2362 problem(s) found in 1578 milliseconds (displaying 100 problem(s)).

1 - P0000033
S. N. Ravishankar
5467v Die Schwalbe 98 04/1986
P0000033
(5+3) cooked
#1 vor 14
VRZ, Typ friedlich
R: 1. Tg1-f1 2. Tf2-f3 Te2- 3. Te1-g1 4. Te2-f2 Ta2- 5. Ta1-e1 Tb2-a2 6. Tb1-a1 Tc2-b2 7. Tc1-b1 Td2-c2 8. Tg1-c1 Tc2-d2 9. Td2-e2 Tb2-c2 10. Tc2-d2 Ta2-b2 11. Tb2-c2 g3-g2 12. Lg2-h3+, dann 1. Th1#
play all play one stop play next play all
Cook: Kurzlösung:
R: 1. Tg1-f1 droht 2. Tf1-f3, dann 1. Th1#
R: 1. Tg1-f1 Tf2-g2 2. Tf1-g1, dann 1. T3xf2#
(Mario Richter)
Mario Richter: So wie abgebildet, sollte die Problemno. nicht '5467v' sein.
Die Verbesserung (also das 'v') scheint erst später erschienen zu sein.
Das Diagramm ist kurzlösig durch: R: 1. Tg1-f1 (dr. 2. Tf1-f3, dann 1. Th1#) Tf2-g2 2. Tf1-g1, dann 1. Tf3xf2#. (2011-8-18)
Alfred Pfeiffer: Dies ist schon eine Veränderung des Originals. Wo die (in der LB bereits erwähnte) "Korrekturfassung" erschien, ist unklar. (2018-1-16)
comment
Keywords: Defensive Retractor, Type Pacific
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-1-17 more...
2 - P0000067
Karlheinz Bachmann
5821 Die Schwalbe 104 04/1987
P0000067
(11+15) cooked
BP in 48,0
1. Sf3 a5 2. Sd4 a4 3. Sb3 axb3 4. a3 Ta4 5. Ta2 bxa2 6. Tg1 axb1=S 7. Th1 Sc3 8. Tg1 Sd5 9. Th1 Sb6 10. Tg1 Sa8 11. Th1 b6 12. Tg1 La6 13. Th1 Dc8 14. Tg1 Db7 15. Th1 Df3 16. gxf3 h5 17. Lh3 h4 18. Le6 h3 19. La2 Lc4 20. Lb1 La2 21. b3 Sa6 22. Lb2 Sc5 23. Lf6 gxf6 24. Kf1 Lh6 25. Kg1 Lf4 26. Df1 Sh6 27. Dg2 hxg2 28. h4 0-0 29. Th3 Kh7 30. Tg3 Sg8 31. Kh2 g1=S 32. Kg2 Kh6 33. Tg4 Lh2 34. Tb4 Kh5 35. f4 Sf3 36. Tb5 Sd4 37. Ta5 Sb5 38. Kf3 Lg1 39. Ke3 Kg4 40. Ta7 Kh3 41. Tb7 Kg2 42. Tb8 Kf1 43. Kf3 Ke1 44. Kg2 Kd1 45. Kf1 Kc1 46. Ke1 Kb2 47. Kd1 Ka1 48. Kc1 Ta6
play all play one stop play next play all
Cook: 1. a3 b5 2. Ta2 b4 3. h4 b3 4. Th3 bxa2 5. Tb3 axb1=S 6. Tb4 Sa6 7. Sf3 Sc5 8. Se5 La6 9. Tb5 Dc8 10. Tb6 Db7 11. Tb4 Df3 12. gxf3 h5 13. Lh3 Th6 14. Le6 Sc3 15. La2 Lc4 16. Lb1 La2 17. b3 S3a4 18. Sg4 hxg4 19. Lb2 g3 20. Tb7 Ta6 21. Lf6 gxf6 22. Dc1 Lh6 23. Db2 Kf8 24. Dc3 Kg7 25. Db4 Tf8 26. Db5 Sb6 27. Dc6 Sa8 28. Dd6 g2 29. De6 g1=S 30. Dd6 Lf4 31. Dc6 Lh2 32. f4 Sf3+ 33. Kf1 Sd4 34. Kg2 Sb5 35. Kf3 Kh6 36. Ke3 Kh5 37. Dd6 Kg4 38. Dc6 Kh3 39. Dd6 Kg2 40. Db6 Kf1 41. Kf3 Ke1 42. Kg2 Kd1 43. Kf1 Kc1 44. Ke1 Kb2 45. Kd1 Ka1 46. Kc1 axb6 47. Tb8 Lg1
paul: See P0002277 as a correction. (2018-3-3)
more ...
comment
Keywords: Unique Proof Game, Length Record, Non-standard material, Castling
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-3-3 more...
3 - P0000121
Tivadar Kardos
12552 Schweizerische Schachzeitung 12/1984
P0000121
(2+2) C+
-1(w+s), dann h#1
2 Lösungen
1) R: 1. h4xLg5 Le3xDg5, dann 1. La7 Dd8#
2) R: 1. Kb1xTa1 Ta7xDa1+, dann 1. Ka8 Dh8#
play all play one stop play next play all
Doppelt veröffentlicht!
Sally: Als Vier-Steiner ganz beachtlich und als Abwechslung willkommendes, hübsches und interessantes Retrorätsel. (2018-6-25)
comment
Keywords: Help retractor, Kindergarten Problem
Genre: Retro
Computer test: rawbats
Reprints: 6512 Die Schwalbe 115 02/1989
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-6-26 more...
4 - P0000138
Wolfgang Dittmann
6633v Die Schwalbe 117 06/1989
P0000138
(15+14)
BP in 14,5
Schlagschach
1. Sh3 Sf6 2. Sf4 g5 3. Sd3 e6 4. Tg1 Ke7 5. Sb4 Se8 6. g4 e5 7. h4 gxh4 8. Tg2 h3 9. Tg3 h2 10. d3 h1=L 11. Sd2 Le4 12. dxe4 Lg7 13. Lg2 Kf8 14. Th3 h5 15. gxh5
play all play one stop play next play all
paul: The first 12.5 moves checked by Jacobi, with blackmustcapture and whitemustcapture. (2018-2-27)
A.Buchanan: @Paul: I still don't understand why you don't set kings not royal. You might miss a solution/cook. (2018-2-27)
paul: @Andrew: in the first instance, I wanted to show that the solution also works with orthodox Kings. (2018-2-28)
comment
Keywords: Ceriani-Frolkin Theme (l), Unique Proof Game, Losing Chess, Loss of tempo
Genre: Retro, Fairies
Reprints: (B2) Quartz 35 08/2010
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2015-1-9 more...
5 - P0000140
Narajan Shankar Ram
6686 Die Schwalbe 118 08/1989
P0000140
(3+3) C+
#1 vor 2
VRZ, Typ friedlich
R: 1. Te8-e6? Sg5-h3!
R: 1. Tf8-f6 droht 2. Kb5-c4, dann 1. Te7#
R: 1. Tf8-f6 a6-a5 2. Kc5-c4, dann 1. Te7#
R: 1. Tf8-f6 Ka8-b7,Kb8-b7,Kc8-b7 2. Tf7-f8+, dann 1. Te8#
R: 1. Tf8-f6 Kc7-b7 2. Kc5-c4, dann 1. Te7#
R: 1. Tf8-f6 Kc6-b7,Kb6-b7,Ka6-b7 2. Te7-e6+, dann 1. Tf6#
play all play one stop play next play all
Henrik Juel: Solution
-1.Tf8 thr./Ka8,Kb8,Kc8/a6,Kc7 -2.Kb5/Tf7/Kc5, 1.Te7/Te8/Te7 (2012-8-30)
shankar ram: Try 1.Te8? (2.Kb5 & Tf7#) Sg5! with reciprocal change after 1...K~8/K~6 (2018-1-16)
more ...
comment
Keywords: Defensive Retractor, Type Pacific
Genre: Retro
Computer test: rawbats
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-12 more...
6 - P0000383
Unto Heinonen
8492 Die Schwalbe 146 04/1994
P0000383
(14+15)
BP in 22,5
1. e4 a6 2. Lb5 axb5 3. f4 Ta3 4. Sf3 Tc3 5. dxc3 e5 6. Dd4 exd4 7. a4 d3 8. a5 d2+ 9. Ke2 d1=T 10. a6 Td6 11. a7 Ta6 12. a8=D c6 13. Da7 Da5 14. Dg1 Lc5 15. e5 Ke7 16. e6 Kd6 17. e7 Lb6 18. Dd1+ Kc5 19. e8=L d6 20. Ld7 Ta8 21. Lh3 Ld7 22. g4 Le8 23. Lf1
play all play one stop play next play all
paul: The first 19 moves tested (Euclide 1.11) (2017-12-26)
Henrik Juel: .. and I tested the remaining 3.5 moves (by hand)
These partial tests do not guarantee C+, of course
For clarity, the DTL in Keywords might be replaced by DtL or DLt (2017-12-26)
comment
Keywords: Unique Proof Game, Pronkin Theme (DTL)
Genre: Retro
Reprints: (42a) Die Schwalbe 232 08/2008
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2009-1-7 more...
7 - P0000676
Werner Keym
2477 Die Schwalbe 51 06/1978
P0000676
(5+5)
Welches war der letzte Zug?
R: 1. Lf8xDg7+
play all play one stop play next play all
Henrik Juel: -1.Lf8xDg7 Dg8 -2.Kd3 Dg7
-3.Lg8 h7 etc. (2004-8-12)
A.Buchanan: I think Willcocks deserved a co-author for P1012630 (2018-4-2)
Henrik Juel: Werner probably thought that saving a man was sufficiently original (2018-4-2)
A.Buchanan: Willcocks would have been young enough to have opined: maybe he just said: "it's yours!" (2018-4-2)
Mario Richter: There are several articles flying around discussing the sense or nonsense of "after" and "version of" labels in the domain of record constructions, maybe in 'Die Schwalbe' or 'feenschach', and I think one even by our problem friend M. Caillaud. IIRC the majoriy was in the "makes no sense-party" ... (2018-4-2)
A.Buchanan: As far as I know, there has never been versioning or after for any economy record construction. I kind of like these problems where there are more composers than pieces on the board, and that would be impractical unless all are equal co-authors. And PDB doesn't support versioning/after properly anyway. (2018-4-2)
comment
Keywords: Type C, Last Move? (LxD), Economy record
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2012-4-15 more...
8 - P0000965
Thomas R. Dawson
(86.) The Fairy Chess Review 7, p. 78, 08/1937
P0000965
(3+8)
Letzter Zug?
R: 1. b6xLa7
play all play one stop play next play all
Henrik Juel: A possible retroplay is
-1.b6xLa7 Lb8 -2.a5xSb6 Sd5xSb6 -3.Sc4,
then extract the kings via b6, etc. (2018-4-2)
comment
Keywords: Type A, Last Move? (BxL), Economy record, Type B (a fortiori)
Genre: Retro
Reprints: A/30 feenschach 159, p. 78, 04-06/2005
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-4-3 more...
9 - P0000972
Vilhelm Röpke
Albrecht Brandis
Hugo August
Thomas R. Dawson
Richard Steinweg
Hugo Rohr
Valerian Onitiu

1) Skakbladet 08/1924
P0000972
(6+1)
Letzter Zug?
R: 1. Kd1xSc1
play all play one stop play next play all
Henrik Juel: This position was actually submitted by V. Røpke only, according to the comment by tournament director Niels Høeg (p.88); the other authors had a black DTL on a1, but Høeg liked this position best, and it is the most well-known from the tourney
V. Røpke was an actuary and the strongest Danish solver for many years, and he never used his first name, so in talk others did not either, but called him Røpke; I was 15 when I met him, so I called him Mr. Røpke... (2018-4-2)
more ...
comment
Keywords: Last Move? (KxS), Type A
Genre: Retro
Reprints: Rund um das Schachbrett 1955
385 Arbeiter-Zeitung (Wien) 05/04/1959
RA17 diagrammes 16 08/1975
A7b Length Records in Last Single Moves? , p. 4, 11/2009
1429 Problemskak 30, p. 20, 04-06/2015
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2015-7-8 more...
10 - P0001162
Luigi Ceriani
36 Europe Echecs 24 08/1960
P0001162
(11+15) cooked
Löse die Stellung auf!
Brassaud: Les pions noirs en b3-b5 et c4 ont fait 3 prises, le Fou blanc a été pris en f1 et un pion blanc pris colonne h. Intention de l’auteur : rétro jeu 1) d4xDe5+, Dg3 2) d3, Te6 3) d2, Te4 4) Th4, Tg4e4+ 5) Th5, h7 6) Th4, Ta4 7) Th5, Ta1 8)Th4, Tc1 9) Th5, Tc3 10) Th4, Te3 11) Th5, Te6 12) Th4, Tg6 13) Th6, Te6 14) Tg6, b4 15) Tg8, Th6 16) Tf8 Tg6xh6 17) Th8, Tg8 18) h5, Td8 19) Tg8, Td7 20) Th8, Tc7 21) Fb8, Ca7 22) Tc8, Td7 23) Tc7c8+, Cc8 24) Fa7, Td8 25) Tb7, Td7 26) Tb8, Tb7 27) Ta8, Tc7 28) Fb8, Ca7 29) h4, Cc8 30) Ta3, Ca7 31) Td3, Cc8 32) Td4, Da3 33) Tf4d4+
La dame blanche peut sortir, la Tour noire en c7 peut regagner la case h8 et le Fou noir la case f8. On peut alors reprendre g7-g5 etc …
Une bien belle balade de tours, mais qu’elle est la démolition ? (2017-10-17)
Henrik Juel: Cook:
-1.d4xDe5 Dg3 -2.d3 Te6 -3.d2 Te3 -4.Th4 Tg4, retract Tb4 to g6, -12... h7 -13.Th6 Te6 -14.Tg6 Te3! -15.Tg8 Te6 -16.Tf8 Th6 -17.Tg8 Tg6xPh6 -18.Th8 Tg8 -19.h5 Td8 -20.Tg8 Td7 -21.Tf8 Tc7 -22.Lb8 Sa7 -23.Tc8 Td7 -24.Tc7 Sc8, retract Tc7 to a8, Td7 to c7, -28.Lc8 Sa7 -29.h4 Sc8
In the intended solution Black wasted b4-b3 at -14., forcing White to retract Ta8 to f4 to release the SE corner, but in the cook this also works:
-30.T=a7 b4 -31.a6 Sa7 -31.a5 a6xTSb5 etc. (2017-10-17)
Mario Richter: A much more simple cook is:
R: 1. d4xDe5+ Dg3-e5+ 2. d3-d4 Tg7-g6 3. d2-d3 Dh4-g3! 4. Kf4-f5 g6-g5+
which completely avoids the retro-opposition trouble in the north-west corner, so we first should check, if the given position is correctly typed into the PDB. Is it eg. in one of the Ceriani-books? (2017-10-17)
Brassaud: Remerciements pour ces explications ! (2017-10-17)
Gerald Ettl: Korrekturversuch:
Weiss:Bb6c6d3a2e2f2g2 La7 Tc5g4 Dh2 Kf5 Schwarz:Be7f7h6b5d5g5c4a3 Sc8h1 Lh3g1 Te6g6 De5 Kd6
R: 1.Dg3e5+ d2d3 2.Te4e6 Th4g4 3.Tg4e4+ Th5h4 4.h7h6 Th6h5 5.Te6g6 Tg6h6 6.Te3e6 Tg8g6 7.Te6e3 Tf8g8 8.Th6e6 Te8f8 9.Tg6xBh6 Th8e8 10.Tg8g6 h5h6 11.Td8g8 Tf8h8 12.Td7d8 Th8f8 13.Tc7d7 Lb8a7 14.Sa7c8 Tc8h8 15.Td7c7 Tc7c8+ 16.Sc8a7 La7b8 17.Td8d7 Tb7c7 18.Td7d8 Tb8b7 19.Tb7d7 Ta8b8 20.Tc7b7 Lb8a7 21.Sa7c8 h4h5 22.Sc8a7 Ta4a8 23.Sa7c8 Tb4a4
wT nach f4 (2018-6-24)
comment

Genre: Retro
Input: Gerd Wilts, 1995-6-3
11 - P0001243
Aleksey A. Troitzky
Vladimir Korolkov

(1) Problem 41-44 03/1957
1. Preis
P0001243
(9+12)
Ist die Stellung legal?
Die Stellung ist legal:

R: 1. Kf8-e8 2. Kg8-f8 3. Kh7-g8 4. Kg6-h7 5. Kf5-g6 6. Ke5-f5 7. Kd5-e5 8. Kc4-d5 9. Kb3-c4 10. Kc2-b3 11. Kd1-c2 12. Ke1-d1 13. Kf2-e1 14. Kg1-f2 15. Kf2xTg1
play all play one stop play next play all
Henrik Juel: The long march by black king to uncapture [Th1] was shown in 1930 by Niels Høeg, P0001754 (2018-2-23)
Henrik Juel: ...
But there might exist an even earlier problem by Troitzky, who died in 1942, so this problem must be a version by Korolkov (2018-2-23)
Mario Richter: In his article in 'Problem (Zagreb)' Korolkov mentiones, that in the last years of Troitzky's life, when he lived in Leningrad, Korolkov often visited him and they "not only dealed with the construction of endgame studies, but also of retrograde analysis problems."
Someone with better knowledge of the russian language might perhaps provide more details ... (2018-2-24)
Henrik Juel: So this problem may be a joint composition, although it seems strange that it was published 15 years after Troitzky's death (2018-2-24)
A.Buchanan: According to Wikipedia sadly, Troitsky died of starvation in 1942 in the siege of Leningrad. With all the disruption, perhaps not surprising that publication of this problem was delayed. What was the story of Korolkov's life? Did he leave Leningrad before the siege, or did he survive it? (2018-2-24)
VL: Well, Andrew, VK worked (for appr. 50 years) as an electrical engineer at the famous Kirov plant. Afaik, during the WWII he evacuated together with the plant to Ural (to the so-called Tank City near Chelyabinsk). (2018-2-25)
A.Buchanan: Thank you, Valery. That's quite moving. (2018-2-25)
comment
Keywords: Promenade (k), Non-standard material, Promotion (t), Volet Pawn (extended)
Genre: Retro
Reprints: Problem 61-64 07/1959
528 FIDE Album 1956-1958 1961
116 Europe Echecs 67-68 08/1964
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-24 more...
12 - P0001360
Max Lange
885 Deutsche Schachzeitung , p. 61, 02/1858
P0001360
(8+5) C+
#3
1. dxc6ep+! Kd5 2. Sf2 droht 3. Sc7#
2. ... bxc6+ 3. Lxc6#
play all play one stop play next play all
Originalforderung: Weiß zieht und soll auf die kürzeste Weise matt setzen. Matt in wieviel Zügen?

