Die Schwalbe

9215 problem(s) found in 1250 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20181210]

1 - P0000007
Andrej N. Kornilow
Andriy Frolkin
Dmitri W. Pronkin

5408 Die Schwalbe 97 02/1986
3. Preis
P0000007
(15+15)
BP in 33,0
1. Sc3 Sc6 2. Se4 Se5 3. c3 c6 4. Da4 Da5 5. b3 b6 6. La3 La6 7. Lc5 Lc4 8. Le3 Le6 9. Lh6 Lh3 10. gxh3 gxh6 11. h4 h5 12. Lh3 Lh6 13. Lf5 Lf4 14. Sh3 Sh6 15. Tg1 Tg8 16. Tg3 Tg6 17. Te3 Te6 18. f3 f6 19. Kf2 Kf7 20. Tg1 Tg8 21. Tg4 Tg5 22. Sg3 Sg6 23. Lb1 Lb8 24. Td4 Td5 25. Tdd3 Tdd6 26. Df4 Df5 27. Te4 Te5 28. Ke3 Ke6 29. Sf2 Sf7 30. Sg4 Sg5 31. Sh6 Sh3 32. Sg8 Sg1 33. Dh6 Dh3
play all play one stop play next play all
Henrik Juel: After a couple of hours Natch 3.1 had not even found the symmetrical solution (2018-12-07)
paul: This problem obtained 3rd Prize in the informal tourney, see Die Schwalbe 249/2011 (judge M. Caillaud) (2020-01-06)
comment
Keywords: Unique Proof Game, Symmetrical position
Genre: Retro
FEN: 1b4N1/p2pp2p/1pprkpnQ/4r2p/4R2P/1PPRKPNq/P2PP2P/1B4n1
Reprints: 581 Ukrainisches Album 1986-1990
111 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2020-05-21 more...
2 - P0000033
S. N. Ravishankar
5467v Die Schwalbe 98 04/1986
P0000033
(5+3) cooked
#1 vor 14
VRZ, Typ friedlich
R: 1. Tg1-f1 2. Tf2-f3 Te2- 3. Te1-g1 4. Te2-f2 Ta2- 5. Ta1-e1 Tb2-a2 6. Tb1-a1 Tc2-b2 7. Tc1-b1 Td2-c2 8. Tg1-c1 Tc2-d2 9. Td2-e2 Tb2-c2 10. Tc2-d2 Ta2-b2 11. Tb2-c2 g3-g2 12. Lg2-h3+, dann 1. Th1#
play all play one stop play next play all
Cook: Kurzlösung:
R: 1. Tg1-f1 droht 2. Tf1-f3, dann 1. Th1#
R: 1. Tg1-f1 Tf2-g2 2. Tf1-g1, dann 1. T3xf2#
(Mario Richter)
Mario Richter: So wie abgebildet, sollte die Problemno. nicht '5467v' sein.
Die Verbesserung (also das 'v') scheint erst später erschienen zu sein.
Das Diagramm ist kurzlösig durch: R: 1. Tg1-f1 (dr. 2. Tf1-f3, dann 1. Th1#) Tf2-g2 2. Tf1-g1, dann 1. Tf3xf2#. (2011-08-18)
Alfred Pfeiffer: Dies ist schon eine Veränderung des Originals. Wo die (in der LB bereits erwähnte) "Korrekturfassung" erschien, ist unklar. (2018-01-16)
S N Ravi Shankar: Given Version of the problem is incorrect. bRg2 should be on f2 and a bP should be placed on g2. Stipulation is -12 and #1.
Solution is
-1. Rg1! Rb2 (say) -2. Rf2 Re2! -3.Re1! Rb2 (say) -4. Re2! Ra2!(-4 ... Rd2? -5. Rg1! as in text)
-5. Ra1! Rb2 -6. Rb1 Rc2 -7. Rc1 Rd2 -8. Rg1! Rc2 -9. Rd2! Rb2 -10. Rc2 Ra1 -11. Rb2 g3 -12. Bg2
and now 1. Rh1# (2019-01-02)
comment
Keywords: Defensive Retractor, Type Pacific
Genre: Retro
FEN: 8/8/8/6P1/6pK/5R1B/6rk/5R2
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2018-01-17 more...
3 - P0000040
Wolfgang Dittmann
(VI) Schachkalender 1986
P0000040
(16+14)
BP in 10,5
Schlagschach
1. e4 Sc6 2. Ke2 Sa5 3. Kf3 Sf6 4. e5 Sh5 5. Kg4 d5 6. Kxh5 e6 7. Kg4 b6 8. Kf3 Sb7 9. Ke2 b5 10. Ke1 Sd6 11. exd6
play all play one stop play next play all
paul: This problem obtained 4th HM in the informal tourney, see Die Schwalbe 249/2011 (judge M. Caillaud) (2020-01-06)
more ...
comment
Keywords: Unique Proof Game, En passant, Promenade, Losing Chess
Genre: Retro, Fairies
Computer test: paul: C+ (Popeye 4.55) (2010-3-12)
FEN: r1bqkb1r/p1p2ppp/3Pp3/1p1p4/8/8/PPPP1PPP/RNBQKBNR
Reprints: 5532 Die Schwalbe 99 06/1986
62 Der Blick zurück 2006
(B1) Quartz 35 08/2010
Input: Gerd Wilts, 1995-06-03
Last update: Erich Bartel, 2013-08-17 more...
4 - P0000046
Wolfgang Dittmann
5589 Die Schwalbe 100 08/1986
P0000046
(13+13)
Auf welchem Feld wurde der schwarze Springer geschlagen?
Schlagschach
1. Sc3 Sc6 2. Se4 Se5 3. Sg3 Sg6 4. Sf3 Sf6 5. Sd4 h6 6. b3 Th7 7. Lb2 ... 8. Lc3 ... 9. Db1 ... 10. Kd1 ... 11. Kc1 ... 12. Kb2 ... 13. Ka3 ... 14. Kb4 ... 15. Kb5 Sd5 16. Se6 Sxc3 17. Sxf8 Sxb5 18. Sxh7 ... 19. Se4 ... 20. g3 ... 21. Lg2 ... 22. Lf3 Sd4 23. Shg5 Sxf3 24. Sxf3 Sf8 25. Dd1 Sh7 26. Sc3 Sf6 27. Sb1 Sg8 28. Sg1
play all play one stop play next play all
Der sS wurde auf f3 geschlagen.
paul: This problem obtained 5th HM in the informal tourney, see Die Schwalbe 249/2011 (judge M. Caillaud) (2020-01-06)
comment
Keywords: Losing Chess, Where was piece x captured? (s), Non-Unique Proof Game
Genre: Fairies, Retro
FEN: r1bqk1n1/ppppppp1/7p/8/8/1P4P1/P1PPPP1P/RN1Q2NR
Reprints: 64 Der Blick zurück 2006
(B3) Quartz 35 08/2010
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2014-06-03 more...
5 - P0000049
Wolfgang Dittmann
Klaus Wenda

5648v Die Schwalbe 101 10/1986
P0000049
(12+9)
#1 vor 3
VRZ, Typ Proca
Madrasi
1. Te4-a4? d4-d3 (nicht 1. ... 0-0-0? wegen 2. a4-a5/Lb8-a7!) und nun Zugzwang für Weiß. 2. b4-b5? oder f4-f5? verhindert schließlich den Vorwärts-ep-Schlag, da der Doppelschritt nicht mehr nachweisbar ist. 2. a4-a5!? gestattet die Verteidigung 2. ... Kb8-c8! (wonach 3. a5xLb6 erzwungen). 2. b4xLa5?? macht überraschend die Rücknahme 3. Kc7-d6 illegal wegen Retropatt (d7-d nicht mehr erlaubt, weil auch der wTf8 noch einen sEntschlagstein benötigt!). 2. f4xLe5? Lf6xSe5! und 2. f4xSe5? Sd7-e5 (2. f4xDe5? illegal). Lösung: 1. Tc4-a4! (droht z.B. nach 1. ... d4-d3 das Kurzmatt 2. b4xSc5 vor 1. Tc5#) 1. ... 0-0-0 2. Te4-c4 bel. 3. Kc7-d6 und vor 1. exd6ep# (1. Th6-h4? 0-0-0! 1. Tg,g,f-h4? e4xL,Sd3!, 2. ... 0-0-0)
play all play one stop play next play all
paul: This problem obtained 4th Comm in the informal tourney, see Die Schwalbe 249/2011 (judge M. Caillaud) (2020-01-06)
comment
Keywords: En passant in the retro play, Madrasi, Castling in the retro play, Defensive Retractor, Type Proca
Genre: Retro, Fairies
FEN: 2kr1Rrb/Bp3pPp/1P1K4/PPPpPP2/7R/3p4/4P3/8
Reprints: W174 Dreiklang 2001
163 Der Blick zurück 2006
5648vv Die Schwalbe 217 02/2006
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2012-07-08 more...
6 - P0000051
Andriy Frolkin
(U) Die Schwalbe 102 12/1986
P0000051
(15+13)
Vor mindestens 38 Einzelzügen mußte ep geschlagen werden!
R: 1. Sh3-g5+ a5-a4 2. Tb8-e8 a6-a5 3. Le8-f7 a7-a6 4. Lf7-g8 Lg8-h7 5. b7-b8=T Lh7-g8 6. b6-b7 Lg8-h7 7. b5-b6 Lh7-g8 8. b4-b5 Lg8-h7 9. b2-b4 Lh7-g8 10. Tb3-d3 Lg8-h7 11. Tb8-b3 Lh7-g8 12. b7-b8=T Lg8-h7 13. b6-b7 Lh7-g8 14. b5-b6 Lg8-h7 15. a4xBb5 Lh7-g8 16. Tg8-g7 b6-b5 17. Tf8-g8 Lg8-h7 18. a3-a4 h7-h6 19. a2-a3 Kh6-h5 20. h5xg6ep+ g7-g5 21. Sg5-h3+
play all play one stop play next play all
paul: This problem obtained a Special Prize in the informal tourney, see Die Schwalbe 249/2011 (judge M. Caillaud) (2020-01-06)
comment
Keywords: En passant, En passant in the retro play, Non-standard material, Promotion (TTL)
Genre: Retro
FEN: 4R1B1/3p1BRb/4P1Pp/3PRKNk/p2prB2/3RpqP1/4PprQ/6bn
Input: Gerd Wilts, 1995-06-03
Last update: Nikolai Beluhov, 2011-05-06 more...
7 - P0000052
Andriy Frolkin
(V) Die Schwalbe 102 12/1986
P0000052
(16+11)
Vor mindestens 72 Einzelzügen mußte ep geschlagen werden!
5 weiße Schlagfälle durch Bauern: axb, c3xd4, exf, f5xe6 & hxg; zwei Umwandlungen auf b8 und eine auf g8. Eine schwarze Umwandlung auf c1. Die weißen Figuren, die zur Entwandlung zurückschreiten können, sind die schwarzfeldrigen Lh8 und g5 sowie der retrofreie Sg1. Aber vor jeder Entwandlung muß Weiß das Feld h2 räumen, um dem Sg4 das Pendeln zu ermöglichen und so ein schwarzes Retropatt zu verhindern.
Retro: 1. Sg2-h4+ Sh4-g6+ 2. h7-h6 Se2-g1 3. a3-a2 Tg1-f1 4. a4-a3 Sf1-h2 5. Sh2-g4 Lh6-g5 6. Sg4-h2 Lg7-h6 7. Sh2-g4 Lf8-g7! 8. Sg4-h2 Ld6-f8 9. ~ Lb8-c6 10. ~ Sc3-e2 11. ~ Sb5-c3 12. ~ Sd6-b5 13. ~ Sf7-d6 14. ~ b7-b8=L 15. ~ b6-b7 16. ~ b5-b6 17. ~ b4-b5 18. ~ b3-b4 19. ~ Lg7-h8 20. ~ Lf8-g7 21. ~ Ld6-f8 22. ~ Lb8-d6 23. ~ b7-b8=L 24. ~ b6-b7 25. ~ b5-b6 26. ~ b4-b5 27. Sh2-g4 a3xb4
Nach diesem Entschlag des schwarzen Bb führt die dritte Entwandlung auf g8 zu einem erzwungenen En-passant-Schlag. 28. Sg4-h2 Sg5-f7 29. Kh6-h5 Th2-h3 30. Kh5-h6 Sh3-g5 31. b5-b4 Sg6-h4 32. b6-b5 Se7-g6 33. b7-b6 Sg8-e7! 34. a5-a4 g7-g8=S 35. a6-a5 g6-g7 36. Kh6-h5 h5xg6ep+ 37. g7-g5 Sg5-h3+ 38. a7-a6 Th3-h2 39. Sh2-g4 Dh4-f4 40. Sf4-g2+ g2-g3 41. Tg3-f3
Diese Zugfolge mit möglichen Zugumstellungen kann nicht verkürzt werden. Mindestens 71 Einzelzüge sind nach dem En-passant-Schlag geschehen. Rekord für eines der Themen des 173. Thematurniers der "Schwalbe".
play all play one stop play next play all
paul: This problem obtained first Prize in the informal tourney, see Die Schwalbe 249/2011 (judge M. Caillaud) (2020-01-06)
comment
Keywords: En passant, En passant in the retro play, Non-standard material, Promotion
Genre: Retro
FEN: 7B/8/4PPNp/4pKBk/3PrQnn/3pBrPR/p2P1p1N/4bRNB
Reprints: 568 Ukrainisches Album 1986-1990
H21 FIDE Album 1986-1988 1995
Input: Gerd Wilts, 1995-06-03
Last update: Nikolai Beluhov, 2011-05-06 more...
8 - P0000053
Frank Christiaans
5704v Die Schwalbe 102 12/1986
P0000053
(14+9)
#3
b) Lf1 nach e2
a) 1. T8xa7+ Kxc6 2. Td1 (0-0-0?) Txa7,Txf2,Txd7 3. d8=S,Tc7,Se5#
b) 1. T8xa7+ Kxc6 2. 0-0-0!
play all play one stop play next play all
klären: Forderung b) falsch. a+b unlösbar. Ist wLg1 gemeint? Auch dann unlösbar.(VF)
Anton Baumann: im Diagramm fehlt wLf1 !
aus Lösungsbesprechung: a) Versucht man die O-O-O zu erhalten, dann waren die letzten Züge: 1. … Ka6-b7 2.axb6ep+ b7-b5 3.c4-c5+ Kb5-a6 4.d3xc4+. Weiss muss jetzt noch viermal schlagen; unter den Schlagobjekten war der umgewandelte sBf, der sich nur auf e1 oder f1 - mit Rochadezerstörung - umwandeln konnte.
b) retro: 1. … Ka6-b7 2.axb6ep+ b7-b5 3.Ld1-e2+ Kb5-a6. Lösung: 1.T8xa7+ Kc6 2.O-O-O (2.Td1? Dxg1+) (2020-04-03)
Henrik Juel: wLf1 must be added in diagrem
The forward play in both twins is damaged by the triple threat 3.Se5,d8=S,Txa7 and the resulting mate duals
The main content is the analysis in part a showing that White may not castle (2020-04-03)
Henrik Juel: diagram, not diagrem, of course (2020-04-03)
comment
Keywords: Cant Castler, En passant, Castling (wl), Promotion in forward play
Genre: Retro
FEN: R1b5/pkrPp1p1/1PN5/2P5/6PP/5Nrp/1P4Pq/R3K1BQ
Input: Gerd Wilts, 1995-06-03
Last update: Rainer Staudte, 2019-08-11 more...
9 - P0000074
Leonid M. Borodatow
5887v Die Schwalbe 105 06/1987
P0000074
(14+12)
Löse die Stellung auf!
R: 1. Dh6xSh5 Tg2-g4 2. Lg4-f5 Tf4-f6 3. Lf5-g4 Sf1-h2 4. Lg4-f5 Sg3-f1 5. Lf5-g4 Th2-g2 6. Lg4-f5 Tf7-f4 7. Tf4-e4 Se4-g3 8. Tf5-f4 Sf4-h5 9. Lh5-g4 Sd5-f4 10. Tf6-f5
play all play one stop play next play all
Henrik Juel: I do not see how the stipulation can be fulfilled, but the retroplay is neat: -1.Qh6:S Rg2 -2.Bg4 Rf4 -3.Bf5 Sf1 -4.Bg4 fSg3 -5.Bf5 Rh2 -6.Bg4 Rf7 -7.Rf4 Se4 -8.Rf5 Sf4 -9.Bh5 Sd5 -10.Rf6 etc. bSd5 unpromotes on c1, later c3xd4 is retracted. (2003-08-18)
gw: The correct stipulation of this version is 'Release the position'. (2003-09-12)
Hans-Jürgen Manthey: mogliche Rückfuhrung:
R: 1. Dh6xh5+ Tg2-g4 2. Lg4-f5+ Tf4-f6 3. Lf5-g4 Sf1-h2 4. Lg4-f5 Sg3-f1 5. Lf5-g4 Th2-g2 6. Lg4-f5 Tf7-f4 7. Tf4-e4 Se4-g3+ 8. Tf5-f4 Sf4-h5 9. Lh5-g4+ Sd5-f4 10. Tf6-f5 Sb4-d5 11. Tf5-f6 Sa2-b4 12. Tf6-f5 Sc1-a2 13. Tf5-f6 c2-c1=S 14. Tf6-f5 c3-c2 15. Tf5-f6 c4-c3 16. c3xTd4 Td8-d4 17. Tf6-f5 Da7-e3 18. Tf5-f6 Sc5-e4 19. Ke4-e5 Sa6-c5+ 20. Tf6-f5 c5-c4 21. Tf5-f6 d4-d3 22. Kd3-e4 d5-d4 23. Tf6-f5 c7-c5 24. Tf5-f6 Tb8-d8 25. Tf6-f5 Tb1-b8 26. Tf5-f6 Sb8-a6 27. Tf6-f5 Lf4-g5 28. Tf5-f6 Le5-f4 29. De3-h6 Tf6-f7 30. Lg4-h5 Sf7-h8 31. Tf4-f5 sd6-f7 32. Ta4-f4 Tf4-f6 33. Th8-g8 Kg5-h4 34. Lg8-h7 h4-h3 35. Lh3-g4 b2-b1=T 36. Lf1-h3 b3-b2 37. Kc2-d3 b4-b3+ 38. g2xLf3 h5-h4 39. Lf7-g8 h7-h5 40. h6xDg7 Dg8-g7 41. Lg7-f8 Dd8-g8 42. Le8-f7 b5-b4 43. Tf8-h8 Tc4-f4 44. Dd3-e3+ Th3-h2 45. Tf4-f8 Tg3-h3 46. Th4-f4 Tg4-g3 47. Kd1-c2 Tf4-g4 48. Db1-d3 Tf8-f4 49. Th1-h4 Sf5-d6 50. Lc6-e8 d7-d5 51. La8-c6 Lb7-f3 52. Ta1-a4 Da2-a7 53. Ke1-d1 Lc8-b7 54. Dd1-b1 Db1-a2 55. c2-c3 b7-b5 56. h5-h6 Kf6-g5 57. Lh6-g7+ Kf7-f6 58. h4-h5 Ke8-f7 59. h2-h4 Lg7-e5 60. Lg5-h6 Th8-f8 61. Lf6-g5 Sh6-f5 62. a7-a8=L Sg8-h6 63. a6-a7 Lf8-g7 64. a5-a6 g7-g6 65. a4-a5 f7xSe6 66. a2-a4 b2-b1=D 67. Sg5-e6 b3-b2 68. Se4-g5 Ta4-c4 69. Sc3-e4 Ta8-a4 70. Sb1-c3 b4-b3 71. Lb2-f6 a5xb4 72. Lc1-b2 a7-a5 73. b2-b4 (2020-03-26)
comment
Keywords: Non-standard material, Promotion (l), Whose move?
Genre: Retro
FEN: 5BRn/4p1PB/4prp1/4KBbQ/3PR1rk/3pqP1p/3PPP1n/6N1
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2004-10-25 more...
10 - P0000075
Andriy Frolkin
Leonid Lyubashevsky

5888 Die Schwalbe 105 06/1987
2. Preis
P0000075
(16+11)
Löse die Stellung auf!
R: 1. Sd2xDf3 Dd5-f3 2. Sf3xSd2 Db3-d5 3. Ta3-a2 a7-a6 4. La2-b1 Sb1-d2 5. Sd2-f3+ De6-b3 6. Lb3-a2+ ... 7. Ta2-a3 ... 8. Ld5-b3 ... 9. b3xSa4 Sc5-a4 10. Ta4-a2 Sa6-c5 11. Ka2-a1 Sa3-b1 12. Tb1-b2 Sc4-a3 13. Ka1-a2 Se5-c4 14. Ta2-a4 ... 15. Tb2-a2 ... 16. Ka2-a1 ... 17. Ka3-a2 ... 18. Ka4-a3 ... 19. Ta2-b2 .. 20. Ta3-a2 Kb2-c3
play all play one stop play next play all
Henrik Juel: Solution: -1.Sd2:Q Qd5 -2.Sf3:S Qb3 -3.Ra3 a7 -4.Ba2 Sb1 -5.Sd2 Qe6 -6.Bb3 .. -7.Ra2 .. -8.Bd5 .. -9.b3:S Sc5 -10.Ra4 Sa6 -11.Ka2 Sa3 -12.Rb1 Sc4 -13.Ka1 Se5 -14.Ra2 .. -15.aRb2 .. -16.Ka2 .. -17.Ka3 .. -18.Ka4 .. -19.Ra2 .. -20.Ra3 Kb2 etc. Very nice puzzle. (2003-06-19)
Hans-Jürgen Manthey: mögliche Rückführung:
R: 1. Sd2xDf3 Dd5-f3 2. Sf3xSd2 Db3-d5 3. Ta3-a2 a7-a6 4. La2-b1 Sb1-d2+ 5. Sd2-f3+ De6-b3 6. Lb3-a2+ Df6-e6 7. Ta2-a3 De6-f6 8. Ld5-b3 Df6-e6 9. b3xSa4 Sc5-a4 10. Ta4-a2 Sa6-c5 11. Ka2-a1 Sa3-b1 12. Tb1-b2 Sc4-a3 13. Ka1-a2 Se5-c4 14. Ta2-a4 De6-f6 15. Tb2-a2 Df6-e6 16. Ka2-a1 De6-f6 17. Ka3-a2 Df6-e6 18. Ka4-a3 De6-f6 19. Ta2-b2 Df6-e6 20. Ta3-a2 Kb2-c3 21.Ta1-b1+ De6-f6 22. Le4-d5 Df6-e6 23. Sf3-d2 Td2-e2 24. Lh7-e4 Kc3-b2 25. Sd4-f3 Lf3-e1 26. Le2-f1 Lb7-f3 27. Dh1-e1 Td1-d2 28. Dh5-h1 Th1-d1 29. Sf3-d4 Th4-h1 30. Sd4-f3 Th1-c1 31. Sf3-d4 Th3-h1 32. Th1-a1 Dg7-f6 33. Ta1-a3 Tg4-h4 34. Sg1-f3 Dh8-g7 35. Lf1-e2 Tg8-g4 36. Dd1-h5 Kd4-c3 37. e2-e3+ Tg3-h3 38. Ka3-a4 Tb8-g8 39. Kb2-a3 Dd8-h8 40. Kc1-b2 Tg8-g3 41. Kd2-c1 Lc8-b7 42. Ke1-d2 b7-b6 43. Sb6-a8 Sg4-e5 44. Sc4-b6 Ke5-d4 45. Sd2-c4+ Kf6-e5 46. b2-b3 Kg7-f6 47. a3xLb4 Kf8-g7 48. a2-a3 Lc3-b4 49. Sb1-d2 Lg7-c3+ 50. Ld2-a5 Ke8-f8 51. Lc1-d2 Lf8-g7 52. d2-d3 Th8-g8 53. Lg8-h7 h7-h6 54. g7-g8=L Ta8-b8 55. h6xg7 Sb8-a6 56. h5-h6 Sf6-g4 57. h4-h5 Sg8-f6 58. h2-h4 (2020-03-27)
Henrik Juel: The pawn play hxPg-g8=L is obvious, but the fact that wPa4,b4 have cross-captured is not
wSf3 uncaptures sD and sS, which screen on b3 and b1 (2020-03-27)
comment
Keywords: Uncapture of pieces by pieces, Non-standard material, Promotion (L)
Genre: Retro
FEN: N7/2pppp2/pp5p/B7/PP6/2kPPN2/RRP1rPP1/KBrbQB2
Reprints: 563 Ukrainisches Album 1986-1990
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2004-10-25 more...
11 - P0000108
Andriy Frolkin
6272 Die Schwalbe 111 06/1988
1. Lob
P0000108
(30+0) C+
Färbe die Steine!
BP in 19,0
1. h4 d6 2. Th3 Sd7 3. Tb3 Sdf6 4. Tb6 axb6 5. f4 Ta3 6. Kf2 Th3 7. a4 Th1 8. Ta3 Lh3 9. Tg3 Dd7 10. Tg6 hxg6 11. a5 Th5 12. a6 Ta5 13. h5 Ta1 14. h6 Da4 15. h7 b5 16. h8=T Sh7 17. a7 f6 18. a8=T+ Kf7 19. Ta7 Dd4+
play all play one stop play next play all
Henrik Juel: C+ by Natch 3.1 (16 min.)
The colored position has black Ta1,h1 and Pb5,g6, and white Ta7,h8, otherwise 'natural' (2018-12-07)
François Labelle: Henrik, did you really test all 2^30 possible colorings with Natch, or did you use human deductions to reduce the possibilities (making this HC+), or did you only test the intended coloring (making this a partial C+)? (2018-12-09)
Mario Richter: I do not think that it is necessary to check all 2^30 colorings, since the color of the pawns on files c,d,e and f is completely determined. This and more restrictions on the set of potentially possible colorings may be derived from insights presented in an article "Aggregierte Schlagbilanz" by Frolkin & Kornilov, feenschach 130, p.411ff. Since the mechanisms presented there can at least partially be implemented in a little computer program, even a "full C+" label for this problem is not out of reach ... (2018-12-10)
Henrik Juel: I only tested the intended coloring, Francois,
so the C+ label is not justifiable
In the other coloring proof games I write something like
The colored position was C+ by Natch

