1125 problem(s) found in 1156 milliseconds (displaying 100 problem(s)).

1 - P0000033
S. N. Ravishankar
5467v Die Schwalbe 98 04/1986
P0000033
(5+3) cooked
#1 vor 14
VRZ, Typ friedlich
R: 1. Tg1-f1 2. Tf2-f3 Te2- 3. Te1-g1 4. Te2-f2 Ta2- 5. Ta1-e1 Tb2-a2 6. Tb1-a1 Tc2-b2 7. Tc1-b1 Td2-c2 8. Tg1-c1 Tc2-d2 9. Td2-e2 Tb2-c2 10. Tc2-d2 Ta2-b2 11. Tb2-c2 g3-g2 12. Lg2-h3+, dann 1. Th1#
play all play one stop play next play all
Cook: Kurzlösung:
R: 1. Tg1-f1 droht 2. Tf1-f3, dann 1. Th1#
R: 1. Tg1-f1 Tf2-g2 2. Tf1-g1, dann 1. T3xf2#
(Mario Richter)
Mario Richter: So wie abgebildet, sollte die Problemno. nicht '5467v' sein.
Die Verbesserung (also das 'v') scheint erst später erschienen zu sein.
Das Diagramm ist kurzlösig durch: R: 1. Tg1-f1 (dr. 2. Tf1-f3, dann 1. Th1#) Tf2-g2 2. Tf1-g1, dann 1. Tf3xf2#. (2011-8-18)
Alfred Pfeiffer: Dies ist schon eine Veränderung des Originals. Wo die (in der LB bereits erwähnte) "Korrekturfassung" erschien, ist unklar. (2018-1-16)
S N Ravi Shankar: Given Version of the problem is incorrect. bRg2 should be on f2 and a bP should be placed on g2. Stipulation is -12 and #1.
Solution is
-1. Rg1! Rb2 (say) -2. Rf2 Re2! -3.Re1! Rb2 (say) -4. Re2! Ra2!(-4 ... Rd2? -5. Rg1! as in text)
-5. Ra1! Rb2 -6. Rb1 Rc2 -7. Rc1 Rd2 -8. Rg1! Rc2 -9. Rd2! Rb2 -10. Rc2 Ra1 -11. Rb2 g3 -12. Bg2
and now 1. Rh1# (2019-1-2)
comment
Keywords: Defensive Retractor, Type Pacific
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-1-17 more...
2 - P0000108
Andrey Frolkin
6272 Die Schwalbe 111 06/1988
1. Lob
P0000108
(30+0) C+
Färbe die Steine!
BP in 19,0
1. h4 d6 2. Th3 Sd7 3. Tb3 Sdf6 4. Tb6 axb6 5. f4 Ta3 6. Kf2 Th3 7. a4 Th1 8. Ta3 Lh3 9. Tg3 Dd7 10. Tg6 hxg6 11. a5 Th5 12. a6 Ta5 13. h5 Ta1 14. h6 Da4 15. h7 b5 16. h8=T Sh7 17. a7 f6 18. a8=T+ Kf7 19. Ta7 Dd4+
play all play one stop play next play all
Henrik Juel: C+ by Natch 3.1 (16 min.)
The colored position has black Ta1,h1 and Pb5,g6, and white Ta7,h8, otherwise 'natural' (2018-12-7)
François Labelle: Henrik, did you really test all 2^30 possible colorings with Natch, or did you use human deductions to reduce the possibilities (making this HC+), or did you only test the intended coloring (making this a partial C+)? (2018-12-9)
Mario Richter: I do not think that it is necessary to check all 2^30 colorings, since the color of the pawns on files c,d,e and f is completely determined. This and more restrictions on the set of potentially possible colorings may be derived from insights presented in an article "Aggregierte Schlagbilanz" by Frolkin & Kornilov, feenschach 130, p.411ff. Since the mechanisms presented there can at least partially be implemented in a little computer program, even a "full C+" label for this problem is not out of reach ... (2018-12-10)
Henrik Juel: I only tested the intended coloring, Francois,
so the C+ label is not justifiable
In the other coloring proof games I write something like
The colored position was C+ by Natch

Mario is right, of course, in that not all colorings need testing; but still the number is very large
This genre is somewhat messy; at first I thought that the solver could determine the coloring, but this is clearly not the case; also, the intention is not
'color the men such that a correct proof game in 19 results' (2018-12-11)
A.Buchanan: Henrik: so what exactly should the stipulation be for clarity? (2018-12-12)
comment
Keywords: Unique Proof Game, Coloring problem, under-promotion (TT), Phoenix
Genre: Retro
Computer test: Natch 3.1 (16 min.)
Reprints: 158 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-7 more...
3 - P0000132
Nikita M. Plaksin
6578 Die Schwalbe 116 04/1989
2. ehrende Erwähnung
P0000132
(8+12)
Zeige, daß im Verlauf des Retrospiels zwingend die Möglichkeit zum ep-Schlag bestand!
Madrasi
paul: The stipulation in English: Show that, in the course of the retro game, the possibility for the en passant move existed! Madrasi (2019-1-13)
comment
Keywords: Madrasi, En passant
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2012-7-8 more...
4 - P0000143
Nikita M. Plaksin
6689 Die Schwalbe 118 08/1989
4. Lob
P0000143
(13+9)
Löse die Stellung auf!
Madrasi RI
R: 1. Se6xDd8 Bd2xTe1=L 2. Tb1-e1 c3xTd2 3. Tb8-b1 b4xTc3 4. b7-b8=T 5. a6xT(S)b7
play all play one stop play next play all
paul: If 4. -b5-b4 5.a6xBishop b7? Bc8-b7, then Black will be retro-stalemated. To unlock the position, the retro-play must be: Rf2 - Rg8 - g7-g8=R - Ph6xRg7 - Ph5 -Pg4xSh5(bSg3-h5), Rh1 - Rg8 - g7-g8=R - Ph6xRg7 - Ph5, Sh3-g5, Pg7-g5, Kg6-f7, Pf4-f5+, bBf8 was captured at home. (2019-1-13)
comment
Keywords: Madrasi
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-15 more...
5 - P0000307
Thomas Volet
8130 Die Schwalbe 141 06/1993
P0000307
(12+14)
Ist die Stellung legal?
Die kürzeste Zugfolge bis zum letzten B-Zug sieht prinzipiell so aus ('...' = Wartezug):
R: 1. Ta8-b8 Kd1-c1 2. Kb8-c8 Ke2-d1 3. Lf8-g7 Lg7-h6 4. Lg8-h7 ... 5. Tb1-b2 ... 6. Th1-b1 ... 7. Th7-h1 Lh6-g7 8. Tg7-h7 ... 9. Lh7-g8 ... 10. Tg8-g7 ... 11. Lg7-f8 ... 12. Tc8-g8 ... 13. Lg8-h7 Td8-d7 14. Lh7-g8 Tg8-d8 15. Lf8-g7 Tg7-g8 16. Lg8-h7 Th7-g7 17. Te8-c8 Lg7-h6 18. Kc8-b8 Th1-h7 19. Lh7-g8 Lh6-g7 20. Lg7-f8 Tg1-h1 21. Tg8-e8 Tg4-g1 22. Lf8-g7 ... 23. Tg7-g8 24. Lg8-h7 25. Th7-g7 Lg7-h6 26. Th1-h7 Lh6-g7 27. Kd7-c8 ... 28. Lh7-g8 ... 29. Lg7-f8 ... 30. Tg8-a8 ... 31. Lf8-g7 ... 32. Tg7-g8 ... 33. Lg8-h7 ... 34. Th7-g7 Lg7-h6 35. Th3-h7 Th4-g4 36. ... Th7-h4 37. ... Lh6-g7 38. ... Tg7-h7 39. Lh7-g8 Tg8-g7 40. Lg7-f8 Ta8-g8 41. Lf8-g7 Lg7-h6 42. Lg8-h7 ... 43. Th7-h3 Lh6-g7 44. Tg7-h7 Ld3-c2 45. Lh7-g8 ... 46. Tg8-g7 ... 47. Lg7-f8 ... 48. Td8-g8 ... 49. Ke8-d7 ... 50. Kf8-e8 Lb5-d3 51. ... Ld7-b5 52. ... Lc8-d7 53. ... d7-d6!
play all play one stop play next play all
"Nach 'unserer' Ausdrucksweise ist die Stellung also illegal, weil nur unter Außer-acht-Lassung der 50-Züge-Regel erspielbar." (HHS)
"Schöne Rangierarbeit mit guter Ausnutzung der LL-Schleuse" (DB).
Auf derartige Forderungsfragen erwartet man ja i.a. ein JA als Antwort und so wäre eine Verkürzung der Zügezahl auf genau 50 Züge bis zum letzten B-Zug angebracht (und auch leicht zu bewerkstelligen). So vermutet jeder einen besonderen - aber nicht vorhandenen - Trick des Autors, um die 50-Züge-Beschränkung nicht zu überschreiten. Mehrere Löser kamen beim Rangieren offensichtlich so ins Schwitzen, daß sie gar nicht an die 50-Züge-Regel gedacht haben und so fälschlicherweise 'Legalität' behauptet haben! Ebenso falsch lagen einige Löser, die 'Illegalität' attestierten mit der Begründung sSh8 oder sLh6 seien nicht zu realisieren. 3/III und 5L., welche die Stellung aufgedröselt haben (von denen kam nur HHS zu der Erkenntnis: illegal!).
Brassaud: Je suis d’accord avec la solution proposée jusqu’à 53) Wartezug, d7-d6 et la partie est considérée comme nulle.
La position intermédiaire obtenue après 53) … , d7-d6 est la suivante :
T1ft1R1c/pppp/PPFF/4PtPf/3pppp1/8/1P6/P2pr3/7T
Cette position est-elle légale ? Je ne le crois pas. Les pions noirs ont pris 4 fois. Le pion h2 a donc été promu. Cette promotion peut être encore sur l’échiquier sous forme de T ou de F, ou bien a été prise mais c’est sans réelle importance. Pour dénouer cette position il faut d’abord reprendre d6xCe7 puis c5xDd6 afin de ramener ce pion en c2. A ce moment la tour blanche et les 2 fous de cases noires peuvent sortir mais le FB de g8 et le roi blanc sont encore dans la cage. Le pion de c2 a effectué les 2 seules prises de pièces noires. Les autres PB venus de e2,f2, g2 n’ont pas fait de prise et le pion de h2 a été promu en h8 sans prise. Il faut ensuite reprendre d6-d5 et e7xd6 (pièce quelconque)puis reprendre la promotion du pion en h8. Mais là je ne vois pas comment en raison du cavalier bloqué par les 2 pions blancs de f7 et g6. Le retour d’une pièce promue (dame ou tour ou même le fou de g7) en h8 ne peut se faire, donc on ne peut reprendre le retour de h7-h8 puis h6-h7 et h5-6 ni bien entendu reprendre h6xg5 pour tout dénouer.
Ainsi je pense que le problème en lui-même est illégal avant même de faire intervenir la règle des 50 coups. Pouvez-vous me dire si quelque chose m’aurait échappé ? (2015-9-11)
Thierry LE GLEUHER: Sorry but the position is legal. The retro play can continue with d6-d5 and d5xXe6, and unlock the rest is easy. (2015-9-13)
Brassaud: Merci pour votre aide. (2015-9-17)
Thomas Volet: TV: The composition's only point is the extension of the retroplay by the interaction of the 3 Bs.
I do not accept anyone's "codex" that purports to alter the rules of chess by making the draw automatic or that imports castling. Under the chess rules, a draw is at the option of the moving player whenever the sequence of non-P, non-capturing moves is sufficiently long (and has nothing to do with castling).
If interested in positions that involve the 50-move rule, please see P0008399 (75-move sequence with several rook circuits), P1202286 (where the "codex" automatic draw rule presents the situation in which either player on the move can make a move that is simultaneously a draw and a checkmate), or P1331867 (move preceding the sequence must have been a capture of a non-P by a non-P). (2019-1-2)
comment
Keywords: 50 move rule
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2015-9-17 more...
6 - P0000764
Leonid Makaronez
1160 Die Schwalbe 24 12/1973
P0000764
(9+14)
#2
1. c7! ... 2. c8=D,T#
1. ... 0-0? is illegal!
play all play one stop play next play all
Paulo Roque: Solution:
1. c7 ~ 2. c8=D (or T) # (1. ...0-0 is illegal !)

Demonstration the illegality of the castle:

a) Logical elements in the diagram (LED):
(a.1) The bishops black and white were captured in original squares.
(a.2) sLa7 is pawn-promoted, note square f8. The promotion was in square g1.
(a.3) captured two black pieces (vide a.1, then two bishops ).
(a.4) captured seven white pieces (two rooks,one knight, two bishops, queen and one unknown).
The piece unknown: (uk1) is one pawn, or (uk2) is one pawn-promoted, or (uk3) is one piece original equal the pawn-promoted which is in the diagram.

b) Development:
(b.1) The white pieces were captured in: The pawn-h black was promotion in square g1, is necessary hxgxh2xg1 (three captures) + two bishops white captured in original squares xLc1 xLf1 (two captures) + c7xd6(one capture) + a7xb6(one capture) = seven captures pieces white.
(b.2) The structure in the diagram with sLa7,sBb7,sBb6,sBd7,sBd6 is only possible if the promotion of pawn-h black and -c7xd6- preceding -a7xb6-.
(b.3) Then pawn-a white was promotion in square a8 and the piece unknow (a.4) is uk3, only possibility a8=S.
(b.4) On the way Sa8 for e5, necessarily have to go in square c7,then impossible s0-0.

c) Conclusion: 1. ...0-0 is illegal.