See also P0002092.
VL: The very first retro problem...
The author is presumably Max Lange,
as John Beasley (jointly with Hanspeter Suwe)
determined. See his article on the â??en passant keyâ?�
in The Problemist, May 2004 (pp. 391-392) and
Sept 2004 (p. 459). See also Chess Note 4417 (June 2006) in
http://www.chesshistory.com/winter/ . (2008-11-30)
Mario Richter: The list of contents (p.VIII) for the year 1858 explicitely gives Max Lange as the author of this problem. So could we really say, that the author is 'anonym'? (2010-12-9)
Henrik Juel: Only possible last move is c7-c5
C+ by Popeye 4.61 (2017-9-9)
Henrik Juel: A direct link to Chess Note 4417 is
http://www.chesshistory.com/winter/winter23.html#4417._Zukertort_problem_C.N._4042
But is does not provide new information (2017-11-9)
Henrik Juel: Without the ep key, the shortest mate is in 4 moves
unfortunately with many possible keys 1.Le8,Lc8,Sf6,Se5,Lxc5+
e.g., 1.Sf6 exf6 2.Lf5 Kxd5 3.Sc7+ Kd6 4.Lxc5#
or 1.Lxc5+ Kxd7 2.Txe7+ Kd8 3.Sf6 Kc8 4.Te8# (2018-3-1)
comment
Keywords: En passant, En passant as key
Genre: Retro
Computer test: Popeye 4.61
Reprints: Deutsche Schachzeitung , p. 313, 10/1906
53 Retrograde Analysis 1915
234 Europe Echecs 140-141 10/1970
RA1 diagrammes 11 10/1974
(A) feenschach 154 2004
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-9-12 more...
13 - P0001373
Aleksey A. Troitzky
95A Retrograde Analysis 1915
P0001373
(13+13)
#4
1. dxe6ep Txb8+ 2. Kxb8 ... 3. Dxf7+ Kd8 4. Dd7+
UWF: Lb8 und ein sT.
Umwandlung des wBh2 auf h8, weiße Schlagfälle: cxd, f2xe3, gxf; schwarze Schlagfälle: wLc1, hxg, gxh. R: 1. e7-e5 f2xD(S)e3
play all play one stop play next play all
Henrik Juel: -1... e7 -2.f2xSe3 Sc2 -3.Kc7 Sb4 -4.Kc8 Sc6 -5.Le5 Sb8 -6.Kc7 Sc6 etc., not -1... e6? with wrong tempo. (2004-3-8)
AV: Cook : 1 Dxf7+ ... 3# (2006-4-1)
VL: Apparently, a misprint in the original position: BQ should
stand on h8 instead of R. Among the other 199 problems in
this classic book, none contains non-standard material!
Anyway, BPc7 promoted on c1. The parity (odd-even) effect. (2006-4-7)
VL: No, sorry, Qh8 doesn't repair the problem...
Moreover, there is a dual: 2.Kxb8 or Kc7. (2006-4-8)
Yoav Ben-Zvi: The #4 cannot be salvaged so the stipulation needs to be changed. "White to move. Last move?" is simplest. To retain the e.p. element requires something like "White to move. How many of the BPs can be captured on the first move?".
With such a stipulation BRh8 can (and should) be replaced by BQ. Without a BR obviously promoted on c1 it needs to be shown that White cannot break the tempo by retracting either WPc4xBd5, since then [BPc7] must but cannot unpromote on c1, or WPc4xPd5 since Black captured WB on c1 and the WNs by BPhxg (allowing [WPh2] to promote without capture on h8) followed by BPgxh so it cannot play BPcxd. (2017-12-27)
comment
Keywords: En passant, En passant as key, Non-standard material, Promotion
Genre: Retro
Reprints: 247 Europe Echecs 150 07/1971
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-8-10 more...
14 - P0001506
Michel Caillaud
379 Europe Echecs 265 01/1981
Dr L. Ceriani zum Gedenken
1.-2. Preis e.a.
P0001506
(14+10)
#1 (wer?)
Henrik Juel: With stipulation '#1 (who?)' the solution is: 1... Sg5#, not 1.Re1??, because Black has the move. -1.Sc3 Sf6 ... -5.Sb6 Sa1 -6.Sc8 S=a2 -7.Sb6 a3 -8.Sc8 a4 -9.S=c7 a5 -10.b6xP a6 -11.a5xQ Qb3 -12.a4 Qd1 -13.c2xP d4 -14.g5 e5xS -15.Sb3 Qe1 -16.Sc5 Qd1 -17.Sd3 a7 -18.Se1 e6 -19.Sg2 Qf1 -20.Re1 e7 -21.fRe2 Rf2 etc. To open the cage we need a man on f1; the only possibility is a bQ, uncaptured on b6. But then we also need a man to screen on g2; uncapturing a bS on d3 and retracting it to g2 is too slow, so on d3 we uncapture a bP, which in turn on d4 uncaptures a wS, which screens on g2. A very good and difficult retro. (2003-4-25)
Yoav Ben-Zvi: The side-to-move is determined by the Retro opposition that occurs when the uncaptured WN needs to retract to e1 (on its way to g2) while the uncaptured BQ shuffles between e1 and d1. (2018-4-3)
comment
Keywords: Whose move?, Retro Opposition
Genre: Retro
Reprints: 970 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2006-10-22 more...
15 - P0001517
Michel Caillaud
389v Europe Echecs 271 07/1981
Lob
P0001517
(12+9)
h#2
Henrik Juel: Solution: 1.g5 hxg8=QR 2.gxf4 Kd2#, not 2... 0-0-0??.
Only if White had the move would he be entitled to castle: -1... h5 -2.Sf2 h6 -3.Sd3 Kh1 -4... Bg1 -5... Kh2 .. -8... Kh5 -9... Bh2 -10.Sf2 Bg3 -11.h2 Bh4 -12.Sd3 Bf6 etc. (2003-3-31)
Yoav Ben-Zvi: The need for a tempo move (by WK or WR) arises because WN needs to stand on f2 when Black retracts Bg3-h2. I dont think this is Retro opposition because the role of the WN is positive (Retro Shield) rather than negative. (2018-4-3)
Henrik Juel: Now I notice that Ph7 is a so-callet Volet pawn (coming diagonally from c2)
The definition of Retro Opposition in the latest Album (2010-12, p.620) is:
'In a particular phase of the retro-play it can be proved which side is to play, despite there being mobile units on both sides.' (2018-4-3)
Mario Richter: The position can also be easily resolved by an early retraction of f3-f4, in this case wK had to move earlier in the game not because of RO but to let original wRook h1 out ... (2018-4-5)
Yoav Ben-Zvi: The FIDE Album Theme Index tries to save space so the definitions contain only what is deemed to be the essential core of the theme. In some cases, such as the definition for Retro Opposition, this is carried too far and an essential characteristic is left out. To see this note that the definition (given above) does not distinguish Retro Opposition from the Parity Argument theme. Unless Parity is considered to be a particular type of Retro Opposition, the FIDE Album definition must be rejected.
I think that any satisfactory definition of RO will state that a thematic retraction is prevented (not enabled) by certain circumstances. If this is the case then I see no Retro Opposition here. (2018-4-9)
comment
Keywords: Cant Castler, Retro Opposition, Castling (wg), Volet Pawn
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-4-3 more...
16 - P0001524
Michel Caillaud
396 Europe Echecs 261/262 09/1981
1.-2. Preis e.a.
P0001524
(14+11)
Wer ist am Zug?
R: 1. Sa2-c1 h7xSg6 2. Sf8-g6 Lc1-d2 3. Se6-f8 Ld2-c1 4. Sc5-e6 Lc1-d2 5. Sb7xBc5 Ld2-c1 6. Sd6-b7 Lc1-d2 7. Sb5-d6 Ld2-c1 8. Sa3-b5 Lc1-d2 9. Sb1-a3 Kh2-h1 10. Sd2-b1 Kh3-h2 11. Kg1-f1 c6-c5 12. Sf1-d2 Ld2-c1 13. Sh2-f1 Lc1-d2 14. Tf1-e1 c7-c6 15. 0-0 Dg2-f3 16. Tf3-e3 Le3-c1 17. Sc1-a2 Ld4-e3 18. Te3-f3 Lg7-d4 19. f3-f4
play all play one stop play next play all
Weiße Schläge: hxg; gxf; dxe; axb. Schwarze Schläge: hxg; dxc. Schwarzer Bc7 wurde auf seiner Linie geschlagen, sBa7 wandelt sich auf a1 um. Schwarz ist am Zug.
Yoav Ben-Zvi: The side-to-move is determined by 2 Retro oppositions: The BB is prevented from retracting to d2 when the WN stands there on its way to h2 and White un-castling is prevented with BB standing on d2. The 2 tempo moves provided by a BP that is uncaptured on c5 are not enough to overcome both oppositions if the diagram position is White-to-move. (2018-4-3)
comment
Keywords: Retro Opposition, Castling (wk), Whose move?
Genre: Retro
Reprints: 972 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-4-3 more...
17 - P0001535
Michel Caillaud
407 Europe Echecs 286 10/1982
Roger Diot zum Gedenken
3. ehrende Erwähnung
P0001535
(13+11)
#1
R: 1. Se6-g5 Sc6-b8 2. Sc7-e6 Sd4-c6 3. Sa8-c7 Sb3-d4 4. a7-a8=S Sc1-b3 5. a6-a7 Sb3-c1 6. a5-a6 Sc1-b3 7. a4-a5 Sb3-c1 8. Se6-f8 Sc1-b3 9. Sc7-e6 Sb3-c1 10. Sa8-c7 Sc1-b3 11. a7-a8=S Kg6-h6 12. a6-a7 c2-c1=S 13. a5-a6 c3-c2 14. b4xBa5 c4-c3 15. c3xLb4 Ld6-b4 16. c2-c3 Lf4-d6 17. a3-a4 Lh6-f4 18. a2-a3 Lf8-h6 19. h6-h7 g7xSf6
play all play one stop play next play all
Schwarz Schläge: gxf6; hxgxf. Weiße Schläge: dxe3; exf3; fxg; cxbxa. Der schwarze Bauer a7 wurde auf seiner Linie geschlagen. Um die Stellung aufzulösen, muß der sLf8 über h6 auf sein Ausgangsfeld zurückgespielt werden. Schwarz ist am Zug.
Yoav Ben-Zvi: When the second unpromoted WP uncaptures a BB on b4 it must retreat in all haste to f8 so that BK must stand on g6 (not h6) and unpromoted BP must stand on c4 (not c5). This determines the side-to-move in the diagram position. Is it justified to consider a conflict between pieces of the same color a Retro opposition? (2018-4-3)
comment
Keywords: Retro Opposition, Promotion
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-4-3 more...
18 - P0001547
Andrey Frolkin
Andrej N. Kornilow

418 Europe Echecs 292 04/1983
dedicated to K P Q N N P B R
1. ehrende Erwähnung
P0001547
(27+0)
Das Brett ist nicht gefärbt.
1) Färbe das Brett,
2) Bestimme die Art und Farbe der Steine,
3) Welches war der letzte Zug?
4) Wem ist das Problem gewidmet?
hans: Turn board 90°
Last move 0-0+
White:Kg1,Tf1,Te1,Lb6,Sf7,a5,b4,c3,d2,d7,f2,g2,g7, (13)
Black:Kc1,Da8,Ta4,Lb2,Sa2,Sb3,a7,b7,c5,d4,e5,f4,g3,(14)
captures White: exd hxg Black: fxe gxf hxg (5)
A=Bauer C=König D=Toren I-Dame L=Springer U=Laufer
For 4) probably a name with those six letters A-C-D-I-L-U (2012-2-22)
Henrik Juel: The answer to part 4) is, I think, Michel Caillaud, as his last name only uses the six letters in the problem (2012-2-22)
Alain Brobecker: Dedication was given with pieces symbols. This eases things a lot! (2012-2-22)
Brassaud: Wem ist das problem gewidmet ? My ‘april fool ‘solution.
Probably a name with those six letters : KPQNNPBR … for King, Pawn, Queen etc … Which suggests: ACDILU and so Michel CAILLAUD. But this is a code, and there is no reason to say that it is not the coding of other letters.Chess problem Data Base Server contains several ' retro ' problem authors whose names contain 6 different letters.
When classifying by number of published problems, we can find : M. Caillaud, L. Ceriani, T. Dawson, W. Dittmann, T. Steudel, A. Kisljak, A. Buchanan, G. Donati, T. Kardos, N. Dupont, W. Frangen, D. Baibikow, E. Bartel, P. Kniest, M. Richter etc. .. (and even, but very far behind : F. Brassaud)- So everyone has to make a choice. (2017-12-9)
Henrik Juel: Curious that so many well-known composers happen to have exactly six different letters in their last names (2017-12-9)
Olaf Jenkner: Footballers have eleven different letters in their last names. (2017-12-9)
comment
Keywords: Last Move?, Castling (wk)
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alain Brobecker, 2012-2-22 more...
19 - P0001555
Philippe Serfati
426 Europe Echecs 301 01/1984
P0001555
(12+14)
#1
Welches war der letzte Zug des weißen Königsläufers?
Brassaud: White : dxe, hxg - Black : exdxcxbxa
White checkmate : Qe5#
Rétro : 1)… a2=S 2) b2, b3xa2 3) De4, cxSb3 3) Td2, dxLc4 4) Lf1 (last move), d6 5) e2, Ld4 …. (2017-12-11)
comment
Keywords: Last move of a specific piece?, Non-standard material
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-8-10 more...
20 - P0001566
Andrey Frolkin
436 Europe Echecs 307 07-08/1984
Lob
P0001566
(22+0)
Färbe die Steine! Welches war der letzte Zug?
Henrik Juel: White: Kg8, Qh8, Bf8,g3, Pa2,a6,b3,c2,d2,f2,h7 (11+11). -1.B=g7:S. (2003-11-20)
Brassaud: The solution proposed by Henrik does not seem appropriate. White: Kg8, Qh8, Bf8,g3, Pa2,a6,b3,c2,d2,f2,h7. So : Queen g8 and one of the two bishops are promotions, and seven pawns ?
Whatever the color of the pieces : on the diagram there are eleven pawns, at least three queens promotion and two bishops promotion (four bishops on black fields). Total sixteen pawns (or equivalents after promotion). So there is the necessary presence of the two originals queens.
The queen in g8 is a white promotion (last move g7xh8 = D +)
If the king f6 is black: the queens d6 d8 f4 and h6 are black. The white queen from e1 is absent.
If the king f6 is white: the queens d6 d8 f4 and h6 are white. This is the black queen from e8 who is absent.
Could this be a diagram error (2017-12-13)
Brassaud: erratum : queen in h8 (2017-12-13)
Mario Richter: Henrik's solution is absolutely legal - wQh8 is the original wQueen and last move was: g7xSf8=L+. (2017-12-13)
Brassaud: Sorry I had not understood the last move B=g7:S, it's easier with g7xSf8=L+. Thank you Mario. (2017-12-13)
Henrik Juel: In my uninformed youth I wrote in English, also for the men (S=knight), with very abbreviated notation in retroplay
-1.B=g7:S reads 'bishop unpromotes (=) to g7, uncapturing (:) a knight' (this is sufficient, as there is no bishop on h8)
Nobody else thought this was a good idea, and now I use KDTLSP for the men and full notation for uncaptures, e.g., -1.g7xSf8=L
Sorry about the confusion, Francois (2017-12-13)
Henrik Juel: For this enjoyable problem I should also have written the pawn play, like
White: e2xd3x..xa6, g7xSf8=L
Black: c3xb2, dxe, fxe, e1=D three times, gxh, hxg, g1=L (2017-12-13)
comment
Keywords: Last Move?, Coloring problem, Promotion
Genre: Retro
Input: Gerd Wilts, 1995-6-3
21 - P0001568
Michel Caillaud
438 Europe Echecs 310 10/1984
Lob
P0001568
(12+13)
h#1,5*
* 1. ... ... 2. 0-0-0 Tb8#
1. ... d6 2. Lf7 (nicht 0-0-0?) Tb8#
play all play one stop play next play all
Schlagfälle und Umwandlungen: axb, bxc, cxd, h=; dxc, exf, fxe, hxg, a=
Henrik Juel: Maybe the stipulation should be h#1: 1.0-0-0 Rb8#. The castling is preserved by -1.Bb8 Ba5 -2.Kg1 Bb6 ... -10.Kb4 Bb6 -11.Ka5 Ba7 -12.Ka6 g4 -13.Kb7 Bb6 -14.Kc6 Ba5 -15.Rb6 Ba6 etc. (2003-4-14)
Michel Caillaud: Correct stipulation : h#1,5*
Set : 1.0-0-0 Rb8#
Play : 1...d6 2.Bf7 (not 0-0-0?) Rb8# (2003-4-15)
Yoav Ben-Zvi: Release of the position without moving BK and BRa8 requires that WK retracts to c6 (to shield the BK from WBa4) via a3,b4,a5,a6,b7. When WK is retracted from a5 to a6, BB must be standing on a7 (to shield WK from BRa8) and Black must respond with retraction of BPg4-g3. This implies that, when WK is retracted from b4 to a5, BB cannot stand on a7 (as Black would then need to use his only tempo retraction too early) so it stands on b6 while WB stands on b8 (WB cannot stand on a7 as this would be a Retro-opposition preventing Black's following retraction BBa7-b6). WK does not have a triangulation available on the retro-path from h1 to b4 so the configuration of WKb4, WBb8, BBb6, BPg3 with White to play the next retraction can only be achieved, under the assumption of Black retaining castling rights, if it is Black to move in the diagram position. This means 0-0-0 is available in the set play but not in the solution (reversed because of the H#1.5 stipulation). (2018-4-5)
comment
Keywords: Cant Castler, Retro Opposition, Castling (sg)
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-4-6 more...
22 - P0001598
Michel Caillaud
468 Europe Echecs 334 10/1986
P0001598
(15+11)
#1 (wer?)
1. ... c1=S# (1. Sxb3#??)
R: 1. Sg2-e1 La2-b1 2. Sh4-g2 Lb1-a2 3. Sg6-h4 La2-b1 4. Sh8-g6 Lb1-a2 5. Sf7-h8 La2-b1 6. Sd8-f7 Lb1-a2 7. Sc6-d8 La2-b1 8. Sb4-c6 Lb1-a2 9. Sa2-b4 b4-b3 10. Sc1-a2 ... 11. Se2-c1 ... 12. Sg3-e2 ... 13. Sh5-g3 ... 14. Sg7-h5 ... 15. Se8-g7 ... 16. Sc7-e8 ... 17. Sa8-c7 ... 18. a7-a8=S ... 19. a6-a7 ... 20. a5-a6 ... 21. a4-a5
play all play one stop play next play all
Springerkreisel
Henrik Juel: Black has the move; the retroplay is -1.Sg2 Ba2 ... -8.Sb4 Bb1 -9.Sa2 b4 -10.Sc1 Ba2 ... -17.Sa8 ... -18.S=a7 etc. (2003-4-22)
Renny Bosch: Aside from that sensational 1 5/8 full circle Knight tour, this composition has some additional challenges. One never really knows one has seen all of a composition's beauty until one has actually produced a proof game. In this case a pawn analysis shows that white Pawns h and g have captured on g and f, exd, dxc, cxb6, bxc3, and a has promoted, black Pawn a has captured on b, and h has promoted. The question is, what happened to the piece that the black h Pawn promoted to? It cannot be one of the pieces still on the board, so it must have been one of the white Pawn capturees, but which one? The only way to unlock the central cluster is to uncapture a white Knight on b5, then walk the bK to b5 and the wQ to d4, after which the wPd6 can uncapture from e5.

Here is a PG (as pretty as I could make it) that shows the whole thing: 1. a4 b5 2. c4 c6 3. c5 Qb6 4. cxb6 c5 5. Ra3 c4 6. Re3 c3 7. Re6 c2 8. e4 Na6 9. e5 Nc5 10. a5 Na4 11. h4 Nc3 12. bxc3 Bb7 13. Ba3 Bd5 14. Bc5 Bb3 15. Be3 b4 16. g4 Rc8 17. g5 Rc4 18. Qe2 Re4 19. Qd3 Kd8 20. Qd4 Kc8 21. Bc4 Kb7 22. Bd5+ Ka6 23. Ke2 Kb5 24. Kd3 f5 25. Rh2 f4 26. Rg2 f3 27. Rg3 h5 28. Rg4 Nf6 29. gxf6 g5 30. Rf4 g4 31. Ne2 Rg8 32. Ng1 Rg5 33. Ne2 Rf5 34. Ng1 Bh6 35. Ne2 Bg5 36. hxg5 h4 37. Ng1 h3 38. Ne2 h2 39. Ng1 h1=Q 40. Ne2 Qh8 41. Ng1 Qb8 42. Ne2 Qd6 43. exd6 a6 44. Qe5 Ba2 45. Nd4+ Kc5 46. Na3 Bb1 47. Nab5 axb5 48. a6 Ba2 49. a7 Bb1 50. a8=N Ba2 51. Nc7 Bb1 52. Ne8 Ba2 53. Ng7 Bb1 54. Nh5 Ba2 55. Ng3 Bb1 56. Nge2 Ba2 57. Nc1 Bb1 58. Na2 b3 59. Nb4 Ba2 60. Nbc6 Bb1 61. Nd8 Ba2 62. Nf7 Bb1 63. Nh8 Ba2 64. Ng6 Bb1 65. Nh4 Ba2 66. Ng2 Bb1 67. Ne1 (2007-12-11)
Brassaud: Fantastic ride of the white knight, bravo Michel Caillaud. Yes we can unpromote rook e4 still present on the board. PG 1) c4, f5 2) Sh3, f4 3) Sg1, c6 4) Dc2, b5 5) Db3, Sa6 6) Da4, Sc5 7) Dd1, Se4 8) c5, Sd6 9) g4, Sf6 10) g5, Tg8 11) g5xSf6, g5 12) e4, g4 13) e5, Lb7 14) Se2, Db6 15) c5xDb6, c5 16) e5xSd6, c4 17) a4, Tg5 18) h4, Tf5 19) Th3, Lh6 20) Te3, Lg5 21) Te6, Le4 22) Sc3, Lb1 23) Sd5, c3 24) Sg3, c2 25) a5, O-O-O 26) Sc7, Kb7 27) Sa8, Tc8 28) h4xLg5, Tc3 29) b2xTc3, h5 30) Lg2+, Ka6 31) Ld5, h4 32) Ke2, f3+ 33) Kd3, h3 34) Ta4, h2 35) Tf4, h1=T 36) De2, Th8 37) De5, Tc8 38) Se2, Tc4 39) La3, Te4 40) Lc5, b4 41) Le3, Kb5 42) Sd4+, Kc5 43) Sc7, a6 44) Sb5, a6xSb5 (the cage is closed) 45) a6, La2 46) a7, Lb1 47) a8=S, La2 48) Sc7, Lb1 49) Se8, La2 50) Sg7, Lb1 51) Sh5, La2 52) Sg3, Lb1 53) Se2, La2 54) Sc1, Lb1 55) Sa2, b3! 56) Sb4, La2 57) Sc6, Lb1 58) Sd8, La2 59) Sf7, Lb1 60) Sh8, La2 61) Sg6, Lb1 62) Sh4, La2 63) Sg2, Lb1 64) Se1, … c1=S# (2017-12-16)
Yoav Ben-Zvi: A similar concept appears in P0001979. (2017-12-18)
more ...
comment
Keywords: Whose move?, Retro Opposition, Promotion, under-promotion (S)
Genre: Retro
Reprints: Die Schwalbe 120 12/1989
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-18 more...
23 - P0001599
Leonid M. Borodatow
469 Europe Echecs 334 10/1986
A. Hazebrouck gewidmet
P0001599
(10+15)
#1
AV: Les Noirs ont le trait et matent par ...g3#. Derniers coups : 1 e3-e4 (ou d3xCe4) Ce5-d7+ 2 e4-e5 Cd7-f6 3 b2-b3 Cf6-e8 4 a2-a3 Tc3-f3+ 5 Rf4-e4 Tf3xb3+ 6 Re4-f4 Tb3-f3+ 7 Rf4-e4 Tf3xa3+ 8 Re4-f4 Ta3-f3+ 9 Rf4-e4. (2005-6-27)
Brassaud: Alain Villeneuve proposes : 1)Kf4e4, Ta3f3+ 2)Ke4f4, Tf3xa3+ 3)Kf4e4, Tb3f3+ 4)Ke4f4, Tf3xb3+ 5)Kf4e4, Tc3f3+ 6)a2a3, Sf6e8 7)b2b3, Sd7f6 8)e4e5, Se5d7+ Then he proposes d3xSe4 or e3e4. I think that the sequence d3xSe4 is not legal : 9) d3xSe4, Sf6e4 ? 10) d2d3 What else? and the white bishop can not go back to c1. The only possibility is 9)e3e4, Ta3c3 10)Ke4f4, Sf3e5+ 11)Tf5d5 … (2017-12-17)
Henrik Juel: I think that both of Alain's suggestions work
-9.d3xSe4 Sd2! -10.Ke4 Sf3-d2 -11.Kf4 Tb3 -12.Ke4 and, e.g., -12... Sc6 -13.Tf5, and there is no more time pressure (2017-12-17)
Brassaud: Agree with you Henrik, it's an oversight on my part for the shield 10 Cd2f3 (I progress slowly taking advantage of my mistakes) (2017-12-17)
comment
Keywords: Whose move?, Uncapture of pieces by pieces
Genre: Retro
Input: Gerd Wilts, 1995-6-3
24 - P0001605
Dmitri W. Pronkin
Andrey Frolkin

475 Europe Echecs 337 01/1987
P0001605
(1+16) C+
BP in 17,0
1. d3 h6 2. Lg5 hxg5 3. h4 Txh4 4. a4 Txa4 5. Th6 Sxh6 6. g4 Sxg4 7. Lg2 Sxf2 8. Lc6 Sxc6 9. d4 Sxd4 10. c4 Sxe2 11. c5 Sxg1 12. c6 dxc6 13. Dd4 Dxd4 14. Ta3 Dxb2 15. Th3 Lxh3 16. Sc3 0-0-0 17. Sd5 Txd5= patt!
play all play one stop play next play all
Henrik Juel: Black makes 15 captures.
The first 13.0 moves are correct by Euclide 1.0, but it takes some 4 minutes, so a complete test would probably take more than a day (2014-12-9)
paul: Jacobi checked the last 16 moves (in about 20 min). (2018-5-10)
Mario Richter: I would like to label this problem as a "Massacre PG", but the current definition of that term only knows of two-sided MPGs. Perhaps we could make the same differentiation as for "Homebase"?!
Btw., wasn't "popeye" best for such massacres?
rawbats confirms complete correctness of the problem after approx. 25 minutes. (2018-5-11)
Henrik Juel: Yes, Mario, Popeye is fairly good at this type
C+ by Popeye 4.61 in 57 minutes (2018-5-11)
A.Buchanan: @Mario: yes I agree it would be good to make massacre more specific. There are 69 massacres currently, almost all 2-sided, but maybe also some series-movers (unique or non-unique) which are currently not counted? (2018-5-12)
comment
Keywords: Unique Proof Game, Castling, Homebase (w)
Genre: Retro
Computer test: rawbats
Reprints: 116 Shortest Proof Games 11/1991
20a 64 Proof Games 2012
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-5-11 more...
25 - P0001654
Andrey Frolkin
523 Europe Echecs 373 01/1990
M. Caillaud gewidmet
P0001654
(11+6)
#1 vor 8
VRZ, Typ Proca
Alex Levit: It looks like here is the short solution in a 5 moves. So may be there is a typo in the stipulation.

