Die Schwalbe

293 problem(s) found in 3393 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND COOKED AND S='Problem'] [download as LaTeX]

1 - P0002327
Jasper van Atten
The Problemist 1985-1986
3. Preis
P0002327
(16+14) cooked
BP in 20,0
1. a4 Sf6 2. Ta3 Sh5 3. Td3 f6 4. Td6 Kf7 5. d3 Kg6 6. Le3 Kf5 7. Ld4 Kg5 8. e3 Kg6 9. Dg4+ Kf7 10. De6+ Ke8 11. g4 Sc6 12. Lg2 Sa5 13. Lxb7 Tb8 14. Lxc8 Tb3 15. Ke2 Ta3 16. Kf3 Ta1 17. Sa3 Td1 18. Se2 Td2 19. Tb1 a6 20. Sc1 Te2
play all play one stop play next play all
Cook: 1. d3 b5 2. Le3 b4 3. Ld4 b3 4. axb3 Sf6 5. Ta6 Sh5 6. Td6 Sc6 7. e3 Sa5 8. Dg4 Tb8 9. De6 Tb4 10. g4 Ta4 11. Ke2 Ta1 12. Sa3 Td1 13. Lg2 La6 14. Lb7 Lc4 15. Lc8 Lb5 16. Kf3 La4 17. bxa4 Td2 18. Se2 f6 19. Tb1 a6 20. Sc1 Te2

1. d3 Sc6 2. Le3 Tb8 3. Ld4 Sf6 4. e3 Sh5 5. Dg4 b5 6. Ke2 La6 7. De6 b4 8. g4 Lb5 9. Lg2 b3 10. axb3 f6 11. Ta6 La4 12. bxa4 Sa5 13. Td6 Tb3 14. Lb7 Ta3 15. Kf3 Ta1 16. Sa3 Td1 17. Se2 Td2 18. Tb1 a6 19. Sc1 Te2 20. Lc8
more ...
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Moldenhauer: Cooked Stelvio 1.11:13 Keine Lösung BP 19.0, BP 19.5 Cooked
FEN: 2Bqkb1r/2ppp1pp/p2RQp2/n6n/P2B2P1/N2PPK2/1PP1rP1P/1RN5
Reprints: 168 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-03-06 more...
2 - P0002476
Werner Kuntsche
1777v Problem 73-78 06/1961
P0002476
(5+7) cooked
h#3 AP
Einheitslösung!
1) 1. cxd3ep Ta5 2. Sf5 0-0 3. Sd4 Txe5#
2) 1. gxf3ep Th5 2. Sd5 0-0-0 3. Sf4 Txe5#
play all play one stop play next play all
Cook: 707 cooks which do not begin with e.p., e.g. 1.Sg3-e2 Ra1-a2 2.Ke4-d3 Rh1-h3 3.e5-e4 Ra2-d2 #
What is the obscure intent behind "Einheitslösung!"? (= "One size fits all solution"?)
Mario Richter: Im Nachdruck in problem 144-147 steht nur auf e5 ein sB (also keiner auf e3). Allerdings gibt es in allen drei Varianten (sBe5+e3, nur sBe5, nur sBe3) jede Menge NL, die ohne Rochade und e.p.-Key auskommen - am wenigsten dann, wenn nur auf e3 ein sB steht. (2010-10-10)
VL: Cf. P0002475. (2012-08-26)
A.Buchanan: Possibly "Einheitlösung!" is a request to unify retro implications derived across separate parts of the PRA solution. But cooked chessically irrespective of these philosophical issues, which still wait to be resolved 60 years on. (2022-02-16)
comment
Keywords: a posteriori (AP) (Type Petrovic - ccee), En passant as key (2), Castling (wb), Symmetrical position, Symmetrical solution, Superseded by (P1401449,P1399112)
Genre: h#, Retro
Computer test: C- Forward play cooked by Popeye v4.87. However the basic idea is good, if a suitable theoretical framework can be found.
FEN: 8/8/8/4p3/2pPkPp1/2n1p1n1/8/R3K2R
Reprints: (66) Problem 144, p. 52, 12/1971
Die Schwalbe 99 06/1986
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-24 more...
3 - P0003335
Tomislav Petrovic
(XXI) Problem 37-40 09/1956
P0003335
(5+9) cooked
h#9
1. dxc3ep dxc3+ 2. Ka5 c4 3. d2 c5 4. d1=L c6 5. Lg4 hxg4 6. Kb6 g5 7. Ka7 g6 8. Kb8 g7 9. Kc8 g8=D/T#
play all play one stop play next play all
Cook: 1. b2 c5 2. b1=S c6 3. Sc3 dxc3+ 4. Ka5 cxd4 5. Kb6 d5 6. Ka7 d6 7. Kb8 dxc7+ 8. Ka7 c8=D 9. a5 Db7#
paul: See P0003212 as version. (2011-08-06)
Anton Baumann: C+?? Die Aufgabe ist eindeutig inkorrekt! (2021-01-27)
James Malcom: Fixed. (2021-01-27)
comment
Keywords: En passant as key, Promotion (D), konsekutive Umwandlungen 2 (L, D/T), En passant, Kindergarten Problem
Genre: h#, Retro
FEN: 8/2p5/p7/8/1kPp3p/1p1p2pP/3P2Pp/7K
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-01-27 more...
4 - P0003339
Tivadar Kardos
2519 Revista Romana de Sah 01/1948
2. Preis
P0003339
(10+15) cooked
h# in wieviel?
1. ... cxd6ep 2. Tc8 dxe7 3. Tf8 exf8=S#
play all play one stop play next play all
AL ('Revista Romana de Sah', 06/1948, S.225-226):
Bekanntlich beginnt im Hilfsmatt Schwarz, also hat in der Diagrammstellung Weiß den letzten Zug gemacht. Man findet aber, wenn man die Position analysiert, daß Weiß den letzten Zug nicht gemacht haben kann.
Der weiße Doppelbauer auf der d-Linie läßt sich nur durch Schlagen des einzig fehlenden schwarzen Steines, des sBa7, erklären. Dieser konnte aber erst nach Umwandlung geschlagen werden. Dazu mußte er zunächst bis a3 vorrücken, dann nach b2 schlagen, und dann umwandeln.
Also kann Weiß nicht zuletzt b2-b3 gezogen haben.
Die anderen schwarzen Bauern haben mindestens 5 Schläge gemacht, um die Position im Diagramm zu erreichen (man beachte, daß der sBh7 zweimal schlagen mußte, um den wBh2 durchzulassen)
also kann auch g2-g3 nicht der letzte Zug gewesen sein, denn sonst hätte der wLf1 nicht von einem sB geschlagen worden sein können.
Für alle anderen weißen Steine ist leicht zu sehen, daß sie den letzten Zug nicht gemacht haben können.
Es stellt sich heraus, dass der letzte Zug von Schwarz gemacht wurde, und eine einfache Analyse zeigt, daß dies nur möglich ist durch d7-d5 (sonst wäre es unmöglich, daß die weißen Steine ihre Position im Diagramm erreichen könnten).
In diesem Fall Weiß kann 1. ... c5:d6(e.p.) spielen, gefolgt von 2. Tc8 d:e7 3. Tf8 e:f8C matt!
Das kürzeste Hilfsmatt wird also in 2,5 Zügen erreicht!
Cook: 1. ... Txg5+ 2. Kxg5 f3 3. Lg6 gxf4#
1. ... Kxd5 2. Kf6 e4 3. Tg6,Dg6 e5#
A.Buchanan: Popeye v.487. WinChloe has the same diagram, and although it just claims 1 solution, it's C? Yet WinChloe engine gives the cooks right away (2021-10-27)
Mario Richter: Shouldn't this problem get the Label "No legal last move for White"?
(White pawn d2 has captured the missing black piece (Pdxe), so black pawn a7 had to promote to get to the capture square. This requires one capture (Pa3xb2), together with bxc,cxd,hxg,gxh,gxh this accounts for all missing white pieces.)

Btw. "for me, "C?" stands for "Not yet computer-tested or computer test didn't come to a conlusion" ... (2021-10-28)
A.Buchanan: Hi Mario, thank you.
(1) The stipulation is non-standard. I think this is why the WinChloe database doesn't include a solution, and just marks it as "C?" However if I run the WinChloe solving engine manually it (like Popeye) gives 121 h#3 solutions and 4 h#2.5 solutions. I think you, me and Christian would all agree on the meaning of "C?"
(2) The problem does not rely on Article 15 to eliminate the first single move, but implicitly requests the shortest. Currently the PDB usage of "No legal last move..." is to indicate that Codex Article 15 applies, so I did not add it. But I'm ok if you want me to add the keyword. In my correction, I shift the stipulation to h#3 so it's clear that Article 15 and not any desire for brevity which push the problem to h#2.5.
(3) However the PDB usage is confused. Ideallly think the two "No legal..." keywords should be replaced by "Retro-stalemate", while two new keywords "Article 15" & "Whose mate?" indicate the choice of implications of the retropat for forward play. "Board rotation" and other jokes are also implications of retropat (and of illegal diagram).
(4) But this is complicated to implement, requiring either database-level access or screen-scraping. The latter is quite practical for some future time when I have more leisure.
(5) https://www.stere.ro/biblioteca-digitala/reviste/revista-romana-de-sah/ is an excellent archive of Revista Romana de Sah. My sincere compliments and thanks to whoever prepared it. And the magazines themselves contain thorough annual indices. p225-6 of 6/1948, contains the solution to Kardos. I haven't translated it, nor have I found time to locate the prize announcement.
Comments welcome! (2021-10-29)
Mario Richter: I still believe, that the label "No legal last move for White" is justified here, because this is exactly what the author wanted to show.
(And this is too, what the reprint in 'Problem (Zagreb)' 37-40 09/1956 is all about - it appears there inside asn article

Btw., I wouldn't call the presentation of the solution in 'Revista Romana de Sah', p.225, 06/1948, a "reprint" - it lacks the presentation of the position ... (2021-10-30)
A.Buchanan: Added the keyword.
Yes I know that's the usage of "reprint", but then there should be a field for the location of the solution :-) It's idiotic that if I want to say where the solution is contained, I have to embed it in text like this: 2519 Revista Romana de Sah , p. 225-6, 06/1948 (2021-10-30)
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Keywords: En passant as key, Promotion (S), Superseded by (P1394978), No legal last move for White
Genre: h#, Retro
Computer test: Popeye v4.87 & WinChloe both say cooked
FEN: 7b/4p1nP/2r1P1kq/1nPpKbrp/2pp1pRp/1P4P1/P3PP2/8
Reprints: (III) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-30 more...
5 - P0003365
Gyula Bebesi
41 Problemas 04-06/1962
P0003365
(8+14) cooked
h#2
1) 1. axb3ep bxc6+ 2. b5 cxb6ep#
2) 1. exd3ep g8=D,L+ 2. d5 cxd6ep#
play all play one stop play next play all
PRA: 1 solution with 2 parts
Henrik Juel: White captured [sLc8] on c8 and axb, so last move was either b2-b4 or d2-d4
C+ Popeye 4.61, except for the promotion dual (2020-08-03)
A.Buchanan: There's no keyword for an untolerated dual promotion! (2020-08-03)
Henrik Juel: Yes and no, Andrew
What about the cooked label? (2020-08-03)
A.Buchanan: Hi Henrik: this is obviously intentional. I tried to replace the pawn promotion with wDh8-h7+ but I ran out of pieces. I guess that Bebesi had the same difficulty. The word "cooked" seems too strong to me, but it's obviously a significant defect though (2020-08-04)
A.Buchanan: The bar is higher for helpmates than other problems, and this is unsound. However it’s not cooked but dualled. Yet all we have is “cooked” so I suppose it is in PDB-speak. I’ve added that and removed the 2.1… (2023-08-07)
Joost de Heer: Is there an 'unsound' keyword? (2023-08-07)
A.Buchanan: Hi Joost: no there isn't. It can be added, the challenge for any new common keyword would be populating it for more than a few values. (2023-08-07)
A.Buchanan: This time round, I've managed to find a fix. Bebesi's correction in WinChloe 66992 has non-standard wL. I have a feeling I've seen a similar one by Andrey Frolkin & someone else recently with a different matrix, and also non-standard wL. I've sent my effort to Joaquim Crusats at Problemas for his assessment (2023-08-08)
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Keywords: En passant as key (2), Partial Retro Analysis (PRA), En passant as mating move (2), Superseded by (P1411659, P1413906)
Genre: h#, Retro
FEN: 3qn3/1p1p2P1/B1r3p1/1PP1Kp2/pPkPp3/p1p4n/N7/2b5
Reprints: 233 Ungarische Schachproblem Anthologie , p. 188, 1983
1 Problemas 44, p. 1456, 10/2023
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-04 more...
6 - P0003430
Tomislav Petrovic
(XIII) Problem 37-40 09/1956
P0003430
(4+15) cooked
h#3
1. dxe3ep Td1? 2. Le4 Txd6 3. Sg4 Tf6# usual AP try
1. dxe3ep 0-0-0! 2. Le4 Txd6 3. Sg4 Tf6#
play all play one stop play next play all
Cook: 1. dxe3ep 0-0-0 2. Lf5 Txd6 3. Sf3 Td4#
not
1. dxe3ep Td1? 2. Lf5 Txd6 3. Sf3+ ?? usual AP try and also check Bl 3rd move
Henrik Juel: The missing black man is dark-squared, so last move was not fxe4. In the solution Td6 should read Txd6. There seems to be a 'variation': 0... dxe3ep 1.0-0-0 Le4 2.Txd6 Sg4 3.Tf6#, so maybe the stipulation should have 1.1;2.1;1.1 added. (2004-09-23)
A.Buchanan: Well spotted Henrik. Your kindness is legendary, but in the harsh world of helpmates, this counts as a cooked I believe. In fact, it's the 2.Lf5/3.Sf3 version which is the cook. Yours is the actual solution! This is because 3.Sf3 would check if White hadn't castled, and we want the castling to be because of the AP condition only, not for 2 reasons, which one might term a "logical dual". The problem can be trivially fixed by sticking sSe5 on f6. I have no idea whether it's a typo or a cook: WinChloe has the same diagram, and the same confusion between cook & intended solution. The fact that AP does not appear in the stipulation might be a factor. WinChloe as far as I can see has no concept of AP as a keyword, and just picks it up based on a substring of the stipulation. In other compositions, T.Petrovic wasn't shy of flashing the AP acronym in the stipulation, but as usual the detective work peters out in the absence of primary records. (2020-12-08)
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Keywords: En passant as key, Castling (wg), a posteriori (AP) (Type Petrovic), Superseded by (P1382802)
Genre: h#, Retro
Computer test: Popeye v4.85 + retro thinking
FEN: 1n1r4/p1B4p/1p1p4/p3n1p1/3pPk2/3b4/pr5q/R3K3
Reprints: (60) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-02-16 more...
7 - P0003431
Tomislav Petrovic
(XIV) Problem 37-40 09/1952
P0003431
(8+14) cooked
h#3
1. cxb3ep+ c3 2. Ld3 Tg4+ 3. Kh1 0-0-0#
play all play one stop play next play all
paul: White captures was axb and g2xh3, so the retro move c3xb4 is not possible. If b3-b4, the retro check is not justified. So last move was b2-b4 (preceded by Rc3-a3). (2011-08-06)
A.Buchanan: There's a lot to unpack here. Firstly, the intended solution has a definite transposition dual in the order of Black's 2nd & 3rd moves. Second, the pawn capture count is wrong. What happened to the original wBh, given sBh2 never left the h-file? Thirdly, and not a showstopper, White's only solution involves castling: so that's a logical dual. (2020-12-08)
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Keywords: En passant as key, Castling
Genre: h#, Retro
Computer test: Popeye v4.85 + retro thinking
FEN: 3r3n/p7/pp6/bP1q4/RPp5/r3p2P/p1P1P1kp/Rb2K3
Reprints: (61) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-05-02 more...
8 - P0003451
Knud H. Hannemann
3823 Stella Polaris 03/1971
P0003451
(6+8) cooked
h#2 AP
1) 1. gxf3ep 0-0-0 2. Te7 Th4#
2) 1. cxd3ep 0-0 2. Da4 Txa4#
play all play one stop play next play all
AB: I think this is cooked. I don't see how AP castling can justify earlier ep here.
1. Kf3 Bf5 2. Kg2 Be4#
1. Kf3 Bxd7 2. Kg2 Bc6#
1. cxd3 Rf1 2. Qa4 Rxa4#
1. gxf3ep Ra5 2. Kf4 Rh4#
1. gxf3ep Rd1 2. Re7 Rh4#
Also, second solution given has typos 1. *c*xd3ep & 2. Q*a*4. (2002-03-21)
V.Liskovets: Indeed this problem is cooked, and I
failed to correct it preserving symmetry.
Here is a possible correction:
W: Ke1 Ra1 Rh1 Be6 Pd4 Pf4
B: Ke4 Qd7 Rf7 Pc3 Pc4 Pe3 Pg3 Pg4 Bh7 Rb2 Pb3

