Chess Problem Database Server

122 problem(s) found in 6389 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20200919 AND NOT CPLUS AND S='Phenix'] [download as LaTeX]

1 - P0001764
Henri Nouguier
25 Phénix 1 05/1988

(9+13) cooked
shc#6

1. dxc3ep 2. Kxb5 3. Kxc6 4. Kd7 5. Ke8 6. 0-0 Th8#
Aber es geht auch R: 1. Kb2-a1!?
play all

Henrik Juel: The intention may be 1.dxc3ep 2.Kxb5xc6-d7-e8 6.0-0 Rh8#, but -1.Kb2 seems possible. Should bBc1 be moved to a3? (2003-04-28)
GW: Yes, that's the solution, and the problem seems indeed to be cooked. I don't know if it has been corrected. (2003-04-28)
James Malcom: I believe that the intent was that the sLc1 must be the orginal one, and thus an impediment to wK foreplay, as the wBc6 "must" have captured the e7 Black pawn on its way from f2. The problem is that it can take the alternative path fxsLf3xDe3xTc5-c6, and there are enough White pieces to capture for the Black b pawn to make it d2 and for the d pawn to make it to c2. (2021-09-14)
James Malcom: It turns out this problem actually was corrected a long time later: P1012052 (2021-09-14)
comment

Keywords: En passant, Castling (sk), Seriesmover, Consequent, Non-standard material (sLb1), Valladao Task, Promotion in the retro play (sLb1), Obvious promotion ((sLb1)), Superseded by (P1012052)
Genre: Retro, Fairies
FEN: 7r/5pnR/2P3pR/pPpn3p/1kPp4/3P4/P2pP3/Kbb5
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-09-14 more...

2 - P0001765
Kostas Prentos
26 Phénix 1 05/1988

(11+15) cooked
BP in 18,5

1. Sf3 f5 2. Sd4 Kf7 3. Sb5 Kg6 4. Sd6 exd6 5. e4 Le7 6. e5 Lh4 7. e6 Df6 8. e7 Dxb2 9. e8=S Se7 10. Lc4 Tf8 11. 0-0 Tf6 12. f3 Kh5 13. Te1 Th6 14. Lf7+ Sg6 15. Te7 Dxc1 16. De1 Dxd2 17. De6 dxe6 18. Td7 Dg5 19. Sxg7#
play all

Cook: 1. d4 g5 2. Sf3 Lg7 3. e4 Lxd4 4. e5 Lxb2 5. Dd6 exd6 6. e6 f5 7. e7 Kf7 8. e8=S Se7 9. Sxg5+ Kg6 10. Lc4 Kh5 11. 0-0 Tg8 12. Te1 Tg6 13. f3 Th6 14. Lf7+ Sg6 15. Te7 Lf6 16. Se6 dxe6 17. Td7 Lh4 18. Lg5 Dxg5 19. Sg7#

Kostas Prentos: A correction was published in Phenix, 2009 (No.186/Pg.7979)
Solution:
1. Sf3 f5 2. Sd4 Kf7 3. Sb5 Kg6 4. Sd6 exd6 5. e4 Le7 6. e5 Lh4 7. e6 Dg5 8. e7 Dg3 9. e8=T Se7 10. Lc4 Tf8 11. 0-0 Tf6 12. f3 Kh5 13. Te1 Th6 14. Lf7+ Sg6 15. T1e6 dxe6 16. Txc8 Sd7 17. Th8 Txh8 18. Le8 (2022-12-08)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.2 00:33:56 Minuten. (hh:mm:ss)
Keine Lösung: BP 17.5, BP 18.0.
Beispiel: 1.Sf3 f5 2.d4 Kf7 3.e4 g5 4.Lc4+ Kg6 5.e5 Lg7 6.e6 Lxd4
7.0–0 Lxb2 8.Dd6 exd6 9.e7 Kh5 10.e8S Se7 11.Te1 Tf8 12.Sxg5 Tf6
13.f3 Th6 14.Lf7+ Sg6 15.Te7 Lf6 16.Se6 dxe6 17.Td7 Lh4 18.Lg5 Dxg5
19.Sg7# (2023-05-30)
comment

Keywords: Unique Proof Game, Castling, Promotion
Genre: Retro
FEN: rnb5/pppR1BNp/3pp1nr/5pqk/7b/5P2/P1P3PP/RN4K1
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2006-10-15 more...

3 - P0001777
André Simonet
518 Phénix 8 12/1989

(3+8) cooked
Schwarz und Weiß nehmen jeder 12 aufeinanderfolgende schachbietende Züge zurück, dann setzt Weiß einzügig matt. Duale und Zugumstellungen sind nicht erlaubt.

James Malcom: What is the author's solution and the cook? (2021-07-30)
A.Buchanan: One cook is R: 1. b4xBc3ep+ c2-c4+ 2. Le4xDd3+ Dg3-d3+, dann 1. Dd6#.
Maybe the intention was 2. Sc4xD/Tb6+ etc, but the branching is hard to analyze even with Retractor 2.0. (2021-07-31)
more ...
comment

Keywords: Consecutive checks, Help retractor, Non-standard material (ll)
Genre: Retro
FEN: 8/1r1b4/1nR5/1K1k4/8/1rpb3b/B7/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-07-31 more...

4 - P0002758
Andrej N. Kornilow
1078 Phénix 15-16 12/1991

(25+0)
Färbe die Steine! Welches waren die letzten 9 Einzelzüge?

James Malcom: Solution? (2020-11-07)
Mario Richter: I do not know the official solution, but the following works:
wBb7 wBf7 wBb6 wBg6 wBc5 wTf5 wLf4 wBg4 wBe3 wKg3 wTh3 wDf2 wBh2 wSf1 wSh1
sLg8 sDh8 sBa7 sBc7 sBh7 sBe6 sBf6 sKh6 sBe5 sLg1
wCaps: h5xg6ep f3xTg4 g4xTh5 e6xSf7 d5xSe6 a4xBb5
sCaps: d7xLe6
R: 1. h5xg6ep g7-g5 2. Tg5-f5 d7xLe6 3. f3xTg4 Th4-g4 4. g4xTh5 Kg6-h6 5. Tf5-g5 (2020-11-10)
comment

Keywords: Colouring problem, Last Moves? (9), En passant
Genre: Retro
FEN: 6BQ/PPP2P1P/1P2PPPK/2P1PR2/5BP1/4P1KR/5Q1P/5NBN
Reprints: (34) Die Schwalbe 144 12/1993
Input: Gerd Wilts, 1995-06-03

5 - P0006623
Thierry Le Gleuher
1853v Phénix 50 03/1997
3. ehrende Erwähnung

(16+16) cooked
BP in 40.5

1. a4 h5 2. Ta3 Th6 3. Tc3 Tb6 4. Tc4 Tb3 5. Sc3 Ta3 6. b3 Ta1 7. La3 d5 8. Db1 Lf5 9. Kd1 Lh7 10. Kc1 g6 11. Kb2 Lh6 12. Da2 Tc1 13. Sb1 Le3 14. Kc3 Lb6 15. Kd3 c5 16. Ke3 Sc6 17. Kf4 Dc7+ 18. Kg5 0-0-0 19. h4 Td6 20. Th3 Tf6 21. Te3 Tf3 22. Te6 Sf6 23. Kh6 Th3 24. Kg7 Th1 25. Kf8 Dh2 26. g3 Se5 27. Tc6+ Kd7 28. Tc8 Ke6 29. Lg2 Kf5 30. Le4+ Kg4 31. Sf3 Kh3 32. Lf5+ Kg2 33. Tg4 Lg8 34. Sd4 Sh7+ 35. Ke8 Sf3 36. Kd7 Kf1 37. Te8 Ke1 38. Kc8 Kd1 39. Kb8 Te1 40. Lc8 Sg1 41. f3
play all

Yoav Ben-Zvi: The cook found in P0002554 re-opens the question of the current length record for unique capture-free SPG. A search in PDB finds this problem, assuming it is sound, to be the record holder, until Unto Heinonen publishes a correction (expected very soon). Prior to publication of this problem the record was 38.5, in Michel Caillaud's P0002187. (2019-07-10)
Michel Caillaud: cooked (testing last moves with Jacobi 0.7.5 and constraints) :
16...Sd7 17.h4 Tc8 18.Th3 Tc6 19.Kf4 Te6 20.Tf3 Te3 21.Kg5 Db8 22.Tf6 Th3 23.Tc6 Sgf6 24.Kh6 Th1 25.Kg7 Dh2 26.g3 Se5 27.Lg2 Kd7 28.Tc8 Ke6 29.Kf8... (2021-02-13)
James Malcom: And thus, another giant falls. (2021-02-13)
A.Buchanan: Did Unto find a fix? (2021-02-14)
Michel Caillaud: Unto published a correction of P0002554 in StrateGems (42,5 moves, january 2020), not C+ of course... (2021-02-14)
James Malcom: May you input it into PDB please, Michel? (2021-02-14)
James Malcom: Thanks for the email, Michel. Unto's correction can now be seen in the database: P1386520 (2021-02-15)
more ...
comment

Keywords: Unique Proof Game, Capture-free, Move Length Record
Genre: Retro
FEN: 1KB1R1b1/pp2pp1n/1b4p1/2pp3p/P2N2RP/BP3PP1/Q1PPP2q/1Nrkr1n1
Reprints: H34 FIDE Album 1995-1997 2004
Input: Gerd Wilts, 1996-07-07
Last update: James Malcom, 2021-02-16 more...

6 - P0008499
Valery Liskovets
Valery Voynov
Shakhmaty v SSSR 02/1974
after Arthur Ford Mackenzie
Speziallob

(4+1)
#3
Last 4 single moves?

1. La7 Kxa7 2. c8=T! Kxa6 3. Ta8#
R: 1. Ka7-a8 b7-b8=L+ 2. Ka8-a7 b6-b7+
play all

The theme: under-promotions both in the solution and the retro-play.

See P0003960
Henrik Juel: The forward part is C+ Popeye 4.61 (2022-06-01)
comment

Keywords: Last Moves? (4), Type B, Move Length Record, Rex solus, Miniature
Genre: Retro, 3#
FEN: kB6/2P5/N1K5/8/8/8/8/8
Reprints: B5b Length Records in Last Single Moves? , p. 7, 11/2009
B05b Phénix 282, p. 11063, 02/2018
Input: Gerd Wilts, 1996-12-14
Last update: Rainer Staudte, 2022-06-01 more...

7 - P0008667
Maryan Kerhuel
Didier Innocenti
2524 Phénix 51 04/1997

(9+15) cooked
BP in 15,0
Circe Assassin

paul: Cooked by: 1.h3 d5 2.Rh2 Bxh3(ph2) 3.Sxh3(Bc8) Bxh3 4.g4 a5 5.Bg2 Bxg4(pg2) 6.c4 a4 7.b4 e6 8.Bb2 Bxb4(pb2) 9.Sa3 Ra5 10.Qxa4(pa7) Qc8 11.QxKe8(Ke8) (suicide of wQ)b5 12.Sc2 dxc4(pc2) 13.a3 Bxe2(pe2) 14.Ra2 Bxa3(pa2) 15.Kd1 b4. (2010-06-19)
Arnold Beine: Here is something wrong. Either Paul's cook does not work, because 10.Qxa4(Pa7)+ is a check (10...Qc8??) or in the given condition "Rex inclusive" must be added. (2023-07-26)
paul: Right, Arnold. Anyway, the proof game is cooked: 1.a4 e6 2.Sa3 B×a3 3.b4 a5 4.Bb2 a×b4(b2) 5.Ra2 R×a4(a2) 6.e4 Ra5 etc, as in author's solution: 7.Ba6 b×a6(Bf1) 8.B×a6(a7) d5 9.B×c8(bBc8) Bb7 10.c4 Qc8 11.Qc2 d×c4(c2) 12.Se2 B×e4(e2) 13.h3 Bf5 14.Rh2 B×h3(h2) 15.Kd1 B×g2(g2). (2024-03-13)
comment

Keywords: Circe (Assassin), Unique Proof Game
Genre: Retro, Fairies
FEN: 1nq1k1nr/p1p2ppp/4p3/r7/1pp5/b7/PPPPPPPP/3K4
Input: Gerd Wilts, 1997-05-28
Last update: Mario Richter, 2013-09-01 more...

8 - P0530878
Petko A. Petkov
244 Phénix 12/1988

(2+3)
s#8
Längstzüger

1. Kh4 nCHh2(=nS) 2. nCHf1(=nL) nCHa6(=nT) 3. e7
nCHg6(=nD) 4. e8=S nCHb1(=nS) break 5. nCHa3(=nL)
nCHf8(=nT) 6. Sg7 nCHa8(=nD) 7. nCHa1(=nS)
nCHc2(=nL) break 8. Kh5 nCHh7(=nT)#
play all

{ nDR} = Chamäleon
SCHRECKE: Aus der Lösung geht hervor, dass ein wBe6 fehlt, aber das scheint mir hoffnungslos kaputt zu sein. (2023-07-09)
Anton Baumann: mögliche Korrektur: wKh4 +wBe2 +sBc3 nCH-D nach b6 (2+4+1) s#9 Längstzüger
mit der Lösung: 1.e4 nCHg1(=nS)+ 2.nCHe2(=nL) nCHa6(=nT) 3.e5 nCHg6(=nD) 4.e6 nCHb1(=nS) 5.e7 nCHa3(=nL) 6.e8=S nCHf8(=nT) 7.Sg7 nCHa8(=nD) 8.nCHa1(=nS) nCHc2(=nL) 9.Kh5 nCHh7(=nT)#
5. ... nCHd2(=nL)? geht nicht wegen Selbstschach
C+ Alybadix (2023-07-12)
comment

Keywords: Maximummer
Genre: Fairies
FEN: 8/5p2/8/8/5k2/1p5K/*1Q7/8
Input: Ralf Krätschmer, 1998-03-30
Last update: hpr, 1999-11-07 more...

9 - P1000026
Alexandr I. Zolotarev
3348 Phénix 84 04/2000

(14+8)
Minimale Anzahl aller Springer-Züge?

(Beispielauflösung mri)
R: 1. c2xDd3 De3-d3 2. e4xTd5 Dg1-e3 3. d4xLc5 g2-g1=D 4. e3-e4 g3-g2 5. a4-a5 h4xLg3 6. Ld6-g3 f2-f1=S 7. Le7-d6 Lb6-c5 8. La3-e7 Tg5-d5 9. Lc1-a3 Tg1-g5 10. Lb2-c1 g2-g1=T 11. Lc1-b2 g3-g2 12. g2xDf3 Df8-f3 13. Lb2-c1 Db4-f8 14. La3-b2 Db1-b4 15. Lc5-a3 b2-b1=D 16. Lb4-c5 b3-b2 17. La3-b4 b4-b3 18. Lc1-a3 a5xDb4 19. Df8-b4 f3-f2 20. Dh6-f8 f4-f3 21. Dh7-h6 g4-g3 22. Dh5-h7 f5-f4 23. Dh6-h5 Lc5-b6 24. Dh7-h6 Ld6-c5 25. Dh6-h7 Lg3-d6 26. Dh5-h6 Le1-g3 27. Dh6-h5 Ld3-e2 28. f2xDe3 De7-e3 29. De3-h6 Db4-e7 30. De2-e3 Db1-b4 31. Df1-e2 b2-b1=D 32. Dg1-f1 b3-b2 33. b2xDc3 Db4-c3 34. Df1-g1 De7-b4 35. Dg1-f1 Kb4-c4 36. Te5-b5 e2-e1=L 37. Te4-e5 e3-e2 38. Tf4-e4 e4-e3 39. Lc4-a6 e5-e4 40. Ta6-a7 La7-b8 41. Te4-f4 Tb8-b7 42. Sc3-d1 Th8-b8 43. Dd1-g1 Dd8-e7 44. Te1-e4 h5-h4 45. Th1-e1 h7-h5 46. Lg8-c4 g5-g4 47. Kd5-c6 Lc5-a7 48. Tc6-a6 Lf8-c5 49. Sb1-c3 La6-d3 50. Sg1-h3 e7-e5 51. Ke5-d5 Sb8-d7 52. Lc4xSg8 Lc8-a6 53. Lf1-c4 g7-g5 54. Tc3-c6 f7-f5 55. Th3-c3 Kc5-b4 56. e3xBd4 b4-b3 57. Ke4-e5 Kd6-c5 58. Kd3-e4 Kd7-d6 59. Ke2-d3 d5-d4 60. Ke1-e2 Ke8-d7 61. e2-e3 d7-d5 62. Ta3-h3 b5-b4 63. Ta2-a3 b7-b5 64. Ta1-a2 a7-a5 65. a2-a4
play all

Die minimale Anzahl SS-Züge ist 4. (wSb1-c3-d1,wSg1-h3 und sSb8-d7. sSg8 zog garnicht)
Frolkin-Ceriani-UW in 3DD, 1T, 1L (sUWs: h7xg-g1=D, g7-g1=T, a7xb-b1=D, b7-b1=D, e7-e1=L, außerdem die All-Entwandlung vervollständigend f7-f1=S) [mri: allerdings erkauft durch eine ziemlich starke Randbedingung!]

Hans-Jürgen Manthey: R: 1. c2xDd3 De3-d3 2. e4xTd5 Dg1-e3 3. d4xLc5 g2-g1=D 4. e3-e4 g3-g2 5. a4-a5 h4xLg3 6. Le5-g3 f2-f1=S 7. Ld6-e5 Tg5-d5 8. Le5-d6 Tg1-g5 9. Lf6-e5 g2-g1=T 10. Lg7-f6 g3-g2 11. g2xDf3 Df8-f3+ 12. Lh8-g7 g4-g3 13. Lg7-h8 Ld6-c5 14. Lf6-g7 Lg3-d6 15. Le5-f6 f3-f2 16. Lf6-e5 Le1-g3 17. f2xDe3 De7-e3 18. Lg7-f6 Db4-e7 19. Lh8-g7 Db1-b4 20. Lg7-h8 b2-b1=D 21. Lf6-g7 b3-b2 22. Le5-f6 Da3-f8 23. Lf6-e5 Da1-a3 24. Lg7-f6 Db1-a1 25. Lh8-g7 b2-b1=D 26. Lg7-h8 b4-b3 27. Lf8-g7 28. a5xDb4 De7-b4+ 29. b3-b2 De8-e7 30. h5-h4 La3-f8 31. h6-h5 Lc1-a3 32. h7-h6 b2xDc3 33. De3-c3 Dd8-e8 34. g5-g4 De8-d8 35. g7-g5 Dd8-e8 36. f4-f3 De8-d8 37. f5-f4 Dd8-e8 38. f7-f5 De8-d8 39. SF6-D7 Dd8-e8 40. Ld3-e2 De8-d8 41. e2-e2=L De4-e8 42. Dg5-e3 Dg6-e4 43. Kb4-c4 Tf5-b5+ 44. e3-e2 Tf4-f5 45. Lf5-d3 Lc4-a6 46. e4-e3 Ta6-a7 47. e5-e4 Te4-f4 48. La7-b8 Te1-e4 49. Tb8-b7 Th1-e1 50. Th8-b8 Lf1-c4 51. Lc8-f5 Kd5-c6 52. SG8-F6+ Ke4xd5 53. d7-d5+ e3xSd4 54. SC6-D4 Dh5-g6 55. Kc5-b4 Kf3-e4 56. b4-b3 Sg1-h3 57. Kd6-c5 Sc3-d1 58. Ke7-d6 Sb1-c3 59. Ke8-e7 Ke2-f3 60. Dd8-g5 Ke1-e2 61. SB8-C6 Dd1-h5 62. b5-b4 e2-e3 63. b7-b5 Td6-a6 64. Lc5-a7 Td3-d6 65. Lf8-c5 Ta3-d3 66. e7-e5 Ta1-a3 67. a7-a5 a2-a4 (2021-07-10)
Henrik Juel: These solution corrections should help the animation:
3... g2-g1=D, 6... f2-f1=S, 24... Db1-b2
Hans-Jürgen's numbering is a single move off from retraction 28.
(1.c2xDd3 is white, 28.a5xDb4 is black)
The stipulation seems to ask for the minimal number of black knight moves
(usually SS means knights, but here it may mean 'schwarze Springer') (2021-07-10)
Mario Richter: Henrik, if the question were about black Knight moves only, wSh3 would be able to make tempo moves, allowing e.g. to start with c2xTd3 instead of c2xDd3.
I do not have the official solution, but it obviously is: 4 Knight moves - wSb1-c3-d1,wSg1-h3 and bSb8-d7. bSg8 didn't move at all and was captured by a White officer. (2021-07-11)
Henrik Juel: Thanks for your new solution, Mario, and for your enlightenments
I was misled by the originally stated solution and by Hans-Jürgen's retro game
The german convention that D means Dame=queen and DD means Damen=queens etc. may not be generally understood, so for clarification I suggest that the stipulation is spelled out, something like
Welches war die minimale Anzahl von Springerzüge?
I totally agree with your comment on the strong condition implied by the stipulation (2021-07-11)
comment

Keywords: Ceriani-Frolkin Theme (dddtl), Minimal number of moves of a piece
Genre: Retro
FEN: rb6/Rrpn4/B1K5/PRPP4/2k5/2PP1P1N/3Pb2P/3N1n2
Input: Gerd Wilts, 2000-07-31
Last update: Mario Richter, 2021-07-11 more...

