Die Schwalbe

6 problem(s) found in 2457 milliseconds (displaying 6 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND K='Rückkehr' AND K='Kindergarten-Problem'] [download as LaTeX]

1 - P0559179
Tivadar Kardos
300v Europe Echecs 02/1961
P0559179
(9+8) C+
h#19
1. Kb8 Ka4 2. Kc8 Ka3 3. Kd8 Ka4 4. Ke8 Ka3 5. Kf8 Ka4 6. Kg7 Ka3 7. Kf6 Ka4 8. Kg5 Ka3 9. Kf4 Ka4 10. Kxe4 Ka3 11. Kd3 Ka4 12. e4 Ka3 13. e3 Ka4 14. e2 Ka3 15. e1=D Ka4 16. Dxe6 Ka3 17. Dd7 cxd7 18. Kc2 d8=D 19. Kb1 Dd1#
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mit wKa4 h#20 0.1...
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Keywords: Promotion (Dd), Entblockung, Ceriani-Frolkin Theme (d), Model mate, Königswanderung, Switchback (K), Kindergarten Problem, Pronkin Theme (D)
Genre: h#
Computer test: Gustav 4.1d
FEN: 8/k1p1p3/1pP1P2p/1P2p2P/1Pp1P3/KpP5/1P6/8
Input: Hans-Jürgen Schäfer, 1999-01-01
Last update: A.Buchanan, 2021-04-06 more...
2 - P1235258
Guy Sobrecases
392 Gaudium 96 07/2009
nach Harald Grubert
P1235258
(6+5) C+
h#9,5
1. ... Kc1! 2. Kxb4 Kc2 3. Ka5 Kb3 4. Ka6! Kxa3 5. Ka5! Kb2 6. Kb4 a4 7. Kc4! a5 8. Kb4! a6 9. Ka5 a7 10. Ka6! a8=D#
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Yuri Bilokin: you can see *) 1... ... 2.Kxb4 Kc2 3.Ka5 Kb3 4.Ka6 Kxa3 5.Ka5 Kb2 6.Kb4 a4 7.Kc4 a5 8.Kb4 a6 9.Ka5 a7 10.Ka6 a8=Q# (MM) (2022-07-03)
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Keywords: Excelsior white, Model mate, Switchback (k), Tempo Move, Promotion (D), Kindergarten Problem, Promotion in the mating move
Genre: h#
FEN: 8/8/2p5/1pP1p3/1Pk1P3/p3P3/P7/1K6
Input: Gunter Jordan, 2012-03-26
Last update: Gunter Jordan, 2022-07-02 more...
3 - P1376231
Zdzislaw Nowak

