinje
3376 The Fairy Chess Review 14 10/1938
P0003518
(12+10)
h#2
1. Sf7 Td6 2. Tf8 Sxg7#
Not
1. Sf7 Txh6 2. 0-0? Sxe7#
play all play one stop play next play all
Henrik Juel: The missing white TLD were captured on the first row; additionally black captured d7xc6, so [Ph2] promoted and [Pf7] was captured on its file. To preserve the black castling, White must have captured hxgxh7xg8; but only two black men were available for capture: DS. So Black may not castle, and 1.Sf7 Txh6 2.0-0? Sxe7 is not a solution. (2010-12-15)
Mario Richter: Henrik, your analysis is not complete: it is also possible, that an original white piece was captured on c6 (wRh1 or one of the wNN), thereby allowing the promotion on g8 without visiting f7. But in this case, the promoted piece is still on the board, and regardless if it is the wR or one wN, to leave the promotion square g8 was only possible by destroying Black's castling right. (2010-12-16)
Henrik Juel: Good point, Mario. This only makes the problem even better. They knew what they were doing back in 1938. (2010-12-16)
A.Buchanan: Solution & retro try echo one another. (2018-3-17)
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comment
Keywords: Cant Castler, Castling (sk)
Genre: h#, Retro
Computer test: C+ Popeye for the h#2, with manual thinking for the retro aspects.
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-17 more...
99 - P0003536
Paul Leibovici
347 Sahovski Vjesnik 02/1949
P0003536
(2+6) C+
h#2
1. 0-0-0? (illegal!)
1. Kf8 Da1 2. Te8 Dxg7#
play all play one stop play next play all
Der wK kann h8 nur via f7 oder f8 erreicht haben, der sK hat also schon gezogen.
Klären: Datum =02/19?9
Henrik Juel: C+ by Popeye 4.61
Not 1.0-0-0+? Kh7 2.Td7 Da8
because Ke8 has moved to let Kh8 in (2018-2-24)
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comment
Keywords: Cant Castler, Castling (sg)
Genre: h#, Retro
Computer test: Popeye 4.61
Reprints: 12 Volzhskaya kommuna 01/04/1977
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-2-26 more...
100 - P0003661
Hans Frieder Haefele
11285 Schweizerische Schachzeitung 09/1977
P0003661
(3+6) C+
h#2
b) sBd3 nach a2
c) ferner sBg4 nach d3
a) 1. Ta2 Txa2 2. Th1 Tg2#
b) 1. Te2+ Kd1 2. g2 Kxe2#
c) 1. Tf2 0-0-0 2. Tf1 Txf1#
play all play one stop play next play all
Sally: Weshalb aber geht dieletzte Variante auch nicht in den Diagrammen a) und b)?. Weil Weiß bei blockierender Stellung des Lh3 (sB4) zuletzt eindeutig oder mit dem König gezogen haben muss, was die Rochade verbieten würde. (2018-6-24)
Henrik Juel: If you dislike 'ferner', part c) could be written as 'sBg4 nach a2'
Analysis: last move was made by Ke1 or Ta1 in diagram position and in part b), so castling is possible in part c) only
C+ by Popeye 4.61 (2018-6-24)
comment
Keywords: Cant Castler, Castling (wg)
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-25 more...
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