Die Schwalbe

32 problem(s) found in 4157 milliseconds (displaying 32 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND K='Allumwandlung']

1 - P0576207
Torsten Linss
1348 Rochade Europa 01/1997
P0576207
(1+1+4)
h#2
Circe coucou
1. Kxe4[+nSe8] nSxg7[+nDg1] 2. nDxg3[+nTd8] nTxd7[+nLh1]#
play all play one stop play next play all
t/promotion only
t/2KK4BB,
Steen Christensen: In "Circe coucou", 1.Kxe4[+nSe8] is illegal because of the alternative promotions nDe8+/nTe8+. This problem is avoided using "Circe couscous" instead (2013-03-01)
Henrik Juel: With Circe couscous, C+ Popeye 4.61 (2020-10-09)
comment
Keywords: Circe (Couscous), Kindergarten Problem, Allumwandlung
Genre: Fairies
FEN: 8/3-P2-P1/8/8/3k-P3/6-P1/K7/8
Input: Felber, Volker, 1999-12-30
Last update: Alfred Pfeiffer, 2020-10-09 more...
2 - P1083270
Klaus Wenda
6602v Schach-Echo 06/1971
6. Preis
P1083270
(9+5)
s#6
Circe
1. d8=L+ Txd8[+wLc1] 2. f8=T+ Txf8[+wTa1] 3. g8=S+ Txg8[+wSb1] 4. Se4+ Ke6 5. hxg8=D[+sTa8]+ Txg8[+wDd1] 6. Dc4+ Sxc4#
play all play one stop play next play all
vom Verfasser verbessert in Problemkiste 06/1994 Tg3 nach h3
SCHRECKE: C+, popeye 4.85 (2020-11-05)
comment
Keywords: Allumwandlung, Circe
Genre: Fairies
FEN: 1r6/2QP1PPP/5k2/2N3R1/1B6/np5r/1K6/8
Reprints: feenschach 16, p. 121, 08/1973
Problemkiste 06/1994
Input: HBae, 2009-02-06
Last update: HBae, 2015-12-30 more...
3 - P1085218
Horacio Amil Meylan
i010 Mirador 02/2004
P1085218
(9+6)
ser-h#32
1. e6 2. exf5 3. f4 4. f3 5. f2 6. f1=D 7. Dxh3 8. Dxh5 9. Df5 10. h5 11. h4 12. h3 13. h2 14. h1=L 15. Lxc6 16. Le4 17. c6 18. cxb5 19. b4 20. b3 21. b2 22. b1=T 23. Tb6 24. Txd6 25. Te6 26. d5 27. d4 28. d3 29. dxc2 30. c1=S 31. Se2 32. Sf4 d4#
play all play one stop play next play all
Anton Baumann: C+ Alybadix (2020-11-27)
comment
Keywords: Series mover, Allumwandlung, Excelsior (4-fach), Kindergarten Problem, Pawn mate, Ideal mate, Entblockung, Selfblock, Promotion, under-promotion, konsekutive Umwandlungen 4 (dlts)
Genre: Fairies
FEN: 8/2ppp2p/2PP1p2/1PK1kP1P/8/7P/2PP4/8
Reprints: zu 18098 Die Schwalbe 204, p. 656, 08/2020
Input: hpr, 2009-05-30
Last update: Gunter Jordan, 2020-08-14 more...
4 - P1182141
Charles Henry Wheeler
418 The Pittsburgh Gazette Times 14/01/1912
P1182141
(7+9) cooked
s#2
1. Dc2! Dxa7 2. Lxc5+ Dxc5#
1. ... b1=S 2. Dd2+ Sbxd2#
1. ... b1=T 2. Dc1+ Txc1#
1. ... b1=L 2. Dd3+ Lxd3#
1. ... b1=D 2. Dc1+, 2. Dd3+
1. ... Lb1 2. Dd3+ Lxd3#
1. ... Da5 2. Lxc5+ Dxc5#
1. ... cxb4 2. Dc3+ bxc3#
play all play one stop play next play all
Cook: Dual 1. ... b1=D 2. Dc1+, 2. Dd3+
Henrik Juel: Slightly damaged by the dual after 1... b1=D (2020-11-17)
comment
Keywords: Allumwandlung, unechte schwarze
Genre: s#
FEN: 8/P7/2p1R3/2p5/qBK1n1B1/rp2k2N/bp6/1Q6
Input: Frank Müller, 2010-12-10
Last update: Marcin Banaszek, 2020-11-18 more...
5 - P1196739
Alberto Armeni
9436v feenschach 12/2006
P1196739
(8+3) C+
s#6
1. Lb8! d3 2. Te6 d2 3. Sd6 Kg3 4. Se4+ Kh3 5. Dh5
5. ... d1=D+ 6. Lf1+ Dxf1#
5. ... d1=S 6. Sf2+ Sxf2#
5. ... d1=T+ 6. Lf1+ Txf1#
5. ... d1=L 6. Df3+ Lxf3#
play all play one stop play next play all
Korrektur in 04-06/2008, Seite 255.
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-09-20)
comment
Keywords: Allumwandlung, unechte schwarze
Genre: s#
FEN: 8/B7/BR4N1/5N2/3p3P/8/5k1p/3Q3K
Input: Frank Müller, 2011-06-03
Last update: Marcin Banaszek, 2020-09-21 more...
6 - P1226153
Erich Ernst
3214 Badische Neueste Nachrichten 11/06/1994
P1226153
(10+5) cooked
#3
1. Lxe6! (2. c8=S+ 3. Le7#)
1. Lxe6! fxe6 2. c8=T
1. Lxe6! fxg6 2. c8=L
1. Lxe6! f5 2. c8=S+
1. Lxe6! f6 2. c8=D
play all play one stop play next play all
Rosalie Fay: 1 ... f5 doesn't parry the threat. 1 ... fxg6 2 c8=B/Sf8 both work, so this line is dualistic. So no Pickaninny and no AUW. (2020-09-26)
A.Buchanan: I've been meaning to ask about threats, and here's a good chance. They are a cool shorthand for many solutions, and some folks have invented themes about them. But (as here) they destroy the logic of many problems where Black has a limited choice of moves, so we shouldn't apply them robotically, imho.
