Die Schwalbe

17 problem(s) found in 2798 milliseconds (displaying 17 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND K='symmetrische Position' AND K='symmetrisches Spiel'] [download as LaTeX]

1 - P0002476
Werner Kuntsche
1777v Problem 73-78 06/1961
P0002476
(5+7) cooked
h#3 AP
Einheitslösung!
1) 1. cxd3ep Ta5 2. Sf5 0-0 3. Sd4 Txe5#
2) 1. gxf3ep Th5 2. Sd5 0-0-0 3. Sf4 Txe5#
play all play one stop play next play all
Cook: 707 cooks which do not begin with e.p., e.g. 1.Sg3-e2 Ra1-a2 2.Ke4-d3 Rh1-h3 3.e5-e4 Ra2-d2 #
What is the obscure intent behind "Einheitslösung!"? (= "One size fits all solution"?)
Mario Richter: Im Nachdruck in problem 144-147 steht nur auf e5 ein sB (also keiner auf e3). Allerdings gibt es in allen drei Varianten (sBe5+e3, nur sBe5, nur sBe3) jede Menge NL, die ohne Rochade und e.p.-Key auskommen - am wenigsten dann, wenn nur auf e3 ein sB steht. (2010-10-10)
VL: Cf. P0002475. (2012-08-26)
A.Buchanan: Possibly "Einheitlösung!" is a request to unify retro implications derived across separate parts of the PRA solution. But cooked chessically irrespective of these philosophical issues, which still wait to be resolved 60 years on. (2022-02-16)
comment
Keywords: a posteriori (AP) (Type Petrovic - ccee), En passant as key (2), Castling (wb), Symmetrical position, Symmetrical solution, Superseded by (P1401449,P1399112)
Genre: h#, Retro
Computer test: C- Forward play cooked by Popeye v4.87. However the basic idea is good, if a suitable theoretical framework can be found.
FEN: 8/8/8/4p3/2pPkPp1/2n1p1n1/8/R3K2R
Reprints: (66) Problem 144, p. 52, 12/1971
Die Schwalbe 99 06/1986
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-24 more...
2 - P1000172
Andrey Frolkin
Andrej N. Kornilow

