143 problem(s) found in 2103 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20200919 AND CPLUS AND S='Phenix'] [download as LaTeX]
1. c4 c5 2. Db3 Db6 3. Dh3 Dh6 4. b3 b6 5. La3 La6 6. Lb4 Lb5 7. Sa3 Sa6 8. 0-0-0 0-0-0 9. Kb1 Kb8 10. Tc1 Tc8 11. Tc3 Tc6 12. Tg3 Tg6 13. Tg4 Tg5 14. g3 g6 15. Lg2 Lg7 16. Ld5 Ld4 17. Sf3 Sf6 18. Tc1 Tc8 19. Tc3 Tc6 20. Te3 Te6 21. Te4 Te5 22. Tef4 Tef5 23. e4 e5
Keywords: Unique Proof Game, Castling (wgsg), Symmetrical position, Capture-free
Genre: Retro
Computer test: Mondenhauer C+ Stelvio 1.11 00:09:39 Minuten. (hh:mm:ss) Keine Lösung: BP 22.0, BP 22.5.
FEN: 1k6/p2p1p1p/np3npq/1bpBprr1/1BPbPRR1/NP3NPQ/P2P1P1P/1K6
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-03-27 more...
Genre: Retro
Computer test: Mondenhauer C+ Stelvio 1.11 00:09:39 Minuten. (hh:mm:ss) Keine Lösung: BP 22.0, BP 22.5.
FEN: 1k6/p2p1p1p/np3npq/1bpBprr1/1BPbPRR1/NP3NPQ/P2P1P1P/1K6
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-03-27 more...
1. g4 d6 2. Lh3 Dd7 3. Kf1 De6 4. De1 De3 5. fxe3 Kd7 6. Dh4 Kc6 7. Dh6 gxh6 8. Sf3 Lg7 9. Tg1 Ld4 10. Tg3 Sf6 11. Lg2 Tg8 12. Th3 Tg5 13. Th5 Te5 14. Tg5 Lf5 15. Tg8 Sbd7 16. Th8 Tg8 17. Ke1 Tg5 18. Ta8 Th5 19. g5 Sg8 20. g6 Tg5 21. Lf1 Tg1 22. g7 Th1 23. Sg1
Henrik Juel: This is one of the proof games that is solved faster by hand than by computer
The two captures are obvious, and the interchanged rooks make a guess like Th1-g1-g3-h3-h5-g5-g8-h8-a8 reasonable
Natch 3.1 got nowhere in an hour (2018-12-10)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 40 Sekunden.
Keine Lösung: BP 21.5, BP 22.0. (2023-02-26)
comment
The two captures are obvious, and the interchanged rooks make a guess like Th1-g1-g3-h3-h5-g5-g8-h8-a8 reasonable
Natch 3.1 got nowhere in an hour (2018-12-10)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 40 Sekunden.
Keine Lösung: BP 21.5, BP 22.0. (2023-02-26)
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Stelvio 1.0
FEN: R5n1/pppnppPp/2kp3p/4rb2/3b4/4P3/PPPPP2P/RNB1KBNr
Input: Gerd Wilts, 1998-06-26
Last update: Silvio Baier, 2023-03-02 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: R5n1/pppnppPp/2kp3p/4rb2/3b4/4P3/PPPPP2P/RNB1KBNr
Input: Gerd Wilts, 1998-06-26
Last update: Silvio Baier, 2023-03-02 more...
1. g3 h5 2. Lh3 Th6 3. Kf1 Te6 4. Kg2 f6 5. Kf3 Te3+ 6. Kf4 e5+ 7. Kf5 Lb4 8. Kg6 De7 9. Kh7 Dc5 10. Kxg8 d6 11. Kxg7 Lg4 12. Kg6 Lf3 13. exf3 Te1 14. Se2 Tg1 15. Kf5 Tg2 16. Te1 a5 17. Sg1 a4 18. Te3 Ta5 19. Tb3 axb3 20. Ke4 bxa2 21. Kd3 e4+ 22. Ke2 e3 23. Ke1
paul: Sol.: 1.g3 h5 2.Bh3 Rh6 3.Kf1 Re6 4.Kg2 f6 5.Kf3 Re3+ 6.Kf4 e5+ 7.Kf5 Bb4 8.Kg6 Qe7 9.Kh7 Qc5 10.Kxg8 d6 11.Kxg7 Bg4 12.Kg6 Bf3 13.exf3 Re1 14.Se2 Rg1 15.Kf5 Rg2 16.Re1 a5 17.Sg1 a4 18.Re3 Ra5 19.Rb3 axb3 20.Ke4 bxa2 21.Kd3 e4+ 22.Ke2 e3 23.Ke1 (Ra4 is in a5)
The King captures an officer on its place and return.
For comparison, see P1013070 and P1007320 (2008-04-25)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 09:10:17 Stunden.
Keine Lösung: BP 21.5, BP 22.0, Prüfzeit 02:01:51 Stunden. (2023-02-17)
Reto: A good example of Stelvio's progress: Stelvio 1.5 only needs 40min on my notebook. (2023-08-19)
comment
The King captures an officer on its place and return.
For comparison, see P1013070 and P1007320 (2008-04-25)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 09:10:17 Stunden.
Keine Lösung: BP 21.5, BP 22.0, Prüfzeit 02:01:51 Stunden. (2023-02-17)
Reto: A good example of Stelvio's progress: Stelvio 1.5 only needs 40min on my notebook. (2023-08-19)
comment
Keywords: Unique Proof Game, Round Trip (K)
Genre: Retro
Computer test: Stelvio 1.0
FEN: 1n2k3/1pp5/3p1p2/r1q4p/1b6/4pPPB/pPPP1PrP/RNBQK1N1
Reprints: 2799v Phénix 146 12/2005
Input: Gerd Wilts, 1999-02-27
Last update: Silvio Baier, 2023-03-02 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: 1n2k3/1pp5/3p1p2/r1q4p/1b6/4pPPB/pPPP1PrP/RNBQK1N1
Reprints: 2799v Phénix 146 12/2005
Input: Gerd Wilts, 1999-02-27
Last update: Silvio Baier, 2023-03-02 more...
1. fxe3ep d8=S 2. Kxd5 0-0-0# (Td1#?)
White has made 6 pawn captures with one missing black piece unaccounted for, that by parity can only have been captured by an officer. White's last move cannot have been a pawn capture. If R: 1.f2-f3, then sLg1 was promoted, implying 7 captures by black pawns - one too many. So if White can prove they retain castling rights, then the ep is on. Hence AP Petrovic is valid.
White has made 6 pawn captures with one missing black piece unaccounted for, that by parity can only have been captured by an officer. White's last move cannot have been a pawn capture. If R: 1.f2-f3, then sLg1 was promoted, implying 7 captures by black pawns - one too many. So if White can prove they retain castling rights, then the ep is on. Hence AP Petrovic is valid.
Henrik Juel: 0... fxe3ep 1.d8S Kxd5 2.0-0-0#. Not -1.f2? and Lg1 is caught. (2004-09-16)
Vaclav Kotesovec: Similar problems should not be labeled as "C+". Such a designation is only acceptable if the entire analysis was performed by a computer program. (2023-08-03)
Henrik Juel: In principle I agree, Vaclav
But PDB does not (yet) allow HC+, so I find it acceptable to use the C+ label, when you also tell the whole story after 'Computer test:' below (2023-08-03)
A.Buchanan: Hopefully Gerd will have more time at some point, and can expand the functionality in this and other areas. In the meantime, engine solving of conventional retros including AP, is in its infancy. Retractor 2 has some effectiveness, but is still basic. And there is nothing that yet grasps the intricacies of castling/ep etc. However AP problems do often contain considerable forward chess, and the C+ tag is very useful to filter out those that have already been solved forwardly, without pretending that these are in any sense fully solved (2023-08-04)
Ladislav Packa: I know the definition of AP, but I don't understand the logic behind it. The move 1.fxe3 e.p. proves that White CAN castling. But the solution (2. ...Rd1#?) claims that castling is MANDATORY. From my point of view, AP is correct when only castling is necessary for the solution and the Rook move would be a dual. (2023-08-04)
A.Buchanan: @Ladislav: I am not sure how to help you. Maybe you can read this page from Retro Corner: https://www.janko.at/Retros/Glossary/APosteriori.htm (2023-08-05)
Ladislav Packa: Andrew, what should the article help me with? I quote the final sentence:
Some people still oppose this rule and argue that it should certainly not be the default convention. (2023-08-05)
Henrik Juel: You could view it this way, Ladislav
h#2 means that it is Black to move, so White made last move
What was last move? A little analysis shows just three possibilities: f2-f4, move by Ta1, or move by Ke1
So normally we cannot assume that last move was f2-f4
But if White can castle, then the last move was f2-f4
So if we could start with 0... 0-0-0, then 1.fxe3ep would be legitimate
AP says that you are allowed to reverse the sequence of events; first do the ep capture, then later legitimize it by castling
Was this helpful? (2023-08-05)
Ladislav Packa: Henrik, you don't have to explain that to me. I've done a few AP issues myself, like P1348357. But that doesn't mean I agree with AP's logic. I already wrote it - the term "you can castle" is applied as "you must castle". But these are only problems where, in addition to castling, the Rook move can also be used, I consider that a dual.
From that point of view, the P1000662 issue is perfectly fine for me. (2023-08-05)
Joost de Heer: AP: By castling, you prove a posteriori that the ep-capture was not just a try but the actual solution. Without castling, the ep-solution just is that: a try.
So: Try 1. fe3 ep e8=S 2. Kd5 Rd1 - but ep capture not allowed, as there is no proof that f2-f4 must've been the last move.
Solution 1. fe3 ep e8=S 2. Kd5 OOO - Now the ep capture was justified because white castled, thereby proving that the last move before the diagram position indeed was f2-f4. (2023-08-06)
Joost de Heer: See e.g. P1052919 : The try is an ep capture which is unjustified. (2023-08-06)
A.Buchanan: OK Ladislav: I think I get your point. If one solution with castling justifies the e.p., then based on that certainty, why shouldn't an alternative solution with no castling *then* be allowed as well? There are problems in which one twin shows 0-0-0 and the other shows 0-0. Each is based on the other in a similar way, so the idea of dependency is not new. Why are we not allowed to add other "parasitic" solutions as well? Why can we only have the "paying" solutions? We can't say that we are restricted to one solution: that's not the way chess problems operate! And this is just in the help world - in the adversarial world it might get even more complicated. Is this your issue, Ladislav? (2023-08-07)
Ladislav Packa: I don't want to unnecessarily prolong this discussion. However, I will add one more note: in this position, white castling is also possible without e.p. in Black's 1st move. If B1 were an indifferent move, then white can 1...0-0-0! The Codex of Chess Composition writes about it in Article 16 (1):
Castling convention. Casting is permitted unless it can be proven that it is not permissible.
In our case, 0-0-0 is possible because White's last move exists - e2-e4! It does not matter if it is this move or some a2-a3, both moves are equivalent. EP does not prove the possibility of casting, it would be legal even without it. (2023-08-07)
A.Buchanan: Ladislav was what I wrote your issue pls? Y/N :-) (2023-08-07)
Ladislav Packa: I have no problem, I'm just expressing my own opinion about the AP convention. (2023-08-07)
A.Buchanan: OK cos I think the point I raised is a real one that should be addressed by theory some day. Clearly from the nice problem that you composed Ladislav you understand the mechanics very well. From a justification perspective it's all a bit iffy, but that's why it's controversial. Under RS it's really the only way one can end up actually eping, and it's proved compositionally fertile. So that's enough to justify (2023-08-08)
Ladislav Packa: No need to apologize. This is a normal discussion with different views on the issue. Maybe it will come to some conclusion.
I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p. (2023-08-08)
Joost de Heer: "I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p."
You misinterpret AP. The e.p. capture does not authorize castling, castling provides a justification later on (hence the 'a posteriori') for the legality of ep.
Usually, for ep justification you need to examine all game trees that lead to the diagram, and only if all game trees end with the double-step, then ep is allowed.
With AP, you examine all the game trees including the actual play. If all those game trees have as last move before the diagram position the double step, then ep is possible.
In this case, if white doesn't castle, then there are game trees which don't have as last move the double step, and therefore AP logic dictates that the ep capture was illegal. However, all game trees which lead to the diagram and which have castling in the actual play have as last move before the diagram position the double step, hence AP dictates that the ep capture is legal. (2023-08-09)
Ladislav Packa: Joost: A simple question - is white allowed to castle after any 1st move by black (except e.p.)? (2023-08-09)
Joost de Heer: Of course he is. AP only is used to combine the ep justification with castling, not the castling right per se. (2023-08-09)
more ...
comment
Vaclav Kotesovec: Similar problems should not be labeled as "C+". Such a designation is only acceptable if the entire analysis was performed by a computer program. (2023-08-03)
Henrik Juel: In principle I agree, Vaclav
But PDB does not (yet) allow HC+, so I find it acceptable to use the C+ label, when you also tell the whole story after 'Computer test:' below (2023-08-03)
A.Buchanan: Hopefully Gerd will have more time at some point, and can expand the functionality in this and other areas. In the meantime, engine solving of conventional retros including AP, is in its infancy. Retractor 2 has some effectiveness, but is still basic. And there is nothing that yet grasps the intricacies of castling/ep etc. However AP problems do often contain considerable forward chess, and the C+ tag is very useful to filter out those that have already been solved forwardly, without pretending that these are in any sense fully solved (2023-08-04)
Ladislav Packa: I know the definition of AP, but I don't understand the logic behind it. The move 1.fxe3 e.p. proves that White CAN castling. But the solution (2. ...Rd1#?) claims that castling is MANDATORY. From my point of view, AP is correct when only castling is necessary for the solution and the Rook move would be a dual. (2023-08-04)
A.Buchanan: @Ladislav: I am not sure how to help you. Maybe you can read this page from Retro Corner: https://www.janko.at/Retros/Glossary/APosteriori.htm (2023-08-05)
Ladislav Packa: Andrew, what should the article help me with? I quote the final sentence:
Some people still oppose this rule and argue that it should certainly not be the default convention. (2023-08-05)
Henrik Juel: You could view it this way, Ladislav
h#2 means that it is Black to move, so White made last move
What was last move? A little analysis shows just three possibilities: f2-f4, move by Ta1, or move by Ke1
So normally we cannot assume that last move was f2-f4
But if White can castle, then the last move was f2-f4
So if we could start with 0... 0-0-0, then 1.fxe3ep would be legitimate
AP says that you are allowed to reverse the sequence of events; first do the ep capture, then later legitimize it by castling
Was this helpful? (2023-08-05)
Ladislav Packa: Henrik, you don't have to explain that to me. I've done a few AP issues myself, like P1348357. But that doesn't mean I agree with AP's logic. I already wrote it - the term "you can castle" is applied as "you must castle". But these are only problems where, in addition to castling, the Rook move can also be used, I consider that a dual.
From that point of view, the P1000662 issue is perfectly fine for me. (2023-08-05)
Joost de Heer: AP: By castling, you prove a posteriori that the ep-capture was not just a try but the actual solution. Without castling, the ep-solution just is that: a try.
So: Try 1. fe3 ep e8=S 2. Kd5 Rd1 - but ep capture not allowed, as there is no proof that f2-f4 must've been the last move.
Solution 1. fe3 ep e8=S 2. Kd5 OOO - Now the ep capture was justified because white castled, thereby proving that the last move before the diagram position indeed was f2-f4. (2023-08-06)
Joost de Heer: See e.g. P1052919 : The try is an ep capture which is unjustified. (2023-08-06)
A.Buchanan: OK Ladislav: I think I get your point. If one solution with castling justifies the e.p., then based on that certainty, why shouldn't an alternative solution with no castling *then* be allowed as well? There are problems in which one twin shows 0-0-0 and the other shows 0-0. Each is based on the other in a similar way, so the idea of dependency is not new. Why are we not allowed to add other "parasitic" solutions as well? Why can we only have the "paying" solutions? We can't say that we are restricted to one solution: that's not the way chess problems operate! And this is just in the help world - in the adversarial world it might get even more complicated. Is this your issue, Ladislav? (2023-08-07)
Ladislav Packa: I don't want to unnecessarily prolong this discussion. However, I will add one more note: in this position, white castling is also possible without e.p. in Black's 1st move. If B1 were an indifferent move, then white can 1...0-0-0! The Codex of Chess Composition writes about it in Article 16 (1):
Castling convention. Casting is permitted unless it can be proven that it is not permissible.
In our case, 0-0-0 is possible because White's last move exists - e2-e4! It does not matter if it is this move or some a2-a3, both moves are equivalent. EP does not prove the possibility of casting, it would be legal even without it. (2023-08-07)
A.Buchanan: Ladislav was what I wrote your issue pls? Y/N :-) (2023-08-07)
Ladislav Packa: I have no problem, I'm just expressing my own opinion about the AP convention. (2023-08-07)
A.Buchanan: OK cos I think the point I raised is a real one that should be addressed by theory some day. Clearly from the nice problem that you composed Ladislav you understand the mechanics very well. From a justification perspective it's all a bit iffy, but that's why it's controversial. Under RS it's really the only way one can end up actually eping, and it's proved compositionally fertile. So that's enough to justify (2023-08-08)
Ladislav Packa: No need to apologize. This is a normal discussion with different views on the issue. Maybe it will come to some conclusion.
I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p. (2023-08-08)
Joost de Heer: "I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p."
You misinterpret AP. The e.p. capture does not authorize castling, castling provides a justification later on (hence the 'a posteriori') for the legality of ep.
Usually, for ep justification you need to examine all game trees that lead to the diagram, and only if all game trees end with the double-step, then ep is allowed.
With AP, you examine all the game trees including the actual play. If all those game trees have as last move before the diagram position the double step, then ep is possible.
In this case, if white doesn't castle, then there are game trees which don't have as last move the double step, and therefore AP logic dictates that the ep capture was illegal. However, all game trees which lead to the diagram and which have castling in the actual play have as last move before the diagram position the double step, hence AP dictates that the ep capture is legal. (2023-08-09)
Ladislav Packa: Joost: A simple question - is white allowed to castle after any 1st move by black (except e.p.)? (2023-08-09)
Joost de Heer: Of course he is. AP only is used to combine the ep justification with castling, not the castling right per se. (2023-08-09)
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Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg), Promotion (S), Valladao Task
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 + simple retro-logic
FEN: 8/3P2p1/2PP4/1ppPp3/2pkPp2/5PP1/6Pp/R3K1b1
Input: Gerd Wilts, 1999-02-27
Last update: A.Buchanan, 2023-09-11 more...
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 + simple retro-logic
FEN: 8/3P2p1/2PP4/1ppPp3/2pkPp2/5PP1/6Pp/R3K1b1
Input: Gerd Wilts, 1999-02-27
Last update: A.Buchanan, 2023-09-11 more...
1. h4 g5 2. hxg5 e5 3. Txh7 Df6 4. Txf7 Th3 5. g4 Te3 6. dxe3 Lb4+ 7. Ld2 d6 8. Lc3 Le6 9. Dd4 Lxa2 10. Sd2 Ld5 11. Txa7 Lf3 12. exf3 Se7 13. Ld3 Kd7 14. Kf1 Kc6 15. Kg2 Sd7 16. Kg3 Th8 17. Ta8 Th1 18. Sh3 Ta1 19. Tc8 Ta8
Keywords: Unique Proof Game, Pure Round Trip (t)
Genre: Retro
Computer test: Resolution time : 54.34 s., Natch 2.3 Copyright (C) 1997,98,99,2001,2002,2003,2004 Pascal Wassong
FEN: r1R5/1ppnnR2/2kp1q2/4p1P1/1b1Q2P1/2BBPPKN/1PPN1P2/8
Reprints: 2 64 Proof Games 2012
Input: Gerd Wilts, 1999-02-27
Last update: Gerd Wilts, 2012-12-23 more...
Genre: Retro
Computer test: Resolution time : 54.34 s., Natch 2.3 Copyright (C) 1997,98,99,2001,2002,2003,2004 Pascal Wassong
FEN: r1R5/1ppnnR2/2kp1q2/4p1P1/1b1Q2P1/2BBPPKN/1PPN1P2/8
Reprints: 2 64 Proof Games 2012
Input: Gerd Wilts, 1999-02-27
Last update: Gerd Wilts, 2012-12-23 more...
1) 1. Ke5 Kd3 2. Ld6 Tf5#
2) 1. Ke3 Tf2 2. Lf4 Te2#
3) 1. Lf4 Tf6 2. Ke5 Te6#
2) 1. Ke3 Tf2 2. Lf4 Te2#
3) 1. Lf4 Tf6 2. Ke5 Te6#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/2b2R2/8/8/2KNk3/8/8/8
Input: Michal Dragoun, 1998-04-09
Last update: hpr, 2010-06-04 more...
