Die Schwalbe

163 problem(s) found in 5434 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND K='En passant als Schlüssel' AND NOT COOKED ] [download as LaTeX]

1 - P0000036
Valery Liskovets
Nikita M. Plaksin

5528 Die Schwalbe 99 06/1986
P0000036
(10+11)
h#1.5 (AP, RV)
1) 1. ... cxd6ep 2. 0-0-0 Dxc7#
Nicht 2. Kf8 Dg8? da der ep-Schlag AP bewiesen werden muss.
2) 1. ... gxf6ep 2. 0-0-0 Tg8#
Nicht 2. Kd8 Tg8#? da der ep-Schlag AP bewiesen werden muss.
play all play one stop play next play all
VL: Solution:
I 1... c*d6 e.p. 2.0-0-0 Q*c7#
II 1... g*f6 e.p. 2.0-0-0 Rg8#

NOT:
2.Kf8? Q/Rg8#?? no AP-justification!

Castling implies e.p. 'a posteriori' and is necessary only to this end. (2002-04-03)
A.Buchanan: Solutions & tries (Popeye v.485) are:
1. ... cxd6ep 2. 0-0-0 Dxc7#
1. ... cxd6ep 2. Kf8 Dg8#
1. ... gxf6ep 2. d4 Tg8#
1. ... gxf6ep 2. 0-0-0 Tg8#
1. ... gxf6ep 2. Kd8 Tg8#
So after 1. ... gxf6ep:
2. Kf8 Rg8 is not even a mate (f7 flight)
and is 2. d4 a kind of dual thematic AP try? No-one's mentioned it. It would be easily fixable by shifting wBd2 to d4.
However, the main thing issue I don't understand PRA+AP logic (maybe I did once?). Under normal PRA algorithm, the "parts" for cxdep, gxfep & 0-0-0 respectively are YNY, NYY, NNN. Others are either impossible (3) or dominated by application of castling convention (2). OK so far.
There is no solution in the NNN part, so I suppose we must use AP in another part to eliminate it. But castling in another part where we are explicitly *assuming* that castling is ok seems to me to prove nothing. And if this inference did work somehow (which seems to me incredibly unlikely), why would we need to do it in *both* of these other parts? Surely one would be enough, but that means that the other part would be cooked.
Or maybe somehow AP "proves" that there are only 2 dimensions for PRA space, cxdep & gxfep, but that is so incredibly circular and horrible.
This kind of problem needs a proper step-by-step solution. Currently the solver can at best sort-of-vaguely-see-what-the-composer-might-be-alluding-to: i.e. it's just a joke.
Actually, I don't think that it can be PRA at all. I think it must be RS with two solutions supported by AP. But then there's still the question of why we need to castle in *both* solutions. I am sure I have seen an AP problem with two solutions where there is 0-0 in one solution and 0-0-0 in the other, which suggests that we *don't* need to castle twice in this problem. Which interpretation is correct, or do we have such a vague interpretation of these things (in order not to make independent spirits sad) that both are allowed to "work". (2020-12-30)
VL: Generally I agree with Andrew's analysis. The presented solution needs some corrections and clarification.

At first, the extra try 1.gxf6 e.p.? d4. I don't remember details but indeed, at present I'd prefer to exclude it by shifting wPd2 onto d4. One more thematic try enriches a problem but it is better to have an equal number of tries after both e.p.'s. In general, in AP-problems, thematic tries are highly desirable but not necessary formally for soundness. Dual avoidance in tries is here just due to the flight f7. Yes, 2.Kf8? Rg8#?? is indicated wrongly (unfortunately, H.103 with the published solution isn't available for me).

Now the most doubtful point: dual avoidance in the solution. Do we need castling in both partial solutions or at least one would suffice for justification? In my opinion, both approaches make sense in principle. In this problem implemented is the former, what means that every partial solution is permitted to be considered separately and, thus, should contain legalizing castling. This is similar to ordinary AP-problems, in which every line of the solution must contain castling. There is a distinct much subtler and rarer approach, which I call "Total AP", that considers all lines as a whole and thus requires to contain castling at least once (with subtle soundness issues). So, the current problem is treated (implicitly) not in the spirit of Total AP.

The problem implements a certain kind of triples of mutually retrodepending special moves (w/b castlings and e.p.). Namely, it is a "hybrid" AP-problem, where castling justifies a posteriori the typical pRA-choice between two e.p. captures. This is one of lucky triple kinds that admit (controversially) sound implementations based on hybrid logical conventions (logics for short). One more such a triple is represented in my earlier P0002474. Totally 37 distinct kinds of interacting triples can be identified, and only for few of them I know (or at least expect) reasonable implementations under special logics (whichever artificial and arguable they can be but consistent internally). Under an implementation I mean (loosely) a problem with an orthodox stipulation (#n, h#, etc.) supplemented by a suitable retro-convention like an ad hoc combination of pRA, RS or AP such that the position of the problem contains the corresponding triple of moves AND its full solution depends on all their combined (il)legalities. An extremely subtle matter. (2021-01-29)
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comment
Keywords: a posteriori (AP), En passant as key (2), Partial Retro Analysis (PRA), Castling (sg), Volet Pawn
Genre: h#, Retro
FEN: r3k2n/1pp4P/N6p/2PpKpP1/2Q1p1R1/4P1pB/3P1p2/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-23 more...
2 - P0000058
Leonid M. Borodatow
5758v Die Schwalbe 103 02/1987
P0000058
(13+9) C+
h#3
b) sBa6 statt sLa6
a) 1. ... exf6ep 2. 0-0-0 Lxf4 3. Td7 a8=D#
b) 1. ... Kxf4 2. Te7 e6 3. Tb8 axb8=D,T#
play all play one stop play next play all
Anton Baumann: Mattdual in b): 3.Tb8 axb8=D,T# (2022-12-16)
A.Buchanan: So Borodatow got it all working! In a) Black might have captured hxgxf and axPb. So castling rights might still be maintained with the ep. In b) on the other hand, it must be axb, bxa, exf and wPgxh6, so there was the cage. Promotion to TD is tolerated in the final move, although it may not be puristic, without the convention, too many mates would be excluded (2022-12-16)
comment
Keywords: En passant as key, Castling (sg), Cant Castler, Valladao Task
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & basic retro thinking
FEN: r3k3/P7/b3r1pP/4PpBP/3nnpKR/5PRB/5PP1/7N
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-16 more...
3 - P0000583
Andrey Frolkin
Günter Lauinger

3468v Die Schwalbe 72 12/1981
P0000583
(10+12) C+
h#2 (AP)
Satzspiel:
*1. ... 0-0! 2. cxd4 Tc1#

Verführung:
1. exd3ep? 0-0 2. cxb4 Tf4# aber zuletzt R: 1. d2-d4?? ist illegal, da es den wLc1 als schwarzes Bauernschlagobjekt ausschließt

Lösung:
1. ... 0-0! (AP-Legalierung des weissen Anzugrechtes) 2. cxd4 Tc1#
play all play one stop play next play all
Alle Versuche, das Satzspiel 1. ... 0-0! 2. cxd4 Tc1# durch einen schwarzen Vorschaltzug aufrecht zu erhalten, scheitern.
Mario Richter: 1. exd3ep 0-0 2. cxb4 Tf4 ist nur Verfuehrung (scheitert an schwarzer Bauern-Schlagbilanz).
Loesung: 1. ... w0-0! (AP-Legalierung des weissen Anzugrechtes) 2.cxd4 Tc1# (2009-02-10)
A.Buchanan: Supersedes P0000553 (2022-01-08)
Mario Richter: Hi Andrew, I only quoted from the "official solution" ('Die Schwalbe' Heft 72, 12/1981, p.399).
Perhaps a better way to get anwers to your interesting questions is to ask the authors directly ... (2022-01-08)
A.Buchanan: AP Type Petrovic is a try, because wLc1 was captured at home, yet Black still made 6 pawn captures.
AP Type Keym is the actual solution, because if it was really BTM, then White would have lost castling rights.
So there are two kinds of AP here. (2022-03-21)
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comment
Keywords: Castling (wk), a posteriori (AP) (Type Keym), En passant as key, a posteriori (AP) (Type Petrovic)
Genre: h#, Retro
Computer test: BC+ Popeye v4.87
FEN: 8/2p5/1pPp4/bRpP4/BPkPp3/qp2p2p/rP2P3/4K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
4 - P0000598
Nikita M. Plaksin
Andrej N. Kornilow

3876 Die Schwalbe 74 04/1982
P0000598
(4+3)
h=2 (AP)
Circe, Monochromes Schach
Intended solution:
1. dxc3ep[+wBc2] 0-0 2. axb1=S Kh2=
2. ... Kf2? 3. Kf3!
1. ... Tf1? 2. axb1=S Kf2? 3. Kf3!
play all play one stop play next play all
Erich Bartel: vom Dual 2.-- Kf2/Kh2 abgesehen C+ PY V4.41.--- (2008-11-07)
A.Buchanan: This is cooked in Popeye because White can't castle as long as bK controls f1! This is quite reasonable behaviour in monochrome: compare to en passant! So no solution (2022-02-18)
comment
Keywords: a posteriori (AP) (Type Petrovic), Circe, En passant as key, Monochromatic Chess, Castling (wk), Miniature, Golden Age (Monochrome castling)
Genre: Retro, Fairies
FEN: 8/8/8/8/2Pp4/8/p3k3/1N2K2R
Reprints: (IV) Quartz 4 1997
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-02-18 more...
5 - P0000641
Werner Frangen
2201 Die Schwalbe 46 08/1977
P0000641
(14+5)
#4 (AP)
1. bxc6ep
play all play one stop play next play all
Nach 1. bxc6ep ist zwar ein Matt in 2 Zügen möglich, aber Weiß muss noch rochieren, um den ep-Schlag zu begründen.
James Malcom: Full solution? (2021-02-05)
Henrik Juel: White pawns captured all 11 missing black men by axb, f2x..xa7, and g2x..xb7
Black captured hxg and once more, so Pc5 never captured
If last move was c6-c5, the preceding white move was with Ke1 or Th1
So if White can castle, last move was c7-c5
1.bxc6ep dxc6 2.0-0(AP) c5 3.Ta1,Sd7 and #4
2.Sd7 c5 3.0-0(AP) is also possible
I expect the full solution was omitted because it is very dualistic (2021-02-05)
Anton Baumann: Autorabsicht: 1.bxc6ep [2.0-0 3.Lb5#] bxa3 2.0-0 axb2 3.Tb3 nebst 4.Lb5,Tf4#
1. ... dxc6? 2.0-0 nebst 3.Tf4,Lb5#
Dual: 2.Tb3 dxc6 3.0-0 [4.Tf4#] c5 4.Lb5# 2. ... a2,axb2 3.0-0 [4.Lb5#] dxc6 4.Tf4# (2021-02-05)
A.Buchanan: C+ of helpmates with this kind of AP is relatively simple: one can just eliminate all lines without 0-0. But C+ of d# is harder.
(1) Henrik's retro logic is solid. There is no #4 unless 1.bxc6ep, so let's take that as a given: an AP debt is incurred.
(2) Black has 5 responses. Against 4 of them, 2.0-0 gives a genuine short mate with the AP debt paid. Such short mates don't impact soundness in a retro #4, to my mind.
(3) This leaves 1... bxa3. Following 2.0-0 axb2 (the only full length line) 3.Rb3 thr 4.Bb5,Rf4# but both mates are separately provided, so only minor duals.
(4) It remains to consider if White can delay castling after 1...axb3. Apart from 2.Tb3 nothing works, but 2.Tb3 thr 3.0-0 is unstoppable and is the major dual to my mind. I don't see any obvious fix. (2021-02-05)
comment
Keywords: Castling (wk), En passant as key, a posteriori (AP)
Genre: Retro, n#
FEN: 1N6/PP1p4/BR6/pPp5/kp6/B2P4/1PP1P2P/4K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-22 more...
6 - P0000649
André Hazebrouck
2261 Die Schwalbe 47 10/1977
4. Preis
P0000649
(8+14)
h#2.5
b) AP (2 Lösungen)
a) 1. ... 0-0-0 2. 0-0 Tdg1+ 3. Kh8 Txh6#
b) also 1. ... cxb6ep 2. La6 0-0 3. 0-0-0 a8=D#
is clearly the intention
play all play one stop play next play all
Can count 1+7 visible pawn captures, leaving 1+1 unexplained. Need to resolve wPfgh & bPg. Suppose bK never moved, then one of:
1) wPf waylaid, wPhxPg=, wPg=. Here w00 right can remain.
2) Or similarly, wPh waylaid, wPfxPg=, wPg=. Again w00 right can remain.
3) bPgxPh=, wPfxg= (or wPfxe then captured by bPf), wPg= w00 right lost.
1+1 captures explained in either case.
On the other hand if bK moved, then maybe wPf=, and only requires one more capture to resolve g&h files. The w00 right can remain. So there is a captured unit unaccounted for, and we can't validate the ep.
On the other hand if we are in case 3 above, then we can't know that wPbxa captured dark bishop, so White might retract a6-a7.
We also need to know that w00 rights remain. s000 rights (i.e. prior movement of sTa8) are not relevant.
If we know that w00, w000 & b000 remain, then we are in case 1 or 2 above with bPg captured unpromoted. Therefore wPb6xLa7 due to bishop shade. Therefore R: 1. b7-b5 b6xLa7 to unblock.

Only one candidate solution does not begin with ep: 1. ... 0-0-0 2. 0-0 Tdg1+ 3. Kh8 Txh6#. So this is the solution for a).

Let ????? denote validity of w00,w000,b00,b000,ep. Possibilities are: YYY?Y and all of YYN??, YNY??, NYY??, YNN??, NYN??, NNY??, NNN??. So there are 30 possibilities.
Under PRA, the solution parts would be YYYYY, YYNYN, YNYYN & NYYYN. For the first there are 20 solutions, while the second and third have 0 solutions. So this is not the right paradigm.
Under SPRA, there would be a single solution part YYYYY with 20 solutions. So this is not the right paradigm either.

Under RS with AP, the solution of a) still works. This comes from ?YY??. On the other hand, if the first move is ep, then we are in YYYYY. So all castlings are valid. But when we get to perform the mate, we need to know that based on castlings actually performed, the ep is valid. So the solution must include w00. So is 1. ... cxb6ep 2. La6 0-0 3. 0-0-0 a8=D#.

By combining the information of both of these solutions, we know we are in YYY?? so YYY?Y is the only possibility, and ep is legal. However, the combination of these two solutions would also validate any of the other 18 ep solutions that do not include 2. ... 0-0. They contribute no new evidence, but how to exclude them?

This is one of the issues with "AP Consolidation". Normally the number of solutions is not a constraint. But here perhaps we should insist that *only* two solutions are allowed?
Cook: 1. ... cxb6ep 2. La6 Tb1,~ 3. 0-0-0 a8=D#
18 different possibilities for W2 which are validated by the same logic that validates 2. ... 0-0.
Henrik Juel: [I don't follow the silly convention of writing black moves first]. 1.0-0-0 0-0 2.dTg1+ Kh8 3.Txh6#. b) If Ke1,e8 and Th1 never moved, White captured f/hxPg and b6xLa7; if Ta1 also never moved, last white move was b6xLa7. 1.cxb6ep La6 2.0-0/0-0-0 0-0-0 3.a8Q#. The a) solution also works in b). (2003-12-18)
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comment
Keywords: a posteriori (AP) (Type Petrovic), Castling (wkwlsk), En passant as key
Genre: h#, Retro
Computer test: Forward logic Popeye v4.87 & basic retro-logic works, but then AP Consolidated protocol seems to cook the problem.
FEN: r1b1k2r/P2p4/2p1n2p/ppPq4/1np5/p7/P2PP3/R3K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-24 more...
7 - P0000758
Gerd Rinder
1033 Die Schwalbe 21 06/1973
1. Preis
P0000758
(7+11)
Remis (AP)
Weiß ist patt. 1. cxb6ep ist nur zulässig, wenn Schwarz diese a posteriori durch die Rochade rechtfertigt. Weiß kann aber so spielen, daß Schwarz nicht rochieren kann, z.B. 1. ... Lxc7 2. bxc7
play all play one stop play next play all
Guus Rol: This is an incorrect interpretation of the AP-convention. Rules outrank goals in the definition of all GAMES. Therefore the legitimacy of a move cannot be restricted by the desire to achieve the goal (in this case: Remis). The proper way to view AP is that executing e.p. invalidates the legitimacy of all lines of future play that do not contain 0-0-0! In that sense black and white are forced to cooperate. In whatever freedom remains they can compete for the prize promised in the stipulation. By the way, this understanding of AP is not only more logical, it is also much more interesting as a playing field for AP-composition. (2005-09-21)
mri: citeWeiß kann aber so spielen, daß Schwarz nicht rochieren kann, z.B. 1. ... Lxc7 2. bxc7
/cite
How does white prevent black from castling after 1. cxb6 e.p. Ba7xb6+?
E.g. 2.Kxb6 a1=R 3.a7 Rxa7, or 2.Ka4 Bd8xc7 3.a7 Bb8. (2005-09-22)
VL: 1.c5xb6ep(??) a7xb6+ 2.Kxb6 a1R 3.Kb7 R1xa6 4.Rc8! (R6a7#?? illegal).
This study is correct under the generally accepted understanding of AP
a la' N.Petrovic'. Antiform (looking possibly somewhat strange):
Black's unsuccessful try. (2005-10-03)
Guus Rol: Generally accepted, true. Generally acceptable, false. Freedom of interpretation ceases for a concept once its polar concept (a priori validation) has been defined. "Goal induced AP" however, might be a passable stipulation for this type of problem. To keep this place from turning into a discussion forum I will discontinue comments on this issue. (2005-10-03)
paul: Author intention is: If black still can castle, his last move must have been b7-b5. However, to prove this, he has to castle (A Posteriori condition). So: 1.cxb6 e.p. axb6+ 2.Kxb6 a1R! (2...a1Q? 3.Kb7 Qxa6 mate obviously doesn`t prove b7-b5 as the last move) 3.Kb7 R1xa6 4.Rc8! and white has prevented black from castling. So black can`t prove the last move is b7-b5 and therefor is already stalemated in the initial position! (2011-07-12)
A.Buchanan: Isn't Guus' idea just AP-Prioritat? And even if it were "more logical" or "more interesting", it doesn't follow that other forms is AP are "incorrect" (2023-07-31)
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Keywords: En passant as key, Castling (sg), a posteriori (AP)
Genre: Retro, Studies
FEN: r2bk3/p1Rpp3/P1p2p2/KpP2P2/1P2p3/1P6/p7/8
Reprints: (4) Problem 161-164 11/1973
317 Europe Echecs 217 01/1977
(A) Die Schwalbe 80 04/1983
408 Eigenartige Schachprobleme 2010
M36 mpk-Blätter 12/2011
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-07-31 more...
8 - P0000760
André Hazebrouck
1120 Die Schwalbe 23 10/1973
P0000760
(9+10) C+
h#2 (AP)
1. bxc3ep Sa6 2. 0-0-0 Tc4#
play all play one stop play next play all
Henrik Juel: -1.c2 c5xLb4 -2.Lc3 c6 -3.Lb2 c7 -4.Lc1 a6! -5.b2 b2xDSa2 etc. White captured sDTSS by fxexd, gxfxe, allowing Black to capture f7xPe6xPd5 etc. (2003-12-18)
A.Buchanan: Why not e.g. wSb1? (2022-03-04)
Henrik Juel: That also seems to work (2022-03-04)
A.Buchanan: I really like the motivation for ep. I guess the motivation for Rb1 is to be inside the cage that forms around it, but it’s still a bit loose. Note there is no retro try. (2022-03-05)
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Keywords: En passant as key, Castling (sg), a posteriori (AP) (Type Petrovic), Volet Pawn
Genre: h#, Retro
Computer test: HC+ Popeye 4.87 + simple retro reflection
FEN: rN2k3/1p1pp1pp/8/p7/RpP5/PP6/p2PP3/KR6
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-05 more...
9 - P0000793
Nikita M. Plaksin
Andrey Lobusov

