15 problem(s) found in 6217 milliseconds (displaying 15 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND K='Mustermatt' AND K='Kindergarten-Problem'] [download as LaTeX]
1) 1. exd3ep b8=D 2. Kd4 Df4#
2) 1. exd3ep a8=S 2. d4 Sxb6#
Cook: e.p. not justified as R: 0.e3xd4 possible
2) 1. exd3ep a8=S 2. d4 Sxb6#
Cook: e.p. not justified as R: 0.e3xd4 possible
Keywords: En passant as key, Kindergarten Problem, Model mate (2)
Genre: h#, Retro
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/PP6/Kpp1p3/2pp4/1pkPp3/2p5/P7/8
Input: Michal Dragoun, 1998-04-09
Last update: A.Buchanan, 2023-12-03 more...
Genre: h#, Retro
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/PP6/Kpp1p3/2pp4/1pkPp3/2p5/P7/8
Input: Michal Dragoun, 1998-04-09
Last update: A.Buchanan, 2023-12-03 more...
1. Kb8 Ka4 2. Kc8 Ka3 3. Kd8 Ka4 4. Ke8 Ka3 5. Kf8 Ka4 6. Kg7 Ka3 7. Kf6 Ka4 8. Kg5 Ka3 9. Kf4 Ka4 10. Kxe4 Ka3 11. Kd3 Ka4 12. e4 Ka3 13. e3 Ka4 14. e2 Ka3 15. e1=D Ka4 16. Dxe6 Ka3 17. Dd7 cxd7 18. Kc2 d8=D 19. Kb1 Dd1#
Keywords: Promotion (Dd), Entblockung, Ceriani-Frolkin Theme (d), Model mate, Königswanderung, Switchback (K), Kindergarten Problem, Pronkin Theme (D)
Genre: h#
Computer test: Gustav 4.1d
FEN: 8/k1p1p3/1pP1P2p/1P2p2P/1Pp1P3/KpP5/1P6/8
Input: Hans-Jürgen Schäfer, 1999-01-01
Last update: A.Buchanan, 2021-04-06 more...
Genre: h#
Computer test: Gustav 4.1d
FEN: 8/k1p1p3/1pP1P2p/1P2p2P/1Pp1P3/KpP5/1P6/8
Input: Hans-Jürgen Schäfer, 1999-01-01
Last update: A.Buchanan, 2021-04-06 more...
1. f8=D+ Kxf8 2. h8=D+ Kf7 3. d8=S#
1. ... Kxh7 2. d8=D g5 3. Dd3#
1. ... Kxh7 2. d8=D g5 3. Dd3#
Keywords: Miniature Collection (0052844), Promotion key (D), Checking key, under-promotion in mating move (S), Flight giving sacrifice key (D), Model mate, Miniature, Kindergarten Problem
Genre: 3#
Computer test: Juel: Popeye 4.61
FEN: 8/3PpPkP/6p1/8/8/4K3/8/8
Input: Felber, Volker, 2010-09-12
Last update: Dieter Berlin, 2023-02-28 more...
Genre: 3#
Computer test: Juel: Popeye 4.61
FEN: 8/3PpPkP/6p1/8/8/4K3/8/8
Input: Felber, Volker, 2010-09-12
Last update: Dieter Berlin, 2023-02-28 more...
1. ... Kc1! 2. Kxb4 Kc2 3. Ka5 Kb3 4. Ka6! Kxa3 5. Ka5! Kb2 6. Kb4 a4 7. Kc4! a5 8. Kb4! a6 9. Ka5 a7 10. Ka6! a8=D#
Yuri Bilokin: you can see *) 1... ... 2.Kxb4 Kc2 3.Ka5 Kb3 4.Ka6 Kxa3 5.Ka5 Kb2 6.Kb4 a4 7.Kc4 a5 8.Kb4 a6 9.Ka5 a7 10.Ka6 a8=Q# (MM) (2022-07-03)
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Keywords: Excelsior white, Model mate, Switchback (k), Tempo Move, Promotion (D), Kindergarten Problem, Promotion in the mating move
Genre: h#
FEN: 8/8/2p5/1pP1p3/1Pk1P3/p3P3/P7/1K6
Input: Gunter Jordan, 2012-03-26
Last update: Gunter Jordan, 2022-07-02 more...
