18 problem(s) found in 4130 milliseconds (displaying 18 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND COOKED AND A='Kardos, Tivadar'] [download as LaTeX]
1. Sf3 e5 2. Sxe5 Se7 3. Sxd7 Sec6 4. Sxb8 Dxd2 5. Dxd2 Sxb8 6. Dd8+ Kxd8
Cook: 1. Sh3 d5 2. Sf4 Sf6 3. Sxd5 Se4 4. Sxe7 Sxd2 5. Dxd2 Kxe7 6. Dxd8 Kxd8
(Can transpose B1&B2)
Cook: 1. Sh3 d5 2. Sf4 Sf6 3. Sxd5 Se4 4. Sxe7 Sxd2 5. Dxd2 Kxe7 6. Dxd8 Kxd8
(Can transpose B1&B2)
Keywords: Unique Proof Game, Homebase (W), Impostor (s), Superseded by (P1394733)
Genre: Retro
FEN: rnbk1b1r/ppp2ppp/8/8/8/8/PPP1PPPP/RNB1KB1R
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2021-10-21 more...
Genre: Retro
FEN: rnbk1b1r/ppp2ppp/8/8/8/8/PPP1PPPP/RNB1KB1R
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2021-10-21 more...
1. bxc3ep Lxe2 2. Sa3 0-0-0#
Cook: 2. ... Td1#
Cook: 2. ... Td1#
Sally: Der letzte Zug war: Bc2 - c4!
Nr.138 200 Ausgewählte S .Probleme T. Kardos(W. Fentze1983) (2010-09-30)
A.Buchanan: All 9+1 captures are visible by pawns. Note R: 1. Kd1-e1 d3xe2 is illegal because it costs 2 more captures for Black. So e.p. is unconditionally legal, requiring no AP justification. I see no reason why White has lost castling rights. Indeed someone might make a demo game ending with c2-c4. So this one seems cooked. Neither WinChloe nor yacpdb contains this problem. (2022-01-08)
A.Buchanan: If this is AP, it will be rendered sound by removing wPa2. But is this the intention? Does anyone have access to the collection of selected Kardos problems mentioned? (2024-01-25)
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Nr.138 200 Ausgewählte S .Probleme T. Kardos(W. Fentze1983) (2010-09-30)
A.Buchanan: All 9+1 captures are visible by pawns. Note R: 1. Kd1-e1 d3xe2 is illegal because it costs 2 more captures for Black. So e.p. is unconditionally legal, requiring no AP justification. I see no reason why White has lost castling rights. Indeed someone might make a demo game ending with c2-c4. So this one seems cooked. Neither WinChloe nor yacpdb contains this problem. (2022-01-08)
A.Buchanan: If this is AP, it will be rendered sound by removing wPa2. But is this the intention? Does anyone have access to the collection of selected Kardos problems mentioned? (2024-01-25)
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1. dxe3ep+ Kxc4 2. Lc3 Sxc2 3. Da5 axb3#
See the correction P1396159
Cook: 1. dxe3ep+ Kxc4 2. Td5 Sxc2 3. Ta5 axb3#
See the correction P1396159
Cook: 1. dxe3ep+ Kxc4 2. Td5 Sxc2 3. Ta5 axb3#
A.Buchanan: Easy enough to eliminate what I suppose is the intended solution (sL unblocking sD and blocking sT) by e.g. just removing sDf5. However I don't see a way to say goodbye to the cook instead. (2021-11-23)
James Malcom: I believe I may have a fix Andrew. If we substitute the Black queen with a Black rook, the same theme is kept even is if considered watered down.
h#3 8/3p4/3p1p2/3Kbr2/k1ppPp2/1n1r3P/P1p4P/N3nq1b (2021-11-24)
A.Buchanan: Hi James, hurray cool I thought I couldn't get through that way: I was confused in my mind about wPe2 blocking that line, but with the freshness of a new day, I can look at it again. The precise diagram that you propose doesn't quite work because R: 1. e3-e4 Sf3*e1+,Sg2*e1+,g2xf1=Q+,g2xh1=Q+, but this is all fixable with +bPd2,-bSe1. Now Popeye 4.87 says the forward solution is works uniquely, and Retractor 2.0 says R: 1. e2-e4 Rf3-d3+ 2. Ke4-d5 are unique. So for full C+ we only need some demo game that results in the position prior to Ke4-d5.
I don't see any "watering down" here: I think we have faithfully represented Tivadar's idea. Let's post it here as TK, corr JM&AB? (2021-11-24)
A.Buchanan: I have made an unedifying demo game with lichess, so our correction is fully C+. (2021-11-24)
James Malcom: "TK, corr JM&AB" sounds good to me. (2021-11-24)
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James Malcom: I believe I may have a fix Andrew. If we substitute the Black queen with a Black rook, the same theme is kept even is if considered watered down.
h#3 8/3p4/3p1p2/3Kbr2/k1ppPp2/1n1r3P/P1p4P/N3nq1b (2021-11-24)
A.Buchanan: Hi James, hurray cool I thought I couldn't get through that way: I was confused in my mind about wPe2 blocking that line, but with the freshness of a new day, I can look at it again. The precise diagram that you propose doesn't quite work because R: 1. e3-e4 Sf3*e1+,Sg2*e1+,g2xf1=Q+,g2xh1=Q+, but this is all fixable with +bPd2,-bSe1. Now Popeye 4.87 says the forward solution is works uniquely, and Retractor 2.0 says R: 1. e2-e4 Rf3-d3+ 2. Ke4-d5 are unique. So for full C+ we only need some demo game that results in the position prior to Ke4-d5.
