42 problem(s) found in 5276 milliseconds (displaying 42 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND K='Kein letzter Zug von Schwarz' AND NOT CPLUS ] [download as LaTeX]
1 - P0000324
Josef Haas
8259 Die Schwalbe 143 10/1993
(7+5)
a) Wer setzt in 1 Zug matt?
b) Auf welchem Feld muß ein schwarzer Bauer eingefügt werden, damit die andere Partei als in a) mattsetzt?
Josef Haas
8259 Die Schwalbe 143 10/1993
(7+5)
a) Wer setzt in 1 Zug matt?
b) Auf welchem Feld muß ein schwarzer Bauer eingefügt werden, damit die andere Partei als in a) mattsetzt?
b) (+sBc7) 1. ... Lg8xe6#
a) 1. Tg6#
1) R: 1. ... Kg6xBf6! 2. g5xf6ep++ f7-f5 3. La2-b1+
"Vermutlich aus der Kleinkunstkiste des Autors hervorgekramt.
a) sollte einfach formuliert sein: 'Matt in 1 Zug' - denn wie es hier heißt, klingt es als ob nur einer mattsetzen kann. Das aber ist nicht der Fall, denn beide können's: 1. ... Lxe6# und 1. Tg6#. Üblicherweise hat Weiß das Prae und kann darauf pochen, den Schwarz hat einen altklassischen letzten Zug: 1. ... Kg6xBf6! (nebst 2. Bg5xBf6ep++ Bf7-f5 3. La2-(x)b1)" (HHS);
also ist Weiß am Zug und setzt matt mit 1. Tg6#.
b) Nach Einfügen eines sBc7 geht die o.g. Rückzugfolge nicht, weil der wK nicht auf die 8. Reihe gelangen kann. Also Schwarz am Zuge und 1. ... Lxe6#
"Allzubekanntes - kein Problem für Schwalbelöser" (HHS)
Wenn das alles so bekannt ist, erstaunt doch sehr, daß nur drei Löser die Autorintention nachvollziehen konnten. Alle anderen Löser (5) kamen zu genau entgegengesetzten Erkenntnissen (in a) setzt Schwarz matt, in b) Weiß), was wohl durch die nicht ganz konventionelle Formulierung suggeriert wurde. Ich find's ein interessantes Beispiel für Massenhypnose! (GL) 2/I/3L.
a) 1. Tg6#
1) R: 1. ... Kg6xBf6! 2. g5xf6ep++ f7-f5 3. La2-b1+
"Vermutlich aus der Kleinkunstkiste des Autors hervorgekramt.
a) sollte einfach formuliert sein: 'Matt in 1 Zug' - denn wie es hier heißt, klingt es als ob nur einer mattsetzen kann. Das aber ist nicht der Fall, denn beide können's: 1. ... Lxe6# und 1. Tg6#. Üblicherweise hat Weiß das Prae und kann darauf pochen, den Schwarz hat einen altklassischen letzten Zug: 1. ... Kg6xBf6! (nebst 2. Bg5xBf6ep++ Bf7-f5 3. La2-(x)b1)" (HHS);
also ist Weiß am Zug und setzt matt mit 1. Tg6#.
b) Nach Einfügen eines sBc7 geht die o.g. Rückzugfolge nicht, weil der wK nicht auf die 8. Reihe gelangen kann. Also Schwarz am Zuge und 1. ... Lxe6#
"Allzubekanntes - kein Problem für Schwalbelöser" (HHS)
Wenn das alles so bekannt ist, erstaunt doch sehr, daß nur drei Löser die Autorintention nachvollziehen konnten. Alle anderen Löser (5) kamen zu genau entgegengesetzten Erkenntnissen (in a) setzt Schwarz matt, in b) Weiß), was wohl durch die nicht ganz konventionelle Formulierung suggeriert wurde. Ich find's ein interessantes Beispiel für Massenhypnose! (GL) 2/I/3L.
Keywords: Add pieces, No legal last move for Black, En passant in the retro play
Genre: Retro
FEN: 4K1br/1p4pP/4Pk2/R7/3P4/8/8/1B4R1
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2023-01-03 more...
Genre: Retro
FEN: 4K1br/1p4pP/4Pk2/R7/3P4/8/8/1B4R1
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2023-01-03 more...
Set Play
1. ... Kxh1 2. Kf2#
1. ... Kxh3 2. Sf4#
1. ... Kxf3 2. Lb7#
BTM
1. ... hxg5 2. Sc3
2. ... Kxh1 3. Kf2#
2. ... Kxh3 3. Lf1#
2. ... Kxf3 3. 0-0#
Cook: 1. ... hxg5 2. Kd2 Kxh3 3. Df1# 2. ... Kxf3 3. Lb7#
1. ... Kxh1 2. Kf2#
1. ... Kxh3 2. Sf4#
1. ... Kxf3 2. Lb7#
BTM
1. ... hxg5 2. Sc3
2. ... Kxh1 3. Kf2#
2. ... Kxh3 3. Lf1#
2. ... Kxf3 3. 0-0#
Cook: 1. ... hxg5 2. Kd2 Kxh3 3. Df1# 2. ... Kxf3 3. Lb7#
A.Buchanan: We can +wBd2, but then need to e.g. transpose wLg7 & wBg5, otherwise the wBB are impossibly concentrated in corner. Then I think it's sound. (2021-10-08)
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Keywords: Castling (wk), No legal last move for Black, Superseded by (P1394496)
Genre: Retro
Computer test: C- Popeye v4.87
FEN: 8/6BR/B6p/6PP/3P2Np/5P1P/4N1kP/Q3K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-12 more...
Genre: Retro
Computer test: C- Popeye v4.87
FEN: 8/6BR/B6p/6PP/3P2Np/5P1P/4N1kP/Q3K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-12 more...
Kritisiert wurde sowohl von den Lösern als auch vom Retro-SB Frank Schützhold (die Aufgabe war ohne dessen Wissen der Retroabteilung vom Schriftleiter H.-D. Leiß zugeschlagen worden) die irreführende Forderung 'Matt in ZWEI Zügen'.
Kevin Begley: Best guess: #2.5?
wRa1-d1 (completing castling) [Kc2 [Ra1#]] (2009-01-22)
Henrik Juel: after the castling completion:
0... Kxa2 1.Kc2 Ka3 2.Ta1#
C+ Popeye 4.61 (2022-07-10)
comment
Kevin Begley: Best guess: #2.5?
wRa1-d1 (completing castling) [Kc2 [Ra1#]] (2009-01-22)
Henrik Juel: after the castling completion:
0... Kxa2 1.Kc2 Ka3 2.Ta1#
C+ Popeye 4.61 (2022-07-10)
comment
Keywords: No legal last move for Black, Complete an unfinished move (w0-0-0)
Genre: Retro
FEN: 8/8/8/8/P1R5/k1B5/P7/R1K5
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-07-10 more...
Genre: Retro
FEN: 8/8/8/8/P1R5/k1B5/P7/R1K5
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-07-10 more...
4 - P0006632
Anatolii Vasylenko
(2) Die Schwalbe 159, p. 364, 06/1996
2. Preis Ceriani-Gedenkturnier, 2. Abteilung
(6+2)
#2
UW-Figuren in der Diagrammstellung sind 1) zulässig 2) unzulässig
Anatolii Vasylenko
(2) Die Schwalbe 159, p. 364, 06/1996
2. Preis Ceriani-Gedenkturnier, 2. Abteilung
(6+2)
#2
UW-Figuren in der Diagrammstellung sind 1) zulässig 2) unzulässig
1) 1. Tc8 Kxf8 2. Lf6#
2) 1. ... Kxd8 2. Kf7 g6 3. Se6# 1. ... Kxf8 2. Te7 Kg8 3. Te8#
2) 1. ... Kxd8 2. Kf7 g6 3. Se6# 1. ... Kxf8 2. Te7 Kg8 3. Te8#
Henrik Juel: C+ Popeye 4.61
It is obvious that if Ld8 is not a promoted pawn then Black has the move (2021-12-26)
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It is obvious that if Ld8 is not a promoted pawn then Black has the move (2021-12-26)
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Keywords: Non-standard material, Minimal, Homebase, No legal last move for Black
Genre: Retro, 2#
FEN: 3BkN2/2R3p1/1P4K1/6P1/8/8/8/8
Reprints: 3 Problemist Yuga 3-4, p. 37, 01-06/1997
feenschach 137 08-09/2000
Input: Gerd Wilts, 1996-07-11
Last update: A.Buchanan, 2021-12-27 more...
Genre: Retro, 2#
FEN: 3BkN2/2R3p1/1P4K1/6P1/8/8/8/8
Reprints: 3 Problemist Yuga 3-4, p. 37, 01-06/1997
feenschach 137 08-09/2000
Input: Gerd Wilts, 1996-07-11
Last update: A.Buchanan, 2021-12-27 more...
5 - P0006638
Alexander Hildebrand
(37) Die Schwalbe 159, p. 366, 06/1996
2. Lob Ceriani-Gedenkturnier, 2. Abteilung
(5+2)
#2
UW-Figuren in der Diagrammstellung sind 1) zulässig 2) unzulässig
Alexander Hildebrand
(37) Die Schwalbe 159, p. 366, 06/1996
2. Lob Ceriani-Gedenkturnier, 2. Abteilung
(5+2)
#2
UW-Figuren in der Diagrammstellung sind 1) zulässig 2) unzulässig
1) 1. Lxg1 Kxg1 2. Ta1#
2) 1. ... Lxh2 2. Txh2+ Kg1 3. Ta1#
1. ... Lf2+ Kxf2 2. Kxh2 Th8#
1. ... Lxe3 2. Ta1+ Lg1 3. Txg1#
2) 1. ... Lxh2 2. Txh2+ Kg1 3. Ta1#
1. ... Lf2+ Kxf2 2. Kxh2 Th8#
1. ... Lxe3 2. Ta1+ Lg1 3. Txg1#
Keywords: Non-standard material, Minimal, Miniature, No legal last move for Black
Genre: Retro
FEN: R7/8/8/8/8/4P1K1/R6B/6bk
Input: Gerd Wilts, 1996-07-11
Last update: Mario Richter, 2022-01-02 more...
Genre: Retro
FEN: R7/8/8/8/8/4P1K1/R6B/6bk
Input: Gerd Wilts, 1996-07-11
Last update: Mario Richter, 2022-01-02 more...
6 - P0006639
Alexander Hildebrand
(40) Die Schwalbe 159, p. 366, 06/1996
3. Lob Ceriani-Gedenkturnier, 2. Abteilung
(5+2)
#1
UW-Figuren in der Diagrammstellung sind 1) zulässig 2) unzulässig
Alexander Hildebrand
(40) Die Schwalbe 159, p. 366, 06/1996
3. Lob Ceriani-Gedenkturnier, 2. Abteilung
(5+2)
#1
UW-Figuren in der Diagrammstellung sind 1) zulässig 2) unzulässig
1) 1. Se3#
2) 1. ... Txf1 2. Tfg3#, 1. ... Txh1 2. Thg3#
2) 1. ... Txf1 2. Tfg3#, 1. ... Txh1 2. Thg3#
Keywords: Non-standard material, Aristocrat, Minimal, Miniature, No legal last move for Black
Genre: Retro
FEN: 8/8/6K1/8/8/5R1R/6k1/5NrN
Input: Gerd Wilts, 1996-07-11
Last update: Mario Richter, 2022-01-02 more...
Genre: Retro
FEN: 8/8/6K1/8/8/5R1R/6k1/5NrN
Input: Gerd Wilts, 1996-07-11
Last update: Mario Richter, 2022-01-02 more...