9 Die Schwalbe 169, p. 342, 02/1998
3. Preis
P1000172
(14+14) cooked
KBP?
1. a4 h5 2. a5 h4 3. a6 h3 4. axb7 hxg2 5. h4 a5 6. h5 a4 7. h6 a3 8. h7 a2 9. Th6 Ta3 10. Sh3 Sa6 11. b8=D g1=D 12. Db4 Dg5 13. Dh4 Da5 14. b4 g5 15. 15. b5 g4 16. b6 g3 17. b7 g2 18. b8=D g1=D 19. Dbb4 Dgg5 20. Dbg4 Dgb5 21. c4 f5 22. Tf6 Tc3 23. dxc3 exf6 24. Le3 Ld6 25. Sd2 Se7 26. Tb1 Tg8 27. h8=S a1=S 28. Sg6 Sb3 29. Sgf4 Sbc5 30. Sg2 Sb7 31. f4 c5 32. Lg1 Lb8 33. e3 d6 34. Le2 Ld7 35. Sf1 Sc8 36. Dd2 De7 37. Kd1
play all play one stop play next play all
Cook: NL
1. d3 a5 2. Le3 a4 3. Sd2 a3 4. g4 Ta4 5. g5 Tc4 6. dxc4 b5 7. g6 b4 8. gxh7 b3 9. h4 bxa2 10. b4 e6 11. b5 g5 12. b6 g4 13. b7 g3 14. h5 g2 15. h6 Sa6 16. Th5 f6 17. Tb1 a1=S 18. Sh3 g1=D 19. b8=D Dg5 20. c3 Db5 21. Tf5 c5 22. Df4 Ld6 23. Dg4 Lb8 24. f4 Se7 25. Lg1 a2 26. e3 Sb3 27. Le2 a1=D 28. Sf1 Sa5 29. Dd2 Sb7 30. Kd1 Tg8 31. h8=S Da5 32. Sg6 exf5 33. Sh4 d6 34. Sg2 Ld7 35. h7 Sc8 36. h8=D De7 37. Dh8-h4 (Henrik Juel)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.31 00:06:21 Minuten. (hh:mm:ss)
Keine Lösung: BP 36.0.
Beispiel Stelvio: 1.c3 a5 2.d3 a4 3.Le3 a3 4.Sd2 Ta4 5.Tb1 Tc4 6.dxc4 Sa6 7.g4 b5
8.g5 b4 9.g6 b3 10.gxh7 bxa2 11.b4 a1=S 12.b5 a2 13.b6 Sb3 14.h4 g5 15.h5 g4
16.h6 g3 17.Th5 g2 18.Sh3 g1=D 19.b7 Dg5 20.b8=D Db5 21.Tf5 c5 22.Df4 a1=D 23.Dg4 Sa5
24.f4 Sb7 25.Lg1 Daa5 26.e3 e6 27.Le2 Ld6 28.Sf1 Lb8 29.Dd2 Se7 30.Kd1 Tg8
31.h8=S d6 32.Sg6 Ld7 33.Sh4 Sc8 34.Sg2 De7 35.h7 f6 36.h8=D exf5 37.Dhh4 (2023-06-20)
more ...
comment
Keywords: Unique Proof Game, Symmetrical position, Non-standard material, Symmetrical solution
Genre: Retro
FEN: 1bn1k1r1/1n1bq3/n2p1p2/qqp2p2/2P2PQQ/2P1P2N/3QB1N1/1R1K1NB1
Reprints: feenschach 141 06/2001
Input: Gerd Wilts, 2000-08-01
Last update: Alfred Pfeiffer, 2018-12-19 more...
3 - P1148947
Godehard Murkisch
23c Schachkomponist Günther Jahn 04/2005
P1148947
(3+3) C+
#4
1. e8=D+ Tde6 2. Db8+ Td6 3. Db5+ Ke6 4. De8#
3. ... Td5 4. Dxd5#
1. ... Tfe6 2. Dh8+ Tf6 3. Dh5+ Ke6 4. De8#
3. ... Tf5 4. Dxf5
play all play one stop play next play all
mm Schema
more ...
comment
Keywords: Miniature Collection (0349521), Checking key, Echo, Epaulettenmatt, Switchback, Symmetrical position, Promotion (D), Symmetrical solution, Symmetrical end position, Miniature
Genre: n#
Computer test: Gustav 4.2a, Brute Force
FEN: 8/4P3/3r1r2/4k3/4P3/4K3/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Rainer Staudte, 2023-10-06 more...
4 - P1217923
Heinrich Friedrich Ludwig Meyer
181 Brüderschaft 43, p. 197, 23/10/1886
P1217923
(7+5) C+
#2
1. e8=S! Kf5 2. Sxd6#
1. ... Kd5 2. Sxf6#
1. ... d5 2. Sd6#
1. ... f5 2. Sf6#
play all play one stop play next play all
more ...
comment
Keywords: under-promotion key (S), Symmetrical position, Zugzwang-Goal, Symmetrical solution
Genre: 2#
Computer test: Juel: Popeye 4.61
FEN: 8/4P3/3ppp2/1P2p2P/4k3/1P2B2P/4K3/8
Input: Felber, Volker, 2011-11-08
Last update: Dieter Berlin, 2024-03-11 more...
5 - P1249790
Michel Olausson
Springaren (69) 05/1997
P1249790
(8+8) cooked
h==5
1. hxg1=L axb8=L 2. Ta7 Th2 3. gxh2 bxa7 4. h1=T a8=T 5. h2 a7==
play all play one stop play next play all
Cook: 1. hxg1=L Th2 2. gxh2 axb8=L 3. Ta7 bxa7 4. h1=T a8=T 5. h2 a7==
t/Figuren-Kranz 3×3 2-fach a6c8 und f1h3
Bernd Schwarzkopf: Popeye 4.79 findet eine Zugumstellung:
1.hxg1=L Th2 2.gxh2 axb8=L 3.Ta7 bxa7 4.h1=T a8=T 5.h2 a7==
1.hxg1=L axb8=L 2.Ta7 Th2 3.gxh2 bxa7 4.h1=T a8=T 5.h2 a7==
(Auch Lösungsprogramme lernen dazu!) (2018-09-06)
Henrik Juel: Popeye 4.61 also found the cook (in a couple of minutes)
Maybe the original C+ label is just an error; I see no reason why Popeye 3.56 should be different in this respect (2018-09-06)