Keywords: Cant Castler (2009-7-17)
Henrik Juel: The illegality of castling may also be shown by looking at the retroplay. La7 is [Ph7] promoted on g1, so all missing white men are accounted for, and [Pa2] must have promoted on a8. We cannot uncapture a white officer fast, so the retroplay must start by unpromoting Se5. But it needs to pass c7, so black king has moved. (2009-8-21)
Paulo Roque: Henrik, your solution is very elegant! (2009-8-21)
Yoav Ben-Zvi: As noted by Henrik above, proof that Black "Cant Castle" is based on showing that the White piece unpromoted on a8 is wNe5 rather than an officer uncaptured by one of the bPs. This is not affected by time pressure. Instead, note that retraction of bPc7xf6 must be preceded by exit of bBa7 from the North-West (via c7) which requires previous retraction of bPa7xb6 which implies previous unpromotion on a8 with the unpromoted wP retreating past a7 to allow its occupation by bP. This shows the unpromotion on a8 occurs before Black can uncapture on b6 or on d6 or by bP unpromoted on g1. It follows that the piece unpromoted on a8 must be wNe5. (2018-12-26)
Yoav Ben-Zvi: Typo bPc7xd6 (not xf6) (2018-12-26)
comment
Keywords: Castling (sk), Cant Castler
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-27 more...
7 - P0001343
Friedrich Amelung
Düna-Zeitung 1897
P0001343
(5+3) C+
#2
1. hxg6ep Kh5 2. Txh7#
play all play one stop play next play all
siehe P1291160
Sally: Der en passant-Schlag als einziger Schlüselzug lässt sich im Zweizüger erst mit acht Steinen darstellen. Dies ist die früheste Aufgabe und beste Darstellung, die mit Zweispänner
möglich ist. (2019-1-18)
more ...
comment
Keywords: En passant, En passant as key
Genre: Retro, 2#
Computer test: Popeye 4.61
Reprints: 55B Retrograde Analysis 1915
169 Allgemeine Zeitung Chemnitz 04/12/1927
(VIII) Problem 37-40 09/1956
(1) Problem 103-105 01/1967
215 Europe Echecs 124 04/1969
D12 feenschach 27, p. 27, 04/1975
(2) Mat Plus 12 10-12/2009
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-17 more...
8 - P0001576
Alexander Kislyak
446 Europe Echecs 316 04/1985
T. R. Dawson et W. Hundsdorfer zum Gedenken
P0001576
(13+11)
Konnte die Stellung ohne Schach dem sK erreicht werden?
Henrik Juel: Solution: Yes, the bK may never have been checked. -1.Bc4 b6 -2.Bb5 Bb7 -3.Ba6 Bc8 -4.Bb7 Rh2 -5.Ba8 Rh1 -6.B=a7 Rh2 -7.a6 a7xR -8.Rb3 Rh1 -9.Rg3 Bb7 -10.Bh2 Rb1 -11.Bg1 Rb3 -12.Re3 Bc8 -13.Re1 Rg3 -14.Bh2 Bb7 -15.Rh1 Bc8 -16.Bg1 Rb3 -17.Rh2 Rb8 -18.Rh1 b7xB -19.Bb5 Ra8 -20.Bf1 Rb8 -21.e2 Ke4 etc. Two screens on g3 help replacing bR by wR in the SE corner. (2003-5-15)
hans: NO,you can't retrack bK without a check. f7-f6 to let bK out makes Bf8 useless! (2010-5-18)
Henrik Juel: I only see your comment now, Hans, and I agree
Early in the game Sd6+ e7xd6 happened (2019-1-7)
Henrik Juel: The real content of this excellent retro is how to resolve the position, but the author chose to frame it with a question that fooled me some 16 years ago
Here is another tricky question he might have asked:
For which black pawn can the exact play not be deduced? (2019-1-8)
Henrik Juel: The black pawns played
a7xTb6-b5, b7xLc6, e7xSd6, and the rest never moved, except for [Pf7], which played f7-f6 or, if [Pb2] had already captured TLS to reach e5, ready for an ep capture, f7-f5 (2019-1-9)
comment
Keywords: Promotion, Volet Pawn
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-8 more...
9 - P0002213
Anders Olson
Kjell Widlert

7818 Springaren 57 06/1994
P0002213
(2+1)
h-retro-#5
Circe RI
Weiß beginnt
paul: 1. – Ke7xBf8 2.Bg7-f8 Sd6xPf7 3.Bh8-g7 Kd8xRe7 4.Bg7-h8 Kd7xQd8 5.Bf8-g7 Kc6xPd7 & 1.Kxb5(Ke8)#

But cooked:

1. - Ke8-f8 2.Ka4-b5 Sd8-f7 3.Ka3-a4 Sb7xQd8 4.Qd1-d8 Kf8-e8 5.Qh1xQd1 Ke8-f8 & 1.Qb3#

(information obtained from Kjell Widlert) (2018-12-15)
comment
Keywords: Help retractor, Circe, Aristocrat, Rex solus (s)
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-6 more...
10 - P0002289
Andrey Frolkin
Andrej N. Kornilow

2235 diagrammes 92 01-03/1990
P0002289
(14+14)
BP in 21,0
1. f3 Sc6 2. Kf2 Sd4 3. Kg3 Sxe2+ 4. Kg4 Sg3 5. hxg3 Tb8 6. Th5 Ta8 7. Ta5 Tb8 8. Lb5 Ta8 9. c4 Tb8 10. Dc2 Ta8 11. Dg6 Tb8 12. d3 Ta8 13. Ld2 Tb8 14. Le1 Ta8 15. Sd2 Tb8 16. Tc1 Ta8 17. Tc3 Tb8 18. Tca3 Ta8 19. T3a4 Tb8 20. a3 Ta8 21. Lxd7+ Dxd7+
play all play one stop play next play all
Henrik Juel: Natch 3.1 tests the first 20.0 moves OK in 13 seconds, but the first 20.5 moves would take more than an hour, and the entire problem more than a couple of hours, because of the possibility of [Pd7] promoting
So we may never know for sure whether this proof game with 16 oscillations by Ta8 is correct (2018-12-8)
Mario Richter: Henrik, I think certainty about the correctness of this problem can be achieved, if we take into account that Black's last move must have been a capture. (2018-12-10)
A.Buchanan: Henrik: the times you propose for testing don't seem outrageous, even without Mario's sensible heuristic. Also, the last move must have been DxLd7 from one of 5 squares only. (2018-12-12)
more ...
comment
Keywords: Unique Proof Game
Genre: Retro
Reprints: 101 Shortest Proof Games 11/1991
58b 64 Proof Games 2012
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2012-12-26 more...
11 - P0002534
Dirk Borst
Markus Ott

FIDE Kongress 37 Belfort 07/1994
2. Preis
P0002534
(13+15) C+
BP in 15,0
1. h4 e5 2. Th3 Df6 3. Ta3 Lxa3 4. b3 Lxc1 5. Sc3 La3 6. Db1 Lf8 7. Kd1 Ke7 8. Kc1 Kd6 9. Kb2 Kc5 10. De1 Kb4 11. Kc1 Ka3 12. Kd1 Kb2 13. Sd5 La3 14. Se7 Kxa1 15. Sxg8 Lc1
play all play one stop play next play all
(note: location of BK is not thematic for Belfort Theme).
Henrik Juel: C+ by Natch 3.1 (9 hours)
The two Belfort officers are wSg8 and sLc1
Here is the added feature that [Lf8] goes to c1 (to capture wLc1), then back to f8 (to make room for [Dd1] and [Ke1] to interchange, while clearing the way for [Ke8]'s march to a1), and then to c1 a second time (2018-12-9)
more ...
comment
Keywords: Unique Proof Game, Belfort
Genre: Retro
Computer test: Natch 3.1 (9 hours)
Reprints: (24) diagrammes 110 07-09/1994
8 feenschach 114, p. 414, 12/1994
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-13 more...
12 - P0002605
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002605
(7+1)
In welche Richtung ziehen die Bauern?
von oben nach unten
play all play one stop play next play all
Henrik Juel: Last move was g2xDTSh1=L+ (2019-1-1)
comment
Keywords: Promotion
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-26 more...
13 - P0002606
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 13, 1979
P0002606
(7+1)
In welche Richtung ziehen die Bauern?
R: 1. exd6ep+ d7-d5 2. e4-e5+
play all play one stop play next play all
Henrik Juel: The next retraction is also determined
2... Ka7xSa8 (3.Sb6-a8+ or Sb6xDLSa8+) (2019-1-1)
Henrik Juel: oops, that is not true
after 2... Ka7-a8, Lc5 can uncheck directly (2019-1-2)
comment
Keywords: En passant, Rex solus (s)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
14 - P0002607
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002607
(3+1) C+
Welches war der letzte Zug?
Weiß am Zug
R: 1. Ka7xSa8
play all play one stop play next play all
AB: Anticipated by P0001033. I feel almost guilty pointing this out, because Smullyan did so much to popularize RA. (2001-10-30)
Henrik Juel: The author of P0001033, Jan Mortensen, was no slouch either
For some 40 years he was the driving force in DSK, the danish chess problem society (2019-1-1)
comment
Keywords: Last Move? (KxS), Type B, anticipated (P0001033)
Genre: Retro
Computer test: RSP 1.2
Reprints: Schach mit Sherlock Holmes 1982
(1) diagrammes 86 07-09/1988
Outrageous Chess Problems 2005
R1 Phénix 275-276, p. 10810, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-9 more...
15 - P0002608
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002608
(12+14)
Auf welchem Feld wurde die wD geschlagen?
h6
play all play one stop play next play all
Henrik Juel: The pawn captures are determined, and also their sequence
d7xSe6 first, then a2xLb3, and finally g7xDh6 (2019-1-1)
comment
Keywords: Where was piece x captured?
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-26 more...
16 - P0002609
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002609
(3+1+1)
Welche Farbe hat der Bg3?
Monochromes Schach
sBg3 (Weiß hat rochiert)
play all play one stop play next play all
Henrik Juel: ... and wKb4 got out via h2 and g3 (2019-1-1)
comment
Keywords: Monochrome, Castling (wk)
Genre: Retro, Fairies
Reprints: feenschach 50 04-06/1980
Schach mit Sherlock Holmes 1982
R4 Phénix 275-276, p. 10812, 07-07/2017
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-26 more...
17 - P0002610
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002610
(3+1)
Der wK hat weniger als 14 Züge gemacht. Weise nach, daß eine UW stattgefunden hat!
Monochromes Schach
Der sSb8 kann nur von einem Bauern geschlagen worden sein!
play all play one stop play next play all
Henrik Juel: Strictly speaking, [Sb8] could also have been captured by DTL, e.g. h4xPg5xPf6epxPe7xDd8=DxSb8
But White must have promoted (on a dark square) (2019-1-1)
comment
Keywords: Monochrome, Promotion
Genre: Retro, Fairies
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-26 more...
18 - P0002612
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 30, 1979
P0002612
(11+10)
Welcher Stein steht auf h4?
(+wLh4!)
R: 1. c7xSd8=T,c7xLd8=T+
(sBhxXg2)
play all play one stop play next play all
Auf h4 steht ein wL
Henrik Juel: White captured [Lf8] with an officer, and the remaining four missing black men by fxexdxc and c7xLSd8=T+
So Black captured b7xa6, f7xe6xd5xc4, and h3xg2 on light squares, leaving only the dark-squared [Lc1] to be disclosed on h4 (2019-1-2)
Yoav Ben-Zvi: The detailed solution in Smullyan's book (p29) is reprinted in "Four lives, 2014 Ed. Jason Rosenhouse" (a tribute to Smullyan published shortly before his death). Another version appears in the wonderful chapter by Bernd Gräfrath in "Philosophy looks at chess, 2008 Ed. Ben Hale" where it is stated that Smullyan composed this problem at age 16 and considered it his best Retro problem. The following analysis is adapted from these sources:
Last move was -1.wPc7x(B or N, not Q or R)d8=R. The unpromoted wP implies 3 captures by [wPf2] (not 4 captures by [wPg2] plus 1, on g3, by [wPf2] since [bBf8] was not captured by a wP) implying that wPg3 comes from g2. It also implies promotion of [bPh7] (to bB or bN) after capturing on g2 (behind wPg3), a fifth capture by bP. The piece on h4 could not be bQ or bR (both kings would be in check) or bB or bN (requires a second Black promotion) therefore the piece on h4 must be White. A White piece on h4 other than wB would imply that [wBc1] was captured by a bP but all 5 captures by bPs are on light colored squares so:
Solution - White bishop stands on h4. (2019-1-2)
comment
Keywords: Promotion
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
TLG/4 feenschach 173, p. 303, 07-09/2008
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
19 - P0002614
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 45, 1979
P0002614
(12+11)
Schwarz ist am Zug. Darf er rochieren?
Mario Richter: vgl. mit P1012380 (2010-4-17)
Henrik Juel: Last move was a2-a3, so to prevent white retro-stalemate Black must uncapture a wS at once
Tb8xSa8 or LxSc8 do not give White a previous move, so the uncapture happened on e8 or h8, and Black may not castle (2019-1-2)
comment
Keywords: Castling (wksk), Cant Castler
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
20 - P0002615
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 46, 1979
P0002615
(6+4)
Weder Weiß noch Schwarz haben mit ihrem letzten Zug einen Stein geschlagen. Schwarz ist am Zug. Darf er rochieren?
Henrik Juel: Last move was not white castling, because the no-capture stipulation for Black would imply that the only previous white move available could be e2xf3??, rendering the position illegal (because d2-d1=L would be impossible)
So last move was Kh1-g1 or Kh2-g1, Th8 has moved to check, and Black may not castle (2019-1-2)
comment
Keywords: Castling (wksk)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
21 - P0002616
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 49, 1979
P0002616
(9+9)
Welcher Stein steht auf a5?
(+wKa5)
play all play one stop play next play all
Alfred Pfeiffer: Auf a5 steht der wK. (2012-1-11)
Henrik Juel: No Mystery here (2019-1-2)
Mario Richter: No mystery, but a little joke ("Sir Reginald's Jest"): the position was given as a trap to Sherlock Holmes, who immediately started analysing: Let's see now; Black is in check. What could have been White's last move? Obviously a rook from b7 capturing a Black piece on a7. I guess the next question now is, what was the Black piece? If it was a rook, then Black has promoted earlier..."
A this point the spectators could resist any longer laughing out loud pointing out that the piece obviously has to be the White King. Holmes concluded: "I have really been given a good dose of my own medicine. How many times have I not told Dr. Watson: 'In looking for the subtle, be careful not to overlook the obvious.'" (2019-1-3)
comment

Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
22 - P0002618
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 53, 1979
P0002618
(8+10)
Weiß setzt in einem Zug matt.
a) Brettdrehung 90° in Uhrzeigerrichtung (a1->a8) 1. f7xe8=D,L#
b) Brettdrehung 90° gegen die Uhrzeigerrichtung (a1->h1) 1. g4#
play all play one stop play next play all
Henrik Juel: In the diagram, light and dark squares should be inverted (e.g., h1 should be dark), implying that the board must be rotated 90 degrees; this inversion is probably impossible to achieve in the PDB, otherwise Gerd would have done it
Clockwise rotation: 1.'Pb6xTa5=DL#'
Counter-clockwise: 1.'Pc2-d2#' (2019-1-2)
comment
Keywords: Board Rotation
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
R3 Phénix 275-276, p. 10811, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
23 - P0002620
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 56, 1979
P0002620
(13+13)
Keine der Damen hat jemals ihre Felderfarbe gewchselt.
Welche Rochaden sind zulässig?
b) ohne wTg1
c) wTg1->h1
Henrik Juel: An important condition is missing:
The queens never changed square color
With this condition added, we can analyze
White captured all missing black men with exfxgxh
Black captured [Lc1] on c1 and [Dd1] on a light square, so he captured another original white officer with a7xb6, after which White promoted [Pa2] on a8, so Ta8 has moved and Black may not castle
The promoted officer must be Ta1 or Tg1, so White may not castle either (2019-1-2)
Mario Richter: Originalforderung:
It is given that neither queen has ever moved off her own color
a) Which side, if either, can castle?
b) If the rook on g1 is removed, would that affect the answer?
c) If the rook is replaced on h1, then what would the answer be?" (2019-1-3)
Henrik Juel: Thanks for the update, Mario
b)
No need for promotion, as Black could have captured the missing T by a7xTb6
Black may castle, White may not
c)
Like a), but if the promoted officer is Ta1
White may castle short, Black may not castle (2019-1-3)
comment
Keywords: Castling (wgsg)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
24 - P0002621
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 58, 1979
P0002621
(12+14)
Weiß hat die wD vorgegeben und die beiden wSS sind Originalspringer. Welche Rochaden sind zulässig?
Henrik Juel: With g7xh6 Black did not capture [Lc1], nor [Dd1], nor [Lf1], so [Pe2] must have promoted
If g7xh6 captured the promoted man, the promotion needed two white pawn captures, exPf and either f7xe8 or f7xg8, so Black must have played b3xa2-a1=Y, and White may not castle long
If g7xh6 captured an original man, this was also not [Sb1,Sg1], so [Th1] must have moved, and White may not castle short
White may castle short or long, but we cannot say which (2019-1-2)
comment
Keywords: Castling (wkwg), Odds game
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
25 - P0002625
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 69, 1979
P0002625
(3+2)
Ergänze einen wB auf c4, c5, d4 oder d5, so daß die Partie (mit Schwarz am Zug) nicht remis enden muß!
+wBc4, dann 1. bxc3ep
play all play one stop play next play all
Henrik Juel: tiny typo in stipulation: mit Schwarz, not Scharz
A wP on c4 does not imply that last move was c2-c4, so the ep capture is not legitimized as such; but it is the only way to prevent the game from ending in a draw (2019-1-2)
comment
Keywords: Add pieces, En passant, Pawn endgame
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
26 - P0002626
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 73, 1979
P0002626
(8+1)
Darf Weiß rochieren?
Henrik Juel: No, White may not castle right now, because it is Black to move, as he has no last move
Or (if you allow joking) the board is turned upwards down, in which case White could have the move, but castling would still not be possible (2019-1-2)
comment
Keywords: Castling (wkwg), Rex solus (s)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
R6 Phénix 275-276, p. 10813, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-3 more...
27 - P0002627
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002627
(5+1)
Weiß am Zug. Ist die Stellung legal?
R: 1. Kc6-b6 oder 1. Ka6-b6
play all play one stop play next play all
Henrik Juel: Yes, the position is legal, as the retroplay could be -1... Kc6-b6 -2.b7-b8=S++ etc. (or Ka6-b6 -2.a7xb8=S++) (2019-1-2)
comment
Keywords: Last Move?, Promotion
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-28 more...
28 - P0002630
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002630
(15+15)
Welche Farbe ist Schwarz, welche Weiß?
Schwarz ist Weiß, Weiß ist Schwarz
play all play one stop play next play all
Henrik Juel: The number of white moves in the game is uneven, and the number of black moves is even, implying that White just moved (assuming that White started; this is the standard parity argument); but this contradicts that Black just checked on c3
If Black started the game, there is no contradiction (2019-1-2)
comment
Keywords: Parity Argument
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-28 more...
29 - P0002631
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002631
(6+9)
Schwarz am Zug darf rochieren. Ergänze einen wB auf f2 oder g2!
+wBf2
play all play one stop play next play all
Henrik Juel: The diagram white pawns captured 6 times, and black pawns 8 times, so after adding a white pawn there is room for just one more capture by each side
Only addition on f2 permits a legal position, where the remaining captures were black hxPg (with promotion on g1) and white h7xg8=DLS (2019-1-2)
comment
Keywords: Add pieces, Castling (sk)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-28 more...
30 - P0002632
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002632
(14+15)
1. Weiß hat einen Turm vorgegeben,
2. die wSS haben noch nicht gezogen,
3. es fanden keine UW statt,
4. der letzte Zug von Weiß war e2-e4.Darf Schwarz rochieren?
Henrik Juel: Yes, Black may castle, as he had no time to move his king or rooks during the 6.0 moves game (but it is White to move)
Proof game (the black moves could be shifted):
1.a3 Sc6 2.a4 Sh6 3.a5 e5 4.a6 Dg5 5.axb7 Lb4 6.e4 Lxb7
Too many conditions for my taste in this problem (2019-1-2)
comment
Keywords: Conditional problem, Odds game
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-28 more...
31 - P0002633
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 93, 1979
P0002633
(13+15)
Die KK haben noch nicht gezogen. Ergänze einen wB!
Henrik Juel: White captured g2xTh3, so to get [Ta8] out, Black cross-captured b7xTc6 and c7xLb6
The sequence was: [Ta1] to c6 before b7xc6 before g2xh3 before [Th1] to a1
Add wPc4 to permit the wT moves (2019-1-3)
more ...
comment
Keywords: Add pieces, Conditional problem
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
32 - P0002634
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 95, 1979
P0002634
(15+14)
Schwarz ist am Zug. Weiß hat zuletzt mit dem Bf4 gezogen; woher kam dieser Bauer? Es befindet sich keine UWF auf dem Brett,
Henrik Juel: with wPe4 moved to f4:
White captured [Lc8] on a light square with an officer and d2xc3, so Black captured the light-squared [Lf1] either by dxLc or by d3xLe2 (and promotion on e1)
In both cases the sequence must be
e2-e3 (to release [Lf1]) before dxL before d2xc3 before [Lc1] could reach g5 traversing f2
So last move was f3-f4 (2019-1-3)
more ...
comment
Keywords: Conditional problem
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
33 - P0002637
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002637
(15+14)
Befinden sich UWF auf dem Brett?
Yoav Ben-Zvi: The Black piece captured on c3 could not be [bBc8] (captured on a light square) or [bPh7]. Therefore [bPh7] promoted on g1 after capturing [wBc1] (on g3) which was released previously by wPb2xc3. This implies that the piece promoted on g1 could not have been captured on c3 as the capture on c3, releasing [wBc1], occurred before the Black could promote. Therefore the promoted Black piece must be present on the board, replacing the piece captured on c3. The idea is developed further in P0002638. (2018-12-29)
comment
Keywords: Promotion
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-28 more...
34 - P0002638
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002638
(14+14)
Weiß hat gerade rochiert. Befindet sich UWF auf dem Brett?
Yoav Ben-Zvi: The Black piece that accounts for the capture on a3 could not be [bBc8] (captured on a light square) so it was a missing bP that promoted. The bP promotion could not have occurred on h1 ([wRh1] did not move before castling) so the promotion was on g1 or f1. wPg3 came from g2, it could not capture on g3 as this would be the second capture by White on a dark square and Black's 2 missing pieces include [bBc8] which was captured on a light square. This means that the promoting pawn could not have been [bPg7] as this would require 2 captures on the way to promotion (to bypass [wPg2]) plus a third capture by bPh7xg6. Therefore the promoted bP comes from h7 and, to reach the promotion square, it must have captured on column g behind wPg3. If the piece captured on a3 was an "original" (not promoted) Black piece (could be any officer other than [bBc8]) then the piece promoted by Black is present in the diagram, replacing the piece captured on a3. Henceforth we consider the alternative: that the piece captured on a3 was the promoted piece itself. This implies that the capture by the bP on its way to promotion came before the capture on a3. If wBg5 is not promoted then, prior to wPb2xa3, the wB was locked at c1 which implies that [wRa1] had not yet escaped its home corner and that [wBc1] subsequently moved to g5 via b2 crossing c3. This means the White pawn was still standing on c2 and therefore, since the wK had not moved, that the wQ could not have escaped from d1. It follows (for the case of Black promotee being captured on a3) that the White piece captured by the Black pawn on its way to promotion could not have been [wBc1] or [wRa1] or [wQd1] as it has been shown that, in this case, all 3 were locked when this capture occurred. The White piece captured by promoting bP also could not have been a wP since, as noted above, wPg3 came from g2 and the capture occurred behind it. Since the White piece captured on column g could not have been one of the missing original pieces, [wPh2] must have promoted. On its way to promotion [wPh2] could not capture on g7 (with bP waiting on h7) for the same reason as given above for the capture on g3 (not all White captures were on dark squares). Therefore wP must wait on h2 until its way to promotion is cleared by bPh3xg2 so it can subsequently promote on h8 to replace the captured piece (known to be a knight). In conclusion: for every alternative scenario there is a promoted piece on the board.
The stipulation, which might be defined more accurately as "Must there be a promoted piece on the board?", weaves together the alternative strands of the solution.
The presentation of the problem begins on page 106 of the book (chapter "Shades of the Past") relaying the condition that the last move was -1.0-0 and that Sherlock Holme's nemesis, Professor Moriarty, solved the problem in less than 4 minutes while Holmes admits it took him more than 20 minutes. The description of the solution begins on page 155. (2018-12-29)
Mario Richter: @Yoav: Quote: "... to replace the captured piece (known to be a knight)." This is not completely correct.
Just a small thought to think about: Let's assume that Black answers White's castling by playing 1. ... 0-0! In what way does this change the RA? (2018-12-29)
Yoav Ben-Zvi: The conclusion that the piece captured on g2 was a wN is reached under the assumptions that Black's promoted piece was captured on a3 (therefore it is not present in the diagram) and that wBg5 is not promoted (implying that [wBc1] exited after the capture on a3 and before [wQd1] could be released by wPc2-c3). It has been shown that, under these assumptions, [wBc1], [wRa1] and [wQd1] could not have escaped in time to be captured on g2. The piece captured on g2 also could not be a wP ([wPg2] moves to g3) or a wB (wBg4 could not be promoted on the dark square h8) or a promoted piece (the path to promotion of [wPh2] is open only after the capture on g2) so I think the conclusion that it had to be a knight is justified, under the assumptions (although it is not needed to meet the stipulation).
The suggested addition of the condition: "Black retains the right to castle 0-0" prevents any resolution that has [wPh2] promoting on h8. It has been shown above that capture of Black's promoted piece on a3 requires the White promotion on h8 (either to a wB that replaces the one captured on c1 or to a wN that replaces the one captured on g2). This contradiction (promotion on h8 is required but not allowed) means that the piece captured on a3 could not have been Black's promoted piece so it was an original (not promoted) piece. The piece captured on a3 could not be [bBc8] (captured on a light colored square) or a bP so it is a bQ or bR or bB or bN that is replaced in the diagram by the promoted piece, proving that there must be a Black promoted piece present in the diagram position. A fine idea that improves the accuracy of the resolution. (2018-12-30)
comment
Keywords: Promotion, Castling (wksk), Conditional problem
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-28 more...
35 - P0002639
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 113, 1979
P0002639
(11+11)
Weiß setzt matt. In wieviel Zügen?
1. axb6ep#!
play all play one stop play next play all
Henrik Juel: White pawns captured bxa, cxb, f6xe7 (to promote on e8), and g2xh3 (the remaining missing black man was captured by an officer)
Black captured h7xg6xf5xe4xd3 and dark-squared [Lc1] with an officer
Last move was not a6xb5, c4xd3, d4-d3, d7xe6, nor d7-d5, e7-e6 (as White moved f6xe7-e8=L and promoted L to c6 or c8), so last move was b7-b5
White mates by axb6ep# (2019-1-3)
comment
Keywords: En passant
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
36 - P0002640
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 115, 1979
P0002640
(12+11)
Der weiße König ist unsichtbar.
Schwarz am Zug setzt matt!
Henrik Juel: The stipulation might be written more clearly:
Black to move mates in 1
In the Reprints it looks strange that the problem appeared as number R8 in Phenix twice on pages 10810 and 10814 (2019-1-3)
Henrik Juel: White captured [Lf8] on f8, cxd, f2xg3, g2xh3, and once more
Black captured b7xTa6, f7/h7xTg6, and [Lc1] on a dark square
With Black to move, wK could not stand in check on e4, f3, nor g2, so Kc6 stands in check from wLh1, and wK must be ready to uncheck (possibly following the retroplay -1.c5xPd5ep+ d7-d5)
The discovered check by wK could not be from e4 (Lxd3+ is impossible) or f3 (impossible double check), so it was from g2, and wK must stand on g1
Black mates with Sf3#
(On g2 wK would stand in double check explained by f2xLe1=S++, so Black earlier captured h7xTg6, not f7xTg6) (2019-1-3)
comment

Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
R8 Phénix 275-276, p. 10810, 07-08/2017
R8 Phénix 275-276, p. 10814, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
37 - P0002641
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 118, 1979
P0002641
(15+15)
Beide Seiten dürfen rochieren.
Ergänze einen wL auf a3 oder a4!
(+wLa3)
R: ?
play all play one stop play next play all
Mu-Tsun Tsai: Actually to solve this problem there's no need to know if Black can castle. When it comes to the part of explaining why the Pawn originated in e2 can't promoted, it suffice to notice that it can only go straight forward and therefore cannot pass the Pawn originated in e7. (2009-5-12)
Henrik Juel: White's only capture was a2xb3, so Black must have captured [Pe2] with an officer and played e2xLd1=LS or e2xLf1=LS
Add the dark-squared wL on a3 (2019-1-3)
Yoav Ben-Zvi: Smullyan thought that if bK could vacate e8 then [wPe2] could promote there. However, as shown in the solution on page 158, with wK immobile the promotion of [bPe7] occurs from e2 not from d2 and, since Black does not have the captures needed to promote from e2 after clearing the way on the e file, [wPe2] is prevented from moving straight forward to promotion. Therefore (as noted by Mu-Tsun) White retaining castling rights is a sufficient condition . In addition to removing the condition on Black castling, I think wPd5 can be removed ([bPe7] could then capture the wP and arrive at e2 but it needs a further capture to promote). Another idea, closer to Smullyan's intention, is to remove bQd7 and retain the condition on Black castling (preventing wP promotion from d7). (2019-1-5)
A.Buchanan: White is marked as having 15 units - which means that both of the x marks are being counted as White! I am not sure I can edit these in any case. But conventionally the x+y indicates the number of pieces visible in the diagram, for checking purposes, and does not include units to be added. It hardly matters, but it interests me. It would be possible to replace the x marks with lines, which are definitely available for users to edit. (2019-1-5)
A.Buchanan: Curious that the x marks are coded as *Black*: sXa3a4, yet are counted as White. Also, even after units are added to positions, the counter (y+z) is never updated. (Here hit the "play" button above. The "?" after the R: is necessary to get the position to update.) (2019-1-5)
comment
Keywords: Add pieces
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2019-1-5 more...
38 - P0002642
Raymond Smullyan
v The Chess Mysteries of Sherlock Holmes , p. 120, 1979
P0002642
(6+4)
Zeige, daß eine UW und ein ep-Schlag stattgefunden haben!
Weiß am Zug
Monochromes Schach
Cooker: Illegal position. I don't see what black unit takes the white bishop f1. (2002-9-21)
Joost de Heer: In the second (or perhaps even later?) version of this book, a white bishop is added on f1.
See http://janko.at/Retros/Misc/SmullyanErrata.htm for a list of errata in 'Sherlock Holmes'. (2002-9-27)
Henrik Juel: Black has castled and his king exited via h7 and g6, so last move was done by Ka2
The only possibility is Kb3xTa2, preceded by Tc2-a2+
The uncaptured wT is a pawn promoted after four captures; three of these captured [Ta8,Lc8,Pb7], and as [Sg8] never moved, the remaining capture was en passant, e.g.
a2-a4xPb5xPa6epxLb7xTa8=T (2019-1-3)
comment
Keywords: Monochrome, En passant, Promotion
Genre: Retro, Fairies
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
39 - P0002643
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 123, 1979
P0002643
(6+4)
Monochromes Schach?
Henrik Juel: Suppose the monochrome condition is in effect
Then everything is honky-dory except for Da6, which is [Pd7 ] or [Ph7] promoted on f1 or h1, e.g., h7-h5xYg4xPh3epxDg2xLf1=D
Here Y is [Pa2] promoted to DTL on c8 or e8; this seems possible, as [Ta8,Lc8,Pd7] and an ep-capture are available, but it does not work, since [Ta8] cannot reach b5: a2-a4xZb5xPc6epxPd7xLc8??, and a2xVb3xWc4xPd5xPc6epxLd7xTc8?? is even worse
So the monochrome condition is not in effect (2019-1-3)
comment
Keywords: Monochrome
Genre: Retro, Fairies
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
40 - P0002645
Raymond Smullyan
M2 The Chess Mysteries of Sherlock Holmes , p. 146, 1979
P0002645
(3+2)
In den letzten 5 Zügen haben weder der wK noch die Dame einen Zug ausgeführt. Auch sind keine Steine geschlagen worden. Was war der letzte Zug?
R: 1. Lg5-h6 a5-a4 2. Ld8-g5 a6-a5 3. d7-d8=L a7-a6 4. d6-d7 Kg8-h8 5. d5-d6+
play all play one stop play next play all
Henrik Juel: With the stringent conditions the only possibility is to unpromote Lh6 and let the resulting pawn uncheck, when Black must retract Kg8-h8
Unpromotion on b8 is too slow
Last move was Lg5-h6 (2019-1-3)
Mario Richter: Originalforderung: "Neither the White king nor queen has moved during the last five moves, nor has any piece been captured during that time. What was the last move?"
Ich schlage vor, das "Figuren" in der deutschen Version der Forderung durch "Steine" zu ersetzen, weil "Figuren" im Deutschen die Bauern nicht mit einschließt, was aber hier offensichtlich bezweckt zwar. (2019-1-4)
comment
Keywords: Last Move?
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
41 - P0002646
Raymond Smullyan
M3 The Chess Mysteries of Sherlock Holmes , p. 146, 1979
P0002646
(3+8)
In den letzten 5 Zügen hat kein Bauer gezogen, und es wurden auch keine Figuren geschlagen. Versehentlich fiel der sK zu Boden. Auf welchem Feld muß er stehen?
(+sKc8)
R: 1. ... Td8-h8 2. Kg8-f7 0-0-0 3. Kh8-g8 Sc1-a2,S~ 4. Kg8-h8 Sa2-c1,5. Kh8-g8 Sc1-a2,S~ 6. Kg8-h8
play all play one stop play next play all
Henrik Juel: The only way to avoid retrostalemate under the conditions is to put sK on c8 and retract
-1... Td8 -2.Kg8 0-0-0 -3.Kh8 S~ 4.Kg8 S~ -5.Kh8 S~ -6.Kg8 (2019-1-4)
comment
Keywords: Add pieces, Castling in the retro play
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
42 - P0002648
Raymond Smullyan
M5 The Chess Mysteries of Sherlock Holmes , p. 147, 1979
P0002648
(14+14)
Keiner der beiden KK hat bisher gezogen.
a) Weisen Sie nach, daß einer der 4 Springer schon einmal gezogen hat, wenn sich auf dem Brett keine weißen UWF befinden.
b) Weisen Sie nach, daß zwei der SS schon einmal gezogen haben, wenn sich auf dem Brett keine schwarzen UWF befinden.
Henrik Juel: I believe the stipulation is incorrect.
If there are no promoted men on the board:
Black played g3xLh2-h1=Y (DS), so Sg1 has moved
White played dxPc-c7xYb8=S-a6 (or =D), so Sb8 has also moved
If there are no white promoted men on the board:
White captured [Lc8] on c8 with Dd1 and promoted to DTS on c8, later captured on a6
Black promoted to L on h1, so Sg1 has moved; this L is now on a4 (2019-1-4)
comment

Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
43 - P0002649
Raymond Smullyan
M6 The Chess Mysteries of Sherlock Holmes , p. 148, 1979
P0002649
(14+15)
Weiß darf rochieren. Ist die wDd2 die Originaldame?
Henrik Juel: The missing men are a black T, the white pawn from a2 or c2, and the white L from f1
Black crosscaptured to let a T out to b3 ([Lf1] was captured on the light square) and allow a white promotion to replace the captured original officer (capturing a white pawn on the dark square does not work)
The details are:
1. a7xDb6
2. sT gets out to be captured by c2xTb3, and Pa2-a8=D
3. b7xLa6
Promotion to T would not work, because Ta1 is immobile and Tg1 is inaccessible by the castling condition; a light-squared L is not on the board now; an S could not leave a8
Crosscapture on d6,e6 (or a2xTb3) would not permit promotion
Dd2 is promoted (2019-1-4)
comment

Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
44 - P0002650
Raymond Smullyan
M7 The Chess Mysteries of Sherlock Holmes , p. 148, 1979
P0002650
(16+12)
Beide Seiten dürfen noch rochieren. Auf c6 steht eine unbekannte schwarze Figur, aber kein Turm.
a) Angenommen, es ist ein Springer, auf welchem Feld ist dann die fehlende schwarze Dame geschlagen worden?
b) Angenommen, es ist die Originaldame, auf welchem Feld ist dann der fehlende sS geschlagen worden?
c) Angenommen, es ist eine umgewandelte Dame, wo ist dann der schwarze Springer geschlagen worden?
Henrik Juel: The missing [Ta8] was captured in its corner
White captured the other two missing black men with b2xc3 and g2xh3
The only black capture was c7xDb6, so [Pg7] must have promoted to D, T, or L on g1 after g2xh3 (promotion to S is ruled out, because Sg1-f3 would ruin white castling)
b2xc3 (letting [Dd1] out) happened before c7xDb6, which lets [Dd8] out
Here follow the pawn captures and the promotion, and their sequence, for the three situations; this is easily found by considering the few possibilities
A. Black S on c6
1. b2xLc3
2. c7xDb6
3. g2xDh3
4. g1=L, now on g7
The D was captured on h3
B. [Dd8] on c6
1. g2xSh3
2. g1=Y
3. b2xYc3
4. c7xDb6
The S was captured on h3
C. Promoted [Pg7] on c6
1. b2xSc3
2. c7xDb6
3. g2xDh3
4. g1=D, now on c6
The S was captured on c3 (2019-1-4)
comment

Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
45 - P0002651
Raymond Smullyan
M8 The Chess Mysteries of Sherlock Holmes , p. 149, 1979
P0002651
(15+14)
Schwarz hat im ersten Zug Bd7-d5 gezogen. Der auf f5 stehende Springer hat genau dreimal gezogen. sD, sK und sTh8 haben noch nicht gezogen.
Teil I
A) Weisen Sie nach, daß drei Figuren, die jetzt noch auf ihrem Ausgangsfeld stehen, schon einmal gezogen haben.
B) Hat der Bauer h5 ein- oder zweimal gezogen?
C) Stünde der h-Bauer statt auf h5 auf h6, wäre die Stellung dann noch legal?
Teil II
Angenommen, man entfernt den sLc8 und stellt folgende Bedingungen: Der Läufer soll auf irgendeinem anderen Feld stehen. Er darf aber noch nie auf f7 gestanden haben, er darf auch nicht b7 oder c6 überquert haben, und er darf nicht vor dem weißen Läufer g4 gezogen haben. Auf welchem Feld muß der Läufer dann stehen?
Henrik Juel: The first condition could be formulated more clearly:
Black's first move in the game was 1... d7-d5 (2019-1-4)
Henrik Juel: I
Black has moved Sb8-c6-d4-f5
White captured [Lf8] on f8 with an S
The sequence was something like
d2-d3 and d7-d5, c7xLd6, b7-b6 and Sb8-c6-d4-f5, e2xTf3
Now the route by [Lf1] can be determined:
Lf1-e2-d1-b3-c4-a6-c8-e6-g8-h7-g6 (with [Sg8] screening on f7) -h5-g4
A. Dd1, Lc8, and Sg8 must have moved
B. [Ph7] went h7-h6-h5
C. With Ph5 on h6, the position would be illegal, because Sg8 could not get home
II
With the additional conditions Lc8 would have to run ahead of [Lf1] and now stand on h3 (2019-1-4)
comment

Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-6 more...
46 - P0002652
Raymond Smullyan
M9 The Chess Mysteries of Sherlock Holmes , p. 149, 1979
P0002652
(13+14+1)
Keiner der beiden Könige hat bisher gezogen. Auf f2 steht ein schwarzer oder ein weißer Bauer. Ein weißer Springer steht entweder auf f3 oder f4.
A. Welche Farbe hat der Bauer auf f2?
B. Steht der weiße Springer auf f3 oder f4?
Henrik Juel: La5 must be a pawn promoted on g1
A.
If Pf2 were white, [Ph7] must have promoted on g1, as [Pf7] would need too many captures
Black could play h7xLg6xPh5-h2xLg1=L, but then a7xb6 could not happen (promoting [Ph2] on h8 makes no difference)
Or Black could capture [Ph2] and play h7-h2xLg1, but this would leave no dark-squared white men for a7xb6; if Black played h3xLg2-g1=L (after g2-g3), the L could not reach a5
So Pf2 is black, and it just checked by f3-f2+, because e3xf2+ would require too many black captures, as [Pf2] or [Ph2] was not captured by a black pawn
B.
wS is on f4, since Black just left f3 (2019-1-4)
comment
Keywords: Promoted material on the board (sLa5)
Genre: Retro
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-6 more...
47 - P0002653
Raymond Smullyan
M10 The Chess Mysteries of Sherlock Holmes , p. 150, 1979
P0002653
(11+10) C+
Weiß ist am Zug. Kann er in zwei Zügen mattsetzen?
1. Dd6 droht 2. Dxe7#
1. ... exd6 2. Sg7#
1. ... exf6 2. Dxf8,Txf8# (Mattdual)
1. ... Kd8 2. Txf8#
1. ... 0-0-0? (illegal!)
play all play one stop play next play all
Henrik Juel: If Black cannot castle, White can mate in 2 moves
1.Dd6 thr. 2.Dxe7#
1... exd6/exf6/Kd8 2.Sg7/DTxf8/Txf8
C+ by Popeye 4.61, except for the dual (2019-1-5)
Henrik Juel: Let us show that Black may not castle (with White to move)
White captured [Lc8] and four of the five remaining missing black men with his pawns on the king-side
Black Pg2 captured four of the five missing white men, which include [Pa2,Pb2], so one of these must have promoted
h7xg6 is illegal as last move (requiring six black captures), and so is h3xg2 (illegal black pawn position)
If Black made last move with Ta8 or Ke8, he may obviously not castle
1. Suppose last move was Dg7-f8
Then White must retract Th8xYf8+, exhausting the five possible captures by White, so White could not promote [Pb2] as this would require another capture; instead he promoted [Pa2] on a8 to supply four capturable white men, meaning that Ta8 has moved, so Black may not castle
If last move was g7-g6 (so [Lf8] was not captured by a pawn), the same analysis applies
2. Suppose last move was Dg7xYf8
This leaves just the needed four white men captured by Pg2, so White must have captured the last available black man with [Pb2] to promote it, and hence promoted [Pa2] on a8, so Black may not castle
If last move was g3-g2 (so Pg2 did not capture the missing light-squared [Lf1]), the same analysis applies
Conclusion: Black may not castle, because he has moved his K or T (2019-1-5)
Yoav Ben-Zvi: The convoluted stipulation is not needed as this is a standard #2 with solution supported by "Cant Castle" retroanalysis. (2019-1-7)
comment
Keywords: Castling (sg)
Genre: Retro
Computer test: Popeye 4.61
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-6 more...
48 - P0002654
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 122, 1979
P0002654
(5+4)
Monochromes Schach
Der wK hat erst zweimal gezogen.
War das Feld h8 mehr als einmal besetzt?
R: 1. g3xTh4 Th8-h4 2. Kf2-e3 Kh7xDg8 3. Dg4-g8+ Tf8-h8 4. h2xLg3 Lh4xTg3 5. Ke1-f2 Kg8-h7 6. Dd1-g4 0-0
play all play one stop play next play all
Henrik Juel: Black has castled, so [Th8] has visited f8.
Where was it captured? Not on f8 or d8, because by the condition wK could not go that far, [Ta1] could not reach row 8, [Lc1] never moved, and White did not promote a dark-squared pawn
So after the castling [Th8] must have moved back to h8
The retroplay could start like this:
-1.g3xTh4 Th8 -2.Kf2 Kh7xDg8 -3.Dg4 Tf8 -4.h2xLg3 Lh4xTg3 -5.Ke1 Kg8 6.Dd1 0-0 (2019-1-5)
Henrik Juel: should be -6.Dd1, of course (2019-1-5)
comment
Keywords: Monochrome, Castling
Genre: Retro, Fairies
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-6 more...
49 - P0002795
Alexander Kislyak
32 Powerschennii Monarch 1993
P0002795
(9+13) C+
BP in 15,5
1. a4 Sc6 2. Ta3 Sd4 3. Tf3 Sxe2 4. Txf7 Sxc1 5. Txf8+ Kxf8 6. Lc4 De8 7. Lxg8 Txg8 8. f4 Kf7 9. Sf3 Ke6 10. 0-0 Kd5 11. c4+ Kxc4 12. Te1 Kd3 13. Te6 dxe6 14. De2+ Kxe2 15. a5 Sd3 16. Sc3#
play all play one stop play next play all
Henrik Juel: C+ by Natch 3.1 (57 min.)
The author made 64 proof games, all ending in Black being mated, on the 64 squares of the board
This is a neat model mate (2018-12-9)
comment
Keywords: Unique Proof Game, Castling
Genre: Retro
Computer test: Natch 3.1 (57 min.)
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-13 more...
50 - P0003049
Raymond Smullyan
The Chess Mysteries of the Arabian Knights 1981
P0003049
(14+15)
Ein sL hat einen weißen Stein geschlagen. Welcher sL?
sLg4 hat wS geschlagen
play all play one stop play next play all
Alfred Pfeiffer: Falsche Lösung. Richtige Antwort ist: sLe5 hat wL geschlagen. (2010-7-27)
Henrik Juel: Alfred is right, so please correct the official solution
The capture sequence must have been
g7xSh6 before d2xTc3 before Lx[Lc1] (2019-1-23)
comment