1. ... Kxh6 2. Sf8 Kh5 3. Th4#
Keywords: No legal last move for Black, Miniature
Genre: Retro
FEN: 8/8/6NP/7k/6R1/6KN/8/8
Input: Gerd Wilts, 2000-10-07
Last update: Rainer Staudte, 2022-08-03 more...
Genre: Retro
FEN: 8/8/6NP/7k/6R1/6KN/8/8
Input: Gerd Wilts, 2000-10-07
Last update: Rainer Staudte, 2022-08-03 more...
1. ... gxh3ep 2. 0-0-0#! (not 2.Sf3#?,Bh2#?)
to force
R: 1. h2-h4! h3xSg2 (not 1. Kd1-e1? Kf1-g1 2. Lf3-e2# )
Diagram position is retropat so Article 15 give Black the move. Then White might have last move R: 1. h2-h4 or 1. Kd1-e1. To avoid stalemate in the diagram position, White must castle to demonstrate under AP the legality of 0. gxh3ep. So 1. 0-0-0#! not 1. Sf3#?,Bh2#?
to force
R: 1. h2-h4! h3xSg2 (not 1. Kd1-e1? Kf1-g1 2. Lf3-e2# )
Diagram position is retropat so Article 15 give Black the move. Then White might have last move R: 1. h2-h4 or 1. Kd1-e1. To avoid stalemate in the diagram position, White must castle to demonstrate under AP the legality of 0. gxh3ep. So 1. 0-0-0#! not 1. Sf3#?,Bh2#?
VL: Solution. 1.0-0-0#/Bh2#?? - B. is on move.
0...g*h3 e.p. 1.0-0-0#! (1.Bh2#/Sf3#?? - illegal):
W. forces B. to capture e.p. and legalizes this
possibility a posteriori.
W.Ps took 11: b*c*d*e*f*g, c*d*e*f, e*f*g and g*h.
11+5=16, hence b.Pa7 was also captured among them.
Thus it took once: 1+1(h*g)+14=16. Ph3 took on g2
when w.P stood on h2. No last W's move could be a
capture: e5 and f4 are occupied by w.pieces. Qf4
prevents from Ph3-h4 and Kh2-g1 before that. b.Ps
are blocked from above. Therefore, in his last move,
W. could retro-release B. only in two ways: Ph2-h4
with Ph3*Sg2 before that, or Kd1-e1 with Kf1-g1
and Bf3-e2+ before that. Thus, W. may castle, and
castling AP-legalizes ep (2004-12-09)
A.Buchanan: Article 15 (not AP Type Keym) drives this elegant problem, with usual AP Type Petrovic for ep/castling. (2022-02-16)
A.Buchanan: Have added genre as n#, even though n=1 here, because it's important that this is a #1 rather than a h#0.5, as they behave differently under Article 15. (2022-02-17)
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0...g*h3 e.p. 1.0-0-0#! (1.Bh2#/Sf3#?? - illegal):
W. forces B. to capture e.p. and legalizes this
possibility a posteriori.
W.Ps took 11: b*c*d*e*f*g, c*d*e*f, e*f*g and g*h.
11+5=16, hence b.Pa7 was also captured among them.
Thus it took once: 1+1(h*g)+14=16. Ph3 took on g2
when w.P stood on h2. No last W's move could be a
capture: e5 and f4 are occupied by w.pieces. Qf4
prevents from Ph3-h4 and Kh2-g1 before that. b.Ps
are blocked from above. Therefore, in his last move,
W. could retro-release B. only in two ways: Ph2-h4
with Ph3*Sg2 before that, or Kd1-e1 with Kf1-g1
and Bf3-e2+ before that. Thus, W. may castle, and
castling AP-legalizes ep (2004-12-09)
A.Buchanan: Article 15 (not AP Type Keym) drives this elegant problem, with usual AP Type Petrovic for ep/castling. (2022-02-16)
A.Buchanan: Have added genre as n#, even though n=1 here, because it's important that this is a #1 rather than a h#0.5, as they behave differently under Article 15. (2022-02-17)
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Keywords: a posteriori (AP) (Type Petrovic), En passant as key, No legal last move for Black, Castling (wk)
Genre: Retro, n#
FEN: 8/6P1/5P2/4NpPP/5QpP/P5B1/3PBPp1/R3K1kb
Reprints: Die Schwalbe 228 12/2007
Input: Gerd Wilts, 2004-08-13
Last update: James Malcom, 2022-07-05 more...
Genre: Retro, n#
FEN: 8/6P1/5P2/4NpPP/5QpP/P5B1/3PBPp1/R3K1kb
Reprints: Die Schwalbe 228 12/2007
Input: Gerd Wilts, 2004-08-13
Last update: James Malcom, 2022-07-05 more...
9 - P1066819
Valery Kirillov
Mykhailo Myshko
The Ural's Problemist 04-06/2004
2. Thematurnier
4. Preis
(15+7)
s#2
Valery Kirillov
Mykhailo Myshko
The Ural's Problemist 04-06/2004
2. Thematurnier
4. Preis
(15+7)
s#2
1. ... h1=D Lh6 Dg2,Dh2 2. Ld2+ Dxd2#
1. ... h1=D Lh6 Dxd5 2. Txd5 Lb2#
1. ... h1=D Lh6 De4 2. dxe4 Lb2#
1. ... h1=D Lh6 Df3,Dxh3 2. Sxf3,Sxh3 Lb2#
1. ... h1=T Ld6 Th2 2. Lxh2 Lb2#
1. ... h1=T Ld6 Txh3 2. Sxh3 Lb2#
1. ... h1=L Sf4 Lg2,Lf3 2. Sxg2,Sxf3 Lb2#
1. ... h1=L Sf4 Le4 2. dxe4 Lb2#
1. ... h1=L Sf4 Lxd5 2. Txd5 Lb2#
1. ... h1=S Tf5 Sf2 2. Txf2 Lb2#
1. ... h1=S Tf5 Sg3 2. Se2+ Sxe2#
1. ... hxg1=L Lg7+ Ld4 2. Txd4 Lb2#
1. ... hxg1=S Sg5 Sf3,Sxh3 2. Sxf3,Sxh3 Lb2#
Die Retroanlayse zeigt, daß Schwarz am Zuge sein muß.
1. ... h1=D Lh6 Dxd5 2. Txd5 Lb2#
1. ... h1=D Lh6 De4 2. dxe4 Lb2#
1. ... h1=D Lh6 Df3,Dxh3 2. Sxf3,Sxh3 Lb2#
1. ... h1=T Ld6 Th2 2. Lxh2 Lb2#
1. ... h1=T Ld6 Txh3 2. Sxh3 Lb2#
1. ... h1=L Sf4 Lg2,Lf3 2. Sxg2,Sxf3 Lb2#
1. ... h1=L Sf4 Le4 2. dxe4 Lb2#
1. ... h1=L Sf4 Lxd5 2. Txd5 Lb2#
1. ... h1=S Tf5 Sf2 2. Txf2 Lb2#
1. ... h1=S Tf5 Sg3 2. Se2+ Sxe2#
1. ... hxg1=L Lg7+ Ld4 2. Txd4 Lb2#
1. ... hxg1=S Sg5 Sf3,Sxh3 2. Sxf3,Sxh3 Lb2#
Die Retroanlayse zeigt, daß Schwarz am Zuge sein muß.
Olaf Jenkner: Für mich ist das ein Dreizüger. (2017-02-08)
Henrik Juel: An ordinary mate in two is really #1.5, but by ancient convention the stipulation is called #2, because each variation contains 2 white moves; maybe a similar convention has been applied here
White is missing his light-squared [Lf1] only, so the black capture was a6xLb5, not a5xb4 nor g3xh2; the other possible black last moves are obviously illegal, so Black has the move (there is no problem with the white captures, as just six white pawn captures are needed, including g2xh3 and hxg) (2017-02-08)
A.Buchanan: For adversarial stipulations i.e. d# & s# according to codex article 15 footnotes Black gets an extra pre-move. So the stipulation is ok. This is independent of the d# move-counting anomaly that Henrik points out (2021-02-16)
Hans-Jürgen Manthey: s#2 = 1. weiß schwarz 2. weiß schwarz #
also ist das ein S#2,5 oder s#3 schwarz beginnt !! (2021-02-20)
A.Buchanan: H-J: Article 15 of the Codex says that if the 1st move is not with the conventional party then it should be either stated in the stipulation or deductible from retroanalysis. Footnote 19 says "the preliminary move by the unconventional party is not counted, except in help-play problems. The number of moves to be expressed in the stipulation should be the number of moves to be made by White".
So an affected d# or s$ has an extra zeroth black single move, an affected h# loses the initial black single move. There are many aspects of conventions which I rail against, but this one for some reason doesn't trouble me. (2021-02-23)
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Henrik Juel: An ordinary mate in two is really #1.5, but by ancient convention the stipulation is called #2, because each variation contains 2 white moves; maybe a similar convention has been applied here
White is missing his light-squared [Lf1] only, so the black capture was a6xLb5, not a5xb4 nor g3xh2; the other possible black last moves are obviously illegal, so Black has the move (there is no problem with the white captures, as just six white pawn captures are needed, including g2xh3 and hxg) (2017-02-08)
A.Buchanan: For adversarial stipulations i.e. d# & s# according to codex article 15 footnotes Black gets an extra pre-move. So the stipulation is ok. This is independent of the d# move-counting anomaly that Henrik points out (2021-02-16)
Hans-Jürgen Manthey: s#2 = 1. weiß schwarz 2. weiß schwarz #
also ist das ein S#2,5 oder s#3 schwarz beginnt !! (2021-02-20)
A.Buchanan: H-J: Article 15 of the Codex says that if the 1st move is not with the conventional party then it should be either stated in the stipulation or deductible from retroanalysis. Footnote 19 says "the preliminary move by the unconventional party is not counted, except in help-play problems. The number of moves to be expressed in the stipulation should be the number of moves to be made by White".
So an affected d# or s$ has an extra zeroth black single move, an affected h# loses the initial black single move. There are many aspects of conventions which I rail against, but this one for some reason doesn't trouble me. (2021-02-23)
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Keywords: No legal last move for Black, Allumwandlung (s)
Genre: Retro, s#
FEN: 5B2/1pQR1P2/1Pb1N3/1P1R4/1p4P1/1PkP3P/P1p4p/b1K3N1
Input: Frank Müller, 2004-11-01
Last update: A.Buchanan, 2021-02-24 more...
Genre: Retro, s#
FEN: 5B2/1pQR1P2/1Pb1N3/1P1R4/1p4P1/1PkP3P/P1p4p/b1K3N1
Input: Frank Müller, 2004-11-01
Last update: A.Buchanan, 2021-02-24 more...
10 - P1066820
Yakov G. Vladimirov
The Ural's Problemist 04-06/2004
2. Thematurnier
1. ehrende Erwähnung
(15+5)
s#4
Yakov G. Vladimirov
The Ural's Problemist 04-06/2004
2. Thematurnier
1. ehrende Erwähnung
(15+5)
s#4
0. ... Kxh3 1. Se3+ Kg3 2. Lh2+ Kf2 3. Sc4 h3 4. Lg2 hxg2#
Retro 1. ... Kf2-g3 2. Lh2-g1+ Kg3-f2 3. Lg1-h2+, deshalb ist Schwarz am Zuge.
Retro 1. ... Kf2-g3 2. Lh2-g1+ Kg3-f2 3. Lg1-h2+, deshalb ist Schwarz am Zuge.
Keywords: No legal last move for Black
Genre: Retro, s#
FEN: 8/4p3/4R1P1/3P1RpP/5pPp/5NkP/2P1P1N1/1Q3BBK
Input: Frank Müller, 2004-11-01
Last update: A.Buchanan, 2021-02-16 more...