1. f1=L 2. g1=T 3. Tg3 4. Te3 5. g3 6. g2 7. g1=D 8. Dg4 9. Lg2 10. Ld5 11. Ke4 12. Df5 13. g4 14. g3 15. g2 16. g1=S 17. Sf3 Sc5#
paul: With bPd3 to c4, the checkmate looks better. (2022-03-30)
A.Buchanan: I guess the smothered mate is thematic, at the cost of the more common model mate (2022-03-31)
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A.Buchanan: I guess the smothered mate is thematic, at the cost of the more common model mate (2022-03-31)
more ...
comment
Keywords: Allumwandlung, black, Seriesmover, under-promotion key (l), Smothered mate, Model mate, Check Protection, Minimal (S)
Genre: Fairies
Computer test: Gustav 4.1d, Brute Force
FEN: 8/8/N7/4pkp1/3p1pp1/3p4/5pp1/2K5
Reprints: Suomen Tehtäväniekat 01/11/1994
Phénix 32 08/1995
072 Kegelschach [Ebert u. Wolfenter] 1997
Rochade Europa , p. 59, 05/1998
846 Minimalkunst im Schach 2006
Input: Felber, Volker, 2000-01-06
Last update: Gunter Jordan, 2022-03-31 more...
Genre: Fairies
Computer test: Gustav 4.1d, Brute Force
FEN: 8/8/N7/4pkp1/3p1pp1/3p4/5pp1/2K5
Reprints: Suomen Tehtäväniekat 01/11/1994
Phénix 32 08/1995
072 Kegelschach [Ebert u. Wolfenter] 1997
Rochade Europa , p. 59, 05/1998
846 Minimalkunst im Schach 2006
Input: Felber, Volker, 2000-01-06
Last update: Gunter Jordan, 2022-03-31 more...
1. c4 e6 2. Db3 Ke7 3. Db6 axb6 4. d4 Ta3 5. Lh6 Th3 6. gxh3 Kd6 7. Lg2 Se7 8. Lc6 dxc6 9. d5 Kc5 10. dxc6 Kb4 11. cxb7 c5 12. a4 Sec6 13. Ta3 De7 14. Tb3+ Kxb3 15. Lc1 Kf2
Überraschendes Tempoverlustmanöver Lc1-h6-Lc1.
Überraschendes Tempoverlustmanöver Lc1-h6-Lc1.
Keywords: Unique Proof Game, Tempo Loss
Genre: Retro
Computer test: Resolution time : 19.56 s., Natch 2.3 Copyright (C) 1997,98,99,2001,2002,2003,2004 Pascal Wassong
FEN: 1nb2b1r/1P2qppp/1pn1p3/2p5/P1P5/7P/1Pk1PP1P/1NB1K1NR
Input: Gerd Wilts, 2002-04-05
Last update: Gerd Wilts, 2005-12-26 more...
Genre: Retro
Computer test: Resolution time : 19.56 s., Natch 2.3 Copyright (C) 1997,98,99,2001,2002,2003,2004 Pascal Wassong
FEN: 1nb2b1r/1P2qppp/1pn1p3/2p5/P1P5/7P/1Pk1PP1P/1NB1K1NR
Input: Gerd Wilts, 2002-04-05
Last update: Gerd Wilts, 2005-12-26 more...
s) 1. Tc6+ Dxc6+ 2. d5 exd6ep#
w) 1. Dc6+ d5 2. exd6ep+ Txc6#
w) 1. Dc6+ d5 2. exd6ep+ Txc6#
Keywords: En passant
Genre: h#
Computer test: (Popeye WINDOWS98-32Bit-Version 3.75 (2048 KB))
FEN: 8/3prp1B/K2QPB2/4Pq2/1pr1k3/3pp1P1/8/8
Input: hpr, 2003-01-09
Last update: A.Buchanan, 2013-08-13 more...
Genre: h#
Computer test: (Popeye WINDOWS98-32Bit-Version 3.75 (2048 KB))
FEN: 8/3prp1B/K2QPB2/4Pq2/1pr1k3/3pp1P1/8/8
Input: hpr, 2003-01-09
Last update: A.Buchanan, 2013-08-13 more...
s) 1. Lf4+ Txf4 2. Txb5 Lxc2#
w) 1. Tf4 Txb5 2. Lxc2+ Lxf4#
w) 1. Tf4 Txb5 2. Lxc2+ Lxf4#
Genre: h#
Computer test: (Popeye WINDOWS98-32Bit-Version 3.75 (2048 KB))
FEN: 8/8/5N2/1P3R1r/N1k1B1b1/8/2n4b/2K5
Input: hpr, 2003-01-09
Last update: hpr, 2003-01-09 more...
s) 1. Tg7 Lh4 2. f6 Txg7#
w) 1. Lh4 f6 2. Tg7 Txg7#
w) 1. Lh4 f6 2. Tg7 Txg7#
Genre: h#
Computer test: (Popeye WINDOWS98-32Bit-Version 3.75 (2048 KB))
FEN: 5r2/1pKRBp2/8/4pp2/2np4/5P1R/3N2r1/6k1
Input: hpr, 2003-01-09
Last update: hpr, 2003-01-09 more...
s) 1. Lf3+ Txf3 2. Le3 Txe3#
w) 1. Te3+ Lxe3 2. Tf3 Lxf3#
w) 1. Te3+ Lxe3 2. Tf3 Lxf3#
Jean Marc Loustau: Complete reversal of the order of moves:
s)1.A B 2.C D#
w)1.D C 2.B A#
A kind of B/W D/O echo... (2022-05-03)
comment
s)1.A B 2.C D#
w)1.D C 2.B A#
A kind of B/W D/O echo... (2022-05-03)
comment
Genre: h#
Computer test: (Popeye WINDOWS98-32Bit-Version 3.75 (2048 KB))
FEN: KN1rk3/8/3p4/7p/6b1/PR5R/1P2p2P/2b5
Input: hpr, 2003-01-09
Last update: hpr, 2003-01-09 more...
s) 1. Lf7 Txf7 2. Txh6 Lxe5#
w) 1. Tf7 Lxf7 2. Lxe5 Txh6#
w) 1. Tf7 Lxf7 2. Lxe5 Txh6#
Jean Marc Loustau: Double exchange of the White and Black moves:
1.A B 2.C D#
1.B A 2.D C# (2022-05-03)
comment
1.A B 2.C D#
1.B A 2.D C# (2022-05-03)
comment
Genre: h#
Computer test: (Popeye WINDOWS98-32Bit-Version 3.75 (2048 KB))
FEN: 8/4N1Bk/4rRbN/3Knp2/8/4b3/8/8
Input: hpr, 2003-01-09
Last update: hpr, 2003-01-09 more...
1.Be2? Be6! zz 2.Bxb5/Bd3/Bf1/Bf7/Bxg4 Bc4/Bf7/Bd5/Bd3/Bf5+ ! or 1.Bf3? Bc8! Key 1.Bc2 Be8 2.Be4 Bf7 3.Bd3 Be8 4.Bxb5 Bf7 5.Ba4 Be8 6.Bd7 Bf7 7.Be6 Bxe6 8.f5
Described as a correction of his 2856, Themes-64, 1975 (P1969) - what is wrong with that problem ??!?)
Keyword=Roman Theme
Keyword=Duel - Bishops
Anton Baumann: C+ Alybadix (2020-05-30)
Anton Baumann: ursprüngliche Aufgabe vergl. P1010228 (2021-01-05)
comment
Keyword=Roman Theme
Keyword=Duel - Bishops
Anton Baumann: C+ Alybadix (2020-05-30)
Anton Baumann: ursprüngliche Aufgabe vergl. P1010228 (2021-01-05)
comment
Genre: r#
Computer test: Anton Baumann: C+ Alybadix (2020-05-30)
FEN: 6kB/p2b2P1/P5Pp/1p5P/1p3Pp1/1p4p1/1p4P1/bK1B4
Input: Paul Valois, 2001-08-29
Last update: Erich Bartel, 2020-05-31 more...
1. h4 Sf6 2. Th3 Sd5 3. Tc3 f6 4. Tc5 Kf7 5. c4 Ke6 6. Dc2 Ke5 7. Df5+ Kd4 8. d3 a5 9. Lf4 Ta6 10. Sd2 Te6 11. Ld6 Sb4 12. f4 S4c6 13. Kf2 Se5 14. Kg3 Sf7 15. Kg4 Sh6+ 16. Kh5 Sg8 17. g4 h6 18. Kg6 Ke3 19. h5 Kf2 20. Sh3+ Kg3 21. Sf2 Kh4 22. Sh1 De8+
8zügiger Rundlauf des sSg8 zwecks Schachschutz auf d5.
8zügiger Rundlauf des sSg8 zwecks Schachschutz auf d5.
Keywords: Unique Proof Game, Pure Round Trip (s), Check Protection, Capture-free
Genre: Retro
Computer test: Computerprüfung: C+ Stevio 1.0 34 Sekunden. Keine Lösung: BP 21.0, BP 21.5.
FEN: 1nb1qbnr/1pppp1p1/3BrpKp/p1R2Q1P/2P2PPk/3P4/PP1NP3/R4B1N
Input: Gerd Wilts, 2004-03-13
Last update: A.Buchanan, 2023-03-13 more...
Genre: Retro
Computer test: Computerprüfung: C+ Stevio 1.0 34 Sekunden. Keine Lösung: BP 21.0, BP 21.5.
FEN: 1nb1qbnr/1pppp1p1/3BrpKp/p1R2Q1P/2P2PPk/3P4/PP1NP3/R4B1N
Input: Gerd Wilts, 2004-03-13
Last update: A.Buchanan, 2023-03-13 more...
a) 1. De4+ Kd6 2. Tf6+ Kc5 3. Tf5+ Kb6 4. Db4+ Ka6 5. Da4+ Kb6 6. Da7+ Kc6 7. Db7+ Kd6 8. Td5+ Ke6 9. Dd7+ Kf6 10. Tf5+ Kg6 11. De6+ Kg7,Kh7 12. Tf7+ Kh8 13. Df6+ Kg8 14. Tg7+ Kh8 15. Ta7+ Kg8 16. De6+ Kh8,Kf8 17. Dc8+ Dxc8#
Anzumerken ist, daß diese Lösung ab 3. - Kb6 4. Db4+ nach Brettdrehung identisch mit der Lösung des s#20 von Sheglow (Koni Gipanisa 1991)ist.
b) 1. Dd4+ Kc6! 2. Tf6+ Kc7 3. Dd6+ Kc8 4. Db8+ (trickreich, denn Schwarz darf die Dame nicht schlagen) Kd7 5. Td6+ Ke7 6. Dd8+ Kf7 7. Tf6+ Kg7 8. De7+ Kh8! 9. Th6+ Kg8 10. Tg6+ Kh8 11. Df6+ Kh7 12. Th6+ Kg8 13. Dh8+ Kf7 14. Tf6+ Ke7 15. Df8+ Kd7 16. Td6+ Kc7 17. Db8+ Dxb8#
Diese Mattführung ist neu.
Anzumerken ist, daß diese Lösung ab 3. - Kb6 4. Db4+ nach Brettdrehung identisch mit der Lösung des s#20 von Sheglow (Koni Gipanisa 1991)ist.
b) 1. Dd4+ Kc6! 2. Tf6+ Kc7 3. Dd6+ Kc8 4. Db8+ (trickreich, denn Schwarz darf die Dame nicht schlagen) Kd7 5. Td6+ Ke7 6. Dd8+ Kf7 7. Tf6+ Kg7 8. De7+ Kh8! 9. Th6+ Kg8 10. Tg6+ Kh8 11. Df6+ Kh7 12. Th6+ Kg8 13. Dh8+ Kf7 14. Tf6+ Ke7 15. Df8+ Kd7 16. Td6+ Kc7 17. Db8+ Dxb8#
Diese Mattführung ist neu.
Keywords: Langzügige Miniatur, Aristocrat, Minimal (d), Miniature
Genre: s#
FEN: K7/8/8/3k4/5R2/4Q3/8/2q5
Reprints: 56 Selbstmatt-Miniaturen Reflexmatt-Miniaturen 2003
Input: Selbstmatt-Miniaturen/Reflexmatt-Miniaturen, 2004-05-01
Last update: Gunter Jordan, 2023-01-27 more...
Genre: s#
FEN: K7/8/8/3k4/5R2/4Q3/8/2q5
Reprints: 56 Selbstmatt-Miniaturen Reflexmatt-Miniaturen 2003
Input: Selbstmatt-Miniaturen/Reflexmatt-Miniaturen, 2004-05-01
Last update: Gunter Jordan, 2023-01-27 more...
1. Se5! droht 2. Sf7 droht 3. Sxh6#
2. ... Lxd6 3. Sbxd6#
1. ... Txe5 2. Dd3+ Lxd3 3. Sd6#
2. ... Te4 3. Dxe4#
1. ... fxe5 2. Df8+ Sxf8 3. Sd6#
2. ... Sf6 3. Dxf6#
1. ... Lxe5 2. Dd5 droht 3. Sd6#
2. ... exd5 3. Lxd7#
1. ... Sxe5 2. Dxc5 droht 3. Sd6#
2. ... Td1 3. Le4#
Autor: Le thème Stocchi est associé à quatre sacrifices de dégagement de la Dame.
2. ... Lxd6 3. Sbxd6#
1. ... Txe5 2. Dd3+ Lxd3 3. Sd6#
2. ... Te4 3. Dxe4#
1. ... fxe5 2. Df8+ Sxf8 3. Sd6#
2. ... Sf6 3. Dxf6#
1. ... Lxe5 2. Dd5 droht 3. Sd6#
2. ... exd5 3. Lxd7#
1. ... Sxe5 2. Dxc5 droht 3. Sd6#
2. ... Td1 3. Le4#
Autor: Le thème Stocchi est associé à quatre sacrifices de dégagement de la Dame.
Keywords: Brian Stephenson Collection (7983)
Genre: 3#
Computer test: SCHRECKE (2023-06-18): C+, popeye 4.87
FEN: 3B4/1N1n4/n1BQppPp/2p2kpK/2N3Rp/6br/8/4rb2
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-06-18 more...
Genre: 3#
Computer test: SCHRECKE (2023-06-18): C+, popeye 4.87
FEN: 3B4/1N1n4/n1BQppPp/2p2kpK/2N3Rp/6br/8/4rb2
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-06-18 more...
18 - P1066732
Eric Pichouron
PCCC Meeting 09/2004
3. ehrende Erwähnung Champagne TT 2004
(12+14) C+
BP in 24,5
Eric Pichouron
PCCC Meeting 09/2004
3. ehrende Erwähnung Champagne TT 2004
(12+14) C+
BP in 24,5
1. e4 h5 2. Dg4 hxg4 3. Sc3 Th3 4. Sd5 Tc3 5. bxc3 Sc6 6. La3 Sd4 7. Ld6 cxd6 8. h4 Da5 9. h5 b6 10. h6 Lb7 11. h7 0-0-0 12. Th6 La8 13. Tf6 gxf6 14. Lc4 Lh6 15. d3 Lc1 16. Se2 La3 17. Kd2 Lb4 18. Th1 Da3 19. Th5 a5 20. Te5 fxe5 21. h8=D Sf6 22. Dh1 Th8 23. Dd1 Th3 24. Ke1 Tf3 25. gxf3
Richter MC: "A well oiled game using the 'standard Rook' to double the theme, displaying an additional Pronkin and switchback by Ke1."
Richter MC: "A well oiled game using the 'standard Rook' to double the theme, displaying an additional Pronkin and switchback by Ke1."
Henrik Juel: Natch 3.1 did little in half an hour (2018-12-19)
Moldenhauer: Computerprüfung: C+ Stelvio 1.2 02:04:15 Stunden. (hh:mm:ss)
Keine Lösung: BP 23.5, BP 24.0. (2023-05-11)
comment
Moldenhauer: Computerprüfung: C+ Stelvio 1.2 02:04:15 Stunden. (hh:mm:ss)
Keine Lösung: BP 23.5, BP 24.0. (2023-05-11)
comment
Keywords: Unique Proof Game, Pronkin Theme (D), Switchback, Impostor (Tt)
Genre: Retro
Computer test: Stelvio 1.2
FEN: b1k5/3ppp2/1p1p1n2/p2Np3/1bBnP1p1/q1PP1P2/P1P1NP2/3QK3
Reprints: H58 Phénix 02-03/2005
Input: Gerd Wilts, 2004-09-14
Last update: Silvio Baier, 2023-08-15 more...
Genre: Retro
Computer test: Stelvio 1.2
FEN: b1k5/3ppp2/1p1p1n2/p2Np3/1bBnP1p1/q1PP1P2/P1P1NP2/3QK3
Reprints: H58 Phénix 02-03/2005
Input: Gerd Wilts, 2004-09-14
Last update: Silvio Baier, 2023-08-15 more...
1. c4 Sf6 2. Db3 Se4 3. Db6 axb6 4. c5 Ta3 5. c6 bxc6 6. d4 La6 7. Lf4 Sd2 8. e4 Le2 9. Ld6 Td3 10. a4 cxd6 11. a5 bxa5 12. h4 Db6 13. h5 Db3 14. h6 gxh6 15. Th5 Lg7 16. Tb5 cxb5 17. d5 Ld4 18. Sh3 f6 19. Sf4 Kf7 20. Se6 Tc8 21. f4 Tc2 22. Sc5 dxc5
Keywords: Unique Proof Game
Genre: Retro
Computer test: KP: C+ Fully tested with Stelvio 1.0 (on two computers) in combined time of approximately 667 hours. Reto: And also with Stelvio 1.62 in about 5 hours.
FEN: 1n6/3ppk1p/5p1p/pppP4/3bPP2/1q1r4/1Prnb1P1/RN2KB2
Input: Gerd Wilts, 2004-09-30
Last update: Reto, 2023-09-11 more...
Genre: Retro
Computer test: KP: C+ Fully tested with Stelvio 1.0 (on two computers) in combined time of approximately 667 hours. Reto: And also with Stelvio 1.62 in about 5 hours.
FEN: 1n6/3ppk1p/5p1p/pppP4/3bPP2/1q1r4/1Prnb1P1/RN2KB2
Input: Gerd Wilts, 2004-09-30
Last update: Reto, 2023-09-11 more...
1. f3 c6 2. Kf2 Da5 3. Kg3 Dc3 4. dxc3 h5 5. Dd6 h4+ 6. Kg4 h3 7. Dc7 hxg2 8. Sh3 g1=D 9. Lg2 Db6 10. Dxc8+ Dd8 11. Dc7 Th5 12. Dg3 Db6 13. Td1 Dg1 14. Td6 Td5 15. Le3 g5 16. Sd2 Dxa1 17. Lc5 Dg1 18. La3 Db6 19. De1 Td4+ 20. cxd4 Dd8
Henrik Juel: d2xDc3xTd4 was too tricky for Natch 3.1, which did not find the solution in half an hour
Stopped at pos. 917 (2018-12-22)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 00:08:50 Minuten.
Keine Lösung: BP 19.0, BP 19.5. (2023-03-01)
more ...
comment
Stopped at pos. 917 (2018-12-22)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 00:08:50 Minuten.
Keine Lösung: BP 19.0, BP 19.5. (2023-03-01)
more ...
comment
Keywords: Unique Proof Game, Pronkin Theme (d), Promotion (d)
Genre: Retro
Computer test: Stelvio 1.0
FEN: rn1qkbn1/pp1ppp2/2pR4/6p1/3P2K1/B4P1N/PPPNP1BP/4Q3
Reprints: (6) StrateGems 10-12/2007
Input: Gerd Wilts, 2006-01-22
Last update: Silvio Baier, 2023-03-02 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: rn1qkbn1/pp1ppp2/2pR4/6p1/3P2K1/B4P1N/PPPNP1BP/4Q3
Reprints: (6) StrateGems 10-12/2007
Input: Gerd Wilts, 2006-01-22
Last update: Silvio Baier, 2023-03-02 more...
21 - P1068230
Philippe Leroy
4922 Phénix 142 07-08/2005
Pascal Wassong gewidmet
(13+16) C+
BP in 25,5
Philippe Leroy
4922 Phénix 142 07-08/2005
Pascal Wassong gewidmet
(13+16) C+
BP in 25,5
1. e3 h5 2. Lb5 Sh6 3. Lc6 dxc6 4. a4 Dd3 5. Ta3 Dh7 6. Td3 Lg4 7. Td6 f5 8. Tf6 exf6 9. e4 Lb4 10. e5 0-0 11. e6 Td8 12. e7 Td3 13. e8=L Tc3 14. d4 b5 15. d5 bxa4 16. d6 a3 17. d7 a2 18. d8=T a1=D 19. Td7 Da6 20. Tf7 Dd3 21. Ld7 a5 22. Le6 Sa6 23. La2 Td8 24. Te7+ Td5 25. Te6 Tdc5 26. Te8#
Henrik Juel: Natch 3.1 did little in more than an hour
Stopped at position 1 (2018-12-22)
Moldenhauer: Computerprüfung: C+ Stevio 1.0 7:08:52 Stunden.
