Die Schwalbe

23 problem(s) found in 4119 milliseconds (displaying 23 problem(s)). [COMMENTDATE>=20200919 AND NOT A='Stahl, Karl Alfred' AND K='En passant im Retrospiel'] [download as LaTeX]

1 - P0000016
Nikita M. Plaksin
Alexander Kislyak

(F) Die Schwalbe 98 04/1986
P0000016
(11+9)
Welches war der erste Zug der beiden Könige?
R: 1. bxc3ep+ c2-c4 2. b5-b4+
play all play one stop play next play all
Erster K-Zug: Weiß: 0-0; Schwarz: 0-0
173. Thema-Turnier
Henrik Juel: Good motivation for the black castling
The further retroplay includes retracting Tf1-g1, Kd3 to g1, h2xTg3, Tg3 to f8, La6 to c8, d7xTSe6, and e6xPf7 (2021-04-19)
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comment
Keywords: En passant, First Move?, Last Moves? (3), Castling (wksk), Castling in the retro play, En passant in the retro play, Volet Pawn, Type C
Genre: Retro
FEN: 7k/1p2pPpp/b3p3/8/8/2pK2P1/pP1PPPP1/2B3RN
Reprints: 566 Ukrainisches Album 1986-1990
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-04-20 more...
2 - P0000029
Walter Wittstock
5463 Die Schwalbe 98 04/1986
P0000029
(3+2) cooked
-1w -1s, dann h=1
R: 1. b2xBc3 b4xc3ep, dann bxa6 b3=
play all play one stop play next play all
Cook: R: 1. b2xDc3 Da3xSc3, dann 1. bxa6 bxa3=
Adrian Storisteanu: Possible fix: +bPc5. (2015-06-10)
Miguel Ambrona: The fix proposed by Adrian works.
Verified with Deadpos v.2.2. (2024-01-12)
comment
Keywords: En passant in the retro play, Help retractor, Kindergarten Problem, Minimal, Miniature, Ideal stalemate, Superseded by (P1360139)
Genre: Retro, Fairies
Computer test: cooked by Deadpos v2.3 14-Jan-2024
FEN: 8/1pK5/P7/k7/8/2P5/8/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-01-18 more...
3 - P0000052
Andrey Frolkin
(V) Die Schwalbe 102 12/1986
P0000052
(16+11)
Vor mindestens 72 Einzelzügen mußte ep geschlagen werden!
R: 1. ... Sg2-h4+ 2. Sh4-g6+ h7-h6 3. Se2-g1 a3-a2 4. Tg1-f1 a4-a3 5. Sf1-h2 Sh2-g4 6. Lh6-g5 Sg4-h2 7. Lg7-h6 Sh2-g4 8. Lf8-g7! Sg4-h2 9. Ld6-f8 Sh2-g4 10. Lb8-d6 Sg4-h2 11. Sc3-e2 Sh2-g4 12. Sb5-c3 Sg4-h2 13. Sd6-b5 Sh2-g4 14. Sf7-d6 Sg4-h2 15. b7-b8=L Sh2-g4 16. b6-b7 Sg4-h2 17. b5-b6 Sh2-g4 18. b4-b5 Sg4-h2 19. b3-b4 Sh2-g4 20. Lg7-h8 Sg4-h2 21. Lf8-g7 Sh2-g4 22. Ld6-f8 Sg4-h2 23. Lb8-d6 Sh2-g4 24. b7-b8=L Sg4-h2 25. b6-b7 Sh2-g4 26. b5-b6 Sg4-h2 27. b4-b5 Sh2-g4 28. a3xBb4 Sg4-h2 29. Sg5-f7 Kh6-h5 30. Th2-h3 Kh5-h6 31. Sh3-g5 b5-b4 32. Sg6-h4 b6-b5 33. Se7-g6 b7-b6 34. Sg8-e7! a5-a4 35. g7-g8=S a6-a5 36. g6-g7 Kh6-h5 37. h5xg6ep+ g7-g5 38. Sg5-h3+ a7-a6 39. Th3-h2 Sh2-g4 40. Dh4-f4 Sf4-g2 41. Lg2-h1 Sg4-h2 42. Th1-h3 Sh2-g4 43. Lh3-g2 Sg4-h2 44. g2-g3 Sh2-g4 45. Dg4-h4 Tg3-f3 46. Dd1-g4
play all play one stop play next play all
5 weiße Schlagfälle durch Bauern: axb, c3xd4, exf, f5xe6 & hxg; zwei Umwandlungen auf b8 und eine auf g8. Eine schwarze Umwandlung auf c1. Die weißen Figuren, die zur Entwandlung zurückschreiten können, sind die schwarzfeldrigen Lh8 und g5 sowie der retrofreie Sg1. Aber vor jeder Entwandlung muß Weiß das Feld h2 räumen, um dem Sg4 das Pendeln zu ermöglichen und so ein schwarzes Retropatt zu verhindern.
Retro: 1. Sg2-h4+ Sh4-g6+ 2. h7-h6 Se2-g1 3. a3-a2 Tg1-f1 4. a4-a3 Sf1-h2 5. Sh2-g4 Lh6-g5 6. Sg4-h2 Lg7-h6 7. Sh2-g4 Lf8-g7! 8. Sg4-h2 Ld6-f8 9. ~ Lb8-c6 10. ~ Sc3-e2 11. ~ Sb5-c3 12. ~ Sd6-b5 13. ~ Sf7-d6 14. ~ b7-b8=L 15. ~ b6-b7 16. ~ b5-b6 17. ~ b4-b5 18. ~ b3-b4 19. ~ Lg7-h8 20. ~ Lf8-g7 21. ~ Ld6-f8 22. ~ Lb8-d6 23. ~ b7-b8=L 24. ~ b6-b7 25. ~ b5-b6 26. ~ b4-b5 27. Sh2-g4 a3xb4
Nach diesem Entschlag des schwarzen Bb führt die dritte Entwandlung auf g8 zu einem erzwungenen En-passant-Schlag. 28. Sg4-h2 Sg5-f7 29. Kh6-h5 Th2-h3 30. Kh5-h6 Sh3-g5 31. b5-b4 Sg6-h4 32. b6-b5 Se7-g6 33. b7-b6 Sg8-e7! 34. a5-a4 g7-g8=S 35. a6-a5 g6-g7 36. Kh6-h5 h5xg6ep+ 37. g7-g5 Sg5-h3+ 38. a7-a6 Th3-h2 39. Sh2-g4 Dh4-f4 40. Sf4-g2+ g2-g3 41. Tg3-f3
Diese Zugfolge mit möglichen Zugumstellungen kann nicht verkürzt werden. Mindestens 71 Einzelzüge sind nach dem En-passant-Schlag geschehen. Rekord für eines der Themen des 173. Thematurniers der "Schwalbe".
paul: This problem obtained first Prize in the informal tourney, see Die Schwalbe 249/2011 (judge M. Caillaud) (2020-01-06)
Henrik Juel: 41.g2-g3 is illegal, because now wLh1 cannot retract (2021-02-03)
Henrik Juel: 41.Lg2-h1 Sg4-h2 42.Th1-h3 Sh2-g4 43.Lh3-g2 Sg4-h2 44.g2-g3 Sh2-g4 45.Dg4-h4 Tg3-f3 46.Dd1-g4 seems to work (2021-02-03)
comment
Keywords: En passant, En passant in the retro play, Non-standard material, Promotion, Last Moves? (72)
Genre: Retro
FEN: 7B/8/4PPNp/4pKBk/3PrQnn/3pBrPR/p2P1p1N/4bRNB
Reprints: 568 Ukrainisches Album 1986-1990
H21 FIDE Album 1986-1988 1995
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-02-04 more...
4 - P0000324
Josef Haas
8259 Die Schwalbe 143 10/1993
P0000324
(7+5)
a) Wer setzt in 1 Zug matt?
b) Auf welchem Feld muß ein schwarzer Bauer eingefügt werden, damit die andere Partei als in a) mattsetzt?
b) (+sBc7) 1. ... Lg8xe6#
a) 1. Tg6#
1) R: 1. ... Kg6xBf6! 2. g5xf6ep++ f7-f5 3. La2-b1+
play all play one stop play next play all
"Vermutlich aus der Kleinkunstkiste des Autors hervorgekramt.
a) sollte einfach formuliert sein: 'Matt in 1 Zug' - denn wie es hier heißt, klingt es als ob nur einer mattsetzen kann. Das aber ist nicht der Fall, denn beide können's: 1. ... Lxe6# und 1. Tg6#. Üblicherweise hat Weiß das Prae und kann darauf pochen, den Schwarz hat einen altklassischen letzten Zug: 1. ... Kg6xBf6! (nebst 2. Bg5xBf6ep++ Bf7-f5 3. La2-(x)b1)" (HHS);
also ist Weiß am Zug und setzt matt mit 1. Tg6#.