James Malcom: Fixed. (2020-12-31)
A.Buchanan: "Under"-promotion is meaningless - except of course for direct mates and endgame studies. I always remove it if I have the time (2020-12-31)
Hans-Jürgen Manthey: Total Kaputt, jeder der 12 möglichen Züge ist eine Lösung:
1. fxLg1D,T,L,S Tx~g1 2. h1L cxLb8L 3. g2+ Kf2 4. Txa7 Lh2 5. Tc7 bxTc7=
2. h1S Tg2 3. f2 axLb8D,T,L,S 4. Tx~b8 a7 5. h2 axTb8S,L=
2. f2 Th1 3. Txa7 cxLb8L 4. T~7 Lxg3 5. Tc7 bxTc7=
1. hxg1D,T,L,S Tx~g1 2. g2+ Kxf2 3. h2 Kxf3 4. h1L axLb8S 5. Txa6 SxTa6=
1. g2+ Kxf2 2. gxTh1D Lxh2 3. Da1 axLb8S 4. Dxa6 SxDa6 5. Ta7 bxTa7=
1. Txa7 Lxf2 2. gxLf2 Kxf2 3. Txa6 Txh2 4. Ta7 cxLb8 5. Tc7 LxTc7=
1. Lxa7 Lxf2 2. g2+ Ke1 3. g1L bxLa7 4. Lxf2+ Kxf2 5. Tb8 aXTb8L=
1. Lxc7 Lxf2 2. gxLf2 Kxf2 3. Lg3+ Kxf3 4. Lc7 bxLc7 5. Tb8 axTb8L=
mit sehr vielen Dualen
Kürzer zB: in 4 Zügen:
1. fxLg1L cxLb8L 2. f2 Lxg3 3. Tb8 Lc7 4.Txb6 LxTb6=
1. hxLg1L cxLb8L 2. Lh2 Lxg3 3. Txa7 LxLh2 4.Ta7-c7 bxc7=
1. Bg2+ Kxf2 2.Txa7 Txh2 3.Tb7 c7xLb8~ 4.KxLb8 ax/cxb7=
1. Txa7 Lxf2 2.Bxf2 Kxf2 3.Tb7 c7xLb8~ 4.KxLb8 ax/cxb7=
1. Lxa7,c7 Lxf2,h2 2.gxLf2,h2 bxLa7,c7 3.Tb8 axTb8L=
auch mit vielen Dualen
gar in schon 3 Zügen:
1. Txa7 Lxf2,h2 2. g3xLf2,h2 cxLb8L 3.Tc7 bx/LxTc7=
1...cxb8L 2.Tc7 Lxf2,xh2 3.Bg3xLf2,h2 b6x/Lxc7=
1.Lb8xa7 Lxf2,xh2 2.Bg3xLf2,xh2 bxLa7 3.Tb8 axTb8L=
2.Tb8 bxLa7 3.g3xLf2,h2 axb8L=
1...bxLa7 2.Tb8 Lxf2,h2 3.gxLf2,h2 a7xb8L=
1.Lxc7 Lg1xf2,h2 2.Bg3Lxf2,h2 bxLc7 3.Tb8 axTb8L=
2.Tb8 bxLc7 3.gxLf2,h2 axTb8L=
2...axTb8L 3.gxLf2,h2 bx/LxLc7=
1...bxc7 2.Tb8 Lxf2,h2 3.gxLf2,h2 axTb8L= (2020-12-31)
SCHRECKE: Hans-Jürgen, die Forderung lautet h==5 (nicht h=5!) (2020-12-31)
Hans-Jürgen Manthey: OHHH Im so Sorry (2021-01-02)
comment
Keywords: Promotion (LlTt), Symmetrical position, Symmetrical solution
Genre: Fairies
Computer test: %Popeye UNIX32-Version 3.56
FEN: rbk5/P1P5/PPP5/8/8/5ppp/5p1p/5KBR
Input: Erich Bartel, 2012-09-23
Last update: A.Buchanan, 2020-12-31 more...
6 - P1260390
Anatoly N. Skripnik
C11016 The Problemist 05/2012
P1260390
(2+3)
#6
1. Kc6 Kb8 2. Kb6 Sd6 3. Db4 Sc8+ 4. Kc6+ Sb6 5. Dxb6+ Kc8 6. Dc7#
5. ... Ka8 6. Db7#
1. ... Ka7 2. Kc7 Sc5 3. De7 usw.
play all play one stop play next play all
Anton Baumann: C+ Gustav 4.2a (2023-02-21)
comment
Keywords: Aristocrat, Minimal, Symmetrical position, Symmetrical solution, Oneliner
Genre: n#
FEN: k7/1n6/8/3K4/4Q3/5n2/8/8
Input: Frank Müller, 2013-01-20
Last update: Felber, Volker, 2013-05-24 more...
7 - P1334387
Reinhardt Fiebig
18524 Schach , p. 79, 02/2017
P1334387
(3+12) C+
h#2
6.1...
1) 1. Kc4 Ta8 2. Kb3 Da2#
2) 1. Ke4 Tg8 2. Kf3 Dg2#
3) 1. Lb5 Txd6+ 2. Kc5 Dxd4
4) 1. Lf5 Txd6+ 2. Ke5 Dxd4#
5) 1. Kc6 Da2 2. Kb7 Da8#
6) 1. Ke6 Dg2 2. Kf7 Dg8#
play all play one stop play next play all
Stefan Felber: Schlüsselwort muß 'Königsstern' lauten. (2021-05-04)
comment
Keywords: Symmetrical position, Symmetrical solution, Echo, Königskreuz
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 3R4/2pbp3/1p1n1p2/3k4/1p1n1p2/2p1p3/3Q4/3K4
Input: Felber, Volker, 2017-05-29
Last update: Felber, Volker, 2017-05-29 more...
8 - P1380996
Otto Oppenheimer
8 Aufbau (New York) 18/06/1943
P1380996
(5+2) C+
#2
1. Dg7! (Zugzwang)
1. ... Kd4 2. Dxf6#
1. ... Kxf4 2. Dg3#
1. ... Kxd6 2. Dc7#
play all play one stop play next play all
more ...
comment
Keywords: Symmetrical position, Symmetrical solution, Aristocrat
Genre: 2#
Computer test: popeye 4.85
FEN: 7Q/8/3N1r2/4k3/5N2/2R5/8/K7
Input: Mario Richter, 2020-10-16
Last update: Alfred Pfeiffer, 2020-10-16 more...
9 - P1389654
Otto Trinks
20 Bote von der Ybbs 07/03/1930
nach W.J. Baird
P1389654
(5+1) C+
#3
2 Lösungen
1) 1. Se7! droht 2. Te1#
1. ... Ke5 2. Tb6 Ke4 3. Te6#

