Die Schwalbe

2946 problem(s) found in 1515 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20190116]

1 - P0000236
Karlheinz Bachmann
7437 Die Schwalbe 130 08/1991
P0000236
(3+1) cooked
BP in 16,0
Zeroposition
a) Kf8 nach g8
b) Lg5 nach g2
a) 1. Sf3 e5 2. Sxe5 Df6 3. Sxd7 Dxb2 4. Sxf8 Dxb1 5. Sxh7 Txh7 6. Txb1 Txh2 7. Txb7 Txg2 8. Txa7 Txf2 9. Txc7 Txf1+ 10. Txf1 Txa2 11. Tfxf7 Txc2 12. Txc8+ Kxf7 13. Txb8 Txd2 14. Txg8 Txd1+ 15. Kxd1 g5 16. Lxg5 Kxg8
b) 1. Sc3 d5 2. Sxd5 Dd6 3. Sxe7 Dxh2 4. Sxc8 Dxg1 5. Sxa7 Txa7 6. Txh7 Txa2 7. Txh8 Txa1 8. Txg8 Txc1 9. Txg7 Txc2 10. Txf7 Txb2 11. Txc7 Txd2 12. Txb7 Txd1+ 13. Kxd1 Dxf2 14. Txb8+ Ke7 15. Txf8 Dxg2 16. Lxg2 Kxf8
play all play one stop play next play all
Cook: NL
b) 1. Sb1-c3 b7-b5 2. Sc3xb5 c7-c6 3. Sb5xa7 Dd8-c7 4. Sa7xc8 Ta8xa2 5. Sc8xe7 Ta2xa1 6. Se7xc6 Ta1xc1 7. Sc6xb8 Tc1xc2 8. Sb8xd7 Dc7xh2 9. Sd7xf8 Dh2xg1 10. Th1xh7 Tc2xb2 11. Th7xh8 Tb2xd2 12. Th8xg8 Td2xd1+ 13. Ke1xd1 Dg1xf2 14. Tg8xg7 Df2xg2 15. Tg7xf7 Ke8xf7 16. Lf1xg2 Kf7xf8 (Mario Richter)
paul: a) is Jacobi+ (2019-2-23)
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comment
Keywords: Unique Proof Game, Massacre PG, Rex solus (s)
Genre: Retro
Reprints: 119 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-4-25 more...
2 - P0000407
Günter Glaß
4360 Die Schwalbe 81 06/1983
5. Lob
P0000407
(7+9)
Weiß nimmt 1 Zug zurück, so daß Weiß und Schwarz #1
Circe
Duplex
w) R: 1. Kh6xBg5[+sBg7], dann Sf7#
bzw. R: 1. Kh6xBg5[+sBg7], dann 1. Lb5#

s) R: 1. ... Kd3xBc4[+wBc2], dann 1. ... Dgd4#
bzw. R: 1. ... Kd3xBc4[+wBc2], dann 1. Dbg2#
play all play one stop play next play all
HBae: R: 1. ... Kh6xBg5[+sBg7], dann 1. Lb5# bzw. 1. Sf7#
R: 1. ... Kd3xBc4[+wBc2], dann 1. Dgd4# bzw. 1. Dbg2# (2019-2-4)
comment
Keywords: Circe, Help retractor
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-2-4 more...
3 - P0000434
Hans Gruber
4700 Die Schwalbe 86 04/1984
2.-3. Lob e.a.
P0000434
(1+1)
Ergänze einen sS und 2 sBB zu einem IC!
Längstzüger
(+sBf7,sBg6,sSh8)
play all play one stop play next play all
Nicht +sSh1, sBf2, sBg3

Duplicate Diagram: P1187718, P1347424

Henrik Juel: The solution position is illegal, because Sh8-g6 is longer than g7-g6 and h7xg6, so these pawn moves could not happen
The try position is legal with a promoted Sh1 (2019-2-14)
comment
Keywords: Illegal cluster, Maximummer, only Kings
Genre: Retro, Fairies
Reprints: 110 Die Schwalbe 244, p. 582, 08/2010
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-2-15 more...
4 - P0000549
Hans Gruber
René Jean Millour

3464 Die Schwalbe 68 04/1981
P0000549
(1+1)
Ergänze weiße Steine minimaler Gesamtqualität zu einem IC
Keine Bauern auf der 1./8. Reihe
Mars-Circe
+wBe2,wBg2
play all play one stop play next play all
Die Lösung des ursprünglichen Alleinautors HG (+wBe2 f2 g2) ist nicht die Lösung, da die Stellung nach Entfernen des wBf2 immer noch illegal ist. Die Lösung von RJM, der damit auf Wunsch von HG zum Koautor wurde (+ wBe2 g2), ist aber auch nicht richtig: NL +wB auf 1. oder 8. Reihe. Dies muß also ausgeschlossen werden.
Henrik Juel: With the additional condition ruling out solutions like +wPa1, the problem now seems correct
Adding wPe2,g2 gives an illegal position, as [Lf1] could not have been captured on f1 in Mars Circe (2019-2-14)
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comment
Keywords: Circe (Mars), Illegal cluster, only Kings
Genre: Retro, Fairies
Reprints: G) Problemkiste (50) 08/1987
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-2-15 more...
5 - P0000726
Hans Gruber
2873 Die Schwalbe 58 08/1979
P0000726
(3+5) C+
ser-h#19
Wieviele Lösungen?
Eine Lösung ist: 1. e5 2. f5 3. f4 4. f3 5. f2 6. f1=L 7. Ld3 8. g5 9. g4 10. g3 11. g2 12. g1=D 13. De3 14. h5 15. h4 16. h3 17. h2 18. h1=D 19. Dhe4 c3#
play all play one stop play next play all
911,797,992 Lösungen
Basically there are 1,6,6,6 moves, and choices of promotion to D/L in 2 cases. The difficulty is in managing the collisions on f2,f3&g2. The best way is probably consider in turn which pawn has priority to pass through the square. This partitions the solution set into 2^3=8 cases.
A.Buchanan: I see that the term "Pawn Endgame" is now the English translation of "Kindergarten Problem". To me, an endgame is a study. Does "Kindergarten Problem" carry that connotation in German, or does it refer more to general compositions such as this one? (2019-2-2)
Mario Richter: The latter is the case, we even have some famous Kindergarten Problems in the Retro genre (think e.g. of some of Thierry LeGleuher's works). "Kindergarten" refers to the fact that besides the two kings only "children" (aka pawns) are on the board.
So I do not understand the choice of "Pawn Endgame" as the english translation, even less because the english language has a word like "kindergarden" ... (2019-2-2)
A.Buchanan: Rainer Staudte has recently changed it. Out of respect, I don't want to unilaterally change it back but would like to hear his perspective. Apparently even in English, Kindergarten is the more common spelling. (2019-2-2)
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comment
Keywords: Path enumeration, Series mover, Promotion in forward play, Kindergarten Problem, Excelsior
Genre: Mathematics, Fairies
Computer test: Mario Richter: rawbats' output: 911797992 Loesungen gefunden time= 1.535000(s) (2019-2-2)
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-2-3 more...
6 - P0000811
Tibor Orban
1791 Die Schwalbe 38 04/1976
Lob
P0000811
(15+15) C+
BP in genau 4,0
1. e4 e6 2. Lb5 Ke7 3. Lxd7 c6 4. Le8 Kxe8
play all play one stop play next play all
Mark Thornton: In January 2011, a fictional Hungarian detective named "Tibor Orban" appeared in the BBC crime drama "Silent Witness". Tibor Orban was played by the actor Ivan Kamaras (http://en.wikipedia.org/wiki/Iv%C3%A1n_Kamar%C3%A1s). (2012-7-21)
Dirk Borst: The word "genau" can and should be removed. "BP in 4,0" historically and logically means: "Position after the 4th black move; how did the gane go?" So a shorter game cannot be a cook, by definition. (2019-4-18)
Henrik Juel: I disagree, Dirk
Usually the composer asks for a shortest proof game; the 'genau' addition is a handy way of emphasizing the few exceptions, like this one
1.e4 e6/c6 2.Lc4/Lb5 c6/e6 3.Lxe6/Lxc6 dxe6/dxc6 are two of the four shortest proof games without loss of tempo (2019-4-18)
Per Olin: The solution is unique also in 4.5 moves: 1.e3 e6 2.Lb5 Ke7 3.Lxd7 c6 4.Le8 Kxe8 5.e4 (2019-4-19)
comment
Keywords: Unique Proof Game, Switchback, Loss of tempo
Genre: Retro
Computer test: Resolution time : 1.21 s., Natch 2.3 Copyright (C) 1997,98,99,2001,2002,2003,2004 Pascal Wassong
Reprints: 32 Probleme für Tiger 3 03/1984
(I) Schachkalender 1987
7 Shortest Proof Games 11/1991
(3) feenschach 123 01-06/1997
(1) Probleemblad 03/1999
4 Introduction to Proof Games 03/2010
4b 64 Proof Games 2012
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2013-4-20 more...
7 - P0001275
Henry Anthony Adamson
The Chess Amateur 03/1926
P0001275
(14+10)
#2
1. Kf2+ Dc1 2. Txc1#
play all play one stop play next play all
Henrik Juel: Not 1.0-0?, e.g. -1... Dc2 -2.Lc1 Db1 -3.Td2 Dc2 -4.Td1 Db1 -5.Ld2 Dc1 -6.Lc3 D=c2 -7.Td2 ?? (2004-2-23)
Yoav Ben-Zvi: [bBf8] was captured at home by an officer, the other 5 missing Black pieces were captured by the wPs (2 on the b file, by [wPc2] and [wPa2], and 1 each on the d, e and g files). It follows that [bBc8] was captured by a wP outside it's home, after being released by bPb7-b6, and that each of [bPc7], [bPf7] and [bPh7] accounts for a wP capture. Since none of the captures by wPs is on the c, f or h files, each of these bPs either promotes or else captures to arrive at a file where a wP can capture it directly.
Assuming White retains the right to castle implies the following:
[bPh7] could not move directly (without capture) to promotion on h1 as this would require a move by [wRh1]. [bPf7] could not move directly to promotion by bPf2-f1=X as this would require a prior move by wK. Each of these bPs must therefore have captured one of the missing wNs. No other White pieces are missing so [bPc7] did not capture. In order to account for a wP capture it must have moved directly to promotion on c1. Prior to the promotion on c1, the way to promotion on the c file must be cleared by [wPc2] capturing on the b file. Promoting [bPf7] entails a move by wK even if the bP captures (promoting from f2 or on e1) so, to preserve White castling, it must be captured directly by wPf2xPe3 (after capturing a wN on the e file).
Looking backwards from the diagram position:
The pieces on the a and b files form a locked West cage. All officers on the a file are immobile until the cage is released. The West cage remains locked until the retraction of wPc2xb3 or wPc3xb4 or bPb7-b6, not bPc7xb6? as [bPc7] does not capture (see above). Retraction of wPc2xb3 requires the previous release of the cage to allow exit of bKa1 via c2, d3, since alternative exit paths of the bK require a move by wK to clear the way. Retraction of bPb7-b6 requires previous uncapture and return home of [bBc8]. The uncapture of [bBc8], by a wP, occurs on a light-colored square, b3 or d3. Each of the alternatives for uncapturing [bBc8] requires previous release of the cage: wPc2xb3 since it is preceded by exit of bKa1(as noted above), wPa2xb3 or wPe2xd3 since these are preceded by exit of wBa2 to remove the obstruction on a2 or to retract home [wBf1]. It follows that the uncapture of [bBc8] and therefore the retraction of bPb7-b6 requires previous release of the cage. The remaining alternative for release of the West cage under the assumption that White may castle, retraction of wPc3xb4, is next to be considered.
Prior to the unpromotion by bPc2-c1=X, the following is known: the cage remains locked as it can be released only after the unpromoted bP retreats to c4 allowing wPc3xb4 to be retracted without blocking the retreat of bP to c7, the officers on the a file are immobile, retraction of bPb7-b6 locks out [bBc8], retraction of wPc2xb3 or wPc3xb4 blocks the retreat of Black's unpromoted pawn on the c file, retraction of wPd2-d3 requires prior retraction of wBd2 to c1 leading to permanent obstruction of the unpromotion on c1, retraction of wPe2-e3 or wPe2xd3 locks out [wBf1], retraction of wPf2xe3 prevents subsequent retraction of bBa5 to g1 and retraction of wPh2xg3 prevents subsequent unpromotion of bBa5 by bPh2xNg1=B. The rejection of all of these alternatives (prior to the unpromotion on c1) means that neither side can uncapture or play a pawn retraction. This means that the retroplay preceding the unpromotion on c1 consists only of moves by bQc7, wBd2 and wRe2, proving that the Black piece unpromoted on c1 must be bQc7. Since wK and wPs are immobile, wBd2 is restricted to the squares c1, d2 and c3. Since it has been shown that [bPc7] promotes to queen, not bishop, and [bPf7] does not promote at all, the promotion to bBa5 is by [bPh7] playing bPh2xNg1=B.
Since the wK stands immobile on e1, the unpromotion of the bQ by bPc2-c1=Q occurs with a shield standing on d1 to protect the wK from check by the promoted bQ. This shield can only be provided by wRe2 since d1 is a light-colored square that cannot be occupied by wBd2 and (as noted above) no uncaptures can be played prior to the unpromotion so the sheilding piece must be present in the diagram. If the unpromotion on c1 occurs with wB standing on c3 then White responds to the unpromotion by wRd2-d1+ and Black is in Retro-Stalemate caused by wBc3 obstructing the retreat of the unpromoted bP and the lack of Black tempo retractions that would allow White to remove the obstruction (this is shown in the Try noted by Henrik).
Another possibility that needs to be considered is that, when the unpromotion on c1 occurs, wB stands on d2 (instead of c3). In this case White responds to the unpromotion by retracting wBc1-d2+ (shielding bK from wRd1) followed by retreat of the unpromoted bP to c4 and the retraction of wPc3xb4 releasing the West cage. This shows that the position with bQc7 on c1, wRe2 on d1 and all other pieces as in the diagram, and White to play, can be reached with White retaining the right to castle. However, due to Retro-Opposition between bQ and wB colliding on c1 and the lack of tempo retractions by either side, other than moves by wK or wRh1, to overcome parity of bQ shuffling between b1 and c1 and wB shuffling between d2 and c3, there is no valid retraction from the diagram position with castling rights preserved. This is demonstrated in Henrik's Try if Black delays unpromotion of bQ, retracting -6...bQb1-c1 but it is simpler to prove by considering forward play. It can be seen that in the relevant position (with wKe1 and wRh1 immobile) White must play 1.wBd2-c3 (c1 is obstructed by bQ) followed by bQc1-b1 (the shield for the bK must be maintained) 2.wBc3-d2, bQb1-c1 repeating the position. There is no way to advance to the diagram position and preserve White's right to castle so in this case too (wB standing on d2 when bQ is unpromoted) White can't castle.
It has been shown that the assumption that White can castle leads to contradiction in every case thus proving (by "Reducto ad Absurdum") that White cannot castle. (2019-8-5)
A.Buchanan: Beautiful solution, with a dramatic tempo-based finale - thanks for posting such an authoritative solution. Which tempo keyword is meant to be used for this? :) (2019-8-6)
Yoav Ben-Zvi: The reprint of this problem in Ceriani's book appears in the chapter devoted to the Retro-Opposition phase of a resolution, under the heading "Defferred R.O.".
The analysis contains several instances of repeated thematic content (Echo) such as: "Retro-Shield" (by bQ, wR and wB, on b1, c1, d1), "Retro-Opposition" (temporary obstructions by wB and bQ on c3 and c1) and locking of various Home and Dynamic cages.
The #2 stipulation reflects the preference, at the time this was published, for RA problems to be presented as orthodox. This is no longer considered important so the analysis can be used to reject castling in the last move, as in the following version:
wBd2 on c3, wRh1 on f1, wRe2 on f2, wKe1 on g1 - "Last Move?". (2019-8-14)
A.Buchanan: (1) Have you got both of Ceriani's books? How did you get hold of them? I guess they are still under copyright. Retro Corner has been saying for 20 years that you need to write to Ceriani's son. Is that still true? Hasn't he got an email address now.
(3) I think your statement "This is no longer considered important" is too black and white. Generally I find it satisfying if the composer is able to tie future and past together in this way. And a check in the diagram position is to my mind an unpleasant defect, to be avoided if possible. (2019-8-15)
Henrik Juel: There are two ways of telling the solver immediately who has the move:
By having a king in check or by specification, directly by saying so or indirectly by a forward stipulation
It has got out of fashion to cast retro problems as forward ones, but there are still examples of imprecise stipulations, like #1: sometimes it should be interpreted as a condition, saying that White has the move, and sometimes it means 'Who mates in 1?' (2019-8-15)
A.Buchanan: (1) Yes #1 is a special stipulation. There are 4 possible interpretations: who moves first (Codex Article 15, "the official joke") but also who gets mated (maybe should be added to Codex or certainly to PDB glossary somehow).
(2) I get that RA has kind of come of age: it no longer needs to justify itself behind an orthodox stipulation. Hurray, I suppose.
(3) I am not objective in liking these old-style stipulations, because DP is all about interaction between forward and retro play. One of my heroes, Guus Rol, is also a big enthusiast of combining these two modalities, which he terms "retro-activity".
(4) And it is cool to read the same diagram in two ways: both forward and backwards. It's like a cryptic crossword clue where the same text has two meanings. Even if the forward play is not very thematic or interesting.
(5) So I hope that the RA community can feel sufficiently confident in its status now that it doesn't need to "fix" a classic problem with a perfectly natural #2, by making a second-rate Type C position out of it.
(6) Any info about the Ceriani books please? (2019-8-16)
Henrik Juel: You can buy a used copy of '32 characters and 1 author' on an italian homepage for €350
which seems very expensive to me
Most of the problems from the book are on the PDB (2019-8-16)
comment
Keywords: Cant Castler, Castling (wk), Promotion (l)
Genre: Retro
Reprints: 155a 32 personaggi e 1 autore 1955
147 Europe Echecs 86 03/1966
Input: Gerd Wilts, 1995-6-3
8 - P0001343
Friedrich Amelung
Düna-Zeitung 1897
P0001343
(5+3) C+
#2
1. hxg6ep Kh5 2. Txh7#
play all play one stop play next play all
siehe P1291160
Sally: Der en passant-Schlag als einziger Schlüselzug lässt sich im Zweizüger erst mit acht Steinen darstellen. Dies ist die früheste Aufgabe und beste Darstellung, die mit Zweispänner
möglich ist. (2019-1-18)
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comment
Keywords: En passant, En passant as key
Genre: Retro, 2#
Computer test: Popeye 4.61
Reprints: 55B Retrograde Analysis 1915
169 Allgemeine Zeitung Chemnitz 04/12/1927
(VIII) Problem 37-40 09/1956
(1) Problem 103-105 01/1967
215 Europe Echecs 124 04/1969
D12 feenschach 27, p. 27, 04/1975
(2) Mat Plus 12 10-12/2009
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-2-17 more...
9 - P0001438
Niels Høeg
1862 The Problemist FCS 12, p. 129, 06/1935
P0001438
(14+8)
Wer gewinnt?
1. ... bxc2#?
1. Tc1+ Kxa2 2. Sc6 fxe1=D+ 3. Txe1 ... 4. Sb4#