Genre: h#
FEN: 8/8/2p5/1pP1p3/1Pk1P3/p3P3/P7/1K6
Input: Gunter Jordan, 2012-03-26
Last update: Gunter Jordan, 2022-07-02 more...
1. b8=D+! Kd7 2. e8=T c5 3. Dd8+ Kc6 4. a8=D+ Kb5 5. Ddb8+ Kc4 6. Te1 Kd4 7. h8=L+ Kc4 8. Kd1 Kd3 9. Df4 c4 10. Lb2 c3 11. Lc1 c2#
Keywords: Kindergarten Problem, konsekutive Umwandlungen 4 (DTDL), Pawn mate, under-promotion, Minimal (s), Miniature, Selfblock, Model mate, Checking key, Promotion key, Flight taking
Genre: s#
FEN: 8/PPk1P2P/2p5/8/8/8/2K5/8
Reprints: 14) idee & form 143, p. 4843, 07/2019
Input: Frank Müller, 2015-04-11
Last update: Rainer Staudte, 2023-01-19 more...
Genre: s#
FEN: 8/PPk1P2P/2p5/8/8/8/2K5/8
Reprints: 14) idee & form 143, p. 4843, 07/2019
Input: Frank Müller, 2015-04-11
Last update: Rainer Staudte, 2023-01-19 more...
1. Ke2 Kg1 2. Kd3 Kf2 3. Kc4 Ke3 4. Kxd5 Kf4 5. Kc6 Kxg4 6. Kd7 Kh4 7. Ke8 g4 8. Kf8 g5 9. Kg8 g4 10. Kh7 g6 11. Kh6 g5#
[MD 1317]
Verführung:
Schwarz versucht, mittels 1.Kf2?!? 2.Kxg3 usw. zum Ziele zu kommen und durch eine weiße Dameumwandlung das Matt in der geforderten Zügezahl zu erzwingen. Dieser Plan scheitert allerdings daran, dass Weiß ziehen muss und dieses Unterfangen mittels 1.Kh2! unterbinden muss.
Drei weiße Figuren müssen das Feld g4 im Laufe der Lösung betreten. Der schwarze König betritt im Laufe der Lösung drei Ränder des Schachbrettes.
Wahrscheinlich ist diese Aufgabe auch für den Löser nicht allzu einfach zu lösen, weil das Mattbild nicht ersichtlich sein dürfte. Es mutet eher unwahrscheinlich an, dass dabei sogar die Zugreihenfolge absolut eindeutig ist. Durch die zusätzliche starke Verführung wird die Aufgabe inhaltlich nochmals aufgewertet. Zumal jeder versucht, mittels Umwandlung in eine weiße Dame ans Ziel zu gelangen, vergebens!
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-28)
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Verführung:
Schwarz versucht, mittels 1.Kf2?!? 2.Kxg3 usw. zum Ziele zu kommen und durch eine weiße Dameumwandlung das Matt in der geforderten Zügezahl zu erzwingen. Dieser Plan scheitert allerdings daran, dass Weiß ziehen muss und dieses Unterfangen mittels 1.Kh2! unterbinden muss.
Drei weiße Figuren müssen das Feld g4 im Laufe der Lösung betreten. Der schwarze König betritt im Laufe der Lösung drei Ränder des Schachbrettes.
Wahrscheinlich ist diese Aufgabe auch für den Löser nicht allzu einfach zu lösen, weil das Mattbild nicht ersichtlich sein dürfte. Es mutet eher unwahrscheinlich an, dass dabei sogar die Zugreihenfolge absolut eindeutig ist. Durch die zusätzliche starke Verführung wird die Aufgabe inhaltlich nochmals aufgewertet. Zumal jeder versucht, mittels Umwandlung in eine weiße Dame ans Ziel zu gelangen, vergebens!