Mario is right, of course, in that not all colorings need testing; but still the number is very large
This genre is somewhat messy; at first I thought that the solver could determine the coloring, but this is clearly not the case; also, the intention is not
'color the men such that a correct proof game in 19 results' (2018-12-11)
A.Buchanan: Henrik: so what exactly should the stipulation be for clarity? (2018-12-12)
comment
Keywords: Unique Proof Game, Coloring problem, under-promotion (TT), Phoenix
Genre: Retro
Computer test: Natch 3.1 (16 min.)
FEN: 5BNR/RPP1PKPN/3P1PP1/1P6/3Q1P2/7B/1PPPPKP1/RNBQ1BNR
Reprints: 158 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2018-12-07 more...
12 - P0000132
Nikita M. Plaksin
6578 Die Schwalbe 116 04/1989
2. ehrende Erwähnung
P0000132
(8+12)
Zeige, daß im Verlauf des Retrospiels zwingend die Möglichkeit zum ep-Schlag bestand!
Madrasi
paul: The stipulation in English: Show that, in the course of the retro game, the possibility for the en passant move existed! Madrasi (2019-01-13)
comment
Keywords: Madrasi, En passant
Genre: Retro, Fairies
FEN: 4n3/2p1pp2/3p1p2/2P2K2/2p5/p3PkR1/P2PrRr1/1b2B3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2012-07-08 more...
13 - P0000139
Leonid M. Borodatow
6685 Die Schwalbe 118 08/1989
P0000139
(15+10)
Löse die Stellung auf!
R: 1. Dh3-h6# Kf6-g6 2. Tg7-a7 Kg6-f6 3. Tc7-g7+ Kf6-g6 4. Tg7xBc7+ Kg6-f6 5. Td7-g7+ Kf6-g6 6. Tg7xBd7+ Kg6-f6 7. Te7-g7+ Kf6-g6 8. Tg7xBe7 Ke6-f6 9. Tf5-a5+ Kd6-e6 10. Lg5-f4+,Lh6-f4+ ...
play all play one stop play next play all
Nikolai Beluhov: Unplaying 1. Qh3# Kf6 2. Rg7+ Kg6 3. Rc7+ Kf6 4. Rg7:Pc7+ Kg6 5. Rd7+ Kf6 6. Rg7:Pd7+ Kg6 7. Re7+ Kf6 8. Rg7:Pe7+ Ke6 9. Rf5+ Kd6 10. B~f4+... seems to release the position. Three black pawns are uncaptured on their home squares. (2010-07-30)
Henrik Juel: Following Nikolai's retroplay the further resolution is easy:
White captured PaxPb, gxf, and hxg, and promoted on b8,b8,f8,f8,g8
Black captured fxSg and promoted on a1 (2019-09-09)
comment
Keywords: Non-standard material, Promotion in the retro play (LLLLT)
Genre: Retro
FEN: 1BB1RK1B/R6p/2P3kQ/R7/1N1P1BB1/4Brp1/4Prpn/5bbn
Reprints: RC/49 feenschach 192 03-04/2012
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-09-10 more...
14 - P0000143
Nikita M. Plaksin
6689 Die Schwalbe 118 08/1989
4. Lob
P0000143
(13+9)
Löse die Stellung auf!
Madrasi RI
R: 1. Se6xDd8 d2xTe1=L 2. Tb1-e1 c3xTd2 3. Tb8-b1 b4xTc3 4. b7-b8=T ... 5. a6xTb7,a6xSb7
play all play one stop play next play all
paul: If 4. -b5-b4 5.a6xBishop b7? Bc8-b7, then Black will be retro-stalemated. To unlock the position, the retro-play must be: Rf2 - Rg8 - g7-g8=R - Ph6xRg7 - Ph5 -Pg4xSh5(bSg3-h5), Rh1 - Rg8 - g7-g8=R - Ph6xRg7 - Ph5, Sh3-g5, Pg7-g5, Kg6-f7, Pf4-f5+, bBf8 was captured at home. (2019-01-13)
comment
Keywords: Madrasi (Rex inklusive)
Genre: Retro, Fairies
FEN: 3NQK2/p1pppk1p/2B2p2/B4Pp1/5N2/3PP3/P1P2R2/4b2R
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-02-06 more...
15 - P0000169
Leonid M. Borodatow
6988 Die Schwalbe 123 06/1990
4. ehrende Erwähnung
P0000169
(11+8)
#3
b) ohne Bauern
a) 1. Dg2! droht 2. h7 ... 3. h8=D#
1. ... Sd2 2. Kxd2
1. ... Sa3 2. Txa3
1. ... Kxh6? 2. Dg6#
b) 1. Dg8! droht 2. Ta7 ... 3. Th7#
1. ... Sd2 2. Kxd2
1. ... Sa3 2. 0-0-0!
1. Dg2? Kh6!
play all play one stop play next play all
In a) darf Weiß nicht mehr rochieren, da sich der sBa7 auf a1 umgewandelt haben muß.
Henrik Juel: A couple of errors in a):
1... Kxh6? 2.Dg6#, not 2.Ta8? Kh7!
[Pa7] promoted on a1, not [Ph7] on h1 (actually Black captured hxg with promotion on g1) (2019-09-09)
comment
Keywords: Cant Castler, Promotion, Castling
Genre: Retro
FEN: 8/1Ppp4/1Ppp1p1P/1PP1pP1k/1P2P3/8/Q7/Rn2K3
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-09-10 more...
16 - P0000236
Karlheinz Bachmann
7437 Die Schwalbe 130 08/1991
P0000236
(3+1) cooked
BP in 16,0
Zeroposition
a) Kf8 nach g8
b) Lg5 nach g2
a) 1. Sf3 e5 2. Sxe5 Df6 3. Sxd7 Dxb2 4. Sxf8 Dxb1 5. Sxh7 Txh7 6. Txb1 Txh2 7. Txb7 Txg2 8. Txa7 Txf2 9. Txc7 Txf1+ 10. Txf1 Txa2 11. Tfxf7 Txc2 12. Txc8+ Kxf7 13. Txb8 Txd2 14. Txg8 Txd1+ 15. Kxd1 g5 16. Lxg5 Kxg8
b) 1. Sc3 d5 2. Sxd5 Dd6 3. Sxe7 Dxh2 4. Sxc8 Dxg1 5. Sxa7 Txa7 6. Txh7 Txa2 7. Txh8 Txa1 8. Txg8 Txc1 9. Txg7 Txc2 10. Txf7 Txb2 11. Txc7 Txd2 12. Txb7 Txd1+ 13. Kxd1 Dxf2 14. Txb8+ Ke7 15. Txf8 Dxg2 16. Lxg2 Kxf8
play all play one stop play next play all
Cook: NL
b) 1. Sb1-c3 b7-b5 2. Sc3xb5 c7-c6 3. Sb5xa7 Dd8-c7 4. Sa7xc8 Ta8xa2 5. Sc8xe7 Ta2xa1 6. Se7xc6 Ta1xc1 7. Sc6xb8 Tc1xc2 8. Sb8xd7 Dc7xh2 9. Sd7xf8 Dh2xg1 10. Th1xh7 Tc2xb2 11. Th7xh8 Tb2xd2 12. Th8xg8 Td2xd1+ 13. Ke1xd1 Dg1xf2 14. Tg8xg7 Df2xg2 15. Tg7xf7 Ke8xf7 16. Lf1xg2 Kf7xf8 (Mario Richter)
paul: a) is Jacobi+ (2019-02-23)
more ...
comment
Keywords: Unique Proof Game, Massacre PG, Rex solus (s)
Genre: Retro
FEN: 5k2/8/8/6B1/8/8/4P3/3K4
Reprints: 119 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2017-04-25 more...
17 - P0000285
Unto Heinonen
7941v Die Schwalbe 138 12/1992
2. Preis
P0000285
(13+14) C+
BP in 19,5
1. Sa3 Sf6 2. Sc4 Se4 3. Sa5 Sxd2 4. Kxd2 f5 5. Kc3 f4 6. Kb4 f3 7. Lf4 fxg2 8. Ld6 cxd6 9. Lxg2 Dc7 10. Ld5 Dc6 11. Sf3 Da6 12. Tg1 Dd3 13. Tg6 Df5 14. Th6 Dg6 15. Dg1 Dd3 16. Td1 Da6 17. Td3 Dc6 18. Ta3 Dc7 19. c3 Dd8 20. Dg6+
play all play one stop play next play all
"11 sDD-Züge - fantastisch" (TC) "Weltrekord" (BG) "nicht allzu schwer, aber raffiniert ausgeklügelt" (AG) "Schwierigkeit ist ja kein Wertkriterium und umso reizvoller ist dann das Suchen nach den (echt weiblichen!) verschlungenen Wegen, auf denen die D sich ihren Zeitgewinn erschleicht" (HHS) "eine respektable Leistung" (MS) 3,5/III/9L.
paul: bQ circuit. (2020-01-13)
comment
Keywords: Unique Proof Game, Loss of tempo (d11)
Genre: Retro
Computer test: Natch 2.2 Copyright (C) 1997,98,99,2001,2002,2003 Pascal Wassong
FEN: rnbqkb1r/pp1pp1pp/3p2QR/N2B4/1K6/R1P2N2/PP2PP1P/8
Reprints: Pat a Mat 19 04/1994
3385 U.S. Problem Bulletin 102/103 07-10/1995
feenschach 137 08-09/2000
H27 FIDE Album 1992-1994 2001
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2005-06-28 more...
18 - P0000286
Unto Heinonen
7942v Die Schwalbe 138 12/1992
3. Preis
P0000286
(13+14)
BP in 24,5
1. d4 Sc6 2. d5 Sd4 3. h4 Sxe2 4. Th3 Sc3 5. La6 h5 6. Td3 Th6 7. Le3 Tb6 8. Sd2 Tb3 9. cxb3 Sa4 10. bxa4 bxa6 11. Db3 Lb7 12. 0-0-0 Lc6 13. Db8 Lb5 14. b4 Lc4 15. Kb2 Lb3 16. Tc1 Ld1 17. Tc4 Lc2 18. Tg4 hxg4 19. h5 Lb3 20. h6 Lc4 21. h7 Lb5 22. h8=S Lc6 23. Sg6 Lb7 24. Sf4 Lc8 25. Se2
play all play one stop play next play all
"nochmal fantastisch" (TC) "Weltrekord" (BG) "hier sind es sogar 13 Züge, die der sL benötigt um eine Tempo zu verlieren, wobei das weiße Spiel mit äußerster Präzision angelegt sein muß, um Zugumstellungen zu vermeiden" (MS) "wenn die Bändigung der D auch schwerer zu bewerkstelligen ist und entsprechend mehr Respekt verdient, so hat diese L-Darstellung doch mehr Finessen, eine interessanteres Spiel beider Parteien mit mehr Alternativen. Und dann gefällt mir 'optisch' die Db8, die sekundenlang suggeriert, sie könne den sS geschlagen haben und die zur Unzeit dorthin ziehen muß und alle Hoffnung auf Tempoverlustmanöver von sD und sT zunichte macht" (HHS) "Zwei Superstücke mit 11 D- bzw. 13 L-Tempozügen!" (CP) "Wäre es nicht redaktionell klüger gewesen, die beiden Stück nicht nebeneinander zu stellen?" (HHS) Die Überlegung brauchte ich aufgrund meiner mageren Retrovorräte nicht anzustellen ... 4/III-IV/8=L.
paul: bB circuit. (2020-01-13)
comment
Keywords: Unique Proof Game, Non-standard material, Castling, Loss of tempo (l13), Promotion (S)
Genre: Retro
FEN: rQbqkbn1/p1ppppp1/p7/3P4/PP4p1/3RB3/PK1NNPP1/6N1
Reprints: Pat a Mat 19 04/1994
3386 U.S. Problem Bulletin 102/103 07-10/1995
feenschach 137 08-09/2000
H30 FIDE Album 1992-1994 2001
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2005-12-27 more...
19 - P0000301
Frank Christiaans
8066 Die Schwalbe 140 04/1993
P0000301
(12+3)
Problem ohne Worte
1. Kb2#
play all play one stop play next play all
Henrik Juel: Black has the move, because a retroplay like
-1... Kb2xTb1? -2.Tc1 Tb1 -3.f2?? prevents the black king from exiting
-1... b2xLSa1=T? -2.f2?? is even worse
Black to move has one possibility only, 1... Kb2#
The position is legal, e.g.,
-1.b2xPa3 b4xDa3 -2.Da4 a3 -3.Da5 Ta2 -4.Da4 Ka1 -5.Kc1 b5 -6.Ld1 etc.
allowing sK to exit via d2 and e3 later (2020-01-17)
comment
Keywords: Next move? (K-#), Non-standard material, Type A, Ending move?
Genre: Retro
FEN: 8/8/8/8/8/PPPP1P2/p1PRB1P1/rk1KNB2
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-01-17 more...
20 - P0000307
Thomas Volet
8130 Die Schwalbe 141 06/1993
P0000307
(12+14)
Ist die Stellung legal?
Die kürzeste Zugfolge bis zum letzten B-Zug sieht prinzipiell so aus ('...' = Wartezug):
R: 1. Ta8-b8 Kd1-c1 2. Kb8-c8 Ke2-d1 3. Lf8-g7 Lg7-h6 4. Lg8-h7 ... 5. Tb1-b2 ... 6. Th1-b1 ... 7. Th7-h1 Lh6-g7 8. Tg7-h7 ... 9. Lh7-g8 ... 10. Tg8-g7 ... 11. Lg7-f8 ... 12. Tc8-g8 ... 13. Lg8-h7 Td8-d7 14. Lh7-g8 Tg8-d8 15. Lf8-g7 Tg7-g8 16. Lg8-h7 Th7-g7 17. Te8-c8 Lg7-h6 18. Kc8-b8 Th1-h7 19. Lh7-g8 Lh6-g7 20. Lg7-f8 Tg1-h1 21. Tg8-e8 Tg4-g1 22. Lf8-g7 ... 23. Tg7-g8 24. Lg8-h7 25. Th7-g7 Lg7-h6 26. Th1-h7 Lh6-g7 27. Kd7-c8 ... 28. Lh7-g8 ... 29. Lg7-f8 ... 30. Tg8-a8 ... 31. Lf8-g7 ... 32. Tg7-g8 ... 33. Lg8-h7 ... 34. Th7-g7 Lg7-h6 35. Th3-h7 Th4-g4 36. ... Th7-h4 37. ... Lh6-g7 38. ... Tg7-h7 39. Lh7-g8 Tg8-g7 40. Lg7-f8 Ta8-g8 41. Lf8-g7 Lg7-h6 42. Lg8-h7 ... 43. Th7-h3 Lh6-g7 44. Tg7-h7 Ld3-c2 45. Lh7-g8 ... 46. Tg8-g7 ... 47. Lg7-f8 ... 48. Td8-g8 ... 49. Ke8-d7 ... 50. Kf8-e8 Lb5-d3 51. ... Ld7-b5 52. ... Lc8-d7 53. ... d7-d6!
play all play one stop play next play all
"Nach 'unserer' Ausdrucksweise ist die Stellung also illegal, weil nur unter Außer-acht-Lassung der 50-Züge-Regel erspielbar." (HHS)
"Schöne Rangierarbeit mit guter Ausnutzung der LL-Schleuse" (DB).
Auf derartige Forderungsfragen erwartet man ja i.a. ein JA als Antwort und so wäre eine Verkürzung der Zügezahl auf genau 50 Züge bis zum letzten B-Zug angebracht (und auch leicht zu bewerkstelligen). So vermutet jeder einen besonderen - aber nicht vorhandenen - Trick des Autors, um die 50-Züge-Beschränkung nicht zu überschreiten. Mehrere Löser kamen beim Rangieren offensichtlich so ins Schwitzen, daß sie gar nicht an die 50-Züge-Regel gedacht haben und so fälschlicherweise 'Legalität' behauptet haben! Ebenso falsch lagen einige Löser, die 'Illegalität' attestierten mit der Begründung sSh8 oder sLh6 seien nicht zu realisieren. 3/III und 5L., welche die Stellung aufgedröselt haben (von denen kam nur HHS zu der Erkenntnis: illegal!).
Brassaud: Je suis d’accord avec la solution proposée jusqu’à 53) Wartezug, d7-d6 et la partie est considérée comme nulle.
La position intermédiaire obtenue après 53) … , d7-d6 est la suivante :
T1ft1R1c/pppp/PPFF/4PtPf/3pppp1/8/1P6/P2pr3/7T
Cette position est-elle légale ? Je ne le crois pas. Les pions noirs ont pris 4 fois. Le pion h2 a donc été promu. Cette promotion peut être encore sur l’échiquier sous forme de T ou de F, ou bien a été prise mais c’est sans réelle importance. Pour dénouer cette position il faut d’abord reprendre d6xCe7 puis c5xDd6 afin de ramener ce pion en c2. A ce moment la tour blanche et les 2 fous de cases noires peuvent sortir mais le FB de g8 et le roi blanc sont encore dans la cage. Le pion de c2 a effectué les 2 seules prises de pièces noires. Les autres PB venus de e2,f2, g2 n’ont pas fait de prise et le pion de h2 a été promu en h8 sans prise. Il faut ensuite reprendre d6-d5 et e7xd6 (pièce quelconque)puis reprendre la promotion du pion en h8. Mais là je ne vois pas comment en raison du cavalier bloqué par les 2 pions blancs de f7 et g6. Le retour d’une pièce promue (dame ou tour ou même le fou de g7) en h8 ne peut se faire, donc on ne peut reprendre le retour de h7-h8 puis h6-h7 et h5-6 ni bien entendu reprendre h6xg5 pour tout dénouer.
Ainsi je pense que le problème en lui-même est illégal avant même de faire intervenir la règle des 50 coups. Pouvez-vous me dire si quelque chose m’aurait échappé ? (2015-09-11)
Thierry LE GLEUHER: Sorry but the position is legal. The retro play can continue with d6-d5 and d5xXe6, and unlock the rest is easy. (2015-09-13)
Brassaud: Merci pour votre aide. (2015-09-17)
Thomas Volet: TV: The composition's only point is the extension of the retroplay by the interaction of the 3 Bs.
I do not accept anyone's "codex" that purports to alter the rules of chess by making the draw automatic or that imports castling. Under the chess rules, a draw is at the option of the moving player whenever the sequence of non-P, non-capturing moves is sufficiently long (and has nothing to do with castling).
If interested in positions that involve the 50-move rule, please see P0008399 (75-move sequence with several rook circuits), P1202286 (where the "codex" automatic draw rule presents the situation in which either player on the move can make a move that is simultaneously a draw and a checkmate), or P1331867 (move preceding the sequence must have been a capture of a non-P by a non-P). (2019-01-02)
comment
Keywords: 50 move rule
Genre: Retro
FEN: 1RK4n/ppprPPBB/3pPrPb/3pppp1/8/1P6/PRbP4/2k5
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2015-09-17 more...
21 - P0000391
Nikita M. Plaksin
Alexandr I. Zolotarev

8550 Die Schwalbe 147 06/1994
P0000391
(14+13)
Löse die Stellung auf!
Henrik Juel: -1.Bg8 h5 -2.B=g7 h6 -3.f6:Q h7 -4.f5 Qa1 -5.f4 Qb1 -6.b4 Q=b2 -7.b3 c3:S -8.Sa4 c4 -9.Sb6:P c5 -10.Sd7 c6 -11.Sf6 c7 -12.Sg8 a5 -13.S=g7 a6 -14.h6:Q Qa1 -15.h5 Qb1 -16.h4 Ka1 -17.a2 a7 -18.Qa3 etc. Good activity on b1 and g8. (2003-12-10)
Hans-Jürgen Manthey: eine mögliche Rückführung mit dem schwer lesbaren Anfang von Henrik Juel:
1. Lg8-h7 h5-h4 2. g7-g8=L h6-h5 3. f6xDg7 h7-h6 4. f5-f6 Da1-g7 5. f4-f5 Db1-a1 6. b4-b5 b2-b1=D 7. b3-b4 c3xSb2 8. Sa4-b2 c4-c3 9. Sb6xa4 c5-c4 10. Sd7-b6 c6-c5 11. Sf6-d7 c7-c6 12. Sg8-f6 a5-a4 13. g7-g8=S a6-a5 14. h6xDg7 Da1-g7 15. h5-h6 Db1-a1 16. h4-h5 Ka1-a2 17. a2-a3 a7-a6 18. Da3-c1 Dc1-b1 19. Dd6-a3 Kb2-a1 20. Da6-d6 Db1-c1 21. Tc1-d1 Kc3-b2 22. Td1-c1 Db2-b1 23. Tb1-d1 Da3-b2 24. Ta1-b1 Dc5-a3 25. Tb1-a1 Kb4-c3 26. Ta1-b1 Td1-d2 27. d2-d3 Td3-e3 28. Tb1-a1 Td8-d3 29. Ta1-b1 e3-e2 20. Tb1-a1 d4xLe3 31. Ta1-b1 d5-d4 32. Ld4-e3 Db6-c5 33. Lb2-d4 Sd3-e1 34. Lc1-b2 Se5-d3 35. Tb1-a1 Te1-d1 36. Df1-a6 Te3-e1 37. Dd1-f1 Tc3-e3 38. b2-b3 Tg8-d8 39. Ta1-b1 Kc5-b4 40. Tb1-a1 Kd6-c5 41. Ta1-b1 Kd7-d6 42. Tb1-a1 Ke8-d7 43. Ta1-b1 Tc6-c3 44. Se2-g1 Td6-c6 45. Sc3-e2 Td8-d6 46. e2-e4 Ta8-d8 47. Tb1-a1 Dd6-b6 48. Ta1-b1 Lg1-h2 49. Tb1-a1 Le5-g1 50. Ta1-b1 Sc6-e5 51. Sb1-c3 Lg7-e5 52. Kg1-h1 Se3-g2 53. Lf1-h3 Sf5-e3 54. Th3-g3 Sh6-f5 55. g2-g4 Lg4-f3 56. Th1-h3 Lc8-g4 57. h2-h4 Lf8-g7 58. Kf2-g1 g7-g6 59. Sg6-h8 Th8-g8 60. Sh4-g6 Sg8-h6 61. Sf3-h4 Sb8-c6 62. Sg1-f3 Dd8-d6 63. Ke1-f2 d7-d5 64. f2-f4 (2020-03-28)
Henrik Juel: Yes Hans-Jürgen, I know that my old retroplays may be difficult to read, because they use english names for the men and my own very abbreviated notation
Now I use german names (except for pawns, because B can be both Bauer and Bishop); and my abbreviated notation now only applies to plain movements, not captures or promotions (2020-03-28)
comment

Genre: Retro
FEN: 7N/1p2pp1B/6p1/1P6/4P1Pp/P2PrbRB/k1Prp1nb/2QRn1NK
Input: Gerd Wilts, 1995-06-03
Last update: Nikolai Beluhov, 2010-07-23 more...
22 - P0000401
Andriy Frolkin
Anatolii Vasylenko

4296 Die Schwalbe 80 04/1983
P0000401
(9+12)
h#3* (AP)
1. ... dxc6ep 2. 0-0 h5 3. Kf7 Sxd6#
1. 0-0 Se5 2. Kh8 Lc2 3. Tg8 Sf7#
play all play one stop play next play all
Henrik Juel: If Black may castle, White captured fxPg and g7xBf8=B. 1.dxc6ep 00! 2.h5 Kf7 3.Sxd6#; 0... 00 1.Se5 Kh8 2.Bc2 Rg8 3.Sf7#. (2003-11-07)
Hans-Jürgen Manthey: Rochade ist noch möglich, Rückfuhrungen nach den Mattstellungen:
R: 1. Se5-f7# Tf8-g8 2. Lb3-c2 Kg8-h8 3. Sc4-e5 o-o 4. Kb5-b4 c7-c5+ 5. Se3-c4 Da6-a7 6. Sf5-e3 Df1-a6 oder
1. Sc4xd6# Kg8-f7 2. h4-h5 o-o 3. d5xc6ep c7-c5 4. Kb4-b5 Da6-a7 5. Se3-c4 Dd3-a6 6. Sf5-e3 Df1-d3
und weiter...
7. Sh6-f5 Da6-f1 8. Sg8xh6 Df1-a6 9. g7-g8=S Da6-f1 10. g6-g7 Df1-a6 11. Lg7-c3 Da6-f1 12. Lf8-g7 Df1-a6 13. g5-g6 Da6-f1 14. e4xLd5 a7xSb6 15. Sa4-b6 Df1-a6 16. Sc3-a4 Da6-f1 17. Sb1-c3 Df1-a6 18. Lc4-b3 Dc1-f1 19. Kc3-b4 Dh1xLc1+ 20. Lf1-c4 b3xTa2 21. Kd3-c3 Le6-d5 22. Ta1-a2 Sb6-c8 23. a2-a3 Lc8-e6 24. Ke2-d3 c4xDb3 25. Dd1-b3 d5xc4 Ke1-e2 e6xTd5 26. c2-c4 f7xSe6 27. Sf4-e6 Dh3-h1 28. Td3-d5 Dd7-h3 29. Th3-d3 Dd8-d7 30. Th1-h3 Sd5-b6 31. Se2-f4 Sf6-d5 32. Sg1-e2 Sg8-f6 33. e2-e4 d7-d6 34. h2-h4 Sb6-a8 35. g4-g5 Ta8-b8 36. g2-g4 Sd5-b6 37. g7xLf8=L Sb4-d5 38. f6xg7 Sa6-b4 39. f5-f6 Sb8-a6 40. f4-f5 h7-h6 41. f2-f4 (2020-03-29)
Henrik Juel: Here is a detailed analysis
Black captured [Lc1] with an officer, a7xb6, and f7xe6xd5xPc4xb3xb2
To enable black castling White captured exLd, fxPg, g7xLc8=L, and [Ph7] with an officer, and also promoted on g8
With White to move, last move was c7-c5, provided Black never moved Ke8 and Th8, so he must justify the en passant capture a posteriori by castling
1... dxc6 2.Kf7 h5 3.Tf8 Sxd6 is not a solution in 2.5 moves
CH+ by Popeye 4.61 and Henrik's analysis... (2020-03-29)
comment
Keywords: a posteriori (AP), En passant, Castling (sk)
Genre: h#, Retro
FEN: nrn1k2r/qp2p3/1p1p4/1KpP4/2N4P/PBB5/pP1P4/8
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2005-10-08 more...
23 - P0000407
Günter Glaß
4360 Die Schwalbe 81 06/1983
5. Lob
P0000407
(7+9)
Weiß nimmt 1 Zug zurück, so daß Weiß und Schwarz #1
Circe
Duplex
w) R: 1. Kh6xBg5[+sBg7], dann Sf7#
bzw. R: 1. Kh6xBg5[+sBg7], dann 1. Lb5#

s) R: 1. ... Kd3xBc4[+wBc2], dann 1. ... Dgd4#
bzw. R: 1. ... Kd3xBc4[+wBc2], dann 1. Dbg2#
play all play one stop play next play all
HBae: R: 1. ... Kh6xBg5[+sBg7], dann 1. Lb5# bzw. 1. Sf7#
R: 1. ... Kd3xBc4[+wBc2], dann 1. Dgd4# bzw. 1. Dbg2# (2019-02-04)
comment
Keywords: Circe, Help retractor
Genre: Retro, Fairies
FEN: 4B2B/6p1/1r1n2b1/3n2K1/1pk4P/5p2/1qP4R/6Q1
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-02-04 more...
24 - P0000434
Hans Gruber
4700 Die Schwalbe 86 04/1984
2.-3. Lob e.a.
P0000434
(1+1)
Ergänze einen sS und 2 sBB zu einem IC!
Längstzüger
(+sBf7,sBg6,sSh8)
play all play one stop play next play all
Nicht +sSh1, sBf2, sBg3