I don't see any "watering down" here: I think we have faithfully represented Tivadar's idea. Let's post it here as TK, corr JM&AB? (2021-11-24)
A.Buchanan: I have made an unedifying demo game with lichess, so our correction is fully C+. (2021-11-24)
James Malcom: "TK, corr JM&AB" sounds good to me. (2021-11-24)
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Keywords: En passant as key, Superseded by (P1396159)
Genre: h#, Retro
Computer test: Popeye C-Version 4.87 & trivial retro-logic
FEN: 8/3p4/3p1p2/3KbqP1/k1ppPpp1/1n1r3P/P1p4P/N6b
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-24 more...
Genre: h#, Retro
Computer test: Popeye C-Version 4.87 & trivial retro-logic
FEN: 8/3p4/3p1p2/3KbqP1/k1ppPpp1/1n1r3P/P1p4P/N6b
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-24 more...
1. exf3ep e3 2. 0-0-0 Tb4 3. Tg4 Tb8#
I think that this cooked problem is an early A osteriori. I can see ways that it might be made sound, but I would like to see the published version. San anyone help please? Thanks.
Cook: 17 Black pawns, retro cook and numerous forward cooks
I think that this cooked problem is an early A osteriori. I can see ways that it might be made sound, but I would like to see the published version. San anyone help please? Thanks.
Cook: 17 Black pawns, retro cook and numerous forward cooks
klären wK im Schach, vielleicht wBb2?
Alfred Pfeiffer: 9 schwarze Bauern! (2012-02-07)
Ladislav Packa: Auch mit wBb2 NL, z.B. 1.exf3 e.p. Txg5 2.0-0-0 Tb5 3.Tg~ Tb8# (2012-02-07)
A.Buchanan: And adding to earlier comments, if we do swap sBb2 for wB, the retraction is still not unique with R: 1. f3-f4 Lh6xg5+ (2021-11-26)
A.Buchanan: I think that this cooked problem is an early A Posteriori. I can see ways that it might be made sound, but I would like to see the published version. Can anyone help please? Thanks. (2022-04-25)
Gerald Ettl: Verbesserungsvorschlag: -sBa2, -sBb2, -sSg7, +sBg7
r3k3/3b2p1/5p2/6b1/4pPRp/2pq2rp/2p1P1pB/2K3n1/ (2022-04-25)
Gerald Ettl: und +sSg8 (wegen exf4 Vermeidung) (2022-04-25)
Gerald Ettl: +sSa4 nicht g8 (2022-04-25)
A.Buchanan: Hi Gerald. Thanks for this. Your final proposed version is r3k3/3b2p1/5p2/6b1/n3pPRp/2pq2rp/2p1P1pB/2K3n1, yes? There are 16 candidate solutions, all using castling. But wPa cannot leave the a-file, and is required for capture balance, so Black cannot castle. Five of the candidates begin with e.p.: play might have just been R: 1. Kb1-c1 b3xPc2+, so e.p. is not permitted in any case. What am I missing? (2022-04-25)
Gerald Ettl: Hi Andrew,
Those were 2 mistakes I made. I improved it again.
r3k3/3b4/4pp2/6b1/4pPRp/n1pq2rp/PPp1P1pB/2K3n1/
(den wBa2 habe ich auf das Brett gestellt, da sonst wieder Lh6xXg5 geht.) (2022-04-26)
A.Buchanan: Hi Gerald: Deine Retro-Logik ist gut. Aber es gibt 18 Lösungsvorschläge für die Zukunft. Ich habe heute im Discord meinen eigenen Vorschlag zur AP-Korrektur von Kardos veröffentlicht. Ich werde ihn hier im PDB hinzufügen. (2022-04-26)
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Alfred Pfeiffer: 9 schwarze Bauern! (2012-02-07)
Ladislav Packa: Auch mit wBb2 NL, z.B. 1.exf3 e.p. Txg5 2.0-0-0 Tb5 3.Tg~ Tb8# (2012-02-07)
A.Buchanan: And adding to earlier comments, if we do swap sBb2 for wB, the retraction is still not unique with R: 1. f3-f4 Lh6xg5+ (2021-11-26)
A.Buchanan: I think that this cooked problem is an early A Posteriori. I can see ways that it might be made sound, but I would like to see the published version. Can anyone help please? Thanks. (2022-04-25)
Gerald Ettl: Verbesserungsvorschlag: -sBa2, -sBb2, -sSg7, +sBg7
r3k3/3b2p1/5p2/6b1/4pPRp/2pq2rp/2p1P1pB/2K3n1/ (2022-04-25)
Gerald Ettl: und +sSg8 (wegen exf4 Vermeidung) (2022-04-25)
Gerald Ettl: +sSa4 nicht g8 (2022-04-25)
A.Buchanan: Hi Gerald. Thanks for this. Your final proposed version is r3k3/3b2p1/5p2/6b1/n3pPRp/2pq2rp/2p1P1pB/2K3n1, yes? There are 16 candidate solutions, all using castling. But wPa cannot leave the a-file, and is required for capture balance, so Black cannot castle. Five of the candidates begin with e.p.: play might have just been R: 1. Kb1-c1 b3xPc2+, so e.p. is not permitted in any case. What am I missing? (2022-04-25)
Gerald Ettl: Hi Andrew,
Those were 2 mistakes I made. I improved it again.
r3k3/3b4/4pp2/6b1/4pPRp/n1pq2rp/PPp1P1pB/2K3n1/
(den wBa2 habe ich auf das Brett gestellt, da sonst wieder Lh6xXg5 geht.) (2022-04-26)
A.Buchanan: Hi Gerald: Deine Retro-Logik ist gut. Aber es gibt 18 Lösungsvorschläge für die Zukunft. Ich habe heute im Discord meinen eigenen Vorschlag zur AP-Korrektur von Kardos veröffentlicht. Ich werde ihn hier im PDB hinzufügen. (2022-04-26)
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5 - P0003339
Tivadar Kardos
2519 Revista Romana de Sah 01/1948
2. Preis
(10+15) cooked
h# in wieviel?