10 - P1011875
Andrej N. Kornilow
Andrey Frolkin
12111 Die Schwalbe 204 12/2003
3. Preis

(13+12)
Ergänze einen weißen Stein auf der h-Linie!
a) Letzter Zug?
b) Letzter Zug des wK?

a) +wSh8 R: 1. Sg6xTh8 Th7-h8 2. Sc3-d1 Th8-h7 3. Sb5-c3 Th7-h8 4. Sd4-b5 Th8-h7 5. Sc6-d4 Th7-h8 6. Sb8-c6 Th8-h7 7. b7-b8=S Th7-h8 8. b6-b7 Th8-h7 9. b5-b6 Th7-h8 10. b4-b5 Th8-h7 11. Sh2-f1 Th7-h8 12. Sf3-h2 Th8-h7 13. Sd4-f3 Th7-h8 14. Sc6-d4 Th8-h7 15. Sb8-c6 Th7-h8 16. b7-b8=S Th8-h7 17. b6-b7 Th7-h8 18. b5-b6 Th8-h7 19. a4xBb5 Th7-h8 20. Dh8-g8 b6-b5 21. Kg8xSf8 Te8-e7 22. a3-a4 Le7-d8 23. a2-a3 Lc5-e7 24. b3-b4 e7-e6 25.
play all

Das Schach, in dem der sK steht, kann nur durch einen wSh8 oder einen wLh7 aufgehoben werden. Damit Schwarz vor dem Schach gezogen haben kann, muß die weiße Figur eine schwarze Figur entschlagen. Die beiden anderen fehlenden weißen Steine wurden von den sBBg und h geschlagen, d.h. die beiden wBa2b2 müssen sich beide auf b8 umgewandelt haben. Im letzten weißen Zug wurde auf der h-Linie ein sT entschlagen, da ein sL oder sS vorher nicht gezogen haben konnten und eine sD die Umwandlung des sBb7 auf b1 in eine D erfordert hätte, was unmöglich ist, da dann der wB mit zwei Schlägen um den sBb herumgeschlagen haben müßte, was aber insgesamt 5 weiße Schläge erfordert hätte. Als letzter Zug von Weiß ist also Sg6xTh8 oder Lg6xTh7 denkbar.
Um die Stellung aufzulösen, muß die wD nach h8 und der wK nach g8 ausweichen und ein Stein auf f8 gestellt werden, damit der sTe8 nach e7 kann. Da dazu einige weiße und schwarze Tempozüge benötigt werden kann dies nur wie folgt erreicht werden:

more ...
comment

Keywords: Uncapture of pieces by pieces, Add pieces, Last move of a specific piece?, Last Move?
Genre: Retro
FEN: 3b1KQ1/p1pprp2/4pR1k/5pRq/6PB/4P1pb/2PP1PP1/3N1N2
Reprints: feenschach 155 2004
A3855 Phénix 147 01/2006
(8) Die Schwalbe 240 12/2009
Input: Gerd Wilts, 2003-12-30
Last update: A.Buchanan, 2024-01-15 more...

11 - P1013125
Didier Innocenti
4139v Phénix 113 12/2002

(12+15) cooked
BP in 19,0

1. b4 d5 2. La3 Kd7 3. Dc1 Kc6 4. Db2 Kb5 5. Dxg7 Ka4 6. Sc3+ Kxa3 7. Tc1 Kb2 8. Sb1+ Kxc1 9. Da1 Lh6 10. f4 Lxf4 11. Kf2 Le3+ 12. Kg3 Kd1 13. Kh4 Ke1 14. Kh5 Kxf1 15. Sf3+ Kf2 16. Td1 d4 17. Se1 Kg1 18. Sc3 Kh1 19. Sd3+ Lg1
play all

Cook: Zugumstellung
10. f4 d4 11. Kf2 Kd1 12. Kg3 Ke1 13. Kh4 Kxf1 14. Sf3+ Kf2 15. Td1 Lxf4 16. Se1 Kg1 17. Kh5 Kh1 18. Sc3 Le3 19. Sd3+ Lg1 (SH)

SH: cooked? 1. b4 d5 2. Ba3 Kd7 3. Qc1 Kc6 4. Qb2 Kb5 5. Qxg7 Ka4 6. Nc3+ Kxa3 7. Rc1 Kb2 8. Nb1+ Kxc1 9. Qa1 Bh6 10. f4 d4 11. Kf2 Kd1 12. Kg3 Ke1 13. Kh4 Kxf1 14. Nf3+ Kf2 15. Rd1 Bxf4 16. Ne1 Kg1 17. Kh5 Kh1 18. Nc3 Be3 19. Nd3+ Bg1 (2006-06-06)
Henrik Juel: Yes, the move order is not unique after 10.f4, so the problem is indeed cooked (2018-12-17)
more ...
comment

Keywords: Unique Proof Game, Promenade (k)
Genre: Retro
Computer test: Computerprüfung: C- oder cooked Stelvio 1.4 48 Sekunden. Keine Lösung: BP 18.5.
FEN: rnbq2nr/ppp1pp1p/8/7K/1P1p4/2NN4/P1PPP1PP/Q2R2bk
Input: Gerd Wilts, 2004-03-13
Last update: Silvio Baier, 2023-08-15 more...

12 - P1013869
Hans Gruber
Dieter Linden
77 Phénix 05/1988
7.-8. Lob ex ,{ae}quo

(2+6)
H=4

1. Lh7 Lxh7 2. Lg6 Kxb3 3. Lb1 Lxb1 4. Sc2 Kxc2=
play all

Anton Baumann: C+ Gustav 4.1d (2020-12-03)
comment

Genre: Fairies
FEN: 8/8/8/7b/8/Kp6/1pb5/kB2n3
Input: Hans Gruber, 2004-05-01

13 - P1013903
Theodor Steudel
Hans Gruber
AVIII Phénix 08/1989

(2+2)
ser-R#7
b) wB c3 nach g2
Circe

a) 1. Ka6 2. c4 6. c8=L 7. Lb7 Da5#
b) 1. Ka4 2. g4 6. g8=L 7. Lb3 Da5#
play all

Anton Baumann: C+ Alybadix (2020-11-11)
comment

Keywords: Circe, Seriesmover
Genre: Fairies
FEN: 8/8/8/K7/7k/2P5/3q4/8
Input: Hans Gruber, 2004-05-01
Last update: Gerd Wilts, 2004-05-01 more...

14 - P1013957
Bernhard Geismann
Hans Gruber
Stefan Höning
1423 Phénix 12/1992

(6+3)
S#3 Marscirce

1. Sxd2+ Txg8+ 2. La8+ Tg1+ 3. Tf8+ Txf8#
play all

bg: Marscirce !! (2005-08-22)
SCHRECKE: C+, popeye 4.87 (2023-09-25)
comment

Keywords: Circe (Mars)
Genre: s#, Fairies
FEN: 4KrQ1/5R2/8/5P2/8/8/3p4/3Nk2B
Input: Hans Gruber, 2004-05-01
Last update: Mario Richter, 2010-08-13 more...

15 - P1017659
Pascal Slechten
Michel Caillaud
R160 Problemesis 08/2004

(16+0)
ser-BP in 31

1. Sf3 2. Sd4 3. f3 4. Kf2 5. Kg3 6. Kh4 7. g3 8. Lh3 9. Le6 10. Sf5 11. d4 12. Ld2 13. La5 14. Sc3 15. Db1 16. Td1 17. Td3 18. Sd1 19. Tb3 20. Tb6 21. b4 22. b5 23. Db4 24. Tb1 25. Tb3 26. Tc3 27. Tcc6 28. c4 29. c5 30. Lc4 31. d5
play all

Längste eindeutige Serienzug-BP ohne Schläge

Cf: P1347359
paul: Checked with stip ser-dia 31 forsyt rsbqkbsr/pppppppp/1RR5/BPPP1S2/1QB4K/5PP1/P3P2P/3S4 by Jacobi. (2021-09-27)
comment

Keywords: Unique Proof Game, Seriesmover, Capture-free, Move Length Record (ex-aequo)
Genre: Retro, Fairies
FEN: 8/8/1RR5/BPPP1N2/1QB4K/5PP1/P3P2P/3N4
Reprints: H54 Vkontakte 2013
H54 Phénix 261/262, p. 10359, 05-06/2016
Phénix 279-280, p. 11000, 11-12/2017
Input: Gerd Wilts, 2004-08-01
Last update: A.Buchanan, 2021-04-09 more...

16 - P1038532
Dieter Werner
2179 Phénix 36 12/1995
ehrende Erwähnung

(8+11)
#5

BS Problemid: 23483
Authors: Werner, Dieter
Sources:
Years: 1995-1996

Henrik Juel: damaged by double threat 1.g4 thr. 2.Lg5,Lf6
and the dual 1... d4 2.Le7 thr. 3.Sc4+ Kb5 4. Sa3+,Lb4 (2021-03-29)
comment

Keywords: Brian Stephenson Collection (23483)
Genre: n#
FEN: 3B4/pB1p3p/1p1N2p1/k2p3p/4p2r/1K1N2Pb/2P2P2/8
Input: Brian Stephenson, 2004-08-12
Last update: Roland Ott, 2021-03-29 more...

17 - P1051320
Ralf Krätschmer
Phénix 03/1990
2. ehrende Erwähnung

(9+13)
#5

1. Tg4? hxg4#
1. Lg4? hxg4#
1. Lf8 dxc5 2. Tg4 hxg4+ 3. Kg7 g3 4. Lg4 Txg4 5. Sd7#
play all

SCHRECKE: C+, Gustav 4.1d, Brute Force
außerdem: 4. ... L:g4 5.Sc4# (2021-01-23)
comment

Keywords: Brian Stephenson Collection (36359), Berlin Theme, Nowotny
Genre: n#
FEN: 8/6Bp/1N1p1p1K/2PPk1pp/1p5r/1p1QP2b/2p3R1/3B2rn
Input: Brian Stephenson, 2004-08-12
Last update: Ralf Kr?tschmer, 2012-04-02 more...

18 - P1052844
Ralf Krätschmer
Phénix 1990
3. ehrende Erwähnung

(8+7)
#4

BS Problemid: 37886
Authors: Kratschmer, Ralf
Sources:
Years: 1990

SCHRECKE: C+, Gustav 4.1d, Brute Force
1.Sf4+? K:c5+!
1.Tf2! e4! 2.Tf5+ De5 3.Sf4+! K:c5 4.Sge6# (2021-01-20)
comment

Keywords: Brian Stephenson Collection (37886)
Genre: n#
FEN: b6q/r3p3/1R2N3/P1BkpRN1/7p/1P6/8/7K
Input: Brian Stephenson, 2004-08-12
Last update: Ralf Kr?tschmer, 2012-04-02 more...

19 - P1066780
Michel Caillaud
3755 Phénix 98 01/2001
1. Preis

(16+12) cooked
BP in 21,5

1. b4 g5 2. b5 g4 3. b6 g3 4. bxc7 b5 5. c4 Lb7 6. Sc3 Lf3 7. gxf3 b4 8. Lh3 b3 9. Lf5 b2 10. Lc2 b1=S 11. d3 Sd2 12. Sh3 Sf1 13. Dd2 g2 14. Dh6 g1=D 15. Ld2 Dg5 16. Tc1 Se3 17. Lb1 Sg4 18. 0-0 Df4 19. Tfd1 Se3 20. Le1 Sf1 21. Kxf1 Dd2 22. Txd2
play all

Zuerst schirmt der schwarze UWS auf f1 die schwarze UWD auf g1 ab, anschließend schirmt der Springer die Dame auf g4 ab, und schließlich werden beide geschlagen.
Cook: 1. b4 Sf6 2. c4 b6 3. Sc3 c5 4. bxc5 Lb7 5. cxb6 Lf3 6. gxf3 Sd5 7. Lh3 Se3 8. Lf5 Sf1 9. Lc2 g5 10. Sh3 g4 11. d3 g3 12. Dd2 g2 13. Dh6 g1=D 14. Ld2 Dg3 15. Tc1 Se3 16. Lb1 Dgc7 17. bxc7 Sd1 18. 0-0 Se3 19. Tfd1 Sd5 20. Kf1 Sf6 21. Le1 Sg8 22. Td2

Henrik Juel: Natch 3.1 did not even find the solution in an hour (2018-12-15)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.2 296:36:23 Stunden. (hh:mm:ss)
Keine Lösung BP 20.5, BP 21.0. Histogramm 355767/10739k
Cooked bei 59917/922k. Die letzten 295850 Strategien wären sicher
schneller geprüft worden da die meisten großen Werte bereits waren.
Notations Beispiel: 1.b4 Sf6 2.c4 b6 3.Sc3 c5 4.bxc5 Lb7 5.cxb6 Lf3
6.gxf3 Sd5 7.Lh3 Se3 8.Lf5 Sf1 9.Lc2 g5 10.Sh3 g4 11.d3 g3 12.Dd2 g2
13.Dh6 g1D 14.Ld2 Dg3 15.Tc1 Se3 16.Lb1 Dgc7 17.bxc7 Sd1 18.0–0 Se3
19.Tfd1 Sd5 20.Kf1 Sf6 21.Le1 Sg8 22.Td2
oder wie vor bis 19. dann 20.Le1 Sf6 21.Kf1 Sg8 22.Td2 (2023-05-24)
comment

Keywords: Ceriani-Frolkin Theme (ds), Unique Proof Game, Castling, Promotion (sd), Homebase
Genre: Retro
FEN: rn1qkbnr/p1Pppp1p/7Q/8/2P5/2NP1P1N/P2RPP1P/1BR1BK2
Reprints: feenschach 161 09-11/2005
Input: Gerd Wilts, 2004-10-03
Last update: Silvio Baier, 2023-08-15 more...

20 - P1067438
Michel Caillaud
WCCC Halkidiki 2004
2. Preis Sake TT

(20+12)
BP in 15,0
Crazyhouse

1. b4 a5 2. bxa5 Txa5 3. [+wBa7] Te5 4. a8=L d5 5. Lxb7 Kd7 6. [+wBa7] Ke6 7. a8=S Kf5 8. Sxc7 Le6 9. [+wBd7] Dc8 10. d8=T g6 11. Txd5 Lg7 12. [+wBd7] Lf6 13. d8=D Sd7 14. Dxe7 Sf8 15. [+wBb2] [+sBd7]
play all

James Malcom: I wonder if the newly placed wBb2 and sBd7 could be considered as imposters. (2021-06-27)
A.Buchanan: I think they are. This is not so hard a problem to solve. (2021-06-28)
more ...
comment

Keywords: Allumwandlung, Crazyhouse, Unique Proof Game, Promotion (x4 LSTD), Non-standard material (DTLS), Impostor (Bb)
Genre: Retro, Fairies
FEN: 2q2nnr/1BNpQp1p/4bbp1/3Rrk2/8/8/PPPPPPPP/RNBQKBNR
Reprints: feenschach 154 2004
H46 Phénix 02-03/2005
Input: Gerd Wilts, 2005-01-09
Last update: A.Buchanan, 2021-06-28 more...

21 - P1068095
Didier Innocenti
3542v Phénix 2000

(8+6) cooked
BP in 10,0
Berkeley-Schach

1. d4[-wTa1,-wTh1,-sTa8,-sTh8,-wBa2,-wSb1,-wSg1,-wBh2,-sBa7,-sSb8,-sSg8,-sBh7] g5 2. e4[-wBe4] g4 3. Le2[-wBg2] g3 4. Lf3 g2 5. Ke2 g1=T 6. d5 Lg7 7. d6 Kf8[-sDd8,-sLc8,-sBd7] 8. d7[-sBc7] Th1 9. d8=S Th8 10. Se6+ Ke8
play all

Cook: 1. Sf3 [-wTa1h1, -wSb1, -wBa2a7 -sBh7, -sTa8h8, -sSb8g8] g5 2. e4 [-wLe4] d5 3. d4 g4 4. Lc4 [-wBg2] g3 5. Lxd5 gxh2 6. Ke2 h1=T 7. Sg5 c5 8. dxc5 [-Bc5] Da5 [-Da5, -Lc8] 9. Se6 Lg7 10. Lf3 Th8

more ...
comment

Keywords: Berkeley Chess, Unique Proof Game
Genre: Retro, Fairies
FEN: 4k2r/1p2ppb1/4N3/8/8/5B2/1PP1KP2/2BQ4
Input: Gerd Wilts, 2005-10-19
Last update: A.Buchanan, 2024-03-15 more...

22 - P1068185
Thomas Volet
9677 Thema Danicum 118 04/2005

(14+13)
Löse die Stellung auf!

R: 1. e3xSd4 Sf5-d4 2. e2-e3 Sd6-f5 e6 3. Le4-b7 Sb7-d6+ 4. Lc6-e4 Dc5-b4 5. Le4-c6 Dd4-c5+ 6. Lf5-e4 Dd5-d4 7. Le6-f5 b4-b3 8. Lg8-e6 Dd4-d5 9. f7xLg8=L De3-d4 10. f6-f7 Ld5-g8 11. f5-f6 Lc6-d5 12. f4-f5 Dc5-e3 13. f3-f4 Kd5-c4 14. f2-f3 Sc4-a3
Die sBB schlugen die zwei fehlenden weißen Steine. wBb2 und wBd2 schlugen je einmal, der wBf2 schlug einmal zur Umwandlung auf e8 oder g8. Der Käfig kann nur aufgelöst werden, indem der sK nach d5 zieht. Dazu muß vorher das Schach durch wTb5 und wLb7 abgedeckt werden.
play all

Thomas Volet: TV: solution given is slightly incorrect. Black's first retraction cannot be Se6-d4. It should be Sf5-d4, and the next two Black retromoves would then be Sd6-f5 and Sb7-d6. GW is so reliable I never check the solutions -- just happened to look at this one in connection with some correspondence. (2010-02-07)
Gerd Wilts: Thank you, Tom, I have now corrected the solution. (2010-02-07)
Mario Richter: Instead of ... 8.Lg8-e6 Dd4-d5 9. f7xLg8=L De3-d4 a.s.o. the unpromotion can also be done on e8: 8.Lf7-e6 Dd4-d5 9.Le8-f7+ De3-d4 10.f7xLe8=L a.s.o. Does that make the problem dualistic? (2010-02-08)
Thomas Volet: White also might have begun the game with either 1.Sg1-f3 or 1.Sg1-h3. The point was to show reciprocal retroscreens (here by the WBb7 and BQb4, each of which screens for and is screened by the other) involving both Kings. Beyond that .... (2010-02-12)
Henrik Juel: This problem was awarded 1st HM by judge Klaus Wenda in the informal fairy tourney (including retros) for 2005
Klaus wrote:
Nach meinem Geschmack die anspruchsvollste der klassischen Retroaufgaben. Die 14-zügige Auflösung der Stellung mit wechselseitigem Schachschutz durch retroentfesselte Figuren, garniert mit der Entwandlung eines wL auf g8, wobei der entwandelte Bauer af sein Grundfeld f2 zurück zieht (Retro-Exzelsior), präsentiert sich als spannender und geistreicher Ablauf.
I expect that Mario's observation (that the unpromotion could also happen on e8) would not have changed the award; if the wording had been 'auf e8 oder g8', we would know for sure (2021-06-18)
comment

Genre: Retro
FEN: Nr1B1b2/rBKpp1p1/Qp4p1/RR5p/PqkP4/npP5/2PP3P/1N6
Reprints: H7 Vkontakte 2013
H7 Phénix 261/262, p. 10348, 05-06/2016
Input: Gerd Wilts, 2005-12-21
Last update: A.Buchanan, 2017-09-07 more...