One obvious case is that in a problem where *every* Black move counters the threat, the threat is meaningless. Another obvious case is if it only counters one Black move, then it's kind of lame and again meaningless as shorthand. So unless there is an artificial theme declared with the solution, a threat should not be given unless it works against at least two Black moves.
Here every Black play except for 1... f5 defeats the "threat". Even 1... Kc5 which leads to the short solution 2. Le7# also refutes 2. c8=S. There *is* a theme AUW/Pickaninny, but the symmetric expression of this threatless theme is actually damaged by including a threat in the solution. (2020-09-27)
A.Buchanan: According to the Codex, a directmate or selfmate is unsound if it is cooked [i.e. has a solution that differs in its first move from the author’s solution] or has a short solution or no solution. The gravity of defects such as unintended duals, or unintended multiple refutations of [intended] tries is a matter for a tourney judge.
One issue with PDB is that we do not have a "sound/unsound" field, nor even a keyword for this! But even a brutally dualized problem can never be classified as cooked, and this one is only mildly dualized. (2020-09-27)
A.Buchanan: I am not trying to be "kind to duals" here. They are defects, and I applaud Henrik's analysis of them. Since we are not running a tourney, could we imagine some formula based on the graph structure of the solution which will automatically give us a figure. E.g. dual-less = 0, any dual in 2nd move is twice as bad as a dual in 3rd move, etc? The length & breadth of the problem would has to be a factor. Can we construct an ideal solution, suppressing all duals, and come up with a comparison of that? E.g. sum(i=2..n) (d_i - s_i)/(2^i), where d_i & s_i are the number of dual moves & solution moves respectively occurring at the ith White move. (2020-09-27)
A.Buchanan: I agree with Rosie that 1 ... fxg6 2 c8=B/Sf8 is fatal to the intended AUW. Replacing wSh7 with sBf8 or wBg7g8 does restore AUW, but with an obvious cost. [Legality does not affect soundness, according to the Codex.] As discussed earlier, I think the problem is still Pickaninny as the threat is meaningless. (2020-09-27)
comment
Keywords: Allumwandlung, Pickaninny
Genre: 3#
FEN: N1B5/2P2p1N/3kp1R1/1P2p1B1/2P1p3/4P1K1/8/8
Input: Felber, Volker, 2011-12-02
Last update: James Malcom, 2020-09-26 more...
7 - P1245423
Andrey Selivanov
12739 Die Schwalbe 08/2005
P1245423
(11+2) C+
s#7
1. Te7! Kc6 2. f7+ Kc7 3. f8=S Kd8 4. Te8+ Kc7 5. d8=L+ Kc8 6. Tc6+ Txc6 7. Da6+ Txa6#
1. ... Kd8 2. La4 Kc7 3. Te8 Kd6 4. d8=T+ Kc7 5. Dc5+ Tc6 6. Ld2 Txc5 7. La5+ Txa5#
1. ... Kd6 2. d8=D+ Kc6 3. Da4+ Tb5 4. Tc7+ Kb6 5. Tb7+ Kc6 6. Da6+ Tb6 7. Tb8 Txa6#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-05)
comment
Keywords: Allumwandlung
Genre: s#
FEN: K7/2kP1R2/1r3P1R/Q4P2/3P1P2/8/8/2BB4
Input: Frank Müller, 2012-07-25
Last update: Marcin Banaszek, 2020-10-05 more...
8 - P1252301
G. Karlsson
Our Folder 08/1924
P1252301
(11+4) cooked
#3
1.b7 e5/e\x f6/e\x d6/e6
2.b8=D[S]/T/L/S
play all play one stop play next play all
Erich Bartel: Nachdruck:
1) Themes-64 (2) IV 1956 (2012-10-27)
Rosalie Fay: 1 ... e5 doesn't parry White's key's threats, and 1 ... e6 2 Sb6+/b8=S+ both work, so no Pickaninny.

No Black move uniquely forces 2 b8=S, so no AUW. (2020-09-26)
comment
Keywords: Allumwandlung, Pickaninny
Genre: 3#
FEN: B5Kb/P2kp1nR/1P1N1BR1/3N1P2/3P4/8/8/8
Input: Erich Bartel, 2012-10-27
Last update: James Malcom, 2020-09-27 more...
9 - P1273225
Jorma Pitkänen
A3 Problemkiste 08/2009
P1273225
(10+3) C+
s#9
1. g8=D+ Kd6 2. d8=T+ Kc6 3. a8=L+ Tb7 4. Dc4+ Tc5 5. c8=S Txc4 6. Se7+ Kc7 7. Tc8+ Kd6 8. Tc6+ Txc6 9. Sc8+ Txc8#
play all play one stop play next play all
Anton Baumann: C+ Gustav 4.1d (2020-11-13)
comment
Keywords: Allumwandlung, konsekutive Umwandlungen 4 (DTLS)
Genre: s#
FEN: 4K3/P1PP2PR/P3k3/r5R1/3B4/1r6/B7/8
Input: Frank Müller, 2013-06-26
Last update: Marcin Banaszek, 2020-11-18 more...