R: 1. ... Ka1-b1 2. Sc6-b8 Kb1-a1 3. Sd8-c6 Ka1-b1 4. Se6-d8 Kb1-a1 5. Sf4-e6 Ka1-b1 6. Sh3-f4 Kb1-a1 7. Sf4xBh3 Ka1-b1 8. Sg2-f4 Kb1-a1 9. Se3-g2 Ka1-b1 10. Sb6-a4 Kb1-a1 11. Sc4-b6 Ka1-b1 12. Sa3-c4 b4-b3 13. Sb1xBa3 a4-a3 14. Tc1-c2 a5-a4 15. Kc2-d1 a6-a5 16. Kd3-c2 b5-b4 17. Dd1-e1 h4-h3 18. Db3-d1 h5-h4 19. Te1-c1 h6-h5 20. Sd1-e3 h7-h6 21. Sa3-b1 Kb1-a1 22. Sc4-a3 Ka1-b1 23. Kd4-d3 Kb1-a1 24. Da3-b3 Kc1-b1 25. Sa5-c4 Kc2-c1 26. Sb3-a5 Kb1-c2 27. Sc1-b3 Ka1-b1 28. Se3-d1 Kb1-a1 29. Sg4-e3 Kc2-b1 30. Sb3-c1 d6-d5 31. Ta1-e1 d7-d6 32. Tb1-f1 Kd1-c2 33. Sc1-b3
play all play one stop play next play all
8/2bbb1bb/b7/1b6/3K2S1/D1B2B2/BB1BBb1B/TTSk2Lt (14+10)
A possible proof game from this intermediate position is:
1. Sb3+ Kc2 2. Tf1 h6 3. Tae1 h5 4. Sc1 Kb1 5. Se3 Ka1 6. Sd1 Kb1 7. Sb3 Kc2 8. Sa5 Kc1 9. Db3 Kb1 10. Kd3 Kc1 11. Sc4 Kb1 12. Sa3+ Ka1 13. Sb1 h4 14. Se3 h3 15. Tc1 d6 16. Dd1 d5 17. De1 a5 18. Kc2 a4 19. Kd1 a3 20. Tc2 b4 21. Sxa3 b3 22. Sb5 Kb1 25. Sb8 Ka1 28. Sxh3 Kb1 32. Sa4 Kb1
Black captured the white bishops on c1 and f1. White captured Lf8 on f8 and g2xf3 and promoted his f-pawn on b8 to L, which was brought to g1, implying that a7, b6, and b7 are unoccupied. Between moves 13 and 21 white has no time for a tempo move, and after this neither side can change the tempo, so white has the move in the problem position and wins.
Henrik Juel: Moving Sb8 to b4 would allow a more contemporary stipulation: #1 (who?)
with the solution: 1.Tc1#, not 1... bxc2? (2016-10-12)
Henrik Juel: If you prefer retroplay, the plan is to uncapture black pawns on h3 and a3, screen with a knight on b1, retract Tc1-c2, extract Kd1 and De1, retract Te1-c1, screen with the other knight on d1, retract the first knight to c1, extract Sd1, hide the white rooks on a1 and b1 while black king waits on c2, and then he can get out via g2 and h3. The details might be
-0... Ka1 -1.Sc5 Kb1 -2.Se4 Ka1 -3.Sg5 Kb1 -4.Sh3 Ka1 -5.Sf4xPh3 Kb1 -6.Sg2 Ka1 -7.Se3 Kb1 -8.Sc6 Ka1 -9.Sa7 Kb1 -10.Sb5 Ka1 -11.Sa3 b4 -12.Sb1xPa3 b5 -13.Tc1 a4 -14.Kc2 a5 -15.Kd3 a6 -16.De1 d6 -17.Db3 d7 -18.Te1-c1 h4 -19.Sd1 h5 -20.Sa3 Kb1 -21.Sc4 Ka1 -22.Kd4 Kb1 -23.Da3 Kc1 -24.Sa5 Kc2 -25.Sb3 Kb1 -26.Sc1 Ka1 -27.Se3 Kb1 -28.Sg4 Kc2 -29.Sb3 h6 -30.Ta1 h7 -31.Tb1-f1 Kd1 -32.Sc1 (2016-10-12)
Henrik Juel: The source with more details is
1862 The Problemist Fairy Chess Supplement no.12, June 1935, p.129
This magazine was later renamed Fairy Chess Review (2019-5-28)
more ...
comment
Keywords: Whose move?, Promoted material on the board (L)
Genre: Retro
Reprints: 220 FIDE Album 1914-1944/III 1975
312 Europe Echecs 213/214 10/1976
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-5-28 more...
10 - P0001884
Thomas R. Dawson
Aachener Anzeiger 1926
P0001884
(8+2)
#1 vor 2
VRZ, Typ Hoeg
R: 1. c7-c8=D Lb4xSa3 2. Sc5-a6, dann 1. Sb3#
R: 1. c7-c8=D Lc5xSa3 2. Sb4-a6, dann 1. Sc2#
play all play one stop play next play all
klären: Quelle: Schach ohne Grenzen, S.35, Nr.3 = Magyar Sakkvilag, 1926 (VF)
Henrik Juel: -1.Q=c7 Bb4:S -2.Sc5, 1.Sb3#; -1.. Bc5:S -2.Sb4, 1.4Sc2#. It is illegal to supplement a checking bS on a6. (2003-10-9)
Sally: Weiß nimmt c7-c8D zurück. Nimmt Schwarz Lb4-a3 zurück, so ergänzt Weiß auf a3 einen Springer und nimmt Sc5-a6 zurück, um durch Sb3#. Nimmt Schwarz Lc5-a3 zurück, so ergänzt Weiß auf a3 wieder einen Springer und nimmt Sb4-a6 zurück, um durch Sc2 mattzusetzen. (2012-2-21)
Henrik Juel: Also 'On Retraction Chess Problems' gives Magyar Sakkvilag as original source (2019-2-10)
comment
Keywords: Promotion, Defensive Retractor, Defensive Retractor, Type Høeg
Genre: Retro
Reprints: 127 Magyar Sakkvilag 04/1926
(31) On Retraction Chess Problems 1927
3 Chess unlimited , p. 35, 1969
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-2-12 more...
11 - P0001951
Luigi Ceriani
Karl Fabel