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-28)
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Keywords: Model mate, Kindergarten Problem
Genre: h#
FEN: 8/5p2/3p1P2/3P1P2/6p1/6P1/6P1/5k1K
Input: Marcin Banaszek, 2018-07-29
Last update: Marcin Banaszek, 2020-10-29 more...
Genre: h#
FEN: 8/5p2/3p1P2/3P1P2/6p1/6P1/6P1/5k1K
Input: Marcin Banaszek, 2018-07-29
Last update: Marcin Banaszek, 2020-10-29 more...
1) 1. ... e4 2. c3 e5 3. c2 e6 4. c1=D,T exd7 5. Dc8,Tc8 dxc8=D 6. a2 Dc1#
2) 1. ... g4 2. Kb2 g5 3. Kc3 g6 4. Kd4 g7 5. Kxd5 g8=D 6. Kc6 Dxc4#
Cook: Umwandlungsdual (in 1)
2) 1. ... g4 2. Kb2 g5 3. Kc3 g6 4. Kd4 g7 5. Kxd5 g8=D 6. Kc6 Dxc4#
Cook: Umwandlungsdual (in 1)
Olaf Jenkner: Warum steht hier C+ ? Die Aufgabe ist doch eindeutig inkorrekt. (2020-04-13)
Gunter Jordan: Hm. Berechtigter Einwand. Das C+ stand in der Originalquelle am Diagramm. (2021-01-26)
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Gunter Jordan: Hm. Berechtigter Einwand. Das C+ stand in der Originalquelle am Diagramm. (2021-01-26)
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Keywords: Corner mate (in 1), Excelsior white, Kindergarten Problem, Model mate, Phoenix (Anti-), Promotions to queens
Genre: h#
Computer test: Gustav 4.0 i
FEN: 8/K2p4/3p4/3P4/2p5/p7/4P1P1/k7
Input: Gunter Jordan, 2020-04-07
Last update: Alfred Pfeiffer, 2020-04-07 more...
Genre: h#
Computer test: Gustav 4.0 i
FEN: 8/K2p4/3p4/3P4/2p5/p7/4P1P1/k7
Input: Gunter Jordan, 2020-04-07
Last update: Alfred Pfeiffer, 2020-04-07 more...
1. Kc4 Ka2 2. Kxd5 Kb3 3. Kxe6 Kc4 4. Kf5 Kd5 5. Kf6 Kxe4 6. Ke6 Kxe3 7. Kd5 Kd3 8. e6 e4#
Die Aufgabe wurde im Reprint (Schach 06/2020) in Notation abgedruckt. Die Originalquelle ist nicht bekannt.
Die Aufgabe wurde im Reprint (Schach 06/2020) in Notation abgedruckt. Die Originalquelle ist nicht bekannt.
Silvio Baier: Originalquelle ist 15201v Schach 5/2003, S. 80. Davor wurde eine illegale Stellung als 15201 in Schach 3/2003 veröffentlicht. (2020-11-09)
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Keywords: Pawn mate, Kindergarten Problem, Model mate, Switchback (k), Round Trip (k-3), Selfblock, Tempo Loss, Umnov (verzögert)
Genre: h#
Computer test: Gustav 4.0 i
FEN: 8/4p1p1/1p1pP1P1/1P1Pp3/1P2p3/1k2p3/1P2P3/K7
Reprints: Schach , p. 80, 06/2020
Input: Gunter Jordan, 2020-05-23
Last update: Gunter Jordan, 2020-05-23 more...
Genre: h#
Computer test: Gustav 4.0 i
FEN: 8/4p1p1/1p1pP1P1/1P1Pp3/1P2p3/1k2p3/1P2P3/K7
Reprints: Schach , p. 80, 06/2020
Input: Gunter Jordan, 2020-05-23
Last update: Gunter Jordan, 2020-05-23 more...