23 - P1068215
Zdravko Maslar
4936 feenschach 12/1986
2. Preis WJP

(1+2)
-1s, dann h=1
b) Kc1 nach b2
c) Kc1 nach a3
d) Kc1 nach a4

a) R: 1. Kb2xDc1, dann 1. Kb3 Da1=
b) R: 1. Ka1xTb2, dann 1. b3 Kc3=
c) R: 1. a5xSb4, dann 1. a4 Kc3=
d) R: 1. c5xLb4, dann 1. c4+ Kxc4=
play all

Henrik Juel: a real gem (2023-05-20)
Adrian Storisteanu: Not an Allentschlag, there is no pawn uncapture. (2023-05-21)
comment

Keywords: Help retractor, RIFACE Retro Solving Tourney (2022), Kindergarten Problem, Minimal, Miniature, Kindergarten Problem, Miniature, Kindergarten Problem, Kindergarten Problem
Genre: Retro, Fairies
FEN: 8/8/8/8/1p6/3K4/8/2k5
Reprints: feenschach 158 01-03/2005
3 Phénix 331, p. 12922, 06/2022
Input: Gerd Wilts, 2006-01-21
Last update: A.Buchanan, 2024-01-18 more...

24 - P1068539
Eric Pichouron
5008 Phénix 146 12/2005

(13+12) cooked
BP in 23,0

1. a3 e5 2. Ta2 Lb4 3. axb4 h5 4. Ta3 h4 5. Tg3 hxg3 6. hxg3 f5 7. Th3 f4 8. gxf4 a5 9. Ta3 Th1 10. Sf3 Txf1+ 11. Kxf1 Ta6 12. Kg1 Tg6 13. Kh2 d6 14. Dh1 Lg4 15. Kg3 Sf6 16. Dh7 Th6 17. Ta1 Th1 18. Sa3 Txc1 19. Kh4 Th1+ 20. Kg5 Th3 21. Th1 Tg3 22. Dh3 e4 23. Sh4 Lc8+
play all

Cook: 1. Sa3 a5 2. Sb5 e5 3. a3 Lb4 4. axb4 h5 5. Ta3 h4 6. Tg3 hxg3 7. hxg3 Ta6 8. Th7 Th6 9. Sf3 Th1 10. Th2 Txf1+ 11. Kxf1 Th3 12. Kg1 e4 13. Th1 f5 14. Sh4 f4 15. gxf4 Ta3 16. Kh2 Ta1 17. Kg3 Txc1 18. Kg4 Ta1 19. Dg1 Ta3 20. Dh2 Tb3 21. Sa3 Sf6+ 22. Kg5 d6 23. Dh3 Tg3+

Henrik Juel: Natch 3.1 did not find the solution in half an hour
Stopped at pos. 4961 (2018-12-22)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.11 14:12:45 Stunden. (hh:mm:ss)
Keine Lösung: BP22.0, BP 22.5.
Beispiel: 1.Sa3 a5 2.Sb5 e5 3.a3 Lb4 4.axb4 h5 5.Ta3 h4 6.Tg3 hxg3 7.hxg3 Ta6
8.Th7 Th6 9.Sf3 Th1 10.Th2 Txf1+ 11.Kxf1 Th3 12.Kg1 e4 13.Th1 f5
14.Sh4 f4 15.gxf4 Ta3 16.Kh2 Ta1 17.Kg3 Txc1 18.Kg4 Ta1 19.Dg1 Ta3
20.Dh2 Tb3 21.Sa3 Sf6+ 22.Kg5 d6 23.Dh3 Tg3+ (2023-03-28)
more ...
comment

Keywords: Unique Proof Game, Pure Round Trip (T)
Genre: Retro
FEN: 1nbqk3/1pp3p1/3p1n2/p5K1/1P2pP1N/N5rQ/1PPPPPP1/7R
Input: Gerd Wilts, 2006-08-14
Last update: Silvio Baier, 2023-04-05 more...

25 - P1080434
Thierry Le Gleuher
R301 Probleemblad 01-02/2006

(10+10) cooked
h#2
Duplex

hans: a) 1. Ke5 Td1 (0-0-0?) 2. f5 Lxg7# b) 1. 0-0-0! Dd8 2. Dxd1#
Some comment: The composer shows how important a tempo can be. Masterly accomplished! (HM). A very intensive study is needed to find the solutions: in fact not the solutions but the motivation. Has cost me days to solve this fine, extremely difficult and profound problem. In (a) 0-0-0 is not allowed., in (b) it is. In my opinion a 1st Prize Retros 2006 (GHB)

R: -1. … Dd8-b8 -2. a5-a6 Kf6-f5 -3. a4-a5 Ke7-f6 -4. a3-a4 Ke8-e7 -5. a2-a3 Lh2-g1 -6. h7-h8=L Ld6-h2 -7. h6-h7 Lf8-d6 -8. h5-h6 e7-e6 -9. h4-h5 Le6-c4 -10. h3-h4 Lc8-e6 -11. h2-h3 d7xDc6 -12. Dc5-c6 f5xSe4 -13. c6xb7 g6xTf5 -14. d5xTc6 etc.
bCap: axbxc2-c1, dxc6, hxg6xf5xe4, wCap: dxe3, gxf3xe4xd5xc6xb7, (2013-08-30)
hans: *2. Kc1-b1 (2013-08-30)
Mario Richter: I've found a cook for a), based on the idea to unpromote the black queen on c1 (shielded by the black bishop c4 on d1). The following PG shows, that the position can be reached with White still able to castle queenside:
1.Ng1-f3 a7-a6 2.Nb1-a3 a6-a5 3.Na3-c4 Ra8-a6 4.Rh1-g1 Ra6-f6 5.Nf3-h4 Rf6-f3 6.Nh4-g6 h7xg6 7.g2xf3 Ng8-f6 8.Bf1-h3 Nf6-e4 9.f3xe4 Nb8-c6 10.Bh3-f5 Nc6-b4 11.Rg1-g4 Nb4-d5 12.e4xd5 Rh8-h3 13.Rg4-e4 Rh3-c3 14.Nc4-e5 Rc3-c6 15.d5xc6 g6xf5 16.c6xb7 f5xe4 17.Ne5-c6 d7xc6 18.h2-h3 Qd8-d4 19.h3-h4 Qd4-e3 20.d2xe3 Bc8-e6 21.Bc1-d2 Be6-b3 22.Bd2-b4 a5xb4 23.Qd1-c1 e7-e6 24.Qc1-d1 Ke8-e7 25.Qd1-c1 Ke7-f6 26.Qc1-d1 Kf6-f5 27.Qd1-c1 Bf8-d6 28.Qc1-d1 Bd6-h2 29.c2-c3 Bh2-g1 30.Qd1-c1 Bb3-d1 31.Qc1-d2 b4-b3 32.Qd2-c2 b3xc2 33.h4-h5 c2-c1Q 34.h5-h6 Qc1-c2 35.h6-h7 Qc2-a4 36.h7-h8B Qa4-a8 37.a2-a3 Qa8-b8 38.a3-a4 Bd1-b3 39.a4-a5 Bb3-c4 40.a5-a6 (and now) Kf5-e5 43.0-0-0! (still possible!) f7-f5 44.Bh8xg7# (2013-08-31)
Henrik Juel: Nicely found, Mario.
So it was fortunate that the problem was not awarded in the tourney, despite the enthusiastic solver comments (2013-08-31)
Henrik Juel: According to judge Bernd Gräfrath, he did not see the cook and awarded the problem 1st-2nd prize (2013-09-01)
A.Buchanan: Was Thierry made aware of the cook? Did this ever get fixed? (2021-06-29)
comment

Keywords: Cant Castler (wl)
Genre: Retro, h#
FEN: 1q5B/1Pp2pp1/P1p1p3/5k2/2b1p3/2P1P3/1P2PP2/R3K1b1
Reprints: H5 Vkontakte 2013
H5 Phénix 261/262, p. 10347, 05-06/2016
Input: Gerd Wilts, 2009-01-06
Last update: Rainer Staudte, 2019-08-11 more...

26 - P1080443
Vlaicu Crisan
Klaus Wenda
R310 Probleemblad 05-06/2006

(4+4)
s#1 vor 16
Verteidigungsrückzüger, Typ Proca
Anticirce, Typ Cheylan

paul: -1.Bg7-h8 Bg1-h2+ -2.Kf2×Pg2(Ke1) Bh2-g1+ -3.Ke1-f2 Bg1-h2+ -4.Ke2×Pd2(Ke1) f4-f3+ -5.Kf2-e2 Bh2-g1+ -6.Kg3-f2 Bg1-h2+ -7.Bh8-g7 f5-f4+ -8.Kf2-g3 Bh2-g1+ -9.Ke1-f2 d3-d2+ -10.h7-h8=B Bg1-h2+ -11.Kh4×Bh5(Ke1) Bh2-g1+ (h2-h1=R? illegal) -12.Kg3-h4 Bg1-h2+ -13.Kf2-g3 Bh2-g1+ -14.Ke1-f2 Bg1-h2+ -15.Kg8×Qh8(Ke1) Qf6-h8+ -16.Bf4-e5 & 1.h8=S+ Q×h8(Qd8)# (2023-06-12)
comment

Keywords: Circe (Anti-), Defensive Retractor, Type Proca
Genre: Retro, Fairies
FEN: 7B/8/6k1/4B3/8/4Pp2/7b/4K2r
Reprints: H49 Vkontakte 2013
H49 Phénix 261/262, p. 10358, 2013
Input: Gerd Wilts, 2009-01-06
Last update: A.Buchanan, 2018-12-04 more...

27 - P1090940
Petko A. Petkov
373 Phénix 06/1989
1. Preis

(12+9)
s#4

Korrektur der 582 Rex Multiplex 1986
1. f8=S droht 2. De7+ Kxf5 3. Dxe4+ Sxe4 4. Sg3+ Sxg3#
1. f8=S Db5 2. d4+ exd3ep 3. Lg4+ Ke4 4. Df4+ Sxf4# (2. Sxd7+?)
1. f8=S Dc5 2. Sxd7+ Txd7 3. Lg6+ Ke6 4. Df6+ Sxf6# (2. d4+?)
play all

Anton Baumann: C+ Gustav 4.2a (2023-07-05)
comment

Keywords: Beseitigung hinderlicher Kraft, Beseitigung hinderlicher Masse, double-check mate, Dual avoidance, Echo-Manöver, half-battery, black, half-pin white pieces
Genre: s#
FEN: 8/2rp1P1N/2qp3P/R2nkBQK/1p2p2R/2n5/3PN1P1/B7
Input: Frank Müller, 2009-09-09
Last update: Frank Müller, 2009-09-09 more...

28 - P1090949
Lajos Riczu
461 Phénix 08/1989

(11+8) cooked
s#6

1. Tf4+ Se4 2. Da1+ c3 3. Da4+ Tc4 4. Dd7+ Td5 5. Sf5+ exf5 6. Lf6+ Sgxf6#
6. ... Se5!
play all

Cook: unlösbar 2. ... Kd5!

Anton Baumann: scheitert ferner auch an 6.Lf6+ Se5!
Mögliche Korrektur: sSg4 nach g8, -wBe7, wSg7 nach e7 (10+8)
Mit diesen Korrekturen C+ Gustav 4.2a (2022-04-29)
comment

Keywords: no solution
Genre: s#
FEN: 5q2/4PPNK/3npRP1/2r3r1/2pk2nB/3N4/3PP3/7Q
Input: Frank Müller, 2009-09-09
Last update: Marcin Banaszek, 2022-05-02 more...

29 - P1091121
George P. Sphicas
617 Phénix 03/1990

(6+2) cooked
s#12

1. f8=T+ Kg7 2. h8=L+ Kxf8 3. b8=T+ Ke7 4. De8+ Kd6 5. d8=D+ Kc5 6. Tc8+ Kb4 7. Dd2+ Kb3 8. Dde3+ Kb4 9. Lc3+ Kb3 10. La1+ Kb4 11. De1+ Kb3 12. Tc1 a2#
NL 1. b8=D+ Kg7 2. Dg8+ Kf6 3. f8=T+ Ke7 4. De8+ Kd6 5. d8=D+ Kc5 6. Da2 Kb4 7. h8=L Kc5 8. La1 Kb4 9. Tf1 Kc5 10. Tc1+ Kb4 11. Db3+ Kxb3 12. Dd4,De4 a2#
play all

paul: The source is Phenix 09/1990 (2022-09-13)
comment

Keywords: konsekutive Umwandlungen 4 (TLTD)
Genre: s#
FEN: 7k/1P1P1P1P/8/7Q/8/p7/8/1K6
Input: Frank Müller, 2009-09-13
Last update: Olaf Jenkner, 2010-12-28 more...

30 - P1092954
Nikolay S. Zinovyev
3646 Phénix 2000-2001
Informalturnier 2000-01
Lob

(2+4)
#16

1. Kd1 Sf7 2. Kc2 Sd6 3. Tb4 Sf5 4. Kxc3 Sg3 5. Tb2 Se4+ 6. Kc2 Sc5 7. Tb4 Sb3 8. Te4 Sd4+ 9. Kc3 Sf3 10. Tb4 Sd2 11. Th4 Sb1+ 12. Kc2 Sd2 13. Td4 Sb1 14. Kb3 Sa3 15. Td2 Sb1 16. Txa2#
play all

paul: Stockfish+ (2021-05-07)
comment

Keywords: Minimal
Genre: n#
FEN: 7n/8/1R6/8/8/2p5/p7/k3K3
Input: Frank Müller, 2009-10-24
Last update: Frank Müller, 2009-10-24 more...

31 - P1093002
Nikolay S. Zinovyev
4036 Phénix 07-08/2002

(2+5)
#8

1. Ld1 Tf5 2. Lg4 Tf8! 3. Ld7 Tf6 4. Lc8 Tb6! 5. Lf5 Tb4 6. Lh3 Tg4 7. Lxg4 nebst 8. Lf3#
play all

Anton Baumann: C+ Gustav 4.2a (2022-05-06)
comment

Keywords: Minimal
Genre: n#
FEN: 8/8/8/1r6/8/1B6/1b3p1p/5K1k
Input: Frank Müller, 2009-10-24
Last update: Frank Müller, 2009-10-24 more...

32 - P1107168
Jan Janocko
924 Phénix 13 06/1991

(3+5) cooked
h#6

1. d3 g4 2. d2 g5 3. d1=L g6 4. c1=T g7 5. Kc2 g8=D 6. b1=S Da2#

NL:
1. c1=L e4 2. Ta3 e5 3. Ta1 e6 4. Ka2 e7 5. Tb1 e8=D 6. Ka1 Da4#
1. Ta3 e4 2. c1=L e5 3. Ta1 e6 4. Ka2 e7 5. Tb1 e8=D 6. Ka1 Da8#
play all

Yuri Bilokin: Correction: bRc3, +bBa8, +bPa4, +bPc6, +bPe5 b7/8/2p5/4p3/p2p4/2p5/1pp1P1P1/1k4K1 (3+9) (2021-05-02)
comment

Genre: h#
Computer test: Popeye Windows-32Bit v4.51 (100000 KB)
FEN: 8/8/8/8/3p4/2r5/1pp1P1P1/1k4K1
Input: hpr, 2010-06-05
Last update: hpr, 2010-06-05 more...

33 - P1107846
Viktor Sizonenko
6043 Phénix 11-12/2009
2. Preis

(7+2)
s#16

1. Tf4 Kh6 2. Tf6+ Kh5 3. Sf4+ Kh4,Kh6 4. Sg2+ Kh5 5. Ke3 Kh6 6. Kd3+ Kh5 7. Kd2 Kh6 8. Ke1+ Kh5 9. Tg5+ Kh6 10. Ld2 Txf6 11. Tg6+ Kh5 12. Th6+ Kg4 13. Dh5+ Kg3 14. Dh4+ Kxg2 15. Dh3+ Kg1 16. Df1+ Txf1#
play all

paul: Self-anticipated by P1271622 (2022-09-26)
comment

Keywords: Stalemate dissolution
Genre: s#
FEN: 8/5Q2/6r1/7k/6R1/5KRN/4P3/2B5
Input: Frank Müller, 2010-06-17
Last update: Frank Müller, 2014-08-17 more...

34 - P1112253
Bo Lindgren
5104 feenschach 83 04-06/1987
Walter Jörgensen zum 70. Geburtstag
1. Preis Informalturnier

(9+10) cooked
ser-s#42

1. e8=S 2. Sxf6 3. Sd5 4. f6 5. f7 6. f8=D 7. Dxf3 8. Dg2 9. f4 10. f5 11. f6 12. f7 13. f8=L 14. Lxh6 15. Le3 16. h6 17. h7 18. h8=T 19. Txh4 20. Te4 21. h4 22. h5 23. h6 24. h7 25. h8=D 26. Dxb8 27. De5 28. b8=L 29. Lxa7 30. Lc5 31. a7 32. a8=T 33. Txa4 34. Tb4 35. a4 36. a5 37. a6 38. a7 39. a8=S 40. Sab6 41. Sc4 42. Dxe2+ Sxe2#
play all

Preisbericht (Gruppe 8 = "Rest") siehe feenschach 10/1990, S. 368.
Doppelte AUW in einem langzügigen Serienzugselbstmatt, da kann man nur mit Mutter Kempowski sagen: "Wie isses nur möglich!". Kein Wort, nur tief durchatmen und staunen! (Preisrichter Theodor Steudel).
Cook: 1. e8=S 2. Sxf6 3. Se4 4. Sd2 5. f6 6. f7 7. f8=D 8. Dxf3 9. Dxe2 10. f4 11. f5 12. f6 13. f7 14. f8=L 15. Lxh6 16. Le3 17. h6 18. h7 19. h8=T 20. Txh4 21. Te4 22. h4 23. h5 24. h6 25. h7 26. h8=D 27. Dxb8 28. De5 29. b8=L 30. Lxa7 31. Lc5 32. a7 33. a8=T 34. Txa4 35. Tb4 36. a4 37. a5 38. a6 39. a7 40. a8=L 41. Ld5 42. Sc4+ Sxe2# mit Dualen (Arnold Beine)

Erich Bartel: Ein Wahnsinnsproblem!!! (2012-06-13)
Arnold Beine: Leider kaputt, denn am Ende kann man das Selbstmatt auch mit einem Batterieschach erzwingen. Die thematisch vergleichbare P1278403 hat aber gute Chancen, korrekt zu bleiben. (2022-10-22)
comment

Keywords: Allumwandlung (2x), Seriesmover, konsekutive Umwandlungen 8 (SDLTDLTS), Excelsior white (3x)
Genre: Fairies
FEN: 1r6/pP2P3/P4r1p/5P1P/p2K3p/5p2/P1k1pP1P/6n1
Reprints: 1938 U.S. Problem Bulletin 01-02/1990
feenschach 96 10/1990
Springaren (46), p. 125, 09/1991
G30 FIDE Album 1986-1988 1995
18 Mat Plus (6-7), p. 237, 1995
Die Schwalbe (156), p. 236, 12/1995
Tim Krabbé's Website (57) 2000
G-III Probleemblad 01-02/2000
(9) Springaren , p. 108, 09/2011
(9) Tehtäväniekka 3 30/09/2011
L11 Phénix 09-10/2011
(1) Die Schwalbe , p. 337, 12/2011
(34) The Problemist , p. 272, 01/2012
Problem Observer 05/2012
Input: HBae, 2010-08-03
Last update: Arnold Beine, 2022-10-23 more...

