92 problem(s) found in 4368 milliseconds (displaying 92 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT CPLUS AND K='symmetrische Position'] [download as LaTeX]
1) 1. cxd3ep Ta5 2. Sf5 0-0 3. Sd4 Txe5#
2) 1. gxf3ep Th5 2. Sd5 0-0-0 3. Sf4 Txe5#
Cook: 707 cooks which do not begin with e.p., e.g. 1.Sg3-e2 Ra1-a2 2.Ke4-d3 Rh1-h3 3.e5-e4 Ra2-d2 #
What is the obscure intent behind "Einheitslösung!"? (= "One size fits all solution"?)
2) 1. gxf3ep Th5 2. Sd5 0-0-0 3. Sf4 Txe5#
Cook: 707 cooks which do not begin with e.p., e.g. 1.Sg3-e2 Ra1-a2 2.Ke4-d3 Rh1-h3 3.e5-e4 Ra2-d2 #
What is the obscure intent behind "Einheitslösung!"? (= "One size fits all solution"?)
Keywords: a posteriori (AP) (Type Petrovic - ccee), En passant as key (2), Castling (wb), Symmetrical position, Symmetrical solution, Superseded by (P1401449,P1399112)
Genre: h#, Retro
Computer test: C- Forward play cooked by Popeye v4.87. However the basic idea is good, if a suitable theoretical framework can be found.
FEN: 8/8/8/4p3/2pPkPp1/2n1p1n1/8/R3K2R
Reprints: (66) Problem 144, p. 52, 12/1971
Die Schwalbe 99 06/1986
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-24 more...
Genre: h#, Retro
Computer test: C- Forward play cooked by Popeye v4.87. However the basic idea is good, if a suitable theoretical framework can be found.
FEN: 8/8/8/4p3/2pPkPp1/2n1p1n1/8/R3K2R
Reprints: (66) Problem 144, p. 52, 12/1971
Die Schwalbe 99 06/1986
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-24 more...
1. Sa3 Sa6 2. Sc4 Sc5 3. Se5 Se4 4. c4 c5 5. Da4 Da5 6. b3 b6 7. Lb2 Lb7 8. Tc1 Tc8 9. Tc3 Tc6 10. Th3 Th6 11. e3 e6 12. Le2 Le7 13. Lh5 Lh4 14. Sgf3 Sgf6 15. 0-0 0-0 16. Tc1 Tc8 17. Tc3 Tc6 18. Td3 Td6 19. Td4 Td5 20. d3 d6 21. Dd7 Dd2 22. De7 De2 23. Sd7 Sd2 24. Tg4 Tg5 25. Le5 Le4 26. Lf4 Lf5 27. Sfe5 Sfe4 28. f3 f6 29. Le8 Le1 30. Lg3 Lg6 31. Lf2 Lf7 32. Thg3 Thg6 33. h3 h6 34. Kh2 Kh7
Cook: 1. Sa3 Sa6 2. Sc4 Sc5 3. Se5 Se4 4. c4 c5 5. Da4 Da5 6. b3 b6 7. Lb2 Lb7 8. Tc1 Tc8 9. Tc3 Tc6 10. Th3 Th6 11. e3 e6 12. Le2 Le7 13. Lh5 Lh4 14. Sgf3 Sgf6 15. 0-0 0-0 16. Tc1 Tc8 17. Tc3 Tc6 18. Td3 Td6 19. Td4 Td5 20. d3 d6 21. Dd7 Dd2 22. De7 De2 23. Sd7 Sd2 24. Tg4 Tg5 25. Le5 Le4 26. Lf4 Lf5 27. Sfe5 Sfe4 28. f3 Le1 29. Lg3 f6 30. Le8 Lg6 31. Lf2 Lf7 32. Thg3 Thg6 33. h3 h6 34. Kh2 Kh7
Cook: 1. Sa3 Sa6 2. Sc4 Sc5 3. Se5 Se4 4. c4 c5 5. Da4 Da5 6. b3 b6 7. Lb2 Lb7 8. Tc1 Tc8 9. Tc3 Tc6 10. Th3 Th6 11. e3 e6 12. Le2 Le7 13. Lh5 Lh4 14. Sgf3 Sgf6 15. 0-0 0-0 16. Tc1 Tc8 17. Tc3 Tc6 18. Td3 Td6 19. Td4 Td5 20. d3 d6 21. Dd7 Dd2 22. De7 De2 23. Sd7 Sd2 24. Tg4 Tg5 25. Le5 Le4 26. Lf4 Lf5 27. Sfe5 Sfe4 28. f3 Le1 29. Lg3 f6 30. Le8 Lg6 31. Lf2 Lf7 32. Thg3 Thg6 33. h3 h6 34. Kh2 Kh7
Keywords: Unique Proof Game, Castling, Symmetrical position, Capture-free
Genre: Retro
FEN: 4B3/p2NQbpk/1p1ppprp/2p1N1r1/2P1n1R1/1P1PPPRP/P2nqBPK/4b3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-05-13 more...
Genre: Retro
FEN: 4B3/p2NQbpk/1p1ppprp/2p1N1r1/2P1n1R1/1P1PPPRP/P2nqBPK/4b3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-05-13 more...
R: 1. ... Ke4xSd4, dann Kf4 Sge6#
Keywords: Symmetrical position, Asymmetrical solution
Genre: h#
FEN: 7K/6N1/1P3N2/4p3/3k4/2q5/5P2/8
Reprints: H25 ASymmetrie 2013
Input: hpr, 1996-07-23
Last update: Alfred Pfeiffer, 2013-07-17 more...
Genre: h#
FEN: 7K/6N1/1P3N2/4p3/3k4/2q5/5P2/8
Reprints: H25 ASymmetrie 2013
Input: hpr, 1996-07-23
Last update: Alfred Pfeiffer, 2013-07-17 more...
1. Kxe3 c5 2. Kd2 Sc4#
NL:
1. Td5 Lf5 2. Txe5 Sc2#
1. Lf3 S3g4 2. Lxe4 Lf2#
NL:
1. Td5 Lf5 2. Txe5 Sc2#
1. Lf3 S3g4 2. Lxe4 Lf2#
Yuri Bilokin: correction bRd7-f7, bBg4-a4, -bN7 8/5r2/4p3/4N3/bKPkB2B/4N3/4p3/2nr4 (6+7) (2022-12-15)
A.Buchanan: The whole point of this ornamental problem is the symmetry. Any correction must preserve that. How about getting rid of the 2 rooks and the g-h-file bishops, then shift wBe4 to a4? 8/2n5/4p3/4N3/BKPk4/4N3/4p3/2n5? (2022-12-16)
Yuri Bilokin: I agree that the position should be symmetrical and economical, without unnecessary figures. The value of the positions reflected here is close to zero. (2022-12-16)
comment
A.Buchanan: The whole point of this ornamental problem is the symmetry. Any correction must preserve that. How about getting rid of the 2 rooks and the g-h-file bishops, then shift wBe4 to a4? 8/2n5/4p3/4N3/BKPk4/4N3/4p3/2n5? (2022-12-16)
Yuri Bilokin: I agree that the position should be symmetrical and economical, without unnecessary figures. The value of the positions reflected here is close to zero. (2022-12-16)
comment
Keywords: Sacrifice of white pieces, Symmetrical position
Genre: h#
FEN: 8/2nr4/4p3/4N3/1KPkB1bB/4N3/4p3/2nr4
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-24 more...
Genre: h#
FEN: 8/2nr4/4p3/4N3/1KPkB1bB/4N3/4p3/2nr4
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-24 more...
1. Sxe6 Sf3 2. Sg7 Tf8#
NL:
1. Sf7 exf7 2. Kg7 f8=D#
NL:
1. Sf7 exf7 2. Kg7 f8=D#
Yuri Bilokin: correction wKa1-b2, then a2=a1 8/7R/4n3/4Pk2/4NPn1/8/8/1K6 (5+3) h#2
1.Sxe5 Sf2 2.Sg6 Rf7# (MM) (2022-12-15)
comment
1.Sxe5 Sf2 2.Sg6 Rf7# (MM) (2022-12-15)
comment
Keywords: Symmetrical position
Genre: h#
FEN: 7R/4n3/4Pk2/4NPn1/8/8/8/K7
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-24 more...
Genre: h#
FEN: 7R/4n3/4Pk2/4NPn1/8/8/8/K7
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-24 more...
1. d4 Sh6 2. Tg5 Ta6#
Cook: NL:
1. d4 Kg8 2. Tf5 Ta6#
Cook: NL:
1. d4 Kg8 2. Tf5 Ta6#
Adrian Storisteanu: Possible fix (a bit rough, but the wK is still employed):
Kg7 Ra1 Se6 Sf5 / Ke5 Rb4 Rd2 Sh8 pc4 pd3 (4+6)
1.c3 Sg5 2.Rf4 Ra5#. (2019-10-12)
A.Buchanan: Pushing wS to f8 & h6 seems to fix the cook. Maybe that's where they were meant to be all along: hard to imagine old TRD making such an error. WinChloe hasn't got this one, so can't confirm. (2019-10-14)
Adrian Storisteanu: Nice workaround, Andrew! Dawson had his share of cooks... (2019-10-14)
Yuri Bilokin: possibly wNf7-f5, bRe2-f2, -bPe4 7K/8/5kN1/1r1p1N2/8/8/5r2/R7 (4+4) (2022-12-16)
comment
Kg7 Ra1 Se6 Sf5 / Ke5 Rb4 Rd2 Sh8 pc4 pd3 (4+6)
1.c3 Sg5 2.Rf4 Ra5#. (2019-10-12)
A.Buchanan: Pushing wS to f8 & h6 seems to fix the cook. Maybe that's where they were meant to be all along: hard to imagine old TRD making such an error. WinChloe hasn't got this one, so can't confirm. (2019-10-14)
Adrian Storisteanu: Nice workaround, Andrew! Dawson had his share of cooks... (2019-10-14)
Yuri Bilokin: possibly wNf7-f5, bRe2-f2, -bPe4 7K/8/5kN1/1r1p1N2/8/8/5r2/R7 (4+4) (2022-12-16)
comment
Keywords: Symmetrical position, Asymmetrical solution, Superseded by (P1389169)
Genre: h#
FEN: 7K/5N2/5kN1/1r1p4/4p3/8/4r3/R7
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: A.Buchanan, 2021-05-02 more...