Genre: Retro
Reprints: Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-5 more...
51 - P0003050
Raymond Smullyan
The Chess Mysteries of the Arabian Knights 1981
P0003050
(5+1)
Im letzten Zug wurde kein Stein geschlagen. In welche Richtung spielt Weiß?
R: 1. Td2-f2 Kf2-f1 2. Be2xXd1=S+
play all play one stop play next play all
Henrik Juel: The stated retroplay is the only possibility
so White pawns move downwards (2019-1-23)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-5 more...
52 - P0003927
Herbert Hultberg
Springaren 1979
P0003927
(10+2)
-1w, dann #1
VRZ, Typ Proca
R: 1. g7xSh8=S? (illegale w Bauernstruktur)
R: 1. c7xSb8=S!, dann 1. c8=D#
play all play one stop play next play all
klären: # vor 1 Zügen!? - 1 Zug oder n Zügen! (VF)
Mario Richter: #1 vor 1 ist möglich: R: c7xSb8=S, dann 1.c7-c8=D#
Der spiegelbildliche Versuch R: g7xSh8=S, dann 1.g7-g8=D# scheitert an der Illegalität der wB-Struktur. (Das erklärt aber natürlich noch nicht das 'VRZ,Typ Proca'.) (2009-12-8)
Henrik Juel: Hultberg also made Høeg retractors, so maybe the type designation just underscores that this problem is not a Høeg retractor. If it were, it would be unsolvable: Black chooses to supplement some other officer than a knight on b8, and then there is no mate. (2009-12-11)
Mario Richter: Thank you, Henrik! Your explanation sounds very plausible to me. (2009-12-11)
paul: Actually, this is a help retractor. (2018-12-14)
comment
Keywords: Symmetrical position, Defensive Retractor, Type Proca, Asymmetrical solution
Genre: Retro
Reprints: RA135 diagrammes 49 01-02/1981
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-14 more...
53 - P0004043
Karl Fabel
Parallele 50 1950
P0004043
(2+1)
Weiß nimmt 1 Zug zurück, dann #2
R: 1. "0-0", dann 1. "0-0-0" Ka1 2. Ta3#
play all play one stop play next play all
Veröffentlicht in der Rubrik "Professeur Cosinus"
Mario Richter: Vorwärtsspiel m.E. zumindest teilweise vorweggenommen durch P1359470. (2019-1-12)
A.Buchanan: This one, in constrast to P1359470, remains a joke and a good one. (2019-1-12)
comment
Keywords: Odds game, Help retractor, Joke, Castling (wkwg)
Genre: Retro
Reprints: 490 La Composition Contemporaine [Martin] 1951
(9) diagrammes 86 07-09/1988
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2015-8-12 more...
54 - P0004066
S. N. Ravishankar
2069 diagrammes 89 04-06/1989
P0004066
(2+1)
#1 vor 6
VRZ, Typ Proca
S N Ravi Shankar: This problem is not mine. (2019-1-2)
Mario Richter: My first guess for the solution was:
R: 1. Ke2xLf1 2. Kd3xLe2 3. Kc4xLd3 4. Kb5xLc4 5. Ka6xLb5 Lc6-b5+ 6. Sd7xLb8, dann 1. Sb6#, but that doesn't work because of 5. ... Ld7-b5+!
Does someone see (or know) the correct solution? (2019-1-3)
Henrik Juel: No, because with 1... Lh3-f1+, 5.Ka6-b5 thr. 6.Sd7xLb8 fails similarly on 5... Ld7-h3 (2019-1-3)
comment
Keywords: Defensive Retractor, Type Proca, Rex solus (s), Aristocrat
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-4 more...
55 - P0004348
Edward J.M.D.P. Dunsany
1 The Week-End Problems Book , p. 179, 1932
P0004348
(8+16)
#4
(Brettdrehung 180°)
1,2) 1. Sc6,Sd7 Sf3 2. Sb4,Sc5 Se5 3. Dxe5 ... 4. Sd3#
play all play one stop play next play all
Das Brett muss um 180 Grad gedreht werden, da sK und sD vertauscht sind.
AB: Two variant solutions.
(In any case, board must be rotated by 180 degrees, then 1 Nc6/d7 Nf3 2 Nb4/c5 Ne5 3 Qxe5 ~ 4 Nd3# (2002-4-3)
more ...
comment
Keywords: Joke, Board Rotation (180), Illegal position
Genre: Retro, n#
Reprints: Problem 101-102 09/1966
73 100 Classics of the Chessboard 1983
17 Die gefesselte Zeit , p. 137, 1987
(L) Die Schwalbe 151 02/1995
Karl 4/2018, p. 57, 12/2018
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-6 more...
56 - P0004367
Andrey Frolkin
560 Europe Echecs 403 07-08/1992
P0004367
(10+12) cooked
KBP
a) Weiß am Zug
b) Schwarz am Zug
a) 1. e4 h5 2. Dxh5 Txh5 3. h3 Txh3 4. a3 Txa3 5. Txa3 a6 6. Txa6 Sf6 7. Txf6 gxf6 8. Th6 Lxh6 9. d3 Lxc1
b) 1. d3 h6 2. Lxh6 Txh6 3. h4 Txh4 4. a4 Txa4 5. Txa4 a6 6. Txa6 Sf6 7. Txf6 gxf6 8. Th6 Lxh6 9. Dc1 Lxc1 10. e4
play all play one stop play next play all
Cook: Duale
a) 1. e4 h5 2. Dxh5 Txh5 3. h3 Txh3 4. a3 Txa3 5. Txa3 a6 6. Txa6 Sh6! 7. Tf6 gxf6 8. Txh6 Lxh6 9. d3 Lxc1
b) 1. d3 h6 2. Lxh6 Txh6 3. h4 Txh4 4. a4 Txa4 5. Txa4 a6 6. Txa6 Sh6! 7. Tf6 gxf6 8. Txh6 Lxh6 9. Dc1 Lxc1 10. e4
paul: Dual: a) 6.- Sh6! 7.Tf6 gxf6 8.Txh6 Lxh6 9.d3 Lxc1. (2010-7-30)
Henrik Juel: Part b) is also ruined, by the same dual (2018-12-9)
Henrik Juel: ... almost the same, namely
6... Sh6 7.Tf6 gxf6 8.Txh6 Lxh6 9.Dc1 Lxc1 10.e4 (2018-12-9)
comment
Keywords: Unique Proof Game
Genre: Retro
Reprints: (12) diagrammes 15 07-09/1994
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-10 more...
57 - P0004845
Dmitri W. Pronkin
4833v Die Schwalbe 84 08/1984
1. Preis
P0004845
(14+1)
BP in 26,5
1. Sh3 g5 2. Sf4 gxf4 3. Sa3 f3 4. gxf3 Sf6 5. Lg2 Se4 6. fxe4 d5 7. exd5 Sc6 8. dxc6 Dd3 9. exd3 h5 10. Dg4 hxg4 11. cxb7 g3 12. hxg3 f5 13. Th2 f4 14. gxf4 e5 15. fxe5 Ld6 16. exd6 Th3 17. dxc7 Te3+ 18. fxe3 a5 19. Kf2 Ta6 20. Kg3 Tc6 21. Kh4 Tc3 22. dxc3 Le6 23. Ld2 Lb3 24. cxb3 a4 25. bxa4 Kf7 26. Ld5+ Kg6 27. Lf7+
play all play one stop play next play all
Henrik Juel: Mario, can your rawbats test this one? (2018-12-9)
Mario Richter: White pawns captured all missing black men, and we know exactly on which squares all these captures took place. So one testing idea would be to generate all possible mappings M: BLACK_PIECES -- CAPTURE_SQUARES and use these mappings as constraints for programs like 'jacobi' or 'rawbats'.
The main task is to find a subset M' of M which reduces the number of test cases from approx. 15! to a manageable size.
Can you provide some mathematical/logical insight how this might be done?! (Some observations that might be helpful are: Bishops could only have been captured on squares of their own color, Ph7 captured at least once and he or Pg7 either promoted or did the last remaining black capture,so most of the other black pawns never left their homefile, ...) (2018-12-10)
Henrik Juel: I have no further insights, Mario (2018-12-11)
comment
Keywords: Unique Proof Game, Massacre PG, Rex solus (s)
Genre: Retro
Reprints: 118 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-13 more...
58 - P0005393
Alexander Kislyak
38 Shakhmatnaya Kompozitsiya 04/1993
P0005393
(11+13) C+
BP in 16,0
1. e4 a5 2. De2 Ta6 3. Dxa6 a4 4. Dg6 hxg6 5. h3 Txh3 6. e5 Ta3 7. e6 Txa2 8. exd7+ Lxd7 9. Th3 e6 10. Ta3 Lb4 11. Sf3 Lc3 12. dxc3 Df6 13. Lg5 Se7 14. Lh4 g5 15. c4 Dg6 16. Sc3 Txa1+
play all play one stop play next play all
more ...
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Natch 3.1 (1 hour 40 min.)
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2018-12-13 more...
59 - P0005598
Jorge Abel Barros
Raul Ocampo
C. Buchborn
Alfred Gschwend
Josef Haas
Hans Hofmann
G. Jensen
Karl Kaul
Jorge Joaquin Lois
Julio Alberto Pancaldo
Pedro Gomez Masia
Emiliano F. Ruth
Helmut Mertes
John Niemann
Hector G. Zucal
Horacio Amil Meylan

(3) Die Schwalbe 25 02/1974
P0005598
(5+0)
51 gedeckte Felder
Konstruktionsausschreiben 06/1973
A.Buchanan: Is this (16) the maximum number of composers for a problem? Sublime! (2019-1-1)
comment
Keywords: Construction task
Genre: Retro
Input: Gerd Wilts, 1995-6-5
60 - P0005787
Andrey Frolkin
Leonid Lyubashevsky

Zaporizka pravda 1988
Spezialpreis
P0005787
(26+0) C+
Färbe die Steine!
KBP?
1. Sa3 d5 2. Sc4 Lg4 3. Se5 Lf3 4. Sg6 hxg6 5. gxf3 Th3 6. f4 Tg3 7. Lh3 c6 8. Lc8 e6 9. hxg3 Lb4 10. Th8 Lc3 11. bxc3 Ke7 12. La3+ Kf6 13. Db1 Sh6 14. Db6 axb6 15. Lf8 Ta3 16. Sh3 Tb3 17. axb3 Dd6 18. Ta8 Sa6
play all play one stop play next play all
Henrik Juel: The fastest pawn captures are a2xb3, b2xc3, g2xf3, h2xg3, and a7xb6, h7xg6
Surprisingly, in the intended coloring, the four men on row 8 are white; the rest is 'normal' (2018-12-9)
Henrik Juel: The colored position is C+ by Natch 3.1 (1 sec.)
No solution in 17.5 or 17.0 moves (2018-12-9)
comment
Keywords: Unique Proof Game, Coloring problem
Genre: Retro
Computer test: Natch 3.1 (1 sec.)
Reprints: 586 Ukrainisches Album 1986-1990
(4) Die Schwalbe 144 12/1993
Input: Gerd Wilts, 1995-6-7
Last update: Alfred Pfeiffer, 2018-12-13 more...
61 - P0005845
Unto Heinonen
U.S. Problem Bulletin 1993
1. Preis
P0005845
(16+16) C+
BP in 21,5
1. d4 h5 2. Lh6 Sf6 3. f4 Se4 4. Sf3 Sd2 5. e4 a5 6. La6 e5 7. c4 Lb4 8. Da4 c5 9. Dc6 b5 10. Lb7 Ta6 11. a4 Tb6 12. Sa3 Sa6 13. 0-0-0 Sf1 14. Td3 Le1 15. b4 Dh4 16. Tb3 Df2 17. h4 Kd8 18. Th3 d5 19. Tg3 Lh3 20. Tg6 f5 21. Tf6 g5 22. g4
play all play one stop play next play all
more ...
comment
Keywords: Unique Proof Game, Castling, Ornament, Capture-free
Genre: Retro
Computer test: Natch 3.1 (1 min.)
Reprints: feenschach 121, p. 311, 11/1996
H28 FIDE Album 1992-1994 2001
feenschach 141 06/2001
Input: Gerd Wilts, 1995-6-20
Last update: Alfred Pfeiffer, 2018-12-13 more...
62 - P0005880
Michel Caillaud
R222v The Problemist 01/1994
Ladislav Packa gewidmet
P0005880
(12+14) C+
BP in 29,0
1. h4 a5 2. h5 a4 3. h6 a3 4. hxg7 axb2 5. Th6 bxa1=T 6. Tc6 h5 7. Sh3 h4 8. Sf4 h3 9. Sd5 h2 10. f4 h1=T 11. Kf2 Txf1 12. Kg3 Thh1 13. a4 Sh6 14. g8=L dxc6 15. Lh7 Sd7 16. Lf5 Sb6 17. Lh3 Lf5 18. a5 e6 19. a6 Lc5 20. a7 Le3 21. dxe3 Dd6 22. Dd3 Kd7 23. Ld2 Th8 24. a8=D Lh7 25. Dg8 Ta8 26. Dgg6 Kc8 27. La5 Kb8 28. Sbc3 Ta1 29. Kh4 Dd8
play all play one stop play next play all
Henrik Juel: C+ by Natch 3.1 (21 min.)
A fantastic idea: By move 10 Black has promoted on a1,h1, so he has rooks in all four corners; during the next 18 moves the rooks interchange cyclically clockwise, motivated by the need for white to play a8=D-g8-g6
This leaves an ugly promoted wD on the board, whereas the promoted wLh3 is more discrete; maybe the author had a8=T in the first version, which was then cooked (2018-12-9)
comment
Keywords: Unique Proof Game, Non-standard material, Platzwechsel, zyklischer (tttt), Promoted material on the board (L), Four corners
Genre: Retro
Computer test: Natch 3.1 (21 min.)
Reprints: H32 FIDE Album 1992-1994 2001
(1) Quartz 18 10-12/2002
Input: Gerd Wilts, 1995-6-26
Last update: Alfred Pfeiffer, 2018-12-13 more...
63 - P0005903
Jasper van Atten
R195 The Problemist 09/1993
P0005903
(14+15) C+
BP in 20,0
1. d3 a5 2. Le3 Ta6 3. La7 h5 4. e3 h4 5. Dh5 Tah6 6. Le2 T6h7 7. Dh6 b6 8. Lh5 Lb7 9. Ke2 La6 10. Kf3 a4 11. Se2 a3 12. Sxa3 h3 13. Tag1 hxg2 14. Sc1 gxh1=S 15. Tg4 Sf6 16. Tb4 Tg8 17. Sc4 Thh8 18. a3 Sh7 19. Ke4 Lc8 20. f3 Sa6
play all play one stop play next play all
more ...
comment
Keywords: Unique Proof Game, Loss of tempo (l3), Promotion
Genre: Retro
Computer test: Natch 3.1 (7 sec.)
Input: Gerd Wilts, 1995-6-26
Last update: Alfred Pfeiffer, 2018-12-13 more...
64 - P0005946
Yis Yoront
5508 feenschach 91 05-08/1989
P0005946
(16+15) C+
KBP, dann #1 (wer?)
1. h4 g5 2. hxg5 d6 3. Th4 Lh3 4. g4 Dd7 5. Lg2 Db5 6. Lc6+ Sd7 7. e4 0-0-0 8. Df3 Kb8 9. Db3 Dd3, dann 10. Dxb7#
play all play one stop play next play all
FJS: "Einfaches Auszählen ergibt, daß beide Parteien schon mindestens 9 Züge gemacht haben. Eine 9-zügige Beweispartie ist leicht zu finden: "1.h4 g5 2.hxg5 d6 3.Th4 Lh3 4.g4 Dd7 5.Lg2 Db5 6.Lc6+ Sd7 7.e4 000 8.Df3 Kb8 9.Db3 Dd3, also ist Weiß am Zug: 10.Dxb7#
JV: "Ich würde sagen: Das ist eine Aufgabe für Retro-Unerfahrene." Retro für alle, wie GL das in der Schwalbe nennt. [2,6/II]
more ...
comment
Keywords: Unique Proof Game, Castling
Genre: Retro
Computer test: Natch 3.1
Input: Gerd Wilts, 1995-6-26
Last update: Alfred Pfeiffer, 2018-12-13 more...
65 - P0006245
Peter Wong
2024 Phénix 31 07/1995
1. Preis
P0006245
(12+15) C+
BP in 27,5
1. Sf3 a6 2. Sd4 Ta7! 3. Sb5 axb5 4. f3! Ta3 5. bxa3 Sc6 6. Lb2 Sa5 7. Le5 Sc4 8. Ld6 cxd6 9. c3 Da5 10. Dc2 Da4 11. Dg6 Dc2 12. Dh6 gxh6 13. f4 Lg7 14. f5 Ld4 15. f6 Sxf6 16. h3! Tg8 17. h4 Tg3 18. h5 Th3 19. g3! La7 20. Lg2 b6 21. La8 Lb7 22. 0-0 Lg2 23. Lf3 Se4 24. g4 f6 25. g5 Kf7 26. g6 Ke6 27. g7 Kd5 28. g8=S
play all play one stop play next play all
more ...
comment
Keywords: Bahnung, Räumung, Unique Proof Game, Castling, Loss of tempo (t1), Promotion
Genre: Retro
Computer test: Natch 3.1 (2 min.)
Reprints: 3402 U.S. Problem Bulletin 102/103 07-10/1995
H17 FIDE Album Annexe 1995-1997 2004
(66) Parallel Strategy 2004
Input: Gerd Wilts, 1995-8-17
Last update: Alfred Pfeiffer, 2018-12-13 more...
66 - P0006428
Andrey Frolkin
9133v Die Schwalbe 157, p. 283, 02/1996
P0006428
(13+12) cooked
BP in 20,0
May White castle?
Weiß darf noch rochieren: 1. h4 Sa6 2. h5 Sc5 3. h6 a6 4. hxg7 h5 5. f4 h4 6. f5 h3 7. f6 h2 8. fxe7 Sf6 9. g8=L Lh6 10. Lxf7 Kxf7 11. e8=T Kg6 12. Te6 Dg8 13. Tc6 Db3 14. axb3 dxc6 15. Ta4 Lh3 16. Te4 Tag8 17. Te8 hxg1=D 18. e4 Dd4 19. Lc4 Tg7 20. Lg8 Dd8
Ohne die Bedingung, daß Weiß rochieren darf, gibt es andere BPs: 1. f4 Sa6 2. f5 Sc5 3. f6 a6 4. fxe7 f5 5. e4 f4 6. Lb5 f3 7. Lc6 f2+ 8. Ke2 fxg1=D 9. h4 dxc6 10. h5 Lf5 11. h6 Sf6 12. hxg7 Dd5 13. g8=L Db3 14. Lxh7 Kf7 15. axb3 Lh6 16. Ta4 Tag8 17. Td4 Dxd4 18. e8=T Tg7 19. Lg8+ Kg6 20. Ke1 Dd8
play all play one stop play next play all
SH: Cooked?:
1. e4 f5 2. Ne2 f4 3. h4 f3 4. h5 fxe2 5. f4 exf1B 6. f5 Bc4 7. f6 Bb3 8. axb3 Na6 9. fxe7 Nc5 10. Ra6 Nf6 11. Rc6 dxc6 12. h6 Bh3 13. hxg7 Qd7 14. g8B Bh6 15. Bxh7 Kf7 16. Qf3 Rag8 17. Qe2 Rg7 18. Bg8+ Kg6 19. Qd1 a6 20. e8R Qd8 (2005-6-20)
Henrik Juel: The stipulation question was probably intended as an implicit condition; when answered affirmatively, there should be a unique solution
But SH's solution shows that the problem is cooked (2018-12-9)
comment
Keywords: Anti-Pronkin Theme, Conditional problem, Unique Proof Game, Castling in the forward play
Genre: Retro
Input: Gerd Wilts, 1996-6-12
Last update: Alfred Pfeiffer, 2018-12-13 more...
67 - P0006438
Andrey Frolkin
9191 Die Schwalbe 158, p. 343, 04/1996
Werner Keym gewidmet
2. ehrende Erwähnung Abt. II
P0006438
(15+15)
KBP?
UWF in der Diagrammstellung sind
1) zulässig
2) nicht zulässig
1) 1. h4 h5 2. Th3 Th6 3. Te3 Tc6 4. Te6 dxe6 5. a4 Dd5 6. a5 Kd7 7. a6 Kd6 8. axb7 a5 9. Sh3 Sa6 10. b8=T a4 11. Tb7 Tb8 12. Ta7 Lb7
2) 1. a4 h5 2. a5 Th6 3. a6 Tc6 4. axb7 a5 5. h4 Sa6 6. b8=D a4 7. Db3 Tb8 8. De6 dxe6 9. Th3 Dd5 10. Tb3 Kd7 11. Tb7 Kd6 12. Ta7 Lb7 13. Sh3
play all play one stop play next play all
Henrik Juel: Part 1) is C+ by Natch 3.1 (2018-12-9)
comment
Keywords: Ceriani-Frolkin Theme (D), Unique Proof Game, Promotion
Genre: Retro
Input: Gerd Wilts, 1996-6-12
Last update: Alfred Pfeiffer, 2018-12-13 more...
68 - P0006626
Andrey Frolkin
(56v) Die Schwalbe 159, p. 362, 06/1996
1. ehrende Erwähnung
Ceriani-Gedenkturnier, 1. Abteilung
P0006626
(13+12) cooked
BP in 20,0
(21. 0-0 is possible)
1. h4 Sa6 2. h5 Sc5 3. h6 a6 4. hxg7 h5 5. f4 h4 6. f5 h3 7. f6 h2 8. fxe7 Sf6 9. g8=L Lg7 10. Lxf7 Kxf7 11. e8=T Kg6 12. Te6 Dg8 13. Tc6 Db3 14. axb3 dxc6 15. Ta4 Lg4 16. Te4 Taf8 17. Te8 hxg1=D 18. e4 Dd4 19. Lc4 Dd8 20. Lg8 Tf7
play all play one stop play next play all
Cook: NL
1. e4 f5 2. Se2 f4 3. h4 f3 4. h5 fxe2 5. f4 exf1=L 6. f5 Lc4 7. f6 Lb3 8. axb3 Sa6 9. fxe7 Sc5 10. Ta6 Sf6 11. Tc6 dxc6 12. h6 Lh3 13. hxg7 Dd7 14. g8=L Lg7 15. Lxh7 Kf7 16. Df3 Taf8 17. Lg8+ Kg6 18. De2 Tf7 19. Dd1 a6 20. e8=T Dd8 (Henrik Juel)
more ...
comment
Keywords: Unique Proof Game, Castling
Genre: Retro
Input: Gerd Wilts, 1996-7-11
Last update: Alfred Pfeiffer, 2018-12-13 more...
69 - P0007032
Henrik Juel
3000 Probleemblad 05/1996
P0007032
(15+16) C+
BP in 19,0
1. c3 h5 2. Dc2 Th6 3. Dh7 f5 4. Kd1 Kf7 5. Kc2 Ke6 6. Kd3 Kd5 7. Ke3 Kc4 8. a3 Kb3 9. Sh3 Kc2 10. Sf4 Kd1 11. h3 Ke1 12. Th2 Kxf1 13. Kf3 Ke1 14. Kg3 Kd1 15. Th1+ Kc2 16. Kh2 Td6 17. Kg1 Td5 18. Kf1 d6 19. Ke1 Le6
play all play one stop play next play all
Henrik Juel: C+ by Jacobi using the constraints
Ke8-c2-d1-e1xf1-e1-d1-c2 Ke1-d1-c2-d3-g3-h2-g1-f1-e1
which are valid, because [Ke8] is the only black man who could capture [Lf1] in time, so [Ke1] would have to get out via c2-d3 and back home via g3-h2
It is recommended that HC+ is used, but this is not available on the PDB (yet)
Ke1 made a round trip (which is stronger than a promenade) (2018-12-9)
comment
Keywords: Unique Proof Game, Promenade (Kk), Pure Round Trip (K)
Genre: Retro
Computer test: Jacobi
Reprints: Ex2 64 Proof Games 2012
Input: Gerd Wilts, 1996-8-12
Last update: Alfred Pfeiffer, 2018-12-13 more...
70 - P0008413
Guus Rol
Harry Goldsteen