35 - P1117005
Sujunbek I. Bolotbekow
Phénix 1989

(5+2)
#5

1. Kb3 e5 2. Lg3 Ke3 3. Sc3 Kd2 4. Lf2 Kc1 5. Le3#
play all

LX8L
SCHRECKE: C+, Gustav 4.2b, Brute Force (2022-10-16)
comment

Keywords: Miniature Collection (0328030)
Genre: n#
FEN: 8/8/4p3/8/N2kBB2/K2P4/8/8
Input: Zuncke/Bruder, 2010-09-11
Last update: Zuncke/Bruder, 2010-09-11 more...

36 - P1157276
Sujunbek I. Bolotbekow
592 Phénix 03/1990

(4+2)
#5

1. Kg3

SfK m
Rosalie Fay: 1. Kg3 (droht 2. Kh3) e6 2. Ld4 (droht 3. Kh3) e5 3. Lf2 ~ 4. Kh3 ~ 5. Sg3#
C+ Popeye Windows-64Bit v4.69 (2023-12-20)
comment

Keywords: Miniature Collection (0328050)
Genre: n#
FEN: 8/4p3/8/4B3/8/5K2/4N2P/7k
Input: Zuncke/Bruder, 2010-09-12
Last update: Zuncke/Bruder, 2010-09-12 more...

37 - P1157965
Evgeny Bogdanov
Phénix 2000

(2+2)
#3

1. Db2 Kh2 (1... Kh1 2. Kxf2 Kh2 3. Dh8#) 2. Dxf2+
play all

A12-34+ mm Echo
SCHRECKE: C+, popeye 4.87 (2021-11-09)
comment

Keywords: Miniature Collection (0327868)
Genre: 3#
FEN: 1Q6/8/8/8/8/5K2/5b2/6k1
Input: Zuncke/Bruder, 2010-09-12
Last update: Zuncke/Bruder, 2010-09-12 more...

38 - P1165943
Bernard Ivanov
5228 Phénix 157 12/2006

(4+2)
#5

1. Sd6 Kh6 2. Sf5+ Kg6 3. Kf4 Kh5 4. Lf7+ g6 5. Sf6#
play all

ASb5
vf: a1<>a8, Nikolai Chartschinschin, 07.2005, Kudesnik (94.95)
SCHRECKE: C+, Gustav 4.2f, Brute Force
Der "Vorgänger" (P1123589) hat einen Dual! (2024-03-08)
comment

Keywords: anticipated (P1123589)
Genre: n#
FEN: 6B1/5NpN/6k1/8/6K1/8/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Felber, Volker, 2024-03-08 more...

39 - P1186866
Thierry Le Gleuher
T10 Phénix 173/174, p. 7566, 05-06/2008
nach Gerd Wilts

(9+9)
Wer ist am Zug?

R: 1. ... f4xLg3 2. Lh4-g3 f5-f4 3. Lf6-h4 h3-h2 4. Lb2-f6 h4-h3 5. Lc1-b2 h5-h4 6. b2xLa3 Lc5-a3 7. e3-e4 Ld4-c5 8. c5-c6 Lf6-d4 9. c4-c5 Le7-f6 10. c3-c4 Lf8-e7 11. c2-c3 e7xTd6 12. Td4-d6 Kd8-c8 13. d6xTc7
play all

Henrik Juel: White has the move
-1... f4xLg3 -2.Lh4 f5 -3.Lf6 h3 -4.Lb2 h4 -5.Lc1 h5 -6.b2xLa3 Lc5 -7.e3 Ld4 -8.c5 Lf6 -9.c4 Le7 -10.c3 Lf8 -11.c2 e7xTd6 -12.Td4 Kd8 -13.d6xTc7, retract Td4 to h1, Ka8 via g6 to e1, Pd6 to h2, g3-g2, g2xLf3 etc. (2013-08-28)
James Malcom: Is the given retraction unique? (2020-11-08)
Henrik Juel: Unique up to 11.c2-c3, I think (2020-11-08)
Henrik Juel: One of my favorite retros with just kings and pawns
even though the retroplay is not completely unique (so my previous comment is imprecise)
R: 2... h3-h2 3.Lf6-h4 h4-h3 or 3... f5-f4 also work
but not R: 1.e3-e4? or 1.c5-c6?, and White runs out of pawn retractions
nor 2. e3-e4? or 2. c5-c6? f5-f4 3. Le5-g3, and same difficulty (2020-11-09)
Henrik Juel: In the forward play we have several temporal implications, e.g.,
e2-e3 before b7xLa6 before g2xLf3 before g3-g2 before h2xg3
d6xc7 before e7xd6 before b2xLa3 before f4xLg3
Thierry was inspired by P0008574 (2020-11-09)
James Malcom: I see the similarities as well. If Thierry's last 21 moves, stopping at 11. c2-c3 of course, are indeed unique, it seems to be the record for a kindergarten position? (2020-11-09)
A.Buchanan: I think the last 2 single moves are determined. Prior to that it could be f5-f4 or h3-h2, no? (2020-11-10)
Henrik Juel: You are right, Andrew
So, no record, James (2020-11-10)
James Malcom: Ah well then-the linked problem with 16 moves by Gerd oughtta be it then, from what I've searched so far. (2020-11-10)
A.Buchanan: Isn’t the retro record one of the Breyer versions by Thierry Le Gleuher? (2020-11-10)
James Malcom: As far as I know, the TOTAL retro record is, all from P1339006, by Theierry indeed: Type A, 100 moves, Type B, 101 with bP6-h6 & White to move, and, finally Type C, 102 with bP6-h6 and wSc7-a8. (2020-11-10)
James Malcom: For Type B, I meant "bPh5-h6." (2020-11-10)
comment

Keywords: Whose move?, Kindergarten Problem
Genre: Retro
FEN: K1k5/p1Pp2p1/p1Pp4/8/P3P3/P4Pp1/3P1Ppp/8
Input: Gerd Wilts, 2011-02-06
Last update: James Malcom, 2020-11-08 more...

40 - P1187236
Christian Poisson
129 Phénix 1988

(8+9)
s#10
Längstzüger

1. e4 e5 2. Dg2 dxe4 3. Sd4 exd4 4. Ta6 b5 5. d8=L bxa4 6. Lxg5 axb3 7. Ta2 bxa2 8. Le3 g5 9. Lg1 hxg1=D 10. Dxg5 Dxg5#
9. ... hxg1=T 10. Df2+ Txf2#
9. ... hxg1=L 10. Dg4 Le3#
9. ... hxg1=S 10. De2+ Sxe2#
play all

Anton Baumann: kürzer: 5.Kb1 bxa4 6.Ka1 axb3 7.Df1+ Kd2 8.Df2+ Kc1 9.Db2+ cxb2# (2023-03-07)
comment

Keywords: Allumwandlung, black, Maximummer
Genre: Fairies
FEN: 8/1p1Pp1p1/1R6/1N1p2p1/P7/1Ppp4/1Q2P2p/2K1k3
Input: HBae, 2011-02-14
Last update: Olaf Jenkner, 2017-12-27 more...

41 - P1187847
Vitaly Medintsev
5545 Phénix 168, p. 7425, 2008

(4+3)
h#2
b) sLg7->g8

a) 1. Kxe6 e8=T 2. Ke6-f7 Se5#
b) 1. Kxg6 e8=S 2. Kg6-f7 Txf6#
play all

SCHRECKE: a)+b): C+, popeye 4.87 (2023-09-12)
comment

Keywords: Miniature, Phoenix, Zilahi
Genre: h#
FEN: 3K4/4P1b1/4RnN1/5k2/8/8/8/8
Input: Vitaly Medintsev, 2011-02-21
Last update: Alfred Pfeiffer, 2014-08-18 more...

42 - P1205139
Maryan Kerhuel
28 Phénix 08/1995

(1+2+1)
ser-#5
Anticirce
wKR=königlicher Läufer sKL=reflektierender König nBR=neutraler Superbauer

1. kLg4 2. kLd1 3. b8=nD 4. nDc8 5. kLf3#
Der Block der nD auf c8 ermöglicht den Mattzug. Märchen-Umwandlung.
play all

more ...
comment

Keywords: Circe, Seriesmover, Vielväterstellung
Genre: Fairies
FEN: *3k1*1K5/p7/1-*1P6/8/8/8/8/8
Input: Hans Gruber, 2011-10-09
Last update: Gerd Wilts, 2024-02-28 more...

43 - P1205859
Romeo Bedoni
R25 Phénix 27 (47) 09/1994

(2+1)
Ser-#8
Anticirce

1. Kb5 6. a8=T 7. Te8 8. Kc6#
play all

Arnold Beine: Mit Typ Cheylan korrekt, mit Typ Calvet unlösbar. (2022-08-09)
Henrik Juel: With Anticirce Cheylan, C+ Popeye 4.61 (2022-09-22)
comment

Keywords: Circe (Anti-), Seriesmover
Genre: Fairies
FEN: 8/3k4/8/8/K7/8/P7/8
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-09-22 more...

44 - P1205861
Romeo Bedoni
R27 Phénix 27 (47) 09/1994

(1+2)
Ser-+9
Anticirce

1. Ka7 8. Kf8 9. Ke8+
play all

Arnold Beine: Mit Typ Cheylan korrekt, mit Typ Calvet unlösbar. (2022-08-09)
comment

Keywords: Circe (Anti-), Seriesmover, Move Length Record
Genre: Fairies
FEN: 1K6/3k4/8/3b4/8/8/8/8
Reprints: C7 Problemkiste (169) 02/2007
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-02-24 more...

45 - P1205868
Romeo Bedoni
R34 Phénix 27 (47) 09/1994

(1+3)
Ser-+12
Anticirce

4. Kf5 8. Kb6 12. Ke8+
play all

Arnold Beine: Mit Typ Cheylan korrekt, mit Typ Calvet unlösbar. (2022-08-09)
comment

Keywords: Circe, Seriesmover
Genre: Fairies
FEN: 1n5K/5k2/8/4b3/8/8/8/8
Input: Hans Gruber, 2011-10-09
Last update: Hans Gruber, 2011-10-09 more...

46 - P1205877
Romeo Bedoni
R46 Phénix 27 (47) 09/1994

(2+1)
Ser-H=7
Anticirce

7. Ka1 Th1=
play all

Anton Baumann: Forderung ergänzen: Anticirce, Typ Cheylan (Typ Calvet keine Lösung!)
C+ Alybadix (2021-03-18)
Henrik Juel: 1.Kg5 2.Kf4 3.Ke3 4.Kd2 5.Kc1 6.Kb1 7.Ka1 Th1=
In the final position wTh1 does not check sKa1 because of type Cheylan
wKb3 controls a2 and b2, and wTh1 controls b1, so Black is stalemated (2021-03-18)
comment

Keywords: Circe, Seriesmover
Genre: Fairies
FEN: 7R/8/7k/8/8/1K6/8/8
Input: Hans Gruber, 2011-10-09
Last update: Hans Gruber, 2011-10-09 more...

47 - P1205880
Romeo Bedoni
R50 Phénix 27 (47) 09/1994

(2+2) cooked
Ser-H=13
Anticirce

5. g1=S 6. Se2 8. Kd2 10. Sd1 13. Ka1 Txd1[Th1]=
play all

Anton Baumann: Forderung ergänzen: Anticirce Cheylan (Typ Calvet: Keine Lösung!)
NL: 5.g1=T 6.Tg2 7.Te2 8.Ke3 9.Kd2 10.Te8 13.Ka1 Txe8[Th1]= (2021-04-14)
comment

Keywords: Circe, Seriesmover, Minimal, Miniature
Genre: Fairies
FEN: 8/6p1/8/8/5k2/1K6/8/4R3
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-08-09 more...

48 - P1205881
Romeo Bedoni
R51 Phénix 27 (47) 09/1994

(2+2)
Ser-H+8
Anticirce

1. Kc2 8. Kf8 Ke8+
play all

Arnold Beine: Mit Typ Cheylan korrekt, mit Typ Calvet unlösbar. (2022-08-09)
comment

Keywords: Circe (Anti-), Seriesmover, Move Length Record
Genre: Fairies
Computer test: %C+ PY 3.21 am 21.12.1994
FEN: 8/3K1p2/5P2/8/8/8/8/1k6
Input: Hans Gruber, 2011-10-09
Last update: Erich Bartel, 2012-05-30 more...

49 - P1205938
Romeo Bedoni
R110 Phénix 27 (47) 09/1994

(2+2)
Ser-H+7
Marscirce

5. h1=L 7. Lb3 axb3+
play all

Arnold Beine: In dieser Stellung ist die Aufgabe unlösbar, da der wK bedroht ist. Mit wKg8 wäre die Aufgabe korrekt. (2022-08-10)
comment

Keywords: Circe, Seriesmover
Genre: Fairies
FEN: 5K2/7p/P7/8/8/k7/8/8
Input: Hans Gruber, 2011-10-09
Last update: Hans Gruber, 2011-10-09 more...

50 - P1210776
Petko A. Petkov
1909 Phénix 27 09/1994
Zum Gedenken an meine Mutter Danka
4. Preis

(10+10)
s#4
Circe
sDU=Grashüpfer
sSU=Nachtreiter
wSL=Kamel
wSR=Zebra

1. Da8! droht 2. f8=ZE+ Kh8 3. ZEd5+ Gxd5[+wZEd8] 4. ZEd8-b5+ Gxb5[+wZEb8]#
1. ... Ga2 2. f8=G+ Kh8 3. Gb4+ Lxb4[+wGb8] 4. Gxb3[+sBb7]+ Nxb3[+wGb8]#
1. ... Gd5 2. f8=CM+ Kh8 3. CMe5+ fxe5[+wCMe8] 4. CMf5+ Gxf5[+wCMf8]#
1. ... d3 2. f8=N+ Kh8 3. Nd4+ Gxd4[+wNd8] 4. Nf4+ Gxf4[+wNf8]#
play all

PR B. Kampmann, PB Phenix (65) 07/1998

Anton Baumann: C+ Alybadix (2022-11-24)
comment

Keywords: Circe, Allumwandlung (Märchen)
Pieces:

= Zebra (ZE),

= Grasshopper (G),

= Nightrider (N),

= Camel (CM)
Genre: Fairies
FEN: 4Q3/2R2P1k/5pR1/2P5/3pp3/1p2p2*3N/1P1*2qPp*1N1/*2n3bK2
Reprints: G158 FIDE Album 1992-1994 2001
Input: Hans Gruber, 2011-10-09
Last update: HBae, 2017-11-14 more...

51 - P1210778
George P. Sphicas
1913 Phénix 27 09/1994

(9+6)
ser-s#22
sSU=Nachtreiter

1. g8=N 2. Ne4 3. Nxc5 4. Na1 5. c5 6. c6 7. c7 8. c8=N 9. Nxa7 10. N7g4 11. a7 12. a8=N 13. Nd2 14. f4 15. d8=N 16. Na2 17. f5 18. f6 19. f7 20. f8=N 21. Nfc2 22. Nh4+ Nxh4#
play all

more ...
comment

Keywords: Seriesmover
Pieces:

= Nightrider (N)
Genre: Fairies
FEN: 8/p*2n1P2P1/P7/p1p5/2P5/7p/1R3PkP/1KR5
Input: Hans Gruber, 2011-10-09
Last update: Arnold Beine, 2022-10-30 more...

52 - P1211091
Eric Huber
4356 Phénix 120 07-08/2003

(3+1)
h#2
Augsburger Schach Circe
b) wSd4 -> f4 c) wLa6 -> f1

Intendiert ist vermutlich, daß auch T+L getrennt wiedergeboren werden. (Vgl. andere Definition im zeitgleich erschienenen Quartz. )
a) 1. Kd3 Sb5=TS 2. Kc4 Lb5=TLS#
b) 1. Kxf4 [Sg1] Lb5=TL 2. Kg4 TLg5#
c) 1. Kxd4 [Sg1] Se2 2. Kc4 Le2=LS#
play all

paul: Co-author: I. Murarasu (2024-01-25)
paul: I. Murarasu added the twin d)Sd4 to h5. Published in Phenix 150/2006. (2024-01-25)
comment

Keywords: Augsburg Chess, Circe
Genre: Fairies
FEN: 8/8/B7/1R6/3Nk3/8/8/8
Input: Hans Gruber, 2011-10-09
Last update: Hans Gruber, 2011-10-09 more...

53 - P1211411
Romeo Bedoni
B1 Phénix 96-97, p. 5215, 05-06/2001

(2+1)
ser-#6
wDR=Chimäre

1. a8=L 2. Ld5 3. Cd6 4. Le6 5. Cf6 6. Lf7#
play all

Alfred Pfeiffer: Wie zieht die Figur "Chimäre"? (2011-10-17)
Arnold Beine: Chimäre: Zieht wie Grashüpfer über einen Sprungbock der eigenen Farbe und wie Heuschrecke über einen Sprungbock der gegnerischen Farbe. Über einen neutralen Stein kann die Chimäre nach freier Wahl entweder wie Grashüpfer oder Heuschrecke ziehen. (2022-08-10)
comment

Keywords: Seriesmover
Genre: Fairies
FEN: 5k2/P7/8/8/8/8/8/3*1Q4
Input: Hans Gruber, 2011-10-09
Last update: Frank Müller, 2011-10-17 more...

54 - P1224627
George P. Sphicas
The Problemist 1991
6. Preis

(10+10) cooked
ser-s#42

1. d8=D 2. Dxe7 3. Dc5 4. e7 5. e8=L 6. Lexg6 7. Lxh5 8. g6 9. g7 10. g8=T 11. Txg4 12. Tf4 13. g4 14. g5 15. g6 16. g7 17. g8=T 18. Tg3 19. Td3 20. g4 21. g5 22. g6 23. g7 24. g8=T 25. Tgg3 26. Tge3 27. Lf3 28. h5 29. h6 30. h7 31. h8=D 32. Dxa8 33. Dad5 34. a8=D 35. Dxa4 36. Daxd4 37. a4 38. axb5 39. b6 40. b7 41. b8=L 42. Le5 Sf2,Sg3#
play all

Das FIDE Album nennt The Problemist 1990, das USPB und Phenix hingegen 1991.
Vorläufer siehe P1112541.
Cook: 8. g6 9. g7 10. g8=T 11. Txg4 12. Tf4 13. g4 14. g5 15. g4 16. g6 17. g5 18. g7 19. g6 20. g8=D 21. g7 22. Dxa8 23. g8=T 24. Dad5 25. a8=T 26. Txa4 27. Txd4 28. a4 29. axb5 30. Td3 31. b6 32. b7 33. Tgg3 34. Tge3 35. Lf3 36. h5 37. h6 38. h7 39. b8=L 40. h8=D 41. Dhd4 42. Le5 Sf2,Sg3# (Paul Raican)

VL: The Problemist 03/1991, p.348, F1166v (FEN only). (2016-08-22)
more ...
comment

Keywords: Seriesmover, konsekutive Umwandlungen 8 (DLTTTDDL)
Genre: Fairies
FEN: r7/P2Pp3/4P1p1/1p3BPp/p2pK1pP/6P1/P5P1/1k5n
Reprints: A1009 Phénix 05/1994
3142 U.S. Problem Bulletin 07-10/1994
G43 FIDE Album 1989-1991 1997
Input: Frank Müller, 2011-11-13
Last update: Arnold Beine, 2022-11-17 more...