10 - P1277937
Mark Kirtley
George P. Sphicas

1801 U.S. Problem Bulletin 05-06/1989
P1277937
(15+6) C+
s#7
1. d6-d7! g6xf5 2. g7-g8=D h3-h2 3. h7-h8=T h2-h1=D 4. Th8xh1 d4-d3 5. d7-d8=L b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... b6-b5 5. a7-a8=S d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... d4-d3 4. d7-d8=L h2-h1=S 5. Th8xh1 b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... b6-b5 4. a7-a8=S h2-h1=D 5. Th8xh1 d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
2. ... d4-d3 3. d7-d8=L h3-h2 4. h7-h8=T h2-h1=S 5. Th8xh1 b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
2. ... b6-b5 3. a7-a8=S h3-h2 4. h7-h8=T h2-h1=D 5. Th8xh1 d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
1. ... h3-h2 2. h7-h8=T h2-h1=D 3. Th8xh1 d4-d3 4. d7-d8=L b6-b5 5. a7-a8=S g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... g6xf5 5. g7-g8=D b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... b6-b5 4. a7-a8=S d4-d3 5. d7-d8=L g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... g6xf5 5. g7-g8=D d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... g6xf5 4. g7-g8=D d4-d3 5. d7-d8=L b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... b6-b5 5. a7-a8=S d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
2. ... d4-d3 3. d7-d8=L h2-h1=D 4. Th8xh1 b6-b5 5. a7-a8=S g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... g6xf5 5. g7-g8=D b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... b6-b5 4. a7-a8=S h2-h1=D 5. Th8xh1 g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... g6xf5 5. g7-g8=D h2-h1=S 6. Th8xh1 d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... g6xf5 4. g7-g8=D h2-h1=S 5. Th8xh1 b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
2. ... b6-b5 3. a7-a8=S h2-h1=D 4. Th8xh1 d4-d3 5. d7-d8=L g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... g6xf5 5. g7-g8=D d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... d4-d3 4. d7-d8=L h2-h1=D 5. Th8xh1 g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... g6xf5 4. g7-g8=D h2-h1=D 5. Th8xh1 d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
2. ... g6xf5 3. g7-g8=D h2-h1=D 4. Th8xh1 d4-d3 5. d7-d8=L b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... b6-b5 5. a7-a8=S d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... d4-d3 4. d7-d8=L h2-h1=S 5. Th8xh1 b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... b6-b5 4. a7-a8=S h2-h1=D 5. Th8xh1 d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
1. ... d4-d3 2. d7-d8=L h3-h2 3. h7-h8=T h2-h1=D 4. Th8xh1 b6-b5 5. a7-a8=S g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... g6xf5 5. g7-g8=D b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... b6-b5 4. a7-a8=S h2-h1=D 5. Th8xh1 g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... g6xf5 4. g7-g8=D h2-h1=S 5. Th8xh1 b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
2. ... g6xf5 3. g7-g8=D h3-h2 4. h7-h8=T h2-h1=S 5. Th8xh1 b6-b5 6. a7-a8=S d3xc2 7. Dg8-e6+ Lc4xe6#
1. ... b6-b5 2. a7-a8=S h3-h2 3. h7-h8=T h2-h1=D 4. Th8xh1 d4-d3 5. d7-d8=L g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
4. ... g6xf5 5. g7-g8=D d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... d4-d3 4. d7-d8=L h2-h1=D 5. Th8xh1 g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
3. ... g6xf5 4. g7-g8=D h2-h1=D 5. Th8xh1 d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
2. ... d4-d3 3. d7-d8=L h3-h2 4. h7-h8=T h2-h1=D 5. Th8xh1 g6xf5 6. g7-g8=D d3xc2 7. Dg8-e6+ Lc4xe6#
2. ... g6xf5 3. g7-g8=D h3-h2 4. h7-h8=T h2-h1=D 5. Th8xh1 d4-d3 6. d7-d8=L d3xc2 7. Dg8-e6+ Lc4xe6#
play all play one stop play next play all
SCHRECKE: Unlösbar, eventuell fehlt ein wBf4. (2020-10-28)
A.Buchanan: Mark Kirtley wrote to me: George found the original issue of the U.S. Problem Bulletin, showed me, and yes, there is a wPf4 in the original. George and I couldn't remember why we also had a wPa2, but a new computer test (Gustav) showed us the reason: it guards against a major dual Rh1-a1 in some variations.
There is still a minor dual in some variations (of varying length) if the bP promotes to a Q at h1, for then wRh8-h6+, bQh1xh6, and wQe6+ and bQxe6#. (2020-11-11)
A.Buchanan: So I have corrected the confirmed diagram typo (2020-11-11)
comment
Keywords: Allumwandlung, konsekutive Umwandlungen 4 (DTLS)
Genre: s#
Computer test: Gustav 4.1c
FEN: 1BK1N3/P1P3PP/NpkP2p1/5Q2/1Rbp1P2/7p/P1RP4/8
Input: Frank Müller, 2013-09-18
Last update: Marcin Banaszek, 2020-11-12 more...
11 - P1287382
Martin Minski
3144v Freie Presse (Chemnitz) 09/11/1990
P1287382
(11+7)
#3
1. f7!
1. ... dxc6 2. fxe8=T Kd7 3. Txd8#
1. ... d6 2. fxe8=D d5,dxc5 3. Dxd8#,Dd7#
1. ... d5 2. fxe8=L Lc7,L~ 3. Ld7#
1. ... dxe6 2. fxe8=S Lc7,L~ 3. Lxe6#
1. ... Tf8 2. gxf8=D d6,d~3. Dxd8#
1. ... Tg8 2. fxg8=D d6,d~ 3. Dxd8#
1. ... Th8 2. gxh8=D d6,d~ 3. Dxd8#
play all play one stop play next play all
Korrekturfassung vom 11.01.1991 zu P1234674
Henrik Juel: Impressive problem by the recent study GM, but slightly damaged by the mate dual after 1... d6 (2020-11-17)
James Malcom: Even so, a Pickaninny+AUW with the Black king on the last rank is still further impressive! (2020-11-17)
comment
Keywords: Pickaninny, Allumwandlung
Genre: 3#
FEN: Rnkbr3/1N1pp1P1/P1P1NP2/2P4p/3P3K/8/B7/8
Input: Felber, Volker, 2014-08-26
Last update: James Malcom, 2020-11-16 more...
12 - P1288815
Theodor Steudel
B20 Problemkiste (110) 04/1997
2. Lob, 16. PK-KT
Richter: Hans Gruber
P1288815
(8+4) C+
h=2
0.8.1.1
Madrasi
Cavalier Majeur
wSR=Kamelreiter
wSL=Antilope
wLL=Rose
wLR=Wurzel-50-Springer
1) 1. ... c8=D 2. b1=D+ Dg6=
2) 1. ... c8=T 2. b1=T+ Tc1=
3) 1. ... c8=L 2. b1=L Lf5=
4) 1. ... c8=N 2. b1=N Ne7=
5) 1. ... c8=CR 2. b1=CR CRe2=
6) 1. ... c8=AN 2. b1=AN ANf4=
7) 1. ... c8=RO 2. b1=RO+ ROd6=
8) 1. ... c8=W5 2. b1=W5 Dc6=
play all play one stop play next play all
Auf die Spitze getriebener Task (die im Anhang gedruckten Zwischenstufen mit 5-7 Umwandlungen bringen nichts Neues, sondern sind eher Konstruktionsskizzen auf dem Weg zur Achtfachsetzung). Die verwendeten Motive sind immer die gleichen (und dadurch, dass eine Geschichte öfter erzält wird, wird sie nicht unbedingt besser); die Bedingung "`Cavalier Majeur"' ist ein Taschenspielertrick, um den Ärger mit der lästigen Springerumwandlung zu vermeiden. Die achtfache Synchronumwandlung mit nur 12 Steinen ist aber dennoch sehenswert (Richter HG)
James Malcom: A neat multi-piece fairy. (2020-11-27)
comment
Keywords: Allumwandlung, Babson task, Madrasi, Cavalier majeur
Pieces: sr = Camelrider (CR), sl = Antelope (AN), ll = Rose (RO), lr = Root-50-leaper (W5)
Genre: Fairies
FEN: q3Q3/2P5/5*3N2/1K2*1B1*1N1/8/P7/kp6/r2*3B4
Input: Erich Bartel, 2014-10-03
Last update: Alfred Pfeiffer, 2014-10-04 more...