P1376231
(8+8) C+
h#8
1. Kc4 Ka2 2. Kxd5 Kb3 3. Kxe6 Kc4 4. Kf5 Kd5 5. Kf6 Kxe4 6. Ke6 Kxe3 7. Kd5 Kd3 8. e6 e4#
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Die Aufgabe wurde im Reprint (Schach 06/2020) in Notation abgedruckt. Die Originalquelle ist nicht bekannt.
Silvio Baier: Originalquelle ist 15201v Schach 5/2003, S. 80. Davor wurde eine illegale Stellung als 15201 in Schach 3/2003 veröffentlicht. (2020-11-09)
comment
Keywords: Pawn mate, Kindergarten Problem, Model mate, Switchback (k), Round Trip (k-3), Selfblock, Tempo Loss, Umnov (verzögert)
Genre: h#
Computer test: Gustav 4.0 i
FEN: 8/4p1p1/1p1pP1P1/1P1Pp3/1P2p3/1k2p3/1P2P3/K7
Reprints: Schach , p. 80, 06/2020
Input: Gunter Jordan, 2020-05-23
Last update: Gunter Jordan, 2020-05-23 more...
4 - P1394769
Oleg Paradzynskyi
G44/124 feenschach 245, p. 149, 05-06/2021
P1394769
(2+2) C+
h#6
Beamtenschach
1. d2 b8=T 2. d1=D Tb1 3. Dg1+ Tb7+ 4. Ka6 Ta7+ 5. Ka5 Kd4 6. Ka4 Kc4#
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Gunter Jordan: Ein sehr schöner Wenigsteiner, der es verdient hätte, im Urdruckteil von feenschach zu erscheinen, statt in der Grube versenkt zu werden. (2021-10-21)
Henrik Juel: In Functionary chess all men are functionaries
A functionary has no powers (except the ability to observe), unless it is observed by an enemy man
In this problem, initially the pawns are observed by the kings, so they may move and promote
2... Tb1 is possible, because Tb8 is observed Ka7, and then Tb1 observes Dd1, who checks on g1
3... Tb7+ is possible, because Tb1 is observed by Dg1, and this white move releases the check from Dg1, because Dg1 is no longer observed, and it checks, because Tb7 is observed by Ka7
5.Ka5 escapes from check, because Ta7 is no longer observed
6... Kc4# is possible, because Kd4 is observed by Dg1, and this white move delivers check from Ta7, because now Ta7 is observed by Dg1
7.Ka5,Ka3? are illegal, because the black king is still in check from the observed Ta7
Kc4 has no powers before Black attempts the illegal moves 7.Kb3,Kb4,Kb5? which observe Kc4
Popeye 4.61 quickly tests this h#6, because there are relatively few moves to consider (2021-10-22)
Henrik Juel: Andrew, your english definition might be clearer, if you replace 'threaten' by 'observe' (2021-10-22)
A.Buchanan: OK will do - I will add that to observe is to attack a friendly piece. Attack is a term from the laws (2021-10-22)
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Keywords: Functionary Chess, Kindergarten Problem, konsekutive Umwandlungen 2 (Td), Cross check, Minimal (B,b), Model mate, Rückkehr nach Umwandlung, Round Trip (B-3), Promotion (d), under-promotion (T)
Genre: Fairies
FEN: 8/kP6/8/8/8/3pK3/8/8
Input: Gunter Jordan, 2021-10-21
Last update: Gunter Jordan, 2021-10-21 more...
5 - P1402955
Kurt Keller
3675 ChessStar 23/07/2022
P1402955
(2+5) C+
h#5
1. a4 bxa4+ 2. Kc4 a5 3. Kb5 a6 4. Ka5 a7 5. b5 a8=D,T#
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Comments:
SCHRECKE: Umwandlungsdual (a8T#) im Hilfsmatt ist nicht jedermanns Sache - meine auch nicht! (2022-07-23)
Henrik Juel: so the problem is not C+... (2022-07-23)
Kurt Keller: see keyword "tolerated dual promotion":
"Sometimes, the mating move is a promotion, and both D/T would mate. Similarly, sometimes D/L would both work. This is a tolerated dual under Article 13 of the Codex, because if it were not allowed, too many matrices would be invalid."
Article 13 (https://www.wfcc.ch/1999-2012/codex/):
"(2) Help-play compositions are unsound also if they are dualized, except that in the final move a promotion into different pieces having partially the same power (for example queen/rook or queen/bishop) may be tolerated [16]."
Therefore, the problem is sound (C+). (2022-07-23)
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Keywords: Symbol problem (cross), Kindergarten Problem, Minimal (B), Miniature, Symmetrical position, Asymmetrical solution, Sacrifice key, Sacrifice of black pieces (active), Active sacrifice, White correction (for Black), Selfblock, Switchback (k), Promotion in the mating move, Tolerated dual promotion (D/T)
Genre: h#
Computer test: Gustav 4.1 d
FEN: 8/1K6/1p6/pkp5/1p6/1P6/8/8
Input: Kurt Keller, 2022-07-23
Last update: Kurt Keller, 2022-10-28 more...
6 - P1410865
Mirko Degenkolbe
10582 Seven Chess Notes 210, p. 23, 07/2023
spezielles Lob
Abt. h#5,5-n
PR Alexej Iwunin
P1410865
(5+1) C+
h#6
0.2.1...
b) wKf1<->sKc1
a1) 1. ... d4 2. Kd2 d5 3. Ke3 d6 4. Kf4 d7 5. Kg3 d8=D 6. Kh2 Dh4#
a2) 1. ... g4 2. Kxd2 g5 3. Ke3 g6 4. Kf4 g7 5. Kg3 g8=D+ 6. Kh2 Dg2#
b1) 1. ... b4 2. Kxe2 b5 3. Kd3 b6 4. Kc4 b7 5. Kb3 b8=D+ 6. Ka2 Db2#
b2) 1. ... e4 2. Ke2 e5 3. Kd3 e6 4. Kc4 e7 5. Kb3 e8=D 6. Ka2 Da4#
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Komplett gleichbleibende schwarze Züge innerhalb der Lösung a) und innerhalb der Lösung b) mit völlig anderen Mattbildern.
Vier verschiedene Excelsiors. Jeder Bauer, der sich auf dem Brett befindet, führt einen Excelsior aus. Zweimal Rückkehr im Mattzug. Zweimal Chamäleonechomatts.
Rex solus. Sechssteiner
(MD1924)
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Keywords: Miniature, Kindergarten Problem, Rex solus (s), Excelsior white, Promotion (D), Chameleon Echo, Rückkehr nach Umwandlung (in a2+b1), Round Trip (B/D in a2+b1), Twin, Symmetrical solution
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/8/8/8/8/8/1P1PP1P1/2k2K2
Input: Felber, Volker, 2023-07-11
Last update: Gunter Jordan, 2024-02-04 more...
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The problems of this query have been registered by the following contributors:

Hans-Jürgen Schäfer (1)
Gunter Jordan (3)
Kurt Keller (1)
Felber, Volker (1)