Tivadar Kardos
2519 Revista Romana de Sah 01/1948
2. Preis
(10+15) cooked
h# in wieviel?
1. ... cxd6ep 2. Tc8 dxe7 3. Tf8 exf8=S#
AL ('Revista Romana de Sah', 06/1948, S.225-226):
Bekanntlich beginnt im Hilfsmatt Schwarz, also hat in der Diagrammstellung Weiß den letzten Zug gemacht. Man findet aber, wenn man die Position analysiert, daß Weiß den letzten Zug nicht gemacht haben kann.
Der weiße Doppelbauer auf der d-Linie läßt sich nur durch Schlagen des einzig fehlenden schwarzen Steines, des sBa7, erklären. Dieser konnte aber erst nach Umwandlung geschlagen werden. Dazu mußte er zunächst bis a3 vorrücken, dann nach b2 schlagen, und dann umwandeln.
Also kann Weiß nicht zuletzt b2-b3 gezogen haben.
Die anderen schwarzen Bauern haben mindestens 5 Schläge gemacht, um die Position im Diagramm zu erreichen (man beachte, daß der sBh7 zweimal schlagen mußte, um den wBh2 durchzulassen)
also kann auch g2-g3 nicht der letzte Zug gewesen sein, denn sonst hätte der wLf1 nicht von einem sB geschlagen worden sein können.
Für alle anderen weißen Steine ist leicht zu sehen, daß sie den letzten Zug nicht gemacht haben können.
Es stellt sich heraus, dass der letzte Zug von Schwarz gemacht wurde, und eine einfache Analyse zeigt, daß dies nur möglich ist durch d7-d5 (sonst wäre es unmöglich, daß die weißen Steine ihre Position im Diagramm erreichen könnten).
In diesem Fall Weiß kann 1. ... c5:d6(e.p.) spielen, gefolgt von 2. Tc8 d:e7 3. Tf8 e:f8C matt!
Das kürzeste Hilfsmatt wird also in 2,5 Zügen erreicht!
Cook: 1. ... Txg5+ 2. Kxg5 f3 3. Lg6 gxf4#
1. ... Kxd5 2. Kf6 e4 3. Tg6,Dg6 e5#
AL ('Revista Romana de Sah', 06/1948, S.225-226):
Bekanntlich beginnt im Hilfsmatt Schwarz, also hat in der Diagrammstellung Weiß den letzten Zug gemacht. Man findet aber, wenn man die Position analysiert, daß Weiß den letzten Zug nicht gemacht haben kann.
Der weiße Doppelbauer auf der d-Linie läßt sich nur durch Schlagen des einzig fehlenden schwarzen Steines, des sBa7, erklären. Dieser konnte aber erst nach Umwandlung geschlagen werden. Dazu mußte er zunächst bis a3 vorrücken, dann nach b2 schlagen, und dann umwandeln.
Also kann Weiß nicht zuletzt b2-b3 gezogen haben.
Die anderen schwarzen Bauern haben mindestens 5 Schläge gemacht, um die Position im Diagramm zu erreichen (man beachte, daß der sBh7 zweimal schlagen mußte, um den wBh2 durchzulassen)
also kann auch g2-g3 nicht der letzte Zug gewesen sein, denn sonst hätte der wLf1 nicht von einem sB geschlagen worden sein können.
Für alle anderen weißen Steine ist leicht zu sehen, daß sie den letzten Zug nicht gemacht haben können.
Es stellt sich heraus, dass der letzte Zug von Schwarz gemacht wurde, und eine einfache Analyse zeigt, daß dies nur möglich ist durch d7-d5 (sonst wäre es unmöglich, daß die weißen Steine ihre Position im Diagramm erreichen könnten).
In diesem Fall Weiß kann 1. ... c5:d6(e.p.) spielen, gefolgt von 2. Tc8 d:e7 3. Tf8 e:f8C matt!
Das kürzeste Hilfsmatt wird also in 2,5 Zügen erreicht!
Cook: 1. ... Txg5+ 2. Kxg5 f3 3. Lg6 gxf4#
1. ... Kxd5 2. Kf6 e4 3. Tg6,Dg6 e5#
A.Buchanan: Popeye v.487. WinChloe has the same diagram, and although it just claims 1 solution, it's C? Yet WinChloe engine gives the cooks right away (2021-10-27)
Mario Richter: Shouldn't this problem get the Label "No legal last move for White"?
(White pawn d2 has captured the missing black piece (Pdxe), so black pawn a7 had to promote to get to the capture square. This requires one capture (Pa3xb2), together with bxc,cxd,hxg,gxh,gxh this accounts for all missing white pieces.)
Btw. "for me, "C?" stands for "Not yet computer-tested or computer test didn't come to a conlusion" ... (2021-10-28)
A.Buchanan: Hi Mario, thank you.
(1) The stipulation is non-standard. I think this is why the WinChloe database doesn't include a solution, and just marks it as "C?" However if I run the WinChloe solving engine manually it (like Popeye) gives 121 h#3 solutions and 4 h#2.5 solutions. I think you, me and Christian would all agree on the meaning of "C?"
(2) The problem does not rely on Article 15 to eliminate the first single move, but implicitly requests the shortest. Currently the PDB usage of "No legal last move..." is to indicate that Codex Article 15 applies, so I did not add it. But I'm ok if you want me to add the keyword. In my correction, I shift the stipulation to h#3 so it's clear that Article 15 and not any desire for brevity which push the problem to h#2.5.
(3) However the PDB usage is confused. Ideallly think the two "No legal..." keywords should be replaced by "Retro-stalemate", while two new keywords "Article 15" & "Whose mate?" indicate the choice of implications of the retropat for forward play. "Board rotation" and other jokes are also implications of retropat (and of illegal diagram).
(4) But this is complicated to implement, requiring either database-level access or screen-scraping. The latter is quite practical for some future time when I have more leisure.