2) 1. Sh4! droht 2. Tb4#
1. ... Kf4 2. Tg1 Ke4 3. Tg4#
play all play one stop play next play all
bei der Bairdschen Vorlage handelt es sich vermutlich um P1144237

Beim Abdruck im 'Boten von der Ybbs' Forderung nur "Matt in drei Zügen", bei den Lösungen (21.03.1930): "Beabsichtigte Doppellösung (sogenannter 'Zweispänner') 1. Sc6-e7 und 1. Sg2-h4." (Die Aufgabe war Teil eines Lösewettbewerbs, bei dem es für gefundene NLs Extrapunkte gab, die "beabsichtigten" 2 Lösungen waren also evtl. ein Test für die Löser)
Henrik Juel: No asymmetry... (2021-05-16)
more ...
comment
Keywords: Rex solus (s), Aristocrat, Symmetrical position, Miniature, Flight giving and taking key, Symmetrical solution
Genre: 3#
Computer test: C+ Popeye 4.61
FEN: 8/8/2N5/8/4k3/3R4/2K3N1/1R6
Input: Mario Richter, 2021-05-16
Last update: Alfred Pfeiffer, 2021-08-17 more...
10 - P1398982
Werner Keym
Die Zeit 2020
P1398982
(5+1)
#2
1. De5? Kxd7,Kxf7 2. e8=D#
aber Schwarz hatte zuletzt keinen Zug, also
0) 1. ... Kxd7,Kxf7! e8=D+ 2. Kd6,Kf6 D2e5#
play all play one stop play next play all
Letztform eines symmetrischen Sechssteiners mit schwarzem Anzug.
more ...
comment
Keywords: Miniature, Homebase, Rex solus (s), Promotion (D), Symmetrical position, Symmetrical solution
Genre: 2#
Computer test: C+ Popeye 4.61 (it is obvious that Black has the move)
FEN: 4k3/3RPR2/8/8/8/8/4Q3/4K3
Input: Alfred Pfeiffer, 2022-02-09
Last update: A.Buchanan, 2022-02-10 more...
11 - P1399112
Werner Kuntsche
Valery Liskovets
Andrew Buchanan