Another story, justifying its contents (e.p.).
In my opinion, all published treatments are
insatisfactory (the same concerns P0004295
(corrected) by Werner Kuntsche as well).
There is a way to make it sound under the
sophisticated HYBRID stipulation 'AP, pRA':
2 partial solutions legalized JOINTLY by
both castlings (details to be published). (2002-04-02)
VL: Sorry, Andrew, I see no issues with my version (excepting the mentioned special retro-convention/genre for justifying its soundness, of course!). h#2 (pRA&AP). The full solution consists of 2 partial AP-based ones: I 1.gxf3 e.p.(!?) 0-0-0! 2.Te7 Th4#; II 1.cxd3 e.p.(!?) 0-0! 2.Da4 Txa4#.
C+(popeye): h#2 & two h#1.5 after the keys (added Tb2 & Lh7 are cookstoppers).
The main features of the corresponding suitable AP-genre ("consolidated")are rather clear. However, not all subtle aspects have been analyzed thoroughly yet. I have got only a draft manuscript with few examples, still. (2022-02-15)
A.Buchanan: Yes Valery I think your correction is technically sound. Theological debate is something else, heh. Have posted it as separate entry. Please tell me if it was original here, or appeared somewhere else (2022-05-29)
Henrik Juel: I looked in Stella Polaris 1971 p.202-203, where the problem is given without AP under the diagram
It turns out that both the author and the editor (Jan Knöppel) consider the problem correct
After explaining the AP convention the latter writes [my translation]:
The author has elegantly applied the AP conventionn in combination with partial analysis. If we assume that last move was not f2-f4 or T-h1, the possibilities d2-d4, K-e1, and T-a1 remain, but the two latter disappear by 1... 0-0. The other assumption (last move was not d2-d4 or T-a1) is analogous.
So something like Valery's HYBRID stipulation was the intention, and the problem was considered correct in 1971; later developments do not change this fact (2022-05-29)
Henrik Juel: Of course, the obvious cooks 1.Kf3 etc. remain (2022-05-29)
A.Buchanan: I agree. Basic AP Petrovic does not allow multiple ep, nor does RS, so some alignment of AP with PRA is required. I would like to see this codified though. (2022-05-29)
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Keywords: Castling (wb), En passant as key (2), a posteriori (AP) (Type Petrovic), Superseded by (P1401508, P1399178), Quasi-symmetrical position, Partial Retro Analysis (PRA)
Genre: h#, Retro
Computer test: C- Forward play cooked by Popeye v4.87. However the basic idea is good, if a suitable theoretical framework can be found.
FEN: 8/3q1r2/4B3/8/2pPkPp1/2p1p1p1/8/R3K2R
Reprints: (65) Problem 144-147 12/1971
(8) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-29 more...
9 - P0003781
Imre Sztankovszky
(IX) Problem 29-30 05/1955
P0003781
(5+14) cooked
h#3*
1. ... b6 2. Le7 Lxg2+ 3. Kd6 Sxc4#
play all play one stop play next play all
Cook: Popeye V4.87
1. ... Sxc4 2. Da1 Kxb3 3. Le5 Lxg2#
1. ... bxa5 2. Le5 Kb4 3. d6 Lxg2#
1. ... Sxd1,Sxd3 2. Le5 Sb2,Sf2 3. d6 Lxg2#
1. ... Sxc4 2. Le5 Sb2,Sd2 3. d6 Lxg2#
WinChloe has same diagram, also says is cooked.
Henrik Juel: Black is missing [Lc8], which was captured on c8, and a rook
Last move was not c3xTb4, because sTc4's check is impossible, so White has the move (2020-10-01)
A.Buchanan: Shifting sLd6 to c5 removes the cooks. What's the artistic intent here though? (2021-10-16)
Henrik Juel: Maybe the unique h#2 try plays a role: 1.Le5 b6 2.d6 Lxg2# (2021-10-16)
A.Buchanan: In the h#2 try, b5-b6 is cool as the sole tempo move available to White. However there are plenty of *pairs* of White moves e.g. Sxd1-f2, which lose two tempi. These lead directly to h#2.5 cooks, and I see no way to eliminate these without losing the h#2 try. (2021-10-17)
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Keywords: No legal last move for White
Genre: h#, Retro
FEN: 8/1p1p4/3br3/pP1k4/KPbp4/pn1p4/qN4p1/3n3B
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-07 more...
10 - P0004199
Werner Frangen
Problem 41-44, p. 52, 03/1957
P0004199
(14+10) cooked
#5
1. axb6ep+ Kb5 2. bxc7+ Tb6 3. 0-0-0 ...
play all play one stop play next play all
K. Fabel: "Von Interesse ist, dass diese strittige Idee [Beweis des e.p.-Schlagrechts durch spätere Ausführung der Rochade] auch im direkten Mattproblem dargestellt werden kann, vergl. das Diagramm [diese Aufgabe P0004199]. (Vielleicht ist diese Aufgabe noch nicht korrekt doch es wird nicht schwer sein, sie zu verbessern). Falls Schwarz zuletzt Bb6-b5, Tb6-c6 oder Lb6-c7 gezogen hat, ergibt sich, dass Weiss im letzten oder vorletzten Zug den K oder T bewegt haben muss. Falls jedoch K und T noch nicht gezogen haben, muss b7-b5 der letzte Zug gewesen sein. Weiss spielt daher 1. ab6e.p.+ Kb5 2. bc7+ Tb6. Jetzt könnte Weiss mit Dxb6 sofort mattsetzen, aber er muss ja den e.p.-Schlag noch legalisieren. Daher 3. 0-0-0! und Matt erst im 5. Zuge."
Cook: 1. Sxc7+!
1. Lxc7!
Innerhalb des 2. Teils einer Artikelserie "Die Konventionen im Problemschach" von Karl Fabel.
A.Buchanan: The retro logic is fine, but forward play is savagely cooked. I wonder about changing wSc8 to sS. The retro stuff still works OK, indeed sSc8 is a fourth thematic unit to retract in the try. Ignoring proof of ep legality, there is a unique #4 beginning with ep, and no #5. Promising: but when can we interpolate w000? Any solution must begin 1. axb6ep+ Kb5. There are now numerous #4, but none include w000, so I think we must stick with the still unique line beginning 2. Dxc8 thr 3. 0-0-0. There are 3 black defenses to refute this. 2. ... Txb6,axb3,d5. So maybe #6 needed for White to prevail? (2022-03-28)
A.Buchanan: But if we shift to #6 then 1. Sxc7!,Qxc8+! mate without ep. Can anyone retrieve the original diagram for this one, please? (2022-03-28)
Mario Richter: The position here is identical to the original diagram, but it should be regarded more as a schematic example than a "real problem". Fabel in his quote above: "... perhaps the problem is still not correct, but it should be easy to improve it ..." (2022-03-28)
Henrik Juel: unfortunately K. Fabel forgot to give the easy correction... (2022-03-28)
A.Buchanan: Thanks for this. Valery Liskovetz, an AP expert, was kind enough to send a pdf of the relevant Problem issue, so I can confirm. It's easy enough to remove the two cooks (e.g. sTc8) but the difficulty is in validation of the intended solution. Is there any "exact" option in Popeye that forces the solution to include a waiting move? The actual solution might be expected to be included in that set. (2022-03-29)
Henrik Juel: Yes, Andrew
'stip exact-#5' would disregard #4 as a solution, I believe (2022-03-29)
A.Buchanan: Even with the "exact", it's still very complicated to investigate. I think this kind of problem requires an engine feature to disallow any mate or pat if the specified castling has not been executed. Gazing at the 20,000 lines of output, I don't think sTc8 works as 1. axb6ep+ Kb5 2. Qb7 bxa3! threatens axb2+ after castling. I wonder if the board might be flipped left-right except for wK, but I haven't explored this. (2022-05-31)
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Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg), Non-standard material (TLL)
Genre: Retro, n#
FEN: NQNB4/B1brpp2/k1rp4/Ppp5/Rp6/BP6/RPP5/R3K3
Reprints: (8) Problem 101-102 09/1966
(52) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-29 more...
11 - P0004296
Luis Alberto Garaza
1809 Problem 73-78 06/1961
P0004296
(16+13) cooked
h#1? h#2?
1. fxe3ep? Dxa8# No justification for the ep, so just retro try.
play all play one stop play next play all
White pcs: dxexf5,hxBg. Black none. Assume that Black can still castle. White can't have just played h4xg5 as sBh2 would be blocked. White might apparently just have moved D,Se5,Td4,Tc3,g4-g5,a5-a6,e3-e4 or e2-e4 but what might Black have played before? Only the last allows a move sDf1-e1. So set up for AP Type Petrovic is OK.
Cook: 446 candidate h#2
However 27 have no ep, while 59 have both ep & castling.
So a total of 86 viable solutions, 85 of which must be cooks.
s.a. Version P0004341
more ...
comment
Keywords: Castling (sg), En passant as key, a posteriori (AP) (Type Petrovic), Superseded by (P0004341)
Genre: h#, Retro
Computer test: Popeye v4.87 indicates cook
FEN: r3k3/p1ppp3/Pp6/4NPP1/2PRPp2/2RK2PN/1PBn1PQp/2Brq1b1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-22 more...
12 - P0004341
Luis Alberto Garaza
(9) Problem 101-102 09/1966
P0004341
(15+12) cooked
h#1 oder h#2
1. fxe3ep Dxa8#? because no AP justification for ep

1. 0-0-0 g7 2. Tf8 gxf8=D#
play all play one stop play next play all
62 apparent h#2, so seems cooked.
Cook: 415 candidate solutions for h#2. 401 begin with ep, of which 48 contain 0-0-0 to justify. There are also 14 solutions without ep, of which 13 begin with 0-0-0. The odd one is 1. Kd8 Sc6+ 2. Kc8 Sge7#
Version zu P0004296

Autor: "In Nr.9, I intended to do something similiar to No. 8 [P0004199], but with a different key: the solution 1. PxP "e.p.", Qxa8 checkmate will not go, for if blackside does not castle, the "en-passant" capture cannot be justified. Though, well considering, there is the demolition 1. PxP "e.p." -any 2. 0-0-0! Qb7 or a8 checkmate.
A.Buchanan: Thanks Mario for retrieving the author's intent with this. So he knew it was cooked! Assume s000 rights remain. R: 1. b5xa6? as sBb promoted on b1. R: 1. h4xg5? as sBh retro-blocked. R: 1. Ke3-d3? impossible check from sBf4. R. 1. K~-d3 d3-d2? illegal check. I like these! So by elimination, R: 1. e2-e4 e3xTd2 2. T~d2 L~e1. So must have sLe1. (2022-03-22)
more ...
comment
Keywords: Castling (sg), En passant as key, a posteriori (AP) (Type Petrovic), Superseded by (P0004342)
Genre: h#, Retro
Computer test: Popeye v4.87 & simple retro-logic
FEN: r3k1N1/p1pp4/P5P1/4PPp1/2PNPprB/3K1QRp/P2p1PB1/4b2n
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-22 more...
13 - P0004342
Luis Alberto Garaza
(10) Problem 101-102 09/1966
P0004342
(15+11) cooked
h#2
1. bxc3ep Dg8#? (thematic try)
1. bxc3ep Dd5 2. 0-0-0 Db7#
play all play one stop play next play all
Cook: 1. bxc3ep Ld6 2. 0-0-0 Dc4#
Author: "From the former [d.h. P0004341], the No. 10 was born, something similar to No. 8 [P0004199] but with Black-castling for it is a help-mate. The mating move 1. ... Qg8? will not go."
more ...
comment
Keywords: Castling (sg), En passant as key, a posteriori (AP) (Type Petrovic), Superseded by (P1399966)
Genre: h#, Retro
Computer test: Popeye v4.87 & simple retro-logic
FEN: r3k3/p2p4/8/NP6/BpPPN1PP/B2K1Ppp/QP1p1pP1/Rrb5
Reprints: (55) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-23 more...
14 - P0004481
Matjaz Zigman
Länderkampf Mazedonien-Slowenien 1969
7. Platz
P0004481
(13+10) cooked
ser-h#6** AP
* 1. ... Sb5#
* 1. ... dxc3#
1. fxe3ep 2. e2 3. exf1=S 4. Se3? 5. Sd5 Sb5# (must castle for AP)
1. fxe3ep 2. e2 3. exf1=S 4. Sxd2 5. Sxb1 6. Sxa3 0-0-0!#
play all play one stop play next play all
Luckily, illegal diagram can be fixed by removal of bPa4.
Then if White castling rights remain, ep is on. One ser-h#5 & 18 ser-h#6 tries exist, in which White does not bother to castle.
We don't know if this was a transcription error or a counting mistake by the composer.
Cook: Too many pawn captures required. For retro problem, illegal position implies unsound
Mike Neumeier: The solution appears to be 1.fxe4 e.p. 2.e2 3.exf1=L 4.Ld3 5.Le4 6.Ld5 dxc3#. Was that the intention? (2013-02-18)
Arno Tüngler: There would even be a solution in 5 moves by 3.exf1=S 5.Sd5 Sb5#
However, in order to justify the e.p.-key there must be an AP prove that e2-e4 (and not a move by the wK or wRa1) was played as White's last move. Thus the only solution giving this in 6 moves is 1.fxe3 e.p. 2.e2 3.exf1=S 4.Sxd2 5.Sxb1 6.Sxa3 0-0-0!# (2013-02-18)
Mike Neumeier: It struck me as odd there was no solution listed. (2013-02-18)
Mike Neumeier: And, if we let black be the idle side, there is 1.Txg1 2.Lxh1 3.Kd1 4.Kc1 hxg1T#. What does the asterisk(*) mean? (2013-02-18)
Henrik Juel: The asterisk means that there is also a white mate if he had the move, in this case two mates, so maybe the stipulation should be ser-h#6**:
1.dxc3,Sb5# (2013-02-18)
Ladislav Packa: It is clear that e.p. is possible only when the wK and wRa1 done neither move.
What convention is used here for the right to castling? (2013-02-18)
Henrik Juel: White may castle, unless you can show that he has lost the right to castle. In this problem there is a major difficulty, I think: the position seems illegal.
White pawns captured b2xc3xd4xe5xf6, g2xf3, and axb, promoting on b8; Black captured bxc, dxc, and g3xh2. We cannot explain the destiny of [Ph7].
Reversing wPh3 and bPh2 seems to handle the illegality, but then the problem can be solved in 5 moves (2013-02-18)
Mike Neumeier: Thanks, Henrik. Maybe the stipulation was a typo. Considering all comments together, perhaps the stip should have been ser-h#5**, with the one solution being the 5-mover Arno gave. I do not think it can be proven, except by a stipulation of ser-h#5 that en passant is possible. Which leads to the question of convention. Can the existence of a unique solution as implied only by the stipulation be used to determine that en passant is permissible? Whether there is castling or not here seems immaterial. It is just another 6-move solution. There are 19 6-movers (Popeye) with one queenside castling among them. But only the one 5-mover. (2013-02-18)
Henrik Juel: By convention, an en passant capture as first move is not permitted, unless the pawn double step can be shown by some kind of retro analysis.
(Conversely, a castling is permitted, unless it can be shown by retro analysis that the right to castle has been lost, i.e., that king and/or rook has moved) (2013-02-18)
A.Buchanan: Suggested repair: Remove bPa4. Add AP to stipulation.
As Henrik points out, the diagram as it stands is illegal. We can't swap wPh3 & bPh2, because that allows 2 h#1 cooks.
Suppose we remove bPa4 instead. Then we still at least 5 White pawn captures: bxcxdxexf6 & gxf3. But wPh3 did still move from h2, so there are 3 Black pawn captures bxc, dxc & gxh2. So [bhP] died without capturing or promoting. [waP] must have promoted - so either [baP] was captured to clear the way, or [waP] captured to promote, and later [baP] promoted. Either way, all the numbers add up, and the position is legal. wPe4 cannot have just come from d3. So AP is triggered. Forward logic works just as before without bPa4. There is 1 5-move try, and 18 6-move tries, but AP eliminates them all because of need for castling to retrospectively justify the ep. (2013-02-23)
A.Buchanan: Mike asked: "Can the existence of a unique solution as implied only by the stipulation be used to determine that en passant is permissible?"
Answer: No. The stipulation does imply a default player to move, but otherwise cannot be used as a premise to determine game state (castling, en passant). (2022-03-21)
A.Buchanan: WinChloe & Yacpdb have the same cooked diagram as PDB, so I think this cook was in the design. I would like to post a sound version with bPa4 removed, and I think it would just be “Zigman correction” with no one else’s name mentioned in the credits. Is everyone ok with this? (2022-05-30)
Mario Richter: 'Bilten 1970' (printed 1971) contains on pp. 62-81 a complete report on the "Problem Duel Slovenia - Macedonia 1969", the problem here can be found on page 79 and is printed there exactly as given here.
Andrew's handling of the suggested correction (remove black pawn a4) is o.k. for me. (2022-05-31)
more ...
comment
Keywords: Castling (wg), Seriesmover, a posteriori (AP) (Type Petrovic), Illegal position, En passant as key, Promotion (s), Valladao Task, Superseded by (P1401546)
Genre: Retro, Fairies
Computer test: Popeye v4.87 but simple retro-logic shows illegality
FEN: 8/8/5P2/2p1p3/p1pkPp2/N1p2P1P/2PP1PBp/RN2KRbr
Reprints: 104 Bilten 1970 1971
(72) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-01 more...
15 - P0004657
Mato Prikril
(27) Problem 206-210 07/1981
1. ehrende Erwähnung
P0004657
(5+7) cooked
h#2*
*) 1. ... Ta4 2. Kxg4 Txf4#
1. fxg3ep Ta4#? (no proof of ep right)
1. fxg3ep 0-0-0! 2. g2 Td4#
play all play one stop play next play all
A short retro try h#1 and 16 h#2 tries. B2 is unique tempo move
Cook: 1. Kxg4 Ta5 2. h4 Tg5#
1. Kxg4 Ta4 2. Kh4 Txf4#
61. TT (Pavlovic Memorial), Gruppe A
more ...
comment
Keywords: Castling (wg), En passant as key, a posteriori (AP) (Type Petrovic), Tempo Move
Genre: h#, Retro
Computer test: Popeye v4.87 & simple retro-logic
FEN: 8/6p1/6pB/7p/5pPk/5p1p/5P2/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-04-06 more...
16 - P0005911
Unto Heinonen
2375 U.S. Problem Bulletin 01-02/1992
P0005911
(13+16) cooked
BP in 34,5
1. Sc3 h5 2. Se4 h4 3. Sg3 hxg3 4. h4 Th5 5. Th2 gxh2 6. Tb1 hxg1=S 7. Ta1 Sh3 8. Tb1 Sf4 9. Ta1 Sd5 10. Tb1 Sb4 11. Ta1 Td5 12. Tb1 g5 13. Ta1 Lg7 14. Tb1 Ld4 15. Ta1 Lb6 16. Tb1 c5 17. Ta1 Dc7 18. Tb1 De5 19. Ta1 Ld8 20. Tb1 b6 21. Ta1 La6 22. Tb1 Lc4 23. Ta1 a6 24. Tb1 Ta7 25. Ta1 Tc7 26. Tb1 Tc6 27. Ta1 Tf6 28. Tb1 d6 29. Ta1 Kd7 30. Tb1 Ke6 31. Ta1 Kf5 32. Tb1 Kg4 33. Ta1 Tf5 34. Tb1 Sf6 35. Ta1
play all play one stop play next play all
Korrektur siehe P0008426.
James Malcom: What is the cook? (2023-05-02)
more ...
comment
Keywords: Unique Proof Game, Non-standard material, Pendulum (T x30), Superseded by (P0008426)
Genre: Retro
FEN: 1n1b4/4pp2/pp1p1n2/2prqrp1/1nb3kP/8/PPPPPPP1/R1BQKB2
Reprints: (12) feenschach 117 11/1995
Input: Gerd Wilts, 1995-06-26
Last update: James Malcom, 2023-05-02 more...
17 - P0008879
Arpad Molnar
R259 The Problemist 01/1997
P0008879
(10+9) cooked
Welches waren die letzten 16 Einzelzüge?

play all play one stop play next play all
Cook: R: 1. a4xSb3+ Lb8-c7 2. d6xSc5 Ld8-b6 3. b6xSa5 e7xTd8=L
Gerald Ettl: Weiss jemand wie die Autorloesung geplant war? (2023-09-28)
comment
Keywords: Last Moves? (16), Non-standard material
Genre: Retro
FEN: 8/p1Bp1ppp/RBR5/pBpP4/1kP5/Rp6/1PK5/8
Input: Gerd Wilts, 1998-06-26
Last update: Gerd Wilts, 2006-10-08 more...
18 - P0501007
Thomas Brand
Jörg A. R. Kuhlmann
Bo Lindgren
Arno Tüngler
Kjell Widlert

3707v feenschach 63 12/1982
P0501007
(1+8) cooked
h#8
Circe (nur Offiziere) Rex inklusive
1. b1=S Kb2 2. a1=T Kxa1[+sTh8] 3. Te8 Kxb1[+sSg8] 4. c1=L Kxc1[+sLf8] 5. Ke1 Kc2 6. Se7 Kd3 7. f1=D+ Ke3 8. De2+ Kxe2[+sDd8]#
play all play one stop play next play all
Korrektur in feenschach 1988
Cook: Michel Caillaud (2022-07-19): cooked using Jacobi 0.7.5 :
1. a1=L Kb3 2. b1=T Ka2 3. c1=D Kxa1[+sLf8] 4. Sb6 Kxb1[+sTa8] 5. Te8 Kxc1[+sDd8]+ 6. Ke1 Kc2 7. Sd5 Kd3 8. Se7+ Ke2#
Michel Caillaud: cooked using Jacobi 0.7.5 :
1.a1=L Kb3 2.b1=T Ka2 3.c1=D Kxa1(Lf8) 4.Sb6 Kxb1(Ta8) 5.Te8 Kxc1(Dd8)+ 6.Ke1 Kc2 7.Sd5 Kd3 8.Se7+ Ke2# (2022-07-19)
more ...
comment
Keywords: Circe (Rex inklusive), Allumwandlung
Genre: Fairies
FEN: n7/8/4pp2/8/8/2K5/pppk1p2/8
Reprints: The Problemist , p. 91, 09/1985
Rex Multiplex 12/1988
969 Minimalkunst im Schach 2006
My problems [Arno Tüngler] , p. 82, 06/2009
Input: Gerd Wilts, 1996-06-06
Last update: Mario Richter, 2022-07-19 more...
19 - P0501019
Zdravko Maslar
2837 Problemkiste 12/1991
P0501019
(1+12) cooked
ser-h=29
1. b1=D 2. Db4 3. De1 4. b4 5. b3 6. b2 7. b1=D 8. Db6 9. Dbg1 10. b5 11. b4 12. b3 13. b2 14. b1=D 15. Db8 16. c1=D 17. Dcf4 18. Dff1 19. Tf2 20. f5 21. f4 22. f3 23. Sh1 24. Dbh2 25. Tg3 26. Lh3 27. Dfg2 28. Def1 29. Ke1 Kc2 =
play all play one stop play next play all
Cook: NL (s.PK137):
von George P.~Sphicas wird folgende von
Mike Neumeier gefundene NL mitgeteilt: 1.Tf2 2.b1\prom{S} 3.Sd2
4.Sf3 5.Sg1 6.b4 9.b1\prom{L} 10.La2 11.Lad5 12.Lf1 13.L5g2 14.b5
18.b1\prom{D} 19.Db4 20.De1 21.f5 23.f3 24.Sh1 25.Tg3 26.Lh3
27.L1g2 28.Df1 29.Ke1 K×c2=
Erich Bartel: Nachdrucke:
1) G29 Fide-Album 1989-1991
2) 975 Minimalkunst im Schach 2006 (2013-03-07)
paul: See P1330761 as correction. (2022-07-10)
comment
Keywords: Promotion (dddd), Rex solus (w), Seriesmover
Genre: Fairies
FEN: 8/1p3p2/5r2/1p6/6p1/3K2nr/1pp1p1b1/3k4
Input: Gerd Wilts, 1996-06-06
Last update: Alfred Pfeiffer, 2013-07-17 more...
20 - P0501419
Stanko Milenkovic
101 Problemas 04-06/1964
P0501419
(3+8) cooked
h#4
1. f2 Tb1 2. Sf3 Tb2 3. Ke1 Txc2 4. Sd2 Tc1#
play all play one stop play next play all
Cook: NL
1. Sg2 Th1 2. f2 Th8 3. Ke1 Th2 4. Kf1 Th1#
Adrian Storisteanu: Possible fix:
Kh1 Rb1 / Kc2 Sd1 ppb2 d2 e3 g3 h2 h3 (2+8) h#4
1.e2 Ra1 2.Se3 Ra2 3.Kd1 Rxb2 4.Sc2 Rb1# (2015-07-24)
milan: milan frelih: i've found key solution,your move? (2015-07-24)
milan: Milan Frelih:[Ka1 h1,+bBb1,wPe3=bPe4] (2015-08-31)
Yuri Bilokin: Correction: wKa1-h1, wRc1-b1, bKd2-c2, bPc2-b2, bNe1-d1, bPe2-d2, bPf3-e3, -bPb3, -bPd3, -wPe3, -bPe4, +bQg3 8/8/8/8/8/4p1q1/1pkp4/1R1n3K (2+6) h#4 1.e2 Ra1 2.Se3 Ra2 3.Kd1 Rxb2 4.Sc2 Rb1# (MM) (2022-04-21)
comment
Keywords: Interchange (ks (2)), Pure Round Trip (T)
Genre: h#
FEN: 8/8/8/8/4p3/1pp1Pp2/2pkp3/K1R1n3
Input: hpr, 1996-07-01
Last update: Alfred Pfeiffer, 2015-07-24 more...
21 - P0505083
Zoltan Zilahi
788v Problemas 09/1955
P0505083
(4+13) cooked
h#5
1. Tc7 a4 2. Sb7 a5 3. Kd5 a6 4. Kc6 a7 5. Dd5 Ta6#