(5) https://www.stere.ro/biblioteca-digitala/reviste/revista-romana-de-sah/ is an excellent archive of Revista Romana de Sah. My sincere compliments and thanks to whoever prepared it. And the magazines themselves contain thorough annual indices. p225-6 of 6/1948, contains the solution to Kardos. I haven't translated it, nor have I found time to locate the prize announcement.
Comments welcome! (2021-10-29)
Mario Richter: I still believe, that the label "No legal last move for White" is justified here, because this is exactly what the author wanted to show.
(And this is too, what the reprint in 'Problem (Zagreb)' 37-40 09/1956 is all about - it appears there inside asn article
Btw., I wouldn't call the presentation of the solution in 'Revista Romana de Sah', p.225, 06/1948, a "reprint" - it lacks the presentation of the position ... (2021-10-30)
A.Buchanan: Added the keyword.
Yes I know that's the usage of "reprint", but then there should be a field for the location of the solution :-) It's idiotic that if I want to say where the solution is contained, I have to embed it in text like this: 2519 Revista Romana de Sah , p. 225-6, 06/1948 (2021-10-30)
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Mario Richter: Shouldn't this problem get the Label "No legal last move for White"?
(White pawn d2 has captured the missing black piece (Pdxe), so black pawn a7 had to promote to get to the capture square. This requires one capture (Pa3xb2), together with bxc,cxd,hxg,gxh,gxh this accounts for all missing white pieces.)
Btw. "for me, "C?" stands for "Not yet computer-tested or computer test didn't come to a conlusion" ... (2021-10-28)
A.Buchanan: Hi Mario, thank you.
(1) The stipulation is non-standard. I think this is why the WinChloe database doesn't include a solution, and just marks it as "C?" However if I run the WinChloe solving engine manually it (like Popeye) gives 121 h#3 solutions and 4 h#2.5 solutions. I think you, me and Christian would all agree on the meaning of "C?"
(2) The problem does not rely on Article 15 to eliminate the first single move, but implicitly requests the shortest. Currently the PDB usage of "No legal last move..." is to indicate that Codex Article 15 applies, so I did not add it. But I'm ok if you want me to add the keyword. In my correction, I shift the stipulation to h#3 so it's clear that Article 15 and not any desire for brevity which push the problem to h#2.5.
(3) However the PDB usage is confused. Ideallly think the two "No legal..." keywords should be replaced by "Retro-stalemate", while two new keywords "Article 15" & "Whose mate?" indicate the choice of implications of the retropat for forward play. "Board rotation" and other jokes are also implications of retropat (and of illegal diagram).
(4) But this is complicated to implement, requiring either database-level access or screen-scraping. The latter is quite practical for some future time when I have more leisure.
(5) https://www.stere.ro/biblioteca-digitala/reviste/revista-romana-de-sah/ is an excellent archive of Revista Romana de Sah. My sincere compliments and thanks to whoever prepared it. And the magazines themselves contain thorough annual indices. p225-6 of 6/1948, contains the solution to Kardos. I haven't translated it, nor have I found time to locate the prize announcement.
Comments welcome! (2021-10-29)
Mario Richter: I still believe, that the label "No legal last move for White" is justified here, because this is exactly what the author wanted to show.
(And this is too, what the reprint in 'Problem (Zagreb)' 37-40 09/1956 is all about - it appears there inside asn article
Btw., I wouldn't call the presentation of the solution in 'Revista Romana de Sah', p.225, 06/1948, a "reprint" - it lacks the presentation of the position ... (2021-10-30)
A.Buchanan: Added the keyword.
Yes I know that's the usage of "reprint", but then there should be a field for the location of the solution :-) It's idiotic that if I want to say where the solution is contained, I have to embed it in text like this: 2519 Revista Romana de Sah , p. 225-6, 06/1948 (2021-10-30)
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Keywords: En passant as key, Promotion (S), Superseded by (P1394978), No legal last move for White
Genre: h#, Retro
Computer test: Popeye v4.87 & WinChloe both say cooked
FEN: 7b/4p1nP/2r1P1kq/1nPpKbrp/2pp1pRp/1P4P1/P3PP2/8
Reprints: (III) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-30 more...
Genre: h#, Retro
Computer test: Popeye v4.87 & WinChloe both say cooked
FEN: 7b/4p1nP/2r1P1kq/1nPpKbrp/2pp1pRp/1P4P1/P3PP2/8
Reprints: (III) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-30 more...
6 - P0005275
Otto Kerekes
Tivadar Kardos
10 L'Echiquier de France 11/1956
(11+15) cooked
h#2
b) sBg2 statt wBg2
Otto Kerekes
Tivadar Kardos
10 L'Echiquier de France 11/1956
(11+15) cooked
h#2
b) sBg2 statt wBg2
a) 1. cxd4 Lxc4 2. Dd5 Ld3#
b)
b)
Paulo Roque: Illegale Stellung. Diagrammfehler? (2009-11-17)
Alfred Pfeiffer: außerdem in b) 9 schwarze Bauern. (2010-01-13)
A.Buchanan: Twin a) is also illegal, as too many Bl captures (2021-11-24)
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Alfred Pfeiffer: außerdem in b) 9 schwarze Bauern. (2010-01-13)
A.Buchanan: Twin a) is also illegal, as too many Bl captures (2021-11-24)
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Keywords: En passant as key, Castling, Illegal position, Superseded by (P1400824)
Genre: h#, Retro
FEN: 8/p1p2p1b/1B3pp1/q1p1b3/r1pPk3/1Bp3P1/PPP2PPr/3n1RK1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-04-23 more...
Genre: h#, Retro
FEN: 8/p1p2p1b/1B3pp1/q1p1b3/r1pPk3/1Bp3P1/PPP2PPr/3n1RK1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-04-23 more...