Keine Lösung: BP 24.5, BP 25.0. (2023-02-14)
more ...
comment
Stopped at position 1 (2018-12-22)
Moldenhauer: Computerprüfung: C+ Stevio 1.0 7:08:52 Stunden.
Keine Lösung: BP 24.5, BP 25.0. (2023-02-14)
more ...
comment
Keywords: Unique Proof Game, Non-standard material (d), Promotion (LTd), Phoenix (TL)
Genre: Retro
Computer test: Stelvio 2.0 in 12min
FEN: 4R1k1/2p3pq/n1p2p1n/p1r2p1p/1b4b1/2rq4/BPP2PPP/1NBQK1NR
Input: Gerd Wilts, 2006-01-22
Last update: Reto, 2023-12-19 more...
Genre: Retro
Computer test: Stelvio 2.0 in 12min
FEN: 4R1k1/2p3pq/n1p2p1n/p1r2p1p/1b4b1/2rq4/BPP2PPP/1NBQK1NR
Input: Gerd Wilts, 2006-01-22
Last update: Reto, 2023-12-19 more...
22 - P1068639
Roberto Osorio
Jorge Joaquin Lois
1961 Orbit 32 10/2006
Nicolas Dupont gewidmet
3rd Prize
(15+13) C+
BP in 20,0
Roberto Osorio
Jorge Joaquin Lois
1961 Orbit 32 10/2006
Nicolas Dupont gewidmet
3rd Prize
(15+13) C+
BP in 20,0
1. Sc3 Sc6 2. Sd5 Tb8 3. Sxe7 Kxe7 4. a4 Kf6 5. a5 Kg6 6. a6 Dh4 7. axb7 Sf6 8. bxc8=S Tb3 9. h3 Lb4 10. Sd6 Te8 11. Sf5 Tee3 12. Sg3 Se5 13. f4 Tf3 14. e4 Tf2 15. S1e2 Tbf3 16. Sc3 c6 17. d3 Td2 18. Sb1 Tff2 19. Se2 Kh5 20. Sg1+ Tfe2#
Henrik Juel: Sb1 is actually [Sg1], and Sg1 is [Pa2] promoted on c8.
Testing with Euclide ran out of time. (2011-02-27)
paul: The first 19 moves checked by Euclide in half a day. (2020-12-02)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 01:04:22 Stunde. (hh:mm:ss)
Keine Lösung: BP 19.0, BP 19.5. (2023-03-02)
more ...
comment
Testing with Euclide ran out of time. (2011-02-27)
paul: The first 19 moves checked by Euclide in half a day. (2020-12-02)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 01:04:22 Stunde. (hh:mm:ss)
Keine Lösung: BP 19.0, BP 19.5. (2023-03-02)
more ...
comment
Keywords: Unique Proof Game, Interchange
Genre: Retro
Computer test: Stelvio 1.0
FEN: 8/p2p1ppp/2p2n2/4n2k/1b2PP1q/3P3P/1PPrr1P1/RNBQKBNR
Reprints: H30 Vkontakte 2013
H30 Phénix 261/262, p. 10353, 05-06/2016
Input: Gerd Wilts, 2006-12-05
Last update: Silvio Baier, 2023-03-03 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: 8/p2p1ppp/2p2n2/4n2k/1b2PP1q/3P3P/1PPrr1P1/RNBQKBNR
Reprints: H30 Vkontakte 2013
H30 Phénix 261/262, p. 10353, 05-06/2016
Input: Gerd Wilts, 2006-12-05
Last update: Silvio Baier, 2023-03-03 more...
1. e3 h5 2. Ld3 Th6 3. Lh7 e5 4. d3 Dh4 5. Ld2 g5 6. La5 Lb4+ 7. Sc3 c5 8. Lc7 a5 9. g3 Taa6 10. f3 Tab6 11. Kf2 Sa6 12. Sd5 Ld2 13. Se7 d5 14. Sh3 Lxh3 15. c3 Lf5 16. h3 Lg6 17. Th2 f5 18. Da4+ Kf7 19. Dc6 Tb3 20. axb3 Db4 21. Ta4 Da3 22. bxa3 b5
Henrik Juel: Natch 3.1 did little in more than half an hour
Stopped at pos. 15 (2018-12-22)
Moldenhauer: Computerprüfung: Stelvio 1.0 20:35:18 Stunden. (hh:mm:ss)
Keine Lösung: BP 21.0, BP 21.5.
Notation: 1.e3 h5 2.Ld3 Th6 3.Lh7 e5 4. d3 Dh4 5.Ld2 g5 6.La5 Lb4+
7.Sc3 c5 8.Lc7 a5 9.g3 Taa6 10.f3 Tab6 11.Kf2 Sa6 12.Sd5 Ld2
13.Se7 d5 14.Sh3 Lxh3 15.c3 Lf5 16.h3 Lg6 17.Th2 f5
18.Da4+ Kf7 19.Dc6 Tb3 20.axb3 Db4 21.Ta4 Da3 22.bxa3 b5 (2023-03-10)
comment
Stopped at pos. 15 (2018-12-22)
Moldenhauer: Computerprüfung: Stelvio 1.0 20:35:18 Stunden. (hh:mm:ss)
Keine Lösung: BP 21.0, BP 21.5.
Notation: 1.e3 h5 2.Ld3 Th6 3.Lh7 e5 4. d3 Dh4 5.Ld2 g5 6.La5 Lb4+
7.Sc3 c5 8.Lc7 a5 9.g3 Taa6 10.f3 Tab6 11.Kf2 Sa6 12.Sd5 Ld2
13.Se7 d5 14.Sh3 Lxh3 15.c3 Lf5 16.h3 Lg6 17.Th2 f5
18.Da4+ Kf7 19.Dc6 Tb3 20.axb3 Db4 21.Ta4 Da3 22.bxa3 b5 (2023-03-10)
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Stelvio 1.0
FEN: 6n1/2B1Nk1B/n1Q3br/pppppppp/R7/PPPPPPPP/3b1K1R/8
Reprints: H35 Vkontakte 2013
H35 Phénix 261/262, p. 10354, 05-06/2016
Input: Gerd Wilts, 2007-01-02
Last update: Silvio Baier, 2023-03-20 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: 6n1/2B1Nk1B/n1Q3br/pppppppp/R7/PPPPPPPP/3b1K1R/8
Reprints: H35 Vkontakte 2013
H35 Phénix 261/262, p. 10354, 05-06/2016
Input: Gerd Wilts, 2007-01-02
Last update: Silvio Baier, 2023-03-20 more...
1. h4 c5 2. h5 c4 3. Th4 c3 4. Tc4 a6 5. Txc8 Sc6 6. Txa8 Db8 7. Ta7 Dg3 8. fxg3 d5 9. Kf2 d4 10. Kf3 d3 11. Kg4 dxc2 12. Kh4 cxb1=L 13. Db3 e5 14. Db6 e4 15. b3 e3 16. Lb2 exd2 17. e3 Lf5 18. Ld3 d1=T 19. Lc2 Td8 20. Td1 Ta8 21. La1 Lc8 22. Td7 Sb8
Ersatz der beiden auf ihren Ursprungsfeldern geschlagenen sTa8 und sLc8 durch Pronkin-Figuren.
Ersatz der beiden auf ihren Ursprungsfeldern geschlagenen sTa8 und sLc8 durch Pronkin-Figuren.
Reto: The 21.5 move paths leading to this position are known to me and they are not cooks in my eyes, as move parity is part of the position to find. Anyone who likes can think "exact spg" or similar if that helps them. (2023-03-13)
A.Buchanan: A number of different opinions exist. To me:
(1) a shorter PG, unique or not, does not cook a PG in x.y.
(2) This is true whether the delta is z.0 or z.5 moves.
(3) A composer may choose to include "exactly" in the stipulation, but if they choose not to then the composer's stipulation "Originalforderung" may not be fiddled with by later generations.
(4) However, there may be a "database stipulation" added by curators for uniformity within a catalogue, and if the database stipulation does not match the Originalforderung, then the Originalforderung must appear in an Originalforderung field, not just as a comment. [PDB does not support this feature.]
(5) Accidental shorter solutions do constitute a defect, in my view.
Again to say: this is just my personal opinion :) (2023-03-14)
more ...
comment
A.Buchanan: A number of different opinions exist. To me:
(1) a shorter PG, unique or not, does not cook a PG in x.y.
(2) This is true whether the delta is z.0 or z.5 moves.
(3) A composer may choose to include "exactly" in the stipulation, but if they choose not to then the composer's stipulation "Originalforderung" may not be fiddled with by later generations.
(4) However, there may be a "database stipulation" added by curators for uniformity within a catalogue, and if the database stipulation does not match the Originalforderung, then the Originalforderung must appear in an Originalforderung field, not just as a comment. [PDB does not support this feature.]
(5) Accidental shorter solutions do constitute a defect, in my view.
Again to say: this is just my personal opinion :) (2023-03-14)
more ...
comment
Keywords: Unique Proof Game, Pronkin Theme (tl)
Genre: Retro
Computer test: Solving time: Natch 3.3: >10h, Euclide 1.11: >10h, Stelvio 1.15: 33:30min
FEN: rnb1kbnr/Rp1R1ppp/pQ6/7P/7K/1Pp1P1P1/P1B3P1/B5N1
Reprints: H34 Vkontakte 2013
H34 Phénix 261/262, p. 10354, 2013
Input: Gerd Wilts, 2009-01-06
Last update: Reto, 2023-03-30 more...
Genre: Retro
Computer test: Solving time: Natch 3.3: >10h, Euclide 1.11: >10h, Stelvio 1.15: 33:30min
FEN: rnb1kbnr/Rp1R1ppp/pQ6/7P/7K/1Pp1P1P1/P1B3P1/B5N1
Reprints: H34 Vkontakte 2013
H34 Phénix 261/262, p. 10354, 2013
Input: Gerd Wilts, 2009-01-06
Last update: Reto, 2023-03-30 more...
* 1. ... Lb7 2. Dc6 Lxc6#
1. Sb8! Lb7 2. Sd7 Lc6 3. Sf8 Lb7 4. Dc6 Kb8 5. Se6 Ka8 6. Sc7+ Kb8 7. Sa6+ Ka8 8. Ta1 Lxc6#
Frank Müller: läßt sich mit wDf3 und sLe4 um zwei Züge erweitern
1. Sb8! Lb7 2. Sd7 Lc6 3. Sf8 Lb7 4. Dc6 Kb8 5. Se6 Ka8 6. Sc7+ Kb8 7. Sa6+ Ka8 8. Ta1 Lxc6#
Frank Müller: läßt sich mit wDf3 und sLe4 um zwei Züge erweitern
Hier liegt Keine Vorgängerschaft vor, denn es wird ein interessanter 6-zügiger Rundlauf des wS gezeigt!
paul: Anticipated by P1186964 (Schildberg) (2022-09-14)
Jacques Rotenberg: not at all anticipated !!
the solution is completely different (2022-12-04)
Jacques Rotenberg: the P1186964 itself is anticipated! (2022-12-04)
Jacques Rotenberg: about P1186964 see P1186601 (2022-12-04)
Iwan Soroka: @paul. P1186964 is kein Vorgänger zu P1090925. Was genau ist anticipated? (2022-12-04)
more ...
comment
paul: Anticipated by P1186964 (Schildberg) (2022-09-14)
Jacques Rotenberg: not at all anticipated !!
the solution is completely different (2022-12-04)
Jacques Rotenberg: the P1186964 itself is anticipated! (2022-12-04)
Jacques Rotenberg: about P1186964 see P1186601 (2022-12-04)
Iwan Soroka: @paul. P1186964 is kein Vorgänger zu P1090925. Was genau ist anticipated? (2022-12-04)
more ...
comment
Keywords: Minimal (l), Corner mate, Model mate, Switchback (Skl), Tempo Loss, Round Trip (S-6)
Genre: s#
Computer test: I. Soroka: Gustav 3.2 d
FEN: k7/8/N1b5/3Q4/8/8/7P/1R4BK
Input: Frank Müller, 2009-09-09
Last update: Gunter Jordan, 2022-12-05 more...
Genre: s#
Computer test: I. Soroka: Gustav 3.2 d
FEN: k7/8/N1b5/3Q4/8/8/7P/1R4BK
Input: Frank Müller, 2009-09-09
Last update: Gunter Jordan, 2022-12-05 more...
1. h8=L+ Kf8 2. d8=T+ Ke7 3. f8=D+ Ke6 4. Te8+ Kd7 5. De7+ Kc6 6. b8=S+ Kb6+ 7. Db7+ Lxb7#
Erich Bartel: Nachdrucke:
1) Phenix (RM) V 1994,S.2451
2) 79 Das Matt des weißen Königs 1995
3) Problem Paradise II 1997,S.39
4) feenschach (146) III-I 2002 (2009-09-14)
paul: The source is Phenix 10/1990 (2022-09-13)
comment
1) Phenix (RM) V 1994,S.2451
2) 79 Das Matt des weißen Königs 1995
3) Problem Paradise II 1997,S.39
4) feenschach (146) III-I 2002 (2009-09-14)
paul: The source is Phenix 10/1990 (2022-09-13)
comment
Keywords: Allumwandlung (LTDS), konsekutive Umwandlungen 4 (LTDS)
Genre: s#
FEN: K7/1P1P1PkP/8/7Q/8/8/8/7b
Input: Frank Müller, 2009-09-13
Last update: Olaf Jenkner, 2010-12-12 more...
Genre: s#
FEN: K7/1P1P1PkP/8/7Q/8/8/8/7b
Input: Frank Müller, 2009-09-13
Last update: Olaf Jenkner, 2010-12-12 more...
1. Lb6 bxc6 2. Lc5 cxd5 3. Ld4 dxe4 4. Le3 exf3 5. Lf2 fxg2#
Keywords: Alleinunterhalter, Pac-Man, Round Trip (L)
Genre: s#
FEN: 8/1p6/2P5/3P4/4P2p/5P1k/5BRp/7K
Input: Frank Müller, 2009-10-03
Last update: Frank Müller, 2009-10-03 more...
Genre: s#
FEN: 8/1p6/2P5/3P4/4P2p/5P1k/5BRp/7K
Input: Frank Müller, 2009-10-03
Last update: Frank Müller, 2009-10-03 more...
1. Dd4+ Kd6 2. Dxd5+ Ke7 3. Dxg5+ Kd6 4. Dxd8+ Kc5 5. Dd5+ Kxb6 6. Dc6+ Ka7 7. Da8+ Kb6 8. Dxa6+ Kc5 9. Le7+ Kxc4 10. Txc3+ Kxc3 11. Lf6+ Kc4 12. Le6+ Kc5 13. Sxd3+ Lxd3#
4. ... Ke5 5. De8+ Kd6 6. Sc8+ Kc5 7. Le7+ wird s#11
4. ... Ke5 5. De8+ Kd6 6. Sc8+ Kc5 7. Le7+ wird s#11
Genre: s#
FEN: 3n2R1/2p5/nN4P1/bpkp2p1/1NP3QB/PprpPP1B/2R4r/2K2b1q
Input: Frank Müller, 2009-10-13
Last update: Marcin Banaszek, 2020-11-24 more...
1. Lg6 droht 2. Te6+ Kxe6 3. gxf5+ Ke5 4. f6+ Ke6 5. Dg4+ Lxg4#
1. Lg6 Lxd6 2. De4+ Kxe4 3. Lxf5+ Ke5 4. Lxc2+ Ke6 5. Lb3+ Lxb3#
1. Lg6 e2 2. Dxb5+ Sxb5 3. Txf5+ Ke4 4. Tf2+ Ke5 5. Txe2+ Lxe2#
1. Lg6 Lxd6 2. De4+ Kxe4 3. Lxf5+ Ke5 4. Lxc2+ Ke6 5. Lb3+ Lxb3#
1. Lg6 e2 2. Dxb5+ Sxb5 3. Txf5+ Ke4 4. Tf2+ Ke5 5. Txe2+ Lxe2#
Keywords: Batterie Typ Siers, Kraftopfer, x pieces capture on one square (w)
Genre: s#
Computer test: A. Baumann: Gustav 4.2a
FEN: 1b3B2/n4Bp1/1N1R4/1p2kpRN/1Q4P1/2P1p1p1/2pP2P1/2rb3K
Input: Frank Müller, 2009-10-14
Last update: Dieter Berlin, 2023-12-07 more...
Genre: s#
Computer test: A. Baumann: Gustav 4.2a
FEN: 1b3B2/n4Bp1/1N1R4/1p2kpRN/1Q4P1/2P1p1p1/2pP2P1/2rb3K
Input: Frank Müller, 2009-10-14
Last update: Dieter Berlin, 2023-12-07 more...
1. Le6? droht 2. Tdd4+ Kc6 3. Ld5+ Kd7 4. Lxb3+ Kc6 5. Lxa4+ Lxa4#
1. Le6? Tc2 2. Td8+ Kc6 3. Ld7+ Kd5 4. Lg4+ Kc6 5. Lxf3+ Lxf3#
aber 1. Le6 Ta1!
1. Sh6! droht 2. Tdb6+ Kd5 3. Lc6+ Ke6 4. Lxa4+ Kd5 5. Lxb3+ Lxb3#
1. Sh6! Tc2 2. Tf6+ Kd5 3. Le6+ Kc6 4. Lg4+ Kd5 5. Lxf3+ Lxf3#
1. Le6? Tc2 2. Td8+ Kc6 3. Ld7+ Kd5 4. Lg4+ Kc6 5. Lxf3+ Lxf3#
aber 1. Le6 Ta1!
1. Sh6! droht 2. Tdb6+ Kd5 3. Lc6+ Ke6 4. Lxa4+ Kd5 5. Lxb3+ Lxb3#
1. Sh6! Tc2 2. Tf6+ Kd5 3. Le6+ Kc6 4. Lg4+ Kd5 5. Lxf3+ Lxf3#
Keywords: Battery play
Genre: s#
Computer test: A. Baumann: Gustav 4.2a
FEN: N4BN1/1P1B1P1p/P2R4/2k5/pR3P2/1pPppp2/1p2rp2/1r1b1K2
Input: Frank Müller, 2009-10-16
Last update: Dieter Berlin, 2023-12-15 more...
Genre: s#
Computer test: A. Baumann: Gustav 4.2a
FEN: N4BN1/1P1B1P1p/P2R4/2k5/pR3P2/1pPppp2/1p2rp2/1r1b1K2
Input: Frank Müller, 2009-10-16
Last update: Dieter Berlin, 2023-12-15 more...
1. Ld6! droht 2. Sd5+ cxd5 3. Te4+ Kf5+ 4. Tf4+ Lxf4#
1. ... Te3 2. S7e6+ dxe6 3. Tf5+ Kxf5 4. Dxe6+ Txe6#
1. ... Se3 2. Te6+ Kf5 3. Tf6+ Kxf6 4. Txf3+ Sf5#
1. ... Te3 2. S7e6+ dxe6 3. Tf5+ Kxf5 4. Dxe6+ Txe6#
1. ... Se3 2. Te6+ Kf5 3. Tf6+ Kxf6 4. Txf3+ Sf5#
Keywords: Battery play, Batterietransformation (s), Batterieumbau, s Abzugsstein, half-battery, black
Genre: s#
FEN: 8/p1NpB1PP/r1p4K/p1N1R2B/2QP1k2/2r2p1R/1p2P3/2bn4
Input: Frank Müller, 2009-10-16
Last update: Marcin Banaszek, 2022-03-25 more...
Genre: s#
FEN: 8/p1NpB1PP/r1p4K/p1N1R2B/2QP1k2/2r2p1R/1p2P3/2bn4
Input: Frank Müller, 2009-10-16
Last update: Marcin Banaszek, 2022-03-25 more...
1. Sc2+ Kb1 2. Sd2+ Kc1 3. Se4+ Kb1 4. Sa3+ Ka1 5. Lg2 Lxg2 6. Tf1+ Lxf1#
Genre: s#
Computer test: Gustav 4.1d, Brute Force
FEN: 8/8/8/8/1NNP4/2QKBB2/pr3R2/k6b
Input: Frank Müller, 2009-10-18
Last update: Marcin Banaszek, 2020-12-31 more...
1. Sc7! Kd8 2. g8=T+ Kxc7 3. Lg3+ Td6 4. Tc8+ Kb6 5. Lf2+ Ka6 6. Tc6+ Txc6 7. Dc8+ Txc8#
1. ... Kxc7 2. La5+ Kc8 3. De8+ Td8 4. g8=D Txe8 5. Dg4+ Te6 6. Dc4+ Tc6 7. Da6+ Txa6#
1. ... Kxc7 2. La5+ Kc8 3. De8+ Td8 4. g8=D Txe8 5. Dg4+ Te6 6. Dc4+ Tc6 7. Da6+ Txa6#
Keywords: Exchange of Promotions
Genre: s#
Computer test: Gustav 4.1d, Brute Force
FEN: K1k5/3r2P1/N3Q3/3R4/8/8/8/4B3
Input: Frank Müller, 2009-10-24
Last update: Marcin Banaszek, 2020-10-05 more...
