Die Schwalbe

7 problem(s) found in 3031 milliseconds (displaying 7 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND K='Allumwandlung' AND S='U.S. Problem Bulletin'] [download as LaTeX]

1 - P0577106
Michel Caillaud
2948 U.S. Problem Bulletin 1994
S. Pantazis gewidmet
1. Preis,Richter: H.P.Rehm
P0577106
(10+11)
h=4
b) sKa3 nach a4
Circe
a) 1. b1=L dxe8=S[+sSg8] 2. La2 hxg8=D 3. Txg8[+wDd1] f8=T 4. Tfxf8[+wTa1] exf8=L=
b) 1. Kb5 dxe8=L[+sSg8]+ 2. Ka6 hxg8=S 3. Txg8[+wSb1] f8=D 4. Tfxf8[+wDd1] exf8=T=
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Henrik Juel: Beautiful problem with fine twinning showing two white all-promotions, cyclicly shifted (SDTL in a), LSDT in b)).
Testing with Popeye was too slow for me (2012-05-06)
Anton Baumann: C+ Alybadix (2021-02-16)
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comment
Keywords: Circe, Allumwandlung
Genre: Fairies
FEN: 2K1nr1b/3PPPnP/4pr2/4Pp1p/1P1B1P1P/k7/1p1p4/8
Input: Felber, Volker, 2000-01-04
Last update: Erich Bartel, 2015-01-12 more...
2 - P1112253
Bo Lindgren
5104 feenschach 83 04-06/1987
Walter Jörgensen zum 70. Geburtstag
1. Preis Informalturnier
P1112253
(9+10) cooked
ser-s#42
1. e8=S 2. Sxf6 3. Sd5 4. f6 5. f7 6. f8=D 7. Dxf3 8. Dg2 9. f4 10. f5 11. f6 12. f7 13. f8=L 14. Lxh6 15. Le3 16. h6 17. h7 18. h8=T 19. Txh4 20. Te4 21. h4 22. h5 23. h6 24. h7 25. h8=D 26. Dxb8 27. De5 28. b8=L 29. Lxa7 30. Lc5 31. a7 32. a8=T 33. Txa4 34. Tb4 35. a4 36. a5 37. a6 38. a7 39. a8=S 40. Sab6 41. Sc4 42. Dxe2+ Sxe2#
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Preisbericht (Gruppe 8 = "Rest") siehe feenschach 10/1990, S. 368.
Doppelte AUW in einem langzügigen Serienzugselbstmatt, da kann man nur mit Mutter Kempowski sagen: "Wie isses nur möglich!". Kein Wort, nur tief durchatmen und staunen! (Preisrichter Theodor Steudel).
Cook: 1. e8=S 2. Sxf6 3. Se4 4. Sd2 5. f6 6. f7 7. f8=D 8. Dxf3 9. Dxe2 10. f4 11. f5 12. f6 13. f7 14. f8=L 15. Lxh6 16. Le3 17. h6 18. h7 19. h8=T 20. Txh4 21. Te4 22. h4 23. h5 24. h6 25. h7 26. h8=D 27. Dxb8 28. De5 29. b8=L 30. Lxa7 31. Lc5 32. a7 33. a8=T 34. Txa4 35. Tb4 36. a4 37. a5 38. a6 39. a7 40. a8=L 41. Ld5 42. Sc4+ Sxe2# mit Dualen (Arnold Beine)
Erich Bartel: Ein Wahnsinnsproblem!!! (2012-06-13)
Arnold Beine: Leider kaputt, denn am Ende kann man das Selbstmatt auch mit einem Batterieschach erzwingen. Die thematisch vergleichbare P1278403 hat aber gute Chancen, korrekt zu bleiben. (2022-10-22)
comment
Keywords: Allumwandlung (2x), Seriesmover, konsekutive Umwandlungen 8 (SDLTDLTS), Excelsior white (3x)
Genre: Fairies
FEN: 1r6/pP2P3/P4r1p/5P1P/p2K3p/5p2/P1k1pP1P/6n1
Reprints: 1938 U.S. Problem Bulletin 01-02/1990
feenschach 96 10/1990
Springaren (46), p. 125, 09/1991
G30 FIDE Album 1986-1988 1995
18 Mat Plus (6-7), p. 237, 1995
Die Schwalbe (156), p. 236, 12/1995
Tim Krabbé's Website (57) 2000
G-III Probleemblad 01-02/2000
(9) Springaren , p. 108, 09/2011
(9) Tehtäväniekka 3 30/09/2011
L11 Phénix 09-10/2011
(1) Die Schwalbe , p. 337, 12/2011
(34) The Problemist , p. 272, 01/2012
Problem Observer 05/2012
Input: HBae, 2010-08-03
Last update: Arnold Beine, 2022-10-23 more...
3 - P1240551
George P. Sphicas
3257 U.S. Problem Bulletin (99-100) 01-04/1995
P1240551
(8+6) cooked
ser-h=34
1. g6 2. gxh5 3. h4 4. h3 5. h2 6. h1=T 7. Txh6 8. Txb6 9. h5 10. h4 11. h3 12. h2 13. h1=L 14. Lxd5 15. La2 16. d5 17. d4 18. d3 19. d2 20. d1=D 21. Dd4 22. Da1 23. Tb2 24. b5 25. b4 26. b3 27. f6 28. fxe5 29. e4 30. e3 31. e2 32. e1=S 33. Sc2 34. Kb1 Le3=
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Anton Baumann: kürzer (mit ZU): 1.d6 2.f6 3.fxe5 ... 7.e1=D 8.Dxg1 ... 13.Kxh6 14.g5 15.Dg4 Lxg4= (2021-02-03)
comment
Keywords: Seriesmover, Allumwandlung, Excelsior (4-fach), konsekutive Umwandlungen 4 (TLDS)
Genre: Fairies
FEN: 6K1/1p1p1ppp/1N5P/3PPB1P/8/8/8/2k3B1
Input: Erich Bartel, 2012-06-03
Last update: James Malcom, 2021-02-03 more...
4 - P1252405
George P. Sphicas
2286v U.S. Problem Bulletin 09-10/1991
Spezielle ehrende Erwähnung
P1252405
(6+2)
s#13
1. h8=L+! Kf8 2. c8=D+ Ke7 3. De8+ Kd6 4. d8=T+ Kc7 5. Dd7+ Kb6 6. Tb8+ Ka6 7. De2 Ka5 8. Da2+ Sa3 9. f8=S Ka6 10. Se6 Ka5 11. Dad2+ Ka6 12. Db5+ Sxb5 13. Sc7+ Sxc7#
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Korrektur in feenschach 08-09/2002, Seite 491 und 527.
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comment
Keywords: Allumwandlung (LDTS), konsekutive Umwandlungen 4, Minimal
Genre: s#
FEN: K7/2PP1PkP/8/7Q/2n5/8/8/8
Input: Frank Müller, 2012-10-28
Last update: Marcin Banaszek, 2022-06-12 more...
5 - P1267514
Michel Caillaud
2648 U.S. Problem Bulletin 01-04/1993
2. ehrende Erwähnung
P1267514
(6+10) C+
s#2
1. Tf8+ Ke6 2. e8=D+ Lxe8#
1. Tf8+ Ke5 2. e8=T+ Lxe8#
1. Tf8+ Kg5 2. e8=L+ Lxe8#
1. Tf8+ Kg7 2. e8=S+ Lxe8#
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more ...
comment
Keywords: Allumwandlung, Checking key
Genre: s#
Computer test: SCHRECKE: popeye 4.89
FEN: 1q1B2RR/4P3/3p1k2/K1nr3B/bn1p4/r1b5/8/8
Input: Frank Müller, 2013-04-15
Last update: Dieter Berlin, 2024-02-16 more...
6 - P1277924
Mark Kirtley
U.S. Problem Bulletin 01-02/1989
P1277924
(8+4) C+
s#4
1. b8=L+! Kd8 2. g8=T+ Ke7 3. d8=S+ Sxa7 4. f8=D+ Lxf8#
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SCHRECKE: C+, Gustav 4.2a, Brute Force (2022-04-01)
comment
Keywords: Allumwandlung, Batteriematt vertikal, konsekutive Umwandlungen 4 (LTSD)
Genre: s#
Computer test: %C+ PY 3.37 am 7.5.1996
FEN: 7K/RPkP1PP1/2n4b/1Q4P1/8/7r/8/8
Reprints: Die Schwalbe 195, p. 464, 06/2002
Input: Frank Müller, 2013-09-18
Last update: Marcin Banaszek, 2022-04-03 more...
7 - P1277937
Mark Kirtley
George P. Sphicas