1. Lxa2 Txa2 2. 0-0-0 Txa7 3. Td7 Ta8#
1. Lxa2 0-0-0? 2. Dxg2 Tg1 3. 0-0 Txg2# but White can't castle
Cook: 1. Lxa2 Lf6 2. Lb1 Txa7 3. Kf8 Txa8#
1. Lxa2 Lf6 2. Lxb3 Txa7 3. Kf8 Txa8#
1. Dxg2 Txb1 2. Dxf2+ Kxf2 3. 0-0 Tg1#
1. Dg3 Txb1 2. Dxb3 Txb3 3. 0-0 Tg3#
1. Lxa2 0-0-0? 2. Dxg2 Tg1 3. 0-0 Txg2# but White can't castle
Cook: 1. Lxa2 Lf6 2. Lb1 Txa7 3. Kf8 Txa8#
1. Lxa2 Lf6 2. Lxb3 Txa7 3. Kf8 Txa8#
1. Dxg2 Txb1 2. Dxf2+ Kxf2 3. 0-0 Tg1#
1. Dg3 Txb1 2. Dxb3 Txb3 3. 0-0 Tg3#
paul: White Rook h1 left the S-E camp, so the white castle is no more possible.
Intention: 1.L×a2 T×a2 2.0-0-0 T×a7 3.Td7 Ta8#
1.L×a2 0-0-0 2.D×g2 Tg1 3.0-0 T×g2#
Cooked by 1.L×a2 Lf6 2.Lb1 T×a7 3.Rf8 T×a8# or
1.D×g2 T×b1 2.D×f2+ K×f2 3.0-0 Tg1# (2011-09-15)
milan: wBe5-f4 M.Frelih (2021-12-01)
A.Buchanan: @Milan: that removes all 4 cooks, and alas the intended try also. (2021-12-01)
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Intention: 1.L×a2 T×a2 2.0-0-0 T×a7 3.Td7 Ta8#
1.L×a2 0-0-0 2.D×g2 Tg1 3.0-0 T×g2#
Cooked by 1.L×a2 Lf6 2.Lb1 T×a7 3.Rf8 T×a8# or
1.D×g2 T×b1 2.D×f2+ K×f2 3.0-0 Tg1# (2011-09-15)
milan: wBe5-f4 M.Frelih (2021-12-01)
A.Buchanan: @Milan: that removes all 4 cooks, and alas the intended try also. (2021-12-01)
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Keywords: Cant Castler, Obvious promotion (l), Superseded by (P1396304)
Genre: Retro
FEN: r3k1qr/pp3p1p/2p5/3pB2p/8/1P6/P1PPPPPP/Rb2K3
Input: Gerd Wilts, 1996-08-11
Last update: A.Buchanan, 2021-12-01 more...
Genre: Retro
FEN: r3k1qr/pp3p1p/2p5/3pB2p/8/1P6/P1PPPPPP/Rb2K3
Input: Gerd Wilts, 1996-08-11
Last update: A.Buchanan, 2021-12-01 more...
1. La1 Ke7 2. Sb2 Kf6 3. Sd3+ Kg5 4. Le5 Sd2#
NL:
1. Lc3 Kc7 2. Lb4 Lh2 3. Kd4 Sa3 4. Kc5 Lg1#
1. Kd3 Kc7 2. Kc4 Lh2 3. Ld4 Sa3+ 4. Kc5 Ld6#
NL:
1. Lc3 Kc7 2. Lb4 Lh2 3. Kd4 Sa3 4. Kc5 Lg1#
1. Kd3 Kc7 2. Kc4 Lh2 3. Ld4 Sa3+ 4. Kc5 Ld6#
Yuri Bilokin: correction wKe8-f8, +bSb7, +bPg4, +bPh4 5K1b/1n6/8/3b4/n3k1pp/8/8/1N4B1 (3+7) h#4
1.Ba1 Ke7 2.Sb2 Kf6 3.Sd3+ Kg5 4.Be5 Sd2# (MM)
AntiZielElement (B2, line obstruction)
Corner-to-corner (bB)
Hesitation (bB)
Indian (black)
Model mate × 1 (2023-05-24)
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1.Ba1 Ke7 2.Sb2 Kf6 3.Sd3+ Kg5 4.Be5 Sd2# (MM)
AntiZielElement (B2, line obstruction)
Corner-to-corner (bB)
Hesitation (bB)
Indian (black)
Model mate × 1 (2023-05-24)
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Keywords: Check Protection
Genre: h#
FEN: 3K3b/8/8/3b4/n3k3/8/8/1N4B1
Input: Markus Manhart, 1997-06-26
Last update: hpr, 1999-10-19 more...
Genre: h#
FEN: 3K3b/8/8/3b4/n3k3/8/8/1N4B1
Input: Markus Manhart, 1997-06-26
Last update: hpr, 1999-10-19 more...
1. cxb3ep+ Sb4+ 2. Kb1 Sxe2 3. b2 0-0#
Cook: NL 1. Db2,Sb3 Sxe2 2. Sb3,Db2 0-0 3. Lxb4 Sxb4#
Cook: NL 1. Db2,Sb3 Sxe2 2. Sb3,Db2 0-0 3. Lxb4 Sxb4#
A.Buchanan: Two aspects of cookery here. First, NL 1. Db2,Sb3 Sxe2 2. Sb3,Db2 0-0 3. Lxb4 Sxb4# Second, White can retract c3xb4 (and earlier captured onto c-file). Black could have captured axbxcxdxe, exf, fxe, with wPg waylaid (2021-11-23)
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Keywords: En passant as key, Superseded by (P1396163)
Genre: h#, Retro
Computer test: Popeye v4.87 says cooked
FEN: 8/8/1p6/b1P2P2/1PpqPpp1/r2ppb1p/k1N1p2P/n3K1NR
Input: Felber, Volker, 1999-12-20
Last update: A.Buchanan, 2021-11-25 more...