Genre: s#
Computer test: Gustav 4.1d, Brute Force
FEN: K1k5/3r2P1/N3Q3/3R4/8/8/8/4B3
Input: Frank Müller, 2009-10-24
Last update: Marcin Banaszek, 2020-10-05 more...
1. Da7+ Kc8 2. Dd7+ Kb8 3. De8+ Ka7,b7,c7 4. Td7+ Kb6 5. Db8+ Kc5 6. Dd6+ Kb6 7. Dd4+ c5 8. Df6+ Le6 9. Dd8+ Kc6 10. Dc8+ Kb6 11. Db8+ Kc6 12. Db5+ axb5#
Genre: s#
FEN: 8/2k5/p1p5/3R4/K1b5/4Q3/8/1n2b3
Input: Frank Müller, 2009-10-25
Last update: Marcin Banaszek, 2020-12-21 more...
1. Th7+ Kg8 2. Kh6+ Kf8 3. Sd7+ Ke8 4. Lh5+ Kd8 5. Da5+ Kc8 6. Tg8+ Kb7 7. Sxf6+ Kc6 8. Da4+ Kd6 9. Dd7+ Ke5 10. Te8+ Kxf6 11. Lg5+ Lxg5#
Moldenhauer: Computerprüfung: C+ Gustav 4.1d in 51 Tagen 21 Std. 33 Min.
Keine Nebenlösungen! (2022-10-04)
Henrik Juel: An interesting comparison:
Popeye 4.61 with 'opt non 0 1 thr 0' found no flaws in 0.2 seconds (2022-10-04)
comment
Keine Nebenlösungen! (2022-10-04)
Henrik Juel: An interesting comparison:
Popeye 4.61 with 'opt non 0 1 thr 0' found no flaws in 0.2 seconds (2022-10-04)
comment
Keywords: Königslenkung
Genre: s#
FEN: 1N5k/6R1/p4pK1/3p4/8/4B3/4B3/2b1Q1R1
Input: Frank Müller, 2009-10-25
Last update: Marcin Banaszek, 2022-10-08 more...
Genre: s#
FEN: 1N5k/6R1/p4pK1/3p4/8/4B3/4B3/2b1Q1R1
Input: Frank Müller, 2009-10-25
Last update: Marcin Banaszek, 2022-10-08 more...
a) 1. Lb3 h2 2. Ka2 h3 3. La3 a6 4. Sc4 a5 5. Sd2 a4 6. Sb1 axb3#
b) 1. Dxd7+ Kf6 2. Tc6+ Ld6 3. Sf2 h3 4. Sxh3 a6 5. Sc4 a5 6. Sb2 axb4#, 3. ... a6 4. Sc4 a5 5. Sb2 h3 6. Sxh3 axb4#
b) 1. Dxd7+ Kf6 2. Tc6+ Ld6 3. Sf2 h3 4. Sxh3 a6 5. Sc4 a5 6. Sb2 axb4#, 3. ... a6 4. Sc4 a5 5. Sb2 h3 6. Sxh3 axb4#
Keywords: Chameleon Echo
Genre: s#
FEN: 5R2/p3Qb2/7P/N1R1bk1P/BB3P1p/K3PP1p/8/7N
Input: Frank Müller, 2009-10-31
Last update: Marcin Banaszek, 2020-12-09 more...
Genre: s#
FEN: 5R2/p3Qb2/7P/N1R1bk1P/BB3P1p/K3PP1p/8/7N
Input: Frank Müller, 2009-10-31
Last update: Marcin Banaszek, 2020-12-09 more...
1. h4 g5 2. hxg5 c5 3. Th6 c4 4. Tb6 axb6 5. Sc3 Ta3 6. Sb5 Te3 7. fxe3 c3 8.
dxc3 h5 9. Dd5 Th6 10. Ld2 Tf6 11. 0-0-0 Txf1 12. Le1 Tf4 13. Df3 f5 14. Td6 Td4
15. Tf6 exf6 16. Sa3 De7 17. Sb1 Da3 18. Ld2 Da8 19. a4 La3 20. Kd1 d6 21. Ke1
Kd7 22. Lc1
dxc3 h5 9. Dd5 Th6 10. Ld2 Tf6 11. 0-0-0 Txf1 12. Le1 Tf4 13. Df3 f5 14. Td6 Td4
15. Tf6 exf6 16. Sa3 De7 17. Sb1 Da3 18. Ld2 Da8 19. a4 La3 20. Kd1 d6 21. Ke1
Kd7 22. Lc1
Henrik Juel: Natch 3.1 did little in half an hour
Stopped at pos. 1 (2018-12-27)
paul: 1.h4 g5 2.hxg5 c5 3.Rh6 c4 4.Rb6 axb6 5.Sc3 Ra3 6.Sb5 Re3 7.fxe3 c3 8.dxc3 h5 9.Qd5 Rh6 10.Bd2 Rf6 11.O-O-O Rxf1 12.Be1 Rf4 13.Qf3 f5 14.Rd6 Rd4 15.Rf6 exf6 16.Sa3 Qe7 17.Sb1 Qa3 18.Bd2 Qa8 19.a4 Ba3 20.Kd1 d6 21.Ke1 Kd7 22.Bc1. Hidden white castling. (2020-12-01)
Moldenhauer: Computerprüfung: C+ Stelvio 1.11 00:25:05 Minuten. (hh:mm:ss)
Keine Lösung: BP 20.5, BP 21.0. (2023-03-12)
comment
Stopped at pos. 1 (2018-12-27)
paul: 1.h4 g5 2.hxg5 c5 3.Rh6 c4 4.Rb6 axb6 5.Sc3 Ra3 6.Sb5 Re3 7.fxe3 c3 8.dxc3 h5 9.Qd5 Rh6 10.Bd2 Rf6 11.O-O-O Rxf1 12.Be1 Rf4 13.Qf3 f5 14.Rd6 Rd4 15.Rf6 exf6 16.Sa3 Qe7 17.Sb1 Qa3 18.Bd2 Qa8 19.a4 Ba3 20.Kd1 d6 21.Ke1 Kd7 22.Bc1. Hidden white castling. (2020-12-01)
Moldenhauer: Computerprüfung: C+ Stelvio 1.11 00:25:05 Minuten. (hh:mm:ss)
Keine Lösung: BP 20.5, BP 21.0. (2023-03-12)
comment
Keywords: Unique Proof Game, Castling Paradox (wk hidden)
Genre: Retro
Computer test: Stelvio 1.11
FEN: qnb3n1/1p1k4/1p1p1p2/5pPp/P2r4/b1P1PQ2/1PP1P1P1/1NB1K1N1
Input: Gerd Wilts, 2010-01-31
Last update: Silvio Baier, 2023-03-20 more...
Genre: Retro
Computer test: Stelvio 1.11
FEN: qnb3n1/1p1k4/1p1p1p2/5pPp/P2r4/b1P1PQ2/1PP1P1P1/1NB1K1N1
Input: Gerd Wilts, 2010-01-31
Last update: Silvio Baier, 2023-03-20 more...
1) 1. Sb6 Tc8+ 2. Ka7 Tb8 3. Sa8 Tb7#
2) 1. Sa7 Ld7 2. Ka8 Lc8 3. Sb8 Lb7#
2) 1. Sa7 Ld7 2. Ka8 Lc8 3. Sb8 Lb7#
Yuri Bilokin: the idea is not new P1005163 (2022-08-06)
Jean Marc Loustau: ***
The matrix and the mates are indeed the same; but in this problem (P1100532) there is one more significant feature which is, in fact the main idea (which is not on the P1005163):
The 2 white thematic pieces can already play on the mate square in the diagram position: thus we have a kind of "peri-white Grimwhaw" (a 3 moves manoeuvre to reach the mate square which was already reachable).
Of course I did no know the P1005163 when I have composed this one... I would say "fortunately", because if I had knew it, probably I would not have worked on this matrix: my final result, in my opinion, is interesting enough with its new feature to deserve the publication. (2022-08-14)
Yuri Bilokin: you can see 1...Bd5 2.Sa7 Rc6 3.Ka8 Rc8#
1...Be4 2.Sa7 Rc6 3.Ka8 Rc8#
1...Bf3 2.Sa7 Rc6 3.Ka8 Rc8#
1...Bg2 2.Sa7 Rc6 3.Ka8 Rc8# (2024-03-18)
comment
Jean Marc Loustau: ***
The matrix and the mates are indeed the same; but in this problem (P1100532) there is one more significant feature which is, in fact the main idea (which is not on the P1005163):
The 2 white thematic pieces can already play on the mate square in the diagram position: thus we have a kind of "peri-white Grimwhaw" (a 3 moves manoeuvre to reach the mate square which was already reachable).
Of course I did no know the P1005163 when I have composed this one... I would say "fortunately", because if I had knew it, probably I would not have worked on this matrix: my final result, in my opinion, is interesting enough with its new feature to deserve the publication. (2022-08-14)
Yuri Bilokin: you can see 1...Bd5 2.Sa7 Rc6 3.Ka8 Rc8#
1...Be4 2.Sa7 Rc6 3.Ka8 Rc8#
1...Bf3 2.Sa7 Rc6 3.Ka8 Rc8#
1...Bg2 2.Sa7 Rc6 3.Ka8 Rc8# (2024-03-18)
comment
Genre: h#
Computer test: Popeye Windows-32Bit v4.51 (100000 KB)
FEN: 1kn5/2R5/n1B5/8/8/3K4/8/8
Input: hpr, 2010-02-13
Last update: hpr, 2010-02-13 more...
1. h4 2. h5 3. h6 4. h7 5. h8=D 6. Dg8 7. Db3 8. g8=L 9. Lc4 10. d5 11. d6 12. d7 13. d8=T 14. Td2 15. Tc2 16. Ld2 17. f4 18. f5 19. f6 20. f7 21. f8=S 22. Se6
23. Sd4 exd4#
23. Sd4 exd4#
Keywords: Ideal mate, Minimal, Seriesmover
Genre: Fairies
Computer test: Alybadix-2002
FEN: 8/6P1/8/4p3/1R1PkB2/2K5/1P3P1P/8
Input: YM, 2010-03-28
Last update: Frank Müller, 2010-06-17 more...
Genre: Fairies
Computer test: Alybadix-2002
FEN: 8/6P1/8/4p3/1R1PkB2/2K5/1P3P1P/8
Input: YM, 2010-03-28
Last update: Frank Müller, 2010-06-17 more...
40 - P1102159
Yaakov Mintz
5924 Phénix 04/2009
(5+2) C+
s#11
b) Dh2 nach a7
c) ferner wKb6 nach a3
d) ferner wDa7 nach a5
Yaakov Mintz
5924 Phénix 04/2009
(5+2) C+
s#11
b) Dh2 nach a7
c) ferner wKb6 nach a3
d) ferner wDa7 nach a5
a) 1. e8=T+! Kd7 2. c8=D+ Kd6 3. Ka5 Kd5 4. Dd2+ Td4 5. Sc3+ Kd6 6. Sb5+ Kd5 7. De6+ Kc5 8. Dc3+ Tc4 9. Td8 Txc3 10. Db6+ Kc4 11. Sa3+ Txa3#
b) 1. Db8+! Kd7 2. e8=D+ Kd6 3. c8=D+ Kd5 4. Dcd7+ Kc4 5. Dee6+ Kb4 6. Ka6+ Ka3 7. Dd3+ Kxa4 8. Dbe8+ Kb4 9. Deb3+ Kc5 10. De7+ Kc6 11. Da4+ Txa4#
c) 1. e8=T+! Kd7 2. c8=D+ Kd6 3. Dab8+ Kd5 4. Te5+ Kd4 5. Db2+ Kd3 6. Sc5+ Kc4 7. Se6+ Kd3 8. Da6+ Tc4 9. De2+ Kc3 10. Tc5 Txc5 11. Da5+ Txa5#
d) 1. e8=D! Kb7 2. c8=L+ Kb8 3. La6+ Ka7 4. Dc7+ Kxa6 5. De2+ Tc4 6. Sc5+ Kb5 7. Dd6 Ka5 8. Sb7+ Kb5 9. Dee5+ Tc5 10. Db2+ Kc4 11. Sa5+ Txa5#
b) 1. Db8+! Kd7 2. e8=D+ Kd6 3. c8=D+ Kd5 4. Dcd7+ Kc4 5. Dee6+ Kb4 6. Ka6+ Ka3 7. Dd3+ Kxa4 8. Dbe8+ Kb4 9. Deb3+ Kc5 10. De7+ Kc6 11. Da4+ Txa4#
c) 1. e8=T+! Kd7 2. c8=D+ Kd6 3. Dab8+ Kd5 4. Te5+ Kd4 5. Db2+ Kd3 6. Sc5+ Kc4 7. Se6+ Kd3 8. Da6+ Tc4 9. De2+ Kc3 10. Tc5 Txc5 11. Da5+ Txa5#
d) 1. e8=D! Kb7 2. c8=L+ Kb8 3. La6+ Ka7 4. Dc7+ Kxa6 5. De2+ Tc4 6. Sc5+ Kb5 7. Dd6 Ka5 8. Sb7+ Kb5 9. Dee5+ Tc5 10. Db2+ Kc4 11. Sa5+ Txa5#
41 - P1110024
Manfred Rittirsch
6978 Die Schwalbe 123 06/1990
E. Bartel zum 60. Geburtstag gewidmet
(7+5) C+
h=3
Circe
b) sTa8 nach h7
Manfred Rittirsch
6978 Die Schwalbe 123 06/1990
E. Bartel zum 60. Geburtstag gewidmet
(7+5) C+
h=3
Circe
b) sTa8 nach h7
a) 1. g1=L c8=S 2. Lh2 Sa7 3. Lb8 Txc2[+sBc7]=
b) 1. c1=D c8=T 2. Dc3 Tg8 3. Dh8 Tfxg2[+sBg7]=
AUW mit circespezifischer Einkerkerung der schwarzen Umwandlungsfiguren. Ganz toll gemacht und ganz herzlichen Dank für dieses Schmuckstück in meiner Widmungsgalerie!! (EB). Zwei Mausefallen, in denen sich die "Allumgewandelten" ein Stelldichein geben! Alles passt millimetergenau zusammen (MS). Starke Circe-AUW mit viel Strategie und Spiel aufgepäppelt, ob sich EB was abguckt? - und auf h=Circe umsteigt? (TLi).
b) 1. c1=D c8=T 2. Dc3 Tg8 3. Dh8 Tfxg2[+sBg7]=
AUW mit circespezifischer Einkerkerung der schwarzen Umwandlungsfiguren. Ganz toll gemacht und ganz herzlichen Dank für dieses Schmuckstück in meiner Widmungsgalerie!! (EB). Zwei Mausefallen, in denen sich die "Allumgewandelten" ein Stelldichein geben! Alles passt millimetergenau zusammen (MS). Starke Circe-AUW mit viel Strategie und Spiel aufgepäppelt, ob sich EB was abguckt? - und auf h=Circe umsteigt? (TLi).
Keywords: Allumwandlung, Circe
Genre: Fairies
Computer test: Popeye Windows-32Bit v4.55 (1643 MB)
FEN: r7/2P5/2P3KN/8/6R1/1p5k/1Pp2Rp1/8
Reprints: Phénix (37) 01/1996
Input: HBae, 2010-07-09
Last update: Alfred Pfeiffer, 2017-01-16 more...
Genre: Fairies
Computer test: Popeye Windows-32Bit v4.55 (1643 MB)
FEN: r7/2P5/2P3KN/8/6R1/1p5k/1Pp2Rp1/8
Reprints: Phénix (37) 01/1996
Input: HBae, 2010-07-09
Last update: Alfred Pfeiffer, 2017-01-16 more...
1. Ta8! Kc6 2. Le6
1. ... Kd7 2. Ld5 Kd6 3. Td8#
1. ... Kd7 2. Ld5 Kd6 3. Td8#
1. Sd4! Kb4 2. Dc2 Ka5 3. Db3 droht 4. Db5#
1. ... Kc3 2. Dc5+ Kd3,Kd2,Kb2 3. Dc2+
1. ... Kc3 2. Dc5+ Kd3,Kd2,Kb2 3. Dc2+
Keywords: Miniature Collection (0328079), Zugzwang-Goal, Minimal (b), Miniature
Genre: n#
Computer test: Juel: Popeye 4.61
FEN: 8/p7/P7/5Q2/2k3K1/4P3/4N3/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Dieter Berlin, 2024-02-16 more...
Genre: n#
Computer test: Juel: Popeye 4.61
FEN: 8/p7/P7/5Q2/2k3K1/4P3/4N3/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Dieter Berlin, 2024-02-16 more...
1. Kh6 Lg7+ 2. Kg5 Se7 3. Kf4 Kb3 4. Ke3 Sd5+ 5. Kd2 Sc3 6. Kc1 Lh6#
Yuri Bilokin: version given by me SuperProblem (Website) 30/10/2017 wKa3-a2 8/7k/5BN1/8/8/8/K7/8 (2022-12-12)
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comment
Genre: h#
Computer test: Popeye Windows-32Bit v4.51 (100000 KB)
FEN: 8/7k/5BN1/8/8/K7/8/8
Input: hpr, 2011-02-18
Last update: Felber, Volker, 2020-11-16 more...
1. f4 d5 2. f5 d4 3. f6 d3 4. fxe7 dxe2 5. exd8=L exd1=T+ 6. Ke2 Txc1 7. Lxc7 Txb1 8. Lg3 Txa1 9. Le1 Txe1+ 10. Kxe1
Henrik Juel: The double CF is even double Prentos, as the promoted men are captured by officers (2018-12-29)
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Keywords: Ceriani-Frolkin Theme (Lt), Homebase (2), Unique Proof Game, Prentos Theme (Lt), Switchback (K)
Genre: Retro
Computer test: Computerprüfung: C+ Stelvio 1.4 08:35:12 Stunden. (hh:mm:ss) Keine Lösung: BP 9.0.
FEN: rnb1kbnr/pp3ppp/8/8/8/8/PPPP2PP/4KBNR
Input: YM, 2011-03-03
Last update: A.Buchanan, 2023-07-11 more...
Genre: Retro
Computer test: Computerprüfung: C+ Stelvio 1.4 08:35:12 Stunden. (hh:mm:ss) Keine Lösung: BP 9.0.
FEN: rnb1kbnr/pp3ppp/8/8/8/8/PPPP2PP/4KBNR
Input: YM, 2011-03-03
Last update: A.Buchanan, 2023-07-11 more...
* 1. ... Kxe6 2. Dd7+ Ke5 3. Kh4 Ke4 4. Dd3+ Ke5 5. Lc6 Ke6 6. Dd7+ Ke5 7. Sg5 Kf4 8. Dd4+ Kf5 9. Le4+ Kf4 10. Se6+ Txe6 11. Lh6+ Txh6#
1. Kg4! Kxe6 2. Dd7+ Ke5 3. Kh4 Ke4 4. Dd3+ Ke5 5. Lc6 Ke6 6. Dd7+ Ke5 7. Sg5 Kf4 8. Dd4+ Kf5 9. Le4+ Kf4 10. Se6+ Txe6 11. Lh6+ Txh6#
PR Yves Tallec 03/2015
1. Kg4! Kxe6 2. Dd7+ Ke5 3. Kh4 Ke4 4. Dd3+ Ke5 5. Lc6 Ke6 6. Dd7+ Ke5 7. Sg5 Kf4 8. Dd4+ Kf5 9. Le4+ Kf4 10. Se6+ Txe6 11. Lh6+ Txh6#
PR Yves Tallec 03/2015
Keywords: Aristocrat, Wartezug
Genre: s#
FEN: 8/6B1/4Nr2/1B2k3/8/3Q2KN/8/8
Input: Frank Müller, 2011-03-19
Last update: Marcin Banaszek, 2020-11-07 more...
Genre: s#
FEN: 8/6B1/4Nr2/1B2k3/8/3Q2KN/8/8
Input: Frank Müller, 2011-03-19
Last update: Marcin Banaszek, 2020-11-07 more...
47 - P1204543
Roland Lecomte
5265 Phénix 12/2006
(3+1) C+
h#3
b) wSe1 -> d4 c) f. wKf1 -> c7 d) f. wSc4 -> d3
Roland Lecomte
5265 Phénix 12/2006
(3+1) C+
h#3
b) wSe1 -> d4 c) f. wKf1 -> c7 d) f. wSc4 -> d3
a) 1. Kb3 Sa3 2. Kb2 Ke2 3. Kc1 Sd3#
b) 1. Kd3 Sb3 2. Kc2 Kf2 3. Kd1 Se3#
c) 1. Kb4 Se6 2. Kb5 Kb8 3. Ka6 Sc7#
d) 1. Kc4 Sc2 2. Kb3 Kb6 3. Ka4 Sc5#
b) 1. Kd3 Sb3 2. Kc2 Kf2 3. Kd1 Se3#
c) 1. Kb4 Se6 2. Kb5 Kb8 3. Ka6 Sc7#
d) 1. Kc4 Sc2 2. Kb3 Kb6 3. Ka4 Sc5#
Genre: h#
FEN: 8/8/8/8/2N5/2k5/8/4NK2
Input: Hans Gruber, 2011-10-09
Last update: Frank Müller, 2011-10-09 more...