Duplicate Diagram: P1187718, P1347424

Henrik Juel: The solution position is illegal, because Sh8-g6 is longer than g7-g6 and h7xg6, so these pawn moves could not happen
The try position is legal with a promoted Sh1 (2019-02-14)
comment
Keywords: Illegal cluster, Maximummer, only Kings
Genre: Retro, Fairies
FEN: k7/8/8/8/8/8/8/K7
Reprints: 110 Die Schwalbe 244, p. 582, 08/2010
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-02-15 more...
25 - P0000456
Hendrik Prins
5027 Die Schwalbe 91 02/1985
P0000456
(11+6)
Welches war der letzter Zug?
b) sLh1 statt Sg1
a) R: 1. f2xSg1=S+
b) R: 1. g2xDf1=D+
play all play one stop play next play all
Henrik Juel: The twinning is not very nice, but clear enough, I think:
remove Sg1 and add sLh1 (another double check) (2019-10-05)
more ...
comment
Keywords: Last Move? (BxS=S), Type C, Last Move? (BxD=D), Promotion in the retro play
Genre: Retro
FEN: 8/8/8/5P2/4PPn1/3pRKp1/PPPPP2k/2B2qn1
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-10-15 more...
26 - P0000530
Leonid M. Borodatow
3328 Die Schwalbe 66 12/1980
P0000530
(13+9)
Löse die Stellung auf!
Henrik Juel: -1.Bd1:Q Qd2 -2.Bc2-b1 Qg5 -3.Rg8 Rh8 -4.R=h7:Q Qc5 -5.g6:Q etc. The 3 uncaptured bQ's unpromote on c1, a wB unpromotes on g8. (2003-08-18)
Hans-Jürgen Manthey: mögliche Rückführung:
R: 1.Ld1xDc2+ Dd2-c2 2. Lc2-b1+ Dg5-d2 3. Sf4-h3 Lh3-f1 4. Kf3-e4 Sg3-h1 5. Dh1-d1 Lc8-h3 6. Dh4-h1 Dc5-g5 7. Se6-f4 Sf5-g3 8. Db4-h4 Kd2-c1 9. Lb1-c2 Ke1-d2 10. Da5-b4 Kf1-e1 11. Tc1-c3 Kg1-f1 12. Lc2-b1 Kh2-g1 13. Ta1-c1 Kh3-h2 14. Lb1-c2 Kh4-h3 15. Tg8-h8 Th8-h7 16.Sf4-e6 Kg5-h4 17. Kg2-f3 Kf6-g5 18. Sh3-f4 Dc1-c5 19. Sg1-h3 c2-c1=D 20. h7xDg8=T c3-c2 21. g6xDh7 c4-c3 22. Kf1-g2 Ke6-f6 23. h5xTg6 Kd7-e6 24. Dd2-h5 Ta6-g6 25. De1-d2 c5-c4 26. h4-h5 d6xLc5 27. Le3-c5 Sd4-f5 28. Lf4-e3 Df5-h7 29. Le3-f4 Dc5-f5 30. Lf4-e3 Dc1-c5 31. Le3-f4 c2-c1=D 32. Lf4-e3 c3-c2 33. Le3-f4 c4-c3 34. Lf4-e3 b5xSc4 35. Sa3-c4 Dh7-g8 36. Le3-f4 Df5-h7 37. Lf4-e3 Dc5-f5 38. Le3-f4 Dc1-c5 39. Lf4-e3 c2-c1=D 40.Lc1-f4 c3-c2 41. d2-d3 c4-c3 42. Lc2-d1 Ta8-a6 43. Lh7-c2 Sc6-d4 44. Lg8-h7 Sb8-c6 45. h7xSg8=L Ke8-d7 46. g6xDh7 b7-b5 47. g5-g6 Dg6-h7 48. Le4-b1 h7-h6 49. c2xb3 a4xTb3 50. Th3-b3 a5-a4 51. Dd1-e1 d7-d6 52. Ke1-f1 c5-c4 53. Sb1-a3 a6-a5 54. Lg2-e4 a7-a6 55. Lf1-g2 Db6-g6 56. g4-g5 c6-c5 57. g2-g4 Dd8-b6 58. Th1-h3 c7-c6 59. h2-h4 (2020-03-29)
comment

Genre: Retro
FEN: 5b1R/4pppr/7p/8/4K3/1PRP3N/PPB1PP2/1Bk1Qb1n
Input: Gerd Wilts, 1995-06-03
27 - P0000540
Bernd Schwarzkopf
3397 Die Schwalbe 67 02/1981
P0000540
(12+16)
Woher kamen die wTT a1 und h1?
R: 1. Th3-h1 a6-a5 2. Tf3-h3 Kg5-h6 3. h3-h4+
play all play one stop play next play all
Der wTa1 kommt von h1, der wTh1 von a1.
Henrik Juel: Following the initial retroplay, Th1 cannot get back behind the white pawns before Ta1 has retracted to the right, wLa7 to c1, and b2-b3 (2020-01-27)
comment
Keywords: Non-standard material, Interchange, Which are original men?
Genre: Retro
FEN: nqb1Kbqn/Brp2prb/1p4pk/p6p/P6P/1P2P3/2PP1PP1/R6R
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2020-01-27 more...
28 - P0000549
Hans Gruber
René Jean Millour

3464 Die Schwalbe 68 04/1981
P0000549
(1+1)
Ergänze weiße Steine minimaler Gesamtqualität zu einem IC
Keine Bauern auf der 1./8. Reihe
Mars-Circe
+wBe2,wBg2
play all play one stop play next play all
Die Lösung des ursprünglichen Alleinautors HG (+wBe2 f2 g2) ist nicht die Lösung, da die Stellung nach Entfernen des wBf2 immer noch illegal ist. Die Lösung von RJM, der damit auf Wunsch von HG zum Koautor wurde (+ wBe2 g2), ist aber auch nicht richtig: NL +wB auf 1. oder 8. Reihe. Dies muß also ausgeschlossen werden.
Henrik Juel: With the additional condition ruling out solutions like +wPa1, the problem now seems correct
Adding wPe2,g2 gives an illegal position, as [Lf1] could not have been captured on f1 in Mars Circe (2019-02-14)
more ...
comment
Keywords: Circe (Mars), Illegal cluster, only Kings
Genre: Retro, Fairies
FEN: 8/8/8/8/8/8/1K5k/8
Reprints: G) Problemkiste (50) 08/1987
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-02-15 more...
29 - P0000556
Wolfgang Dittmann
3532 Die Schwalbe 69 06/1981
Herbert Grasemann gewidmet
2. Preis
P0000556
(7+11) C+
#1 vor 3
VRZ, Typ Proca
R: 1. La1-g7 (2. Lh8xTa1) f6-f5 Le5xTa1 Ta2-a1+ 3. Le4xSf3, dann 1. Txc7#
R: 1. Lf8-g7? c4xb3ep 2. b2-b4 d5xBc4
play all play one stop play next play all
paul: If 1...Th5-g5, then 2.Lh8xTa1 Ta2 3.Bg7xS(L)h8=L and Bg8=T(D)# (2010-09-30)
TBr: General plan: 1.Txc7#, but 1... Bxf3, so basic plan: R: 1.Le4xSf3 and 1.Txc7#, but 1... fxe4.
Safeguarding play: R: 1.La1-g7! (thr. 2.Lh8xTa1 Ta2/3-a1+ 3.h7-h8=L and 1.h8=D#) 1... f6-f5
2nd foreplan: 2.Le5xTa1! (preventing Tg5-d5) Ta2/3-a1+, and now the basic plan works: 3.Le4xSf3 and 1.Txc7#.
Not immediately R: 1.Lh8-g7? (thr. 2.h7-h8=L and 1.h8=d#) due to the retro analytic defence 1... c4xb3ep! 2.b2-b4 d5xBc4 closing e4-a8!
"Dresden" theme presented in New German form (safeguarding play is pure of aims) with retro refutation in the try R: 1.Lh8-g7? (2020-05-01)
comment
Keywords: En passant in the retro play, Defensive Retractor, Type Proca
Genre: Retro
Computer test: RSP 1.0
FEN: k7/PRpp2B1/1p1Pp1P1/5pr1/p6p/1p3B2/8/5K1b
Reprints: 119 Der Blick zurück 2006
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2010-10-10 more...
30 - P0000600
Nikita M. Plaksin
3944 Die Schwalbe 75 06/1982
4. ehrende Erwähnung
P0000600
(7+11)
Welches waren die letzten 3 Einzelzüge?
R: 1. f7xTe8=T f2-f1=L 2. g7xTf8=T
mögliche weitere Auflösung:
2. ... e3xTf2 3. Tf1-f2 Kc7-d8 4. f2-f3 f3xLg2 5. Th1-f1 e4xSf3 6. Sg1-f3 d4xTe3 7. Tb3-e3 Kd6-c7 8. Tb1-b3 d5xDe4 9. Dd3-e4 c6xSd5 10. Sb6-d5 Ta8-e8 11. Dd1-d3 Ta5-a8 12. Lf1-g2 Ta8-f8 13. Kh7-h6 Db8-g8 14. Tc1-b1 Ke6-d6 15. Sc8-b6 h3-h2 16. Kg8-h7 Th5-a5 17. Sb6xLc8 Dh2-b8 18. Kf8-g8 Sb3-a1 19. Ke8-f8 Sc5-b3 20. Kd8-e8 Sa6-c5 21. Sc4-b6 Sb8-a6 22. Kc7-d8 Te5-h5 23. Kb6-c7 Th5-e5 24. Kc5-b6 Th8-h5 25. Kb4-c5 h4-h3 26. Kc3-b4 c5xBd4 27. Ta1-c1 b6xLc5 28. La3-c5 a7xBb6 29. Lc1-a3 h5-h4 30. Kd2-c3 h7-h5 31. h6xLg7 Lf8-g7 32. Ke1-d2 g7-g6 33. g6xSf7 Dc7-h2 34. g5-g6 Dd8-c7 35. h5-h6 Sh6-f7 36. g4-g5 Sg8-h6 37. h4-h5 Kf7-e6 38. Sa3-c4 Ke8-f7 39. Sb1-a3 c7-c6 40. b5-b6 f7-f6 41. b4-b5 Sh6-g8 42. b2-b4 Sg8-h6 43. d2-d4 Sh6-g8 44. g2-g4 Sg8-h6 45. h2-h4
play all play one stop play next play all
Henrik Juel (PDB 2020-03-25): White must uncapture both black rooks at the start of the retroplay, to avoid something like -44... h7 -45.h6xLg7 Lf8 -46... g7 -47.g6xTf7?? with a black rook caught on f7
Henrik Juel: -1.R=f7:R B=f2 -2.R=g7:R. (2003-12-10)
Mu-Tsun Tsai: As a last 3 single moves only problem, this is a hard one! (2011-04-27)
Hans-Jürgen Manthey: mögliche Zugfolge:
1.g4 Sf6 2.d4 Sg8 3.h4 Sf6 4.Th3 Sg8 5.Tc3 Sf6 6.Le3 Sg8 7.b4 Sf6 8.b5 Sg8 9.b6 axb6 10.Tc5 bxc5 11.Sc3 cxd4 12.Sf3 dxe3 13.Dd5 c6 14.Se4 cxd5 15.Lg2 dxe4 16.OOO exf3 17.Kb2 fxg2 18.Kc3 Ta3+ 19.Kc4 Da5 20.Tf1 De1 21.f3 Kd8 22.h5 Kc7 23.g5 Kb6 24.g6 Ka7 25.Kb5 Ka8 26.Kb6 Sh6 27.Kc7 f6 28.Kxc8 Sf7 29.gxf7 g6 30.h6 Lg7+ 31.Kc7 Tc8+ 32.Kb6 Tcc3 33.hxg7 Td3 34.Kc7 Ka7 35.Kd8 Sc6+ 36.Ke8 Sd4 37.Kf8 Sb3 38.Kg8 h5 39.Kh8 Sa1 40.Kh7 Da5 41.Kh6 Dd8 42.Tf2 Dg8 43.Tf1 Kb6 44.Tf2 Kc7 45.Tf1 Ta8 46.Tf2 Tf8 47.Tf1 Ta3 48.Tf2 Taa8 49.Tf1 Tae8 50.Tf2 h4 51.Tf1 h3 52.Tf2 h2 53.Tf1 Kd8 54.Tf2 exf2 und nun 55.gxf8T f1L 56.fxe8T+ (2020-03-25)
Henrik Juel: Here are the three last single moves with clearer notation than I used in 2003
-1.f7xTe8=T f2-f1=L -2.g7xTf8=T
Then Black must uncapture some officer on f2, so White has retractions (2020-03-25)
Henrik Juel: White must uncapture both black rooks at the start of the retroplay, to avoid something like
-44... h7 -45.h6xLg7 Lf8 -46... g7 -47.g6xTf7?? with a black rook caught on f7 (2020-03-25)
more ...
comment
Keywords: Last Moves? (3)
Genre: Retro
FEN: 3kRRq1/1p1pp3/5ppK/8/8/5P2/P1P1P1pp/n4b2
Reprints: (27) Die Schwalbe 156, p. 227, 12/1995
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-03-26 more...
31 - P0000637
Matjas Zigman
Marko Klasinc

2139 Die Schwalbe 45 06/1977
P0000637
(3+14)
Weiß nimmt 1 Zug zurück, dann #2
R: 1. Sf7xTh8, dann 1. Kxf6
play all play one stop play next play all
Henrik Juel: Black pawns have captured all 13 missing white men, including [Pa2,h2], both of which must have promoted
axTb-b8=Y has captured the single missing black man, so [Ph2] promoted on h8, and Black may not castle (2020-03-06)
comment
Keywords: Cant Castler, Help retractor, Castling (sk)
Genre: Retro
FEN: 4k2N/p7/3RKbp1/5pp1/5pp1/5pp1/6b1/5nnq
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2009-12-18 more...
32 - P0000643
Carl Erik Israel Lind
2203 Die Schwalbe 46 08/1977
P0000643
(9+8) cooked
-1s, dann h#1
b) sSe5 statt sLe5
a) R: 1. f7xLg6, dann 1. f5 Lf7#
b) R: 1. f7xSg6, dann 1. f5 Sf4#
play all play one stop play next play all
Cook: NL
a) R: 1. a6xDb5, dann 1. Ke6-d5 Db5-c4#
Adrian Storisteanu: Possible fix: wPb3->b6, wPh3->h6. (2020-02-07)
more ...
comment
Keywords: Help retractor
Genre: Retro
FEN: 4K3/1p5p/2p1k1p1/1pP1b1Pp/1P5P/1P5P/1P5P/8
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2016-07-11 more...
33 - P0000726
Hans Gruber
2873 Die Schwalbe 58 08/1979
P0000726
(3+5) C+
ser-h#19
Wieviele Lösungen?
Eine Lösung ist: 1. e5 2. f5 3. f4 4. f3 5. f2 6. f1=L 7. Ld3 8. g5 9. g4 10. g3 11. g2 12. g1=D 13. De3 14. h5 15. h4 16. h3 17. h2 18. h1=D 19. Dhe4 c3#
play all play one stop play next play all
911,797,992 Lösungen
Basically there are 1,6,6,6 moves, and choices of promotion to D/L in 2 cases. The difficulty is in managing the collisions on f2,f3&g2. The best way is probably consider in turn which pawn has priority to pass through the square. This partitions the solution set into 2^3=8 cases.
A.Buchanan: I see that the term "Pawn Endgame" is now the English translation of "Kindergarten Problem". To me, an endgame is a study. Does "Kindergarten Problem" carry that connotation in German, or does it refer more to general compositions such as this one? (2019-02-02)
Mario Richter: The latter is the case, we even have some famous Kindergarten Problems in the Retro genre (think e.g. of some of Thierry LeGleuher's works). "Kindergarten" refers to the fact that besides the two kings only "children" (aka pawns) are on the board.
So I do not understand the choice of "Pawn Endgame" as the english translation, even less because the english language has a word like "kindergarden" ... (2019-02-02)
A.Buchanan: Rainer Staudte has recently changed it. Out of respect, I don't want to unilaterally change it back but would like to hear his perspective. Apparently even in English, Kindergarten is the more common spelling. (2019-02-02)
more ...
comment
Keywords: Path enumeration, Series mover, Promotion in forward play, Kindergarten Problem, Excelsior
Genre: Mathematics, Fairies
Computer test: Mario Richter: rawbats' output: 911797992 Loesungen gefunden time= 1.535000(s) (2019-2-2)
FEN: 8/4pppp/8/8/1KPk4/8/2P5/8
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-02-03 more...
34 - P0000764
Leonid Makaronez
1160 Die Schwalbe 24 12/1973
P0000764
(9+14)
#2
1. c7! ... 2. c8=D,T#
1. ... 0-0? is illegal!
play all play one stop play next play all
Paulo Roque: Solution:
1. c7 ~ 2. c8=D (or T) # (1. ...0-0 is illegal !)

Demonstration the illegality of the castle:

a) Logical elements in the diagram (LED):
(a.1) The bishops black and white were captured in original squares.
(a.2) sLa7 is pawn-promoted, note square f8. The promotion was in square g1.
(a.3) captured two black pieces (vide a.1, then two bishops ).
(a.4) captured seven white pieces (two rooks,one knight, two bishops, queen and one unknown).
The piece unknown: (uk1) is one pawn, or (uk2) is one pawn-promoted, or (uk3) is one piece original equal the pawn-promoted which is in the diagram.

b) Development:
(b.1) The white pieces were captured in: The pawn-h black was promotion in square g1, is necessary hxgxh2xg1 (three captures) + two bishops white captured in original squares xLc1 xLf1 (two captures) + c7xd6(one capture) + a7xb6(one capture) = seven captures pieces white.
(b.2) The structure in the diagram with sLa7,sBb7,sBb6,sBd7,sBd6 is only possible if the promotion of pawn-h black and -c7xd6- preceding -a7xb6-.
(b.3) Then pawn-a white was promotion in square a8 and the piece unknow (a.4) is uk3, only possibility a8=S.
(b.4) On the way Sa8 for e5, necessarily have to go in square c7,then impossible s0-0.

c) Conclusion: 1. ...0-0 is illegal.

Keywords: Cant Castler (2009-07-17)
Henrik Juel: The illegality of castling may also be shown by looking at the retroplay. La7 is [Ph7] promoted on g1, so all missing white men are accounted for, and [Pa2] must have promoted on a8. We cannot uncapture a white officer fast, so the retroplay must start by unpromoting Se5. But it needs to pass c7, so black king has moved. (2009-08-21)
Paulo Roque: Henrik, your solution is very elegant! (2009-08-21)
Yoav Ben-Zvi: As noted by Henrik above, proof that Black "Cant Castle" is based on showing that the White piece unpromoted on a8 is wNe5 rather than an officer uncaptured by one of the bPs. This is not affected by time pressure. Instead, note that retraction of bPc7xf6 must be preceded by exit of bBa7 from the North-West (via c7) which requires previous retraction of bPa7xb6 which implies previous unpromotion on a8 with the unpromoted wP retreating past a7 to allow its occupation by bP. This shows the unpromotion on a8 occurs before Black can uncapture on b6 or on d6 or by bP unpromoted on g1. It follows that the piece unpromoted on a8 must be wNe5. (2018-12-26)
Yoav Ben-Zvi: Typo bPc7xd6 (not xf6) (2018-12-26)
comment
Keywords: Castling (sk), Cant Castler
Genre: Retro
FEN: 4k2r/bp1ppppq/1pPpr1n1/4N2n/8/7P/1P1PPPP1/3K4
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2018-12-27 more...
35 - P0000811
Tibor Orban
1791 Die Schwalbe 38 04/1976
Lob
P0000811
(15+15) C+
BP in genau 4,0
1. e4 e6 2. Lb5 Ke7 3. Lxd7 c6 4. Le8 Kxe8
play all play one stop play next play all
Jeff Coakley in 'The Puzzling Side of Chess': "This puzzle has surely boggled millions of minds.
... Tibor Orbán was born in Kaposvár, Hungary on July 5, 1956. After attending university, he joined the military. Tragically, on September 4, 1981, one day after completing his service, he was found dead at a railway station. Just twenty-five years old.
... The remarkable feature of this proof game is the switchback of a piece making
a capture on its original square, in this case the black king. In honour of
Tibor, I suggest that this theme be called the 'Orbán effect'."
Mark Thornton: In January 2011, a fictional Hungarian detective named "Tibor Orban" appeared in the BBC crime drama "Silent Witness". Tibor Orban was played by the actor Ivan Kamaras (http://en.wikipedia.org/wiki/Iv%C3%A1n_Kamar%C3%A1s). (2012-07-21)
Dirk Borst: The word "genau" can and should be removed. "BP in 4,0" historically and logically means: "Position after the 4th black move; how did the gane go?" So a shorter game cannot be a cook, by definition. (2019-04-18)
Henrik Juel: I disagree, Dirk
Usually the composer asks for a shortest proof game; the 'genau' addition is a handy way of emphasizing the few exceptions, like this one
1.e4 e6/c6 2.Lc4/Lb5 c6/e6 3.Lxe6/Lxc6 dxe6/dxc6 are two of the four shortest proof games without loss of tempo (2019-04-18)
Per Olin: The solution is unique also in 4.5 moves: 1.e3 e6 2.Lb5 Ke7 3.Lxd7 c6 4.Le8 Kxe8 5.e4 (2019-04-19)
comment
Keywords: Unique Proof Game, Switchback, Loss of tempo
Genre: Retro
Computer test: Resolution time : 1.21 s., Natch 2.3 Copyright (C) 1997,98,99,2001,2002,2003,2004 Pascal Wassong
FEN: rnbqkbnr/pp3ppp/2p1p3/8/4P3/8/PPPP1PPP/RNBQK1NR
Reprints: 32 Probleme für Tiger 3 03/1984
(I) Schachkalender 1987
7 Shortest Proof Games 11/1991
(3) feenschach 123 01-06/1997
(1) Probleemblad 03/1999
4 Introduction to Proof Games 03/2010
4b 64 Proof Games 2012
PG3 The Puzzling Side of Chess 3 30/06/2012
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-05-24 more...
36 - P0000888
Bruno Ebner
638 Die Schwalbe 13 02/1972
P0000888
(5+10)
#1
a) -wDc6: 1. Sc6#
b) -wSd4: 1. Td4#
c) -wTd3: 1. Sd3#
d) -wSc5: 1. Dc5#
play all play one stop play next play all
Mario Richter: Illegale Stellung (mehr schwarze Bauernschläge notwendig als weiße Steine fehlen).
Offensichtlich ein Scherzproblem, Lösung vermutlich: entferne eine weiße Figur, dann:
- wTd3: Sd3#
- wSd4: Td4#
- wSc5: Dc5#
- wDc6: Sc6# (2010-02-24)
Henrik Juel: Writing the above solution in this order
-Td3, Sc5-d3#
-Sc5, Dc6-c5#
-Dc6, Sd4-c6#
-Sd4, Td3-d4#
discloses a cyclical pattern. (2010-02-26)
A.Buchanan: I guess it would spoil the joke to ask why we're not removing a black pawn? (2019-10-22)
Alfred Pfeiffer: Die Entfernung eines beliebigen schwarzen Bauern erlaubt kein #1. (2019-10-22)
A.Buchanan: Exactly, Alfred (2019-10-22)
comment
Keywords: Illegal position, Joke, Remove pieces, Cycle
Genre: Retro
FEN: 8/2p5/2Q5/rpNK4/pk1N4/p1pR4/1p1p4/2r5
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-10-22 more...
37 - P0000947
Theophilus Harding Willcocks
Werner Keym

Die Schwalbe 1978
P0000947
(3+9)
Letzter Zug?
R: 1. Da8xTb8 Tb7-b8 and e.g. 2. Lb8xSc7
play all play one stop play next play all
siehe auch P0000948
more ...
comment
Keywords: Last Move? (DxT), Type A, Economy record, Type B (a fortiori)
Genre: Retro
FEN: 1qkB4/P1brp3/Kppp4/1p6/8/8/8/8
Reprints: 1.9A Eigenartige Schachprobleme , p. 174, 2010
1.9B Eigenartige Schachprobleme , p. 174, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2019-10-30 more...
38 - P0000957
Theophilus Harding Willcocks
Die Schwalbe 1959
P0000957
(4+8)
Letzter Zug?
R: 1. a7xTb8=L
play all play one stop play next play all
Yoav Ben-Zvi: WBd8 can be replaced with a BN after moving BPg7 to f7 and BPh5 to h6. (2018-08-08)
A.Buchanan: Yes after all these years, I found this a few months ago, but when I told Thomas Brand, he said that Werner Keym had found it - one of a series of modifications through seeking to avoid non-standard material. (2018-08-12)
Henrik Juel: Werner's improvement can be found in his 'Eigenartige Schachprobleme' from 2010, p.196, dia 1.68 (2018-08-12)
A.Buchanan: I thought it was more recent (2018-08-12)
A.Buchanan: In fact Werner was not trying to avoid non-standard material, but to prefer "cheaper" knights over bishops. But this is not the canonical ordering, which regards knights and bishops as equivalent. So the older record will win out in classical terms. (2019-10-04)
A.Buchanan: And non-standard material is no defect, according to the 1977 grading criteria, so old Theophilus reigns supreme (2019-10-04)
Henrik Juel: The further retroplay is
-1... h6 -2.a6 and e.g. -2... Ka7 -3.a5 Ta8 -4.Tb8 Ka6 -5.Kc8
and wK out via g6 (2019-10-04)
more ...
comment
Keywords: Type A, Last Move? (BxT=L), Promotion in the retro play (L), Economy record, Non-standard material
Genre: Retro
FEN: kBRB4/1pKpp1p1/1pp5/7p/8/8/8/8
Reprints: 1.49A Eigenartige Schachprobleme , p. 190, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2019-10-04 more...
39 - P0001056
Niels Høeg
Skakbladet 1923
P0001056
(2+1)
Welches war der letzte Zug?
R: 1. Bc7-c8=L+
play all play one stop play next play all
A.Buchanan: In Eigenartige Schachprobleme, this one is attributed to Branko Pavlovic, Sahovski Vjesnik, 1950. Don't know if this is typo or anticipation. (2016-07-18)
Henrik Juel: In ES this one is also included, as 1.47C
The difference is the stipulation question
Pavlovic asks: First move by bishop? (2016-07-18)
A.Buchanan: So how best to represent this in PDB? It seems silly to have a separate problem for what is at best a version of a very tiny problem. There are a few other simplistic cases where a "Last Move" problem functions as a "First Move". Best maybe to keep one entry, and indicates Pavlovic's version changed the stipulation slightly. (2016-07-18)
Henrik Juel: Fine with me
The Pavlovic question is (translated from german): First move by the bishop? (i.e., Lc8)
Answer: It never moved, ha-ha (2020-04-23)
A.Buchanan: Where someone wants to change an earlier stipulation slightly to indicate a new aspect of the same solution (especially for retro records), I suggest the nomenclature "deemed stipulation". This is not part of the problem, and does not constitute a new version, but is part of whatever judgement or republication is happening. (2020-04-24)
comment
Keywords: Type C, Last Move? (B-=L), Promotion (L), Economy record (Last move), First Move? (UWL0), Aristocrat, Move Length Record (ex-aequo), Economy record (First move)
Genre: Retro
FEN: 2B5/1K1k4/8/8/8/8/8/8
Reprints: Sahovski Vjesnik 1950
C/42 feenschach 159 04-06/2005
C3b Length Records in Last Single Moves? , p. 10, 11/2009
1.47C Eigenartige Schachprobleme , p. 190, 2010
2.65 Eigenartige Schachprobleme , p. 204, 2010
C03b Phénix 282, p. 11066, 02/2018
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-05-01 more...
40 - P0001134
Philip Hamilton Williams
The Chess Amateur 08/1910
P0001134
(12+11)
#2
1. Df6!
play all play one stop play next play all
Schwarz muß zuletzt entweder mit dem König oder dem Turm gezogen haben.
Henrik Juel: Black captured all missing white men with his [Pc7,g7], so last move was not a black pawn capture (2020-01-24)
comment
Keywords: Cant Castler, Castling (sk)
Genre: Retro
FEN: 2b1k2r/1N1ppp1p/1p5Q/P7/p3R1P1/4PpKp/1PPN4/5B1R
Reprints: 33 Retrograde Analysis 1915
10 Europe Echecs 12 08/1959
(1) Problem 83-86 09/1962
1498a Augsburger Allgemeine 11/11/2017
405 Scobs lignea 12/11/2017
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2020-01-24 more...
41 - P0001141
George Hume
Jamaica Gleaner 12/1891
Weihnachtsturnier 1891
1. Preis
P0001141
(9+9)
Auf welche Gedanken kommen Sie bei dieser Stellung?