Black pawns where made 4 captures on the white squares, so only the dark-squared bishop could be uncaptured by a black officer.

R. 1.Be8xRh5 Rh3-h5+ 2.g5xh6 e.p. (2.Kd4-e5? Bd2xBe3+ and forward 1.Bc3#) h7-h5 3.Rf3xBf4 Bh2xBf4+ 4.Kd4-e5 Bd2-e3+
5.Sc4-b6 and forward 1.a3# or 4...Bc1-e3+ 5.Sc4-b6 and forward 1.c3# (2018-2-10)
comment
Keywords: Defensive Retractor, Type Proca
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2004-8-28 more...
26 - P0001664
Leonid M. Borodatow
533 Europe Echecs 373 10/1990
P0001664
(8+9)
Wer gewinnt?
Beispielauflösung (mri)
R: 1. Sa3-b1 e3xBd2 2. Sb5-a3 f4xLe3 3. Lc5-e3 g5xSf4 4. La3-c5 h6xDg5 5. Lc1-a3 h7-h6 6. b2xTc3 Tf3-c3 7. Sg6-f4 c3-c2 8. Lb3-d1 Tf8-f3 9. Lg8-b3 Ta8-f8 10. f7xDg8=L Dd8-g8 11. Df4-g5 Kd1-e1 12. Sd6-b5 Kc2-d1 13. Sc8-d6 Kb3-c2 14. Df1-f4 Kc4-b3 15. Dd1-f1 Kd5-c4 16. f6-f7 Ke6-d5 17. Kf1-g1 d4xBc3 18. c2-c3 Kf7-e6 19. Ke1-f1 d5-d4 20. Sb6xLc8 e6xBd5 21. c4xSd5 Se3-d5 22. b3xTc4 Sf1-e3 23. f5-f6 Ke8-f7 24. f4-f5 Se3xLf1 25. f2-f4 Tf4-c4 26. Sc4-b6 Tf8-f4 27. Sa3-c4 f7xTe6 28. Sb1-a3 Tg8-f8 29. Ta6-e6 Sd5-e3 30. Ta1-a6 Sf6-d5 31. a2xSb3 Sc5-b3 32. Sf8-g6 Th8-g8 33. Se6xLf8 Sg8-f6 34. Sf4-e6 Sa6-c5 35. Sh3-f4 Sb8-a6 36. Sg1-h3
play all play one stop play next play all
AV: Les Noirs ont le trait et gagnent. Derniers coups : 1 bxT(D,C)c3 h7-h6 2 Fc1-a3 hxT(D)g5 3 Fa3-c5 gxD(T)f4 4 Fc5-e3 fxFe3 5 Cb5(c4)-a3 exPd2 6 Ca3-b1. (2005-6-28)
hans: Dont think this solution is correct (Ld1 is promoted pawn on g- or e-line) (2018-5-24)
Henrik Juel: Good to hear from you again, Hans
I think that the AV solution is OK
With German-like notation the retroplay could be
-1.Sa3 e3xPd2 -2.Sb5 f4xLe3 -3.Lc6 g5xSf4 -4.La3 h6xTg5 -5.Lc1 h7 -6.b2xTc3
The other captures by White pawns were: a2xb3xc4xd5 and, e.g., f7xe8=L
[Pf7] went something like f7xDe6xPd5xPc4-c3-c2 (2018-5-24)
Henrik Juel: ... more precisely: a2xb3xc4 and cxd (2018-5-24)
Henrik Juel: ... and -3.Lc5, not Lc6 (2018-5-24)
comment
Keywords: Retro Opposition, Whose move?, Promoted material on the board
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-5-25 more...
27 - P0001722
Thomas R. Dawson
Charles Edward Kemp

5677 The Fairy Chess Review 8 10/1943
P0001722
(8+12)
h=Retropatt in 3
R: 1. Kf7xSe7 Sc8-e7 2. Kg8xTf7 Tc7-f7! 3. 0-0 Td7-c7 Retropatt
play all play one stop play next play all
Henrik Juel: Stipulation should be 'help-retrostalemate in 3'. -0... Kf7xSe7 -1.Sc8 Kg8xTf7 -2.Tc7! 0-0 -3.Td7 and Black is retrostalemate. Not a defensive retractor, but a help retractor with a weird aim. (2004-3-18)
Sally: Zurück:
1. Kd7xSe7? - Sg8-e7,
2. Kc8xTd7? - Tg7-d7,
3. O O O??? - Tfg7!
In der Verführung wäre die Rücknahme der langen Rochade illegal, da der w. Bauer a2 als Schlagobjekt im Osten gebraucht wurde und sich auf "a8" umwandelte. Somit musste der
schwarze Turm auf "a8" bereits gezogen haben! (2018-6-5)
comment
Keywords: Help retractor, Symmetrical position, Asymmetrical solution, Castling
Genre: Retro
Reprints: 336 FIDE Album 1914-1944/III 1975
H28 ASymmetrie 2013
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-5 more...
28 - P0001736
Harold Holgate Cross
2455 The Fairy Chess Review 10/1936
P0001736
(13+15)
Wer gewinnt?
1. ... Lg2#?
1. Sc3+! b1=D,T,L,S 2. Txb1#
play all play one stop play next play all
Brassaud: 0) …, Lh3 1) Tc1, Sg6 2) Td1, Sf4 3) Tc1, Sd3 4) Td1, Sc1 5) Sc3, Lf1 6) Sd5, Lh3 7) Sf4, Lf1 8) Sg6, Lh3 9) Sh8, Lf1 10) h7=S, Lh3 11) h6, Lf1 12) h5, Lh3 13) h4, Lf1 14) h3!, h4xDg3 15) Dd6, h5 16) g2, g3xSf2 17) Se4, Tf2 … retract black bishop on c8 and b6b7. Retract wK via g3 … (with 14) h2 ? the black king can’t escape from the south-west cage) (2018-1-31)
Henrik Juel: The problem appeared as no.2455, p.17, FCR Oct. 1936
The solution on p.25, FCR Feb. 1937 has this comment by TR Dawson
'.. an excellent double opposition, Sh4 and Bf1 v. Rcd1, followed by white S from b1 v. Bf1,h3'
(B,R are L,T in German) (2018-1-31)
comment
Keywords: Whose move?, Retro Opposition
Genre: Retro
Reprints: 221 FIDE Album 1914-1944/III 1975
(40) Die Schwalbe 72 12/1981
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-2-1 more...
29 - P0001739
Karl Fabel
9561 The Fairy Chess Review 06/1953
P0001739
(14+14)
Welches waren die letzten Züge?
R: 1. Tf1-h1 f6xSe5 2. Sf3-e5 Kh1-g2 3. Sg1-f3 Kg2-h1 4. Lc3-b2 Kh1-g2 5. Tb2-b1 Kg2-h1 6. Ta2-b2 Kh1-g2 7. Ta3-a2 Kg2-h1 8. Tb1-c1 Kh1-g2 9. Tb2-b1 Kg2-h1 10. Ta2-b2 Kh1-g2 11. Tb1-d1 Kg2-h1 12. Kd1-e1 Kh1-g2 13. Kc1-d1 Kg2-h1 14. Td1-f1 Kh1-g2 15. Kb2-c1 Kg2-h1 16. Tc1-b1 Kh1-g2 17. Kb1-b2 Kg2-h1 18. Tb2-a2 Kh1-g2 19. Ka2-b1 Kg2-h1 20. Tb1-b2 Kh1-g2 21. Kb2-a2 Kg2-h1 22. Ta2-a3 Kh1-g2 23. Ka3-b2 Kg2-h1 24. Kb4-a3 Kh1-g2 25. Ta3-a2 Kg2-h1 26. Tb2-b1 Kh1-g2 27. Ta2-b2 Kg2-h1 28. Tb1-c1 Kh1-g2 29. Tb2-b1 Kg2-h1 30. Sf3-g1 d5-d4 31. Th1-d1 Kf1-g2 32. Sg1-f3 Ke1-f1 33. Le5-c3 Kd1-e1 34. Kc3-b4 Kc1-d1 35. Kd3-c3 Kd1-c1 36. Ke3-d3 Kc1-d1 37. Kf3-e3 Kd1-c1 38. Kg2-f3 Kc1-d1 39. Kf1-g2 Kd1-c1 40. Sf3-g1 Kc1-d1 41. Tg1-h1 Kd1-c1 42. Tg8-g1 Kc1-d1 43. Kg2-f1 Kd1-c1 44. Kg3-g2 Ke1-d1 45. Sh4-f3 Kf1-e1 46. Kg4-g3 Kg2-f1 47. Sf3-h4 Kh1-g2 48. Th8-g8 Kg2-h1 49. Tb1-b2 d6-d5 50. Th1-b1 Kf1-g2 51. Sg1-f3 Ke1-f1 52. Kg3-g4 Kd1-e1 53. Kg2-g3 Kc1-d1 54. Kf1-g2 Kd1-c1 55. Sf3-g1 Kc1-d1 56. Tg1-h1 Kd1-c1 57. Tg8-g1 Kc1-d1 58. Kg2-f1 Kd1-c1 59. Kg3-g2 Ke1-d1 60. Sh4-f3 Kf1-e1 61. Kg4-g3 Kg2-f1 62. Sf3-h4 Kh1-g2 63. Tb2-a2 Kg2-h1 64. Tb1-b2 d7-d6 65. Th1-b1 Kf1-g2 66. Sg1-f3 Ke1-f1 67. Kg3-g4 Kd1-e1 68. Kg2-g3 Kc1-d1 69. Kf1-g2 Kd1-c1 70. Sf3-g1 Kc1-d1 71. Tg1-h1 Kd1-c1 72. Tg7-g1 Kc1-d1 73. Kg2-f1 Kd1-c1 74. Kg3-g2 Ke1-d1 75. Sh4-f3 Kf1-e1 76. Kg4-g3 Kg2-f1 77. Sf3-h4 Kh1-g2 78. Ta2-a3 Kg2-h1 79. Tb2-a2 Kh1-g2 80. Lf4-e5 Kg2-h1 81. Tb1-b2 f7-f6 82. Th1-b1 Kf1-g2 83. Sg1-f3 Ke1-f1 84. Kh4-g4 Kd1-e1 85. Tg3-g7 Kc1-d1 86. g7-g8=T Kb2-c1 87. g6-g7 Ka3-b2 88. Le5-f4 Kb4-a3 89. Lb2-e5 Kc5-b4 90. Lc1-b2 Kd6-c5 91. b2-b3
play all play one stop play next play all
weiter: Bg2xLh3, sLh3 nach c8, wT entwandelt auf a8, sBa6/7xS, wBhxsBg
hans: R: -1. Rf1-h1 f6xSe5 -2. Sf3-e5 Kh1-g2 -3. Sg1-f3+ Kg2-h1 -4. Bc3-b2 K -5.Rb2-b1 K -6. Ra2-b2 K -7. Ra3-a2 K -8.Rb1-c1 K -9. Rb2-b1 K -10. Ra2-b2 K -11. Rc1-d1 K -12. Rb1-c1 K -13. Kd1-e1 K -14. Kc1-d1 K -15. Kb2-c1 K -16. Re1-b1 K -17.Kb1-b2 K -18. Rb2-a2 K -19. Ka2-b1 K -20. Rb1-b2 K -21. Kb2-a2 K -22. Ra2-a3 K -23. Ka3-b2 K -24. Rb2-b1 K -25. Rb1-e1 K -26. Kb4-a3 K -27. Ra3-a2 K -28. Ra2-b2 K -29. Rb2-b1 Kg2-h1 -30. Sf3-g1 d5-d4 -31. Rh1-f1 Kf1-g2 -32. Sg1-f3+ Kg2-f1 -33. Bd4-c3 Kf1-g2 -34. Kc3-b4 Kg2-f1 -35. Kd3-c3 Kf1-g2 -36. Ke3-d3 Ke2-f1 -37. Kf3-e3 Kd1-e1 -38. Kg2-f3 Kc1-d1 -39. Kf1-g2 Kd1-c1 -40. Sf3-g1 Kc1-d1 -41. Se5-f3 Kd1-c1 -42. Rg1-h1 Kc1-d1 -43. Rg8-g1 etc.
Kd1-c1 -44. Rh8-g8 -45. Kg3-g2 Kc1-d1 -46. Kg2-gf1 Kd1-c1 -47. Kf3-g2 Ke1-d1 -48. Kf4-f3 Kf1-e1 -49. Sf3-e5 Kg2-f1 -50. Rb1-b2 d6-d5 -51. Rh1-d1 Kf1-g2 -52. Sg1-f3+ Ke1-f1 -53. Kf3-f4 Kd1-e1 -54. Kg2-f3 Kc1-d1 -55. Kf1-g2 Kd1-c1 -56. Sf3-g1 Kc1-d1 -57. Rg1-h1 Kd1-c1 -58. Rg7-g1 ------------ -95. ... Kb4-a3 -96. Bb2-e5 Kc5-b4 -97. Bc1-b2 Kd6-c5 -98. b2-b3 etc.
(wK and wS manoeuvre to let wRooks pass the bK, with the necessary bPawn tempo-moves) (2011-12-8)
Brassaud: A theme widely explored by Karl Fabel, confer problems P0001383 (1972) and P0001419 (1975) (2018-2-1)
comment
Keywords: Last Moves?, Castling (wk), Promotion (TT), Promoted material on the board, under-promotion
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-2-2 more...
30 - P0001759
Nikita M. Plaksin
The Problemist 1980
4. ehrende Erwähnung
P0001759
(8+6)
Welches war der letzter Zug?
Monochromes Schach
Brassaud: Last moves :
1) Kd5c4, e5xDf6 2) Df4f6 b3xTa4 3) Dg3 (e3) f4 a2xDb3 4) DxTg3(Tf3) …
Proof game :
1) c4, e5 2) Dc2, a5 3) Dxh7, Ta6 4) DxSg8, Tg6 5) Dh7, Le7 6) Dh3, f5 7) Dxf5, Lh4 8) De4, Lg3 9) h2xLg3, Tg4 10) Th5, De7 11) Tf5, Db4 12) Dc6, Dc3 13) Da4, DxLc1+ 14) Dd1, Dc3 15) Tf3, De3 16) Dc2, Dh6 17) Td3, Dh2 18) Dd1, DxSg1 19) Dc2, Dh2 20) Dd1, b5 21) Dc2, b5xc4 22) Dd1, c4xTd3 23) Dc2, Ta4 24) Dc4, d5 25) Dxd5, c5 26) Dc4, Th4 27) Dc2, Tf4 28) Dd1, g5 29) Dc2, d3xDc2 30) g3xTf4, c2xSb1=D 31) f4xe5, Df5 32) Tc1, Dh4 33) Tc3, Dh3 34) Ta3, Dh1 35) Tc3, DxLf1 36) Ta3, Dh1 37) Tc3, Dh3 38) Tc1, Db3 39) Tc3, Kd7 40) Tc1, Kc6 41) Tc3, Kd5 42) Tc1, Lf5 43) Tc3, Lg6 44) Tg3, DxTg3 45) a2xDb3, Df4 46) b3xTa4, Df6 47) e5xDf6, Kc4 (2018-2-3)
comment
Keywords: Last Move?, Monochrome
Genre: Retro
Reprints: RA158 diagrammes 73 09-10/1985
984 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2003-12-20 more...
31 - P0001848
Thomas R. Dawson
The Chess Amateur 1918
P0001848
(12+10)
Ergänze einen wT, dann #1
+wTb1? +wTc3!: 1. b3#
play all play one stop play next play all
Sally: Die w. Bauern haben 6 mal geschlagen, und zwar auch Bb7 nach Umwandlung Bb7 hat auf a2 einen w. Turm geschlagen.
Nr. 3 : Schach ohne Grenzen (Fabel & Kemp 1969). (2012-2-21)
Henrik Juel: Here is a detailed solution
White pawns captured all six missing black men by c2xd3x..xh7 (on light squares) and h2xLg3
Black captured [Lf1] at home and the remaining two missing white men by b3xa2 (to promote to D or S on a1) and g7xf6
The forward sequence was gxf6 before hxg3 before [Th1] could exit; but it could not reach a2, so [Th1] is still on the board (and the black pawns captured g7xSf6 and [Ta1] on a2 )
The only possible #1 is with [Th1] added on c3, as it could not reach b1 (2018-1-6)
Mario Richter: Henrik's analysis shows that it would suffice to stipulate: "Add a Piece, then #1". I would prefer this version since it gives the solver the chance to detect some more RA issues by himself (e.g. that the Piece to add can only be a White rook). (2018-1-16)
comment
Keywords: Promotion, Add pieces
Genre: Retro
Reprints: 107 Caissa's Wild Roses in Clusters 1937
3 Chess unlimited , p. 37, 1969
35 Die Schwalbe 71, p. 326, 10/1981
1 feenschach 143, p. 225, 08-10/2001
(F) The Problemist 07/2010
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-1-16 more...
32 - P0001863
Nikita M. Plaksin
Rex Multiplex 1985
3. Preis
P0001863
(13+12)
#1
hans: 1. e6-e7# (not 1. … Dxh5#)
R: -1. … Sd5-b6 -2. d7-d8=L Se3-d5 -3. c6xLd7 Sg4-e3 -4. c5-c6 Sh6-g4 -5. b4xLc5 Lg1-c5 -6. a3xLb4 g2-g1=L -7. a2-a3 g3-g2 -8. c3-c4 g4-g3 -9. c2-c3 g5-g4 -10. g4xSh5 De1-e2 -11. g2-g4 Sg3-h5 -12. Kh5-g6 Se2-g3+ -13. Kg6-h5 Ke7-f8 -14. Kh5-g6 Kd6-e7 -15. Tg6-g7 Tg7-h7 -16. Lh7-g8 and cage is open.
captures black: exf, fxe [Lc1] (2012-9-14)
Brassaud: Agree with Hans untill 12) .. Se2g3+ and then 13) Tg6f6, Tf6f5 and cage is open. (2018-3-2)
comment
Keywords: Promotion, Whose move?
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: hpr, 2001-3-18 more...
33 - P0001899
Fritiof Lindgren
Eskilstuna-Kuriren 1937
P0001899
(4+8)
#1 vor 5
VRZ, Typ Hoeg
R: 1. Kg8xTh8 Th3-h8+ 2. Kf8xDg8 Dh7-g8+ 3. Ke8xTf8 Tf3-f8+ 4. Kd8xDe8 Df7-e8+ 5. b6xSc7, dann 1. b7#
play all play one stop play next play all
Henrik Juel: The problem seems cooked as stated, so the type probably should be Høeg, where the opponent chooses which man (if any) to supplement on the abandoned square:
-1.Kg8:R Rh3 -2.Kf8:Q Qh7
-3.Ke8:R Rf1 -4.Kd8:Q Qf7
-5.b6:S (supplementing Q, R or B is now illegal), 1.b7#
If Black doesn't keep supplementing a checking man, he is mated at once with 1.c8=QR#. -2.Kf7?:B! (2003-2-24)
paul: Probably, this problem is by Fritiof LINDGREN (1997-1957), because Bo Lindgren was born in 1927. (2018-2-3)
paul: Of course, Fritiof was born in 1897, not 1997. (2018-2-3)
comment
Keywords: Defensive Retractor, Type Høeg
Genre: Retro
Reprints: 335 FIDE Album 1914-1944/III 1975
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-27 more...
34 - P0001901
Thomas R. Dawson
The Pittsburgh Gazette Times 1915
P0001901
(9+12)
Ergänze eine wD, dann #1
+wDe8: 1. Sc3#
R: 1. Ka3-a2 e7-e8=D
play all play one stop play next play all
Henrik Juel: Analysis
White pawns captured all four missing black men by axb, bxa, and cxbxa, and he promoted [Ph2] on h8 (and possibly [Pe2] on e8)
Black pawns captured all five (after addition) missing white men by e7xf6 and h7xPg6x...xc2
-1... Ka1 -2.Tb2 Kb1 -3.Ta2 Ka1 -4.Tb2 Ka2 -5.Tb1 leads nowhere, so -5... Ka3 D=Pe7 must happen sooner or later (2018-2-23)
Henrik Juel: all six, not five, of course (2018-2-23)
comment
Keywords: Add pieces, Promotion, Promotion in the retro play
Genre: Retro
Reprints: Arnhemsche Courant 24/12/1926
103 Caissa's Wild Roses in Clusters 1937
344 FIDE Album 1914-1944/III 1975
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-2-23 more...
35 - P0001970
Thomas R. Dawson
26 Kongreßbuch Teplitz-Schönau 1923
P0001970
(13+13)
h#1
1. exf3ep Lc2#
play all play one stop play next play all
1.exf3e.p. Bc2# is the only possible solution, but this necessitates R: 1.f2-f4. Can we prove this?