5. Kxg3[Bf3] 6. gxf3[Bg2] 11. f8=D 12. Db4#
Keywords: Circe, Interchange, Seriesmover, Kindergarten Problem, Minimal, Miniature
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/8/k7/6p1/6P1/7K
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-08-09 more...
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/8/k7/6p1/6P1/7K
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-08-09 more...
3. exf6[Bf2] 8. f8=T 9. Te8 10. Kc6#
Keywords: Circe (Anti-), Seriesmover, Move Length Record, Kindergarten Problem
Genre: Fairies
Computer test: %C+ PY 3.21 am 17.12.1994
FEN: 8/3k4/5p2/1K6/8/8/4P3/8
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-02-20 more...
Genre: Fairies
Computer test: %C+ PY 3.21 am 17.12.1994
FEN: 8/3k4/5p2/1K6/8/8/4P3/8
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-02-20 more...
3. Ke1 7. Ka5 11. Kxe8[Ke1]
Keywords: Circe, Seriesmover
Genre: Fairies
Computer test: %C+ PY 3.21 am 17.12.1994
FEN: 4q3/8/8/3k4/7K/8/4P3/8
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-02-25 more...
Genre: Fairies
Computer test: %C+ PY 3.21 am 17.12.1994
FEN: 4q3/8/8/3k4/7K/8/4P3/8
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-02-25 more...
5. h8=D+ 6. Dh2 Ke1+
Keywords: Circe (Anti), Seriesmover, Move Length Record
Genre: Fairies
Computer test: %C+ PY 3.21 am 21.12.1994
FEN: 8/8/8/8/8/8/3K3P/5k2
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-08-08 more...
Genre: Fairies
Computer test: %C+ PY 3.21 am 21.12.1994
FEN: 8/8/8/8/8/8/3K3P/5k2
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-08-08 more...
4. gxh7[Bh2] 9. h8=D 10. Dh2 Ke1+
Keywords: Circe (Anti-), Seriesmover, Kindergarten Problem
Genre: Fairies
Computer test: %C+ PY 3.21 am 21.12.1994
FEN: 8/7p/8/8/8/8/3K2P1/5k2
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-08-08 more...
Genre: Fairies
Computer test: %C+ PY 3.21 am 21.12.1994
FEN: 8/7p/8/8/8/8/3K2P1/5k2
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-08-08 more...
53 - P1211268
Alain Brobecker
6066 Phénix 11-12/2009
Composed with a computer
(2+1) C+
#6
5x6-Brett
Loch a3
wSL=Grenouille
Alain Brobecker
6066 Phénix 11-12/2009
Composed with a computer
(2+1) C+
#6
5x6-Brett
Loch a3
wSL=Grenouille
1. Kc1 Ka2 2. Kc2 Ka1 3. GRe6 Ka2 4. GRe2+ Ka1 5. GRe5 Ka2 6. GRa5#
Alain Brobecker: The initial problem was given with full 5*6 board and the stipulation was: "White removes a square and mates in 6 moves".
The Forg is a (0;3)+(0;4) leaper. (2021-12-27)
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The Forg is a (0;3)+(0;4) leaper. (2021-12-27)
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Keywords: no 8x8 board, Aristocrat, Rex solus (s)
Pieces:
= Frog ()
Genre: Fairies
FEN: qqqqqqqq/qqqqqqqq/5qqq/5qqq/5qqq/q3*3Nqqq/5qqq/k2K1qqq
Input: Hans Gruber, 2011-10-09
Last update: Alfred Pfeiffer, 2018-12-18 more...
Pieces:
= Frog ()
Genre: Fairies
FEN: qqqqqqqq/qqqqqqqq/5qqq/5qqq/5qqq/q3*3Nqqq/5qqq/k2K1qqq
Input: Hans Gruber, 2011-10-09
Last update: Alfred Pfeiffer, 2018-12-18 more...
1. Kg1 Kg3 2. Kf1 Kf2=
1. Kg5 Kf3 2. Kh4 Kg4=
1. Kg5 Kf3 2. Kh4 Kg4=
Steen Christensen: Anticipated by / identical to Nixon (P1295399):
Use symmetry axis a8-h1. {wKg3,sKe3} becomes {wKf2,sKf4}, then
interchange kings and solutions. {wKf2,sKf4} becomes {wKf4,sKf2}. (2023-10-01)
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Use symmetry axis a8-h1. {wKg3,sKe3} becomes {wKf2,sKf4}, then
interchange kings and solutions. {wKf2,sKf4} becomes {wKf4,sKf2}. (2023-10-01)
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Keywords: Grid Chess
Genre: Fairies
FEN: 8/8/8/8/5K2/8/5k2/8
Input: Hans Gruber, 2011-10-09
Last update: Hans Gruber, 2011-10-09 more...
Genre: Fairies
FEN: 8/8/8/8/5K2/8/5k2/8
Input: Hans Gruber, 2011-10-09
Last update: Hans Gruber, 2011-10-09 more...
55 - P1211811
Eric Huber
5936 Phénix 04/2009
(1+3) C+
h#4
Beamtenschach
Bicolores
b) sLf1->e2
c) sLf1->d7
Eric Huber
5936 Phénix 04/2009
(1+3) C+
h#4
Beamtenschach
Bicolores
b) sLf1->e2
c) sLf1->d7
a) 1. Te6 Tf4 2. Ld3 Tf5+ 3. Kg6 Tf3+ 4. Le4 Te3#
b) 1. Tf6 Tg4+ 2. Kh5 Tg6 3. Tf5 Tg2+ 4. Lf3 Tf2#
c) 1. Tc8 Tc5+ 2. Kg4 Tc6 3. Tg8 Tc8+ 4. Tg7 Tc7#
b) 1. Tf6 Tg4+ 2. Kh5 Tg6 3. Tf5 Tg2+ 4. Lf3 Tf2#
c) 1. Tc8 Tc5+ 2. Kg4 Tc6 3. Tg8 Tc8+ 4. Tg7 Tc7#
Keywords: Functionary Chess, Aristocrat, Miniature
Genre: Fairies, h#
Computer test: Popeye 4.61
FEN: 8/8/2r5/6k1/2R5/8/8/5b2
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-12-12 more...
Genre: Fairies, h#
Computer test: Popeye 4.61
FEN: 8/8/2r5/6k1/2R5/8/8/5b2
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-12-12 more...
1. ncSb4-d3=ncL 2. nBb2-b4 5. nBb6-b7 6. nBb7-b8=ncD 7. ncDb8-g3=ncS 8. ncSg3-h1=ncL 9. ncLd3-f1=ncT 10. Kd1-e1xf1 11. Kg2 12. Kh2=
Author: Bantegnie A
Bernd Schwarzkopf: Der Autor ist wohl André Bantegnie. Lösung: 1.ncSb4-d3=ncL 2.nBb2-b4 5.nBb6-b7 6.nBb7-b8=nD=nc 7.ncDb8-g3=ncS 8.ncSg3-h1=ncL 9.ncLd3-f1=ncT 10.Kd1-e1xf1 11.Kg2 12.Kh2 = (nc = neutral + Chamäleon) (2021-03-20)
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Bernd Schwarzkopf: Der Autor ist wohl André Bantegnie. Lösung: 1.ncSb4-d3=ncL 2.nBb2-b4 5.nBb6-b7 6.nBb7-b8=nD=nc 7.ncDb8-g3=ncS 8.ncSg3-h1=ncL 9.ncLd3-f1=ncT 10.Kd1-e1xf1 11.Kg2 12.Kh2 = (nc = neutral + Chamäleon) (2021-03-20)
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Keywords: Circe, Seriesmover, Miniature
Genre: Fairies
Computer test: popeye 4.85
FEN: 8/8/8/8/1-N6/8/1-P6/3K2k1
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-09-20 more...
Genre: Fairies
Computer test: popeye 4.85
FEN: 8/8/8/8/1-N6/8/1-P6/3K2k1
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-09-20 more...
57 - P1224493
Alexandar A. Atanasijevic
11795 British Chess Magazine 1982
2. ehrende Erwähnung
(2+5) C+
ser-s=49
Alexandar A. Atanasijevic
11795 British Chess Magazine 1982
2. ehrende Erwähnung
(2+5) C+
ser-s=49
1. Ke8 2. e3-e4 3. e5 4. e6 5. Kd7 6. Kd6 7. Kd5 8. e7 9. e8=D 10. De6 11. Kd6 12. Kd7 13. Ke8 14. Df7 15. Kf8 16. Kg8 17. Dg6 18. Kh7 19. Kh6 20. Kh5 21. Dg5 22. Kh4 23. Kg3 24. Df4 25. Df2 26. Kg2 27. Kf1 28. Ke1 29. Ke1xd1 30. Ke1 31. Kf1 32. Kg2 33. Kg3 34. Df4 35. Dg5 36. Kh4 37. Kh5 38. Dg6 39. Kh6 40. Kh7 41. Kg8 42. Df7 43. Kf8 44. Ke8 45. De6 46. Kd7 47. Kd6 48. Kd5 49. De3+ Kxe3=
Keywords: Seriesmover, Move Length Record, Minimal
Genre: Fairies
Computer test: %C+ PY 3.43 am 11.2.1997
FEN: 8/3K4/5q2/5b2/8/3kP3/2r5/3n4
Reprints: XXVI Phénix 3, p. 259, 12/1988
L Problemkiste 63 06/1989
170 Phénix 14, p. 1345, 09/1991
398 Zuglängenrekorde im Serienzüger 2003
Input: Erich Bartel, 2011-11-12
Last update: Alfred Pfeiffer, 2016-08-02 more...
Genre: Fairies
Computer test: %C+ PY 3.43 am 11.2.1997
FEN: 8/3K4/5q2/5b2/8/3kP3/2r5/3n4
Reprints: XXVI Phénix 3, p. 259, 12/1988
L Problemkiste 63 06/1989
170 Phénix 14, p. 1345, 09/1991
398 Zuglängenrekorde im Serienzüger 2003
Input: Erich Bartel, 2011-11-12
Last update: Alfred Pfeiffer, 2016-08-02 more...
1. h2-h4 g7-g5 2. h4xg5 c7-c5 3. Th1-h6 c5-c4 4. Th6-b6 a7xb6 5. Sb1-c3 Ta8-a3 6. Sc3-b5 Ta3-e3 7. f2xe3 c4-c3 8. d2xc3 h7-h5 9. Dd1-d5 Th8-h6 10. Lc1-d2 Th6-f6 11. 0-0-0 Tf6xf1 12. Ld2-e1 Tf1-f4 13. Dd5-f3 f7-f5 14. Td1-d6 Tf4-d4 15. Td6-f6 e7xf6 16. Sb5-a3 Dd8-e7 17. Sa3-b1 De7-a3 18. Le1-d2 Da3-a8 19. a2-a4 Lf8-a3 20. Kc1-d1 Ke8-e7 21. Kd1-e1 Ke7-d6 22. Ld2-c1
Mario Richter: I do not know the intended solution, but the following play does the job:
1.h2-h4 g7-g5 2.h4xg5 c7-c5 3.Rh1-h6 c5-c4 4.Rh6-b6 a7xb6 5.Nb1-c3 Ra8-a3 6.Nc3-b5 Ra3-e3 7.f2xe3 c4-c3 8.d2xc3 h7-h5 9.Qd1-d5 Rh8-h6 10.Bc1-d2 Rh6-f6 11.0-0-0 Rf6xf1 12.Bd2-e1 Rf1-f4 13.Qd5-f3 f7-f5 14.Rd1-d6 Rf4-d4 15.Rd6-f6 e7xf6 16.Nb5-a3 Qd8-e7 17.Na3-b1 Qe7-a3 18.Be1-d2 Qa3-a8 19.a2-a4 Bf8-a3 20.Kc1-d1 Ke8-e7 21.Kd1-e1 Ke7-d6 22.Bd2-c1
I think the theme is the so-called Lois-theme, here executed by wK and wBc1 (2014-10-02)
Henrik Juel: Thanks, Mario.
Besides the interchange by two men doubled (Lois), there is a nice roundtrip by Sb1 and an unlikely castling; very good (2014-10-02)
Henrik Juel: Natch 3.1 did little in half an hour
Stopped at pos. 2 (2018-12-27)
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1.h2-h4 g7-g5 2.h4xg5 c7-c5 3.Rh1-h6 c5-c4 4.Rh6-b6 a7xb6 5.Nb1-c3 Ra8-a3 6.Nc3-b5 Ra3-e3 7.f2xe3 c4-c3 8.d2xc3 h7-h5 9.Qd1-d5 Rh8-h6 10.Bc1-d2 Rh6-f6 11.0-0-0 Rf6xf1 12.Bd2-e1 Rf1-f4 13.Qd5-f3 f7-f5 14.Rd1-d6 Rf4-d4 15.Rd6-f6 e7xf6 16.Nb5-a3 Qd8-e7 17.Na3-b1 Qe7-a3 18.Be1-d2 Qa3-a8 19.a2-a4 Bf8-a3 20.Kc1-d1 Ke8-e7 21.Kd1-e1 Ke7-d6 22.Bd2-c1
I think the theme is the so-called Lois-theme, here executed by wK and wBc1 (2014-10-02)
Henrik Juel: Thanks, Mario.
Besides the interchange by two men doubled (Lois), there is a nice roundtrip by Sb1 and an unlikely castling; very good (2014-10-02)
Henrik Juel: Natch 3.1 did little in half an hour
Stopped at pos. 2 (2018-12-27)
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Keywords: Unique Proof Game
Genre: Retro
Computer test: Moldenhauer Computerprüfung: C+ Stelvio 1.11 00:43:00 Minuten. (hh:mm:ss) Keine Lösung: BP 20.5, BP 21.0.
FEN: qnb3n1/1p1p4/1p1k1p2/5pPp/P2r4/b1P1PQ2/1PP1P1P1/1NB1K1N1
Input: Gerd Wilts, 2012-06-04
Last update: A.Buchanan, 2023-03-23 more...
Genre: Retro
Computer test: Moldenhauer Computerprüfung: C+ Stelvio 1.11 00:43:00 Minuten. (hh:mm:ss) Keine Lösung: BP 20.5, BP 21.0.
FEN: qnb3n1/1p1p4/1p1k1p2/5pPp/P2r4/b1P1PQ2/1PP1P1P1/1NB1K1N1
Input: Gerd Wilts, 2012-06-04
Last update: A.Buchanan, 2023-03-23 more...
1. Ta3 ? Db8+ 2. Kxg1 Dg3+ 3. Kf1 Dd3+ !
1. De6+ Kh8 2. Dh3+ Kg8 3. Dxb3+ Kh8 4. Dh3+ Kg8 5. De6+ Kh8 6. Ta3 !Db8+
7. Kxg1 Lb3 8. Dh3+ Kg8 9. Dxb3+ Kh8 10. Dh3+ Kg8 11. De6+ Kh8 12. Th3 #
Recommandé: n°23;Bernard DELOBEL.
Une solution quelque peu brutale, mais la double manoeuvre triangulaire de la Dame blanche est
plaisante.
1.Ta3 ? Db8+ 2.Rxg1 Dg3+ 3.Rf1 Dd3+ !
1.De6+ Rh8 2.Dh3+ Rg8 3.Dxb3+ Rh8 4.Dh3+ Rg8 5.De6+ Rh8 6.Ta3 !Db8+
7.Rxg1 Fb3 8.Dh3+ Rg8 9.Dxb3+ Rh8 10.Dh3+ Rg8 11.De6+ Rh8 12.Th3 #
(Juge : Claude Wiedenhoff)
1. De6+ Kh8 2. Dh3+ Kg8 3. Dxb3+ Kh8 4. Dh3+ Kg8 5. De6+ Kh8 6. Ta3 !Db8+
7. Kxg1 Lb3 8. Dh3+ Kg8 9. Dxb3+ Kh8 10. Dh3+ Kg8 11. De6+ Kh8 12. Th3 #
Recommandé: n°23;Bernard DELOBEL.
Une solution quelque peu brutale, mais la double manoeuvre triangulaire de la Dame blanche est
plaisante.
1.Ta3 ? Db8+ 2.Rxg1 Dg3+ 3.Rf1 Dd3+ !
1.De6+ Rh8 2.Dh3+ Rg8 3.Dxb3+ Rh8 4.Dh3+ Rg8 5.De6+ Rh8 6.Ta3 !Db8+
7.Rxg1 Fb3 8.Dh3+ Rg8 9.Dxb3+ Rh8 10.Dh3+ Rg8 11.De6+ Rh8 12.Th3 #
(Juge : Claude Wiedenhoff)
Genre: n#
Computer test: Anton Baumann: C+ Gustav 4.1d (2021-02-22)
FEN: q5k1/6p1/6P1/1p3QP1/bP2P3/1p6/RP5K/6r1
Reprints: Phénix 2012
Input: Ralf Kr?tschmer, 2012-05-10
Last update: Erich Bartel, 2021-02-23 more...
60 - P1245522
George P. Sphicas
Q0067 StrateGems 2001
1.Preis, Richter: David L. Brown
(11+4) C+
s=17
George P. Sphicas
Q0067 StrateGems 2001
1.Preis, Richter: David L. Brown
(11+4) C+
s=17
1. a8=D+ Kb6 2. b8=D+ Kc5 3. c8=D+ Kd4 4. d8=D+ Ke3 5. De4+ Kxe4 6. e8=D+ Kf3 7. f8=D+ Kg2 8. g8=D+ Kxh1 9. Dbb7+ Kh2 10. Dg3+ Kxg3 11. Df4+ Kxf4 12. De5+ Kxe5 13. h8=D+ Kf4 14. De5+ Kxe5 15. Dd6+ Kxd6 16. Dc5+ Kxc5 17. Db6+ Kxb6=
Olaf Jenkner: Wirklich C+? Da scheint mir mit heutiger Technik unmöglich zu sein. (2012-07-27)
paul: Published in FIDE Album 2001-2003. (2024-04-02)
Dieter Berlin: Die Aufgabe ist im FIDE_Album 2001-2003 nicht als C+ gekennzeichnet. (2024-04-02)
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paul: Published in FIDE Album 2001-2003. (2024-04-02)
Dieter Berlin: Die Aufgabe ist im FIDE_Album 2001-2003 nicht als C+ gekennzeichnet. (2024-04-02)
more ...
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Keywords: Promotions to queens (8-fach), konsekutive Umwandlungen 8 (DDDDDDDD)
Genre: Fairies
Computer test: %C+ lt Quelle
FEN: 8/PPPPPPPP/k7/8/K7/8/B1n5/r1n4N
Reprints: A3508 Phénix 110-111 09-10/2002
The Problemist , p. 517, 11/2002
C) Problemkiste 187 02/2010
G7 FIDE Album 2001-2003 , p. 442, 2011
11322 Sachova skladba 116 07/2012
Input: Erich Bartel, 2012-07-27
Last update: Dieter Berlin, 2024-04-02 more...
Genre: Fairies
Computer test: %C+ lt Quelle
FEN: 8/PPPPPPPP/k7/8/K7/8/B1n5/r1n4N
Reprints: A3508 Phénix 110-111 09-10/2002
The Problemist , p. 517, 11/2002
C) Problemkiste 187 02/2010
G7 FIDE Album 2001-2003 , p. 442, 2011
11322 Sachova skladba 116 07/2012
Input: Erich Bartel, 2012-07-27
Last update: Dieter Berlin, 2024-04-02 more...
61 - P1257927
Hubert Gockel
556 mpk-Blätter 11/2012
Informalturnier 2012/13
3. Preis
(7+5) C+
h#2
2.1.1.1
take&make
Hubert Gockel
556 mpk-Blätter 11/2012
Informalturnier 2012/13
3. Preis
(7+5) C+
h#2
2.1.1.1
take&make
1. Tf4 Txf4-f3 2. Sxg3-g4 Txd3-c1#
1. S3f4+ Txf4-g2 2. Txg3-g4 Txe2-c1#
1. S3f4+ Txf4-g2 2. Txg3-g4 Txe2-c1#
Keywords: take&make Chess
Genre: Fairies
FEN: 8/8/8/3B3K/N3P1R1/3n1rPP/4n3/k2b4
Reprints: A5270 Phénix (253) 09/2015
Input: Frank Müller, 2012-12-30
Last update: Olaf Jenkner, 2020-11-10 more...
Genre: Fairies
FEN: 8/8/8/3B3K/N3P1R1/3n1rPP/4n3/k2b4
Reprints: A5270 Phénix (253) 09/2015
Input: Frank Müller, 2012-12-30
Last update: Olaf Jenkner, 2020-11-10 more...