Der Ld6 ist keine UWF und der sBg7 wurde auf seinem Ausgangsfeld geschlagen. Nach dem Autor muss der letzte Zug also Lf8-d6 gewesen sein, also illegale Stellung.
Datum der Originalpublikation nicht 100% sicher, laut ACM aus der "Jamaica Gleaner Christmas column".

Originalforderung: How has the position been arrived at and who is the winner, and in how many moves?

From the Jamaica Gleaner: "White mates in two moves. The last move made was by Black playing his Bishop and announcing mate. As it can be demonstrated that the Bishop is not a promoted Pawn and that Black's King's Knight's Pawn was captured on its original square by White's Queen's Knight's Pawn the Black Bishop must have been played from Bishop's square (f8) to Q3 (d6). This being an illegal move, White enforces the penalty of compelling Black to retract it and move his King whereupon White plays 1 PXB(Q) ch (1.gxf8=Q+) and mates next move by 2 Q-B4 (Qf4#). The following is a brief but pointed analysis, demonstrating the false move: White's Pawns have made six captures all on black squares. The Q Kt P (Pb2) made five of these and consequently captured the Kt P on the square upon which it now stands (g7). They could not have captured the Q B which is also lost. The White Bishop is the QRP (Pa2) promoted, the original KB having been captured on its own square as the unmoved Pawns show. To allow this promotion Black's QRP (Pa7) made two captures, the QKtP (Pb7) one, and the QBP (Pc7) two. The KRP (Ph7) has also made a capture, which accounts for the seven pieces White has lost. The Black Bishop is not a promoted Pawn, as if the Black KBP (Pf7) had played to the 7 th square (f2) and then captured a White piece on K or Kt square (e1 or g1) the captures by White Pawns cannot be accounted for without including the Black QB or KRP neither of which is available. As it can be demonstrated, then that the Black Bishop is not a promoted one, and that the KKtP was captured by the White Pawn which now stands on that square, in order to reach Q3 the Black Bishop must have an impossible move.

Der Kolumnist des ACM merkt aber zurecht an:
ACM: The above is a very fine piece of analytical work; but there is a slight flaw in connection with the minor condition, 'mate in two'. In a position of this kind we believe only that which can be proved; thus we do not think that White has any right to enact a penalty, as neither the analysis nor the conditions show that the Black Bishop came from Bishop's square on his last move; indeed, that Bishop may have played outside the Pawns on the very first move of the game which, being played, brought about the position.
A.Buchanan: I don't think this is cooked, I think it's just a very bad joke. Most time when moves are retracted it's because of self-check or illegal castling, occasional illegal en passant. But here we are meant to conclude that the Bl bishop has hopped over Bl pawn. There are problems by Hieronymus Fischer e.g. P1309484 where we are meant to conclude that a unit has escaped its game array cage somehow, but the piece is simply replaced: there is no move to be retracted and supplanted. But as long as such a problem is true to its own (joke) internal logic, it can't be described as cooked. If it fails (e.g. P1246715) it can indeed be cooked and repaired. (2019-10-22)
HBae: White plays 1 PXB(Q) ch (1.gxf8=Q+). Muß der sK nicht auf f5 stehen? (2019-10-22)
Henrik Juel: Last move (supposedly) was Lf8-d6#, which is obviously impossible and hence illegal
The penalty for this is that Black must replace Ld6 on f8 AND instead make an arbitrary move with his king
So the forward play is
0... Kf5,Kf6,Kh6 1.gxf8=D+ Kg5,Ke5 2.Df4# (2019-10-22)
comment
Keywords: Illegal position, Joke, Retract illegal move (stuck at home), Touch Move
Genre: Retro
FEN: 6B1/4p1P1/p2b2p1/p5kq/p7/4P1K1/2PPP1PP/3n4
Reprints: American Chess Monthly 1, p. 11, 03/1892
Jamaica Gleaner 30/04/1892
17 Europe Echecs 14 10/1959
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-10-23 more...
42 - P0001248
Marijan Dumic
(7) Problem 91-94 04/1964
1. Preis
P0001248
(13+14)
Löse die Stellung auf!
a) Weiß am Zug
b) Schwarz am Zug
R: 1. g5-g4 g2xLh3 2. Lg4-h3 e3-e4 3. Le2-g4 Sc3-b5 4. Lb5-e2 Se4-c3 5. g6-g5 Sf6-e4 6. h7-h6 Se8-f6 7. Se5-c6 Sc7-e8+
play all play one stop play next play all
: il y a 2 solutions distinctes selon que le trait est aux Blancs ou aux Noirs (2002-12-15)
AV: Trait aux Noirs :
1.e3 Cf6 2.Fc4 Cg8 3.Fe6 fxe6 4.Re2 Ch6 5.a4 g6 6.Ca3 Fg7 7.c4 Ff6 8.c5 Fe5 9.c6 d5 10.f4 Dd6 11.f5 Dc5 12.f6 Rd8 13.f7 Te8 14.Cb5 Fd7 15.cxd7 Dxc1 16.Db3 Dc3 17.Tc1 Da5 18.Tc6 Fd6 19.Rd3 Fa3 20.Ta6 Cc6 21.Ce2 Tc8 22.f8D Cb8 23.Df3 Tf8 24.Tc1 Tf4 25.Tcc6 Tc4 26.Td6 c6 27.Cc7 Tc3+ 28.Rd4 Cg4 29.Db6 Tb3 30.Cc3 Ce5 31.C3b5 Tb4+ 32.Rc5 d4 33.Dd5 cxd5 34.e4 Cec6 (début de la suite forcée) 35.Ce8+ Tc7 36.Cg7 g5 37.Ch5 h6 38.Cf4 g4 39.Cd3 Tb3+ 40.Cb4 Th3 41.gxh3
Trait aux Blancs :
1.c4 Cf6 2.c5 Cg8 3.c6 d6 4.e3 Dd7 5.a4 Df5 6.Cc3 Dc5 7.Ca2 Rd8 8.Ce2 Ch6 9.Cd4 g6 10.Fc4 Fg7 11.f4 Fh3 12.f5 Fe5 13.Fe6 d5 14.Cb5 Fd6 15.Re2 Dxc1 16.f6 Dc3 17.Tc1 Da5 18.Rd3 Ff5+ 19.Rd4 fxe6 20.Db3 Rc8 21.f7 Td8 22.f8D Fe4 23.Df3 Td7 24.cxd7+ Rd8 25.Tc6 Fa3 26.Td6 Ca6 27.Tc1 Tc8 28.Tcc6 Cb8 29.Ta6 c6 30.Cc7 Fd3 31.Db6 Cg4 32.Cb4 Fb5 33.Rc5 d4 34.Dd5 cxd5 35.Tc6 Ce5 36.Td6 Cec6 (début de la suite forcée : le clouage et la batterie sont intervertis) 37.Ce8+ Tc7 38.Cf6 g5 39.Ce4 h6 40.Cc3 Fd3+ 41.Cb5 Ff5 42.e4 Fh3 43.gxh3 g4 . (2005-06-26)
Hans-Jürgen Manthey: in der abspielbaren Lösung ist ein Fehler: 7.Tc8-c7 Sf7-e8+ 8.Se5-c6

da AV eine nicht schlüssige Notation verwand (T = Turm aber auch König), hier in lesbarer Notation :

a) 1.c4 Sf6 2.c5 Sg8 3.c6 d6 4.e3 Dd7 5.a4 Df5 6.Sc3 Dc5 7.Sa2 Kd8 8.Se2 Sh6 9.Sd4 g6 10.Lc4 Lg7 11.f4 Lh3 12.f5 Le5 13.Le6 d5 14.Sb5 Ld6 15.Ke2 Dxc1 16.f6 Dc3 17.Tc1 Da5 18.Kd3 Lf5+ 19.Kd4 fxe6 20.Db3 Kc8 21.f7 Td8 22.f8D Le4 23.Df3 Td7 24.cxd7+ Kd8 25.Tc6 La3 26.Td6 Sa6 27.Tc1 Tc8 28.Tcc6 Sb8 29.Ta6 c6 30.Sc7 Ld3 31.Db6 Sg4 32.Sb4 Lb5 33.Kc5 d4 34.Dd5 cxd5 35.Tc6 Se5 36.Td6 Sec6 37.Se8+ Tc7 38.Sf6 g5 39.Se4 h6 40.Sc3 Ld3+ 41.Sb5 Lf5 42.e4 Lh3 43.gxh3 g4

b) 1.e3 Sf6 2.Lc4 Sg8 3.Le6 fxe6 4.Ke2 Sh6 5.a4 g6 6.Sa3 Lg7 7.c4 Lf6 8.c5 Le5 9.c6 d5 10.f4 Dd6 11.f5 Dc5 12.f6 Kd8 13.f7 Te8 14.Sb5 Ld7 15.cxd7 Dxc1 16.Db3 Dc3 17.Tc1 Da5 18.Tc6 Ld6 19.Kd3 La3 20.Ta6 Sc6 21.Se2 Tc8 22.f8D Sb8 23.Df3 Tf8 24.Tc1 Tf4 25.Tcc6 Tc4 26.Td6 c6 27.Sc7 Tc3+ 28.Kd4 Sg4 29.Db6 Tb3 30.Sc3 Se5 31.S3b5 Tb4+ 32.Kc5 d4 33.Dd5 cxd5 34.e4 Sec6 35.Se8+ Tc7 36.Sg7 g5 37.Sh5 h6 38.Sf4 g4 39.Sd3 Tb3+ 40.Sb4 Th3 41.gxh3 (2020-03-23)
Henrik Juel: .
White captured cxd and g2xh3, and promoted on f8; Black captured cxd, f7xe6, and [wLc1]
Resolution plan: On h3 White uncaptures sL/T, which releases wSb5/Sb4, which releases sTc7
Possible retroplays
a) White to play
-1... g5 -2.g2xLh3 Lg4 -3.e3 Le2 -4.Sc3 Lb5 -5.Se4 g6 -6.Sf6 h7 -7.Se8 Tc8 -8.Sc7 Se5 -9.Tc6 Sg4 -10.Td6 c6xTe5 etc.
Tiny typo in 'official' retroplay: 7.Tc8-c7, not Se5-c6
b) Black to play
-1.g2xTh3 Tb3 -2.Sd3 Tb4 -3.Se5 g5 -4.Sg4 g6 -5.Sf6 h7 -6.Se8 etc. as above (2020-03-23)
comment
Keywords: Promotion (S)
Genre: Retro
FEN: 1n1k4/pprPp3/RQnRp2p/qNKp4/PN1pP1p1/b6P/1P1P3P/8
Reprints: 121 Europe Echecs 70 10/1964
Input: Gerd Wilts, 1995-06-03
Last update: Nikolai Beluhov, 2011-04-28 more...
43 - P0001275
Henry Anthony Adamson
The Chess Amateur 03/1926
P0001275
(14+10)
#2
1. Kf2+ Dc1 2. Txc1#
play all play one stop play next play all
Henrik Juel: Not 1.0-0?, e.g. -1... Dc2 -2.Lc1 Db1 -3.Td2 Dc2 -4.Td1 Db1 -5.Ld2 Dc1 -6.Lc3 D=c2 -7.Td2 ?? (2004-02-23)
Yoav Ben-Zvi: [bBf8] was captured at home by an officer, the other 5 missing Black pieces were captured by the wPs (2 on the b file, by [wPc2] and [wPa2], and 1 each on the d, e and g files). It follows that [bBc8] was captured by a wP outside it's home, after being released by bPb7-b6, and that each of [bPc7], [bPf7] and [bPh7] accounts for a wP capture. Since none of the captures by wPs is on the c, f or h files, each of these bPs either promotes or else captures to arrive at a file where a wP can capture it directly.
Assuming White retains the right to castle implies the following:
[bPh7] could not move directly (without capture) to promotion on h1 as this would require a move by [wRh1]. [bPf7] could not move directly to promotion by bPf2-f1=X as this would require a prior move by wK. Each of these bPs must therefore have captured one of the missing wNs. No other White pieces are missing so [bPc7] did not capture. In order to account for a wP capture it must have moved directly to promotion on c1. Prior to the promotion on c1, the way to promotion on the c file must be cleared by [wPc2] capturing on the b file. Promoting [bPf7] entails a move by wK even if the bP captures (promoting from f2 or on e1) so, to preserve White castling, it must be captured directly by wPf2xPe3 (after capturing a wN on the e file).
Looking backwards from the diagram position:
The pieces on the a and b files form a locked West cage. All officers on the a file are immobile until the cage is released. The West cage remains locked until the retraction of wPc2xb3 or wPc3xb4 or bPb7-b6, not bPc7xb6? as [bPc7] does not capture (see above). Retraction of wPc2xb3 requires the previous release of the cage to allow exit of bKa1 via c2, d3, since alternative exit paths of the bK require a move by wK to clear the way. Retraction of bPb7-b6 requires previous uncapture and return home of [bBc8]. The uncapture of [bBc8], by a wP, occurs on a light-colored square, b3 or d3. Each of the alternatives for uncapturing [bBc8] requires previous release of the cage: wPc2xb3 since it is preceded by exit of bKa1(as noted above), wPa2xb3 or wPe2xd3 since these are preceded by exit of wBa2 to remove the obstruction on a2 or to retract home [wBf1]. It follows that the uncapture of [bBc8] and therefore the retraction of bPb7-b6 requires previous release of the cage. The remaining alternative for release of the West cage under the assumption that White may castle, retraction of wPc3xb4, is next to be considered.
Prior to the unpromotion by bPc2-c1=X, the following is known: the cage remains locked as it can be released only after the unpromoted bP retreats to c4 allowing wPc3xb4 to be retracted without blocking the retreat of bP to c7, the officers on the a file are immobile, retraction of bPb7-b6 locks out [bBc8], retraction of wPc2xb3 or wPc3xb4 blocks the retreat of Black's unpromoted pawn on the c file, retraction of wPd2-d3 requires prior retraction of wBd2 to c1 leading to permanent obstruction of the unpromotion on c1, retraction of wPe2-e3 or wPe2xd3 locks out [wBf1], retraction of wPf2xe3 prevents subsequent retraction of bBa5 to g1 and retraction of wPh2xg3 prevents subsequent unpromotion of bBa5 by bPh2xNg1=B. The rejection of all of these alternatives (prior to the unpromotion on c1) means that neither side can uncapture or play a pawn retraction. This means that the retroplay preceding the unpromotion on c1 consists only of moves by bQc7, wBd2 and wRe2, proving that the Black piece unpromoted on c1 must be bQc7. Since wK and wPs are immobile, wBd2 is restricted to the squares c1, d2 and c3. Since it has been shown that [bPc7] promotes to queen, not bishop, and [bPf7] does not promote at all, the promotion to bBa5 is by [bPh7] playing bPh2xNg1=B.
Since the wK stands immobile on e1, the unpromotion of the bQ by bPc2-c1=Q occurs with a shield standing on d1 to protect the wK from check by the promoted bQ. This shield can only be provided by wRe2 since d1 is a light-colored square that cannot be occupied by wBd2 and (as noted above) no uncaptures can be played prior to the unpromotion so the sheilding piece must be present in the diagram. If the unpromotion on c1 occurs with wB standing on c3 then White responds to the unpromotion by wRd2-d1+ and Black is in Retro-Stalemate caused by wBc3 obstructing the retreat of the unpromoted bP and the lack of Black tempo retractions that would allow White to remove the obstruction (this is shown in the Try noted by Henrik).
Another possibility that needs to be considered is that, when the unpromotion on c1 occurs, wB stands on d2 (instead of c3). In this case White responds to the unpromotion by retracting wBc1-d2+ (shielding bK from wRd1) followed by retreat of the unpromoted bP to c4 and the retraction of wPc3xb4 releasing the West cage. This shows that the position with bQc7 on c1, wRe2 on d1 and all other pieces as in the diagram, and White to play, can be reached with White retaining the right to castle. However, due to Retro-Opposition between bQ and wB colliding on c1 and the lack of tempo retractions by either side, other than moves by wK or wRh1, to overcome parity of bQ shuffling between b1 and c1 and wB shuffling between d2 and c3, there is no valid retraction from the diagram position with castling rights preserved. This is demonstrated in Henrik's Try if Black delays unpromotion of bQ, retracting -6...bQb1-c1 but it is simpler to prove by considering forward play. It can be seen that in the relevant position (with wKe1 and wRh1 immobile) White must play 1.wBd2-c3 (c1 is obstructed by bQ) followed by bQc1-b1 (the shield for the bK must be maintained) 2.wBc3-d2, bQb1-c1 repeating the position. There is no way to advance to the diagram position and preserve White's right to castle so in this case too (wB standing on d2 when bQ is unpromoted) White can't castle.
It has been shown that the assumption that White can castle leads to contradiction in every case thus proving (by "Reducto ad Absurdum") that White cannot castle. (2019-08-05)
A.Buchanan: Beautiful solution, with a dramatic tempo-based finale - thanks for posting such an authoritative solution. Which tempo keyword is meant to be used for this? :) (2019-08-06)
Yoav Ben-Zvi: The reprint of this problem in Ceriani's book appears in the chapter devoted to the Retro-Opposition phase of a resolution, under the heading "Defferred R.O.".
The analysis contains several instances of repeated thematic content (Echo) such as: "Retro-Shield" (by bQ, wR and wB, on b1, c1, d1), "Retro-Opposition" (temporary obstructions by wB and bQ on c3 and c1) and locking of various Home and Dynamic cages.
The #2 stipulation reflects the preference, at the time this was published, for RA problems to be presented as orthodox. This is no longer considered important so the analysis can be used to reject castling in the last move, as in the following version:
wBd2 on c3, wRh1 on f1, wRe2 on f2, wKe1 on g1 - "Last Move?". (2019-08-14)
A.Buchanan: (1) Have you got both of Ceriani's books? How did you get hold of them? I guess they are still under copyright. Retro Corner has been saying for 20 years that you need to write to Ceriani's son. Is that still true? Hasn't he got an email address now.
(3) I think your statement "This is no longer considered important" is too black and white. Generally I find it satisfying if the composer is able to tie future and past together in this way. And a check in the diagram position is to my mind an unpleasant defect, to be avoided if possible. (2019-08-15)
Henrik Juel: There are two ways of telling the solver immediately who has the move:
By having a king in check or by specification, directly by saying so or indirectly by a forward stipulation
It has got out of fashion to cast retro problems as forward ones, but there are still examples of imprecise stipulations, like #1: sometimes it should be interpreted as a condition, saying that White has the move, and sometimes it means 'Who mates in 1?' (2019-08-15)
A.Buchanan: (1) Yes #1 is a special stipulation. There are 4 possible interpretations: who moves first (Codex Article 15, "the official joke") but also who gets mated (maybe should be added to Codex or certainly to PDB glossary somehow).
(2) I get that RA has kind of come of age: it no longer needs to justify itself behind an orthodox stipulation. Hurray, I suppose.
(3) I am not objective in liking these old-style stipulations, because DP is all about interaction between forward and retro play. One of my heroes, Guus Rol, is also a big enthusiast of combining these two modalities, which he terms "retro-activity".
(4) And it is cool to read the same diagram in two ways: both forward and backwards. It's like a cryptic crossword clue where the same text has two meanings. Even if the forward play is not very thematic or interesting.
(5) So I hope that the RA community can feel sufficiently confident in its status now that it doesn't need to "fix" a classic problem with a perfectly natural #2, by making a second-rate Type C position out of it.
(6) Any info about the Ceriani books please? (2019-08-16)
Henrik Juel: You can buy a used copy of '32 characters and 1 author' on an italian homepage for €350
which seems very expensive to me
Most of the problems from the book are on the PDB (2019-08-16)
comment
Keywords: Cant Castler, Castling (wk), Promotion (l)
Genre: Retro
FEN: 8/p1qpp1p1/rp6/b7/rP1P4/QP1PP1P1/BP1BR1P1/k3K2R
Reprints: 155a 32 personaggi e 1 autore 1955
147 Europe Echecs 86 03/1966
Input: Gerd Wilts, 1995-06-03
44 - P0001306
Thomas R. Dawson
Falkirk Herald 17/06/1914
P0001306
(11+6)
#2
1. gxf6ep
play all play one stop play next play all