Am Rande des Schachbretts 1947
P0001951
(9+16)
KBP?
(AL: 183,0)
1. a4 c5 2. a5 c4 3. a6 c3 4. b3 d5 5. Lb2 cxb2 6. Sa3 Kd7 7. Sc4 Kc6 8. Se5+ Kb5 9. Ta5+ Kb4 10. Tb5+ Ka3 11. Sef3 Ka2 12. c3 d4 13. Dc1 e5 14. Kd1 e4 15. Kc2 e3 16. Kd3 g5 17. Ke4 g4 18. Kf4 d3 19. Dc2 dxc2 20. h3 c1=T 21. Th2 Ta1 22. Th1 Kb1 23. Th2 Kc1 24. Th1 Lf5 25. Th2 Lb1 26. d3 f5 27. Sd2 exd2 28. Sf3 Sf6 29. Kg5 Ld6 30. Kh6 Sd5 31. Kg7 Se3 32. Kf7 h5 33. Kg7 Ta4 34. Kf7 La2 35. Tb6 d1=L 36. Kg7 Lc2 37. Kf7 Lcb1 38. Kg7 Sd1 39. Kf7 g3 40. Kg7 gxh2 41. e3 h1=T 42. Le2 Sd7 43. Sh2 Sc5 44. Lg4 Se4 45. Kf7 hxg4 46. Kg7 g3 47. Kf7 gxh2 48. Kg7 Te1 49. Kf7 Te2 50. Kg7 Tc2 51. Kf7 h1=T 52. Kg7 Te1 53. Kf7 Lh2 54. Kg7 Sg3 55. Kf7 Sh1 56. Kg7 Tah4 57. Kf7 Kd2 58. Kg7 Ke2 59. Kf7 Tc1 60. Kg7 Lc2 61. Kf7 Ta1 62. Kg7 Lab1 63. Kf7 Ta5 64. Kg7 La2 65. g3 Kf3 66. Tb4 Tb5 67. Kf7 Te2 68. Kg7 Lcb1 69. Kf7 Tc2 70. Kg7 Tc1 71. Kf7 Lc2 72. Kg7 Ta1 73. Kf7 Lab1 74. Kg7 Ta5 75. Ta4 bxa6 76. Ta1 La2 77. Tc1 Lcb1 78. Tc2 f4 79. Te2 Lc2 80. Te1 Lab1 81. Tg1 Ta1 82. Tg2 La2 83. Kf7 Tc1 84. Kg7 Lcb1 85. Kf7 Tc2 86. Kg7 Te2 87. Kf7 Te1 88. Kg7 Tg1 89. Kf7 Lc2 90. Kg7 Lab1 91. Kf7 Ta5 92. Kg7 Ta1 93. Kf7 La2 94. Kg7 Tc1 95. Kf7 Lcb1 96. Kg7 Tc2 97. Kf7 Te2 98. Kg7 Tee1 99. Kf7 Tef1 100. Kg7 Lc2 101. Kf7 Lab1 102. Kg7 a5 103. Kf7 a4 104. Kg7 a3 105. Kf7 a2 106. Kg7 a1=T 107. Kf7 La2 108. Kg7 Tc1 109. Kf7 Lcb1 110. Kg7 Tc2 111. Kf7 Te2 112. Kg7 Tee1 113. Kf7 Lc2 114. Kg7 Lab1 115. Kf7 a5 116. Kg7 a4 117. Kf7 a3 118. Kg7 a2 119. Kf7 a1=T 120. Kg7 La2 121. Kf7 Tc1 122. Kg7 Lcb1 123. Kf7 Tc2 124. Kg7 Ke2 125. Kf7 Kd2 126. Kg7 Kc1 127. Kf7 Tce2 128. Kg7 Kd2 129. Kf7 Lc2 130. Kg7 Lab1 131. Kf7 Ta1 132. Kg7 La2 133. Kf7 Tc1 134. Kg7 Lcb1 135. Kf7 Tc2 136. Kg7 Kc1 137. Kf7 Tcd2 138. Kg7 Lc2 139. Kf7 Kb1 140. Kg7 Ka1 141. Kf7 Lab1 142. Kg7 Ka2 143. Kf7 Ka3 144. Kg7 La2 145. Kf7 Lcb1 146. Kg7 Tc2 147. Kf7 Tc1 148. Kg7 Lc2 149. Kf7 Ta1 150. Kg7 Lcb1 151. Kf7 Tc2 152. Kg7 Dd5 153. Kf6 Df3 154. Kf7 De2 155. Kg7 Dd2 156. Kf7 Dc1 157. Kg7 Tce2 158. Kf7 Dd2 159. Kg7 Lc2 160. Kf7 Tc1 161. Kg7 Lcb1 162. Kf7 Tc2 163. Kg7 Dc1 164. Kf7 Tcd2 165. Kg7 f3 166. Kf7 Lc2 167. Kg7 Da1 168. Kf7 Lcb1 169. Kg7 Tc2 170. Kf7 Tc1 171. Kg7 Lc2 172. Kf7 Lab1 173. Kg7 Ka2 174. Kf7 Ted2 175. Ke7 Tee2 176. Kd7 Tfe1 177. Kc7 Tgf1 178. Kb7 Lg1 179. Ka7 T4h6 180. Th2 Tb6 181. Tg2 Th7+ 182. Ka8 Thb7 183. Th2 Tb8+
play all play one stop play next play all
Yoav Ben-Zvi: The Move Length Record has been surpassed, after more than 70 years, by Goldsteen, see P1345778. (2019-7-7)
more ...
comment
Keywords: Non-Unique Proof Game, konsekutive Umwandlungen 6 (tltttt), Non-standard material, under-promotion, Move Length Record
Genre: Retro
Reprints: 127 32 personaggi e 1 autore 1955
1438 FIDE Album 1945-1955 1964
Die Schwalbe 3, p. 81, 02/1970
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-6-13 more...
12 - P0002178
Niels Høeg
Deutsches Wochenschach 02/06/1907
P0002178
(14+11)
#3 (RV)
1) R: 1. f7-f5: 1. gxf6ep Txa1 2. Sg7+, 1. ... Txh5+ 2. Dxh5+
2) R: 1. d7-d5: 1. cxd6ep Ta5+ 2. Txa5
3) R: 1. T-a8: 1. Sg6
4) R: 1. T-h8: 1. Sc6
5) R: 1. K-e8: 1. Sg6/1. Sc6
play all play one stop play next play all
Henrik Juel: The solution text above should be construed to sit in two columns, reading: If last move was f7-f5, White mates in three by 1.gxf6ep Txa1 2.Sg7+, 1... Txh5+ 2.Dxh5+; if last move was d7-d5, White mates in three by 1.cxd6ep Ta5+ 2.Txa5; etc. (2004-4-26)
Henrik Juel: The pawn captures were
White: axb, d4xc5, fxe, hxg (plus one capture with an officer)
Black: b3xc2 (and possible one more, but not with Pc4)
so last move was not b5xc4 (2019-8-22)
comment
Keywords: En passant, Partial Retro Analysis (PRA), Castling (sksg)
Genre: Retro
Reprints: 99 Retrograde Analysis 1915
34 32 personaggi e 1 autore 1955
(D) Die Schwalbe 13 02/1972
RA65 diagrammes 27 05-06/1977
(19) Die Schwalbe 68 04/1981
Input: Gerd Wilts, 1995-6-3
Last update: Gerd Wilts, 2005-12-3 more...
13 - P0002554
Unto Heinonen
Probleemblad 1991
1. Preis
P0002554
(16+16) cooked
BP in 43,0
1. h4 a5 2. Th3 Ta6 3. Tf3 Tg6 4. Sh3 Tg3 5. Sf4 Th3 6. g3 Th2 7. Lh3 Sh6 8. Le6 Sf5 9. Lc4 d5 10. Kf1 Th1+ 11. Kg2 Tg1+ 12. Kh3 Kd7 13. Kg4 h5+ 14. Kg5 Th6 15. a4 Tb6 16. T1a3 Kc6 17. Tac3 Tb3 18. Sg6 Ta3 19. b3 Ta2 20. La3 Dd6 21. Lc5 Sd7 22. La7 Sb6 23. Sh8 Kc5 24. La6+ Kb4 25. Tc5 g6 26. Sc3 Lg7 27. Se4 Lc3 28. Da1 Sd4 29. Kh6 Ld7 30. Kg7 Lb5 31. Kf8 Ld3 32. Ke8 Dc6+ 33. Kd8 Sc4 34. Kc8 Ka3 35. Kb8 Lb4 36. Ka8 De8+ 37. Lb8 Sb6+ 38. Ka7 Sa8 39. c4 Sc2 40. Df6 Sa1 41. Db6 Kb2 42. Sf6 Ta3 43. Sd7 Ka2
play all play one stop play next play all
Cook: NL
1. h4 a5 2. Th3 Ta6 3. Tf3 Te6 4. g3 Te3 5. Lh3 Sh6 6. Le6 Sf5 7. Lc4 d5 8. Kf1 Dd6 9. Kg2 Da6 10. Kh3 Kd7 11. Kg4 h5+ 12. Kg5 Th6 13. a4 Tb6 14. Ta3 Kc6 15. Tc3 Tb3 16. Sh3 Ta3 17. b3 Ta2 18. La3 Sd4 19. Lc5 Lf5 20. La7 Db6 21. Sf4 Kc5 22. Sg6 Kb4 23. Sh8 g6 24. La6 Lg7 25. Tc5 Db5 26. c4 Sc2 27. Sc3 Ka3 28. Se4 Lc3 29. Da1 Lb4 30. Df6 Tc3 31. Kh6 Kb2 32. Kg7 Ta3 33. Kf8 Sd7+ 34. Ke8 Ka2 35. Kd8 Sa1 36. Kc8 Sf8+ 37. Kb8 Sd7+ 38. Ka8 Tc1 39. Lb8 Sb6+ 40. Ka7 Sa8 41. Db6 Tg1 42. Sf6 De8 43. Sd7 Ld3 (Sebastian Natschke)
Henrik Juel: Very good, Sebastian (although not for the author...) (2019-6-17)
paul: Probably the cook of the year, because the problem is well known. Which is now the length record for a capture free proof game? (2019-7-16)
paul: The length record for a capture-free PG is now 40.5 moves by Th. le Gleuher (Phenix50/1997) (2019-7-16)
Mario Richter: The problem Paul was referring to is P0006623. So far it has resisted all my and rawbats' attempts to cook it, and I think that chances are high that it is indeed correct ... (2019-7-17)
more ...
comment
Keywords: Unique Proof Game, Length Record, Capture-free
Genre: Retro
Reprints: H17 FIDE Album 1989-1991 1997
feenschach 137 08-09/2000
Input: Gerd Wilts, 1995-6-3
Last update: Olaf Jenkner, 2019-6-18 more...
14 - P0002661
Henry Tanner
5094 Thema Danicum 07/1991
P0002661
(1+1)
Ergänze sT, sL und sS zu einem IC!
3 Lösungen
a) +sTb4+sLc4+sSb3
b) +sTc2+sLb3+sSc4
c) +sTd1+sLb1+sSc3
play all play one stop play next play all
Henrik Juel: The solutions feature impossible check by T, L, and S (2019-2-14)
comment
Keywords: Illegal cluster, no 8x8 board, Aristocrat
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-2-18 more...
15 - P0002678
Hans Gruber
18) feenschach 45, p. 37, 01-03/1979
P0002678
(1+1)
Ergänze 1 wB zu einem IC!
Wieviele Lösungen?
Gitterschach
b) +Ohneschlag

a) 20 Lösungen: a1, ..., h1, a8, ..., h8, c2, e2, a6, h6
b) 34 Lösungen: a1, ..., h1, a8, ..., h8, c2, e2, a6, ..., h6, a7, ..., h7
Henrik Juel: In Grid Chess a white pawn cannot reach a6 (nor h6), as a5-a6 and b5xa6 are impossible
With No-capture Chess added as extra condition a white pawn can reach no higher than row 5 (2019-2-14)
more ...
comment
Keywords: Illegal cluster, No-capture chess, Grid Chess, only Kings
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2015-3-20 more...
16 - P0002730
Maryan Kerhuel
991 Phénix 14 09/1991
Michel Caillaud gewidmet
P0002730
(1+3)
Ergänze wD, wL, 3 wBB, sT und 2 sBB zu einem IC!
Patrouilleschach
(+wDb7,wLc6,wBb6d5d7,sTd6,sBb5e7) R: 1. Dc7xb7, aber keine Auflösung
play all play one stop play next play all
Henrik Juel: The stipulation and solution are inconsistent
Assuming that 2 wBB is changed to 2 sBB, I cannot see how the solution position without Td6 could be legal
-1.Dc7xSb7+ Sd6xSb7 is not possible, as sSd6 checks wK (2019-2-14)
comment
Keywords: Illegal cluster, Patrol Chess, Kindergarten Problem, Rex solus (w)
Genre: Retro, Fairies
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-2-15 more...
17 - P0003049
Raymond Smullyan
The Chess Mysteries of the Arabian Knights , p. xii, 1981
P0003049
(14+15)
Ein sL hat einen weißen Stein geschlagen. Welcher sL?

Der sLe5 hat den wL geschlagen.
H.Juel: The capture sequence must have been g7xSh6 before d2xTc3 before Lx[Lc1]
more ...
comment

Genre: Retro
Reprints: Die Schachgeheimnisse des Kalifen , p. 10, 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
18 - P0003050
Raymond Smullyan
The Chess Mysteries of the Arabian Knights , p. xiii, 1981
P0003050
(5+1)
In welche Richtung spielt Weiß?
Im letzten Zug wurde kein Stein geschlagen.
R: 1. Td2-f2 Kf2-f1 2. Be2xXd1=S+
play all play one stop play next play all
Weiß spielt von oben nach unten!
Henrik Juel: The stated retroplay is the only possibility
so White pawns move downwards (2019-1-23)
comment
Keywords: Conditional problem, Aristocrat, Rex solus (s)
Genre: Retro
Reprints: Die Schachgeheimnisse des Kalifen , p. 12, 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
19 - P0003053
Raymond Smullyan
3a The Chess Mysteries of the Arabian Knights 1981
P0003053
(12+11)
Ersetze einen der Steine durch den wK, so daß die Stellung legal ist!
Henrik Juel: Solution
0. Replacing wK on g8, h7, or h8 obviously does not work; neither does a4, a6, a7, b5, b7, b8, c4, c6, d7, f7, or g6, having both kings in check
1. What about replacing the white man on d5, e4, g4, or h5? This gives four missing white men, three of which were captured on light squares by b7xa6 and d7xc6xb5, while the fourth, [Lc1], was captured on a dark one
Hence the retroplay -1.Df8xYg8 Yxg8 does not work, because g8 is light, nor does -1.Df8xSg8 Sf6 -2.Dh6, because Sf6 would check wK (on d5, e4, g4, or h5)
(-1... Kg7 is illegal, and no other black men can retract)
2. Replacing a black man on a5, a8, e7, or e8 does not work, because the three missing white men include the dark-squared [Lc1]
3. This leaves the solution: putting wK on c7; now the black pawn play could have been b7xa6 and c7xb6-b5, so many retroplays are possible (after the uncheck -1.Df8xg8) (2019-1-23)
comment
Keywords: Add pieces
Genre: Retro
Reprints: 3a Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
20 - P0003054
Raymond Smullyan
3b The Chess Mysteries of the Arabian Knights 1981
P0003054
(12+10)
Ersetze einen Stein einer anderen Art als in der vorigen Aufgabe 3a durch den wK, so daß die Stellung legal ist!
Henrik Juel: Replacing Pa7 or Pc7 with wK would work, but this is ruled out by Alfred's stipulation clarification: wK may not take the place of a black pawn
Compared to P0003053, Da8 has been removed, but an extra missing black man makes no difference, so the arguments from there still apply
b7 is no longer attacked by Black, however, so the solution is putting wK on b7 (2019-1-23)
Mario Richter: Imho, Alfred's stipulation doesn't rule out Pa7, it should be: "Ersetze einen Stein einer anderen Art als in der vorangegangenen Aufgabe 3a (P0003053) durch dem wK, so daß die Stellung legal ist". This fits the original intention, where the problem is embedded into a story about Caliph Haroun al Rashid (the wK), who wents out one night masquerading as some other piece (=3a), and then again the next night (=3b), quote: "Only on this second night, he costumed himself differently than he had on the first." (2019-1-24)
Henrik Juel: Thanks for your clarification clarification, Mario
At first I thought that a7 was a cook, but then I interpreted Alfred's stipulation more broadly (2019-1-24)
more ...
comment
Keywords: Add pieces
Genre: Retro
Reprints: 3b Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
21 - P0003055
Raymond Smullyan
4 The Chess Mysteries of the Arabian Knights 1981
P0003055
(11+11)
Schwarz ist am Zug. Welcher Stein steht auf g4?
Darf Schwarz rochieren?

Steinkontrolle wegen des 'x' nicht exakt.
Henrik Juel: Solution
Black captured [Lc1] on c1 and played e7xd6xc5xb4xa3-a2xb1=L, capturing all six missing white men, so [Pf7,g7,h7] never captured, and Yg4 is black
Last move was not Te1-d1, so it was 0-0-0, and Y is not L
To let [Th1] out to be captured, [Pg2,h2] crosscaptured, so Lh2 is [Pg7] promoted on g1, and Y is not P
The forward sequence was: g2xh3 before [Th1] got out before g1=L before h2xg3, so there were not any more black promotions, hence the hidden black man is Sg4, and [Pf7,h7] were captured on their files
The white captures were a2xLb3, g2xPh3, and h2xLg3, leaving only [Pf7] who was captured on f2, f3, .. , or f7
[Pe2] must have promoted, either on e8, or on f8 via f7, so Ke8 has moved, and Black may not castle (2019-1-23)
comment

Genre: Retro
Reprints: 4 Die Schachgeheimnisse des Kalifen 1984
R10 Phénix 275-276, p. 10810, 07-08/2017
R10 Phénix 275-276, p. 10815, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
22 - P0003058
Raymond Smullyan
7 The Chess Mysteries of the Arabian Knights 1981
P0003058
(12+13)
Der schwarze Damenturm ist von einem Bauern geschlagen worden, der weiße Königsläufer wurde vorgegeben, Die beiden wT sind auf der selben Reihe geschlagen worden. Schwarz kann noch rochieren.
Wo wurden die wTT geschlagen?
Henrik Juel: Too many conditions for my taste
Alfred's addition shows that Ke8 (and Th8) never moved
The only white pawn capture was f2xe3, i.e., f2xTe3, so [Pb7,c7] cross-captured to let [Ta8] out
At first, only [Lc1] could get out, so the first black pawn capture was c7xLb6
But [Lc8] was in the way for [Ta8], so it was captured on c8, and La6 is a pawn promoted on f1
g2-g3 happened early to let promoted Lf1 reach a6, so Sf1 is also a promoted pawn
Hence Black captured gxf, and since the white rooks fell on the same row, they were captured on c6 an f6 (2019-1-24)
Henrik Juel: Alfred's addition was
Schwarz kann noch rochieren. (2019-1-24)
more ...
comment
Keywords: Conditional problem, Odds game
Genre: Retro
Reprints: 7 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
23 - P0003059
Raymond Smullyan
8 The Chess Mysteries of the Arabian Knights 1981
P0003059
(13+13+1)
Schwarz hat soeben rochiert und es sind keine weißen Umwandlungsfiguren auf dem Brett.
Ist der Ta5 weiß oder schwarz?