Genre: h#
FEN: 7K/5N2/5kN1/1r1p4/4p3/8/4r3/R7
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: A.Buchanan, 2021-05-02 more...
a) 1. Ke6 Kc5 2. Ke5 Te1#
a) 1. Kc6 Ke5 2. Kc5 Tc1#
b) 1. Lbd7 Tb1 2. Kc6 Tb6#
b) 1. Lfd7 Tf1 2. Ke6 Tf6#
a) 1. Kc6 Ke5 2. Kc5 Tc1#
b) 1. Lbd7 Tb1 2. Kc6 Tb6#
b) 1. Lfd7 Tf1 2. Ke6 Tf6#
Keywords: Symmetrical position, Miniature, Obvious promotion
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/3k4/1p1N1p2/3K4/8/8/3R4
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: Rainer Staudte, 2023-02-27 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/3k4/1p1N1p2/3K4/8/8/3R4
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: Rainer Staudte, 2023-02-27 more...
*) 1. ... Kc3 2. fxe6 Dd4#
1) 1. f4 Lf5 2. f6 Dc5#
NL:
1. fxe6 Kc3 2. Kd5 Dd4#
1) 1. f4 Lf5 2. f6 Dc5#
NL:
1. fxe6 Kc3 2. Kd5 Dd4#
Yuri Bilokin: correction wPc6(-bPc6), -bPf7, +bRd6 8/8/2PrB3/4kp2/8/8/1K6/6Q1 (4+3) h#2*
1...Kc3 2.Rxe6 Qd4# (MM)
1.f4 Bf5 2.Rf6 Qc5# (MM) (2022-08-28)
comment
1...Kc3 2.Rxe6 Qd4# (MM)
1.f4 Bf5 2.Rf6 Qc5# (MM) (2022-08-28)
comment
Keywords: Sacrifice of white pieces, Symmetrical position
Genre: h#
FEN: 8/5p2/2p1B3/4kp2/8/8/1K6/6Q1
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-25 more...
Genre: h#
FEN: 8/5p2/2p1B3/4kp2/8/8/1K6/6Q1
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-25 more...
1. Tb7+ Kxc6 2. f3 Dd5#
NL:
1. c5 Kxc5 2. Tb7 Dd5#
NL:
1. c5 Kxc5 2. Tb7 Dd5#
Yuri Bilokin: Correction: -wBh1, bPf4-c5 b5Q1/5r2/1Kp5/2p5/4k3/8/6N1/8 (3+5)
1.Rb7+ Kxc6 2.c4 Qd5# (MM) (2020-11-27)
milan: +wPc5 original and symmetrical position M.Frelih (2020-12-15)
comment
1.Rb7+ Kxc6 2.c4 Qd5# (MM) (2020-11-27)
milan: +wPc5 original and symmetrical position M.Frelih (2020-12-15)
comment
Keywords: Symmetrical position
Genre: h#
FEN: b5Q1/5r2/1Kp5/8/4kp2/8/6N1/7B
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-25 more...
Genre: h#
FEN: b5Q1/5r2/1Kp5/8/4kp2/8/6N1/7B
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-25 more...
*) 1. ... Le3 2. Td3 De6#
1) 1. Tf5 Lf4 2. Tf3 Dc4#
Cook: NL 1. Tc5 Lf4 2. Tf5 Dc4#
1) 1. Tf5 Lf4 2. Tf3 Dc4#
Cook: NL 1. Tc5 Lf4 2. Tf5 Dc4#
Adrian Storisteanu: Possible fix: +bPc5 (3+4). (2015-08-21)
Arno Tüngler: Mit sBf3 geht bei gleichem Satzsoiel nur 1. Tc5 Lf4 2. Tf5 Dc4# (2024-02-05)
comment
Arno Tüngler: Mit sBf3 geht bei gleichem Satzsoiel nur 1. Tc5 Lf4 2. Tf5 Dc4# (2024-02-05)
comment
Keywords: Symmetrical position
Genre: h#
FEN: K7/8/8/8/4k3/1Qr2r2/8/2B5
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: A.Buchanan, 2024-02-03 more...
Genre: h#
FEN: K7/8/8/8/4k3/1Qr2r2/8/2B5
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: A.Buchanan, 2024-02-03 more...
1. Kxf5 Dc2+ 2. Kg4 Dg6#
NL:
1. Ke4 Kc2 2. Td5 Df4#
NL:
1. Ke4 Kc2 2. Td5 Df4#
klären: NL oder 2. AL ?
Yuri Bilokin: Correction: bPd6, wKc1-d7 8/2QK4/3p1p2/4kP2/8/6P1/6P1/8 (5+3)
1.Kxf5 Qc2+ 2.Kg4 Qg6# (MM) (2020-11-27)
comment
Yuri Bilokin: Correction: bPd6, wKc1-d7 8/2QK4/3p1p2/4kP2/8/6P1/6P1/8 (5+3)
1.Kxf5 Qc2+ 2.Kg4 Qg6# (MM) (2020-11-27)
comment
Keywords: Symmetrical position
Genre: h#
FEN: 8/2Qp4/3r1p2/4kP2/8/6P1/6P1/2K5
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-25 more...
Genre: h#
FEN: 8/2Qp4/3r1p2/4kP2/8/6P1/6P1/2K5
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-25 more...
1. f5 b4 2. f4 b5 3. f3 b6 4. f2 b7 5. f1=L b8=L 6. Lc4 Lxd6 7. Lcg8 Le5#
NL:
1. Le4 b4 2. Ld5 b5 3. Kg8 b6 4. Kf8 b7 5. Ke8 b8=D+ 6. Kd7 Ka6 7. Kc6 Dc8#
NL:
1. Le4 b4 2. Ld5 b5 3. Kg8 b6 4. Kf8 b7 5. Ke8 b8=D+ 6. Kd7 Ka6 7. Kc6 Dc8#
Yuri Bilokin: correction wKa7-b1, +bNd1 7k/5p1b/3p4/8/8/8/1Pn5/1K1n4 (2+6) h#7
1.f5 b4 2.f4 b5 3.f3 b6 4.f2 b7 5.f1=B b8=B 6.Bc4 Bxd6 7.Bcg8 Be5# (MM)
Excelsior (black)
Excelsior (white)
Promotion (Bb, 1, 1)
Model mate × 1 (2023-05-10)
comment
1.f5 b4 2.f4 b5 3.f3 b6 4.f2 b7 5.f1=B b8=B 6.Bc4 Bxd6 7.Bcg8 Be5# (MM)
Excelsior (black)
Excelsior (white)
Promotion (Bb, 1, 1)
Model mate × 1 (2023-05-10)
comment
Keywords: Symmetrical position, Promotion, Excelsior black (auto key), Excelsior white (auto key), Excelsior (sw)
Genre: h#
FEN: 7k/K4p1b/3p4/8/8/8/1Pn5/8
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: Rainer Staudte, 2014-06-21 more...
Genre: h#
FEN: 7k/K4p1b/3p4/8/8/8/1Pn5/8
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: Rainer Staudte, 2014-06-21 more...
1. Kf5 Lh5 2. Sf7 Sc8 3. d5 Sd7 4. Ke6 Lg4#
Cook: NL
1. Kh4 Sc6 2. Sc4 Sd4 3. Se5 Kg2 4. Sg4 Sf3#
Cook: NL
1. Kh4 Sc6 2. Sc4 Sd4 3. Se5 Kg2 4. Sg4 Sf3#
Adrian Storisteanu: Possible fix: wKh1->a1, wSa7->b6. (2015-07-25)
Felber, Volker: Der Korrekturversuch aus der LB Seite 318 (wKa1-h1) reicht nicht aus. (2023-03-31)
comment
Felber, Volker: Der Korrekturversuch aus der LB Seite 318 (wKa1-h1) reicht nicht aus. (2023-03-31)
comment
Keywords: Symmetrical position
Genre: h#
FEN: 1N2B3/N2p4/3n4/8/6k1/8/8/7K
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: Felber, Volker, 2023-03-31 more...
Genre: h#
FEN: 1N2B3/N2p4/3n4/8/6k1/8/8/7K
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: Felber, Volker, 2023-03-31 more...
1. Tb3 a3 2. Kxa3 Dxa1#
NL:
1. De1 Dxd5 2. d2 Dxc4#
NL:
1. De1 Dxd5 2. d2 Dxc4#
klären Quelle ?
Bath+Welts Chronicle+Herald ?
Yuri Bilokin: correction wKg4-f4, -wPa6, bBd3(-bPd3), bNa7-c6, -bNa1, -bPd5 8/8/2n5/r7/kqpQ1K2/r2b4/P7/8 (3+7) (2022-12-15)
A.Buchanan: Any acceptable correction must surely retain the thematic symmetry? (2022-12-16)
A.Buchanan: Bath & Wells (not Welts) are two small neighbouring cities in the West of England which are kind of paired together. E.g. there is a Bishop of B&W (which it occurs for me might stand for Black & White, suggesting a thematic problem with a neutral bishop). (2022-12-16)
milan: +wPb3b5 1.T×b3 a3 2. K×a3 D×a1# simply correction M.Frelih (2022-12-18)
comment
Bath+Welts Chronicle+Herald ?
Yuri Bilokin: correction wKg4-f4, -wPa6, bBd3(-bPd3), bNa7-c6, -bNa1, -bPd5 8/8/2n5/r7/kqpQ1K2/r2b4/P7/8 (3+7) (2022-12-15)
A.Buchanan: Any acceptable correction must surely retain the thematic symmetry? (2022-12-16)
A.Buchanan: Bath & Wells (not Welts) are two small neighbouring cities in the West of England which are kind of paired together. E.g. there is a Bishop of B&W (which it occurs for me might stand for Black & White, suggesting a thematic problem with a neutral bishop). (2022-12-16)
milan: +wPb3b5 1.T×b3 a3 2. K×a3 D×a1# simply correction M.Frelih (2022-12-18)
comment
Keywords: Symmetrical position
Genre: h#
FEN: 8/n7/P7/r2p4/kqpQ2K1/r2p4/P7/n7
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-28 more...
Genre: h#
FEN: 8/n7/P7/r2p4/kqpQ2K1/r2p4/P7/n7
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: hpr, 1999-10-28 more...