1558 Die Schwalbe 33 06/1975
4. Preis
P0000793
(13+5) C+
#3 (AP)
1. cxd6ep+! Kxg3 2. 0-0! (proving ep ok)
2. ... Kg4 3. g8=D,T#
2. ... a1=D,L 3. Dg5#

R: 1. d7-d5 Tc6xh6 (unless R: Kg1-g2 Th~*h1)
play all play one stop play next play all
VL: A posteriori (AP)!
2.g8Q(R)+/Rg1+? Kf4 3.Qg5#??
Retro: d7-d5, Rc6xh6+ (unless Kg1-g2, Rh~-h1+).
One of the best AP-type problems. (2015-08-20)
James Malcom: The first Valladao AP? (2020-10-03)
A.Buchanan: Hi James, there are 6 earlier ones in PDB, not counting those which are not marked as Valladao (could quite a few, as basic AP is 2/3 of Valladao). Type k='a p' and not g='fairies' and k='valladao', and set sort order by date. The ur-problem is P0003417. (2020-10-03)
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comment
Keywords: Castling (wk), a posteriori (AP) (Type Petrovic), En passant as key, Promotion (ws), Valladao Task (w w w/s)
Genre: Retro, 3#
Computer test: Popeye v4.85 + minor retro/AP thought
FEN: B7/p5PP/p6R/Q1Pp4/8/PP1P2P1/p3P1k1/4K2R
Reprints: (B) Die Schwalbe 48 12/1976
feenschach 40 11-12/1977
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-11 more...
10 - P0001107
Michel Caillaud
3332 Die Schwalbe 66 12/1980
2. Preis
P0001107
(7+9) C+
h#4.5 (AP)
Circe
1. ... hxg6ep[+sBg7] 2. a1=T+ Txa1[+sTh8] 3. 0-0 Ta3 4. bxa3[+wTa1] 0-0-0 5. Td8 Txd8[+sTh8]#
play all play one stop play next play all
Wenn die beiden Könige noch nicht gezogen haben (was a.p. durch Ausführung beider Rochaden bewiesen wird!), kann der letzte Zug nur g7-g5 gewesen sein, Sonst ginge z.B. auch R: 1. Kd8-e8 c2xDb3
Henrik Juel: A possible retroplay is -1... g7 -2.f3xP(-Pg7) b5 -3.f2 c6xP(-Pb2) -4.b2 a6 -5.Rc3 a7 -6.Rc1 b6xB -7.Bf8 b7 -8.Bg7xB etc. (2003-04-22)
Michel Caillaud: The problem is not cooked as indicated, as under A Posteriori convention both castles must be played in the solution to justify the en passant key. (2022-02-04)
A.Buchanan: If wK never moved, then Black has not just moved another non-capturing pawn, as White has no prior move. The only possible exception is R: 1. g7-g5 f/h3xPg4[+Pg7]. (2022-02-04)
comment
Keywords: a posteriori (AP), Circe, En passant as key, Castling (wgsk), Promotion in forward play, Valladao Task
Genre: Retro, Fairies, h#
Computer test: HC+ all solutions begin with ep, but only one includes both white & black castling
FEN: 4k3/8/7p/p1p3pP/Pp4Pp/RP4p1/pP6/4K3
Reprints: feenschach 61, p. 534, 08/1982
RA152 diagrammes 72 07-08/1985
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-28 more...
11 - P0001146
W. Wolf
Deutsches Wochenschach 23/04/1911
P0001146
(15+8)
#3
1. bxc6ep e4 2. Se3 Kxg5 3. Kxd6
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61 (the three threats never materialize)
It is obvious that last move was c7-c5 (2020-12-02)
comment
Keywords: En passant as key
Genre: Retro
FEN: 4B1R1/3NP1Pp/1Q1p1Prr/RPpKpNPk/6p1/6P1/P2B4/8
Reprints: 41 Volksgemeinschaft (Heidelberg) 19/01/1936
252 Comoedia 21/06/1936
22 Europe Echecs 18 02/1960
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-12-02 more...
12 - P0001228
Wolfgang Hundsdorfer
Deutsches Wochenschach 1909
1. Preis
En-passant-Turnier 1910
P0001228
(13+12)
#3
1. bxc6ep

R: 1. c7-c5 g5-g6 2. Tc6-c2 g4-g5 3. Tg6-c6 g3-g4 4. Tg8-g6 g2-g3 5. Ld4-a7 h4-h5 6. Lg7-d4 h3-h4 7. Lf8-g7 h2-h3 8. g7xLh6,g7xSh6
play all play one stop play next play all
Henrik Juel: minor dual in forward play
1.bxc6ep+ Db5 2.DLxb5+ Tc4 3.LDxc4#
1... b5,bxa6 2.Kxb4+ Tc3 3.Txc3# (2022-07-01)
Henrik Juel: Last move must be c7-c5, enabling Tc2 to reach g8 in just three retractions (2022-07-01)
comment
Keywords: En passant as key
Genre: Retro, 3#
FEN: 8/bp2p2p/B5Pp/RPp2q1P/Qp2P3/RK1kPP2/P1rppP2/8
Reprints: 139 Favorit-Schachaufgaben , p. 35, nach 1910
75 Retrograde Analysis 1915
101 Europe Echecs 53 05/1963
10 Die Schwalbe 276 12/2015
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-07-01 more...
13 - P0001310
Dragan Petrovic
182 Europe Echecs 107 01/1968
4. Preis
P0001310
(13+14) C+
#2 (AP)
1. gxf6ep! droht 2. 0-0#! (2.Kf2#?)
R: 1. f7-f5 f6xDe7,f6xTe7 etc
play all play one stop play next play all
Wh caps: fxe7, hxg5
Bl caps: axbxc2, wBf1
If wK castling right remains, the only way to give White a prior move is to retract f7-f5, so ep would be on.
The key threatens (inter alia) 2. 0-0#/Kf2#, and both remain whatever Black plays, so the castling retro-justification for ep can never be disrupted.
R: 1. S~a3? a3-a4? blocks wT from retracting to home square if wK castling right remains.
Dragan Petrovic: Author is Dragan T. Petrovic (2007-12-02)
more ...
comment
Keywords: En passant as key, Castling (wk), a posteriori (AP) (Type Petrovic)
Genre: Retro, 2#
Computer test: HC+ Popeye v4.87 & simple retro-logic
FEN: 4r3/1p2P1n1/4p2B/b1pp1pPb/P5pp/nPP5/Q1pPP1P1/N1k1K2R
Reprints: (50) Problem 144-147 12/1971
(38) Mat Plus 12 10-12/2009
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-07-21 more...
14 - P0001345
F. ben Galuth
219 Europe Echecs 126 07/1969
P0001345
(10+10) C+
h#2
1. cxd3ep? g3 2. Bd4 Lg2# (wLc1 retro-blocked)
1. c5! g3 2. cxd4 Lg2#
play all play one stop play next play all
James Malcom: Solution? (2020-12-29)
Hans-Jürgen Manthey: wohl beabsichtigt: 1. cxd3ep g3 2. Bd4 Lg2#
doch auch ein Dual: 1. c5 g3 2. cxd4 Lg2# (2020-12-29)
Mario Richter: rawbats says, that f2-f4 is White's only legal last move, and 1. c5 g3 2. cxd4 Lg2# the only solution, so 1. cxd3ep g3 2. d4 Lg2# might be a try, intended to fool the solvers ...
(notice that R: 1. d2-d4?? excludes wLc1 from the set of objects available for black pawn captures!) (2020-12-29)
James Malcom: Furthermore, the h pawn couldn't have moved last, as that rook is needed for the Black pawns. wPe6 takes all remaining captures of Black pieces, and bBf8 could never escape. So the d2 and h2 pawns did not move last, and gxf3ep does nothing, meaning that all en passants are not a solution. A very fine retro "joke." (2020-12-29)
James Malcom: This means that 1. c5 g3 2. cxd4 Bg2# is the only possible solution, and as such, this should be C+? (2020-12-29)
Hans-Jürgen Manthey: Stimmt Mario
habe übersehen das der Lc1 nicht gezogen haben kann bei 1. d2-d4; aber 6 schlagfälle von Schwarz nötig sind. (2020-12-30)
A.Buchanan: I think the composer here is exactly "trolling solvers' preoccupations for the lulz", to quote Hauke Reddmann in MatPlus today, which even my allegedly fine German skills are unable to translate. But Hauke is German, so maybe he could do it? (2020-12-30)
more ...
comment
Keywords: En passant, En passant as key (Tries)
Genre: h#, Retro
Computer test: Popeye v4.85 + thinking
FEN: 8/2p1p1p1/4P3/3p1p2/2pPkPpP/4p3/1PP1P1P1/Kb3B2
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2021-01-06 more...
15 - P0001420
Branko Koludrovic
294 Europe Echecs 197 04/1975
1. ehrende Erwähnung
P0001420
(13+12) C+
h#3*
1. ... cxd6ep 2. 0-0-0 0-0-0 3. Kd7 Sa7#
1. De7 c6 2. Th8 c7 3. Tf8 Sd6#
play all play one stop play next play all
White pawn caps: axb,dxe,gxf,hxg.
Black: fxg,bxc,cxb.
wPb4 came from b3 to release wBa3, so bPb3 captured to reach that square.
All pcs accounted for means bPd never captured.
In the set play, there are 13 retro tries in which one or both players do not castle. The intention is that both castling rights are needed in order to imply the pawn double hop.
A.Buchanan: White pawn caps: axb,dxe,gxf,hxg definite.
Black: fxg and two to resolve c-file. But that may be c&d cross-capture, so in set play last move might have been c6xd5. So I think this problem is cooked. What am I missing? (2022-03-21)
Mario Richter: If Black's last move was c6xd5, how do you get white Bishop a3 out of his cage? (In that case, black pawn b7 never left the b-file). (2022-03-21)
A.Buchanan: I agree Mario thanks (2022-03-21)
Hans-Jürgen Manthey: beide Rochaden und im Satz ep. ist möglich:
R.: 1. ... d7-d5 2. Sa7-b5 b5xTc4 3. Tg4-c4 Dd8-h4 4. c4-c5 Th8-h3 5. c2-c4 c4xDb3 6. Dd3-b3 h3-h2 7. Dd1-d3 h4-h3 8. Sc8-a7 h5-h4 9. Th4-g4 c5-c4 10. Th1-h4 h7-h5 11. h2xSg3 Sf5-g3 12. b3-b4 Sh6-f5 13. Lb4-a3 c7-c5 14. Ld2-b4 g3-g2 15. Lc1-d2 a3-a2 16. a2xSb3 Sc5-b3 17. Lb3-a4 Sa6-c5 18. Lc4-b3 Sb8-a6 19. d2xLe3 Lc5-e3 20. Ld3-c4 Lf8-c5 21. Lf5-d3 a4-a3 22. Lh3-f5 a5-a4 23. Lf1-h3 g4-g3 24. g2xLf3 Lb7-f3 25. Sb6-c8 Lc8-b7 26. Sa4-b6 a7-a5 27. Sc3-a4 b7-b5 28. Sb1-c3 f5xSg4 29. Se5-g4 Sg8-h6 30. Sf3-e5 e7-e6 31. Sg5-f3 f6-f5 32. Sh3-g5 f7-f6 33. Sg1-h3 (2023-02-23)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wgsg)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & retro-logic.
FEN: r3k3/6p1/4p3/1NPp4/BPp4q/Bp2PPPr/pP2PPpp/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
16 - P0001453
Luis Alberto Garaza
327v Europe Echecs 225/226 10/1977
P0001453
(11+14) C+
h#1
1. hxg3ep! 0-0#! (Tf1#?)
play all play one stop play next play all
Hans-Jürgen Manthey: 1. hxg3 O-O#(auch Tf1# !) mögliche zugfolge:
1. d2-d4 f7-f5 2. Lc1-d2 f5-f4 3. Ld2-c1 e7-e6 4. Lc1-d2 c7-c5 5. Ld2-c1 b7-b5
6. Lc1-d2 a7-a6 7. Ld2-c1 Lc8-b7 8. c2-c4 Ke8-f7 9. Lc1xf4 Sg8-f6 10. Lf4-h6 g7xh6
11. Dd1-d3 h6-h5 12. Dd3-d1 Lf8-h6 13. h2-h4 Lh6-g5 14. h4xLg5 h5-h4 15. Dd1-d3 h7-h5
16. Dd3-d1 b5xc4 17. a2-a4 Lb7-e4 18. d4-d5 e6xd5 19. Ta1-a3 Le4-c2 20. f2-f4 Th8-e8
21. Ta3-g3 Te8-e3 22. f4-f5 Sf6-e4 23. f5-f6 Kf7-e6 24. f6-f7 Se4-d2 25. Sg1-h3 Sd2xf1
26. Sh3-f2 Sf1-d2 27. Sf2-g4 Sd2-e4 28. Dd1-d3 Lc2-d1 29. Sg4-f6 c4-c3 30. Sf6-h7 c3-c2
31. b2-b4 c5-c4 32. b4-b5 Sb8-c6 33. b5-b6 Sc6-a5 34. b6-b7 c2-c1L 35. g5-g6 c4-c3
36. Sb1-a3 c3-c2 37. Sa3-b5 Ta8-c8 38. b7-b8L Tc8-c3 39. Lb8-d6 La5-c4 40. a4-a5 a6xSb5
41. a5-a6 Ke6-f5 42. a6-a7 Dd8-e8 43. a7-a8S De8-e5 44. Sa8-c7 Lc1-b2 45. Sc7-e6 Lb2-a1
46. Se6-f8 Kf5-f4 47. Tg3-g5 Se4-f6 48.Ld6-a3 Te3-h3 49. La3-b2 Sc4-a3 50. g2-g4 (2020-12-11)
Henrik Juel: The white castling is needed to prove (a posteriori) that last move was g2-g4, legitimizing the ep capture (2020-12-31)
more ...
comment
Keywords: En passant as key, Castling (wk), a posteriori (AP) (Type Petrovic)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & simple retro-logic
FEN: 5N2/3p1P1N/5nP1/1p1pq1Rp/5kPp/n1rQ3r/1Bp1P3/b2bK2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-22 more...
17 - P0001561
Michel Caillaud
432 Europe Echecs 304 04/1984
Lob
P0001561
(8+13)
Kürzestes h#?
1. ... bxa6ep! 2. Txe2 axb7 3. Td2 b8=D 4. De2 Db1#
1. Dc6? bxc6 2. Ld7 cxd7 3. Ke1,Kxe2 d8=D 4. Kf1 Dd1# too slow
R: 1. a7-a5 e3xLf4 2. Ld6-f4 d2xTe3 3. Ta3-e3 b4-b5 4. Ta6-a3 b3-b4 5. Tc6xBa6 a5-a6 6. Tc8-c6 a4-a5 7. Tg8-c8 a3-a4 8. Lf8-d6 a2-a3 9. e7xDf6,e7xTf6
play all play one stop play next play all
The forward play gives shortest h# in 3.5 moves, *if* e.p. is on. Otherwise the shortest is a mildly dualized 4.0 moves. So our mission is clear: assuming that Black moved last, what was that move? The position looks very open - how can one ever know? There is a knot in the south-east corner, which will only be resolved by wQ/R visiting g1.

White pawns have captured dxexf & hxg, accounting for BSP. So wPa was waylaid while wPc promoted to B. Black pawns captured dxexfxgxh, exf as well as wBf1 captured at home and wPa. That's 7 units, but bPc must also have captured to allow wPc to promote (to B on c8). So all captured units are accounted for. bPc promoted (bPh7 came from h6, so is bPd). We can't undo any of the Black pawn captures now, but we can undo d2xe3xf4, to release 2 Black units.