Duplicate Diagram: P1226354

in UT und Mat Plus spiegelverkehrt, ebenso in AA
hpr: Im Original erschien die Aufgabe spiegelverkehrt, wie Paul Valois im Original nachgesehen hat. Insofern dürfte die Aufgabe HIER falsch wiedergegeben sein. (2011-12-04)
Henrik Juel: TRD himself used this version in Retrograde Analysis, 1915, so maybe the Falkirk Herald editor got it wrong (2020-02-21)
Henrik Juel: White pawns captured all 10 missing black men, so last move was f7-f5, not d7-d5 that would interfere with [sLc8] (2020-02-21)
more ...
comment
Keywords: En passant, En passant as key, Symmetrical position
Genre: Retro
FEN: 4k3/1p2P2p/2N1P1N1/2PpKpP1/3PpP2/4P3/4P3/8
Reprints: 61B Retrograde Analysis 1915
35 Ultimate Themes 1938
22 Al Hamishmar 22/11/1945
274 Problemista 01-02/1965
178 Europe Echecs 104-105 10/1967
3 Chess unlimited 1969
212 FIDE Album 1914-1944/III 1975
84a 100 Classics of the Chessboard 1983
(49) Mat Plus 12 10-12/2009
1149 Augsburger Allgemeine 05/03/2011
H1 ASymmetrie 2013
Input: Gerd Wilts, 1995-06-03
Last update: Marcin Banaszek, 2020-02-20 more...
45 - P0001343
Friedrich Amelung
53 Düna-Zeitung 129, p. 2, 11/06/1897
P0001343
(5+3) C+
#2
1. hxg6ep Kh5 2. Txh7#
play all play one stop play next play all
siehe P1291160, P1327727
Sally: Der en passant-Schlag als einziger Schlüselzug lässt sich im Zweizüger erst mit acht Steinen darstellen. Dies ist die früheste Aufgabe und beste Darstellung, die mit Zweispänner
möglich ist. (2019-01-18)
more ...
comment
Keywords: En passant, En passant as key
Genre: Retro, 2#
Computer test: Popeye 4.61
FEN: 7R/7p/5P1k/4PKpP/8/8/8/8
Reprints: 55B Retrograde Analysis 1915
169 Allgemeine Zeitung Chemnitz 04/12/1927
(VIII) Problem 37-40 09/1956
(1) Problem 103-105 01/1967
215 Europe Echecs 124 04/1969
D12 feenschach 27, p. 27, 04/1975
(2) Mat Plus 12 10-12/2009
Input: Gerd Wilts, 1995-06-03
Last update: Rainer Staudte, 2020-03-11 more...
46 - P0001348
Miroslav Havel
The Chess Amateur 01/1922
P0001348
(12+11)
#3
klären: in Breuers "Ideengeschichte", S186, Nr.894 = Cas (dort steht beim benachbarten linken Problem "Chess Amateur". (VF)
Henrik Juel: To preserve black castling, we must retract b7-b6, sLa7 to f8, and e7xf6, etc.
If the white castling is also to be preserved, wK must be shielded from check from sLa5
But White runs out of preserving retractions, e.g.
-1... b7 -2.e2xSf3 Sd2 -3.a3 Lb6 -4.a2 La5, and -5.g3 ruins the white castling by preventing wTf7 from reaching h1 without moving wK
-1... Kd8 easily allows white castling, so the castlings are mutually exclusive (2019-11-24)
Henrik Juel: 1.000 thr. 2.Dxg7,T~xd7,Txg7,Te1+
Not 1.Td1? 000! (2019-11-24)
A.Buchanan: How about R: 1. ... b7-b6 2. e2xSf3 Sd2-e3+ 3. a3-a4 Lb6-a7 4. a2-a3 La5-b6 5. h3xLg4 b6xBc5 6. c4-c5 a7xSb6 7. Sa4-b6 Lb4-a5 8. S~ Lf8-b4 9. S~ e7xLf6, and I think from there I can retract all the way to game array, without losing castling rights for either side? sTh8 captured at home. Other Wh pawn captures dxc,exf,gxhxg. The forward play although it has a unique key move, is incredibly messy and dualistic. The fact that this problem has been so widely circulated makes me wonder if the diagram is correct. But Winchloe has the same diagram, although assigned to a magazine called Cas. (2019-11-24)
Mario Richter: R: 1. ... b7-b6 excludes sLc8 from the list of pawn-capturable black pieces, so 5. h3xLg4?? is illegal! (2019-11-24)
Henrik Juel: h3xYg4? would suffice to make Andrew right (where Y need not be L), but hxg requires too many captures by white pawns: dxc, exf, and gxhxg (4), because [Lc8,Th8] were not captured by pawns (2019-11-24)
more ...
comment
Keywords: Castling (wlsl), Castling, mutual exclusive
Genre: Retro
FEN: r3k1BQ/b1pp1Rpp/1p3pp1/2p5/P5P1/5P2/1PP2P1P/R3K3
Reprints: Problem 37-40 09/1956
(I) Problem 61-64 07/1959
(1) Problem 101-102 09/1966
222 Europe Echecs 130 09/1969
(D) Die Schwalbe 1 10/1969
(BI) Die Schwalbe 4 04/1970
(11) Problem 144-147 12/1971
(E) Die Schwalbe 16 10/1972
(IV) Die Schwalbe 27 06/1974
(3) diagrammes 46 07-08/1980
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2019-11-25 more...
47 - P0001438
Niels Høeg
1862 The Problemist FCS 12, p. 129, 06/1935
P0001438
(14+8)
Wer gewinnt?
1. ... bxc2#?
1. Tc1+ Kxa2 2. Sc6 fxe1=D+ 3. Txe1 ... 4. Sb4#

R: 1. ... Ka1-b1 2. Sc6-b8 Kb1-a1 3. Sd8-c6 Ka1-b1 4. Se6-d8 Kb1-a1 5. Sf4-e6 Ka1-b1 6. Sh3-f4 Kb1-a1 7. Sf4xBh3 Ka1-b1 8. Sg2-f4 Kb1-a1 9. Se3-g2 Ka1-b1 10. Sb6-a4 Kb1-a1 11. Sc4-b6 Ka1-b1 12. Sa3-c4 b4-b3 13. Sb1xBa3 a4-a3 14. Tc1-c2 a5-a4 15. Kc2-d1 a6-a5 16. Kd3-c2 b5-b4 17. Dd1-e1 h4-h3 18. Db3-d1 h5-h4 19. Te1-c1 h6-h5 20. Sd1-e3 h7-h6 21. Sa3-b1 Kb1-a1 22. Sc4-a3 Ka1-b1 23. Kd4-d3 Kb1-a1 24. Da3-b3 Kc1-b1 25. Sa5-c4 Kc2-c1 26. Sb3-a5 Kb1-c2 27. Sc1-b3 Ka1-b1 28. Se3-d1 Kb1-a1 29. Sg4-e3 Kc2-b1 30. Sb3-c1 d6-d5 31. Ta1-e1 d7-d6 32. Tb1-f1 Kd1-c2 33. Sc1-b3
play all play one stop play next play all
8/2bbb1bb/b7/1b6/3K2S1/D1B2B2/BB1BBb1B/TTSk2Lt (14+10)
A possible proof game from this intermediate position is:
1. Sb3+ Kc2 2. Tf1 h6 3. Tae1 h5 4. Sc1 Kb1 5. Se3 Ka1 6. Sd1 Kb1 7. Sb3 Kc2 8. Sa5 Kc1 9. Db3 Kb1 10. Kd3 Kc1 11. Sc4 Kb1 12. Sa3+ Ka1 13. Sb1 h4 14. Se3 h3 15. Tc1 d6 16. Dd1 d5 17. De1 a5 18. Kc2 a4 19. Kd1 a3 20. Tc2 b4 21. Sxa3 b3 22. Sb5 Kb1 25. Sb8 Ka1 28. Sxh3 Kb1 32. Sa4 Kb1
Black captured the white bishops on c1 and f1. White captured Lf8 on f8 and g2xf3 and promoted his f-pawn on b8 to L, which was brought to g1, implying that a7, b6, and b7 are unoccupied. Between moves 13 and 21 white has no time for a tempo move, and after this neither side can change the tempo, so white has the move in the problem position and wins.
Henrik Juel: Moving Sb8 to b4 would allow a more contemporary stipulation: #1 (who?)
with the solution: 1.Tc1#, not 1... bxc2? (2016-10-12)
Henrik Juel: If you prefer retroplay, the plan is to uncapture black pawns on h3 and a3, screen with a knight on b1, retract Tc1-c2, extract Kd1 and De1, retract Te1-c1, screen with the other knight on d1, retract the first knight to c1, extract Sd1, hide the white rooks on a1 and b1 while black king waits on c2, and then he can get out via g2 and h3. The details might be
-0... Ka1 -1.Sc5 Kb1 -2.Se4 Ka1 -3.Sg5 Kb1 -4.Sh3 Ka1 -5.Sf4xPh3 Kb1 -6.Sg2 Ka1 -7.Se3 Kb1 -8.Sc6 Ka1 -9.Sa7 Kb1 -10.Sb5 Ka1 -11.Sa3 b4 -12.Sb1xPa3 b5 -13.Tc1 a4 -14.Kc2 a5 -15.Kd3 a6 -16.De1 d6 -17.Db3 d7 -18.Te1-c1 h4 -19.Sd1 h5 -20.Sa3 Kb1 -21.Sc4 Ka1 -22.Kd4 Kb1 -23.Da3 Kc1 -24.Sa5 Kc2 -25.Sb3 Kb1 -26.Sc1 Ka1 -27.Se3 Kb1 -28.Sg4 Kc2 -29.Sb3 h6 -30.Ta1 h7 -31.Tb1-f1 Kd1 -32.Sc1 (2016-10-12)
Henrik Juel: The source with more details is
1862 The Problemist Fairy Chess Supplement no.12, June 1935, p.129
This magazine was later renamed Fairy Chess Review (2019-05-28)
more ...
comment
Keywords: Whose move?, Obtrusive material (L)
Genre: Retro
FEN: 1N6/2p1p1p1/8/3p4/N7/1pP2P2/PPRPPp1P/1k1KQRBr
Reprints: 220 FIDE Album 1914-1944/III 1975
312 Europe Echecs 213/214 10/1976
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-05-28 more...
48 - P0001455
Alexander Kislyak
Die Schwalbe 1976
1. Preis
P0001455
(12+14)
#1 (wer?)
1. ... Sxb2#? - aber Schwarz hat zuletzt gezogen

1. Sxc4#

R: 1. ... Se3-c4 2. Sd3-b2 Sg2-e3 3. Se5-d3 Se1-g2 4. Sg6-e5 Sg2-e1 5. Sf8-g6 Se1-g2 6. f7-f8=S Sg2-e1 7. f6-f7 Se1-g2 8. f5-f6 e2-e1=S 9. f4-f5 e3-e2 10. f3-f4 f4xLe3 11. Ld4-e3 f5-f4 12. Lb2-d4 f6-f5 13. Lc1-b2 f7-f6 14. b2-b3 Sb3-a1 15. h2-h3
play all play one stop play next play all
Unglaublich, wie die 4 weißen Bauern e-h mit ihren Schritten haushalten müssen, damit am Ende der Weg für den weißen Königsturm und den umgewandelten schwarzen Läufer a7 nicht versperrt wird.
Dr. K. Fabel-Gedenkturnier
Henrik Juel: Typos:
The solution should read something like
1.Sxc4# (not 1... Sxb2??)
(because the retroplay shows that White has the move)
The last retraction in the given retroplay should read h2-h3, not h2-h1
Finally, the current PDB standard is to write the white retraction first, so the retroplay should read something like
-1... Se3 -2.Sd3 Sg2 ... -14.b2 Sb3 -15.h2
(Yes, I know that the animation machine requires full retro notation, but abbreviated notation is so much easier to write and to read...) (2019-11-10)
Henrik Juel: This fine retro deserves a closer look, I think
White captured [Lf8] and axb (to promote on b8, as Ld8 cannot get home to c1)
Black captured bxc, c7xd6, a third pawn capture to promote [Pf7] or [Ph7] to L on a black square, and a fourth capture to promote the other missing black pawn (since White did not capture a black pawn on the f- or h-file)
So Black did not capture [Lc1] on c1, and the plan for the retro play is to unpromote wSb2 on f8 and retract the resulting wP to f3 (not to f2, as sLa7 must unpromote on g1), allowing sSc4 to unpromote on e1 and letting the resulting sP uncapture on e3 a dark-squared wL, which goes to c1, permitting b2-b3 and Sb3-a1
The two knights cannot change the tempo, h2-h3 is needed at the end, and d3-d4 would prevent a white rook to get home to h1, so we can determine which camp starts the retroplay (2019-11-11)
comment
Keywords: Whose move?
Genre: Retro
FEN: rRbB4/bBqpp1p1/1krp4/2p5/K1n1P3/RP4PP/pNPP4/n7
Reprints: 329 Europe Echecs 225/226 10/1977
feenschach 41 01-03/1978
632 FIDE Album 1974-1976 1980
(2) Die Schwalbe 103 02/1987
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2019-11-12 more...
49 - P0001571
Marko Klasinc
Matjas Zigman

1649 feenschach 30 10/1975
1. Preis e.a.
P0001571
(12+15)
Welches war der erste und letzte Zug des fehlenden Turms?
R: 1. Th5-h1 c7-c6 2. h2xBg3 g4-g3 3. Tc5-h5 g5-g4 4. Sf5-e7 Te7-f7 5. Se3-f5 Lh5-e8 6. Kf1-e1 Te8-e7 7. Kg1-f1 Ta8-e8 8. Sf1-e3 Db1-a2 9. Ld6-f8 Ka2-a3 10. Le5-d6 Dc1-b1 11. Ld4-e5 a3xTb2 12. Tb1-b2+ a4-a3 13. Se3-f1 Da3-c1+ 14. Tf1-b1 a5-a4 15. 0-0
Erster Zug: 0-0, letzter Zug: Tb1-b2+
play all play one stop play next play all
Henrik Juel: The further retroplay includes something like
-33.Da3-b4 Ka2-b1 -34.Dc1-a3+ to get wD home, then wL to c1, and b2-b3 (2020-03-06)
comment
Keywords: Castling (wk), First Move?, Last Move?
Genre: Retro
FEN: 4bBnQ/3pNrbr/2p1pp1p/8/8/kPP3P1/qppPPPP1/n3K2R
Reprints: feenschach 37 01-03/1977
634 FIDE Album 1974-1976 1980
441 Europe Echecs 313 01/1985
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2002-06-08 more...
50 - P0001576
Alexander Kislyak
446 Europe Echecs 316 04/1985
T. R. Dawson et W. Hundsdorfer zum Gedenken
P0001576
(13+11)
Konnte die Stellung ohne Schach dem sK erreicht werden?
Henrik Juel: Solution: Yes, the bK may never have been checked. -1.Bc4 b6 -2.Bb5 Bb7 -3.Ba6 Bc8 -4.Bb7 Rh2 -5.Ba8 Rh1 -6.B=a7 Rh2 -7.a6 a7xR -8.Rb3 Rh1 -9.Rg3 Bb7 -10.Bh2 Rb1 -11.Bg1 Rb3 -12.Re3 Bc8 -13.Re1 Rg3 -14.Bh2 Bb7 -15.Rh1 Bc8 -16.Bg1 Rb3 -17.Rh2 Rb8 -18.Rh1 b7xB -19.Bb5 Ra8 -20.Bf1 Rb8 -21.e2 Ke4 etc. Two screens on g3 help replacing bR by wR in the SE corner. (2003-05-15)
hans: NO,you can't retrack bK without a check. f7-f6 to let bK out makes Bf8 useless! (2010-05-18)
Henrik Juel: I only see your comment now, Hans, and I agree
Early in the game Sd6+ e7xd6 happened (2019-01-07)
Henrik Juel: The real content of this excellent retro is how to resolve the position, but the author chose to frame it with a question that fooled me some 16 years ago
Here is another tricky question he might have asked:
For which black pawn can the exact play not be deduced? (2019-01-08)
Henrik Juel: The black pawns played
a7xTb6-b5, b7xLc6, e7xSd6, and the rest never moved, except for [Pf7], which played f7-f6 or, if [Pb2] had already captured TLS to reach e5, ready for an ep capture, f7-f5 (2019-01-09)
comment
Keywords: Promotion, Volet Pawn
Genre: Retro
FEN: b3NqRQ/2pp1nPp/2pp1K2/1p6/4Pk2/7P/B1PP1PP1/6Br
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-08 more...
51 - P0001763
Philippe Leroy
Phénix 1989
To the memory of Jean Bertin
P0001763
(14+14)
#1
Andersen-Eröffnung 1. a3
1. Txd7#
R: 1. ... Td1xDd2 2. Dc2-d2 Td2-e2 3. Se2-c1 Tc1-d1 4. Sf4-e2 Td1-c1 5. Sd5-f4 Tc1-d1 6. Sb4-d5 Td1-c1 7. Te8-e7 Tc1-d1 8. Ld6-f8 Td1-c1 9. Th8-e8 Tc1-d1 10. h7-h8=T Td1-c1 11. h6-h7 Tc1-d1 12. g5xSh6 Sg4-h6 13. Lf4-d6 Se5-g4 14. Sd5-b4 Sc6-e5 15. Le5-f4 Sb4-c6 16. Dd1-c2 Sc2-b4 17. Dg4-d1 Td1-c1 18. Tc1-b1 Sb4-c2 19. Lb1-a2 Sa6-b4 20. Lc2-b1 Sb4-a6 21. Tb1-c1 Tc1-d1 22. Ld1-c2 Sc2-b4 23. Le2-d1 Td1-c1 24. Tc1-b1 Ka2-a3 25. Sf4-d5 Sb4-c2 26. Sc2-a1 Sc6-b4 27. Sh3-f4 Ka3-a2 28. Sb4-c2 Se7-c6 29. Tc2-c1 Ta1-d1 30. Sd5-b4 Ka2-a3 31. Df4-g4 Kb1-a2 32. Lg4-e2 Ta4-a1 33. Df3-f4 Tb4-a4 34. a4xDb5 Ka2-b1 35. Tc1-c2 Db6-b5 36. Dd1-f3 Dd8-b6 37. Dc2-d1 Tb6-b4 38. Lf3-g4 Ta6-b6 39. Le2-f3 Ta8-a6 40. Kb4-c3 a7-a5 41. Kb5-b4 Td1-d2 42. Lf4-e5 Ka3-a2 43. g4-g5 Lb4-e1 44. Sc3-d5 Tg1-d1 45. Se4-c3 Tg3-g1 46. Th1-c1 Sg8-e7 47. Lf1-e2 Lf8-b4 48. Dd1-c2 Tf3-g3 49. c2-c4 Sc4-b2 50. Sg1-h3 Sa5-c4 51. Kc4-b5 Sc6-a5 52. Kc3-c4 Sb8-c6 53. Kd2-c3 Kb4-a3 54. Ke1-d2 c4xTd3 55. b2-b3 c5-c4 56. e2-e3 c7-c5 57. Lc1-f4 Tf6-f3 58. Ta3-d3 Th6-f6 59. Sc3-e4 Kc5-b4 60. d2-d4 Kd6-c5 61. Ta1-a3 Th8-h6 62. Sb1-c3 Ke7-d6 63. g3-g4 Ke8-e7 64. g2-g3 e7-e6 65. a3-a4 h7-h5 66. a2-a3
play all play one stop play next play all
Die Steine wKc3, wBb3c4d5e3f2, sTd2, sLe1, sSb2, sBd3 sind innerhalb des südlichen Käfigs besonders verklemmt. Der wBb5 darf erst dann nach a4 zurückschlagen, wenn ein sT aus dem südlichen Käfig befreit worden ist.
Ein stark verklemmter Käfig, der nur mit langwierigen Manövern aufzulösen ist, allerdings erkauft durch eine sehr starke Zusatzbedingung (1. Zug des wBa2 war a2-a3, was wohl vorrangig dem Ausschluß der Rücknahme a2xb3 dient).
Die auf h8 zu entwandelnde Figur ist nicht eindeutig bestimmt, statt des wT könnte dort auch ein wS entwandeln.
Pascal Wassong: The author of this problem is Philippe Leroy.
The stipulation adds : Anderssen beginning : 1.a3.
It is dedicated to the memory of Jean Bertin. (2002-09-11)
Hans-Jürgen Manthey: die Abspielvariante hat einige Fehler, zB 23.Tc1-d1
Lösung mit 1.a2-a3:
R: 1.Td1xDd2 Dc2-d2 2.Td2-e2+ Se2-c1 3.Tc1-d1 Sf4-e2 4.Td1-c1 Sg6-f4 5.Tc1-d1 Sh8-g6 6.Td1-c1 h7-h8S 7.Tc1-d1 g6xSh7 8.Td1-c1 Tc1-b1 9.Sf6-h7 Tb1-c1 10.Se8-f6 Tc1-b1 11.Sc7-e8 Tb1-c1 12.Sa6-c7 Tc1-b1 13.Sb4-a6 Tb1-c1 14.Tc1-d1 Dd1-c2 15.Sc2-b4+ Dg4-d1 16.Td1-c1 Tc1-b1 17.Sb4-c2 Lb1-a2 18.Ka2-a3 Lc2-b1+ 19.Sc6-b4 Tb1-c1 20.Tc1-d1 Dg3-g4 21.Sb4-c6 Ld1-c2 22.Sc2-b4+ Lg4-d1 23.Td1-c1 Tc1-b1 24.Sb4-c2 Sc2-a1 25.Sc6-b4 Dg1-g3 26.Ka3-a2 Sb4-c2+ 27.Sb8-c6 Tc2-c1 28.Ta1-d1 Sc6-b4 29.Ka2-a3 Se5-c6 30.Kb1-a2 Sf3-e5 31.Ta4-a1 Df1-g1 32.Tb4-a4 a4xDb5 33.Dc6-b5 Sg1-f3 34.Tb6-b4 Lf3-g4 35.Ta6-b6 Lg2-f3 36.Ta8-a6 Kb4-c3 37.a7-a5+ Ka3-b4 38.Td1-d2 Sf3-g1 39.La5-e1 De2-f1 40.Ld8-a5 Lh3-g2 41.Tg1-d1 Kb4-a3 42.Ka2-b1 Kc3-b4 43.Ka3-a2 Kd2-c3 44.Kb4-a3 Tc1-c2 45.Ka5-b4 g5-g6 46.Kb6-a5 c2-c4 47.Tb4-b1 Te8-e7 48.Kc7-b6 Ke1-d2 49.Sc4-b2 La3-f8 50.Le7-d8 Th8-e8 51.Lf8-e7 Th6-h8 52.Kd8-c7 Tf6-h6 53.Ke8-d8 Sd2-f3 54.Dc7-c6 Tf3-f6 55.Tf4-g4 Tg3-f3 56.Dd8-c7 Ta1-c1 57.Sd6-c4 Tg1-g3 58.c4xSd3 Dd1-e2 59.Tf6-f4 Se5-d3 60.Th6-f6 Sf3-e5 61.Th8-h6 Th1-g1 62.Sf5-d6 Lf1-h3 63.Sh6-f5 Lc1-a3 64.Sg8-h6 a3-a4 65.c5-c4 Sg1-f3 66.c7-c5 e2-e3 67.h7-h5 g4-g5 68.Lb4-f8 g2-g4 69.Ld6-b4 Sb1-d2 70.Le7-d6 b2-b3 71.Lf8-e7 d2-d4 72.e7-e6 a2-a3 (2020-03-24)
Henrik Juel: Thanks for posting a correct retro-play, Hans-Jürgen
Now a super-user can relatively easily change the official solution, so the rest of us can watch the animation
Another time you can make it even easier by having a space after each . (this is required for the animation to work). Also, I believe that most users prefer the convention n. [white retraction] [black retraction]
For this problem
R: 1. ... Td1xDd2 2. Dc2-d2 Td2-e2+ etc. (2020-03-24)
Hans-Jürgen Manthey: Henrik Juel verstanding 1. Td1xDd2 usw. and not 1.Td1xDd2 (2020-03-25)
comment
Keywords: Whose move?
Genre: Retro
FEN: 2b2B2/1p1pRpp1/4p3/pP5p/2PP4/kPKpP3/Bn1rrP1P/NRN1b3
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-03-25 more...
52 - P0001884
Thomas R. Dawson
Aachener Anzeiger 1926
P0001884
(8+2)
#1 vor 2
VRZ, Typ Hoeg
R: 1. c7-c8=D Lb4xSa3 2. Sc5-a6, dann 1. Sb3#
R: 1. c7-c8=D Lc5xSa3 2. Sb4-a6, dann 1. Sc2#
play all play one stop play next play all
klären: Quelle: Schach ohne Grenzen, S.35, Nr.3 = Magyar Sakkvilag, 1926 (VF)
Henrik Juel: -1.Q=c7 Bb4:S -2.Sc5, 1.Sb3#; -1.. Bc5:S -2.Sb4, 1.4Sc2#. It is illegal to supplement a checking bS on a6. (2003-10-09)
Sally: Weiß nimmt c7-c8D zurück. Nimmt Schwarz Lb4-a3 zurück, so ergänzt Weiß auf a3 einen Springer und nimmt Sc5-a6 zurück, um durch Sb3#. Nimmt Schwarz Lc5-a3 zurück, so ergänzt Weiß auf a3 wieder einen Springer und nimmt Sb4-a6 zurück, um durch Sc2 mattzusetzen. (2012-02-21)
Henrik Juel: Also 'On Retraction Chess Problems' gives Magyar Sakkvilag as original source (2019-02-10)
comment
Keywords: Promotion, Defensive Retractor, Defensive Retractor, Type Høeg
Genre: Retro
FEN: 1KQ5/8/N2P4/8/8/b7/PP6/kBB5
Reprints: 127 Magyar Sakkvilag 04/1926
(31) On Retraction Chess Problems 1927
3 Chess unlimited , p. 35, 1969
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-02-12 more...
53 - P0001914
Roland Baier
Johannes M. Ott

3721 Mat (Belgrade) 11-12/1982
M. Kovacevic gewidmet
1. ehrende Erwähnung
P0001914
(12+13) C+
BP in 18,5
1. h4 f5 2. h5 Kf7 3. h6 Kf6 4. hxg7 h5 5. Th4 Sh6 6. Ta4 h4 7. g8=D h3 8. Df7+ Kg5 9. De8 h2 10. Dxd8 h1=S 11. Dxc8 Sxf2 12. De8 Sxd1 13. Df7 Sxb2 14. Db3 Sxa4 15. La3 f4 16. Db2 Sf5 17. Dc1 Th1 18. Dd1 Kh4 19. Lc1
play all play one stop play next play all
Vladimir Rey: Update: 3721 Mat (Belgrade) 11-12/1982, M. Kovacevic gewidmet (2020-04-15)
comment
Keywords: Unique Proof Game, Homebase (W), Promotion, Pronkin Theme (D), under-promotion (s), Non-standard material
Genre: Retro
Computer test: Natch 2.2 Copyright (C) 1997,98,99,2001,2002,2003 Pascal Wassong
FEN: rn3b2/ppppp3/8/5n2/n4p1k/8/P1PPP1P1/RNBQKBNr
Reprints: 987 FIDE Album 1980-1982 1988
33 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2020-04-15 more...
54 - P0001945
Samuel Loyd
Texas Siftings 1888
P0001945
(2+7) C+
#3
Entweder 1. Dd4! oder 1. Dg5!
play all play one stop play next play all
Loyds Lösung:
Wenn K oder Ta8 zuletzt zogen, dann 1. Dg5 Kd8 2. Dd5+ 1. ... Kf8 2. De7+
Wenn K oder Th8 zuletzt zogen, 1. Dd4 Tg8 2. Dd7+
AB: Is this really cooked if properly declared as RV?
1 Qd4! if kside not ok, 1 Qg5! if qside not ok, and both solutions work if neither castling ok. This latter overlap is not a defect, in that both winning lines are otherwise forced. Or is there some other winning line that I am missing? (2001-10-17)
GW: The problem is indeed not cooked but C+! (2001-10-17)
Andrew Buchanan: Note also the try 1.Qc5? which is defeated by either castling. (2010-03-01)
Sally: Zwei Teilaufgaben:
1. 0 0 0 (Zulässig): 1.Dd4+ -Tg8, 2. Dd7+ -Kf8, 3.Dxe7#.
2. 0 0 (zulässig): 1.Dg5! -Kd8, 2. Dd5+ -K bel. 3.Dxa8#.
Auch wenn Ke8 zuletzt war, gibt es diese 2 Lösungen! (2010-06-26)
Adrian Storisteanu: But when Ke8 has moved, *three* solutions work, not just the two (1.Qd4/g5/c5!)!? (2019-12-31)
A.Buchanan: Under PRA (as it's more often called today) we apply the conventions to find the local maxima, where we can't apply the conventions any more. There are basically 4 possibilities: KQ, K-, -Q, --. KQ is impossible. But K- & -Q are local maxima, so we have to solve them. -- is not a local maxima: we can apply the castling convention in one of two ways, to reach K- or -Q. So we don't have to solve --. Is that ok? (2019-12-31)
A.Buchanan: To say we need a sound solution for K-, -Q & --, is analogous in a one castling situation to saying we need a sound solution for both K & -. It's not reasonable. That is where PRA in its wisdom leads us to the right cases. (2020-01-01)
comment
Keywords: Cant Castler, Partial Retro Analysis (PRA), Castling (sksg), Minimal
Genre: Retro
FEN: r3k2r/p1p1p2p/4K3/8/8/4Q3/8/8
Reprints: 64 Sam Loyd and his Chess Problems 1913
64 Sam Loyd und seine Schachaufgaben 1926
Comoedia 23/07/1933
599 Sachove umeni 25/04/1949
33 32 personaggi e 1 autore 1955
(G) Die Schwalbe 16 10/1972
Problem 152-156 04/1973
(D15) feenschach 27 04/1975
(5) Die Schwalbe 86 04/1984
(I) Die Schwalbe 234 12/2008
(1) Die Schwalbe 241 02/2010
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2016-03-30 more...
55 - P0001951
Luigi Ceriani
Karl Fabel