(13+13) with 1+2 pawn captures. Bf8 captured at home, so to satisfy White appetite, the missing Black pawn (a or b) must have promoted via c2 on c1. Two more White units must be captured to allow this.

The kings cage can only be unlocked by retracting WPc2. But the clock is ticking as there are only 6 black moves which can be retracted.

The promoted piece was captured on e3 or h3. If either capture is undone, then a White bishop square is cut off, so WB must be replaced prior to this.

Now the order of the early moves is: WdP moves, WQB & WQR escape, BP promotes on c1 to X (capturing WR at some point), X captured by WP.

So the first White capture must be dxNe3 and the second White capture releases gxXh3. The second White capture releases WKB & WKR. WKR captured by original BfP.

The clock starts ticking with gxh3. Black has 6 pawn moves. WKB has 3 moves to reach h7. WR has 3 if it goes via d file, or 2 if it starts on g1 (in which case WfP or WQB must also move once). So certainly at least 6 White moves. Last move was therefore White (even if the stipulation didn't tell us), and it can only have been WfP coming from f3 or f4. If it had been coming from f3 it would have blocked WKB in its progress, so the last White move was indeed R: 1.f2-f4.

WKR did therefore move from g1-g4-e4, and R: 1. ... fxRe5 2. Rg4-e4. Prior to that, move order not unique, but counting still exact.

Note that WN loitering on b4, pretending to be part of the cage, is present on the board just to make up the numbers.
Jeliss: "Obstruction of passage square f3 to Bishop of same colour."

"Version 'Pittsburgh Leader' 08.06.1913"
Henrik Juel: -1.f2 f5xTe4 -2.Tg4 f6 -3.Tg1 f7 -4.Le4 h5 -5.Lg2 h6 -6.Lf1 h7 -7.g2xDTSh3, unpromote DTS on c1, etc. (2004-3-18)
Henrik Juel: Nice analysis, Andrew, but your last comment seems incorrect.
Without Sb4, 1.b4 Txb4+ is not mate because of 2.Txb4#! (2013-7-26)
A.Buchanan: Thanks Henrik, I have fixed the solution. Forward chess is even harder than retro chess. And because Rb7 is retro-pinned, I overlooked that it's not forward-pinned! (2013-7-27)
Yoav Ben-Zvi: Appears as the first problem (D445) in the booklet on Dawson's RA problems by G.P. Jellis. The obstruction that occurs in the Try -1.Pf3-f4?, by WP of WB, is described as "obstruction of passage square". It is not considered by Dawson and his disciples to be a Retro opposition. Dawson's conception of RO was quite broad, it included cases where the interference was not by occupation of the target square, so the only valid reason that I can see to exclude this case is that the 2 pieces involved are both of the same color. Fabel's definition explicitly excludes "Monochrome RO". I conclude that it would be preferrable to interpret RO as a bi-chromatic interference. The keyword Retro opposition should be removed. (2018-4-7)
comment
Keywords: Last Moves?, En passant as key
Genre: h#, Retro
Reprints: D445 Retro-Opposition [Jelliss] 1989
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-4-9 more...
36 - P0001974
Thomas R. Dawson
Eskilstuna-Kuriren 1917
P0001974
(11+15)
#3
Henrik Juel: 1.Tb5 Txg6+ 2.Lxg6. -1... d5 -2.Lf4 Tf8 -3.Dg3 Dh3 -4.Dh2 Sg3 -5.Dh1 Lh2 etc. (2004-3-18)
Erich Bartel: Nachdrucke:
1) Retro Opposition, 1989.---
2) Problemkiste (66) XII 1989.--- (2007-4-15)
Yoav Ben-Zvi: Might be the earliest publication of a sound problem showing Retro-Opposition (on g3 after -1...BPd5-d4 -2.Bf4-g3) It may also be the first instance of "Sliding Block" (Verschiebepuzzle) without conditions. Appears as D918 in Dawson's booklet on Retro-Opposition. (2017-12-5)
comment
Keywords: Cant Castler, Castling (sk)
Genre: Retro
Reprints: Problemkiste (66) 12/1989
Input: Gerd Wilts, 1995-6-3
Last update: Erich Bartel, 2013-7-27 more...
37 - P0001978
Thomas R. Dawson
Eskilstuna-Kuriren 1918
P0001978
(11+13)
Ergänze einen schwarzen Springer in einer Ecke, so daß Weiß in einem Zug mattsetzen kann!
Henrik Juel: Add sSh8. 1.Sxh3#. -1... Sg6 -2.Lc2 Sf4 -3.Ld1 Se2 -4.Lc2 Sc1 -5.Ka1 Sa2 -6.Lb1 Dc1 etc. (2004-3-18)
Yoav Ben-Zvi: Not +BNa8?: Black is to move due to Parity Argument.
Not +BNa1?: Illegal position due to Retro-Opposition between BN and WB on c2.
An alternative stipulation: "If the position is legal: #1 (who?)" with a)BN on a1 (illegal), b)BNa1 to b2 (1.WNg1xh3#! not 1...BQa3-a2#?), c)BNa1 to c2 (illegal).
Appears as D1089 in Dawson's "Seventy Five Retros", 1928. (2017-12-21)
Henrik Juel: I just discovered that an edited version of Dawson's 1928 manuscript can be found at
www.theproblemist.org/trd-retop.html (2017-12-21)
Henrik Juel: Just for the record:
This problem did not appear in Dawson's 1928 manuscript, but was added by the editor G. P. Jelliss
In the edited version the manuscript retros are marked by ¤

On the RO discussion:
Now we have not only Dawson's notion of RO, but also Jelliss's interpretation of Dawson's notion... (2017-12-21)
comment
Keywords: Retro Opposition, Add pieces
Genre: Retro
Input: Gerd Wilts, 1995-6-3
38 - P0001979
Thomas R. Dawson
Svenska Dagbladet 1923
P0001979
(11+14)
#2
1. gxh6 ... 2. g8=D,T#
play all play one stop play next play all
"Blundering Horsemen"
Henrik Juel: 1.gxh6 (2.g8DT#). Black could castle, only if he had the move: -1.Sc2 Sf7 ... -9.Sg8 Sf7 -10.Sh6 Sd8 -11.Sf7 d4 -12.Sh8 Sf7 -13.S=h7 etc. (2004-3-18)
Henrik Juel: The stipulation implies that White has the move, so Black starts the retroplay
Assume (for contradiction) that Black may castle; then Ta8 and Ke8 may not retract, and Black is left to retract Sh6 (because e4-e3 is needed at the end of the retroplay), which must pendle on f7, d8, h8, h6, reaching f7 every other retraction
The only way to release the position is to unpromote Sa1 on h8; one route is a1-c2-e3-d1 and then c3-a4-b6-c8-e7-g8-h6-f7-h8
The retroplay goes -0... Sf7 -1.Sc2 Sh6 .. -9.Sg8 Sd8 -10.Sh6 and now we are stuck: -10... e4 is premature (-11.Sf7 occupies the square Black wants to go to), and -10... Sf7 occupies the square White wants to retract to
We conclude that Black may not castle, allowing 1.gxh6 thr. 2.g8=DT#
In a 1928 manuscript Dawson called the theme Retro Opposition, and this has been the accepted terminology ever since; for this situation I prefer the more descriptive term Retro Collision, as the white and black knights collide on f7 (2017-12-20)
Henrik Juel: corrections: not e4-e3, but d4-d3, and later -10... d4 (2017-12-20)
Yoav Ben-Zvi: Dawson did not attempt a definition of "Retrograde Opposition" in the 1928 manuscript. His conception of the theme was broad as seen by examples such as P0001982 (D1141 in the manuscript). Fabel narrowed things down to a contest over occupation of a square between opposite-colored pieces which Henrik prefers to call "Retro-Collision". The Themes Index of the FIDE Albums defines Retro Opposition as "In a particular phase of the retro-play it can be proved which side is to play, despite there being mobile pieces on both sides." ignoring entirely the characteristic contested square. According to this definition the problem asking "Whose move?" for a position identical to the initial array would qualify although it is an elementary example of "Parity Argument" rather than RO. (2017-12-21)
Henrik Juel: What a mess!
According to Yoav we have three notions of RO, so whenever we use these words we really should add: according to Fabel, Dawson, or FIDE Albums
In the PDB Gerd entered lots of RO problems, but he (wisely?) neglected to define RO (2017-12-21)
comment
Keywords: Cant Castler, Retro Opposition, Castling (sg)
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-21 more...
39 - P0002098
Max Lange
Handbuch der Schachaufgaben [Lange] 1862
P0002098
(6+9)
#1
1. axb6ep#
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Eine sehr frühe (erste?) Darstellung des retroanalytisch begründeten en passant Schlages. (\eb)
ML schreibt dazu: "In dieser Position läßt sich die Voraussetzung des exceptionellen Zuges begründen...".
TBr: Nein, nicht erste Darstellung, siehe P0001360 (ebenfalls von Max Lange), das wohl das erste korrekte Retro überhaupt zu sein scheint. (2015-9-6)
Yoav Ben-Zvi: WBe2, WPd5 and BPg7 can be removed. (2018-3-1)
A.Buchanan: I think wPd5 is needed so that bK can’t unmove with check from b7 (2018-3-1)
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comment
Keywords: En passant, En passant as key
Genre: Retro
Reprints: 57A Retrograde Analysis 1915
K588 Problemkiste (110) 04/1997
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2015-9-10 more...
40 - P0002107
Rudolf Behal
Neues Illustrirtes Blatt 1897
P0002107
(12+3) C+
#3
1. exd6ep Kxg3 2. Dg1+ Kh4 3. Sf3#
1. ... Kxg4 2. De5 Kh4 3. Df4#
1. ... Kxg5 2. Dg7+ Kh4 3. Sf5#
play all play one stop play next play all
für eine ökonomisierte Version s. P1012712
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comment
Keywords: En passant as key, Model mate (3x)
Genre: Retro, 3#
Computer test: Popeye 4.61
Reprints: 62 Retrograde Analysis 1915
(X) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-1-26 more...
41 - P0002122
Wolfgang Hundsdorfer
Deutsches Wochenschach 03/10/1909
P0002122
(13+12)
#3
1. fxe6ep! Txe6+ 2. Lxe6+ Kxh5 3. Dg4#
1. ... Lh7+ 2. Lf5+ Kxh5 3. Dg4#
R: 1. ... e7-e5 2. Ke5-e4 Tf6-d6
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Yoav Ben-Zvi: The 4 missing BPs are all needed to account for 4 WP captures. [BPa7] and [BPb7] capture all 3 missing White pieces to promote on c1 so [BPc7] does not capture and also promotes on c1. Therefore White's last move could not be -2.WPc4xd5 or -2.WKe3-e4 (forcing -2...BPc5xd4) as, in both cases, the path to promotion of [BPc7] is closed off. This implies that White's last move was WKe5-e4 preceded by BRf6-d6.
The e.p. key opens up 2 checks for Black but closes off the threatened mate on d5. The skill shown by the pioneers of RA in dressing up their problems with an orthodox stipulation is to be admired but also shows why it was neccessary to shed this practice in order to make further progress. (2018-3-22)
Henrik Juel: C+ by Popeye 4.61 (after analysis) (2018-3-22)
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comment
Keywords: En passant
Genre: Retro
Reprints: 69B Retrograde Analysis 1915
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-3-22 more...
42 - P0002139
Aleksey A. Troitzky
Bohemia 1910
P0002139
(14+14)
#2
Henrik Juel: 1.bxc6ep+. -1... c7 -2.Tc6 etc.
Not -1... c6? -2.Lc7 and the tempo is wrong. (2004-3-8)
Yoav Ben-Zvi: -1...BPc6-c5? -2.Bc7-b8 leads to a Retro-opposition between the bishops on b8 which cannot be resolved by switching the side to move due to the Parity Argument (for the moves of the bishops) and lack of a tempo retraction for either side. This part was shown in P0002141. The WB must stand on b8 when Black retracts BPc7-c6/c5 (releasing WRb6 and opening the North-West cage) because standing on d8,e7,f8 it cannot be released from the back rows before BBa4 is retracted home to c8 (to allow retraction of BPd7-d8) but the release of BBa4 from the South cage awaits the retraction of WB home to c1 (to allow retraction of WPd2-d3) causing a deadlock (the release of WBc1 and BBc8 must each precede the other so neither can come first).
Retro-opposition (supported by the Parity argument) combined with a clever deadlock argument, refute a Try thus justifying the En Passant key of a #2. An impressive achievement at the time that remains beautifull when viewed today. (2018-2-18)
A.Buchanan: In the world of chess problems, it amazes me that (1) so many different ideas can be conceived (2) so many of those can be realized. (2018-2-19)
comment
Keywords: En passant, Retro Opposition
Genre: Retro, 2#
Reprints: 79 Retrograde Analysis 1915
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-19 more...
43 - P0002141
Wolfgang Hundsdorfer
Münchner Neueste Nachrichten 1908
P0002141
(9+12)
#5
1. bxc6ep Lxb6 2. De5! dxe5 3. Lxe5 Ld4+ 4. Lxd4 ... 5. Lb2#
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Henrik Juel: 1.bxc6ep Lxb6 2.De5! dxe5 3.Lxe5 Ld4+ 4.Lxd4. -1... c7 -2.Tc6 Lg1 -3.La7 h2xg1=L -4.Db6 a5xb4 etc. Not -1... c6? -2.Lc7, and perpetual repetition by movable wLc7 and sDLS! Very good. (2004-2-26)
Yoav Ben-Zvi: BBa7 is promoted by [BPh7] playing BPh2xg1=B. all 7 missing White pieces were captured by BPs. This means [WPh2] accounts for one of the captures by BPs so it must have captured 2 Black pieces, one on the g file to clear the way for [BPh7] and the other to promote on f8 or h8. This leaves only 1 missing Black piece that can be captured by other WPs so WPb5 came from the a file not from the c file and WBb8 could not promote on d8.
The last move of the game was by Black (determined by the stipulation). It was not -1...BPd7-d6? (BBa6 also promoted but not enough BPs to promote). Also not BPc7xd6? (too many captures by BPs).
Not -1...Pc6-c5? -2.Bc7-b8 (not -2.Pc4xb5? since WP captured only once) Bb8-a7 (or -2...Qb8-a8 -3.Bd8-c7 Qa8-b8 repeats while Pc7-c6/Qc7-b8 locks WBd8 which cannot unpromote) -3.Bd8-c7 Na7-c8/Qa7-a8/Ba7-b8/ (not -3...Pc7-c6/Bc7-b8 as WBd8 cannot unpromote) -4.Bc7-d8 and retro-stalemate or forced repetition.
The main Try is refuted by Retro-opposition on b8 between WB and both BB and BQ with no way to switch the side-to-move due to the Parity argument and lack of tempo retractions for either side. This problem is considered to be the earliest implementation of Retro-opposition. (2018-2-12)
A.Buchanan: Very clean retro play... and nice forward play with double sacrifice for the win. (2018-2-12)
comment
Keywords: En passant as key, Retro Opposition
Genre: Retro
Reprints: 116 150 exzentrische Schachaufgaben 1910
79B Retrograde Analysis 1915
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-2-12 more...
44 - P0002277
Karlheinz Bachmann
v Die Schwalbe 104, p. 217, 04/1987
1. ehrende Erwähnung
P0002277
(11+15)
BP in 48,0
1. Sf3 a5 2. Sd4 a4 3. Sb3 axb3 4. a3 Ta4 5. Ta2 bxa2 6. Tg1 axb1=S 7. Th1 Sc3 8. Tg1 Sd5 9. Th1 Sb6 10. Tg1 Sa8 11. Th1 b6 12. Tg1 La6 13. Th1 Dc8 14. Tg1 Db7 15. Th1 Df3 16. gxf3 h5 17. Lh3 h4 18. Le6 h3 19. La2 Lc4 20. Lb1 La2 21. b3 Sa6 22. Lb2 Sc5 23. Lf6 gxf6 24. Kf1 Lh6 25. Kg1 Kf8 26. Df1 Kg7 27. Dg2+ hxg2 28. h4 Kg6 29. Kh2 g1=S 30. Kg2 Lf4 31. h5+ Kg5 32. h6 Lg3 33. h7 Sh6 34. Th4 Tb8 35. Tb4 Tb7 36. f4+ Kh4 37. h8=T Sf3 38. Tg8 Se5 39. Tg5 Sg6 40. Kf3 Kh3 41. Ke3 Kg2 42. Te5 Kf1 43. Kf3 Ke1 44. Kg2 Kd1 45. Kf1 Kc1 46. Ke1 Kb2 47. Kd1 Ka1 48. Kc1 Sh8
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paul: Correction of P0000067. (2018-3-3)
comment
Keywords: Unique Proof Game, Length Record, Non-standard material, Promotion (Tss)
Genre: Retro
Reprints: 82 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2006-1-10 more...
45 - P0002313
Yaakov Mintz
The Problemist 1987-1988
3.-5. ehrende Erwähnung e.a.
P0002313
(12+11)
BP in 17,5
1. f3 e5 2. Kf2 e4 3. De1 e3+ 4. Kxe3 Ke7 5. Dg3 De8 6. Kf2 Kd8 7. Ke1 Lc5 8. Kd1 Lxg1 9. De1 Lxh2 10. Txh2 d6 11. Txh7 Le6 12. Txg7 Th1 13. Th7 Lxa2 14. Th8 Lxb1 15. Txa7 b5 16. Tb7 Ta1 17. Ta7 b4 18. Ta8
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Cook: NL
1. f3 e5 2. Kf2 e4 3. De1 e3+ 4. Kxe3 b5 5. Dg3 b4 6. Kf2 Lc5+ 7. Ke1 Lxg1 8. Kd1 Lxh2 9. Txh2 d6 10. Txh7 Le6 11. Txg7 Th1 12. Th7 Lxa2 13. Th8 Lxb1 14. Txa7 Ke7 15. Tb7 Ta1 16. Ta7 De8 17. Ta8 Kd8 18. De1 (Mario Richter)
paul: C+ (Euclide 1.11) for the first 13 moves (in about 51 hours). I do not dare to check for 13.5 moves. (2018-3-8)
Henrik Juel: Tiny typo in Mario's cook: 10.Txh7 (2018-3-8)
Mario Richter: The typo comes from a "by hand conversion" of the output of several tools I'm using (here: rawbats and chessbase) - unfortunately each tool has it's own output format, incl. the PDB solution field format ... (2018-3-9)
A.Buchanan: I have a janitor's tool which allows me to change the representation of positions & solutions.
Try to copy the file here: https://www.dropbox.com/sh/ld64s00zm0f9tx8/AAA7r8BsA0vuLcZOOKNvKkmua?dl=0
Click on it, and then hit the download button on the right.
The most useful is the one which converts from FEN to PDB "pieces" format.
Stick the input string in the yellow cell, and pick up the result from the green cell.
If you want to see how it's done, unhide the hidden rows and columns: no VBA just simple Excel.
Only 1% as clever as rawbats, but it still saves me a lot of time.
Feel free to use and to improve. (2018-3-9)
Mario Richter: @Andrew: Thanks for your offer - but I have such tools myself. My fault was not to use them (I thought that I'll be able to transform such a short PG by hand without errors ...)
Would be nice if the PDB-System would be more helpful with respect to language support.
I've decided to use 'english' in the language settings, but that doesn't help here, since solutions still have to be given in german piece notation.
Might be difficult to change this, especially when thinking of fairy piece names, so I can live with that, but there are other aspect which sometimes drive me crazy, e.g. the handling of source names in different languages ... (2018-3-9)
A.Buchanan: I thought you might have such a tool, but I thought it was a nice opportunity to announce it for others who might find it useful. (2018-3-9)
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comment
Keywords: Unique Proof Game, Interchange, Belfort
Genre: Retro
Reprints: 144 Shortest Proof Games 11/1991
Best Problems 47 07/2008
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-3-9 more...
46 - P0002380
Vladimir Korolkov
Prawda 1929
1. Preis
P0002380
(12+6)
Gewinn
1. Lxh3? Lf3!+ 2. Lg2 f1=D#
1. Tc1+? Sxc1 2. La4+ b3 Schwarz gewinnt
1. Td2+! Kc1 2. Td1+ Kxd1 3. La4+ b3! 4. Lxb3+ Ke1 5. Lb4+ Sc3! 6. Lxc3+ Kf1
7. Lc4 Lxc4 8. Dc5! Ld3 9. Db5! Lxb5 10. b8=S! Ld3 11. a8=L! Le2 13. f8=T! Gewinn
11. a8=D? Le4+ 12. Dxe4 Patt
8. ... Le2 9. f8=T
2. ... Kxb2 3. Lxh3
2. Tc2+? Kb1! 3. Tc1+ Sxc1 4. Lf5+ Sd3 5. Lxd3+ Lxd3 Schwarz gewinnt
1. ... Ke1 2. Txe2+ Kxe2 3. Lxh3 Gewinn
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Yoav Ben-Zvi: A fine study with 3 underpromotions. This is not a Retro and none of the promoted pieces are captured so there is no Ceriani-Frolkin. (2018-2-7)
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comment
Keywords: Promotion (SLT), under-promotion
Genre: Studies
Reprints: 43 Int. GM und M für Schachkompositionen 1988
A. Die Schwalbe 127, p. 373, 02/1991
Rochade Europa , p. 24, 04/1997
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-2-7 more...
47 - P0002461
S. N. Ravishankar
Rex Multiplex 1986
P0002461
(2+3)
#1 vor 15
VRZ, Typ friedlich
R: 1. Kg6-h5 Lg8-h7+ 2. Kf7-g6 Lh7-g8+ 3. Ke7-f7 Lg7-f8+ 4. Kf6-e7 Lf8-g7+ 5. Kf5-f6 Lg8-h7+ 6. Ke6-f5 Lh7-g8+ 7. Kd6-e6 Lg7-f8+ 8. Ke5-d6 Lf8-g7+ 9. Ke4-e5 Lg8-h7+ 10. Kd5-e4 Lh7-g8+ 11. Kc5-d5 Lg7-f8+ 12. Kd4-c5 Lf8-g7+ 13. Kd3-d4 Lg8-h7+ 14. Kc4-d3 Lh7-g8+ 15. Kb3-c4, dann 1. Th6-h1#
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more ...
comment
Keywords: Defensive Retractor, Type Pacific, Aristocrat, Minimal, Staircase (K)
Genre: Retro
Reprints: 4 Die Schwalbe 104, p. 214, 04/1987
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-1-16 more...
48 - P0002611
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 26, 1979
P0002611
(3+1)
Ergänze einen wL auf e3 oder e4!
Monochromes Schach
+wLe3
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Forderungs-Alternative: Einfarben-Schach. Auf dem Brett steht ein unsichtbarer Läufer. Steht er auf einem schwarzen oder einem weißen Feld?
Yoav Ben-Zvi: In the book (page 26) the WB is placed between e3 and e4. It seems simpler to represent this with WB on e4, the stipulation "Monochrome chess. Is the position legal?" and a Twin b) WBe4 to e3. Proof of illegality with WB on e4: There is no piece that could perform the last capture on a dark square since no piece on the board is capable of a dark-squared capture and it could not be a piece that is missing since such a piece would itself have been captured later on a dark square. Smullyan's version uses poetic language including the metaphor of a Bear and a Lion fighting until each has entirely devoured the other. Essentially the argument uses the well-known mathemtical technique of "Infinite descent" leading to "Reductio ad Absurdum": It can be shown that assuming the existence of a "minimal" instance that has some property (such as most recent capture on a dark square) leads to the conclusion that it is not really minimal (there is a more recent capture on a dark square) so the assumption leads to self contradiction and is therefore not true. A formal definition of this method was developed by Fermat (17th Century) but it was used as far back as Euclid's "Elements" (300 B.C.). (2017-12-14)
Henrik Juel: It might be simpler to consider the retroplay:
With Le4 there is no way of producing a dark-squared man by uncapture (2017-12-14)
Brassaud: With Le4 it seems possible to producing a dark-squared man with the retroplay : 1) Lc2-e4, Kd7-e8 2) Ld3xPc2, b3xPc2 3) Ld3-e4, a4xb3 ep 4) b2-b4... But the position remains illegal as shown with the metaphor of the lion and the bear. (2017-12-15)
Henrik Juel: Good point, Francois
But the en passant trick still cannot create a full retroplay back to the initial position with 32 men
I should have written 'officer' instead of 'man' (2017-12-15)
Yoav Ben-Zvi: Henrik's modified claim that "with WBe4 there is no way of producing a dark-squared officer by uncapture" is correct but I do not see a simple way to prove it directly. A "lion and bear" type argument with retroplay could ask "Which of the pieces that move on the dark squares was the first to uncapture?". It should be noted that this piece could not be a pawn that was itself uncaptured e.p. (since the history of such a pawn does not include an uncapture) and that proving that such a piece does not exist proves illegality (since it implies that dark-squared officers such as BQd8 could not be uncaptured). A similar clarification is needed when applying the argument to forward moves.
The Homebase position of the diagram is an IC. It could be presented (optionally adding a WB on f1 and/or a BB on c8) with the stipulation "Is the position legal?" and the Twin b)-WPf2. (2017-12-17)
comment
Keywords: Monochrome, Add pieces (L), Homebase (2)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-28 more...
49 - P0002619
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002619
(15+13)
Darf Weiß noch rochieren?
Yoav Ben-Zvi: Appears on page 54 of the Book. WPb4 and BPg5 both captured Rooks. Neither BR could have escaped from the bottom rows, to be captured by [WPa2], before capture of the WR cleared the h column. It follows that the WR was captured first with WP still on column a and therefore the captured WR could not have come from a1 and was originally from h1 escaping through the h column. WRh1 is a "Sibling Impostor" and White "Can't Castle". (2018-3-15)
Henrik Juel: It seems that Lc1 is unnecessary
Even without it, White cannot castle, by a very similar argument; the only difference is that Th1 might be [Th1], but if so, it must have moved to make way for [Ta1] (2018-3-15)
comment
Keywords: Castling (wk), Cant Castler, Impostor (T)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
(A) Probleme für Tiger 4 04/1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-15 more...
50 - P0002624
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 66, 1979
P0002624
(12+13)
Ergänze einen wB auf f4 oder f5!
1) +wBf5
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Henrik Juel: The dark-squared bishops were captured by officers, so the pawn captures were c7xSb6, d7xLc6 by Black and exLf, f2xSg3 by White (when the pawn has been added)
The forward sequence was e2-e3 (or e2-e4) before d7xLc6 before exLf on a light square, so [Pe2] could not reach f4, and the undetermined capture was e4xLf5.
This simple idea was later shown more elegantly in P1012384.
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comment
Keywords: Add pieces
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
R5 Phénix 275-276, p. 10810, 07-08/2017
R5 Phénix 275-276, p. 10812, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-9 more...
51 - P0002628
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002628
(3+2)
#1
Aprilscherz!
1. b8=sS#
play all play one stop play next play all
vgl. P1349637
Mario Richter: Could be, inspired by P1349637, presented as twin: a) diagram, b) +sSb8 (2018-5-2)
Ladislav Packa: Mario: Position b) would be enough. H#1*: 1...bxa8=R#, 1.Sd7 b8=S# (2018-5-2)
comment
Keywords: Joke, Joke promotion (s)
Genre: Fairies
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-5-2 more...
52 - P0002686
Narajan Shankar Ram
4154 feenschach 70 08/1984
P0002686
(1+1) cooked
Ergänze wT, wS und wB zu einem IC!
Madrasi