We can unpromote bPc, but we can't undo its capture to release a White unit, until wBh3 has unpromoted. The only White unit we can get now is from e7xf6. So this means that the two Black units we can release must be B & R, so they can retreat to f8 & g8 respectively. The timing is very tight, and there is only one way to do it. The black rook must visit a6 to unwaylay wPa, which gives White 5 more tempi, just enough.

bPc promoted on b1 to R, so we would need to undo the cage to get that. Therefore all we can do is send wQg1, then Rf1-f2 f2-f3 etc. bPa must retract immediately tp a7, so that wPa when unwaylaid can make fully 4 unmoves. Black officers are arranged to give unique retro & forward play (although with minor dual for the try) with Sh8 not just retro dressing but ensuring unique retraction Tg8-c8 not Th8-c8.
A.Buchanan: Another surprising motivation for e.p. I love Sh8. Sorry for W3 dual in the try play else the stipulation could be h#4*. I can’t fix it but it’s hard to improve on MC. Very enjoyable (2021-10-23)
A.Buchanan: Non-standard material is where the diagram contains for a player more than 1 queen or bishop of a hue or more than 2 rooks or knights. Obtrusive material is standard material, but there is some cheap reason why the unit must be promoted, most commonly that a bishop's home square remains blockaded by pawns. These categories are disjoint: no piece is ever both. Many problems in PDB do not apply this consistently, but the distinction goes back a long way in chess problem history, and is discussed by Morse.
Honestly, I dislike the word "obtrusive" whose negativity (while perhaps valid in forward problems) is inappropriate for retros. One distinguished composer objected to this tag being assigned to one of his problems. Nevertheless the concept has some interest. Renaming is a perilous business, but I am looking for suggestions... :) (2021-10-24)
A.Buchanan: Another distinction that comes to mind between "non-standard material" and "obtrusive promotion" is that normally in the former, one can't immediately point to which of the non-standard pieces was promoted: it's just that there's too many; while for the latter, one can usually point to a specific unit immediately.
"Obvious" is a candidate replacement for "obtrusive", but this might commit a cardinal sin of trying to nail down a perfectly useful and inherently vague term. Both "obvious" & "obtrusive" begin with "ob" which is helpful. What do you think? (2021-10-24)
Henrik Juel: I am curious about the award; why did this problem with good forward play and excellent retro-play only obtain a Commendation?
Maybe the judge did not like that Lh3 obviously is obtrusive...
. (2021-10-24)
A.Buchanan: Yes, and the lovely P0001117 with a similar obtrusion only received 12th Lob! But there may have been other factors. I do observe that "non-standard material" is arguably a worse defect than "obtrusive material", but the term doesn't cause offence because it's objective and non-judgemental. "obtrusive" is more subjective and inherently pejorative. To have such terms in the glossary is to put curators in an invidious position. I think the concept has its place, but I would like to replace it with something less scornful. I'm up for "obvious". It's an easy and reversible change: let's do it and see if mobs of protesters form outside the gate :) (2021-10-24)
A.Buchanan: Have changed "obtrusive material" to the non-pejorative "obvious promotion". It may still be regarded as a defect. As a placeholder, I have also changed the unclear German "mit Umwandlungfigur(en)" to "augenscheinlich Umwandlungfigur". A native German speaker I'm sure will propose a better term. (2021-10-26)
A.Buchanan: “offensichtlich” it is thanks Mario (2021-10-26)
more ...
comment
Keywords: En passant, Last Moves?, Obvious promotion (L), En passant as key, Promotion (D)
Genre: h#, Retro
FEN: 7n/1p3pp1/4bp1p/pP6/4qPP1/5PrB/4PrPp/3k3K
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-24 more...
18 - P0001859
William A. Langstaff
The Chess Amateur 1922
P0001859
(5+3) C+
#2
If Black can castle, e.p. is ok:
1. hxg6ep! 0-0 2. h7#
1. ... Tf8,Kf8 2. Td8#
Otherwise Black can't castle:
1. Ke6! ... 2. Td8#
play all play one stop play next play all
more ...
comment
Keywords: Cant Castler, Partial Retro Analysis (PRA), Castling (sk), En passant as key
Genre: Retro, 2#
Computer test: HC+ Popeye 4.61 & trivial retro-logic
FEN: 4k2r/8/5B1P/3R1KpP/8/8/8/8
Reprints: (D17) feenschach 27 04/1975
RA64 diagrammes 27 05-06/1977
(1) Die Schwalbe 86 04/1984
Razem 34 23/08/1987
(I) diagrammes 15 07-09/1994
(10) Die Schwalbe 241 02/2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-30 more...
19 - P0001937
Werner Kuntsche
6025 Schach , p. 191, 06/1969
2. Preis
P0001937
(4+12) C+
h#2
1. exd3ep Lxg4 2. f3 Le6#
play all play one stop play next play all
Klären: Quelle = Schachmatt? - Felber, Volker: SCHACH ist korrekt, 6/1969, Seite 191 (2010-10-09)

Eliminierung von 4 Steinen zwischen sK und wT im h#2 (mit Hilfe von ep-Schlag)!
more ...
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: 8/8/8/1pn4b/2kPpppR/2q1rB1p/1p4r1/3K4
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-01-09 more...
20 - P0001941
Nenad Petrovic
2nd International Team Match 1967-1970
3. (2.?) Platz
P0001941
(10+12)
Gewinn
AP
Henrik Juel: If White may castle, last move was g7-g5 to avoid retrostalemate. 1.fxg6ep followed by 0-0 to legitimize the en passant capture. (2004-09-23)
A.Buchanan: In V&V Encyclopedia, which I admire more for its scope than for its precision, this problem is given to illustrate "Petrovic Theme". The definition given is: "PETROVIC THEME Also called 'retroproblem of Petrovic Type'. Mutual dependence of en passant capture and castling. By playing an en passant capture other retro elements of position are legalized (usually castling)."
The definition makes no reference to A Posteriori. I am trying to get my head around the text here, because the e.p. does not "legalize" castling, rather it mandates it. I also encountered Öffner for this castling/e.p. AP (but not in V&V), but that might be someone's confusion in that Types Öffner vs Keym exist in PRA. (2022-02-15)
comment
Keywords: En passant as key, Castling (wk), a posteriori (AP) (Type Petrovic), En passant
Genre: Retro, Studies
FEN: b7/p4P2/2kbPp1p/3ppPp1/n3pp2/8/P1PPP2P/4K2R
Reprints: (2) Problem 141-143 08/1971
(77) Problem 144-147 12/1971
(C) Die Schwalbe 16 10/1972
Encyclopedia of Chess Problems 2012
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-02-15 more...
21 - P0001970
Thomas R. Dawson
26 Schachkongress Teplitz-Schönau im Oktober 1922 1923
P0001970
(13+13)
h#1
1. exf3ep Lc2#
R: 1. f2-f4 f5xTe4 2. Tg4-e4 & e.g. f6-f5 3. Tg1-g4 f7-f6 4. Le4-h7 h5-h4 5. Lg2-e4 h6-h5 6. Lf1-g2 h7-h6 7. g2xh3
play all play one stop play next play all
1.exf3e.p. Bc2# is the only possible solution, but this necessitates R: 1.f2-f4. Can we prove this?

(13+13) with 1+2 pawn captures. Bf8 captured at home, so to satisfy White appetite, the missing Black pawn (a or b) must have promoted via c2 on c1. Two more White units must be captured to allow this.

The kings cage can only be unlocked by retracting WPc2. But the clock is ticking as there are only 6 black moves which can be retracted.

The promoted piece was captured on e3 or h3. If either capture is undone, then a White bishop square is cut off, so WB must be replaced prior to this.

Now the order of the early moves is: WdP moves, WQB & WQR escape, BP promotes on c1 to X (capturing WR at some point), X captured by WP.

So the first White capture must be dxNe3 and the second White capture releases gxXh3. The second White capture releases WKB & WKR. WKR captured by original BfP.

The clock starts ticking with gxh3. Black has 6 pawn moves. WKB has 3 moves to reach h7. WR has 3 if it goes via d file, or 2 if it starts on g1 (in which case WfP or WQB must also move once). So certainly at least 6 White moves. Last move was therefore White (even if the stipulation didn't tell us), and it can only have been WfP coming from f3 or f4. If it had been coming from f3 it would have blocked WKB in its progress, so the last White move was indeed R: 1.f2-f4.

WKR did therefore move from g1-g4-e4, and R: 1. ... fxRe5 2. Rg4-e4. Prior to that, move order not unique, but counting still exact.

Note that WN loitering on b4, pretending to be part of the cage, is present on the board just to make up the numbers.
Jeliss: "Obstruction of passage square f3 to Bishop of same colour."

"Version 'Pittsburgh Leader' 08.06.1913"
Yoav Ben-Zvi: Appears as the first problem (D445) in the booklet on Dawson's RA problems by G.P. Jellis. The obstruction that occurs in the Try -1.Pf3-f4?, by WP of WB, is described as "obstruction of passage square". It is not considered by Dawson and his disciples to be a Retro opposition. Dawson's conception of RO was quite broad, it included cases where the interference was not by occupation of the target square, so the only valid reason that I can see to exclude this case is that the 2 pieces involved are both of the same color. Fabel's definition explicitly excludes "Monochrome RO". I conclude that it would be preferrable to interpret RO as a bi-chromatic interference. The keyword Retro opposition should be removed. (2018-04-07)
A.Buchanan: To my mind, RO involves some kind of parity-tempo issue between the sides, not just some kind of race-tempo. If it was just about "bi-chromatic interference", one might say that bPe4 blocks wBh7 from an immediate retreat, so it has to be wPf4 that retreats first, legitimizing the ep key. So I agree this is not RO. (2024-01-06)
more ...
comment
Keywords: Last Moves?, En passant as key
Genre: h#, Retro
FEN: nqb5/1rrpp1pB/KRp5/1p4B1/kN2pP1p/2P1P2P/PP2P2P/8
Reprints: D445 Retro-Opposition & Other Retro-Analytical Chess Problems 1989
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-01-06 more...
22 - P0002100
Adolf Norlin
v Tidskrift för Schack , p. 34, 01/1907
P0002100
(13+10)
#2
1. exf6ep+!
play all play one stop play next play all
Version in der 'Aarsskrift' 1935 innerhalb eines Artikels von K. Hannemann "Et Tema Fra den Retrograde Analyse". Im Original wDg4 statt h3 und wBh3 statt h4.
Henrik Juel: 1.exf6ep+. Not -1... a6?, requiring 3 black captures on light squares (incl. orig. Lf1); but missing orig. Lc1 was dark-squared. (2004-03-08)
Henrik Juel: C+ Popeye 4.61 and analysis (2022-06-11)
Hans-Jürgen Manthey: mögliche Zugfolge:
1. f2-f4 d7-d5 2. c2-c3 d5-d4 3. c3xd4 c7-c5 4. h2-h4 c5-c4 5. b2-b4 Lc8-d7 6. a2-a4 Ld7-b5 7. a4xLb5 Sb8-a6 8. Th1-h3 Sa6-c5 9. d4xSc5 Sg8-f6 10. d2-d4 Sf6-e4 11. c5-c6 Se4-g3 12. Lc1-d2 Se4xLf1 13. Sb1-c3 Sf1-g3 14. Sc3-a4 Sg3-e4 15. c6-c7 Ke8-d7 18. Sa4-c5+ Kd7-d6 19. Sc5-a6 Se4-c5 20. b4xSc5+ Kd6-e6 21. Ld2-a5 b7-b6 22. Sa6-b8 b6xLa5 23. Th3-e3+ Ke6-f6 24. Te3-e5 Dd8-c8 25. Dd1-d3 Dc8-a6 26. Dd3-h3 Da6-b6 27. Ta1-a3 Db6-c6 28. Ta3-g3 Dc6-d6 29. Te5-d5 Dd6-e6 30. c7-c8L De6-d6 31. Lc8-f5 Dd6-c6 32. Sg1-f3 Dc6-b6 33. Sf3-e5 Db6-a6 34. Se5-g6 Da6-b6 35. Sg6xTh8 Db6-c6 36. Tg3-g6+ h7xg6 37. Ke1-f2 Dc6-d6 38. Kf2-g3 Dd6-e6 39. Kg3-g4 De6-d6 40. Lf5-c2 Dd6-c7 41. b5-b6 Dc7-e5 42. f4xDe5+ Kf6-e6 43. Kg4-g5+ f7-f5 und nun :
1. e5xf6ep+ Ke6xTd5 2. Dh3-d7# (2023-02-24)
comment
Keywords: En passant as key
Genre: Retro
FEN: rN3b1N/p3p1p1/1P2k1p1/p1PRPpK1/2pP3P/7Q/2B1P1P1/8
Reprints: 58 Retrograde Analysis 1915
Aarsskrift DSK , p. 14, 1935
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2022-06-11 more...
23 - P0002353
Theodor Tauber
Michel Caillaud

The Problemist 1991
P0002353
(14+11) C+
ser-h#3 (AP)
1. dxe3ep 2. fxg1=L 3. 0-0 Tg4#
1. dxe3ep 2. Ke7? 3. Kd6 Sf5# doesn't pay AP debt
play all play one stop play next play all
Henrik Juel: If Black may castle, his latest move must have been e3xf2, so last move was e2-e4. (Orig. wPg2 promoted on g8, so g7xh6 happened early). 1.dxe3 e.p. 2.fxg1=B 3.0-0 Tg4# (2003-03-21)
James Malcom: Is this the only know one-sided Valladao in a regular series-mover helpmate? Also, can wPh2 be shifted to h4, and the White king moved as well to h2, so that the solution must have 2. fxg1=S? (2020-12-08)
James Malcom: Well, the only known one that is in minimum form, i.e. 3 moves, I mean. (2020-12-08)
A.Buchanan: This is nice. I don't know of any other AP ser-h#3 with Valladao, but there could be. Just been cleansing PDB data today. Yes I think wKh3 and wBh2 can be transposed, and then promote to S instead of L. (2020-12-08)
A.Buchanan: The legality of intermediate positions in seriesmovers is of course irrelevant. However, each proof game that leads to the diagram position with BTM can be appended with a black move and then a "flip" that changes the player to move. We can repeat this process, and then the fact that Black retains castling rights implies that they had castling rights in the diagram position. I think this is the right formal way to handle AP with seriesmovers. (2022-03-21)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (sk), Seriesmover, Promotion, Valladao Task
Genre: Retro, Fairies
Computer test: C+ Popeye v4.85 + thinking
FEN: 4k2r/1pp2p1p/1N5p/3P4/2RpP2N/P2P1P1K/p1BP1p1P/B3b1R1
Reprints: Die Schwalbe 143 10/1993
Rex Multiplex 45-46 05/1994
(XII) Quartz 5 1997
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
24 - P0003100
John Derek Beasley
Cambridge 1985
P0003100
(3+8) C+
h#2
Zeroposition
a) -sBe4
b) -sSf5
a) 1. Sg3 Kxh4 2. Le4 hxg3#
b) 1. hxg3ep Kh4 2. Lf5 hxg3#
play all play one stop play next play all
Henrik Juel: in a) last move could be Kg2-h3
in b) last move must be g2-g4 (2024-01-14)
more ...
comment
Keywords: En passant as key, Zeroposition
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 & trivial retro-logic
FEN: 8/7b/8/4pn2/4pkPp/4pp1K/7P/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-01-15 more...
25 - P0003122
Albert Zickermann
789 Kieler Neueste Nachrichten 18/03/1934
P0003122
(3+6)
h#2
1. fxg3ep Lxg7 2. Lg4 Lf6#
play all play one stop play next play all
A.Buchanan: Sg7 would be better than T, from both forward & retro perspectives I think? (2021-04-14)
comment
Keywords: En passant as key
Genre: h#, Retro
FEN: 7B/6rp/7K/8/5pPk/5b1r/8/8
Input: Gerd Wilts, 1995-06-03
26 - P0003132
Frank Bentler
10997 Schach-Echo , p. 228, 06/1985
P0003132
(9+13) C+
h#2
1. axb3ep Texf1 2. b2 Kd2#
play all play one stop play next play all
more ...
comment
Keywords: En passant as key, En passant
Genre: h#, Retro
FEN: n7/2ppp1p1/1p6/B7/pP6/5PP1/p4pPP/rk1KRrRn
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2021-02-11 more...
27 - P0003138
Branko Koludrovic
4208 Problem 12/1979
P0003138
(11+9)
h#3 (AP)
0.1...
1. ... axb6ep 2. 0-0-0 0-0-0 3. Td7 a8=D#
play all play one stop play next play all
This problem can be solved presuming that both castlings are executable. It implies that the last halfmoves have been.-1.Bb6xa7 sBb7-b5.
Bb5 could not come from c6 (sBc6xFb5), because all of the missing white pieces(5) have been captured on white squares except wLc1,which must have been captured by Bc7(Bc7xwLb6).Further,it has not played immediately before -1.Bb6-b5 because this would prevent white castling(forcing wT or wK to move)
Here is the proof that 4 remaining white pcs have been captured on white squares:
black d-pawn must have been captured on d4 and h,g f pawns had to promote after Bh3xwFg2,then wBh2moved to h4, enabling Bg4x Fh3 ..h1T, and finnaly sBf7
after fxg2... g1S. sLf1 prevented the check from Th1, and later has been captured by a white officer.
Conclusion:
Retro:-1.wBb6xFa7 Bb7-b5
Forward(AP) 1....axb6 e. p.2.0-0-0 0-0-0 3.Td7 a8Q# (Author)
Branko Koludrovic: P.S.
The black pawn a4(on the diagramm)came from c7 after capturing the white bishop on b6, then moving to b5 and capturing a white officer on a4. (2010-09-28)
A.Buchanan: I think sBf must have captured on g2 & then promoted on f1 to S, otherwise it’s impossible to unlock the southeast cage (2023-07-11)
A.Buchanan: So that means it’s sound. However I don’t see that it needs to have been sL shielding on f1 (2023-07-11)
more ...
comment
Keywords: a posteriori (AP), En passant as key, Castling (sgsgwg), Promotion (D), Valladao Task
Genre: h#, Retro
FEN: r3k3/P3p3/p7/Pp6/p6P/2P3PR/2PPP2b/R3K1nr
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-07-11 more...
28 - P0003142
Marco Bonavoglia
3652 Sinfonie Scacchistiche 01-03/1982
P0003142
(6+5) C+
h#2
b) +sTd4
a) 1. Sxb4 Sxc3 2. Ka5 Sxc4#
b) 1. cxb3ep Sc4 2. Sb4 Sxc3#
play all play one stop play next play all
Henrik Juel: In a) last move could be Kb2-a1 (2022-12-05)
more ...
comment
Keywords: En passant as key, Cant ep, Zilahi
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: 8/8/8/1P6/kPp5/N1p5/n1pP4/KN6
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-06 more...
29 - P0003143
Zvi Roth
947 Shahmat 08/1972
P0003143
(6+7) C+
h#2*
*) 1. ... Kxb3 2. Txd5 Txd5#
1) 1. bxc3ep Kxb3 2. Txd5 Lxc3#
play all play one stop play next play all
A.Buchanan: Attractive. It reminded me of P0003347, which I have just discovered is sound as set play. (Just omit the first move!) Here part of the interest, although the intermediate moves are the same, the mating move is different, but in both cases has to cover d4 & e5. (2020-12-09)
more ...
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: C+ Popeye 4.61
FEN: 8/8/1P6/BRrP4/KpPkp3/1r1nq3/8/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-12-09 more...
30 - P0003151
Laszlo Talaber
Tivadar Kardos

3649 Arbejder-Skak 01/1954
1. Preis
P0003151
(9+16) C+
h#2.5*
* 1. ... ... 2. fxe3ep Sge4 3. Txe4 Sf3#
1. ... e5 2. dxe5 Sde4 3. fxe4 Sf5#
play all play one stop play next play all
Sally: Der letzte Zug war e2-e4! (2010-04-06)
A.Buchanan: Great harmony between the phases (2021-11-23)
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye C-Version 3.52 & trivial retro-logic
FEN: 8/7p/3p3p/2nq1ppP/p1PkPp1r/P1p3N1/n2N2Pb/1b1r1B1K
Reprints: (XX) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-23 more...
31 - P0003180
Jozsef Korponai
6875 Arbejder-Skak 02/1968
P0003180
(12+12)
h#2
1. hxg3ep Sc1 2. gxf2 Se3#
play all play one stop play next play all
Welches ist die Originalquelle? Oder wurde es zweimal als Urdruck gebracht?