Genre: Retro, s#
FEN: 8/4p3/4R1P1/3P1RpP/5pPp/5NkP/2P1P1N1/1Q3BBK
Input: Frank Müller, 2004-11-01
Last update: A.Buchanan, 2021-02-16 more...
0. ... Kxc4 1. Db1
0. ... Kxe6 1. Dh7
0. ... Kxe6 1. Dh7
Keywords: Symmetrical position, No legal last move for Black, Aristocrat, Miniature
Genre: Retro
FEN: K7/1N6/4R3/3k4/2R5/5N2/8/7Q
Input: Gerd Wilts, 2010-06-23
Last update: Rainer Staudte, 2022-02-15 more...
Genre: Retro
FEN: K7/1N6/4R3/3k4/2R5/5N2/8/7Q
Input: Gerd Wilts, 2010-06-23
Last update: Rainer Staudte, 2022-02-15 more...
Schwarz hat keinen letzten Zug, deshalb (Zugzwang):
1. ... b4 2. Tb3 bxa3 3. Lb7#
1. axb6ep? axb6+ 2. Txb6# (aber zuletzt R: b7-b5? ist wegen wLa8 und sBa7 illegal.)
1. ... b4 2. Tb3 bxa3 3. Lb7#
1. axb6ep? axb6+ 2. Txb6# (aber zuletzt R: b7-b5? ist wegen wLa8 und sBa7 illegal.)
Keywords: No legal last move for Black, En passant as key
Genre: Retro
FEN: B7/p7/k1N5/PpK5/8/B7/8/1R6
Reprints: 3 Der Schachzug (FV Schach Berlin) 15 05-06/1976
Input: Gerd Wilts, 2010-06-23
Last update: Mario Richter, 2022-08-09 more...
Genre: Retro
FEN: B7/p7/k1N5/PpK5/8/B7/8/1R6
Reprints: 3 Der Schachzug (FV Schach Berlin) 15 05-06/1976
Input: Gerd Wilts, 2010-06-23
Last update: Mario Richter, 2022-08-09 more...
a) BTM
1. ... bxa3ep! 2. Dc3#! (2.0-0#??)
1.0-0#?
b) BTM pushed by Wh
1. ... bxa3ep! 2. 0-0#! (2.Dc3#? AP needs the 00)
1.0-0#?
(a) Wh made 11 pcs, right to left, which accounts for all missing Bl units. wBa never captured, so sBa must have captured a3xSb2, prior to Wh a2-a4. Since Wh is missing only 1 unit, bBh promoted on h1, disrupting Wh 00 rights. Moreover Bl has no last move and by Codex Article 15, it’s Bl to move. Last move by Wh must allow Bl a prior move. This can only be R: 1. a2-a4 a3xSb2. So ep is on and there is no alternative.
(b) Again Wh has made 11 pcs, but Black may now have made 2. If WTM, then Black's last move was R: 1. Kc2xSc1 Td1-d2+ 2. Kc3-c2 or R: 1. cxSb1=T or R: 1. cxSb2 (as wBc4 & wBc7 might be foreign to c-file and allow bBc a smooth retraction). In any case, sBa3xSb2 was played so sBh-h1= disrupting 00. So Wh can still not play 1. 0-0#! Now White pushes the move to Bl and also asserts that bxa3ep is on. Both claims will be "proved" by Wh 0-0. We know that with WTM, Wh can't castle, so that's half of it. But if BTM with Wh to castle, then bPaxb & bPhxg, and the only way we can retract is as in (a). The mating move is different, because we have that extra Bl pc to keep castling legal, but we must actually castle so that the whole AP logic can work!
However, I don't understand why Wh can't just play 1. Txb2#?
Cook: In (b) Wh can just play 1. Txb2#
1. ... bxa3ep! 2. Dc3#! (2.0-0#??)
1.0-0#?
b) BTM pushed by Wh
1. ... bxa3ep! 2. 0-0#! (2.Dc3#? AP needs the 00)
1.0-0#?
(a) Wh made 11 pcs, right to left, which accounts for all missing Bl units. wBa never captured, so sBa must have captured a3xSb2, prior to Wh a2-a4. Since Wh is missing only 1 unit, bBh promoted on h1, disrupting Wh 00 rights. Moreover Bl has no last move and by Codex Article 15, it’s Bl to move. Last move by Wh must allow Bl a prior move. This can only be R: 1. a2-a4 a3xSb2. So ep is on and there is no alternative.
(b) Again Wh has made 11 pcs, but Black may now have made 2. If WTM, then Black's last move was R: 1. Kc2xSc1 Td1-d2+ 2. Kc3-c2 or R: 1. cxSb1=T or R: 1. cxSb2 (as wBc4 & wBc7 might be foreign to c-file and allow bBc a smooth retraction). In any case, sBa3xSb2 was played so sBh-h1= disrupting 00. So Wh can still not play 1. 0-0#! Now White pushes the move to Bl and also asserts that bxa3ep is on. Both claims will be "proved" by Wh 0-0. We know that with WTM, Wh can't castle, so that's half of it. But if BTM with Wh to castle, then bPaxb & bPhxg, and the only way we can retract is as in (a). The mating move is different, because we have that extra Bl pc to keep castling legal, but we must actually castle so that the whole AP logic can work!
However, I don't understand why Wh can't just play 1. Txb2#?
Cook: In (b) Wh can just play 1. Txb2#
b) Urdruck in Die Schwalbe 228, 12/2007
A.Buchanan: Any ideas about (b)? (2022-06-09)
Henrik Juel: Andrew, you can find Heft 228 on
https://www.dieschwalbe.de/archiv.htm
part b) is mentioned in an article by Valery Livkovets, p.299-304
diagram p.301, solution p.303 (2022-06-09)
A.Buchanan: Thanks Henrik - just the pointer I needed. Please check the detailed solution I'll post above. (2022-06-09)
A.Buchanan: OK the logic nearly works for me. But I don't understand why White can't just play 1. Txb2# in part b, because b2 is now covered by wD. What am I missing? (2022-06-09)
Henrik Juel: Indeed, 1.Txb2# looks like a cook (2022-06-09)
A.Buchanan: Werner agrees. He has fixed it with a better twinning condition (2022-06-12)
more ...
comment
A.Buchanan: Any ideas about (b)? (2022-06-09)
Henrik Juel: Andrew, you can find Heft 228 on
https://www.dieschwalbe.de/archiv.htm
part b) is mentioned in an article by Valery Livkovets, p.299-304
diagram p.301, solution p.303 (2022-06-09)
A.Buchanan: Thanks Henrik - just the pointer I needed. Please check the detailed solution I'll post above. (2022-06-09)
A.Buchanan: OK the logic nearly works for me. But I don't understand why White can't just play 1. Txb2# in part b, because b2 is now covered by wD. What am I missing? (2022-06-09)
Henrik Juel: Indeed, 1.Txb2# looks like a cook (2022-06-09)
A.Buchanan: Werner agrees. He has fixed it with a better twinning condition (2022-06-12)
more ...
comment
Keywords: Cant Castler, En passant as key, No legal last move for Black, a posteriori (AP) (Type Petrovic), Castling, a posteriori (AP) (Type Keym), Superseded by (P1406456)
Genre: Retro
FEN: 8/2P5/3P4/QP2N1B1/PpP5/1P1P4/1p1RBP2/brk1K2R
Reprints: (10) Die Schwalbe 228, p. 301, 12/2007
Input: Gerd Wilts, 2010-06-23
Last update: A.Buchanan, 2022-12-05 more...
Genre: Retro
FEN: 8/2P5/3P4/QP2N1B1/PpP5/1P1P4/1p1RBP2/brk1K2R
Reprints: (10) Die Schwalbe 228, p. 301, 12/2007
Input: Gerd Wilts, 2010-06-23
Last update: A.Buchanan, 2022-12-05 more...
b) +wBf7 #1 1. f8=D#,l#
c) +wSf7 #1, White moved last 1. ... Lxf7 2. Sxf7#
d) +wLf7 #2 1. Lxc4 ... 2. Le3#
e) +wTf7 #3 1. Tf4 Txd4 2. Txd4 Lxf7 3. Sxf7#
1. ... Txb4 2. Le3 Txf4+ 3. Lxf4#
f) +wDf7 #4, White moved last 1. ... Txd4+ 2. Kg3 Lxf7 3. Sxf7+ Kh5 4. Th1+ Th4 5. Txh4#
2. ... Td3+ 3. cxd3 Lxf7 4. Sxf7+ Kh5 5. Th1#
c) +wSf7 #1, White moved last 1. ... Lxf7 2. Sxf7#
d) +wLf7 #2 1. Lxc4 ... 2. Le3#
e) +wTf7 #3 1. Tf4 Txd4 2. Txd4 Lxf7 3. Sxf7#
1. ... Txb4 2. Le3 Txf4+ 3. Lxf4#
f) +wDf7 #4, White moved last 1. ... Txd4+ 2. Kg3 Lxf7 3. Sxf7+ Kh5 4. Th1+ Th4 5. Txh4#
2. ... Td3+ 3. cxd3 Lxf7 4. Sxf7+ Kh5 5. Th1#
Henrik Juel: C+ Popeye 4.61, except for dual in e) 1... Txc5 2.Lxc5,bxc5 and several duals in f) (2022-02-25)
comment
comment
Keywords: No legal last move for Black, Twin (Forsberg)
Genre: Retro
FEN: 3N2br/7p/5P1k/2P2P2/1PrB3K/2p5/2P5/5R2
Input: Gerd Wilts, 2010-06-26
Last update: James Malcom, 2022-02-25 more...
Genre: Retro
FEN: 3N2br/7p/5P1k/2P2P2/1PrB3K/2p5/2P5/5R2
Input: Gerd Wilts, 2010-06-26
Last update: James Malcom, 2022-02-25 more...
15 - P1109508
Valery Kirillov
Mykhailo Myshko
1234 Pat a Mat 54 2006
Informalturnier 2006/07
Lob
(15+3) cooked
s#6
Valery Kirillov
Mykhailo Myshko
1234 Pat a Mat 54 2006
Informalturnier 2006/07
Lob
(15+3) cooked
s#6
Schwarz hat keinen letzten Zug, also
1. ... h5! 2. Tc3 h4 3. Tf7+ Kh6 4. Le3+ Kh5 5. Tf5+ Kg4 6. h3+ Kxg3 7. Lg1+ Lxc3#
mit Schwarz am Zug:
1. Te4? h5 2. Le3 h4 3. Seg6 h3 4. Tg4 hxg2 5. Lh6+ Kxh6 6. Sf4+ Lxf6#
Cook: 1) NL: 1. ... h5 2. Df3,Df4,Df5 h4 3. Dg4+ Kxf6 4. Tf3+ Ke5 5. Tf7 Lg7,Lf6,h3,hxg3 6. Ld6+ Kxd6+ 7. Dd4+ Lxd4# (bad wBb6 blocks Kc7).
1. ... h5! 2. Tc3 h4 3. Tf7+ Kh6 4. Le3+ Kh5 5. Tf5+ Kg4 6. h3+ Kxg3 7. Lg1+ Lxc3#
mit Schwarz am Zug:
1. Te4? h5 2. Le3 h4 3. Seg6 h3 4. Tg4 hxg2 5. Lh6+ Kxh6 6. Sf4+ Lxf6#
Cook: 1) NL: 1. ... h5 2. Df3,Df4,Df5 h4 3. Dg4+ Kxf6 4. Tf3+ Ke5 5. Tf7 Lg7,Lf6,h3,hxg3 6. Ld6+ Kxd6+ 7. Dd4+ Lxd4# (bad wBb6 blocks Kc7).