Probleemblad 1 01-02/1989
P0008413
(8+12)
#2 durch Schwarz
1. Kxc2 Sb3 2. ... Tc1#
R: 1. ... Ta2-a1+ 2. a3xLb4 Lf8-b4 3. Lb4-c3 Kb3-a4 4. Le7-b4 a7xSb6 5. Sa4-b6 Dd5-d4 6. Sc3-a4 Dd4-d5 7. Sb1-c3 Ta1-a2 8. Lf6-e7 Kb4-b3 9. a2-a3+ Kc5-b4 10. Lg5-f6 Kd6-c5 11. Lf6-g5 Kd7-d6 12. Le7-f6 Kc8-d7 13. Lf6-e7 Kb8-c8 14. Ld8-f6 e7-e6 15. d7-d8=L Kc8-b8 16. e6xTd7+ Td8-d7 17. f5xLe6 0-0-0 18. f4-f5 Lc8-e6 19. f3-f4 Dd8-d4 20. f2-f3 d7xLc6 21. Lf3-c6 Sc6-a5 etc.
play all play one stop play next play all
"O, W, thuis..."
Henrik Juel: 1.Kxc2 Sb3 2.. Rc1#. -1.. Ra2 -2.a3:B Bf8 -3.Bb4 Kb3 -4.Be7 a7:S -5.Sa4 Qd5
-6.Sc3 Qd4 -7.Sb1 Ra1 -8.Bf6 Kb4 -9.a2 Kc5 -10.Bg5 Kd6 -11.Bf6 Kd7 -12.Be7 Kc8 -13.Bf6 Kb8 -14.Bd8 e7 -15.B=d7 Kc8 -16.e6:R Rd8 -17.f5:B 0-0-0 -18.f4 Bc8 -19.f3 Qd8 -20.f2 d7:B -21.Bf3 Sc6 etc. (2003-8-26)
Yoav Ben-Zvi: An attempt at a coherent argument that reveals the intricate sequence of events in the resolution while refuting substantial alternatives:
The promotion of wBc3, on d8 or f8, requires 2 captures by the promoting wP. These, together with the captures by wPd3 and wPb4, account for all 4 missing Black pieces. Black captured [wBc1] at home. The other 7 missing White pieces were captured by bPs. [wBf1] cannot be released (by wPe2xd3) until [bPh7] plays bPd3xc2 completing the capture of 5 White pieces. Therefore [wBf1] was captured by bPd7xBc6 (the remaining capture by Black on a light colored square), releasing [bBc8]. This means that [wBf1] is released (by wPe2xd3) before [bBc8] is released (by capturing the previously released wB on c6) so the bB could not have been the piece captured on d3. It also could not be captured on b4 (dark colored square) so it was captured by White's promoting pawn. This means the promotion could not have been played by capture from e7 as that would imply that the 2 captures by the promoting pawn were both on dark colored squares in contradiction with the requirement to capture [bBc8]. Therefore the promotion move was wPd7-d8=B with bK standing outside the squares c8,d7,d8,e8.
Looking backward: To avoid White retrostalemate the first 2 retractions must be -1...bRa2-a1+ -2.wPa3xb4.
After this, unlocking the South-West cage and extracting bRa2 requires retraction of wPe2xd3 which requires previous uncapture of wB by bPd7xBc6, so it can be retracted home to f1. bP standing on d7 implies that a bB must previously be uncaptured and retracted home to c8, preceded by retracting BPe7-e6 to clear the path of uncaptured bB to c8. Retreat of bP to e7 is preceded by uncapture and return home of [bBf8]. With both bBs locked at home and bP on e7 the Black Central cage is locked by retracting bPd7xBc6 so bK and bQ must also be retracted home first. It follows that bKa4 needs to exit the West cage before it has been unlocked (to get back home to e8 before the Black Central cage is locked). The bK cannot exit via b5 as this implies retraction of wPc3-c4+ but, with c3 occuppied by wP, bRa2 does not have a valid exit path (not via c3 as it is obstructed by wP or via f1 as it will be occupied by wB). wP standing on c4 prevents retracting bN away from a5 so bK cannot exit via a5. The only valid exit of the bK is via b4 implying retracton of wPa2-a3 which requires bRa2 to retract to a1 (vacating a2 for the wP) which requires provision of a shield, standing on b1, to protect wKc1 from bRa1.
After the unpromotion of wBc3, White has only pawn retractions left to make until a White officer is uncaptured. This is not enough to allow Black to complete the retro-maneuvers required in preparation for retracting bPd7xBc6 (getting bBs,bK,bQ home). It follows that, at some point in the middle of its preparation maneuver, Black will need to uncapture a White officer which provides the tempo retractions needed to complete the maneuver. This is only possible by bPa7xb6. With bP standing on a7, [bRa8] cannot be retracted home via the a file so it must retract to its original corner via row 8 before the bB is locked at c8. This implies that [bRa8] is uncaptured by a wP prior to unlocking of the cage.
Uncaptures by White prior to the unlocking of the South-West cage (one available on b4 and two by pawn unpromoted from wBc3) include uncaptures of both bBs and a bR since, as noted in the above analysis, all 3 must be uncaptured and retracted home before retracting bPd7xBc6 (all of which precedes the unlocking of the South-East cage). This means that the bN is uncaptured later (on d3) so it cannot provide the shield on b1. The shield also could not be provided by [bBc8] as this bishop must be returned home when it is needed to provide the shield. The only remaining possibility is that the shield on b1 is provided by a wN that is uncaptured by bPa7xNb6. The wN on b1 is immobile until the wK can be retracted away from c1 so here too, once the unpromotion occurs Black must perform the preparations for retraction of bPd7xBc6 (which now includes return of the uncaptured bR to a8 or b8) under time pressure, completing the required maneuvers before White runs out of tempo retractions. Having determined the structural elements it is not too difficult to construct a resolution that succeeds in preparing for retraction of bPd7xBc6 before White runs out of tempo retractions. The resolution maintains the following: delay the unpromotion (known from analysis above to be wPd7-d8=B) while retracting bK to b8; bQ to d4 and bB (uncaptured on b4) to f8 and continuing by retracting -1.wBd8-? Pe7-e6 -2.Pd7-d8=B Kc8-b8 -3.Pe6xRd7+ Rd8-d7 -4.Pf5xBe6 0-0-0 -5.Pf4-f5 Bc8-e6 -6.Pf3-f4 Qd8-d4 -7.Pf2-f3 Pd7xBf6 -8.Bc6-? Nc6-a5. Following this the wB is retracted to f1 allowing the unlocking of the cage by wPe2xNd3 and bRa1 is retracted back home to h8 via c1,c3. One of the White pieces uncaptured by bPc2 unpromotes on h8. The alternative of uncapturing the bR on b4 (instead of bB) fails to complete the preparations on time.
To draw attention to the rich, unconditional, content of the resolution the stipulation could be "Squares that must have been occupied by bRa1". This problem deserves a full SPG. The best I can manage is a game of 53.0 moves. (2018-12-23)
comment

Genre: Retro
Input: Gerd Wilts, 1996-9-17
Last update: Alfred Pfeiffer, 2017-2-20 more...
71 - P0008429
Peter Wong
U.S. Problem Bulletin 102/103 07-10/1995
P0008429
(12+14) C+
BP in 22,5
1. Sf3 a6 2. Sd4 Ta7 3. Sb5 axb5 4. h3 Ta3 5. bxa3 Sa6 6. Lb2 Sc5 7. Lf6 gxf6 8. c3 Lh6 9. Db3 Lg5 10. De6 dxe6 11. h4 Dd3 12. hxg5 Dc2 13. g6 hxg6 14. f3 Th3 15. f4 Td3 16. g3 Kd7 17. Lh3 Kc6 18. Lg2+ Kb6 19. Lc6 Se4 20. Le8 Ld7 21. 0-0 Lc6 22. Ld7 Ld5 23. Lc8
play all play one stop play next play all
more ...
comment
Keywords: Unique Proof Game, Castling, Loss of tempo (tBL)
Genre: Retro
Computer test: Natch 3.1 (12 sec.)
Input: Gerd Wilts, 1996-9-18
Last update: Alfred Pfeiffer, 2018-12-19 more...
72 - P0008570
Unto Heinonen
Suomen Tehtäväniekat 06/1995
P0008570
(13+14) C+
BP in 24,0
1. e4 Sc6 2. Dh5 Se5 3. Le2 Sg6 4. Ld1 f5 5. Se2 f4 6. 0-0 f3 7. Kh1 fxe2 8. f4 e1=L 9. Tf3 Lh4 10. Td3 Lf6 11. Td6 Lc3 12. bxc3 exd6 13. La3 Le7 14. Lc5 Lf6 15. Lf2 Ld4 16. cxd4 S8e7 17. Sc3 Sc6 18. Tb1 Sb8 19. Tb6 axb6 20. Lh4 Ta5 21. Le7 Tg5 22. Lf8 Tg3 23. Da5 Se7 24. Da8 Sg8
play all play one stop play next play all
Henrik Juel: C+ by Natch 3.1 (2 min.)
After 2.Dh5 [Pf7] is pinned; to unpin it quickly Black must play Sb8-c6-e5-g6, so when [Pf7] moves, the sSg6 is pinned; later Black has nothing better to do than playing Sg8-e7-c6-b8, and the sSS interchange is halfway there
The long march Lc1-a3-c5-f2-h4-e7-e8 is remarkable (2018-12-10)
comment
Keywords: Ceriani-Frolkin Theme (l), Unique Proof Game, Interchange (ss), Castling
Genre: Retro
Computer test: Natch 3.1 (2 min.)
Reprints: Thema Danicum 100 2000
Input: Gerd Wilts, 1997-1-9
Last update: Alfred Pfeiffer, 2018-12-19 more...
73 - P0008614
Thomas Volet
636 Europe Echecs 455 04/1997
P0008614
(14+10)
Welches waren die letzten 3 Schläge?
R: 1. b4-b5 a7xTb6 2. a3xLb4, dann Lg1-h2, h2-h4, Th3-g6, Th4xBh3, Lg7-b4 Dh6-h7 h4-h3 Df4-h6
play all play one stop play next play all
Yoav Ben-Zvi: The full release of the North cage requires further retractions: bBf4-h6-g7, bKh3-g4-g5-h6-g7-f8, bBf8-h6-f4, bPg7-g6. The maneuvers of [bBf8] include a Shield on g7 and a double Switchback to h6 and to f4.
The cross-over between bK and bB is shown with unique moves in P1338760. (2018-12-29)
comment