55 - P1228076
Dmitri Baibikow
A20 Length Records in Last Single Moves? 04/2009

(10+10)
Last 28 single moves?

n-14... b7-b6 n-13.f2-f3 Bc8-b7 n-12.f3-f4 Bb7-f3 n-11.f4-f5 Bf3-g4 n-10.f5-f6 Bg4-h3 n-9.g2xBh3 g3-g2 n-8.h3-h4 g2-g1=R n-7.h4-h5 Rg1-g4 n-6.Na4-c5+ Rg4-a4 n-5.Nc5-e6 f7xNe6 n-4.f6-f7 e6-e5 n-3.f7-f8=N e5-e4 n-2.Nf8-g6 e4-e3 n-1.Ng6-e7 e3-e2 n.Ne7-g8
play all

Highest number of retro moves with 20 pieces.
See http://abrobecker.free.fr/chess/lengths.pdf
Hans-Jürgen Manthey: R: 1. Se7-g8 e3-e2 2. Sg6-e7 e4-e3 3. Sf8-g6 e5-e4 4. f7-f8=S e6-e5 5. f6-f7 f7xSe6 6. Sc5-e6 Tg4-a4 7. Sa4-c5+ Tg1-g4 8. h4-h5 g2-g1=T 9. h3-h4 g3-g2 10. g2xLh3 Lg4-h3 11. f5-f6 Lf3-g4 12. f4-f5 Lb7-f3 13. f3-f4 Lc8-b7 14. f2-f3 b7-b6 und weiter könnte folgen 15. b6xTa7 g4-g3 16. c5xSb6 Sd5-b6 17. d4xTc5 Tc6-c5 18. e3xDd4 Kb6-a5 19. Sc5-a4+ g5-g4 20. Ta4-a3 Dh8-d4 21. Td4-a4 Dd8-h8 22. Se4-c5 Tg6-c6 23. Sd2-e4 Kc6-b6 24. a5-a6 Kd6-c6 25. Sf3-d2 a6xLb5 26. Td1-d4 Ke7-d6 27. Th1-d1 Tg8-g6 28. Sg1-f3 Th8-g8 29. Lf1-b5 Sf6-d5 30. Kc4-b3 Sg8-f6 31. Kd3-c4 Sb6-a8 32. Ke2-d3 Sd5-b6 33. Ke1-e2 Sb4-d5 34. e2-e3 Sc6-b4 35. a4-a5 b3xTa2 36. Ta1-a2 Sb8-c6 37. a2-a4 c4xDb3 38. Db6-b3 Ke8-e7 39. Dd6-b6 Ta8-a7 40. Dd1-d6 d5xSc4 41. Se3-c4 d6-d5 42. Sd5-e3 e7xLd6 43. Lf4-d6 a7-a6 44. Lc1-f4 g6-g5 45. d2xLc3 Lg7-c3 46. Sb6-d5 Lh6-g7 47. Sa4-b6 Lf8-h6 48. Sc3-a4 g7-g6 49. Sb1-c3 (2021-07-23)
comment

Keywords: Last Moves? (28), Type A, Move Length Record
Genre: Retro
FEN: n5N1/P1pp3p/Pp6/kp5P/r7/RKP5/pPP1p2P/8
Reprints: A20 Phénix 282, p. 11061, 02/2018
Input: Alain Brobecker, 2011-12-27
Last update: A.Buchanan, 2020-05-01 more...

56 - P1230077
Vlaicu Crisan
6367 Phénix 208 07-08/2011

(4+5)
-16 & s#1
Proca-Retraktor
Anticirce

R: 1. Bh5xBh5ep Bg7-g5 2. Dg2xDh1(Dd1) Lh2-g1+
3. Kg3-h4 Lg1-h2+ 4. Kf2-g3 Lh2-g1+ 5. Kf1-f2 Lg1-h2+
6. Ke1-f1 d3-d2+ 7. Kh4xBg4 Lh2-g1+
8. Kg3-h4 Lg1-h2+ 9. Kf2-g3 Lh2-g1+ 10. Ke1-f2 Lg1-h2+
11. Kh4xTg5(Kd1) Lh2-g1+
12. Kg3-h4 Lg1-h2+ 13. Kf2-g3 Lh2-g1+ 14. Ke1-f2 Lg1-h2+
15. Kd5xLe4 Tc8-c6+ 16. Kd6-d5, dann 1. Df3+ Dxf3(Dd8)#
play all

paul: Cooked in 9 moves: 1.QxRh5Qd1 Rg5-h5 2.Kg3-h4 Rh5-g5 3.Kf2-g3 Bh2-g1 4.Ke1-f2 d3-d2 5.Kd7xRc7Ke1 Rc8-c7 6.Ke8-d7 Rc7-c8 7.f6xSg7g2 Se6-g7 8.Kd7-e8 Rc8-c7 9.Qe2xSe1Qd1 & 1.Qe4+ Kxe4(or Kxf6)-Ke8# (Phenix 234/2013) (2023-03-12)
comment

Keywords: Defensive Retractor, Type Proca, Circe (anti)
Genre: Retro, Fairies
FEN: 8/5N2/2r4p/5k2/7K/8/3p2P1/3Q2b1
Input: Mario Richter, 2012-01-13
Last update: A.Buchanan, 2023-04-07 more...

57 - P1237446
Bo Lindgren
5937 Mat (Belgrade) 07-08/1989
1. Preis, Richter:M.Tomasevic

(8+8) cooked
ser-s#34

1. e8=L 2. Lxf7 3. Lc4 4. f7 5. f8=S 6. Sxd7 7. Sc5 8. d7 9. d8=L 10. Lg5 11. Lxh6 12. Le3 13. h6 14. h7 15. h8=T 16. Txh4 17. Te4 18. h4 19. h5 20. h6 21. h7 22. h8=D 23. Dxa8 24. Dd5 25. a8=D 26. Dxa3 27. Db4 28. a4 29. a5 30. a6 31. a7 32. a8=T 33. Ta1 34. Dc3+ Lxc3#
play all

Cook: 1. e8=L 2. Lxd7 3. Le8 4. d7 5. Lxf7 6. Lc4 7. f7 8. f8=L 9. Lxh6 10. Le3 11. h6 12. h7 13. h8=T 14. Txh4 15. Te4 16. h4 17. h5 18. h6 19. h7 20. h8=D 21. Dxa8 22. Dd5 23. a8=D 24. Dxa3 25. Dac5 26. a4 27. a5 28. a6 29. a7 30. d8=D 31. a8=T 32. Ta1 33. Dda5 34. Dc3+ Lxc3# (paul)

more ...
comment

Keywords: konsekutive Umwandlungen 7, Allumwandlung, Seriesmover
Genre: Fairies
FEN: r7/P2pPp2/3P1P1p/7P/3K3p/p7/P1k4P/4b3
Reprints: Phénix (39) 03/1996
G38 FIDE Album 1989-1991 1997
Input: Frank Müller, 2012-04-25
Last update: Arnold Beine, 2022-08-03 more...

58 - P1238308
Hans Peter Rehm
JT Roland Lecomte 85
1. Preis

(9+9)
#8

1. Ke2 (droht 2. Tc4+ Lxc4 3. c3# )
1. Ke2 Lh5+ 2. g4 Lxg4 3. Kf1 Le6 4. Lf8 Le5 5. Lc5+ Kd5 6. Lb4+ Kd4 7. Tc4+ Lxc4 8. Lc3#

1er Prix : n°19 ;Hans Peter REHM.
Une très belle oeuvre basée sur la mise en place d'un double autoblocage
noir.
Un premier essai 1. Fb4 ? (2. Tç4+ Fxç4 3.Fç3#) échoue après
1. ... Fd5 ! préparant une fuite royale en é5.
Le second essai 1. Ff8 ? (2.Fxg7+ Fé5 3.Fxé5#) Fé5 2. Fb4 se
heurte à la superbe manoeuvre d'embuscade 2. ... Tf8 !! (3.Tç4+
Fxç4+ !) et la tentative 2. Fç5+ Rd5 3. Fb4+ permet une autre
fuite royale en é6.
C'est une manoeuvre péri-romaine qui va provoquer un blocage
éloignée en é6 :
1. Ré2 ! (2. Tç4+ Fxç4 3.ç3#) Fh5+ 2.g4 ! Fxg4+ 3. Rf1 (4.
Tç4#) Fé6
Les Blancs forcent ensuite le second blocage en é5 :
4. Ff8 (5. Fxg7+ Fé5 6. Fxé5#) Fé5
A présent la manoeuvre initiale fonctionne parfaitement :
5. Fç5+ Rd5 (Ré5 ??) 6. Fb4+ Rd4 (Ré6 ??) 7. Tç4+ Fxç4 8.
Fç3#.
Très belle logique, passionnant à résoudre. La manoeuvre de
réfutation par embuscade, dans le second essai, a constitué un
élément de poids dans le choix du Premier Prix. (Juge : Claude Wiedenhoff)
play all

Anton Baumann: C+ Gustav 4.1d (2021-04-16)
comment

Keywords: Perilenkung
Genre: n#
FEN: rb6/pp3bp1/3B4/1R4p1/3k4/P1RP2Pp/2PP4/5K2
Reprints: Phénix 2012
Input: Ralf Kr?tschmer, 2012-05-08
Last update: Ralf Kr?tschmer, 2012-05-08 more...

59 - P1241808
Valery Kirillov
Mykhailo Myshko
5164 Phénix 07-08/2006

(8+5) cooked
s#9*
2 Lösungen

* 1. ... Ke6 2. Dd5+ Kf6 3. Dg5+ Ke6 4. Df5+ Kd6 5. Dc5+ Ke6 6. Lc4+ Kf6 7. Dc6+ Te6 8. Sd5+ Kg6 9. De8+ Txe8#
1) 1. Sd7+! Ke6 2. Sf8+ Kf6 3. Lf5 Ke5 4. Le6+ Kf6 5. Th8 Ke5,Kg5 6. Dd5+ Kf6 7. Dd4+ Kg5 8. Dg1+ Kf6 9. Dg7+ Txg7#
2) 1. Sd5+! Ke6 2. Sxf4+ Kf6 3. Dd4+ Te5 4. Sd5 Ke6 5. Sc7 Ke7! 6. Th7+ Kf6 7. Lb1 Kg5 8. Dg4+ Kf6 9. Se8+ Txe8#
play all

SCHRECKE: Nebenlösung
1.Dd4+ Ke6 2.Dd5+ Kf6 3.Dg5+ Ke6 4.Df5+ Kd6 5.Dc5+ Ke6 6.Lc4+ Kf6 7.Dc6+ Te6 8.Sd5+ Kg6 9.De8+ T:e8#
1. ... Te5 2.Sd5+ Ke6 3.Sc7+ Kf6 4.Dd8+ Te7 5.Lf5 Ke5 6.Lh7+ Kf6 7.Te5 K:e5 8.Dd5+ Kf6 9.Se8+ T:e8#
3. ... Ke7 4.Th7+ Kf6 5.Lf5 K:f5 6.Dd7+ Te6 7.Th5+ Kf6 8.Sd5+ Kg6 9.De8+ T:e8#
7. ... Kg6 8.Dh7+ Kf6 9.Se8+ T:e8#
6. ... Kf6,Kg6 7.Dg7+ Kf5 8.Dg4+ Kf6 9.Se8+ T:e8#
5. ... Kg5 6.Dg1+ Kf6! 7.Dg7+ K:f5 8.Dg4+ Kf6 9.Se8+ T:e8# (2020-12-14)
comment

Genre: s#
FEN: 3Q2K1/4r3/pN3k2/P6R/5p2/1p1B1P2/1P6/8
Input: Frank Müller, 2012-06-16
Last update: Marcin Banaszek, 2020-12-14 more...

60 - P1244335
George P. Sphicas
12038 Die Schwalbe 10/2003
2. Preis

(9+8) cooked
ser-s=33

1. c8=D 2. Df5 3. Kd5 4. c7 5. c8=L 6. Ld7 7. La4 8. b5 9. c6 10. c7 11. c8=T 12. Tc4 13. Txe4 14. c4 15. c5 16. c6 17. c7 18. c8=T 19. Tc3 20. Tb3 21. c4 22. c5 23. c6 24. c7 25. c8=S 26. Sd6 27. Sc4 28. Sb2 29. La3 30. Teb4 31. Kd4 32. Kc3 33. Dc2+ Sxc2=
play all

Cook: Dual
11. c8=S 12. Sd6 13. c4 14. c5 15. c6 16. c7 17. c8=T 18. Tc3 19. Tb3 20. c4 21. c5 22. Sc4 23. c6 24. c7 25. c8=T 26. Te8 27. Sb2 28. La3 29. Txe4 30. Teb4 31. Kd4 32. Kc3 33. Dc2+ Sxc2=

t/alle Umwandlungen auf demselben Feld
paul: See P1313191 as a correction (2022-06-24)
more ...
comment

Keywords: Seriesmover, Allumwandlung
Genre: Fairies
FEN: 8/2P1B3/1rPK4/q1P4r/1P2p2P/2P5/2P5/b1k1nb2
Reprints: A4270 Phénix 169-170) 01-02/2008
Input: Erich Bartel, 2012-07-11
Last update: Alfred Pfeiffer, 2017-08-28 more...

61 - P1245453
Maryan Kerhuel
R36 Phénix (35) 11/1995

(2+2) cooked
ser-s=12;
Anticirce

1. Kd5 2. e4 3. e5 4. e6 5. e7 6. e8=D 7. Dd8 8. Kc6 9. Kb7 10. Ka8 11. Dd3 12. Dc2+ Kxc2[+sKe8]=
play all

aber UL:12.-- Kd1!!!!

Arnold Beine: Mit Typ Cheylan unlösbar, mit Typ Calvet nebenlösig, z.B.
1.Kf5 2.e4 3.e5 4.e6 5.e7 6.e8=D 7.Dd8 8.Ke6 9.Kd7 10.Kc8 11.Dd3 12.Dc2+ Kxc2 [sKc2-e8]= (2022-09-22)
comment

Keywords: Seriesmover, Move Length Record, Circe (Anti), Minimal, Miniature
Genre: Fairies
FEN: 8/8/1q6/8/4K3/8/4P3/2k5
Input: Erich Bartel, 2012-07-26
Last update: Arnold Beine, 2022-09-22 more...

62 - P1248056
Christian Poisson
XXXVIII) Phénix (RM) 12/1992

(1+2)
ser-s-Zb4 in 14
Sentinelles

1. Kg1 2. Kf1 3. Ke1 4. Kd1 5. Kc1 6. Kb1 7. Kxa2 8. Kb1[+wBa2] 9. a4 10. a5 11. a6 12. a7 13. a8=D 14. Dd5 Kb4
play all

SCHRECKE: C+, popeye 4.89 (2024-01-18)
comment

Keywords: Seriesmover, Move Length Record, Sentinels, Rex solus (w), Aristocrat, Excelsior
Genre: Fairies
FEN: 8/8/8/8/8/2k5/r7/7K
Input: Erich Bartel, 2012-09-07
Last update: A.Buchanan, 2024-01-18 more...

63 - P1260853
Milenko Dukic
Phénix 07-08/1997

(10+10)
#13

1. Sh6! Lc7 2. Sf7 Ld8 3. Sh8 Lc7 4. Sg6 Ld8 5. Sf8 Lc7 6. Sd7 Ld8 7. Sb8 Lc7 8. Sc6 Ld8 9. Sd4 Lc7 10. Sf3 Ld8 11. Se1 Lc7 12. Sg2 Ld8 13. Se3#
play all

Doppelveröffentlichung Troll / SZ
Anton Baumann: C+ Gustav 4.2a (2023-07-25)
comment

Keywords: Multiple publication
Genre: n#
FEN: 3b2N1/4p3/1p1pPp2/1P1k1Kp1/1Pp3Pp/2Pp3P/3P3P/8
Reprints: 356 Troll 26 10/12/1997
2620 Sächsische Zeitung 28/03/1998
Input: Felber, Volker, 2013-01-23
Last update: Felber, Volker, 2016-09-22 more...

64 - P1260893
Gunter Jordan
405 Troll 25 25/11/1998

(8+5)
#2

1. Se6! droht 2. Sg7#
1. ... Kxe6 2. Dd7#
1. ... fxe6 2. Dh7#
1. ... Sxe6 2. Dxf7#
1. ... Txe6 2. De4#
1. ... Lxe6 2. Db1#
play all

SCHRECKE: C+, popeye 4.85 (2021-05-18)
comment

Keywords: x pieces defend on one square (5), Line closing, Line opening, Flight giving sacrifice key, x pieces capture on one square (5)
Genre: 2#
FEN: 3n1N2/1Q3p2/2r5/4Pk1P/3R1P1K/1bP5/8/8
Reprints: I Phénix 312, p. 12134, 11/2020
Input: Felber, Volker, 2013-01-25
Last update: Gunter Jordan, 2021-05-18 more...

65 - P1263784
René Jean Millour
4141 Die Schwalbe 78 12/1982
2. Preis

(5+15)
h=9

1. g1=D d8=D 2. Db6 Dxd1 3. Db3 axb3 4. h1=D bxc4 5. Dh2 c5 6. Dd6 cxd6 7. e1=D dxe7 8. Df2 Dxg4 9. Df8 exf8=D=
play all

Anton Baumann: 'Die Schwalbe' 06/1984 S.272 NL gem. U. Ring: 1.Scd6 Sxg5 2.Se8 dxe8=D+ 3.Kf5 Dxh5 4.Df4 Dxe2 5.Dd2 Dxd1 6.g1=S Dxd2 7.Sf3 Sxf3 8.h3 Sxh2 9.e5 Dxh6 =
'Die Schwalbe' 08/1984 S.308: der Autor verbessert: Se4 und Be7 tauschen die Plätze! (2022-12-23)
more ...
comment

Keywords: Promotion (DDddd), konsekutive Umwandlungen 5 (dDddD)
Genre: Fairies
FEN: 8/3Pp2p/6kr/6br/2n1n1qp/2p4N/P1B1p1pp/K2b4
Reprints: P1 Phénix 39 03/1996
Input: Erich Bartel, 2013-03-07
Last update: Alfred Pfeiffer, 2018-01-23 more...

66 - P1282642
Romeo Bedoni
Phénix 09/1991

(2+7)
s#6
2 Lösungen
Längstzüger
sSR=Zebra
wBU=Berolinabauer

1) 1. BEg3! Td8 2. BEf4 Td1 3. BEg5 Td8 4. BEh6 Td1 5. BEg7 Td8 6. BEh8=ZE+ Txh8#
2) 1. BEf4! Td8 2. BEg5 Td1 3. BEh6 Td8 4. BEg7 Td1 5. BEf8=ZE Td8 6. ZEd5 Th8#
play all

Hier tritt der Minimalberolinabauer einmal einen normalen und einmal einen verzögerten Exzelsior an.
SCHRECKE: C+, popeye 4.85 (2021-02-17)
comment

Keywords: Maximummer, Excelsior, Minimal
Pieces:

= Zebra (ZE),

= Berolina Pawn (BE)
Genre: Fairies
FEN: 8/4p3/4kp2/4p2K/7n/8/7*2P/3r*1n3
Input: Erich Bartel, 2014-01-31
Last update: Alfred Pfeiffer, 2014-12-02 more...