play all play one stop play next play all
Verführung: wTd1 wSc3 wBe4, aber Stellung ist legal, zuletzt wBd3xsSe4+

Lösung: wTb5 wSb6 wBc4!
Cook: - wTc5 wSc7 wBc6
- wTe5 wSe7 wBe6
- wTd6 wSb6 wBc6
- wTd6 wSf6 wBe6
jeweils illegales Doppelschach, ohne T bzw. S legales Einfachschach, ohne wB jeweils Doppelschach erklärbar durch SxT++

Duplicate Diagram: P0006310

Autor: Td4/Sb4/Bc4 or Td4/Sf4/Be4 are not cooks, since after removing wT, w's last move can be SxBb4 or SxBf4, but after this, there no last move for Black!
Twin: I later added a twin - a)Orthodox, b)Madrasi
The solution to the Orthodox twin is Te5/Se4/Be6.
[Der orthodoxe Zwilling ist C+]
paul: The try is here wTd1 wSc3 wBe4 (legal position -1.d3xSe4+) (2011-9-22)
Henrik Juel: Why are wTd4 wSb4 wBc4 or wTd4 wSf4 wBe4 cooks? The positions seem still illegal without the T.
This looks like a cook: wTe5, wSe4, wBe6 (with no Madrasi effects). (2011-9-22)
hpr: I am no expert here, but my 2 cents anyway:
wTe5, wSe4, wBe6; the position is legal, last move: Sg3xTe4. Right? (2011-9-23)
Henrik Juel: Yes, you are right, of course. Last move could even be KxTf5+. (2011-9-23)
paul: wTd4 wSb4 wBc4 seems to be a cook. Without Td4 the last moves where -1.Sa2xBb4++ Bb2-c4 (2011-9-25)
Henrik Juel: But the last moves should be a white and a black move, not the two white moves Sa2xBb4 and Bb2-c4. (2011-9-25)
paul: Right, Henrik! Then the problem has unique solution. (2011-9-25)
shankar ram: Td4/Sb4/Bc4 or Td4/Sf4/Be4 are not cooks, since after removing wT, w's last move can be SxBb4 or SxBf4, but after this, there no last move for Black!

Twin: I later added a twin - a)Orthodox, b)Madrasi
The solution to the Orthodox twin is Te5/Se4/Be6. (2018-1-16)
Mario Richter: The tries Td4/Sb4/Bc4 or Td4/Sf4/Be4 are interesting (for me: much more than the official wTd1 wSc3 wBd3), because they make use of a strange Madrasi en passant effect ...
In these two tries an illegal triple check is used, but to cook the problem is suffices to construct an illegal double check:
- wTc5 wSc7 wBc6
- wTe5 wSe7 wBe6
- wTd6 wSb6 wBc6
- wTd6 wSf6 wBe6 (2018-1-16)
more ...
comment
Keywords: Illegal cluster, Madrasi, only Kings
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-1-17 more...
53 - P0003126
Nissim Shirin
2189 Shahmat 04/1986
P0003126
(8+13)
h#2
1. fxe3ep Txc5 2. Le4 Sxb3#
play all play one stop play next play all
Der ep-Schlüssel ist nicht gerechtfertigt, weil zuletzt auch f3xTe4 geschehen sein kann.
Mario Richter: Something must be wrong here: White's last move might have been f3xTe4, so ep-key is not justified (2018-3-26)
comment
Keywords: En passant as key
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-3-29 more...
54 - P0003396
Tivadar Kardos
Festgrüße 1956
P0003396
(8+16) C+
h#2
1. Kd4! bxc5 2. Ke5 d4#
1. axb3ep? Txe1 2. Sd3 Txe4# (illegal)
play all play one stop play next play all
1. axb3ep? ist illegal, weil zuletzt R: 1. g7-g8=S geschehen sein konnte
vgl. P1348363
Henrik Juel: C+ by Popeye 4.61
The possibility of a promotion as last move shows that the ep capture cannot be legitimized
But the ep capture also seems illegal, as Black pawns captured all missing white men, including [Lc1] (2018-3-22)
A.Buchanan: Perhaps this is deliberate: to construct an e.p. problem which does not rely on the e.p. convention. (2018-3-22)
Yoav Ben-Zvi: This differs from P1348363 by the addition of the WP on a5 and removal of the Twin that shows the e.p. in the solution. In the present version the promotion to WN is uniquely determined to be White's last move. The Twin can be replaced with: b) -WNg8 leading to model mates. I think the idea of an illusionary e.p. used to trap the sophisticated solver was attempted in P1346195. (2018-3-24)
A.Buchanan: I made P1261604 to have illusionary en passant hxg to distract from the real en passant action elsewhere. (2018-3-24)
A.Buchanan: There's a set of problem in W.Keym's Eigenartige Schachprobleme (a section called "Bosheiten im Einzüger") 308-324, pages 100-105) which explore castling, en passant and the move in various combinations of real and try play, within the context of #1 problems. Most are by Keym himself, but Fabel makes a few appearances. Not sure if these problems are all in PDB yet. (2018-3-25)
Olaf Jenkner: Would it be possible to improve the retro content by moving bPh6 to h7 and replacing Ng8 by Bh8? (2018-3-25)
Olaf Jenkner: I overlooked Bg7-h8 so nothing would be changed. (2018-3-26)
more ...
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: Popeye 4.61
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-26 more...
55 - P0003405
Laszlo Lindner
Magyar Sakkvilag 1943
3. Preis
P0003405
(4+16) C+
h#2
b) sBf3 nach e3
a) 1. Lxd4 Txb3 2. Tc5 Sd2#
R: 1. Kg3-h4 2. gxf3ep+

b)
R: 1. d2-d4, dann 0. ... d2-d4
1. e4xd3ep Kxh3 2. d4 Sa3#
play all play one stop play next play all
Ob der Zwilling b) schon im Original vorhanden war, ist nicht sicher, im Nachdruck in 'Problem [Zagreb]' fehlt er, dafür kommt er in einem Artikel von . Petrovici zum "Thema Than" von 03/2016 vor.
Mario Richter: @Alfred: Wieso funktioniert Abspiel-Button für b) nicht?? (2018-3-22)
A.Buchanan: @Mario, @Alfred: the problem is that the b solution follows the retro bit, and the parser think that it's retro too. If I remove the retro part, b) works fine. I don't know how to reset the parser so it's going forwards again. Normally I just put the R part after the forwards part, but that won't work here because there's twins. (2018-3-22)
Alfred Pfeiffer: Keine Ahnung, warum das Nachspielen von b) nach dem Retro-Part von a) nicht funktioniert. Evtl. ein Bug im Proramm. Das sollte Gerd Wilts prüfen.
Ein Tausch der Lösungen b) und a) in der Textreihenfolge erlaubt das Nachspielen, (2018-3-22)
comment
Keywords: En passant as key, En passant in the retro play, Than theme
Genre: h#, Retro
Reprints: (II) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-3-22 more...
56 - P0003438
Antti Gottfried Ojanen
3977 Stella Polaris 06/1971
4. -6. Platz
P0003438
(3+7) C+
h#3 (AP)
2.1...
1. Tb5 0-0-0 2. Tb3 Kc2 3. T3xb4 Ta1#
1. cxb3ep Tc1 2. Ta5 Txc3 3. Sb5 Tc4#
play all play one stop play next play all
Nordisches Turnier
Jakob Leck: Jahresangabe müsste vermutlich 1971 lauten. Vergleiche Urdrucknummern 3978 (P0003446) und 3979 (P0003436). (2018-2-11)
Henrik Juel: The given theme was a variation on AP:
ep capture in one solution is justified by castling in the other one (2018-2-11)
A.Buchanan: I would prefer sTh5 on d5, allowing remowal of wBd4. (2018-2-11)
more ...
comment
Keywords: a posteriori (AP), En passant as key, Castling (wg)
Genre: h#, Retro
Computer test: C+ by Popeye 4.61
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-12 more...
57 - P0003447
Gerd Rinder
(O) Die Schwalbe 16, p. 393, 10/1972
P0003447
(14+13) C+
h#2 (pRA)
1. Txg3 Sxg3+ 2. Kf3 0-0#
1. cxd3ep Lxg1 2. e2 Sd2#
1. gxf3ep Lxg1 2. Dd3 Txh4#
play all play one stop play next play all
VL: This problem was first published in the article entitled "Konstruktive Kritik am Kodex von Piran" (by W.Keym; H.16). The author is a strong opponent of the retro-synthese (including AP a la Keeble--Petrovic = "Typ Petrovic"). Here we meet a retro-situation resembling that of AP, which, however, is interpreted and resolved purely in the framework of pRA. Namely, the problem contains three retro-variants: (a) 0-0; (b) 0-0-0 & cxd3 ep; (c) 0-0-0 & gxf3 ep. Each of them results in a unique (partial) solution (see above), so that the problem is sound. The absence of 0-0-0 in the latter two solutions is a witty feature that emphasizes a fundamental distinction from AP (where only actual castling can legalize the ep-key). Judging from the article "PRA oder Kodex" by B.Pavlovic in the "Problem", 152-6, where this problem is reproduced, it was initially stipulated "h#2, PRA-Typ Rinder" (this is presently known under the name "Typ Keym"). It is reproduced also in the book "Eigenartige Schachprobleme" by W.Keym, 2010, Pr.385. (2012-8-26)
Sally: Hier schlugen die w. Bauern dreimal, unter anderem eine UW-Figur von "h1 oder "a1",(entweder ist 000 oder 00 zulässig).
Der letzte Zug war 1. K-e1, oder T-a1, oder "d2-d4". oder
"f2-f4". Falls 000 zulässig ist, dann ist 00 unzulässig und jeweils einer der E.-P.-Schläge erlaubt, Also löst entweder:
1. Bg4xf3 E.p.! - Lxg1, 2. Dd3 - Txh4#. oder :
1. Bc4xd3 E.p.! - Lxg1, 2. Be2 - Sd2#.
Beide Male wird das Zugrecht 000 anerkannt, aber nicht aufgeführt! Falls 00 zulässig ist, dann ist 000 unzulässig;
in diesem Fall war zuletzt der Zug "T-a1" möglich, daher kein E.p.-Schlag erlaubt. Also löst :
1. Txg3! - Sxg3+, 2. Kf3 - 00 #. (2018-6-15)
Henrik Juel: C+ by Popeye 4.61, after analysis (2018-6-15)
more ...
comment
Keywords: Castling, En passant as key, a posteriori (AP)
Genre: h#, Retro
Computer test: Popeye 4.61
Reprints: (II) Problem 152-156 04/1973
XI Caissas Schloßbewohner 1 1983
(13) Die Schwalbe 241 02/2010
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-16 more...
58 - P0003451
Knud Harald Hannemann
3823 Stella Polaris 03/1971
P0003451
(6+8) cooked
h#2 (AP)
2.1...
1) 1. gxf3ep 0-0-0 2. Te7 Th4#
2) 1. cxd3ep 0-0 2. Da4 Txa4#
play all play one stop play next play all
AB: I think this is cooked. I don't see how AP castling can justify earlier ep here.
1. Kf3 Bf5 2. Kg2 Be4#
1. Kf3 Bxd7 2. Kg2 Bc6#
1. cxd3 Rf1 2. Qa4 Rxa4#
1. gxf3ep Ra5 2. Kf4 Rh4#
1. gxf3ep Rd1 2. Re7 Rh4#
Also, second solution given has typos 1. *c*xd3ep & 2. Q*a*4. (2002-3-21)
V.Liskovets: Indeed this problem is cooked, and I
failed to correct it preserving symmetry.
Here is a possible correction:
W: Ke1 Ra1 Rh1 Be6 Pd4 Pf4
B: Ke4 Qd7 Rf7 Pc3 Pc4 Pe3 Pg3 Pg4 Bh7 Rb2 Pb3

Another story, justifying its contents (e.p.).
In my opinion, all published treatments are
insatisfactory (the same concerns P0004295
(corrected) by Werner Kuntsche as well).
There is a way to make it sound under the
sophisticated HYBRID stipulation 'AP, pRA':
2 partial solutions legalized JOINTLY by
both castlings (details to be published). (2002-4-2)
more ...
comment
Keywords: Castling (wkwg), En passant as key, a posteriori (AP)
Genre: h#, Retro
Reprints: (65) Problem 144-147 12/1971
(8) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-12 more...
59 - P0003518
Oskar E. Vinje
3376 The Fairy Chess Review 14 10/1938
P0003518
(12+10)
h#2
1. Sf7 Td6 2. Tf8 Sxg7#
Not
1. Sf7 Txh6 2. 0-0? Sxe7#
play all play one stop play next play all
Henrik Juel: The missing white TLD were captured on the first row; additionally black captured d7xc6, so [Ph2] promoted and [Pf7] was captured on its file. To preserve the black castling, White must have captured hxgxh7xg8; but only two black men were available for capture: DS. So Black may not castle, and 1.Sf7 Txh6 2.0-0? Sxe7 is not a solution. (2010-12-15)
Mario Richter: Henrik, your analysis is not complete: it is also possible, that an original white piece was captured on c6 (wRh1 or one of the wNN), thereby allowing the promotion on g8 without visiting f7. But in this case, the promoted piece is still on the board, and regardless if it is the wR or one wN, to leave the promotion square g8 was only possible by destroying Black's castling right. (2010-12-16)
Henrik Juel: Good point, Mario. This only makes the problem even better. They knew what they were doing back in 1938. (2010-12-16)
A.Buchanan: Solution & retro try echo one another. (2018-3-17)
more ...
comment
Keywords: Cant Castler, Castling (sk)
Genre: h#, Retro
Computer test: C+ Popeye for the h#2, with manual thinking for the retro aspects.
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-17 more...
60 - P0003536
Paul Leibovici
347 Sahovski Vjesnik 02/1949
P0003536
(2+6) C+
h#2
1. 0-0-0? (illegal!)
1. Kf8 Da1 2. Te8 Dxg7#
play all play one stop play next play all
Der wK kann h8 nur via f7 oder f8 erreicht haben, der sK hat also schon gezogen.
Klären: Datum =02/19?9
Henrik Juel: C+ by Popeye 4.61
Not 1.0-0-0+? Kh7 2.Td7 Da8
because Ke8 has moved to let Kh8 in (2018-2-24)
more ...
comment
Keywords: Cant Castler, Castling (sg)
Genre: h#, Retro
Computer test: Popeye 4.61
Reprints: 12 Volzhskaya kommuna 01/04/1977
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-2-26 more...
61 - P0003661
Hans Frieder Haefele
11285 Schweizerische Schachzeitung 09/1977
P0003661
(3+6) C+
h#2
b) sBd3 nach a2
c) ferner sBg4 nach d3
a) 1. Ta2 Txa2 2. Th1 Tg2#
b) 1. Te2+ Kd1 2. g2 Kxe2#
c) 1. Tf2 0-0-0 2. Tf1 Txf1#
play all play one stop play next play all
Sally: Weshalb aber geht dieletzte Variante auch nicht in den Diagrammen a) und b)?. Weil Weiß bei blockierender Stellung des Lh3 (sB4) zuletzt eindeutig oder mit dem König gezogen haben muss, was die Rochade verbieten würde. (2018-6-24)
Henrik Juel: If you dislike 'ferner', part c) could be written as 'sBg4 nach a2'
Analysis: last move was made by Ke1 or Ta1 in diagram position and in part b), so castling is possible in part c) only
C+ by Popeye 4.61 (2018-6-24)
comment
Keywords: Cant Castler, Castling (wg)
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-25 more...
62 - P0003701
Istvan Persa
4411 Magyar Sakkelet 11/1980
P0003701
(3+5) C+
h#2
b) sBf7 nach g7
a) 1. 0-0-0 Sc6 2. Td7 La6#
b) 1. Kf8 Lc4 2. Te8 Sxg6#
play all play one stop play next play all
Henrik Juel: C+ by Popeye 4.61 (after analysis)
In part b Black may not castle, because Ke8 has moved to let Kh7 through (2018-3-23)
comment
Keywords: Cant Castler, Castling, Than theme
Genre: h#, Retro
Computer test: Popeye 4.61 (after analysis)
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-3-24 more...
63 - P0003719
Werner Keym
(Q) Die Schwalbe 16, p. 394, 10/1972
H.-D. Leiß gewidmet
P0003719
(3+4)
h#2
pRA
1) 1. Kc2 Ta2 2. Kc1 0-0#
oder
2) 1. Tf2 0-0-0 2. Ke2 The1#
play all play one stop play next play all
siehe P0534178
more ...
comment
Keywords: Cant Castler, Castling
Genre: h#, Retro
Reprints: (IV) Problem 152-156 04/1973
(2) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-4 more...
64 - P0003738
Arpad Molnar
2775v Magyar Sakkelet 11/1960
P0003738
(11+12) cooked
h#2
3.1...
1) 1. Dxa4 Txa4 2. 0-0 Txg4#
2) 1. Txd8 0-0 2. Dd7 Tae1#
3) 1. Tf2 0-0-0 2. Tff8 The1#
play all play one stop play next play all
Cook: NL
1. Txd8 Th7 2. Tc8 bxc8=D,T#
V.Liskovets: C+?? Cooked in this form:
1.Txd8 Th7 2.Tc8 b7xc8T #

My correction (to be published):
bDc6-a6, bLa8-c6, bLa7-a3, wLa4-b5

A unique "typ Keym" problem with
3 castlings (and 3 RVs).