vgl. P0003291
Henrik Juel: White pawns captured all four missing black men
Last black move was not b7xPa6 ([Ta8]) nor e7-e6 ([Lf8]), so it was Lb7-c8, which is possible only if last white move was g2-g4
C+ Popeye 4.61 and above analysis (2021-04-23)
comment
Keywords: En passant as key
Genre: h#, Retro
FEN: 2b5/p2p2pp/p3p2b/6Pr/5BPp/2P5/NRP1PP1P/3Nrk1K
Reprints: F84 The Problemist 05/1970
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2021-04-23 more...
32 - P0003187
Thomas R. Dawson
6577 British Chess Magazine 12/1944
P0003187
(12+14)
h#1.5
1. ... bxc6ep 2. b5 Txa3#
R: 1. ... c7-c5 2. f4xTg5 Tg6-g5 3. f3-f4 Ta6-g6 4. f2-f3 Sc6-a7 5. h4-h5 Ta8-a6 6. h3-h4 a6-a5 7. h2-h3 Ka5-a4 8. b3-b4 Ta4-a3
or R: 1. f4xTg5 Tg6-g5 2. f3-f4 Ta6-g6 3. f2-f3 Sc6-a7 4. h4-h5 Ta8-a6 5. h3-h4 a6-a5 6. h2-h3 Ka5-a4 7. b3-b4 Ta4-a3
but we are told that White has the move.
play all play one stop play next play all
Henrik Juel: Stipulation should probably be interpreted to mean h#1.5 . -1... c7 -2.f4xTg5 Tg6 -3.f3 Ta6 -4.f2 Sc6 -5.h4 Ta8 -6.h3 a6 -7.h2 Ka5 -8.b3 Ta4 etc. (2004-03-18)
A.Buchanan: Idea I suppose is that Black just moved, and moreover it was pawn double hop. I don't see clearly far enough back to confirm that. (2021-10-21)
Mario Richter: If Black moved last, the only legal retraction is R: 1. ... c7-c5! But the position can also be resolved if White moved last, starting with R: 1. f4xTg5 Tg6-g5 2. f3-f4 Ta6-g6 3. f2-f3 Sc6-a7 4. h4-h5 Ta8-a6 5. h3-h4 a6-a5 6. h2-h3 Ka5-a4 7. b3-b4 Ta4-a3.
Therefore the keyword "No legal last move for White" doesn't apply here; and to make the solution work, the Stipulation should be something like "h#2 0.1.1." or "h#1.5". (2021-10-21)
Henrik Juel: HC+ Popeye 4.61 (2021-10-22)
A.Buchanan: To my mind, the retro thinking is serious enough that we can’t claim HC+. If a tool like Replicator 2.0 was to validate the retro status I’d be ok. But I think it would be misleading to put HC+ to indicate the trivial h#1.5 is sound. We can certainly mark that Popeye has checked the h#, but not click the C+ flag. What do you think? (2021-10-22)
Henrik Juel: HC+ is not recognized (yet) by PDB, and I suppose it just meant that some sort of human analysis is needed in addition to a standard forward solver like Popeye
You are suggesting that we distinguish between easy and difficult human analysis and say HC+ for easy analysis only
I suggest saying HC+ for all problems where Popeye is not sufficient; you can write easy or difficult in the C+ comment
If and when a human analyst proves the analysis wrong, we delete the HC+ label, of course (2021-10-22)
A.Buchanan: What does Mario think? He invented the term, I seem to remember (2021-10-22)
comment
Keywords: En passant as key
Genre: h#, Retro
FEN: 2b5/np1p2pp/7q/pPp3PP/kP6/r1PPP3/RKpp2P1/BB2n3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-21 more...
33 - P0003188
Fritz Hoffmann
11614 Schach 04/1988
P0003188
(4+9)
h#2
b) Schlüsselfigur nach f3
a) 1. Sxg4 f3+ 2. Kh5 fxg4#
b) 1. fxg3ep fxg3 2. Kh5 g4#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61 (2021-05-04)
comment
Keywords: En passant as key
Genre: h#, Retro
FEN: 8/4pp2/7p/5K2/5pPk/4r2r/3n1P1n/4B3
Input: Gerd Wilts, 1995-06-03
Last update: Rainer Staudte, 2021-05-04 more...
34 - P0003194
Tivadar Kardos
1597 Schachmaty 05/1963
P0003194
(6+14) C+
h#2
1. cxd3ep? bxc3 2. Lxf4 Lxg2# Last move not d2-d4
1. gxf3ep! bxc3 2. Lf4 Lf5# Last move f2-f4
play all play one stop play next play all
White's last move was certainly one of the two double pawn hops. The last move couldn't be d2-d4 because Black's pawns had already captured 10 of White's pieces, and playing d2-d4 would have resulted in wBc1 being White's 17th piece. So, the only solution is 1.gxf3 e.p.
Viktoras Paliulionis: The last move couldn't be d2-d4 because Black's pawns had already captured 10 of White's pieces, and playing d2-d4 would have resulted in wBc1 being White's 17th piece. So, the only solution is 1.gxf3 e.p. (2023-12-30)
A.Buchanan: Yes that's right! (2023-12-31)
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye C-Version 4.87 & trivial retro-logic
FEN: 2n1q3/5prp/5K1b/3b4/2pPkPp1/2p1p1pB/1P4pP/8
Reprints: 546 FIDE Album 1962-1964 1968
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-31 more...
35 - P0003195
Thomas R. Dawson
2130 Die Schwalbe 07/1932
P0003195
(14+14) C+
h#2
WTM
1. ... bxc6ep 2. Da7 c7#
retro tries:
1) 1. Lxg3 b6 2. Lxd6 Lxd6#
2) 1. Dc6 b6 2. Dc7 dxc7#
3) 1. Ta7 f8=D,f8=T 2. Ka8 Dxc8#,Txd8# ("untolerated" dual)
R: 1. ... c7-c5 2. b4-b5 Dc4-a6 (move order variable beyond this point) 3. b2-b3 Ta6-a8 4. d5-d6 Te6-a6 5. b3-b4 Te8-e6 6. a2xSb3 Th8-e8 7. d4-d5 Lb4-e1 8. d3-d4 Lf8-b4 9. Kg5-h5 e7xSf6+
play all play one stop play next play all
Missing: Wh: SS Bl: SS
Pawn captures: Wh: axb, hxg Bl: exf, fxg
bPf6 comes from e7, else collision with wPf7. So can't uncapture fxg2 until wP retracted. White has 6 pawn retractions before retro-pat, just giving Bl time to put Le1 & Ta8 (impostor) back home, and uncapture exf6. So Black must retract first, and it's WTM. sD must clear out of the way, and c4 is the only possible square, wPaxSb can't happen on b5, or it would block sD. And axSb4 would block sLe1. It was axSb3. So wPb5 must retreat to b4, and thus Black cannot play R: 1. Lb4-e1. So neatly R: 1. c7-c5 is forced.
Ladislav Packa: Is wRh1 needed? (2021-10-22)
Mario Richter: Yes, wRh1 is needed - without it the ep-key would not be justified (last moves could have been R: 1. ... Th1-g1 2. Lg1-h2 or even R: 1. ... Ld2xTe1). (2021-10-23)
A.Buchanan: + three mostly clean retro tries. (2021-10-24)
more ...
comment
Keywords: En passant as key, No legal last move for White, Impostor (t)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & simple retro-logic
FEN: rkb5/1p1p1Ppp/q2P1p2/pPp4K/6PR/1P4PQ/2P1P1pB/4bBrR
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-08 more...
36 - P0003200
William H. Reilly
British Chess Federation 05/1944
2. Preis
P0003200
(4+9) C+
h#4
1. bxc3ep Sxg2 2. cxd2 Sxh4 3. Ke3 Kg3 4. Te4 Sf5#
play all play one stop play next play all
A.Buchanan: So no twinning in the original? What's the point of sDb3? It can be replaced by sB without issue. This problem doesn't appear in WinChloe, so can't check (2021-02-12)
VL: The author could, e.g., prefer the position with black Queen as richer and more hidden for solution. (2021-02-12)
A.Buchanan: Hi Valery well dressing the board is a hypothesis. There is no try to compensate for loss of economy. Indeed here sD forms a distracting battery which “pins” sLd3. It’s all too easy to add this kind of “richness” (noise) to a problem but more is less in my humble opinion. Unless it was a thematic tourney or we are missing a twin, my top hypothesis is that the composer did very well without a computer to make a sound h#4, and it’s easy these days to see a minor improvement. (2021-02-13)
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comment
Keywords: En passant as key, En passant
Genre: h#, Retro
Computer test: C+ Gustav 4.1d
FEN: 8/8/8/8/rpPk3p/1q1b3K/3Pp1rn/4N3
Reprints: 49 PCFT 1944-1945
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-02-13 more...
37 - P0003206
Hans Joachim Schlüter
4443v Schach , p. 349, 11/1963
P0003206
(5+8)
h#2
b) wTf1 tauschen mit wLg1
a) 1. Kxb4 Lb6 2. a4 Tb1#
b) 1. cxb3ep gxf3 2. Sc1 Tg4#
play all play one stop play next play all
Korrektur 1964, Seite 155: sBh3->f3
Henrik Juel: C+ Popeye 4.61 (2022-11-24)
comment
Keywords: En passant as key
Genre: h#, Retro
FEN: 8/8/8/p7/kPp5/p1p2p2/4n1Pp/5RBK
Input: Gerd Wilts, 1995-06-03
Last update: Felber, Volker, 2022-11-24 more...
38 - P0003207
Klaus Gerber
4497 Schach , p. 30, 01/1964
P0003207
(4+9) C+
h#3
1. exf3ep c3 2. Df7 Ke4 3. Dh5 exf3#
play all play one stop play next play all
A.Buchanan: Can shift bQd5 to c4, while replacing bRg5 with bP to reach Meredith status. bBh4 can also be downgraded to bP. But probably even more economy is possible by shifting pieces one file to the right, keeping the ep, White tempo & model mate, which seem to be the main features (2022-11-30)
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comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: 8/8/8/3q2r1/2p1pPkb/4K1pp/2PrP3/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-30 more...
39 - P0003221
Thomas R. Dawson
1511 The Chess Amateur 10/1929
P0003221
(9+16) C+
h#2
1. ... bxc6ep 2. Le7 cxd7#
1. Lc6? bxc6 2. Le7 cxd7# WTM
R: 1. c6-c5? Kd3-e3 2. Dc5-c4+ Ke3-d3 3. Dc4-c5+ retro-loop.
R: 1. c7-c5! Kd3-e3 2. Dc6-c4+ Ke3-d3! clear
play all play one stop play next play all
Easy to see no last move for White. Moreover, Black just double-hopped to allow sD/wK to avoid retro-loop.
Single clean retro try.
more ...
comment
Keywords: En passant as key, No legal last move for White
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & moderate retro-logic
FEN: 3nkr2/3p1r2/1p1npb2/PPpb4/Bpq2PP1/1p2Kpp1/2PPP3/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-08 more...
40 - P0003236
Thomas R. Dawson
10381 The Fairy Chess Review 12/1955
P0003236
(9+16) C+
h#2
1. ... bxc6ep 2. Dxa5 Db7#
1. Sc6? bxc6 2. Dxa5 Db7# but WTM
R: 1. ... c7-c5 2. g5-g6 Sc6-e7 3. De7-b4,D~ Sb4-c6+ unpromote wD on h8, etc.
play all play one stop play next play all
Clean retro try
Henrik Juel: Typo: 2.Dxa5 Db7#. wTa1 is missing, I think (10+15). -1... c7 -2.g5 Sc6 -3.De7 Sb4, unpromote wD on h8, etc. (2004-03-18)
A.Buchanan: I agree Henrik and have made changes. A number of these problems have been marked "Weisz zieht an", which is inappropriate as part of the point of the problem is to deduce this. I think it's 2. c2-c3! not 2. g5-g6? or the cross-captured pawns become retro-locked. (2021-10-21)
Henrik Juel: 2.g5-g6 also works, because the only cross-capture is axb,bxa
White captured [Pd7] with an officer (2021-10-22)
Henrik Juel: HC+ Popeye 4.61 (2021-10-22)
A.Buchanan: If g5-g6 also works, then can’t we have both? I.e. White moved last. I would be surprised if this was TRD’s intention, given the others of this general style (2021-10-22)
Henrik Juel: TRD died in 1951, so someone else may have messed up the problem
FRC is not generally available after 1953, so I cannot check the source (2021-10-22)
A.Buchanan: WinChloe has 29(!) posthumous problems by Dawson - the latest in 1958, FCR's final year. The composition in question is not one of them. (2021-10-23)
A.Buchanan: PROOF OF COOK + SUGGESTED FIX
I agree with much of what you say Henrik.
Capturing history. Basically 3 possibilities for the Black pawns.
Notation: ~,o,| denote "cross-capture", "original" & "waylaid"(=captured on home file by officer).
1) a~b co d~e f~g. This implies either (wPhxg & bPh=X) or (wPh=X & bPh|)
2) a~b co d~e hxgxf f|
3) a~b co hxgxfxexd d|
Suppose WTM. Then R: 1. c6-c5 c2-c3 2. c7-c6 g5-g6 3. Sc6-e7 De7-b4 4. Sb4-c6+ Kc5-c4 5. Lb2-d4+ etc. Now we're free to uncapture wDh8 (or g8 for scenario 1), and any of the three pawn scenarios can work. No e.p. rights means a cook.
If we fix it by e.g. shifting wPg6-g5 then I think that fixes this cook, and also it means that there is no solution if BTM.
Is there any possibility for premature capturing hxg? Not by Bl because scenario 1 says bPfxg, and the other two scenarios rely on wPh=X. If by Wh, then there's no waylaying on d or f, so we are back to scenario 1, but bPh is blocked from promotion, so that won't work.
But: what about R: 1. c6-c5 c2-c3 2. Sc3-b1 Th1-a1. Doesn't this completely cook it anyway?? How about k7/4n3/6P1/PPpPPP2/qQKbrrp1/ppRppp2/b1P5/1n6? h#2 (with Art 15 so it's really h#1.5)
Do you agree? (2021-10-23)
Mario Richter: In the diagram, both for WTM and BTM the retraction sequence c2-c3 Sc6-e7 De1-b4 Sb4-c6+ works and furthermore Andrew's R: 1. c6-c5 c2-c3 2. Sc3-b1 Th1-a1 shows, that Henrik's guess of the omitted wTa1 might be wrong. Instead, I think that Andrew's modification might be in fact the original Dawson diagram. (2021-10-23)
A.Buchanan: Yes that makes sense. I can well believe that there was a lot of constructions in flight when TRD passed away. It's not surprising that something appeared a few years later. Can we get access to FCR from that year to validate? (2021-10-23)
A.Buchanan: Brian Stephenson kindly checked the original magazine. He wrote:
"Eventually got round to looking out this TRD problem. It was published in the issue you quote as problem 10381. The diagram in PDB is wrong. There should be a bPc2. The solution was published in FCR April 1956 as: 1.Pb5xPc5ep Qxa5 2.Qb7#. Last moves must have been 1.Pc7-c5 Pg5-g6 2.Sc6-e7 Qe7-b4 Sb4-c6 ch etc. No flaws were noted, but I have looked later than that issue. Hope this helps." (2021-11-13)
A.Buchanan: The appearance of the 16th Black unit thanks to the offices of Brian Stephenson simplifies the retro logic substantially, and the solution seems sound. Amazing how much disruption a simple typo can cause, but at least this one I believe is laid to rest (2021-11-13)
more ...
comment
Keywords: En passant as key, No legal last move for White
Genre: h#, Retro
Computer test: HC+ Popeye 4.6 + non-trivial retro
FEN: k7/4n3/6P1/PPpPPP2/qQKbrrp1/ppPppp2/b1p5/1n6
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-08 more...
41 - P0003240
Gabor Tar
Magyar Sakkelet 06/1972
P0003240
(4+10) C+
h#2
b) sLe3 nach f3
a) 1. f3 Lxa7 2. Lg5 Lxf2#
b) 1. fxg3ep Lxc7 2. Lh5 Ld8#
play all play one stop play next play all
Henrik Juel: a) C+ Popeye 4.61
b) the ep capture is unjustified, last move could be Ke2-f1 or f3xg4 (2023-08-06)
A.Buchanan: There was an error in the stipulation: "b) sLe3 nach h2 (-wSh2)" is completely incorrect. However "b) sLe3 nach f3" leads to a very nice problem which matches the solution already present. This problem is not in WinChloe, but I am sure this is the resolution of the mystery (2023-08-07)
Henrik Juel: You are probably right, Andrew; maybe there was a misprint in the source
Now part b) is C+ Popeye 4.61 after very simple analysis (2023-08-07)
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye v4.61 & simple retro-logic for b)
FEN: 1B6/npp5/8/8/5pPk/4b2p/3p1p1N/5Kn1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-08-07 more...
42 - P0003281
Fritz Hoffmann
Problem 08/1974
P0003281
(4+11) C+
h#2
3.1...
1) 1. Tb1 Lxf3 2. Tb3 Lc6#
2) 1. Lc6 Le4 2. Lb5 Lc2#
3) 1. cxb3ep Lxc3 2. Lc6 Lxc6#
play all play one stop play next play all
more ...
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: C+ Popeye 4.61
FEN: 8/8/1b6/B7/kPp3p1/p1p2b1p/6Bp/3r1n1K
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-05-05 more...
43 - P0003287
Tomislav Petrovic
(VIII) Problem 37-40 09/1956
P0003287
(5+9) C+
h#2
1. fxg3ep h8=S 2. Sg4 Sxg6#
play all play one stop play next play all
A.Buchanan: The point I think is that the en passant is a tempo move. Otherwise wBf2 serves no purpose. How about sBh5 instead of sT? (2021-10-19)
more ...
comment
Keywords: En passant as key, Promotion (S), Tempo Move
Genre: h#, Retro
Computer test: HC+ Popeye v4.61 & trivial retro-logic
FEN: 8/7P/6pP/6pr/5pPk/4np1n/5P1p/7K
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-19 more...
44 - P0003288
Vladimir Korolkov
211 Biuletyn 03/1960
P0003288
(9+10)
h#2
1. fxg3ep Lxe3 2. Ld5 cxd5#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61 and very simple analysis (2022-08-09)
comment
Keywords: En passant as key
Genre: h#, Retro
FEN: 8/8/8/1PP1P2r/PRPBbpPk/ppKppp1r/8/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2022-08-09 more...
45 - P0003291
Jozsef Korponai
5412 Arbejder-Skak 02/1961
P0003291
(11+13) C+
h#2
1. hxg3ep Sd4 2. gxf2 Se3#
play all play one stop play next play all
vgl. P0003180
Henrik Juel: Last move was g2-g4 giving Black a preceeding move like Da8-b8 or Lb7-c8
C+ Popeye 4.61 (2021-04-24)
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 + simple retro thought
FEN: 1qb5/b1pp1ppp/pp6/6P1/5BPp/2P5/1PN1PP1P/3Nrk1K
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-04-25 more...
46 - P0003297
Wilhelm Hagemann
Deutsche Nachrichten (Sao Paolo) 1960
P0003297
(5+9)
h#2
1. cxd3ep f4 2. Lf3 Kxc5#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61 (2022-04-18)
Henrik Juel: Obviously, last move was d2-d4 (2022-04-18)
comment
Keywords: En passant as key
Genre: h#, Retro
FEN: 8/8/p7/P1r2p2/RKpPk3/p1p1p3/5P2/3b4
Input: Gerd Wilts, 1995-06-03
Last update: Rainer Staudte, 2022-04-18 more...
47 - P0003312
Gerhard Paul Latzel
2680 Deutsche Schachzeitung 02/1970
P0003312
(7+14) C+
h#3
1. cxb3ep e5 2. Lh6 g5 3. Txh4 Txh4#
play all play one stop play next play all
Henrik Juel: The only possible last move is b2-b4, so the ep key is permissible
C+ Popeye 4.61 (2021-07-26)
A.Buchanan: The main idea is to unblock the cluttered 4th rank, and this is complemented thematically by *blocking* four other lines: g8-g4, h8-h4, h8-d4 & "blocking the blocker" h6-f4.
The last move was b2-b4, so by the ep rule, capture is definitely legal. The convention only serves to resolve ambiguous situations where multiple possible histories exist. In retro problems, such ambiguity is rare if the retro logic does its job. However the pessimistic nature of the e.p. convention motivates *why* the retro play must exist. (2021-07-26)
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: Last move was b2-b4, so by ep rule, capture ok as key. HC+ Popeye 4.61
FEN: 6rq/pn6/K7/8/kPprPbPP/p1pppppR/7P/8
Input: Gerd Wilts, 1995-06-03
Last update: Rainer Staudte, 2021-07-26 more...
48 - P0003316
Eduard Schlatter
590v Schach-Echo 05/07/1955
P0003316
(4+15)
h#4
1. bxc3ep Kxa3 2. Ld5 Sg2 3. Tce1 Kb4 4. T1e4 bxc3#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61
The only possible last move is c2-c4 (2021-08-04)
comment
Keywords: En passant as key
Genre: h#, Retro
FEN: 8/2p5/2p3pq/n3r3/KpPk1pp1/bp1p4/1P4b1/2r1N3
Input: Gerd Wilts, 1995-06-03
Last update: Dieter Berlin, 2021-08-04 more...
49 - P0003323
Peter Takacs
Imre Telkes