13 - P1289460
Michel Caillaud
10360 Sachova skladba 10/2010
3. Lob
P1289460
(11+3) C+
s#9
1. d8=T Lg7 2. f8=S+ Lxf8 3. Te8+ Le7 4. c7 Kd7 5. c8=L+ Kxe8 6. h8=D+ Lf8 7. Sd6+ Kd8 8. Dxf6+ Le7 9. Lb1 Lxf6#
play all play one stop play next play all
more ...
comment
Keywords: Allumwandlung, konsekutive Umwandlungen 4 (TSLD)
Genre: s#
Computer test: Gustav 4.1d
FEN: 7b/R2P1P1P/2P1kpP1/5N2/4BP2/8/P7/K7
Input: Frank Müller, 2014-10-20
Last update: James Malcom, 2020-11-13 more...
14 - P1289812
Olaf Jenkner
1453 Schach in Schleswig-Holstein 10/2014
P1289812
(10+2) C+
s#8
1. c7 Ke6 2. f8=S+ Kd6 3. c8=L Kc5 4. Dd4+ Kb5 5. Db4+ Ka6 6. b8=T Ka7 7. Dd4+ Kxb8 8. Sc6+ Sxc6#
1. ... Kc5 2. Dd4+ Kb5 3. b8=D+ Ka6 4. Db5+ Kxb5 5. Db4+ Ka6 6. c8=L+ Ka7 7. Db8+ Kxb8 8. Sc6+ Sxc6#
play all play one stop play next play all
„Die Variante 1. … Kc5 mit origineller Beseitigung der störenden Masse des weißen Bauerns auf b7 und zwei Damen-opfern finde ich ganz witzig. Das zweite Abspiel bietet noch eine Springer- und Turmumwandlung, wiederholt aber auch viele Züge der ersten Variante“ (Stephen Rothwell).
„Nur durch erstaunlich viele Unterverwandlungen kommt man zum Ziel“ (Claus Grupen)
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comment
Keywords: Allumwandlung (verunglückte)
Genre: s#
FEN: 3KB3/1P1P1P2/2Pk1N2/N3n3/R4Q2/8/8/8
Input: Frank Müller, 2014-10-31
Last update: Olaf Jenkner, 2020-11-23 more...
15 - P1292289
Felix Alexander Sonnenfeld
855 Phénix 12/1990
P1292289
(7+9)
ser-r#8
1. axb8=L (dxe8=D?) 2. dxe8=D 3. Dh8 4. e8=T 5. Te4 (Dxh5?) 6. Dxh5 7. Lf4 (Df3?) 8. Df3 d1=S#
play all play one stop play next play all
Anton Baumann: C+ Alybadix (2020-11-19)
comment
Keywords: Series mover, Allumwandlung
Genre: Fairies
FEN: kn2n3/P2PPp2/5bp1/7p/8/2pPK3/2PpP3/8
Input: Erich Bartel, 2014-12-12
Last update: Alfred Pfeiffer, 2014-12-13 more...
16 - P1292295
Ivan Skoba
Sachove umeni 1982
P1292295
(8+3)
ser-r#12
1. f8=L 2. h8=D 3. Dd4 4. b8=S 5. a8=T 6. Ta5 7. Tb5 8. Ka5 9. Da4 10. c6 11. Lb4 12. Sa6 Sc4#
play all play one stop play next play all
Anton Baumann: C+ Alybadix (2020-11-16)
comment
Keywords: Series mover, Allumwandlung
Genre: Fairies
FEN: 3k4/PP1P1P1P/7P/2Pp4/K7/n7/8/8
Input: Erich Bartel, 2014-12-12
Last update: Alfred Pfeiffer, 2014-12-13 more...
17 - P1292298
Drago Biscan
4025 feenschach 68 12/1983
4. ehrende Erwähnung
Richter: Bernd Ellinghoven
P1292298
(10+7)
ser-r#8
1. b8=L 2. c8=S 3. Sb6 4. d8=D 5. Dxg8 6. Dxh7 7. g8=T 8. Tg1 Txh7#
play all play one stop play next play all
Anton Baumann: C+ Alybadix (2020-11-14)
comment
Keywords: Series mover, Allumwandlung
Genre: Fairies
FEN: 6n1/rPPP2Pp/P2RP3/k7/P2Qp3/2p5/8/4n2K
Input: Erich Bartel, 2014-12-12
Last update: Alfred Pfeiffer, 2014-12-13 more...
18 - P1292304
P. Darne
André Simonet

828 Probleemblad 11-12/1983
P1292304
(8+8) cooked
ser-r#25
1. h8=S 2. Sxg6 3. Sf4 4. g6 5. g7 6. g8=L 7. Lxe6 8. Lxg4 9. Lc8 10. g4 11. g5 12. g6 13. g7 14. g8=D 15. Dxd5 16. Df7 17. d5 18. d6 19. d7 20. d8=T 21. Td2 22. Lg4 23. Ld1 24. Se2 25. Df1 cxd2#
play all play one stop play next play all
Anton Baumann: cook: NL mit vielen Varianten (ZU): 1.h8=S 2.Sxg6 3.Se7! 4.Sxd5 5.Sf4 6.d5 7.dxe6 9.e8=L 12.g8=D 13.Dxg4 14.Df5 19.g8=D 20.D8d5 21.Dd2 22.Lh5 23.Ld1 24.Se2 25.Df1 cxd2# (2020-11-18)
comment
Keywords: Series mover, Allumwandlung, Kindergarten Problem
Genre: Fairies
FEN: 8/1p5P/k3p1p1/P2p2P1/P2P2p1/2p1p1P1/6P1/4K3
Input: Erich Bartel, 2014-12-12
Last update: Olaf Jenkner, 2020-11-18 more...