Genre: h#, Retro
Computer test: Popeye v4.87 says cooked
FEN: 8/8/1p6/b1P2P2/1PpqPpp1/r2ppb1p/k1N1p2P/n3K1NR
Input: Felber, Volker, 1999-12-20
Last update: A.Buchanan, 2021-11-25 more...
10 - P0574405
Tivadar Kardos
Pavlos N. Moutecidis
Feladvanykedvelök Lapja 1970
5. ehrende Erwähnung
(2+5) cooked
ser-h=20
Tivadar Kardos
Pavlos N. Moutecidis
Feladvanykedvelök Lapja 1970
5. ehrende Erwähnung
(2+5) cooked
ser-h=20
Erich Bartel (2008-01-25):
1. Kb2 2. Ka3 3. Kb4 4. Kc4 5. Kd3 6. Ke3 7. Kf2 8. Kf1 9. h1=D 10. Dh8 11. Kf2 12. Ke3 13. Kd3 14. Kc4 15. Kb4 16. Ka3 17. Kb2 18. Kb1 19. Da1 20. b2 Sd4=
Cook: Anton Baumann (2020-11-20):
1. a1=L 2. Ld4 3. Lg1 4. h1=T 5. Th8 6. Le3 7. Lc1 8. Kb2 9. Ta8 10. Ta1 11. Tb1 12. Ka1 13. b2 14. d4 15. d3 16. d2 Sc3=
1. Kb2 2. Ka3 3. Kb4 4. Kc4 5. Kd3 6. Ke3 7. Kf2 8. Kf1 9. h1=D 10. Dh8 11. Kf2 12. Ke3 13. Kd3 14. Kc4 15. Kb4 16. Ka3 17. Kb2 18. Kb1 19. Da1 20. b2 Sd4=
Cook: Anton Baumann (2020-11-20):
1. a1=L 2. Ld4 3. Lg1 4. h1=T 5. Th8 6. Le3 7. Lc1 8. Kb2 9. Ta8 10. Ta1 11. Tb1 12. Ka1 13. b2 14. d4 15. d3 16. d2 Sc3=
Anton Baumann: kürzer, wenn eine Umwandlungsfigur rechts abschirmt:
1.a1=L 3.Lg1 4.h1=T 6.Ta8 8.Lc1 9.Kb2 11.Tb1 12.Ka1 13.b2 16.d2 Sc3= (2020-11-20)
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1.a1=L 3.Lg1 4.h1=T 6.Ta8 8.Lc1 9.Kb2 11.Tb1 12.Ka1 13.b2 16.d2 Sc3= (2020-11-20)
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Keywords: Seriesmover
Genre: Fairies
FEN: 8/8/8/3p4/8/1p6/p3N2p/1k1K4
Input: Felber, Volker, 1999-12-20
Last update: Mario Richter, 2020-11-20 more...
Genre: Fairies
FEN: 8/8/8/3p4/8/1p6/p3N2p/1k1K4
Input: Felber, Volker, 1999-12-20
Last update: Mario Richter, 2020-11-20 more...
1. 0-0 Td1 2. Kh7 Td4 3. Tfg8 Txh4#
1. 0-0 0-0-0? 2. Kh7 Td4,Th1 3. Tfg8 Txh4#
Les N ont pris 4 P.B. Les B une P.N. en g3 promue en a1 (2 P.B.) ou d1 (3 P.B.).Le roque B est cassé sauf si PNe3 vient de a7 (4 p.B.) et PNh7 est aller en h1. Donc les B ont pas joués les derniers. Le O-O-O est cassé. S'il n'est pas casséles N ont joués les derniers.
1. 0-0 0-0-0? 2. Kh7 Td4,Th1 3. Tfg8 Txh4#
Les N ont pris 4 P.B. Les B une P.N. en g3 promue en a1 (2 P.B.) ou d1 (3 P.B.).Le roque B est cassé sauf si PNe3 vient de a7 (4 p.B.) et PNh7 est aller en h1. Donc les B ont pas joués les derniers. Le O-O-O est cassé. S'il n'est pas casséles N ont joués les derniers.
No. 438 HN
Henrik Juel: White captured h2xg3, so [Pa7] must have promoted
Black captured [Lf1], hxgxf, and 3 more white men, incl. [Pd2]
The promotion was either axb-b3xa2-a1 or axbxcxPd-d1, so White may not castle
1.0-0 Ra1-d1 2.Kg8-h7 Rd1-d4 3.Rf8-g8 Rd4*h4#
HC+ Popeye 4.61 (2021-11-26)
A.Buchanan: If sBe3 is [sBa], then [sBh] either captured to g3, where it was captured in turn, or it promoted on h1. In either case, White castling rights may endure, so the intended retro try is a cook. There is also a dual. (2021-11-28)
A.Buchanan: Nouguier (in French) noted the possibility of the Western origin of sBe3, which I think the composer overlooked. But (I think) Nouguier did not see that White castling rights remain even with Black to move. He seemed to be concerned about possibility of WTM, but this is not relevant for this problem. (2021-11-28)
A.Buchanan: This can be quickly patched by e.g. shifting bPe3 to e4, and bSc4 to b4, but this is the kind of cook which invites the problem’s expansion, to include both possible origins of bPe3 as thematic retro lines to be explored (2021-11-29)
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Henrik Juel: White captured h2xg3, so [Pa7] must have promoted
Black captured [Lf1], hxgxf, and 3 more white men, incl. [Pd2]
The promotion was either axb-b3xa2-a1 or axbxcxPd-d1, so White may not castle
1.0-0 Ra1-d1 2.Kg8-h7 Rd1-d4 3.Rf8-g8 Rd4*h4#
HC+ Popeye 4.61 (2021-11-26)
A.Buchanan: If sBe3 is [sBa], then [sBh] either captured to g3, where it was captured in turn, or it promoted on h1. In either case, White castling rights may endure, so the intended retro try is a cook. There is also a dual. (2021-11-28)
A.Buchanan: Nouguier (in French) noted the possibility of the Western origin of sBe3, which I think the composer overlooked. But (I think) Nouguier did not see that White castling rights remain even with Black to move. He seemed to be concerned about possibility of WTM, but this is not relevant for this problem. (2021-11-28)
A.Buchanan: This can be quickly patched by e.g. shifting bPe3 to e4, and bSc4 to b4, but this is the kind of cook which invites the problem’s expansion, to include both possible origins of bPe3 as thematic retro lines to be explored (2021-11-29)
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Keywords: Cant Castler
Genre: Retro, h#
FEN: 4k2r/1p4r1/1bpp2p1/1b2pp2/n1n4q/P3pPP1/1PP1P1P1/R3K3
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2021-11-28 more...