15 - P0531421
Thomas R. Dawson
1796 The Problemist Fairy Chess Supplement 02/1935
(4+4) cooked
h#2
b) sTd7 nach e7, sTh3 nach h4
Thomas R. Dawson
1796 The Problemist Fairy Chess Supplement 02/1935
(4+4) cooked
h#2
b) sTd7 nach e7, sTh3 nach h4
a) 1. Kg5 Tg2+ 2. Kh4 Tg4#
b) 1. Kxg7 Tg2+ 2. Kf8 Tg8#
NL:
a) 1. Kg5 Tg2+ 2. Kh4 Shf5#
b) 1. Kxg7 Tg2+ 2. Kf8 Tg8#
NL:
a) 1. Kg5 Tg2+ 2. Kh4 Shf5#
klären Monat
Alfred Pfeiffer: No.1796 ist aus 04/1935 (vgl. P0003272) (2011-01-11)
Yuri Bilokin: possibly bBe4(-bNe4), +bPd3 8/3r2N1/6kN/8/4b3/3p3r/2R5/1K6 (4+5) (2022-12-16)
comment
Alfred Pfeiffer: No.1796 ist aus 04/1935 (vgl. P0003272) (2011-01-11)
Yuri Bilokin: possibly bBe4(-bNe4), +bPd3 8/3r2N1/6kN/8/4b3/3p3r/2R5/1K6 (4+5) (2022-12-16)
comment
Keywords: Sacrifice of white pieces, Symmetrical position, Aristocrat, Aristocrat
Genre: h#
FEN: 8/3r2N1/6kN/8/4n3/7r/2R5/1K6
Reprints: 1796 The Problemist Fairy Chess Supplement 04/1935
Input: Ralf Krätschmer, 1998-03-30
Last update: Arnold Beine, 2022-12-17 more...
Genre: h#
FEN: 8/3r2N1/6kN/8/4n3/7r/2R5/1K6
Reprints: 1796 The Problemist Fairy Chess Supplement 04/1935
Input: Ralf Krätschmer, 1998-03-30
Last update: Arnold Beine, 2022-12-17 more...
16 - P1000171
Andrej N. Kornilow
8 Die Schwalbe 169, p. 342, 02/1998
3. ehrende Erwähnung
(14+14) cooked
KBP?
Andrej N. Kornilow
8 Die Schwalbe 169, p. 342, 02/1998
3. ehrende Erwähnung
(14+14) cooked
KBP?
1. Sf3 Sc6 2. Se5 Sd4 3. Sxd7 Sxe2 4. Sb6 Sg3 5. Lc4 Lf5 6. De2 Dd7 7. Kd1 Td8 8. Te1 Dc8 9. Df1 Td3 10. Te6 Ta3 11. Th6 gxh6 12. bxa3 h5 13. a4 Lh6 14. La3 Le3 15. Ld6 Sh6 16. Sa3 Tg8 17. Tb1 Tg6 18. Tb3 Te6 19. Td3 f6 20. c3 Kf7 21. Kc2 Kg6 22. Kb3 Kg5 23. Kb4 Lg6 24. Lb3 Shf5 25. Sac4 h6 26. a3
Cook: NL
1. Sf3 Sf6 2. e4 Sxe4 3. Lc4 h5 4. Ke2 Sg3 5. Kd3 Th6 6. Lb3 Ta6 7. Te1 Sc6 8. Te6 Ta3 9. Th6 gxh6 10. Se5 Lg7 11. Sxd7 Ld4 12. Sb6 Lf5 13. Kc4 Dd7 14. bxa3 Td8 15. a4 Dc8 16. La3 Td6 17. Df1 Te6 18. Ld6 f6 19. Sa3 Kf7 20. Te1 Kg6 21. Te3 Kg5 22. Td3 Le3 23. c3 Sd4 24. Kb4 Lg6 25. Sc4 Sf5 26. a3 (Henrik Juel)
Cook: NL
1. Sf3 Sf6 2. e4 Sxe4 3. Lc4 h5 4. Ke2 Sg3 5. Kd3 Th6 6. Lb3 Ta6 7. Te1 Sc6 8. Te6 Ta3 9. Th6 gxh6 10. Se5 Lg7 11. Sxd7 Ld4 12. Sb6 Lf5 13. Kc4 Dd7 14. bxa3 Td8 15. a4 Dc8 16. La3 Td6 17. Df1 Te6 18. Ld6 f6 19. Sa3 Kf7 20. Te1 Kg6 21. Te3 Kg5 22. Td3 Le3 23. c3 Sd4 24. Kb4 Lg6 25. Sc4 Sf5 26. a3 (Henrik Juel)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.31 108 Sekunden.
Keine Lösung: BP 25.0. KBP = 25.5! (2023-06-20)
more ...
comment
Keine Lösung: BP 25.0. KBP = 25.5! (2023-06-20)
more ...
comment
Keywords: Unique Proof Game, Symmetrical position
Genre: Retro
FEN: 2q5/ppp1p3/1N1Brpbp/5nkp/PKN5/PBPRb1n1/3P1PPP/5Q2
Input: Gerd Wilts, 2000-08-01
Last update: Alfred Pfeiffer, 2018-12-19 more...
Genre: Retro
FEN: 2q5/ppp1p3/1N1Brpbp/5nkp/PKN5/PBPRb1n1/3P1PPP/5Q2
Input: Gerd Wilts, 2000-08-01
Last update: Alfred Pfeiffer, 2018-12-19 more...
17 - P1000172
Andrey Frolkin
Andrej N. Kornilow
9 Die Schwalbe 169, p. 342, 02/1998
3. Preis
(14+14) cooked
KBP?
Andrey Frolkin
Andrej N. Kornilow
9 Die Schwalbe 169, p. 342, 02/1998
3. Preis
(14+14) cooked
KBP?
1. a4 h5 2. a5 h4 3. a6 h3 4. axb7 hxg2 5. h4 a5 6. h5 a4 7. h6 a3 8. h7 a2 9. Th6 Ta3 10. Sh3 Sa6 11. b8=D g1=D 12. Db4 Dg5 13. Dh4 Da5 14. b4 g5 15. 15. b5 g4 16. b6 g3 17. b7 g2 18. b8=D g1=D 19. Dbb4 Dgg5 20. Dbg4 Dgb5 21. c4 f5 22. Tf6 Tc3 23. dxc3 exf6 24. Le3 Ld6 25. Sd2 Se7 26. Tb1 Tg8 27. h8=S a1=S 28. Sg6 Sb3 29. Sgf4 Sbc5 30. Sg2 Sb7 31. f4 c5 32. Lg1 Lb8 33. e3 d6 34. Le2 Ld7 35. Sf1 Sc8 36. Dd2 De7 37. Kd1
Cook: NL
1. d3 a5 2. Le3 a4 3. Sd2 a3 4. g4 Ta4 5. g5 Tc4 6. dxc4 b5 7. g6 b4 8. gxh7 b3 9. h4 bxa2 10. b4 e6 11. b5 g5 12. b6 g4 13. b7 g3 14. h5 g2 15. h6 Sa6 16. Th5 f6 17. Tb1 a1=S 18. Sh3 g1=D 19. b8=D Dg5 20. c3 Db5 21. Tf5 c5 22. Df4 Ld6 23. Dg4 Lb8 24. f4 Se7 25. Lg1 a2 26. e3 Sb3 27. Le2 a1=D 28. Sf1 Sa5 29. Dd2 Sb7 30. Kd1 Tg8 31. h8=S Da5 32. Sg6 exf5 33. Sh4 d6 34. Sg2 Ld7 35. h7 Sc8 36. h8=D De7 37. Dh8-h4 (Henrik Juel)
Cook: NL
1. d3 a5 2. Le3 a4 3. Sd2 a3 4. g4 Ta4 5. g5 Tc4 6. dxc4 b5 7. g6 b4 8. gxh7 b3 9. h4 bxa2 10. b4 e6 11. b5 g5 12. b6 g4 13. b7 g3 14. h5 g2 15. h6 Sa6 16. Th5 f6 17. Tb1 a1=S 18. Sh3 g1=D 19. b8=D Dg5 20. c3 Db5 21. Tf5 c5 22. Df4 Ld6 23. Dg4 Lb8 24. f4 Se7 25. Lg1 a2 26. e3 Sb3 27. Le2 a1=D 28. Sf1 Sa5 29. Dd2 Sb7 30. Kd1 Tg8 31. h8=S Da5 32. Sg6 exf5 33. Sh4 d6 34. Sg2 Ld7 35. h7 Sc8 36. h8=D De7 37. Dh8-h4 (Henrik Juel)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.31 00:06:21 Minuten. (hh:mm:ss)
Keine Lösung: BP 36.0.
Beispiel Stelvio: 1.c3 a5 2.d3 a4 3.Le3 a3 4.Sd2 Ta4 5.Tb1 Tc4 6.dxc4 Sa6 7.g4 b5
8.g5 b4 9.g6 b3 10.gxh7 bxa2 11.b4 a1=S 12.b5 a2 13.b6 Sb3 14.h4 g5 15.h5 g4
16.h6 g3 17.Th5 g2 18.Sh3 g1=D 19.b7 Dg5 20.b8=D Db5 21.Tf5 c5 22.Df4 a1=D 23.Dg4 Sa5
24.f4 Sb7 25.Lg1 Daa5 26.e3 e6 27.Le2 Ld6 28.Sf1 Lb8 29.Dd2 Se7 30.Kd1 Tg8
31.h8=S d6 32.Sg6 Ld7 33.Sh4 Sc8 34.Sg2 De7 35.h7 f6 36.h8=D exf5 37.Dhh4 (2023-06-20)
more ...
comment
Keine Lösung: BP 36.0.
Beispiel Stelvio: 1.c3 a5 2.d3 a4 3.Le3 a3 4.Sd2 Ta4 5.Tb1 Tc4 6.dxc4 Sa6 7.g4 b5
8.g5 b4 9.g6 b3 10.gxh7 bxa2 11.b4 a1=S 12.b5 a2 13.b6 Sb3 14.h4 g5 15.h5 g4
16.h6 g3 17.Th5 g2 18.Sh3 g1=D 19.b7 Dg5 20.b8=D Db5 21.Tf5 c5 22.Df4 a1=D 23.Dg4 Sa5
24.f4 Sb7 25.Lg1 Daa5 26.e3 e6 27.Le2 Ld6 28.Sf1 Lb8 29.Dd2 Se7 30.Kd1 Tg8
31.h8=S d6 32.Sg6 Ld7 33.Sh4 Sc8 34.Sg2 De7 35.h7 f6 36.h8=D exf5 37.Dhh4 (2023-06-20)
more ...
comment
Keywords: Unique Proof Game, Symmetrical position, Non-standard material, Symmetrical solution
Genre: Retro
FEN: 1bn1k1r1/1n1bq3/n2p1p2/qqp2p2/2P2PQQ/2P1P2N/3QB1N1/1R1K1NB1
Reprints: feenschach 141 06/2001
Input: Gerd Wilts, 2000-08-01
Last update: Alfred Pfeiffer, 2018-12-19 more...