1. Ld6! f3 2. Lf8 Kf4 3. Lh6+ Kf5 4. Sb4 Ke5 5. Sxf3+ Kf5 6. Sd4+ Ke5 7. Sdc6+ Kf5 8. Se7+ Ke5 9. Sc2 f5 10. f4+ Kf6 11. Sg6 fxg6#
Genre: s#
FEN: 1B6/5p2/2N2p2/2PB1k1K/5p1P/8/5P2/4N3
Input: Frank Müller, 2013-09-27
Last update: Marcin Banaszek, 2022-02-21 more...
63 - P1282643
Romeo Bedoni
Phénix 09/1991
(2+5) C+
s#6
2 Lösungen
Längstzüger
sLR=Gnu
wBU=Berolinabauer
Romeo Bedoni
Phénix 09/1991
(2+5) C+
s#6
2 Lösungen
Längstzüger
sLR=Gnu
wBU=Berolinabauer
1) 1. BEg3! Tc8 2. BEf4 Tc1 3. BEg5 Tc8 4. BEh6 Tc1 5. BEg7 Tc8 6. BEh8=GN+ Txh8#
2) 1. BEf4! Tc8 2. BEg5 Tc1 3. BEh6 Tc8 4. BEg7 Tc1 5. BEf8=GN Tc8 6. GNc7 Th8#
2) 1. BEf4! Tc8 2. BEg5 Tc1 3. BEh6 Tc8 4. BEg7 Tc1 5. BEf8=GN Tc8 6. GNc7 Th8#
Dasselbe Thema mit dem Gnu als Märchenfigur läß sich sogar in Minimalminiaturform darstellen.
SCHRECKE: C+, popeye 4.85 (2021-02-04)
comment
SCHRECKE: C+, popeye 4.85 (2021-02-04)
comment
Keywords: Excelsior, Maximummer, Minimal
Pieces:
= Gnu (GN), 
= Berolina Pawn (BE)
Genre: Fairies
FEN: 8/4k3/5p2/4p3/7K/8/7*2P/2r4*1b
Input: Erich Bartel, 2014-01-31
Last update: James Malcom, 2021-02-04 more...
Pieces:
= Gnu (GN), = Berolina Pawn (BE)
Genre: Fairies
FEN: 8/4k3/5p2/4p3/7K/8/7*2P/2r4*1b
Input: Erich Bartel, 2014-01-31
Last update: James Malcom, 2021-02-04 more...
64 - P1282677
Romeo Bedoni
Phénix 09/1991
(3+4) C+
s#6
2 Lösungen
Längstzüger
sSU=Nachtreiter
wBU=Berolinabauer
Romeo Bedoni
Phénix 09/1991
(3+4) C+
s#6
2 Lösungen
Längstzüger
sSU=Nachtreiter
wBU=Berolinabauer
1) 1. BEg3! Tb8 2. BEf4 Tb1 3. BEg5 Tb8 4. BEh6 Tb1 5. BEg7 Tb8 6. BEh8=N+ Txh8#
2) 1. BEf4! Tb8 2. BEg5 Tb1 3. BEh6 Tb8 4. BEg7 Tb1 5. BEf8=N Tb8 6. Nb6 Th8#
2) 1. BEf4! Tb8 2. BEg5 Tb1 3. BEh6 Tb8 4. BEg7 Tb1 5. BEf8=N Tb8 6. Nb6 Th8#
Keywords: Excelsior, Maximummer, Promotion (Märchen-), Bartel Theme
Pieces:
= Nightrider (N), = Berolina Pawn (BE)
Genre: Fairies
FEN: 8/8/3k1*2n2/8/4*2n2K/7P/7*2P/1r6
Input: Erich Bartel, 2014-02-02
Last update: Erich Bartel, 2021-02-04 more...
Pieces:
= Nightrider (N), = Berolina Pawn (BE)
Genre: Fairies
FEN: 8/8/3k1*2n2/8/4*2n2K/7P/7*2P/1r6
Input: Erich Bartel, 2014-02-02
Last update: Erich Bartel, 2021-02-04 more...
1. De4! Ka8 2. Lf4 Ka7 3. Sb8 Ka8 4. Sxa6 Ka7 5. Sc7 Kb8 6. De8+ Ka7 7. Sd5 Ka6 8. Db8 Ka5 9. Dxb7 Ka4 10. Dxb6 Ka3 11. Sc3 bxc3 12. Dxb5 c2#
1. Df3? .... 6. Df8?? scheitert an Selbstbehinderung
PR Gunter Jordan 10/2016
1. Df3? .... 6. Df8?? scheitert an Selbstbehinderung
PR Gunter Jordan 10/2016
Genre: s#
FEN: 8/kp1N4/bp6/1p6/1p3Q2/1p6/1p1B4/1K6
Input: Frank Müller, 2014-08-12
Last update: James Malcom, 2021-02-20 more...
1. Td2 droht 2. Tc2+ Lxc2+ 3. Db3+ Lxb3# AB
1. ... Sfxd2,Sbxd2 2. Db3+ Sxb3 3. Tc5+ Sxc5# BC
1. ... Lh3,Lg4 2. Tc5+ Txc5 3. Dc4+ Txc4# CD
1. ... Se3 2. Dc4+ Sxc4 3. Tc2+ Lxc2# DA
1. ... Sxa3 2. Tc5+ Sc4 3. Da3+ Dxa3#
Plagiat!
1. ... Sfxd2,Sbxd2 2. Db3+ Sxb3 3. Tc5+ Sxc5# BC
1. ... Lh3,Lg4 2. Tc5+ Txc5 3. Dc4+ Txc4# CD
1. ... Se3 2. Dc4+ Sxc4 3. Tc2+ Lxc2# DA
1. ... Sxa3 2. Tc5+ Sc4 3. Da3+ Dxa3#
Plagiat!
Gunter Jordan: Als Preisrichter dieses Jahrganges schrieb ich damals im Vorspann meines Berichtes: "Dies ist ein - durchaus geschickt umgebautes - Plagiat(!). Quelle: Ivan Soroka, Problemist of Ukraine 2008, Waleri Kopyl 50 JT, 3. Preis (siehe PDB P1088770)." (2022-01-03)
comment
comment
Keywords: white move cycle
Genre: s#
Computer test: Popeye Windows-64Bit v4.55 (4803 MB)
FEN: 8/r1b5/4p3/pP1R1b1r/K2R4/N1k2N2/Qp2P3/qn3n2
Input: Frank Müller, 2014-08-12
Last update: Gunter Jordan, 2022-01-03 more...
Genre: s#
Computer test: Popeye Windows-64Bit v4.55 (4803 MB)
FEN: 8/r1b5/4p3/pP1R1b1r/K2R4/N1k2N2/Qp2P3/qn3n2
Input: Frank Müller, 2014-08-12
Last update: Gunter Jordan, 2022-01-03 more...
1. Sc5 b3 2. Se6 b2 3. Sd3+ Kd5 4. Da5+ Kc6 5. Tc4+ Kd7 6. Db5+ Tc6 7. Td4+ Kc8 8. Da6+ Txa6#
1. ... e6 2. Lxe6 b3 3. Db8 b2 4. S5d3+ Kxe6 5. De8+ Kd5 6. Sb4+ Kc5 7. Sb3+ Kb6 8. Dd8+ Txd8#
1. ... e6 2. Lxe6 b3 3. Db8 b2 4. S5d3+ Kxe6 5. De8+ Kd5 6. Sb4+ Kc5 7. Sb3+ Kb6 8. Dd8+ Txd8#
Genre: s#
FEN: K7/2Q1pB2/3r4/4k3/Pp2NR2/4P3/8/2N5
Input: Frank Müller, 2014-08-17
Last update: Marcin Banaszek, 2020-10-12 more...
1. Se7 Lg8 2. Te6+ Lxe6 3. Dd8+ Ld7 4. Ta5 g5 5. Kb7 g4 6. Ka6 g3 7. Sef5+ Kc6 8. Dc8+ Lxc8#
Genre: s#
FEN: K1Q5/P5Nb/3k2p1/3N2R1/4R3/8/8/8
Input: Frank Müller, 2014-08-17
Last update: Marcin Banaszek, 2020-10-12 more...
* 1. ... Lxb2 2. Dd2+ Kxd2#
1. De2! Kd4 2. Lb6+ Kc3 3. Le3 b3 4. Sa4+ Kb4 5. Dc4+ Ka5 6. Ld2+ Lb4 7. Sxb3+ Kxa4 8. Dc6+ Ka3 9. Lc1+ Ka2 10. Sd2+ Ka1 11. Dc3+ Lxc3#
PR Mike Prcic 01-02/2016
1. De2! Kd4 2. Lb6+ Kc3 3. Le3 b3 4. Sa4+ Kb4 5. Dc4+ Ka5 6. Ld2+ Lb4 7. Sxb3+ Kxa4 8. Dc6+ Ka3 9. Lc1+ Ka2 10. Sd2+ Ka1 11. Dc3+ Lxc3#
PR Mike Prcic 01-02/2016
Henrik Juel: Popeye 4.61 with 'opt non 1 1' found no flaws (2020-11-05)
SCHRECKE: C+, Gustav 4.2c, Brute Force (2023-03-20)
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SCHRECKE: C+, Gustav 4.2c, Brute Force (2023-03-20)
comment
Genre: s#
FEN: 6BK/7P/8/B7/1p6/b1k5/1N3Q2/2N5
Input: Frank Müller, 2014-08-17
Last update: Marcin Banaszek, 2023-03-28 more...
1. Sc3 e5 2. Sd5 Lc5 3. Se7 d5 4. e3 Lh3 5. Dg4 a5 6. De6 f5 7. Se2 Sf6 8. Sc3 Tf8 9. Dg8 Ta6 10. Dh8 La7 11. Sg8 Tf7 12. Sb1 Td7 13. Sh6+ Ke7 14. Sf7 Df8 15. Sg5 Se8 16. Sf3 Tf6 17. Sg1
Henrik Juel: Thanks for the solution, Hans; I could not find it
The white knights switch places, very nice proof game (2015-01-26)
Henrik Juel: Natch 3.1 did little in half an hour
Stopped at pos. 1 (2018-12-31)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 05:48:08 Stunden. (hh:mm:ss)
Keine Lösung: BP 15.5, BP 16.0. (2023-03-05)
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The white knights switch places, very nice proof game (2015-01-26)
Henrik Juel: Natch 3.1 did little in half an hour
Stopped at pos. 1 (2018-12-31)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 05:48:08 Stunden. (hh:mm:ss)
Keine Lösung: BP 15.5, BP 16.0. (2023-03-05)
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Keywords: Unique Proof Game, Interchange (SS), Impostor (SS), Capture-free
Genre: Retro
Computer test: Stelvio 1.0
FEN: 1n2nq1Q/bpprk1pp/5r2/p2ppp2/8/4P2b/PPPP1PPP/RNB1KBNR
Input: A.Buchanan, 2015-01-25
Last update: Silvio Baier, 2023-03-20 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: 1n2nq1Q/bpprk1pp/5r2/p2ppp2/8/4P2b/PPPP1PPP/RNB1KBNR
Input: A.Buchanan, 2015-01-25
Last update: Silvio Baier, 2023-03-20 more...
71 - P1305233
Alexandre Leroux
4 Retro Championnat de France RIFACE 2015
(2+1) C+
KBP in 7.0
Ergänze die fehlenden Steine!
Alexandre Leroux
4 Retro Championnat de France RIFACE 2015
(2+1) C+
KBP in 7.0
Ergänze die fehlenden Steine!
a) 1. a4 Sf6 2. a5 Se4 3. a6 Sxd2 4. Kxd2 h5 5. Kc3 Th6 6. Kb4 Te6 7. Ka5 Te4
Originalforderung: Ajouter des pieces pour avoir une PCPJ en 7,0 Coups
Henrik Juel: Given the final position, the proof game is C+ by Euclide 1.01 (2015-07-08)
paul: Easily verified by Jacobi with the code: stipulation PG 7 pieces white Ka5 Pa6 black Re4 AddPieces (2021-07-06)
A.Buchanan: An essential linking word in the author's stipulation has been lost in translation: "Ajouter des pieces *pour* avoir une PCPJ en 7,0 Coups." I'm glad that on this occasion the Originalforderung was retained, but can we use a German template for these which is something like "Ergänze die fehlenden Steine um ein KBP in 7,0 zu haben". In English it would be "Add the missing pieces for an SPG in 7.0." (2021-07-07)
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Henrik Juel: Given the final position, the proof game is C+ by Euclide 1.01 (2015-07-08)
paul: Easily verified by Jacobi with the code: stipulation PG 7 pieces white Ka5 Pa6 black Re4 AddPieces (2021-07-06)
A.Buchanan: An essential linking word in the author's stipulation has been lost in translation: "Ajouter des pieces *pour* avoir une PCPJ en 7,0 Coups." I'm glad that on this occasion the Originalforderung was retained, but can we use a German template for these which is something like "Ergänze die fehlenden Steine um ein KBP in 7,0 zu haben". In English it would be "Add the missing pieces for an SPG in 7.0." (2021-07-07)
more ...
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Keywords: Unique Proof Game, Add pieces, Constrained problem
Genre: Retro
Computer test: rawbats, jacobi & Euclide
FEN: 8/8/P7/K7/4r3/8/8/8
Reprints: Phénix 2015
12 Phénix 296-297, p. 11536, 05-06/2019
1 Die Schwalbe 301, p. 440, 02/2020
Input: A.Buchanan, 2015-07-08
Last update: A.Buchanan, 2023-04-13 more...
Genre: Retro
Computer test: rawbats, jacobi & Euclide
FEN: 8/8/P7/K7/4r3/8/8/8
Reprints: Phénix 2015
12 Phénix 296-297, p. 11536, 05-06/2019
1 Die Schwalbe 301, p. 440, 02/2020
Input: A.Buchanan, 2015-07-08
Last update: A.Buchanan, 2023-04-13 more...
1. Sc6 bxc6 2. d8=T c5 3. b7 c4 4. b8=T cxd3 5. Dxb3+ Saxb3+ 6. c8=T+ Sc5 7. exd3 Ta1#
Henrik Juel: Popeye 4.61 with opt nichtt 0 1 found no flaws (2016-06-01)
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-10)
comment
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-10)
comment
Keywords: konsekutive Umwandlungen 3 (TTT)
Genre: s#
FEN: K5Q1/1pPP4/1P6/8/3N4/1pkN4/1ppnP3/nrb1B3
Input: Frank Müller, 2016-06-01
Last update: Marcin Banaszek, 2020-10-12 more...
Genre: s#
FEN: K5Q1/1pPP4/1P6/8/3N4/1pkN4/1ppnP3/nrb1B3
Input: Frank Müller, 2016-06-01
Last update: Marcin Banaszek, 2020-10-12 more...
1. f8=S 2. dxc8=D 3. Df5 4. c8=T 5. Tc6 6. b8=T 7. Lc8 8. Sd7 9. Kb7 10. a8=L 11. Dh7+ Txh7,Kxh7=
Keywords: konsekutive Umwandlungen 5 (SDTTL), Allumwandlung, Seriesmover, under-promotion key, Antiphönix, pin-stalemate, blocking of a piece (Selbst-)
Genre: Fairies
Computer test: V. Kotesovec: Alybadix (6 h 52 m)
FEN: K1n4k/PPPP1Pr1/B7/q7/8/8/8/7b
Input: Frank Müller, 2016-06-01
Last update: Gunter Jordan, 2022-11-28 more...
Genre: Fairies
Computer test: V. Kotesovec: Alybadix (6 h 52 m)
FEN: K1n4k/PPPP1Pr1/B7/q7/8/8/8/7b
Input: Frank Müller, 2016-06-01
Last update: Gunter Jordan, 2022-11-28 more...
1. f4 e5 2. fxe5 Ld6 3. exd6 Se7 4. dxc7 Sec6 5. cxb8=D Dc7 6. Dxa8 Sb8 7. Dxb7 Dxc2 8. Db3 Dxd1+ 9. Dxd1
Keywords: Homebase (2), Pronkin Theme (D), Unique Proof Game, Impostor (s), Prenix (D)
Genre: Retro
FEN: 1nb1k2r/p2p1ppp/8/8/8/8/PP1PP1PP/RNBQKBNR
Input: YM, 2017-07-03
Last update: A.Buchanan, 2019-01-26 more...
Genre: Retro
FEN: 1nb1k2r/p2p1ppp/8/8/8/8/PP1PP1PP/RNBQKBNR
Input: YM, 2017-07-03
Last update: A.Buchanan, 2019-01-26 more...
1. Lf8 Sh3 2. Dd5+ Kf4! 3. Ld6+ Ke3 4. Lc5+ Kf4 5. De5+ Kf3 6. Df5+ Sf4 7. Lb4 Ke3 8. Ld2+ Kd4! 9. Dc5+ Kd3! 10. Dc3+ Ke4 11. Dc4+ Kf3 12. Dd3+ Sxd3#
76 - P1347210
Pascal Wassong
Thierry Le Gleuher
Axel Gilbert
RIFACE 2017
2nd Prize
(16+16) C+
KBP in 16,5
Weißer Längstzüger
Weißer Ohneschlag
Pascal Wassong
Thierry Le Gleuher
Axel Gilbert
RIFACE 2017
2nd Prize
(16+16) C+
KBP in 16,5
Weißer Längstzüger
Weißer Ohneschlag
1. Sf3 Sc6 2. Sd4 Se5 3. Sc6 a6 4. Sb8 c6 5. Sa3 Db6 6. Sc4 Db3 7. Sa5 Sc4 8. a4 Db5 9. Sb3 g5 10. Sc5 Lg7 11. Se4 Le5 12. Sc3 Lc7 13. Sb1 d6 14. Sd7 Sf6 15. Se5 0-0 16. Sf3 Kh8 17. Sg1
Joost de Heer: Solution: 1.Sf3 Sc6 2.Sd4 Se5 3.Sc6 a6 4.Sb8 c6 5.Sa3 Qb6 6.Sc4 Qb3 7.Sa5 Sc4 8.a4 Qb5 9.Sb3 g5 10.Sc5 Bg7 11.Se4 Be5 12.Sc3 Bc7 13.Sb1 d6 14.Sd7 Sf6 15.Se5 O-O 16.Sf3 Kh8 17.Sg1 (2021-01-04)
comment
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Keywords: Unique Proof Game, No-capture chess (w), Maximummer (w), RIFACE Retro Composition Tourney (2017)
Genre: Retro, Fairies
FEN: r1b2r1k/1pb1pp1p/p1pp1n2/1q4p1/P1n5/8/1PPPPPPP/RNBQKBNR
Reprints: Phénix 279-280, p. 10966, 11-12/2017
Input: A.Buchanan, 2018-02-24
Last update: Gerd Wilts, 2021-01-04 more...
Genre: Retro, Fairies
FEN: r1b2r1k/1pb1pp1p/p1pp1n2/1q4p1/P1n5/8/1PPPPPPP/RNBQKBNR
Reprints: Phénix 279-280, p. 10966, 11-12/2017
Input: A.Buchanan, 2018-02-24
Last update: Gerd Wilts, 2021-01-04 more...
77 - P1347216
Philippe Rouzaud
RIFACE 2017
1. Lob
(12+16) C+
KBP in 15,0
Weißer Längstzüger
Weißer Ohneschlag
Philippe Rouzaud
RIFACE 2017
1. Lob
(12+16) C+
KBP in 15,0
Weißer Längstzüger
Weißer Ohneschlag
paul: 1.Sa3 d5 2.Sc4 d×c4 3.Sf3 Qd3 4.Sd4 Kd8 5.Sb3 c×b3
6.h4 b×c2 7.Rh3 c×d1=B 8.Re3 Ba4 9.Re6 Be8 10.Ra6 Qd7
11.Rh6 g6 12.a4 Bg7 13.Ra3 Be5 14.Rh3 Bg3 15.Rh1 Bh2 (2021-08-19)
comment
6.h4 b×c2 7.Rh3 c×d1=B 8.Re3 Ba4 9.Re6 Be8 10.Ra6 Qd7
11.Rh6 g6 12.a4 Bg7 13.Ra3 Be5 14.Rh3 Bg3 15.Rh1 Bh2 (2021-08-19)
comment
Keywords: Unique Proof Game, No-capture chess (w), Maximummer (w), Non-standard material (l), RIFACE Retro Composition Tourney (2017)
Genre: Retro, Fairies
FEN: rnbkb1nr/pppqpp1p/6pR/8/P6P/8/1P1PPPPb/2B1KB1R
Reprints: Phénix 279-280, p. 10967, 11-12/2017
Input: A.Buchanan, 2018-02-24
Last update: A.Buchanan, 2020-10-05 more...
Genre: Retro, Fairies
FEN: rnbkb1nr/pppqpp1p/6pR/8/P6P/8/1P1PPPPb/2B1KB1R
Reprints: Phénix 279-280, p. 10967, 11-12/2017
Input: A.Buchanan, 2018-02-24
Last update: A.Buchanan, 2020-10-05 more...