NL:
1. Ke3 h5 2. Kf3 h6 3. Ke2 h7 4. Kf1 h8=D 5. De2 Dh1#
play all play one stop play next play all
Yuri Bilokin: Correction: -bRf2, -wPh4, bBd7, bNe7-c1, bBe5-f4, bPf6-c3 8/r2b4/8/npp5/4kb2/2p5/Pp1q4/RKn5 (3+11) (2020-11-28)
comment
Keywords: Bahnung
Genre: h#
FEN: 8/r2pn3/5p2/npp1b3/4k2P/8/Pp1q1r2/RK1b4
Input: hpr, 1996-12-26
Last update: hpr, 1999-07-11 more...
22 - P0505122
Filip S. Bondarenko
2122 Problemista 98-99 09-10/1969
P0505122
(5+8) cooked
h#2
1. Dh8 Le6 2. Lg7 f5#
play all play one stop play next play all
Cook: NL 1. b5 Lxb2 2. h6 Lb1#
Yuri Bilokin: Correction: wKe7-a7, wBa2-b3, wPf2-g5, bSc7-e2, -bPb6, -bPd7 8/K6p/6k1/6Pp/5P2/1B6/1q2n3/b1B5 (5+6) (2021-05-10)
comment
Keywords: Bahnung
Genre: h#
FEN: 8/2npK2p/1p4k1/7p/5P2/8/Bq3P2/b1B5
Input: hpr, 1996-12-26
Last update: Marcin Banaszek, 2023-12-13 more...
23 - P0506988
Vaclav Gebelt
Problem 07/1981
2. Preis
59. Thematurnier
P0506988
(10+9) cooked
h#2
b) wLe1 nach h2
a) 1. Dxd5 Sd2 2. De4 Sd5#
b) 1. Txg4 Sg5+ 2. Te4 Sg4#

NL:
a) 1. Kd4 Sxd2 2. Sc3 Lf2#
play all play one stop play next play all
Vitaly Medintsev: Correction
5K1Q/p6p/4RN1p/2nP1Pr1/4N1P1/b3k3/1pPqp3/3rB3 (10+11)
b) SLe1 nach h2
white Be1 Kf8 Qh8 Pd5g4c2f5 Sf6e4 Re6 (10)
black Ba3 Ke3 Qd2 Pa7h7h6e2b2 Sc5 Rg5d1 (11)
b) BBe1 move to h2
Version by Vitaly Medintsev, October 1st 2014 (2014-10-01)
SCHRECKE: Medintsev: P1288792 (2022-10-30)
more ...
comment
Keywords: Bahnung, Fesselungsspiel (212 202 000)
Genre: h#
FEN: 5K1Q/7p/3nRN2/3P1Pr1/4N1P1/b3k3/1pPqn3/3rB3
Input: hpr, 1997-01-22
Last update: Alfred Pfeiffer, 2014-10-01 more...
24 - P0507001
Nikolay Dolginovich
1471 Problemista 67 02/1967
3. ehrende Erwähnung
P0507001
(10+8) cooked
h#2
3.1...
1) 1. Txc6 Lc4 2. Sc7 Sd5#
2) 1. Tc4 dxc4 2. Sd4 Sd3#
3) 1. cxd2 c4 2. Sc3 Sc2#
play all play one stop play next play all
Cook: NL 1. Txd3 Ke6 2. Td4 Sd3#
Adrian Storisteanu: Possible fix: +wPe6 (11+8). (2015-09-21)
Yuri Bilokin: correction +bNg7 8/p1r1pKn1/PpP5/1nkB4/1N1r4/B1pP4/P1PP4/8 (10+9) (2022-06-06)
comment
Keywords: Bahnung
Genre: h#
FEN: 8/p1r1pK2/PpP5/1nkB4/1N1r4/B1pP4/P1PP4/8
Reprints: 905 Problemista 11-12/1968
Input: hpr, 1997-01-22
Last update: Marcin Banaszek, 2022-06-06 more...
25 - P0507791
Mykola Parkhomenko
532 Problemas 07-09/1974
P0507791
(4+6) cooked
h#2
2.1...
1) 1. Td2 Lb2 2. Ld3 Lb5#
2) 1. Ld3 Lb5 2. Td2 Lb2#
play all play one stop play next play all
Cook: NL
1. Txa3 Lc6 2. Tg3 Txa6#
1. Txa3 Lc6 2. Tf3 Txa6#
Eher Dual als Zweispänner!
Adrian Storisteanu: Possible fix (shift right for extras): Kd8 Rb1 Bb3 Bb4 / Kb8 Ra8 Rh3 Bb6 Bf1 pp.a7 c7 (4+8) - 1.Re2 Bc2 2.Be3 Bc5#, 1.Be3 Bc5 2.Re2 Bc2#. (2015-10-07)
Yuri Bilokin: Correction: rk1K4/p1p5/1b6/8/1B6/1B5q/1r6/1R3b2 (4+8) 1.Re2 Bc2 2.Be3 Bc5#
1.Be3 Bc5 2.Re2 Bc2# (2021-05-19)
comment

Genre: h#
FEN: k1K5/1p6/b7/8/B7/B6r/r7/R3b3
Input: hpr, 1997-05-19
Last update: Alfred Pfeiffer, 2015-10-07 more...
26 - P0509913
Paul Vatarescu
246 Problemas 09-12/1969
P0509913
(2+10) cooked
h#3
1. Kf8+ Df6+ 2. Sf7+ Kg6 3. Lc6 Df7#

NL:
1. Tc6 Kg4 2. Ke6 Kf4 3. Kd5 De5#
play all play one stop play next play all
Yuri Bilokin: correction bRb6-g8, +bQg3, +bNg4
3bb1rn/4k1p1/r5p1/6K1/2p3n1/5pq1/8/Q7 (2+12) h#3

1.Kf8+ Qf6+ 2.Sf7+ Kxg6 3.Bc6 Qxf7#

Active sacrifice (black, delayed)
AntiZielElement (B1, check)
Consecutive checks (3). Crosscheck (2)
Self-pin/self-unpin (white). Self-pin/unpin (white) (2024-02-09)
comment
Keywords: Check Protection
Genre: h#
FEN: 3bb2n/4k1p1/rr4p1/6K1/2p5/5p2/8/Q7
Input: Markus Manhart, 1997-06-28
Last update: hpr, 1999-10-19 more...
27 - P0510541
Dragomir Rusin
Problem 41-44 03/1957
3. Preis
15. Thematurnier
P0510541
(3+14) cooked
h#4
1. ... Txg7 2. Td3 Txg6 3. Sd4 Txg4 4. Sb3 Ta4#
play all play one stop play next play all
Cook: NL
1. ... Txg7 2. Ka1 Txf7 3. Sg3 Tf2 4. Dc8 Lxd4#
Yuri Bilokin: Correction: 4nrRB/2p2pbK/p3p1p1/5n2/3r2q1/5p2/k7/1b6 (3+14) (2019-01-19)
A.Buchanan: The diagram matches the published one (2020-10-01)
A.Buchanan: Yuri’s correction is sound and seems economical (2020-10-01)
more ...
comment
Keywords: Check Protection, No legal last move for White, Superseded by (P1389481)
Genre: h#, Retro
FEN: 5rRB/pp2ppbK/2pp2p1/5n2/3r2q1/8/k7/1b6
Input: Markus Manhart, 1997-06-26
Last update: A.Buchanan, 2021-05-12 more...
28 - P0512942
Sergey Sinakevich
Yuri Fokin

2563 Problemista 136-139 01-04/1973
P0512942
(3+3) cooked
h#3
b) wSa1 nach b6
a) 1. Ld3 Sac2 2. Le2 Sd3 3. Sd2 Se3#
b) 1. Sd2 Sc4 2. Kc1 Sa3 3. Ld1 Sd3#
play all play one stop play next play all
Cook: NL:
a) 1. Kc1 Sg2 2. Lb1 Se3 3. Sb2 Sb3#
b) 1. Lh7 Sa4 2. Lc2 Sd3 3. Sd2 Sc3#
Yuri Bilokin: possibly +bPa4 8/8/K7/8/p1n5/8/2b5/N2kN3 (3+4) h#3 b) wNa1-a5
a) 1.Bd3 Sac2 2.Be2 Sd3 3.Sd2 Se3# (MM)
b) 1.Sd2 Sc4 2.Kc1 Sa3 3.Bd1 Sd3# (MM) (2022-12-31)
comment
Keywords: Aristocrat, Miniature
Genre: h#
FEN: 8/8/K7/8/2n5/8/2b5/N2kN3
Input: Markus Manhart, 1997-09-30
Last update: Marcin Banaszek, 2021-03-25 more...
29 - P0514864
Thomas R. Dawson
533 The Chess Problem (Whitburn) 26/06/1946
P0514864
(6+8) cooked
h#2
1. Kxe3 c5 2. Kd2 Sc4#

NL:
1. Td5 Lf5 2. Txe5 Sc2#
1. Lf3 S3g4 2. Lxe4 Lf2#
play all play one stop play next play all
Yuri Bilokin: correction bRd7-f7, bBg4-a4, -bN7 8/5r2/4p3/4N3/bKPkB2B/4N3/4p3/2nr4 (6+7) (2022-12-15)
A.Buchanan: The whole point of this ornamental problem is the symmetry. Any correction must preserve that. How about getting rid of the 2 rooks and the g-h-file bishops, then shift wBe4 to a4? 8/2n5/4p3/4N3/BKPk4/4N3/4p3/2n5? (2022-12-16)
Yuri Bilokin: I agree that the position should be symmetrical and economical, without unnecessary figures. The value of the positions reflected here is close to zero. (2022-12-16)
comment
Keywords: Sacrifice of white pieces, Symmetrical position
Genre: h#
FEN: 8/2nr4/4p3/4N3/1KPkB1bB/4N3/4p3/2nr4
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-24 more...
30 - P0517203
Janos Kiss
8671v Schach-Echo 23, p. 367, 07/1975
P0517203
(5+15) cooked
h#5
1. Lg8 Sxe5 2. Da8+ Sc6 3. Da1 Sxd4 4. Tb2 Sxe2 5. Tc1 Sc3#

NL:
1. Tc1 Kd5 2. Sa1 Sxe5 3. Sc3+ Kxd6 4. Sa2 Sc4 5. Tb2 Sa3#
play all play one stop play next play all
F159
Verst-4
Entfesselung 5-fach

in Problemas als Doppelveröffentlichung ohne sBb6 erschienen, aber auch NL

Misslungene Korrekturfassung aus SE 08/1976, Heft 16, Seite 256 (auch ohne sBb6)
Yuri Bilokin: Correction: bSc2-c7, bPb6-c2, -wPf2, bPg3 (-wPg3) 4q3/2n4b/3p2N1/1p2b3/1r1pK1p1/3P1pp1/2p1n3/1k2r3 (3+15) (2021-03-05)
milan: +sBe6 original solution time 20 min M.Frelih (2021-03-24)
Hans-Jürgen Manthey: Total kaput außer 1.Te1-c1 gibt es noch einige Nebenlösungen:
1.Kb1-a2/b2 Ke4-d5 2.Ka2-b3 Sg6xe5 3.Se2-c3 Kd5xd6 4.Lh7xd3 Se5xf3 5.Kb3-c4 Sf3-d2#
1.Sc2-a1 Ke4-d5 2.Te1-c1 Sg6xe5 3.Se2-c3+ Kd5xd6 4.Sc3-a2 Se5-c4 5.Tb4-b2 Sc4-a3#
1.Se2-c1+ Ke4-d5 2.Sc1-a2 Sg6xe5 3.Te1-c1 Kd5xd6 4.Sc2-a1 weiter wie oben
1.Se2-c3+ Ke4-f5 2.Te1-c1 Kf5xg4 3.Sc2-a1 Sg6xe5 4.Sc3-a2 weiter wie oben
auch 1.Tb4-b2 ist mat in 5 sowie Duale zB
1.Lh7-g8 Sg6-h8 2.Te1-c1 Sh8xf7 3.Sc2-a1 Sf7xd6 4.Tb4-b2 Sd6xb5 5.Lg8-a2 Sb5-a3# (2021-03-25)
milan: by PY-4.61 C+ Time:24 min 40 sec Original losung! M.Frelih (2021-03-25)
Hans-Jürgen Manthey: mit sBe6 gibt es nur die Autorenlösung. gefunden in 3,74 sekunden mit Gustav Brute Force
allerdings entfällt die 5-fache Entfesselung. es ist aber noch eine 4-fache... (2021-03-25)
Viktoras Paliulionis: I like Yuri's fix, which keeps the author's solution and 5 wS unpins.
C+: Popeye v4.85, Time=0.458 s (2021-03-26)
comment

Genre: h#
FEN: 4q3/5p1b/1p1p2N1/1p2b3/1r1pK1p1/3P1pP1/2n1nP2/1k2r3
Reprints: 71 Problemas 01-03/1979
Input: HBae, 1997-09-27
Last update: Felber, Volker, 2015-11-02 more...
31 - P0517281
Thomas R. Dawson
456v The Chess Problem (Whitburn) 23/01/1946
P0517281
(2+9) cooked
h#3
1. Lf5 Sf3 2. Sd3 Sg5 3. Lg7 Sf7#
play all play one stop play next play all
Cook: NL 1. Sd3+ Sf5 2. Th1 Sxh6 3. Lg7 Sf7#
Verst-4
Adrian Storisteanu: Possible fix: wSh4->b4, +bPh4 (2+10) -- 1.Bf5 Sc6 2.Sd3 Sd8 3.Bg7 Sf7#. (2015-08-26)
Yuri Bilokin: possibly bBb1-g6 6nk/7q/6bp/3Kn2r/3b3N/8/8/3r4 (2+9) (2022-12-19)
A.Buchanan: As well as bBb1-g6, one can shift bPh6-h7, i.e. removing bQ which serves no purpose (2022-12-20)
Yuri Bilokin: After correction, you can improve the efficiency (bPh6-h7), you can improve the sparsity (wNh4-b2). (2022-12-21)
A.Buchanan: I also wondered about shifting wSh4, but I thought it's good to have a knight start near to its destination square, because there are more convoluted paths for dual elimination, rather than pulling the line more taut. b4, b8 & e1 also work - it becomes a matter of taste. On balance I like Sh4 because it suggests 1. ... Sf5? unpinning the bS (2022-12-21)
more ...
comment

Genre: h#
FEN: 6nk/7q/7p/3Kn2r/3b3N/8/8/1b1r4
Input: HBae, 1997-10-18
Last update: A.Buchanan, 2022-12-20 more...
32 - P0517577
David W. A. Brotherton
88v The Problemist 09/1966
P0517577
(3+4) cooked
h#4
1. Tg5 Kd2 2. Lf8 Se1 3. Tb5 Sc2 4. Lc5 Le6#

NL:
1. Td1+ Kf2 2. Kd3 Le6 3. Ld2 Kg3 4. Ke2 Lc4#
play all play one stop play next play all
Klären Autor
Verst-4

Original ohne sBg6 abgedruckt, Korrektur(versuch) 05/1967, S. 140
Als Autor ist angegeben: D.W.A. Brotherton
Yuri Bilokin: correction +bPg3 8/8/6pb/3r4/2k3B1/6p1/6N1/4K3 (3+5) (2023-05-24)
comment
Keywords: Miniature
Genre: h#
FEN: 8/8/6pb/3r4/2k3B1/8/6N1/4K3
Input: HBae, 1997-08-18
Last update: Mario Richter, 2021-01-31 more...
33 - P0521991
Pal Siklosi
1083 Problemista 09/1965
Spezialpreis
Version Banaszek s. comment
P0521991
(4+3) cooked
h#2
b) sDc4, h#3
a) 1. Sb5 Ke3 2. Sd6 Sb4#
b) 1. Sc6 Ke2 2. Db4 Ke3 3. Dd6 Sb6#
play all play one stop play next play all
Cook: NL in b): 1. Sd4-e6 Sd3-e1 2. Kd5-d4 Sd7-f6 3. Se6-c5 Se1-f3#
1. Sd4-e6 Sd3-e5 2. Kd5-d4 Sd7-f6 3. Se6-c5 Se5-f3#
1. Sd4-e6 Sd3-b4+ 2. Kd5-d4 Sd7-f6 3. Se6-c5 Sb4-c6#
1. Sd4-e6 Sd7-f6+ 2. Kd5-d4 Sd3-e1 3. Se6-c5 Se1-f3#
Harry Fougiaxis: Cook in b): 1.Se6 Sf6+ 2.Kd4 Se5 3.Sc5 Sc6(Sf3)# (2005-08-02)
Marcin Banaszek: Mit sBe6 statt wBf5 ist die Aufgabe korrekt (a+b C+) (2022-05-30)
comment
Keywords: Tempo Move (K), Multiple publication, Model mate (2), Miniature
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 8/3N4/8/3k1P2/2pn4/3N4/3K4/8
Reprints: 1447 Problemista 66 01/1967
Input: Markus Manhart, 1998-02-10
Last update: Marcin Banaszek, 2022-06-12 more...
34 - P0522092
Aleksandr Kakovin
3597 Land og Folk 15/09/1979
P0522092
(4+3) cooked
h#2
b) sSa5 nach c3
a) 1. Sb6 b3 2. Sac4 b4#
b) 1. Sb6 De4 2. Sb5 b4#