Genre: Retro
FEN: 1bn1k1r1/1n1bq3/n2p1p2/qqp2p2/2P2PQQ/2P1P2N/3QB1N1/1R1K1NB1
Reprints: feenschach 141 06/2001
Input: Gerd Wilts, 2000-08-01
Last update: Alfred Pfeiffer, 2018-12-19 more...
18 - P1013743
Rudolf Queck
Hans Gruber
4687 feenschach 76 08/11/1985
In memoriam Albert H. Kniest
(1+2)
=6*
Zwei Lösungen
Längstzüger
Gitterschach
6x6-Brett
sDU=Grashüpfer
Rudolf Queck
Hans Gruber
4687 feenschach 76 08/11/1985
In memoriam Albert H. Kniest
(1+2)
=6*
Zwei Lösungen
Längstzüger
Gitterschach
6x6-Brett
sDU=Grashüpfer
* = Diagrammstellung (Nullsatz)
1) 1. Se3! Ge4 2. Sc2 Gb1 3. Sb4 Gb5 4. Sd5 Ge5 5. Se3 Ge2 6. Sd1=
2) 1. Sc3! Kf2 2. Sb5 Ga6 3. Sd6 Ge6 4. Sf5! Kf3 5. Se3 Ge2 6. Sd1=
RQ-Buch: "In der Ausgangsstellung steht Schwarz schon patt. Die erste Lösung läuft konventionell ab mit Rundläufen von Springer und Grashüpfer; in der zweiten Lösung wird wohl sehr überraschend der schwarze König vom einzig denkbaren Pattfeld mit einem kürzestmöglichen Längstzug fortgezwungen - eine Löserhürde!"
1) 1. Se3! Ge4 2. Sc2 Gb1 3. Sb4 Gb5 4. Sd5 Ge5 5. Se3 Ge2 6. Sd1=
2) 1. Sc3! Kf2 2. Sb5 Ga6 3. Sd6 Ge6 4. Sf5! Kf3 5. Se3 Ge2 6. Sd1=
RQ-Buch: "In der Ausgangsstellung steht Schwarz schon patt. Die erste Lösung läuft konventionell ab mit Rundläufen von Springer und Grashüpfer; in der zweiten Lösung wird wohl sehr überraschend der schwarze König vom einzig denkbaren Pattfeld mit einem kürzestmöglichen Längstzug fortgezwungen - eine Löserhürde!"
Keywords: Grid Chess, Maximummer, no 8x8 board, Thema Null, Aristocrat, Oneliner, Symmetrical position, Asymmetrical solution
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: qqqqqqqq/qqqqqqqq/6qq/6qq/6qq/5kqq/4*2q1qq/3N2qq
Reprints: (27) RQu -- 36 Gitterschachaufgaben von Rudolf Queck , p. 35, 1989
Input: Hans Gruber, 2004-05-01
Last update: Alfred Pfeiffer, 2018-11-20 more...
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: qqqqqqqq/qqqqqqqq/6qq/6qq/6qq/5kqq/4*2q1qq/3N2qq
Reprints: (27) RQu -- 36 Gitterschachaufgaben von Rudolf Queck , p. 35, 1989
Input: Hans Gruber, 2004-05-01
Last update: Alfred Pfeiffer, 2018-11-20 more...
I) 1. Sg4 f4+ 2. Kxf4 0-0+ 3. Kg3 Tf3#
II) 1. Sc4 d4+ 2. Kxd4 0-0-0+ 3. Kc3 Td3#
Symmetrical (both the position and partial solutions). The last move?
II) 1. Sc4 d4+ 2. Kxd4 0-0-0+ 3. Kc3 Td3#
Symmetrical (both the position and partial solutions). The last move?
Keywords: Partial Retro Analysis (PRA), Symmetrical position, Castling
Genre: Retro
FEN: 8/8/8/4k3/1p5p/4n2p/P2PPP2/R3K2R
Input: Valery Liskovets, 2004-06-25
Last update: James Malcom, 2021-01-23 more...
Genre: Retro
FEN: 8/8/8/4k3/1p5p/4n2p/P2PPP2/R3K2R
Input: Valery Liskovets, 2004-06-25
Last update: James Malcom, 2021-01-23 more...
20 - P1038093
Manfred Zucker
8304 Schach , p. 326, 07/1977
Problemturnier des DSV der DDR 1977
1. Preis Mehrzüger-Abteilung
Richter: Volker Zipf
(4+5)
#4
Manfred Zucker
8304 Schach , p. 326, 07/1977
Problemturnier des DSV der DDR 1977
1. Preis Mehrzüger-Abteilung
Richter: Volker Zipf
(4+5)
#4
1. Tbb7! Sd2+ 2. Kg3 Sc4 3. Kxh3 Sa5,S~ 4. Sb6#
1. Tdb7? Sg5+ 2. Kf2 Se6 3. Kxf1 c4!
1. Tdb7? Sg5+ 2. Kf2 Se6 3. Kxf1 c4!
(MZ436)
.
Sally: Schach, Juli 1977. Nationales Problemturnier der DDR,1977,
1. Pr. FIDE - Album 1977 - 1979, Nr, 387.
1. Tdb7? - Sg5+, 2. Kf2 - Se6, 3.Kxf1 - Bc4!
1. Tbb7! -Sd2+, 2. Kg3 - Sc4, 3. Kxh3 - S--, 4. Sb6#.
Diagonal - symmetrische Stellung !
S. 38 Ausgewählte S. Aufgaben (Zucker).
S. 156 Problem S. ( Siehndel).
S. 130 Schwalbe Jun1 2007.
S. 118 S. ohne Partner (Grasemann)
S. 47 S. Report April 1988. (2010-08-21)
Henrik Juel: damaged by duals
1... Sh2+ 2.Kg3,Ke4
1... Sg5+ 2.Kf2,Ke2 (2021-03-12)
comment
.
Sally: Schach, Juli 1977. Nationales Problemturnier der DDR,1977,
1. Pr. FIDE - Album 1977 - 1979, Nr, 387.
1. Tdb7? - Sg5+, 2. Kf2 - Se6, 3.Kxf1 - Bc4!
1. Tbb7! -Sd2+, 2. Kg3 - Sc4, 3. Kxh3 - S--, 4. Sb6#.
Diagonal - symmetrische Stellung !
S. 38 Ausgewählte S. Aufgaben (Zucker).
S. 156 Problem S. ( Siehndel).
S. 130 Schwalbe Jun1 2007.
S. 118 S. ohne Partner (Grasemann)
S. 47 S. Report April 1988. (2010-08-21)
Henrik Juel: damaged by duals
1... Sh2+ 2.Kg3,Ke4
1... Sg5+ 2.Kf2,Ke2 (2021-03-12)
comment
Keywords: Brian Stephenson Collection (23043), Symmetrical position, Asymmetrical solution
Genre: n#
FEN: k7/3R4/3p4/1RpN4/8/5K1n/8/5n2
Reprints: 118 Schach ohne Partner für Könner 1982
213 Problemschach [Siehndel] 1984
Input: Brian Stephenson, 2004-08-12
Last update: Felber, Volker, 2021-03-12 more...
Genre: n#
FEN: k7/3R4/3p4/1RpN4/8/5K1n/8/5n2
Reprints: 118 Schach ohne Partner für Könner 1982
213 Problemschach [Siehndel] 1984
Input: Brian Stephenson, 2004-08-12
Last update: Felber, Volker, 2021-03-12 more...
1. Te1! droht 2. Dc3#
1. ... e3 2. Dc6#
1. ... exf3 2. Te6#
1. ... gxf3 2. Tg6#
1. ... e3 2. Dc6#
1. ... exf3 2. Te6#
1. ... gxf3 2. Tg6#
Keywords: Brian Stephenson Collection (23707), Symmetrical position, Asymmetrical solution
Genre: 2#
FEN: 5K2/5B2/5k2/5p2/4pPp1/4RQR1/5P2/5r2
Reprints: 50 Bote von der Ybbs 24/10/1930
Input: Brian Stephenson, 2004-08-12
Last update: Mario Richter, 2021-05-16 more...
Genre: 2#
FEN: 5K2/5B2/5k2/5p2/4pPp1/4RQR1/5P2/5r2
Reprints: 50 Bote von der Ybbs 24/10/1930
Input: Brian Stephenson, 2004-08-12
Last update: Mario Richter, 2021-05-16 more...
BS Problemid: 50409
Authors: Rupp, R
Sources:
Years: 1956
SCHRECKE: 1.Kf1! (Zugzwang)
1. ... Ld7,Lc8 2.Ld3 (3.T:e4#) L:f5 3.Sf3#
1. ... Lf7,Lg8 2.Lf3 (3.T:e4#) L:d5 3.Sd3#
1. ... Sb~/Sh~ 2.Lc4/Lg4 (2021-03-03)
comment
1. ... Ld7,Lc8 2.Ld3 (3.T:e4#) L:f5 3.Sf3#
1. ... Lf7,Lg8 2.Lf3 (3.T:e4#) L:d5 3.Sd3#
1. ... Sb~/Sh~ 2.Lc4/Lg4 (2021-03-03)
comment
Keywords: Brian Stephenson Collection (50409), Symmetrical position, Asymmetrical solution
Genre: 3#
FEN: 8/8/1n1pbp1n/3PkP2/1N2p2N/2P1R1P1/4B3/4K3
Reprints: B43 ASymmetrie 2013
Input: Brian Stephenson, 2004-08-12
Last update: Felber, Volker, 2021-03-02 more...
Genre: 3#
FEN: 8/8/1n1pbp1n/3PkP2/1N2p2N/2P1R1P1/4B3/4K3
Reprints: B43 ASymmetrie 2013
Input: Brian Stephenson, 2004-08-12
Last update: Felber, Volker, 2021-03-02 more...
1. Th7! droht 2. Th3#
1. ... Ke3 2. Td7 droht 3. Td3#
2. ... f3 3. Td3+ Kf4 4. Td4+ Kg3 5. Sh1+ Kh3,Kh2 6. Th4#
1. ... Ke3 2. Td7 droht 3. Td3#
2. ... f3 3. Td3+ Kf4 4. Td4+ Kg3 5. Sh1+ Kh3,Kh2 6. Th4#
Keywords: Asymmetrical solution, Oneliner, Miniature, Symmetrical position, Model mate
Genre: n#
Computer test: Gustav 3.1s Brute Force
FEN: 8/5R2/5B2/5r2/5p2/5k2/5N2/5K2
Input: Frank Müller, 2010-03-27
Last update: Gunter Jordan, 2022-11-20 more...