Ta5 is black
Henrik Juel: First some observations
Black has captured b7xa6 and played g3xh2-h1=L (other ways to promote [Pg7] on a light square need to many captures)
Assume that Ta5 is white
Then the black captures were b7xYa6 (Y is [Pe2] promoted) and g3xLh2
La2 cannot be promoted, because White must play b2-b3 before [Lc1] can reach h2 to enable the black promotion
Lb7 also cannot be promoted, because Black must play c7-c6 before [Dd8] can get out to enable [Pe2] to promote on g8
So Ta5 is black
(Then one of the two needed black pawn captures could be b7xTa6 or g3xTh2) (2019-1-25)
Henrik Juel: For a slightly clearer argument, please replace
'Lb7 also cannot be promoted'
with
La2 also cannot be the original [Lc8] (2019-1-25)
Mario Richter: My first attempt was: +wTa5, then R: 1. ... Lc8-b7 2. ~ b7xSa6 3. Sb8-a6 ~ 4. c7xTb8=S ~ 5. d6xDc7 ~ 6. e5xLd6, before I realized that afterwards it is not possible to unpromote sLa2 ... (2019-1-26)
Alfred Pfeiffer: For the sLL both is possible, each of them can be the original or the promoted piece. Beside the above discussed solution White could play first wTa1 to a6. After bxa6 Black could move its Ta8 to a5 and play its Lc8 to a2. Then White plays b2-b3 and the wLc1 to h2. After the promotion of sBg7 at h1 the promoted bishop could move to b7. Then Black moves c7-c6. In this case there is no need to promote the wBe2. It could be captured somewhere, the sDd8 also. (2019-1-26)
more ...
comment
Keywords: Non-standard material (l)
Genre: Retro
Reprints: 8 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
24 - P0003061
Raymond Smullyan
10 The Chess Mysteries of the Arabian Knights 1981
P0003061
(14+13+1)
Kein Bauer hat bisher mehr als einen Stein geschlagen, die Dh5 ist eine Originaldame. Zeige, daß sich die Farbe der Dh5 bestimmen läßt, wenn bekannt ist, ob die fehlende Dame auf ihrer eigenen Linie geschlagen worden ist!
Henrik Juel: .
If [Dd8] was captured by d2xDc3, Dh5 is white
If not, the capture was d2xTSc3, and Black later played exDd-d1=TS, so Dh5 is black (the sequence was d2xc3 before the promotion before Se3-d1 before e2-e3 before [Lf1] could exit)
Thus, Dh5 is black if the missing D was captured on the d-line, and white otherwise (2019-1-24)
more ...
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 10 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
25 - P0003062
Raymond Smullyan
11 The Chess Mysteries of the Arabian Knights 1981
P0003062
(11+10)
Woher kommt der wBg3?
Henrik Juel: The retroplay was not
-1... Kf6 -2.d5xPe5ep e7 -3.d4
because this would require too many black pawn captures (incl. promotion of Ld8)
So it was -1... Kf6xSg6 -2.Se5
If Pg3 came from f2, too many white pawn captures would be required (incl. promotion to S), so Pg3 came from h2 (2019-1-24)
Henrik Juel: for clarity, please replace the last parenthesis by
(because White must promote to S) (2019-1-24)
comment

Genre: Retro
Reprints: 11 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
26 - P0003063
Raymond Smullyan
12 The Chess Mysteries of the Arabian Knights 1981
P0003063
(13+15)
Weiß darf noch rochieren. Hat sich der sBb7 umgewandelt?
Henrik Juel: Black is missing one man ([Pb7]), so the only white capture was b2xc3, and the obvious explanation of the position is that White captured an original black officer, which was later replaced by promotion
Still, suppose Black did not promote
Then he must have captured a white officer with bxc, and White might promote [Ph2] on h8 after h7xg6 (later Black would have to complete the cross-capture with g7xh6)
In his first pawn capture Black must have captured an original white officer, but we can rule out all five possibilities:
Not S, as a promoted S could not leave h8
Not [Lf1], as it could not be replaced by promotion on h8
Not [Lc1], as it could not get out
Not T, as [Ta1] could not get out, and Th1 never moved
Not D, as Black would have to capture [Lc1] to let her out, and a8=L-h4 would require a total of four black captures
So [Pb7] did promote
(The possibility of White capturing the promoted officer after a2-a3 and b3xTa2-a1=Y will not work, as [Lc1] could not leave the SW corner, and b3xSLa2 are ruled out as above, so the promoted [Pb7] is still on the board) (2019-1-26)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 12 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
27 - P0003064
Raymond Smullyan
13 The Chess Mysteries of the Arabian Knights 1981
P0003064
(14+15)
Beide Könige haben nur je einmal gezogen.
Der sBa7 hat sich umgewandelt; in welche Figur?
Henrik Juel: solution: the promoted pawn is Dd7
Both kings have castled
White castled early to let out [Th1], so Black could capture axTb
To avoid a check on b2, Black must capture again bxTa and promote on a1
Let us consider the possible promotions:
S or L could not move without checking
T could not reach d8,e8
So the promotion was to D (2019-1-26)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 13 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
28 - P0003065
Raymond Smullyan
14 The Chess Mysteries of the Arabian Knights 1981
P0003065
(13+14)
Die schwarze Dame wurde auf ihrer eigenen Reihe und der weiße Damenturm auf seiner Linie geschlagen, keiner der beiden Könige hat gezogen, Schwarz darf rochieren. Was geschah mit dem weißen Bauern h2, der sich umgewandelt hat?
Henrik Juel: Too many conditions for my taste
The move sequence must have been
h7xg6 before h6-h7 before g7xh6 before b2xLa3 before b7xTa6 before h7xDg8=D! (with a screen on f8)
(A promoted S would check on f6 and a promoted L or T could not exit)
So the promoted pawn is Dd1
. (2019-1-26)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 14 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
29 - P0003066
Raymond Smullyan
15 The Chess Mysteries of the Arabian Knights 1981
P0003066
(15+13)
Welcher der beiden wL ist der Originalläufer?
Henrik Juel: solution: La2 is original
[Ta8] was captured in its corner, so White could not promote before g7xf6
Hence the sequence must have been
Lf1-a2 before b2-b3 before g7xLf6 before g8=L-g2
. (2019-1-26)
comment
Keywords: Non-standard material (L)
Genre: Retro
Reprints: 15 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-28 more...
30 - P0003067
Raymond Smullyan
16 The Chess Mysteries of the Arabian Knights 1981
P0003067
(14+13)
Der Th8 ist auf auf seinem Ursprungsfeld geschlagen worden, keiner der beiden KK hat gezogen, auf dem Brett befinden sich keine schwarzen Umwandlungsfiguren. Welches ist der weiße Originalläufer?
Henrik Juel: solution: Lb2 is original
Both h-pawns promoted
The sequences must have been
c2-c3 before c7xDd6 before h6xTg7xTh8=L-h2 before g2-g3
and hxTg before h1=Y before b2xYa3
. (2019-1-26)
Henrik Juel: If [Ta8] was captured on a3, [Ph7] need not promote, and White could just capture [Th8,Ph7] with officers
The result is unchanged (2019-1-26)
comment
Keywords: Conditional problem, Non-standard material (L)
Genre: Retro
Reprints: 16 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
31 - P0003068
Raymond Smullyan
17 The Chess Mysteries of the Arabian Knights 1981
P0003068
(4+4)
Was geschah mit dem weißen Königsläufer?
Henrik Juel: solution: [Lf1] was captured on f1
-1... f4xg4ep -2.g2 f5
. (2019-1-26)
comment
Keywords: Non-standard material (L)
Genre: Retro
Reprints: 17 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-28 more...
32 - P0003069
Raymond Smullyan
18 The Chess Mysteries of the Arabian Knights 1981
P0003069
(11+11)
Welcher weiße Stein wurde vorgegeben?
Henrik Juel: solution: [Lc1]
The retroplay was -1.Dd8xYe8 Yxe8 (-1... b7xa6/c6xb5 are illegal as they would prevent wK from reaching c8), so Black has captured the other missing white men on a light square
. (2019-1-27)
comment
Keywords: Odds game
Genre: Retro
Reprints: 18 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-5 more...
33 - P0003070
Raymond Smullyan
18b The Chess Mysteries of the Arabian Knights 1981
P0003070
(11+11)
Es fanden keine Umwandlungen statt.
Welcher weiße Stein wurde vorgegeben?
Henrik Juel: Seems cooked
As in P0003069 the retroplay shows that Black captured on a6,b5,c6,e8
The captured men must be wTTLS, as no wP could reach any of these squares (White also captured Dd8xe8)
But any one of [Pd2,e2,h2] could have been given as odds (one of Pd7,e6 could be [Ph2]) (2019-1-27)
Mario Richter: Smullyan wrongly argues: "... four White pieces must have been captured (one on e8, and three by the pawns on a6 and b5). The pawn from h2 could certainly not have been captured by either of the two Black pawns, nor could it get to e8 without promoting, which we are given it did not. Hence this pawn must have been given as odds."
As Henrik explained, Smullyan overlooked the simple possibility that wPh2 is still on the board (on d7 or e6).
So the problem is indeed cooked. (2019-1-28)
comment
Keywords: Conditional problem, Odds game
Genre: Retro
Reprints: 18b Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-28 more...
34 - P0003072
Raymond Smullyan
20 The Chess Mysteries of the Arabian Knights 1981
P0003072
(14+14)
Es befinden sich keine UWF auf dem Brett.
Zeige, daß der weiße Königsspringer bereits gezogen hat!
Henrik Juel: .
[Pb7] did not promote, because otherwise it would be on the board
The capture sequence must have been bxTa before b2xPa3
So [Sg1] must have moved to let a wT out
. (2019-1-27)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 20 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-28 more...
35 - P0003073
Raymond Smullyan
21 The Chess Mysteries of the Arabian Knights 1981
P0003073
(13+10)
Einer der beiden weißen Springer hat noch nicht gezogen. Welcher?
Henrik Juel: solution: Sg1
The retroplay was -1.Pc5xPd5ep d7 -2.c4 Ke8, so [Lc8] was captured on c8
The other white captures were b2xc3, e2xd3xc4, fxg, while Black played f7xTg6xPh5, axLb-b1=Y, so Sb1 must have moved
(The problem could have formulated without a condition by asking
Which wS must have moved?)
. (2019-1-27)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 21 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-5 more...
36 - P0003074
Raymond Smullyan
22 The Chess Mysteries of the Arabian Knights 1981
P0003074
(5+12+1)
Schwarz ist am Zug. Ist der Sa1 weiß oder schwarz?
Henrik Juel: solution: Sa1 is white
Last move was Kd1xSd2, so the black knights are accounted for
. (2019-1-27)
comment

Genre: Retro
Reprints: 22 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2019-1-28 more...
37 - P0003075
Raymond Smullyan
23 The Chess Mysteries of the Arabian Knights 1981
P0003075
(12+10)
Ein weißer und ein schwarzer Springer haben die Farbe getauscht. Welche Springer?
Henrik Juel: solution: Sa1 and Sa3
White pawns captured all missing black men, so last move was Sc2-a3+, preceded by b2xa1=S
. (2019-1-27)
more ...
comment

Genre: Retro
Reprints: 23 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-28 more...
38 - P0003083
Raymond Smullyan
30 The Chess Mysteries of the Arabian Knights 1981
P0003083
(12+14)
Eine Figur hat die falsche Farbe. Welche?
Henrik Juel: solution: Lf1
The pawns are true by stipulation (Figur means officer) and the kings are obviously true
[Lc1] was captured on c1, so Lh4 is true and checking Ke1
Hence Sf3 and Dd8,Th8,Sc7,Sf6 are true
Ta8 is true, because a wT could not have left row 1
Dc4 is true, because a black promotion would require four captures, but only wDS and one wT are available
So Lf1 is black, explainable by Black capturing [Lf1] and playing c5xTd4xTe3xSf2=L
. (2019-1-27)
comment