b) Nach Einfügen eines sBc7 geht die o.g. Rückzugfolge nicht, weil der wK nicht auf die 8. Reihe gelangen kann. Also Schwarz am Zuge und 1. ... Lxe6#
"Allzubekanntes - kein Problem für Schwalbelöser" (HHS)
Wenn das alles so bekannt ist, erstaunt doch sehr, daß nur drei Löser die Autorintention nachvollziehen konnten. Alle anderen Löser (5) kamen zu genau entgegengesetzten Erkenntnissen (in a) setzt Schwarz matt, in b) Weiß), was wohl durch die nicht ganz konventionelle Formulierung suggeriert wurde. Ich find's ein interessantes Beispiel für Massenhypnose! (GL) 2/I/3L.
vergl. P0004915 (Hans Gruber, Schach 1979)
Brassaud: La solution proposée 1/Tg6# est possible
Mais il y a aussi le rétro jeu -1) Fa2-b1, Rg5g6 -2) Ta4-a5+, Rf4-f5 etc … et avec le trait aux noirs : 1) Fxe6 # est possible (2017-08-30)
A.Buchanan: @Brassaud: yes I agree. There is no reason why White should not have moved last. So both players can mate, but part (b) implies that the intended solution in (a) is 1 player. If the published stipulation for (a) was maybe just "#1", which by default is white to move, then there is a unique solution.
For (b) I am wondering about +sBg6, which would also stop the en passant trick, both by blocking sK from retreating there and also by locking sL in an impossible cage with sBf7. (2017-08-31)
Henrik Juel: Adding a black pawn on g6 of course prevents a black last move by Kf6, but it allows f7xg6 as last move; Lg8 is not locked, because Ph7 is white (2017-08-31)
A.Buchanan: Yes (2017-08-31)
Anton Baumann: vergl. P0004915 (Hans Gruber, Schach 1979) (2023-01-03)
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comment
Keywords: Add pieces, No legal last move for Black, En passant in the retro play
Genre: Retro
FEN: 4K1br/1p4pP/4Pk2/R7/3P4/8/8/1B4R1
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2023-01-03 more...
5 - P0000772
Klaus Wenda
1419 Die Schwalbe 30 12/1974
4. ehrende Erwähnung
P0000772
(4+7)
Weiß nimmt 1 Zug zurück, dann #2
b) sBh7 nach b6
a) R: 1. Kd5-e4, dann 1. Kd6
b) R: 1. dxc6ep, dann 1. d6
play all play one stop play next play all
In a) ist die s0-0-0 nicht mehr möglich, weil sich das Schach durch den sLg8 nur durch Kf7(x)e8 erklären läßt, in b) muß mindestens einer der sTT via e8 auf seinen Diagrammplatz gelangt sein.
In a) Entschlagdual R: Kd5xBe4, das wurde in der Lösungsbesprechung noch kritisiert und als NL vermerkt. Hat das der PR gelassener gesehen ('geduldeter Entschlagdual'), oder gibt's noch eine korrigierte Version dieses Problems?
Anton Baumann: Korrektur in 'Die Schwalbe' 12/1975 S.422: +sLh2, +sBe5;
nun geht in a) nur noch zurück: Kd5 x Be4.
Ausgezeichnet wurde gem. Preisbericht in 'Die Schwalbe' 06/1977 S.82 die korrigierte Version 1419v. (2022-12-08)
comment
Keywords: Castling (sg), Help retractor, En passant in the retro play, Cant Castler (sl)
Genre: Retro
FEN: r3k1bR/pr1p3p/2P5/8/2B1K3/8/8/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-02-10 more...
6 - P0003366
Laszlo Lindner
3040v Europe Echecs 07-08/1982
P0003366
(8+16)
h#2
b) sBc7 nach f6
a) 1. Dc4 Lxb6+ 2. c5 dxc6ep#
b) 1. fxe3ep Lxb4 2. Sc4 bxc3#
play all play one stop play next play all
Lindner in 'Mattbilder eines Lebens':
In a) ist die Lösung der stellung b) nicht möglich, weil das e.p.-Schlagen durch Schwarz nicht legal ist. Der letzte Zug von Weiß muß nicht unbedingt e2-e4 geweseb sein. Es kommt als letzter zug auch Kh3-g2 in Betracht, mit den vorherigen Zügen h4:g3 e.p.+ und g2-g4.
In b) demgegenüber sind Kh3-g2 und vorher f4:g3 e.p. illegal, weil die Rücknahme von g2-g4 unmöglich ist: der sB würde 7 Schlagfälle benötigen, und es fehlen nur 6 weiße Steine. Der letzte weiße Zug muß also e2-e4 gewesen sein.
In 'Mattbilder eines Lebens' abgedruckt mit sTh7 statt h8 und der Quellenangabe: Europe Echecs, 1964
AB: (1) Where is wK?
(2) Why is 1.fxe3ep legal in b) but not a)? (2002-01-31)
Henrik Juel: wK is probably on g2. In part a) last move could have been Kh3-g2, I think (2002-02-01)
A.Buchanan: Very convincing, Henrik. I've repaired the diagram accordingly. (2023-05-28)
comment
Keywords: En passant as key, En passant in the retro play
Genre: h#, Retro
FEN: 7r/2pn4/1nqRb3/B2Pp3/pb1kPp2/2p2Pp1/1PP2pKp/7r
Reprints: 501 Mattbilder eines Lebens , p. 379, 1996
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2023-05-28 more...
7 - P0003973
André Simonet
RA166 diagrammes 74 11-12/1985
Lob
P0003973
(6+8)
Die Position wurde nach 22 konsekutiven Schachgeboten erreicht. Finde die Anfangsposition heraus, dann #1! Kein Dual oder Vertauschen von Zügen ist erlaubt.
R: 1. ... b4xc3ep+ 2. c2-c4 Lf5xDd3+ 3. Df1xDd3 De4xDd3 5. Df3xDd3 De2xTd3 6. Te3-d3+ Td3-b3+ 7. Tc4xDc6+ Dh6xDc6+ 8. Dg6-c6+ De8xTd7+ 9. Tc7-d7+ Sd7xSb6+ 10. Sa4-b6 Ta7xDb7+ 11. Da8xDb7+ Dc8-b7+ 12. Tb7xSc7+ Sa6xSc7+ 13. Se6-c7+
play all play one stop play next play all
James Malcom: It seems likely that this could be cooked. (2021-01-23)
Hans-Jürgen Manthey: wenn man dem Player bis zum ende folgt und dies die Anfangsposition sein soll, ist die 2. Bedingung 'dann #1' nicht möglich ! Also ist es nicht gelöst und es muß eine andere Zugfolge nötig sein ! (2021-01-23)
Hans-Jürgen Manthey: mögliche Zugfolgen:
1. h4 b5 2. g4 Lb7 3. Sh3 La6 4. Lg2 Lc8 5. h5 c5 6. g5 c4 7. g6 c3 8. dxc3 d5 9. c4 e5 10. c5 f5 11. c6 f4 12. c7 f3 13. Kd2 d4 14. Kd3 b4 15. Kc4 fxe2 16. f4 e1D 17. f5 e4 18. f6 e3 19. a4 Lc5 20. a5 Lb6 21. axb6 Sh6 22. b7 Sg4 23. h6 e2 24. Ld5 Lf5 25. c8T a5 26. Kb5 Sa6 27. b8D Ta7 28. Da8 Se5 29. Sf4 a4 30. Sc3 Sd7 31. La2 a3 32. hxg7 Dg1 33. Tc7 Dc8 34. Tb7 Kd8 35. f7 De3 36. g8D+ De8 37. g7 h5 38. Dg1 d3 39. Dg6 h4 40. Sa4 Ke7 41. Se6 Kd6 42. Lg5 h3 43. Tag1 d2 44. Tg4 h2 45. Tc4 e1D 46. Lb1 Th3 47. Dh8 Td3 48. g8D Kd5 49. Dhh3 De4 50. Dgh8 a2 51. D8h5 a1D 52. La2 Dae1 53. Dg2 D1h4 54. Dhf3 Dh6 55. Te1 h1D 56. Te3 De1 57. Dgf1 De2 = Anfangsposition, aber kein Matt in 1 Zug