9 - P1389667
Mykola Kolesnik
8760 Seven Chess Notes 174 07/2020
(2+5) C+
h#6
Zero
a) wBe2->g2
b) sBe4->f3
Mykola Kolesnik
8760 Seven Chess Notes 174 07/2020
(2+5) C+
h#6
Zero
a) wBe2->g2
b) sBe4->f3
a) 1. c1=L g4 2. Lh6 g5 3. e3 gxh6 4. e2 h7 5. e1=L h8=D 6. Lb4 Da1#
b) 1. f2 e4 2. f1=L e5 3. Lb5 e6 4. Ld7 exd7 5. c1=L d8=D 6. Lb2 Da5#
b) 1. f2 e4 2. f1=L e5 3. Lb5 e6 4. Ld7 exd7 5. c1=L d8=D 6. Lb2 Da5#
Keywords: Antiphönix, Echo, corner to corner (D in a), Kindergarten Problem, konsekutive Umwandlungen 3 (llD), Miniature, Minimal (B), Model mate, Selfblock, Promotions to queens, Promotions to bishops, under-promotion key (in a)
Genre: h#
Computer test: SCHRECKE:: C+, Gustav 4.1d, Brute Force (2021-05-16)
FEN: 8/4p3/8/8/4p3/kp6/2p1P3/7K
Input: Gunter Jordan, 2021-05-16
Last update: Alfred Pfeiffer, 2021-08-18 more...
Genre: h#
Computer test: SCHRECKE:: C+, Gustav 4.1d, Brute Force (2021-05-16)
FEN: 8/4p3/8/8/4p3/kp6/2p1P3/7K
Input: Gunter Jordan, 2021-05-16
Last update: Alfred Pfeiffer, 2021-08-18 more...
10 - P1394769
Oleg Paradzynskyi
G44/124 feenschach 245, p. 149, 05-06/2021
(2+2) C+
h#6
Beamtenschach
Oleg Paradzynskyi
G44/124 feenschach 245, p. 149, 05-06/2021
(2+2) C+
h#6
Beamtenschach
1. d2 b8=T 2. d1=D Tb1 3. Dg1+ Tb7+ 4. Ka6 Ta7+ 5. Ka5 Kd4 6. Ka4 Kc4#
Gunter Jordan: Ein sehr schöner Wenigsteiner, der es verdient hätte, im Urdruckteil von feenschach zu erscheinen, statt in der Grube versenkt zu werden. (2021-10-21)
Henrik Juel: In Functionary chess all men are functionaries
A functionary has no powers (except the ability to observe), unless it is observed by an enemy man
In this problem, initially the pawns are observed by the kings, so they may move and promote
2... Tb1 is possible, because Tb8 is observed Ka7, and then Tb1 observes Dd1, who checks on g1
3... Tb7+ is possible, because Tb1 is observed by Dg1, and this white move releases the check from Dg1, because Dg1 is no longer observed, and it checks, because Tb7 is observed by Ka7
5.Ka5 escapes from check, because Ta7 is no longer observed
6... Kc4# is possible, because Kd4 is observed by Dg1, and this white move delivers check from Ta7, because now Ta7 is observed by Dg1
7.Ka5,Ka3? are illegal, because the black king is still in check from the observed Ta7
Kc4 has no powers before Black attempts the illegal moves 7.Kb3,Kb4,Kb5? which observe Kc4
Popeye 4.61 quickly tests this h#6, because there are relatively few moves to consider (2021-10-22)
Henrik Juel: Andrew, your english definition might be clearer, if you replace 'threaten' by 'observe' (2021-10-22)
A.Buchanan: OK will do - I will add that to observe is to attack a friendly piece. Attack is a term from the laws (2021-10-22)
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Henrik Juel: In Functionary chess all men are functionaries
A functionary has no powers (except the ability to observe), unless it is observed by an enemy man