19 - P1292307
Branko Koludrovic
6968 feenschach 119 01-09/1996
1. Preis
Richter: G. P. Sphicas
P1292307
(6+7)
ser-r#24
1. a8=T 2. Txa6 3. Tc6 4. a6 5. axb7 6. b8=L 7. Kb7 8. c8=S 9. Le5 10. Lxg7 11. Lf8 12. g7 13. g8=T 14. Txg5 15. Tb5 16. g5 17. g6 18. g7 19. g8=D 20. Dg3 21. Db8 22. Ld6 23. Kc7 24. Tb7 Sd5#
22. Kc7? 23. Sd6#
13. g8=D? 14. Dxg5 15. De7#
8. c8=L? 9. Le5 10. Lxg7 11. Lf8 12. g7 13. g8=T 14. Txg5 15. Tb5 16. g5 17. g6 18. g7 19. g8=D 20. Ld6#
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Branko Koludrovic: There must be added black Pc6,on the diagram and (6+8) with the same solution.
The following(reflex#) tries can be cited:
1---8.c8L?---19.g8D Ld6#!
--13.g8D? 14. Dxg5 De7#!
--22.Kc7? 23.Sd6#! (2014-12-12)
Anton Baumann: ohne sBc6 NL 1.Kxb7
mit sBc6: C+ Alybadix (2020-11-16)
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comment
Keywords: Series mover, Allumwandlung
Genre: Fairies
FEN: 2K1k3/PrP3p1/p5P1/P5p1/4p1P1/2n5/8/8
Reprints: feenschach 143, p. 234, 08-10/2001
Input: Erich Bartel, 2014-12-12
Last update: Alfred Pfeiffer, 2014-12-13 more...
20 - P1292424
Theodor Steudel
L) Suomen Tehtäväniekat 29/06/1994
P1292424
(5+5)
h#4
b) h=4
a) 1. f1=T b6 2. Tc1 b7 3. Tc5 b8=S 4. Tb5 Sc6#
b) 1. f1=L b6 2. Lh3 b7 3. Lhd7 b8=D+ 4. Ldb5 Db6=
play all play one stop play next play all
Anton Baumann: C+ Gustav 4.1d (2020-11-25)
comment
Keywords: Allumwandlung, Thema Argentino
Genre: Fairies
FEN: 8/8/8/1P1p4/bk1P1P2/1p1P4/1K3p2/8
Input: Erich Bartel, 2014-12-14
Last update: Alfred Pfeiffer, 2014-12-15 more...
21 - P1294155
Ivan Soroka
470 KoBulChess 04/12/2014
P1294155
(6+3) C+
s#7
1. h8=D+ Kg6 2. f8=S+ Kf7 3. e8=L+ Ke7 4. Dg7+ Kd6 5. Dbe5+ Kc6 6. d8=T+ Kb6 7. Db7+ Dxb7#
play all play one stop play next play all
more ...
comment
Keywords: konsekutive Umwandlungen 4 (DSLT), Allumwandlung
Genre: s#
Computer test: SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-25)
FEN: 2K5/3PPP1P/7k/1Q6/7n/8/8/7q
Input: Frank Müller, 2015-01-05
Last update: Erich Bartel, 2020-10-26 more...
22 - P1310337
Ivan Soroka
48 Gravure 2015
Spezielle ehrende Erwähnung
P1310337
(6+3) C+
s#7
1. g8=D+ Kh6 2. f8=L+ Dg7 3. h8=T+ Kg6 4. e8=D+ Kf6 5. Def7+ Dxf7 6. Dgg5+ Ke6 7. Dd7+ Dxd7#
1. ... Kf6 2. e8=S+ Ke6 3. f8=D+ Dxg8 4. Sg7+ Dxg7 5. Dff5+ Kd6 6. Db4+ Kc6 7. Dd7+ Dxd7#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-11-15)
comment
Keywords: konsekutive Umwandlungen 3 (DSD), konsekutive Umwandlungen 4 (DLTD), Allumwandlung
Genre: s#
FEN: 3K4/4PPPP/6k1/1Q6/8/6q1/8/3b4
Input: Frank Müller, 2015-10-03
Last update: Marcin Banaszek, 2020-11-18 more...
23 - P1321264
Torsten Linss
Z562 Probleemblad 04-06/2016
2. Preis
P1321264
(5+2) C+
a) s#8
b) r#8
a) 1. c8=T+ Kd5 2. a8=D+ Kd6 3. Td8+ Kc7 4. Daa7+ Kc6 5. Dh6+ Tg6 6. Db7+ Kc5 7. De3+ Kc4 8. Da6+ Txa6#
b) 1. Tb4+ Kd5 2. a8=L+ Kd6 3. c8=S+ Kd7,Kc7 4. De7+ Kxc8 5. De8+ Kc7 6. Tb7+ Kd6 7. Td7+ Kc5 8. Ka5 Ta3#
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Anton Baumann: C+ Alybadix (2020-11-16)
comment
Keywords: Stipulation change, Allumwandlung
Genre: r#, s#
FEN: 1R6/P1P5/8/8/K1k5/4Q1r1/8/8
Input: Frank Müller, 2016-06-12
Last update: Marcin Banaszek, 2020-11-18 more...