Anton Baumann: ohne den wBb6 ist die Aufgabe C+ (Gustav 4.1d) (2021-05-12)
A.Buchanan: WinChloe has the identical diagram with wBb6, but doesn't pick up the cook (2021-05-12)
A.Buchanan: Note need to have something like "1)" at the beginning of the cook, else it assumes that the play is a variation from the retro try which began 1. Te4? (2021-10-09)
Mario Richter: The award ('Pat a Mat', issue 61 (April 2008), pp. 190-193) too has the "bad wBb6"; the distinction given is "1. Lob" ["1. cestné uznanie"] (2021-10-09)
A.Buchanan: Pat A Mat site has Tourney records only back to 2010. I've sent emails to request that the authors be contacted. I have given Anton's name as the corrector. (2021-10-10)
A.Buchanan: Resolved, see P1394513 (2021-10-12)
more ...
comment
A.Buchanan: WinChloe has the identical diagram with wBb6, but doesn't pick up the cook (2021-05-12)
A.Buchanan: Note need to have something like "1)" at the beginning of the cook, else it assumes that the play is a variation from the retro try which began 1. Te4? (2021-10-09)
Mario Richter: The award ('Pat a Mat', issue 61 (April 2008), pp. 190-193) too has the "bad wBb6"; the distinction given is "1. Lob" ["1. cestné uznanie"] (2021-10-09)
A.Buchanan: Pat A Mat site has Tourney records only back to 2010. I've sent emails to request that the authors be contacted. I have given Anton's name as the corrector. (2021-10-10)
A.Buchanan: Resolved, see P1394513 (2021-10-12)
more ...
comment
Keywords: No legal last move for Black, Superseded by (P1394513)
Genre: s#, Retro
FEN: 5N1b/4N1kP/1P2PR1p/2B5/8/4R1P1/P5PP/KB3Q2
Input: Frank Müller, 2010-07-03
Last update: A.Buchanan, 2021-10-11 more...
Genre: s#, Retro
FEN: 5N1b/4N1kP/1P2PR1p/2B5/8/4R1P1/P5PP/KB3Q2
Input: Frank Müller, 2010-07-03
Last update: A.Buchanan, 2021-10-11 more...
1. ... Kxb4 2. Ld3,Kb1 Ka4 3. c3 Kb3 4. Sc5#
1. c3? Kb3 2. Ld3,Kb1 Ka4 3. Sc5# but BTM
1. Ka2? Kxb4 2. c3+ Ka4 3. b3# but BTM
1. c3? Kb3 2. Ld3,Kb1 Ka4 3. Sc5# but BTM
1. Ka2? Kxb4 2. c3+ Ka4 3. b3# but BTM
RA3
A.Buchanan: Shifting wK to c1 removes the cooks and duals in the retro tries. (2021-10-12)
comment
A.Buchanan: Shifting wK to c1 removes the cooks and duals in the retro tries. (2021-10-12)
comment
Keywords: Miniature Collection (0346135), No legal last move for Black, Miniature
Genre: 3#, Retro
Computer test: C- Popeye v4.87
FEN: 8/1N6/B7/8/kP6/8/1PP5/K7
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2021-10-12 more...
Genre: 3#, Retro
Computer test: C- Popeye v4.87
FEN: 8/1N6/B7/8/kP6/8/1PP5/K7
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2021-10-12 more...
17 - P1119724
Vyacheslav P. Antipov
32 Schachmatnyje Sadatschi (Borowitschi) 03/1987
(6+1) cooked
#4
Vyacheslav P. Antipov
32 Schachmatnyje Sadatschi (Borowitschi) 03/1987
(6+1) cooked
#4
0. ... Kxd7 1. c8=D+! Kxc8 2. Lb8 Kxb8 3. Tc5 Ka8 4. Tc8#
0. ... Kxd5 1. Lf4+! Ke6 2. c8=D Kf5 3. Tf7+ Kg6 4. Df5#
2. ... Kf6 3. Df8+ Kg6 4. Df7#
3. ... Ke6 4. Df7#,Td6#
1. ... Kc5 2. Ld2,Ka5 droht 3. c8=D#,c8=T#
Dual 1. c8=D! droht 2. Dc4#
1. ... Ke6 2. Lf4 Kf5 3. Tf7+ Kg6 4. Df5#
2. ... Kf6 3. Df8+ Ke6 4. Df7#,Td6#
3. ... Kg6 4. Df7#
oder 2. Td8+ Kf7,Kf6 3. Dg4 ... 4. Tf8#
bzw. 2. De8+ Kf6 3. Dh5 Ke6 4. Df7#
2. ... Kf5 3. Tg7 droht 4. Dg6#,Df7#,De5#
Cook: Duale nach 1. ... Kxd5 2. Lf4 und 2. c8=D
0. ... Kxd5 1. Lf4+! Ke6 2. c8=D Kf5 3. Tf7+ Kg6 4. Df5#
2. ... Kf6 3. Df8+ Kg6 4. Df7#
3. ... Ke6 4. Df7#,Td6#
1. ... Kc5 2. Ld2,Ka5 droht 3. c8=D#,c8=T#
Dual 1. c8=D! droht 2. Dc4#
1. ... Ke6 2. Lf4 Kf5 3. Tf7+ Kg6 4. Df5#
2. ... Kf6 3. Df8+ Ke6 4. Df7#,Td6#
3. ... Kg6 4. Df7#
oder 2. Td8+ Kf7,Kf6 3. Dg4 ... 4. Tf8#
bzw. 2. De8+ Kf6 3. Dh5 Ke6 4. Df7#
2. ... Kf5 3. Tg7 droht 4. Dg6#,Df7#,De5#
Cook: Duale nach 1. ... Kxd5 2. Lf4 und 2. c8=D
E7-5 RA4
A.Buchanan: This reminds me of Plato's two chariot horses: one divine, the other a recalcitrant nag (2021-10-10)
comment
A.Buchanan: This reminds me of Plato's two chariot horses: one divine, the other a recalcitrant nag (2021-10-10)
comment
Keywords: Miniature Collection (0342661), No legal last move for Black, Miniature
Genre: n#, Retro
Computer test: C- Popeye v4.87
FEN: 8/2PR4/K1kB4/3R4/8/3P4/8/8
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2021-10-12 more...
Genre: n#, Retro
Computer test: C- Popeye v4.87
FEN: 8/2PR4/K1kB4/3R4/8/3P4/8/8
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2021-10-12 more...
1. ... b5 2. Txb5 Kxa2 3. Ta5#
1. ... b6 2. Txb6 Kxa2 3. Ta6#
1. ... Kxa2? 2. Ta8#
1. Txb7? Kxa2 2. Ta7# BTM
1. ... b6 2. Txb6 Kxa2 3. Ta6#
1. ... Kxa2? 2. Ta8#
1. Txb7? Kxa2 2. Ta7# BTM
Keywords: Miniature Collection (0312088), No legal last move for Black, Minimal, Miniature
Genre: 2#, Retro
FEN: 1R6/1p6/8/8/8/8/P1K5/k7
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2021-10-07 more...
Genre: 2#, Retro
FEN: 1R6/1p6/8/8/8/8/P1K5/k7
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2021-10-07 more...
1. Da8? Kxb1 2. Dh1#
1. ... Lxb1 2. Dh1 Ka2 3. Da8#
1. ... Lxb3 2. Kxb3 Kxb1 3. Dh1#
1. ... Kxb1 2. Dh1#
1. ... Lxb1 2. Dh1 Ka2 3. Da8#
1. ... Lxb3 2. Kxb3 Kxb1 3. Dh1#
1. ... Kxb1 2. Dh1#
Keywords: Miniature Collection (0011969), No legal last move for Black, Minimal, Miniature
Genre: 2#, Retro
FEN: 8/8/2Q5/8/8/1PK5/b3P3/kN6
Input: Felber, Volker, 2010-09-11
Last update: Rainer Staudte, 2022-08-03 more...
Genre: 2#, Retro
FEN: 8/8/2Q5/8/8/1PK5/b3P3/kN6
Input: Felber, Volker, 2010-09-11
Last update: Rainer Staudte, 2022-08-03 more...
a) 1. d8=T Ka5 2. Td6 Ka4 3. Ta6#;
b) kein letzter Zug für Schwarz, also
1. ... Kxa5 2. d8=D+ Ka6 3. Db8 Ka5 4. Db5,Da7#
b) kein letzter Zug für Schwarz, also
1. ... Kxa5 2. d8=D+ Ka6 3. Db8 Ka5 4. Db5,Da7#
RA3 BUT32 RA
b) Werner Speckmann, 04.1973, DSZ, S.134, B;
vf: klären Spiegelung in DSZ
SCHRECKE: b) kein letzter Zug für Schwarz, also: 0. ... Kxa5 1. d8D+ Ka6 2. Db8 Ka5 3. Db5,Da7# (2022-08-11)
Henrik Juel: C+ Popeye 4.61, except for the mate dual in b) (2022-08-12)
comment
b) Werner Speckmann, 04.1973, DSZ, S.134, B;
vf: klären Spiegelung in DSZ
SCHRECKE: b) kein letzter Zug für Schwarz, also: 0. ... Kxa5 1. d8D+ Ka6 2. Db8 Ka5 3. Db5,Da7# (2022-08-11)
Henrik Juel: C+ Popeye 4.61, except for the mate dual in b) (2022-08-12)
comment
Keywords: Miniature Collection (0046916), No legal last move for Black, Kindergarten Problem, Miniature, Kindergarten Problem
Genre: 3#, Retro
FEN: 8/3P4/8/8/k1K5/8/1P6/8
Input: Felber, Volker, 2010-09-11
Last update: Mario Richter, 2022-08-12 more...
Genre: 3#, Retro
FEN: 8/3P4/8/8/k1K5/8/1P6/8
Input: Felber, Volker, 2010-09-11
Last update: Mario Richter, 2022-08-12 more...
1. ... Ka7 2. b8=D+ Ka6 3. Db6#
1. b8=D#? BTM
1. b8=D#? BTM
BUD20 AS-2
A.Buchanan: While it's true that there is no legal last move for Black, does this make the problem a "Retro"? The reasoning is hyper-trivial. Was this intended as a joke? Or is there some context for the composition? If only I knew a Danish person who might have some knowledge of the culture at the time... :) (2021-10-07)
Henrik Juel: Ha-ha, here goes
Knud Hannemann was the best danish composer in his prime, but this is surely a joke
Possibly the try 1.g8=D#?? was intended
Skakbladet 1972 is not available for me, but it might throw some light on the problem (2021-10-07)
more ...
comment
A.Buchanan: While it's true that there is no legal last move for Black, does this make the problem a "Retro"? The reasoning is hyper-trivial. Was this intended as a joke? Or is there some context for the composition? If only I knew a Danish person who might have some knowledge of the culture at the time... :) (2021-10-07)
Henrik Juel: Ha-ha, here goes
Knud Hannemann was the best danish composer in his prime, but this is surely a joke
Possibly the try 1.g8=D#?? was intended
Skakbladet 1972 is not available for me, but it might throw some light on the problem (2021-10-07)
more ...
comment
Keywords: Miniature Collection (0013220), No legal last move for Black (check), Joke, Kindergarten Problem, Minimal, Miniature
Genre: 2#
FEN: k7/1PK5/8/8/8/8/8/8
Input: Felber, Volker, 2010-09-11
Last update: A.Buchanan, 2023-12-05 more...
Genre: 2#
FEN: k7/1PK5/8/8/8/8/8/8
Input: Felber, Volker, 2010-09-11
Last update: A.Buchanan, 2023-12-05 more...