Am Rande des Schachbretts 1947
P0001951
(9+16)
KBP?
(AL: 183,0)
1. a4 c5 2. a5 c4 3. a6 c3 4. b3 d5 5. Lb2 cxb2 6. Sa3 Kd7 7. Sc4 Kc6 8. Se5+ Kb5 9. Ta5+ Kb4 10. Tb5+ Ka3 11. Sef3 Ka2 12. c3 d4 13. Dc1 e5 14. Kd1 e4 15. Kc2 e3 16. Kd3 g5 17. Ke4 g4 18. Kf4 d3 19. Dc2 dxc2 20. h3 c1=T 21. Th2 Ta1 22. Th1 Kb1 23. Th2 Kc1 24. Th1 Lf5 25. Th2 Lb1 26. d3 f5 27. Sd2 exd2 28. Sf3 Sf6 29. Kg5 Ld6 30. Kh6 Sd5 31. Kg7 Se3 32. Kf7 h5 33. Kg7 Ta4 34. Kf7 La2 35. Tb6 d1=L 36. Kg7 Lc2 37. Kf7 Lcb1 38. Kg7 Sd1 39. Kf7 g3 40. Kg7 gxh2 41. e3 h1=T 42. Le2 Sd7 43. Sh2 Sc5 44. Lg4 Se4 45. Kf7 hxg4 46. Kg7 g3 47. Kf7 gxh2 48. Kg7 Te1 49. Kf7 Te2 50. Kg7 Tc2 51. Kf7 h1=T 52. Kg7 Te1 53. Kf7 Lh2 54. Kg7 Sg3 55. Kf7 Sh1 56. Kg7 Tah4 57. Kf7 Kd2 58. Kg7 Ke2 59. Kf7 Tc1 60. Kg7 Lc2 61. Kf7 Ta1 62. Kg7 Lab1 63. Kf7 Ta5 64. Kg7 La2 65. g3 Kf3 66. Tb4 Tb5 67. Kf7 Te2 68. Kg7 Lcb1 69. Kf7 Tc2 70. Kg7 Tc1 71. Kf7 Lc2 72. Kg7 Ta1 73. Kf7 Lab1 74. Kg7 Ta5 75. Ta4 bxa6 76. Ta1 La2 77. Tc1 Lcb1 78. Tc2 f4 79. Te2 Lc2 80. Te1 Lab1 81. Tg1 Ta1 82. Tg2 La2 83. Kf7 Tc1 84. Kg7 Lcb1 85. Kf7 Tc2 86. Kg7 Te2 87. Kf7 Te1 88. Kg7 Tg1 89. Kf7 Lc2 90. Kg7 Lab1 91. Kf7 Ta5 92. Kg7 Ta1 93. Kf7 La2 94. Kg7 Tc1 95. Kf7 Lcb1 96. Kg7 Tc2 97. Kf7 Te2 98. Kg7 Tee1 99. Kf7 Tef1 100. Kg7 Lc2 101. Kf7 Lab1 102. Kg7 a5 103. Kf7 a4 104. Kg7 a3 105. Kf7 a2 106. Kg7 a1=T 107. Kf7 La2 108. Kg7 Tc1 109. Kf7 Lcb1 110. Kg7 Tc2 111. Kf7 Te2 112. Kg7 Tee1 113. Kf7 Lc2 114. Kg7 Lab1 115. Kf7 a5 116. Kg7 a4 117. Kf7 a3 118. Kg7 a2 119. Kf7 a1=T 120. Kg7 La2 121. Kf7 Tc1 122. Kg7 Lcb1 123. Kf7 Tc2 124. Kg7 Ke2 125. Kf7 Kd2 126. Kg7 Kc1 127. Kf7 Tce2 128. Kg7 Kd2 129. Kf7 Lc2 130. Kg7 Lab1 131. Kf7 Ta1 132. Kg7 La2 133. Kf7 Tc1 134. Kg7 Lcb1 135. Kf7 Tc2 136. Kg7 Kc1 137. Kf7 Tcd2 138. Kg7 Lc2 139. Kf7 Kb1 140. Kg7 Ka1 141. Kf7 Lab1 142. Kg7 Ka2 143. Kf7 Ka3 144. Kg7 La2 145. Kf7 Lcb1 146. Kg7 Tc2 147. Kf7 Tc1 148. Kg7 Lc2 149. Kf7 Ta1 150. Kg7 Lcb1 151. Kf7 Tc2 152. Kg7 Dd5 153. Kf6 Df3 154. Kf7 De2 155. Kg7 Dd2 156. Kf7 Dc1 157. Kg7 Tce2 158. Kf7 Dd2 159. Kg7 Lc2 160. Kf7 Tc1 161. Kg7 Lcb1 162. Kf7 Tc2 163. Kg7 Dc1 164. Kf7 Tcd2 165. Kg7 f3 166. Kf7 Lc2 167. Kg7 Da1 168. Kf7 Lcb1 169. Kg7 Tc2 170. Kf7 Tc1 171. Kg7 Lc2 172. Kf7 Lab1 173. Kg7 Ka2 174. Kf7 Ted2 175. Ke7 Tee2 176. Kd7 Tfe1 177. Kc7 Tgf1 178. Kb7 Lg1 179. Ka7 T4h6 180. Th2 Tb6 181. Tg2 Th7+ 182. Ka8 Thb7 183. Th2 Tb8+
play all play one stop play next play all
Yoav Ben-Zvi: The Move Length Record has been surpassed, after more than 70 years, by Goldsteen, see P1345778. (2019-07-07)
more ...
comment
Keywords: Non-Unique Proof Game, konsekutive Umwandlungen 6 (tltttt), Non-standard material, under-promotion, Move Length Record
Genre: Retro
FEN: Kr6/8/1r6/8/8/1PPPPpPP/kpbrrP1R/qbrnrrbn
Reprints: 127 32 personaggi e 1 autore 1955
1438 FIDE Album 1945-1955 1964
Die Schwalbe 3, p. 81, 02/1970
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-06-13 more...
56 - P0001964
Poul Anker Rasch Nielsen
5705 Skakbladet 02/1946
Dr. N. Høeg zum 70. Geburtstag
P0001964
(2+1) cooked
Hilfs-Subretropatt vor 2 Zügen
R: 1. Kh2xTh1 Td1xTh1 2. Kg1xTh2 0-0-0+ (einziger legaler Rückzug nun) 3. g2xSh1=T
play all play one stop play next play all
Cook: (Mario Richter & rawbats):
R: 1. Kg2xTh1 h2-h3 2. Kf2xBg2 Kd2-c1 (einziger legaler Rückzug nun) 3. Kf1xLf2
wegen der Forderung s. P1366564

N. Høeg: "Noget af det smukkeste, jeg har set paa Skakbrættet; at en Stilling med 3 Brikker kan skjule saa nydeligt og genialt et Indhold, er forbavsende." [Eine der schönsten Aufgaben, die ich auf dem Schachbrett gesehen habe; es ist erstaunlich, dass eine Stellung mit drei Steinen einen so schönen und brillanten Inhalt verbergen kann.]
Henrik Juel: In the stipulation, the word 'retropatt' is incorrect. It should be 'sub-retropatt', meaning that Black has just one legal retraction, which is g2xSh1=T. (2003-02-21)
Mario Richter: Inspired by Henrik's question (s. P1366564) I let my program 'rawbats' make some tests, and it claims that there is at least one alternative solution: R: 1. Kg2xTh1 h2-h3 2. Kf2xB(auer)f2 Kd2-c1 (with the only legal retraction now being 3. Kf1xLf2 (which reminds me of P0000454).
If Henrik can confirm the correctness of the claim, the problem should be labeled "cooked". (2019-08-23)
Henrik Juel: It is certainly a nice solution (2. Kf2xBg2, not Bf2)
Well done, rawbats
I am uncertain whether the 'Hultberg conditions' were meant to exclude a solution like this, which involves retracting into a check, but I would consider it a cook (or a second solution...), because the only black retraction is not an uncheck (2019-08-23)
Henrik Juel: I found Høeg's presentation of subretrostalemate in Skakbladet 07/1945 p.107
http://www.skak.dk/images/skakbladet/1945/1945-07.pdf
(I was born before 07/1945, so I should have known...)
The 'Hultberg conditions' are a misnomer, because they are included in Høeg's definition
Much as I admire Niels Høeg's contributions, I find that a stipulation which includes two exceptions is rather dubious
Apparently subretrostalemate problems only appeared for less than a year, and only in Skakbladet; in his seminal work 'Der Blick zurück' Wolfgang Dittmann does not mention them
Høeg' presentation includes two examples, one of which is cooked, and the other is very simple:
Diagram: wKc3, sKf3 (1+1); Help-subretrostalemate in 2
-1.Ke2xTf3 Kc2-c3 -2.Ke1xDe2 Dg2xPe2 allowing -3.e3-e2 only (2019-08-23)
Mario Richter: Since the "official" solution starts with a self-check (Kh2xTh1), it would make the stipulation even more "dubious", as Henrik put it, if self-checks were allowed in the retractions leading to the subretrostalemate position, but not in that position itself.
Conclusion: there is a second solution (in the meantime, rawbats has finished its investigation [computation time 9 hours 46 min]), and it is the only one rawbats found, so a possible correction could be to simply add "2 solutions". (2019-08-24)
Mario Richter: Just to make the literature list a little bit more complete: Høeg's presentation of retrostalemate can be found in Skakbladet 01/1939 p.10ff (2019-08-24)
Henrik Juel: Thanks, Mario
The result of the mini-tourney is in Skakbladet 04/1939 p.67-68
Most of the retrostalemate problems were cooked, but not IV (which is already in the PDB) and I (which is a nice introduction to the genre)
I particularly like the tricky retractor A, which also ought to be in the PDB... (2019-08-24)
Mario Richter: Done, s. P1366626 (2019-08-24)
Henrik Juel: Thanks, Mario; is retrostalemate I also in the PDB? (2019-08-24)
Mario Richter: Now it is - s. P1366629 (2019-08-24)
Henrik Juel: Thank you again (2019-08-24)
comment
Keywords: Help retractor, Castling in the retro play (wg), Kindergarten Problem, Rex solus (s), Promotion in the retro play (t)
Genre: Retro
FEN: 8/8/8/8/8/7P/8/2K4k
Reprints: 1423 FIDE Album 1945-1955 1964
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-08-30 more...
57 - P0001972
Thomas R. Dawson
Pittsburgh Post 1923
P0001972
(16+11)
h#1
1. cxd3ep Kd4#

R: 1. d2-d4 Tf5-f6 2. Sf6-g4+ Td5-f5 3. Sf5-h4+ Td3-d5
play all play one stop play next play all
Cook: Henrik Juel (2005-2-18): R: 1. Le5-g3 Tf5-f6 2. Lf6-e5+ Td5-f5 3. d2-d4 Td3-d5 etc.
auch in der Zeitschrift 'The Chess Problem' exakt mit dieser Stellung nachgedruckt, als Quelle ist dort (in der Rubrik "Selected From Early Days") genannt: "Italia Scac. 1917".

Falls tatsächlich ein Druckfehler vorliegt, und der wLg3 nach f2 gehört, scheint er sich weit verbreitet zu haben ...
Henrik Juel: 0... cxd3ep 1.Kd4#. -1.d2 Tf5 -2.Sf6 Td5 -3.Sf5 Td3 etc. (2004-03-18)
Henrik Juel: The problem is incorrect, because the retroplay could also be -1.Le5 Tf5 -2.Lf6 Td5 etc. (2005-02-18)
Mario Richter: Since there's also the even more trivial retroplay 0. ... f2-f3 Tf5-f6 1. Sf6-g4+ Tf3-f5 2. Sf5-h4+, my guess is, that the diagram is misprinted and that the wLg3 should be placed on f2. Doing so, the ep-key is justified, because in this case White's last move must have been d2-d4 (to provide d3 as a square for the black rook). (2011-08-19)
Mario Richter: A sin from my youth - today I do not see how the retroplay can be continued after 0. ... f2-f3 Tf5-f6 1. Sf6-g4+ Tf3-f5 2. Sf5-h4+ ???
So Henrik's cook is the only one, but I still think that my suggested correction is valid. (2019-10-18)
A.Buchanan: I agree with Mario. And it feels like a bug rather than a typo. This problem does not appear in WinChloe, either in source or number of pieces, so I can't check. (2019-10-19)
comment
Keywords: En passant, Last Moves?, Retro Opposition, En passant as key
Genre: h#, Retro
FEN: 3R2n1/p2PPprP/P2pkrRq/2P3pp/2pPK1NN/4QPBB/6P1/8
Reprints: The Chess Problem (Whitburn)
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2019-10-18 more...
58 - P0002008
Frideswide F. Rowland
Leeds Mercury 12/12/1896
P0002008
(12+4)
#2
-sBb5, dann (a) 1. Ka4 droht 2. Sa5#
play all play one stop play next play all
Die Stellung ist wegen eines fehlenden schwarzen Schlagobjekts illegal. Weiß hat im letzten Zugep geschlagen und dabei vergessen, den sBb5 vom Brett zu nehmen.
A.Buchanan: This one involves the completion of the *penultimate* move (ep), after which Black played Rxe5+. wPh2 is superfluous. (2020-02-10)
comment
Keywords: En passant, Illegal position, Joke, Finish or retract an unfinished move
Genre: Retro
FEN: 6B1/7p/PPP5/Kp1r4/2k5/BNP5/P1PP3P/8
Reprints: 8 Retrograde Analysis 1915
67 Fern vom Alltag 1925
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-02-10 more...
59 - P0002033
Niels Høeg
Tidskrift för Schack 03/1904
P0002033
(15+12)
1) Welches waren die letzten 3 Züge von Weiß?
2) Statt dessen zieht Weiß und setzt in drei Zügen auf e8 mat
R: 1. e7xDf8=T# Kd8-e8 2. d6xSe7+ Sd5-e7+ 3. Df7-f6+
play all play one stop play next play all
Tg8 is the white a-rook, Tc7 is the black h-rook, and both passed g3 or g4 before the barrier was closed. The black a-rook was captured on a8 or b8, the white h-rook was captured south-west of the barrier.
The try R: 1.Tf7xDf8# Kd8-e8 2.Te7-f7+ Ke8-d8 3.Tf7-e7+ fails because of perpetual uncheck.
translation:
1) What were White's last 3 moves?
2) Instead of these moves, White mates in 3 on e8

Zusammen mit P0002034 als Mini-Preislösungsturnier abgedruckt.
Henrik Juel: The intention for part 2 of the stipulation is probably 1.Dxd7+ Lxd7 2.Txf8+ Le8 3.Txf8#
But this part is silly and almost surely not due to Høeg; it may have been added by the editor of 150 Schachkuriositäten in an attempt to make Høeg's problem curiousser...
Part 2 is not mentioned in Retrograde Analysis
I suggest that you delete part 2 again, Andrew; sorry about your wasted effort (2020-04-28)
Mario Richter: The original publication has both parts of stipulation exactly as given here. Perhaps the superflous part 2) was omitted in 'Retrograde Analysis' to let the problem appear more serious ... (2020-04-28)
Henrik Juel: Thank you Mario, that settles the question, and problem should stay as it is now in the PDB
But it is interesting that part 2 was also omitted in an article in Aarsskrift 1935 by Knud Hannemann on barriers in retro-analysis
Maybe we should blame the editor of Tidskrift för Schack, who may have wanted identical stipulations for his mini solving tourney; in P0002034 the forward stipulation #3 works fine (the promotion dual to DL was not considered a flaw then), whereas here the silly condition of mate on e8 is needed to reach #3 (2020-04-28)
Henrik Juel: There is another try for the retroplay:
R: 1.Tf7xSf8# Sh7-f8+ 2.Th8xDg8+ (or 2.Th8xSg8+)
It fails because we cannot explain the two white rooks, as an unpromotion of one of them would require two white pawn captures (cxdxe), but only one is possible now (2020-04-28)
Henrik Juel: Now I regret blaming innocent editors
Around 1900 retractors (with backward and forward play) were in high fashion
It was only with the advent of Retrograde Analysis in 1915 that pure retro-analysis (without forward play) also became acceptable for the general chess problem community (2020-04-28)
more ...
comment
Keywords: Last Moves? (5), Promotion, Constrained problem
Genre: Retro
FEN: 1bb1kRR1/pprp2p1/2B1pQKp/P1p1Np1N/5P2/6PP/1P1PP3/2B5
Reprints: 50 150 Schachkuriositäten 1910
21A Retrograde Analysis 1915
2 Aarsskrift DSK , p. 17, 1935
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-04-28 more...
60 - P0002049
Steiner
Aachener Anzeiger 08/1912
P0002049
(16+13)
Nehme einen Zug zurück, dann #1
R: 1. 0-0, dann 1. 0-0-0#
play all play one stop play next play all
vgl. P1317143
Henrik Juel: -1.0-0, 1.0-0-0#. (2004-03-08)
Henrik Juel: The uncastling is forced, allowing -1... Dh2 to avoid retro-stalemate (2020-04-16)
Henrik Juel: The Retrograde Analysis reprint gives S. Steiner as author and Magyar Sakkujsag as source (2020-04-16)
comment
Keywords: Castling in the retro play (wk), Help retractor, Castling in the forward play (wg)
Genre: Retro
FEN: 8/2pppp2/1p4p1/p4P1p/3PPQbr/PP1kBBrq/1PN1NPP1/R4RK1
Reprints: 29 Retrograde Analysis 1915
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-04-15 more...
61 - P0002092
Karl Portius
35 Leipziger Illustrirte Zeitung 24/08/1844
P0002092
(5+6)
#2
1. gxf6ep+ Ke8 2. Sd6#
Der En passant-Schlag kann nicht begründet werden.
play all play one stop play next play all
Erschien mit folgendem Begelttext:
In einem Club spielten zwei mittelmäßige Spieler mit einander, als derjenige, der die Weißen hatte, ausrief: "Wenn Sie so ziehen, werden Sie gleich Matt." Bei diesen Worten trat der Präsident des Clubs, ein berühmter Meister, an das Schachbrett und erklärte: Weiß könne unmöglich Matt geben. Weiß ließ sich aber nicht stören, zog und setzte mit dem zweiten Zuge Matt; und der Herr Präsident konnte weiter nichts sagen als "Ah, so!"
In a club, two mediocre players were playing with each other when White exclaimed: "If you move like this, you'll mated." With these words, the president of the club, a famous master, stepped up to the chess board and said: White couldn't possibly Mate. White did not allow himself to be disturbed, however, and moved and mated Black on the second move; and the Mr. President could say nothing more than "Oh I see!"

from Dawson & Hunsdorfer, 1915:
"The actual origin of the en passant analytic is not certain. Way back in 1944, a year before the publication of the Indian problem, old Portius, the genial editor of the Leipzig Illustrated, published No. 53A [this problem] in connection with one of his chess tales. It is simply a trick problem, quite free of any thought of analysis, but we quote it for its historical significant. It set solvers' brains in action, and suggested the possibility of an analytic en passant key. [...] No. 53 [P0001360, 1858] fourteen years after No. 53A, is analytically sound, but unfortunately unidentified." [Author now known to be Max Lange.]
So this is a joke rather than cooked.
Henrik Juel: From the story we know that White can mate in two
this is possible only if last move was f7-f5
then C+ by Popeye 4.61 (2017-09-09)
A.Buchanan: These days this would be regarded as a constrained problem, rather than a joke. wLg4 serves no purpose, as far as I can see. (2020-02-10)
comment
Keywords: En passant, Joke (en passant), Constrained problem (mate exists)
Genre: Retro
FEN: 3n1n2/3bk3/4p2N/5pP1/4N1B1/5K2/8/8
Reprints: 53A Retrograde Analysis 1915
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-02-10 more...
62 - P0002105
Walter Irving Kennard
The Illustrated London News 27/12/1890
P0002105
(9+4)
#3
1. bxc6ep! g6 2. c7 g5 3. c8=S#
1. ... g5 2. Kc4 Kxa6 3. Kc5#
play all play one stop play next play all
Henrik Juel: C+ by Popeye 4.61 (2020-04-02)
more ...
comment
Keywords: En passant, En passant as key, under-promotion (S), Promotion in the mating move
Genre: Retro
FEN: 8/p5p1/Pk1P4/NPpKP3/6P1/1N6/4B3/8
Reprints: 61 Retrograde Analysis 1915
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2020-04-02 more...
63 - P0002178
Niels Høeg
Deutsches Wochenschach 02/06/1907
P0002178
(14+11)
#3 (RV)
1) R: 1. f7-f5: 1. gxf6ep Txa1 2. Sg7+, 1. ... Txh5+ 2. Dxh5+
2) R: 1. d7-d5: 1. cxd6ep Ta5+ 2. Txa5
3) R: 1. T-a8: 1. Sg6
4) R: 1. T-h8: 1. Sc6
5) R: 1. K-e8: 1. Sg6/1. Sc6
play all play one stop play next play all
Henrik Juel: The solution text above should be construed to sit in two columns, reading: If last move was f7-f5, White mates in three by 1.gxf6ep Txa1 2.Sg7+, 1... Txh5+ 2.Dxh5+; if last move was d7-d5, White mates in three by 1.cxd6ep Ta5+ 2.Txa5; etc. (2004-04-26)
Henrik Juel: The pawn captures were
White: axb, d4xc5, fxe, hxg (plus one capture with an officer)
Black: b3xc2 (and possible one more, but not with Pc4)
so last move was not b5xc4 (2019-08-22)
comment
Keywords: En passant, Partial Retro Analysis (PRA), Castling (sksg)
Genre: Retro
FEN: r3k2r/4N3/1P2P3/2PpKpPN/2p1p1p1/1PP1n3/2p1P1P1/R2b1B1Q
Reprints: The Chess Amateur 11, p. 340, 08/1907
99 Retrograde Analysis 1915
34 32 personaggi e 1 autore 1955
(D) Die Schwalbe 13 02/1972
RA65 diagrammes 27 05-06/1977
(19) Die Schwalbe 68 04/1981
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2019-08-29 more...
64 - P0002213
Anders Olson
Kjell Widlert

7818 Springaren 57 06/1994
P0002213
(2+1)
h-retro-#5
Circe RI
Weiß beginnt
paul: 1. – Ke7xBf8 2.Bg7-f8 Sd6xPf7 3.Bh8-g7 Kd8xRe7 4.Bg7-h8 Kd7xQd8 5.Bf8-g7 Kc6xPd7 & 1.Kxb5(Ke8)#

But cooked:

1. - Ke8-f8 2.Ka4-b5 Sd8-f7 3.Ka3-a4 Sb7xQd8 4.Qd1-d8 Kf8-e8 5.Qh1xQd1 Ke8-f8 & 1.Qb3#

(information obtained from Kjell Widlert) (2018-12-15)
comment
Keywords: Help retractor, Circe, Aristocrat, Rex solus (s)
Genre: Retro, Fairies
FEN: 5K2/5N2/8/1k6/8/8/8/8
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2018-12-06 more...
65 - P0002215
Ronald Turnbull
The Problemist 14 07/1994
P0002215
(4+4)
h#2
Fuddled Men
Ceriani Ethics
b) from mating position of a)
a) 1. Ka3 Lf8 2. Tb2 Lg8#
b) 1. Tb4 Lg7 2. Kb2+ Lc4#
play all play one stop play next play all
Author's solution:
"Ceriani Ethics": In the diagram, each piece must be considered as potentially retaining all its powers.
a) Black is in check. 1.Ka3 Bf8 2.Rb2 Bg8.
b) Again, Black is in check. 1.Rb4 Bg7 2.Kb2+ (check to wK from reviving bR!) Bc4. Such paradoxical stipulations have been the subject of an article Quantum Fairies by Peter Fayers and me.
In each twin, the actual past is forgotten, which explains any paradox.
a) we forget that bK can't move (to run away to b1 or c2) at the end of b).
b) we forget that bR can't move (to block on b4) at the end of a).
A.Buchanan: The chess is clear, but I don't really understand the meaning of "Ceriani Ethics" (a kind of PRA?). How would this problem break if the stipulation was under RS rather than PRA? This is so annoyingly vague. (2019-10-08)
comment
Keywords: Fuddled Men, Partial Retro Analysis (PRA)
Genre: h#, Retro, Fairies
FEN: 7r/6B1/8/8/prB3K1/8/1k6/2N5
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-10-15 more...
66 - P0002247
Michel Caillaud
Mat (Belgrade) 1982
2. ehrende Erwähnung
P0002247
(13+15) C+
BP in 27,0
1. b4 Sc6 2. b5 Se5 3. b6 c6 4. bxa7 Db6 5. Sc3 Db1 6. a4 b5 7. a5 Lb7 8. a6 0-0-0 9. a8=S Sh6 10. Sc7 Sf5 11. Se6 h6 12. Sg5 hxg5 13. a7 Th3 14. a8=S Td3 15. Sc7 La8 16. Se8 Kb7 17. Sd6+ exd6 18. h4 Le7 19. h5 Tf8 20. h6 Ld8 21. h7 Lc7 22. h8=S Lb8 23. Sg6 fxg6 24. Th4 Tf6 25. Td4 Sh4 26. e4 Sef3+ 27. Ke2 Te3+
play all play one stop play next play all
Vladimir Rey: Update: 3722 Mat (Belgrade) 11-12/1982 (2020-05-11)
comment
Keywords: Ceriani-Frolkin Theme (SSS), Unique Proof Game, Castling
Genre: Retro
Computer test: Resolution time : 4 h 17 mn 54.29 s., Natch 2.3 Copyright (C) 1997,98,99,2001,2002,2003,2004 Pascal Wassong
FEN: bb6/1k1p2p1/2pp1rp1/1p4p1/3RP2n/2N1rn2/2PPKPP1/RqBQ1BN1
Reprints: 29 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2006-01-09 more...
67 - P0002287
Geza Schweig
Tükör 1938
P0002287
(15+14) C+
BP in 4,0
1. Sc3 d6 2. Sd5 Sd7 3. Sxe7 Sdf6 4. Sxg8 Sxg8
play all play one stop play next play all
Jeff Coakley in 'The Puzzling Side of Chess': "This proof game was published in 1938 in the Budapest periodical 'Tükör' (Magyar for "mirror"). The name is often given incorrectly as 'Tukon'."
A.Buchanan: Apparently a mirror-image of Mortimer's original P0002288 (2020-05-23)
comment
Keywords: Unique Proof Game, Homebase (w), Impostor
Genre: Retro
FEN: r1bqkbnr/ppp2ppp/3p4/8/8/8/PPPPPPPP/R1BQKBNR
Reprints: 2715 FEENSCHACH 09-10/1955
Die Schwalbe 42, p. 594, 12/1976
Die Schwalbe 71 10/1981
(II) Schachkalender 1987
99 Shortest Proof Games 11/1991
18 Introduction to Proof Games 03/2010
6 The Puzzling Side of Chess 8 18/08/2012
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-05-24 more...
68 - P0002288
Ernest Clement Mortimer
Andriy Frolkin

Die Schwalbe 71 10/1981
E.Mortimer v A.Frolkin
P0002288
(15+13) C+
BP in 4,0
1. Sf3 e5 2. Sxe5 Se7 3. Sxd7 Sec6 4. Sxb8 Sxb8
play all play one stop play next play all
Version A. Frolkin. Die Originalfassung war mit sBd5 und e7.
Another version is reflected left-to-right.
YM: Possible symmetrical game:

BP in 4,0 (15+13) C+

1. Sc3 d5 2. Sxd5 Sd7 3. Sxe7 Sdf6 4. Sxg8 Sxg8

and even improved versions:

BP in 4,5 (13+15) C+

1.e3! (tempo) Sf6 2.e4 Sxe4 3.Se2 Sxd2 4.Sc3 Sxb1 5.Sxb1.