24 - P1375825
Marcin Banaszek
S2796 The Problemist 27-8, p. 308, 03/2020
P1375825
(11+3) C+
s#10
1. Le4!
1. ... e1=D 2. Tb3+ Ka4 3. Lc6+ Ka5 4. Dc7+ Kxa6 5. Db7+ Ka5 6. Tb5+ Ka4 7. Da7+ Da5 8. Dd4+ Db4 9. Tc5+ Ka3 10. Db2+ Dxb2#
1. ... e1=L 2. Tc4+ Lb4 3. Tc3+ Ka4 4. Td4! Ka5 5. Dc7+ Kxa6 6. Db7+ Ka5 7. Sb3+ Ka4 8. Lb1! Ka3 9. Sc5+ Lxc3+ 10. Db2+ Lxb2#
1. ... e1=S 2. Tb1+ Ka4 3. Dd7+ Ka5 4. Sb3+ Kxa6,Kb6 5. Dc6+ Ka7 6. Dc7+ Ka6 7. Td6+ Kb5 8. Sd4+ Ka4 9. Lc6+ Ka3 10. Sc2+ Sxc2#
1. ... e1=T 2. Tb3+ Ka4 3. Ta3+ Kb5 4. Db7+ Kc4 5. Td4+ Kxd4 6. Ta4+ Kc3 7. Db3+ Kd2 8. Td4+ Kxc1 9. De3+ Txe3 10. La3+ Txa3#
play all play one stop play next play all
Nebenuntervarianten nach 1. ... e1=L 2. Tc4+ Lb4 3. Tc3+ Ka4 4. Td4! Ka5 5. Dc7+
5. ... Kb5 6. Db7+ Ka4 7. Sb3 Ka3 8. Lb1 Lc5 9. Db4+ Lxb4 10. Sc5+ Lxc3#
6. ... Ka4 7. Sb3 Ka3 8. Lb1 Lc5,L~ 9. Db4+ Lxb4 10. Sc5+ Lxc3#
oder 7. Lb1 Ka5 8. Sb3+ Ka4 9. Dc6+,Dd7+ Ka3 10. Sc5+ Lxc3#
5. ... Ka4 6. Db7 Ka5 7. Sb3+ etc. =Hauptvariante, oder 6. Lb1 Kb5 7. Db7+ Ka4 8. Sb3 etc. =Hauptvariante oder
7. ... Ka5 8. Sb3+ Ka4 9. Dc6+,Dd7+ Ka3 10.Sc5+ Lxc3#
Nach 4. ... Kb5 5. Db7+ Ka4 6. Lb1 Ka5 7. Sb3+ Ka4 8. Dc6+ Ka3 9. Sc5+ Lxc3#

Erste schwarze Allumwandlung im Selbstmatt in zehn Zügen.
Weiße Batteriespiele (7), weiße Linienverstellungen (4), Mustermatts (3).
Zwischen Varianten 1...e1=D und 1...e1=L ein Spielwechsel nach dem Marsch und Rückkehr des schwarzen Königs (a3-a6-a3), dazu Verstellungswechsel auf c5 und Mattwechsel auf b2.
In der Variante 1...e1=S ein Marsch und Rückkehr des schwarzen Königs (a3-a7-a3) und Linienverstellungen auf d6 und c6.
In der Variante 1...e1T ein Marsch des schwarzen Königs von a3 zu anderem Oppositionsfeld c1 und vier weiße Figurenopfer. (Autor)
First black AUW in a S#10 (Composer).
Marcin also notes: “long bK marches in each variation, three times returning to a3 having visited a6 or a7, and, after 1…e1R, finishing at the echoed opposition square c1”.
Masterly problem! Bravo Marcin! (RL)
A top-level problem! (JP)
SCHRECKE: Nach 1. ... e1L 2.Tc4+ Lb4 3.Tc3+ Ka4 4.Td4 Ka5! 5.Dc7+ geht's aber unsauber zu.
Es existiert das völlig gleichwertige 5. ... Ka4, worauf 6.Db7 Ka5 7.Sb3+ Ka4 8.Lb1 Ka3 9.Sc5+ L:c3+ 10.Db2+ L:b2# geschieht.
Allerdings geht auch dualistisch:
6.Lb1 Kb5 7.Db7+ Ka4 8.Sb3 Ka3 9.Sc5+ L:c3+ 10.Db2+ L:b2#
7. ... Ka5 8.Sb3+ Ka4 9.Dc6+,Dd7+ Ka3 10.Sc5+ L:c3#
Nach 5. ... Kb5 6.Db7+ Ka4 geht auch der ZU-Dual 7.Lb1 Ka5 8.Sb3+ ...
Mir gefallen diese Niedlichkeiten aber nicht - Kodex hin, Kodex her !! (2020-09-20)
comment
Keywords: Allumwandlung, black (10)
Genre: s#
Computer test: O. Jenkner: Gustav 4.1 d
FEN: 3R1B2/7Q/P3p3/4P3/1R3P2/k7/2B1pP2/K1N5
Input: Marcin Banaszek, 2020-05-11
Last update: Felber, Volker, 2020-11-23 more...
25 - P1379460
Joost de Heer
F190 Problemesis 35 2003
P1379460
(6+4) cooked
ser-!=24
1. b3 2. e7 3. exf8=S 4. Se6 5. Sd8 6. c8=D 7. Dxc3 8. Dh8 9. c4 10. b4 11. b5 12. b6 13. b7 14. b8=T 15. Tb7 16. Tg7 17. Sf7 18. c5 19. c6 20. c7 21. c8=L 22. Lf5 23. Lh7 24. g6!=
play all play one stop play next play all
Cook: 1. b4 2. b5 3. b6 4. b7 5. b8=S 6. Sc6 7. Sd8 8. c8=T 9. Txc3 10. Tc7 11. c4 12. c5 13. c6 14. Tg7 15. c7 16. c8=L 17. Sf7 18. e7 19. exf8=S 20. Lf5 21. Lh7 22. Sg6 23. Sgh8 24. g6!=
1. bxc3 2. c4 3. c5 4. c4 5. c6 6. e7 7. exf8=S 8. Se6 9. Sd8 10. c8=D 11. c7 12. Dh3 13. Dh8 14. c8=T 15. Tc7 16. Tg7 17. Sf7 18. c5 19. c6 20. c7 21. c8=L 22. Lf5 23. Lh7 24. g6!=
Joost de Heer: Vaclav, is this correct with b2 on b3 and ser-!=23? I wanted to add the first move to get an extra unpin. (2020-10-01)
comment
Keywords: Series mover, Allumwandlung
Genre: Fairies
Computer test: V. Kotesovec: cooks found by Gustav 4.1 d 64 Bit (Lösezeit: 08 : 11 : 56 : 47,12 d, Hashtables: 53247 MB)
FEN: 4knK1/2P5/4P3/6P1/8/2b5/bPP5/8
Input: Vaclav Kotesovec, 2020-08-29
Last update: Vaclav Kotesovec, 2020-09-04 more...