(57. ... Df2 58. Lf4 De2 = Anfangsposition mit Matt in 1 Zug: 59. Td4#)
es folgen die 22 Schachgebote bis zur Diagramstellung mit Lg5:
58. Sc7+ Sxc7+ 59. Tbxc7+ Db7+ 60. Dxb7+ Txb7+ 61. Sb6+ Sxb6+ 62. Td7+ Dxd7+ 63. Dc6+ Dhxc6+ 64. Txc6+ Tb3+ 65. Td3+ D2xd3+ 66. D3xd3+ Dxd3+ 67. Dxd3+ Lxd3+ 68. c4+ bxc3ep+ (ist auch möglich mit Lf4) (2021-01-24)
comment
Keywords: Consecutive checks (22), Help retractor, En passant in the retro play, Non-standard material, En passant
Genre: Retro
FEN: 8/1r1q1P2/1nR5/1K1k2B1/8/1rpb4/BP1p4/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-07-30 more...
8 - P0004711
Karl Fabel
Berliner Morgenpost 1943
P0004711
(8+7)
Weiß nimmt 1 Zug zurück, dann #1
R: 1. bxc6ep+, dann 1. dxc6ep#
play all play one stop play next play all
Adrian Storisteanu: A try may be worth mentioning: - 1.c5-c6+?? & 1.d5-d6# (fails due to retrostalemate). (2021-04-19)
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Keywords: Help retractor, En passant, En passant in the retro play, En passant in the forward play
Genre: Retro
FEN: 2brrb2/1R1pkPp1/2P5/3P1K2/1B1P4/8/B7/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-04-19 more...
9 - P0005379
Anatolii Vasylenko
6493 feenschach 107 01-09/1993
Lob
P0005379
(5+2)
a) h#2
b) -1(w+s), dann h#2
a) 1. Kf7 Lg6+ 2. Kg8 f7#
b) R: 1. exf6ep+ f7-f5, dann 1. Kg5 Sf6 [A] 2. Lh4 Lc1# [B]
Nicht: R: 1. g5xf6ep+ f7-f5, dann 1. Kh5 Lc1 [B] 2. Lh4 Sf6# [A], weil das Schach durch den wLb1 nach Rücknahme von Bf7-f5 illegal wäre.
play all play one stop play next play all
Autor: "Originelle Zwillinge mit 3 Modellmatts."
FM: "Hübsch, wenngleich die Zwillingsbildung wohl zwangsläufig den ep-Effekt erfordert."
Aber welchen? Das war hier die Frage! Die Verführung sah offenbar kein Löser?!
MR: "Beeindruckend ökonomischer ep-Witz mit hübschen Mustermatts." 2,5/I
Henrik Juel: part a) is C+ Popeye 4.61 (2021-04-14)
comment
Keywords: En passant in the retro play, Help retractor, Stipulation change, Miniature, Model mate (3)
Genre: Retro, h#
FEN: 8/3N4/5Pk1/8/8/8/KB6/1B2b3
Reprints: feenschach 142, p. 166, 07/2001
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-04-14 more...
10 - P0005849
E. A. von Vegesack
Danziger Neueste Nachrichten 1941
P0005849
(5+3)
Welches waren 4 Einzelzüge?
R: 1. fxe6ep+ e7-e5 2. Kd4xSc5 Se4-c5
play all play one stop play next play all
In 'Probleme für Tiger' nachgedruckt mit der Forderung: "Welches waren die letzten zwei Züge von Schwarz und Weiß?"
Axel Steinbrink: Hinweis von Bernd Schwarzkopf: Der letzte Zug ist nicht eindeutig: auf c5 hätte auch ein beliebiger schwarzer Stein geschlagen worden sein können. (2020-12-20)
Henrik Juel: I think that any white man (not black) could have been captured on c5
But the last 3 single moves are determined (2020-12-20)
Hans-Jürgen Manthey: die Lösung ist eindeutig!
Der wK muß d4xc5 geschlagen haben, und da der wK auf d4 im schach stand und der sT weder von a5 noch von a3 gekommen sein konnte, muß der zug sSe4-c5+ vor dem wK schlag gewesen sein. Also:
1... Se4-c5+ 2. Kd4xc5+ e7-e5 3. f5xe6ep+ (2020-12-21)
A.Buchanan: Hi Hans-Jürgen, Sie haben Recht mit den ersten "dreieinhalb" Zügen. Henriks Idee ist, dass Ne4-c5 ein Schlag eines unbekannten Steins sein könnte. Normalerweise müssen wir das genaue Diagramm vor dem Zug kennen, um einen Zug klar zu charakterisieren. (2020-12-21)
Hans-Jürgen Manthey: A.Buchanan ist es denn wichtig ob ein w Stein auf c5 geschlagen worden ist, oder nicht ? Auf jedenfall muß ein sS von e4 nach c5. (2020-12-21)
A.Buchanan: Hans-Jürgen, heute halten wir es für wichtig, weil Wir haben Rekorde für z.B. "Letzten 17 Einzelzüge?" brauche also eine einheitliche Definition von "Zug". Manchmal ist die Forderung eines älteren Problems auf diese Weise ungenau, aber nicht kaputt. (2020-12-22)
Hans-Jürgen Manthey: Ich hätte da eine Idee:
das Diagramm wird vervollständigt mit wBa2,b3,c2,d2,e2,g3 wLh1 wSb1,g1 wTc1 wDd1. Nun ist es nicht mehr möglich eine weiße Figur zu Schlagen! :-) (2020-12-23)
Mario Richter: Shouldn't the stipulation be: "Welches waren die letzten 4 Einzelzüge?" or "Letzte 4 Einzelzüge?
And, imho, the problem is cooked. Jans-Jürgen's suggestion would make the problem correct, but at the cost of much too much material. (2020-12-24)
A.Buchanan: The stipulation field in PDB has always been used to communicate the solvable intent of the composition. Stipulations have been rewritten by Gerd or others where necessary. What we lack is an Originalforderung field. But we can fake that in the Comment field. It hardly breaks the problem to change stip to 3 from 4 (2020-12-25)
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comment
Keywords: Last Moves?, En passant in the retro play
Genre: Retro
FEN: 8/8/4Pk2/2K4p/7r/7P/8/B4R2
Reprints: 255 Probleme für Tiger 2 04/1986
2318 Landeszeitung für die Lüneburger Heide 16/06/2012
Input: Gerd Wilts, 1995-06-21
Last update: A.Buchanan, 2020-12-25 more...
11 - P0006274
Tivadar Kardos
6460 FEENSCHACH 09-10/1963
P0006274
(5+6)
-1s, dann h=2
R: 1. ... cxb3ep, dann 1. Sb1 0-0 2. Sa3 Txa1=
play all play one stop play next play all
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comment
Keywords: En passant in the retro play, Help retractor, Castling, En passant