In this problem, initially the pawns are observed by the kings, so they may move and promote
2... Tb1 is possible, because Tb8 is observed Ka7, and then Tb1 observes Dd1, who checks on g1
3... Tb7+ is possible, because Tb1 is observed by Dg1, and this white move releases the check from Dg1, because Dg1 is no longer observed, and it checks, because Tb7 is observed by Ka7
5.Ka5 escapes from check, because Ta7 is no longer observed
6... Kc4# is possible, because Kd4 is observed by Dg1, and this white move delivers check from Ta7, because now Ta7 is observed by Dg1
7.Ka5,Ka3? are illegal, because the black king is still in check from the observed Ta7
Kc4 has no powers before Black attempts the illegal moves 7.Kb3,Kb4,Kb5? which observe Kc4
Popeye 4.61 quickly tests this h#6, because there are relatively few moves to consider (2021-10-22)
Henrik Juel: Andrew, your english definition might be clearer, if you replace 'threaten' by 'observe' (2021-10-22)
A.Buchanan: OK will do - I will add that to observe is to attack a friendly piece. Attack is a term from the laws (2021-10-22)
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Keywords: Functionary Chess, Kindergarten Problem, konsekutive Umwandlungen 2 (Td), Cross check, Minimal (B,b), Model mate, Rückkehr nach Umwandlung, Round Trip (B-3), Promotion (d), under-promotion (T)
Genre: Fairies
FEN: 8/kP6/8/8/8/3pK3/8/8
Input: Gunter Jordan, 2021-10-21
Last update: Gunter Jordan, 2021-10-21 more...
Genre: Fairies
FEN: 8/kP6/8/8/8/3pK3/8/8
Input: Gunter Jordan, 2021-10-21
Last update: Gunter Jordan, 2021-10-21 more...
1. g1=L b4 2. Lc5 bxc5 3. a2 c6 4. a1=T c7 5. Ta7 c8=D#
Keywords: Corner mate, Kindergarten Problem, Model mate, Promotion (ltD x3), Minimal (B), Ceriani-Frolkin Theme (l)
Genre: h#
FEN: k7/8/8/8/8/p5K1/1P4p1/8
Input: Gunter Jordan, 2021-11-07
Last update: James Malcom, 2021-11-07 more...
Genre: h#
FEN: k7/8/8/8/8/p5K1/1P4p1/8
Input: Gunter Jordan, 2021-11-07
Last update: James Malcom, 2021-11-07 more...
1) 1. Kb2 Kd7 2. e5 fxe5 3. Kc3 e6 4. Kd4 e7 5. Ke5 e8=D 6. Kf6 De7#
2) 1. g5 fxg5 2. f4 g6 3. f3 g7 4. f2 g8=D 5. f1=T Dg3 6. Tb1 Da3#
2) 1. g5 fxg5 2. f4 g6 3. f3 g7 4. f2 g8=D 5. f1=T Dg3 6. Tb1 Da3#
Keywords: Kindergarten Problem, Miniature, Minimal (B), Promotion (D), under-promotion (t in 2), konsekutive Umwandlungen 2 (Dt in 2), Selfblock (in 2), Corner mate (in 2), Model mate (in 2), Entblockung
Genre: h#
FEN: 8/4p3/4K1p1/5p2/5P2/8/8/k7
Input: Gunter Jordan, 2023-01-28
Last update: Gerd Wilts, 2023-01-29 more...
Genre: h#
FEN: 8/4p3/4K1p1/5p2/5P2/8/8/k7
Input: Gunter Jordan, 2023-01-28
Last update: Gerd Wilts, 2023-01-29 more...
1. Kb5 Kg4 2. Kc4 Kh5 3. Kd3 Kg4 4. Ke2 Kh5 5. Kf1 Kg4 6. Kg1 Kh5 7. Kh2 Kg4 8. f3+ Kh5 9. g4+ fxg4 10. g3 gxf3 11. Kh3 f2 12. g4#
9. ... Kh4 10. g3#
9. ... Kh4 10. g3#
Keywords: Kindergarten Problem, Model mate
Genre: n#
FEN: 8/8/K5p1/5pPk/5P2/6P1/5PP1/8
Input: Rainer Staudte, 2023-06-14
Last update: Felber, Volker, 2023-09-20 more...