1. ... Txa6/Txb7+/d5/d6 2. Dxa6#/Dxb7#/De8#/De8#
1. Da4? Txa6/Txb7+/d5/d6 2. Dxa6#/axb7#/De8#/De8# but BTM
1. Da4? Txa6/Txb7+/d5/d6 2. Dxa6#/axb7#/De8#/De8# but BTM
B14f C5c 2MW RA!
vf: Leonid Makaronez, 08.1995, Minimat (12)
SCHRECKE: Schwarz hat keinen letzten Zug! (2023-07-13)
Henrik Juel: so it is Black to move
1... Txa5,Txb7+/d5,d5 2.DxT/De8# (2023-07-13)
A.Buchanan: Here the diagram position is not just retropat but also zugzwang. Is this unintentional? Or is it some old-school assumption that if BTM, Black loses a move rather than gains one? (2023-12-05)
comment
vf: Leonid Makaronez, 08.1995, Minimat (12)
SCHRECKE: Schwarz hat keinen letzten Zug! (2023-07-13)
Henrik Juel: so it is Black to move
1... Txa5,Txb7+/d5,d5 2.DxT/De8# (2023-07-13)
A.Buchanan: Here the diagram position is not just retropat but also zugzwang. Is this unintentional? Or is it some old-school assumption that if BTM, Black loses a move rather than gains one? (2023-12-05)
comment
Keywords: Miniature Collection (0308322), No legal last move for Black, Miniature
Genre: 2#
FEN: k7/rNKp4/P7/1Q6/8/8/8/8
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2023-12-05 more...
Genre: 2#
FEN: k7/rNKp4/P7/1Q6/8/8/8/8
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2023-12-05 more...
1... b6
Cook: 1. ... b5 2. Ta1/Ta1/Ta6/Ta5/Kd7/Kd8
1. ... b6 2. b4/Kd7/Kd8
Cook: 1. ... b5 2. Ta1/Ta1/Ta6/Ta5/Kd7/Kd8
1. ... b6 2. b4/Kd7/Kd8
A18d RA3
Henrik Juel: duals, e.g., 0... b5 1.Kd8,Kd7,Ta1 (2022-12-05)
A.Buchanan: If WTM, no solution, but since no legal last move for Black, we let Black start:
1...b5
2.Ra1/Ra2/Ra6 b4
3.Kd7/Kd8 Kb7 4.a8=Q#
2.Ra5 b4
3.Rc5 Kxa7 4.Ra5#
3.Kd7/Kd8 Kb7 4.a8=Q#
2.Kd7/Kd8 b4
3.Ra1/Ra2/Ra6/Ra5/Ra4 Kb7 4.a8=Q#
1...b6
2.b4 b5
3.Re3 Kxa7 4.Ra3#
3.Kd7/Kd8 Kb7 4.a8=Q#
2.Kd7/Kd8 b5 3.b4 Kb7 4.a8=Q#
The play is so savagely dualized, that one must marked it as cooked. Typo? (2023-12-04)
comment
Henrik Juel: duals, e.g., 0... b5 1.Kd8,Kd7,Ta1 (2022-12-05)
A.Buchanan: If WTM, no solution, but since no legal last move for Black, we let Black start:
1...b5
2.Ra1/Ra2/Ra6 b4
3.Kd7/Kd8 Kb7 4.a8=Q#
2.Ra5 b4
3.Rc5 Kxa7 4.Ra5#
3.Kd7/Kd8 Kb7 4.a8=Q#
2.Kd7/Kd8 b4
3.Ra1/Ra2/Ra6/Ra5/Ra4 Kb7 4.a8=Q#
1...b6
2.b4 b5
3.Re3 Kxa7 4.Ra3#
3.Kd7/Kd8 Kb7 4.a8=Q#
2.Kd7/Kd8 b5 3.b4 Kb7 4.a8=Q#
The play is so savagely dualized, that one must marked it as cooked. Typo? (2023-12-04)
comment
Keywords: Miniature Collection (0334424), No legal last move for Black, Minimal, Miniature
Genre: 3#, Retro
Computer test: HC- Popeye v4.87 & trivial retro argument
FEN: k1K5/Pp6/8/8/8/RP6/5B2/8
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2023-12-04 more...
Genre: 3#, Retro
Computer test: HC- Popeye v4.87 & trivial retro argument
FEN: k1K5/Pp6/8/8/8/RP6/5B2/8
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2023-12-04 more...
1. ... c5 2. Txb7 a5 3. Txa5#
1. ... b5 2. Txb5 c5 3. Tb8#
1. ... b5 2. Txb5 c5 3. Tb8#
Keywords: Miniature Collection (0312119), No legal last move for Black, Miniature
Genre: 2#, Retro
FEN: k1K5/ppp5/8/8/8/8/8/RR6
Input: Zuncke/Bruder, 2010-09-11
Last update: Rainer Staudte, 2022-02-15 more...
Genre: 2#, Retro
FEN: k1K5/ppp5/8/8/8/8/8/RR6
Input: Zuncke/Bruder, 2010-09-11
Last update: Rainer Staudte, 2022-02-15 more...
1. ... Kxd7 2. Db7+ Ke8 3. Sd6#
1. ... Kxe7 2. Df5 Ke8 3. De6#
1. ... Kxf7 2. Dh7+ Ke8 3. Sf6#
1. Df5? Kxe7 2. De6# (but BTM)
1. ... Kxe7 2. Df5 Ke8 3. De6#
1. ... Kxf7 2. Dh7+ Ke8 3. Sf6#
1. Df5? Kxe7 2. De6# (but BTM)
RA2 e423 3m
A.Buchanan: I think this is the true original, not Haas 1976. It is basically the same whether L or B on 7th rank, whether K on d5 or e5, whether everything is shifted by files, whether (if L on 7th) board rotated. (2021-10-06)
Henrik Juel: I agree that P1142901 is anticipated by this problem
And this is also slightly more economical
Haas is not to blame, because the problem section in Skakbladet was not very prominent in 1970
I expect that Hilding tried to fool unwary solvers (2021-10-06)
Henrik Juel: Some old issues of Skakbladet are available at https://skakbladet.skak.dk/ (move the cursor to Arkiv at the top of the page), but issues from 1963 to 1999 are not (yet) available, so I cannot document the details of Hilding's problem (2021-10-06)
A.Buchanan: No worries about Haas or Skakbladet, Henrik. Like probably hundreds of others, Hilding's problem had the correct solution, but as marked neither as G="retro" nor k="No legal last move for Black". I've flipped a bunch of these tonight, but have run out of energy. (2021-10-06)
Henrik Juel: Thanks for your effort, Andrew (2021-10-06)
A.Buchanan: You're very welcome Henrik. Article 15 is my second favourite convention, so I am happy to have identified 146(!) in the last 24 hours that were lurking unrecognized in PDB. I was looking for g='2#' and sol='3.' so I also managed to fix typos etc in about 100 false positives. (2021-10-07)
Henrik Juel: My goodness me
I cannot handle even my old task of just testing; only thanks to Michael S, who is now doing the lion's share, we are just scraping by in the testing department
Tiny typo here in the try: 2.De6#, not 3. (2021-10-07)
comment
A.Buchanan: I think this is the true original, not Haas 1976. It is basically the same whether L or B on 7th rank, whether K on d5 or e5, whether everything is shifted by files, whether (if L on 7th) board rotated. (2021-10-06)
Henrik Juel: I agree that P1142901 is anticipated by this problem
And this is also slightly more economical
Haas is not to blame, because the problem section in Skakbladet was not very prominent in 1970
I expect that Hilding tried to fool unwary solvers (2021-10-06)
Henrik Juel: Some old issues of Skakbladet are available at https://skakbladet.skak.dk/ (move the cursor to Arkiv at the top of the page), but issues from 1963 to 1999 are not (yet) available, so I cannot document the details of Hilding's problem (2021-10-06)
A.Buchanan: No worries about Haas or Skakbladet, Henrik. Like probably hundreds of others, Hilding's problem had the correct solution, but as marked neither as G="retro" nor k="No legal last move for Black". I've flipped a bunch of these tonight, but have run out of energy. (2021-10-06)
Henrik Juel: Thanks for your effort, Andrew (2021-10-06)
A.Buchanan: You're very welcome Henrik. Article 15 is my second favourite convention, so I am happy to have identified 146(!) in the last 24 hours that were lurking unrecognized in PDB. I was looking for g='2#' and sol='3.' so I also managed to fix typos etc in about 100 false positives. (2021-10-07)
Henrik Juel: My goodness me
I cannot handle even my old task of just testing; only thanks to Michael S, who is now doing the lion's share, we are just scraping by in the testing department
Tiny typo here in the try: 2.De6#, not 3. (2021-10-07)
comment
Keywords: Miniature Collection (0311347), No legal last move for Black, Miniature, Homebase
Genre: 2#, Retro
FEN: 4k3/3NPN2/8/3K4/8/8/8/1Q6
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2021-10-08 more...
Genre: 2#, Retro
FEN: 4k3/3NPN2/8/3K4/8/8/8/1Q6
Input: Zuncke/Bruder, 2010-09-11
Last update: A.Buchanan, 2021-10-08 more...
1. ... Txh7 2. Tf8#
1. Tg7#? 1. Sf6#?
1. Tg7#? 1. Sf6#?
RA1
Henrik Juel: C+ Popeye 4.61 and analysis
not 1.Tg7? because Black has the move (2022-07-19)
comment
Henrik Juel: C+ Popeye 4.61 and analysis
not 1.Tg7? because Black has the move (2022-07-19)
comment
Keywords: Miniature Collection (0321213), No legal last move for Black, Aristocrat, Minimal, Miniature
Genre: n#, Retro
FEN: 6kr/5R1N/4K2B/8/8/8/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2023-12-04 more...
Genre: n#, Retro
FEN: 6kr/5R1N/4K2B/8/8/8/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2023-12-04 more...
1. ... Kxh2 2. Lh3 Kxh3 3. Th1#
LOT RA2
A.Buchanan: Thanks for spotting the duplicate keyword. For speed, I have 3 tabs open with PDB and cycle between them - that means I don't have to wait for each query to finish. However occasionally it means a duplicate keyword occurs. I would like if there was an easy way to catch these in PDB. Even the count of something doesn't add up (e.g. 101 cases of "Ceriani-Frolkin" in just 100 problems) it's hard to locate the issue. I will copy Gerd on this thread, and he can maybe add it to his backlog. (2021-10-07)
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A.Buchanan: Thanks for spotting the duplicate keyword. For speed, I have 3 tabs open with PDB and cycle between them - that means I don't have to wait for each query to finish. However occasionally it means a duplicate keyword occurs. I would like if there was an easy way to catch these in PDB. Even the count of something doesn't add up (e.g. 101 cases of "Ceriani-Frolkin" in just 100 problems) it's hard to locate the issue. I will copy Gerd on this thread, and he can maybe add it to his backlog. (2021-10-07)
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Keywords: Miniature Collection (0311965), No legal last move for Black
Genre: 2#, Retro
FEN: 8/8/8/8/8/5K2/4N2B/4RB1k
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2021-10-07 more...
Genre: 2#, Retro
FEN: 8/8/8/8/8/5K2/4N2B/4RB1k
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2021-10-07 more...
1. ... Dg7#
Keywords: Miniature Collection (0321222), Miniature, No legal last move for Black
Genre: n#, Retro
FEN: 6Bk/3p3q/5K2/5Q1P/8/8/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Rainer Staudte, 2022-02-25 more...
Genre: n#, Retro
FEN: 6Bk/3p3q/5K2/5Q1P/8/8/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Rainer Staudte, 2022-02-25 more...
1. ... h5,h6 Th6#
Schwarz kann nicht zuletzt gezogen haben, ist also am Zug.
Schwarz kann nicht zuletzt gezogen haben, ist also am Zug.