Genre: Retro
Reprints: 30 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
39 - P0003084
Raymond Smullyan
31 The Chess Mysteries of the Arabian Knights 1981
P0003084
(13+11)
Weiß ist am Zug, beide KK haben noch nicht gezogen. Zeige, daß der wLg7 bereits die 8. Reihe betreten hat!
Henrik Juel: .
White captured [Ta8,Lc8,Dd8] with an S in the NW corner, g2xTh3, and [Lf8] somewhere
So Pb3,c3 did not cross-capture, [Ta1] was captured in the SW corner, and Pf5 never captured
Sg8 entered via h6, and last move was f6-f5 (not Sc2-a1 or Sd3-c1), allowing these (forward) sequences:
L-g7 before f7-f6
White captured [Lf8] on f8 before Th8-f8 before Sh6-g8 before g7xDh6 before g2xTh3
So [Th8] went Th8-f8-f7-g7-h3, showing that Lg7 visited h8 or f8 to make way (and that last move was not f7-f5)
(The penultimate move was g2xTh3 or L-e2) (2019-1-29)
Henrik Juel: It may be clearer to reverse the two sequences and rewrite:
g7xDh6 before L-g7 (or L-h8) before f7-f6 before Tf8-f7 (2019-1-29)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 31 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
40 - P0003085
Raymond Smullyan
32 The Chess Mysteries of the Arabian Knights 1981
P0003085
(14+13)
Der wK und die wD haben noch nicht gezogen und sind noch nicht angegriffen worden. Was geschah mit dem sBg7?
Henrik Juel: Dd8 is [Pg7] promoted on g1
White captured L or S on b3 and some original black officer (not S) on c3, before [Ta1] could get out to help [Pg7] promote on g1
Promoting to LT does not work, so after d2xDc3 Black played gxT...xLg2-g1=D (with a screen on f1)
. (2019-1-29)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 32 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
41 - P0003086
Raymond Smullyan
33 The Chess Mysteries of the Arabian Knights 1981
P0003086
(14+14)
Der sK und die sD haben noch nicht gezogen, Weiß darf noch rochieren. Welches ist der schwarze Königsturm?
Henrik Juel: Ta2
The only feasible sequence is
a2xLb3 before Ta1-f6 before g7xTf6 before Th8-a2 before b2xLa3 before c7xLb6 before Ta8-h3
. (2019-1-29)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 33 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
42 - P0003087
Raymond Smullyan
34 The Chess Mysteries of the Arabian Knights 1981
P0003087
(14+13)
Beide Seiten dürfen noch rochieren, die wD ist nie angegriffen worden, die sD nur einmal. Welcher weiße Offizier hat einen illegalen Zug gemacht?
Henrik Juel: Silly problem
Retroanalysis requires legality throughout
Silly answer:
[Ta1] illegally reached e6 early, allowing d7xTe6 and then e.g. d2xDc3
. (2019-1-29)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 34 Die Schachgeheimnisse des Kalifen 1984
R11 Phénix 275-276, p. 10810, 07-08/2017
R11 Phénix 275-276, p. 10815, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-9 more...
43 - P0003088
Raymond Smullyan
35 The Chess Mysteries of the Arabian Knights 1981
P0003088
(13+16)
Ergänze den weißen Damenläufer, wenn möglich. Wenn nicht: wo wurde er geschlagen?
Henrik Juel: [Lc1] was captured on c1
The sequence must have been
d7xDc6 before Lc8-a2 before b2-b3
. (2019-1-29)
comment
Keywords: Where was piece x captured?
Genre: Retro
Reprints: 35 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
44 - P0003089
Raymond Smullyan
36 The Chess Mysteries of the Arabian Knights 1981
P0003089
(13+15)
Der weiße Damenläufer ist nicht auf seinem Ausgangsfeld geschlagen worden. Ergänze, wenn möglich, den weißen Damenläufer oder zeige, auf welchem Feld er geschlagen worden ist!
Henrik Juel: [Lc1] was captured on b2
[Lc8] could not get out before d7xDc6, so La2 must be promoted: a3xLb2-b1=L
. (2019-1-29)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 36 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
45 - P0003090
Raymond Smullyan
37 The Chess Mysteries of the Arabian Knights 1981
P0003090
(13+15)
Die wD wurde auf c6 geschlagen, Weiß darf noch rochieren. Ergänze einen weißen Läufer. Ergänze, wenn möglich, den schwarzen Königsläufer oder zeige, auf welchem Feld dieser geschlagen worden ist!
Henrik Juel: Add wLh8, [Lf8] was captured on h6
[Lc1] was captured on c1, so the added wL must be [Pg2] playing g5xLh6-h8=L
. (2019-1-29)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 37 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
46 - P0003091
Raymond Smullyan
38 The Chess Mysteries of the Arabian Knights 1981
P0003091
(12+14)
Weiß hat einen Springer vorgegeben, der wK hat noch nicht gezogen. Nur eine Figur ist auf ihrem Ausgangsfeld geschlagen worden, und dies war nicht die erste Figur, die geschlagen worden ist. Befindet sich der schwarze Damenläufer noch auf dem Brett?
Henrik Juel: Yes
The sequence must have been
c2-c3 before e7xDf6 before Sb3xLc1 before Ta1-c1 before Sa3-b1 before b2xLa3 before b7xTa6
Only then could [Lc8] get out (it was not captured at home, because [Lc1] was), but White cannot have captured it, so it is still on the board somewhere
. (2019-1-29)
comment
Keywords: Conditional problem, Odds game
Genre: Retro
Reprints: 38 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
47 - P0003244
M. Geofth
1022 L'Echiquier de Paris 1954
1. -2. Preis e.a.
P0003244
(5+10) cooked
h#4
b) sBb2 statt wBb2
a) 1. dxe3ep Kd4 2. Tc6 Kd5 3. Dg6 dxe3 4. Kf5 e4#
b) 1. Se3 Lxb2 2. Dg1 Lxd4 3. Dg4 Lxf6 4. Lg3 dxe3#
play all play one stop play next play all
Cook: NL
b) 1. Da2 Lxb2 2. De6 Lxd4 3. h3 Lxf2 4. Ke5 Lg3#
Yuri Bilokin: Correction: bpb2, +bnh5 2.1… b7/8/5p2/7n/3pPknp/3K1p2/1prP1b2/1qB5 (4+12)
1.dxe3 e.p. Kd4 2.Rc6 Kd5 3.Qg6 dxe3+ 4.Kf5 e4#
1.Se3 Bxb2 2.Qg1 Bxd4 3.Qg4 Bxf6 4.Bg3 dxe3# (2019-3-13)
comment
Keywords: En passant as key, Check Protection
Genre: h#, Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2017-7-11 more...
48 - P0005374
Stefan Höning
6638 feenschach 111 01-09/1994
P0005374
(2+1)
Ergänze wK, wD, wT, wL, wS, wB; sK, 2sTT, sL zu einem weißen L.C.!
+wKd3,wDd7,wTe4,wLc2,wSc5,wBd2,sKa4,sTd1d8,sLb1
play all play one stop play next play all
FM: "Bemerkenswerte Idee, dieser Semi-Legal Cluster."
3/III
Henrik Juel: The stipulated position is not an ordinary Legal cluster (LC), but an easier variant called a White LC, defined as a legal position that becomes illegal if you remove any one white man (so removing a black man is irrelevant)
The solution position is legal, as last move could be Sb3-c5++
Removing Lc2, Pd2, Dd7, or Te4 puts both kings in check, removing Pb4 or Pb5 gives an illegal triple check, and removing Sc5 gives impossible check from wLc2 (and removing Kd3 obviously gives an illegal position) (2019-2-18)
Henrik Juel: Alfred has waved his magic wand again, so you don't need a board, just click on the little right-arrow, then move the cursor up, and, presto, the diagram shows the solution
I agree with solver FM that this is a clever way to avoid a condition (like Checkless Chess), but the idea hasn't caught on; at least this is the only White LC in the PDB (2019-2-19)
Olaf Jenkner: Good idea: Alfred used a zero-position and the solution as part a) (2019-2-19)
A.Buchanan: Sorry been very busy. One feature still missing from the animation is the ability to return to the zero position. Compare Julia's Fairies animation, where there are *** at the top which you can click on. (2019-2-20)
comment
Keywords: Legal cluster (w)
Genre: Retro
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-2-18 more...
49 - P0005567
Raymond Smullyan
39 The Chess Mysteries of the Arabian Knights 1981
P0005567
(16+13)
Weiß und Schwarz dürfen noch rochieren. Welcher der 3 wSS muß vom Brett entfernt werden, damit die Stellung legal wird?
-wSg1
play all play one stop play next play all
Henrik Juel: .
The sequence must have been
b2xLc3 before c7xDb6 before g2xDh3 before g1=L
and f2-f3 before Lg1-g7
A wS could not reach g1 after Lg1 had left, so Sg1 must be removed
. (2019-1-29)
comment
Keywords: Conditional problem, Non-standard material, Illegal position, Remove pieces
Genre: Retro
Reprints: 39 Die Schachgeheimnisse des Kalifen 1984
R12 Phénix 275-276, p. 10810, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
50 - P0005568
Raymond Smullyan
40 The Chess Mysteries of the Arabian Knights 1981
P0005568
(14+15)
Keiner der KK hat gezogen.
Wo wurde der weiße Königsturm geschlagen?
Henrik Juel: On b6
The sequence must have been
b7xSc6 before g2xTh3 or g3xTh4 before [Th1] could get out
So it was captured on b6
. (2019-1-29)
comment

Genre: Retro
Reprints: 40 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
51 - P0005569
Raymond Smullyan
41a The Chess Mysteries of the Arabian Knights 1981
P0005569
(14+14)
Die KK und die DD haben weder gezogen noch sind sie angegriffen worden. Welcher Offizier muß vom Brett entfernt werden, damit die Stellung legal ist?
Henrik Juel: Lf1
No S was captured by a pawn
The pawn captures were f2xLe3, b7xTc6, g2xTf3, in this order, so Lf1 must be removed
. (2019-1-29)
comment
Keywords: Conditional problem, Remove pieces
Genre: Retro
Reprints: 41a Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
52 - P0005570
Raymond Smullyan
41b The Chess Mysteries of the Arabian Knights 1981
P0005570
(14+14)
Kein König hat je gezogen und keine Dame ist jemals angegriffen worden. Welche Figur muß vom Brett entfernt werden, damit die Stellung legal wird?
Henrik Juel: .
Seems to be unsolvable, as no white man could be captured on c6 to release [Ta8,Lc8]
. (2019-1-29)
Mario Richter: Wrong stipulation. The correct one is:
""This time, neither king has moved, and neither queen has been under attack. Where is the genie [the piece to be removed to make the position legal] now?" (2019-1-30)
A.Buchanan: I suppose sometime we should put English & French translations of these wretchedly long Smullyanesque stipulations. It's the kind of thing that novice visitors might come for. (2019-1-30)
Henrik Juel: With Mario's condition modification:
Remove Lc8, so that Dd8 could step aside to c8, allowing b7xSc6 (2019-1-30)
comment
Keywords: Conditional problem, Remove pieces
Genre: Retro
Reprints: 41b Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
53 - P0005571
Raymond Smullyan
42 The Chess Mysteries of the Arabian Knights 1981
P0005571
(15+13)
Welcher der beiden LLh2 und h4 muß entfernt werden, damit Weiß zwingend in 2 Zügen gewinnen kann?
Henrik Juel: Lh4
Suppose that Black may castle
Then [Ta8] was captured in its corner, leaving a light-squared L and a h-pawn as missing men for White and for Black
d2xc3 and e7xf6 were captures on dark squares, so both missing pawns must have promoted
White could not capture h6xg7 on a dark square, so first Black captured h3xLg2 allowing White to play h2-h7xLg8 later
But then we cannot explain Lh2
So remove Lh4 and play 1.Da6 thr. 2.Dc8#; Black cannot defend, because he may not castle
(The position without Lh4 is clearly legal, because Black need not promote)
. (2019-1-29)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 42 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
54 - P0005572
Raymond Smullyan
43 The Chess Mysteries of the Arabian Knights 1981
P0005572
(13+14)
Die KK und DD haben noch nicht gezogen. Welcher der 4 SS ist in Wirklichkeit ein Läufer?
Henrik Juel: Sc6
White captured 3 times, but only 2 black men are missing, so Sc6 or Sf6 must be a wL
Only wLc6 works, as g7xLh6 is needed (2019-1-30)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 43 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
55 - P0005573
Raymond Smullyan
44 The Chess Mysteries of the Arabian Knights 1981
P0005573
(14+15)
Es sind keine weißen UWF auf dem Brett. Der wB b3 kam von b2. Welcher der sSS ist eine UWF?
Henrik Juel: Sh8
[Pa2] promoted on b8, so Sa8 is original
Later [Pd7] promoted on b1, so Sa1 is original (2019-1-30)
comment
Keywords: Conditional problem, Non-standard material
Genre: Retro
Reprints: 44 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
56 - P0005574
Raymond Smullyan
44b The Chess Mysteries of the Arabian Knights 1981
P0005574
(14+15)
Es sind keine weißen UWF auf dem Brett. Der wK hat noch nicht gezogen. Welcher der sSS ist eine UWF?
Henrik Juel: Sa8
[Pe2] promoted on d8 after capturing [Lf8], so Sh8 is original
Later [Pd7] promoted on b1, f1, or d1 after capturing [Lc1], so Sa1 is original (2019-1-30)
comment
Keywords: Promotion, Conditional problem, Non-standard material
Genre: Retro
Reprints: 44b Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
57 - P0005575
Raymond Smullyan
45 The Chess Mysteries of the Arabian Knights 1981
P0005575
(11+13)
Kein wSS hat über die 6. Reihe hinaus gezogen. Der sK und die sD haben weder gezogen noch sind sie angegriffen worden. Der schwarze Königsspringer hat erst einmal gezogen. Ist die wD eine Originaldame?
Henrik Juel: No
After d7xTc6, [Pa2] could play a4xLb5-b6xSa7-a8=D, but the promoted D could not go to d6 to be captured, because it is impossible to screen on d7 (2019-1-30)
comment
Keywords: Conditional problem, Promotion
Genre: Retro
Reprints: 45 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
58 - P0005576
Raymond Smullyan
46 The Chess Mysteries of the Arabian Knights 1981
P0005576
(13+13)
Der erste schwarze Zug war Bd7-d5. Der sK und die sD haben noch nicht gezogen. Weiß kann noch rochieren. das Feld d7 war nur einmal besetzt.
Welches ist die weiße Originaldame?
Henrik Juel: Seems unsolvable
The only possible sequence is
d7-d5 before e7-e6 before d2xLe3 before a7xLb6 before g2xTh3 before h7xTLg6 before Th8-a7 before b7xLTa6 before c6xTb7-b8=D
With a screen on d7 both wDD can go via c6, so we cannot say which is which
. (2019-1-30)
Mario Richter: Original stipulation:
(1) Black's first move was the pawn from d7 to d5.
(2) The Black royalty has not yet moved, and White can castle.
(3) The square d7 has been occupied only once. (2019-1-30)
Henrik Juel: .
With Mario's additional condition, please change the last sentences in my above comment to:
The promoted D cannot leave the NW corner, so Dg8 is original
. (2019-1-30)
comment
Keywords: Promotion, Conditional problem, Non-standard material
Genre: Retro
Reprints: 46 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
59 - P0005577
Raymond Smullyan
47 The Chess Mysteries of the Arabian Knights 1981
P0005577
(13+12)
Die ersten beiden Einzelzüge waren 1. d2-d4 d7-d5. Der sK und die sD haben noch nicht gezogen; Weiß darf noch rochieren. Die Felder d7 und e2 sind nie wieder besetzt und auch nicht überquert worden.
Welches ist die weiße Originaldame?
Henrik Juel: Db8
The only possible capture sequence after 1.d4 d5 is
a7xLb6 before g2xTh3
Then [Dd1] goes to b8, and [Lf1,Th1] are captured on a6,g6
Now [Lc8] can get out via b7 and with [Lf8,Th8] enable e2xf3xgxh6 and promotion on h8
Db8 cannot leave the NW corner, so she is original
. (2019-1-30)
comment
Keywords: Conditional problem, Castling, Promotion, Non-standard material
Genre: Retro
Reprints: 47 Die Schachgeheimnisse des Kalifen 1984
R12 Phénix 275-276, p. 10810, 07-08/2017
R12 Phénix 275-276, p. 10816, 07-08/2017
Input: Gerd Wilts, 1995-6-3
Last update: Alfred Pfeiffer, 2019-1-30 more...
60 - P0005578
Raymond Smullyan
48 The Chess Mysteries of the Arabian Knights 1981
P0005578
(13+13)
Die beiden KK und die sD haben noch nicht gezogen. Die wD wurde von einem Turm geschlagen. Von welchem?
Henrik Juel: [Th8]
The only possible capture sequence was
g2xLf3 before b7xLc6 before b2xTc3
So [Ta8] was captured before wD (2019-1-30)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 48 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
61 - P0005579
Raymond Smullyan
49 The Chess Mysteries of the Arabian Knights 1981
P0005579
(14+13)
Die beiden KK haben noch nicht gezogen. Welcher wT ist eine UWF?
Henrik Juel: Th1
d7xLe6 permits T-d7, and e7xLd6 frees [Lf8], needed for [Pe2] to promote (on h8)
b2-b3 (before e7xLd6) prevents the promoted T from reaching a1, so Ta1,d7 are original (2019-1-30)
comment
Keywords: Conditional problem, Promotion, Non-standard material
Genre: Retro
Reprints: 49 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
62 - P0005580
Raymond Smullyan
50 The Chess Mysteries of the Arabian Knights 1981
P0005580
(14+15)
Der sK hat noch nicht gezogen; der wK nur einmal. Zwei Türme haben nie gezogen; welche?
Henrik Juel: Ta8 and Th1
Black played gxLf-f3xLe2-e1=T (DL would check immediately, S on f3)
The promoted T could exit only via a1, after axTb, so Ta1 has moved to make way (and Th8 is promoted)
. (2019-1-30)
comment
Keywords: Conditional problem
Genre: Retro
Reprints: 50 Die Schachgeheimnisse des Kalifen 1984
Input: Gerd Wilts, 1995-6-3
Last update: A.Buchanan, 2018-3-7 more...
63 - P0006465
Frank Müller
3892 Problemkiste (102), p. 166, 12/1995
P0006465
(1+0)
Platzwechselcirce
a) Ergänze sK und 3sBB zu einem IC!
b) Ergänze sK, 2sBB und wB zu einem IC!
a) sKa8 sBa7b7b8
b) sKa8 sBa6b7 wBa7
play all play one stop play next play all
Erich Bartel: Lösung:
a) sKa8, sBa7b7b8, b)sKa8,sBa6b7,wBa7.--
Konvention bei solchen Retros mit Bedingung, die nicht zu
üblichen PAS zurückzuführen sind, ist: Als legal gilt eine
Stellung, die in eine retrograde Ruhestellung rückführbar
ist (Hans Gruber) (2007-2-11)
Henrik Juel: The solution to part b) should probably have a black pawn on a6 like Erich says, not on a7 (2019-2-14)
Mario Richter: I don't know much about Platzwechselcirce, so can please somebody explain why in b) position without black pawn b7 is legal? (2019-2-15)
Henrik Juel: PWC is very iffy in retroproblems, as you cannot increase the number of men by uncaptures; hence we need the strange construct Ruhestellung
Earlier we had sKa7 and a checking wPb6, then KxPb6[+Pa7] explains the pawn inversion on the a-line (2019-2-15)
Henrik Juel: or, if you want to avoid an illegal selfcheck
Ka7xPb7[+Pa7] ... (2019-2-15)
comment
Keywords: Illegal cluster, only Kings, Interchange Circe
Genre: Retro, Fairies
Input: Gerd Wilts, 1996-6-16
Last update: Alfred Pfeiffer, 2019-2-15 more...
64 - P0006522
Nikita M. Plaksin
Alexandr I. Zolotarev