Genre: Retro, Fairies
FEN: 8/8/8/1p6/k7/1pP2p2/2Pn1P2/n3K2R
Input: Gerd Wilts, 1995-08-20
Last update: A.Buchanan, 2024-01-18 more...
12 - P0008675
Valeriu Petrovici
(VII) Quartz 4 1997
P0008675
(10+8) cooked
Schwarz nimmt 3, Weiß 2 Züge zurück, dann h#1
R: 1. ... h4xg3ep 2. g2-g4 e2xTd1=L 3. Sc6-d4 0-0, dann 1. Tf7 Td8#
play all play one stop play next play all
Cook: R: 1. ... h4xg3ep+ 2. g2-g4 e2xTd1=L+ 3. e3-e4 Td8xTd7, dann 1. c1=T Dh7#
R: 1. ... h4xg3ep+ 2. g2-g4 e2xTd1=L+ 3. Sf5xLd4 Td8xTd7, dann 1. Lh8 Sxh6#
R: 1. ... h4xg3ep+ 2. g2-g4 d2-d1=L+ 3. e3-e4 Kf7xSg8, dann 1. c1=T Dg6#
Korrektur s. P1402012
Henrik Juel: -1... h4xPg4ep -2.g2 e2xTd1=L -3.Sc6 0-0, 0... Tf7 1.Td8#. (2004-09-09)
Mario Richter: Lots of Cooks, e.g.
R: 1. ... h4xg3ep+ 2. g2-g4 d2-d1=L+ 3. e3-e4 Kf7xSg8, dann 1. c1=T Dg6# (2022-06-17)
James Malcom: Seems the diagram is wrong then. Perhaps something like +sBd2 will fix it? (2022-06-17)
James Malcom: Wait, nevermind on the fix idea. (2022-06-17)
Mario Richter: Hi James, there is already a correction by the author himself, s. P1402012. (2022-06-18)
James Malcom: Thank you, Mario. It only took 25 years to find its way into PDB! The online Quartz archive dates back only to 2007. (2022-06-18)
Mario Richter: James, you may want to take a look at http://www.stere.ro/, where I think a complete run of all 'quartz' issues, starting with the very first number 1 of 1996 can be found ... (2022-06-18)
more ...
comment
Keywords: Help retractor, Valladao Task, Promotion in the retro play (l), Castling in the retro play (sk), En passant in the retro play, Superseded by (P1402012), Castling (sk), Promotion (l), En passant
Genre: Retro
FEN: 5rk1/3r4/7b/7K/2PNPP2/2P3p1/PPp2P1q/1Q1b4
Input: Gerd Wilts, 1997-06-11
Last update: A.Buchanan, 2022-07-10 more...
13 - P0008794
Alexandr A. Klibanski
2 Shakhmaty v SSSR , p. 31, 07/1977
P0008794
(14+4)
#1
1. Tb1#
zuletzt geschah
R: 1. ... Kc2-b2 2. e5xf6ep+ f7-f5 3. e4-e5+
oder
R: 1. ... Kc1-b2 2. 0-0+
oder
R: 1. ... a2-a1=L
play all play one stop play next play all
weiße Bauernschläge: axb3,b2xc3xd4xe5xf6,c2xd3xe4xf5xg6xh7-h8=L,e2xfxg = 12 Schläge, alle fehlenden schwarzen Steine sind erklärt, insbesondere hat der wBh2 nie die h-Linie verlassen.
Der sBh4 stammt also entweder von f7 (2 Schläge) oder von h7 (ebenfalls 2 Schläge, um den wBh2 vorbeizulassen). Damit sind auch alle fehlenden weißen Steine erklärt. Da zu diesen auch der schwarzfeldrige wLc1 gehört, kann zuzletzt nicht h5-h4? geschehen sein ('Shakhmaty v SSSR' nennt das "Farbeffekt").
paul: La question est si les Blancs sont a jouer et le reponse est affirmative. Les seuls retro-jeux plausibles sont:
1.Rc1-b2 0-0;
1.Rc2-b2 e6xf6 e.p. 2.f7-f5 Tg6-a6+;
1.a2-a1F.
Donc le task Valladao. Le coup matant est 1.Tb1#
Est interessant a voir pourquoi ne va pas le retro-jeu h5-h4?.
L?analyse demontre que le seul Pion blanc transforme en en h8 a ete Pc2 et la sequence des coups a ete c2xd3xe4xf5xg6xh7-h8F. Le P blanc h6 vient de h2 sans captures, donc le P noir h4 a effectue deux prises, don?t une d?un F blanc de camps noirs. Donc h5-h4 est illegal. (Quartz 4/1997) (2010-03-22)
Henrik Juel: For the benefit of readers, whose French is a bit rusty:
Paul points out that the retroplay given on top is incorrect. Ph4 is [Pf7] who captured the dark-squared [Lc1] on its way to h4; so its latest move was g5xh4, not h5-h4. (2010-03-26)
Paulo Roque: Henrik:
Not R: 1.h5-h4. See also that [Pa7] was promoted in the square a1, at some point. But I think also possible Ph4 is [Ph7], by: h7xg6-g5xh4 or h7-h6xg5xh4 (2010-03-27)
Henrik Juel: You are right, Paulo; my mistake, not Paul's. I should have written: Ph4 is [Pf7] or [Ph7], who captured the dark-squared [Lc1] on its way to h4; so its latest move was g5xh4, not h5-h4. (2010-03-27)
James Malcom: Question: What prevents the Black king from going to c1 after castling is retracted? (2022-06-17)
comment
Keywords: En passant in the retro play, Castling, Promotion in the retro play, Valladao Task
Genre: Retro
FEN: 6NB/Q5pB/R4P1P/6P1/7p/1P4P1/1k1P1P2/b4RK1
Reprints: (V) Quartz 4 1997
Input: Gerd Wilts, 1997-06-21
Last update: Mario Richter, 2022-06-17 more...
14 - P1035188
Norman Alasdair Macleod
The Christian Science Monitor 1947
P1035188
(3+5) C+
#2
1. Kg2! droht 2. Txc8#
Nicht 1...0-0?? da der sK schon gezogen hat: R: 1. h4xg3ep+ g2-g4 2. Kd7-e8+,Kd7xSe8+,Kd7xTe8+
play all play one stop play next play all
BS Problemid: 20117
Authors: Macleod, Norman A
Sources:
Years: 1947
Mario Richter: vgl. mit P1012182 (2011-05-28)
more ...
comment
Keywords: Brian Stephenson Collection (20117), En passant in the retro play, Cant Castler
Genre: 2#, Retro
Computer test: HC+ Popeye 4.61 + trivial retro logic
FEN: R1b1k2r/1Q6/8/8/8/6pK/7b/8
Input: Brian Stephenson, 2004-08-12
Last update: A.Buchanan, 2024-02-27 more...
15 - P1277178
Rasmus Peter Larsen
5 Skakbladet 18/09/1904
P1277178
(4+4) C+
-1w, dann #1
R: 1. c5xb6ep dann 1. Tb6#
play all play one stop play next play all
Originalforderung: Hvid tager sidste Traek tilhage og goer derpaa Mat straks.
Adrian Storisteanu: Shifting all pieces one file right, with wPh7 falling off the board, makes it a miniature:
Kg4 Rc8 Re7 c6 / Kg6 Rc1 Bb3 (4+3)
- 1.d5xc6ep & 1.Rc8-c6# (2021-04-21)
more ...
comment
Keywords: Help retractor, En passant in the retro play
Genre: Retro
FEN: 1R6/3R3p/1P3k2/8/5K2/b7/8/1r6
Input: Mario Richter, 2013-09-03
Last update: Mario Richter, 2013-09-03 more...
16 - P1375497
Iosif Schlarko
Valerian Onitiu