Genre: n#
Computer test: Gustav 3.1s Brute Force
FEN: 8/5R2/5B2/5r2/5p2/5k2/5N2/5K2
Input: Frank Müller, 2010-03-27
Last update: Gunter Jordan, 2022-11-20 more...
0. ... Kxc4 1. Db1
0. ... Kxe6 1. Dh7
0. ... Kxe6 1. Dh7
Keywords: Symmetrical position, No legal last move for Black, Aristocrat, Miniature
Genre: Retro
FEN: K7/1N6/4R3/3k4/2R5/5N2/8/7Q
Input: Gerd Wilts, 2010-06-23
Last update: Rainer Staudte, 2022-02-15 more...
Genre: Retro
FEN: K7/1N6/4R3/3k4/2R5/5N2/8/7Q
Input: Gerd Wilts, 2010-06-23
Last update: Rainer Staudte, 2022-02-15 more...
1. Dg8 Sf6! 2. Dg5+ Kh3 3. Kf3 Sf2,Sg3 4. Dxg3#
3. ... Kh2 4. Dg2#
3. ... Sd5,Se4,Sh7,Se8,Sd7 4. Dh6,Dh5#
3. ... Sg8,Sg4,Sh5 4. Dxh5#
3. ... Kh2 4. Dg2#
3. ... Sd5,Se4,Sh7,Se8,Sd7 4. Dh6,Dh5#
3. ... Sg8,Sg4,Sh5 4. Dxh5#
Sally: Nach 1.Dg8!(droht 2 Dg4# und 2. Dxh7#; 1. -Kh3, 2. Dg1;3.D#)
Zwar mehr nur ein Schema, die nach dem 3. weißem Zug ent-
stehende Zugzwangstellung (KD/KSS) dürfte aber nicht uninteressant sein. Nebenbei: ein einfacher Fall von Asymmetie - symmetrisch wäre als Lösung. De4? mit der Doppeldrohung 2. Dxh7# und Dxh1#.
Nr. 35 Schachmatt in 4 und mehr Zügen (Speckmann 1992). (2012-04-28)
Anton Baumann: C+ Gustav 4.2a (2023-02-21)
comment
Zwar mehr nur ein Schema, die nach dem 3. weißem Zug ent-
stehende Zugzwangstellung (KD/KSS) dürfte aber nicht uninteressant sein. Nebenbei: ein einfacher Fall von Asymmetie - symmetrisch wäre als Lösung. De4? mit der Doppeldrohung 2. Dxh7# und Dxh1#.
Nr. 35 Schachmatt in 4 und mehr Zügen (Speckmann 1992). (2012-04-28)
Anton Baumann: C+ Gustav 4.2a (2023-02-21)
comment
Keywords: Aristocrat, Minimal, Symmetrical position
Genre: n#
FEN: 8/7n/8/8/2Q2K1k/8/8/7n
Input: Frank Müller, 2010-08-31
Last update: Frank Müller, 2010-08-31 more...
Genre: n#
FEN: 8/7n/8/8/2Q2K1k/8/8/7n
Input: Frank Müller, 2010-08-31
Last update: Frank Müller, 2010-08-31 more...
26 - P1124575
Bernhard Walter
Hilmar Ebert
11 Rochade Europa , p. 44, 03/1995
Garri Kasparow gewidmet
(3+1)
#13
Bernhard Walter
Hilmar Ebert
11 Rochade Europa , p. 44, 03/1995
Garri Kasparow gewidmet
(3+1)
#13
1. Kc3 Kc1 2. Lg3 Kd1 3. Kd3 Kc1 4. Le5 Kd1 5. Lc3 Kc1 6. Sa3 Kd1 7. Sc4 Kc1 8. Ld2+ Kb1 9. Kc3 Ka2 10. Kc2 Ka1 11. Kb3 Kb1 12. Sa3+ Ka1 13. Lc3#
Keywords: Miniature Collection (0070348), Rex solus (s), Aristocrat, Symmetrical position, Asymmetrical solution
Genre: n#
FEN: 1B6/8/8/1N6/1K6/8/8/1k6
Reprints: C87 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Alfred Pfeiffer, 2013-06-20 more...
Genre: n#
FEN: 1B6/8/8/1N6/1K6/8/8/1k6
Reprints: C87 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Alfred Pfeiffer, 2013-06-20 more...
1. La4 Kxa4 2. Kc5 Ka5 3. Ta8#
1. ... Kc4 2. Td8 Kb4 3. Td4#
1. ... Kc4 2. Td8 Kb4 3. Td4#
Keywords: Miniature Collection (0291414), Symmetrical position, Asymmetrical solution, Oneliner, Rex solus (s), Flight giving sacrifice key
Genre: 3#
FEN: 1R6/8/1K6/1B6/1k6/8/1P6/8
Reprints: B33 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Gunter Jordan, 2023-07-17 more...
Genre: 3#
FEN: 1R6/8/1K6/1B6/1k6/8/1P6/8
Reprints: B33 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Gunter Jordan, 2023-07-17 more...
28 - P1127437
Nikolay S. Zinovyev
11132 Ideal-Mate Review 79 07/2000
ehrende Erwähnung
PR Eugene Albert
(4+2)
#8
Nikolay S. Zinovyev
11132 Ideal-Mate Review 79 07/2000
ehrende Erwähnung
PR Eugene Albert
(4+2)
#8
1. Se3 exf3 2. Tf2 Kg1 3. Sg4 Kh1 4. Kc6 Kg1 5. Kd5 Kh1 6. Ke4 Kg1 7. Kxf3 Kh1 8. Tf1#
Keywords: Miniature Collection (0328461), Minimal (b), Miniature, Flight taking, Oneliner, Symmetrical position, Asymmetrical solution, Ideal mate, Corner mate
Genre: n#
FEN: 8/1K6/8/3N4/4p3/5P2/6R1/7k
Input: Zuncke/Bruder, 2010-09-11
Last update: Gunter Jordan, 2024-02-29 more...
Genre: n#
FEN: 8/1K6/8/3N4/4p3/5P2/6R1/7k
Input: Zuncke/Bruder, 2010-09-11
Last update: Gunter Jordan, 2024-02-29 more...
1. Le3 Kb4 2. Kb2 Ka5 3. Lb5 Kb4 4. Sec6#
Keywords: Miniature Collection (0328000), Rex solus (s), Symmetrical position, Asymmetrical solution
Genre: n#
FEN: 8/N3N3/2B5/8/2k5/8/2K5/2B5
Reprints: C74 ASymmetrie 2013
Input: Zuncke/Bruder, 2010-09-11
Last update: Alfred Pfeiffer, 2013-06-20 more...
Genre: n#
FEN: 8/N3N3/2B5/8/2k5/8/2K5/2B5
Reprints: C74 ASymmetrie 2013
Input: Zuncke/Bruder, 2010-09-11
Last update: Alfred Pfeiffer, 2013-06-20 more...
1. Dh3! (Zugzwang)
1. ... Sd1,Sb2~ 2. Dd3#
1. ... f1=D,f1=T,f1=L 2. De3#
1. ... f1=S 2. Dg2#
1. ... Sd1,Sb2~ 2. Dd3#
1. ... f1=D,f1=T,f1=L 2. De3#
1. ... f1=S 2. Dg2#
B7b2DD0 AS-2
SCHRECKE: C+, popeye 4.85 (2021-05-16)
Teppo Mänttä: Reprints. Fröberg/Hultberg: "Svenska Miniatyrer i urval" (Uppsala/Copenhagen) 1978 and
Giöbel: "Problem och profiler" (Uppsala) 1984. (2021-09-18)
comment
SCHRECKE: C+, popeye 4.85 (2021-05-16)
Teppo Mänttä: Reprints. Fröberg/Hultberg: "Svenska Miniatyrer i urval" (Uppsala/Copenhagen) 1978 and
Giöbel: "Problem och profiler" (Uppsala) 1984. (2021-09-18)
comment
Keywords: Miniature Collection (0011687), Oneliner, Symmetrical position, Asymmetrical solution, Miniature
Genre: 2#
FEN: 8/8/8/8/8/8/1nKBkpQ1/8
Reprints: 17 Bote von der Ybbs 07/02/1930
75 Kurioses Schach 1975
A12 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Mario Richter, 2021-05-16 more...
Genre: 2#
FEN: 8/8/8/8/8/8/1nKBkpQ1/8
Reprints: 17 Bote von der Ybbs 07/02/1930
75 Kurioses Schach 1975
A12 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Mario Richter, 2021-05-16 more...
1. Dg7! droht 2. Kc2 ... 3. Da7#
sowie 2. Kb3 ... 3. Dg1#
1. ... Ka2 2. Dg2+ Kb1,Ka1 3. Db2#
2. ... Ka3 3. Da8#
1. ... Kb1 2. Db7+ Ka2,Ka1 3. Db2#
2. ... Kc1 3. Dh1#
1. ... f3 2. Kc2 ... 3. Da7#
1. ... Sc4 2. Kb3+ Kb1 3. Dg1#
2. ... Sb2 3. Dxb2#
2. ... Se5 3. Dg1#
1. ... Sd3 2. Kc2+ Ka2 3. Da7#
2. ... Sb2 3. Dxb2#
2. ... Se5 3. Da7#
1. ... Sf3 2. Db7 ... 3. Db2#
1. ... Sc6 2. Dg2 ... 3. Db2#
sowie 2. Kb3 ... 3. Dg1#
1. ... Ka2 2. Dg2+ Kb1,Ka1 3. Db2#
2. ... Ka3 3. Da8#
1. ... Kb1 2. Db7+ Ka2,Ka1 3. Db2#
2. ... Kc1 3. Dh1#
1. ... f3 2. Kc2 ... 3. Da7#
1. ... Sc4 2. Kb3+ Kb1 3. Dg1#
2. ... Sb2 3. Dxb2#
2. ... Se5 3. Dg1#
1. ... Sd3 2. Kc2+ Ka2 3. Da7#
2. ... Sb2 3. Dxb2#
2. ... Se5 3. Da7#
1. ... Sf3 2. Db7 ... 3. Db2#
1. ... Sc6 2. Dg2 ... 3. Db2#
Keywords: Miniature Collection (0046866), Symmetrical position
Genre: 3#
FEN: 8/8/3p1Q2/4n3/5p2/2K5/8/k7
Reprints: 557 Wiener Hausfrauen-Zeitung 33, p. 299, 18/08/1889
629 Wiener Hausfrauen-Zeitung 2, p. 15, 11/01/1891
Besedy lidu 1894
352 Schachminiaturen 1902
419 777 Chess Miniatures in Three 1908
7 Idun 02/06/1918
33 Österreichische Schachrundschau 12/1923
3 Arbeiter-Schachzeitung (Chemnitz) 1, p. 15, 01/1925
Input: Felber, Volker, 2010-09-11
Last update: Felber, Volker, 2023-10-20 more...