78 - P1347219
François Labelle
RIFACE 2017
3. Lob
(16+16) C+
Move a black rook to c2 in 6 moves
Längstzüger
Schwarzer Ohneschlag
François Labelle
RIFACE 2017
3. Lob
(16+16) C+
Move a black rook to c2 in 6 moves
Längstzüger
Schwarzer Ohneschlag
1. c4 Sc6 2. Dc2 Sd4 3. Dxh7 Sb5 4. Dh4 Th5 5. cxb5 Tc5 6. Dg5 Tc2
Joost de Heer: 1. c4 Sc6 2. Qc2 Sd4 3. Qh7 Sb5 4. Qh4 Rh5 5. cxb5 Rc5 6. Qg5 Rc2 (2021-01-04)
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Keywords: Synthetic problem, No-capture chess (s), Maximummer, RIFACE Retro Composition Tourney (2017), Homebase
Genre: Retro, Fairies
FEN: rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR
Reprints: Phénix 279-280, p. 10968, 11-12/2017
Input: A.Buchanan, 2018-02-24
Last update: James Malcom, 2023-07-04 more...
Genre: Retro, Fairies
FEN: rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR
Reprints: Phénix 279-280, p. 10968, 11-12/2017
Input: A.Buchanan, 2018-02-24
Last update: James Malcom, 2023-07-04 more...
1. ... Le4-d5 2. Lg6 Ka1 3. Da4+ La2 4. De8 Lb1 5. f6 Le4 6. Kf7 Le4-d5#
Selbstplagiat. Die Aufgabe erschien auch auch in Die Schwalbe 299, Nr. 17958, 10/2019.
Meeraner, Urform, Themafigur: wL
Selbstplagiat. Die Aufgabe erschien auch auch in Die Schwalbe 299, Nr. 17958, 10/2019.
Meeraner, Urform, Themafigur: wL
Jakob Leck: Scheinbar auch teilgenommen am Kosjura-64 Turnier, siehe yacpdb 482902. (2021-05-16)
comment
comment
Keywords: Remote selfblock (3 x), Meerane-Thema, Minimal, Model mate, Switchback, Round Trip, Multiple publication
Genre: h#
FEN: 1n3rk1/4bpp1/1r1p4/8/4Bq2/2p5/K1b5/8
Reprints: 17958 Die Schwalbe 299, p. 330, 10/2019
Input: Gunter Jordan, 2018-02-28
Last update: Gunter Jordan, 2020-04-10 more...
Genre: h#
FEN: 1n3rk1/4bpp1/1r1p4/8/4Bq2/2p5/K1b5/8
Reprints: 17958 Die Schwalbe 299, p. 330, 10/2019
Input: Gunter Jordan, 2018-02-28
Last update: Gunter Jordan, 2020-04-10 more...
1. Sc3 Sc6 2. Se4 Sd4 3. Sg5 Sxe2 4. Sxh7 Sxc1 5. Sxf8 Txh2 6. Se6 Txg2 7. Sxd8 Txf2 8. Sc6 Txd2 9. Sxa7 Txc2 10. Sxc8 Txb2 11. Sb6 Txb6 12. Th8 0-0-0 13. Txg8 Te8 14. Txe8#
Moldenhauer: Computerprüfung: C+ Stelvio 1.4 00:41:06 Minuten.(hh:mm:ss)
Keine Lösung: BP 13.0 mit Stelvio 1.31 überprüft.
Das heißt, nach Retraktion müsste man nicht mehr auf 13.0 überprüfen. (2023-07-23)
comment
Keine Lösung: BP 13.0 mit Stelvio 1.31 überprüft.
Das heißt, nach Retraktion müsste man nicht mehr auf 13.0 überprüfen. (2023-07-23)
comment
Keywords: Unique Proof Game, Castling
Genre: Retro
Computer test: Stelvio 1.4 Not shown as C+ in Phenix
FEN: 2k1R3/1pppppp1/1r6/8/8/8/P7/R1nQKBN1
Input: A.Buchanan, 2018-03-03
Last update: Silvio Baier, 2023-08-15 more...
Genre: Retro
Computer test: Stelvio 1.4 Not shown as C+ in Phenix
FEN: 2k1R3/1pppppp1/1r6/8/8/8/P7/R1nQKBN1
Input: A.Buchanan, 2018-03-03
Last update: Silvio Baier, 2023-08-15 more...
81 - P1347479
Pascal Wassong
Axel Gilbert
Thierry Le Gleuher
Michel Caillaud
7952 Phénix 277, p. 10888, 09/2017
(16+16) C+
BP in 15,0
Längstzüger
Schwarzer Ohneschlag
Pascal Wassong
Axel Gilbert
Thierry Le Gleuher
Michel Caillaud
7952 Phénix 277, p. 10888, 09/2017
(16+16) C+
BP in 15,0
Längstzüger
Schwarzer Ohneschlag
1. e4 Sa6 2. Lc4 Sc5 3. Ld5 Sa4 4. c4 Sb6 5. Da4 Sh6 6. Dc6 Sf5 7. a4 Sd4 8. Sa3 Sb3 9. Tb1 Sa5 10. b3 h5 11. Le6 Sd5 12. Lb2 Sf6 13. Dd5 Sg8 14. Lf6 Sc6 15. e5 Sb8
Joost de Heer: Solution: 1.e4 Sa6 2.Bc4 Sc5 3.Bd5 Sa4 4.c4 Sb6 5.Qa4 Sh6 6.Qc6 Sf5 7.a4 Sd4 8.Sa3 Sb3 9.Rb1 Sa5 10.b3 h5 11.Be6 Sd5 12.Bb2 Sf6 13.Qd5 Sg8 14.Bf6 Sc6 15.e5 Sb8 (2021-01-04)
Adrian Storisteanu: "Ohneschlag" is an unnecessary condition for a 16+16 position!? (2021-09-19)
Adrian Storisteanu: (Ah, OK, sorry, it prevents unwanted maximummer alternative moves...) (2021-09-19)
comment
Adrian Storisteanu: "Ohneschlag" is an unnecessary condition for a 16+16 position!? (2021-09-19)
Adrian Storisteanu: (Ah, OK, sorry, it prevents unwanted maximummer alternative moves...) (2021-09-19)
comment
Keywords: Unique Proof Game, Maximummer, No-capture chess (s)
Genre: Retro, Fairies
FEN: rnbqkbnr/ppppppp1/4BB2/3QP2p/P1P5/NP6/3P1PPP/1R2K1NR
Input: A.Buchanan, 2018-03-03
Last update: Gerd Wilts, 2021-01-04 more...
Genre: Retro, Fairies
FEN: rnbqkbnr/ppppppp1/4BB2/3QP2p/P1P5/NP6/3P1PPP/1R2K1NR
Input: A.Buchanan, 2018-03-03
Last update: Gerd Wilts, 2021-01-04 more...
1. e4 d5 2. exd5 Sc6 3. dxc6 Dd4 4. cxb7 Dxb2 5. d4 Dxa1 6. Lb2 Dxb2 7. d5 Db5 8. d6 Dd7 9. bxc8=T+ Dd8 10. d7#
Moldenhauer: Computerprüfung: C+ Stelvio 1.4 3 Sekunden.
Keine Lösung: BP 9.0 mit Stelvio 1.31 überprüft.
Notation: 1.e4 d5 2.exd5 Sc6 3.dxc6 Dd4 4.cxb7 Dxb2 5.d4 Dxa1 6.Lb2 Dxb2
7.d5 Db5 8.d6 Dd7 9.bxc8=T+ Dd8 10.d7# (2023-07-23)
comment
Keine Lösung: BP 9.0 mit Stelvio 1.31 überprüft.
Notation: 1.e4 d5 2.exd5 Sc6 3.dxc6 Dd4 4.cxb7 Dxb2 5.d4 Dxa1 6.Lb2 Dxb2
7.d5 Db5 8.d6 Dd7 9.bxc8=T+ Dd8 10.d7# (2023-07-23)
comment
Keywords: Unique Proof Game, Homebase (s), Pure mate, Round Trip (d), Hit Squad
Genre: Retro
Computer test: Stelvio 1.4
FEN: r1Rqkbnr/p1pPpppp/8/8/8/8/P1P2PPP/1N1QKBNR
Input: A.Buchanan, 2019-01-25
Last update: Silvio Baier, 2023-11-14 more...
Genre: Retro
Computer test: Stelvio 1.4
FEN: r1Rqkbnr/p1pPpppp/8/8/8/8/P1P2PPP/1N1QKBNR
Input: A.Buchanan, 2019-01-25
Last update: Silvio Baier, 2023-11-14 more...
1. Sb1-a3 e7-e5 2. Sa3-c4 Lf8-a3 3. Sc4xe5 La3xb2 4. a2-a4 Lb2-a3 5. Lc1xa3 Sb8-c6 6. La3-e7 d7-d6 7. Dd1-b1 Lc8-g4 8. Db1-b5 Lg4-f3 9. g2xf3 Dd8-d7 10. Lf1-h3 Sc6-b8 11. Lh3-e6 Dd7-c6 12. h2-h3 Sb8-d7 13. Th1-h2 Dc6xc2 14. Th2-g2 Dc2-c6 15. Tg2-g4 Sd7-b8 16. Tg4-c4 Dc6-d7 17. Tc4-c2 Sb8-c6 18. Le6-c4 Dd7-d8 19. Se5-d7 Sc6-b8
Reto: 1.Sb1-a3 Pe7-e5 2.Sa3-c4 Bf8-a3 3.Sc4xe5 Ba3xb2 4.Pa2-a4 Bb2-a3
5.Bc1xa3 Sb8-c6 6.Ba3-e7 Pd7-d6 7.Qd1-b1 Bc8-g4 8.Qb1-b5 Bg4-f3
9.Pg2xf3 Qd8-d7 10.Bf1-h3 Sc6-b8 11.Bh3-e6 Qd7-c6 12.Ph2-h3 Sb8-d7
13.Rh1-h2 Qc6xc2 14.Rh2-g2 Qc2-c6 15.Rg2-g4 Sd7-b8 16.Rg4-c4 Qc6-d7
17.Rc4-c2 Sb8-c6 18.Be6-c4 Qd7-d8 19.Se5-d7 Sc6-b8 (2023-05-18)
Henrik Juel: For this PG Stelvio 1.2 is a clear winner
Eulide 1.01 did nothing in half an hour (2023-05-18)
comment
5.Bc1xa3 Sb8-c6 6.Ba3-e7 Pd7-d6 7.Qd1-b1 Bc8-g4 8.Qb1-b5 Bg4-f3
9.Pg2xf3 Qd8-d7 10.Bf1-h3 Sc6-b8 11.Bh3-e6 Qd7-c6 12.Ph2-h3 Sb8-d7
13.Rh1-h2 Qc6xc2 14.Rh2-g2 Qc2-c6 15.Rg2-g4 Sd7-b8 16.Rg4-c4 Qc6-d7
17.Rc4-c2 Sb8-c6 18.Be6-c4 Qd7-d8 19.Se5-d7 Sc6-b8 (2023-05-18)
Henrik Juel: For this PG Stelvio 1.2 is a clear winner
Eulide 1.01 did nothing in half an hour (2023-05-18)
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Stelvio 1.2, 3sec
FEN: rn1qk1nr/pppNBppp/3p4/1Q6/P1B5/5P1P/2RPPP2/R3K1N1
Input: A.Buchanan, 2019-01-25
Last update: Silvio Baier, 2023-11-14 more...
Genre: Retro
Computer test: Stelvio 1.2, 3sec
FEN: rn1qk1nr/pppNBppp/3p4/1Q6/P1B5/5P1P/2RPPP2/R3K1N1
Input: A.Buchanan, 2019-01-25
Last update: Silvio Baier, 2023-11-14 more...
1. Deb5+! Td5 2. Dc7+ Ted6 3. De8+ Tfe6 4. Dg7+ Tff6 5. Dh5+ T4f5 6. Dg3+ Tef4 7. Dhe2+ De4 8. Dxe4+ Tbxe4 9. Dc3+ Tdd4 10. Dbb5+ T6d5 11. Dc7+ Ted6 12. De8+ Tfe6 13. Dg7+ Tff6 14. Dh5+ T4f5 15. Dg3+ Tef4 16. Dhe2+ Tde4 17. Dxe4+ Taxe4 18. Dc3+ Tdd4 19. Db5+ T6d5 20. Dc7+ Ted6 21. De8+ Tfe6 22. Dg7+ Tff6 23. Dh5+ T4f5 24. Dg3+ Tef4 25. De2+ Tde4 26. Dxe4+ Kxe4 27. De3#
Keywords: Non-standard material, Consecutive checks (27)
Genre: n#
Computer test: V. Kotesovec: Gustav 4.0 f, Lösezeit: 22 : 11 : 39 : 23,46 d
FEN: 1n6/K7/Qp1rrr2/4kr2/rr1qrr2/N1Q5/r1P1QP2/1Q6
Input: Vaclav Kotesovec, 2019-02-04
Last update: Mu-Tsun Tsai, 2023-06-15 more...
Genre: n#
Computer test: V. Kotesovec: Gustav 4.0 f, Lösezeit: 22 : 11 : 39 : 23,46 d
FEN: 1n6/K7/Qp1rrr2/4kr2/rr1qrr2/N1Q5/r1P1QP2/1Q6
Input: Vaclav Kotesovec, 2019-02-04
Last update: Mu-Tsun Tsai, 2023-06-15 more...
85 - P1379124
Klaus Wenda
Petko A. Petkov
5) feenschach 95, p. 294, 06-09/1995
1. Preis
(6+6) C+
ser-s#13
Circe
Madrasi
Klaus Wenda
Petko A. Petkov
5) feenschach 95, p. 294, 06-09/1995
1. Preis
(6+6) C+
ser-s#13
Circe
Madrasi
1. Df2 2. Tgg1 3. Dd4 4. Lc3 5. La5 6. Ta1 7. Ta2 8. Lc3 9. La1 10. Dg1 11. Kg3 12. Kxh2[+sSb8] 13. b7+ Kxb7[+wBb2]#
Keywords: Circe, Madrasi, Seriesmover
Genre: Fairies
Computer test: V. Kotesovec: Alybadix (47 h 42 m)
FEN: k1b5/8/1P6/4b3/7K/1p6/3r2Rn/B5QR
Reprints: Problemesis 16 2000
2488 Phénix 90, p. 4996, 2000
5v feenschach 135, p. 231, 01-05/2000
W45 StrateGems 15, p. 178, 2001
G34 FIDE Album 1995-1997 , p. 429, 2004
O29 Phénix 257, p. 10228, 2016
Input: Vaclav Kotesovec, 2020-08-17
Last update: Vaclav Kotesovec, 2020-08-18 more...
Genre: Fairies
Computer test: V. Kotesovec: Alybadix (47 h 42 m)
FEN: k1b5/8/1P6/4b3/7K/1p6/3r2Rn/B5QR
Reprints: Problemesis 16 2000
2488 Phénix 90, p. 4996, 2000
5v feenschach 135, p. 231, 01-05/2000
W45 StrateGems 15, p. 178, 2001
G34 FIDE Album 1995-1997 , p. 429, 2004
O29 Phénix 257, p. 10228, 2016
Input: Vaclav Kotesovec, 2020-08-17
Last update: Vaclav Kotesovec, 2020-08-18 more...
1. d4 Sf6 2. Lh6 Tg8 3. e3 Ta8-h8 4. Da6 Sxa6 5. Sd2 Tb8 6. 0-0-0 Tba8 7. Kb1 Sb8 8. La6 Tgh8 9. Sf1 Sg8 10. Le1
Henrik Juel: C+ Jacobi 0.7.5
1.d4 Sf6 2.Bh6 Rg8 3.e3 Rah8 4.Qa6 Sxa6 5.Sd2 Rb8 6.O-O-O Rba8 7.Kb1 Sb8 8.Ba6 Rgh8 9.Sf1 Sg8 10.Be1
On a standard board Black would have made an even number of moves; not so here, with Ra8-h8-b8-a8 (2020-10-05)
A.Buchanan: This has exactly 200 solutions as a PG in 8.5, for example 1.d4 Sf6 2.Sd2 Sd5 3.e3 Sc3 4.Ba6 Sxd1 5.Sf1 Sc3 6.Bd2 Se4 7.O-O-O Sf6 8.Kb1 Sg8 9.Be1. It's restored to soundness if "genau" is stuck in the stipulation. (2021-06-10)
comment
1.d4 Sf6 2.Bh6 Rg8 3.e3 Rah8 4.Qa6 Sxa6 5.Sd2 Rb8 6.O-O-O Rba8 7.Kb1 Sb8 8.Ba6 Rgh8 9.Sf1 Sg8 10.Be1
On a standard board Black would have made an even number of moves; not so here, with Ra8-h8-b8-a8 (2020-10-05)
A.Buchanan: This has exactly 200 solutions as a PG in 8.5, for example 1.d4 Sf6 2.Sd2 Sd5 3.e3 Sc3 4.Ba6 Sxd1 5.Sf1 Sc3 6.Bd2 Se4 7.O-O-O Sf6 8.Kb1 Sg8 9.Be1. It's restored to soundness if "genau" is stuck in the stipulation. (2021-06-10)
comment
Keywords: Unique Proof Game, Vertical Cylinder, Homebase (s), RIFACE Retro Composition Tourney (2016), Initial Game Array (s)
Genre: Retro, Fairies
Computer test: C+ Jacobi 0.7.5 but shorter BPs exist
FEN: rnbqkbnr/pppppppp/B7/8/3P4/4P3/PPP2PPP/1K1RBNNR
Reprints: II Phénix 310-311, p. 12121, 09-10/2020
Input: A.Buchanan, 2020-10-05
Last update: A.Buchanan, 2021-06-10 more...
Genre: Retro, Fairies
Computer test: C+ Jacobi 0.7.5 but shorter BPs exist
FEN: rnbqkbnr/pppppppp/B7/8/3P4/4P3/PPP2PPP/1K1RBNNR
Reprints: II Phénix 310-311, p. 12121, 09-10/2020
Input: A.Buchanan, 2020-10-05
Last update: A.Buchanan, 2021-06-10 more...
87 - P1380946
Olaf Jenkner
8737 Phénix 306-307 04-05/2020
1. Preis
PR Sergij I. Borodawkin
(6+2) C+
s#9
Olaf Jenkner
8737 Phénix 306-307 04-05/2020
1. Preis
PR Sergij I. Borodawkin
(6+2) C+
s#9
1. c8=D! e1=D 2. Dd3+ De3 3. Df1+ Df2 4. Sd2+ Ke3 5. Te4+ Kxd2 6. Dcc4 De2 7. Tf2 Dxf2 8. Da2+ Kc3 9. Db2+ Dxb2#
1. ... e1=T 2. Dc6+ Te4 3. Dd1+ Ke3 4. Dc5+ Td4 5. Sd2 Kd3 6. Sc4+ Kc3 7. Df3+ Td3 8. Da5+ Kb3 9. Dd1+ Txd1#
1. ... e1=L 2. Dd5+ Ke3 3. Dc1+ Ld2 4. Df5 Lxc1 5. T4g3+ Kd4 6. Td3+ Kc4 7. Tc2+ Kb4 8. Td4+ Kb3 9. Tb2+ Lxb2#
1. ... e1=S 2. Ddc3+ Sd3 3. Ta2 Ke3 4. Dd4+ Kf3 5. Sd2+ Ke2 6. Te4+ Kd1 7. Dg4+ Kc1 8. Dc5+ Sxc5 9. Sb3+ Sxb3#
Award 01/2021
1. ... e1=T 2. Dc6+ Te4 3. Dd1+ Ke3 4. Dc5+ Td4 5. Sd2 Kd3 6. Sc4+ Kc3 7. Df3+ Td3 8. Da5+ Kb3 9. Dd1+ Txd1#
1. ... e1=L 2. Dd5+ Ke3 3. Dc1+ Ld2 4. Df5 Lxc1 5. T4g3+ Kd4 6. Td3+ Kc4 7. Tc2+ Kb4 8. Td4+ Kb3 9. Tb2+ Lxb2#
1. ... e1=S 2. Ddc3+ Sd3 3. Ta2 Ke3 4. Dd4+ Kf3 5. Sd2+ Ke2 6. Te4+ Kd1 7. Dg4+ Kc1 8. Dc5+ Sxc5 9. Sb3+ Sxb3#
Award 01/2021
Vier Mustermatts
Preisrichter Sergij I. Borodawkin:
Allumwandlung noir, qui comporte quatre variations différentes et quatre mats modèles. Huit pièces sur l'échiquier, sans un seul dual, est toujors impressionnant.
Iwan Soroka: Großartig! (2020-10-15)
Mirko Degenkolbe: Eine sensationelle Aufgabe!!
Sie ist noch einen Tick besser als das Goldstück vom 8.FIDE WORLD CUP.
Der Autor hatte mir dieses Meisterwerk vorab gezeigt und ich kann immer noch nicht so recht glauben, dass das alles genauso funktioniert, wie es angedacht ist.