PDB Website 14/02/2022
WK, correction AB
P1399112
(5+8) C+
h#3 AP

No solutions except for those beginning with e.p.
297 candidate solutions begin 1.gxf3ep, but only one includes castling. Queenside 2. ... 0-0-0
22 candidate solutions begin 1.fcxd3ep, but only one includes castling. Kingside 2. ... 0-0
In some way, these are trying to be combined so that from AP perspective, White's last move can only have been double hop with wBd or wBf.
We need a clear delineation of the precise PRA-AP algorithm to be followed.

The point: if this problem is "sound", then surely P1382808 is "unsound", because there only one of the two parts needs to prove that White castling rights remain, so there are 4 cooks.
This is an important schema for AP. Previous cooked problems P0002476 & P0004295 (together with versions of each lacking sBe3) had multiple chess cooks that do not involve e.p. as key. This chessically sound composition allows us to focus on the fundamental theoretical issue of AP.

The double e.p. idea cannot work as an AP retro strategy problem, because one can never prove that one double pawn hop rather than the other occurred. PRA+AP seems potentially feasible, but I see no clear statement of how the normal PRA method should be extended to this case. All prescriptive suggestions are welcome.

In WinChloe, I found a correction from 2002 by Valery Liskovitz, just posted in PDB as P1401449. However it used three extra pawns, rather than 2, so the current version still has merit, but I will add Valery as co-corrector.