Genre: 3#
FEN: 8/8/3p1Q2/4n3/5p2/2K5/8/k7
Reprints: 557 Wiener Hausfrauen-Zeitung 33, p. 299, 18/08/1889
629 Wiener Hausfrauen-Zeitung 2, p. 15, 11/01/1891
Besedy lidu 1894
352 Schachminiaturen 1902
419 777 Chess Miniatures in Three 1908
7 Idun 02/06/1918
33 Österreichische Schachrundschau 12/1923
3 Arbeiter-Schachzeitung (Chemnitz) 1, p. 15, 01/1925
Input: Felber, Volker, 2010-09-11
Last update: Felber, Volker, 2023-10-20 more...
32 - P1139236
Gunter Jordan
69 Die Schwalbe 238, p. 193, 08/2009
Klaus-Peter-Zuncke-Gedenkturnier
3. Preis
PR Martin Minski
(4+3)
#4
2.1...
Gunter Jordan
69 Die Schwalbe 238, p. 193, 08/2009
Klaus-Peter-Zuncke-Gedenkturnier
3. Preis
PR Martin Minski
(4+3)
#4
2.1...
1. Ld5-f7+!
1. Ld5-c6+!
1. Ld5-c6+!
Gunter Jordan: Preisrichter Martin Minski: "„Gedenkkreuz“ mit thematischer Doppelsetzung in Zweispännerform und das als Miniatur! Die thematische Verführung 1.Le6+? Ke4 2.Tf7 Kf3 3.Ld5+ Kg4 4.Tg7+ Kh~ scheitert daran, dass der sK auf der rechten Seite zu viel Platz besitzt. Deshalb besser: 1.Lc6+! Kc4 2.Tb7 (droht 3.Txb5 nebst 4.Tb4#) Kb3 3.Ld5+ Ka4 4.Ta7# mit Mustermatt. Die zweite asymmetrische Lösung lautet: 1.Lf7+ Ke4 2.Ke2 b4 3.Lh5 (droht 4.Lf3#) f4 4.Lg6#. Dieser Läufertanz ist auf der linken Seite aus Platzgründen nicht möglich: 1.Lb7? Kc4 2.Kc2 f4 3.L?." (2012-03-17)
SCHRECKE: C+, Gustav 4.1d, Brute Force (2021-02-01)
comment
SCHRECKE: C+, Gustav 4.1d, Brute Force (2021-02-01)
comment
Keywords: Miniature Collection (0356029), Symmetrical position, Asymmetrical solution, Miniature, Checking key, Symbol problem (Kreuz)
Genre: n#
FEN: 8/3R4/8/1p1B1p2/3k4/3N4/3K4/8
Reprints: C108 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Gunter Jordan, 2023-01-10 more...
Genre: n#
FEN: 8/3R4/8/1p1B1p2/3k4/3N4/3K4/8
Reprints: C108 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Gunter Jordan, 2023-01-10 more...
1. Sc5+ Kc6 2. Kc4 Kb6 3. Lb8 Ka5,Kc6 4. Lc7,Td6#
1. ... Ke8,Kd8,Kc8 2. Tf5 ... 3. Tf8#
1. ... Ke8,Kd8,Kc8 2. Tf5 ... 3. Tf8#
Keywords: Miniature Collection (0075796), Symmetrical position, Asymmetrical solution, Rex solus (s), Aristocrat, Oneliner
Genre: n#
FEN: 8/3k4/3B4/3R4/3K4/3N4/8/8
Input: Felber, Volker, 2010-09-11
Last update: Alfred Pfeiffer, 2014-03-26 more...
Genre: n#
FEN: 8/3k4/3B4/3R4/3K4/3N4/8/8
Input: Felber, Volker, 2010-09-11
Last update: Alfred Pfeiffer, 2014-03-26 more...
1. Sf2 Kf4 2. Tc3 Kf5 3. Tf3#
T12T AS/3
Sally (2018-12-27): Asymmetrie : der zur (hier: schrägen) Symmetrieachse analoge Zug des [Sh7] (das wäre 1. [Si5]) ist wegen Brettüberschreitung nicht möglich.
in der Miniature Collection auch gespiegelt (wKd2-sKf4 als (0049342)
SCHRECKE: C+, popeye 4.85 (2021-05-16)
comment
Sally (2018-12-27): Asymmetrie : der zur (hier: schrägen) Symmetrieachse analoge Zug des [Sh7] (das wäre 1. [Si5]) ist wegen Brettüberschreitung nicht möglich.
in der Miniature Collection auch gespiegelt (wKd2-sKf4 als (0049342)
SCHRECKE: C+, popeye 4.85 (2021-05-16)
comment
Keywords: Miniature Collection (0329456), Symmetrical position, Asymmetrical solution, Rex solus (s), Aristocrat, Miniature
Genre: 3#
FEN: 2R5/3K3N/4R3/5k2/8/3N4/8/8
Input: Zuncke/Bruder, 2010-09-11
Last update: Mario Richter, 2021-05-16 more...
Genre: 3#
FEN: 2R5/3K3N/4R3/5k2/8/3N4/8/8
Input: Zuncke/Bruder, 2010-09-11
Last update: Mario Richter, 2021-05-16 more...
1. 0-0 Kxe7 2. Sb7 Ke8 3. Tbe1#
Keywords: Miniature Collection (0051782), Rex solus (s), Symmetrical position, Asymmetrical solution, Castling, Castling key
Genre: 3#
FEN: 3NkN2/4P3/8/8/8/8/8/1R2K2R
Reprints: B38 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Gunter Jordan, 2021-12-28 more...
Genre: 3#
FEN: 3NkN2/4P3/8/8/8/8/8/1R2K2R
Reprints: B38 ASymmetrie 2013
Input: Felber, Volker, 2010-09-11
Last update: Gunter Jordan, 2021-12-28 more...
1. Sa4 Ka1 2. Sc2+ Ka2 3. Tb2#
Keywords: Miniature Collection (0324724), Symmetrical position, Asymmetrical solution
Genre: 3#
FEN: 8/8/4K3/1PN5/3N4/1R1P4/k7/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Rainer Staudte, 2022-12-08 more...
Genre: 3#
FEN: 8/8/4K3/1PN5/3N4/1R1P4/k7/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Rainer Staudte, 2022-12-08 more...
1. Lc7 Kf6 2. Ld8+ Kg6 3. Tbg5+ Dxg5 4. Txg5+ Kh6 5. Kf7 e3 6. Tg4 Kh5 7. Th4#
Keywords: Miniature Collection (0292553), Symmetrical position, Asymmetrical solution, Symbol problem (Kreuz)
Genre: n#
FEN: 4K3/8/4k3/1R2B2R/4p3/4q3/8/8
Reprints: C68 ASymmetrie 2013
Input: Felber, Volker, 2010-09-12
Last update: Gunter Jordan, 2022-08-29 more...
Genre: n#
FEN: 4K3/8/4k3/1R2B2R/4p3/4q3/8/8
Reprints: C68 ASymmetrie 2013
Input: Felber, Volker, 2010-09-12
Last update: Gunter Jordan, 2022-08-29 more...
38 - P1157291
Werner Speckmann
Schach-Echo 1941
(4+3) cooked
#2
a) Diagramm
b) nach Schlüsselzug von a)
Werner Speckmann
Schach-Echo 1941
(4+3) cooked
#2
a) Diagramm
b) nach Schlüsselzug von a)
a) 1. Kg4
b) 1. Kg5
Cook: b) 1. Kh6
1. Kf6
b) 1. Kg5
Cook: b) 1. Kh6
1. Kf6
B12S ASc2
vf: a1<>h1, Speckmann, 1943, Schach-Echo sowie a1<>a8, John A. White, 1879, Canadian Illustrated News (P1160494)
'Elementary Electronics': "This pyramid-shaped problem has a sort of pinwheel solution and was created by Dr. Werner Speckmann, Germany, a well-known composer and collector of two movers."
milan: alles nach links 1.Kb4 1.Kb5 +set play h#2 change kings 1.Kb4 Lb3 2.Ka3 Sec2# M.Frelih (2023-03-30)
comment
vf: a1<>h1, Speckmann, 1943, Schach-Echo sowie a1<>a8, John A. White, 1879, Canadian Illustrated News (P1160494)
'Elementary Electronics': "This pyramid-shaped problem has a sort of pinwheel solution and was created by Dr. Werner Speckmann, Germany, a well-known composer and collector of two movers."
milan: alles nach links 1.Kb4 1.Kb5 +set play h#2 change kings 1.Kb4 Lb3 2.Ka3 Sec2# M.Frelih (2023-03-30)
comment
Keywords: Miniature Collection (0024111), anticipated (P1160494), Symmetrical position, Asymmetrical solution, Aristocrat, Miniature
Genre: 2#
FEN: 8/8/8/8/8/5K2/4nBn1/3N1k1N
Reprints: 25 Elementary Electronics 07-08/1970
79 Kurioses Schach 1975
A3A ASymmetrie 2013
Input: Felber, Volker, 2010-09-12
Last update: Rainer Staudte, 2023-03-11 more...
Genre: 2#
FEN: 8/8/8/8/8/5K2/4nBn1/3N1k1N
Reprints: 25 Elementary Electronics 07-08/1970
79 Kurioses Schach 1975
A3A ASymmetrie 2013
Input: Felber, Volker, 2010-09-12
Last update: Rainer Staudte, 2023-03-11 more...