67 - P1282678
Romeo Bedoni
Phénix 09/1991

(2+2)
s#3
2 Lösungen
Längstzüger
sLU=Prinzessin
wBR=Superberolinabauer

1) 1. SBe5! PRg8 2. SBh8=PR PRa2 3. PRc3+ PRxc3#
2) 1. SBb8=PR! PRg8 2. PRe5 PRa2 3. PRc3+ PRxc3#
play all

Zwei verschiedene beschleunigte Exzelsiormärsche des Superberolinabauern im Wenigsteiner, die allerdings auf das gleiche Schlußspiel hinauslaufen.
Anton Baumann: C+ Alybadix (2023-04-01)
comment

Keywords: Excelsior, Maximummer, Promotion (Märchen-)
Pieces:

= Princess (PR),

= Berolina Superpawn (SB)
Genre: Fairies
FEN: 8/8/8/8/4k3/8/*2b6*1P/K7
Input: Erich Bartel, 2014-02-02
Last update: Alfred Pfeiffer, 2014-12-02 more...

68 - P1282680
Romeo Bedoni
Phénix 09/1991

(4+5)
s#6
Längstzüger
b) ohne wLh6
sDL=Elefant(D+N)

a) 1. e3! ETc8 2. e4 ETc1 3. e5 ETc8 4. e6 ETc1 5. e7 ETc8 6. e8=ET+ ETxe8#
b) 1. e4! ETc8 2. e5 ETc1 3. e6 ETc8 4. e7 ETc1 5. Kg8 ETc8+ 6. e8=ET+ ETxe8#
play all

Gute Zwillingsbildung zur Exzelsiordifferenzierung.
Anton Baumann: kurz: a) 1.Kh8 ETc8+ 2.Lf8 ETc1 3.Lc5 ETf7#
b) 1.Kh6 ETc8 2.Lxf5 ETc1 3.Lc1 ETf7#
a) & b) 1.Kf6,Kg6 ETc8(+) 2.Kxg5 ETc1+ 3.Kh4 ETxh6# (2021-12-16)
comment

Keywords: Excelsior, Maximummer, Promotion (Märchen-)
Pieces:

= Elephant (ET)
Genre: Fairies
FEN: 8/6KB/7B/5pp1/8/6p1/4P2k/2*3q5
Input: Erich Bartel, 2014-02-02
Last update: Alfred Pfeiffer, 2016-08-16 more...

69 - P1284588
Steven B. Dowd
Rolf Wiehagen
6823 Phénix 234 12/2013

(5+2)
s#12

1. Dh6+ Kg8 2. Tg3+ Kf7 3. Dd6 Ke8 4. Tg8+ Kf7 5. Dd8 Ke6 6. Tf8 Ke5 7. Df6+ Ke4 8. Dc3 d4 9. De1+ Kd3 10. Tf3+ Kc2 11. Tc3+ dxc3
12. Sb2 cxb2#
play all

Anton Baumann: C+ Gustav 4.2a (2023-02-27)
comment

Genre: s#
FEN: 7k/8/6Q1/3p4/8/2R5/B7/K2N4
Input: hpr, 2014-04-16
Last update: hpr, 2014-04-20 more...

70 - P1287094
Ivan Soroka
6722 Phénix (231) 09/2013

(5+2)
s#11

1. Ta4 b3 2. Dc5+ Kd3 3. Da3 Kc3 4. Kd1 Kd3 5. Sc2 Kc3 6. Sd4 Kd3 7. Se6 Kc3 8. Te4 Kd3 9. Te1 Kc4 10. Dc5+ Kd3 11. Dc2+ bxc2#
play all

Anton Baumann: C+ Gustav 4.2a (2022-07-18)
comment

Genre: s#
FEN: 8/8/8/3Q4/1p6/2k5/R7/N1B1K3
Input: Frank Müller, 2014-08-17
Last update: Frank Müller, 2014-08-17 more...

71 - P1287695
George P. Sphicas
6945 Phénix (238) 04/2014

(7+8)
ser-hc#33

1. h1=D 2. Dxf3 3. Dxg4 4. f3 5. f2 6. f1=T 7. Txf5 8. Tc5 9. f5 10. f4 11. f3 12. f2 13. f1=L 14. Lb5 15. Kc4 16. Dd4 17. g4 18. g3 19. g2 20. g1=D 21. Dxg6 22. Dgd3 23. g5 24. g4 25. g3 26. g2 27. g1=S 28. Se2 29. Sc1 30. Sa2 31. axb3ep 32. Sb4 33. Sd5 cxb3#
play all

Henrik Juel: In the position after 30.Sa2, the last white move must have been b2-b4, allowing the ep capture. This is permitted by the stipulation's c (= consequential), requiring that all intermediate positions are legal.
The content is all-promotion plus one D-promotion.
The retro content is very small, but traditionally consequential series movers are considered to be retro problems (2014-09-07)
paul: 1.h1=B 2.Bxf3 3.Bc6 4.Kc4 5.f3 6.f2 7.f1=R 8.Rxf5 9.Rc5 10.Bb5 11.f5 12.fxg4 13.g3 14.g2 15.g1=S 16.Se2 17.Sc1 18.g4 19.g3 20.g2 21.Sa2 22.g1=Q 23.Qxg6 24.Qd3 25.g5 26.g4 27.g3 28.g2 29.g1=Q 30.Qgd4 etc. (2022-07-12)
A.Buchanan: If I've got it right, consequential sm is more than just asking that intermediate positions are legal. It involves at every move potentially a complete recalculation of rights. In regular sm and Alsatian fairy conditions, rights carry over from one move to the next. In Alsatian fairy conditions, all positions must be legal. Is this correct? (2022-07-12)
Henrik Juel: Yes, I think you are right, Andrew (2022-07-12)
comment

Keywords: Seriesmover, Consequent, Kindergarten Problem, Allumwandlung (dtlds), En passant, Excelsior, Promotion (dtlsd x5)
Genre: Retro, Fairies
FEN: 8/6p1/5pP1/5Pp1/pP1k1pP1/K1p2P2/2P4p/8
Input: Frank Müller, 2014-09-05
Last update: A.Buchanan, 2022-07-12 more...

72 - P1288722
Arnold Beine
Best Problems 2005
3. Preis
L. Vitale Memorial

(3+11)
h#19
Doppellängstzüger

1. a5 d4 2. c5 dxc6ep 3. Db6 cxb7 4. Dh6 bxc8=S 5. Dc1+ Ka2 6. Dh6 Sd6+ 7. Dxd6 Kb1 8. Dh2 Ka1 9. Db8 d5 10. Dh2 d6 11. Da2+ Kxa2 12. 0-0-0 dxe7 13. d5 Kb3 14. Td6 Ka4 15. Th6 Kb5 16. Ta6 Kxa6 17. g5 Kb5 18. Lh6 Kc6 19. Lf8 exf8=D,T (UW-Dual)
play all

Anton Baumann: abgesehen vom Umwandlungsdual C+ (Alybadix) (2023-03-28)
more ...
comment

Keywords: Valladao Task, En passant, Castling, Maximummer (Doppel-)
Genre: Fairies
FEN: r1bqkb2/ppppp1p1/8/3P4/8/8/3P4/K7
Reprints: A4387 Phénix (178), p. 7731, 11/2008
Input: Erich Bartel, 2014-09-30
Last update: Alfred Pfeiffer, 2014-09-30 more...

73 - P1289704
Zdenek Meergans
1047 Phénix 09/1991

(3+8)
h#3
2.1...
Anticirce

1) 1. Kc4 d8=D 2. Td7 e8=L 3. Kd3 Lxd7[+wLf1]#
2) 1. Sa3 d8=D 2. Ld7 e8=L 3. Ka4 Dxd7[+wDd1]#
play all

Anton Baumann: C+ Alybadix (2023-04-26)
comment

Keywords: Promotion, Circe (Anti-)
Genre: Fairies
FEN: 8/3PP3/8/r7/bb3K2/1knr4/2n5/q7
Input: Erich Bartel, 2014-10-28
Last update: Alfred Pfeiffer, 2014-10-28 more...

74 - P1292099
Unto Heinonen
Problemkiste (124) 08/1999
2. Platz
19. PK-Kompositionsthema

(5+2)
1w->ser-h#7
2.1...

1) 1. ... a8=S, dann 1. ... d5 2. d4 3. d3 4. d2 5. d1=L 6. Le2 7. Lb5 Sc5#
2) 1. ... Sbd4, dann 1. ... dxc6 2. c5 3. c4 4. c3 5. cxb2 6. b1=T 7. Tb6 a8=D#
play all

Richter Hans Gruber: Zwar die konventionelle Umwandlungsverteilung, die scheinbar vorgegebenen gewohnten Bahnen werden aber geschickt vermieden: schön, daß eine weiße Umwandlung im Vorschaltzug und eine im Mattzug erfolgt. Die zweite Lösung beginnt bei Weiß und bei Schwarz mit attraktiven Zügen, der Exzelsior dauert in beiden Lösungen unterschiedlich lang.
paul: Tested by Jacobi:
stip ~1
stip ser-h#7 forsyth 8/P2p4/k1S5/8/8/1S6/1P3K2/8 (2023-01-14)
comment

Keywords: Seriesmover, Allumwandlung, Excelsior
Genre: Fairies
FEN: 8/P2p4/k1N5/8/8/1N6/1P3K2/8
Reprints: Phénix (81) 01/2000
Input: Erich Bartel, 2014-12-07
Last update: Alfred Pfeiffer, 2014-12-08 more...

75 - P1292289
Felix Alexander Sonnenfeld
855 Phénix 12/1990

(7+9)
ser-r#8

1. axb8=L (dxe8=D?) 2. dxe8=D 3. Dh8 4. e8=T 5. Te4 (Dxh5?) 6. Dxh5 7. Lf4 (Df3?) 8. Df3 d1=S#
play all

Anton Baumann: C+ Alybadix (2020-11-19)
comment

Keywords: Seriesmover, Allumwandlung
Genre: Fairies
FEN: kn2n3/P2PPp2/5bp1/7p/8/2pPK3/2PpP3/8
Input: Erich Bartel, 2014-12-12
Last update: Alfred Pfeiffer, 2014-12-13 more...

76 - P1293839
Torsten Linss
6993 Phénix 241, p. 9626, 07-08/2014
Lob
Sektion h#4-n

(2+4)
h#7

1. d5 Kd3 2. d4 Kd2 3. d3 Kc3 4. d2 Kd3 5. d1=L Kd2 6. Lb3 Kc3 7. La2 Lb2#
play all

PR Yves Tallec 10/2016

doppelter konsekutiver Rundlauf des wK, schwarzer Excelsior
Henrik Juel: C+ Popeye 4.61 (also) (2020-11-13)
comment

Keywords: Excelsior black, Pure Round Trip (K K), Minimal (L), under-promotion (l), Selfblock, Model mate
Genre: h#
Computer test: DB 2013.1
FEN: 8/3p4/8/4r3/q7/k1K5/8/B7
Input: TLi, 2015-01-03
Last update: Gunter Jordan, 2022-11-16 more...

77 - P1296513
Christian Poisson
838 Phénix 12/1990
6. Preis, Tanagras
Richter: Maryan Kerhuel

(1+1+3)
#7
2.1...
Spiegelcirce
Längstzüger

1) 1. a8=nD Dh1+ 2. Dh5 Dxb5[+nBb7] 3. b8=nL Lh2 4. Lf4 Dh5 5. Ld2 Db5 6. La5 Dh5 7. Dxa5[+nLc1]#
2) 1. a8=nT Th8 2. Th5 Txb5[+nBb7] 3. b8=nS Th5 4. Sd7 Tb5 5. Sb6 Th5 6. Sa4 Ta5 7. Txa4[+nSb1]#
play all

Anton Baumann: C+ Alybadix (2023-03-24)
comment

Keywords: Allumwandlung, Circe (Spiegel-), Maximummer
Genre: Fairies
FEN: 8/-P7/8/1-P6/8/k7/-P7/K7
Input: Erich Bartel, 2015-02-01
Last update: Alfred Pfeiffer, 2015-02-02 more...

78 - P1299392
Raffi Ruppin
2775 Phénix (58) 12/1997

(6+9)
ser-h#9
Anticirce

1. c1=D 2. Dxd2[+sDd8] 3. d2 4. d1=L 5. Lxe2[+sLc8] 6. e2 7. exf1=T[+sTa8] 8. f1=S 9. Sxh2[+sSb8] Sb5#
play all

Anton Baumann: NL (mit ZU): 1.Tb2 2.c1=D 3.d6 4.Dxf1 [sDd8] 5.f1=S 6.exd2 [sBd7] 7.Txe2 [sTa8] 8.Tc8 9.Sxh2 [sSb8] Sd5# (2021-01-05)
comment

Keywords: Seriesmover, Allumwandlung, Circe (Anti-)
Genre: Fairies
FEN: 8/1pkp4/1rp5/8/8/2Npp3/2pPPp1P/5N1K
Input: Erich Bartel, 2015-03-16
Last update: Alfred Pfeiffer, 2015-03-17 more...

79 - P1299920
Krasimir Gandev
491 Phénix 08/1989

(2+2+4)
hs#6
Circe

1. d8=nS Kc3 2. cxd8=nL[+nSb8] Kb4 3. Kxd8[+nLf8] Ka5 4. g8=nT a6 5. fxg8=nD[+nTa8] Dxe6[+wBe2] 6. Dxa6[+sBa7] Sxa6[+nDd1]#
play all

Anton Baumann: unlösbar: Sxa6# ist nicht zwingend;
wegen sBa7 kann die Dame von a6 wieder wegziehen: 6.- Db7,Dc6,Dxe2... (2022-11-09)
comment

Keywords: Allumwandlung, Circe
Genre: Fairies
FEN: 4K3/p1-P-P1-P-P1/4P3/8/8/8/3k4/8
Input: Erich Bartel, 2015-03-24
Last update: Alfred Pfeiffer, 2015-03-24 more...

80 - P1303938
Christian Poisson
Phénix (RM), p. 284, 12/1988
Spezial-Lob

(4+3)
=3
Paracirce
Vulkancirce für Weiß
Spiegelcirce für Schwarz

1. Dc6 (Zugzwang)
1. ... exf1=D[+sDd1] 2. bxa8=D[+wDd1] Da1,D~ 3. Dxa1[+wDd1],DxD[+wDd1]=
1. ... exf1=T[+sTh1] 2. bxa8=T[+wTh1] Ta1,T~ 3. Txa1[+wTh1],TxT[+wTh1]=
1. ... exf1=L[+sLf1] 2. bxa8=L[+wLf1] Lh3,L~ 3. Lxh3[+wLf1],LxL[+wLf1]=
1. ... exf1=S[+sSb1] 2. bxa8=S[+wSb1] Sa3,S~ 3. Sxa3[+wSg1],SxS[+wSg1]=
1. ... e1=D,T,L,S 2. Txe1[+wTa1] Lxb7[+sLf1] 3. Txf1[+wTh1]=
play all

Walter Lindenthal: Unter dem hier ausgewiesenen, normalen Paracirce gilt die Regel, dass Bauern die auf ihre Umwandlungsreihe schlagen, als Bauern(!) wiedergeboren werden. Da im gegenständlichen Beispiel stattdessen aber die umgewandelte Figur wiedergeboren werden soll, muss hier die spezielle Bedingung "Paracirce p.r.p. ..." (pions renaissant promus) anstelle von normalem "Paracirce ..." zur Anwendung kommen. Dies hat Chr. Poisson auch selbst (in rex multiplex #23/24, dort Beispiel IX) so dargestellt. (2021-02-16)
comment

Keywords: Allumwandlung, Circe (Para-), Babson task, Miniature
Genre: Fairies
FEN: bk6/KP6/8/8/8/2Q5/4p3/5R2
Input: Erich Bartel, 2015-06-02
Last update: James Malcom, 2021-02-16 more...

81 - P1315670
Romeo Bedoni
1317 Phénix 1992
1. Lob
Informalturnier
Richter: T. Maeder

(0+0+5)
#5
Längstzüger
nBL=neutraler Superbauer
nKe8=Neutraler König

1. SUd8=nL Lh4 2. SUa5 Ld8 3. SUc8=nT Tc1 4. SUh8=nS Tc8 5. SUaxd8=nD#
play all

Henrik Juel: The solution looks OK, but it was not found by Popeye 4.61, which cannot find the last move axd8=nD#, for some reason... (2016-01-17)
Henrik Juel: Popeye 4.73 is no better
In the position with five neutral men, Ke8 Tc8 Ld8 Sh8 SBa5, it does not find the #1, 1.a5xd8=nD# (2016-01-17)
Anton Baumann: Auch Alybadix findet die Lösung nicht, d.h. 5.axd8=nD ist nicht auf der Liste der möglichen 5.Züge.
Gemäss Definition im Märchenschachlexikon kann der neutrale König aber so angegriffen werden!
Dann ist die Aufgabe allerdings, wegen mehreren NL, trotzdem nicht korrekt:
zB. 1.c8=nT+ Tc1 2.d8=nS(nL) Tc8 3.a5 Tc1 4.h8=nS Tc8 5.axd8=nD#
oder 1.d8=nD+ Dd1 2.Dc2 Dh7 3.c8=nL(nS) Db1 4.a8=nT Dh7 5.hxc8=nT(nD)# (2023-03-13)
Ulrich Voigt: Nein, die Lösungen funktionieren alle nicht, weil der letzte weiße Zug 5. a5xd8=nD nicht nur dem gegnerischen König Schach gibt, sondern auch dem eigenen, mithin also illegal ist. Die Definition im Märchenschachlexikon erlaubt es Weiß, den neutralen König mit einer WEISSEN Figur anzugreifen. Den neutralen König mit einer NEUTRALEN Figur anzugreifen, erzeugt ein illegales Selbstschach. Ausnahme: ein Schachgebot mit einem neutralen (Super-)Bauern, aufgrund der asymmetrischen Zugweise.

Übrigens ist die Stellung ohne die Längstzüger-Bedingung ein korrektes h#3:
1.nSPd3-d1=nR nRd1-d7 2.nSPa3-a1=nQ nSPc3-c6 3.nQa1-f6 nSPh3xd7#
(C+ Popeye Linux 4.87) (2023-03-14)
comment

Keywords: Allumwandlung, Maximummer
Pieces:

= Superpawn (SU)
Genre: Fairies
FEN: 4-K3/8/8/8/8/-*3P1-*3P-*3P3-*3P/8/8
Input: Erich Bartel, 2016-01-17
Last update: Alfred Pfeiffer, 2016-01-18 more...

82 - P1319883
Maryan Kerhuel
Jacques Dupin
Michel Caillaud
1428 Phénix (19-20) 12/1992
2. Preis
Informalturnier
Richter: Torsten Linß

(5+4) cooked
ser-dr#18
non stop

1. g8=S 2. Sf6 3. Se8 4. f8=D 5. Dh8 6. Dc3! 7. Sf6 8. Sd7 9. e8=L 10. Lg6 11. Dg7 12. Dh6 13. Sf6 14. Sg8 15. h8=T 16. Lxd3 17. Le2 18. Dh2#
play all

Alfred Pfeiffer: Was bedeutet der Zusatz "non stop"? (2016-05-10)
paul: Cooked in 15 moves: (virtual mate Sc3#) 1.g8=S 2.Sf6 3.e8=S 4.Sd6 5.Sfe8 6.f8=Q 7.Qh6 8.Sf6 9.Sde8 10.h8=Q (no more helpful moves) 11.Q8h7! 12.Sg7 13.Q×d3 14.Qde3 15.Qhh3‡
This genre is explained in Quartz 6/1998) (2021-05-26)
more ...
comment

Keywords: Seriesmover, Direct-Reflex
Genre: Fairies
FEN: r7/4PPPP/8/8/8/3n4/n5k1/K7
Reprints: Phénix 39, p. 3111, 03/1996
V Quartz 7, p. 114, 05/1998
feenschach 128, p. 317, 06-07/1998
Input: Erich Bartel, 2016-05-06
Last update: Arnold Beine, 2021-05-27 more...