Genre: Retro, h#
FEN: 4k2r/1p4r1/1bpp2p1/1b2pp2/n1n4q/P3pPP1/1PP1P1P1/R3K3
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2021-11-28 more...
1. Sb8 cxb8=S 2. Sc6 Sxc6 3. Td8+ exd8=S 4. Te8+ fxe8=S 5. Df8+ gxf8=S=
Cook: Dual 4. ... fxe8=D 5. Df7 Dxf7=
NL: 1.Dd3 e8D+ 2.Kb7 D×e3 3.Sc6 D×d2 4.Sa7 D×d3 5.Ka8 D×a6+
mit vielen Umstellungen.
Cook: Dual 4. ... fxe8=D 5. Df7 Dxf7=
NL: 1.Dd3 e8D+ 2.Kb7 D×e3 3.Sc6 D×d2 4.Sa7 D×d3 5.Ka8 D×a6+
mit vielen Umstellungen.
1. Sg8 hxg8=S 2. Th8 gxh8=S 3. Lb8 axb8=S 4. Ta8 bxa8=S 5. Db6 Sxb6 6. Sc4 Sxc4=
Korrektur Schwalbe 10/1989 S. 130
Cook: 1. Sd2-c4 b7-b8=D 2. Th3-h6 h7-h8=D 3. Db4-b3 Db8xb3 4. Ta5-b5 Dh8xh6 5. Tb5-b8 a7xb8=D 6. Lh2-c7 Db8xc7=
Korrektur Schwalbe 10/1989 S. 130
Cook: 1. Sd2-c4 b7-b8=D 2. Th3-h6 h7-h8=D 3. Db4-b3 Db8xb3 4. Ta5-b5 Dh8xh6 5. Tb5-b8 a7xb8=D 6. Lh2-c7 Db8xc7=
Anton Baumann: Arnold Beine fand den Dual: 2.Db3 b8=D 3.Sc4 Dxb3 4.Th8 gxh8=D 5.Ta7 Dxh2 6.Tc7 Dxc7 = mit ZU (vergl. BuB in 'Die Schwalbe' 12/2010 S.743
Mögliche Korrektur: sBa3 nach a4, wBa2 nach a3 (2023-04-07)
Vaclav Kotesovec: Correction above (sBa3 nach a4, wBa2 nach a3) is C+, Popeye 4.87 65:22:47 h:m:s (2023-06-26)
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Mögliche Korrektur: sBa3 nach a4, wBa2 nach a3 (2023-04-07)
Vaclav Kotesovec: Correction above (sBa3 nach a4, wBa2 nach a3) is C+, Popeye 4.87 65:22:47 h:m:s (2023-06-26)
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Keywords: konsekutive Umwandlungen 4 (SSSS)
Genre: Fairies
FEN: 8/PP4PP/4kn2/r1p5/1q2P3/p4p1r/P2n1P1b/7K
Input: HBae, 2010-07-07
Last update: Vaclav Kotesovec, 2023-06-23 more...
Genre: Fairies
FEN: 8/PP4PP/4kn2/r1p5/1q2P3/p4p1r/P2n1P1b/7K
Input: HBae, 2010-07-07
Last update: Vaclav Kotesovec, 2023-06-23 more...
1. bxc8=S+! Kb7 2. cxd8=S+ Kc7 3. dxe8=S+ Kd7 4. gxf8=S+ Kxe8 5. Sf5+ Dxe2#
Cook: Dual
Cook: Dual
Keywords: Promotions to Knights, konsekutive Umwandlungen 4 (SSSS), Multiple publication
Genre: s#
FEN: rnrnbbQ1/kPPPNNP1/p6p/6p1/5pK1/7P/4R3/3q4
Reprints: 1734 Schach 2 01/1954
Input: Frank Müller, 2012-03-04
Last update: Marcin Banaszek, 2021-09-24 more...
Genre: s#
FEN: rnrnbbQ1/kPPPNNP1/p6p/6p1/5pK1/7P/4R3/3q4
Reprints: 1734 Schach 2 01/1954
Input: Frank Müller, 2012-03-04
Last update: Marcin Banaszek, 2021-09-24 more...