285 The Chess Amateur 12/1922
P0003323
(3+13) C+
h#2
1. gxf3ep Dxh2 2. Ld3 Dxh4#
play all play one stop play next play all
more ...
comment
Keywords: En passant as key, Selfblock, Line opening
Genre: h#, Retro
Computer test: C+ Popeye 4.61 and very simple analysis
FEN: 6n1/2r4q/3pK3/7p/4kPpp/4r1pQ/7n/b4b2
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-06 more...
50 - P0003325
Tivadar Kardos
4272 Arbejder-Skak 08/1956
P0003325
(6+13) C+
h#5
a) 1. gxf3ep g4 2. Kd5 gxf5 3. Kc6 fxe6 4. Kb7 exd7 5. Ka8 dxc8=D#
play all play one stop play next play all
A.Buchanan: Popeye v4.87 (via Olive v1.4 ) for PDB problem P0003325 h#5 delivers the correct solution with en passant set to f2f3f4. However no solution when the "intelligent" flag is also set. Reported to Popeye Github. (2021-11-23)
Henrik Juel: Popeye 4.61 with 'opt var int enp f3' works fine
Maybe you just have to change f2f3f4 to f3, Andrew (2021-11-23)
A.Buchanan: Thanks for the suggestion, Henrik, but even without the "intelligent", opti vari enpa f3 fails with v4.87. I think that the syntax has been rendered more complicated since v4.61 in order to support fancy fairy en passants. (2021-11-23)
comment
Keywords: En passant as key, Promotion (D), Excelsior, Pac-Man
Genre: h#, Retro
Computer test: HC+ Popeye C-Version 3.52 & trivial retro-logic
FEN: 2n5/p2p4/4b3/p4p2/P3kPp1/Ppp5/Pp4P1/bK2n3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-23 more...
51 - P0003326
Tivadar Kardos
4252 Arbejder-Skak 07/1956
P0003326
(3+13) C+
h#5
1. dxc3ep Kxg7 2. f6 Kxf6 3. e5 Kxe5 4. Lc4 Kd4 5. Lb5 dxc3#
play all play one stop play next play all
A.Buchanan: Can be done with lighter material e.g. sLa5, sBa4, sSa3g7 (2021-11-23)
more ...
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: Popeye C-Version 4.87 & trivial retro-logic
FEN: 6bK/5pr1/2p1p3/p4p2/rkPp4/qp1p4/3P4/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-23 more...
52 - P0003328
Tivadar Kardos
4311 Arbejder-Skak 09/1956
P0003328
(7+16) C+
h#3
1. cxb3ep Sb4 2. Sc4 Sc2 3. Sa5 Sxc3#
play all play one stop play next play all
Henrik Juel: The only possible last move is b2-b4
C+ Popeye 4.61 (2021-04-24)
comment
Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 & simple retro thought
FEN: 8/2p5/2P5/2p2p2/kPp2Pn1/n1pp1Kp1/N2P2pb/rNr1q2b
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-04-25 more...
53 - P0003337
Rudolf Buljan
Problem 41-44 03/1957
2. Preis
15. Thematurnier
P0003337
(11+15) C+
h#2
1. ... exf6ep 2. Sf5 f7#
play all play one stop play next play all
White captured fxg and promoted [Pd2] on d8
Black captured axbxa2-a1=Y, b7xc6, d5xe4, and gxf
White cannot have moved last, and in fact Black's last move can only have been f7-f5 in order to give White a prior move. R: 1... d5-e4 would have retro-blocked wPd marching to its promotion.
So the retroplay was R: 1... f7-f5 2.f5xYg6
Numerous retro tries but none distinct.
"Autor Ing. Rudolf Buljan, Zagreb"
AB: Have therefore marked him in the author table as Croatian. Yugoslavia has been removed from the PDB country list, I see.
A.Buchanan: Any ideas how to distinguish usage of “whose move?” and “no legal last move for white” (or black) keywords (2020-10-01)
Henrik Juel: This problem is clearly the latter
I would use 'Whose move?' in retro problems where a deeper analysis is required to determine the move, often with stipulations like '#1 (who?)' (2020-10-01)
A.Buchanan: I think "Whose move?" is where there is no forward stip, or where we have to determine if the forward stip should be interpreted as orthodox or as half-duplex. "no legal last move for..." is where the mater/stalemater/etc is the usual one, but we add or remove a single move at the beginning of the forward stip. I guess a third possibility is "last move?" where in a Type A position we also have to figure out who moved last.
With respect, I don't think the level of analysis can be relevant. (2023-12-06)
more ...
comment
Keywords: En passant as key, No legal last move for White
Genre: h#, Retro
Computer test: Popeye 4.61
FEN: 5nkb/1qp1p1n1/2p3PQ/4PpKb/4prRp/P4prB/1PP3PP/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-06 more...
54 - P0003347
Marko Klasinc
3. Makuc-Moder-Gedenkturnier 1971-1973
1. Lob
P0003347
(7+6) C+
h#2
1. axb3ep bxc6+ 2. b5 cxb6ep#
play all play one stop play next play all
Marko Klasinc: The most economical h#2 with two e.p. captures. (2002-01-28)
A.Buchanan: Very nice - and i think this is unbeatable at least in the case where ep is first and last move (2020-08-02)
A.Buchanan: Also works as set play! Just truncate Black's first move! :) (2020-12-09)
more ...
comment
Keywords: En passant as key, Economy record, En passant as mating move
Genre: h#, Retro
Computer test: C+ Popeye v4.61 + a little thinking
FEN: 8/1p6/B1p5/RPP5/pPkp4/K1p5/P7/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2020-12-09 more...
55 - P0003359
André Hazebrouck
3256 Themes-64 07-09/1977
P0003359
(14+10) C+
h#2
2.1...
1) 1. 0-0 Le6+ 2. Kh8 Sg6#
2) 1. bxc3ep 0-0 2. 0-0-0 Tc4#
play all play one stop play next play all
If all three castlings are legal, then the ep is on. So evidence must be accumulated from the two solutions. White 0-0 serves only in this retro role, eliminating 26 other candidate solutions.
A.Buchanan: There was a diagram error here. It should be bPd7 not bPe7. The existing diagram is vastly cooked with e.g. 1. Ke8 Kd1 2. Te8 Lb6#. WinChloe has the correct diagram here. (2022-05-24)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wksksg)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & retro logic
FEN: r3k2r/B2p2pp/8/NP6/RpP4N/pP5B/1p1PPPP1/n3K2R
Reprints: feenschach 54 04/1981
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-06 more...
56 - P0003366
Laszlo Lindner
3040v Europe Echecs 07-08/1982
P0003366
(8+16)
h#2
b) sBc7 nach f6
a) 1. Dc4 Lxb6+ 2. c5 dxc6ep#
b) 1. fxe3ep Lxb4 2. Sc4 bxc3#
play all play one stop play next play all
Lindner in 'Mattbilder eines Lebens':
In a) ist die Lösung der stellung b) nicht möglich, weil das e.p.-Schlagen durch Schwarz nicht legal ist. Der letzte Zug von Weiß muß nicht unbedingt e2-e4 geweseb sein. Es kommt als letzter zug auch Kh3-g2 in Betracht, mit den vorherigen Zügen h4:g3 e.p.+ und g2-g4.
In b) demgegenüber sind Kh3-g2 und vorher f4:g3 e.p. illegal, weil die Rücknahme von g2-g4 unmöglich ist: der sB würde 7 Schlagfälle benötigen, und es fehlen nur 6 weiße Steine. Der letzte weiße Zug muß also e2-e4 gewesen sein.
In 'Mattbilder eines Lebens' abgedruckt mit sTh7 statt h8 und der Quellenangabe: Europe Echecs, 1964
AB: (1) Where is wK?
(2) Why is 1.fxe3ep legal in b) but not a)? (2002-01-31)
Henrik Juel: wK is probably on g2. In part a) last move could have been Kh3-g2, I think (2002-02-01)
A.Buchanan: Very convincing, Henrik. I've repaired the diagram accordingly. (2023-05-28)
comment
Keywords: En passant as key, En passant in the retro play
Genre: h#, Retro
FEN: 7r/2pn4/1nqRb3/B2Pp3/pb1kPp2/2p2Pp1/1PP2pKp/7r
Reprints: 501 Mattbilder eines Lebens , p. 379, 1996
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2023-05-28 more...
57 - P0003369
Valerian Onitiu
6643 The Fairy Chess Review 02/1946
P0003369
(14+11) C+
h#1*
1. ... fxg6ep#
1. dxe3ep fxe3#
play all play one stop play next play all
Gerald Ettl: Der rumänische Autor zeigt, dass der letzte Zug jeweils ein Doppelschritt g7g5 oder e2e4 gewesen sein muss. Die wBc6,d7 schlugen ueber Kreuz und der wUW-L hat bxaB und a7xXb8 geschlagen. Die Forderung lautet wohl h#1 (2010-07-12)
Alfred Pfeiffer: Ja, die Forderung ist h#1*.
Online: "http://problem64.beda.cz/silo/fcr_4_1946.pdf" (2010-12-15)
more ...
comment
Keywords: En passant as key (2), Promotion (L), Non-standard material (L)
Genre: h#, Retro
Computer test: C+ Popeye 4.61 and analysis
FEN: 4b3/1p1P1p2/2PRBR1P/2prpPpK/3pPkr1/5pN1/P4P1B/6B1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-06-30 more...
58 - P0003384
Tivadar Kardos
4299 Stella Polaris 12/1971
P0003384
(9+16) C+
h#2
b) alles eine Reihe nach links
a)
1. gxf3ep Sxg7 2. d5 Lf5#
1. cxd3ep? Sxc7 2. f5 Ld5#
b) 1. bxc3ep Sxb7 2. e5 Lc5#
1. fxe3ep Sxf7 2. c5 Le5#
play all play one stop play next play all
Sally: a)Der letzte Zug war: Bf2 - f4!
b)Der lrtzte Zug war: Bc2 - c4!
Nr. 139 200 Ausgwwählte S. Pr. T. Kardos (W. Frentze 1983) (2010-09-30)
Henrik Juel: Black pawns captured all 7 missing white men, incl. [Pa1], which promoted on a8
Only possible last moves are d2-d4 and f2-f4
In each twin the closing off for an original white bishop determines the last move (2021-11-22)
Henrik Juel: HC+ Popeye 4.61 (2021-11-22)
comment
Keywords: En passant as key, Twin by board shift
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & Retractor 2.1.1 Human contribution is "positions prior to retractions look legal enough."
FEN: 2bKNb2/2rn1pqn/3pBp2/4B1P1/2pPkPpr/2p1p3/1P2p2P/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-27 more...
59 - P0003387
Tivadar Kardos
(4) Land og Folk 22/12/1973
P0003387
(6+15) C+
h#1
1. bxc3ep Lxc5#
1. fxe3ep Le5#
R: 1. c2-c4,e2-e4
play all play one stop play next play all
Originalforderung? "2 Lösungen"
A.Buchanan: The original stipulation here asks for 2 solutions. I don't think this would work as 2 solutions under Retro Strategy protocol which was the default in those days. Dubious e.p. captures are just not permitted. This is why AP was invented as a funny work-around.
However this problem works under the PRA protocol, which decomposes the history as "one solution, two parts". Note that this problem does not make use of the e.p. convention, as it is certain that the two e.p. cannot be simultaneously legal. (2021-12-22)
Henrik Juel: I can strengthen the human contribution
The positions before c2-c4 and e2-e4 are surely legal (2021-12-22)
more ...
comment
Keywords: En passant as key, Partial Retro Analysis (PRA)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 + Retractor 2.1.1 Human contribution is "position prior to retractions looks legal enough."
FEN: 3K4/1rp1n3/3Bbnq1/N1p2Qr1/1pPkPpp1/1p1p1p2/8/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-12-22 more...
60 - P0003411
Norman Alasdair Macleod
3970 Themes-64 04-06/1982
P0003411
(4+6) C+
h#2 (AP)
2.1...
1. Kc3 0-0-0 2. Txc4 Txd3#
1. bxc3ep e4 2. Kc4 Ta4#
play all play one stop play next play all
The idea is that the ep in one solution is validated by the castling in the other solution. Since no other solutions exist, there are no parasites which might "piggyback" off the proof given by the castling solution. This is not PRA: both solutions have the same history with both castling & hence ep legal.
Mario Richter: How is the (AP) to be interpreted here? Is the intention as follows: Since in solution 1) White castles, Black is allowed to capture e.p. in solution 2)? (2011-05-28)
Henrik Juel: It seems to be an unusual situation, not covered by keywords like AP or PRA.
If last move was c2-c4, both solutions work; if not, there is no solution, because White may not castle.
(In the second solution, Kxc4 should be Kc4). (2011-05-28)
VL: This a generalized type of AP, which I call "consolidate AP": both solutions are considered as parts of one complete solution. However the order of both parts is significant. I know two similar problems: P0003437 and P0003186. (2011-06-01)
A.Buchanan: @Valery: I've started to classify all the AP problems in PDB. This and its kin are "Type Petrovic - cons" (standing for consolidated, but there's only a limited number of characters for a PDB parameter). I truly hope that the theory in the end will not have this as a special case, but rather is part of a more general pattern.
It's not just that PRA & RS each scales up within its own paradigm to handle seamlessly very complex collections of conditional move dependencies. They also scale *down* to handle situation when there is just one conditional move, or even zero conditional moves. And when n=0 or n=1, PRA & RS are in complete agreement. This is the kind of robust seaworthy behaviour we need if are going to set sail in the stormy seas of fairydom.
But small steps. The first thing is to classify all the problems in PDB into buckets, to find out what we have. I doubt there are 37 categories, so will probably need the results of your scholarship too. (2022-02-17)
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic consol), En passant as key, Castling (wg)
Genre: h#, Retro
Computer test: HC+ Forward play proved by Popeye v4.87 AP logic requires some framework but I think we know we want this cool idea to end up being sound.
FEN: 8/8/8/1nr5/1pPk4/1p1p4/4P3/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-09-12 more...
61 - P0003417
John Frederick Keeble
2206 The Problemist Fairy Chess Supplement 16, p. 173, 02/1936
P0003417
(4+5) C+
h#2.5 (AP)
1. ... exd6ep 2. 0-0-0 dxe7+ 3. Tf8 exf8=T,D#
play all play one stop play next play all
H.Juel: If Black may castle, last move was not made by Ke8 or Ta8, but by Pd5, so it was d7-d5, and hence White may capture en passant. 1... exd6ep 2.0-0-0 dxe7 3.Tf8 exf8=D,T# where the castling (belatedly) justifies the e.p. capture.
Not 1... exd6ep 2.Kd8? dxe7 3.Kc8 e8=D,T
AB: Another 120 retro tries (=60x2 due to tolerated dual promotion) of general form 1. exd6ep 2. T~ dxc7 3. T~ c8=D,T.
No set play
Nachdruck in "Die Schwalbe" 33 mit Diagrammfehler (wBe6 fehlt).
VL: The first AP-problem! Thematic illegal try:
1. ... exd6ep 2.Kd8? dxe7+ 3.Kc8 e8=T(D)#?? (2007-02-11)
Mario Richter: 46 years between this Problem and P1366663 - perhaps this was not Keeble's first AP-Problem?! (2019-08-29)
Ladislav Packa: Of course I know the idea a posteriori. But let my heresy be forgiven - I do not consider it logical. In this particular example, I consider e.p. for proof that black can castling - not vice versa. (2019-08-29)
A.Buchanan: Hi Ladislav. If ep is ok, then Black just moved a pawn with double hop. That doesn't stop Black having e.g. moved bK right at the beginning of the game. So you can't prove that Black definitely can castle this way. What am I missing here? (2019-08-29)
Ladislav Packa: Your statement is perfectly fine. However, the AP condition is usually interpreted as castling is evidence of e.p. However, the second party does not have to do castling - the possibility has already been demonstrated by the existence of e.p. (2019-08-29)
A.Buchanan: Hi again Ladislav. Please try again, I am obviously being very stupid. I don't understand how 1. exd6ep is any more indicative that Black can castle than 1. K~. (2019-08-30)
Ladislav Packa: Hi, Andre!
e.p. is just a result of the d7-d5 move. Black can castle only if it was the last move of black (even without wPe5). Therefore, it does not have the logic of joining the e.p. with castling. For example, ask yourself if black is allowed to castle in the position without wPe5. (2019-08-30)
A.Buchanan: @Ladislav: ep is not "proof that black can castle", rather it is a *necessary* condition for Black to be able to castle. The logical implication is the other way round. We can castle because of the optimistic convention, and because sPd might just have moved. Without wPe, there is no solution, but whatever White plays, Black can castle (2020-12-11)
Hans-Jürgen Manthey: was heißt hier Thematisch Illegal ??
Mir völlig wurscht ob ep möglich oder nicht, nach dem weißen Zug ist natürlich Kd8 möglich !!
also ist auch 1. ... exd6ep 2. Kd8 dxe7+ 3. Kc8 e8DT# eine Lösung, sonst müßte auf die erzwungende Rochade in der Aufgabenstellung hingewiesen werden ! (2020-12-11)
A.Buchanan: Can one tolerate “tolerated dual promotion” in Valladao? Well Valladao himself did, so it must be ok (2022-03-26)
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comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (sg), Promotion (D/T), Tolerated dual promotion (D/T), Valladao Task, Retro Strategy (RS)
Genre: h#, Retro
Computer test: Popeye 4.61
FEN: r3k3/2p1p3/2P1P3/2KpP3/8/8/8/8
Reprints: V. Die Schwalbe 33, p. 323, 06/1975
2001 CHM Themes 12/2000
3 Die Schwalbe 215, p. 240, 10/2005
A1 Problemkiste 169 02/2007
402 Eigenartige Schachprobleme , p. 130, 2010
14 Die Schwalbe 241, p. 374, 02/2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-10 more...
62 - P0003423
Matti Arvo Myllyniemi
3975 Stella Polaris 01/1971
P0003423
(7+11)
h#3 (AP)
0.2.1...
1. ... g6 2. 0-0 gxf7 3. Kh8 Le5#
1. ... cxb6ep 2. 0-0-0 bxa7 3. Td7 a8=D#
play all play one stop play next play all
Henrik Juel: Analysis
If Black can castle both ways, last move must have been b7-b5
C+ Popeye 4.61 (2020-10-25)
comment
Keywords: a posteriori (AP), En passant as key, Castling (sksg), Promotion (D), Valladao Task
Genre: h#, Retro
FEN: r3k2r/p4p1p/8/KpP2PP1/4PBpP/5pp1/6p1/8
Reprints: Nordisches Turnier 1970-1971
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2020-10-25 more...
63 - P0003428
Imre Sztankovszky
130 Die Schwalbe 09-10/1953
P0003428
(10+11) C+
h#1.5 AP
1. ... fxg6ep 2. 0-0 gxh7#
play all play one stop play next play all
Henrik Juel: Black captured c7xd6x..x.h2 and once more with an officer
White captured a2xb3, b2xa3, f2xg3, and e.g. exf and once more
If Black may castle, last move was g7-g5 (not b7-b6, because of Lh3) (2022-04-26)
Henrik Juel: HC+ Popeye 4.61
The castling serves two purposes:
enabling the mate and legitimizing the ep capture
so the a posteriori legitimizing is impure (2022-04-26)
A.Buchanan: Yes Henrik. The absence of other candidate solutions (beginning e.p. but excluding 0-0) declines an opportunity to embed additional content, and is arguably an artistic defect. However this very early AP problem is sound, and purity of motive is just one school. IMHO, there is space for such problems, if other content compensates: e.g. 4k2r/p2ppp1p/p7/5PpK/8/1PBB2Pb/2PP2Pp/8 h#2* AP. (2022-04-27)
more ...
comment
Keywords: En passant as key, Castling (sk), a posteriori (AP) (Type Petrovic), Volet Pawn
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: 4k2r/3ppp1p/1p6/4BPpK/P7/pPPB2Pb/3P2Pp/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-04-27 more...
64 - P0003434
Jozsef Bajtay
2432 Problem 101-102 09/1966
P0003434
(10+11)
h#2
1. fxg3ep 0-0 2. Lg4 hxg3#
play all play one stop play next play all
A.Buchanan: Surely diagram typo. Change to sBh3, then everything works (2022-03-29)
Mario Richter: Yes, Pawn h3 is black (2022-03-29)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wk)
Genre: h#, Retro
FEN: 8/b3p3/4p3/6pp/2P2pPk/1pPP3p/2PP1P1P/r2bK2R
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2022-03-29 more...
65 - P0003442
Janko Furman
3. Makuc-Moder-Gedenkturnier 1971-1973
1. Preis
P0003442
(12+13) C+
h#2
b) wBd4 nach d5
a) 1. cxd3ep Sd5 2. 0-0 Se7#
NOT 1. ... Lf6? 2. Kf8 Tx8# because no AP justification
b) 1. Kd7 Lf6 2. Te8 Sxb6#
NOT 1. 0-0? Tf6 2. Kh8 Txf8# because rights lost
play all play one stop play next play all
Assume that bPb6 is really on b7:
Bl captures: dxe, exf, fxg, a|
Wh captures: bxc, g|, cxd=
So all pawn captures are accounted for.
a) If Bl 00 rights remain, then only way to give Black a prior move is by d2-d4.
b) No way to give Black a prior move, so Bl 00 rights must be lost.
Cook: NL
b) 1. 0-0 Tf6 2. Kh8 Txf8#
A.Buchanan: There is definitely something wrong here, with both (a) & (b). I think it's a simple diagram error: bPb7 has been misplaced on b6. Then the AP logic for (a) works great, and the castling "NL" for (b) is seen to be a thematic retro try. Can anyone confirm? (2022-03-21)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (sk)
Genre: h#, Retro
Computer test: Popeye v4.87 & simple retro-logic
FEN: 4k2r/7p/1pR5/2P5/NNpP4/KB2PPPP/p3pppq/B4bnr
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
66 - P0003817
Jean Oudot
Nation Belge 1956
P0003817
(14+12) C+
#2
1. cxd6ep
play all play one stop play next play all
paul: Since the wB couldnt leave c1, the captured piece on b6 is the promoted wPh2. If last black move was f7-f5, then h-Pawn captured four pieces to promote on d8, among which bRh8, impossible. Thus, the h-Pawn could only have been promoted from f7 and therefore d7-d5 remains as the last move. (2011-07-02)
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comment
Keywords: En passant as key
Genre: Retro, 2#
Computer test: C+ Popeye 4.61
FEN: qrRNkb2/PpQ1p1pp/1pp1R3/2PpKpP1/6N1/7B/1P1PPP2/8
Reprints: RA15 diagrammes 15 06/1975
(51) Mat Plus 12 10-12/2009
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-27 more...
67 - P0003925
Ivan Skoba
1009 diagrammes 47 09-10/1980
P0003925
(6+7) C+
a) ser-h#6 (AP)
b) nach dem Schlüssel von a): ser-h#5
a)
1. dxc3ep 2. Kc4? 3. Tb5 4. Td5 5. Dc5 6. Kd4 Th4#
2. Tb2! 3. Kb3 4. Kc2 5. Kc1 6. c2 0-0#
b)
1. Tb2? 2. Kb3 3. Kc2 4. Kc1 5. c2 0-0#
1. Kc4! 2. Tb5 3. Td5 4. Dc5 5. Kd4 Th4#
play all play one stop play next play all
There are basically two candidate solutions ending Th4# and 0-0#. In (a), the initial ep can only be justified by 0-0#. On the other hand in the diagram position in (b), White's last move must have been with wK or wR, so 0-0# is disrupted. Nice and paradoxical.
A.Buchanan: Why is there sDe3? Isn't sL sufficient? (2022-05-27)
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comment
Keywords: Seriesmover, Castling (wk), Cant Castler, a posteriori (AP) (Type Petrovic), En passant as key
Genre: Retro, Fairies
Computer test: HC+ Popeye v4.87 & simple retro-logic
FEN: 8/8/8/8/bkPp4/pr1pq3/3PRP2/4K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-29 more...
68 - P0004192
Tomislav Petrovic
(IX) Problem 37-40 09/1956
P0004192
(14+8) C+
h#2*
1. ... dxc6ep 2. dxc3 Lxb6#
1. dxe3 Sd4 2. e2 Sc6#
play all play one stop play next play all
more ...
comment
Keywords: En passant as key, Interchange (Sb)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & trivial retro-logic
FEN: B5Rr/k4pPp/1p3P1p/1KpPP2N/2Pp4/2PPB3/2P1N3/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-23 more...
69 - P0004269
Herbert Hultberg
7969 Tidskrift för Schack 03/1938
P0004269
(3+6) C+
#3
Längstzüger
1. exf6ep d5,g5 2. Db7 g5,d5 3. Dg7#
play all play one stop play next play all
Henrik Juel: The longest among the possible last moves is f7-f5, so 1.exf6ep d5 2.f7 g5 3.f8Q!?, but 3... Kh7!, so something is wrong. (2003-11-11)
HBae: Habe korrigiert. Es fehlte der wKa1 und die wDb2. (2019-10-11)
Henrik Juel: C+ by Popeye 4.61 (assuming that the condition was in effect also in last move)
Pd7 and Pg4 can be removed without affecting correctness or symmetry (2019-10-11)
Bernd Schwarzkopf: Pd7 and Pg4 are necessary. Without them last move could have been: 1.Pg6xXf5. (2021-02-06)
Mario Richter: Interestingly, the Editors of 'TfS' too thought that Pd7 and Pg4 can be omitted (s. 'TfS' 06/1938, p.124: "Går det inte lika bra utan bönderna på d7 och g4? (BL). Jo, det går visst lika bra. Men förf. har väl haft någon mening med dem också (Red.)."