F19 Skakbladet 15, p. 172, 09/1923
P1375497
(1+11) C+
-1(w+s), dann h#4
R: 1. Ke3xBd3 Be4xd3ep, dann 1. Dg7 dxe5 2. Kh6 exf6 3. g5 fxg7 4. Tg6 gxh8=D#
play all play one stop play next play all
A.Buchanan: Corrected typo: Tf6g6 are really pawns in the skakbladet diagram (2020-09-18)
Mario Richter: also C+ with rawbats (2020-09-20)
comment
Keywords: Help retractor, En passant in the retro play, Promotion in the mating move, Rex solus (w)
Genre: Retro
Computer test: rawbats for retro play ^=& Popeye v4.85 for the forward play
FEN: 7n/q7/2r2pp1/3pr1k1/8/3K1n2/8/3bb3
Input: Mario Richter, 2020-05-04
Last update: A.Buchanan, 2020-09-21 more...
17 - P1375499
Iosif Schlarko
Wolfgang Pauly

F20 Skakbladet 15, p. 172, 09/1923
P1375499
(4+14)
-3w,2s, dann h#2.5
R: 1. Ke3xBd3 Be4xd3ep 2. Bd2-d4 Dd7-a7+ 3. Kf4-e3 (g7-g5+), dann 1. hxg6ep+ Ke8 2. g7 Te7 3. g8=D#
play all play one stop play next play all
T.R. Dawson zu dieser Aufgabe und P1375497: "Two interesting combinations of retraction play with helpmating; the elementary exhibition of the PxPe.p. retraction, as in these problems, must soon be abandoned however, I think in favour of greater elaborations."