26 - P1380170
Nikolay N. Akimov
41 64 - Shakhmatnoe obozrenie 05/2020
P1380170
(3+4) C+
#3
1. Tf1! Lh7 2. Dxh7 droht 3. Db1#,Dg8#,Df7#
2. ... b1=D,T,L,S+ 3. Dxb1#
1. ... Lg6 2. Dg8+ Lf7 3. Dxf7#
1. ... Lf5 2. Dg8+ Le6 3. Dxe6#
1. ... Le4 2. Dg8+ Ld5 3. Dxd5#
1. ... Ld3 2. Dg8+ Lc4 3. Dxc4#
1. ... Lc2 2. Dg8+ Lb3 3. Dxb3#
1. ... Ka1 2. Kb3 a2 3. Dxb2#
play all play one stop play next play all
more ...
comment
Keywords: Allumwandlung, unechte schwarze
Genre: 3#
Computer test: Popeye 4.61
FEN: 7Q/8/8/8/8/p1K5/kp3R2/1b6
Input: Rainer Staudte, 2020-09-22
Last update: Alfred Pfeiffer, 2020-09-23 more...
27 - P1380294
Rudolf Reussel
Illustrierte Kronen Zeitung 27/12/1933
P1380294
(10+10) cooked
#29
1. Th2+! Kf3 2. Tf2+ Kg4 3. Tf4+ Kh5 4. Th4+ Kg6 5. Th6+ Kf7 6. Tf6+ Ke8 7. Tf8+ Kd7 8. Td8+ Kc6 9. Td6+ Kb5 10. Tb6+ Kc4 11. Tb4+ Kd3 12. Td4+ Kc2 13. Td2+ Kb3 14. Ta3+ Kc4 15. Td4+ Kb5 16. Tb4+ Kc6 17. Tb6+ Kd7 18. Td6+ Ke8 19. Td8+ Kf7 20. Tf8+ Kg6 21. Tf6+ Kh5 22. Th6+ Kg4 23. Th4+ Kf3 24. Tf4+ Kg2 25. Tf2+ Kg1 26. Th2+ Kxf1 27. Tf2+ Kg1 28. Ta1+ e1=D,T,L,S 29. Txe1#
play all play one stop play next play all
Der Führer der schwarzen Heerscharen ist im Verlauf des Kampfgetümmels von seinen Getreuen getrennt worden und befindet sich nunmehr zu seinem Entsetzen inmitten seiner blutgierigen Feinde. Tollkühn zieht der Held sein Schwert, um sich den Rückweg zu den Seinen zu erkämpfen. Da wird er von hinten von einem schwer bewaffneten Ritter angefallen, der, auf einem weißen Mustang reitend, die edle Beute lebend fangen will. Das Königspferd bekommt die Sporen und nun entspinnt sich folgende Hetzjagd auf Leben und Tod:
1. Th2+ Kf3 2. Tf2+ Kg4 3. Tf4+ Kh5 4. Th4+ Kg6 5. Th6+ Kf7 6. Tf6+ Ke8.
Mit keuchendem Atem flüchtet der König in bebuschtes Terrain ...
7. Tf8+ Kd7 8. Td8+ Kc6, doch auch hier findet er keinen Schutz, da ihm sein besser berittener Widersacher stets dicht auf den Fersen ist, 9. Td6+ Kb5 10. Tb6+ ... der ihm den Rückzug zum eigenen Lager blitzschnell verwehrt.
10. ... Kc4 Mit 'verkehrter Direktion' wird die Hetzjagd im Eilzugtempo fortgesetzt.
11. Tb4+ Kd3 12. Td4+ Kc2 13. Td2+ Kb3 14. Ta3+ ...
Der Lanzenstich eines neuen Feindes scheucht den armen Gehetzten nun wieder ins Getümmel der Feldschlacht zurück!
14. ... Kc4 15. Td4+ ... Wo er von seinem alten Verfolger mit Sehnsucht erwartet wird.
15. ... Kb5 16. Tb4+ Kc6 17. Tb6+ Kd7 18. Td6+ Ke8. 'Die hohle Gasse schein´ ich zu kennen, mein Rößlein, laß uns weiter rennen!'
19. Td8+ Kf7 20. Tf8+ Kg6 21. Tf6+ Kh5 22. Th6+ Kg4 23. Th4+ Kf3 24. Tf4+ Kg2. Am alten Standplatz wieder, der König das Schwert in die Erde rammt: 'A so ein Leben ist eh nix mehr wert, habt´s mi gern miteionander, i stürz´ mi ins Schwert!'
25. Tf2+ Kg1 26. Th2+ Kxf1 27. Tf2+ Kg1 28. Ta1+ e1=D 29. Txe1#
Dem Kunax voll Mut und ohne Bangen, ihm ist nun die Puste ausgegangen.!"
Cook: 3. Sh2+! Kxg3! 4. Tg1+ Kh4 5. Tf4+ Kh5! 6. Tf5+ Tg5! 7. Tgxg5+ Kh6 8. Tg1+ Kh7 9. Th5#
3. ... Kh5? 4. Tf5+ Tg5! 5. Txg5+ Kh6 6. Sg4+ Kh7 7. Sf6+ Kh8,Kh6 8. Txg8#
Motto: "Schön is so a Ringelspiel! Oder: 'Man steigt nach!'"
Diagramm und glossierte Lösung ohne konkrete Forderung abgedruckt (#29 muß also nicht stimmen)
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comment
Keywords: Allumwandlung, unechte schwarze, Checking key
Genre: n#
FEN: qbN3b1/1pn1P1r1/8/4K3/p7/2P1B1Pp/1P2p1k1/R4N1R
Input: Mario Richter, 2020-09-26
Last update: Alfred Pfeiffer, 2020-10-02 more...