I think, pawn d7 serves to prevent retractions like R: 1.Pg6xXf5, but pawn d4 is only there to complete the symmetry (i.e. Pd7 is necessary, Pg4 is not). (2021-02-06)
A.Buchanan: Doesn’t bPg4 stop 2.Dg2 as a dual? (2021-02-07)
comment
Keywords: Maximummer, En passant as key, Asymmetrical solution, Symmetrical position
Genre: Retro, 3#, Fairies
FEN: 7k/3p2p1/4p3/4Pp2/6p1/8/1Q6/K7
Reprints: (II) Problem 65-68 01/1960
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-03 more...
70 - P0004479
Matjaz Zigman
Länderkampf Mazedonien-Slowenien 1969
6. Platz
P0004479
(10+13) C+
ser-h#5* (AP)
* 1. ... Lxd2#
1. dxe3ep 2. Txf2 3. Txg2 4. Th2 5. Th3 0-0#
play all play one stop play next play all
more ...
comment
Keywords: Castling (wk), Seriesmover, En passant as key, a posteriori (AP) (Type Petrovic)
Genre: Retro, Fairies
Computer test: HC+ Popeye 4.61 after analysis
FEN: 8/8/8/4pPp1/1p1pPkpb/1P1P2p1/pPpr1PP1/rbB1K2R
Reprints: 103 Bilten 1970 1971
(70) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-07-20 more...
71 - P0004647
Branko Pavlovic
International Solving Match 1947
P0004647
(7+3)
#2
1. Kg6,Sf8 g3 2. f7#
1. fxg6ep? because e.g. R: 1. Kf7-g8 gxSh8=S+ can be history
play all play one stop play next play all
Paulo Roque: NL : 1. Sf8! g3 2. f7# (2009-08-22)
Henrik Juel: The organizers of solving matches in the old days liked tricky problems. Here there are two tricks: The 'obvious' e.p. key does not work (because last move could be Kf7-g8), and there are two solutions. (2009-08-22)
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comment
Keywords: En passant as key
Genre: Retro, 2#
FEN: 6kN/3N3R/5P1B/5PpK/6p1/8/8/8
Reprints: (10) Problem 198-201 07/1980
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-01 more...
72 - P0006159
Marko Klasinc
8126 Schach-Echo 20, p. 319, 10/1974
P0006159
(15+9) C+
h#6* (AP)
*) 1. ... Sxb3#
1) 1. gxh3ep Ld1 2. h2 Lxc2 3. Kxc2 Df1 4. Kc3 Dxd3+ 5. Lxd3 0-0-0 6. Lxc4 Se4#
play all play one stop play next play all
Wh has made 6 visible pawn captures, Bl 1. If bPfxg, then bPh was waylaid, and bPe promoted, disrupting White's castling rights. If Wh 000 rights remain, therefore, bPhxg and bPe was waylaid instead. Since original g-pawns remain on g-file, they must be wPg3 & bPg4, and wPh must retract a double hop to allow bPh3xg2. So Black can ep, avoiding immediate pat. To castle then mate requires a lot of work.
A.Buchanan: Popeye v4.87 finds 11 solutions to h004.5 following the mandatory ep. Only one of them can be followed by h#1. Any cook therefore would have to be of the form 6. ... 000# Searching now for h005.5, as can then easily check if there are any mates (2022-06-10)
Yuri Bilokin: H#1* *) 1. ... Sxb3#
1) 1. gxh3ep Sxb3# (2022-06-10)
A.Buchanan: Hi Yuri - you know that h#1 doesn't work, right? (2022-06-10)
Yuri Bilokin: Hi - don't know, please email polidox579@gmail.com (2022-06-11)
A.Buchanan: Hi there are over 110,000 ways to reach 6. 000, but *none* of them are also checkmate. Therefore I am happy to pronounce this problem sound. Happy, because (1) it deserves to be ok (2) I couldn't face trying to fix it. If White 000 rights remain, then the last move was certainly h2-h4. Orthodoxically, we cannot perform the e.p. but under the AP Type Petrovic we can ep, as long as we justify it with castling later in the game. Hurray! (2022-06-12)
A.Buchanan: 1. gxh3ep Sxb3#? fails because White never castles to justify the ep. It's like there is an additional check before granting that a position is checkmate or stalemate: have all AP debts been paid? If not, the move is illegal because the game would end with no chance to repay the AP debt later. Yes it's weird but that's AP. (2022-06-13)
Michel Caillaud: Now, the post en passant part of this kind of problem can be tested with Jacobi.
With the following set of data:
stip h#5.5 pieces
White Ke1 Qg1 Ra1f2 Be3h5 Sd2 Pa3b4c4d4f4g3g5
Black Kc1 Rb2 Bb1 Pa2b3c2d3g2h3
constraints Ke1!c1~ Ra1!d1~
Jacobi looks for helpmates in 5.5 moves including 0-0-0 in the play.
No need to scrutinize the 110000 ways found by Andrew; Jacobi makes all the work (but it takes some hours...) (2022-06-13)
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comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg)
Genre: h#, Retro
Computer test: C+ Jacobi v0.7.5
FEN: 8/8/8/6PB/1PPP1PpP/Pp1pB1P1/prpN1Rp1/Rbk1K1Q1
Reprints: 4113 Problem 05/1979
(19) diagrammes 112 01-03/1995
Input: Gerd Wilts, 1995-07-19
Last update: A.Buchanan, 2022-07-10 more...
73 - P0006655
Thomas R. Dawson
The Chess Amateur 1925
P0006655
(7+3) C+
#2
1. fxg6ep+ Kg5 2. Lh4#
R: 1. g7-g5
play all play one stop play next play all
more ...
comment
Keywords: En passant as key
Pieces: du = Grasshopper (G)
Genre: Retro, 2#, Fairies
Computer test: HC+ Popeye 4.61 after very simple analysis
FEN: 8/5*2Q1K/5P1P/5Ppk/6p1/6B1/6N1/8
Reprints: 115 Caissa's Wild Roses 1935
Input: Gerd Wilts, 1996-07-16
Last update: A.Buchanan, 2021-05-03 more...
74 - P0006745
Gligor Denkovski
453 feenschach 7 01/1972
P0006745
(6+3) C+
ser-h#7*
1. ... hxg6ep#, 1. gxh4 2. h3 3. h2 4. h1=L 5. Lc6 6. Le8 7. Lxh5 g5#
play all play one stop play next play all
Anton Baumann: C+ Gustav 4.1d (2021-01-29)
comment
Keywords: En passant as key, Seriesmover, Promotion in forward play
Genre: Retro
FEN: 8/7p/4NP1k/5KpP/6PR/8/8/8
Input: Gerd Wilts, 1996-07-24
Last update: James Malcom, 2021-01-29 more...
75 - P0008246
Alexander Kislyak
4 Shakhmaty v SSSR 04/1974
P0008246
(12+12)
#2
1. bxc6ep
play all play one stop play next play all
Lösetip beim Originalabdruck: beim Abzählen der geschlagenen Figuren beachte man die Farbe der Felder, auf denen sie fielen.