R220v The Problemist 03/1994
2182 Phénix 36 12/1995
L. Ceriani zum Gedächtnis
P0006522
(11+14)
Löse die Stellung auf!
R: 1. ... Lh5xTg4 2. Te4-g4 Tg4-g3 3. Te6-e4 c3xDd2 4. Td6-e6 c4-c3 5. Td8-d6 c5-c4 6. d7-d8=T c6-c5 7. d6-d7 d5-d4 8. e5xLd6 Lc5-d6 9. Da5-d2 Le3-c5 10. Da8-a5 Lh6-e3 11. a7-a8=D Lf8-h6 12. a6-a7 a7xDb6 13. Db1-b6 Lg7-f8 14. Dc1-b1 Lf8-g7 15. Dg5-c1 Lh6-f8 16. Dg8-g5 Lg5-h6 17. g7-g8=D Lh6-g5 18. g6-g7 Lf8-h6 19. b6-b7 b7xDc6 20. Dc3-c6 Lg7-f8 21. Dd2-c3 Lf8-g7 22. Dh6-d2 Lg7-f8 23. Dh8-h6 Lh6-g7 24. Dg8-h8 Lf8-h6 25. d2-d3 Sd3-e1 26. g5-g6 Sb4-d3 27. g7-g8=D Sc6-b4 28. g6-g7 g7xSf6
play all play one stop play next play all
Korrektur zu P1012537
Henrik Juel: -1... Lh5xTg4 -2.Te4 Tg4 -3.Te5 c3xDd2 -4.Td5 c4 -5.Td8 c5 -6.T=d7 c6 -7.d6 d5 -8.e5xLd6, unpromote Dd2 on a8, retract a7xDb6, unpromote Db6 on g8, retract b6-b7, b7xDc6, wDc6 to g8, bL to f8, d2-d3 etc. Uncaptured DDDT unpromote. (2003-12-15)
AV: "Jumeau" du P0002344 : la pièce capturée en g4 n'est plus une D mais une T, car le PNe7 au lieu de e5 interdit le trajet Dd8-e7-f8-g7-g4 mais autorise le trajet Td8-d6(d5)-e6(e5)-e4-g4. Les Noirs ont un tempo de moins, mais du fait de l'interversion CNe1/FBg1 (au lieu de FBe1/CNg1), on peut reprendre d2-d3 et donner un tempo au Ce1 (quand les pions blancs g5 et g7 immobilisent le Fh6). (2005-6-5)
Rosalie Fay: Nikolai Beluhov, The Ceriani Quartex (March 2010), N15, cites this problem as "N. Plaksin & A. Zolotarev. The Problemist, 1994". (2019-6-30)
more ...
comment
Keywords: Ceriani-Frolkin Theme (DDDT)
Genre: Retro
Input: Gerd Wilts, 1996-6-16
Last update: Mario Richter, 2019-7-1 more...
65 - P0006623
Thierry Le Gleuher
1853v Phénix 50 03/1997
3. ehrende Erwähnung
P0006623
(16+16)
BP in 40,5
1. a4 h5 2. Ta3 Th6 3. Tc3 Tb6 4. Tc4 Tb3 5. Sc3 Ta3 6. b3 Ta1 7. La3 d5 8. Db1 Lf5 9. Kd1 Lh7 10. Kc1 g6 11. Kb2 Lh6 12. Da2 Tc1 13. Sb1 Le3 14. Kc3 Lb6 15. Kd3 c5 16. Ke3 Sc6 17. Kf4 Dc7+ 18. Kg5 0-0-0 19. h4 Td6 20. Th3 Tf6 21. Te3 Tf3 22. Te6 Sf6 23. Kh6 Th3 24. Kg7 Th1 25. Kf8 Dh2 26. g3 Se5 27. Tc6+ Kd7 28. Tc8 Ke6 29. Lg2 Kf5 30. Le4+ Kg4 31. Sf3 Kh3 32. Lf5+ Kg2 33. Tg4 Lg8 34. Sd4 Sh7+ 35. Ke8 Sf3 36. Kd7 Kf1 37. Te8 Ke1 38. Kc8 Kd1 39. Kb8 Te1 40. Lc8 Sg1 41. f3
play all play one stop play next play all
Yoav Ben-Zvi: The cook found in P0002554 re-opens the question of the current length record for unique capture-free SPG. A search in PDB finds this problem, assuming it is sound, to be the record holder, until Unto Heinonen publishes a correction (expected very soon). Prior to publication of this problem the record was 38.5, in Michel Caillaud's P0002187. (2019-7-10)
more ...
comment
Keywords: Unique Proof Game, Capture-free
Genre: Retro
Reprints: H34 FIDE Album 1995-1997 2004
Input: Gerd Wilts, 1996-7-7
Last update: Alfred Pfeiffer, 2014-7-4 more...
66 - P0006650
Thomas R. Dawson
440v The Chess Amateur 01/1924
N. Hoeg gewidmet
P0006650
(11+12)
#1 vor 2
VRZ, Typ Hoeg
R: 1. a2xTb3 ... 2. f6xSe7,f6xLe7, dann 1. Lg7#
R: 1. a2xLb3 ... 2. f5xTe6,f5xSe6, dann 1. Sf7#
R: 1. a2xSb3 ... 2. Kf8-e8,Kf8xLe8, dann 1. Lg7#
play all play one stop play next play all
Henrik Juel: .
Black pawns captured all five missing white men
Black is missing TLLS, three of which were captured by white pawns (axb, fxe, h5xg6) and the remaining one by a white officer
The potential mates are 1.Lg7 (requiring that g7 is covered) and 1.Sf7 (requiring that g6 is covered)
If White immediately moves back so as to cover g7 or g6, Black can defend by supplementing wisely:
-1.f6?:Te7!, -1.f5?:Le6!, -1.Kf8?:Se8!
So White starts by moving Pb3 back to a2, forcing Black to commit himself by supplementing T, L, or S, the absence of which is then exploited by White
There is also another try, -1.a3?:Lb4! -2.f5:Le6!, where Black is successful, because he can afford to 'lose' his dark-squared bishop
In the third variation above, 2.Kf8-e8 is slightly misleading, as it could also be 2.Kf8xLe8; but this is no dual: White does not retract in the usual sense, he just moves his king back to f8 and lets Black complete the retraction by choosing what (if anything) to supplement on e8; Black would like to supplement D, T, or S (to prevent 1.Lg7#), but all three possibilities are illegal (D and S are not missing, and Txe8+ would imply too many black captures)
In Caissa's Wild Roses the author wrote:
... my best example of variations in addition, one of the loveliest features of this Fairy type.
. (2019-2-4)
more ...
comment
Keywords: Defensive Retractor, Type Høeg
Genre: Retro
Reprints: (7) On Retraction Chess Problems 1927
106 Caissa's Wild Roses 1935
Input: Gerd Wilts, 1996-7-16
Last update: Alfred Pfeiffer, 2019-2-5 more...
67 - P0006651
Thomas R. Dawson
1438 Eskilstuna-Kuriren 09/02/1924
P0006651
(10+12)
#1 vor 2
VRZ, Typ Hoeg
R: 1. f2-f3 b7-b6 2. Le4-g2, dann 1. c3#
R: 1. f2-f3 e7-e6 2. Sf1-e3, dann 1. Sfd2#
R: 1. f2-f3 h6-h5,h7-h5 2. Sd5-e3, dann 1. Sc3#
R: 1. f2-f3 Sh7xDf8 2. Db4-f8, dann 1. Scd2#
play all play one stop play next play all
Henrik Juel: The last variation is better written as -1... Sh7xDf8 (or just -1... Sh7:D) etc. (2004-3-18)
Henrik Juel: In the first three variations Black loses the right to add a light-squared bishop, a dark-squared bishop, and a rook, respectively
In the last variation Black permits White to add a queen (2019-2-4)
comment
Keywords: Grimshaw, Defensive Retractor, Type Høeg
Genre: Retro
Reprints: (10) On Retraction Chess Problems 1927
107 Caissa's Wild Roses 1935
Input: Gerd Wilts, 1996-7-16
Last update: Alfred Pfeiffer, 2019-2-5 more...
68 - P0006652
Thomas R. Dawson
1437 Eskilstuna-Kuriren 09/02/1924
P0006652
(7+13)
#1 vor 3
VRZ, Typ Hoeg
R: 1. Ke4-e3 Sf7-g5 2. Ke5-e4 Sd6-f7 3. Lf7-h5, dann 1. g5#
R: 1. Ke4-e3 Se6-g5 2. Kf4-e4 Sc7-e6 3. Lf7-h5, dann 1. g5#
R: 1. Ke4-e3 Sf3-g5 2. Kd4-e4 Sd2-f3 3. Lf7-h5, dann 1. g5#
play all play one stop play next play all
Henrik Juel: All captures were pawn captures, so whenever an officer is moved back, the opponent may not add anything (2019-2-4)
comment
Keywords: Defensive Retractor, Type Høeg
Genre: Retro
Reprints: (9) On Retraction Chess Problems 1927
108 Caissa's Wild Roses 1935
Input: Gerd Wilts, 1996-7-16
Last update: Alfred Pfeiffer, 2019-2-5 more...
69 - P0006667
Charles Mason Fox
(33) On Retraction Chess Problems 1927
1. Preis
Hoeg-Rückzüger
P0006667
(11+8)
#1 vor 3
VRZ, Typ Hoeg
R: 1. g3xLh4 ... 2. Kh5-h6 f7xTg6 3. Sf6-g8, dann 1. Tg8#
play all play one stop play next play all
Henrik Juel: .
[Pd7,f7,g7] captured all five missing white men (dxexfxg, fxg, gxh), so [Pa7,b7,c7] never captured and did not promote, but were captured on their files
If White immediately moves his king back to h5, a foolish Black might add Lh6 permitting White to mate, but a smart Black adds nothing
In Høeg's notation with additions in brackets (0 meaning no addition):
1.Kh5-h6?[L?] f7-g6+[T!] 2.Sf6-g8 rm
(1... g7-g6 is illegal)
(Høeg usually did not write the mating move (Tg8 or Txg8); instead he wrote rm (for retromate) meaning that now White could win by mating); (and his stipulation was Retromate in 3 moves)
But 1.Kh5-h6?[0!] g7-g6+! and no mate in sight
So a Vorplan is needed
1.g3-h4[L] (this addition is forced)
and now Black cannot prevent the threat
2.Kh5-h6[0] (Black may not add anything) forcing 2... f7-g6+[T] 3.Sf6-g8 rm
(A black defense like 1... Sa6-b8 does not prevent the threat, but it does permit short mate by 2.Sf6-g8[DTL] rm (Dxg8))
I prefer abbreviated notation with a colon separating the decisions of the two camps and negative move numbers for retractions, e.g.
-1.Kh5?:0! g7!
-1.g3:L thr. -2.Kh5:0 f7:T -3.Sf6, 1.Tg8#
or slightly less abbreviated, but clearer
-1.g3:Lh4 thr. -2.Kh5:0 f7:Tg6 -3.Sf6, 1.Tg8#
. (2019-2-5)
A.Buchanan: Thanks for the lucid explanation, Henrik :) (2019-2-5)
Henrik Juel: You are most welcome, Andrew
A tiny inaccuracy above:
Black CAN prevent the threat, if he falls completely apart and voluntarily moves back the way White wants
-1.g3:Lh4 f7?:Tg6 -2.Sf6, 1.Tg8#
(-2.Kh5?:Dh6! Df8 -3.Sf6, 1.Tg8?? Dxg8 (or -2... Dg7)) (2019-2-6)
more ...
comment
Keywords: Defensive Retractor, Type Høeg
Genre: Retro
Reprints: 192 C. M. Fox, His Problems 1936
Input: Gerd Wilts, 1996-7-17
Last update: A.Buchanan, 2019-2-5 more...
70 - P0006671
Charles Mason Fox
(43) On Retraction Chess Problems 1927
P0006671
(14+9) cooked
#1 vor 4
VRZ, Typ Hoeg
R: 1. f7-f8=L Sf8xLh7 2. Lg8-h7 Sd7xLf8 3. g4-g5 Sb8-d7 4. d6xBc7, dann 1. Sxc7#
R: 1. f7-f8=L Sf8xLh7 2. Lg8-h7 Sh7xLf8 3. b5-b6 Dd4-e4,Ld6-e5 4. De4-f5,Dd5-f5, dann 1. cxb7#
R: 1. f7-f8=L Sf8xLh7 2. Lg8xSh7 Sd7xLf8 3. Kc3-b3 Ld6-e5+ 4. Dd5-f5, dann 1. cxb7#
R: 1. f7-f8=L Dd4-e4,Ld6-e5 2. De4-f5,Dd5-f5, dann 1. cxb7#
play all play one stop play next play all
Cook: NL
R: 1. Kc4xSb3 Sd4-b3+ 2. Kb3xTc4,Kb3xSc4 Sc2xTd4+,S~xTd4+ 3. g4-g5, dann 1. Td8#
R: 1. Kc4-b3 Ld4-e5,De3-e4 2. Dd5-f5,De4-f5, dann 1. cxb7# (V. Røpke)
Henrik Juel: Diagram error: Qf5 should be white. -1.B=f7 Sf8:B -2.Bg8 Sd7:B -3.g4 Sb8 -4.d6:P, 1.Sxc7#; -2... Sh7:B -3.b5 Qd4/Bd6 -4.Qe4/Qd5, 1.cxb7#; -2.Bg8:S Sd7:B -3.Kc3 Bd6 -4.Qd5, 1.cxb7#; -1... Qd4/Bd6 -2.Qe4/Qd5, 1.cxb7#. (2003-11-11)
Henrik Juel: .
Cooked by V. Røpke (by letting wK walk into check)
-1.Kc4:Sb3 Sd4-b3+ -2.Kb3:TSc4 S~:Td4+ and e.g. -3.g4, 1.Td8#
(even if Black adds a fourth knight on c4, it is legal for White to add a third rook on d4)
If Black does not add Sb3, the mate is even faster:
-1.Kc4 Ld4/D~ -2.Dd5/De4, 1.cxb7#
(White chooses not to add anything on e5/e4; Black cannot prevent the mate by addition on f5)
. (2019-2-5)
comment
Keywords: Defensive Retractor, Type Høeg
Genre: Retro
Reprints: 197 C. M. Fox, His Problems 1936
Input: Gerd Wilts, 1996-7-17
Last update: Alfred Pfeiffer, 2019-2-6 more...
71 - P0006756
Gideon Husserl
526 feenschach 8 03/1972
P0006756
(2+2)
Ergänze einen schwarzen Bauern, dann
a) =1
b) s#1
c) s=1
d) #1 durch Schwarz
a) (+sBh4) 1. Df3=
b) (+sBh2) 1. Dc4 g2#
c) (+sBg4) 1. Dh2+ gxh2=
d) (+sBf2) 1. ... g2#
play all play one stop play next play all
Henrik Juel: Nice Wenigsteiner
The a addition also permits #1: 1.De6# (2019-6-5)
more ...
comment
Keywords: Add pieces
Genre: Retro
Input: Gerd Wilts, 1996-7-28
Last update: Alfred Pfeiffer, 2019-6-5 more...
72 - P0006887
Thomas Brand
K500 Problemkiste 106 08/1996
P0006887
(1+1)
Ergänze wB und sT zu einem IC!
Circe
+wBe2, sTe1
play all play one stop play next play all
Henrik Juel: Here the content is why the five tries do not work:
Pa2,Ta2, Pc2,Tc1, similar on d-file, f-file, g-file
These positions are all legal (2019-2-14)
comment
Keywords: Circe, Illegal cluster, only Kings
Genre: Retro, Fairies
Input: Gerd Wilts, 1996-8-7
Last update: A.Buchanan, 2017-4-6 more...
73 - P0008817
Niels Høeg
T11 Tidskrift för Schack 07/1924
P0008817
(11+2)
Schwarz konnte vor 2 Zügen mattsetzen
VRZ, Typ Hoeg
R: 1. Lb2xTa1 Ta2-a1 2. La1-b2 Tb2xSa2, dann 1. ... Txc2#
R: 1. Lb2xTa1 Ta2-a1 2. La1xSb2 Sa4-b2,Sc4-b2, dann 1. ... Txc2#
play all play one stop play next play all
In a retromate problem white achieves, against all black defences, a position where white can mate. In a selfretromate problem white achieves, against all black defences, a position where black can mate. Since white starts in both forms, a selfretromate lasts .5 retractions longer than the corresponding retromate).