1. Sg8 hxg8=S 2. Th6 Sxh6 3. Ld8 cxd8=S 4. Se6 Sxe6 5. Tc8 bxc8=S 6. Db8 axb8=S=
16 - P1268134
Tivadar Kardos
12984v Schweizerische Schachzeitung 09/1987
Informalturnier 1987/88
1. Lob
(11+5) cooked
s#12
Tivadar Kardos
12984v Schweizerische Schachzeitung 09/1987
Informalturnier 1987/88
1. Lob
(11+5) cooked
s#12
Korrektur in 05/1988, Seite 187
1. De7+ 2. Dd6+ 3. Dd4+ 4. Tb1+ 5. Dd5+ Sb3 6. Dg2+ Sd2 7. Ta1+ Kb3 8. Dd5+ Sc4 9. Df3+ Se3 10. Ta3+ Kc4 11. Df7+ Sd5 12. Df4+ Sxf4#
Cook: Gustav findet 4 Nebenlösungen in 11 Zügen
1. Dc6+
1. Df7+
1. Dc8+
1. Lf5+
1. De7+ 2. Dd6+ 3. Dd4+ 4. Tb1+ 5. Dd5+ Sb3 6. Dg2+ Sd2 7. Ta1+ Kb3 8. Dd5+ Sc4 9. Df3+ Se3 10. Ta3+ Kc4 11. Df7+ Sd5 12. Df4+ Sxf4#
Cook: Gustav findet 4 Nebenlösungen in 11 Zügen
1. Dc6+
1. Df7+
1. Dc8+
1. Lf5+
Anton Baumann: Mit Stellung gem. Diagramm (wBh2 sBh4) unlösbar!
Original: ohne wBh2 ; Korrektur: "im s#129984 versetzt der Verfasser den sBh4 nach h2 und fügt einen wBh4 hinzu". Die oben angegebenen NL beziehen sich auf diese Korrektur-Stellung!
Verbesserungsvorschlag ABm: wDb7 nach a7, -wBh2, -wBh6, sKe5, +sBg2, +sBg7, h4=sB (9+7)
Lösung gemäss Autorabsicht: 1.De7+ Kd5 2.Dd6+ Kc4 3.Dd4+ ... (2023-09-12)
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Original: ohne wBh2 ; Korrektur: "im s#129984 versetzt der Verfasser den sBh4 nach h2 und fügt einen wBh4 hinzu". Die oben angegebenen NL beziehen sich auf diese Korrektur-Stellung!
Verbesserungsvorschlag ABm: wDb7 nach a7, -wBh2, -wBh6, sKe5, +sBg2, +sBg7, h4=sB (9+7)
Lösung gemäss Autorabsicht: 1.De7+ Kd5 2.Dd6+ Kc4 3.Dd4+ ... (2023-09-12)
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Genre: s#
FEN: 8/1Q5B/4k2P/1pB3PK/N5Pp/8/7P/n4RRr
Input: Frank Müller, 2013-04-21
Last update: Frank Müller, 2018-02-04 more...
1. a1=L f4 2. Le5 fxe5 3. 0-0-0 e6 4. Kb8 e7 5. Ka8 e8=S 6. Tb8 Sc7#
Cook: vielfach NL, bereits in 5 Zügen:
1. 0-0-0 f2-f4 2. Td8-d7 f4-f5 3. Kc8-d8 f5-f6 4. La7-b8 f6-f7 5. Lb8-c7 f7-f8=D#
1. Ke8-f7 f2-f4 2. Ta8-h8 f4-f5 3. Kf7-g8 f5-f6 4. Th8-h7 f6-f7+ 5. Kg8-h8 f7-f8=D# u.a.
Cook: vielfach NL, bereits in 5 Zügen:
1. 0-0-0 f2-f4 2. Td8-d7 f4-f5 3. Kc8-d8 f5-f6 4. La7-b8 f6-f7 5. Lb8-c7 f7-f8=D#
1. Ke8-f7 f2-f4 2. Ta8-h8 f4-f5 3. Kf7-g8 f5-f6 4. Th8-h7 f6-f7+ 5. Kg8-h8 f7-f8=D# u.a.
1. De1-d1 Sh1-f2 2. Dd1-a4 Sf2-d3+ 3. Kb4-a5 b2-b4#
Cook: NL 1. De1-h4 Ta1-g1 2. Kb4-a5 Tg1-g8 3. Dh4-b4 Tg8-a8#
1. De1-g3 Ta1-c1 2. Kb4-a5 b2-b3 3. b5-b4 Tc1-c5#
1. De1-c3 Ta1-g1 2. Kb4-a5 Tg1-g6 3. Dc3-b4 Tg6-a6#
und viele andere
Cook: NL 1. De1-h4 Ta1-g1 2. Kb4-a5 Tg1-g8 3. Dh4-b4 Tg8-a8#
1. De1-g3 Ta1-c1 2. Kb4-a5 b2-b3 3. b5-b4 Tc1-c5#
1. De1-c3 Ta1-g1 2. Kb4-a5 Tg1-g6 3. Dc3-b4 Tg6-a6#
und viele andere
Yuri Bilokin: correction wRa1-a2, bQe1-h5, + bPd8, +bPd7, +bPg3 3b4/1K1p4/8/1p5q/1k6/6p1/RP6/7N (4+6) (2022-06-25)
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Show statistic for complete result. Show search result faster by using ids.
https://pdb.dieschwalbe.de/search.jsp?expression=COMMENTDATE%3E%3D20200919+AND+NOT+K%3D%27Hilfsr%C3%BCckz%C3%BCger%27+AND+COOKED++AND+A%3D%27Kardos%2C+Tivadar%27
The problems of this query have been registered by the following contributors:
Gerd Wilts (7)Markus Manhart (1)
Felber, Volker (2)
Henri Nouguier (1)
HBae (2)
Frank Müller (2)
Erich Bartel (2)
Marcin Banaszek (1)
Als Vergleichsaufgaben sind in der 'Schwalbe' angegeben: G. Schweig (P0002287), Mortimer (P1394750), W. Naef & H. Klüver (P0002832)
A.Buchanan: It's curious that if we shift sK to e8 (i.e. make the position fully homebase) then it is sound as BP in 6.0! The magic of homebase! :) I don't know if it was a typo - maybe someone can check the magazine archive? (2021-10-19)
A.Buchanan: WinChloe & YACPDB don't know this composition. (2021-10-20)
Mario Richter: No typo, the position with black Kd8 was intended, the cook was found by the 'Schwalbe'-solvers (Heft 71, Oktober 1981, p. 349) (2021-10-21)
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