83 - P1320838
George P. Sphicas
7455 Phénix (256) 12/2015

(7+7) cooked
ser-h=18

1. f1=S 2. d1=D 3. Dxd5 4. Db3 5. e3 6. e2 7. e1=T 8. Te3 9. Tc3 10. e4 11. e3 12. e2 13. e1=T 14. Tb1 15. c1=L 16. Sd2 17. Kb2 18. a1=L Lxb3=
play all

Cook: 1. Kb2 2. d1=L 3. a1=T 4. f1=L 5. Lc4 6. La2 7. Lb1 8. Le2 9. Ka2 10. e3 11. e4 Txe2=
1. Kb2 2. Kc1 3. Kd1 4. Ke2 5. c1=S 6. Sd3 7. Kf1 8. d1=D 9. Da1 10. Se1 11. e3 12. e2 13. e4 14. e3 Dxa1=

Olaf Jenkner: Korrektur siehe P1415262 (2024-02-25)
comment

Keywords: konsekutive Umwandlungen 6 (SDTTLL), Allumwandlung, Seriesmover
Genre: Fairies
FEN: 5BBQ/8/8/N2Pp3/4p3/8/p1pp1p1R/k6K
Input: Frank Müller, 2016-06-01
Last update: Vaclav Kotesovec, 2019-07-15 more...

84 - P1321438
Romeo Bedoni
B73 Phénix (60) 02/1998

(2+8)
ser-Obtention d'une position legale en orthodoxe in 2
4 Lösungen
Promotioncirce
Kamikaze

1) 1. c8=D[+wDd1] 2. Dxh5[-Dh5]
2) 1. c8=T[+wTh1] 2. Txh2[-Th2]
3) 1. c8=L[+wLf1] 2. Lxh3[-Lh3]
4) 1. c8=S[+wSb1] 2. Sxa3[-Sa3]
play all

Arnold Beine: Kamikaze wird nur in der 4. Lösung benötigt. (2022-08-10)
comment

Keywords: Allumwandlung, Circe (Promotion-), Kamikaze, Seriesmover, Kindergarten Problem, Minimal
Genre: Fairies
FEN: 6k1/2P4p/7p/7p/7p/p6p/7p/4K3
Input: Erich Bartel, 2016-06-18
Last update: Arnold Beine, 2022-08-10 more...

85 - P1329364
Evgeny Fomichev
Orbit 2014
1.-2. Preis ex aequo

(15+4) cooked
s#7

1. c8=S Sxb6 2. c4+ Sxc4 3. Te5+ Sxe5 4. g8=D+ Sf7 5. Tg7 b6 6. Kg6 Ke6 7. Sf4+ Sxf4#
1. ... Sc7 2. g8=D+ Se6 3. Lh4 Kd4 4. Da1+ Kd5 5. Dd4+ Kxd4 6. Lf6+ Kd5 7. Se3+ Sxe3#
play all

Cook: Duale

Anton Baumann: Umwandlungsduale: 1. ...Sc7 2.g8=D,L+ desgl. nach 1. ... Sb6 ... 4.g8=D,L+ (2021-04-15)
comment

Genre: s#
FEN: n3R3/1pP3PP/1P4R1/1B1k1K2/1P4N1/3P3N/2P2Bn1/7Q
Reprints: S/78 feenschach 07-08/2016
mpk6 Phénix 09/2016
Input: Frank Müller, 2017-01-07
Last update: Marcin Banaszek, 2021-04-19 more...

86 - P1338817
Dmitri Baibikow
7595 Phénix 265, p. 10474, 09/2016
4me Mention d'Honneur Phenix 2015-2016

(12+15)
Resolve the position

R: 1. ... Tb4-b3+ 2. Db3-a3 Sg5-f3 3. e7-e8=S Sf3-g5 4. e6-e7 Sg5-f3 5. e5-e6 Sf3-g5 6. e4-e5 Sg5-f3 7. e2-e4 Sf3-g5 8. Lf4-d2 Sd2-f3+ 9. Ld6-f4 g3-g2 10. Le7-d6 g4-g3 11. Ld8-e7 g5-g4 12. d7-d8=L g6-g5 13. d6-d7 a3-a2 14. d5-d6 d6xDc5 15. De3-c5+
play all

Bauernschläge
w: axb
s: bxc,dxc,exf,hxg
wUW: e8,d8,h8
Die Stellung läßt sich nur durch d6xc5 entsperren, nachdem der wUW-Bd bis d5 zurückgezogen hat. Nur der wLd2 läßt sich zunächst befreien, er muß also auf d8 entwandeln. Nach dem dafür notwendigen Lf4-d2 Sd2-f3+ braucht Schwarz 5 Tempi, vier liefert der sBg2, den fünften der sBa2. Nachdem dafür notwendigen Db3-a3 ist allerdings die falsche Seite am Retrozug, e7-e8=S würde die Retrozugpflicht auf Schwarz abwälzen, versperrt aber dem wL den Weg nach d8, analog e5-e6 und e3-e4. e6-e7 bzw. e4-e5 und e3-e3 würden den Weg wieder freimachen, aber mit der falschen Seite am Retrozug. Nur e2-e4! verhndert beides.

Dreifache Retro-Intersection (e7,e5,e3), dreimal Retroopposition (e8,e6,e4), weißer Excelsior-Bauer e.

'phénix': "Trois positions de rétro-intersection pour le pé (é7, é5, é3).
Trois positions de rétro-opposition pour le pé (é8, é6, é4).
Cinq rétro-coups pour un excelsior du pé (promu en Cavalier), afin de changer la parité de la position, dont trois essais correspondant aux trois rétro-intersections.
Une idée nouvelle semble-t-il, et en tout cas extrèmement originale."

Yoav Ben-Zvi: Analysis in English (approved by the composer):
The release of the Western cage requires unpromotion of WBd2 on d8 (via f4-d6-e7) and retreat of the unpromoted pawn to d5 allowing retraction of BPd6xc5. When WBf4-d2 is retracted BN stands on f3 or f1 (ready to retract to d2 to replace the WB as a shield for the WK) and completion of the maneuver requires 5 tempo retractions by BPs including BPa3-a2. This means WQa3 and WRa4 need to stand on b3,a4 (not on a3 as this obstructs the retreat of BPa2). The position of the mobile pieces WQ,WR and BN implies, by the "Parity Argument", that prior to the retraction of WBf4-d2 White must retract an odd number of moves by a pawn unpromoted from WNe8. Standing on e6 or e4 the unpromoted pawn has played an even number of retractions while on e7, e5 or e3 it interferes with the retro-path of WBd2 to d8 so its only option is to retract to e2 using a double-step first move.
Parity Argument is the main theme of the problem combined with Retro-Opposition on a3 between BPa2 and WQb3/WRa4. (2017-11-27)
Hans-Jürgen Manthey: R: 1. Tb3+ Da3 2. Sf3 e8=S 3. Sg1 e7 4. Sh3 e6 4. Sg5 e5 5. Se6 e4 6. Sd4 Ld2 7. Sf3+ Lf4 8. g2 Ld6 9. g3 Le7 10. g4 d8=L 11. g5 d7 12. a2 d6 13. dxDc5 Dc5+ 14. Kb5 De3+ 15. Tb6 Dh6 16. Kc5 Kc3 17. Kb6 h8=D 18. Sd2 h7 19. Le1 Td1 20. Dc1 h6 21. Ld2 Db3 22. Se4 Kd4 23. Lg5 Dd3 24. Le3 Lc2 25. Sg3 Kc3 26. Dg1 Kd2 27. c4 Le4 28. Sf5 h5 29. Dg4 h4 30. Thb4 Lg2 31. Th4 Ta4 32. Se7 Tc4 33. Tb5 Sb1 34. Tb4 Tc1 35. Te4 d5 36. Ka7 d4 37. hxBg6 g6 38. Lb6 g5 39. La5 b7 40. a3 b6 41. Kb8 g4 42. a4 axSb5 43. bxLc5 Lc5 44. Te8 Le3 45. O-O-O d3 46. Dd7 a4 47. d6 Sc3 48. Lb4 c6 Sb5 c5 49. Sa7 c4 50. exSf6 Sf6+ 51. Sc6 Sd5 52. La6 Sb4 53. b6 Sd3 54. a5 Se5 55. a6 Sf3 (2021-07-27)
more ...
comment

Keywords: Retro Opposition, Excelsior white
Genre: Retro
FEN: 4N3/1Pp2pp1/brP2p2/1kp5/R1p5/QrK2n2/pPBB1Pp1/1NqRb3
Reprints: Phénix 290-291, p. 11371, 11-12/2018
Input: A.Buchanan, 2017-09-05
Last update: A.Buchanan, 2019-02-09 more...

87 - P1339430
Gianni Donati
Phénix 2014
1. Preis
Phenix 2014

(11+14)
"non-unique PG in 46.5 to fool the animation engine"

Minimum number of white K moves?

1. Sf3 a5 2. Sd4 a4 3. Sb3 axb3 4. a3 Sh6 5. Sc3 Sf5 6. Sa2 bxa2 7. Tb1 axb1=L 8. h4 Se3 9. Th2 Sxd1 10. Th3 Se3 11. Tf3 Sf5 12. Te3 Sg3 13. Te6 Sh1 14. Te5 La2 15. Te4 Le6 16. Te5 Lf5 17. Te6 Lg6 18. Te5 Ta5 19. Te6 fxe6 20. h5 Lf7 21. h6 g6 22. Kd1 Lg7 23. Ke1 Le5 24. Kd1 Lh2 25. g3 0-0 26. Lg2 Le8 27. Ld5 Tf5 28. La2 Lf7 29. b3 Df8 30. Lb2 Dg7 31. hxg7 Le8 32. Ld4 Kf7 33. La7 Kf6 34. g8=D Lf7 35. Df8 Lg1 36. Dh6 b6 37. Dh2 Lb7 38. Ke1 Lf3 39. Kf1 Lg4 40. Kg2 Lf3+ 41. Kh3 Kg5 42. Dg2 Kh5 43. Dh2 Tg5 44. Dg2 Taf5 45. Dh2 Lg4+ 46. Kg2+ Lh3+ 47. Dxh3
example non-unique proof game
play all

answer = 8

Yoav Ben-Zvi: The last move was WQh2xh3# leaving one further missing Black piece. BPb6 came from b7, it could not have played BPa7xb6 as this would prevent entry of a White bishop to a7.
WP could not have promoted on f8 or h8 as this would require 2 captures by White in addition to the capture on h3. This implies that WBa7 comes from c1.
WBa2 could not originate from a promotion of WPh2 on g8 since, to open the way for the promoting WP, BP would need to vacate g7 prior to the promotion by BPg7-g6 and BPs standing on g6, e6 (or f7) and d7 prevent the escape of the promoted bishop from the North-East corner. This implies that WBa2 comes from f1.
BBg1 could not originate from a promotion of BPa7 on a1 since escape of the promoted BB from the promotion square requires its release by WPb2-b3 which implies that WBf1 has previously arrived at a2 so it was previously released by WPg2-g3 but WP standing on g3 obstructs the subsequent path of the promoted BB to h2-g1. This implies that BBg1 comes from f8.
BBf7 could not have originated from c8 since release of [BBc8] by BPb7-b6 must be preceded by the arrival of [WBc1] at a7 which is preceded by release of [WBc1] by WPb2-b3 which is preceded by arrival of WB at a2 which is preceded by release of [WBf1] by WPg2-g3 which is preceded by arrival of [BBf8] at h2 which is preceded by release of [BBf8] by BPg7-g6. But BP standing on g6 obstructs the subsequent path of [BBc8] to f7. This implies that BBf7 originates from a promotion on b1 by [BPa7].
On its way to promotion on b1, [BPa7] could not play BPa3xb2 (since this requires previous advance of WPb2 to b3 which would prevent the escape of the bishop promoted on b1 to f7) so it must capture 3 White pieces. All three captures must be completed and the promoted bishop must exit via a2 before WPb2-b3 is played releasing [WBc1]. This means [WRh1] could not cross c1 to be captured by [BPa7] on a2 or b1. A fourth White piece is captured on e6 by [BPf7].
The following is known about the position when Black plays the last of his 4 captures by pawn (BPf7xe6 or BPa2xb1=B):
Prior to its fourth pawn capture Black could not complete the entry of the promoted bishop to its dynamic cage (e8,f7,g8) as the promotion requires 3 captures and entry into the cage requires removal of the obstructing [BPf7], a fourth capture. BPg7 had not yet advanced to g6 (on g6 it obstructs the path of the bishop promoted on b1 to f7) therefore it stood on g7. BBg1 stood on f8 (locked in its home cage by [BPg7]). [BRh8] stood locked in the North-East corner. WPg3 stood on g2 (on g3 it obstructs the path of [BBf8], after its release by BPg7-g6, to g1 via h2). WBa2 stood on f1 (locked in its home cage by [WPg2]). WPb3 stood on b2 (on b3 it would obstruct the path of WBf1, after its release by WPg2-g3, to a2). WBa7 stood on c1 (locked in its home cage by [WPb2]). WK stood on e1 or d1 while WQd1 either stood on d1 or had been captured there. With both WBs locked at home White’s central cage was also locked. BPb6 stood b7 (on b6 it obstructs the path of [WBc1], after its release by WPb2-b3, to a7). [WPa2] stood on a3 (required to allow entry of [BPa7] to a2). [WPh2] could not have promoted on g8 via g7 (due to obstruction by BP standing on g7), if it has not been captured then it advanced at least to h4 to allow escape of [WRh1] from the South-East corner (to be captured on e6 or b file).
The critical position (prior to last capture by BP) looks like this (alternatively BPf7 has already captured on e6 and BP stands on a2 ready to capture on b1 and promote to bishop): 2bqkb1r/1ppppppp/2n1R1b1/r7/7P/P7/1PPPPPP1/2B1(Q?)KB1n Playing forward from this position: after 0…BPf7xe6 Black must play 1…B-f7, 2…P-g6, 3…B-g7, 4…B-e5, 5…B-h2 before White can play 6.P-g3 so White needs 5 tempo moves (in the alternative position after 0…BPa2xNb1=B White will need 4 additional tempo moves). 2 of these tempo moves can be Ph4-h5-h6 leaving 3 more. These 3 tempo moves can only be played by WK oscillating between e1 and d1 which proves that WQd1 was captured earlier on d1 and so WQh3 was promoted by WPh2 after capturing [BQd8] (not [BBc8]) on the dark square g7. Either WK plays K-d1, K-e1, K-d1 or else it starts on d1 which implies the move Ke1-d1 had been played earlier.
Going back to retraction from the diagram position: The Black piece captured on h3 by White’s last move (Qh2xh3#) could not be a Knight or Rook (This would require a second Black promotion) or a Queen (BQd8 was captured previously on g7) so it must have been BBc8. After -1.WQh2xBBh3 comes -1…BBg4-h3+ (since WQ was captured on d1 and the other 4 missing White pieces were captured by the BPs, no capture is available on h3) followed by -2.Kh3-g2 Bf3-g4+.

The moves Ke1-d1[1], Kd1-e1, Ke1-d1[2] as well as Kh3-g2 have been shown to be mandatory in any proof game. A minimal move path of the WK would add Kd1-e1[2] (third switchback), Ke1-f1, Kf1-g2, Kg2-h3 turning Kh3-g2 into the fourth switchback. These additional moves are conditional (required only for the move-efficient path) since WK could also get to h3 by exiting via b2,c3 and entering via g4 or h4.
Minimal path of WK: 1.Ke1-d1! 2.Kd1-e1! 3.Ke1-d1! 4.Kd1-e1 5.Ke1-f1 6.Kf1-g2 7.Kg2-h3 8.Kh3-g2! (2017-09-23)
Henrik Juel: Retroplay with eight moves by [Ke1]
White captured Dh2xLh3 and g6xDg7, and promoted to D on g8
Black captured [Dd1] on d1, axbxa2xb1=L, and f7xe6
-1.Dh2xLh3 Lg4 -2.Kh3 Lf3
then retract Lf3 to c8, b7-b6, La7 to c1, b2-b3, Kh3 to d1 (5 moves), La2 to f1, Tf5 to h8, h6xDg7-g8=D, Dg7 to d8, Kh5 to e8, Lh2-g1, then
-22.g2 Le5 -23.h5 Lg7 -24.h4 Lf8 -25.Ke1 g7 -26.Kd1 Lg6 -27.Ke1 f7xe6, etc. (2017-09-23)
James Malcom: Proof Game: 1. Nf3 a5 2. Nd4 a4 3. Nb3 axb3 4. a3 Nh6 5. Nc3 Nf5 6. Na2 bxa2 7. Rb1 axb1=B 8. h4 Ne3 9. Rh2 Nxd1 10. Rh3 Ne3 11. Rf3 Nf5 12. Re3 Ng3 13. Re6 Nh1 14. Re5 Ba2 15. Re4 Be6 16. Re5 Bf5 17. Re6 Bg6 18. Re5 Ra5 19. Re6 fxe6 20. h5 Bf7 21. h6 g6 22. Kd1 Bg7 23. Ke1 Be5 24. Kd1 Bh2 25. g3 O-O 26. Bg2 Be8 27. Bd5 Rf5 28. Ba2 Bf7 29. b3 Qf8 30. Bb2 Qg7 31. hxg7 Be8 32. Bd4 Kf7 33. Ba7 Kf6 34. g8=Q Bf7 35. Qf8 Bg1 36. Qh6 b6 37. Qh2 Bb7 38. Ke1 Bf3 39. Kf1 Bg4 40. Kg2 Bf3+ 41. Kh3 Kg5 42. Qg2 Kh5 43. Qh2 Rg5 44. Qg2 Raf5 45. Qh2 Bg4+ 46. Kg2+ Bh3+ 47. Qxh3# (2023-04-22)
A.Buchanan: Thanks James - to get the animation to run, I have to add a bogus sentence to the stipulation (2023-04-22)
comment

Genre: Retro
FEN: 1n6/B1pppb1p/1p2p1p1/5rrk/8/PP4PQ/B1PPPPK1/6bn
Reprints: H1 The Problemist 26-3, p. 119, 05/2017
Input: A.Buchanan, 2017-09-15
Last update: A.Buchanan, 2023-04-22 more...

88 - P1339644
Kostas Prentos
10 Belgrade Sake Tourney 2016
1st Prize

(8+0)
h#2
b) Tb1 nach d1
Colorless chess

a) 1. Tb7 L7b6 2. Sd7 cxb7#
b) 1. Lb8 c7 2. Td7 cxb8=D#
1. Kxc7? Se6+ 2. Kc8 Td8+ 3. Lxd8!
play all

a) The four pieces which move reveal their colours. So with 2. ... cxb7# delivers check to bK, whichever it turns it to be! All other flight squares are covered by wK, wLb6 & if necessary sSd7.
b) Now wK, wDb8 & (if necessary) sTd7 cover the flight squares.

A.Buchanan: Amazing that this idea can be implemented so cleanly. (2017-09-18)
paul: a)1.Rb7 B7b6 2.Sd7 cxb7#
b)1.Bb8 c7 2.Rd7 cxb8=Q#
1.Kxc7? Se6+ 2.Kc8 Rd8+ 3.Bxd8!
The two Kings' colors are not revealed in either phase. (2021-05-18)
A.Buchanan: What are the roles of La5 & Ba4?
Has this been proved sound? (Could run 128 h#2, then compare versions which allowed the same mate to see if all versions of unspecified piece support the mate.) (2021-05-18)
comment

Keywords: Colorless chess
Genre: Retro, Fairies, h#
FEN: K1K5/2B5/2P5/B1N5/P7/8/8/1R6
Reprints: 10 Problem Paradise 74, p. 44, 04-06/2016
B64 Phénix 275-276, p. 10838, 07-08/2017
Input: A.Buchanan, 2017-09-18
Last update: A.Buchanan, 2021-05-18 more...