Originalforderung: Hvidhar trukket sidst. 3 Træk tidligere var det muligt, at Hvid ved Sorts Hjælp kunde gøre Mat i 3 Træk. Hvorledes?
Klarstellung Heft 18 (December 1923) S.211: "For ikke at misforstaans, burde Fordringen lyde '3 hvide Træk tidligere' etc. -"
Walter Lindenthal: Wie wäre es mit einer wDa7:
R 1.Ke3xBd3 Be4xd3ep 2.Bd2-d4 Dd7xDa7+ 3.Da~-a7
& vor 1.wDa7-a8 Ke7-f6 2.Da8-g8 Dd7-e7 3.Dg8-g6# (2020-09-15)
Walter Lindenthal: Korrektur Flüchtigkeitsfehler in der NL:
... & vor 1.wDa~-a8 ... (2020-09-16)
A.Buchanan: Yes Walter something not quite right. Maybe wP missing from diagram. But even then g7-g5 is not forced so how is the White e.p. ok? (2020-09-17)
Walter Lindenthal: It's not ok with today's rules! (That's why my solution avoids it). As far as I understand, the ep-rules were handled differently in that time (1923!), ep had not to be 'forced'. As Dawson (above) seems to hint to that fact ("... must soon be abandoned...") (2020-09-17)
Walter Lindenthal: And I do not think a wP (or any other w piece) is missing mistakenly! The idea seems to be that the wK MUST start to retract into fields EACH threatened twice, so only the (first) ep can R-save the wK. And if there is NO additional wP (or a wQ like mine) then again ONLY the wK can retract. And such he is "forced" into the next threat, where the second ep would R-save him again and finally lead to mate. If there is no second ep (old style 1923!) then there's no mate in h#2.5. So, any (rectractable) additonal w piece would destroy this tactic (like my wQa7 does by eliminating the need for wK's move e3-f4 into the second threat from bPg5). The only point is if this additional w piece can establish a different mate in h#2.5 (as my wQ can). (2020-09-17)
A.Buchanan: Hi Walter, thanks for your responses. I checked skakbladet: the diagram, stipulation and intended solution are accurate. However by 1915 (Dawson & Hunsdorfer "Retrograde Analysis" page 111), the notion of analytic en passant was already established. Moreover, the other problem (P1375497) that Dawson apparently mentioned does *not* contain a forward en passant, so I think he was referring to the simplistic retro logic present in both. Maybe Dawson was being polite in his criticism of the unproven forward e.p. here.
So how about the chess? Is Dd7xDa7+ & Kf4-e3 the only retraction which leads to any #2.5? It seems that other retractions might at least be possible: e.g. S~-b3, T~-c4, D~-a7, and any of them could be any uncapture. Maybe I will look at this later, but I must go now. (2020-09-18)
Walter Lindenthal: Hi Andrew, thanks for the clarifying info! So, the "unproven ep"-issue was decided even before 1923 (I just assumed because of Dawson's comment...), but then the problem would have been broken from start! Of course, some other retractions might be possible, too, but I have not analysed any other one if it could lead to a h#2.5 solution. My only intention with wQa7 was to show that the intended solution was not the only one possible, so it's cooked. (2020-09-18)
Mario Richter: The intended solution is the only possible one (checked with 'rawbats'), if we accept that g7-g5 preceeded the other retractions (perhaps the idea was help-play in the retractions).
The suggested R 1.Ke3xBd3 Be4xd3ep 2.Bd2-d4 Dd7xDa7+?? doesn't work (illegal black pawn structure)! (2020-09-20)
Walter Lindenthal: Hi Mario - GREAT, yes, you're right! The bBe1 is the 'killjoy'... 5+7+4=16, there is no room for ANY additional w stone! thanks! (2020-09-21)
comment
Keywords: Help retractor, En passant in the retro play, En passant as key, Promotion in the mating move
Genre: Retro
FEN: 8/q3k3/2p4p/3pr1pP/2r3pp/1n1K4/5P1P/1n1bb3
Input: Mario Richter, 2020-05-04
Last update: A.Buchanan, 2020-09-21 more...
18 - P1380127
Nikola Predrag
(32) MatPlus.net Forum 15/8/2019
P1380127
(8+11)
-1(s+w), dann #3?
R: 1. c4xb3ep b2-b4, dann 1. Sc3+ Kc2 2. Dd3+ Kxd3 3. 0-0-0#?!
But castling is illegal! This is because Black's dark squared bishop is a promoted piece and White's king must have moved to let the promotion through.
play all play one stop play next play all
http://matplus.net/start.php?px=1600656376&app=forum&act=posts&tid=2343&fid=xshows&page=1
Henrik Juel: Removing wPh2 might help (2020-09-21)
James Malcom: The illegality of the castling is intentional. (2020-09-21)
A.Buchanan: I guess it is intended as a joke. There are numerous cooks e.g. R: 1. Dh1xDh5 Td6-b6 dann 1. Sb2-d2+! (2020-09-22)
James Malcom: Andrew, the White king is in check from the Black bishop. Ep is the only legal way to resolve it. Your suggestion is illegal. Did you forget to eat breakfast again? :) (2020-09-23)
A.Buchanan: Ha this is just like when I play chess otb - so hard to spot extraordinarily distant black pieces on dark squares :-) (2020-09-23)
James Malcom: Sounds fair enough to me! And the position is legal, not illegal, Andrew. (2020-09-23)
A.Buchanan: I meant "no solution" - and I've classified it as a joke which I think is the composer's intent (2020-09-24)
James Malcom: Quite simply, I agree. (2020-09-24)
Mario Richter: I think the "normal usage" of the keyword "no solution" in the PDB so far is to indicate, that the intended solution fails e.g. because of some hidden defense (which corresponds to the german "unlösbar").
This problem doen't fall into that category! In fact, it has as solution, namely that there is no mate in 3 after the (forced) retractions!
(There are 1064 cooked problems with the keyword "no solution", only 9 "no solution" problems with the label "C+", and for all of the latter either the "no solution" or the "C+" is wrongly attributed.
Perhaps the simplest way to handle the Pedrag-problem is to add "intended" to the KW "no solution". (2020-09-25)
James Malcom: I agree, Mario. It is now doe. (2020-09-25)
A.Buchanan: Yes that's fair. Most jokes follow a template, but this is quite original. (2020-09-25)
more ...
comment
Keywords: Belen Theme, Valladao Task, Help retractor, Castling as mating move, En passant in the retro play, Obvious promotion, Joke, no solution (Intentional), Cant Castler (wg)
Genre: Retro, 3#
FEN: 8/1pppp1p1/1R6/b6q/6N1/rp5Q/p5PP/RNk1K3
Input: James Malcom, 2020-09-21
Last update: Mario Richter, 2020-10-07 more...
19 - P1381571
Jeff Coakley
50 The Puzzling Side of Chess 191, p. 14, 30/6/2020
P1381571
(14+8)
Welches waren die letzten 10 Einzelzüge?
R: 1. h4xg3ep+ g2-g4 2. Te6-e2+ c5xb6ep+ 3. b7-b5 c4-c5+ 4. Kb6-a6 b5xc6ep+ 5. c7-c5 Sd4-f3+
play all play one stop play next play all
https://www.canadatype.com/cc/puzzlingside/archives/Puzzling_Side_191_Retro_World_V_Momentary_Lapse_in_Time.pdf
Henrik Juel: Three ep captures in the retroplay was first shown 105 years ago, P0002031 (2020-11-06)
James Malcom: Many, many thanks for that Henrik! However, this seems to be the first bicolor 3 ep representation?!