AL
Le4 ist ein UW-L, der nur so entstanden sein kann: h2-h7xg8=L.
Schwarz zog h7xg6x5, um ihn vorbeizulassen.
Somit ergibt sich folgende Schlagbilanz:
Weiß: axb, dxc, fxg (als Schlagobjekt für den sBh7) [Anmerkung: statt fxg auch fxe mit UW auf e8 möglich, ändert aber nichts]
Schwarz: bxc, h7xg6xh5 sowie den wLf1, der nicht von den sBB geschlagen wurde

Unter den geschlagen weißen Figuren befindet sich der schwarzfeldrige Lc1.
Die Schläge h7xg6xh5 fanden auf weißen Feldern statt, also wurde der Lc1 mittels b4xc3 geschlagen. ("Effekt Zvetnosti")
Als letzte schwarze Züge kommen also nicht infrage: b3xc2, e7-e5 (sLf8 wird als Schlagobjekt gebraucht), g6xh5 (dann käme der wUW-L nicht von g8 nach e4).
Einziger legaler letzter schwarzer Zug war also c7-c5, und es löst: 1. bxc6ep
Des Autors (geb.27.12.1938)"`Erstling"', also mit 36 Jahren.

abgedruckt in der Rubrik: "Redkije Shanry"
Henrik Juel: Solution: 1.bxc6 ep (2.cxd7#). White captured axb, dxc, fxe, h7xg8=B and promoted on e8; Black captured orig. Bf1, bxc, h7xg6xh5 and promoted on a1. So last move must be c7-c5. (2003-05-27)
Mario Richter: @all PDB activists: Would the introduction of a new keyword: "Farbbalance / color balance"
or something similiar make any sense? (describing the fact, that a certain capture must have happened on a square of a determined color) (2022-04-26)
A.Buchanan: The pieces have colour: black & white. But the squares and the bishops have *shade*. Informally of course one can say anything, but if we are glossarizing then maybe be a bit more formal. And what is “balance” here? I think of balance in terms of pawn captures required vs available. Typically the issue you are talking about is where almost all pawn captures are in one shade square, allowing us say something interesting about a bishop capture. Maybe: “shade logic”? (2022-04-26)
Henrik Juel: I use Andrew's terminologi: men are white or black, and squares are light or dark
But my non-retro friends (both of them) use white/black for squares also
So 'Shade logic' may be too esoteric
What about 'Square color argument'?
It is used far more frequently in retro analysis than, say, 'Parity argument', so a keyword is needed
Thanks for the suggestion, Mario (2022-04-26)
A.Buchanan: I am convinced by Henrik, but I will continue to use “shade” in my own writing. (2022-04-27)
comment
Keywords: En passant as key, Obvious promotion (wLe4)
Genre: Retro
FEN: brkn2R1/Rn1p1pp1/N7/1PpKp2p/QPP1B3/2P5/2p1P1P1/8
Reprints: Caissas Schloßbewohner 3 1987
Input: Gerd Wilts, 1996-09-16
Last update: Mario Richter, 2022-04-26 more...
76 - P0008985
Gianni Donati
9862 Die Schwalbe 168 12/1997
P0008985
(10+14)
ser-h#6 (AP)
1. gxf3ep 2. Dg4 3. 0-0-0 4. Te8 5. Kd8 6. Dxh5 0-0-0#
play all play one stop play next play all
Henrik Juel: 1.gxf3ep 2.Qg4 3.000 4.Re8 5.Kd8 6.Qxh5 000#. Both castlings are necessary to legitimize the en passant capture. (2003-09-29)
A.Buchanan: I don't think this is consequent series mover, under which every position would considered afresh from the perspective of legality i.e. possible histories. Instead, this is regular series mover where one player is simply saying "pass". It's hard to imagine how AP might operate in a consequent context. I will change the keyword suitably. (2021-11-08)
comment
Keywords: a posteriori (AP), Seriesmover, Castling, En passant as key
Genre: Retro, Fairies
FEN: r3k3/ppp1p3/2p5/6PP/5Ppq/1P4nB/PrP1P1p1/R3K1nb
Input: Gerd Wilts, 1998-06-26
Last update: A.Buchanan, 2021-11-08 more...
77 - P0009121
Tomislav Petrovic
2949 Phénix 69 12/1998
P0009121
(10+9) C+
h#2 (AP)
1. fxe3ep d8=S 2. Kxd5 0-0-0# (Td1#?)
play all play one stop play next play all
White has made 6 pawn captures with one missing black piece unaccounted for, that by parity can only have been captured by an officer. White's last move cannot have been a pawn capture. If R: 1.f2-f3, then sLg1 was promoted, implying 7 captures by black pawns - one too many. So if White can prove they retain castling rights, then the ep is on. Hence AP Petrovic is valid.
Henrik Juel: 0... fxe3ep 1.d8S Kxd5 2.0-0-0#. Not -1.f2? and Lg1 is caught. (2004-09-16)
Vaclav Kotesovec: Similar problems should not be labeled as "C+". Such a designation is only acceptable if the entire analysis was performed by a computer program. (2023-08-03)
Henrik Juel: In principle I agree, Vaclav
But PDB does not (yet) allow HC+, so I find it acceptable to use the C+ label, when you also tell the whole story after 'Computer test:' below (2023-08-03)
A.Buchanan: Hopefully Gerd will have more time at some point, and can expand the functionality in this and other areas. In the meantime, engine solving of conventional retros including AP, is in its infancy. Retractor 2 has some effectiveness, but is still basic. And there is nothing that yet grasps the intricacies of castling/ep etc. However AP problems do often contain considerable forward chess, and the C+ tag is very useful to filter out those that have already been solved forwardly, without pretending that these are in any sense fully solved (2023-08-04)
Ladislav Packa: I know the definition of AP, but I don't understand the logic behind it. The move 1.fxe3 e.p. proves that White CAN castling. But the solution (2. ...Rd1#?) claims that castling is MANDATORY. From my point of view, AP is correct when only castling is necessary for the solution and the Rook move would be a dual. (2023-08-04)
A.Buchanan: @Ladislav: I am not sure how to help you. Maybe you can read this page from Retro Corner: https://www.janko.at/Retros/Glossary/APosteriori.htm (2023-08-05)
Ladislav Packa: Andrew, what should the article help me with? I quote the final sentence:
Some people still oppose this rule and argue that it should certainly not be the default convention. (2023-08-05)
Henrik Juel: You could view it this way, Ladislav
h#2 means that it is Black to move, so White made last move
What was last move? A little analysis shows just three possibilities: f2-f4, move by Ta1, or move by Ke1
So normally we cannot assume that last move was f2-f4
But if White can castle, then the last move was f2-f4
So if we could start with 0... 0-0-0, then 1.fxe3ep would be legitimate
AP says that you are allowed to reverse the sequence of events; first do the ep capture, then later legitimize it by castling
Was this helpful? (2023-08-05)
Ladislav Packa: Henrik, you don't have to explain that to me. I've done a few AP issues myself, like P1348357. But that doesn't mean I agree with AP's logic. I already wrote it - the term "you can castle" is applied as "you must castle". But these are only problems where, in addition to castling, the Rook move can also be used, I consider that a dual.
From that point of view, the P1000662 issue is perfectly fine for me. (2023-08-05)
Joost de Heer: AP: By castling, you prove a posteriori that the ep-capture was not just a try but the actual solution. Without castling, the ep-solution just is that: a try.
So: Try 1. fe3 ep e8=S 2. Kd5 Rd1 - but ep capture not allowed, as there is no proof that f2-f4 must've been the last move.
Solution 1. fe3 ep e8=S 2. Kd5 OOO - Now the ep capture was justified because white castled, thereby proving that the last move before the diagram position indeed was f2-f4. (2023-08-06)
Joost de Heer: See e.g. P1052919 : The try is an ep capture which is unjustified. (2023-08-06)
A.Buchanan: OK Ladislav: I think I get your point. If one solution with castling justifies the e.p., then based on that certainty, why shouldn't an alternative solution with no castling *then* be allowed as well? There are problems in which one twin shows 0-0-0 and the other shows 0-0. Each is based on the other in a similar way, so the idea of dependency is not new. Why are we not allowed to add other "parasitic" solutions as well? Why can we only have the "paying" solutions? We can't say that we are restricted to one solution: that's not the way chess problems operate! And this is just in the help world - in the adversarial world it might get even more complicated. Is this your issue, Ladislav? (2023-08-07)
Ladislav Packa: I don't want to unnecessarily prolong this discussion. However, I will add one more note: in this position, white castling is also possible without e.p. in Black's 1st move. If B1 were an indifferent move, then white can 1...0-0-0! The Codex of Chess Composition writes about it in Article 16 (1):
Castling convention. Casting is permitted unless it can be proven that it is not permissible.
In our case, 0-0-0 is possible because White's last move exists - e2-e4! It does not matter if it is this move or some a2-a3, both moves are equivalent. EP does not prove the possibility of casting, it would be legal even without it. (2023-08-07)
A.Buchanan: Ladislav was what I wrote your issue pls? Y/N :-) (2023-08-07)
Ladislav Packa: I have no problem, I'm just expressing my own opinion about the AP convention. (2023-08-07)
A.Buchanan: OK cos I think the point I raised is a real one that should be addressed by theory some day. Clearly from the nice problem that you composed Ladislav you understand the mechanics very well. From a justification perspective it's all a bit iffy, but that's why it's controversial. Under RS it's really the only way one can end up actually eping, and it's proved compositionally fertile. So that's enough to justify (2023-08-08)
Ladislav Packa: No need to apologize. This is a normal discussion with different views on the issue. Maybe it will come to some conclusion.
I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p. (2023-08-08)
Joost de Heer: "I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p."
You misinterpret AP. The e.p. capture does not authorize castling, castling provides a justification later on (hence the 'a posteriori') for the legality of ep.
Usually, for ep justification you need to examine all game trees that lead to the diagram, and only if all game trees end with the double-step, then ep is allowed.
With AP, you examine all the game trees including the actual play. If all those game trees have as last move before the diagram position the double step, then ep is possible.
In this case, if white doesn't castle, then there are game trees which don't have as last move the double step, and therefore AP logic dictates that the ep capture was illegal. However, all game trees which lead to the diagram and which have castling in the actual play have as last move before the diagram position the double step, hence AP dictates that the ep capture is legal. (2023-08-09)
Ladislav Packa: Joost: A simple question - is white allowed to castle after any 1st move by black (except e.p.)? (2023-08-09)
Joost de Heer: Of course he is. AP only is used to combine the ep justification with castling, not the castling right per se. (2023-08-09)
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg), Promotion (S), Valladao Task
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 + simple retro-logic
FEN: 8/3P2p1/2PP4/1ppPp3/2pkPp2/5PP1/6Pp/R3K1b1
Input: Gerd Wilts, 1999-02-27
Last update: A.Buchanan, 2023-09-11 more...
78 - P0519781
Tomislav Petrovic
Problem 41-44 03/1957
4. Platz
BiH - Macedonien
P0519781
(14+10) C+
h#2*
*) 1. ... dxc6ep 2. dxc3 Lxb6#
1) 1. dxe3 Dxg7 2. Kxb7 Dxd7#
2) 1. Lxb7 Sc6+ 2. Ka8 Sc7#
play all play one stop play next play all
pawns history:
Bl: axb,exd,f=
Wh: hxgxh,gxh,fxgxh,cxd,a=,e=
All accounted for.
Bl can't uncapture axb or exd else block promotion.
If WTM, Bl just played c7-c5 so ep is on
A.Buchanan: WinChloe doesn't think this problem is cooked at all. It says there are two full solutions, with "Echange de place de pièces noires entre les positions finales" i.e. Kb7 La8 vs Ka8 Lb7. WinChloe does not cover the (single) set play. Must the number of set plays normally match the number of full solutions? I will mark this problem HC+ uncooked. (2021-10-31)
comment
Keywords: En passant as key, Sacrifice of white pieces
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 + simple retro logic.
FEN: bN6/kB1p2p1/Np1P4/1KpP3P/1prp3P/1PQRB2P/2R4p/8
Input: Hans-Jürgen Schäfer, 1997-10-11
Last update: A.Buchanan, 2021-10-31 more...
79 - P0577550
Johann J. Chaschtschanski
14447 Schach , p. 79, 03/2000
P0577550
(3+9)
h#7
b) sTc2 nach h6
a) 1. Txg2 Kxg2 2. Ld4 Kh1 3. Le5 fxe5 4. Kf4 e6 5. Kg5 e7 6. Kh4 e8=D 7. Kh3 Dxh5#
b) 1. gxf3ep gxf3 2. Ke5 Kg2 3. Le4 fxe4 4. Kf6 exf5 5. Kg7 f6 6. Kh8 f7 7. Th7 f8=D#
play all play one stop play next play all
Anton Baumann: C+ Gustav 4.1d (2020-11-24)
comment
Keywords: Switchback (K in a), Entblockung, Promotion (D), Promotion in the mating move (D in b), Twin, En passant as key, Selfblock (in b), Corner mate (in b), Model mate (in b)
Genre: h#, Retro
FEN: 8/8/8/5p1p/4kPp1/3bb1p1/2r3Pp/7K
Input: hpr, 2000-10-27
Last update: Gunter Jordan, 2020-11-25 more...
80 - P1000662
Gianni Donati
R074 Probleemblad 11/1999
P1000662
(10+14) C+
h#1.5 (AP)
1. ... gxh6ep 2. exf1=L 0-0-0#
play all play one stop play next play all
Kommentare:
Als einziger letzter schwarzer Zug, der die weiße Rochade
erhält, kommt nur Bh7-h5 infrage, was dem Weißen den e.p.-Schlag
ermöglicht, um nicht die Rochade oder das Mattnetz zerstören zu
müssen (H.P.Suwe)
Gianni Donati: This intends to show the Valladao theme in the minimum number of moves. (2004-03-19)
VL: The waiting ep capture. Cf. also P1000260
(by T.Petrovic, 2000) somewhat enriched
thematically with the illegal try 2... Rd1#??. (2004-06-03)
A.Buchanan: The “illegal try” 2. Rd1+ is not actually mate because c2 is unprotected. This is kind of “logic dual” spoils the A.P. motivation for the castling (2020-05-20)
Henrik Juel: White captured h6xg7 and once more, e.g. axPb-b8=Y
Black captured cxdxe, dxexf, fxg, and once more, e.g. a2xb1=Y
Possible retroplay 1... h7-h5 2.h6xSg7 Df8-f4 3.h5-h6 Sf4-h3 4.Sh3-g1 etc., preserving the castling right
Any other black last move would force White to retract Ta1, as d2xc3, d2xe3, and h6xh7 would be illegal retractions
I agree with Andrew that the double motivation of 2... 000# is a weakness:
a. legitimizing h7-h5
b. mating (2020-05-21)
Vaclav Kotesovec: Similar problems should not be labeled as "C+". Such a designation is only acceptable if the entire analysis was performed by a computer program. (2023-08-03)
A.Buchanan: See discussion at P0009121 (2023-08-04)
more ...
comment
Keywords: a posteriori (AP), En passant, En passant as key, Castling, Valladao Task, Promotion (l)
Genre: Retro
Computer test: HC+ Popeye v4.87 + simple retro logic
FEN: 6n1/4p1P1/6p1/6Pp/2b1rqrb/2PkPppn/1P2pP2/R3KRN1
Reprints: König & Turm (4), p. 28, 03/2001
H Problemkiste (143) 10/2002
(V2) Problemkiste 156 12/2004
Input: Gerd Wilts, 2000-08-01
Last update: A.Buchanan, 2023-08-03 more...
81 - P1000901
Tomislav Petrovic
3 feenschach 137, p. 340, 08-09/2000
Zdravko Maslar gewidmet
P1000901
(14+8) C+
s#2
1. dxc6ep!
1. ... dxc6+ 2. Lxc6 Sc7#
1. ... d6 2. d5 Sc7#
1. ... d5 2. exd5 Sc7#
1. ... dxe6 2. e5 Sc7#
1. ... gxf6 2. Sf5 Sc7#
1. ... g6 2. Lxg6 Sc7#
1. ... g5 2. Sg4 Sc7#
1. ... gxh6 2. Lh5 Sc7#
play all play one stop play next play all
James Malcom: This is a most excellent problem! En passant as the key and a double pickaninny in a short s#2 is surely no easy feat, I'd say. Now, question: Why can't dxc5 be Black's last move? The illegal retraction od b6-b7 is already quite obvious. (2020-10-24)
A.Buchanan: R: 1. cxb6/dxc5? both imply 3 pawn captures by Bl (2020-10-24)
A.Buchanan: I agree this is a beautifully integrated composition (2020-10-24)
more ...
comment
Keywords: En passant, Pickaninny (2x), En passant as key, Grab
Genre: Retro, s#
Computer test: C+ Popeye 4.61 after retro-analysis shows that last move was c7-c5
FEN: n2RB3/k2p2pR/Pp2PP1N/bKpP4/PpNPP3/1P6/8/8
Input: Gerd Wilts, 2000-10-08
Last update: A.Buchanan, 2020-10-25 more...
82 - P1012015
Henri Nouguier
Jean-Claude Gandy
Jean Claude Dumont

diagrammes 1975
Lob
P1012015
(12+8) C+
#2
1. Sg5? droht 2. Sxf7#
1. ... f5!

1. dxc6ep! droht 2. Kb6#
1. ... bxc6+ 2. Kxc6#
play all play one stop play next play all
Le Fnf1 provient de la promotion du PNh7 (2 prises) après capture à domicile du Fbf1 (1 prise). bxc5, dxc5 ou dxe6 comme dernier coup N sont à rejeter puisqu'ils nécessiterait 2 prises supplémentaires. Le RN n'a pu venir de d6 au coup précédent car cela impliquerait exf8:F+ comme dernier coup B. Dans ce cas les PB auraient effectué 9 prises or il ne manque que 8 PN. Le RN n'a pu venir de f4 ou de f5 après fxe4 car la position des PB e2, f3 et g2 rendrait inexpli- cable la présence simultanée de la TB en f2 et du FN en f1. Le PNe6 ne vient pasde e7 car le FB n'aurait pu accéder à f8 et le PNc5 ne vient pas de c6 à cause de l'+ non paré au RB.
No. 1111 HN
Correction of P0003822
A.Buchanan: Odd that the correction has fewer composers than the cooked original (2023-05-27)
HENRI: To be corrected :
The third author Jean-Claude Dumont must be add as mentioned in the award 1975-1976 page 539 diagrammes n° 31 jan - feb 1978. (2023-05-30)
more ...
comment
Keywords: En passant as key
Genre: Retro
Computer test: HC+ Popeye 4.61 and (french) analysis
FEN: 5B2/1p3ppN/4p3/RKpPk3/3pP3/3P2P1/2P1PRP1/5b2
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2023-05-30 more...
83 - P1012017
Carlos Sabadini
FEENSCHACH 1961
P1012017
(5+9) C+
ser-h#6
1. exd3ep 2. Td5 3. Lc5 4. Lb4 5. Dc5 6. Sd4 exd3#
play all play one stop play next play all
No. 1126 HN
A.Buchanan: Consequential series movers were invented in 1979. (2015-11-11)
A.Buchanan: Although there is trivial retro consideration at the beginning, this is not a consequent problem. After Black's first four series moves, the position has no last move for White, which violates the consequent condition. This is just a regular seriesmover, with ep convention in the diagram, contrary to the initial post in 2004. (2020-12-10)
more ...
comment
Keywords: En passant as key, Seriesmover
Genre: Retro
Computer test: C+ Gustav 4.1d & minimal retro logic
FEN: 8/8/8/1pr5/2kPp3/2p1bn1p/2P1Pq1P/7K
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2020-12-10 more...
84 - P1012052
Henri Nouguier
diagrammes 2004
P1012052
(9+15)
shc#6
1. dxc3ep 2. Kxb5 3. Kc6 4. Kd7 5. Ke8 6. 0-0 Txg7#
play all play one stop play next play all
Un des PNd a pris 1 pièce blanche. pour venir de e7. Donc les PB b, c et d ne peuvent se croiser. Le PBg6 ne peut venir de f5 car il faudrait 2 prises noires! Seule reste le dernier coup blanc 0... c2-c4 Ceci implique que le FNb1 est issue de promtion ! C'est le PNb7, il aurait pris 2 pièces blanches. Les PNg5 et h5 ont pris 2 pièces blanches.
No. 11661 HN
A.Buchanan: “Obvious promotion” is intended to refer to something visible in the initial diagram position, not what is reached during series play (2022-09-14)
A.Buchanan: Similarly “non-standard material (2022-09-14)
more ...
comment
Keywords: Seriesmover, Consequent, En passant as key, Promotion in the retro play (sLb1), Castling, Valladao Task
Genre: Retro, Fairies
FEN: 7r/5pnR/5PnR/1Pp2ppq/1kPp4/p2P4/P2pP3/Kbb4r
Input: Henri Nouguier, 2004-01-11
Last update: Mario Richter, 2022-09-14 more...
85 - P1012718
Tivadar Kardos
Themes-64 1961
P1012718
(10+11) C+
h=4
1. axb3ep g8=T 2. bxc2 Txg6 3. c1=S e4+ 4. Sd3 Txh6=
play all play one stop play next play all
Le Pb6 venant de f2 et g7 de h2 (5 prises au total, soit le maximum possible). Le dernier coup blanc ne peut être une prise.
No. 531 HN
more ...
comment
Keywords: En passant as key, Promotion (Ts)
Genre: Retro, Fairies
Computer test: C+ Popeye v4.61 + Retractor v2.1.1
FEN: 8/1p4Pp/1P4qb/K1p1p3/pPkp4/6p1/P1PPPpP1/5B2
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2021-11-26 more...
86 - P1020121
Philipp von Klett

P1020121
(9+4) C+
#2
1. gxf6ep (ZZ) gxf6 2. Sxf6#
1. ... Kxg4 2. Le2#
play all play one stop play next play all
Klett: Statt der Dc1 würde auch ein Läufer genügen,; die Dame in ihrer freien Stellung erschien uns aber hier ausnahmsweise angemessener.