BP in 4,5 (13+15) C+

1.d3! (tempo) Sc6 2.d4 Sxd4 3.Sd2 Sxe2 4.Sf3 Sxg1 5.Sxg1. (2016-09-27)
A.Buchanan: These days, the style seems to be more common to mark as "BP in exactly 4.5", if a shorter proof game exists. (2018-10-01)
Olaf Jenkner: Isn't it anticipated by Schweig (P0002287) ? (2018-10-01)
A.Buchanan: We don't know when Mortimer published his original: but his 12 publication dates in PDB are between 1917 & 1935, while Schweig's composition is 1938.
The Imperial War Museum in UK has 4kg of private papers of Mortimer, who was a Chaplain in WW1, serving in Egypt and Palestine from 1916-1919, see https://www.iwm.org.uk/collections/item/object/1030014260. Given that overlaps with his publication career, we might see some mention of chess in these papers, to address the vexed question of this famous composition.
Mortimer was still active in 1959, when he published on Blaise Pascal 12-Feb-1959 London Methuen. See: "Catalog of Copyright Entries. Third Series: 1959: Jan-Jun".
In any case, if Mortimer anticipated Schweig, then Frolkin follows Mortimer. Otherwise, Schweig anticipated Mortimer, and Frolkin can be considered to follow Schweig. (2020-05-23)
Yoav Ben-Zvi: The position (along with its mirror image) also solves the construction task: Position with shortest possible sound SPG showing Sibling Impostor", 2 solutions. (2020-05-24)
A.Buchanan: I think there are 4 solutions to this task in 4.0 moves: this, and Schweig, and their respective mirror images. The original Mortimer (+sBd5e7, as mentioned above) wasn't sound, but maybe that wasn't what Mortimer was aiming at. There are a bunch of other SPGs in 4.0 where instead of wS raiding, its wQ or wB, e.g. rnbqkb1r/1ppp1ppp/8/4p3/8/2P5/PP1PPPPP/RNB1KBNR. But nothing shorter I think (2020-05-24)
more ...
comment
Keywords: Unique Proof Game, Homebase (2), Impostor (s)
Genre: Retro
FEN: rnbqkb1r/ppp2ppp/8/8/8/8/PPPPPPPP/RNBQKB1R
Reprints: 100 Shortest Proof Games 11/1991
(5) diagrammes 103 10-12/1992
6 Introduction to Proof Games 03/2010
06b The Puzzling Side of Chess 8 18/08/2012
72 The Puzzling Side of Chess 141 16/12/2018
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-05-23 more...
69 - P0002289
Andriy Frolkin
Andrej N. Kornilow

2235 diagrammes 92 01-03/1990
P0002289
(14+14)
BP in 21,0
1. f3 Sc6 2. Kf2 Sd4 3. Kg3 Sxe2+ 4. Kg4 Sg3 5. hxg3 Tb8 6. Th5 Ta8 7. Ta5 Tb8 8. Lb5 Ta8 9. c4 Tb8 10. Dc2 Ta8 11. Dg6 Tb8 12. d3 Ta8 13. Ld2 Tb8 14. Le1 Ta8 15. Sd2 Tb8 16. Tc1 Ta8 17. Tc3 Tb8 18. Tca3 Ta8 19. T3a4 Tb8 20. a3 Ta8 21. Lxd7+ Dxd7+
play all play one stop play next play all
Henrik Juel: Natch 3.1 tests the first 20.0 moves OK in 13 seconds, but the first 20.5 moves would take more than an hour, and the entire problem more than a couple of hours, because of the possibility of [Pd7] promoting
So we may never know for sure whether this proof game with 16 oscillations by Ta8 is correct (2018-12-08)
Mario Richter: Henrik, I think certainty about the correctness of this problem can be achieved, if we take into account that Black's last move must have been a capture. (2018-12-10)
A.Buchanan: Henrik: the times you propose for testing don't seem outrageous, even without Mario's sensible heuristic. Also, the last move must have been DxLd7 from one of 5 squares only. (2018-12-12)
more ...
comment
Keywords: Unique Proof Game
Genre: Retro
FEN: r1b1kbnr/pppqpppp/6Q1/R7/R1P3K1/P2P1PP1/1P1N2P1/4B1N1
Reprints: 101 Shortest Proof Games 11/1991
58b 64 Proof Games 2012
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2012-12-26 more...
70 - P0002302
Kostas Prentos
5426 feenschach 89 10-12/1988
Ehrende Erwähnung
P0002302
(14+13)
BP in 18,0
1. c4 Sc6 2. c5 Se5 3. c6 dxc6 4. Db3 Lh3 5. Kd1 Sg4 6. Kc2 Dd3+ 7. Kxd3 0-0-0+ 8. Ke4 f5+ 9. Kxf5 e6+ 10. Kxe6 Lc5 11. Kf7 Td6 12. Kf8 Se7+ 13. Dg8 Sh6 14. b3 Ld7 15. La3 Le8 16. Lb4 Td8 17. Sa3 Ld6 18. Tc1 Txg8#
play all play one stop play next play all
paul: 2 x Indian theme. (2018-11-09)
Henrik Juel: Euclide 1.01 ran for more than an hour, producing nothing
But the first 17.5 moves were tested correct in 8 minutes (2018-11-09)
Henrik Juel: Good proof game, considering its age
The black bishops go Lc8-h3-d7-e8 and Lf8-c5-d6 with interferences (including a swithcback by Td8) after their first moves to let Kf8 through (2018-11-09)
François Labelle: The last move must be Th8xg8, so Henrik's test in 17.5 moves plus three similar tests with white S, L, T at g8 (returning no solutions) should be considered an HC+ proof of correctness. (2018-11-10)
Henrik Juel: Good point, Francois
What does HC+ stand for? (2018-11-10)
Henrik Juel: ... never mind
It must mean correct by Computer testing with some (correct) Human reasoning added
If so, HC+ is the label we can use with many other retros, where human reasoning rules out a castling, etc. (2018-11-10)
Michel Caillaud: Full Computer testing (C+) is possible with Natch 3.2 and some time (86 hours) (2020-03-02)
comment
Keywords: Bahnung, Räumung, Unique Proof Game, Castling
Genre: Retro
FEN: 2krbKr1/ppp1n1pp/2pb3n/8/1B6/NP6/P2PPPPP/2R2BNR
Reprints: 128 Shortest Proof Games 11/1991
H23 FIDE Album 1986-1988 1995
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2014-11-06 more...
71 - P0002318
Andriy Frolkin
The Problemist 1989
3. Preis
P0002318
(31+0) C+
Färbe die Steine!
BP in 17,5
1. e4 c5 2. Dg4 Da5 3. De6 fxe6 4. Ke2 Kf7 5. Kf3 Kf6 6. Kg4 Ke5 7. Kg5 h5 8. Kg6 Kf4 9. Kf7 Sh6+ 10. Ke8 Sf7 11. Lb5 Th6 12. d3+ Dd2 13. g4 a5 14. Sh3+ Kf3 15. g5 Ke2 16. Sg1+ Ke1 17. h3 Dd1 18. Sf3++
play all play one stop play next play all
Henrik Juel: The capture was fxDe
If White made it, Dd1 is white and so is Ke1, but he would stand in an illegal check from sPf2
So Dd1 and Ke1 are black (and Ke8 is white), and the rest of the men have a 'natural' color because of the shortish proof game, which is
C+ by Natch 3.1 (2 sec.) (2018-12-08)
Michel Caillaud: HC+ Jacobi 0.7.1 RC1 with constraints Ke8-e1 Qd8-d1 (3 hours)
Constraints applied in Jacobi are traducing Henrik's analysis.
The problem is not C+ (that would be with solving without constraints). (2019-12-26)
Olaf Jenkner: If Henrik's proof is right the problem may be considered C+. (2019-12-27)
A.Buchanan: But Natch couldn’t have coloured the pieces, while Jacobi not only does that, but allows us to keep track of exactly what assumptions (constraints) we make. Effectively the definition of “C+” is being shifted. The computational overhead of proving these constraints from first principles is huge. Mario’s solution, of describing such a problem as HC+, which specific detailing of the constraints, is the right way forward. We have got the computer test field to describe the situation, but as far as the cplus flag is concerned, it must remain false until it permits a third value maybe (2019-12-27)
comment
Keywords: Unique Proof Game, Coloring problem
Genre: Retro
Computer test: Natch 3.1 (2 sec.)
FEN: RNB1KB2/1P1PPNP1/4P2R/PBP3PP/4P3/3P1N1P/PPP2P2/RNBQK2R
Reprints: 155 Shortest Proof Games 11/1991
feenschach 137 08-09/2000
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2018-12-13 more...
72 - P0002321
Samuel Loyd
Le Sphinx 1866
P0002321
(16+16)
Welches ist die kürzeste Partie, die mit Patt endet?
1. e3 a5 2. Dh5 Ta6 3. Dxa5 h5 4. Dxc7 Tah6 5. h4 f6 6. Dxd7+ Kf7 7. Dxb7 Dd3 8. Dxb8 Dh7 9. Dxc8 Kg6 10. De6=
play all play one stop play next play all
Die (Loydsche) englische Version der Forderung zielt nicht auf Eindeutigkeit ab: "Find how a stalemate might result in ten moves."

in 'Ruy Lopez' abgedruckt in der Rubrik "Partidas de fantasia"
AB: Not quite unique alas. 4 Dxc7 & 5 h4 can be transposed. (2001-10-17)
Kostas Prentos: Besides the minor transposition, there's another totally different solution:
1.c4 d5 2.Db3 Lf5 3.Dxb7 h5 4.Dxa7 Lh7 5.Dxb8 Ta6 6.h4 Th6 7.Dxc7 f6 8.Dxd8+ Kf7 9.Dxd5+ Kg6 10.De6= with many duals, too (2002-07-03)
AB: Yes, I was referring to uniqueness of proof game to reach the diagram position. KP responds to the task which appears here as the stipulation. (2002-07-07)
Yoav Ben-Zvi: What is the most simple stipulation that makes the solution unique?

My candidate: "Shortest game ending in Stalemate, given that White has not moved a Pawn after his fourth move"

I would add the length of the composer's solution as a courtesy to solvers: "Game in less than 10.0 moves ending in Stalemate, given that White has not moved a Pawn after his fourth move" (2012-08-27)
A.Buchanan: Hi YBZ: the proof game that Kostas gave 5bnr/4p1pb/4Qpkr/7p/7P/2P5/PP1PPPP1/RNB1KBNR has 12 solutions. 1.c3 gives another 12 solutions. And there's 2 solutions for Loyd. Out of these 26 indeed only one has the property that Wh gets all pawn moves out of the way before 4th move. But it's just occurred to me that there's a variant of Loyd which begins 1.c3 and wQ develops via a4 & a5, ending with 5bnr/4p1pq/4Qpkr/7p/7P/2P5/PP1PPPP1/RNB1KBNR this has 15 solutions, and in 6 of these, Wh plays both pawn moves as moves 1 or 2. Similarly if 1.c4. This only differs from Prentos' solution in the occupant of h7. So the suggested stipulation alas wouldn't work. I am pretty sure i have seen a longer version which is sound as a PG. (2020-05-28)
A.Buchanan: See P1004131 for a longer sound PG. (2020-05-28)
more ...
comment
Keywords: Construction task, Non-Unique Proof Game
Genre: Retro
FEN: rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR
Reprints: American Chess Journal , p. 18, 15/06/1876
335 Chess Strategy (Loyd) , p. 174, 1878
Ruy Lopez 3 03/1897
61-IV Sam Loyd and his Chess Problems , p. 58, 1913
61/IV Sam Loyd und seine Schachaufgaben 1926
132 Ultimate Themes 1938
6-5 De Waag 03/10/1941
R424 feenschach 21 04/1974
162 Shortest Proof Games 11/1991
Best Problems 45 2008
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-05-28 more...
73 - P0002337
Michel Caillaud
4019 Die Schwalbe 76 08/1982
Dr. Karl Fabel zum Gedenken
1. Preis
P0002337
(11+15)
BP in 47,0
1. Sf3 a5 2. Sd4 a4 3. Sb3 axb3 4. a3 Ta4 5. Ta2 bxa2 6. Tg1 axb1=S 7. Th1 Sc3 8. Tg1 Sd5 9. Th1 Sb6 10. Tg1 Sa8 11. Th1 b6 12. Tg1 La6 13. Th1 Dc8 14. Tg1 Db7 15. Th1 Df3 16. gxf3 h5 17. Lh3 h4 18. Le6 h3 19. La2 Lc4 20. Lb1 La2 21. b3 Thh4 22. Lb2 Thb4 23. Lf6 gxf6 24. Kf1 Lh6 25. Kg1 Kf8 26. Df1 Kg7 27. Dg2+ hxg2 28. h4 Kg6 29. Kh2 g1=S 30. Kg2 Lf4 31. h5+ Kg5 32. Th4 Lh2 33. Td4 Sh3 34. f4+ Kh4 35. Kf3 Sg5+ 36. Ke3 Kh3 37. h6 Kg2 38. h7 Kf1 39. h8=T Ke1 40. Th5 Sh7 41. Ta5 Kd1 42. Ta7 Kc1 43. Tb7 Ta7 44. Kd3 Sa6 45. Tb8 Kb2 46. Tf8 Ka1 47. Kc3 Lg1
play all play one stop play next play all
paul: Cooked: 1.a3 g5 2.Sh3 a5 3.Sf4 a4 4.Sg6 hxg6 5.Ra2 Rh4 6.h3 Rb4 7.h4 Ra5 8.h5 Bg7 9.Rh4 Be5 10.Rd4 Bh2 11.g3 Kf8 12.Bg2 Kg7 13.Bc6 Kf6 14.Kf1 Qf8 15.Kg2 Qh6 16.Kf3 g4+ 17.Ke4 Qf4+ 18.Kd3 Kg5 19.gxf4+ Kh4 20.Qe1 Kh3 21.Qd1 g3 22.Ra1 g2 23.Qh1 g1=S 24.Qd5 Sf3 25.Qc5 Kg2 26.Qc4 Kf1 27.Qc5 Ke1 28.Qc4 Kd1 29.Qd5 Kxc1 30.Qb3 axb3 31.Ra2 bxa2 32.h6 axb1=S 33.h7 Sc3 34.h8=R Sa4 35.Rh5 Sb6 36.Rb5 Sa8 37.Rb6 Sg5 38.Ra6 Sh7 39.Ra7 b6 40.Rb7 Ra7 41.Bd5 Sa6 42.Rb8 Bb7 43.Ba2 Bd5 44.Bb1 Ba2 45.b3 Kb2 46.Rf8 Ka1 47.Kc3 Bg1.[N. Plaksin, Die Schwalbe 130/1991] (2019-09-09)
paul: Comparing the obtained positions, it was observed that the pawn in the g6 must be at f6. A mistake by the publishers, but mine! (2019-09-10)
Henrik Juel: So Michel's proof game is not cooked; yet... (2019-09-10)
comment
Keywords: Unique Proof Game, Move Length Record, Non-standard material, Promotion (ssT)
Genre: Retro
FEN: n4Rn1/r1pppp1n/np3p2/8/1r1R1P2/PPK5/b1PPPP2/kB4b1
Reprints: diagrammes 69 01-02/1985
989 FIDE Album 1980-1982 1988
81 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-05-01 more...
74 - P0002345
Harry Goldsteen
diagrammes 1989
nach A. Frolkin
Super Preis
P0002345
(4+14)
#1
R: 1. ... Sh7-f8+ 2. Le8xTf7 Tf8xSf7 3. Se5-f7 Tf7-f8+ 4. Sc4-e5 Tf8xSf7 5. Sh6-f7 Tf7-f8+ 6. Sa3-c4 Tf8xSf7 7. Sg5-f7 Tf7-f8+ 8. Sb5-a3 Tf8xSf7 9. Se5-f7 Tf7-f8+ 10. Sc7-b5 Tf8xSf7 11. Sb5xDc7 Dc8-c7 12. Dd8-d7 Dc7xSc8 13. Ld7-e8 Te8-f8 14. Sf5-h6 Tf8-e8 15. Sh6-f7 Tf7-f8+ 16. Df8-d8 Dd8-c7 17. Le8-d7 Kc7-b8 18. Sa3-b5+ Lb8-a7 19. Sa7-c8 Kc8-c7 20. Sb5-a7+ Lc7-b8
play all play one stop play next play all
"Super-F"
Originalquelle=PB
Henrik Juel: (Please try to solve this wonderful problem yourself; if you need a hint, White
made four S-promotions). 1.exf8QR#. -1.. Sh7 -2.Be8:R Rf8:S -3.Se5 Rf7 -4.Sc4 Rf8:S -5.Sh6 Rf7 -6.Sa3 Rf8:S -7.Sg5 Rf7 -8.Sb5 Rf8:S -9.Se5 Rf7 -10.Sc7 Rf8:S -11.Sb5:Q Qc8 -12.Qd8 Qc7:S -13.Bd7 Re8 -14.Sf5 Rf8 -15.7Sh6 Rf7 -16.Qf8 Qd8 -17.Be8 Kc7 -18.Sa3 Bb8 -19.Sa7 Kc8 -20.7Sb5 Bc7 etc. Earlier in the game Black captured a7xPb6, c6xRd5, d7xRc6, e7xBd6, h7xPg6, and White promoted on a8, c8, d8, h8. The Keyword designation 'Whose move?' should be deleted. (2003-08-26)
Hans-Jürgen Manthey: eine mögliche Rückführung (sehr schwer) :
R: 1. ... Sh7-f8+ 2. Le8xTf7 Tf8xSf7 3. Se5-f7 Tf7-f8+ 4. Sc4-e5 Tf8xSf7 5. Sh6-f7 Tf7-f8+ 6. Sa3-c4 Tf8xSf7 7. Sg5-f7 Tf7-f8+ 8. Sb5-a3 Tf8xSf7 9. Se5-f7 Tf7-f8+ 10. Sc7-b5 Tf8xSf7 11. Sb5xDc7 Dc8-c7 12. Dd8-d7 Dc7xSc8+ 13. Ld7-e8 Te8-f8 14. Sf5-h6 Tf8-e8 15. Sh6-f7 Tf7-f8+ 16. Df8-d8 Dd8-c7 17. Le8-d7 Kc7-b8 18. Sa3-b5+ Lb8-a7 19. Sa7-c8 Kc8-c7 20. Sb5-a7+ Lc7-b8 21. Sd4-b5 Kb8-c8 22. Sc4-e5 Ka7-b8 23. Ld7-e8 Db8-d8 24. Dc8-f8 Ka6-a7 25. Le8-d7 Da7-b8 26. Kd7-e6 Ld8-c7 27. e6-e7 Le7-d8+ 28. e5-e6 Tf8-f7 29. Lf7-e8 Te8-f8 30. e4-e5 Lf8-e7 31. Ke6-d7 e7xLd6+ 32. Lf4-d6 Td8-e8 33. Dd7-c8 Te8-d8 34.Sd6-f5 Td8-e8 35. Sc8-d6 Te8-d8 36. c7-c8=S Tb8-e8 37. De8-d7 Tc8-b8 38. Kd7-e6 Tb8-c8 39. Se6-d4 Tc8-b8 40. Sd8-e6 Tb8-c8 41. Ke6-d7 Tc8-b8 42. d7-d7=S Tb8-c8 43. d6-d7 Tc8-b8 44. Kd7-e6 Tb8-c8 45. Le6-f7 Tc8-b8 46. Lh3-e6 Tb8-c8 47. Dc8-e8 Lf7-g8 48. Sf3-g5 Sg5-h7 49. Lf1-h3 Sh3-g5 50. Ke6-d7 Le8-f7+ 51. Sf7-h6 Tg8-h8 52. Sh8-f7 Sf2-h3 53. h7-h8=S Sh3xf2 54. h6-h7 Th8-g8 55. Kf5-e6 h7xg6+ 56. Kg4-f5 Sg5-h3 57. Sg1-f3 Sf7-g5 58. Kf3-g4 Tg8-h8 59. Dg4-c8 Th8-g8 60. h5-h6 Ld7-e8 61. Ke2-f3 Lc8-d7 62. Sd2-c4 d7xTc6 63. Tc1-c6 Sh6-f7 64. c6-c7 Sc7-a8 65.Sb5-a3 Ka5-a6 66. Ke1-e2 Kb4-a5 67. c5-c6 Da5-a7 68. Dd1-g4 Sa6-c7 69. Sc7-b5 Sg8-h6 70. Sa8-c7 f7-f6 71. a7-a8=S Ta8-b8 72. Ta1-c1 Sb8-a6 73. a6-a7 a7xb6 74. c4-c5 c6xTd5 75. Td3-d5 Kc5-b4 76. b5-b6 Kb4-c5 77. Th3-d3 Da3-a5 78. Sb1-d2 Kc5-b4 79. Lc1-f4 Kb6-c5 80. d5-d6 Kc7-b6 81. Th1-h3 Dd6-a3 82. a5-a6 Kd8-c7 83. a4-a5 Dc7-d6 84. b4-b5 Ke8-d8 85. d4-d5 Dd8-c7 86. g5-g6 Dc7-d8 87. g4-g5 Dd8-c7 88. h4-h5 Dc7-d8 89. h2-h4 Dd8-c7 90. g2-g4 Dc7-d8 91. e2-e4 Dd8-c7 92. d2-d4 Dc7-d8 93. c2-c4 Dd8-c7 94. b2-b4 c7-c6 95. a2-a4 (2020-04-02)
Hans-Jürgen Manthey: 42.d7-d7=S muß natürlich d7-d8=S lauten. (2020-04-02)
comment
Keywords: Ceriani-Frolkin Theme (SSSS), Uncapture of pieces by pieces
Genre: Retro
FEN: nk3nbr/bp1QPBp1/1pppKpp1/3p4/8/8/8/8
Reprints: Probleemblad 1 01-02/1989
9 Die Schwalbe 146 04/1994
(8) diagrammes 15 07-09/1994
(20) diagrammes 15 07-09/1994
20 Shakhmatnaya Kompozitsiya 14 1996
feenschach 137 08-09/2000
(3) Quartz 18 10-12/2002
(13) Mat Plus Review 13-14 08/2010
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2012-07-17 more...
75 - P0002554
Unto Heinonen
Probleemblad 1991
1. Preis
P0002554
(16+16) cooked
BP in 43,0
1. h4 a5 2. Th3 Ta6 3. Tf3 Tg6 4. Sh3 Tg3 5. Sf4 Th3 6. g3 Th2 7. Lh3 Sh6 8. Le6 Sf5 9. Lc4 d5 10. Kf1 Th1+ 11. Kg2 Tg1+ 12. Kh3 Kd7 13. Kg4 h5+ 14. Kg5 Th6 15. a4 Tb6 16. T1a3 Kc6 17. Tac3 Tb3 18. Sg6 Ta3 19. b3 Ta2 20. La3 Dd6 21. Lc5 Sd7 22. La7 Sb6 23. Sh8 Kc5 24. La6+ Kb4 25. Tc5 g6 26. Sc3 Lg7 27. Se4 Lc3 28. Da1 Sd4 29. Kh6 Ld7 30. Kg7 Lb5 31. Kf8 Ld3 32. Ke8 Dc6+ 33. Kd8 Sc4 34. Kc8 Ka3 35. Kb8 Lb4 36. Ka8 De8+ 37. Lb8 Sb6+ 38. Ka7 Sa8 39. c4 Sc2 40. Df6 Sa1 41. Db6 Kb2 42. Sf6 Ta3 43. Sd7 Ka2
play all play one stop play next play all
Cook: NL
1. h4 a5 2. Th3 Ta6 3. Tf3 Te6 4. g3 Te3 5. Lh3 Sh6 6. Le6 Sf5 7. Lc4 d5 8. Kf1 Dd6 9. Kg2 Da6 10. Kh3 Kd7 11. Kg4 h5+ 12. Kg5 Th6 13. a4 Tb6 14. Ta3 Kc6 15. Tc3 Tb3 16. Sh3 Ta3 17. b3 Ta2 18. La3 Sd4 19. Lc5 Lf5 20. La7 Db6 21. Sf4 Kc5 22. Sg6 Kb4 23. Sh8 g6 24. La6 Lg7 25. Tc5 Db5 26. c4 Sc2 27. Sc3 Ka3 28. Se4 Lc3 29. Da1 Lb4 30. Df6 Tc3 31. Kh6 Kb2 32. Kg7 Ta3 33. Kf8 Sd7+ 34. Ke8 Ka2 35. Kd8 Sa1 36. Kc8 Sf8+ 37. Kb8 Sd7+ 38. Ka8 Tc1 39. Lb8 Sb6+ 40. Ka7 Sa8 41. Db6 Tg1 42. Sf6 De8 43. Sd7 Ld3 (Sebastian Natschke)
Henrik Juel: Very good, Sebastian (although not for the author...) (2019-06-17)
paul: Probably the cook of the year, because the problem is well known. Which is now the length record for a capture free proof game? (2019-07-16)
paul: The length record for a capture-free PG is now 40.5 moves by Th. le Gleuher (Phenix50/1997) (2019-07-16)
Mario Richter: The problem Paul was referring to is P0006623. So far it has resisted all my and rawbats' attempts to cook it, and I think that chances are high that it is indeed correct ... (2019-07-17)
more ...
comment
Keywords: Unique Proof Game, Move Length Record, Capture-free
Genre: Retro
FEN: nB2q2N/KppNpp2/BQ4p1/p1Rp3p/PbP4P/rP1b1RP1/k2PPP2/n5r1
Reprints: H17 FIDE Album 1989-1991 1997
feenschach 137 08-09/2000
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-05-01 more...
76 - P0002593
Thierry Le Gleuher
2511 diagrammes 98 07-09/1991
1. Lob
P0002593
(16+5)
BP in 12,5
Einsteinschach
1. e3 h5 2. Dxh5 d5 3. Dxd5 Th5[=sL] 4. Dxb7 Ld1[=sS] 5. Dxc7 Lg4[=sS] 6. Dxa7 Dc7[=sT] 7. Dxb8+ Kd7 8. Dxf8 f5 9. Dxg7 Sf6[=sB] 10. Dxg4 Tg8[=sL] 11. Dxd1 f4 12. exf4[=wS] Kc8 13. Se2[=wB]
play all play one stop play next play all
paul: The first 11.5 moves tested by Jacobi (~19 hours) (2019-12-10)
comment
Keywords: Unique Proof Game, Einstein Chess, Homebase (W), Initial Game Array (W)
Genre: Retro, Fairies
FEN: 2k3b1/2r1p3/5p2/8/8/8/PPPPPPPP/RNBQKBNR
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2013-01-27 more...
77 - P0002605
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002605
(7+1)
In welche Richtung ziehen die Bauern?
von oben nach unten
play all play one stop play next play all
Henrik Juel: Last move was g2xDTSh1=L+ (2019-01-01)
comment
Keywords: Promotion
Genre: Retro
FEN: k1K5/4Q3/8/2B1P3/3P4/7P/8/7B
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-26 more...
78 - P0002606
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 13, 1979
P0002606
(7+1)
In welche Richtung ziehen die Bauern?
R: 1. exd6ep+ d7-d5 2. e4-e5+
play all play one stop play next play all
Henrik Juel: The next retraction is also determined
2... Ka7xSa8 (3.Sb6-a8+ or Sb6xDLSa8+) (2019-01-01)
Henrik Juel: oops, that is not true
after 2... Ka7-a8, Lc5 can uncheck directly (2019-01-02)
comment
Keywords: En passant, Rex solus (s)
Genre: Retro
FEN: k1K5/4Q3/3P4/2B5/3P4/7P/8/7B
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-03 more...
79 - P0002607
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002607
(3+1) C+
Welches war der letzte Zug?
Weiß am Zug
R: 1. Ka7xSa8
play all play one stop play next play all
AB: Anticipated by P0001033. I feel almost guilty pointing this out, because Smullyan did so much to popularize RA. (2001-10-30)
Henrik Juel: The author of P0001033, Jan Mortensen, was no slouch either
For some 40 years he was the driving force in DSK, the danish chess problem society (2019-01-01)
comment
Keywords: Last Move? (KxS), Type B, anticipated (P0001033)
Genre: Retro
Computer test: RSP 1.2
FEN: k1K5/8/8/8/8/8/7P/6B1
Reprints: Schach mit Sherlock Holmes 1982
(1) diagrammes 86 07-09/1988
Outrageous Chess Problems 2005
R1 Phénix 275-276, p. 10810, 07-08/2017
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-03-09 more...
80 - P0002608
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002608
(12+14)
Auf welchem Feld wurde die wD geschlagen?
h6
play all play one stop play next play all
Henrik Juel: The pawn captures are determined, and also their sequence
d7xSe6 first, then a2xLb3, and finally g7xDh6 (2019-01-01)
comment
Keywords: Where was piece x captured?
Genre: Retro
FEN: r2qk1nr/ppp1pp1p/2n1p2p/8/8/1P6/NPPPPPPP/R3K2R
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-26 more...
81 - P0002609
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002609
(3+1+1)
Welche Farbe hat der Bg3?
Monochromes Schach
sBg3 (Weiß hat rochiert)
play all play one stop play next play all
Henrik Juel: ... and wKb4 got out via h2 and g3 (2019-01-01)
comment
Keywords: Monochrome, Castling (wk)
Genre: Retro, Fairies
FEN: 4k3/8/8/8/1K6/6-P1/3P1P2/8
Reprints: feenschach 50 04-06/1980
Schach mit Sherlock Holmes 1982
R4 Phénix 275-276, p. 10812, 07-07/2017
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-26 more...
82 - P0002610
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002610
(3+1)
Der wK hat weniger als 14 Züge gemacht. Weise nach, daß eine UW stattgefunden hat!
Monochromes Schach
Der sSb8 kann nur von einem Bauern geschlagen worden sein!
play all play one stop play next play all
Henrik Juel: Strictly speaking, [Sb8] could also have been captured by DTL, e.g. h4xPg5xPf6epxPe7xDd8=DxSb8
But White must have promoted (on a dark square) (2019-01-01)
comment
Keywords: Monochrome, Promotion
Genre: Retro, Fairies
FEN: 4k3/8/8/8/8/8/1P1P4/4K3
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-26 more...
83 - P0002612
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 30, 1979
P0002612
(11+10)
Welcher Stein steht auf h4?
(+wLh4!)
R: 1. c7xSd8=T,c7xLd8=T+
(sBhxXg2)
play all play one stop play next play all
Auf h4 steht ein wL
Henrik Juel: White captured [Lf8] with an officer, and the remaining four missing black men by fxexdxc and c7xLSd8=T+
So Black captured b7xa6, f7xe6xd5xc4, and h3xg2 on light squares, leaving only the dark-squared [Lc1] to be disclosed on h4 (2019-01-02)
Yoav Ben-Zvi: The detailed solution in Smullyan's book (p29) is reprinted in "Four lives, 2014 Ed. Jason Rosenhouse" (a tribute to Smullyan published shortly before his death). Another version appears in the wonderful chapter by Bernd Gräfrath in "Philosophy looks at chess, 2008 Ed. Ben Hale" where it is stated that Smullyan composed this problem at age 16 and considered it his best Retro problem. The following analysis is adapted from these sources:
Last move was -1.wPc7x(B or N, not Q or R)d8=R. The unpromoted wP implies 3 captures by [wPf2] (not 4 captures by [wPg2] plus 1, on g3, by [wPf2] since [bBf8] was not captured by a wP) implying that wPg3 comes from g2. It also implies promotion of [bPh7] (to bB or bN) after capturing on g2 (behind wPg3), a fifth capture by bP. The piece on h4 could not be bQ or bR (both kings would be in check) or bB or bN (requires a second Black promotion) therefore the piece on h4 must be White. A White piece on h4 other than wB would imply that [wBc1] was captured by a bP but all 5 captures by bPs are on light colored squares so:
Solution - White bishop stands on h4. (2019-01-02)
comment
Keywords: Promotion
Genre: Retro
FEN: 2nR3K/pk1Rp1p1/p2p4/P1p5/1Pp4x/2PP2P1/4P2P/n7
Reprints: Schach mit Sherlock Holmes 1982
TLG/4 feenschach 173, p. 303, 07-09/2008
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-03 more...
84 - P0002614
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 45, 1979
P0002614
(12+11)
Schwarz ist am Zug. Darf er rochieren?
Mario Richter: vgl. mit P1012380 (2010-04-17)
Henrik Juel: Last move was a2-a3, so to prevent white retro-stalemate Black must uncapture a wS at once
Tb8xSa8 or LxSc8 do not give White a previous move, so the uncapture happened on e8 or h8, and Black may not castle (2019-01-02)
comment
Keywords: Castling (wksk), Cant Castler
Genre: Retro
FEN: r1b1k2r/p1p1p1p1/1p3p1p/8/8/P7/1PPPPPPP/2BQKB2
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-03 more...
85 - P0002615
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 46, 1979
P0002615
(6+4)
Weder Weiß noch Schwarz haben mit ihrem letzten Zug einen Stein geschlagen. Schwarz ist am Zug. Darf er rochieren?
Henrik Juel: Last move was not white castling, because the no-capture stipulation for Black would imply that the only previous white move available could be e2xf3??, rendering the position illegal (because d2-d1=L would be impossible)
So last move was Kh1-g1 or Kh2-g1, Th8 has moved to check, and Black may not castle (2019-01-02)
comment
Keywords: Castling (wksk)
Genre: Retro
FEN: 4k2r/8/8/8/2p5/5P2/2P2PP1/3b1RK1
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-03 more...
86 - P0002616
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 49, 1979
P0002616
(9+9)
Welcher Stein steht auf a5?
(+wKa5)
play all play one stop play next play all
Alfred Pfeiffer: Auf a5 steht der wK. (2012-01-11)
Henrik Juel: No Mystery here (2019-01-02)
Mario Richter: No mystery, but a little joke ("Sir Reginald's Jest"): the position was given as a trap to Sherlock Holmes, who immediately started analysing: Let's see now; Black is in check. What could have been White's last move? Obviously a rook from b7 capturing a Black piece on a7. I guess the next question now is, what was the Black piece? If it was a rook, then Black has promoted earlier..."
A this point the spectators could resist any longer laughing out loud pointing out that the piece obviously has to be the White King. Holmes concluded: "I have really been given a good dose of my own medicine. How many times have I not told Dr. Watson: 'In looking for the subtle, be careful not to overlook the obvious.'" (2019-01-03)
comment