Genre: Retro
Reprints: H4 FIDE Album Annexe 1995-1997 2004
Input: Gerd Wilts, 1997-5-2
Last update: Gerd Wilts, 2004-8-6 more...
74 - P0008654
Ronald Turnbull
12857 British Chess Magazine 1993
Lob
P0008654
(15+14) C+
BP in exactly 11,5
1. g4 e6 2. g5 Ke7 3. g6 Kf6 4. gxh7 Kg6 5. hxg8=S Th3 6. Se7+ Kh7 7. Sc6 dxc6 8. Lg2 Sd7 9. Ld5 Sf6 10. Lf3 Dd5 11. Lg2 Ld7 12. Lf1
play all play one stop play next play all
A.Buchanan: I imagine that e.g. 12. ... Tc8 would allow the removal of the "exactly" limitation, which is unsavory in a tempo problem. (2018-12-12)
A.Buchanan: Yes confirmed C+ BP 12.0 after 12. ... Tc8 with Euclide 1.11. (2018-12-12)
more ...
comment
Keywords: Ceriani-Frolkin Theme (S), Unique Proof Game, Homebase (W), Loss of tempo (L)
Genre: Retro
Computer test: Natch 3.1 (1 sec.)
Input: Gerd Wilts, 1997-5-19
Last update: Alfred Pfeiffer, 2018-12-12 more...
75 - P0008658
Thierry Le Gleuher
1550v Phénix 50 03/1997
P0008658
(14+14) C+
BP in 19,0
1. h4 g5 2. hxg5 f5 3. Th6 f4 4. Tc6 f3 5. exf3 bxc6 6. Lc4 La6 7. d3 Lb5 8. Kd2 La4 9. Kc3 Lb3 10. a4 La2 11. Kb4 Lxb1 12. c3 Lc2 13. De1 Ld1 14. Lf4 Le2 15. Lh2 Lf1 16. g3 Lh3 17. Td1 Le6 18. Td2 Ld5 19. Da1 c5+
play all play one stop play next play all
paul: Correction of P0002202 (2014-7-4)
more ...
comment
Keywords: Unique Proof Game, Promenade (l)
Genre: Retro
Computer test: Natch 3.1 (17 min.)
Input: Gerd Wilts, 1997-5-20
Last update: Alfred Pfeiffer, 2018-12-19 more...
76 - P0008883
Unto Heinonen
1350 Suomen Tehtäväniekat 03-04/1997
P0008883
(13+13)
BP in 29,5
1. h4 c6 2. Th3 Db6 3. Tc3 De3 4. fxe3 Sa6 5. Kf2 Sc5 6. Kf3 Sb3 7. Ke4 Sxa1 8. Kd4 a5 9. Kc5 Sb3+ 10. Kb6 Sc5 11. Sf3 Sa6 12. Sd4 Sb8 13. Kc7 b6 14. Sb5 La6 15. Sa7 Lc4 16. g4 Lb3 17. cxb3 e5 18. Dc2 Ke7 19. Dxh7 Kf6 20. Dc2 Th5 21. Kd8 Tf5 22. h5 Kg5 23. h6 Kh4 24. h7 Kg3 25. h8=T Kf2 26. Th4 Th5 27. g5 Ke1 28. Tb4 axb4 29. Ke8 bxc3 30. Dd1+
play all play one stop play next play all
Joost de Heer: [Event "Edited game"]
[Site "COCOS10"]
SOlution: 1. h4 c6 2. Rh3 Qb6 3. Rc3 Qe3 4. fxe3 Na6 5. Kf2 Nc5 6. Kf3 Nb3 7. Ke4
Nxa1 8. Kd4 a5 9. Kc5 Nb3+ 10. Kb6 Nc5 11. Nf3 Na6 12. Nd4 Nb8 13. Kc7 b6
14. Nb5 Ba6 15. Na7 Bc4 16. g4 Bb3 17. cxb3 e5 18. Qc2 Ke7 19. Qxh7 Kf6 20.
Qc2 Rh5 21. Kd8 Rf5 22. h5 Kg5 23. h6 Kh4 24. h7 Kg3 25. h8=R Kf2 26. Rh4
Rh5 27. g5 Ke1 28. Rb4 axb4 29. Ke8 bxc3 (2001-11-5)
Henrik Juel: In an hour Natch 3.1 could not even find the intended solution (2018-12-10)
A.Buchanan: how about "demolition mode" in Jacobi? (2018-12-12)
more ...
comment
Keywords: Ceriani-Frolkin Theme (T), Unique Proof Game, Interchange, under-promotion (T)
Genre: Retro
Input: Gerd Wilts, 1998-6-26
Last update: Alfred Pfeiffer, 2018-12-12 more...
77 - P0008919
Gianni Donati
R012 Probleemblad 11/1997
5. Preis
P0008919
(14+14) C+
BP in 17,0
1. Sf3 h5 2. Se5 Sh6 3. Sxd7 Kxd7 4. g4 Kc6 5. Lg2+ Kb5 6. Le4 Lxg4 7. Lh7 g6 8. Kf1 Lg7 9. Kg1 Ld4 10. Df1 Lb6 11. Dg2 c5 12. Dxb7 Dc7 13. Dg2 Td8 14. Df1 Td5 15. Dd1 Sd7 16. Kf1 Tc8 17. Ke1 Db8
play all play one stop play next play all
more ...
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Natch 3.1 (5 min.)
Reprints: feenschach 137 08-09/2000
Input: Gerd Wilts, 1998-6-26
Last update: Alfred Pfeiffer, 2018-12-19 more...
78 - P0008957
Gianni Donati
2700 Phénix 58 12/1997
P0008957
(15+15)
BP in 22,5
1. g4 d6 2. Lh3 Dd7 3. Kf1 De6 4. De1 De3 5. fxe3 Kd7 6. Dh4 Kc6 7. Dh6 gxh6 8. Sf3 Lg7 9. Tg1 Ld4 10. Tg3 Sf6 11. Lg2 Tg8 12. Th3 Tg5 13. Th5 Te5 14. Tg5 Lf5 15. Tg8 Sbd7 16. Th8 Tg8 17. Ke1 Tg5 18. Ta8 Th5 19. g5 Sg8 20. g6 Tg5 21. Lf1 Tg1 22. g7 Th1 23. Sg1
play all play one stop play next play all
Henrik Juel: This is one of the proof games that is solved faster by hand than by computer
The two captures are obvious, and the interchanged rooks make a guess like Th1-g1-g3-h3-h5-g5-g8-h8-a8 reasonable
Natch 3.1 got nowhere in an hour (2018-12-10)
comment
Keywords: Unique Proof Game
Genre: Retro
Input: Gerd Wilts, 1998-6-26
Last update: Gerd Wilts, 2005-12-30 more...
79 - P0009124
Michel Caillaud
2952 Phénix 69 12/1998
P0009124
(14+13) C+
BP in 18,0
1. e3 b5 2. Lc4 b4 3. d3 b3 4. Sd2 bxa2 5. b4 g6 6. Lb2 Lg7 7. Dc1 Le5 8. Lxe5 d6 9. Da3 Sd7 10. 0-0-0 a1=L 11. Le6 Lc3 12. Sc4 Le1 13. f3 Lg3 14. h4 Lf4 15. h5 Lh6 16. hxg6 Lf8 17. g7 d5 18. gxf8=S dxc4
play all play one stop play next play all
Schlag des Original-sLf8 auf e5 durch eine Figur, anschließend Schlag des Pronkin-Lf8.
Henrik Juel: C+ by Natch 3.1 (15 min.)
You can count the white moves, but Black has to work hard to get rid of his [Pb7]; surprisingly it makes 11 moves to promote to L and reach f8 (2018-12-10)
comment
Keywords: Ceriani-Frolkin Theme (l), Unique Proof Game, Promenade (l), Pronkin Theme (l)
Genre: Retro
Computer test: Natch 3.1 (15 min.)
Input: Gerd Wilts, 1999-2-27
Last update: Alfred Pfeiffer, 2018-12-19 more...
80 - P0009125
Mikhailo Kozulya
2953 Phénix 69 12/1998
P0009125
(14+13) C+
BP in 26,0
2 Lösungen
1. a4 d5 2. a5 d4 3. a6 d3 4. axb7 dxe2 5. Ta6 exd1=L 6. Tc6 a5 7. h4 a4 8. h5 a3 9. h6 a2 10. hxg7 Ta3 11. Thh6 Sa6 12. Thf6 h5 13. b8=L h4 14. La7 h3 15. Le3 h2 16. Lg5 Thh3 17. f4 Sh6 18. g8=L Ldg4 19. Lh7 Lgd7 20. Lhd3 e6 21. Lb5 Lb4 22. c4 Lc3 23. dxc3 Ke7 24. Sd2 Dh8 25. Sdf3 Le8 26. Sh4 Lcd7
1. h4 d5 2. h5 d4 3. h6 d3 4. hxg7 dxe2 5. Th6 exd1=L 6. Tf6 h5 7. a4 h4 8. a5 h3 9. a6 h2 10. axb7 Th3 11. Taa6 Sh6 12. Tac6 a5 13. g8=L a4 14. Lh7 a3 15. Lhd3 a2 16. Lb5 Taa3 17. c4 Sa6 18. b8=L Ldg4 19. La7 Lgd7 20. Le3 e6 21. Lg5 Lb4 22. f4 Lc3 23. dxc3 Ke7 24. Sd2 Dh8 25. Sdf3 Le8 26. Sh4 Lcd7
play all play one stop play next play all
Henrik Juel: C+ by Natch 3.1 (10 sec.)
The last 4.5 moves are identical in the two solutions (2018-12-10)
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Natch 3.1 (10 sec.)
Input: Gerd Wilts, 1999-2-27
Last update: Alfred Pfeiffer, 2018-12-19 more...
81 - P0009131
Unto Heinonen
R041 Probleemblad 01/1999
P0009131
(15+13)
BP in 19,0
1. e4 h5 2. Dxh5 g6 3. Dd1 Txh2 4. g3 Tg2 5. Th8 Lh6 6. a4 Kf8 7. Ta3 Kg7 8. Te3 Sf6 9. b3 Dg8 10. La3 Dh7 11. Txc8 Sa6 12. Th8 Dg8 13. Lxa6 Dd8 14. Lf1 Sg8 15. d3 Kf8 16. Kd2 Ke8 17. Kc1 Lf8 18. Th1 Th2 19. f3 Th8
play all play one stop play next play all
3 weiße und 5 schwarze Switchbacks, vier davon mit Schlag begründet.
Henrik Juel: Natch 3.1 made no progress after an hour (2018-12-13)
comment
Keywords: Bahnung, Räumung, Unique Proof Game, Switchback (DTLkdlts)
Genre: Retro
Reprints: (C) Quartz 29 01-06/2006
(100) Die Schwalbe 250A 08/2011
Input: Gerd Wilts, 1999-2-27
Last update: Gerd Wilts, 2011-10-15 more...
82 - P0009132
Michel Caillaud
R042 Probleemblad 01/1999
P0009132
(13+15)
BP in 24,0
1. g4 c5 2. Lg2 Da5 3. Lc6 Dxa2 4. Lb5 Dd5 5. Ta6 Sh6 6. Tc6 dxc6 7. b3 Lf5 8. Lb2 Sd7 9. Lf6 exf6 10. g5 Ld6 11. g6 Ke7 12. gxh7 Thb8 13. h8=T a5 14. Tc8 a4 15. Tc7 Th8 16. f3 Ke8 17. Kf2 Lf8 18. Kg3 a3 19. Kh4 Ta4+ 20. Kh5 Tg4 21. d4 Sb8 22. Dd3 Dd8 23. Sd2 Lc8 24. Dh7 Sg8
play all play one stop play next play all
Switchback von 7 schwarzen Figuren, davon nur einer mit Schlag!
Henrik Juel: Natch 3.1 made no progress after half an hour (2018-12-13)
comment
Keywords: Unique Proof Game, Pure Round Trip (d), Switchback (sldklst), Promotion (T)
Genre: Retro
Input: Gerd Wilts, 1999-2-27
Last update: Gerd Wilts, 2006-1-12 more...
83 - P0009136
Michel Caillaud
R025 Probleemblad 07/1998
3. Preis
P0009136
(13+15)
BP in 19,0
1. c4 g6 2. c5 Lh6 3. c6 Le3 4. dxe3 f5 5. Dd6 cxd6 6. Ld2 Db6 7. La5 Dd4 8. Ld8 b6 9. c7 Lb7 10. c8=D f4 11. Dc6 f3 12. Lc7 fxg2 13. Df3 d5 14. Ld6 Sh6 15. La3 Tf8 16. b4 Txf3 17. Lc1 Th3 18. f4 Sf7 19. Kf2 h5
play all play one stop play next play all
Um den wBc2 los zu werden, muß Weiß ihn auf c8 in eine D umwandeln und auf f3 vom sTh8 schlagen lassen. Um die Umwandlung möglich zu machen, muss der wLc1 auf d8 Schachschutz geben.
Henrik Juel: Natch 3.1 did nothing during a couple of hours (2018-12-10)
comment
Keywords: Ceriani-Frolkin Theme (D), Unique Proof Game, Round Trip (L), Check Protection
Genre: Retro
Reprints: feenschach 153 10-12/2003
Input: Gerd Wilts, 1999-2-27
Last update: A.Buchanan, 2014-5-22 more...
84 - P0009149
Andrey Frolkin
R036 Probleemblad 11-12/1998
P0009149
(14+13)
BP in 26,0
1. h4 d5 2. h5 d4 3. h6 d3 4. hxg7 dxc2 5. d4 f5 6. Ld2 c1=L 7. Da4+ Kf7 8. Dxa7 e5 9. La5 Lh6 10. Sa3 f4 11. 0-0-0 e4 12. Kc2 e3 13. Kb3 exf2 14. Sc2 La3 15. Ka4 Se7 16. b4 Te8 17. g8=T Lf8 18. Th6 Lh3 19. gxh3 Lc1 20. Lg2 f1=L 21. Lc6 Dd5 22. Lb5 Sbc6 23. h4 Tad8 24. Sh3 Td6 25. Sf2 Lh3 26. a3 Lc8
play all play one stop play next play all
paul: Here, we have also an interchange between Bc1 and Bf8. (2018-3-21)
Henrik Juel: The months should be 11-12, not 09 (2018-3-21)
Mario Richter: @Henrik: Is my guess correct that "9" might be the issue number? (i.e. issue 9 of 1998 was for the months Nov.+Dec.?) (2018-3-21)
Henrik Juel: No, Mario; I think the error might have occurred, because Andrej also had a proof game in the preceding issue
Back then PB had six issues per year, numbered 1-6 for each year (unlike Die Schwalbe), so the issue number contains little information
This problem appeared in issue 6, Nov-Dec 1998 (2018-3-21)
Henrik Juel: Natch 3.1 did not even find the solution in an hour (2018-12-10)
comment
Keywords: Unique Proof Game, Pronkin Theme (l)
Genre: Retro
Input: Gerd Wilts, 1999-2-27