89 - P1339646
Eric Huber
Vlaicu Crisan
15 Belgrade Sake Tourney 2016
3rd Prize

(8+0)
h#2 (3 sols)
Colorless chess

paul: 1.Rg1 Sc3 2.Rf1 Re2#
1.Rd2 O-O 2.Rxc2 Sc3#
1.Sxb2 Rxc2 2.Sa4 Kd2#
Unexpected solution: 1.Kc1 Se3 2.b1=S(R) Rxc2#
Tries: 1.Kf1? Se3+ 2.Kg1 Rg2+ 3.hxg2!
1.Kd2? Se3 2.Re2 Sc4+ unsound if Pb2=black
1.Ka1? Rxh3 2.b1=R Ra3+ unsound if Sd1=black (2021-05-18)
comment

Keywords: Colorless chess
Genre: h#, Retro, Fairies
FEN: 8/8/8/8/8/7P/1PP4R/1K1NK2R
Reprints: 15 Problem Paradise 74, p. 45, 04-06/2016
B66 Phénix 275-276, p. 10838, 07-08/2017
Input: A.Buchanan, 2017-09-18
Last update: A.Buchanan, 2018-03-09 more...

90 - P1339767
Klaus Wenda
F1000v The Problemist 1988
3. Preis
PR Y. Cheylan

(6+10) cooked
ser-s#17
Circe
Madrasi

1. Kg3 2. Kh4 3. Sd4 4. Lc3 5. Le1 6. Lf2 7. Tg1 8. Le1 9. La5 10. Ta1 11. T1a2 12. Lc3 13. La1 14. Sb5 15. Kg3 16. Kh2 17. cxb7[+sLc8]+ Kxb7[+wBb2]#
play all

Cook: 1. Kxh3[+sSg8] 2. Sd6 3. Sf7 4. Sxe5[+sLf8] 5. Ld4 6. Lf2 7. Tg7 8. Lh4 9. Txc7 10. Tc8 11. c7 12. Sc6 13. cxb8=L 14. Lbg3+ Lxc8#

paul: See P1379124 (Wenda and Petkov) as a correction. (2022-07-04)
comment

Keywords: Circe, Madrasi, Nowotny, Seriesmover
Genre: Fairies
FEN: kn6/1bp5/2P5/1N2b2p/4p3/1p5n/4r1RK/B6B
Reprints: A245 Phénix 13, p. 1216, 1991
2 diagrammes 98, p. 2011, 1991
XII Problemas 56, p. 175, 1991
G68 FIDE Album 1986-1988 , p. 478, 1995
Input: HBae, 2017-09-19
Last update: James Malcom, 2023-05-11 more...

91 - P1347359
François Labelle
8061 Phénix 279-280, p. 10986, 2017

(16+16)
ser-BP in 31

1. Sc3 2. Sd5 3. c3 4. Da4 5. Da6 6. a4 7. a5 8. Ta4 9. Tg4 10. Tg5 11. g4 12. Lg2 13. Le4 14. Lb1 15. d3 16. Lf4 17. e3 18. Se2 19. Tg1 20. Tg3 21. Th3 22. Th6 23. h3 24. Lh2 25. Sdf4 26. Sh5 27. f4 28. Kf2 29. Kg3 30. Kh4 31. Seg3
play all

Längste eindeutige Serienzug-BP ohne Schläge

Cf: P1017659
paul: Verified by Jacobi with: stip ser-dia 31 forsyth rsbqkbsr/pppppppp/Q6R/P5RS/5PPK/2PPP1SP/1P5B/1B6 (2021-12-09)
Joost de Heer: This is probably Kriegspiel? If there are no black pieces, the knight path on moves 25/26 can go over f6 as well. (2022-10-25)
A.Buchanan: Good catch, Joost. The black units (because of bK) are necessary. I haven’t heard the term Kriegspiel used to describe this. (2022-10-25)
Henrik Juel: This is a series proof game (where only White moves, and he may not check with an intermediate move)
I see no relation to the fairy condition Kriegspiel (2022-10-25)
comment

Keywords: Unique Proof Game, Seriesmover, Move Length Record (ex-aequo), Capture-free, Homebase (s)
Genre: Retro, Fairies
Computer test: paul: Verified by Jacobi with: stip ser-dia 31 forsyth rsbqkbsr/pppppppp/Q6R/P5RS/5PPK/2PPP1SP/1P5B/1B6
FEN: rnbqkbnr/pppppppp/Q6R/P5RN/5PPK/2PPP1NP/1P5B/1B6
Input: A.Buchanan, 2018-02-28
Last update: A.Buchanan, 2023-06-29 more...

92 - P1360105
Marken Foo
www.chess.com 2014

(14+15)
PG in 4.0
Add the black queen

Author was inspired by a series of computer educational games entitled "Where on Earth is Carmen Sandiego", starring the eponymous villainess.
Moldenhauer: Computerprüfung: C+ Jacobi v0.7.5 in 5 Sekunden.
Notation: 1.h4 e6 2.Th3 De7 3.Ta3 Dxa3 4.b4 Dxc1 (2023-07-31)
comment

Keywords: Unique Proof Game, Add pieces (d)
Genre: Retro
FEN: rnb1kbnr/pppp1ppp/4p3/8/1P5P/8/P1PPPPP1/RN1QKBN1
Reprints: 1 Phénix 287, p. 11251, 07-08/2018
Input: A.Buchanan, 2019-01-25
Last update: A.Buchanan, 2019-01-25 more...

93 - P1360119
Marken Foo
www.chess.com 2016

(14+12)
PG in 7.0 moves
Add the black queen
b) +wSb1

Marken Foo: There is a twin (b) +wSb1 pointed out by the chess.com user caveatcanis back in 2016, when accidentally misreading the diagram. It turns out to be a cute twin that fits the idea. (2020-10-21)
A.Buchanan: How many of these "Where in the world is Carmen Sandiego?" problems have you got, Marken? is it worth making a keyword? https://en.wikipedia.org/wiki/Carmen_Sandiego (2020-10-21)
comment

Keywords: Unique Proof Game, Add pieces (d)
Genre: Retro
FEN: rnbN1knr/pppppp2/8/8/8/8/PPPPPPP1/R1BQKB1R
Reprints: 9 Phénix 287, p. 11252, 07-08/2018
Input: A.Buchanan, 2019-01-25
Last update: A.Buchanan, 2020-10-21 more...

94 - P1360129
Joaquim Crusats
8252 Phénix 287, p. 11266, 07-08/2018

(14+12)
Resolve the position

Joaquim Crusats: ?1.Sg6-h8 Bh7-g8 (1) ?2.Se7/h4-g6 Bg8-h7+ ?3.Sf5-e7/h4 Bh7-g8 (2) ?4.Sd6-f5 Bg8-h7+ ?5.Se4-d6 Bh7-g8 (3) ?6.Sc5-e4 Bg8-h7+ ?7.Sd3-c5 Bh7-g8 (4) ?8.Sb4-d3 Bg8-h7+ ?9.Sc2-b4 Bh7-g8 (5) ?10.Sa3-c2 Bg8-h7+ ?11.Sc2xPa3 Bh7-g8 (6) ?12.Sb4-c2 Bg8-h7+ ?13.Sd3-b4 Bh7-g8 (7) ?14.Sc5-d3 Bg8-h7+ ?15.Se4-c5 Bh7-g8 (8) ?16.Sd6-f5 Bg8-h7+ ?17.Sf5-d7 Bh7-g8 (9) ?18.Se7/h4-f5 Bg8-h7+ ?19.Sg6-e7/h4 Bh7-g8 (10) ?20.Sh8-g7 Bg8-h7+ ?21.h7?h8=S a4-a3 ?22.h6?h7 a5-a4 ?23.h5?h6 h6xSg5 ?24.Se4-g5 Bh7-g8 (11); then e.g.: ?25.Sd2-e4 Bg8-h7+ ?26.Sb3-d2 a7/a6-a5 ?27.Sc1-b3 Kd2-d1 (12) ?28.h4-h5 Ke3-d2 ?29.Kc2-b1 etc.

Full both ways stair walk of the wS (unavoidable).
12 screenings.

White balance: 14 + gxf + hxg = 16 bPb7?b1=R
Black balance: 12 + bxc + cxd + dxe + a-bP = 16 wPh2?h8 (2023-10-03)
comment

Keywords: Non-standard material (t)
Genre: Retro
FEN: 6bN/5p2/4P3/3Pp1p1/2Pp1PP1/2p2prB/P3PrRb/RK1krQB1
Input: A.Buchanan, 2019-01-25
Last update: A.Buchanan, 2019-01-25 more...

95 - P1380670
Dmitri Baibikow
Retro Championnat de France RIFACE 2015
5. ehrende Erwähnung
Phenix 2015-2016

(12+9)
Ordre et lieux des captures?

Beispielauflösung mri:
R: 1. ... Lc8xDb7 2. Dc6xDb7 g6xTh5 3. Da4-c6 Dc6-b7 4. Th1-h5 Kb7-a8 5. Sf4-e6 Ta8-b8 6. Sh3-f4 Kb8-b7 7. Sg1-h3 Lb7-c8 8. Kd7-d8 Dc5-c6 9. Ke6-d7 Kc8-b8 10. Ke5-e6 Kd7-c8 11. Da1-a4 Th8-a8 12. Kd4-e5 Dd6-c5 13. Kc3-d4 Lc8-b7 14. Kc2-c3 Ke8-d7 15. La8-d5 Tb7-a7 16. a7-a8=L Tb8-b7 17. Kd1-c2 b7xTa6 18. Ke1-d1 Dd7-d6 19. Dd1-a1 Ta8-b8 20. Ta1-a6 Dd8-d7 21. a6-a7 a7xLb6 22. Ld4-b6 Dd7-d8 23. Lb2-d4 Dd8-d7 24. Lc1-b2 Dd7-d8 25. c3-c4 Dd8-d7 26. b2xLc3 Lg7-c3 27. a5-a6 Lf8-g7 28. a4-a5 g7-g6 29. g6xBh7 Tg8-h8 30. f5xSg6 Th8-g8 31. Sc3-e4 Se5-g6 32. h5-h6 Sc6-e5 33. e4xBf5 Sb8-c6 34. d3xSe4 Sf6-e4 35. c2xBd3 d4-d3 36. Sb1-c3 d5-d4 37. h4-h5 Sg8-f6 38. h3-h4 f7-f5 39. h2-h3 d7-d5 40. a2-a4
play all

Reihenfolge und Art der Entschläge sind vollständig determiniert:
sLc8xDb7, wDc6xDb7, sBg6xTh5, sBb7xTa6, sBa7xLb6, wBb2xLc3, wBg6xBh7, wBf5xSg6, wBe4xBf5,
wBd3xSe4, wBc2xBd3

Kees: All captures are determinate.
R: sLc8xDb7 / wDc6xDb7 / sg6xTh5 / sb7xTa6 / sa7xLb6 / wb2xLc3 / wg6xh7 / wf5xSg6 / we4xf5 /
wd3xSe4 / wc2xd3

R: -1. … Lc8xDb7+ -2. Dc6xDb7+ g6xTh5 -3. Da4-c6 Dc6-b7 -4. Ke8-d8 Db7-c6+ -5. Kf7-e8 Dc6-b7 -6. Db5-a4 Ld7-c8 -7. Da4-b5 Tg8-b8 -8. Db5-a4 Kb8-a8 -9. c3-c4 Dc5-c6 -10. Sf4-e6 Kc8-b8 -11. Da4-b5 Tb7-a7 -12. Db5-a4 Tb8-b7 -13. La8-d5 Th8-g8 -14. a7-a8=L b7xTa6 -15. Ta5-a6 Dc6-c5 -16. a6-a7 a7xLb6 -17. Lc5-b6 Kd8-c8 -18. La3-c5 Dc5-c6 -19. Lc1-a3 Kc8-d8 -20. b2xLc3 Lg7-c3 -22. Da4-b5 Lf8-g7 -23. Th1-h5 g7-g6 etc. (2022-02-22)
comment

Keywords: Volet Pawn, Obvious promotion (wL)
Genre: Retro
FEN: kr1K4/rbp1p2P/pp2N2P/3B3p/2P1N3/8/3PPPP1/5B2
Reprints: R2 Phénix 253 09/2015
Phénix 290-291, p. 11371, 11-12/2018
Input: A.Buchanan, 2020-10-05
Last update: Mario Richter, 2022-02-23 more...

96 - P1381558
Milomir Babic
8091 Phénix 279-280 11-12/2017

(11+7)
s#11

1. Tb1+! Sxb1 2. Da3+ Sxa3 3. 0-0+ Sb1 4. a8=T+ La7 5. d5+ e5 6. dxe6ep+ Tg7+ 7. Kh1 e2 8. Te1 h5 9. b8=D h4 10. Db7 h3 11. Dg2 hxg2#
play all

Henrik Juel: Damaged by the dual 7... h5 8.b8=D,Te1 (2020-11-05)
paul: See P1373761 as a correction (2021-05-08)
comment

Keywords: Checking key, Castling, under-promotion (T), Promotion (D), En passant, Pawn mate, Corner mate, Pinning, pin-mate
Genre: s#
FEN: 7B/PPr1p3/7p/2b5/1NNP4/n2Qp3/1R5P/k3K2R
Input: Marcin Banaszek, 2020-11-05
Last update: Gunter Jordan, 2020-11-05 more...

97 - P1381602
Milomir Babic
8358 Phénix 290-291 11-12/2018

(12+6) cooked
s#11

1. a8=D! Kc6 2. c8=T+ Kd5 3. Da1 b6 4. f8=L bxc5 5. Tf7 Kxd6 6. e8=S+ Kd5 7. Dd4+ cxd4 8. Ld6 d3 9. Te7 d2 10. Sf6+ Kxd6 11. Te6+ dxe6#
play all

Cook: 4. e8=S! bxc5 5. Dd4 cxd4 6. f8=T d3 7. T6f7 d2 8. Te7 d1=D 9. Sf6+ Kxd6 10. Te6+ dxe6#

Siehe neue Version: P1381646
more ...
comment

Keywords: Allumwandlung (DTLS), konsekutive Umwandlungen 4
Genre: s#
FEN: 8/PpPpPP2/3N1RN1/1pPk1KP1/1pr5/1B6/8/6B1
Input: Marcin Banaszek, 2020-11-07
Last update: Marcin Banaszek, 2020-11-09 more...

98 - P1381628
Milomir Babic
8555 Phénix 298 07-08/2019

(6+4) cooked
s#12
3 Lösungen

1) 1. Kb3-c3! Ke7-e8 2. Dg3-g6+ Ke8-e7 3. Lc8-a6 Ke7-d7 4. Tf3-d3+ Kd7-e7 5. La6-c4 Ke7-f8 6. Th1-h8+ Kf8-e7 7. Kc3-d4 Ke7-d7 8. Dg6-g4+ Kd7-e7 9. Th8-g8 Ke7-f6 10. Dg4-g7+ Kf6-f5 11. Dg7-g6+ Kf5-f4 12. Dg6-f6+ Ld8xf6#
2) 1. Kb3-a4! Ke7-e8 2. Th1-h8+ Ke8-e7 3. Th8-h3 Ke7-e8 4. Dg3-g8+ Ke8-e7 5. Tf3-b3 Ke7-f6 6. Th3-e3 Ld8-e7 7. Te3-f3+ Kf6-e5 8. Dg8-e6+ Ke5-d4 9. Tf3-d3+ Kd4xc5 10. De6-f5+ Kc5-c4 11. Tb3-b4+ Le7xb4 12. Df5-b5+ c6xb5#
3) 1. Tf3-f4! Ke7-e8 2. Dg3-g8+ Ke8-e7 3. Lc8-a6 Ke7-d7 4. Th1-d1+ Kd7-e7 5. Dg8xd8+ Ke7-e6 6. Td1-b1 Ke6-e5 7. Dd8-f6+ Ke5-d5 8. Kb3-a4 Kd5xc5 9. Ka4-a5 Kc5-d5 10. Tf4-d4+ Kd5-c5 11. Tb1-b5+ c6xb5 12. Df6-b6+ c7xb6#
play all

Cook: 1. Tg1 Ke8 2. Dg6+ Ke7 3. La6 Kd7 4. Td3+ Ke7 5. Kc3 Kf8 6. Dg8+ Ke7 7. Lc4 Kf6 8. Df7+ Ke5 9. De6+ Kf4 10. Kd4 Lf6+ 11. De5+ Lxe5#
1. Kc3

SCHRECKE: 2 Kurzlösungen in 11 Zügen: 1.Kc3, 1.Tg1
z.B.: 1.Tg1 Ke8 2.Dg6+ Ke7 3.La6 Kd7 4.Td3+ Ke7 5.Kc3 Kf8 6.Dg8+ Ke7 7.Lc4 Kf6 8.Df7+ Ke5 9.De6+ Kf4 10.Kd4 (11.Df6+ L:f6#) Lf6+ 11.De5+ L:e5# (2020-11-08)
comment

Genre: s#
FEN: 2Bb4/2p1k3/2p5/2P5/8/1K3RQ1/8/7R
Input: Marcin Banaszek, 2020-11-08
Last update: Alfred Pfeiffer, 2020-11-09 more...

99 - P1381642
Milomir Babic
8650 Phénix 301-302 11-12/2019

(8+7)
s#11

1. d3-d4+! f7-f5 2. g5xf6ep+ Tg4-g6 3. 0-0+ Lf4-c1 4. Kg1-h1 h5-h4 5. Lg3-h2 h4-h3 6. f6-f7 b5-b4 7. f7-f8=L h6-h5 8. Lf8-d6 h5-h4 9. Lh2-g1 h3-h2 10. Ld6xh2 h4-h3 11. Tf2-g2 h3xg2#
play all

SCHRECKE: Nach 4. ... b4 geht 5.Lh2 oder 5.f7 (2020-11-09)
comment

Keywords: Checking key, En passant, Castling, under-promotion (L), Valladao Task, Pawn mate
Genre: s#
FEN: 8/5p1B/7p/1p4Pp/5br1/1N1P2B1/5R2/1k2K2R
Input: Marcin Banaszek, 2020-11-09
Last update: Alfred Pfeiffer, 2020-11-09 more...

100 - P1384148
Bernd Graefrath
6120 Phénix 194, p. 8176, 04/2010

(13+11)
Beweispartie in 7,5 Zügen
2 Lösungen
Schlagschach

1. b4 h5 2. e4 h4 3. Dg4 h3 4. Dxg7 hxg2 5. Dxh8 gxf1=L 6. Dxg8 c5 7. Dxf7 Kxf7 8. Kxf1 (ein L-Schnoebelen)
1. g3 h5 2. e4 Sh6 3. Dxh5 Sf5 4. Dxh8 Sxg3 5. Dxg7 Sxf1 6. Dxf7+ Kxf7 7. Kxf1 c5 8. b4 (il est original ici que le C vienne se faire capturer sur la même case que le Fou dans l'autre solution.)
Un problème qui était proposé par l'auteur pour le concours de Messigny 2010, mais que j'ai jugé trop difficile à résoudre dans le temps et les conditions de l'épreuve.
play all

Keywords: Beweispartie, Schnoebelen-Umwandlung (L)

paul: Verified by Jacobi 0.7.5. (2021-09-24)
comment

Keywords: Losing Chess, Unique Proof Game
Genre: Retro, Fairies
FEN: rnbq1b2/pp1ppk2/8/2p5/1P2P3/8/P1PP1P1P/RNB2KNR
Input: RJB, 2011-05-30
Last update: Gerd Wilts, 2020-12-26 more...

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