1. Le1 Kg5 2. Dh7 Ld8 3. Lh4#
1. ... Ke5 2. Dd7 Lh8 3. Lc3#
1. ... Ke5 2. Dd7 Lh8 3. Lc3#
L10 ASc3
Frank Müller: Im Original stehen die Steine in der c-Linie !! (2016-01-23)
SCHRECKE: C+, popeye 4.85 (2021-05-19)
comment
Frank Müller: Im Original stehen die Steine in der c-Linie !! (2016-01-23)
SCHRECKE: C+, popeye 4.85 (2021-05-19)
comment
Keywords: Miniature Collection (0321725), Oneliner, Symmetrical position, Asymmetrical solution
Genre: 3#
FEN: 8/5Q2/5b2/5k2/5p2/5K2/5B2/8
Reprints: B4 ASymmetrie 2013
Input: Zuncke/Bruder, 2010-09-12
Last update: Alfred Pfeiffer, 2016-01-23 more...
Genre: 3#
FEN: 8/5Q2/5b2/5k2/5p2/5K2/5B2/8
Reprints: B4 ASymmetrie 2013
Input: Zuncke/Bruder, 2010-09-12
Last update: Alfred Pfeiffer, 2016-01-23 more...
1. Ke6? ... Kg8!;
1. Kg6? ... Ke8!;
1. Dc7! (Zugzwang) ... Ke8/Kg8 2. De7/Dg7
1. Kg6? ... Ke8!;
1. Dc7! (Zugzwang) ... Ke8/Kg8 2. De7/Dg7
Keywords: Miniature Collection (0247216), Symmetrical position, Asymmetrical solution
Genre: 2#
FEN: 5k2/8/5P2/5K2/5Q2/8/8/8
Input: Felber, Volker, 2010-09-12
Last update: Rainer Staudte, 2022-12-08 more...
Genre: 2#
FEN: 5k2/8/5P2/5K2/5Q2/8/8/8
Input: Felber, Volker, 2010-09-12
Last update: Rainer Staudte, 2022-12-08 more...
Qe ASc3
vf: Valerian Onitiu, 07.05.1933, Allgemeine Zeitung Chemnitz
Alfred Pfeiffer: horizontal gespiegelt: W. Heinrich, Der Feierabend 1961 =P1136449 (2013-06-13)
athulin: From the Chess Player's Chronicle 1885 tourney, entered under the
motto "Garvest II". Tourney may have been abandoned, as no report has been
found, so motto identity was never revealed. (2022-11-09)
SCHRECKE: C+, popeye 4.87 (2022-11-09)
comment
vf: Valerian Onitiu, 07.05.1933, Allgemeine Zeitung Chemnitz
Alfred Pfeiffer: horizontal gespiegelt: W. Heinrich, Der Feierabend 1961 =P1136449 (2013-06-13)
athulin: From the Chess Player's Chronicle 1885 tourney, entered under the
motto "Garvest II". Tourney may have been abandoned, as no report has been
found, so motto identity was never revealed. (2022-11-09)
SCHRECKE: C+, popeye 4.87 (2022-11-09)
comment
Keywords: Miniature Collection (0321861), Oneliner, Symmetrical position
Genre: 3#
FEN: 8/5K2/8/5k2/8/5P2/5P2/5Q2
Reprints: B6 ASymmetrie 2013
Input: Zuncke/Bruder, 2010-09-12
Last update: Alfred Pfeiffer, 2013-06-13 more...
Genre: 3#
FEN: 8/5K2/8/5k2/8/5P2/5P2/5Q2
Reprints: B6 ASymmetrie 2013
Input: Zuncke/Bruder, 2010-09-12
Last update: Alfred Pfeiffer, 2013-06-13 more...
* 1. ... Se4 2. Dh3#
* 1. ... Sg4 2. Dd3#
1. De2? droht 2. De6#
1. ... Se4 2. Di2#???
1. Dg2! droht 2. Dg6#
1. ... f3 2. Dxf3#
1. ... Sg4 2. Dc2#
* 1. ... Sg4 2. Dd3#
1. De2? droht 2. De6#
1. ... Se4 2. Di2#???
1. Dg2! droht 2. Dg6#
1. ... f3 2. Dxf3#
1. ... Sg4 2. Dc2#
Keywords: Miniature Collection (0025905), Symmetrical position, Asymmetrical solution, Oneliner
Genre: 2#
FEN: 8/5K2/5B2/5k2/5p2/5Q2/5n2/8
Reprints: A30 ASymmetrie 2013
Input: Felber, Volker, 2010-09-12
Last update: Felber, Volker, 2014-05-16 more...
Genre: 2#
FEN: 8/5K2/5B2/5k2/5p2/5Q2/5n2/8
Reprints: A30 ASymmetrie 2013
Input: Felber, Volker, 2010-09-12
Last update: Felber, Volker, 2014-05-16 more...
1. Dd7 h6+ 2. Kxh6 Kf8 3. Dd8#
1. ... Kg7 2. Le5+ Kf8 3. Dd8#
1. ... Kg7 2. Le5+ Kf8 3. Dd8#
Keywords: Miniature Collection (0323441), Symmetrical position
Genre: 3#
FEN: 6k1/5p1p/6p1/6K1/6Q1/6B1/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2020-10-13 more...
Genre: 3#
FEN: 6k1/5p1p/6p1/6K1/6Q1/6B1/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: A.Buchanan, 2020-10-13 more...
1. Sh4
ASb3 SfS m
Henrik Juel: C+ Popeye 4.61 (except for double mate threat) (2022-12-08)
Henrik Juel: 1.Sh4 thr. 2.Sh5 thr. 3.Sxh6,Se7# (2022-12-08)
comment
Henrik Juel: C+ Popeye 4.61 (except for double mate threat) (2022-12-08)
Henrik Juel: 1.Sh4 thr. 2.Sh5 thr. 3.Sxh6,Se7# (2022-12-08)
comment
Keywords: Miniature Collection (0324736), Symmetrical position, Asymmetrical solution
Genre: 3#
FEN: 6k1/6P1/5pKp/8/8/8/6N1/6b1
Input: Zuncke/Bruder, 2010-09-12
Last update: Rainer Staudte, 2022-12-08 more...
Genre: 3#
FEN: 6k1/6P1/5pKp/8/8/8/6N1/6b1
Input: Zuncke/Bruder, 2010-09-12
Last update: Rainer Staudte, 2022-12-08 more...
1. ... Kxg4 2. Kxg6! Kxg3 3. Th5 Kg2 4. Tg5+ Kh2,Kh1,Kh3 5. Th7#
Keywords: Miniature Collection (0344445), No legal last move for Black, Symmetrical position, Minimal, Miniature
Genre: n#, Retro
FEN: 8/5RKR/6p1/6k1/6P1/6P1/8/8
Reprints: 69 Jitvesha schachova Miniatjura [Davydjuk] 1992
Input: Zuncke/Bruder, 2010-09-12
Last update: James Malcom, 2021-01-23 more...
Genre: n#, Retro
FEN: 8/5RKR/6p1/6k1/6P1/6P1/8/8
Reprints: 69 Jitvesha schachova Miniatjura [Davydjuk] 1992
Input: Zuncke/Bruder, 2010-09-12
Last update: James Malcom, 2021-01-23 more...
1. Lc5+! Sd4+ 2. Dxd4+ Ke2! 3. Dxe4+ Kf1 4. Dxd3+ Ke1 5. De3+ Kd1 6. Dxf3+ Ke1 7. Lxf2+ Kf1 8. Le3+ Ke1 9. Df2+ Kd1 10. Dxd2#
2. ... Kf4? 3. De5+ Kg4 4. Lxf2 nebst matt
"Symmetrische Glocke mit asymmetrischer Lösung." [PH] Nach 1.Lg5+? Sf4+ 2.Dxf4+ Kd4 3.De5+ Kc4 4.Lxd2 Kb3! entkommt der sK. Als "reichlich Schachorgelei" empfand dies Eberhard Schulze. Ja, aber die Eindeutigkeit ist hier erstaunlich! (Lösungsbesprechung)
2. ... Kf4? 3. De5+ Kg4 4. Lxf2 nebst matt
"Symmetrische Glocke mit asymmetrischer Lösung." [PH] Nach 1.Lg5+? Sf4+ 2.Dxf4+ Kd4 3.De5+ Kc4 4.Lxd2 Kb3! entkommt der sK. Als "reichlich Schachorgelei" empfand dies Eberhard Schulze. Ja, aber die Eindeutigkeit ist hier erstaunlich! (Lösungsbesprechung)
Keywords: Asymmetrical solution, Symbol problem, Symmetrical position, Checking key, Perpetual check
FEN: 8/4B3/4K3/4Q3/4p3/3pkp2/2ppnpp1/8
Input: Gunter Jordan, 2011-07-04
Last update: Gunter Jordan, 2021-07-14 more...
FEN: 8/4B3/4K3/4Q3/4p3/3pkp2/2ppnpp1/8
Input: Gunter Jordan, 2011-07-04
Last update: Gunter Jordan, 2021-07-14 more...
1. Ke6 Sd4+ 2. Kf7 Se6 3. Kg8 Sh6#
Keywords: Indian, Vertical Cylinder, Aristocrat, Miniature, Symmetrical position, Asymmetrical solution
Genre: Fairies
FEN: K7/1N6/2N5/3k4/8/8/8/8
Input: Hans Gruber, 2011-10-09
Last update: Alfred Pfeiffer, 2021-10-19 more...
Genre: Fairies
FEN: K7/1N6/2N5/3k4/8/8/8/8
Input: Hans Gruber, 2011-10-09
Last update: Alfred Pfeiffer, 2021-10-19 more...
Keywords: Symmetrical position, Homebase (s), Variation Asymmetry, corner to corner (D), Model mate
Genre: 3#
FEN: 4k3/1pp3pp/4K3/8/4P3/3P1P2/2P1Q1P1/8
Reprints: 69 Kurioses Schach 1975
Input: Mario Richter, 2012-01-06
Last update: Gunter Jordan, 2023-07-05 more...
Genre: 3#
FEN: 4k3/1pp3pp/4K3/8/4P3/3P1P2/2P1Q1P1/8
Reprints: 69 Kurioses Schach 1975
Input: Mario Richter, 2012-01-06
Last update: Gunter Jordan, 2023-07-05 more...