Most retractions and supplements are forced. It is illegal for black to supplement a queen on a1. The black rook entered the cage via d1, and the kings entered via a3 and b2.
Henrik Juel: Retromate and Selfretromate are the stipulation names used by Høeg (in danish Retromat and Selvretromat)
In the PDB 'Retromate in n moves' is written as '#1 vor n'
'Selfretromate in n moves' is written as 'Schwarz konnte vor n Zügen mattsetzen'
(Note that 's#1 vor n' is very different from 'Selfretromate in n moves') (2019-2-6)
comment
Keywords: Defensive Retractor, Type Høeg
Genre: Retro
Reprints: (19) On Retraction Chess Problems 1927
Hoegs Skakproblemer 1982
Input: Gerd Wilts, 1997-6-26
Last update: Alfred Pfeiffer, 2019-2-7 more...
74 - P0500869
Wolfgang Dittmann
2141 Die Schwalbe 45 06/1977
P0500869
(0+6)
Ergänze wK, 2 sTT, sL, sB zu einem IC!
(+wKe3,sTd6f6,sLg1,sBe5)
R: 1. f2-f1=S++? kein letzter wZug!
-Bc4 oder -Bg4:
legal R: 1. Kd3xBe3 d4xe3ep++
oder R: 1. Kf3xBe3 f4xe3ep++
play all play one stop play next play all
more ...
comment
Keywords: En passant in the retro play, Illegal cluster, Promotion
Genre: Retro
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2019-2-18 more...
75 - P0500963
Michael McDowell
1122v The Problemist 09/1986
3. Preis
P0500963
(2+12) cooked
h#7
1. Se7 Lb2 2. Tf5 La3 3. Tc5 Lb4 4. d5 La5+ 5. Kd6 Lb6 6. Te3 La7 7. Te6 Lb8#
play all play one stop play next play all
Cook: NL 1. Td3 Le5 2. Se3 Lxf4 3. c5 Lxg3 4. Kc6 Lh4 5. Kd5 Kf2 6. Kd4 Kf3 7. d5 Lf6#
uvm
Läuferleiter
Michael McDowell: The correction of this was published in The Problemist 11/1996
8/2k1p3/2pp4/8/2p2pb1/2r4p/6rp/B4s1K h#7 (2004-7-28)
Olaf Jenkner: Korrektur siehe P1360471 (2019-2-2)
comment
Keywords: Superseded by (P1360471), Minimal, Staircase (L)
Genre: h#
Reprints: E220 FIDE Album 1986-1988 1995
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2019-2-3 more...
76 - P0500982
Conrad Bayer
424 Leipziger Illustrirte Zeitung 16/08/1851
P0500982
(8+10) C+
#9
1. Tb7 Dxb7 2. Lxg6+ Kxg6 3. Dg8+ Kxf5! 4. Dg4+ Ke5 5. Dh5+ Tf5 6. f4+ Lxf4 7. Dxe2+ Lxe2 8. Te4+ dxe4 9. d4#
play all play one stop play next play all
Gemäß Büsing in Die Schwalbe 12/2003 ist die häufig zitierte Quellenangabe Era-Turnier 1856 1. Sendungspreis falsch.
Das unsterbliche Schachproblem - häufig zitiert

auch die AZW schreibt "Era 1856"

DZ im Ostland: "Seltsamerweise ist die Aufgabe weder im Handbuch der Schachaufgaben M. Lange 1862 noch bei J. Dufresne 1864 genannt worden."

In 'Austrums' ist das Problem in eine kleine Schachhumoreske von H.Adolphi eingebettet.

Die 'Encyclopedia' schreibt zwar auch "1.pr The Era Tourney 1856" hat aber auch noch den folgenden Hinweis: "According to Friedrich Amelung the problem was first published in 'Leipziger Illustrierte Zeitung' in 1855 without author's name. (Chicco & Porreca)"
Henrik Juel: Popeye 4.61 with opt dro 1 found no flaws (2016-7-21)
Sally: °
Weiß opfert sechs Steine von sieben und setzt mit dem letzten
verbliebenden Bäuerchen auf d4 Matt. Das Schlußmodel dieses
Opferminimals ist gewiß imposant, aber dieses ganz in der Vergangenheit stehende Problem verdient gewiß nicht den Titel
"Das unsterbliche Problem"! den seine Zeit ihm gegeben hat. (2019-1-24)
more ...
comment
Keywords: Opferminimal
Genre: n#
Computer test: Gustav 4.0f, Brute Force
Reprints: I Austrums 01/01/1899
Arbeiter-Zeitung (Wien) 01/02/1932
56 Deutsche Zeitung im Ostland 30/11/1942
14 Snamenitye komposizii [Grin] 1973
Die Schwalbe , p. 299, 12/2003
1027 Minimalkunst im Schach 2006
793 Encyclopedia of Chess Problems 2012
VI) Tehtäväniekka 03/2012
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2019-1-24 more...
77 - P0501005
Albert Heinrich Kniest
Erich Bartel

182 Frankfurter Notizen 1965
Theo Steudel zum Geburtstag gewidmet.
P0501005
(1+5) C+
ser-=11
Frankfurter Schach
1. Kd7 2. Kxc7=B 3. c8=S 4. Sxa7=B 5. a8=T 6. Th8 7. Txh7=B 8. h8=L 9. Lxg7=B 10. g8=D 11. Dg3=
play all play one stop play next play all
t/2KK4BB
more ...
comment
Keywords: Allumwandlung, Frankfurt Chess, Series mover, Kindergarten Problem, Rex solus (w), Ideal mate, Alleinunterhalter, Durbar Theme, konsekutive Umwandlungen 4
Genre: Fairies
Computer test: WinChloe
Reprints: 10 Gemeinsames 02/1966
111 1.Wolfschach-Club 1962 (Notizbuch) 1967
115 Der Schnatterer 01/04/1974
Serienzugrekorde 1978
Serienzugrekorde 1979
61) 206mal Allumwandlung 1991
Die Schwalbe 05/1991
5 Problemkiste 05/1991
964 Minimalkunst im Schach 2006
R13 Problemkiste (181) 02-03/2009
(216) feenschach 210, p. 305, 11-12/2015
Input: Gerd Wilts, 1996-6-6
Last update: Alfred Pfeiffer, 2019-8-14 more...
78 - P0501293
Antonis Tataris
3003 Sinfonie Scacchistiche 04-06/1979
P0501293
(3+4) cooked
h#3
1. Lc1 Tb7+ 2. Kh6 Lb1 3. Lg5 Th7#
play all play one stop play next play all
Cook: NL
1. Kf6 Kg2 2. Ke5 Te1+ 3. Kf4 Te4#

Duplicate Diagram: P0510116

Vorgänger:
E. Reichel, 1975
P0510116
Yuri Bilokin: Correction: wKh1-d1 8/6kB/8/6b1/8/8/p7/rR1K4 (3+4) (2019-3-30)
comment
Keywords: Interchange (TL (72)), Check Protection
Genre: h#
Input: hpr, 1996-6-14
Last update: Alfred Pfeiffer, 2019-4-2 more...
79 - P0501522
Kjell Widlert
feenschach 7, p. 193, 01/1972
4. Preis
25. Thematurnier
P0501522
(4+14) cooked
h#4
1. La2+ Lf1 2. Lgb1 Lxg2 3. Lf7+ Lxa8 4. Lfg6 Lf3#
play all play one stop play next play all
Cook: NL
1. Ld4 gxf4 2. La7 Lb7 3. Lf2+ Lxa8 4. Lxh4 Lf3#
Yuri Bilokin: Correction: +bpb6 rn4q1/8/Bp3pbp/4b2k/5p1P/2p3P1/6p1/Kb4rn (4+15) (2019-3-13)
comment
Keywords: Interchange (ll (50)), Check Protection, Non-standard material
Genre: h#
Input: hpr, 1996-7-1
Last update: Alfred Pfeiffer, 2019-3-14 more...
80 - P0501896
Jan A. Rusek
1614 Gazeta Czestochowska 18/12/1973
P0501896
(4+3) cooked
h#3
1. Kd4 Sc7 2. Td5 Ta6 3. Kc5 Se6#
play all play one stop play next play all
Cook: NL
1. Tc1 Kb2 2. Tc5 Sb4+ 3. Kc4 Te4#
1. Tc4 Sb4+ 2. Kc5 Ka3 3. Td4 Tc6#
Adrian Storisteanu: Possible fix: bPa5->b4, wKb3->f8, +wPb3 (5+3). (2015-10-6)
Yuri Bilokin: Correction: wKb3-g8, bpa5-b4, +bbc4 6K1/8/N3R3/2rk4/Ppb5/8/8/8 (3+5) (2019-3-4)
comment
Keywords: Interchange (TS kt)
Genre: h#
Input: hpr, 1996-7-12
Last update: Alfred Pfeiffer, 2015-10-6 more...
81 - P0502647
John Niemann
128-ro Schachmatt 13 31/12/1946
P0502647
(2+5)
h#2*
4x4-Brett (e5-h8)
* 1. ... g8=S 2. Tg7 Sxf6#
1. Lg5! g8=D 2. h6 Dxg6#
play all play one stop play next play all
Wurde als eine von vier Teilaufgaben in einem 8x8-Brett veröffentlicht, und zwar in der Ecke rechts oben.
Die anderen Teilaufgaben sind P1363314, P1363315 und P1363316.
more ...
comment
Keywords: no 8x8 board, Promotion (S,D)
Genre: h#, Fairies
Computer test: Popeye 4.61
Input: hpr, 1996-7-23
Last update: Alfred Pfeiffer, 2019-4-17 more...
82 - P0503631
Yosif Krikheli
feenschach 47, p. 174, 07-09/1979
nach L. Ugren
P0503631
(4+1) cooked
h#4
0.1...
1. ... Tf5 2. Ke4 Tg5 3. Kf4 Tg4+ 4. Kf5 Tf4#
play all play one stop play next play all
Cook: NL
1. ... Ke6 2. Kc4 d5+ 3. Kb5 Tb4+ 4. Kc5 Lf8# (Henrik Juel)
Yuri Bilokin: Correction: 5K2/7B/8/3P1R2/3k4/8/8/8 (4+1)
1…Rf6 2.Ke5 Rg6 3.Kf5 Rg5+ 4.Kf6 Rf5# (2019-2-1)
Henrik Juel: There is another unique solution
1... Ke6 2.Kc4 d5+ 3.Kb5 Tb4+ 4.Kc5 Lf8#
So with 2 solutions stipulated the problem is C+ by Popeye 4.61
But this other solution does not show a round-trip, which is probably why Yuri has offered a correction (2019-2-1)
comment
Keywords: Pure Round Trip (T), Rex solus (s)
Genre: h#
Input: Hans-Jürgen Schäfer, 1996-9-23
Last update: Alfred Pfeiffer, 2019-2-1 more...
83 - P0503635
Yosif Krikheli
6390v Springaren 12/1988
P0503635
(2+5) cooked
h#4
1. Kg7 Le7 2. Th7 Lf8+ 3. Kf6 Lh6 4. Tg7 Lg5#
play all play one stop play next play all
Cook: NL
1. Kg7 Kg3 2. Th7 Lh6+ 3. Kf6 Kf4 4. Tg7 Lg5#
Steven B. Dowd: Korrektur: +WBf3 (da auch 1. Kf3 und dann Kf4 geht) und + SBh4 ist dann C+ (Alybadix). (2005-10-9)
Yuri Bilokin: Correction: +brd3 8/5p1k/4q1pr/6B1/5K2/3r4/8/8 (2+6) (2019-2-1)
A.Buchanan: +sBe7 then shift and rotate to get 2K5/1L6/tp1d4/k1pp4/8/8/8/8 The single new pawn does get captured in the solution, which might be seen as a downside, but the minimal ideal mate is retained. A glance at P0564037 by the same composer shows that he is ok to have a unit captured in the course of a round trip. So this is my preferred fix. (2019-2-2)
more ...
comment
Keywords: Pure Round Trip (L), Minimal (L), Ideal mate
Genre: h#
Input: hpr, 1996-9-23
Last update: A.Buchanan, 2019-2-2 more...
84 - P0503847
Albert Zickermann
279v Bottroper Volkszeitung 05/02/1936
P0503847
(4+10) cooked
h#4
1. Lh5 Lg4 2. Le8 Lc8 3. Lxb5 La6 4. Lc4+ Lxc4#
play all play one stop play next play all
Cook: NL
1. Lf1 b6 2. Lh3 b7 3. Lc8 bxc8=D 4. c4+ Dxc4#
Yuri Bilokin: Correction: 8/8/1p6/1PpK4/8/p1pkr3/1pprb3/1nbB4 (3+12)
Version 1: h#2 2.1… 8/8/1p6/1PpK4/8/p1pkr2p/1pppb3/1nbB4 (3+13)
1.Bh5 Bg4 2.Be8 Bc8 3.Bxb5 Ba6 4.Bc4+ Bxc4#
1.Rg3 Ke5 2.Bf3 Kf4 3.Rg4+ Kxf3 4.Rd4 Be2#
Version 2: 4B3/3brp2/3rkp2/6p1/4K1P1/8/8/8 (3+7)
1.Ba4 Bb5 2.Bd1 Bf1 3.Bxg4 Bh3 4.Bf5+ Bxf5# (2019-3-13)
comment
Keywords: Alleinunterhalter
Genre: h#
Input: Hans-Jürgen Schäfer, 1996-9-23
Last update: Alfred Pfeiffer, 2019-3-13 more...
85 - P0505287
Constantin Bidulescu
Revista de Sah 01/1977
3. Platz
Rumänische Meisterschaft
P0505287
(4+6) cooked
h#4
1. La1 Lb2 2. f5 Lh8 3. Lg7 d3+ 4. Ke5 Lxg7#
play all play one stop play next play all
Cook: NL 1. Lc3 Lb2 2. Ke5 La1 3. Le4 dxc3 4. f5 c4#
Adrian Storisteanu: The author's name is Constantin Bidulescu. (2015-10-12)
Yuri Bilokin: Correction: -wPa3, bpa4-b4, bqf4-c5, +bnc8, bpd5(-bbd5), +brf4
2n4b/3K1p2/8/2qp4/1p2kr2/8/3P4/2B5 (3+8) (2019-3-12)
comment
Keywords: Clearance
Genre: h#
Input: hpr, 1996-12-26
Last update: Alfred Pfeiffer, 2015-10-13 more...
86 - P0505291
Mykola Nagnibida
Nikolay Budkov