See also P1399178.
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key (2), Symmetrical position, Symmetrical solution, Castling (wb)
Genre: h#, Retro
Computer test: HC+ Forward play proved by Popeye v4.87 AP logic requires some framework but I think we know we want this cool idea to end up being sound.
FEN: 8/8/2p3p1/8/2pPkPp1/2n1p1n1/8/R3K2R
Input: A.Buchanan, 2022-02-14
Last update: A.Buchanan, 2022-05-24 more...
12 - P1403724
Claus Grupen
1628 Kieler Nachrichten 1971
P1403724
(7+6)
#2
1. c4! dxc4 2. Sxc4#
1. ... dxe4 2. Sxe4#
1. ... b5 2. c5#
1. ... c5 2. Sb5#
1. ... e5 2. Sf5#
1. ... f5 2. e5#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61 also (2022-08-19)
comment
Keywords: Pawn mate, Symmetrical position (nach Schlüssel), Symmetrical solution
Genre: 2#
Computer test: Gustav 4.1 a
FEN: 3K4/3B4/1ppkpp2/3p4/3BP3/N5N1/2P5/8
Input: Gunter Jordan, 2022-08-18
Last update: Gunter Jordan, 2022-08-18 more...
13 - P1406913
Miroslav Svitek
Zhiguliovskiye zori 2011
Lob
P1406913
(3+2)
#3
1. De5! Kg8 2. De8+ Kh7 3. Dg6#
2. ... Kg7 3. Dg6#,Df7#
1. ... Kh7 2. Dh5+ Kg8 3. Df7#
2. ... Kg7 3. Df7#,Dg6#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61, except for two mate duals (2022-12-29)
comment
Keywords: Symmetrical position, Symmetrical solution, Minimal (l), Aristocrat, Oneliner
Genre: 3#
FEN: 7b/6k1/5R2/8/3Q4/8/8/K7
Input: Rainer Staudte, 2022-12-29
Last update: Gunter Jordan, 2022-12-29 more...
14 - P1407350
Ivar Godal
207 Østlendingen 05/01/1960
P1407350
(3+2)
#3
1. e4 Kd8 2. Tc1 Ke8 3. Tc8#
1. ... Kf8 2. Tg1 Ke8 3. Tg8#
play all play one stop play next play all
SCHRECKE: Forderung: #3 / Genre: 3#
C+, popeye 4.87 (2023-01-20)
comment
Keywords: Symmetrical position, Symmetrical solution, Oneliner, Minimal (b), Miniature
Genre: 3#
FEN: 4k3/8/4K3/4p3/8/8/4P3/4R3
Input: Rainer Staudte, 2023-01-20
Last update: Rainer Staudte, 2023-01-20 more...
15 - P1407363
Albert Goetze
722 Dresdner Volkszeitung 02/11/1932
P1407363
(4+4)
#3
1. De7! Kd4 2. Dc5+ Ke4 3. De3#
1. ... Kf4 2. Dg5+ Ke4 3. De3#
1. ... d4 2. Db7+ Kf4 3. Df3#
1. ... f4 2. Dh7+ Kd4 3. Dd3#
play all play one stop play next play all
SCHRECKE: C+, popeye 4.87 (2023-01-21)
comment
Keywords: Symmetrical position, Symmetrical solution
Genre: 3#
FEN: 4Q3/8/8/3ppp2/1P2k2P/8/4K3/8
Input: Rainer Staudte, 2023-01-21
Last update: Rainer Staudte, 2023-01-21 more...
16 - P1414367
Paul Wenman
104 Two Hundred Assorted Problems , p. 28, 1945
P1414367
(10+8) C+
#2
1. Dd2! dxc2 2. e4#
1. ... dxe2 2. c4#
1. ... e4 2. Dg5#
1. ... c4 2. Da5#
1. ... Sxb6+ 2. Sxb6#
1. ... Sa7 2. Se7#
1. ... Sxf6+ 2. Sxf6#
1. ... Sg7 2. Sc7#
play all play one stop play next play all
more ...
comment
Keywords: Zugzwang-Goal, pin-mate (zweifach), ambush key, Switchback, Symmetrical solution, Epaulettenmatt, Pawn mate, Symmetrical position (nach Schlüssel)
Genre: 2#
Computer test: Juel: Popeye 4.61
FEN: N1n1n1N1/3K4/1P1p1P2/2pkp1Q1/3p4/1P1p1P2/2P1P3/8
Input: Dieter Berlin, 2024-01-07
Last update: Dieter Berlin, 2024-01-07 more...
17 - P1415284
Claus Grupen
2014/63 Schach in Schleswig-Holstein 2014
P1415284
(7+8)
#5
1. Dd3! Kc6 2. Db5+ Kd5 3. Dxb3+ Kc6 4. Sf5 ... 5. Se7#
4. ... c4 5. Db5#
4. ... d5 5. Db5,Db6# (Dual)
1. ... Ke6 2. Df5+ und weiter symmetrisch wie oben
play all play one stop play next play all
Henrik Juel: Popeye 4.61 found no solution (2024-02-26)
SCHRECKE: Es fehlen: wBb2+wBf2 (2024-02-26)
Gunter Jordan: ... ja, tatsächlich. Die beiden Bauern fehlen. Danke für den Hinweis - ich habe es korrigiert. (2024-02-27)
Henrik Juel: now C+ Popeye 4.61, except for the mate duals (2024-02-27)
more ...
comment
Keywords: Changed continuation, Switchback (k), Symbol problem (Weihnachtsbaum), Symmetrical position, Symmetrical solution
Genre: n#
FEN: 3B4/3p4/3p4/2pkp3/3b4/Np3pN1/1P1Q1P2/3K4
Input: Gunter Jordan, 2024-02-26
Last update: Gunter Jordan, 2024-02-27 more...
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The problems of this query have been registered by the following contributors:

Gerd Wilts (2)
Zuncke/Bruder (1)
Felber, Volker (2)
Erich Bartel (1)
Frank Müller (1)
Mario Richter (2)
Alfred Pfeiffer (1)
A.Buchanan (1)
Gunter Jordan (2)
Rainer Staudte (3)
Dieter Berlin (1)