Genre: n#
FEN: 8/8/K5p1/5pPk/5P2/6P1/5PP1/8
Input: Rainer Staudte, 2023-06-14
Last update: Felber, Volker, 2023-09-20 more...
1. g4! g5 2. h4 gxh4 3. g5+ Kh5 4. h3 h6 5. g6 fxg6 6. e4 g5 7. Kf5 g4 8. hxg4#
Keywords: Pawn mate, Flight taking, Illegal position, Kindergarten Problem, Model mate
Genre: n#
FEN: 8/5p1p/5Kpk/8/8/4P2P/6PP/8
Input: Gunter Jordan, 2023-07-08
Last update: Gunter Jordan, 2023-07-08 more...
Genre: n#
FEN: 8/5p1p/5Kpk/8/8/4P2P/6PP/8
Input: Gunter Jordan, 2023-07-08
Last update: Gunter Jordan, 2023-07-08 more...
1. a5 2. a4 3. a3 4. a2 5. a1=T 6. Ta6 7. Th6 8. b5 9. b4 10. b3 11. b2 12. b1=L 13. Lg6 14. c5 15. c4 16. c3 17. c2 18. c1=T 19. Tg1 20. d5 21. d4 22. d3 23. d2 24. d1=S 25. Se3 26. Sf5 27. Sh4 28. Te1 g4#
Keywords: Alphabetic Chess, Pawn mate, Excelsior black, Kindergarten Problem, konsekutive Umwandlungen 4 (tlts), Miniature, Minimal (B), Model mate, Selfblock, Seriesmover, Promotions to rooks, under-promotion (ttls)
Genre: Fairies
FEN: 8/pppp4/8/7k/5K2/6P1/8/8
Input: Gunter Jordan, 2024-02-15
Last update: Gunter Jordan, 2024-02-15 more...
Genre: Fairies
FEN: 8/pppp4/8/7k/5K2/6P1/8/8
Input: Gunter Jordan, 2024-02-15
Last update: Gunter Jordan, 2024-02-15 more...
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https://pdb.dieschwalbe.de/search.jsp?expression=COMMENTDATE%3E%3D20200919+AND+NOT+K%3D%27Hilfsr%C3%BCckz%C3%BCger%27+AND+K%3D%27Mustermatt%27+AND+K%3D%27Kindergarten-Problem%27
The problems of this query have been registered by the following contributors:
Michal Dragoun (1)Hans-Jürgen Schäfer (1)
Felber, Volker (1)
Gunter Jordan (9)
Frank Müller (1)
Marcin Banaszek (1)
Rainer Staudte (1)
This is possibly a unique 2-move helpmate with ep-key and 2 solutions of the type 1.2.1.1 (at least so currently in the PDB).
Publi?ation details. H551 in the Helpmate section of the July issue, with no preview. Here is the text of the solution published in the Nov.-77 issue: “…White may have just played P(e3)xd4. Very few solvers have spotted this. Full marks for claim of no solution with correct reasoning but, in fairness, one mark for composer's intention. White cannot have just played K(a5)a6 in reply to Pxb6+ as too many captures by Black are required.” (2023-12-01)
A.Buchanan: Yes Valery you are right this must be cooked. However, I'm not a fan of +bSe3 because it spoils one of the model mates. Separately, I mildly prefer bPf7 to bPe6. (2023-12-03)
VL: I do prefer bPf7, as well. I don't see any way to save at least one of the properties Kindergarten Problem and Model mate (2) after fixing (what for these keywords have been added just now?). Besides, Andrew, please, refine the specification ((full) number and publication month 07-08). (2023-12-03)
A.Buchanan: Ok have added the publication details. The keywords are useful to indicate the aim, even though the problem is cooked. I guess there is a way to keep the model mates but it’s very clunky and probably +bSe3 is better (2023-12-03)
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