NL:
a) 1. Sa3 Kd7 2. Kd5 Dd4#
b) 1. Sd5 b3 2. Sb6 b4#
b) 1. Sa5 Kd7 2. Kd5 Dd4#
play all play one stop play next play all
Doppelveröffentlichung
Yuri Bilokin: Correction: a1=b1, +bRa7 8/r7/5K2/1n1k4/1Q1n4/5P2/2P5/8 (4+4) h#2 b) b) bSb5--a4
a)1.Sc6 c3 2.Sbd4 c4# (MM)
b)1.Sc6 Qf4 2.Sc5 c4# (2021-03-03)
A.Buchanan: Not in WinChloe: I would say this is a genuine cook, and yours is a genuine fix (2021-03-04)
comment
Keywords: Tempo Move (B)
Genre: h#
FEN: 8/8/4K3/n1k5/Q1n5/4P3/1P6/8
Reprints: 267 Problemas 01-03/1982
Input: Markus Manhart, 1998-02-10
Last update: hpr, 2012-06-01 more...
35 - P0523855
Yosif Krikheli
(26) Problem 02/1968
P0523855
(4+7) cooked
h#2
b) sBf5 nach g6
a) 1. Se8 Txe8 2. Ke4 Lc4#
b) 1. Se8 Txe8 2. Kf6 Ld4#

NL:
a) 1. g3 La2+ 2. Se6 Txe6#
play all play one stop play next play all
Yuri Bilokin: Correction: w Kg2-g1, bQh4-h3, bPg4-f3, bPg5-f7, bPh5-h6, +wPf3, +wPf7, +wPh4, +bBg8, +bBh8, +bRh7, +bPh6 6bb/4Rpnr/4BP1p/4kp1p/7P/4Bp1q/5P2/6K1 (7+11) (2021-05-20)
Gerald Ettl: bei der Verbesserung ist b) eine illegale Stellung. (2021-05-21)
comment
Keywords: Tempo Move (T s)
Genre: h#
FEN: 8/4R1n1/4B3/4kppp/6pq/4B3/6K1/8
Input: Markus Manhart, 1998-02-10
Last update: hpr, 1999-06-06 more...
36 - P0526338
Aleksandr Pankratiev
Nichy Gheran

1588 Buletin Problemistic 1987
P0526338
(3+6) cooked
h#3
2.1...
1) 1. Tg5 Lb1 2. De6 Tc2 3. Tg4 Tf2#
2) 1. Df6 Ta5 2. Tg6 Lb5 3. Lf4 Ld7#

NL:
1. Tg4 La6 2. Dg5 Tc6 3. Tf4 Lc8#
1. Tg6 Lc4 2. Dg5 Tc7 3. Kf6 Tf7#
play all play one stop play next play all
Yuri Bilokin: Correction: -bSh4, +bBe8, bQe7-d6 4b3/8/3q4/2R1bk2/4r3/K2B2r1/8/8 (3+6) (2021-02-08)
comment
Keywords: Fesselungsspiel (246 000 642)
Genre: h#
FEN: 8/4q3/8/2R1bk2/4r2n/K2B2r1/8/8
Input: Markus Manhart, 1998-03-01
Last update: hpr, 1999-02-06 more...
37 - P0528520
Aleksandr Kakovin
76 Problemas 01-03/1963
P0528520
(6+5) cooked
h#2*
*) 1. ... Dxe5+ 2. Kxe5 Lc7#
1) 1. Lxf4+ Ld2 2. Ke5 Lxf4#

NL:
1. Kd7 Dxe5 2. Kc8 Dc7#
play all play one stop play next play all
Yuri Bilokin: Correction: -wPe4, -wPf3, -bPf6, bPd4-c3, wPg3-g4, wBa5-h4, +bPc2, +bSd4, +bPd5, +bPe4, +wSg8 6N1/8/3kp3/3pb3/3np1PB/2p3Q1/2p5/2K5 (5+8) 1...Qxe5+ 2.Kxe5 Bg3# (MM) 1.Bxg3 Bd8 2.Ke5 Bc7# (MM) (2021-02-28)
Yuri Bilokin: wQf4-g3 (2021-02-28)
comment
Keywords: Sacrifice of white pieces
Genre: h#
FEN: 8/8/3kpp2/B3b3/3pPQ2/5PP1/8/2K5
Input: Hans-Jürgen Schäfer, 1998-03-11
Last update: hpr, 1999-11-06 more...
38 - P0530034
Slavko Maslar
Zdravko Maslar

Problem 02/1961
3. Preis II. Int. Turnier Parti?
P0530034
(4+4) cooked
h#3*
*) 1. ... Tb6 2. Ta6 Tb4 3. Tc6 Tb5#
1) 1. Tc6 Tb4 2. Td7 Tb6 3. Td6 Tb5#

NL:
1. Td5 Txa7 2. Kc6 Td7 3. Tb5 Tc7#
play all play one stop play next play all
RK klären
Anton Baumann: Bei Drehung um 180° ist die Aufgabe korrekt! (2020-11-11)
Hans-Jürgen Manthey: Wenn schon Kurz-Notation, dann sollte auch bei doppeldeutigen Zügen dies angezeigt werden!.
so wird bei der Lösung stehts der falsche Turm nach d6 gestellt. Nur 3 Zeichenn mehr ist für eine eindeutige Lösung nötig: 1. Tc7 Tb4 2. Td7 Tab6 3. Tdd6 T6b5# (2020-11-12)
comment

Genre: h#
FEN: b7/rR6/R2r4/P1k5/8/8/8/7K
Input: Ralf Krätschmer, 1998-02-01
Last update: Ralf Kr?tschmer, 2014-12-18 more...
39 - P0531421
Thomas R. Dawson
1796 The Problemist Fairy Chess Supplement 02/1935
P0531421
(4+4) cooked
h#2
b) sTd7 nach e7, sTh3 nach h4
a) 1. Kg5 Tg2+ 2. Kh4 Tg4#
b) 1. Kxg7 Tg2+ 2. Kf8 Tg8#

NL:
a) 1. Kg5 Tg2+ 2. Kh4 Shf5#
play all play one stop play next play all
klären Monat
Alfred Pfeiffer: No.1796 ist aus 04/1935 (vgl. P0003272) (2011-01-11)
Yuri Bilokin: possibly bBe4(-bNe4), +bPd3 8/3r2N1/6kN/8/4b3/3p3r/2R5/1K6 (4+5) (2022-12-16)
comment
Keywords: Sacrifice of white pieces, Symmetrical position, Aristocrat, Aristocrat
Genre: h#
FEN: 8/3r2N1/6kN/8/4n3/7r/2R5/1K6
Reprints: 1796 The Problemist Fairy Chess Supplement 04/1935
Input: Ralf Krätschmer, 1998-03-30
Last update: Arnold Beine, 2022-12-17 more...
40 - P0533559
Toma Garai
451v The Problemist 03-04/1975
P0533559
(4+8) cooked
h#2
b) wKg4 nach g3
a) 1. Tc4 Td4 2. Kb4 Lxd2#
b) 1. Tb4 Tc7 2. Tc4 Le5#

NL:
b) 1. Kb4 Tc7 2. Th5 Lxd2#
play all play one stop play next play all
Daniel Novomesky: In b) position is needed to take away even black Pawn a3. So, a) Diagram b) Kwg4-g3 and -Pba3. Problem is correct. C+ (2007-10-26)
Yuri Bilokin: Correction: -bBb8 8/3R4/8/1pr5/3r1BK1/p1kp4/3p4/3B4 (4+7) h#2 b) wPa3-e4
a) 1.Rdc4 Rd4 2.Kb4 Bxd2# (MM)
b) 1.Rb4 Rc7 2.Rcc4 Be5# (MM) (2021-05-20)
comment
Keywords: Fesselungsspiel (234 202 220)
Genre: h#
FEN: 1b6/3R4/8/1pr5/3r1BK1/p1kp4/3p4/3B4
Input: Markus Manhart, 1998-03-28
Last update: hpr, 1999-11-07 more...
41 - P0533723
Rudolf A. Pieprzyk
223 Problemista 02/1964
(4. Platz wurde annulliert)
IV Schlesischer Problemistenkongress
Blitzthematurnier 17.11.1963
P0533723
(3+4) cooked
h#3
1. Kc4 0-0-0 2. Lb4 La6+ 3. Kc3 Txd3#

NL:
1. c5 0-0-0 2. Ka2 Txd3 3. Ka1 Ta3#
1. Kc3 La6 2. Lb4 0-0-0 3. c5 Txd3#
play all play one stop play next play all
Auszeichnung wurde in Problemista 04/1964 annulliert.
Yuri Bilokin: correction wBc8-e8, bKb3-d4, bBf8-e3, bPc7-f7, +bQa6, -bPd3 4B3/5p2/q7/8/3k4/4b3/8/R3K3 (3+4) h#3

1.Kc3 Bb5 2.Bc5 0-0-0 3.Bb4 Rd3#

Castling (white, long) (2023-06-10)
comment
Keywords: Castling (wg)
Genre: h#
FEN: 2B2b2/2p5/8/8/8/1k1p4/8/R3K3
Input: Andreas Mokosch, 1997-09-11
Last update: Marcin Banaszek, 2019-11-15 more...
42 - P0540829
Filippo Minieri
H551 The Problemist 07-08/1977
P0540829
(5+9) cooked
h#2
1.2.1.1
1) 1. exd3ep b8=D 2. Kd4 Df4#
2) 1. exd3ep a8=S 2. d4 Sxb6#
play all play one stop play next play all
Cook: e.p. not justified as R: 0.e3xd4 possible
VL: Unjustified ep-capture because of –e3xd4. For correction it suffices e.g. to add bSe3.
This is possibly a unique 2-move helpmate with ep-key and 2 solutions of the type 1.2.1.1 (at least so currently in the PDB).
Publi?ation details. H551 in the Helpmate section of the July issue, with no preview. Here is the text of the solution published in the Nov.-77 issue: “…White may have just played P(e3)xd4. Very few solvers have spotted this. Full marks for claim of no solution with correct reasoning but, in fairness, one mark for composer's intention. White cannot have just played K(a5)a6 in reply to Pxb6+ as too many captures by Black are required.” (2023-12-01)
A.Buchanan: Yes Valery you are right this must be cooked. However, I'm not a fan of +bSe3 because it spoils one of the model mates. Separately, I mildly prefer bPf7 to bPe6. (2023-12-03)
VL: I do prefer bPf7, as well. I don't see any way to save at least one of the properties Kindergarten Problem and Model mate (2) after fixing (what for these keywords have been added just now?). Besides, Andrew, please, refine the specification ((full) number and publication month 07-08). (2023-12-03)
A.Buchanan: Ok have added the publication details. The keywords are useful to indicate the aim, even though the problem is cooked. I guess there is a way to keep the model mates but it’s very clunky and probably +bSe3 is better (2023-12-03)
more ...
comment
Keywords: En passant as key, Kindergarten Problem, Model mate (2)
Genre: h#, Retro
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/PP6/Kpp1p3/2pp4/1pkPp3/2p5/P7/8
Input: Michal Dragoun, 1998-04-09
Last update: A.Buchanan, 2023-12-03 more...
43 - P0545925
A. H. Haddy
The Chess Problem (Whitburn) 15/11/1946
P0545925
(2+5) cooked
h#4
1. Tb2 e7 2. Da8 e8=S 3. Lb8 Sd6 4. Tb7 Sc8#

NL:
1. Ta2 e7 2. Ta4 e8=D 3. Kb6 Dc6+ 4. Ka5 Dc5#
1. Lc1+ Ke7 2. Kb8 Kd6 3. Kc8 e7 4. Db7 e8=T#
play all play one stop play next play all
K+B, F112, Umw (S)
Verst-4
Yuri Bilokin: Correction: bSa6, wKf8-g8, bRf2-g1, bQf3-g2, bBf4-g3 6K1/k7/n3P3/8/8/6b1/6q1/6r1 (2+5)
1.Rb1 e7 2.Qa8+ e8=S 3.Bb8 Sd6 4.Rb7 Sc8# (MM) (2021-11-25)
comment

Genre: h#
FEN: 5K2/k7/p3P3/8/5b2/5q2/5r2/8
Input: HBae, 1997-08-30
Last update: hpr, 1999-04-06 more...
44 - P0546083
Frank Raven Adcock
1822 The Problemist Fairy Chess Supplement 06/1935
P0546083
(4+10) cooked
h#3
1. Txa7+ Kb6 2. Lf8 Ta8 3. Te7 Ld7#
play all play one stop play next play all
Cook: NL 1. Lc5 Ta8 2. Lxa7 Ld7 3. Lb6 Kxb6#
Verst-4
Adrian Storisteanu: Possible fix: bRc2->g8, +bQc2 (4+11). (2015-08-22)
Yuri Bilokin: Correction: bSd3-e6, bPd4-b6, bPd5-c2(-bRc2) 4R3/B3r3/Kp2n3/8/B7/bp6/kpp5/1b6 (4+9) 1.Rxa7+ Kxb6 2.Bf8 Ra8 3.Re7 Bd7# (2021-05-23)
A.Buchanan: That's a very nice corrected version, Yuri (2021-05-24)
comment
Keywords: Sacrifice of white pieces
Genre: h#
FEN: 4R3/B3r3/K7/3p4/B2p4/bp1n4/kpr5/1b6
Input: HBae, 1998-01-19
Last update: Alfred Pfeiffer, 2015-08-22 more...
45 - P0548009
Vaclav Gebelt
1670 Problemista 75 10/1967
P0548009
(8+5) cooked
h#2
b) wBb2 nach g6
a) 1. Tb6 e4 2. Kd4 Sxc6#
b) 1. Le4 Tc5+ 2. Kd4 Sf5#

NL:
a) 1. Ld5 Txc6 2. Le6 Ld4#
1. Lf3 Th5+ 2. Ke4 Tc4#
b) 1. Ta1 Th5+ 2. Ke4 Tc4#
play all play one stop play next play all
Yuri Bilokin: correction -bRa6, -bPc6, bRa5-b3, +bNa3, +bNc2 8/B3N2K/3P4/4k3/7R/nrR5/1Pn1P3/7b (8+5) (2022-06-17)
comment
Keywords: Fesselungsspiel (222 202 000)
Genre: h#
FEN: 8/B3N2K/r1pP4/r3k3/7R/2R5/1P2P3/7b
Input: Markus Manhart, 1998-05-11
Last update: Marcin Banaszek, 2022-06-17 more...
46 - P0551313
Israel Zur
387 Haproblemai 12/1981
P0551313
(5+3) C+ cooked
h#3
1. Kd5 0-0-0+ 2. Ke6 Sb6 3. Tf6 Te1#

NL:
1. Kf4 Kxf2 2. Td5 Tg1 3. Te5 Tg4#
1. Txa2 Sc7 2. Tf2 Ta4 3. Tf5 Sg4#
play all play one stop play next play all
Anton Baumann: Diagrammfehler? Mit zusätzlichen sBh5 werden die NL-Matts auf g4 verhindert!
Computerprüfung mit +sBh5 (5+4): C+ Gustav 4.1d (2021-01-28)
comment
Keywords: Castling (wg), Check Protection, Symmetrical position
Genre: h#
FEN: N7/8/3r3N/4k3/8/8/P4r2/R3K3
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-05-02 more...
47 - P0552393
Tibor Balo
554 Problemas 10-12/1988
2. Lob
P0552393
(3+4) cooked
h#5
1. Sf5 Lf6 2. Kxf6 gxf5 3. Kg7 fxg6 4. Kh8 Kf7 5. Sh7 g7#

NL:
1. g5 Kd8 2. Kf7 La1 3. Kg6 Ke8 4. Kh6 Kf7 5. Sh7 Lg7#
play all play one stop play next play all
Yuri Bilokin: possibly bNe7-f7, +bPf6, +bPg5 4Kn1B/5n2/4kpp1/6p1/6P1/8/8/8 (3+6) h#5
1.f5 Bf6 2.Kxf6 gxf5 3.Kg7 fxg6 4.Kh8 Kxf7 5.Sh7 g7# (MM) (2023-01-11)
comment
Keywords: Sacrifice of white pieces
Genre: h#
FEN: 4Kn1B/4n3/4k1p1/8/6P1/8/8/8
Input: Hans-Jürgen Schäfer, 1998-07-01
Last update: hpr, 2012-06-03 more...
48 - P0553527
Veljko Vorgic
Problem 07/1960
4. ehrende Erwähnung
II. Nationales Jugoslawisches Turnier
P0553527
(4+6) cooked
h#2*
b) wSd3 nach d8
a*) 1. ... Sb4 2. Te6 Td5#
a1) 1. Tc4 Sf4 2. Tc6 Td5#
b*) 1. ... Tc5 2. Te6 Sb7#
b1) 1. Tc4 Te5 2. Tc6 Sf7#

NL:
b) 1. c5 Txc5 2. Te6 Sb7#
play all play one stop play next play all
Yuri Bilokin: correction +wPb6, bPc7-b7 8/1p1pp3/1P1k4/R6K/4r3/3Np3/4P3/8 (5+6) h#2* b) wSd3-d8
a) 1...Sb4 2.Re6 Rd5#
1.Rc4 Sf4 2.Rc6 Rd5#
b) 1...Rc5 2.Re6 Sxb7#
1.Rc4 Re5 2.Rc6 Sf7# (2023-06-26)
comment
Keywords: Echo
Genre: h#
FEN: 8/2ppp3/3k4/R6K/4r3/3Np3/4P3/8
Input: Hans-Jürgen Schäfer, 1998-08-04
Last update: hpr, 1999-05-04 more...
49 - P0556423
Thomas R. Dawson
Israel Problem Association 1948
3. Lob
Seidemann Memorial
P0556423
(4+6) cooked
h#2
b) alles eine Reihe tiefer
a) 1. c5 Lf4 2. Te4 Td8#
b) 1. Ld1 Txe2 2. Ld4 La6#

NL:
b) 1. Td2 Te1 2. Ld4 La6#
play all play one stop play next play all
Yuri Bilokin: possibly bNb3(-wPb3), bPc3(-bBc3), +bPc4, +bPf4 1B2R3/2p5/8/8/2pk1p2/1np1r3/2r3bK/8 (3+9) h#2 b) alles eine Reihe tiefer
a) 1.c5 Bxf4 2.Re4 Rd8# (MM)
b) 1.Sd1 Rxe2 2.Bd4 Ba6# (2022-12-16)
milan: a) -wPb3+bPa7wBf1
b)all pieces to the left
1.Ra6 B×b7 2.Bc5 Ba6#
1.Kc5 Rd5+ 2.Ka4 Ra5#
1.b5 Be4 2.Rd4 Rc8#
i'ts look like battle of the bishops
M.Frelih (2022-12-18)
Yuri Bilokin: Very bad. In a problem that has nothing to do with the author's intention, there is still an extra white bishop in the solution 1.Kc5 Rd5+ 2.Ka4 Ra5# (2022-12-19)
milan: +wBa6bPa5-wPb3 1.c5 Bf4 2.Re4 Rd8# 1.Rb6 B×c7 2.Bd5 B×b6#
your solution b) not C+... bRb5? M.Frelih (2022-12-19)
Yuri Bilokin: Sorry for your misunderstanding. Everything is fine in my edition. Twin FEN Code a) You see Twin FEN Code b) Showing 8/1B2R3/2p5/8/8/2pk1p2/1np1r3/2r3bK, solution
1.Sd1 Rxe2 2.Bd4 Ba6# (2022-12-20)
comment

Genre: h#
FEN: 1B2R3/2p5/8/8/3k4/1Pb1r3/1r4bK/8
Input: Franz Pachl, 1998-08-31
Last update: hpr, 1999-04-04 more...
50 - P0559272
Miklos Zboray
(57) Problem 08/1974
Lob
57. Thematurnier
P0559272
(2+12) cooked
h#7
1. a1=T hxg3 2. Ta2 g4 3. Tb2 g5 4. Tb5 gxf6 5. Tg5 f7 6. Tg8 f8=D 7. Th8 Df7#

NL:
1. a1=T hxg3 2. Ta2 g4 3. Tb2 g5 4. Tb6 gxf6 5. Kh8 f7 6. Tg6 f8=D+ 7. Tg8 Dxh6#
play all play one stop play next play all
klären AL ?
Yuri Bilokin: correction +bQh4(h3) 8/7k/1p3p1p/8/2n4q/p1pp2n1/p1p4P/1bK5 (2+13) (2023-05-08)
comment
Keywords: Promotion, Excelsior white (auto key)
Genre: h#
FEN: 8/1p5k/5p1p/8/2n5/p1pp2n1/p1p4P/1bK5
Input: Hans-Jürgen Schäfer, 1999-01-01
Last update: hpr, 1999-11-25 more...
51 - P0562586
Aleksandr Kakovin
Nikolay Budkov