29.9.2000 (2000-9-29)
G. Wilts: This was a display mistake (all problems were displayed as C+!). The problem is of course not C+. (2000-9-29)
more ...
comment
Keywords: Retro variants (RV, pRA), Castling
Genre: h#, Retro
Reprints: (9) StrateGems SG19, p. 157, 07/2002
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-2 more...
65 - P0003821
Pierre Gre
RA23 diagrammes 18 11-12/1975
P0003821
(6+5)
h#2
1) 1. Lf8 0-0-0 2. Lb4 Sb1#
2) 1. Kb2 0-0 2. Lc3 Tfb1#
play all play one stop play next play all
more ...
comment
Keywords: Castling (wkwg), Retro variants (RV, pRA)
Genre: h#, Retro
Reprints: (3) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-4 more...
66 - P0003831
Vasile I. Tacu
RA35 diagrammes 21 05-06/1976
P0003831
(8+8)
Nur die Bauern haben geschlagen; alle 16 Bauern haben sich umgewandelt. Sind alle 4 Rochaden noch zulässig?

Duplicate Diagram: P1004154, P1176381, P1258300

Henrik Juel: Yes, all four castling rights may be preserved, I believe
A feasible proof game seems possible with these 8+8 pawn captures
White axb, bxc, cxb, dxc, exfxg, fxg, hxg
Black axb, dxc, exdxc, fxg, gxhxg, hxg
[Pg2,Pb7,Pc7] promoted without capturing (2018-2-17)
A.Buchanan: I think one capture less for e pawns suffices. The second to move off the file can go to e2 or e7 and promote to minor piece (2018-2-18)
Henrik Juel: Yes, I saw that; but it is stipulated that all captures were made by pawns, so it was natural to change exf to exfxg (2018-2-18)
A.Buchanan: The requirement that all captures are made by pawns seems extraneous. The 16th capture might be made by any of the pawns, so why use it to hide the nice subtlety on the e-file? (2018-2-18)
Henrik Juel: To force the sublety, you could add a black rook on a7, but that would destroy the neat diagram position (2018-2-18)
A.Buchanan: I agree Henrik. There is a curious way to "force the subtlety" in your excellent phrase, by *reversing* the first (unnecessary) condition. It could state instead: "Not every capture was made by a pawn." (2018-2-19)
comment
Keywords: Promotion, Castling (wkwgsksg), Homebase (2), Aristocrat, Symmetrical position
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-18 more...
67 - P0004295
Werner Kuntsche
1777 Problem 73-78 06/1961
P0004295
(5+6)
h#3
Mario Richter: Doublette von P0002476 (2010-10-10)
more ...
comment
Keywords: Castling (wkwg)
Genre: h#, Retro
Reprints: (7) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-2 more...
68 - P0004434
Johannes Manfred Wittlich
9643 The Fairy Chess Review 08/1953
P0004434
(10+10)
# in wieviel?
1. ... Td8 ("0-0-0") 2. a8=D#
play all play one stop play next play all
Henrik Juel: The counting of captures is no Joke
White captured [Lc8] on c8 and the remaining five missing black men by f2xe3x..xa7
Black captured c7xb6, e7xd6xc5, and gxf out on the board, where [Ta1,Th1] could not reach, so they were captured by f2xTe1 and f2xTg1, with the promotees then being captured by [Pf2] or now standing on e7,e4
All six missing white men were thusly captured by black pawns, including [Lc1], and the only possible retroplay is to retract (half of) black castling, so c7 is available for Kd6; incidentally, [Pa7] was captured at home by b6xPa7
The Joke part can be avoided by moving Ta8 to d8 and changing the stipulation to something like 'Last two single moves?' or 'Which men never moved?' (2018-1-10)
comment
Keywords: Finish or retract an unfinished move, Joke, Castling
Genre: Retro
Reprints: 2716 FEENSCHACH 09-10/1955
(180) Problem 127-132 09/1969
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2015-8-12 more...
69 - P0004446
Johannes Manfred Wittlich
8197 The Fairy Chess Review 7 08/1949
P0004446
(14+13) C+
#2
1. Dxh5 droht 2. Dxf7#
1. ... Sg5 2. Dxh8#
1. ... Tf8 2. Sg7#
play all play one stop play next play all
Henrik Juel: Solution argument
Black captured b7xTa6 and g7xLf6, and promoted [Ph7] on h1
White captured b2xYa3 (Y is not [Lf8]), g2xLf3, and h2xLg3
The first capture in the game was bxa3, so Y is [Th8], Th8 is not original, and Black may not castle
(White may castle, but this castling is not needed)
C+ by Popeye 4.61 (2018-1-8)
Henrik Juel: 1.Dxh5 thr./Sg5/Tf8 2.Dxf7/Dxh8/Sg7#
Unusually varied forward play for a retro problem (2018-1-8)
Yoav Ben-Zvi: Elaboration of Henrik's analysis: Prior to the first capture WPs stood on b2,g2,h2 and BPs on b7,g7. This means all original officers except the knights and [BRh8] were locked and could not escape to be the first piece that is captured. The missing [BPh7] accounts for one of 3 captures by the WPs. White's 2 missing pieces were captured by [BPb7] and [BPg7] so [BPh7] did not capture therefore it cannot be captured directly on g3, it must have promoted. The promotion was on h1 after the capture by WPh2 clears the way so the promoted Black piece could not be the first piece captured. The first piece captured also could not be an original BN since then one of the BNs in the diagram must be promoted but the promotion occurs on h1 after WP clears the way by capturing on g3 which prevents the escape of the promoted BN from h1. The only remaining possibility is that the piece captured first was [BRh8] so Black cannot castle.
The capture of [BRh8] must be on a3 (as noted by Henrik) since otherwise the Black piece captured on a3 was [BBf8] which implies that each of [WBc1] and [BBf8] depends for its release on capture of the other leading to deadlock. WPb2xRa3 is followed by capture of [WBc1] on f6 freeing [BBf8] to be captured on g3 and by capture of WR on a6 freeing [BBc8] to be captured on f3.
The main point is that [BRh8] was the first piece to be captured so BRh8 in the diagram is an impostor (either promoted or [BRa8]) and Black cannot castle. The argument can be stated as follows: If Black can castle then [BRh8] never moved leading to the absurd conclusion that no piece could be the first piece captured. Since the assumption that "Black can castle" leads to contradiction, it is proven (by "Reductio ad Absurdum") that Black "Cant castle". A similar argument shows why the capture of [BRh8] could not be on g3 (neither dark squared bishop could be the first to be captured).
Many years later the composer published P0006836, a more sophisticated problem using this type of reasoning. For a discussion of the mathematical nature of this kind of argument see P0002611. I am not aware of an earlier implementation of the idea other than the strange case of P0007092. (2018-1-21)
comment
Keywords: Castling (wgsk), Cant Castler (sk)
Genre: Retro
Computer test: Popeye 4.61
Reprints: Problem 141-143 08/1971
Input: Gerd Wilts, 1995-6-3
Last update: Mario Richter, 2018-1-17 more...
70 - P0004532
György Paros
Magyar Sakkelet 1954
1. Preis
P0004532
(5+9) C+
h#3
2 Lösungen
1) 1. 0-0-0 0-0 2. Kb7 Tfb1+ 3. Ka6 Txa4#
2) 1. Lxe4 0-0-0 2. 0-0 Tdg1+ 3. Kh7 Txh5#
play all play one stop play next play all
Da Schwarz am Zug ist, muß Weiß im letzten Zug entweder einen der Türme oder den König gezogen haben. Es ist deshalb nur eine der beiden Rochaden legal.
klären: Retrogehalt? darf Weiß rochieren?
klären award: 1. oder 2. Preis?
more ...
comment
Keywords: Retro variants (RV, pRA), Castling
Genre: h#, Retro
Reprints: 1313 FIDE Album 1945-1955 1964
(VI) Problem 152-156 04/1973
(17) StrateGems SG19, p. 159, 07/2002
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-12-2 more...
71 - P0004655
Michel Caillaud
(6) Problem 206-210 07/1981
2.-3. Preis e.a.
61. Thematurnier
(Branko-Pavlovic-Gedenkturnier 1980/1981)
P0004655
(12+13)
#1 (wer?)
1. ... Td4!#
1. Ta5#?
R: 1. Lb8-a7 Sh6-g8 2. Lc7-b8 Sg8-h6 3. Ld8-c7 Sh6-g8 4. e6-e7 Sg8-h6 5. Le7-d8 Sh6-g8 6. Lf8-e7 Sg8-h6 7. Lg7-f8 Sh6-g8 8. Lh8-g7 Sg8-h6 9. h7-h8=L Sh6-g8 10. Lg6-h5 Sg8-h6 11. h6-h7 d4-d3 12. h5-h6 Sh6-g8 13. h4-h5 h5xSg4,h5xDg4
play all play one stop play next play all
Schlagfälle und Umwandlungen: axb, bxc, cxd, h=; dxe, exd, gxf, hxg, a=
61. TT (Pavlovic Memorial), Gruppe A
Yoav Ben-Zvi: To release the position WBa7 is unpromoted on h8 and retracts back to h4 to allow BPh5xg4. When White retracts WPh6-h7 BN stands on g8 and as retraction of BNh6-g8 is prevented due to Retro-opposition, Black needs to use his only tempo retraction BPd4-d3 and White must immediately release the opposition by retracting WPh5-h6 which implies that WB must be standing on g6 (not on h7 as it would obstruct the unpromotion or on h5 as it would obstruct the retreat of the pawn to h5). The configuration of WPh7, WBg6, BNg8 with White to play the next retraction can only be achieved if it is Black to move in the diagram position. (2018-4-5)
more ...
comment
Keywords: Retro Opposition, Promoted material on the board, Whose move?
Genre: Retro
Reprints: feenschach 60, p. 458, 05/1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-4-6 more...
72 - P0005118
Luigi Ceriani
Sahovski Vjesnik 10/1948
1. Preis
P0005118
(14+11)
h#1
1. 0-0-0? Tc7 illegal
1. Kd8! Txa8#
play all play one stop play next play all
Alfred Pfeiffer: Diagramm korrigiert. (2018-1-23)
Henrik Juel: Solution
1.Ke8 Txa8#, not 1.0-0-0? Tc7, because Ke8 or Ta8 has moved
All missing men were captured by pawns
Black captured fxexd3 and promoted on a1 and h1
White captured a3xb4, b3xc4, cxd, fxe, h3xg4
Trying to preserve the castling right fails
Sb1 must unpromote on h1, and Ta7 must reach the SE corner, before the position unravels by retracting h3xg4
If Ta7 goes to g1 early, retracting Sb1 to h1 forces White to retract Sa6, so Ta8 must uncheck
If Black unpromotes early, we have -12.Tb7 h5 -13.Tb5 h6 -14.Th5 h7 -15.Th1, and Black is forced to retract Ta8 or Ke1 (2018-1-23)
more ...
comment
Keywords: Castling
Genre: h#, Retro
Reprints: 116 32 personaggi e 1 autore , p. 384, 1955
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-1-24 more...
73 - P0005279
Yehuda Veisberg
7135 The Fairy Chess Review 10 02/1947
P0005279
(10+10)
Weiß am Zug. Letzter Zug?
R: 1. ... Sd8-e6! 2. b6xLa7 Lb8-a7 3. c5xSb6 Lf4-b8 4. d4xTc5 Lh6-f4 5. e3xTd4 Lf8-h6 6. f2xDe3 g7xLf6 7. Lg5-f6 Df3-e3 8. Lc1-g5 Kc4-b3 9. d2-d3+ ...
play all play one stop play next play all
Zvi Mendlowitz: This is a *great* problem!
Solution: Sd8-e6 (2004-12-7)
hans: R: -1. … Sd8-e6 -2. b6xLa7 Lb8-a7 -3. c5xSb6 Lf4-b8 -4. d4xTc5 Lh6-f4 -5. e3xTd4 Lf8-h6 -6. f2xDe3 g7xLf6 -7. Lg5-f6 Df3-e3 -8. Lc1-g5 Kc4-b3 -9. d2-d3+ etc.
Other captures: black h7xg6xf5xe4xd3xc2 Captured pieces are random.
It’s *great* that d8 is only square for S. (2013-1-30)
Henrik Juel: Another try, d7-d5 as last move, fails, not because the access for [Lc8] is cut off ([Lc8] could have been captured on c8), but because following -2.b6xLa7 [Ta8] cannot get home when g7xLf6 is retracted (2013-1-30)
Yoav Ben-Zvi: The cage locking element in the try noted above is made thematic through 5-fold Echo
Tries:
-1.Pd7-d5 -- NW cage prevents escape of BRa8 to be captured by WPf2
-1.BPg7xBf6 -- Cage prevents escape of BBf8 to be captured by WPf2
-1.Nc5(d4)-e6 -- Blocks path of White Pa7 to f2
-1… Pb6xBa7 -2.Ne6-c5(d4) Pc5xb6 -3.Bb8-a7 Pd4xc5 -4.Bf4-b8 Pe3xd4 -5.Bh6-f4 Pf2xe3 -6.Bf8-h6
-6…Pd2-d3 -- Cage prevents escape of WBc1 to be captured by BPg7
-6…Pa3-a4 -- SW cage prevents escape of WRa1 to be captured by BPh7
-6…Ph3-h4 -- SE cage prevents escape of WRh1 to be captured by BPh7
Two other Retros by Yehuda Veisberg were printed in "The Israel Problemist" (1964) one from FCR and the other from "The Palestine Post" (2013-1-31)
Mario Richter: For -1.Pd7-d5 and …Pa3-a4 more precisely the reason for the illegality consists in a conflict between the uncapture of a bishop and a rook. (2013-2-1)
A.Buchanan: A satisfyingly unified little problem with precise tempo. WQR cannot be captured on c2 inside the White cage, since c2 is surrounded by dark-squared White units prior to Pd2-d3. BQR cannot be captured on a7 inside the Black cage, since BKB is too slow to reach any square for capture apart from a7 right at the end of the line. (2013-2-3)
Henrik Juel: It is nice to review this fine retro (although it would be even better, if it had not been necessary to stipulate that it is White to move)
The last three single moves are determined (2018-1-12)
Alfred Pfeiffer: Deleted "White to move", because this was not a part of the stipulation in the original. (2018-1-12)
Henrik Juel: Please undelete this again, Alfred
Without the knowledge that Black must start the retroplay, we can start with -1.b6xLa7 Lb8 etc., and the surprising intended solution -1... Sd8! vanishes (2018-1-12)
Alfred Pfeiffer: OK, but "White to move" is usually the standard in problems (except help problems). (2018-1-12)
Henrik Juel: Yes, Alfred; but there is no forward stipulation (like #2) in this retro problem (2018-1-12)
Yoav Ben-Zvi: Apparently Dawson considered the stipulation "What was Black's last move" as indicating that Black was the last to move and therefore equivalent to "White to move. Last move". An alternative could be "Last move. a)Black to move b)White to move". (2018-1-14)
Mario Richter: For 'Last Movers' we also have the "Type A", "Type B" etc. categories ... (2018-1-16)
comment
Keywords: Last Move?, Type B
Genre: Retro
Reprints: 18 L'Echiquier de France 01/1957
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-2 more...
74 - P0005363
Hans Klüver
stern 02/04/1966
P0005363
(16+16)
Erfinden Sie eine möglichst kurze Schachpartie, in der durch den Umwandlungszug "Bauer wird Springer" das Matt erfolgt!
1. d4 e5 2. Kd2 exd4 3. b3 d3 4. Kc3 dxe2 5. Kb2 exd1=S#
play all play one stop play next play all
Cook: Alternative Zugfolgen
1. d4 e5 2. b3 exd4 3. Kd2 d3 4. Kc3 dxe2 5. Kb2 exd1=S#
1. d3 e5 2. Kd2 e4 3. Kc3 exd3 4. b3 dxe2 5. Kb2 exd1=S#
1. d3 e5 2. Kd2 e4 3. b3 exd3 4. Kc3 dxe2 5. Kb2 exd1=S#
1. d3 e5 2. b3 e4 3. Kd2 exd3 4. Kc3 dxe2 5. Kb2 exd1=S#
1. b3 e5 2. d4 exd4 3. Kd2 d3 4. Kc3 dxe2 5. Kb2 exd1=S#
1. b3 e5 2. d3 e4 3. Kd2 exd3 4. Kc3 dxe2 5. Kb2 exd1=S#
more ...
comment
Keywords: Non-Unique Proof Game, Construction task, Umwandlung im Mattzug, under-promotion (s)
Genre: Retro
Reprints: Die Stern-Schachprobleme 10/1991
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-6-2 more...
75 - P0005364
Hans Klüver
stern 04/05/1967
P0005364
(16+16)
Erfinden Sie eine möglichst kurze Schachpartie, in welcher der Mattzug durch den En-passant-Schlag eines Bauern erfolgt!
1) 1. e4,e3 e5 2. g4 Sc6 3. g5 d6 4. Dh5 Kd7 5. Lh3+ f5 6. gxf6ep#
2) 1. e4 e6 2. e5 Sh6 3. f4,h4 g5 4. fxg5,hxg5 Ke7 5. Dh5 f5 6. gxf6ep#
3) 1. e4 e6 2. e5 Sh6 3. Sc3 g5 4. Se4 Ke7 5. Dh5 f5 6. exf6ep#
4) 1. b3,b4 h6,h5 2. Lb2 f5 3. e4 Kf7 4. exf5 De8 5. Dg4 g5 6. fxg6ep#
5) 1. e4 h6,h5 2. Ld3 f5 3. De2 Kf7 4. exf5 De8,e5 5. De5 g5 6. fxg6ep#
6) 1. d4 d6 2. Dd3 Kd7 3. Dg6 f5 4. d5 Sc6 5. Lg5 e5 6. dxe6ep#
play all play one stop play next play all
Sally: Es gibt 3 Schlüsselzüge mit 1. Be4!
Hier können natürlich verschiedene Züge in allen Beispielen umgestellt werden. (2018-6-2)
comment
Keywords: Non-Unique Proof Game, En passant, Construction task
Genre: Retro
Reprints: Die Stern-Schachprobleme 10/1991
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2014-3-26 more...
76 - P0005976
Sergey I. Tkachenko
8821 Die Schwalbe 152 04/1995
P0005976
(11+2) C+
#1
1. ... Lxa8 e8=S#
1. ... Lxc8 Kc4#
1. ... Lxc6 Da3#
1. ... Lxa6 Dh6#
play all play one stop play next play all
Schwarz ist am Zug!
Sally: 1. Da3#?/ 1. Dh6#?/ 1. Kc4#?/ 1. Be8S#?
Aber natürlichist Schwarz am Zug
Die vier Mattzüge werden differenziert, also das Fleck-Thema im Retro-Gewand. Erfrischende Darstellung mit schwarzen Läufer-Stern. (2018-6-6)
Henrik Juel: Last move was obviously not made by Lb7, and Kd6 could not have moved from d7 (illegal check from Lc8) or from e6 (illegal double check), so White made last move, and it is Black to move
C+ by Popeye 4.61 (with 'ford #2 opt var nac') (2018-6-6)
comment
Keywords: Whose move?, Läuferstern, Umwandlung im Mattzug, under-promotion (S)
Genre: Retro, n#
Computer test: Popeye 4.61
Input: Gerd Wilts, 1995-7-1
Last update: Alfred Pfeiffer, 2018-6-6 more...
77 - P0005979
Frank Christiaans
8824 Die Schwalbe 152 04/1995
4. ehrende Erwähnung
P0005979
(11+3)
Letzter Zug?
R: 1. Ka5xBa4
play all play one stop play next play all
12 weiße Schläge: exd, fxexdxc; gxfxexd; hxgxfxexd, sLf8.
There was only one White pawn capture on c file, so if the BaP was not the last capture, it & BbP would have had to make 5 pawn captures, which is impossible.
doppelt veröffentlicht
Henrik Juel: A possible retroplay is
-1.Ka5xPa4 b5xLa4 -2.Sc3 b7 -3.e4xLd5 etc.
To reach the resulting position Black has captured [Lc1] on c1, axbxc, and cxd, and promoted [Ph7] on h1 (2018-4-2)
more ...
comment
Keywords: Last Move? (KxB), Type A, Economy record
Genre: Retro
Reprints: Sinfonie Scacchistiche 07/1995
Input: Gerd Wilts, 1995-7-1
Last update: A.Buchanan, 2018-4-2 more...
78 - P0006310
Albert Heinrich Kniest
7328 FEENSCHACH 06/1965
P0006310
(1+1)
-1s, dann h=6
Ohneschach
b) Alles eine Reihe höher
c) Alles zwei Reihen höher
d) Alles drei Reihen höher