Last update: Mario Richter, 2018-3-21 more...
85 - P0009151
Gianni Donati
R038 Probleemblad 09/1998
Michel Caillaud gewidmet
1. Lob
P0009151
(14+15)
BP in 22,0
1. h4 Sf6 2. h5 Sd5 3. h6 gxh6 4. Sf3 Lg7 5. Tg1 Lc3 6. Se5 Kf8 7. f3 Kg7 8. Kf2 Dg8 9. Kg3 Kf8+ 10. Kh4 Dg6 11. d4 Db6 12. Kh5 Db3 13. axb3 Ke8 14. Ta6 Kd8 15. Tf6 exf6 16. Sa3 Se7 17. d5 Te8 18. Dd4 Sg8 19. Da4 Lb4 20. c4 Lf8 21. Sc2 Te7 22. Se1 Ke8
play all play one stop play next play all
Henrik Juel: Natch 3.1 did little in an hour and a half (2018-12-10)
comment
Keywords: Unique Proof Game, Round Trip (k), Pure Round Trip (sl)
Genre: Retro
Input: Gerd Wilts, 1999-2-27
Last update: Gerd Wilts, 2006-1-12 more...
86 - P0009156
Satoshi Hashimoto
PR09 Problem Paradise 10 07-09/1998
2. Preis
P0009156
(14+14) C+
BP in 21,5
1. h4 g5 2. Th3 Lg7 3. Td3 Le5 4. Td6 cxd6 5. Sc3 Da5 6. Se4 Da3 7. bxa3 a5 8. Lb2 Ta6 9. Ld4 Tc6 10. Le3 Tc3 11. dxc3 b6 12. Dd5 Lb7 13. De6 fxe6 14. 0-0-0 Kf7 15. Kb2 Kg6 16. Lc1 Kf5 17. Sd2 Kf4 18. g4 Lg2 19. Sgf3 Lh3 20. Lg2 Sf6 21. Th1 Tf8 22. Sb1
play all play one stop play next play all
more ...
comment
Keywords: Unique Proof Game, Pure Round Trip (SL)
Genre: Retro
Computer test: Natch 3.1 (8 min.)
Reprints: feenschach 153, p. 195, 10-12/2003
3 64 Proof Games 2012
Input: Gerd Wilts, 1999-2-27
Last update: Alfred Pfeiffer, 2018-12-19 more...
87 - P0009163
Hitoshi Yanami
H16c Problem Paradise 11 10-12/1998
P0009163
(15+15) C+
BP in 20,0
1. g3 Sa6 2. Lg2 Tb8 3. Lc6+ bxc6 4. Sf3 Tb3 5. 0-0 Te3 6. dxe3 d5 7. Dd4 Lf5 8. Td1 e6 9. Td3 Dg5 10. Df6 d4 11. Ta3 d3 12. Se5 d2 13. f3 d1=T+ 14. Kf2 Td4 15. b3 Ta4 16. Lb2 Lb4 17. Ld4 Se7 18. Sc3 Kd8 19. Th1 Kc8 20. Ke1 Td8
play all play one stop play next play all
Weiß hat rochiert, wTh1 ist von a1. Schwarz hat nicht rochiert, sTd8 ist von h8.
more ...
comment
Keywords: Unique Proof Game, Castling Paradox (wk hidden sd fake)
Genre: Retro
Computer test: Natch 3.1 (2 min.)
Input: Gerd Wilts, 1999-2-27
Last update: Alfred Pfeiffer, 2018-12-19 more...
88 - P0009164
Satoshi Hashimoto
PR16 Problem Paradise 12 01-03/1999
1. Preis
P0009164
(13+14)
BP in 21,5
1. a4 Sc6 2. a5 Tb8 3. a6 bxa6 4. Ta4 Tb3 5. Th4 Tc3 6. dxc3 g5 7. Dd6 exd6 8. Le3 Df6 9. Sd2 Df3 10. exf3 g4 11. Ld3 g3 12. Se2 gxh2 13. Sg3 h5 14. Ke2 Lh6 15. Ta1 h1=T 16. Taa4 Ta1 17. Th1 Ta2 18. Ta1 Sd4+ 19. Ke1 Sb5 20. Tah4 c5 21. Th1 h4 22. Lf1
play all play one stop play next play all
Henrik Juel: Natch 3.1 made no progress after half an hour (2018-12-13)
comment
Keywords: Unique Proof Game, Pure Round Trip (TT)
Genre: Retro
Reprints: feenschach 153 10-12/2003
9 64 Proof Games 2012
Input: Gerd Wilts, 1999-2-27
Last update: Gerd Wilts, 2012-12-23 more...
89 - P0009165
Michel Caillaud
PR17 Problem Paradise 12 01-03/1999
3. ehrende Erwähnung
P0009165
(15+13)
BP in 22,5
1. f4 Sc6 2. f5 Tb8 3. f6 exf6 4. a4 Lb4 5. a5 Lc3 6. dxc3 De7 7. Le3 De5 8. Lxa7 b6 9. a6 Tb7 10. Lb8 Sge7 11. a7 Tg8 12. a8=L Ta7 13. Lb7 Ta8 14. h4 Sa7 15. Le4 d5 16. Lxh7 g6 17. h5 Tg7 18. h6 Dh5 19. Lg8 Lf5 20. h7 Sec8 21. h8=D Th7 22. Dg7 Th8 23. Dh7
play all play one stop play next play all
Rundlauf der sTT a8 und h8.
Henrik Juel: Natch 3.1 made no progress after half an hour (2018-12-13)
comment
Keywords: Unique Proof Game, Pure Round Trip (tt), Promotion
Genre: Retro
Input: Gerd Wilts, 1999-2-27
Last update: Gerd Wilts, 2005-12-30 more...
90 - P0500338
Claude Goumondy
2912 Die Schwalbe 59 10/1979
1. ehrende Erwähnung
P0500338
(3+5) C+
h#3
b) sBc4 nach f3
a) 1. Dc5 Td1 2. Te4 Ld2 3. Kd4 Lf4#
b) 1. Tf5 Lc1 2. Dg4 Td2 3. Kf4 Te2#
play all play one stop play next play all
Sally: Ein doppelwendiger weißer Grimshaw ist im hilfsmatt nicht neu,
wird aber hier in bestechender Ökonomie vorgeführt. (2019-1-15)
comment
Keywords: Grimshaw
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
Reprints: 2912 Die Schwalbe 72, p. 406, 12/1981
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2019-1-15 more...
91 - P0500354
Claude Goumondy
3187 Die Schwalbe 64, p. 104, 08/1980
3. ehrende Erwähnung
P0500354
(4+6) C+
h#2
b) wTf7 statt wLf7
c) sDd4 nach d5
d) wTf6 statt wLf6
a) 1. Kc3 Te5 2. Dd3 Tc5#
b) 1. Ke3 Le7 2. Ld3 Lg5#
c) 1. Kc4 Te6 2. Dd3 Tc6#
d) 1. Ke2 Le6 2. Ld3 Lg4#
play all play one stop play next play all
(KSp)
Sally: Selbstfesselung des sK auf vier Feldern, Entfesselung der beiden Blockfiguren durch gegenseitige Verstellung von T und LL. Obwohl sich die 2. schwarzen Züge wiederholen, ist die Ausführung imponierend. (2019-1-15)
comment
Keywords: Figurenspiel, Forsberg twin
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2019-1-16 more...
92 - P0500360
Claude Goumondy
3243 Die Schwalbe 65, p. 134, 10/1980
3. Lob
P0500360
(4+8) C+
h#2
b) sBe6 nach d2
c) wDg4 nach b1
d) wDg4 nach b7
a) 1. Kxe5 c3 2. Tf5 Dd4#
b) 1. Ke3 cxd3 2. Tf2 De4#
c) 1. Kc3 cxb3 2. Tb4 Db2#
d) 1. Kc5 c4 2. Td4 Db5#
play all play one stop play next play all
KSp Königsstern
BSp
Sally: Diesen mit einem Albino verbundenen sK - Stern ist ganz besonders reizvoll, weil immer derselbe Turm blockt. (2019-1-15)
comment
Keywords: Albino, Figurenspiel, king's star
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2019-1-15 more...
93 - P0500390
Claude Goumondy
3716 Die Schwalbe 72 12/1981
Lob
P0500390
(6+6) C+
h#2
b) Tausch sTd4<->sLd5
c) Tausch sLd5<->sSc1
d) wTd1->h4
a) 1. Kd6 Lxd4 2. Lc6 Le5#
b) 1. Ke6 Txd5 2. Lxf6 Te5#
c) 1. Kxf6 Txd4 2. Se7 Td6#
d) 1. Kf5 Lxd5 2. Ta4 Lf7#
play all play one stop play next play all
(KSp)
Sally: Fast vollkommende Harmonie der Lösungen, gute Materialökonomie
und angemessene Schwierigkeit Schade um die d) Variante:
Ta4 ist kein Selbstblock, und 2. - Lf7 kein Doppelschach. (2019-1-15)
more ...
comment
Keywords: Figurenspiel
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2019-1-16 more...
94 - P0505519
Wilhelm Kluxen
4067 Deutsche Schachblätter 15/04/1927
P0505519
(5+10) cooked
h#4
1. Ta1 Txa3 2. Lb1 Lc2 3. Lf4 Lxb3 4. Le4+ Ld1#
play all play one stop play next play all
Cook: NL
1. Lf5 Kg1 2. Ke4 Kxf2 3. Lf4 Lxf5#
Yuri Bilokin: Correction: 8/8/6B1/P2p4/RP1Pb3/pp3k2/qp3r2/1rb4K (6+10) (2019-1-19)
comment
Keywords: Clearance
Genre: h#
Input: hpr, 1996-12-27
Last update: Alfred Pfeiffer, 2019-1-20 more...
95 - P0505713
Talip Amirov
338 Land og Folk 15/03/1970
P0505713
(6+8) cooked
h#3
b) sLh4 nach g1
a) 1. Lxg5+ Lf4 2. Ld8 Lh6 3. Lc7 Lf8#
b) 1. Lxf2+ Kf4 2. Lb6 Le1 3. Lc7 Lb4#
play all play one stop play next play all
Cook: NL
a) 1. Lxa6 Lxh4 2. Sc4+ Kd3 3. Ke5 Lg3#
1. Lb7 Ta5 2. Se7 Txe5 3. Lc6 Td5#
b) 1. Lxf2+ Lxf2 2. Sf7 Lg1 3. Ke5 Lh2#
1. Lb7 Ta7 2. Se7 Kd4 3. Lc6 Lxe5#
LSp
Yuri Bilokin: Correction: 2b5/3p4/R1nkp3/1p1pp1P1/p3p2b/4KnB1/5P2/8 b) Bh4-g1 (5+12) (2019-1-7)
comment
Keywords: Figurenspiel
Genre: h#
Input: hpr, 1996-12-29
Last update: Alfred Pfeiffer, 2019-1-9 more...
96 - P0506750
Talip Amirov
434 Land og Folk 10/1971
P0506750
(6+12) cooked
h#2
2.1...
1) 1. b6+ Lc6 2. Ta7 Txa7#
2) 1. b5+ Tc6 2. Lc7 Lxc7#
play all play one stop play next play all
Cook: NL
1. Lh1 Td1 2. Db6 Ta1#
Korrekturmöglichkeit HJS Co+:wKa8, wTd6h7, wLd7h2, wBa2b3, sKa5, sTe6e7, sLe5g2, sSe3f6, sBb4b7c3
Yuri Bilokin: Correction: K7/1p1Br1R1/3Rrn2/k3b3/1p1p4/1Pp3B1/8/7b (6+10) (2019-1-7)
comment
Keywords: Clearance
Genre: h#
Input: hpr, 1997-1-22
Last update: Alfred Pfeiffer, 2019-1-9 more...
97 - P0509227
Talip Amirov
435 Land og Folk 10/01/1971
P0509227
(4+4) cooked
h#3
1. Kg5+ g4 2. Tf3 h4+ 3. Kh6 g5#
play all play one stop play next play all
Cook: NL
1. Lg6 Ld3 2. Th6 h4 3. Kh5 Le2#
Yuri Bilokin: Correction: wPg3-g2 (2019-1-7)
comment
Keywords: Check Protection
Genre: h#
Input: Markus Manhart, 1997-6-26
Last update: Alfred Pfeiffer, 2019-1-9 more...
98 - P0510541
Dragomir Rusin
Problem 41-44 03/1957
3. Preis
15. Thematurnier
P0510541
(3+14) cooked
h#4
0.1...
1. ... Txg7 2. Td3 Txg6 3. Sd4 Txg4 4. Sb3 Ta4#
play all play one stop play next play all
Cook: NL
1. ... Txg7 2. Ka1 Txf7 3. Sg3 Tf2 4. Dc8 Lxd4#
Yuri Bilokin: Correction: 4nrRB/2p2pbK/p3p1p1/5n2/3r2q1/5p2/k7/1b6 (3+14) (2019-1-19)
comment
Keywords: Check Protection, Whose move?
Genre: h#, Retro
Input: Markus Manhart, 1997-6-26
Last update: Alfred Pfeiffer, 2019-1-20 more...
99 - P0516138
Talip Amirov
3610v Problem 08/1974
P0516138
(6+7) cooked
h#3
1. Kd4 Tc6 2. De5 Sg7 3. De4 Sf5#
play all play one stop play next play all
Cook: NL
1. Dh6 Sg3 2. Dh4 Sf1 3. Db4 Tc6#
Verstellung SL
nefedov: Correction:+WPg3. (2005-7-19)
Yuri Bilokin: Correction: -wPa2, -bpa3, bpg5(-wPg5) (4+7) (2019-1-8)
comment
Keywords: Verstellung
Genre: h#
Input: Andreas Mokosch, 1997-7-25
Last update: Alfred Pfeiffer, 2019-1-8 more...
100 - P0517914
Franz Palatz
Tijdschrift van den NSB 07/1924
P0517914
(4+4) C+
h#4
1. Td6 La2 2. Sc6 b3 3. Kd5 Kd3 4. Te5 b4#
play all play one stop play next play all
Verstellung BcL
Sally: °
1. Tf6? - LI2??
Asymmetrischer Hilfsmatt-Inder mit feiner Begründung Zugreihenfolge. Aufspaltung des Bauerndoppelschrittes ind dreifachen Block om Mattbild. (2019-1-4)
comment
Keywords: Symmetrical position, Verstellung, Asymmetrical solution
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
Reprints: E8 ASymmetrie 2013
Input: Hans-Jürgen Schäfer, 1997-9-1
Last update: Alfred Pfeiffer, 2017-9-27 more...
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hpr (3)
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