145 Problemas 01-03/1980
P0562586
(3+9) cooked
h#3
b) sKe1 nach a3
c) sKe1 nach h4
a) 1. Le2 Ld4 2. d1=L Lxc5 3. Kd2 Lb4#
b) 1. La4 Le5 2. d1=L Lxd6 3. Lb3 Lxc5#
c) 1. Lh5 Lg7 2. d1=L Lxf8 3. Lg4 Lxe7#

NL:
a) 1. Le2 Lh8 2. d1=T+ Kb2 3. Kd2 Lc3#
c) 1. Lh5 f4 2. d1=L Ld4 3. Lg4 Lf2#
play all play one stop play next play all
Yuri Bilokin: Correction: bBf8-c5 (-bPc5), +bSc4, +bRh2 8/4p3/3p4/2b5/2n4k/3p3p/3p1P1r/BK1b4 (3+10) (2021-02-28)
comment

Genre: h#
FEN: 5b2/4p3/3p4/2p5/8/3p3p/3p1P2/BK1bk3
Input: Markus Manhart, 1998-12-25
Last update: hpr, 1999-11-30 more...
52 - P0564216
Carel Johan Robert Sammelius
1017v The Problemist 03/1985
P0564216
(2+9) cooked
h#6
1. Ld2 Sxe4 2. La5 Sd6 3. Te6 Sxf5 4. Tb6 Sxg7 5. Dh7 Se6 6. Da7 Sxc5#
play all play one stop play next play all
Cook: NL 1. La3 Kf4 2. Db3 Ke5 3. La4 Kd6 4. Ka5 Kc7 5. Kb4 Kb6 6. c4 Sd5#
Adrian Storisteanu: Possible fix: wKg3->g2, bRe1->e3, +bPd6 (2+10) [2...Sxd6]. (2015-11-04)
Viktoras Paliulionis: Other possible fix: bPc5-d4, bBc1-h6, +bPf6. (2021-02-02)
comment

Genre: h#
FEN: 8/6p1/k7/1bp2p2/4p3/2N3K1/8/1qb1r3
Input: Markus Manhart, 1999-02-17
Last update: Alfred Pfeiffer, 2015-11-04 more...
53 - P0564422
Oleksy M. Stelman
520v Buletin Problemistic 04-06/1975
P0564422
(2+6) cooked
h#6
1. Lf2 e4 2. Td5+ Kf6 3. Kb4 e5 4. Kc5 e6 5. Kd6 e7 6. Lc5 e8=S#

NL:
1. Ka2 e4 2. Ld5 exd5 3. Ta6 d6 4. Sc7 dxc7 5. Ka1 c8=D 6. Ta2 Dc1#
ua
play all play one stop play next play all
Yuri Bilokin: correction bNb5-a1, bBh4-d8 3b4/3p4/2br4/4K3/8/k7/4P3/n7 (2+6)
1.Bb6 e4 2.Rd5+ Kf6 3.Kb4 e5 4.Kc5 e6 5.Kd6 e7 6.Bc5 e8=S# (MM)
the idea is not new P0564440 (2022-08-17)
comment
Keywords: Excelsior white (auto key)
Genre: h#
FEN: 8/3p4/2br4/1n2K3/7b/k7/4P3/8
Input: Markus Manhart, 1999-02-21
Last update: hpr, 1999-04-06 more...
54 - P0564974
Charles Edward Kemp
The Problemist 05/1944
nach T. R. Dawson
P0564974
(2+11) cooked
h#5
1. c6 Lh6 2. Da5+ Ld2 3. Dh5 Le3 4. Kd8 Lxa7 5. De8 Lb6#
play all play one stop play next play all
Cook: NL
1. c6 Lh6 2. e6 Ke2 3. Dc7 Ke3 4. Ke7 Kd4 5. Kd6 Lf8#
Adrian Storisteanu: Possible fix: +bSg8 (2+12). (2015-08-07)
Jakob Leck: Die Dawson-Aufgabe könnte P0555591 sein - zeitgleich erschienen. (2022-12-28)
comment

Genre: h#
FEN: 2bqkB2/ppppp3/5p2/8/8/6p1/6p1/4K3
Input: Markus Manhart, 1999-02-27
Last update: Alfred Pfeiffer, 2015-08-07 more...
55 - P0567778
Albinas Biciusas
3870 Problem 09/1976
P0567778
(3+5) cooked
h#3
2.1...
1) 1. Td5 Ld3 2. Lc5 Le1 3. Ld4 Lg3#
2) 1. Ld7 Lh7 2. Ke6 Lf4 3. Tf5 Lg8#

NL:
1. Kd5 Lc3 2. Kc4 Kc2 3. Ld5 Ld3#
play all play one stop play next play all
Yuri Bilokin: Correction: -bRc5, +bQd3 8/4b3/4bp2/4kB2/8/3q4/3B4/3K4 (3+5)
1.Qd5 Bd3 2.Bc5 Be1 3.Bd4 Bg3# (MM)
1.Bd7 Bh7 2.Qf5 Bf4+ 3.Ke6 Bg8# (MM)
Exchange of functions (bBe6/bBe7, Passive self-block / Self-block)
Exchange of functions (wBd2/wBf5, Guard / Mate) (2021-11-16)
comment
Keywords: Reihen-Echo
Genre: h#
FEN: 8/4b3/4bp2/2r1kB2/8/8/3B4/3K4
Input: Ralf Binnewirtz, 1998-10-29
Last update: hpr, 1999-12-12 more...
56 - P0569828
Evgeny Sorokin
564 Problemas 01-03/1975
A.F.Argüelles gewidmet
P0569828
(4+1) cooked
h#2*
2.1...
*) 1. ... Te8 2. Kf7 Lh5#
1) 1. Kg5 Tg1 2. Kh4 Lf6#
2) 1. Kf7 Le6+ 2. Kf8 Tf1#

NL:
1. Kf7 Lh5+ 2. Kf8 Te8#
play all play one stop play next play all
Yuri Bilokin: Correction: rotate 180, then wKe2-e1, +bPe2 3R4/8/5B2/1B6/8/1k6/4p3/4K3 (4+2) h#2* 2.1…
1...Rd1 2.Kc2 Ba4#
1.Kc2 Bd3+ 2.Kc1 Rc8#
1.Kb4 Rb8 2.Ka5 Bc3# (MM)
Orthogonal-diagonal transformation. (2022-05-11)
comment

Genre: h#
FEN: 8/3K4/6k1/8/6B1/2B5/8/4R3
Input: hpr, 1999-04-01
Last update: hpr, 2012-05-07 more...
57 - P0572507
William Edmund Frank Fillery
Donald A. Smedley

875v The Problemist 01/1983
P0572507
(3+5) cooked
h#4
3.1...
1) 1. Sd7 c5 2. Kb7 c6+ 3. Ka7 c7 4. Sb8 c8=S#
2) 1. Sh7 c5 2. Kb5 c6 3. Kb6 c7 4. Ka7 cxd8=D#
3) 1. Tc8 Ta7 2. Tc7 c5 3. Kd7 c6+ 4. Kc8 Ta8#

NL:
1. Ta7 Tg8 2. Kb7 c5 3. Ka8 c6 4. Sg6 Txd8#
1. Kd6 Td7+ 2. Ke5 Kg2 3. Lf6 Kf3 4. Se6 Td5#
play all play one stop play next play all
Yuri Bilokin: Correction: wRg7-f7, +bPg7, +bRg8, +bPh3 r2b1nr1/5Rp1/p1k5/8/2P5/7p/8/7K (3+8) (2022-04-20)
comment

Genre: h#
FEN: r2b1n2/6R1/p1k5/8/2P5/8/8/7K
Input: Markus Manhart, 1999-03-28
Last update: Markus Manhart, 1999-03-29 more...
58 - P0572779
Alexander Hildebrand
Problemas 07-12/1972
A.F.Argüelles gewidmet
P0572779
(3+7) cooked
h#6
2.1...
1) 1. Le4+ dxe4+ 2. Kd4 e5 3. Ke3 e6 4. Kf2 e7 5. Kg2 e8=D 6. Kh1 De4#
2) 1. Ke5 d4+ 2. Kf4 d5 3. Kg3 d6 4. Ld5 d7 5. Kg2 d8=D 6. Kh1 Dxd5#

NL:
1. Le4+ dxe4+ 2. Kd4 e5 3. Sf6+ exf6 4. Ke3 f7 5. Kf2 f8=D+ 6. Kg2 Df3#
1. Lc5 d4 2. Kc4 d5 3. Lf3 d6 4. h1=T d7 5. Tb1 d8=D 6. Tb4 Dd3#
play all play one stop play next play all
Yuri Bilokin: correction wKh7-a1, bPh6-e3, -wPe2, -bNg8 1n6/8/8/3k4/8/3Pp3/7p/K5bb (2+6) h#6 2.1…
1.Be4 dxe4+ 2.Kd4 e5 3.Ke4 e6 4.Kf3 e7 5.Kg2 e8=Q 6.Kh1 Qe4# (MM)
1.Ke5 d4+ 2.Kf4 d5 3.Kg3 d6 4.Bd5 d7 5.Kg2 d8=Q 6.Kh1 Qxd5# (MM) (2022-07-12)
comment

Genre: h#
FEN: 1n4n1/7K/7p/3k4/8/3P4/4P2p/6bb
Input: Markus Manhart, 1999-04-03
Last update: hpr, 2012-03-25 more...
59 - P0575046
Carl Eric Nylund
Problemnoter 1965
P0575046
(2+5) cooked
h#4
1. Sh6+ gxh6 2. Lg7 Kg5 3. 0-0 Kxg6 4. Lh8 h7#

NL:
1. Th6 gxh6 2. Kf7 h7 3. Kg7 Kf4 4. Kh6 h8=D#
play all play one stop play next play all
Yuri Bilokin: Correctiom: bSg8-f7 (2021-11-25)
comment

Genre: h#
FEN: 4kbnr/8/6p1/6P1/6K1/8/8/8
Input: Felber, Volker, 1999-12-23
Last update: hpr, 2000-01-21 more...
60 - P0576946
Evgeny Sorokin
Land og Folk 1976
P0576946
(4+12) cooked
ser-h=19
1. Ke5 2. Kd4 3. Kxd3 4. Kc2 5. Kxb1 6. Kc2 7. b1=L 8. Da1 9. b2 10. b3 11. b4 12. Ta5 13. Ta2 14. T5a5 15. T5a3 16. La4 17. b5 18. La5 19. b6 Ke2=
play all play one stop play next play all
Kurzlösung in 18 Zügen
Cook: 1. Txd3 2. Th3 3. Kd5 4. Kc4 5. Le5 6. Lf5 7. Lxb1 8. La2 9. b1=L 10. Da1 11. Kd3 12. Tc2 13. Lb2 14. La3 15. Tb2 16. Kc2 17. Th2 18. Te2+ Kxe2=
Joshua Green: I've been testing some modifications to Popeye with the goal of improving its performance against seriesmovers. Unfortunately, my improved -- assuming there are no bugs -- Popeye cooked this problem, offering:
1. Txd3 2. Th3 3. Kd5 4. Kc4 5. Le5 6. Lf5 7. Lxb1 8. La2 9. b1L 10. Da1 11. Kd3 12. Tc2 13. Lb2 14. La3 15. Tb2 16. Kc2 17. Th2 18. Te2+ Kxe2= (2022-09-13)
comment
Keywords: Seriesmover
Genre: Fairies
FEN: 8/1pbb4/1p2k3/1prr4/1p6/1pqP4/1p1B4/1N2K3
Reprints: B21 Shift of groups of pawns in chess problems 28/04/2005
Input: Felber, Volker, 2000-01-03
Last update: Arnold Beine, 2022-09-13 more...
61 - P0577226
Jonathan Paul Levitt
B) The Problemist (2), p. 32, 03/1995
P0577226
(6+4) cooked
ser-h#30
1. Kb2 2. Kc3 3. Kd4 4. Kxe5 5. Kf6 6. e5 7. e4 8. e3 9. e2 10. e1=L 11. Lxh4 12. Lg5 13. Lxh6 14. Kg7 15. Kh8 16. Lg7 17. h5 18. h4 19. h3 20. h2 21. h1=L 22. Lxd5 23. Lg8 24. d5 25. d4 26. d3 27. d2 28. d1=T 29. Th1 30. Th7 Sg6#
play all play one stop play next play all
Erich Bartel: im Problemist ist hierzu vermerkt:
Jonathan's Artikel has already apeared, in translation,in the
March 1995 issue of Rochade-Europa, and these originals
should compete in the informal tourney of that magazine.
--------
Die Frage ist nun welches Magazin als Erstqueelle gelten soll. (2011-11-28)
Anton Baumann: NL: 1.d6 2.dxe5 .. 6.e1=D .. 8.Dg8 .. 13.e1=L 14.Lxh4 15.Lg5 16.Lxh6 .. 23.Kh8 24.Lg7 .. 29.h1=T 30.Th7 Sg6# (2020-11-21)
more ...
comment
Keywords: Seriesmover, corner to corner (sKa1h8), Excelsior (3-fach), under-promotion, konsekutive Umwandlungen 3 (llt)
Genre: Fairies
FEN: 8/3pp2p/7P/1K1PP3/5N1P/8/8/k7
Reprints: Rochade Europa 03/1995
Input: Felber, Volker, 2000-01-06
Last update: Olaf Jenkner, 2020-11-23 more...
62 - P1001744
Samuel Loyd
The Chess Monthly , p. 324, 11/1860
P1001744
(3+4) cooked
h#3
1. Lf3 Kc3,Kc4 2. Ke4 Td8 3. Df5 Td4#
play all play one stop play next play all
Autorlösung war 1. Lf3 usw. In der überarbeiteten Fassung P0516986 machte er den ursprunglichen Cook zur Lösung.
Cook: NL 1. Kf6 Ta8 2. Kg7 Lb8 3. Kh8 Le5#
Die "Ur-Position", die korrekte Fassung siehe P0516986
Sally: S69 Ideengeschichte :
Berühmteste Nwbenlösung der S. Geschichte! (2010-07-09)
milan: [+bNb2 and Bh2-c7]it's first helpmate ever composed corrected by Milan Frelih. (2016-04-11)
Yuri Bilokin: Correction: -bBh2, +bPb5, wKd4-d3 6R1/7q/8/1p3k2/5B2/3K4/6b1/8 (3+4) (2021-02-08)
comment
Keywords: Hilfsmatt-Inder (TL)
Genre: h#
FEN: 6R1/7q/8/5k2/3K1B2/8/6bb/8
Reprints: 139 Encyclopedia of Chess Problems , p. 47, 2012
Input: hpr, 2001-12-19
Last update: Alfred Pfeiffer, 2016-03-29 more...
63 - P1004145
Thierry Le Gleuher
R052 Problem Paradise 20 2002
P1004145
(5+9) cooked
shc#12
1. d5 2. d4 3. d3 4. d2 5. d1=L 6. Lb3 7. Lxa2 8. Lc4 9. Lf1 10. Lg2 11. Lh1 12. fxg3ep fxg3#
play all play one stop play next play all
Aber nach 11. Lh1 kann Weiß auch g2xLh3 zurücknehmen!
Cook: gxsLh3!
Henrik Juel: 1.d5-d4-d3-d2-d1B-b3xa2-c4-f1 10.Bg2-h1 12.fxg3ep+?? fxg3# seems to fail, because after 11.Bh1 last move could be g2xh3. So what is the solution? (2003-04-28)
Thierry LE GLEUHER: After 11.Bh1, the last move can't be g2xh3 because of the promoted Bishop h1 imcompatible with the bP structure! (2005-09-25)
Henrik Juel: Why couldn't Black have a promoted bishop at this point in time (where wPa2 and bPd7 are no longer present)? 12 captures by black pawns seem to match the 12 missing white men. (2005-09-26)
Joost de Heer: Besides, after g2-g4, the black bishop must've been promoted too. (2005-09-30)
James Malcom: Henrik, gxh3 is indeed impossible. The last move sequence must go something like 1. Kfg8 Se2+ 2. Kh2 Sg1. There cannot be a knight on h3, cutting off g8, or a queen/rook, cutting off h2. Thus, gxh3 has already been played and g2-g4 is the last move. (2021-09-14)
Mario Richter: Position after 11. Lh1 is 8/5p2/8/5ppp/5pPk/5p1P/5P1K/6nb.
It can be easily shown, that in this position g2xLh3! is indeed a legal retraction.
So the ep-capture is not justified and the problem is cooked!
(Perhaps Thierry forgot, that black pawn d7 "disappeared"? But Joost's argument raises [correctly] the question, why a promoted Bishop on h1 is ok for g2-g4, but not for g2xLh3.) (2021-09-15)
Henrik Juel: So the good guys (Mario, Joost, and me) win over the bad ones (Thierry and James) by 3-2... (2021-09-15)
Henrik Juel: or, less insultingly:
By a majority of 3 to 2 this problem has been deemed cooked (2021-09-15)
James Malcom: Make it 4 to 1: 1. Nc3 Nf6 2. Nd5 Rg8 3. Nxf6+ exf6 4. d4 Ke7 5. Bg5 fxg5 6. Nf3 Kf6 7. Ne5 Bd6 8. Nc6 Bg3 9. hxg3 bxc6 10. Rh4 gxh4 11. b4 Ba6 12. a4 Bd3 13. b5 Bf5 14. b6 h3 15. bxa7 h2 16. a5 Bh3 17. g4 Re8 18. a6 Re5 19. dxe5+ Kg5 20. Qd6 Qe7 21. c4 Qe6 22. Ra3 Qd5 23. cxd5 cxd5 24. Rf3 Nc6 25. e4 Re8 26. a8=Q Nd4 27. a7 cxd6 28. Qxe8 dxe4 29. Qe6 dxe6 30. a8=Q exf3 31. Bd3 Kh4 32. Bf5 exf5 33. Qa5 g5 34. Qd5 h5 35. Qe4 dxe5 36. Qf4 exf4 37. Kf1 h1=B 38. Kg1 Ne2+ 39. Kh2 Ng1 40. gxh3 (2021-09-16)
A.Buchanan: Is it also possible that in the critical position, the last moves were R: 1.gxSh3 exXf345 2.X~? I think I can fix the cook R: 1.gxLh3 nicely. (2021-09-17)
more ...
comment
Keywords: Seriesmover, Consequent, Excelsior, Promotion (l)
Genre: Retro, Fairies
FEN: 8/3p1p2/8/5ppp/5pPk/5p1P/P4P1K/6n1
Input: Gerd Wilts, 2002-07-27
Last update: A.Buchanan, 2021-09-17 more...
64 - P1004179
Arpad Molnar
R275 The Problemist 05/1998
4. ehrende Erwähnung
P1004179
(11+10) cooked
Letzte 12 Einzelzüge?
R: 1. a4xSb3+ Dd8-b6 2. b6xSa5 Tc8-c6 3. c7xSb6 Lc6-b5 4. b5xSa4 Sa8-b6 5. b6-b5 Lb7-c6 6. Kb5-b4 c3-c4+
play all play one stop play next play all
Gerald Ettl: Wie lautet der Cook? (2023-09-28)
comment
Keywords: Ceriani-Frolkin Theme (SSSS), Last Moves? (12)
Genre: Retro
FEN: 1N6/p2p1ppp/RQRp4/pBNP4/1kP5/bp6/PPK5/8
Reprints: (1) Quartz 18 10-12/2001
Input: Gerd Wilts, 2002-09-05
Last update: Gerd Wilts, 2004-08-28 more...
65 - P1012536
Thomas R. Dawson
British Chess Magazine 06/1925
P1012536
(10+5) cooked
#2
Grashüpfer d5,d6
1. b8=S? droht 2. Sc6#
1. ... Gxa6!