Duplicate Diagram: P0002686

Mario Richter: Stimmt hier alles (Position,Forderung)? Wenn ja, wie sieht die AL aus? (2018-1-17)
Henrik Juel: Something must be wrong, otherwise an obvious cook in part a) is
-1... Kc2xTd3, 1.Kc1 Ta3 2.Kd1 Ta2 .. 6.Kh1 Tg2= (2018-1-17)
Henrik Juel: ... or even faster
1.Kb1 Ke3 2.Ka2 Tb3 3.Ka1 Kd3 4.Ka2 Kc3 5.Ka1 Tb2= (2018-1-17)
Mario Richter: I thought that the stipulation might have been: -1s, dann ser-h=6, but in this case I do not see any solution in a) (2018-1-17)
Alfred Pfeiffer: Noch schneller:
a) R: 1. ... Kc2xTd3 , dann 1. Kb1 Ke2 2. Ka1 Kd1 3. Ka2 Kc1 4. Ka1 Td2=, oder
a) R: 1. ... Kc3xLd3, dann 1. Kb2 Ke3 2. Ka1 Kd4 3. Ka2 Kc3 4. Ka1 Kb3=, oder
a) R: 1. ... Kc2xSd3, dann 1. Kb1 KKe2 2. Ka1 Kd1 3. Ka2 Kc2 4. Ka1 Sb4= (2018-1-17)
comment
Keywords: Help retractor, Checkless, Twin by board shift, only Kings
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-8-26
Last update: Alfred Pfeiffer, 2018-1-18 more...
79 - P0006524
Paul Raican
2184v Phénix 36 12/1995
P0006524
(14+13) cooked
BP in 8,0
Einsteinschach
1. e4 Sf6[=sB] 2. Ld3[=wS] f5 3. exf5[=wS] h6 4. Sxe7[=wL] Dxe7+ 5. Se2[=wB] Df6[=sT] 6. Tf1[=wL] Txf2[=sD]+ 7. Sxf2[=wL] Th7[=sL] 8. Lg1[=wS] Lg8[=sS]
play all play one stop play next play all
P.R.: This version is in Phenix 50/1997. (2006-6-2)
paul: Cook (Jacobi): 1.f3 e6 2.Kf2 Qg5=R 3.Ke1 Rg3=B+ 4.hxg3=S h5 5.Rxh5=Q Rxh5=Q 6.Sf5=P Qg4=R 7.fxg4=S exf5=S 8.Sh2=P Sfh6=P
In 7.5 moves: 1.f3 e6 2.f4 Qg5=R 3.f5 Rg3=B+ 4.hxg3=S h5 5.Rxh5=Q Rxh5=Q 6.Sxh5=B exf5=S 7.Bg4=S Sfh6=P 8.Sh2=P (2018-1-20)
comment
Keywords: Unique Proof Game, Einstein, Homebase (w)
Genre: Retro, Fairies
Input: Gerd Wilts, 1996-6-16
Last update: A.Buchanan, 2018-1-21 more...
80 - P0006560
Peter Fayers
Christopher Cedric Lytton

F1557R The Problemist 05/1995
P0006560
(11+13)
Wo wurde was geschlagen?
Die Springer wurden durch Equihopper ersetzt.
wSL,sSL=Equihopper
paul: See P1001280 (2017-12-2)
comment

Pieces: sl = Equihopper (E)
Genre: Retro, Fairies
Input: Gerd Wilts, 1996-6-16
Last update: Alfred Pfeiffer, 2017-12-2 more...
81 - P0006656
Thomas R. Dawson
Western Morning News & Mercury 1919
P0006656
(4+1)
Ergänze die wD, dann #1
+wDf5: 1. Db1#

R: 1. ... Kb1-a1 2. Se4-d2+
play all play one stop play next play all
more ...
comment
Keywords: Add pieces, Model mate, Rex solus (s)
Genre: Retro
Reprints: Arnhemsche Courant 24/12/1926
123 Caissa's Wild Roses 1935
Input: Gerd Wilts, 1996-7-16
Last update: Alfred Pfeiffer, 2018-2-26 more...
82 - P0006836
Johannes Manfred Wittlich
Stella Polaris 1970
1. Preis
P0006836
(14+14)
#2
1. Dh4
play all play one stop play next play all
Yoav Ben-Zvi: Assume Black can castle so BRh8 never moved. [BRa8] was captured by WP (on g3 or a3/a4) so it escaped via the d file after BPd7xe6 and prior to BPe7xd6. Before the first capture of the game, BPs were standing on d7,e7 and WPs on h2 and on b2 or b3. The first piece captured could not be a WR (both WRs were locked in the back rows) or [WBc1] (captured on the dark square d6 after the capture on e6) or [BBf8] (locked at home) or [BRa8] (locked in the back rows). Under the assumption that Black can castle, there are no other alternatives so the assumption leads to an absurdity (no piece could be the first captured) therefore Black cannot castle.
WRh1 can be removed, a nice economy since all other White officers participate in the mate. The argument must, in this case, be modified to refer to first capture by a pawn. A similar type of argument appears in a much earlier composition by the same composer: P0004446. (2018-1-8)
Henrik Juel: The argument given in SP Dec. 1971 p.281 was somewhat different, arguing that Ke8 might never have moved (but this would imply that [Th8] has moved) and that Th8 might never have moved (but this would imply that the black king has moved) (2018-1-8)
Yoav Ben-Zvi: With immobile [BRh8] but BK free to move the escape of [BRa8] could be via the e file (not the d file). In this case [WBc1] could be the first piece captured (on d6) so the claim, quoted by Henrik above, "that BRh8 might never have moved (but this would imply that the black king has moved)" is correct. To deal with this possibility my argument needs to be modified as follows:
Assume Black can castle so BK and BRh8 never moved. [BRa8] was captured by WP (on g3 or a3/a4). It could not escape via the e file, after BPe7xd6 and prior to BPd7xe6, (this would require that BK vacate e8) or via the h file (requires both BK and [BRh8] to move) so it escaped via the d file ... (2018-1-9)
Henrik Juel: Manfred Wittlich had an interesting life, according to the obituaries in SP Dec. 1970 p.191
Jan Knöppel wrote (my translation):
.. He was one of those, who came to Sweden during the world catastrophies in the 1940s ..
Alexander Hildebrand wrote:
MW was one of the first chess players, I got to know, when I started as tournament player in 1936 at the 'Verein Revaler Schachfreunde' in the Schwarzhäupter club in Estonia's capitol Tallinn. .. He even edited a chess column in a German language paper, where he showed a keen interest in composition ..
It is unknown to me, whether MW was born in Estonia by German parents or in Germany; in 1905 he played against Nimzowitsch in Tallinn. Also I do not know why he emigrated to Sweden (2018-1-9)
Henrik Juel: correction:
The Nimzowitsch-Wittlich game was played in 1919, not 1905
Nimzowitsch started without Ta1 (and with [Pa2] on a3), but he still won the game
The source for this info is 'Aron Nimzowitsch: On the Road to Chess Mastery, 1886-1924' p.272 (2018-1-9)
Mario Richter: The estonian version of his last name seems to have been 'Vitsut' (s. nimed.ee/päring?kood=546276); furtermore he seems to have written a book about astrology (s. erb.nlib.ee/?kid=12266504).
I do not know the german language paper Henrik mentioned, but in 1928 he was the editor of the chess column "Kuninglik mäng" in the (estonian language) newspaper 'Uuleht' ("Cand. math. J.M. Wittlich'i toimetusel"). (2018-1-16)
comment
Keywords: Cant Castler, Castling in the forward play
Genre: Retro
Reprints: feenschach 14, p. 61, 05/1973
Input: Gerd Wilts, 1996-7-29
Last update: Alfred Pfeiffer, 2018-1-16 more...
83 - P0007077
Werner Keym
(I) Die Schwalbe 18, p. 432, 12/1972
H. D. Leiss gewidmet
P0007077
(3+3)
h#2 (RV)
1) 1. Kc3 0-0-0 2. Tc4 Th3#
2) 1. Kc2 Ta2+ 2. Kc1 0-0#
play all play one stop play next play all
Nur eine der beiden Rochaden ist zulässig.
more ...
comment
Keywords: Retro variants (RV, pRA), Castling in the forward play, Castling
Genre: Retro
Computer test: Popeye C-Version 3.42 (1024 KB)
Reprints: D18 feenschach 27, p. 27, 04/1975
(1) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1996-8-13
Last update: Alfred Pfeiffer, 2017-12-4 more...
84 - P0007092
Karl Fabel
The Fairy Chess Review 12/1942
P0007092
(12+12)
Wieviele Züge umfaßt die kürzeste Beweispartie für dieses Diagramm?
Beide Parteien sind absolut Retropatt.
play all play one stop play next play all
In 'Kurioses Schach' wird angemerkt, daß es sich hier um eine Variation handelt.
Alfred Pfeiffer: Eine solche Aufgabe ist in FCR 12/1942 nicht enthalten! (2015-10-26)
A.Buchanan: Mysterious. If this one didn't appear in FCR 12/1942 then was it effectively anticipated by P1211899 which did appear then? Fabel was German and this was a British magazine. Weren't communications between the two countries limited in 1942? (2015-10-26)
Yoav Ben-Zvi: An identical position is reprinted in "The Problemist", January 1976 stating that it was published in Zadachy v Etudi 1/1963 with the straight-forward stipulation "Is the position possible?". A version with the 2 a pawns and 2 h pawns each advanced by one square (delaying but not avoiding retro-stalemate) was published as number 34 in "Introduction to Retrograde-Analysis" by Nikolay Beluhov. The intended solution is as follows: The last capture could not have been played by any of the pieces on the board so the piece that made the last capture must itself have been captured later, a contradiction proving the position is illegal. For a discussion of the mathematical nature of this argument see P0002611. Unfortunately the sophisticated argument is not really needed because the position is in Retro-Stalement (in Beluhov's version, close to it). (2017-12-24)
comment
Keywords: Non-Unique Proof Game, Illegal position
Genre: Retro
Reprints: 140 Kurioses Schach 1975
D27 feenschach 29, p. 114, 08-09/1975
Input: Gerd Wilts, 1996-8-13
Last update: Alfred Pfeiffer, 2015-10-26 more...
85 - P0007394
Ewald Reichel
(5) feenschach 40 11-12/1977
P0007394
(1+1)
Welches war der letzte Zug?
Längstzüger
R: 1. Ka2xSa1
play all play one stop play next play all
Vorgänger
Henrik Juel: I believe that 'White to move' should be added
This problem may very well have been made before, but an earlier appearance is nowhere to be found in the PDB (yet) (2018-2-18)
Yoav Ben-Zvi: Did Andrew, along with Henrik, miss the "Dead Reckoning" intention? (2018-2-18)
A.Buchanan: Never seen this problem before. 20 years before the dead position rule.

But I think there would still have been draw by insufficient material, which would have had the same effect here. The game ends before the knight capture.

Checkmate and pat of Black in Längstzüger are the same as in orthodox chess. Same if Black has just 1 legal orthodox move. It's only if Black has a choice that there is a difference.

So White doesn't have the move, and must have just captured something. But what? It must have been a rook, because the queen cannot checkmate as it will always have a longer move. But even then it seems hard for KvKR to co-operate for White to be mated.

In the middle of the board, can wK move next to bK in Längstzüger? That might allow wK to push bK around the board. So bK ends up on c2. This forces bR to h1. Now bK pushes wK to e.g. c3, and then moves to a3. bR can now mate on a1. Need to check the details of this, but it seems doable.

This is amazingly rich, and all based on draw by insufficient material rule. Was this the intention do you think? Certainly the stipulation seems to be correct. (2018-2-19)
A.Buchanan: Argh no, this doesn't work. Black K+R/Q can't checkmate wK under Längstzüger. wK can always wander somewhere so that bR has a longer move.
And the draw by insufficient material rule what was it when the problem was composed? The 1977 rules in Retro Corner have no such rule, either for FIDE or USCF. The 1993 FIDE rules say: "10.4 The game is drawn when one of the following endings arises: (a) king against king; (b) king against king with only bishop or knight; (c) king and bishop against king and bishop, with both bishops on diagonals of the same colour. This immediately ends the game."
Sorry for all the accidental line feeds in the last reply. (2018-2-19)
A.Buchanan: OK, it seems from the Glossary that black checkmate under Maximummer is normal. Not sure about check though, which we need if wK is going to "shoo" bK around the board. There is also an "Exacte Längstzüger" discussed in the German glossary here, which defeats my rudimentary German skills. (2018-2-19)
A.Buchanan: It boggles me that the 1977 Laws listed in Retro Corner (which are some kind of amalgam of FIDE & USCF rules) have no mention of Draw by Insufficient Material. Surely this would have been around before? A British chess instruction book in 1958 gives "too weak an army" as one of 5 ways that a game could be drawn, listing KBvK, KNvK & KvK as cases. (2018-2-19)
comment
Keywords: Maximummer, Last Move? (KxS), only Kings
Genre: Retro, Fairies
Input: Gerd Wilts, 1996-8-21
Last update: A.Buchanan, 2016-12-1 more...
86 - P0008290
Vladimir Korolkov
Aleksey A. Troitzky

15 Shakhmaty v SSSR , p. 33, 10/1982
1. Spezialpreis
P0008290
(9+12)
Ist die Stellung legal?
Beispielauflösung (mri):
R: 1. ... Kd8-c8 2. Kb8-a8 Ke8-d8 3. Ka8-b8 Lh5-f7 4. Kb8-a8 Kf7-e8 5. Ka8-b8 Ke6-f7 6. Kb8-a8 Kd5-e6 7. Ka8-b8 Kc5-d5 8. Kb8-a8 Kb4-c5 9. Ka8-b8 Kb3-b4 10. Kb8-a8 Kc2-b3 11. Ka8-b8 Kd1-c2 12. Kb8-a8 Ke1-d1 13. Ka8-b8 Kf2-e1 14. Kb8-a8 Kg1-f2 15. Ka8-b8 Kf2xTg1 16. Th1-g1 Ke1-f2 17. Tg1-h1 Kd1-e1 18. Th1-g1 Kc2-d1 19. Tg1-h1 Kb3-c2 20. Th1-g1 Kb4-b3 21. Tg1-h1 Kc5-b4 22. Th1-g1 Kd5-c5 23. Tg1-h1 Ke6-d5 24. Th1-g1 Kf7-e6 25. Tg1-h1 Ke8-f7 26. Th1-g1 Kd8-e8 27. Tg1-h1 Kc8-d8 28. Th1-g1 Td8-d7 29. Tg1-h1 Td7-c7 30. Th1-g1 c7xDd6 31. De6-d6 Td4-d7 32. Dg8-e6 Ta4-d4 33. f7xTg8=D Td5-d8 34. f6-f7 Kd7-c8 35. Kb8-a8 Ta5-d5 36. f5-f6 Kd6-d7 37. Kc8-b8 Kc5-d6 38. Kd7-c8 Ta1-a4 39. Ke6-d7 Tb1-a1 40. Ke5-e6 c2xSb1=T 41. Kf4-e5 Kd6-c5 42. Ke3-f4 c3-c2 43. Kf2-e3 c4-c3 44. Ke1-f2 d5xBc4 45. f4-f5 e6xTd5 46. Tb5-d5 Kd7-d6 47. Tb3-b5 Ke8-d7 48. Ta3-b3 Td5-a5 49. Ta1-a3 Td8-d5 50. f2-f4 f7xDe6 51. b3xSc4 Se5-c4 52. Dc4-e6 Ta8-d8 53. Dc3-c4 Sd7-e5 54. Dc2-c3 Sb8-d7 55. Dd1-c2 Lg4-h5 56. a2xSb3 Lc8-g4 57. c2xDd3 Dd8-d3 58. Tg1-h1 d7xSc6 59. Se5-c6 Sd4-b3 60. Sf3-e5 Sf5-d4 61. Th1-g1 Th8-g8 62. Sh4-f3 Sh6-f5 63. Sf3-h4 Sg8-h6 64. Sg1-f3
play all play one stop play next play all
wCaps: f7xTg8=D/L/S, a2xb3xc4, c2xd3
sCaps: Kf2xTg1, c7xd6, d7xc6, f7xe6xd5xBc4xb1=T
Version zu P0001243, die den dritten sT im Diagramm vermeidet. (Autorangabe wie im Original in der Rubrik 'Redkije Shanry' als Problem Nr. 15)

Der Entschlag eines eingesperrten Original-T als Tempobringer ist ein immer wieder gern genutztes Sujet, s. z.B P1013078 oder P1346006
Henrik Juel: Yes, legal position. -1... Kd8 -2.Kb8, sK uncaptures wTg1 and returns to c8, retract c7xd6 etc. White promoted f7xTg8=DLS, Black promoted c2xb1=T. (2004-1-2)
Yoav Ben-Zvi: A stipulation such as "Which captures are fully determined" would require a full analysis, including why WK cannot uncapture BN.
The problem appears as No. 46 in an article by Plaksin and Kornilov on Troitzky from 1997. It is presented as an adaptation by Korolkov of a problem by Troitzky. (2018-1-22)
comment