Rosalie Fay: Black has no previous move, so it is Black's turn. 1 ... h~ 2 Th6# (2015-09-18)
Henrik Juel: try 1.Td8? (2022-03-28)
comment
Henrik Juel: try 1.Td8? (2022-03-28)
comment
Keywords: Miniature Collection (0025566), No legal last move for Black
Genre: Retro
FEN: 7k/5K1p/3R4/8/8/8/8/8
Input: Felber, Volker, 2010-09-12
Last update: Mario Richter, 2022-03-27 more...
Genre: Retro
FEN: 7k/5K1p/3R4/8/8/8/8/8
Input: Felber, Volker, 2010-09-12
Last update: Mario Richter, 2022-03-27 more...
1... Kxe5 (1... Kxg5 2. Lg3 Kf5 3. Td5#) ((Satz:) 1... -- 2. Sh3 Kxe5 3. Td5#) 2. Se6 Kf5 3. Td5#
Cook: R: 1. Ke6-f5 Sf7-g5++ So position is legal with WTM
Cook: R: 1. Ke6-f5 Sf7-g5++ So position is legal with WTM
FO3LS RA2
A.Buchanan: I don't see how to correct this pleasant problem, while retaining miniature status, the retro logic + the model mates. With an extra Black pawn, I found 8/2p5/2N3K1/8/4BkN1/3R4/5P2/8. With just 7 units, I seemed to need non-standard material, e.g. 8/5B2/5K2/8/4BkN1/3R4/5P2/8. If anyone manages to salvage this one successfully, pls let me know. (2021-10-08)
comment
A.Buchanan: I don't see how to correct this pleasant problem, while retaining miniature status, the retro logic + the model mates. With an extra Black pawn, I found 8/2p5/2N3K1/8/4BkN1/3R4/5P2/8. With just 7 units, I seemed to need non-standard material, e.g. 8/5B2/5K2/8/4BkN1/3R4/5P2/8. If anyone manages to salvage this one successfully, pls let me know. (2021-10-08)
comment
Keywords: Miniature Collection (0314232), No legal last move for Black, Miniature
Genre: 2#, Retro
FEN: 6B1/6K1/8/4BkN1/3R4/5P2/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2021-10-07 more...
Genre: 2#, Retro
FEN: 6B1/6K1/8/4BkN1/3R4/5P2/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2021-10-07 more...
1. ... Kxg4 2. Kxg6! Kxg3 3. Th5 Kg2 4. Tg5+ Kh2,Kh1,Kh3 5. Th7#
Keywords: Miniature Collection (0344445), No legal last move for Black, Symmetrical position, Minimal, Miniature
Genre: n#, Retro
FEN: 8/5RKR/6p1/6k1/6P1/6P1/8/8
Reprints: 69 Jitvesha schachova Miniatjura [Davydjuk] 1992
Input: Zuncke/Bruder, 2010-09-12
Last update: James Malcom, 2021-01-23 more...
Genre: n#, Retro
FEN: 8/5RKR/6p1/6k1/6P1/6P1/8/8
Reprints: 69 Jitvesha schachova Miniatjura [Davydjuk] 1992
Input: Zuncke/Bruder, 2010-09-12
Last update: James Malcom, 2021-01-23 more...
1. ... fxg6! 2. Se2 g5 3. Kg3 g4 4. h3 gxh3 5. Kf2 Kh2 6. Sd4 Kh1 7. Sf5 Kh2 8. Se3 Kh1 9. Sf1 h2 10. Sg3#
1. Tf6? Kxg1 2. Txf7 Kh1 3. Tf1# but BTM
1. Tf6? Kxg1 2. Txf7 Kh1 3. Tf1# but BTM
Keywords: Miniature Collection (0344079), No legal last move for Black, Minimal, Miniature
Genre: n#, Retro
FEN: 8/5p2/6R1/8/8/7K/7P/6Nk
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2023-12-05 more...
Genre: n#, Retro
FEN: 8/5p2/6R1/8/8/7K/7P/6Nk
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2023-12-05 more...
1. ... Kxb2 2. Db3+ Ka1 3. Sc2#
1. ... Kxd4 2. Kc1 Kc3 3. Dc4#
1. ... Kxb4 2. Dc4+ Ka3 3. Db3#
2. ... Ka5 3. Db5#
Leser Hans Gruber wies darauf hin, dass mit wSf5 eine normaler Dreizüger mit Schlüssel 1. Sd4 möglich ist.
1. ... Kxd4 2. Kc1 Kc3 3. Dc4#
1. ... Kxb4 2. Dc4+ Ka3 3. Db3#
2. ... Ka5 3. Db5#
Leser Hans Gruber wies darauf hin, dass mit wSf5 eine normaler Dreizüger mit Schlüssel 1. Sd4 möglich ist.
A.Buchanan: If this was simply stipulated #2 it would work great. Was the stipulation currently given here (#3* BTM) actually the originalforderung? How are we meant to interpret the *? (2024-01-10)
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Keywords: No legal last move for Black, Rex solus
Genre: 3#, Retro
FEN: 8/8/4Q3/8/1P1N4/2k5/1N2P3/3K4
Reprints: 141 Kniffelige Schachaufgaben III 2011
Input: Frank Müller, 2011-06-12
Last update: A.Buchanan, 2024-01-10 more...
Genre: 3#, Retro
FEN: 8/8/4Q3/8/1P1N4/2k5/1N2P3/3K4
Reprints: 141 Kniffelige Schachaufgaben III 2011
Input: Frank Müller, 2011-06-12
Last update: A.Buchanan, 2024-01-10 more...
1. Dc4-g8!
Mario Richter: Cook: Schwarz hat keinen legalen letzten Zug (2014-05-25)
A.Buchanan: This is not a retro problem. If we grant Black first move, then 0. ... Txb7! refutes. It's just a technical oversight. I can find no correction in PDB or WinChloe. Observe that sBb6 serves no purpose. If we remove it, then wLb5 serves little purpose. Removing both units, and shifting wD to e1,e5,e6,g6 or h5 retains soundness, but gives Black a last move. All variations persist, including the minor dual after 1. ... Lxb7, where both mates are separately forced. I prefer wDe6, because the key defending Sc8 is otherwise too strong. Also note the try 1. Dg8? In summary therefore: correction krN5/pN6/b2KQ3/8/8/8/R7/8 #2. (2021-10-09)
A.Buchanan: WinChloe gives a different original source, Wiener Schach Zeitung, with the same year 1932, towards the end of Keeble's chess problem career. (2021-10-09)
Mario Richter: My guess is, that the publication in 'Wiener Schach-Zeitung' is only a reprint as part of what I call "a real solving competition" (since amongst the problems to be solved there were also [intentionally] some with severals cooks or with seemingly or real illegal positions):
"Aus dem diesjährigen internationalen Lösungswettkampf.
Diesem Turnier ... lagen zum Teil sehr knifflige Probleme zugrunde. Es sei für unsere Löser vorausgeschickt, daß die Aufgaben zum Teil mehrfach nebenlösig sind, mitunter eine partieunmögliche Stellung vortäuschen oder auch haben. Die Illegalität der Stellung ist zu beweisen." (2021-10-09)
A.Buchanan: Wow, thanks Mario! This is a great example then of how one can't understand a problem sometimes, without knowing the context in which it's composed. How should we classify this one here in PDB? (2021-10-09)
A.Buchanan: Since illegality is the intention, it's not cooked. And it's a joke. bBb6 is a weasel. So much is clear, but I am uncertain whether to use the descriptive keyword "illegal position" or "no legal last move for black" or something else. The latter is actually a retro-stalemate (defined as a one-sided illegal position). However, 'retro-stalemate' as a keyword it has the sense more of applying to retro compositions where a retro-stalemate is sought in the history of the game, not Article 15 cases where the diagram is already one-sidedly illegal. So I think we should keep the keyword 'no legal last move for black'. (2021-10-10)
comment
A.Buchanan: This is not a retro problem. If we grant Black first move, then 0. ... Txb7! refutes. It's just a technical oversight. I can find no correction in PDB or WinChloe. Observe that sBb6 serves no purpose. If we remove it, then wLb5 serves little purpose. Removing both units, and shifting wD to e1,e5,e6,g6 or h5 retains soundness, but gives Black a last move. All variations persist, including the minor dual after 1. ... Lxb7, where both mates are separately forced. I prefer wDe6, because the key defending Sc8 is otherwise too strong. Also note the try 1. Dg8? In summary therefore: correction krN5/pN6/b2KQ3/8/8/8/R7/8 #2. (2021-10-09)
A.Buchanan: WinChloe gives a different original source, Wiener Schach Zeitung, with the same year 1932, towards the end of Keeble's chess problem career. (2021-10-09)
Mario Richter: My guess is, that the publication in 'Wiener Schach-Zeitung' is only a reprint as part of what I call "a real solving competition" (since amongst the problems to be solved there were also [intentionally] some with severals cooks or with seemingly or real illegal positions):
"Aus dem diesjährigen internationalen Lösungswettkampf.
Diesem Turnier ... lagen zum Teil sehr knifflige Probleme zugrunde. Es sei für unsere Löser vorausgeschickt, daß die Aufgaben zum Teil mehrfach nebenlösig sind, mitunter eine partieunmögliche Stellung vortäuschen oder auch haben. Die Illegalität der Stellung ist zu beweisen." (2021-10-09)
A.Buchanan: Wow, thanks Mario! This is a great example then of how one can't understand a problem sometimes, without knowing the context in which it's composed. How should we classify this one here in PDB? (2021-10-09)
A.Buchanan: Since illegality is the intention, it's not cooked. And it's a joke. bBb6 is a weasel. So much is clear, but I am uncertain whether to use the descriptive keyword "illegal position" or "no legal last move for black" or something else. The latter is actually a retro-stalemate (defined as a one-sided illegal position). However, 'retro-stalemate' as a keyword it has the sense more of applying to retro compositions where a retro-stalemate is sought in the history of the game, not Article 15 cases where the diagram is already one-sidedly illegal. So I think we should keep the keyword 'no legal last move for black'. (2021-10-10)
comment
Keywords: No legal last move for Black (illegal), Joke
Genre: 2#
FEN: krN5/pN6/bp1K4/1B6/2Q5/8/R7/8
Reprints: 2196 Wiener Schach-Zeitung 15 08/1932
26 Deutsche Zeitung (Celje, Dravabanat) 23/10/1932
Input: Felber, Volker, 2011-11-08
Last update: A.Buchanan, 2023-12-05 more...
Genre: 2#
FEN: krN5/pN6/bp1K4/1B6/2Q5/8/R7/8
Reprints: 2196 Wiener Schach-Zeitung 15 08/1932
26 Deutsche Zeitung (Celje, Dravabanat) 23/10/1932
Input: Felber, Volker, 2011-11-08
Last update: A.Buchanan, 2023-12-05 more...
35 - P1248622
Oleksiy I. Borisenko
1674 Zadachi i etyudy 01-04/2003
2. ehrende Erwähnung
(9+3)
s#5
b) -wBg2
Oleksiy I. Borisenko
1674 Zadachi i etyudy 01-04/2003
2. ehrende Erwähnung
(9+3)
s#5
b) -wBg2
a) 1. hxg6ep+ Kh5 2. Dd1+ Kh6 3. Dh5+ Kxh5 4. g4+ Kh6 5. f4 hxg6#
b) 1. Dd1 g4 2. Dh1+ g3 3. f4 g2 4. Dxg2 Kxh5 5. Dg6+ hxg6#
b) 1. Dd1 g4 2. Dh1+ g3 3. f4 g2 4. Dxg2 Kxh5 5. Dg6+ hxg6#
Anton Baumann: Retro: Warum soll Dxc1+ g7-g5 illegal sein?
s#5: a) & b) C+ Gustav 4.2a (2024-02-05)
Henrik Juel: You are right, Anton
The keyword 'No legal last move for Black' should be deleted (2024-02-05)
comment
s#5: a) & b) C+ Gustav 4.2a (2024-02-05)
Henrik Juel: You are right, Anton
The keyword 'No legal last move for Black' should be deleted (2024-02-05)
comment
Keywords: En passant as key, No legal last move for Black
Genre: s#, Retro
FEN: 8/7p/4NB1k/4PKpP/4P3/8/5PP1/2Q5
Input: Frank Müller, 2012-09-16
Last update: A.Buchanan, 2017-10-04 more...