Genre: Retro
FEN: k2q3r/R1B4p/R4p2/x2B2p1/1P2n1P1/P7/2P5/r4b2
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-03 more...
87 - P0002618
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 53, 1979
P0002618
(8+10)
Weiß setzt in einem Zug matt.
a) Brettdrehung 90° in Uhrzeigerrichtung (a1->a8) 1. f7xe8=D,L#
b) Brettdrehung 90° gegen die Uhrzeigerrichtung (a1->h1) 1. g4#
play all play one stop play next play all
Henrik Juel: In the diagram, light and dark squares should be inverted (e.g., h1 should be dark), implying that the board must be rotated 90 degrees; this inversion is probably impossible to achieve in the PDB, otherwise Gerd would have done it
Clockwise rotation: 1.'Pb6xTa5=DL#'
Counter-clockwise: 1.'Pc2-d2#' (2019-01-02)
comment
Keywords: Board Rotation
Genre: Retro
FEN: 2bq3r/b1p1p3/1P3n2/r2p4/3Q4/8/1PP1BR2/R1K1k3
Reprints: Schach mit Sherlock Holmes 1982
R3 Phénix 275-276, p. 10811, 07-08/2017
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-03 more...
88 - P0002620
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 56, 1979
P0002620
(13+13)
Keine der Damen hat jemals ihre Felderfarbe gewchselt.
Welche Rochaden sind zulässig?
b) ohne wTg1
c) wTg1->h1
Henrik Juel: An important condition is missing:
The queens never changed square color
With this condition added, we can analyze
White captured all missing black men with exfxgxh
Black captured [Lc1] on c1 and [Dd1] on a light square, so he captured another original white officer with a7xb6, after which White promoted [Pa2] on a8, so Ta8 has moved and Black may not castle
The promoted officer must be Ta1 or Tg1, so White may not castle either (2019-01-02)
Mario Richter: Originalforderung:
It is given that neither queen has ever moved off her own color
a) Which side, if either, can castle?
b) If the rook on g1 is removed, would that affect the answer?
c) If the rook is replaced on h1, then what would the answer be?" (2019-01-03)
Henrik Juel: Thanks for the update, Mario
b)
No need for promotion, as Black could have captured the missing T by a7xTb6
Black may castle, White may not
c)
Like a), but if the promoted officer is Ta1
White may castle short, Black may not castle (2019-01-03)
comment
Keywords: Castling (wgsg)
Genre: Retro
FEN: r3kr2/1pp2p2/1pn2npP/1B1pp3/1b6/2N2NPP/1PPP1P2/R3K1R1
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-03 more...
89 - P0002621
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 58, 1979
P0002621
(12+14)
Weiß hat die wD vorgegeben und die beiden wSS sind Originalspringer. Welche Rochaden sind zulässig?
Henrik Juel: With g7xh6 Black did not capture [Lc1], nor [Dd1], nor [Lf1], so [Pe2] must have promoted
If g7xh6 captured the promoted man, the promotion needed two white pawn captures, exPf and either f7xe8 or f7xg8, so Black must have played b3xa2-a1=Y, and White may not castle long
If g7xh6 captured an original man, this was also not [Sb1,Sg1], so [Th1] must have moved, and White may not castle short
White may castle short or long, but we cannot say which (2019-01-02)
comment
Keywords: Castling (wb), Odds game
Genre: Retro
FEN: 2kr3r/1qppp2p/pn3n1p/4b3/b6P/P1N2N2/1PPP1PP1/R3K2R
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Rainer Staudte, 2019-08-11 more...
90 - P0002625
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 69, 1979
P0002625
(3+2)
Ergänze einen wB auf c4, c5, d4 oder d5, so daß die Partie (mit Schwarz am Zug) nicht remis enden muß!
+wBc4, dann 1. bxc3ep
play all play one stop play next play all
Henrik Juel: tiny typo in stipulation: mit Schwarz, not Scharz
A wP on c4 does not imply that last move was c2-c4, so the ep capture is not legitimized as such; but it is the only way to prevent the game from ending in a draw (2019-01-02)
comment
Keywords: Add pieces, En passant, Kindergarten Problem
Genre: Retro
FEN: 8/8/8/8/1p6/kP6/P7/K7
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-03 more...
91 - P0002626
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 73, 1979
P0002626
(8+1)
Darf Weiß rochieren?
Henrik Juel: No, White may not castle right now, because it is Black to move, as he has no last move
Or (if you allow joking) the board is turned upwards down, in which case White could have the move, but castling would still not be possible (2019-01-02)
comment
Keywords: Castling (wb), Rex solus (s)
Genre: Retro
FEN: 8/8/8/8/NN1Q4/1k1B4/8/R1B1K2R
Reprints: Schach mit Sherlock Holmes 1982
R6 Phénix 275-276, p. 10813, 07-08/2017
Input: Gerd Wilts, 1995-06-03
Last update: Rainer Staudte, 2019-08-11 more...
92 - P0002627
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002627
(5+1)
Weiß am Zug. Ist die Stellung legal?
R: 1. Kc6-b6 oder 1. Ka6-b6
play all play one stop play next play all
Henrik Juel: Yes, the position is legal, as the retroplay could be -1... Kc6-b6 -2.b7-b8=S++ etc. (or Ka6-b6 -2.a7xb8=S++) (2019-01-02)
comment
Keywords: Last Move?, Promotion
Genre: Retro
FEN: QN6/7R/1k6/1N6/1K6/8/8/8
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-28 more...
93 - P0002630
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002630
(15+15)
Welche Farbe ist Schwarz, welche Weiß?
Schwarz ist Weiß, Weiß ist Schwarz
play all play one stop play next play all
Henrik Juel: The number of white moves in the game is uneven, and the number of black moves is even, implying that White just moved (assuming that White started; this is the standard parity argument); but this contradicts that Black just checked on c3
If Black started the game, there is no contradiction (2019-01-02)
comment
Keywords: Parity Argument
Genre: Retro
FEN: r1b1kb1r/pppppppp/2N5/5n2/6N1/2n5/PPPPPPPP/1RBK1B1R
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-28 more...
94 - P0002631
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002631
(6+9)
Schwarz am Zug darf rochieren. Ergänze einen wB auf f2 oder g2!
+wBf2
play all play one stop play next play all
Henrik Juel: The diagram white pawns captured 6 times, and black pawns 8 times, so after adding a white pawn there is room for just one more capture by each side
Only addition on f2 permits a legal position, where the remaining captures were black hxPg (with promotion on g1) and white h7xg8=DLS (2019-01-02)
comment
Keywords: Add pieces, Castling (sk)
Genre: Retro
FEN: 4k2r/p4pp1/pp6/1p6/PPP5/p7/PP6/4K3
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-28 more...
95 - P0002632
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002632
(14+15)
1. Weiß hat einen Turm vorgegeben,
2. die wSS haben noch nicht gezogen,
3. es fanden keine UW statt,
4. der letzte Zug von Weiß war e2-e4.Darf Schwarz rochieren?
Henrik Juel: Yes, Black may castle, as he had no time to move his king or rooks during the 6.0 moves game (but it is White to move)
Proof game (the black moves could be shifted):
1.a3 Sc6 2.a4 Sh6 3.a5 e5 4.a6 Dg5 5.axb7 Lb4 6.e4 Lxb7
Too many conditions for my taste in this problem (2019-01-02)
comment
Keywords: Constrained problem, Odds game
Genre: Retro
FEN: r3k2r/pbpp1ppp/2n4n/4p1q1/1b2P3/8/1PPP1PPP/1NBQKBNR
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-28 more...
96 - P0002633
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 93, 1979
P0002633
(13+15)
Die KK haben noch nicht gezogen. Ergänze einen wB!
Henrik Juel: White captured g2xTh3, so to get [Ta8] out, Black cross-captured b7xTc6 and c7xLb6
The sequence was: [Ta1] to c6 before b7xc6 before g2xh3 before [Th1] to a1
Add wPc4 to permit the wT moves (2019-01-03)
more ...
comment
Keywords: Add pieces, Constrained problem
Genre: Retro
FEN: 3qk2r/p2pbp1p/bpp2np1/2nBp3/8/NP2PN1P/P2P1P1P/R2QK3
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-04 more...
97 - P0002634
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 95, 1979
P0002634
(15+14)
Schwarz ist am Zug. Weiß hat zuletzt mit dem Bf4 gezogen; woher kam dieser Bauer? Es befindet sich keine UWF auf dem Brett,
Henrik Juel: with wPe4 moved to f4:
White captured [Lc8] on a light square with an officer and d2xc3, so Black captured the light-squared [Lf1] either by dxLc or by d3xLe2 (and promotion on e1)
In both cases the sequence must be
e2-e3 (to release [Lf1]) before dxL before d2xc3 before [Lc1] could reach g5 traversing f2
So last move was f3-f4 (2019-01-03)
more ...
comment
Keywords: Constrained problem
Genre: Retro
FEN: r2qk2r/p1p2ppp/1pn2n2/1Nb1p1B1/5P2/2P1P2N/PPPQ2PP/2KR3R
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-04 more...
98 - P0002637
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002637
(15+14)
Befinden sich UWF auf dem Brett?
Yoav Ben-Zvi: The Black piece captured on c3 could not be [bBc8] (captured on a light square) or [bPh7]. Therefore [bPh7] promoted on g1 after capturing [wBc1] (on g3) which was released previously by wPb2xc3. This implies that the piece promoted on g1 could not have been captured on c3 as the capture on c3, releasing [wBc1], occurred before the Black could promote. Therefore the promoted Black piece must be present on the board, replacing the piece captured on c3. The idea is developed further in P0002638. (2018-12-29)
comment
Keywords: Promotion
Genre: Retro
FEN: r2qk2r/p1pp1pp1/1pn3n1/2b1p3/2B1P1P1/N1P3N1/P1PP1P1P/R2QK2R
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-28 more...
99 - P0002638
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes 1979
P0002638
(14+14)
Weiß hat gerade rochiert. Befindet sich UWF auf dem Brett?
Yoav Ben-Zvi: The Black piece that accounts for the capture on a3 could not be [bBc8] (captured on a light square) so it was a missing bP that promoted. The bP promotion could not have occurred on h1 ([wRh1] did not move before castling) so the promotion was on g1 or f1. wPg3 came from g2, it could not capture on g3 as this would be the second capture by White on a dark square and Black's 2 missing pieces include [bBc8] which was captured on a light square. This means that the promoting pawn could not have been [bPg7] as this would require 2 captures on the way to promotion (to bypass [wPg2]) plus a third capture by bPh7xg6. Therefore the promoted bP comes from h7 and, to reach the promotion square, it must have captured on column g behind wPg3. If the piece captured on a3 was an "original" (not promoted) Black piece (could be any officer other than [bBc8]) then the piece promoted by Black is present in the diagram, replacing the piece captured on a3. Henceforth we consider the alternative: that the piece captured on a3 was the promoted piece itself. This implies that the capture by the bP on its way to promotion came before the capture on a3. If wBg5 is not promoted then, prior to wPb2xa3, the wB was locked at c1 which implies that [wRa1] had not yet escaped its home corner and that [wBc1] subsequently moved to g5 via b2 crossing c3. This means the White pawn was still standing on c2 and therefore, since the wK had not moved, that the wQ could not have escaped from d1. It follows (for the case of Black promotee being captured on a3) that the White piece captured by the Black pawn on its way to promotion could not have been [wBc1] or [wRa1] or [wQd1] as it has been shown that, in this case, all 3 were locked when this capture occurred. The White piece captured by promoting bP also could not have been a wP since, as noted above, wPg3 came from g2 and the capture occurred behind it. Since the White piece captured on column g could not have been one of the missing original pieces, [wPh2] must have promoted. On its way to promotion [wPh2] could not capture on g7 (with bP waiting on h7) for the same reason as given above for the capture on g3 (not all White captures were on dark squares). Therefore wP must wait on h2 until its way to promotion is cleared by bPh3xg2 so it can subsequently promote on h8 to replace the captured piece (known to be a knight). In conclusion: for every alternative scenario there is a promoted piece on the board.
The stipulation, which might be defined more accurately as "Must there be a promoted piece on the board?", weaves together the alternative strands of the solution.
The presentation of the problem begins on page 106 of the book (chapter "Shades of the Past") relaying the condition that the last move was -1.0-0 and that Sherlock Holme's nemesis, Professor Moriarty, solved the problem in less than 4 minutes while Holmes admits it took him more than 20 minutes. The description of the solution begins on page 155. (2018-12-29)
Mario Richter: @Yoav: Quote: "... to replace the captured piece (known to be a knight)." This is not completely correct.
Just a small thought to think about: Let's assume that Black answers White's castling by playing 1. ... 0-0! In what way does this change the RA? (2018-12-29)
Yoav Ben-Zvi: The conclusion that the piece captured on g2 was a wN is reached under the assumptions that Black's promoted piece was captured on a3 (therefore it is not present in the diagram) and that wBg5 is not promoted (implying that [wBc1] exited after the capture on a3 and before [wQd1] could be released by wPc2-c3). It has been shown that, under these assumptions, [wBc1], [wRa1] and [wQd1] could not have escaped in time to be captured on g2. The piece captured on g2 also could not be a wP ([wPg2] moves to g3) or a wB (wBg4 could not be promoted on the dark square h8) or a promoted piece (the path to promotion of [wPh2] is open only after the capture on g2) so I think the conclusion that it had to be a knight is justified, under the assumptions (although it is not needed to meet the stipulation).
The suggested addition of the condition: "Black retains the right to castle 0-0" prevents any resolution that has [wPh2] promoting on h8. It has been shown above that capture of Black's promoted piece on a3 requires the White promotion on h8 (either to a wB that replaces the one captured on c1 or to a wN that replaces the one captured on g2). This contradiction (promotion on h8 is required but not allowed) means that the piece captured on a3 could not have been Black's promoted piece so it was an original (not promoted) piece. The piece captured on a3 could not be [bBc8] (captured on a light colored square) or a bP so it is a bQ or bR or bB or bN that is replaced in the diagram by the promoted piece, proving that there must be a Black promoted piece present in the diagram position. A fine idea that improves the accuracy of the resolution. (2018-12-30)
comment
Keywords: Promotion, Castling (wksk), Constrained problem
Genre: Retro
FEN: r2qk2r/ppp2p2/2np1np1/2b1p1B1/N5B1/P1P2NP1/P2PPP2/R4RK1
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2018-02-28 more...
100 - P0002639
Raymond Smullyan
The Chess Mysteries of Sherlock Holmes , p. 113, 1979
P0002639
(11+11)
Weiß setzt matt. In wieviel Zügen?
1. axb6ep#!
play all play one stop play next play all
Henrik Juel: White pawns captured bxa, cxb, f6xe7 (to promote on e8), and g2xh3 (the remaining missing black man was captured by an officer)
Black captured h7xg6xf5xe4xd3 and dark-squared [Lc1] with an officer
Last move was not a6xb5, c4xd3, d4-d3, d7xe6, nor d7-d5, e7-e6 (as White moved f6xe7-e8=L and promoted L to c6 or c8), so last move was b7-b5
White mates by axb6ep# (2019-01-03)
comment
Keywords: En passant
Genre: Retro
FEN: RbB5/n1p2pp1/2B1p3/PpKp4/kP2P3/p2p3P/P2P3P/8
Reprints: Schach mit Sherlock Holmes 1982
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2019-01-04 more...
Show statistic for complete result.

The problems of this query have been registered by the following contributors:

Gerd Wilts (100)