Für ein Problem, in dem die wD tatsächlich notwendig ist bringt Klett die P0002091.
more ...
comment
Keywords: Brian Stephenson Collection (4961), En passant as key
Genre: 2#, Retro
Computer test: Henrik Juel (2021-02-20): C+ Popeye 4.61
FEN: 8/6p1/4P1P1/4KpPk/6Nb/3B4/5P2/2Q4R
Reprints: 2 Schachprobleme [Klett] 1878
Sammlung leichterer Schachaufgaben II , p. 6, 1882
96 Schackproblem [Geijerstam] , p. 7, 1908
50 Westdeutsche Landeszeitung 11/12/1927
263 La Suisse Liberale 31/12/1928
29 Volksstimme (Magdeburg) 29/06/1930
Kleine Volks-Zeitung (Wien) 16/05/1938
29 Der Schachzug (FV Schach Berlin) 23 01-02/1978
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-03-24 more...
87 - P1020144
Josef Kling
23 The Chess Euclid 1849
P1020144
(6+6)
#2
1. axb6ep+ Kb1 2. 0-0#
1. ... Da7 2. Kf2#
play all play one stop play next play all
in 'Le Pion' fälschlich wBa4 ("1 - R 1 R ... 5 - P 4 TD ...")

Nach heutigen Konventionen ist der Ep-Schlag unzulässig, man beachte aber:
Kling im 'Chess Euclid' zur Intention dieser Aufgabe: "This problem I have compossed expressly to shew the error the modern composers of problems have committed, in introducing the system of castling in the ends of games. In this problem I consider I have as good a reason to say that Black has just moved his Q. Kt. P. [b5] two squares as that White has not moved his K. R. or K."
James Malcom: I found this hidden ancient, another that rode the rails of the unjustified en passant key. (2020-12-28)
SP: Unsound in its own terms, as, whatever Black plays (Kb1/Qa7),
castling is never forced due to 2.Kf2#
I use the keyword "non-analytic en passant key" for such problems. (2023-08-21)
A.Buchanan: The composer's stated intention seems to be that (1) ep is ok (2) castling is not ok. In these terms, the problem is sound (2023-08-22)
comment
Keywords: Brian Stephenson Collection (4985), En passant as key, Castling (wk), En passant, Castling as mating move, Golden Age
Genre: 2#
FEN: R7/7q/7r/Pp6/5p1r/7P/4Q3/k3K2R
Reprints: 458 Dubuque Chess Journal 35 01/1873
P10 Le Pion 01/05/1873
Input: Brian Stephenson, 2004-08-12
Last update: A.Buchanan, 2023-08-22 more...
88 - P1054640
Jaques Fulpius
10038 Schweizerische Schachzeitung 09/1968
P1054640
(10+5) C+
#2
1. dxe6ep! Lxb2,Ld3 2. Da8#
1. ... c3 2. Tb3#
play all play one stop play next play all
more ...
comment
Keywords: Brian Stephenson Collection (39688), En passant as key, En passant in the forward play, Blocknutzung, Deckungsverlust
Genre: 2#, Retro
Computer test: Juel: C+ Popeye 4.61 clearly, last move was e7-e5
FEN: 8/8/3P1B2/1BNPpK2/1Ppp4/k7/NR4Q1/b7
Reprints: 20 Kunstschach in der Schweiz , p. 19, 1980
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-11-12 more...
89 - P1066685
Valery Liskovets
12365 Die Schwalbe 208 08/2004
P1066685
(14+5)
#1 (AP)
1. ... gxh3ep 2. 0-0-0#! (not 2.Sf3#?,Bh2#?)
to force
R: 1. h2-h4! h3xSg2 (not 1. Kd1-e1? Kf1-g1 2. Lf3-e2# )
play all play one stop play next play all
Diagram position is retropat so Article 15 give Black the move. Then White might have last move R: 1. h2-h4 or 1. Kd1-e1. To avoid stalemate in the diagram position, White must castle to demonstrate under AP the legality of 0. gxh3ep. So 1. 0-0-0#! not 1. Sf3#?,Bh2#?
VL: Solution. 1.0-0-0#/Bh2#?? - B. is on move.

0...g*h3 e.p. 1.0-0-0#! (1.Bh2#/Sf3#?? - illegal):
W. forces B. to capture e.p. and legalizes this
possibility a posteriori.

W.Ps took 11: b*c*d*e*f*g, c*d*e*f, e*f*g and g*h.
11+5=16, hence b.Pa7 was also captured among them.
Thus it took once: 1+1(h*g)+14=16. Ph3 took on g2
when w.P stood on h2. No last W's move could be a
capture: e5 and f4 are occupied by w.pieces. Qf4
prevents from Ph3-h4 and Kh2-g1 before that. b.Ps
are blocked from above. Therefore, in his last move,
W. could retro-release B. only in two ways: Ph2-h4
with Ph3*Sg2 before that, or Kd1-e1 with Kf1-g1
and Bf3-e2+ before that. Thus, W. may castle, and
castling AP-legalizes ep (2004-12-09)
A.Buchanan: Article 15 (not AP Type Keym) drives this elegant problem, with usual AP Type Petrovic for ep/castling. (2022-02-16)
A.Buchanan: Have added genre as n#, even though n=1 here, because it's important that this is a #1 rather than a h#0.5, as they behave differently under Article 15. (2022-02-17)
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, No legal last move for Black, Castling (wk)
Genre: Retro, n#
FEN: 8/6P1/5P2/4NpPP/5QpP/P5B1/3PBPp1/R3K1kb
Reprints: Die Schwalbe 228 12/2007
Input: Gerd Wilts, 2004-08-13
Last update: James Malcom, 2022-07-05 more...
90 - P1066741
Tomislav Petrovic
R033 Probleemblad 11-12/1998
Ing. R. Tomasevic gewidmet
P1066741
(14+10) C+
h#2 (AP)
1. gxf3ep 0-0-0 2. gxh1=T gxh4#
play all play one stop play next play all
White PCs: axb=, bxc=, dxexf, cxdxe
Black PCs: fxg2. wRh was captured by officer in cage, and since wK didn’t move wRg5 is promoted
A.Buchanan: Suppose White: dxexf,cxdxe,bxc=,a| Black: fxg. This means there is one capture by white unaccounted for. So can’t White have just played e.g. QxS? What am I missing? (2022-03-22)
Mario Richter: Regarding the "can’t White have just played e.g. QxS?-question", the following considerations may be helpful:
1. black Pawn f3 x Yg2 can only be retracted after wPf2 has returned home.
2. If at this moment the black K is still on g1, Y cannot be a white rook.
3. Assuming that W can still castle, wRg5 must be a promoted Piece, since wKe1+wPf2+wPg3+wPh2 form a cage from which the originalwRh1 could not escape ...

I think the same considerations can also be useful by answering the question about +sBc6 ... (2022-03-22)
A.Buchanan: Hi Mario, thanks I agree (2022-03-22)
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg), Valladao Task, Promotion (t)
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 & retro-logic
FEN: 1B6/p2p4/1p4Q1/5PRN/4PPpb/3Np1Pp/4P1pP/R3KbkB
Input: Gerd Wilts, 2004-09-16
Last update: A.Buchanan, 2023-09-11 more...
91 - P1066793
Vladimir Korolkov
The Chess-player Smiles 1969
Version Andrey Frolkin
P1066793
(3+7)
Wer gewinnt?
1. axb6ep#
play all play one stop play next play all
Henrik Juel: Apparently White stands mated
But if last move were b6-b5#, White would have no preceding legal move
So last move was b7-b5+, and White wins by mating with axb6ep# (2021-02-08)
comment
Keywords: En passant as key, En passant
Genre: Retro
FEN: 8/p7/R1pq4/Pp6/kpK5/3r4/8/8
Reprints: Retros mailing list 09/10/2004
Input: Gerd Wilts, 2004-10-17
Last update: James Malcom, 2021-02-08 more...
92 - P1066796
Thomas Volet
Retros mailing list 14/10/2004
P1066796
(2+16)
Wer gewinnt?
1. hxg6ep#
play all play one stop play next play all
Henrik Juel: Black captured all 14 missing men with his pawns, e.g., axPb-b1=D, cxdxexf, dxexfxg, exfxgxh, fxgxh, gxh, and hxg; White promoted on a8 and c8 (and possibly more promotions)
The only possible retroplay (without repetitions) is
R: 1... g7-g5 2.Kf8-f7 Te7-e8+ 3.Kf7-f8 Te6-e7 4.Kf8-f7 D-d6+ 5.Kf7-f8 etc.
So despite his precarious situation, White wins with 1.hxg6ep# (2021-02-08)
comment
Keywords: En passant as key, En passant
Genre: Retro
FEN: 4r1nq/1p3K1k/3q1n1b/4r1pP/5pbp/6pp/7p/8
Input: Gerd Wilts, 2004-10-17
Last update: James Malcom, 2021-02-08 more...
93 - P1066797
Thomas Volet
Retros mailing list 14/10/2004
P1066797
(2+16)
Wer gewinnt?
1. hxg6ep#
play all play one stop play next play all
Henrik Juel: similar to Tom's P1066796 (2021-02-08)
comment
Keywords: En passant as key, En passant
Genre: Retro
FEN: 4r1nr/p4K1k/5n1b/4q1pP/1b3pbp/6pp/7p/8
Input: Gerd Wilts, 2004-10-17
Last update: James Malcom, 2021-02-08 more...
94 - P1066798
Thomas Volet
Retros mailing list 14/10/2004
P1066798
(2+16)
Wer gewinnt?
1. fxg6ep#
play all play one stop play next play all
Henrik Juel: similar to Tom's P1066796 (2021-02-08)
comment
Keywords: En passant as key, En passant
Genre: Retro
FEN: 6nr/5K1k/2bq1n1b/3prPp1/5ppp/6np/7p/8
Input: Gerd Wilts, 2004-10-17
Last update: James Malcom, 2021-02-08 more...
95 - P1068187
Valery Liskovets
9679 Thema Danicum 118 04/2005
P1068187
(15+5) C+
h#1* (AP)
2 Lösungen
1. ... Ke2#! (0-0#?? illegal)
1. cxd3 Sb3#! (Ke2??, 0-0+?)
1. cxb3ep 0-0#! (Ke2#?, Sxb3#?) AP
play all play one stop play next play all
VL: Solution: 1... Ke2# (1... 0-0#?? illegal).
1.cxd3 Sb3# (1... Ke2??, 0-0+?).
1.cxb3 ep! 0-0#! (1... Ke2#??, Sxb3#?? AP after N.Petrovic).
If castling is legal, then B. is on move and the last move
was b2-b4 (with b3x(B)c2 before that). Different mates. (2006-01-27)
A.Buchanan: If Wh 00 is ok, then bPh & hence bPa were waylaid. R: 1. Sa3-b1? Sb1-d2+ retropat, so R: 1. b2-b4 b3xBc2. (2022-05-24)
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wk), Volet Pawn
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 + thinking
FEN: 8/2Pp4/3N4/1PP5/1PpB4/2PR4/P1pN1PP1/Qnk1K2R
Input: Gerd Wilts, 2005-12-21
Last update: A.Buchanan, 2022-06-06 more...
96 - P1072281
Werner Keym
Tomislav Petrovic

Hannoversche Allgemeine Zeitung 1999
P1072281
(4+3) C+
h#1.5 (AP)
1. ... cxb6ep 2. 0-0-0 b7#
play all play one stop play next play all
Very elegant representation of AP Type Petrovic. Keym himself established in the Codex that the stipulation should include "AP".
more ...
comment
Keywords: En passant as key, Miniature, a posteriori (AP) (Type Petrovic), Castling
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 together with elementary reflection
FEN: r3k3/8/N1P5/KpP5/8/8/8/8
Reprints: (A2) Problemkiste (169), p. 6, 02/2007
Input: hpr, 2007-03-04
Last update: A.Buchanan, 2023-09-11 more...
97 - P1079607
Igor Vereshchagin
29 Zadachi i etyudy 14, p. 52-53, 1997
3. Lob
Thematurnier "Uschol-Prischol-Vernulsa"
P1079607
(6+15)
h#3 (AP)
1. cxb3ep 0-0-0 (T~?,L~?) 2. Dxd2+ Kxd2 3. La1 Txa1#
play all play one stop play next play all
im Kongreßbuch St. Petersburg 1998 nur Nachdruck im Kapitel "Aus dem Schaffen der Kongreßteilnehmer"

Das Originaldiagramm in 'Zadachi i etyudy' ebenso wie der Nachdruck im Kongreßbuch St. Petersburg 1998 haben einen sTd8, aber der begleitende Lösungstext erwähnt im Zusammenhang mit der Frage, ob zuletzt axb3,cxb3 oder cxb6 möglich war, daß auf dem Brett folgende schwarze Steine stehen: eine Dame, zwei Türme, zwei Springer, der schwarzfeldrige Läufer und 8 Bauern.
Also offensichtlich Diagrammfehler, und sSd8 ist korrekt.
Ladislav Packa: Why NL? Castling is a posteriori proof for e.p.! (2018-08-28)
A.Buchanan: Why not a3xSb4 or c3xSb4 as last move? Where is the promotion? (2018-08-28)
VL: Yes, it definitely looks as AP (with thematic illegal castling avoiding tries). I suspect missing two b knights somewhere: "superfluous" similarly to the b rooks...
wBa5 proves to be a promotee. Bl to move of course. (2018-08-29)
A.Buchanan: I agree with VL. WinChloe adds sSh1 & sTd8 (the latter is illegal with 8sB+2sT on the board already). If we add sSh1d8, then the problem is sound forwardly and retroly. The missing light sL can't just have been captured. (2022-05-24)
Mario Richter: Adding black Sh1+Sd8 is correct: obviously the original diagram is misprinted, the accompanying solution text speaks of: one black Queen, two black Rooks, TWO black Knights, one black dark-squared Bishop and 8 black Pawns. (2022-05-24)
A.Buchanan: Issue with animation (2022-05-25)
more ...
comment
Keywords: Valladao Task, En passant as key, Castling (wg), Promotion (L), a posteriori (AP) (Type Petrovic)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & simple retro-logic
FEN: 3n3b/1p5p/1P1p2p1/Bp6/kPp1p2r/3p3r/q2P4/R3K2n
Reprints: WCCC St. Petersburg 1998
Input: hpr, 2008-10-26
Last update: A.Buchanan, 2023-07-30 more...
98 - P1080354
Zoltan Laborczi
Gabor Tar

PS2104F The Problemist 09/2008
P1080354
(4+10) C+
h#2 (AP)
2.1...
1. Kxb4 Tb1+ 2. Ka4 Lb5#
1. cxb3ep 0-0-0! (Td1?) 2. Lh4 Txd4#
play all play one stop play next play all
See P1401524 & P1401526.
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg)
Genre: Retro, h#
Computer test: Popeye v4.87 & simple retro-logic
FEN: 8/1p2p3/B4b2/p7/kPpp4/p1p5/7r/R3K3
Input: Gerd Wilts, 2009-01-03
Last update: A.Buchanan, 2022-06-08 more...
99 - P1095638
Andrej W. Borodulin
Sportklub Bogatyr Kriwoj Rog 1988
Spezielle ehrende Erwähnung (im Russ. Turnier)
P1095638
(12+6) C+
s#5
Zuletzt geschah zwingend e7-e5.
1. dxe6ep dxe6+ 2. Kf4 Ld7 3. c8=S+ Lxc8 4. Th8 Ld7 5. Td8 e5#
play all play one stop play next play all
more ...
comment
Keywords: Multiple publication, En passant as key, Stalemate dissolution
Genre: s#, Retro
Computer test: A. Baumann: Gustav 4.2a
FEN: 2b5/1pPp4/1P1k1P2/1B1PpKPR/1P2P1p1/4B1P1/8/8
Reprints: S1246 The Problemist 01/1989
6657 Die Schwalbe 08/1989
Input: Frank Müller, 2009-12-07
Last update: A.Buchanan, 2024-01-04 more...
100 - P1096298
Guus Rol
R362 Probleemblad 10-12/2009
P1096298
(6+3) C+
h#2.5
2 Lösungen
Circe (AP)
1. ... dxc6ep[+sBc7] 2. 0-0-0 c5 3. Tg8 Dxg8[+sTa8]#
1. ... Kc6 2. Txa4 Dxa4[+sTa8] 3. 0-0-0 Da8#
play all play one stop play next play all
1. ... dxc6ep[+sBc7] 2. Txa4? Dxa4[+sTa8] 3. 0-0-0 Da8# doesn't work because we don't know whether Ta8 in the diagram position had already moved.
There are another 11 retro tries where Black does not castle at all, so can be eliminated in the usual way.
Henrik Juel: 1...d5*c6ep[+bPc7] 2.Ra8*a4 Qa2*a4[+bRa8] 3.0-0-0 Qa4-a8#
1...Kb5-c6 2.Ra8*a4 Qa2*a4[+bRa8] 3.0-0-0 Qa4-a8# (2022-01-05)
A.Buchanan: I think that the solution with e.p. is 1. ... dxc6ep[+sBc7] 2. 0-0-0 c5 3. Tg8 Dxg8[+bTa8]# The one that you give Henrik doesn't work in Circe, because we don't know whether sTa8 had moved there prior to the diagram position (2022-01-07)
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), Circe, Castling, En passant as key
Genre: Retro, Fairies, h#
Computer test: HC+ Popeye 4.61 + thinking about AP
FEN: r3k3/8/8/1KpP4/P1P5/8/QP6/8
Input: Gerd Wilts, 2009-12-19
Last update: A.Buchanan, 2022-03-21 more...
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The problems of this query have been registered by the following contributors:

Gerd Wilts (88)
Hans-Jürgen Schäfer (1)
hpr (3)
Henri Nouguier (4)
Brian Stephenson (3)
Frank Müller (1)