Genre: Retro
Input: Gerd Wilts, 1996-9-16
Last update: Mario Richter, 2018-1-23 more...
87 - P0008416
Harry Goldsteen
Probleemblad 1 01-02/1989
P0008416
(10+15)
#1 (wer?)
Beispielauflösung (mri):
R: 1. ... Sh6-g8 2. f6xLe7 Kg8-h8 3. f5-f6 Kf8-g8 4. f4-f5 Ke8-f8 5. f3-f4 Lf8-e7 6. f2-f3 e7-e6 7. Se6-d8 Kd7-e8 8. Sf4-e6 Ke6-d7 9. Sh3-f4 Kf5-e6 10. Sf4-h3 Kg5-f5 11. Sd5-f4 Kh4-g5 12. Sf4-d5 Kh3-h4 13. Sh5-f4 Kg2-h3 14. Sg3-h5 Kf1-g2 15. Sh5-g3 Ke1-f1 16. Sf4-h5 Kd1-e1 17. Sh3-f4 De1-d2 18. Sf4-h3 Td2-c2 19. Sh3-f4 Sc2-a1 20. Ka1-b1 Sd4-c2 21. Lb1-a2 La2-b3 22. Sg1-h3 Tb3-c3 23. Sh3-g1 Tb6-b3 24. Sf4-h3 Dh1-e1 25. Sh3-f4 Dd5-h1 26. Sg1-h3 Tc2-d2 27. Sh3-g1 Tc3-c2 28. Sg1-h3 Tb3-c3 29. Sf3-g1 Tb5-b3 30. c3-c4 Dd8-d5 31. Se5-f3 Le6-a2 32. La2-b1 Kc2-d1 33. Ld5-a2 Kb3-c2 34. Lg2-d5 Kb4-b3 35. c2-c3 Kc5-b4 36. Kb1-a1 Kd6-c5 37. Kc1-b1 Kd7-d6 38. Sc4-e5 Ke8-d7 39. Sa3-c4 Lc8-e6 40. Lf1-g2 d7xDc6 41. Dh1-c6 Th5-b5 42. Kd2-c1 Sf5-h6 43. Ke1-d2 Th8-h5 44. Sb1-a3 Tg8-h8 45. Dh8-h1 g5-g4 46. h7-h8=D Th8-g8 47. h6-h7 Ta6-b6 48. h5-h6 h6xLg5 49. Lf6-g5 Sc6-d4 50. Lc3-f6 Sb8-c6 51. Ld2-c3 Ta7-a6 52. Lc1-d2 Ta8-a7 53. d2-d3 d3xSe2 54. Sg1-e2 c4xTd3 55. Ta3-d3 b5xTc4 56. Th4-c4 a6xDb5 57. De2-b5 a7-a6 58. Dd1-e2 h7-h6 59. Th1-h4 Sh6-f5 60. g5-g6 Sg8-h6 61. Ta1-a3 Sh6-g8 62. h4-h5 Sg8-h6 63. g4-g5 Sh6-g8 64. e2-e3 Sg8-h6 65. h2-h4 Sh6-g8 66. g2-g4 Sg8-h6 67. a2-a4
play all play one stop play next play all
Henrik Juel: 1.Sxf7#, not 1.. Rc1? -1.. Sh6 -2.f6:B Kg8 -3.f5 Kf8 -4.f4 Ke8 -5.f3 Bf8 -6.f2 e7 -7.Se6, bK retracts to d1, bQ to e1, etc. (2003-8-26)
Yoav Ben-Zvi: White's only capture was WPf6xBe7. All 6 missing White pieces were captured by BPs. [WPh2] accounts for one of the BP captures and did not itself capture so it must have promoted on h8 after [BPh7] captured on g file to clear the way. The promoted White piece could either replace a knight (moving to d8) or else it is itself captured by a BP.
When [BPa7] completed its fourth capture by BPd3xe2, WP stood waiting on d2 so [WBc1] was locked at c1. After its release [WBc1] is captured on g5 (only BP capture left on a dark square) followed by promotion of [WPh2]. This means [BPa7] could not have captured the promoted piece or [WBc1] so it did capture [WRa1] which escaped via a3 so [WPa2] must already have advanced to a4. Prior to BPh6xBg5 [WPg2] must advance to g6. This implies that the subsequent promotion on h8 was not to knight as it would not be able to exit h8. Since the promotion on h8 occurs after [BPa7] and [BPh7] have completed their captures, the promoted piece is captured by BPd7xc6. Prior to the capture by [BPd7], [BBc8] was locked at c8 and [BPe7] had not advanced to e6 (where it would obstruct the subsequent exit of [BBc8]) so [BBf8] is also locked at home and therefore, when the promoted piece is captured on c6, BQ and BK stand locked in the Central cage.
Looking backward: The above shows that WPa4 and WPg6 cannot retreat before the uncapture BPh6xBg5 which occurs after the unpromotion on h8 and retreat of the unpromoted WP to h5. Immediate Retro-stalemate can be prevented by retracting -1.WPf6xBe7? Bf8-e7 -2.Pf5-f6 Pe7-e6 -3.Ne6-d8 and a knight can provide the shield on d1 extracting BQ via e1 to unravel the South-East cage but with BB locked on f8 and WP standing on g6 (unable to retreat to g5 until the retreat of WP unpromoted from piece uncaptured on c6 allows BPh6xBg5) the BK cannot exit the North-East cage to retract to e8 allowing the uncapture on c6. Therefore the retraction sequence presented by Henrik above is the only way to release WNd8 in time to prevent retro-stalemate when WPe7 retracts back to f2. Standing on f2 the WP prevents a retro-shield by the knights on d1 so BK comes to the rescue.
A lovely "Solver's problem" (see comment by Tom Volet to P1347268). The #1 stipulation is a throw-back to earlier times. A modern replacement could be "Last 12 single moves". (2018-5-4)
comment
Keywords: Whose move?
Genre: Retro
Input: Gerd Wilts, 1996-9-17
Last update: Mario Richter, 2018-5-5 more...
88 - P0008458
Unto Heinonen
1442 Probleemblad 5 1988
P0008458
(14+14) cooked
BP in 42,0
AL: 1. h4 g5 2. Th3 gxh4 3. Tf3 h3 4. g4 h2 5. g5 h1=D 6. g6 Dh6 7. Sh3 De3 8. fxe3 h5 9. Sf2 h4 10. Sg4 h3 11. Kf2 h2 12. Kg3 h1=S+ 13. Kf4 Sf2 14. Lh3 Sd3+ 15. cxd3 a5 16. Dc2 a4 17. Dc6 a3 18. Sc3 axb2 19. a4 b1=S 20. La3 Ta5 21. Lb4 Tc5 22. a5 Sa3 23. a6 Sc4 24. a7 Sb6 25. a8=S Sd5+ 26. Ke5 Lh6 27. Sb6 Lg5 28. Ta8 Sh6 29. Sa4 b6 30. g7 La6 31. g8=L Lb5 32. Lh7 Sa6 33. Lg6 0-0 34. La5 f5 35. Le8 d6+ 36. Ke6 Db8 37. Kd7 Da7 38. Td8 Sf4 39. Kc8 Sg2 40. Td7 f4 41. Kd8 Tf5 42. Lh5 Sb8
play all play one stop play next play all
Paulo Roque: obs: 29.S6a4
obs: 41...T8f5 (2008-12-15)
paul: Cook: 1. Nb1-c3 Pg7-g5 2. Ng1-f3 Pg5-g4 3. Nf3-e5 Pg4-g3 4. Rh1-g1 Pg3xh2 5. Pg2-g4 Pa7-a5 6. Rg1-g3 Pa5-a4 7. Pg4-g5 Ph2-h1=Q 8. Ne5-g4 Qh1-h6 9. Pg5-g6 Qh6-e3 10. Pf2xe3 Ph7-h5 11. Ke1-f2 Ph5-h4 12. Kf2-f3 Ph4-h3 13. Kf3-f4 Ph3-h2 14. Bf1-h3 Pa4-a3 15. Qd1-h1 Pa3xb2 16. Qh1-c6 Ph2-h1=B 17. Pa2-a4 Bh1-e4 18. Rg3-f3 Be4-d3 19. Pc2xd3 Pb2-b1=N 20. Ba3 etc. (Euclide 1.11) (2017-12-26)
comment
Keywords: Unique Proof Game, Castling
Genre: Retro
Input: Gerd Wilts, 1996-10-19
Last update: Gerd Wilts, 2004-8-11 more...
89 - P0008560
Unto Heinonen
Springaren 1996
P0008560
(16+6)
ser-BP in 53
1. f4 2. f5 3. f6 4. fxg7 5. gxh8=T 6. Txh7 7. Th4 8. Tb4 9. h4 10. h5 11. h6 12. h7 13. hxg8=L 14. Lh7 15. Le4 16. Lc6 17. e4 18. Ke2 19. Kd3 20. Kc4 21. Kb5 22. Lc4 23. Se2 24. Dg1 25. Dxa7 26. Dxa8 27. Da3 28. Dc3 29. a4 30. a5 31. a6 32. a7 33. a8=S 34. Sb6 35. Sxc8 36. Sxe7 37. Sf5 38. Sd4 39. Sb3 40. d4 41. Lg5 42. Lxd8 43. Lxc7 44. Kb6 45. Ka7 46. Ka8 47. Ta7 48. Sa3 49. Ta1 50. Ta2 51. Sa1 52. b3 53. Db2
play all play one stop play next play all
paul: See P1007350 (2011-7-3)
paul: The first 28 moves checked by Jacobi(~2.5 hours) (2018-4-24)
more ...
comment
Keywords: Unique Proof Game, Length Record, Series mover
Genre: Retro, Fairies
Input: Gerd Wilts, 1997-1-9
Last update: A.Buchanan, 2018-4-24 more...
90 - P0008584
Bernd Schwarzkopf
6020 Die Schwalbe 107 10/1987
P0008584
(1+0) cooked
Ergänze sK und 5wSS zu einem IC!
a) AL: +sKe7, wSf6f7g8h6h7
b) NL: +sKb6, wSa7a8b3b7b8
play all play one stop play next play all
Schon 1998 fanden die Brüder Ulrich und Roland Voigt die NL: wSa7a8b3b7b8 - sKb6, die auch diagonal gespiegelt und in anderen Ecken möglich ist.
Cook: +wSa7a8b3b7b8+sKb6
Bernd Schwarzkopf: Schon 1998 fanden die Brüder Ulrich und Roland Voigt die NL: wSa7a8b3b7b8 - sKb6, die auch diagonal gespiegelt und in anderen Ecken möglich ist. (2018-6-11)
Henrik Juel: In the intended solution the check is clearly impossible
In the cook the check seems to be explained by -1.Sc7xa8+, but then Black has no preceeding move available, because all empty squares around Kb6 are covered by two white knights, and a possible uncapture on a8 does not help (2018-6-11)
comment
Keywords: Illegal cluster, only Kings, Symmetrical position, Asymmetrical solution
Genre: Retro
Reprints: (V) Problemkiste 109 02/1997
H39 ASymmetrie 2013
Input: Gerd Wilts, 1997-2-22
Last update: Alfred Pfeiffer, 2018-6-13 more...
91 - P0008610
Thomas Volet
8553 Springaren 12/1996
1. Preis
P0008610
(13+9)
Welches waren die letzten 5 Einzelzüge?
R: 1. Td2-d1 h3xDg2 2. Sa3-b1 Kb1-a1 3. Sc2-a3+
play all play one stop play next play all
Mario Richter: Correct solution: Not -1. ... h3xQg2??, since this forces the bPh3 to go back to h5 before the bK can be freed.
Therefore, R: -1.Rd2-d1 g3-g2! -2.Na3-b1 Kb1-a1 -3.Nc2-a3++.
White pawn captures: g2xQf3,d2xBe3, wPh2 captured both bRR and bNN on g3,f4,e5,d6 and bPc7 on c7.
Black pawn captures: h4xQg3, a7xR or Nb6, e7xN or Rd6.
A very fine problem! (2010-3-14)
Henrik Juel: Mario has given the highlights, but the problem deserves a more detailed solution, I think
The pawn captures match the missing men
White captured d2xe3, g2xf3, h2xg3x..xc7
Black captured axb, e7xd6 (after d6xc7), hxg, so [Pc7] did not capture and was captured by d6xPc7
In the diagram position Black cannot retract a6xb5 (because of [Ta8]), nor b6-b5 (because of Lb8), nor e7xd7 (because of [Lf8]), nor f7-f6 (because of Kh8)
Ka1 must be extracted via h3,h4, so retracting h3xg2 would waste a pawn retraction needed at the end of the retroplay, where LDKL from each camp are locked by six pawns
Following the solution
-1.Td2 g3 -2.Sa3 Kb1 -3.Sc2
the retroplay may continue
-3... Kc1 -4.Sa3 Kd1 -5.Tc2
then retract Kd1 to e8, Tc2 to a1, c2-c3, Lb8 to c1, Kh8 to e1, Ld3 to f1, g2xDf3, Df3 to d8, h4xDg3, Dg3 to d1, d2xLe3
Now white LDKL are locked, but White can still retract with Ta1 or Sa3
Then retract f7-f6, Le3 to f8, and now we need the two black pawn retractions:
-55... e7xTd6 (or e7xSd6) -56.Td3 b6 -57.d6xPc7 h5 -58.e5xTd6 (or e5xSd6) etc.
The rest is trivial as there is room for the rooks to get home (2017-12-29)
Henrik Juel: The forced retro sequences like h4xDg3 before Dg3 to d1 before d2xLe3 before Le3 to f8 before e7xd6 show that a retroplay like the one given is necessary (2017-12-29)
comment
Keywords: Last Moves? (5)
Genre: Retro
Reprints: feenschach 153 10-12/2003
Input: Gerd Wilts, 1997-3-22
Last update: Gerd Wilts, 2005-12-3 more...
92 - P0008779
Waleri A. Liskowez
7161 feenschach 123 01-06/1997
P0008779
(4+8)
h#2
a) pRA
b) wSe2 statt wBe2: 2.1...
a)
1) 1. Ke4-f4 0-0+ 2. Kf4-g3 Tf1-f3#
2) 1. Ke4-d4 0-0-0+ 2. Kd4-c3 Td1-d3#

b)
1. Ke4-e3 Th1xh2 2. e5-e4 Th2-h3#
1. Ke4-f3 Ta1-a3+ 2. Kf3-g2 Th1-g1#
play all play one stop play next play all
VL: Solution:
(a) I 1.Ke4-f4 0-0+ 2.Kf4-g3 Rf1-f3#
II 1.Ke4-d4 0-0-0+ 2.Kd4-c3 Rd1-d3#

(b) 1.Ke4-e3 Rh1*h2 2. e5-e4 Rh2-h3#
1.Ke4-f3 Ra1-a3+ 2.Kf3-g2 Rh1-g1#

In (a), the solution depends on legal castling.
But when both castlings are legal (b), we need not castling at all. (2002-4-5)
more ...
comment
Keywords: Retro variants (RV, pRA), Castling, Forsberg twin
Genre: Retro
Reprints: (4) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1997-6-16
Last update: Alfred Pfeiffer, 2017-12-4 more...
93 - P0008898
Paul Raican
P0009 StrateGems Vol.1 No 2 04-06/1998
P0008898
(13+14) C+
BP in 6,5
Einsteinschach
1. d4 e6 2. d5 exd5[=sS] 3. h4 Se3[=sB] 4. Th3[=wL] exf2[=sS] 5. Lxd7[=sT] Sxd1[=wL] 6. Txd1[=wD] Se7[=sB] 7. Sd2[=wB]
play all play one stop play next play all
paul: Pieces
White Ph4 Pa2 Pb2 Pc2 Pd2 Pe2 Pg2 Ra1 Bc1 Qd1 Ke1 Bf1 Sg1
Black Ra8 Sb8 Bc8 Qd8 Ke8 Bf8 Rh8 Pa7 Pb7 Pc7 Pe7 Pf7 Pg7 Ph7
Try: 1.h4? e6 2.Rh3=B Se7=P 3.Bxe6=R dxe6=S 4.d4 Sxd4=B 5.Sd2=P Bxf2=R 6.Kxf2 Kd7 7.Ke1 Ke8 too long.
Sol: 1.d4! e6 2.d5 exd5=S 3.h4 Se3=P 4.Rh3=B exf2=S 5.Bxd7=R Sxd1=B 6.Rxd1=Q Se7=P 7.Sd2=P.
wQd1 isn't the original. (2008-1-23)
more ...
comment
Keywords: Einstein, Unique Proof Game, Homebase (s)
Genre: Fairies, Retro
Computer test: C+ Jacobi (2018-1-20)
Input: Gerd Wilts, 1998-6-26
Last update: A.Buchanan, 2018-2-7 more...
94 - P0008923
Unto Heinonen
3111 Probleemblad 11/1996
3. Preis
P0008923
(12+14)
BP in 30,0
1. h4 a5 2. h5 a4 3. h6 Ta5 4. hxg7 h5 5. Th3 h4 6. Ta3 h3 7. g4 h2 8. g5 h1=S 9. g6 Tg5 10. f4 Tg2 11. f5 Sg3 12. 12. f6 Th1 13. fxe7 f5 14. Sh3 Sf6 15. g8=T Sa6 16. g7 Kf7 17. e8=T Lc5 18. Te5 Lg1 19. Ta5 b5 20. e4 Lb7 21. e5 Da8 22. Tb8 Le4 23. Tb6 cxb6 24. g8=T bxa5 25. Tg4 fxg4 26. e6+ Kg6 27. e7 Sf5 28. e8=T Se7 29. Tc8 Se8 30. Tc6 dxc6 11. f5 Sg3 12. f6 Th1 13. fxe7 f5 14. Sh3 Sf6 15. g8=T Sa6 16. g7 Kf7 17. e8=T Lc5 18. Te5 Lg1 19. Ta5 b5 20. e4 Lb7 21. e5 Da8 22. Tb8 Le4 23. Tb6 cxb6 24. g8=T bxa5 25. Tg4 fxg4 26. e6+ Kg6 27. e7 Sf5 28. e8=T Se7 29. Tc8 Se8 30. Tc6+ dxc6
play all play one stop play next play all
paul: First 24 moves verified with Euclide 1.11. (2017-12-26)
comment
Keywords: Ceriani-Frolkin Theme (TTTT), Unique Proof Game
Genre: Retro
Reprints: feenschach 137 08-09/2000
H32 FIDE Album 1995-1997 2004
Input: Gerd Wilts, 1998-6-26
Last update: Gerd Wilts, 2010-6-29 more...
95 - P0009149
Andrey Frolkin
R036 Probleemblad 11-12/1998
P0009149
(14+13)
BP in 26,0
1. h4 d5 2. h5 d4 3. h6 d3 4. hxg7 dxc2 5. d4 f5 6. Ld2 c1=L 7. Da4+ Kf7 8. Dxa7 e5 9. La5 Lh6 10. Sa3 f4 11. 0-0-0 e4 12. Kc2 e3 13. Kb3 exf2 14. Sc2 La3 15. Ka4 Se7 16. b4 Te8 17. g8=T Lf8 18. Th6 Lh3 19. gxh3 Lc1 20. Lg2 f1=L 21. Lc6 Dd5 22. Lb5 Sbc6 23. h4 Tad8 24. Sh3 Td6 25. Sf2 Lh3 26. a3 Lc8
play all play one stop play next play all
paul: Here, we have also an interchange between Bc1 and Bf8. (2018-3-21)
Henrik Juel: The months should be 11-12, not 09 (2018-3-21)
Mario Richter: @Henrik: Is my guess correct that "9" might be the issue number? (i.e. issue 9 of 1998 was for the months Nov.+Dec.?) (2018-3-21)
Henrik Juel: No, Mario; I think the error might have occurred, because Andrej also had a proof game in the preceding issue
Back then PB had six issues per year, numbered 1-6 for each year (unlike Die Schwalbe), so the issue number contains little information
This problem appeared in issue 6, Nov-Dec 1998 (2018-3-21)
comment
Keywords: Unique Proof Game, Pronkin Theme (l)
Genre: Retro
Input: Gerd Wilts, 1999-2-27
Last update: Mario Richter, 2018-3-21 more...
96 - P0500144
Karl Hasenzahl
1335 Die Schwalbe 20 08/1963
2. ehrende Erwähnung
P0500144
(5+5) C+
h#2
2.1...
1) 1. Tae5 Kg8 2. Ke8 La4#
2) 1. The5 Kg6 2. Ke6 Lf5#
play all play one stop play next play all
more ...
comment
Keywords: Fesselungsspiel (222 202 000)
Genre: h#
Computer test: Popeye C-Version 3.47 (1024 KB)
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2018-2-26 more...
97 - P0500309
Claude Goumondy
2409 Die Schwalbe 50, p. 221, 04/1978
3. Preis
P0500309
(5+8) C+
h#2
b) wBc6 nach a4
c) ferner wSe8 nach d7
d) ferner sBb3 nach d3
a) 1. Ke6 d4 2. Df7 Te5#
b) 1. Kc6 d3 2. Dd7 axb5#
c) 1. Kc4 dxc3 2. Dd3 Tc5#
d) 1. Ke4 dxe3 2. Df3 Te5#
play all play one stop play next play all
KSp Königsstern
BSp
siehe P0503414
Sally: Albino und schwarzer Königsstern. Beide Themen sind zwar auch schon im Hilfsmatt bekannt, aber in dieser Verbindung sind sie hier zum erstenmal dargestellt. (2018-6-22)
comment
Keywords: Albino, Figurenspiel, king's star
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2018-6-23 more...
98 - P0500314
Claude Goumondy
2571 Die Schwalbe 53, p. 313, 10/1978
5. ehrende Erwähnung
P0500314
(4+5) C+
h#3
b) sDc5 tauschen mit sBe5
c) sDc5 nach f6
a) 1. Lc6 Lg8 2. Le4 Tf7 3. Kd5 Tf6#
b) 1. Lb5 La8 2. Lc4 Tb7 3. Kd5 Tb6#
c) 1. Ld7 Lxb3 2. Lf5 c4 3. Ke6 c5#
play all play one stop play next play all
Sally: Drei verschiedene Batteriematts mit nur neun Steinen. (2018-6-22)
comment

Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
Input: Gerd Wilts, 1996-6-6
Last update: hpr, 1999-5-17 more...
99 - P0500324
Claude Goumondy
2798 Die Schwalbe 57, p. 433, 06/1979
4. Preis
P0500324
(5+4) C+
h#2
b) wSh3 nach h2
c) wSh3 nach g2
d) wSh3 nach f2
e) wSh3 nach e3
f) wSh3 nach c8
a) 1. Ke3 Sg5 2. Dd2 Tf3#
b) 1. Ke4 Tf5 2. Dd3 Te5#
c) 1. Kd3 Tf4 2. Dc2 Td4#
d) 1. Kc4 Kc6 2. Db3 Tf4#
e) 1. Kc5 Kc7 2. Db4 Tf5#
f) 1. Kd5 Te6 2. Dc4 Te5#
play all play one stop play next play all
KSp
DSp
Doppelveröffentlichung!
Sally: Mit kleinen Mitteln sehr gut komponiert. Ein hervorragendes Stück! Dieser sechsmal Synchron-side step ist bewundernswert.
Schade , das es auch nicht "Ke5" geht. (2018-6-22)
comment
Keywords: Figurenspiel
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
Reprints: 9455 Schach 04/1981
Input: Gerd Wilts, 1996-6-6
Last update: hpr, 1999-5-17 more...
100 - P0500326
Claude Goumondy
2968 Die Schwalbe 60 12/1979
1. ehrende Erwähnung
P0500326
(4+7) C+
h#2
b) wSb6 nach b8
c) ferner sKd4 nach e4
d) ferner wLe2 nach a6
a) 1. Te3 Lh6 2. Le4 Lxg7#
b) 1. Le4 Ld2 2. Td5 Sc6#
c) 1. Ld4 Sd7 2. Te5 Sf6#
d) 1. Td3 Sd7 2. Ld4 Lxb7#
play all play one stop play next play all
Sally: Vier mal Hilfsmatt-Inder, wobei lediglich , der symmetrische
lösungsverlauf in a) und d) bzw. b) und c) stört. Analoges Spiel der schwarzen Türme und Läufer auf der d und e Linie. (2018-6-24)
comment

Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2018-6-25 more...
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