Also, how many other 3 ep retractor showings are there? I have only found a few: P0000018 (cooked), P1193561, and P1193562 come with a hoard of promoted pieces, and P0000326, P0002591, and P0002031 are all "proper" retractors, but all of them are one-sided. (2020-11-06)
Henrik Juel: James, you might want to try to find the first example of 4 ep captures in the retroplay
The best chance is probably bicolor (2020-11-06)
Henrik Juel: In the proof game genre, which is easier than the last moves? one, the current PDB records are
Orthodox: 3 ep captures, P1000929
Madrasi: 8, P0005964
Circe Parrain: 10, P1095546 (2020-11-06)
James Malcom: Henrik, the fairy record actually is- Anti Take & Make: 13. P1380673
I know of the solution thanks to Juraj, the fairy master, on Matplus.
Also- Monochrome: 3, P1240593

And indeed, 4 is likely is more possible with bicolor, as 4 by one side can only be done with at least one promoted piece Q/B, which may very well be frowned upon no doubt.

And also on an interesting note, in fairy retractors, it seems that 5 has been done at the least in a VRZ, Typ Proca, P0003873. (2020-11-06)
James Malcom: Actually, it turns out that the bicolor representation has been done before, no shocker there: 1969, P0004900 & 1994, P0004497 I've tagged all of these showing under "ep in retroplay' for better clarity and searching. (2020-11-07)
comment
Keywords: Last Moves? (10), En passant in the retro play
Genre: Retro
FEN: 2R1R3/p2b3p/kPP4P/n5Pr/1Q6/1P3NpK/2P1r2P/5BB1
Input: James Malcom, 2020-11-06
Last update: James Malcom, 2020-11-06 more...
20 - P1382586
James Malcom
Andrew Buchanan

chess.stackexchange.com 30/11/2020
P1382586
(15+2) C+
-1w, dann =1
R: 1. e5xf6ep#, dann 1. Sxf5=
play all play one stop play next play all
https://chess.stackexchange.com/a/24903/15543
Henrik Juel: Not R: 1.Le2-g4+?, because Black then has no previous move available
R: 1.e5xf6ep f7-f5 2.Le2-g4+ Kf6 etc. (2020-11-30)
Mario Richter: Cook: R: 1. Tf5-d5, dann 1. Ta7,Tb7,Tc7,Tf7,Td1,Td2,Td3,Td4,Tdd5,Td8=