1. bxc6ep! Gxd4,Gxb6,~ 2. Lb5#

R: 1. c7-c5 2. Gd7-d5+ Gb8-d6
play all play one stop play next play all
'The Problemist', p. 241, 09/1993: "The solution to this #2 with Grasshoppers is 1.bxc6
en passant. lf Black's last move had been 1...c6, then White's previous move would have been the illegal G(d7)-d5+.
Cook: 1. Sc4+ Kxa4 2. Sab6#
No. 2251 HN
A.Buchanan: Diagram error? Solution typo? (2023-01-06)
Mario Richter: Diagram error corrected (2023-01-07)
Ulrich Voigt: NL: 1. Sc4+ Kxa4 2. Sab6# (2023-01-08)
Mario Richter: Vielleicht sind Dawson und alle, die diese Aufgabe unkritisch nachgedruckt haben, einer typischen Halluzination erlegen: im Geiste nimmt man den Zug c7-c5 zurück, der erst den ep-Key ermöglicht, und meint dann, daß die NL: 1. Sc4+ Kxa4 2. Sab6 an 2. ... c7xb6 scheitert ... (2023-01-09)
A.Buchanan: Easily repaired e.g. by replacing wSa8 with wLa7 (2023-01-09)
comment
Keywords: En passant as key
Pieces: du = Grasshopper (G)
Genre: Retro, Fairies
FEN: N2K4/1P6/PN1*2q4/kPp*2Q4/Pp1R4/p2B4/8/8
Reprints: The Problemist , p. 241, 09/1993
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2023-01-09 more...
66 - P1013759
Hans Gruber
1470 Problemkiste 04/1986
P1013759
(6+6) cooked
h=4
1. e1=D g7 2. Dh1 g8=S 3. Db7+ axb7 4. a1=L bxc8=T=
{ NL} 1. a1=L a7 2. e1=L a8=D 3. La5 Dxa5 4. Kc6 Kxc8=
Nachdrucke:
1) 5 Grüße aus Augsburg, 30. 9. 1998
play all play one stop play next play all
{ NL}
Anton Baumann: ergänzen: +wBb4 so C+ Gustav 4.1d (2020-11-26)
A.Buchanan: Not in WinChloe. Have emailed Hans (2020-11-26)
A.Buchanan: Managed to find fix with no extra material - Hans is ok if I post mildly changed material here, see P1382844. (2020-12-10)
comment
Keywords: Allumwandlung, Superseded by (P1382844)
Genre: Fairies
Computer test: C- Popeye v4.85
FEN: 1Kn5/3k4/P3p1P1/4P3/8/4P3/pp2p3/1N6
Input: Hans Gruber, 2004-05-01
Last update: A.Buchanan, 2020-12-10 more...
67 - P1015966
Jan A. Rusek
3470 Themes-64 04-06/1979
2. Lob
Polnisches Championat 1977-1979
5. Platz
MP 1979 - 6. Platz
P1015966
(5+2) cooked
s#10
1. Lg3! Ke4 2. Lh2 Kd4 3. Lg1 Ke4 4. Sf6+ Kd4 5. Ke1 Kd3 6. Dg3 Kd4 7. Kd1 Kd3 8. Lf2 Kd4 9. Df4+ Kd3 10. Le1 e2#
play all play one stop play next play all
2. Lob ist richtig (vgl. geänderter Preisbericht Seite 1963)
Cook: DL 5. Kd1 Kd3 6. Dg6+ Kd4 7. Dg3 Kd3 8. Lf2 Kd4 9. Df4+ Kd3 10. Le1 e2#
Iwan Soroka: Korrektur: Tc1-c2. C+, Brute Force Gustav 4.0i.
Lösung: 1.Le1-g3 Kd4-e4 2.Lg3-h2 Ke4-d4 3.Lh2-g1 Kd4-e4 4.Sd5-f6 Ke4-d4 5.Ke2-d1 Kd4-d3 6.Dg5-g3 Kd3-d4 7.Tc2-c1 Kd4-d3 8.Lg1-f2 Kd3-d4 9.Dg3-f4 Kd4-d3 10.Lf2-e1 Be3-e2# (2021-10-14)
more ...
comment
Keywords: Round Trip (L), Minimal, Miniature
Genre: s#
FEN: 8/8/8/3N2Q1/3k4/4p3/4K3/2R1B3
Reprints: 1638 Problemista 163-165 01-02/1982
1855 Problemista 182-184 07-09/1983
1508 Selbstmatt-Miniaturen Reflexmatt-Miniaturen 2003
Input: Selbstmatt-Miniaturen/Reflexmatt-Miniaturen, 2004-05-01
Last update: Marcin Banaszek, 2021-10-14 more...
68 - P1020088
John Henderson
49 Canadian Chess Problems , p. 51, 1890
P1020088
(8+3) cooked
#2
1. Da7!
play all play one stop play next play all
Cook: 1. Sg6+
Henrik Juel: many cooks, like 1.Sg6+ (2024-02-21)
comment
Keywords: Brian Stephenson Collection (4928)
Genre: 2#
Computer test: Juel: NL
FEN: 1bBB3N/1K6/8/3pk3/5R2/2P5/3P4/Q7
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2024-02-21 more...
69 - P1020257
M.J. Murphy
70 Canadian Chess Problems , p. 72, 1890
P1020257
(7+8) cooked
#2
1. Dc4! droht 2. Dc6#
1. ... dxc4 2. d5#
play all play one stop play next play all
Cook: 1. Da6#
more ...
comment
Keywords: Brian Stephenson Collection (5100), Sacrifice key, Pawn mate
Genre: 2#
Computer test: SCHRECKE: 1 NL
FEN: 8/p1K1N2R/4k1p1/3p1p1b/3P1pqP/2B5/8/5Q2
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2024-03-04 more...
70 - P1020985
James Alfred John Smith
British Chess Federation 1931-1932
1. Preis
P1020985
(14+11) cooked
#3
1. Th2? Dxa8 2. Dxf4 Dxc6+!

1. Tg2! droht 2. Dxf4
1. ... Tgf7 2. Sa5
1. ... Tge7 2. Lxc5
1. ... Tgd7 2. Sd4
1. ... Tgc7 2. Sxc7
1. ... Tgb7 2. Sxb4
play all play one stop play next play all
Cook: 1. Tg2? Df8! 2. Dxf4 b3!
1. Lxc5!
SCHRECKE: !. Tg2!? scheitert an 1. ... Df8! 2. Dxf4 b3!
Dafür geht die NL: 1. Lxc5 Df8 2. Sxb4 Dxa8+ 3. Sd5,Sc6# (2023-02-03)
comment
Keywords: Brian Stephenson Collection (5835), Sperrwechsel (fünffach)
Genre: 3#
Computer test: SCHRECKE: popeye 4.87
FEN: N5q1/r5rp/RPNBp3/2p1PPQ1/ppp2pP1/k1P4P/3R4/3B3K
Reprints: 1039 Beispiele zur Ideengeschichte des Schachproblems , p. 214, 1982
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-02-03 more...
71 - P1021955
John Henderson
62 Canadian Chess Problems , p. 64, 1890
P1021955
(5+7) cooked
#3
1. Ta6! c3 2. Dc2
1. ... Lxg8 2. Txa3+
play all play one stop play next play all
Cook: 1. Lxf7 droht 2. Dc2
Henrik Juel: cook 1.Lxf7 thr. 2.Dc2 (2024-02-22)
comment
Keywords: Brian Stephenson Collection (6810)
Genre: 3#
Computer test: Juel: 1 NL
FEN: 6B1/5b2/7R/8/2p1p3/pp6/kb1Q4/5R1K
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2024-02-23 more...
72 - P1021989
M.J. Murphy
80 Canadian Chess Problems , p. 82, 1890
P1021989
(12+5) cooked
#3
1. Kh6! Kd4 2. Sxf5+
1. ... Kc6 2. Tg8+
play all play one stop play next play all
Cook: 1. Lf6
more ...
comment
Keywords: Brian Stephenson Collection (6844)
Genre: 3#
Computer test: SCHRECKE: 1 NL
FEN: 8/3pB3/p2N4/P2kPp1K/1p3P1P/1P1N4/2P3R1/7B
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2024-02-26 more...
73 - P1021991
M.J. Murphy
75 Canadian Chess Problems , p. 77, 1890
P1021991
(11+5) cooked
#3
1. Tc1! Kc5 2. Tg3
1. ... Kd7 2. e6+
play all play one stop play next play all
Cook: 1. Tf4+ 1. Lg2
Gerald Ettl: Verbesserungsvorschlag: +sBa6, +wBh2, +sBh3
1.Tc1!
1.-Kc5 2.Tb3 Kd4 3.Se6#
1.-Kd7 2.e6+
2.-Kd,c8 3.Tf8#
2.-Kc6 3.Tf5# (2024-02-26)
more ...
comment
Keywords: Brian Stephenson Collection (6846), Zugzwang-Goal
Genre: 3#
Computer test: Juel: 2 NL
FEN: 8/1pN5/1PkP2p1/p3P1Pp/P1N4K/5R2/2R5/7B
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2024-02-26 more...
74 - P1043631
Charles Planck
290 The Chess Problem: Text-Book with Illustrations , p. 235, 1887
P1043631
(6+7) cooked
#3
1. Sf5! Kxd5 2. Se3+ Kc6 3. Da4# 2. ... Ke5 3. Lf6#
1. ... exd5 2. Sg3 Ke6 3. De7# 2. ... d4 3. De4# 2. ... c4,Sc3 3. Df6#
1. ... exf5 2. c4
1. ... Sd2 2. Lf6+ Kxd5 3. Se7# 2. ... Kxf5 3. Dg5#
1. ... Sf3 2. Lf6+ Kxf5 3. Le4#
play all play one stop play next play all
Cook: 1. Lc6 d5 2. Kxb8 ... 3. Lc7#
more ...
comment
Keywords: Brian Stephenson Collection (28626), Flight giving sacrifice key (zweifach), Sacrifice of white pieces (L, S), Edge to edge (wD), Blocknutzung
Genre: 3#
Computer test: SCHRECKE: NL
FEN: Kb1B4/4N3/3pp3/2pBk3/7Q/8/2P5/1n4n1
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2024-01-15 more...
75 - P1043897
Philipp von Klett
75 Schachprobleme [Klett] 1878
P1043897
(7+10) cooked
#4
1. Ld5? Ld3! 2. Sxd3 Kxd5!
1. Ld2! droht 2. Ke7
1. ... Lxd2 2. Ld5 droht 3. Txg5+ Kf6 4. Se4#
2. ... Ld3 3. Sxd3+ Kxd5 4. Txd4#
2. ... dxe3 3. Txg5+ Kxf4 4. Sh3#
play all play one stop play next play all
Cook: NL 1. Txg5!
Sally: Nr. 75.
1. Ld5? scheitert an Ld3!, weil nach 2. Sxd3 - Kxd5! das Feld d4 gedeckt bleibt; darum erst die Weglenkung 1. Ld2! (droht 2. Ke7) - Lxd2 und dann 2. Ld5 (droht auch nach Bgxf4, 3. Txg5+, 4. Se4#. Modell KTLS/K+0). dieses doppelwendige Mustermatt hat Klett in mehreren Stücken bearbritet. Wenn 2. - Ld3, so 3. Sd3+ - Kxd5, 4. Txd4#; oder 2. - Bdxe3. 3. Txg5+ - Kxg4, 4. Dh3# Modell TLS/K+1.
Nr. 427 Ideengeschichte (Breuer 1982). (2011-12-06)
Sally: 4. Lösungen!
1. Ld2!? / 1. Txd5!? / 1. Lxa3!? / 1. Ld5!? (2016-10-10)
TBr: Peter Hoffmann bat mich, hier seine Korrekturversion (C+) anzugeben:
Kd8 Db1 Tf4 Tg6 Lc1 Lf3 Sf2 Bd7 Be2 Be3
Ke5 Tb2 Tc2 Lc3 Lc4 Ba5 Bd4 Bg5 Bh4 Bh5 #4 (10+10)
(FEN: 3K4/3P4/6R1/p3k1pp/2bp1R1p/2b1PB2/1rr1PN2/1QB5)
1.Ld2! (2021-07-25)
comment
Keywords: Brian Stephenson Collection (28893), Model mate
Genre: n#
FEN: 3K4/8/6R1/p3k1pp/2bp1R1p/n1b1P3/2p2N2/2B4B
Reprints: 427 Beispiele zur Ideengeschichte des Schachproblems 1982
Input: Brian Stephenson, 2004-08-12
Last update: Alfred Pfeiffer, 2017-07-06 more...
76 - P1045871
Norman Littlewood
8880 British Chess Magazine 10/1954
P1045871
(7+10) cooked
#3
1. Dg7! droht 2. Dc7+ 1. ... droht 2. f7+
1. ... Tb6 2. f7+ Tf6 3. f4#
1. ... Tf5 2. Dc7+ Ke4 3. f3#
1. ... Sg3 2. f7+ Kf4 3. fxg3#
1. ... Se3 2. f7+ Kf4 3. fxe3#
play all play one stop play next play all
Cook: 1. Dh5+
more ...
comment
Keywords: Brian Stephenson Collection (30883), pin-mate (vierfach), Doppeldrohung, Albino
Genre: 3#
Computer test: Juel; Popeye 4.61
FEN: 7K/1p5B/4pP1Q/2Bpk3/2p5/3p1r2/1r3P2/3n1R1n
Reprints: 1389 Beispiele zur Ideengeschichte des Schachproblems , p. 279, 1982
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-03-16 more...
77 - P1050336
Vincente Maria Norberto Portilla

P1050336
(4+5) cooked
#2
1. Lg8! droht 2. Txc6#
1. ... Kxc5 2. Dxe5#
1. ... Lxc5 2. Dd8#
play all play one stop play next play all
BS Problemid: 35370
Authors: Portilla, Vincente Maria Norberto
Sources: Chess Problems by V. M. N. Portilla 1873
Years: 0000
Cook: 1. Txc6+ Kd5 2. Dd7#
SCHRECKE: 1. Lg8! droht 2. Txc6#
1. ... Kxc5 2. Dxe5#
1. ... Lxc5 2. Dd8#
Nebenlösung: 1. Txc6+ Kd5 2. Dd7# (2023-01-30)
comment
Keywords: Brian Stephenson Collection (35370)
Genre: 2#
FEN: 4Q3/7B/K1pk4/2R1p3/1p6/8/8/6b1
Reprints: 94 Chess Problems [Portilla] 1873
Input: Brian Stephenson, 2004-08-12
Last update: Mario Richter, 2023-01-30 more...
78 - P1052324
Philipp von Klett
73 Schachprobleme [Klett] 1878
P1052324
(10+11) cooked
#4
1. La8! droht 2. Dxb4#
1. ... Lb8 2. Lg1 Kc5 3. Dd4+ Kxd4 4. f4# 2. ... Kc7 3. Sf7 Tc8 4. Dc4# 2. ... Kxe5 3. Lh2+ Kf5 4. Le4#
1. ... Txa8 2. Dxb4+ Kd5 3. Dd2+ Kc5 4. b4# 3. ... Ke4 4. Dd3#
1. ... Kc5 2. Dc4+ Kd6 3. Dxb4#
play all play one stop play next play all
Cook: 1. Ld3 1. Lh1
more ...
comment
Keywords: Brian Stephenson Collection (37366), Sacrifice key, Drag-in sacrifice, discovered checkmate, Pawn mate
Genre: n#
Computer test: H. Juel
FEN: 3r1n2/2bp2p1/1p1kp1Pp/4N2p/Pp2B2Q/7P/1P3P1B/K7
Reprints: 25 Classic Chess Problems by Pioneer Composers , p. 18, 1970
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-12-04 more...
79 - P1053393
Hans Lepuschütz
Wiener Schach-Zeitung 1936
P1053393
(5+9) cooked
#4
1. Td8? Td1! 1. Ta8? Le1!

1. Tg8! Tg1 2. Ta8 Le1 3. Td8 Lg3 4. Td5#
1. ... Lh4 2. Tf8 Sg3 3. Ta8 ... 4. Ta5#
1. ... Le3 2. Ta8 Ld2 3. Td8 Lf4 4. Td5#
play all play one stop play next play all
Cook: 1. Le5
SCHRECKE: NL: 1. Le5 droht 2. Sd4+,Sa7+ (2022-08-15)
milan: wTc8-b8 M.Frelih (2022-10-29)
comment
Keywords: Brian Stephenson Collection (38436)
Genre: n#
FEN: 2R5/1KB5/1NN5/2k3p1/8/1p3p2/2p2b2/n1r4n
Reprints: 139 Problem-Palette , p. 51, 1970
FIDE Album 1914-1944/II 1972
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2022-08-15 more...
80 - P1053917
Carl Eckhardt
Hamburgischer Correspondent 1927
P1053917
(12+10) cooked
#4
1. Lf2! b6 2. e3 Kc5 3. Taxc7,Texc7+ Sxc7 4. Txc7#
1. ... Sb6 2. Lxb6 cxb6 3. e3 Kc5 4. Tc7#
play all play one stop play next play all
Anti-Cheney-Loyd-Thema
Henrik Juel: cooked, also 1.Le3,e3,Kh1,Kg2,Kf1,Kf2,Kh2 (2022-02-15)
milan: [wKg1-h1+sBf2] 1.L×f2! M.Frelih (2022-03-05)
Anton Baumann: +sBf2 ist keine gute Idee: illegale Stellung und schrecklicher Schlüssel! (2022-03-07)
milan: i agree with your observation i have not seen better solutions?
+wSa1 sBg7-e5 sBg5-f4 wBg4-g3 -sLh6 wBg6 Lf2! M.Frelih (2022-03-07)
milan: wBg4-f3 is correct M.Frelih (2022-03-08)
comment
Keywords: Brian Stephenson Collection (38963), Cheney-Loyd (Anti-Kritikus)
Genre: n#
FEN: n1N5/Rpp1R1p1/2k2pPb/1p3Pp1/1p1BP1P1/1P6/1P2P3/6K1
Reprints: Problemschach [Sidler] , p. 22, 1968
71 Encyclopedia of Chess Problems , p. 30, 2012
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2022-02-15 more...
81 - P1054813
Benjamin S. Wash
? 1885
P1054813
(6+8) cooked
#4
1. Lb5! Tbxb5 2. Se4+ Lxe4 3. d4+ cxd3ep 4. Dc1#
1. ... Ta6 2. Dxa6
play all play one stop play next play all
Cook: 1. De6 Tb7 2. Ld7 Ta6 3. Sa4+ 3. Dxe7+
more ...
comment
Keywords: Brian Stephenson Collection (39862), Sacrifice key, En passant (s)
Genre: n#
Computer test: SCHRECKE
FEN: 4B3/n3p3/7Q/r1kNK3/2p5/2Nb4/1r1P4/5n2
Reprints: 38 Spectacular Chess Problems , p. 23, 1965
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-12-05 more...
82 - P1055241
Samuel Loyd
4 Syracuse Standard 11/09/1858
P1055241
(6+4) cooked
#3
1. Kd2+! g1=D,g1=T 2. Tf1 Dxf1,Txf1 3. Dxf1#
1. ... g1=S 2. Ld1 2. ... Sxf3+ 3. Lxf3#
2. ... Se2 3. Lxe2#
1. ... g1=L 2. Ke1 Lxf2+ 3. Kxf2#
play all play one stop play next play all
Cook: 1. Ke2+! g1=D,g1=T 2. Tf1 Dxf1+ 3. Dxf1#
1. ... g1=S+ 2. Kf1 Sxf3 3. Dxf3#
2. ... Se2 3. Kxe2#
1. ... g1=L 2. Kf1,Ke1 Lxf2,Lxf2+ 3. Kxf2#
A.C. White: "His unsound 3-er, No. 622, is very important historically, in that it was the first attempt ever made to combine three promotion variations from a single Black Pawn. Last year, J. Möller quite independently arrived at a similar version, entirely sound and very beautiful [P1246525]. The only difference was that he placed the Rook at c1, the Queen at d4, and a Knight at f4 instead of the Bishop. His solution is 1. Qd3, involving the same principles as Loyd's did. I mention this to show how near Loyd's genius led him to the ultimate rendering which another discovered fifty-four years later. But Loyd was, for once, too impetuous: " That problem should be killed. It is not in 'Strategy', nor in my collection. I revised it in that little corner problem which gives all the good there is in it [s. P1059071]" (L. 1909). This must remain one of the instances where I disagree with Loyd. His monogram, No. 623 [P1059071], is ingenious enough, but it lacks the complete task feature which made No. 622 a remarkable conception for a youth of seventeen to chance on."
Henrik Juel: cooked 1.Kd2,Ke2+ (2022-03-01)
milan: [wPf3e4=bP +wPe3bPd3 1.Kd2! black AUW M.Frelih (2023-03-30)
comment
Keywords: Brian Stephenson Collection (40292)
Genre: 3#
FEN: 8/8/8/8/4P3/1B3P1p/5Qpp/R3K2k
Reprints: 4 The Leader 03/07/1869
622 Sam Loyd and his Chess Problems , p. 404, 1913
Input: Brian Stephenson, 2004-08-12
Last update: Rainer Staudte, 2023-08-19 more...
83 - P1055334
Leopold Szwedowski
Magyar Sakkszövetseg 1983
Ferenc Fleck 75 JT
1. Preis
P1055334
(9+14) cooked
#3
1. e4-e5? droht 2. Td3-c3#
1. ... Df8-b4 2. Sc8-d6+ Db4xd6 3. Td3-c3#
1. ... Tb7-b3,Tb4 2. Sc8-b6+ Tb3xb6 3. Td3-c3#
1. ... Lg8-h7!