Fantastisch! (2020-10-15)
Gerald Ettl: In der Laenge eine AUW eindeutig zu zeigen war sicherlich nicht leicht. Das Goldstück vom World Cup kenne ich nicht. Ist die auch hier in der Datenbank zu sehen? (2020-10-15)
SCHRECKE: siehe: P1377975 (2020-10-16)
comment
Preisrichter Sergij I. Borodawkin:
Allumwandlung noir, qui comporte quatre variations différentes et quatre mats modèles. Huit pièces sur l'échiquier, sans un seul dual, est toujors impressionnant.
Iwan Soroka: Großartig! (2020-10-15)
Mirko Degenkolbe: Eine sensationelle Aufgabe!!
Sie ist noch einen Tick besser als das Goldstück vom 8.FIDE WORLD CUP.
Der Autor hatte mir dieses Meisterwerk vorab gezeigt und ich kann immer noch nicht so recht glauben, dass das alles genauso funktioniert, wie es angedacht ist.
Fantastisch! (2020-10-15)
Gerald Ettl: In der Laenge eine AUW eindeutig zu zeigen war sicherlich nicht leicht. Das Goldstück vom World Cup kenne ich nicht. Ist die auch hier in der Datenbank zu sehen? (2020-10-15)
SCHRECKE: siehe: P1377975 (2020-10-16)
comment
Keywords: Allumwandlung, black (9), Minimal, Model mate (4x)
Genre: s#
Computer test: O. Jenkner: Gustav 4.1 d
FEN: 8/2P5/8/8/6R1/5k2/3Qp1R1/KN6
Input: Olaf Jenkner, 2020-10-15
Last update: Marcin Banaszek, 2021-09-16 more...
Genre: s#
Computer test: O. Jenkner: Gustav 4.1 d
FEN: 8/2P5/8/8/6R1/5k2/3Qp1R1/KN6
Input: Olaf Jenkner, 2020-10-15
Last update: Marcin Banaszek, 2021-09-16 more...
1) 1. ... Te1 2. Sgf2 Te7 3. Kg1 Txc7 4. Tg2 Te7 5. Lxh2 Te1#
2) 1. ... Tc3 2. Kh1 Txh3 3. Se3 Tf3 4. Tg1 h4 5. Sg2 Th3#
3) 1. ... Tc4 2. Shf2 Txg4+ 3. Kh3 Tf4 4. Tg2 Txf5 5. Sg4 Th5#
2) 1. ... Tc3 2. Kh1 Txh3 3. Se3 Tf3 4. Tg1 h4 5. Sg2 Th3#
3) 1. ... Tc4 2. Shf2 Txg4+ 3. Kh3 Tf4 4. Tg2 Txf5 5. Sg4 Th5#
Jacques Rotenberg: .
a lighter version was published soon after the judgement : p.91, Tehtäväniekka (juin 19)
Weiss : Kb7 Ta1 Bh2
Schwarz : Kg2 Tg6 Lb8 Sg4h3 Bc7d7c6f5
FEN : 1b6/1Kpp4/2p3r1/5p2/6n1/7n/6kP/R7 (2022-06-08)
comment
a lighter version was published soon after the judgement : p.91, Tehtäväniekka (juin 19)
Weiss : Kb7 Ta1 Bh2
Schwarz : Kg2 Tg6 Lb8 Sg4h3 Bc7d7c6f5
FEN : 1b6/1Kpp4/2p3r1/5p2/6n1/7n/6kP/R7 (2022-06-08)
comment
Keywords: Corner mate (in 2), Line opening, Model mate, Switchback, Selfblock
Genre: h#
FEN: 1b6/2p5/K1p3r1/1ppp1p2/6n1/7n/6kP/2R5
Reprints: A5556 Phénix 305, p. 11938, 03/2020
Input: Gunter Jordan, 2020-10-19
Last update: Gunter Jordan, 2020-10-19 more...
Genre: h#
FEN: 1b6/2p5/K1p3r1/1ppp1p2/6n1/7n/6kP/2R5
Reprints: A5556 Phénix 305, p. 11938, 03/2020
Input: Gunter Jordan, 2020-10-19
Last update: Gunter Jordan, 2020-10-19 more...
1. e3 d6 2. La6 Lh3 3. Lxb7 Lxg2 4. Lxa8 Lxh1 5. Le4 Lxe4 6. c3 Lxb1 7. Db3 Lxa2 8. Dxa2 f6 9. Dxg8 h6 10. Dxf8 Kxf8
AB: I too made this one yesterday but alas on checking in WinChloe found that Francois’ software had got there first! This shows the utility of WinChloe and the power of Francois’ approach. And at least I can be grateful I didn’t try to publish!
This proof game is too long to be found by François’ general mining program, but he can adapt his program specifically to find ornamental problems such as this where the final positions are highly constrained and he can count whether any move is taking him nearer or further away from the right kind of position. The definitively unproductive lines can easily be pruned. Homebases and symmetric positions are also amenable to this kind of attack
See P1381496.
Henrik Juel: Solution
1.Be2-e3 Bd7-d6 2.Lf1-a6 Lc8-h3 3.La6xb7 Lh3xg2
4.Lb7xa8 Lg2xh1 5.La8-e4 Lh1xe4 6.Bc2-c3 Le4xb1
7.Dd1-b3 Lb1xa2 8.Db3xa2 Bf7-f6 9.Da2xg8 Bh7-h6
10.Dg8xf8 Ke8xf8
was found by Natch 3.1, which was stopped before completion
The C+ was probably found by construction, not by testing
The light-colored bishops do most of the work, with the white queen sweeping up at the end (2020-11-04)
A.Buchanan: Thanks Henrik - Natch 3.2 did complete in about 90 minutes. Oh the sadness of anticipation... (2020-11-05)
comment
This proof game is too long to be found by François’ general mining program, but he can adapt his program specifically to find ornamental problems such as this where the final positions are highly constrained and he can count whether any move is taking him nearer or further away from the right kind of position. The definitively unproductive lines can easily be pruned. Homebases and symmetric positions are also amenable to this kind of attack
See P1381496.
Henrik Juel: Solution
1.Be2-e3 Bd7-d6 2.Lf1-a6 Lc8-h3 3.La6xb7 Lh3xg2
4.Lb7xa8 Lg2xh1 5.La8-e4 Lh1xe4 6.Bc2-c3 Le4xb1
7.Dd1-b3 Lb1xa2 8.Db3xa2 Bf7-f6 9.Da2xg8 Bh7-h6
10.Dg8xf8 Ke8xf8
was found by Natch 3.1, which was stopped before completion
The C+ was probably found by construction, not by testing
The light-colored bishops do most of the work, with the white queen sweeping up at the end (2020-11-04)
A.Buchanan: Thanks Henrik - Natch 3.2 did complete in about 90 minutes. Oh the sadness of anticipation... (2020-11-05)
comment
Keywords: Unique Proof Game, Ornament
Genre: Retro
Computer test: C+ Natch 3.2 in 1hr 32 mins
FEN: 1n1q1k1r/p1p1p1p1/3p1p1p/8/8/2P1P3/1P1P1P1P/R1B1K1N1
Input: A.Buchanan, 2020-11-04
Last update: A.Buchanan, 2020-11-05 more...
Genre: Retro
Computer test: C+ Natch 3.2 in 1hr 32 mins
FEN: 1n1q1k1r/p1p1p1p1/3p1p1p/8/8/2P1P3/1P1P1P1P/R1B1K1N1
Input: A.Buchanan, 2020-11-04
Last update: A.Buchanan, 2020-11-05 more...
1. g7-g8=D+! Kf7-f6 2. Dg8-g4 Kf6-f7 3. Kh7-h8 Kf7-f6 4. Df4-g5+ Kf6-f7 5. Dg5-h5+ Kf7-f6 6. d7-d8=S Sf5-e3,S~ 7. Dg4-f4+ Se3-f5 8. Df4-d6+ Sf5xd6 9. Dh5-e5+ Kf6-g6 10. Te8-g8+ Kg6-h6 11. Sd8-f7+ Sd6xf7#
Keywords: Promotion key, Checking key, under-promotion (S), konsekutive Umwandlungen 2 (DS)
Genre: s#
FEN: 4R3/3P1kPK/8/5n2/5Q2/8/8/8
Input: Marcin Banaszek, 2020-11-04
Last update: Marcin Banaszek, 2020-11-12 more...
Genre: s#
FEN: 4R3/3P1kPK/8/5n2/5Q2/8/8/8
Input: Marcin Banaszek, 2020-11-04
Last update: Marcin Banaszek, 2020-11-12 more...
1. c7-c8=T+! Kc6-d5 2. f7xe8=L b7-b6 3. h7-h8=D b6xc5 4. Dh8-f6 c5xd4 5. Le8-g6 d4-d3 6. Df6-g5 Kd5xd6 7. e7-e8=S Kd6-d5 8. Se8-f6+ Kd5-d6 9. Te1-e6+ d7xe6#
Version zu: P1381602
PR Yves Tallec 04-05/2020
Version zu: P1381602
PR Yves Tallec 04-05/2020
Keywords: Checking key, under-promotion key, Model mate, Selfblock, Allumwandlung, Pawn mate, Obvious promotion, konsekutive Umwandlungen 4 (TLDS)
Genre: s#
Computer test: Gustav 4.1c
FEN: 4b3/1pPpPP1P/2kP4/1pP2K2/1prP4/1B6/3P4/B3R3
Input: Marcin Banaszek, 2020-11-09
Last update: James Malcom, 2020-11-09 more...
Genre: s#
Computer test: Gustav 4.1c
FEN: 4b3/1pPpPP1P/2kP4/1pP2K2/1prP4/1B6/3P4/B3R3
Input: Marcin Banaszek, 2020-11-09
Last update: James Malcom, 2020-11-09 more...
a) 1. Dg7xf6 Th6xg6 2. Df6xb2 La6-c4#
b) 1. Tg6xf6 Lh8xg7 2. Tf6xa6 Tb2-b5#
b) 1. Tg6xf6 Lh8xg7 2. Tf6xa6 Tb2-b5#
Keywords: Capture key
Genre: h#
Computer test: Popeye 4.83
FEN: 1K5B/4rpqp/B4PrR/3k1pp1/1P6/3P4/1R6/8
Input: Marcin Banaszek, 2020-11-14
Last update: Alfred Pfeiffer, 2020-11-16 more...
Genre: h#
Computer test: Popeye 4.83
FEN: 1K5B/4rpqp/B4PrR/3k1pp1/1P6/3P4/1R6/8
Input: Marcin Banaszek, 2020-11-14
Last update: Alfred Pfeiffer, 2020-11-16 more...
93 - P1382055
Jacques Rotenberg
Dominique Forlot
7852 Phénix 273-274 05-06/2017
(3+3) C+
h#4
b) sLg7 statt sBg7
Jacques Rotenberg
Dominique Forlot
7852 Phénix 273-274 05-06/2017
(3+3) C+
h#4
b) sLg7 statt sBg7
a) 1. Se5-f7 Tc6-c8 2. Kd5-e6 Tc8-a8 3. Ke6-e7 Lh2-b8 4. Ke7-f8 Lb8-d6#
b) 1. Kd5-d4 Tc6-c8 2. Se5-d3 Lh2-c7 3. Kd4-c3 Ka1-a2 4. Lg7-d4 Lc7-a5#
b) 1. Kd5-d4 Tc6-c8 2. Se5-d3 Lh2-c7 3. Kd4-c3 Ka1-a2 4. Lg7-d4 Lc7-a5#
Jacques Rotenberg: Dominique Forlot is co-author
Themes :
Indian, critical moves, echo model mates (2020-11-20)
comment
Themes :
Indian, critical moves, echo model mates (2020-11-20)
comment
Keywords: Forsberg Twins
Genre: h#
Computer test: Popeye 4.83
FEN: 8/6p1/2R5/3kn3/8/8/7B/K7
Input: Marcin Banaszek, 2020-11-18
Last update: Alfred Pfeiffer, 2020-11-26 more...
Genre: h#
Computer test: Popeye 4.83
FEN: 8/6p1/2R5/3kn3/8/8/7B/K7
Input: Marcin Banaszek, 2020-11-18
Last update: Alfred Pfeiffer, 2020-11-26 more...
a) 1. Kd5-e6 La4xd1 2. Lc4-d5 Tc1xc6+ 3. Sf5-d6 Ld1-g4#
b) 1. Td1-d3 Tc1-g1 2. Kd5-e4 La4xc6+ 3. Sf4-d5 Tg1-g4#
b) 1. Td1-d3 Tc1-g1 2. Kd5-e4 La4xc6+ 3. Sf4-d5 Tg1-g4#
Genre: h#
Computer test: Popeye 4.83
FEN: 8/4pp2/1rp2b2/3k1n2/BqbP1n2/4p3/8/K1Rr4
Input: Marcin Banaszek, 2020-11-18
Last update: Alfred Pfeiffer, 2020-11-26 more...
1. ... Lh8-d4 2. Lc5-d6 Ld4xb6 3. Ld6-g3 Lb6-c5 4. b7-b5+ Ka7-a6 5. b5-b4 Ka6-b5 6. b4-b3 Kb5-c4 7. b3-b2 Kc4-d3 8. b2-b1=L+ Kd3-e2 9. Lb1-e4 Ke2-f1 10. Le4-h1 Lc5-g1#
PR Menachem Witztum 11-12/2019
PR Menachem Witztum 11-12/2019
Keywords: Minimal (L), Model mate, Liniensperrung, Check Protection, Excelsior black, under-promotion (l), Selfblock
Genre: h#
Computer test: C+ Popeye 4.61
FEN: 7B/Kpq5/1r6/2b5/8/7r/7k/8
Input: Marcin Banaszek, 2020-11-20
Last update: Gunter Jordan, 2020-11-20 more...
Genre: h#
Computer test: C+ Popeye 4.61
FEN: 7B/Kpq5/1r6/2b5/8/7r/7k/8
Input: Marcin Banaszek, 2020-11-20
Last update: Gunter Jordan, 2020-11-20 more...
1. d3-d2 f2-f4 2. d2-d1=S f4-f5 3. Sd1-e3 f5-f6 4. Se3-f5 f6-f7 5. Sf5-g7 f7-f8=S #
Klaus Funk: Vorgänger: P1095144
siehe auch P1191040 mit T-UW (2022-05-05)
Klaus Funk: Ferner fast zeitgleich mit sBh6: Pascale Piet P1397280 (2022-07-30)
comment
siehe auch P1191040 mit T-UW (2022-05-05)
Klaus Funk: Ferner fast zeitgleich mit sBh6: Pascale Piet P1397280 (2022-07-30)
comment
Keywords: Excelsior, under-promotion in mating move (S), under-promotion (s)
Genre: h#
Computer test: Gustav 4.1c
FEN: 6nn/7k/7b/8/8/3p4/5P2/7K
Input: Marcin Banaszek, 2020-11-20
Last update: Alfred Pfeiffer, 2020-12-01 more...
Genre: h#
Computer test: Gustav 4.1c
FEN: 6nn/7k/7b/8/8/3p4/5P2/7K
Input: Marcin Banaszek, 2020-11-20
Last update: Alfred Pfeiffer, 2020-12-01 more...
Joost de Heer: Double entry, see P1013102. (2022-06-10)
A.Buchanan: I guess Messigny entries were reprinted in Phenix. How do you want to handle this? (2022-06-10)
Joost de Heer: @Andrew In the Messigny one a reprint in Phénix. (2022-08-22)
more ...
comment
A.Buchanan: I guess Messigny entries were reprinted in Phenix. How do you want to handle this? (2022-06-10)
Joost de Heer: @Andrew In the Messigny one a reprint in Phénix. (2022-08-22)
more ...
comment
Genre: Retro
FEN: 2k5/p1p2pQp/r2Bpn2/1PnP1P1P/P1P1PbP1/2r2B2/7q/R3KbNR
Input: fs/hg, 2020-12-30
Last update: A.Buchanan, 2022-06-10 more...
98 - P1384724
Andrey Frolkin
Kostas Prentos
Phénix 2009
2. Preis
(15+13) C+
a) H#1.5
b) BP 15, dann H#1.5
Andrey Frolkin
Kostas Prentos
Phénix 2009
2. Preis
(15+13) C+
a) H#1.5
b) BP 15, dann H#1.5
Kostas Prentos: Solution:
a) h#1,5: 1…Dd4 2. 0-0 Dxg7#
b) 1. h4 b6 2. Th3 La6 3. Tf3 Lc4 4. Txf7 Sa6 5. Txf8+ Kxf8 6. h5 De8 7. h6 Dh5 8. d4 Kf7 9. Sd2 Tf8 10. Sdf3 Ke8 11. Sh2 Tf3 12. exf3 Sf6 13. Le2 Sd5 14. Kf1 Sdb4 15. d5 c5 & h#1.5: 1…dxc6 e.p. 2. Kd8 Dxd7# (2022-12-08)
comment
a) h#1,5: 1…Dd4 2. 0-0 Dxg7#
b) 1. h4 b6 2. Th3 La6 3. Tf3 Lc4 4. Txf7 Sa6 5. Txf8+ Kxf8 6. h5 De8 7. h6 Dh5 8. d4 Kf7 9. Sd2 Tf8 10. Sdf3 Ke8 11. Sh2 Tf3 12. exf3 Sf6 13. Le2 Sd5 14. Kf1 Sdb4 15. d5 c5 & h#1.5: 1…dxc6 e.p. 2. Kd8 Dxd7# (2022-12-08)
comment
Genre: Retro
FEN: 4k2r/p2pp1pp/np5P/2pP3q/1nb5/5P2/PPP1BPPN/R1BQ1KN1
Input: fs/hg, 2020-12-30
Last update: Gerd Wilts, 2020-12-30 more...
1. h4 a5 2. h5 a4 3. h6 Ta5 4. hxg7 h5 5. f4 h4 6. f5 h3 7. f6 Th4 8. fxe7 f5 9. b4 Sf6 10. g8=L Lh6 11. Lb3 axb3 12. g4 b2 13. g5 Tg4 14. g6 Lg5 15. g7 Kf7 16. g8=L+ Kg6 17. Lc4 d5 18. e8=T dxc4 19. Te6 Dd3 20. Ta6 bxa6 21. e4 Lb7 22. e5 Le4 23. e6 Te5 24. e7 c5 25. e8=T Sc6 26. Td8 Se8 27. Td4 cxd4
Keywords: Ceriani-Frolkin Theme (TTLL), Future Proof Game, Impostor (TTLL)
Genre: Retro
FEN: 4n3/8/p1n3k1/4rpb1/1Pppb1r1/3q3p/PpPP4/RNBQKBNR
Input: fs/hg, 2020-12-30
Last update: Silvio Baier, 2022-03-31 more...
Genre: Retro
FEN: 4n3/8/p1n3k1/4rpb1/1Pppb1r1/3q3p/PpPP4/RNBQKBNR
Input: fs/hg, 2020-12-30
Last update: Silvio Baier, 2022-03-31 more...
100 - P1384738
Pascal Wassong
Phénix 2014
1./2. Preis ex aequo
Caillaud 50 JT
(14+15) C+
BP in 12,0
b) wLf2 statt wDf2
Pascal Wassong
Phénix 2014
1./2. Preis ex aequo
Caillaud 50 JT
(14+15) C+
BP in 12,0
b) wLf2 statt wDf2
a) 1. a4 a5 2. Ta3 Ta6 3. Th3 Tf6 4. d3 Txf2 5. Lg5 Tf6 6. Lxf6 gxf6 7. g4 Lh6 8. Tg3 Kf8 9. Lh3 Kg7 10. Kf1 Kg6 11. De1 Lf8 12. Df2 Kg7
b) 1. g4 a5 2. Lh3 Ta6 3. Kf1 Tf6 4. De1 Txf2+ 5. Dxf2 Sh6 6. Df6 gxf6 7. a4 Lg7 8. Ta3 Kf8 9. Tg3 Kg8 10. d3 Lf8 11. Le3 Kg7 12. Lf2 Sg8
b) 1. g4 a5 2. Lh3 Ta6 3. Kf1 Tf6 4. De1 Txf2+ 5. Dxf2 Sh6 6. Df6 gxf6 7. a4 Lg7 8. Ta3 Kf8 9. Tg3 Kg8 10. d3 Lf8 11. Le3 Kg7 12. Lf2 Sg8
Keywords: Unique Proof Game
Genre: Retro
Computer test: C+ Euclide 1.01
FEN: 1nbq1bnr/1pppppkp/5p2/p7/P5P1/3P2RB/1PP1PQ1P/1N3KNR
Input: fs/hg, 2020-12-30
Last update: A.Buchanan, 2021-01-02 more...
Genre: Retro
Computer test: C+ Euclide 1.01
FEN: 1nbq1bnr/1pppppkp/5p2/p7/P5P1/3P2RB/1PP1PQ1P/1N3KNR
Input: fs/hg, 2020-12-30
Last update: A.Buchanan, 2021-01-02 more...
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