The retroplay may continue: 1. ... Ke5-e6 2. Tf4-f5+ Ke4-e5 3. Tf5-f4+ Kd4-e4 (2020-11-30)
James Malcom: Ohhh, yikes. Hmm, we still do have an extra Whtie knight to use, however. Placing it on c6 prevents a BK retraction to e5, plus it doesn't interfere with the other knight. (2020-11-30)
Mario Richter: With James' correction +wSc6 the Problem is C+. (2020-11-30)
Mario Richter: Btw., there was a series of articles by Theodor Steudel in 'feenschach' with the title "Weiße Zugrüccknahmen mit Umwandlungs- und Forderungswechsel", amongst others they also covered a stipulation "PsM" (Patt statt Matt), see 'feenschach 60 (Mai 1982) and 'feenschach' 79 (Jul-Sep 1986). (2020-11-30)
James Malcom: Thanks for the hand, Mario, and I do agree that a minor correction here shall suffice. I've also gone and fixed the original source. I think that no further changes are merited, as to keep the original form as intact as possible. (2020-11-30)
A.Buchanan: Ok thanks Mario. Outstanding question: should this be “JM, corrections AB&MR”. (2020-11-30)
A.Buchanan: Or how about this, saving numerous pieces: 8/3R2K1/4kP1P/3R3P/3P2BP/4N1BP/7P/8 (2020-11-30)
James Malcom: Andre, while economy is to strive for, keeping this intact shows a stepping stone of my journey into composing, in addition to times of our interaction we knew each other not. (2020-11-30)
Mario Richter: 8/3R2K1/4kP1P/3R3P/3P2BP/4N1BP/7P/8 (13+1) is C+ too.
My suggestion: Add another PDB-entry with this new position and two comments, one in the current problem: "For a more economical version see Pnnnnnnn", and one in the new problem: "economization of problem P1382586".
Since I did only some testing, but did not supply anything worthy for the correction, the "&MR" in "... corrections AB&MR” is not justified. (2020-11-30)
James Malcom: I see, Andrew. I propose this: We keep this oooked version as it was in CSE, and change that back. We should add in the new, new correction as an 'Addendum" to your CSE answer, and then post it in here. (2020-12-01)
A.Buchanan: In my humble opinion, this little Type C is not worth having more than two diagrams for in total in the world. I've replaced my stackexchange answer by the new improvement, and documented it. I will add a matching PDB entry for it.
I've similarly replaced your stackexchange question with your sound version. But don't feel constrained please edit it and this PDB entry. I predict that in your chess career James you will have (and indeed have already) many much greater achievements to track than this one. Let's just close this one out and move on :) (2020-12-01)
James Malcom: Andrew, I've fixed both of the problems, and did some clean up on CSE to your answer. The publication dates are now today, and I also changed the source on the lighter version. All PDB needs is the lighter version and my correction to your correction of my initial positon. (2020-12-01)
more ...
comment
Keywords: En passant in the retro play, Help retractor, Superseded by (P1382638), Minimal
Genre: Retro, Fairies
Computer test: rawbats
FEN: 8/3R2Kp/2N1kP1P/3R3P/6BP/4N1BP/P1P4P/8
Input: James Malcom, 2020-11-29
Last update: A.Buchanan, 2024-01-18 more...
21 - P1382638
James Malcom
Andrew Buchanan

chess.stackexchange.com 30/11/2020
P1382638
(13+1) C+
-1w, dann =1
R: 1. e5xf6ep#, dann 1. Sxf5=
play all play one stop play next play all
White has made 15 pawn captures, so if the last move (which must have delivered check) was by an officer, then it was not a capture, so Black has no prior move, and the position is illegal. The only possible last move is en passant, R: 1. e5xf6ep# so we conclude that this definitely was the case.

(For retractors, one does not need to prove that the prior move was definitely a double hop in order to allow the en passant retraction. In this case, the logic goes the other way round: the en passant proves the double hop.)

Now the retraction goes R: 1. ... f7-f5 2. B~-g4+ Kf5-e6/Ke7-f6 3. S~e3+/R~-d7+ etc.

Instead of the first retraction, White can play 1. Se3-f5= for stalemate.

(It could be possible to generate this effect in a position in which White is not delivering check, or in which one can retract uniquely further.)

General chess problem solving engines e.g. Popeye don’t currently offer retraction capabilities. It might be possible to solve Baird-style retractors though, but not ones with retro logic.
version of P1382586
more ...
comment
Keywords: Help retractor, En passant in the retro play, Rex solus (s)
Genre: Retro, Fairies
Computer test: Rawbats
FEN: 8/3R2K1/4kP1P/3R3P/3P2BP/4N1BP/7P/8
Input: A.Buchanan, 2020-12-01
Last update: A.Buchanan, 2024-01-18 more...
22 - P1395008
Cor Goldschmeding
4 International Solving Match 1946
P1395008
(11+5)
#2
1. cxb6ep? droht 2. Dxe7#
but R: 1. Kg6xBf6 g5xf6ep 2. f7-f5 Lf3-e4+,~ equally possible history
play all play one stop play next play all
s. Anmerkung zu P1395005
Autorangabe aus der YACPDB (id=241476) übernommen
Henrik Juel: Last move was clearly b7-b5
1.cxb5ep thr. 2.Dxe7#
HC+ Popeye 4.61 (2021-10-29)
Mario Richter: As stated, I do not know the intended solution, but I think 1. cxb5ep? is only a trap.
R: 1. ... Kg6xPf6 2. g5xf6ep++ f7-f5 3. Lf3-d4+ is a legal retraction sequence, so the ep-key is not justified. (2021-10-30)
Henrik Juel: You are right, Mario (as usual, I might add) (2021-10-30)
comment
Keywords: En passant as key, En passant in the retro play, no solution
Genre: 2#, Retro
FEN: 8/4p1pp/P1N1Pk1N/KpP5/4BP2/Q1P3R1/8/8
Input: Mario Richter, 2021-10-29
Last update: A.Buchanan, 2021-10-30 more...
23 - P1410903
Mu-Tsun Tsai
Dream Yeh

MatPlus.net Forum 14/07/2023
P1410903
(16+2)
What is curious about this position?
R: 1. d5xe6ep# e7-e5 2. d4-d5+
play all play one stop play next play all
Mu-Tsun Tsai: Previous record is P1410861 (2023-07-14)
Mu-Tsun Tsai: Original design was 8/2N5/3PPkPR/rP6/B5PP/8/3PPN2/B2RqQK1, but that leads to a surprising cook: remove both d2 and f2, and retract -1. fxe6ep# e7 -2. Rd4+! (2023-07-14)
comment
Keywords: Economy record, En passant, En passant in the retro play, Last Moves? (3), Minimal
Genre: Retro, Fairies
FEN: 3Q1R2/2N1PP2/5k2/7P/2P4P/6N1/3PPP2/B2BqRK1
Input: James Malcom, 2023-07-14
Last update: James Malcom, 2023-09-09 more...
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https://pdb.dieschwalbe.de/search.jsp?expression=COMMENTDATE%3E%3D20200919+AND+NOT+A%3D%27Stahl%2C+Karl+Alfred%27+AND+K%3D%27En+passant+im+Retrospiel%27

The problems of this query have been registered by the following contributors:

Gerd Wilts (13)
Brian Stephenson (1)
Mario Richter (4)
James Malcom (4)
A.Buchanan (1)