Die Schwalbe

6 problem(s) found in 3154 milliseconds (displaying 6 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND K='Kein letzter Zug von Schwarz' AND S='The Problemist'] [download as LaTeX]

1 - P0004141
Karl Fabel
1071 The Problemist Fairy Chess Supplement 12/1933
P0004141
(8+1) C+
#1
1. ... ... 2. 0-0?
1. ... Kxg2 2. e5#
1. ... Kxf4 2. Df6#
play all play one stop play next play all
more ...
comment
Keywords: Castling (wk), No legal last move for Black, Castling in the forward play, Fabel-Opus (82)
Genre: Retro
Computer test: HC+ Popeye 4.61 with analysis
FEN: 8/8/2Q5/8/4PBN1/3P1k2/6R1/4K2R
Reprints: (IV) Problem 17-18 08/1952
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-05-08 more...
2 - P1394484
Andrew Buchanan
A The Problemist Supplement 174, p. 182, 09/2021
Motto="U for Uplex"
P1394484
(4+3) C+
h#2.5 Duplex
w) 1. a2 a6 2. Ka3 Ta5#
s) 1. b2 Td5 2. b1=D Td3 3. Db2#
play all play one stop play next play all
BTM in both twins.
Numerous retro tries but none distinct in the retro twin w).
AB: Duplex means that there is a twin where B/W roles are reversed. If we can deduce who must have the move then, e.g. in a helpmate, one of those twins will lose the first single move. So here it's Black to move, and the twins are BWBWB# (Black checkmating White) and BWBW# (White checkmating Black). "Uplex" is not a Fairy Condition - it's just an identifier of an obvious idea for retro-active compositions, which curiously hasn't been explored before, as far as Geoff Foster and I can see.
Henrik Juel: Thanks for the explanation, Andrew
Here Black has no last move, so he has the move
1.b2 Td5 2.b1=D Td3 3.Db2#
1.a2 a6 2.Ka3 Ta5#
C+ Popeye 4.61 (using 'sti h#2.5 opt hal' and 'sti h#2') (2021-10-09)
comment
Keywords: No legal last move for Black, Miniature, Character problem (U)
Genre: h#, Retro
Computer test: HC+ Last move analysis + Popeye 4.61
FEN: 8/8/8/P1R5/k1P5/ppK5/8/8
Input: A.Buchanan, 2021-10-08
Last update: A.Buchanan, 2023-12-06 more...
3 - P1394485
Andrew Buchanan
B The Problemist Supplement 174, p. 182, 09/2021
P1394485
(16+15) C+
h#2.5 Duplex
w) 1. Se6 Sd5 2. Sd8 Sxc7#
s) 1. Sxd1 Kxd1 2. Se4 Se1 3. Sxf2#
play all play one stop play next play all
BTM in both twins.
Numerous retro tries but none distinct in the retro twin w).
Henrik Juel: The total number of white moves in any proof game is even, and the number of black move is odd
The different parities imply that White made the last move, so it is Black to move
1.Sxd1 Kxd1 2.Se4 Se1 3.Sxf#
1.Se6 Sd5 2.Sd8 Sxc7#
C+ Popeye 4.61 (2021-10-09)
comment
Keywords: No legal last move for Black, Parity Argument
Genre: h#, Retro
Computer test: HC+ Parity counting + Popeye 4.61
FEN: r1b1kb1r/pppppppp/8/2n5/8/2nNN3/PPPPPPPP/R1BQKB1R
Input: A.Buchanan, 2021-10-08
Last update: A.Buchanan, 2023-12-06 more...
4 - P1394486
Geoff Foster
Andrew Buchanan

C The Problemist Supplement 174, p. 182, 09/2021
P1394486
(16+16) C+
h#2.5 Duplex
w) 1. e5 Sxg7+ 2. Ke7 Sd5#
s) 1. g6 d3 2. Lh6 Kd2 3. Sf3#
play all play one stop play next play all
BTM in both twins
Numerous retro tries but none distinct in the retro twin w).
Henrik Juel: A parity argument shows that it is Black to move
1.g6 d3 2.Lh6 Kd2 3.Sf3#
1.e5 Sxg7# 2.Ke7 Sd5#
C+ Popeye 4.61 (2021-10-09)
comment
Keywords: No legal last move for Black, Parity Argument, Capture-free
Genre: h#, Retro
Computer test: HC+ Parity counting + Popeye 4.61
FEN: r1bqkb1r/pppppppp/3n4/6nN/8/2N5/PPPPPPPP/R1BQKB1R
Input: A.Buchanan, 2021-10-08
Last update: A.Buchanan, 2023-12-06 more...
5 - P1394487
Andrew Buchanan
D The Problemist Supplement 174, p. 182, 09/2021
P1394487
(15+15) C+
h#3 Duplex
w) 1. Sb4 Sg5 2. Sc6 Se6 3. Sd8 Sxc7#
s) 1. Sb4 Sf3 2. Sd3 Se1 3. Sxf2#
play all play one stop play next play all
BTM in both twins
Numerous retro tries but none distinct in the retro twin s).
Henrik Juel: A parity argument shows that it White to move
Popeye 4.61 found lots of solutions with 'sti h#3 opt hal' and none with 'sti h#2.5' (2021-10-09)
Henrik Juel: Here are the correct details of the parity argument
White has made an odd number of moves (K odd, TT odd, SS even, P odd)
Black has mad an even number of moves (K even, TT even, SS even, PP even)
So White made last move, and it is Black to move
1.Sb4 Sg5 2.Sc6 Se6 3.Sd8 Sxc7# (White mates, 'h#3')
1.Sb4 Sf3 2.Sd3 Se1 3.Sxf2# (Black mates, 'h#2.5 opt hal')
C+ Popeye 4.61 (2021-10-09)
comment
Keywords: No legal last move for Black, Parity Argument
Genre: h#, Retro
Computer test: HC+ Parity counting + Popeye 4.61
FEN: 2b1kbrn/rppppppN/p6p/8/8/P7/nPPPPPPP/1RBK1BNR
Input: A.Buchanan, 2021-10-08
Last update: A.Buchanan, 2023-12-06 more...
6 - P1394488
Geoff Foster
E The Problemist Supplement 174, p. 182, 09/1021
P1394488
(3+3) C+
h#4 Duplex
w) 1. [...] Kf3! Sc5 2. Sb4 Kd4 3. Kf4! Sc4 4. Se2#
s) 1. Ke5 Kc5! 2. Se4+ Kb5 3. Kd5! Sf5 4. Se5 Sc7#
play all play one stop play next play all
BTM in both twins as Black in check. This is deemed insufficient to make a problem "retro".
Henrik Juel: Ke4 stands in check, so it is Black to move
1.Ke5 Kc5 2.Se4+ Kb5 3.Kd5 Sf5 4.Se5 Sc7#
1.Kf3 Sc5 2.Sb4 Kd4 3.Kf4 Sc4 4.Se2#
C+ Popeye 4.61
Crude analysis, but nice play (2021-10-09)
comment
Keywords: No legal last move for Black (check), Aristocrat, Miniature, Tempo Move (K,k)
Genre: h#
Computer test: C+ Popeye 4.61
FEN: 8/8/N1nN4/8/2K1k3/6n1/8/8
Input: A.Buchanan, 2021-10-08
Last update: A.Buchanan, 2023-12-07 more...
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The problems of this query have been registered by the following contributors:

Gerd Wilts (1)
A.Buchanan (5)