1. Dh4-f6! droht 2. Td3-c3+ d4xc3 3. Df6xc3#
1. ... Df8-b4 2. Sd7-e5+ Kc4-c5 3. Df6-d6#
1. ... Tb7-b3,Tb4 2. Lc6-d5+ Kc4-b5 3. Df6-b6#
play all play one stop play next play all
Cook: NL 1. Dh4-e1! Tb7-b3 2. Lc6-d5+ Kc4-b5 3. Sc8-a7#
milan: bLg1-e3 1.Df6! M.Frelih (2023-12-01)
Nightrider: Just -bPa6 is C+. (2023-12-02)
comment
Keywords: Brian Stephenson Collection (40385)
Genre: 3#
FEN: 2N2qb1/1r1N1pn1/p1B5/B7/p1kpP2Q/p2R4/rp2P3/nK4b1
Reprints: 2160 Problemista 198-200 10-12/1984
III Szachy 07/1985
Input: Brian Stephenson, 2004-08-12
Last update: Rainer Staudte, 2022-10-07 more...
84 - P1058713
Otto B. Wurzburg
Pittsburgh Post 1926
P1058713
(9+6) cooked
s#3
1. Dd4! Zugzwang
1. ... Sc3,Sc5,Sg5 2. Txh2+ Kxh2+ 3. Sf1+ Txf1#
1. ... Sxd2 2. Tf1+ Kxf1 3. Df2+ Kxf2#
1. ... Sxf2 2. Sf1 Kxf1 3. Dxf2+ Kxf2#
1. ... Sxg3 2. Sf3+ gxf3 3. Dg7 Kxf2#
1. ... Sf6 2. Txh2+ Kxh2+ 3. Sf1+ Txf1#
Dual: 2. Sf3+ gxf3 3. Dxf6 Kxf2#
1. ... Sd6 2. Txh2+ Kxh2+ 3. Sf1+ Txf1#
Dual: 2. Sf3+ gxf3 3. Dxd6 Kxf2#
play all play one stop play next play all
Cook: Duale
SCHRECKE: 1.Dd4! (Zugzwang)
1. ... Sc3,Sc5,Sg5 2.T:h2+ K:h2+ 3.Sf1+ T:f1#
1. ... S:d2 2.Tf1+ K:f1 3.Df2+ K:f2#
1. ... S:f2 2.Sf1 K:f1 3.D:f2+ K:f2#
1. ... S:g3 2.Sf3+ g:f3 3.Dg7 K:f2#
1. ... Sf6 2.T:h2+ K:h2+ 3.Sf1+ T:f1#
Dual: 2.Sf3+ g:f3 3.D:f6 K:f2#
1. ... Sd6 2.T:h2+ K:h2+ 3.Sf1+ T:f1#
Dual: 2.Sf3+ g:f3 3.D:d6 K:f2# (2021-03-05)
comment
Keywords: Brian Stephenson Collection (43776)
Genre: s#
FEN: 8/8/8/8/2P1nNp1/p2PQ1P1/P2N1R1p/K5kr
Reprints: The Problemist 2002
Input: Brian Stephenson, 2004-08-12
Last update: Marcin Banaszek, 2021-03-07 more...
85 - P1060586
Julius Buchwald
British Chess Federation 1941-1942
1. Preis
P1060586
(10+9) cooked
#3
1. Ld2! droht 2. Dc5
1. ... Le7 2. Dd6
1. ... Txf7 2. Df6
1. ... Lxf7 2. Df2
play all play one stop play next play all
Cook: 1. Lf2
more ...
comment
Keywords: Brian Stephenson Collection (45665), Grimshaw (s-w)
Genre: 3#
Computer test: Juel: Popeye 4.61
FEN: 1K2N3/1P1B1P1p/1Q4b1/3pp3/4k3/b1PN4/4P1n1/4Br1r
Reprints: 1159 Beispiele zur Ideengeschichte des Schachproblems , p. 235, 1982
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-02-16 more...
86 - P1066823
Tomislav Petrovic
The Ural's Problemist 04-06/2004
2. Thematurnier
4. ehrende Erwähnung
P1066823
(10+4) cooked
s#6
1. hxg6ep Kh5 2. Dg4+ Kh6 3. Dh5+ Kxh5 4. g4+ Kh6 5. f4 fxe6+ 6. dxe6 hxg6#
play all play one stop play next play all
Cook: Retro logic doesn’t work
(As well as major dual)
So unsound
SCHRECKE: Konnte zuletzt nicht auch 0. ... Kg7-h6 geschehen sein? (2021-02-15)
A.Buchanan: I think the diagram must be wrong. Not only does the retro logic fail, but also there is a dual 2. Df3+,Dg4+. It's not in WinChloe. (2021-02-15)
Mario Richter: An additional white Pawn e7 would justify the epkey, but not prevent the mentioned dual. (2021-02-16)
VL: We might shift wPf2 to f3 against the dual. Or exchange Bf6 with Pf2 and add wP on f3 (instead of e7)... (2021-02-16)
A.Buchanan: Shifting wBf2 to f3 leads to short cook solutions 1.Dh2. However I think 8/5p1p/4NB1k/3PPKpP/4P3/8/5PP1/2Q5 fixes the retro issue, and it's C+ by Popeye, with still ideal mate! The composer Tomislav Petrovic is still alive but would be very old (90). Is he still active? (2021-02-17)
A.Buchanan: By the way, if you query for k='foo', that will always return uses of the keyword "foobar". It's just checking for the prefix. If you omit k='foo', then that will also block "foobar". Therefore if we tag with "en passant as key", then we should not tag with "en passant" too. Both keywords should exist, and over time we may refine uses of "en passant" to be more precise.
Because of the sensible way prefixes are handled in PDB, this is a different situation from tagging a problem as both "ceriani-frolkin" and "prentos", which we should do.
On this general subject, when counting instances within a single problem, we should always use Gerd's excellent mechanism of parameters "foo:1" etc, rather than having separate keywords "foo 1", "foo 2" etc. Otherwise the set of keywords becomes unmanageable. (2021-02-17)
more ...
comment
Keywords: En passant as key, Ideal mate, Superseded by (P1386589)
Genre: Retro, s#
FEN: 8/5p1p/4PB1k/3PPKpP/4PQ2/8/5PP1/8
Input: Frank Müller, 2004-11-01
Last update: A.Buchanan, 2021-02-18 more...
87 - P1079398
Boris G. Maslow
4038 The Ural's Problemist 2006
P1079398
(3+9) cooked
h#3
3.1...
NL:
1. f1=D Ta6 2. Lg1 Tg2+ 3. Kc1 Ta1#
1. Sf4 Ta6 2. f1=S Tg2+ 3. Kc1 Ta1#
1. f1=L Ta6 2. Lg1 Tg2+ 3. Kd1 Ta1#
1. Lxg5+ Kxg5 2. Ke3 Txd6 3. Ke4 Te6#
play all play one stop play next play all
klären Stellung (Druckfehler), Lösung
Yuri Bilokin: correction +bPa2, +bPh2 8/8/2Rp3K/3n2R1/3p4/3pbb2/p2k1p1p/4n3 (3+11) h#3 3.1…

1.Sg2 Rb6 2.Sgf4 Rg1 3.Sc3 Rb2# (MM)
1.Sf4 Rxd6 2.Kc3 Rb6 3.Bd2 Rc5# (MM)
1.Bxg5+ Kxg5 2.Ke3 Rxd6 3.Ke4 Re6# (MM)

Active sacrifice (black). Anticipatory unpin
AntiZielElement (B1, line obstruction).Bi-valve (bS-wR-bB) × 2. Helledie theme
Hesitation (wR). Kniest theme (white). Many-ways (wR, 2). Wigwag (wR)
Model mate × 3 (2023-05-02)
comment

Genre: h#
FEN: 8/8/2Rp3K/3n2R1/3p4/3pbb2/3k1p2/4n3
Input: hpr, 2008-10-23
Last update: hpr, 2008-10-23 more...
88 - P1079447
Alexandr I. Shuk
4214 The Ural's Problemist 2006
P1079447
(4+5) cooked
h#3
2.1...
1) 1. Kc4 Lxc6 2. Kd3 Lf3 3. Tc4 0-0-0#
2) 1. c5 Ld5 2. cxb4 La2 3. Ka4 Lc4#

NL:
1. Kxb4 Lxc6 2. Kb3 Tb1+ 3. Kc2 Le4#
1. c5 bxc5 2. Kc4 Ta4+ 3. Kd3 Le4#
play all play one stop play next play all
klären NL
Yuri Bilokin: correction Yuri Bilokin & Alexandr I. Shuk bRc7-h5, bPc6-f5, +bBg8, +bNc6, +bPg6
4B1b1/8/2n3p1/1k3p1r/1P6/2p1p3/8/R3K3 (4+8) h#3 3.1…

1.Bb3 Rd1 2.Ka4 Rd7 3.Sxb4 Ra7# (MM)
1.Rh4 Bf7 2.Rxb4 Ba2 3.Ka4 Bc4# (MM)
1.Kc4 Bxc6 2.Kd3 Bf3 3.Bc4 0-0-0#

AntiZielElement (W2, indirect guard). Bi-valve (wB-wR-bB)
Castling (white, long). Hesitation (wB).Long-trip (wB, 3). Long-trip (wR, 3)
Reciprocal batteries
Model mate × 2. Battery mate × 3. Royal battery mate. Double-check mate (2024-03-09)
A.Buchanan: Possible to remove another piece in the correction: -bPg6, shift bBg8 to f7
4B3/5b2/2n5/1k3p1r/1P6/2p1p3/8/R3K3 (2024-03-10)
Yuri Bilokin: Thank you. Due to the taking of a black figure, this version was not taken into account. (2024-03-10)
more ...
comment

Genre: h#
FEN: B7/2r5/2p5/1k6/1P6/2p1p3/8/R3K3
Input: hpr, 2008-10-24
Last update: A.Buchanan, 2024-03-10 more...
89 - P1081392
Jan A. Rusek
225 Zadaniowiec 5 07-12/1956
dedicated to Marian Wróbel 50
1. Preis
P1081392
(12+4) cooked
s#8
1. Td4! Sxf7 2. Dc6+ Sd6 3. Lg5 h4 4. Ka6 h3 5. Ta7 h2 6. f5+ Ke5 7. Td5+ Ke4 8. Ta5+ Txc6#
1. ... Sg6 2. f8=S+ Sxf8 3. Dc8+ Sd7 4. Lg5 h4 5. a5 h3 6. a6 h2 7. f5+ Ke5 8. Dc7+ Txc7#
play all play one stop play next play all
3. Polnisches Championat 1. Platz
Cook: 1. Txh8 Kd6 2. Le7+ Ke6 3. f8=D h4 4. Lb4 h3 5. De4+ Kd7 6. Td8+ Kc7 7. Dc5+ Txc5 8. La5+ Txa5# oder
2. f8=D Ke6 3. Dff7+ Kd6 4. Db6+ Tc6 5. Db4+ Tc5 6. Sf5+ Kc6 7. De8+ Kc7 8. Da5+ Txa5#
Marcin Banaszek: Mit dem wTd7 statt d8 ist die Aufgabe korrekt, beinhaltet nur die Autorlösung (C+ Gustav 4.1c) (2021-10-25)
more ...
comment
Keywords: Chameleon Echo, Epaulettenmatt
Genre: s#
FEN: R2R3n/KQ3P2/4k2N/7p/P1r2P1B/2P5/B3P3/8
Reprints: Szachy 09/1959
437 FIDE Album 1956-1958 1961
2402 Problemista 210-212 10-12/1985
4923 Problemista 01-03/1997
5474 Problemista 04-06/1998
Input: HBae, 2009-02-06
Last update: Marcin Banaszek, 2022-04-25 more...
90 - P1081499
Jan A. Rusek
7910 Die Schwalbe 09-10/1950
1. Preis
Schwalbe-Ringturnier
2. Halbjahr 1950
P1081499
(9+4) cooked
s#9
1. Lf1! h2 2. Db1+ Sb4 3. Tb8+ Kc6 4. De4+ Sd5 5. Dc2+ Sc3 6. Tb6+ Kd5 7. Dg2+ Se4 8. Se7+ Ke5 9. Dxh2+ Sg3#
play all play one stop play next play all
Cook: 1. Lxc6+ Ka6 2. De2+ Ka5 3. Td5+ Kb4 4. Db2+ Kc4 5. Lb5+ Kxd5 6. Da2+ Ke4 7. Sd6+ Kf3 8. De2+ Kg3+ 9. Dg2+ Lxg2,hxg2#
Korrekte Version: Lb5>f1 & Sg6>e5 (Gustav 4.1c C+)
SBD: Cooked, 1. Bxc6+ also leads to a position in which hxg2/Bxg2 mate will be forced, dualized.

Best solution seems to be Bb5-f1, Sg6-e5. Then 1. Sg6! is the key. Not tested with a brute force mode, though.

An excellent problem that deserves to be rescued. (2009-04-11)
Marcin Banaszek: Die Version mit wLb5 auf g1 und wSg6 auf e5 ist korrekt (Gustav 4.1c C+) (2023-12-04)
comment

Genre: s#
FEN: b2RN3/Pk6/2n1P1N1/1B6/4Q3/7p/8/6BK
Reprints: 1067 Szachy 11/1952
1255 FIDE Album 1945-1955 1964
2743 Problemista 225-227 01-03/1987
214 Polskie samomaty 1991
Input: HBae, 2009-02-06
Last update: Marcin Banaszek, 2023-12-04 more...
91 - P1081611
Hans Peter Rehm
S1028v The Problemist 05/1985
1. Preis
P1081611
(6+8) cooked
s#8
1. Lc7? droht 2. Db5+ Sxb5#
1. ... d3 2. Le5 c2!

1. De7+! Kc6 2. Ld7+ Kd5 3. De6+ Kc5 4. Lc7 Sd2 5. De7+ Kd5 6. Le6+ Kc6 7. Dd7+ Kc5 8. Db5+ Sxb5#
play all play one stop play next play all
FA=8 logisch, Platzwechsel

Original (ohne sBa7) mit NL in 6 Zügen.
Korrektur des Autors (+sBa7) in 11/1985, Seite 106.
Cook: NL 1. Lf6! droht 2. Db5+ Kd6 3. Dd5+ Kc7 4. Le5+ Kb6 5. Db7+ Kc5 6. Db5+ Sxb5#
1. ... Kb6? 2. Db7+ Kc5 3. Le5 ... 4. Db5+ Sxb5#
Rolf Wiehagen: Valery Kirillov points out that the problem can be corrected by wBd8--a5, C+. (2020-10-01)
Gerald Ettl: In meiner Datenbank steht als Verbesserung sBa7 nach g7. Allerdings weiss ich nicht, ob das C+ ist. (2020-10-02)
Rolf Wiehagen: Valery Kirillov points out that bPa7 to g7 is cooked, in 7 moves:
1.De7+ Kc6 2.Ld7+ Kd5 3.De6+ Kc5 4.Lc7 Sd2 5.Db6+ Kd5 6.Db7+ Kc5 7.Db5+ Sxb5# (2020-10-26)
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comment
Keywords: Interchange (DL)
Genre: s#
FEN: 3B4/p2Q4/P3B3/2k5/K2pp3/nPp5/8/rn6
Reprints: 595 FIDE Album 1983-1985 1992
Input: HBae, 2009-02-06
Last update: Marcin Banaszek, 2023-11-03 more...
92 - P1081662
Giulio Cesare Polerio
source? 1590
P1081662
(7+2) cooked
s#6
1. Kc3 Lg7 2. Dg8 Lf8 3. Dh8+ Lg7 4. Kb2 Lxh8 5. Ka1 Lg7 6. Tf7+ Kxf7#
2. ... Lh8 3. Kb2 Lg7 4. Dh8 Lxh8 5. Ka1 usw.
play all play one stop play next play all
Quelle: Manuskript Polerio, 1590
Inkorrekt, weil auch 1. Dg8 geht.
Rainer Staudte: Originalquelle vermutlich: 'L'Elegantia, sottilità, verità della vi' (2013-04-28)
milan: wKb4-d3 1.Kc3! M.Frelih (2023-09-01)
more ...
comment
Keywords: Fluchtfeld-Task
Genre: s#
FEN: Q6b/R7/5k2/3P4/1K3P2/8/P7/1B6
Reprints: 148 Traite analytique du Probleme d'Echecs 1892
74 Beispiele zur Ideengeschichte des Schachproblems 1982
Die Schwalbe , p. 388, 02/2012
Input: HBae, 2009-02-06
Last update: Frank Müller, 2018-04-07 more...
93 - P1083495
Henrik Juel
Kevin James Begley