10316 British Chess Magazine 07/1971
P0505291
(4+8) cooked
h#4
1. Lh1 Lg2 2. Kc4 La8 3. Lb7 b3+ 4. Kd5 Lxb7#
play all play one stop play next play all
Cook: NL
1. Ta1 Lxe2 2. Td6 Kxd6 3. Ta5 Kxc5 4. Ka4 Ld1#
Yuri Bilokin: Correction: bpb5-d3, bne2-f4(-wPf4), -bre1, +bpd2, +bpe2, +bpe5, +bnf6, +bpg4
b7/4K3/5n2/2p1pp2/3r1np1/1k1p4/1P1pp3/5B2 (3+12) (2019-3-13)
comment
Keywords: Clearance
Genre: h#
Input: hpr, 1996-12-26
Last update: Alfred Pfeiffer, 2019-3-13 more...
87 - P0505331
Wilhelm Hagemann
689 Essener Volkswacht 14/03/1931
P0505331
(3+4) cooked
h#3
1. d1=T Th1 2. Tg1+ Kf6 3. Tg4 Tf1#
play all play one stop play next play all
Cook: NL
1. Kg5 Txe3 2. Kh5 Kf6 3. Kh6 Th3#
versetzt man wBh2 nach h3, HJS gibt's ne neue eindeutige Lösung: 1. d1=T Tg1 2. Tf1 Kf6 3. Tf3 Tg4#,
Yuri Bilokin: Correction: +bbe8 4b3/6K1/8/8/4pk2/4p3/3p3P/4R3 (3+5) (2019-3-22)
comment
Keywords: Clearance, Promotion in the key, under-promotion (t)
Genre: h#
Input: hpr, 1996-12-27
Last update: Alfred Pfeiffer, 2019-3-23 more...
88 - P0505408
Heinz Brixi
(F4) L'Opinio 03/10/1934
P0505408
(4+3) cooked
h#4
1. Kf4 e4 2. La1 Lb2 3. g4 Lc1 4. Le5 d3#
play all play one stop play next play all
Cook: NL
1. Kf5 d3 2. Kf4 e4 3. Le5 Lg7 4. g4 Lh6#
Yuri Bilokin: Correction: +bqh4, +bng8, +bnh2 6nB/6b1/8/4k1p1/7q/8/3PP1Kn/8 (4+6) (2019-3-12)
comment
Keywords: Clearance
Genre: h#
Input: hpr, 1996-12-27
Last update: Alfred Pfeiffer, 2019-3-12 more...
89 - P0505519
Wilhelm Kluxen
4067 Deutsche Schachblätter 15/04/1927
P0505519
(5+10) cooked
h#4
1. Ta1 Txa3 2. Lb1 Lc2 3. Lf4 Lxb3 4. Le4+ Ld1#
play all play one stop play next play all
Cook: NL
1. Lf5 Kg1 2. Ke4 Kxf2 3. Lf4 Lxf5#
Yuri Bilokin: Correction: 8/8/6B1/P2p4/RP1Pb3/pp3k2/qp3r2/1rb4K (6+10) (2019-1-19)
comment
Keywords: Clearance
Genre: h#
Input: hpr, 1996-12-27
Last update: Alfred Pfeiffer, 2019-1-20 more...
90 - P0505672
Willibald Roese
25 Schnittpunktkombinationen und ihre Antif 1924
P0505672
(3+3) cooked
h#3
0.1...
1. ... Th1 2. Th2 Kf7 3. Txh4 Txh4#
play all play one stop play next play all
Cook: NL
1. ... Kf6 2. Kg8 Tb3 3. Kf8 Tb8#
Yuri Bilokin: Correction: bra2-g2, bpa3-g3 7k/8/4K3/8/7P/6pR/6r1/8 (3+3) (2019-3-22)
comment
Keywords: Clearance
Genre: h#
Input: hpr, 1996-12-27
Last update: Alfred Pfeiffer, 2019-3-22 more...
91 - P0507988
Viktor Sizonenko
Evgeny Sorokin

3655 Land og Folk 13/10/1979
P0507988
(4+9) cooked
h#2
4.1...
1) 1. Dd5 e8=L 2. Ke6 Ld7#
2) 1. Kg6 e8=T 2. f5 Txg8#
3) 1. Lf3 e8=S 2. Ke4 Sd6#
4) 1. Txg5 e8=D 2. Kf6 Dxf7#
play all play one stop play next play all
Cook: NL
1. Ld5 Lxb5 2. Ke6 Ld7#
t/Allumwandlung, u/61103
Yuri Bilokin: Correction: wBc4-b3, +bpd3 b5r1/2K1Pp1n/8/1q2rkBp/3b4/1B1p4/8/8 (4+10) (2019-2-27)
comment
Keywords: Allumwandlung
Genre: h#
Input: Erich Bartel, 1997-5-23
Last update: Alfred Pfeiffer, 2019-2-27 more...
92 - P0508504
Werner Schlitt
70 FEENSCHACH 21/06/1959
Wilhelm Karsch zum 60. Geburtstag gewidmet
1. Preis
Abteilung h# und h=
P0508504
(3+8) C+
h#1
b) wTc4 statt wDc4: h#2
c) wLc4 statt wDc4: h#3
d) wSc4 statt wDc4: h#4
e) wBc4 statt wDc4: h#5
a) 1. e1=S Df1#
b) 1. e1=S Tf4 2. Sg2 Tf1#
c) 1. e1=L+ Kxb6 2. Lf2 Le2 3. Lg1 Lf3#
d) 1. e1=S Sxb2 2. Sg2 Sd3 3. Tb1 a4 4. Tg1 Sf2#
e) 1. Tb5+ cxb5 2. Kg2 bxc6 3. h1=T c7 4. Tg1 c8=D 5. Kh1 Dh3#
play all play one stop play next play all
t/Allumwandlung+2, u/61114, u/Dssllst, t/Forsberg-Thema
more ...
comment
Keywords: Forsberg twin, Allumwandlung (+2), Phoenix (t)
Genre: h#
Computer test: Popeye 4.61
Input: Erich Bartel, 1997-5-23
Last update: Alfred Pfeiffer, 2019-7-30 more...
93 - P0509078
Franz Palatz
131 L'Echiquier (Brüssel) 09-10/1932
P0509078
(4+4) cooked
h#4
1. Ld4 Lxf4 2. La7 b6 3. Ka8 bxc7 4. Lb8 cxb8=D#
play all play one stop play next play all
Cook: NL
1. c5 bxc6ep 2. Kc8 c7 3. Kd7 c8=D+ 4. Kd6 Lf8#
1. Ka8 b6 2. Ld4 bxc7 3. La7 Lxf4 4. Lb8 cxb8=D#
Yuri Bilokin: Correction: -bbh8, wKe4-f3(-wPf3), +bna8 nk6/2p5/7B/1P6/5p2/5K2/8/8 (3+4)
1.Sb6 Bxf4 2.Sd7 b6 3.Ka8 bxc7 4.Sb8 cxb8=Q# (2019-3-12)
comment
Keywords: Promotion in the mating move, En passant
Genre: h#
Input: hpr, 1997-6-2
Last update: Alfred Pfeiffer, 2019-3-12 more...
94 - P0509474
Yosif Krikheli
1137 Biuletyn 01-02/1969
P0509474
(3+4) cooked
h#5
1. Se6 Lf8 2. Se7 Kf3 3. Kc5 Ke3 4. Kd5 Kd3 5. Sc6 e4#
play all play one stop play next play all
Cook: NL
1. Sb4 Ld4 2. Se6 Kf3 3. Sc6 Ke3 4. Kd5 Kd3 5. Ld6 e4#
1. Lc7 e4 2. Kb5 exd5 3. Ka6 d6 4. Kb7 dxc7 5. Ka8 c8=D#
Adrian Storisteanu: Possible fix: wBc5->d6. (2019-2-16)
comment
Keywords: Excelsior, white (auto key), Check Protection, tempo play (k)
Genre: h#
Input: Markus Manhart, 1997-6-28
Last update: Alfred Pfeiffer, 2019-2-16 more...
95 - P0509757
Pavlos N. Moutecidis
834 Feladvanykedvelök Lapja 05/1972
P0509757
(4+12) cooked
h#4
1. Le2 Kh3 2. Tf3 Kg4 3. Te3+ Kf5 4. Lh5 Lf4#
play all play one stop play next play all
Cook: NL
1. Lf3+ Kh3 2. Kg5 Le1 3. Kf4 Kh4 4. f5 Lg3#
klären Nummer
Yuri Bilokin: Correction: -brh1, -bph2, +bnf1 8/3p2p1/3P1pPk/7b/2p1p3/4r1B1/3b2K1/3q1n2 (4+11) (2019-3-13)
comment
Keywords: Fesselungsspiel (112 110 110), Check Protection
Genre: h#
Reprints: 884 Feladvanykedvelök Lapja 05/1972
Input: Markus Manhart, 1997-6-26
Last update: Alfred Pfeiffer, 2019-3-14 more...
96 - P0509994
Leonid G. Iskra
Evgeny Sorokin

830 Feladvanykedvelök Lapja 05/1972
P0509994
(3+4) cooked
h#3
b) sSf5
a) 1. Dd1 Lh1 2. Df3 Kc4 3. Ke4 Te2#
b) 1. Dxb7 Kc4 2. Df3 Th6 3. Ke4 Te6#
play all play one stop play next play all
Cook: NL
a) 1. De1 Kc6 2. Ke4 Td2 3. De3 Kd6#
b) 1. De4 La6 2. Sd4+ Kc5 3. Sf3 Te2#
Yuri Bilokin: Correction: 8/6Rq/8/3bp3/5k2/1p6/8/1B1K4 (3+5) b) bnc5
a) 1.Qh3 Bh7 2.Qf5 Ke2 3.Ke4 Rg4#
b) 1.Qxb1+ Ke2 2.Qf5 Rc7 3.Ke4 Rc4# (2019-3-30)
comment
Keywords: Fesselungsspiel (111 101 000), Check Protection
Genre: h#
Input: Markus Manhart, 1997-6-28
Last update: Alfred Pfeiffer, 2019-4-2 more...
97 - P0510117
Yosif Krikheli
9121 FEENSCHACH 03/1969
Lob
21. Thematurnier
P0510117
(6+12) cooked
h#4
1. Sd5 Sh3 2. Se3 f3 3. Tf6 Sf2 4. Sf5 f4#
play all play one stop play next play all
Cook: NL
1. Db3 Sh3 2. Dxg3 Sg5 3. Kf4+ Kd4 4. Df3 Se6#
Yuri Bilokin: Correction: 8/1pp5/b1p1qn2/1pK1kr1p/1Pp2NpP/6P1/5P1p/6br (6+15) (2019-1-31)
comment
Keywords: Check Protection
Genre: h#
Input: Markus Manhart, 1997-6-27
Last update: Alfred Pfeiffer, 2019-2-1 more...
98 - P0510195
Hugo Früchtenicht
Franz Palatz

24 Kongreßbuch Teplitz-Schönau 1923
P0510195
(3+6) cooked
h#3
1. Tb2+ Lc2 2. Tb3 Tb2 3. Ka4 Ta2#
play all play one stop play next play all
Cook: NL:
1. La1 Lxb3 2. Le2 Lc4 3. Ka4 Txa1#
ua
Yuri Bilokin: Correction: q7/1b6/Bpp5/krb5/6K1/pRr5/2p5/1n6 (3+11)
1.Rb4+ Bc4 2.Rb5 Rb4 3.Ka6 Ra4# (2019-3-29)
comment
Keywords: Fesselungsspiel (111 101 000), Check Protection
Genre: h#
Input: Markus Manhart, 1997-6-27
Last update: Alfred Pfeiffer, 2019-4-2 more...
99 - P0510541
Dragomir Rusin
Problem 41-44 03/1957
3. Preis
15. Thematurnier
P0510541
(3+14) cooked
h#4
0.1...
1. ... Txg7 2. Td3 Txg6 3. Sd4 Txg4 4. Sb3 Ta4#
play all play one stop play next play all
Cook: NL
1. ... Txg7 2. Ka1 Txf7 3. Sg3 Tf2 4. Dc8 Lxd4#
Yuri Bilokin: Correction: 4nrRB/2p2pbK/p3p1p1/5n2/3r2q1/5p2/k7/1b6 (3+14) (2019-1-19)
comment
Keywords: Check Protection, Whose move?
Genre: h#, Retro
Input: Markus Manhart, 1997-6-26
Last update: Alfred Pfeiffer, 2019-1-20 more...
100 - P0512476
Sigurd Jensen
532 Land og Folk 04/07/1971
P0512476
(4+3) cooked
h#3
1. Tc6 e3 2. Le6 Sd7+ 3. Kd5 Td4#
play all play one stop play next play all
Cook: NL:
1. Ld3 Td4 2. Lb5 e3 3. Tc6 Sd7#
Yuri Bilokin: Correction 2r5/8/8/3k4/2N2P2/6b1/8/4R1K1 (4+3)
1.Rc5 f5 2.Bc7 Sb6+ 3.Kd6 Re6# (2019-3-5)
comment

Genre: h#
Input: Markus Manhart, 1997-9-30
Last update: Alfred Pfeiffer, 2019-3-6 more...
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The problems of this query have been registered by the following contributors:

Gerd Wilts (77)
hpr (12)
Hans-Jürgen Schäfer (2)
Erich Bartel (2)
Markus Manhart (7)