28 - P1380357
Hannes Baumann
14969 Schweizerische Schachzeitung 02/2014
P1380357
(6+1) C+
#4
b)wBc6->a6 #3
c)+wSe5 #3
d)+wBa3 #3
a) 1. c8=D,T? patt
1. La8? Ka6!
1. Lc8! Ka8 2. La6 Ka7 3. c8=T Kxa6 4. Ta8#

b) 1. c8=S+! Kb8 2. Se7 Ka7 3. Sc6#

c) 1. c8=L! Kb8 2. c7+ Ka7 3. Sc6#

d) 1. La6! Kxa6 2. c8=D+ Ka5 3. Da8#
2. ... Ka7 3. Db7#
1. ... Ka8 2. c8=D+ Ka7 3. Db7#
play all play one stop play next play all
Vorgänger: P1143924

Duplicate Diagram: P1143924, P1143924

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comment
Keywords: Rex solus (s), under-promotion in the key (S,L), Allumwandlung
Genre: 3#, n#
Computer test: Popeye 4.61
FEN: 8/kBPK4/2P5/2P5/2P5/8/8/8
Input: Rainer Staudte, 2020-09-27
Last update: Alfred Pfeiffer, 2020-10-02 more...
29 - P1380946
Olaf Jenkner
8737 Phénix 306/307 2020
P1380946
(6+2) C+
s#9
1. c8=D! e1=D 2. Dd3+ De3 3. Df1+ Df2 4. Sd2+ Ke3 5. Te4+ Kxd2 6. Dcc4 De2 7. Tf2 Dxf2 8. Da2+ Kc3 9. Db2+ Dxb2#
1. ... e1=T 2. Dc6+ Te4 3. Dd1+ Ke3 4. Dc5+ Td4 5. Sd2 Kd3 6. Sc4+ Kc3 7. Df3+ Td3 8. Da5+ Kb3 9. Dd1+ Txd1#
1. ... e1=L 2. Dd5+ Ke3 3. Dc1+ Ld2 4. Df5 Lxc1 5. T4g3+ Kd4 6. Td3+ Kc4 7. Tc2+ Kb4 8. Td4+ Kb3 9. Tb2+ Lxb2#
1. ... e1=S 2. Ddc3+ Sd3 3. Ta2 Ke3 4. Dd4+ Kf3 5. Sd2+ Ke2 6. Te4+ Kd1 7. Dg4+ Kc1 8. Dc5+ Sxc5 9. Sb3+ Sxb3#
play all play one stop play next play all
Vier Mustermatts
Iwan Soroka: Großartig! (2020-10-15)
Mirko Degenkolbe: Eine sensationelle Aufgabe!!
Sie ist noch einen Tick besser als das Goldstück vom 8.FIDE WORLD CUP.
Der Autor hatte mir dieses Meisterwerk vorab gezeigt und ich kann immer noch nicht so recht glauben, dass das alles genauso funktioniert, wie es angedacht ist.
Fantastisch! (2020-10-15)
Gerald Ettl: In der Laenge eine AUW eindeutig zu zeigen war sicherlich nicht leicht. Das Goldstück vom World Cup kenne ich nicht. Ist die auch hier in der Datenbank zu sehen? (2020-10-15)
SCHRECKE: siehe: P1377975 (2020-10-16)
comment
Keywords: Allumwandlung, black (9)
Genre: s#
Computer test: O. Jenkner: Gustav 4.1 d
FEN: 8/2P5/8/8/6R1/5k2/3Qp1R1/KN6
Input: Olaf Jenkner, 2020-10-15
Last update: Alfred Pfeiffer, 2020-10-15 more...
30 - P1381247
Juan Carbo y Batlle
6 La Corona (Barcelona) 27/10/1860
P1381247
(8+2)
#4
1. Te1+ Kxd5 2. Le5 hxg2 3. Sg6 g1=D 4. Se7#,Sf4#
play all play one stop play next play all
Scan undeutlich, Feld c6 und a2 nicht sicher
Henrik Juel: Mate dual, also 4.Sf4# (2020-10-23)
comment
Keywords: Checking key, Allumwandlung, unechte schwarze
Genre: n#
FEN: 7N/8/8/1K1R1P2/4k3/7p/P5PB/R7
Input: Mario Richter, 2020-10-23
Last update: Alfred Pfeiffer, 2020-10-23 more...
31 - P1381602
Milomir Babic
8358 Phénix 290-291 11-12/2018
P1381602
(12+6) cooked
s#11
1. a8=D! Kc6 2. c8=T+ Kd5 3. Da1 b6 4. f8=L bxc5 5. Tf7 Kxd6 6. e8=S+ Kd5 7. Dd4+ cxd4 8. Ld6 d3 9. Te7 d2 10. Sf6+ Kxd6 11. Te6+ dxe6#
play all play one stop play next play all
Cook: 4. e8=S! bxc5 5. Dd4 cxd4 6. f8=T d3 7. T6f7 d2 8. Te7 d1=D 9. Sf6+ Kxd6 10. Te6+ dxe6#
Siehe neue Version: P1381646
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comment
Keywords: Allumwandlung (DTLS), konsekutive Umwandlungen 4
Genre: s#
FEN: 8/PpPpPP2/3N1RN1/1pPk1KP1/1pr5/1B6/8/6B1
Input: Marcin Banaszek, 2020-11-07
Last update: Marcin Banaszek, 2020-11-09 more...
32 - P1381646
Milomir Babic
8358v Phénix 301-302 11-12/2019
1. ehrende Erwähnung
P1381646
(12+7) C+
s#9
1. c7-c8=T+! Kc6-d5 2. f7xe8=L b7-b6 3. h7-h8=D b6xc5 4. Dh8-f6 c5xd4 5. Le8-g6 d4-d3 6. Df6-g5 Kd5xd6 7. e7-e8=S Kd6-d5 8. Se8-f6+ Kd5-d6 9. Te1-e6+ d7xe6#
play all play one stop play next play all
Version zu: P1381602
PR Yves Tallec 04-05/2020
SCHRECKE: Das ist ein s#9!
C+, Gustav 4.1d, Brute Force
Umwandlungsläufer sLe8! (2020-11-09)
comment
Keywords: Checking key, under-promotion in the key, Model mate, Selfblock, Allumwandlung, Pawn mate, Obtrusive material, konsekutive Umwandlungen 4 (TLDS)
Genre: s#
Computer test: Gustav 4.1c
FEN: 4b3/1pPpPP1P/2kP4/1pP2K2/1prP4/1B6/3P4/B3R3
Input: Marcin Banaszek, 2020-11-09
Last update: James Malcom, 2020-11-09 more...
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Felber, Volker (3)
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