Genre: s#, Retro
FEN: 8/7p/4NB1k/4PKpP/4P3/8/5PP1/2Q5
Input: Frank Müller, 2012-09-16
Last update: A.Buchanan, 2017-10-04 more...
36 - P1280468
Michael Schlosser
c 90 Jahre Schachkomposition in Chemnitz 31/05/2008
150 Jahre Vereinsschach in Chemnitz
(6+3) cooked
#3
3 Lösungen
Michael Schlosser
c 90 Jahre Schachkomposition in Chemnitz 31/05/2008
150 Jahre Vereinsschach in Chemnitz
(6+3) cooked
#3
3 Lösungen
1) 1. Tg1 b6 2. Lf6 gxf6 3. g7#
2) 1. Tf1 b6 2. Tf6 gxf6 3. Lxf6#
3) 1. Lf7 b6 2. Lxg7+ Kxg7 3. h8=D#
Cook: Black has no last move. And there's no solution with Black to move.
2) 1. Tf1 b6 2. Tf6 gxf6 3. Lxf6#
3) 1. Lf7 b6 2. Lxg7+ Kxg7 3. h8=D#
Cook: Black has no last move. And there's no solution with Black to move.
Stefan Felber: Schwarz hatte keinen letzten Zug, muß also anziehen. Kein Matt in 3 Zügen möglich! (2013-11-16)
A.Buchanan: This problem has no intention of being retro. Fortunately, it is easily fixable: shift wK to c4 & sBb7 to c6. (a-file will work as well, but surely c-file is more entertaining!) (2021-10-10)
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A.Buchanan: This problem has no intention of being retro. Fortunately, it is easily fixable: shift wK to c4 & sBb7 to c6. (a-file will work as well, but surely c-file is more entertaining!) (2021-10-10)
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Keywords: Superseded by (P1394606), No legal last move for Black (unintended), no solution
Genre: 3#
Computer test: C+ Popeye v4.87
FEN: 6Bk/1p4pP/6P1/1K6/8/8/8/B6R
Input: Rainer Staudte, 2013-11-16
Last update: A.Buchanan, 2023-12-04 more...
Genre: 3#
Computer test: C+ Popeye v4.87
FEN: 6Bk/1p4pP/6P1/1K6/8/8/8/B6R
Input: Rainer Staudte, 2013-11-16
Last update: A.Buchanan, 2023-12-04 more...
1. ... b5 2. Dd4+,Dg1+ c5 3. Dxc5#
2. Da5 b4/c5/Lb7+ 3. Dc5#/Sxb5#/axb7# (trial)
1. ... c5 2. Sb5#
1. ... Lb7+ 2. axb7#
1. Da3? b5/c5/Lb7+ 2. Dc5#/Sb5#/axb7# but BTM
2. Da5 b4/c5/Lb7+ 3. Dc5#/Sxb5#/axb7# (trial)
1. ... c5 2. Sb5#
1. ... Lb7+ 2. axb7#
1. Da3? b5/c5/Lb7+ 2. Dc5#/Sb5#/axb7# but BTM
Mir liegt nur die Broschüre mit den Aufgaben vor (ohne Autor- und Lösungsangabe), für deren Komposition 1946 die Mitglieder des "Nederlandse Bond van Probleemvrienden" verantwortlich waren.
Das Besondere an diesem Löserwettbewerb war, daß zu den Aufgaben auch solche mit mehreren Lösungen, unlösbare sowie mit retroanalytischen Inhalt gehörten.
(s.a. Henrik Juels Kommentar zu P0004647)
Henrik Juel: It is clearly Black to move
0... b5! 1.Dd4+,Dg1+ c5 2.Dxc5#
0... b5! 1.Da5 b4/c5/Lb7+ 2.Dc5/Sxb5/axb7#
Trial 1.Dd4+,Dg1+,Da5 (2021-10-29)
comment
Das Besondere an diesem Löserwettbewerb war, daß zu den Aufgaben auch solche mit mehreren Lösungen, unlösbare sowie mit retroanalytischen Inhalt gehörten.
(s.a. Henrik Juels Kommentar zu P0004647)
Henrik Juel: It is clearly Black to move
0... b5! 1.Dd4+,Dg1+ c5 2.Dxc5#
0... b5! 1.Da5 b4/c5/Lb7+ 2.Dc5/Sxb5/axb7#
Trial 1.Dd4+,Dg1+,Da5 (2021-10-29)
comment
Keywords: No legal last move for Black
Genre: 2#, Retro
FEN: b1K5/k1NP4/Ppp5/8/8/8/8/Q7
Input: Mario Richter, 2021-10-29
Last update: A.Buchanan, 2021-10-30 more...
Genre: 2#, Retro
FEN: b1K5/k1NP4/Ppp5/8/8/8/8/Q7
Input: Mario Richter, 2021-10-29
Last update: A.Buchanan, 2021-10-30 more...
1. Kc8,Kd8,Ke6,Ke7,Ke8
1. Ta4,Tb4,Tc4,Te4,Tf4
1. Tg1,Tg3,Tg4,Tg5+,Tg6,Txg7
1. La6,Lb1,Lb5,Lc2,Lc4,Le2+,Lf1,Lf5,Lg6+
1. Lc1,Ld2,Lf2,Lg1
1. a8=D,a8=T,a8=L,a8=S
1. axb8=D,axb8=T,axb8=L,axb8=S
1. h8=D,h8=T,h8=L,h8=S
1. f7
1. fxg7
1. hxg7
zuletzt kann nicht R: 1. ... Kg6-h5,Kg6xYh5 geschehen sein, weil nach dem forcierten R: 2. gxf6ep f7-f5 eine illegale Position des wK entstünde
92 Punkte
1. Ta4,Tb4,Tc4,Te4,Tf4
1. Tg1,Tg3,Tg4,Tg5+,Tg6,Txg7
1. La6,Lb1,Lb5,Lc2,Lc4,Le2+,Lf1,Lf5,Lg6+
1. Lc1,Ld2,Lf2,Lg1
1. a8=D,a8=T,a8=L,a8=S
1. axb8=D,axb8=T,axb8=L,axb8=S
1. h8=D,h8=T,h8=L,h8=S
1. f7
1. fxg7
1. hxg7
zuletzt kann nicht R: 1. ... Kg6-h5,Kg6xYh5 geschehen sein, weil nach dem forcierten R: 2. gxf6ep f7-f5 eine illegale Position des wK entstünde
92 Punkte
Henrik Juel: The retroplay seems to have been something like
R: 1... Kg6-h5 2.g5xf6ep+ f7-f5?
but this prevents Kd7 from getting home to e1, so Black has the move
Several solutions, even in 1.0 moves, e.g. 0... gxh6 1.Lg6,Le2# (2021-11-10)
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R: 1... Kg6-h5 2.g5xf6ep+ f7-f5?
but this prevents Kd7 from getting home to e1, so Black has the move
Several solutions, even in 1.0 moves, e.g. 0... gxh6 1.Lg6,Le2# (2021-11-10)
comment
Keywords: No legal last move for Black
Genre: 2#, Retro
FEN: 1b4N1/PppK2pP/5P1P/7k/3R3P/3BB3/6R1/8
Input: Mario Richter, 2021-11-10
Last update: Mario Richter, 2021-11-10 more...
Genre: 2#, Retro
FEN: 1b4N1/PppK2pP/5P1P/7k/3R3P/3BB3/6R1/8
Input: Mario Richter, 2021-11-10
Last update: Mario Richter, 2021-11-10 more...
Schwarz hat keien legalen letzten Zug, zieht also an:
1. ... Kxa5 2. Db6#
1. ... Kxa3 2. Db3#
1. ... Kxc5 2. Db6#
1. ... Kxc3 2. Dc4#
1. ... Kxa5 2. Db6#
1. ... Kxa3 2. Db3#
1. ... Kxc5 2. Db6#
1. ... Kxc3 2. Dc4#
Henrik Juel: HC+ Popeye 4.61
The human contribution is ensuring that it is Black to move, because he has no last move (2021-12-25)
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The human contribution is ensuring that it is Black to move, because he has no last move (2021-12-25)
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Keywords: No legal last move for Black
Genre: Retro
FEN: 8/8/4Q3/P1P5/1k6/N1N5/8/2KB4
Input: Mario Richter, 2021-12-25
Last update: Mario Richter, 2021-12-25 more...
Genre: Retro
FEN: 8/8/4Q3/P1P5/1k6/N1N5/8/2KB4
Input: Mario Richter, 2021-12-25
Last update: Mario Richter, 2021-12-25 more...
40 - P1402593
Andrew Buchanan
PDB Website 09/07/2022
after G.P.Latzel
(10+4)
h#1.75 (-:
hint rot13: pbqrk negvpyr svsgrra
Andrew Buchanan
PDB Website 09/07/2022
after G.P.Latzel
(10+4)
h#1.75 (-:
hint rot13: pbqrk negvpyr svsgrra
0. ... [-bPg5] 1. Lxb3 Ta8#
Clearly an unfinished move joke. By a usual convention for these things, a player might be halfway through a castling, an en passant, or a promotion. 1.75 is nearly 2.0, so Black would be the moving player.
Black is not in the middle of an e.p. or castling, so the only possibility is a promotion. Black has lifted up the pawn, to replace it with an officer on the 8th rank. However, White has apparently made 12 pawn captures, accounting for all missing Black units, so Black is not part way through promoting a pawn.
Therefore it's not Black in the middle of a move. By a joke application of Article 15, we say that it's *White* in the middle of a move instead. So 1.75 - 0.5 = 1.25 and it's h#1.25.
- White can't be part way through a promotion, because all White pawns are on the board.
- If White were in the middle of castling, then the pawn capture balance would be ok, but Black would have no prior move.
- If White were in the middle of en passant h5xg6, then bPg5 can help with capture balance, but still there is one capture short for the balance.
- So White is in the middle of en passant f5xg6. If we complete the joke move by removing bPg5, then the position is legal, with 12 White pawn captures and 13 missing Black units. A sound h#1 awaits.
Clearly an unfinished move joke. By a usual convention for these things, a player might be halfway through a castling, an en passant, or a promotion. 1.75 is nearly 2.0, so Black would be the moving player.
Black is not in the middle of an e.p. or castling, so the only possibility is a promotion. Black has lifted up the pawn, to replace it with an officer on the 8th rank. However, White has apparently made 12 pawn captures, accounting for all missing Black units, so Black is not part way through promoting a pawn.
Therefore it's not Black in the middle of a move. By a joke application of Article 15, we say that it's *White* in the middle of a move instead. So 1.75 - 0.5 = 1.25 and it's h#1.25.
- White can't be part way through a promotion, because all White pawns are on the board.
- If White were in the middle of castling, then the pawn capture balance would be ok, but Black would have no prior move.
- If White were in the middle of en passant h5xg6, then bPg5 can help with capture balance, but still there is one capture short for the balance.
- So White is in the middle of en passant f5xg6. If we complete the joke move by removing bPg5, then the position is legal, with 12 White pawn captures and 13 missing Black units. A sound h#1 awaits.