1801 U.S. Problem Bulletin 05-06/1989
P1277937
(15+6) C+
s#7
1. d7! and e.g. d3 2. d8=L b5 3. a8=S gxf5 4. g8=D h2 5. h8=T h1=D 6. Txh1 dxc2 7. De6+ Lxe6#
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Author's Note: Black can play d3, b5, gxf5, and h2 in any order, with corresponding White promotions as replies, giving all 24 permutations of White AUW (LSDT, LDST, etc.). If Black plays g5 instead of gxf5, then White replies fxg5 instead of promoting to D. A white pawn added at g5 would eliminate this pesky variation, but the white pawns are all used up!
SCHRECKE: Unlösbar, eventuell fehlt ein wBf4. (2020-10-28)
A.Buchanan: Mark Kirtley wrote to me: George found the original issue of the U.S. Problem Bulletin, showed me, and yes, there is a wPf4 in the original. George and I couldn't remember why we also had a wPa2, but a new computer test (Gustav) showed us the reason: it guards against a major dual Rh1-a1 in some variations.
There is still a minor dual in some variations (of varying length) if the bP promotes to a Q at h1, for then wRh8-h6+, bQh1xh6, and wQe6+ and bQxe6#. (2020-11-11)
A.Buchanan: So I have corrected the confirmed diagram typo (2020-11-11)
A.Buchanan: Have posted a simplified representation of the solution, at the author's request (2021-01-27)
Henrik Juel: So the problem is C+, except for the minor dual mentioned (2021-01-27)
comment
Keywords: Allumwandlung, konsekutive Umwandlungen 4 (DTLS)
Genre: s#, Mathematics
Computer test: Gustav 4.1c
FEN: 1BK1N3/P1P3PP/NpkP2p1/5Q2/1Rbp1P2/7p/P1RP4/8
Input: Frank Müller, 2013-09-18
Last update: James Malcom, 2021-01-28 more...
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The problems of this query have been registered by the following contributors:

Felber, Volker (1)
HBae (1)
Erich Bartel (1)
Frank Müller (4)