The Problemist 2006
P1083495
(4+9) cooked
ser-=20
Platzwechselcirce
1. Se5 2. Sf7 3. Sh8 4. Sxg6[+sBh8] 5. Sf8 6. Sxe6[+sBf8] 7. Sd8 8. Sxc6[+sBd8] 9. Sb8 10. Sxa6[+sBb8] 11. Sc7 12. Sa8 13. Sxb6[+sBa8] 14. Sc8 15. Sxd6[+sBc8] 16. Se8 17. Sxf6[+sBe8] 18. Sg8 19. Sxh6[+sBg8] 20. Sg4 =
play all play one stop play next play all
Cook: 1.Se3 2.g4 3.g5 4.gxf6[+bPg5] 5.f7 6.f8=B!! 7.Kf2 8.Sg4 9.S:h6[+bPg4] 10.B:d6[+bPf8] 11.Bg3 12.Sf7 13.Sd8 14.S:e6[+bPd8] 14.Sc5 15.S:a6[+bPc5] 16.Sc7 17.Sa8 18.S:b6[+bPa8] 19.Sc4 =
Pawns reborn on their 1st rank have no legal move in this condition (unlike Circe-Parrain).
Henrik Juel: I am not a co-author of this problem, which appeared in The Problemist under Kevin's name only
In the solution section there was no mention of a cook (2021-05-17)
Henrik Juel: Kevin has pointed out a memory lapse on my part
He found a cooked problem by me from 1993 with the same idea and suggested that his 2006 problem should include me as co-author, which I accepted (2022-03-31)
Anton Baumann: "cooked" ist zu entfernen! Was soll denn hier cooked sein? (2022-04-06)
Henrik Juel: I believe that Kevin has found a cook (2022-04-06)
Kevin Begley: Norbert Geissler found this impressive cook (which Popeye does not find).
We have long known of a simple correction (I believe it's fully sound starting with wSf7, as ser-=18, but the circuit would be lost). I had hoped to reveal details of the cook (and the solver) in the publication of a correction, but time slipped away, then I stopped composing for some years. Truth be told, prospects to fully restore the intent were never likely. (2022-04-10)
more ...
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Keywords: Circe (Platzwechsel-), Pure Round Trip, Ornament, Seriesmover
Genre: Fairies
FEN: 8/8/pppppppp/8/6N1/5KPk/8/6P1
Input: Kevin Begley, 2009-03-04
Last update: Kevin Begley, 2022-04-10 more...
94 - P1095545
Yaakov Mintz
1635 U.S. Problem Bulletin 07-08/1988
G. P. Sphicas gewidmet
Spezialpreis
P1095545
(14+2) cooked
s#85
1. Tc4+ Kd5 2. Se3+ Kd6 3. Db8+ Dc7 4. Tc6+ Kxc6 5. La4+ Kc5 6. Db5+ Kd4 7. Dd5+ Kc3 8. Db3+ Kd2 9. Dd1+ Kc3 10. Dc2+ Kd4 11. Dd2+ Kc5 12. Dc3+ Kd6 13. Db4+ Dc5 14. Db8+ Dc7 15. Ke8 Kc5 16. Db5+ Kd4 17. Dd5+ Kc3 18. Db3+ Kd2 19. Dd1+ Kc3 20. Dc2+ Kd4 21. Dd2+ Kc5 22. Dc3+ Kd6 23. Db4+ Dc5 24. Db8+ Dc7 25. Lh2 Kc5 26. Db5+ Kd4 27. Dd5+ Kc3 28. Db3+ Kd2 29. Dd1+ Kc3 30. Dc2+ Kd4 31. Dd2+ Kc5 32. Dc3+ Kd6 33. Db4+ Dc5 34. Db8+ Dc7 35. Lg3 Kc5 36. Db5+ Kd4 37. Dd5+ Kc3 38. Db3+ Kd2 39. Dd1+ Kc3 40. Dc2+ Kd4 41. Dd2+ Kc5 42. Dc3+ Kd6 43. Db4+ Dc5 44. Db8+ Dc7 45. Lh4 Kc5 46. Db5+ Kd4 47. Dd5+ Kc3 48. Db3+ Kd2 49. Dd1+ Kc3 50. Dc2+ Kd4 51. Dd2+ Kc5 52. Dc3+ Kd6 53. Db4+ Dc5 54. Db8+ Dc7 55. Lg5 Kc5 56. Db5+ Kd4 57. Dd5+ Kc3 58. Db3+ Kd2 59. Dd1+ Kc3 60. Dc2+ Kd4 61. Dd2+ Kc5 62. Dc3+ Kd6 63. Db4+ Dc5 64. Db8+ Dc7 65. Lh6 Kc5 66. Db5+ Kd4 67. Dd5+ Kc3 68. Db3+ Kd2 69. Dd1+ Kc3 70. Dc2+ Kd4 71. Dd2+ Kc5 72. Dc3+ Kd6 73. Db4+ Dc5 74. Db8+ Dc7 75. Td7+ Kc5 76. Lf8+ Dd6 77. Tc7+ Kd4 78. Db2+ Kd3 79. Tc3+ Kd4 80. Tb3+ Kc5 81. Tb5+ Kc6 82. Te5+ Kc7 83. Sd5+ Dxd5 84. Db6+ Kc8 85. Ld7+ Dxd7#
play all play one stop play next play all
Cook: Nebenlösung in 20 Zügen:
1. Tc4+ Kd5 2. Le4+ Kd6 3. Db8+ Dc7 4. Td4+ Kc5 5. Td5+ Kc4! 6. Se3 Kc3 7. Sd1+ Kc4 8. Sb2+ Kc3 9. Td3+ Kc2 10. Td1+ Kc3 11. Sa4+ Kc4 12. Tc1+ Kd4 13. Db2+ Dc3 14. Td1+ Kc4 15. Sb6+ Kc5 16. Td5+ Kc6 17. Te5+ Kd6 18. Sc4+ dxc4 19. Db8+ Dc7 20. Ke8 Dxb8#
YM: "U.S. Problem bulletin" cloused more than ten years ago...
The correction w'be: wDc8=wBb7, wTc7=wTc4; sKd4=sKd5 and S#84: 1. Se3 Kd6 2. b8=D Dc7 3.Tc6 Dxc6 etc. (2010-04-20)
Olaf Jenkner: The correction does not work:
1. Se3+ Kd6 2. b8D+ Dc7 3. Td7+ Kxd7 4. La4+ Kd6 5. Tc6+ Kd7 6. Tb6+ Dc6 7. Kg8 Dxa4 8. Tb7+ Kc6 9. Tc7+ Kd6 10. Tc4+ Kd7 11. Dc8+ Kd6 12. Dc5+ Kd7 13. Dd5+ Ke8 14. Te4+ Dxe4 15. f7+ Ke7 16. f6+ Kxf6 17. f8D+ Kg6 18. Dff7+ Kh6 19. Df6+ Dg6+ 20. Dg7+ Dxg7#
7... Db5 8. f7 Dc6 9. Kh7 Ke7 10. f8D+ Kd7 11. Db4 Dxa4 12. Td6+ Ke7 13. Dd8+ Kf7 14. Td7+ Dxd7 15. Dg8+ Kf6+ 16. Dg7+ Dxg7#
11... Db5 12. Td6+ Ke7 13. Dd8+ Kf7 14. Td7+ Dxd7 15. Dg8+ Kf6+ 16. Dg7+ Dxg7#
9... Dxa4 10. Db7+ Kd8 11. f8D+ De8 12. Dc6 Dxf8 13. Tb8+ Ke7 14. Dc7+ Kf6 15. Dg7+ Dxg7#
9... Db5 10. Db7+ Kd8 11. f8D+ De8 12. Dc6 Dxf8 13. Tb8+ Ke7 14. Dc7+ Kf6 15. Dg7+ Dxg7#
8... Dxa4 9. Dd6+ Kc8 10. f8D+ De8 11. Dc6+ Kd8 12. Kh7 Dxf8 13. Tb8+ Ke7 14. Dc7+ Kf6 15. Dg7+ Dxg7#
8... Ke7 9. f8D+ Kd7 10. Th6 Dxa4 11. Dfc8+ Ke7 12. Dbc7+ Dd7 13. Th7+ Kf6 14. Df8+ Df7+ 15. Kh8 Dxf8#
10... Dc6 11. Dfc8+ Ke7 12. Da7+ Db7 13. Th7+ Kd6 14. Df8+ De7 15. Kh8 Dxf8#
13... Kf6 14. Df8+ Df7+ 15. Kh8 Dxf8#
12... Dc7 13. Th7+ Kd6 14. Df8+ De7 15. Kh8 Dxf8#
13... Kf6 14. Df8+ Df7+ 15. Kh8 Dxf8#
12... Dd7 13. Th7+ Kd6 14. Df8+ De7 15. Kh8 Dxf8#
13... Kf6 14. Df8+ Df7+ 15. Kh8 Dxf8#
4... Dc6 5. Kg8 Dxa4 6. Dc8+ Kd6 7. Dc5+ Kd7 8. Dd5+ Ke8 9. Te4+ Dxe4 10. f7+ Ke7 11. f6+ Kxf6 12. f8D+ Kg6 13. Dff7+ Kh6 14. Df6+ Dg6+ 15. Dg7+ Dxg7#
5... Db5 6. f7 Dxa4 7. De8+ Kd6 8. De5+ Kd7 9. De6+ Kd8 10. f8D+ De8 11. Db6+ Kd7 12. Tc7+ Kd8 13. Th7+ Kc8 14. Db7+ Kd8 15. Kh8 Dxf8#
6... Dc6 7. f8D Db5 8. Dc5 Dxa4 9. Dcc8+ Ke7 10. f6+ Kxf6 11. Sd5+ Kg6 12. De6+ Kh5 13. Dh3+ Kg6 14. De8+ Dxe8#
8... Dc6 9. Kh7 Dxa4 10. Dd4+ Ke7 11. Tc7+ Dd7 12. Dg8 Dxc7 13. De6+ Kf8+ 14. Dg7+ Dxg7# (2010-04-23)
YM: Maybe S#83, if wDc8=WBb7, wTc7=wTc2, wLc2=wLd1 &
sKd4=sKd6: 1. b8=D Dc7 2. Tc6 Kxc6 3. La4 Kc5!
etc. like in solution of S#85. (2010-04-25)
YM: In S#83 also wSf1=wSe3. (2010-04-25)
Anton Baumann: vergl. P1101367 (2021-07-20)
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Keywords: Sea Snake, Tempo Winning Manouevre
Genre: s#
FEN: 2Q2K2/2Rq1R2/5P2/P4P2/3k1P2/P4P2/2B2P2/5NB1
Reprints: F23 Israeli Chess Problem Art 1932-2010 2011
Input: Frank Müller, 2009-12-05
Last update: Frank Müller, 2012-03-03 more...
95 - P1096030
Yuri Bilokin
SuperProblem (Website) 17/07/2009
P1096030
(2+3) cooked
h#5
1. Kb7 Tb5+ 2. Ka6 Tb7 3. Sb6 Kd2 4. Tb5 Kc3 5. Ka5 Ta7#

NL:
1. Sb6 Kd2 2. Tc7 Tc5 3. Kb7 Kc3 4. Ka6 Kb4 5. Tb7 Ta5#
play all play one stop play next play all
Yuri Bilokin: Correction: 3k4/4R3/1r6/8/n7/8/8/5K2 (2+3) 1.Kc8 Re8+ 2.Kb7 Ke2 3.Ka6 Kd3 4.Sc5+ Kc4 5.Sb7 Ra8# (IM) (2021-09-25)
comment

Genre: h#
Computer test: Popeye Windows-32Bit v4.51 (100000 KB)
FEN: 2k5/8/8/R1r5/2n5/8/8/4K3
Input: hpr, 2009-12-16
Last update: hpr, 2009-12-16 more...
96 - P1106542
Roberto Osorio
Jorge Joaquin Lois
Mario Richter

Quartz 32 07-12/2007
1. Preis
Raican-50-JT
P1106542
(15+12) cooked
BP in 27.0
1. Sf3 e5 2. Sh4 Lb4 3. f3 Lc3 4. bxc3 d5 5. La3 d4 6. Lc5 d3 7. Sa3 dxe2 8. Kxe2 Ld7 9. Kd3 b5 10. De2 b4 11. Kc4 Sc6 12. Kb5 e4 13. Ka6 e3 14. Db5 e2 15. Sc4 e1=L 16. Le2 Lg3 17. The1 Ld6 18. Lg1 Lf8 19. Lf1+ De7 20. Te6 Td8 21. Tae1 Sb8+ 22. Kxa7 g5 23. Ta6 g4 24. Tee6 g3 25. Tec6 Lc8 26. Se5 Td4 27. cxd4 Dd8
play all play one stop play next play all
Cook: 1. Sf3 Sc6 2. Sh4 Sd4 3. f3 Sxe2 4. Kxe2 b6 5. Kd3 Tb8 6. Kc4 Tb7 7. Kb5 g5 8. Ka6 b5 9. Ld3 Tb6+ 10. Kxa7 Tc6 11. Te1 Tc3 12. Te6 g4 13. Ta6 e5 14. bxc3 e4 15. La3 e3 16. Lc5 e2 17. Sa3 e1=S 18. Lf1 b4 19. De2+ De7 20. Db5 Sd3 21. Te1 g3 22. Tee6 Se5 23. Tec6 d5 24. Lg1 d4 25. cxd4 Sd7 26. Sc4 Sb8 27. Se5 Dd8
hans: . (2014-09-09)
Henrik Juel: A record in comment brevity... (2014-09-09)
Michel Caillaud: cooked using Jacobi 0.7.5 with constraints :
1.Sf3 Sc6 2.Sh4 Sd4 3.f3 Sxe2 4.Kxe2 b6 5.Kd3 Tb8 6.Kc4 Tb7 7.Kb5 g5 8.Ka6 b5 9.Ld3 Tb6+ 10.Kxa7 Tc6 11.Te1 Tc3 12.Te6 g4 13.Ta6 e5 14.bxc3 e4 15.La3 e3 16.Lc5 e2 17.Sa3 e1=S 18.Lf1 b4 19.De2+ De7 20.Db5 Sd3 21.Te1 g3 22.Tee6 Se5 23.Tec6 d5 24.Lg1 d4 25.cxd4 Sd7 26.Sc4 Sb8 27.Se5 Dd8 (2021-07-29)
A.Buchanan: Mario: sorry to read this. Is it fixable do you think? (2021-07-29)
more ...
comment
Keywords: Unique Proof Game, Pronkin Theme (l), Switchback (Lsld), Retro Shield
Genre: Retro
Computer test: cooked by Jacobi 0.7.5 with constraints
FEN: 1nbqkbnr/K1p2p1p/R1R5/1Q2N3/1p1P3N/5Pp1/P1PP2PP/5BB1
Reprints: (H3) The Problemist 05/2010
Input: Gerd Wilts, 2010-06-02
Last update: A.Buchanan, 2021-07-31 more...
97 - P1107806
Christopher Jeremy Morse
19 The Problemist , p. 299, 09/1978
P1107806
(2+9) cooked
#25
1. Sb4+ Ka1 2. Sxd3 Ka2 3. Sb4+ Ka1 4. Kc1 b6 5. Kc2 b5 6. Kc1 d3 7. Sxd3 Ka2 8. Kc2 Ka1 9. Sb4 d4 10. Kc1 d5 11. Kc2 d6 12. Kc1 d3 13. Sxd3 Ka2 14. Kc2 d4 15. Sb4+ Ka1 16. Kc1 d5 17. Kc2 d3+ 18. Sxd3 b4 19. Sxb4 d4 20. Kc1 d3 21. Sxd3 Ka2 22. Kc2 Ka1 23. Sb4 a2 24. Kc1 a3 25. Sc2#
play all play one stop play next play all
Cook: Olaf Jenkner zeigte, dass nach 4. ... d3! jedoch 27 Züge zum Matt nötig sind.
4. ... d3! 5. Sxd3 Ka2 6. Kc2 Ka1 7. Sb4 d4 8. Kc1 d5 9. Kc2 b5! 10. Kc1 d3 11. Sxd3 Ka2 12. Kc2 Ka1 13. Sb4 d4 14. Kc1 d3 15. Sxd3 Ka2 16. Kc2 b4 17. Sxb4+ Ka1 18. Kc1 d6 19. Kc2 d5 20. Kc1 d4 21. Sc2+ Ka2 22. Sxd4 Ka1 23. Kc2 Ka2 24. Sc6 Ka1 25. Sb4 a2 26. Kc1 a3 27. Sc2#
mit der ZU 23. Sc6 Ka2 24. Kc2
milan: no bRd3 #25 by stockfish with bR #27 M.Frelih (2023-09-01)
more ...
comment
Keywords: Minimal, no solution
Genre: n#
FEN: 8/1p1p4/N2p4/3p4/p2p4/p2r4/k1K5/8
Input: Frank Müller, 2010-06-16
Last update: Frank Müller, 2012-02-07 more...
98 - P1111703
George P. Sphicas
2101 U.S. Problem Bulletin 11-12/1990
2. Preis
P1111703
(10+12) cooked
ser-s#31
1. g8=S 2. Sxh6 3. Sf5 4. h6 5. h7 6. h8=S 7. Sxf7 8. S7g5 9. f7 10. f8=S 11. Sxd7 12. S7e5 13. d7 14. d8=S 15. Sxb7 16. S7c5 17. b7 18. b8=S 19. S8a6 20. Sxb4 21. Sbd3 22. b4 23. bxa5 24. a6 25. a7 26. a8=S 27. S8b6 28. S6xa4 29. Sc3 30. Sxe2 31. S2f4 exf5#
play all play one stop play next play all
Cook: Dual: 17. Scd3 18. b7 19. b8=D 20. Dxb4 21. Dc5 22. b4 23. bxa5 24. a6 25. a7 26. a8=S 27. Sb6 28. Sxa4 29. Sc3 30. Sxe2 31. Sef4 exf5# (Paul Raican)
more ...
comment
Keywords: Seriesmover, Promotions to Knights, konsekutive Umwandlungen 6 (SSSSSS)
Genre: Fairies
FEN: 8/1n1p1rP1/1PpPpPpp/p6P/np1PK3/4PN2/1P2p3/5k2
Reprints: Die Schwalbe 169 02/1998
Input: HBae, 2010-07-28
Last update: Arnold Beine, 2022-10-04 more...
99 - P1112253
Bo Lindgren
5104 feenschach 83 04-06/1987
Walter Jörgensen zum 70. Geburtstag
1. Preis Informalturnier
P1112253
(9+10) cooked
ser-s#42
1. e8=S 2. Sxf6 3. Sd5 4. f6 5. f7 6. f8=D 7. Dxf3 8. Dg2 9. f4 10. f5 11. f6 12. f7 13. f8=L 14. Lxh6 15. Le3 16. h6 17. h7 18. h8=T 19. Txh4 20. Te4 21. h4 22. h5 23. h6 24. h7 25. h8=D 26. Dxb8 27. De5 28. b8=L 29. Lxa7 30. Lc5 31. a7 32. a8=T 33. Txa4 34. Tb4 35. a4 36. a5 37. a6 38. a7 39. a8=S 40. Sab6 41. Sc4 42. Dxe2+ Sxe2#
play all play one stop play next play all
Preisbericht (Gruppe 8 = "Rest") siehe feenschach 10/1990, S. 368.
Doppelte AUW in einem langzügigen Serienzugselbstmatt, da kann man nur mit Mutter Kempowski sagen: "Wie isses nur möglich!". Kein Wort, nur tief durchatmen und staunen! (Preisrichter Theodor Steudel).
Cook: 1. e8=S 2. Sxf6 3. Se4 4. Sd2 5. f6 6. f7 7. f8=D 8. Dxf3 9. Dxe2 10. f4 11. f5 12. f6 13. f7 14. f8=L 15. Lxh6 16. Le3 17. h6 18. h7 19. h8=T 20. Txh4 21. Te4 22. h4 23. h5 24. h6 25. h7 26. h8=D 27. Dxb8 28. De5 29. b8=L 30. Lxa7 31. Lc5 32. a7 33. a8=T 34. Txa4 35. Tb4 36. a4 37. a5 38. a6 39. a7 40. a8=L 41. Ld5 42. Sc4+ Sxe2# mit Dualen (Arnold Beine)
Erich Bartel: Ein Wahnsinnsproblem!!! (2012-06-13)
Arnold Beine: Leider kaputt, denn am Ende kann man das Selbstmatt auch mit einem Batterieschach erzwingen. Die thematisch vergleichbare P1278403 hat aber gute Chancen, korrekt zu bleiben. (2022-10-22)
comment
Keywords: Allumwandlung (2x), Seriesmover, konsekutive Umwandlungen 8 (SDLTDLTS), Excelsior white (3x)
Genre: Fairies
FEN: 1r6/pP2P3/P4r1p/5P1P/p2K3p/5p2/P1k1pP1P/6n1
Reprints: 1938 U.S. Problem Bulletin 01-02/1990
feenschach 96 10/1990
Springaren (46), p. 125, 09/1991
G30 FIDE Album 1986-1988 1995
18 Mat Plus (6-7), p. 237, 1995
Die Schwalbe (156), p. 236, 12/1995
Tim Krabbé's Website (57) 2000
G-III Probleemblad 01-02/2000
(9) Springaren , p. 108, 09/2011
(9) Tehtäväniekka 3 30/09/2011
L11 Phénix 09-10/2011
(1) Die Schwalbe , p. 337, 12/2011
(34) The Problemist , p. 272, 01/2012
Problem Observer 05/2012
Input: HBae, 2010-08-03
Last update: Arnold Beine, 2022-10-23 more...
100 - P1116599
Janez Moder
Bilten 1962
3. Preis
P1116599
(4+3) cooked
#3
1. Dd8-h4! droht 2. Sh3-f4+ Kh1-g1 3. Sf4-e2#
1. ... g2-g1=D 2. Sh3-f2+ Kh1-g2 3. Dh4-h3#
1. ... g2-g1=S 2. Tf5-g5 droht 3. Sh3-f2# 3. Sh3xg1#
2. ... Sg1xh3 3. Dh4xh3#
2. ... Sg1-f3 3. Sh3-f2#
2. ... Kh1-h2 3. Sh3xg1#
1. ... g2-g1=L 2. Sh3-f2+ Kh1-g2 3. Dh4-h3#
Dual 2. Tf5-g5 Lg1-f2 3. Sh3xf2#
play all play one stop play next play all
Cook: Dual 1. ... g2-g1=L 2. Sh3-f2+, 2. Tf5-g5
B7-3ST
milan: wKa2-d6 M.Frelih (2021-12-01)
comment
Keywords: Miniature Collection (0338050), Miniature
Genre: 3#
FEN: 3Q4/8/8/5R2/4p3/7N/K5p1/7k
Reprints: 2287 Problemista 204-206 04-06/1985
Input: Zuncke/Bruder, 2010-09-11
Last update: Marcin Banaszek, 2021-10-22 more...
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