After P0004346
Henrik Juel: Not completion of 0-0-0, because Black has no last move
Completion of f5xg6ep is feasible, and then 1.Lxb3 Ta8#
Stipulation should be h#1.25, I think (2022-07-10)
A.Buchanan: Hi Henrik: it’s intended to be h#1.75 :-) Can black complete any Valladao move? And if not then what do we do? :-) (2022-07-10)
Henrik Juel: Thanks Andrew
So Black must complete a move, but his four men are stuck, and white pawns captured the remaining 12 black men; so there is nothing for Black to complete
Looks like a weird joke... (2022-07-10)
A.Buchanan: Sorry you don't like the Valladao joke Henrik. "1.75 minus 0.5 = 1.25" is a novel way to combine "unfinished move" with Article 15. I also like the fact that all the cases of pawn capture counting are exact, with no "retro dressing" unit purely to contribute to a balance.s (2022-07-10)
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Henrik Juel: Not completion of 0-0-0, because Black has no last move
Completion of f5xg6ep is feasible, and then 1.Lxb3 Ta8#
Stipulation should be h#1.25, I think (2022-07-10)
A.Buchanan: Hi Henrik: it’s intended to be h#1.75 :-) Can black complete any Valladao move? And if not then what do we do? :-) (2022-07-10)
Henrik Juel: Thanks Andrew
So Black must complete a move, but his four men are stuck, and white pawns captured the remaining 12 black men; so there is nothing for Black to complete
Looks like a weird joke... (2022-07-10)
A.Buchanan: Sorry you don't like the Valladao joke Henrik. "1.75 minus 0.5 = 1.25" is a novel way to combine "unfinished move" with Article 15. I also like the fact that all the cases of pawn capture counting are exact, with no "retro dressing" unit purely to contribute to a balance.s (2022-07-10)
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Keywords: Joke, Complete an unfinished move, En passant, Castling (wg Not!), Promotion (Not!), No legal last move for Black
Genre: h#, Retro
FEN: 7k/5p1P/5PPP/1P4p1/b7/1P6/6PP/R1K5
Input: A.Buchanan, 2022-07-10
Last update: A.Buchanan, 2023-12-08 more...
Genre: h#, Retro
FEN: 7k/5p1P/5PPP/1P4p1/b7/1P6/6PP/R1K5
Input: A.Buchanan, 2022-07-10
Last update: A.Buchanan, 2023-12-08 more...
1. S4b6? axb6 2. c4 b5 3. cxb5#
Cook: Schwarz hat keinen letzten Zug, und mit Schwarz am Zug gibt es kein 3#
Cook: Schwarz hat keinen letzten Zug, und mit Schwarz am Zug gibt es kein 3#
SCHRECKE: Schwarz hat keinen letzten Zug! (2022-10-10)
Henrik Juel: So it is Black to move, and he is stalemated (2022-10-10)
Rainer Staudte: Eine Korrektur wäre einfach, z. B. durch Verschiebung um eine Reihe nach unten. Aber wäre das Autorabsicht? (2022-10-10)
A.Buchanan: According to the Codex, mere illegality does not cook a problem or even make it unsound. But in the grunting world of PDB data fields, we only have "cooked" to express all degrees of structural displeasure. If I was fixing the problem, I would stick wLa8 on h1 instead. For then we have the tiny satisfaction of knowing that Black's last move was R: 1. Kb7xTa6.
This author is unknown to WinChloe, and only has one other problem in YAC. (I have added it here.) Amazingly, WinChloe has not heard of the LA Times either! (2022-10-11)
A.Buchanan: It's a rare name: https://www.findagrave.com/memorial/62652231/norman-l-guinasso 1920-1978 might fit as a California memorial. There's then a Norman L. Guinasso Jr, whose age might fit as a son, who retired as a Professor of Oceanography in 2015 (2022-10-11)
A.Buchanan: Or replace wLa8 with wBc6. (sBb7 also works, but is still illegal!) (2022-10-11)
more ...
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Henrik Juel: So it is Black to move, and he is stalemated (2022-10-10)
Rainer Staudte: Eine Korrektur wäre einfach, z. B. durch Verschiebung um eine Reihe nach unten. Aber wäre das Autorabsicht? (2022-10-10)
A.Buchanan: According to the Codex, mere illegality does not cook a problem or even make it unsound. But in the grunting world of PDB data fields, we only have "cooked" to express all degrees of structural displeasure. If I was fixing the problem, I would stick wLa8 on h1 instead. For then we have the tiny satisfaction of knowing that Black's last move was R: 1. Kb7xTa6.
This author is unknown to WinChloe, and only has one other problem in YAC. (I have added it here.) Amazingly, WinChloe has not heard of the LA Times either! (2022-10-11)
A.Buchanan: It's a rare name: https://www.findagrave.com/memorial/62652231/norman-l-guinasso 1920-1978 might fit as a California memorial. There's then a Norman L. Guinasso Jr, whose age might fit as a son, who retired as a Professor of Oceanography in 2015 (2022-10-11)
A.Buchanan: Or replace wLa8 with wBc6. (sBb7 also works, but is still illegal!) (2022-10-11)
more ...
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Keywords: Minimal, Miniature, No legal last move for Black (unintended), Superseded by (P1413729)
Genre: 3#
FEN: B1N5/p7/k7/8/1KN5/2P5/8/8
Input: Rainer Staudte, 2022-10-10
Last update: A.Buchanan, 2023-11-28 more...
Genre: 3#
FEN: B1N5/p7/k7/8/1KN5/2P5/8/8
Input: Rainer Staudte, 2022-10-10
Last update: A.Buchanan, 2023-11-28 more...
42 - P1406456
Werner Keym
OP016 The Hopper Magazine I02 25/06/2022
corrects Keym Schach-Echo 1967 / Die Schwalbe 2007
(15+5)
#1 AP
b) - Lh8
Werner Keym
OP016 The Hopper Magazine I02 25/06/2022
corrects Keym Schach-Echo 1967 / Die Schwalbe 2007
(15+5)
#1 AP
b) - Lh8
a) 1. ... bxa3ep 2. Dc3#!
(2. 0-0#?)
1. 0-0#? (rights lost)
b) 1. ... bxa3ep 2. 0-0#!
(2. Dc3#?)
1. 0-0#? (Black to move if rights remain)
a) White & Black have made 11+1 pawn captures, accounting for all missing material. bPa captured to b file (must be bPb2 now, to get behind wPb) so bPh promoted on h1, to supply balance. Therefore White cannot castle. Black has no last move, so by Article 15 we can conclude that Black has the move. The only way to give Black a move is R: 1. a2-a4 a3xNb2. Therefore ep is legal, and indeed that is Black's only move. After 0... bxa3ep, White mates with 1.Dc3#! not 1.0-0#? since castling is illegal. AP is not used in this twin, but is available as a condition in order to make twins as similar as possible, and show that the difference in behaviour comes just from wBh8, not from conditions.
b) Now there is a second white unit missing, which gives more retro possibilities. One case is that bPh might have captured to g-file, to promote (or to be captured if original bPg promoted), so White may retain castling rights, but in this case it must be Black to move. So 1.0-0#? doesn't work as a solution. Alternatively, if White has lost castling rights, Black might have just played c2xNb1=R, or c3xNb2 or a/c5xb4. So in this scenario we cannot prove unconditionally that it's really Black to play.
However, under adversarial AP, White makes a double claim: firstly that it is Black to move (AP Type Keym), and secondly that ep is legal (AP Type Petrovic). If White retains castling rights, then both of these items are correct, and the ep must be bxa3 not bxc3. So White mates with 1.0-0#! for AP justification, not 1.Dc3#?.
(2. 0-0#?)
1. 0-0#? (rights lost)
b) 1. ... bxa3ep 2. 0-0#!
(2. Dc3#?)
1. 0-0#? (Black to move if rights remain)
a) White & Black have made 11+1 pawn captures, accounting for all missing material. bPa captured to b file (must be bPb2 now, to get behind wPb) so bPh promoted on h1, to supply balance. Therefore White cannot castle. Black has no last move, so by Article 15 we can conclude that Black has the move. The only way to give Black a move is R: 1. a2-a4 a3xNb2. Therefore ep is legal, and indeed that is Black's only move. After 0... bxa3ep, White mates with 1.Dc3#! not 1.0-0#? since castling is illegal. AP is not used in this twin, but is available as a condition in order to make twins as similar as possible, and show that the difference in behaviour comes just from wBh8, not from conditions.
b) Now there is a second white unit missing, which gives more retro possibilities. One case is that bPh might have captured to g-file, to promote (or to be captured if original bPg promoted), so White may retain castling rights, but in this case it must be Black to move. So 1.0-0#? doesn't work as a solution. Alternatively, if White has lost castling rights, Black might have just played c2xNb1=R, or c3xNb2 or a/c5xb4. So in this scenario we cannot prove unconditionally that it's really Black to play.
However, under adversarial AP, White makes a double claim: firstly that it is Black to move (AP Type Keym), and secondly that ep is legal (AP Type Petrovic). If White retains castling rights, then both of these items are correct, and the ep must be bxa3 not bxc3. So White mates with 1.0-0#! for AP justification, not 1.Dc3#?.
corrects P1108454
Henrik Juel: here is my guess
a) 0... bxa3ep 1.Dc3#
b) 1.0-0# (2022-12-05)
A.Buchanan: Comments on the proposed solution welcome (2023-08-21)
more ...
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Henrik Juel: here is my guess
a) 0... bxa3ep 1.Dc3#
b) 1.0-0# (2022-12-05)
A.Buchanan: Comments on the proposed solution welcome (2023-08-21)
more ...
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Keywords: a posteriori (AP) (Type Keym), a posteriori (AP) (type Petrovic), No legal last move for Black, En passant as key, Castling, Cant Castler (wk)
Genre: Retro
FEN: 7B/2P5/3P4/1P2Q3/PpP1N3/1P1P4/1p1RBP2/brk1K2R
Input: A.Buchanan, 2022-12-05
Last update: A.Buchanan, 2023-08-22 more...
Genre: Retro
FEN: 7B/2P5/3P4/1P2Q3/PpP1N3/1P1P4/1p1RBP2/brk1K2R
Input: A.Buchanan, 2022-12-05
Last update: A.Buchanan, 2023-08-22 more...
Show statistic for complete result. Show search result faster by using ids.
https://pdb.dieschwalbe.de/search.jsp?expression=COMMENTDATE%3E%3D20200919+AND+NOT+K%3D%27Hilfsr%C3%BCckz%C3%BCger%27+AND+K%3D%27Kein+letzter+Zug+von+Schwarz%27+AND+NOT+CPLUS+
The problems of this query have been registered by the following contributors:
Gerd Wilts (12)Frank Müller (5)
Zuncke/Bruder (13)
Felber, Volker (5)
Rainer Staudte (2)
Mario Richter (3)
A.Buchanan (2)
Brassaud: La solution proposée 1/Tg6# est possible
Mais il y a aussi le rétro jeu -1) Fa2-b1, Rg5g6 -2) Ta4-a5+, Rf4-f5 etc … et avec le trait aux noirs : 1) Fxe6 # est possible (2017-08-30)
A.Buchanan: @Brassaud: yes I agree. There is no reason why White should not have moved last. So both players can mate, but part (b) implies that the intended solution in (a) is 1 player. If the published stipulation for (a) was maybe just "#1", which by default is white to move, then there is a unique solution.
For (b) I am wondering about +sBg6, which would also stop the en passant trick, both by blocking sK from retreating there and also by locking sL in an impossible cage with sBf7. (2017-08-31)
Henrik Juel: Adding a black pawn on g6 of course prevents a black last move by Kf6, but it allows f7xg6 as last move; Lg8 is not locked, because Ph7 is white (2017-08-31)
A.Buchanan: Yes (2017-08-31)
Anton Baumann: vergl. P0004915 (Hans Gruber, Schach 1979) (2023-01-03)
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