49 - P1229697
Jan Hartong
Bulletin Ouvrier des Echecs 12/1948
2. Lob im Zwillingsturnier
(4+3)
#2
a) Diagramm
b) alles eine Spalte nach rechts
Jan Hartong
Bulletin Ouvrier des Echecs 12/1948
2. Lob im Zwillingsturnier
(4+3)
#2
a) Diagramm
b) alles eine Spalte nach rechts
a) 1. Dh4! droht 2. Dh8#
1. ... d6,d5 2. Da4#
1. ... f6,f5 2. Dh5#
b) 1. Da1! droht 2. Da8#
1. ... e6,e5 2. Da3#
1. ... g6,g5 2. Dh8#
1. ... d6,d5 2. Da4#
1. ... f6,f5 2. Dh5#
b) 1. Da1! droht 2. Da8#
1. ... e6,e5 2. Da3#
1. ... g6,g5 2. Dh8#
Duplicate Diagram: P1148644, P1148644
a) vollständig vorweggenommen durch P1148644
SCHRECKE: a)+b): C+, popeye 4.87
Die FEN ist Stellung b) (2022-09-21)
comment
SCHRECKE: a)+b): C+, popeye 4.87
Die FEN ist Stellung b) (2022-09-21)
comment
Keywords: Symmetrical position, anticipated (P1148644), Asymmetrical solution, Miniature
Genre: 2#
FEN: 5k2/4pPp1/8/8/8/5R2/5K2/5Q2
Reprints: FIDE Album 1945-1955 1964
71,72 Kurioses Schach 1975
2 El Ajedrez (revista técnica de ajedrez) 0 11/1979
A27 ASymmetrie 2013
Input: Mario Richter, 2012-01-07
Last update: Mario Richter, 2022-09-20 more...
Genre: 2#
FEN: 5k2/4pPp1/8/8/8/5R2/5K2/5Q2
Reprints: FIDE Album 1945-1955 1964
71,72 Kurioses Schach 1975
2 El Ajedrez (revista técnica de ajedrez) 0 11/1979
A27 ASymmetrie 2013
Input: Mario Richter, 2012-01-07
Last update: Mario Richter, 2022-09-20 more...
50 - P1239714
Frank Fiedler
4621 Freie Presse (Chemnitz) 14/12/2007
Den Schachfreunden vom HSV Eintracht Seiffen und den das Schach sponsorenden Seiffener Handwerkskünstlern gewidmet.
(5+2)
#5
Frank Fiedler
4621 Freie Presse (Chemnitz) 14/12/2007
Den Schachfreunden vom HSV Eintracht Seiffen und den das Schach sponsorenden Seiffener Handwerkskünstlern gewidmet.
(5+2)
#5
1. Sa3! Kd2 2. Scxe2 Kd1 3. Kd3 Ke1 4. Sc2+ Kd1 5. Sf2#
2. ... Ke1 3. Ke3 Kd1 4. Sf2+ Ke1 5. Sc2#
2. ... Ke1 3. Ke3 Kd1 4. Sf2+ Ke1 5. Sc2#
Keywords: Obvious promotion, Symmetrical position, Symbol problem (Schwibbogen), Asymmetrical solution
Genre: n#
FEN: 8/8/8/8/4K3/2N3N1/4p3/1N2k2N
Input: Felber, Volker, 2012-05-26
Last update: Alfred Pfeiffer, 2017-08-02 more...
Genre: n#
FEN: 8/8/8/8/4K3/2N3N1/4p3/1N2k2N
Input: Felber, Volker, 2012-05-26
Last update: Alfred Pfeiffer, 2017-08-02 more...
1. hxg1=L axb8=L 2. Ta7 Th2 3. gxh2 bxa7 4. h1=T a8=T 5. h2 a7==
Cook: 1. hxg1=L Th2 2. gxh2 axb8=L 3. Ta7 bxa7 4. h1=T a8=T 5. h2 a7==
Cook: 1. hxg1=L Th2 2. gxh2 axb8=L 3. Ta7 bxa7 4. h1=T a8=T 5. h2 a7==
t/Figuren-Kranz 3×3 2-fach a6c8 und f1h3
Bernd Schwarzkopf: Popeye 4.79 findet eine Zugumstellung:
1.hxg1=L Th2 2.gxh2 axb8=L 3.Ta7 bxa7 4.h1=T a8=T 5.h2 a7==
1.hxg1=L axb8=L 2.Ta7 Th2 3.gxh2 bxa7 4.h1=T a8=T 5.h2 a7==
(Auch Lösungsprogramme lernen dazu!) (2018-09-06)
Henrik Juel: Popeye 4.61 also found the cook (in a couple of minutes)
Maybe the original C+ label is just an error; I see no reason why Popeye 3.56 should be different in this respect (2018-09-06)
James Malcom: Fixed. (2020-12-31)
A.Buchanan: "Under"-promotion is meaningless - except of course for direct mates and endgame studies. I always remove it if I have the time (2020-12-31)
Hans-Jürgen Manthey: Total Kaputt, jeder der 12 möglichen Züge ist eine Lösung:
1. fxLg1D,T,L,S Tx~g1 2. h1L cxLb8L 3. g2+ Kf2 4. Txa7 Lh2 5. Tc7 bxTc7=
2. h1S Tg2 3. f2 axLb8D,T,L,S 4. Tx~b8 a7 5. h2 axTb8S,L=
2. f2 Th1 3. Txa7 cxLb8L 4. T~7 Lxg3 5. Tc7 bxTc7=
1. hxg1D,T,L,S Tx~g1 2. g2+ Kxf2 3. h2 Kxf3 4. h1L axLb8S 5. Txa6 SxTa6=
1. g2+ Kxf2 2. gxTh1D Lxh2 3. Da1 axLb8S 4. Dxa6 SxDa6 5. Ta7 bxTa7=
1. Txa7 Lxf2 2. gxLf2 Kxf2 3. Txa6 Txh2 4. Ta7 cxLb8 5. Tc7 LxTc7=
1. Lxa7 Lxf2 2. g2+ Ke1 3. g1L bxLa7 4. Lxf2+ Kxf2 5. Tb8 aXTb8L=
1. Lxc7 Lxf2 2. gxLf2 Kxf2 3. Lg3+ Kxf3 4. Lc7 bxLc7 5. Tb8 axTb8L=
mit sehr vielen Dualen
Kürzer zB: in 4 Zügen:
1. fxLg1L cxLb8L 2. f2 Lxg3 3. Tb8 Lc7 4.Txb6 LxTb6=
1. hxLg1L cxLb8L 2. Lh2 Lxg3 3. Txa7 LxLh2 4.Ta7-c7 bxc7=
1. Bg2+ Kxf2 2.Txa7 Txh2 3.Tb7 c7xLb8~ 4.KxLb8 ax/cxb7=
1. Txa7 Lxf2 2.Bxf2 Kxf2 3.Tb7 c7xLb8~ 4.KxLb8 ax/cxb7=
1. Lxa7,c7 Lxf2,h2 2.gxLf2,h2 bxLa7,c7 3.Tb8 axTb8L=
auch mit vielen Dualen
gar in schon 3 Zügen:
1. Txa7 Lxf2,h2 2. g3xLf2,h2 cxLb8L 3.Tc7 bx/LxTc7=
1...cxb8L 2.Tc7 Lxf2,xh2 3.Bg3xLf2,h2 b6x/Lxc7=
1.Lb8xa7 Lxf2,xh2 2.Bg3xLf2,xh2 bxLa7 3.Tb8 axTb8L=
2.Tb8 bxLa7 3.g3xLf2,h2 axb8L=
1...bxLa7 2.Tb8 Lxf2,h2 3.gxLf2,h2 a7xb8L=
1.Lxc7 Lg1xf2,h2 2.Bg3Lxf2,h2 bxLc7 3.Tb8 axTb8L=
2.Tb8 bxLc7 3.gxLf2,h2 axTb8L=
2...axTb8L 3.gxLf2,h2 bx/LxLc7=
1...bxc7 2.Tb8 Lxf2,h2 3.gxLf2,h2 axTb8L= (2020-12-31)
SCHRECKE: Hans-Jürgen, die Forderung lautet h==5 (nicht h=5!) (2020-12-31)
Hans-Jürgen Manthey: OHHH Im so Sorry (2021-01-02)
comment
Bernd Schwarzkopf: Popeye 4.79 findet eine Zugumstellung:
1.hxg1=L Th2 2.gxh2 axb8=L 3.Ta7 bxa7 4.h1=T a8=T 5.h2 a7==
1.hxg1=L axb8=L 2.Ta7 Th2 3.gxh2 bxa7 4.h1=T a8=T 5.h2 a7==
(Auch Lösungsprogramme lernen dazu!) (2018-09-06)
Henrik Juel: Popeye 4.61 also found the cook (in a couple of minutes)
Maybe the original C+ label is just an error; I see no reason why Popeye 3.56 should be different in this respect (2018-09-06)
James Malcom: Fixed. (2020-12-31)
A.Buchanan: "Under"-promotion is meaningless - except of course for direct mates and endgame studies. I always remove it if I have the time (2020-12-31)
Hans-Jürgen Manthey: Total Kaputt, jeder der 12 möglichen Züge ist eine Lösung:
1. fxLg1D,T,L,S Tx~g1 2. h1L cxLb8L 3. g2+ Kf2 4. Txa7 Lh2 5. Tc7 bxTc7=
2. h1S Tg2 3. f2 axLb8D,T,L,S 4. Tx~b8 a7 5. h2 axTb8S,L=
2. f2 Th1 3. Txa7 cxLb8L 4. T~7 Lxg3 5. Tc7 bxTc7=
1. hxg1D,T,L,S Tx~g1 2. g2+ Kxf2 3. h2 Kxf3 4. h1L axLb8S 5. Txa6 SxTa6=
1. g2+ Kxf2 2. gxTh1D Lxh2 3. Da1 axLb8S 4. Dxa6 SxDa6 5. Ta7 bxTa7=
1. Txa7 Lxf2 2. gxLf2 Kxf2 3. Txa6 Txh2 4. Ta7 cxLb8 5. Tc7 LxTc7=
1. Lxa7 Lxf2 2. g2+ Ke1 3. g1L bxLa7 4. Lxf2+ Kxf2 5. Tb8 aXTb8L=
1. Lxc7 Lxf2 2. gxLf2 Kxf2 3. Lg3+ Kxf3 4. Lc7 bxLc7 5. Tb8 axTb8L=
mit sehr vielen Dualen
Kürzer zB: in 4 Zügen:
1. fxLg1L cxLb8L 2. f2 Lxg3 3. Tb8 Lc7 4.Txb6 LxTb6=
1. hxLg1L cxLb8L 2. Lh2 Lxg3 3. Txa7 LxLh2 4.Ta7-c7 bxc7=
1. Bg2+ Kxf2 2.Txa7 Txh2 3.Tb7 c7xLb8~ 4.KxLb8 ax/cxb7=
1. Txa7 Lxf2 2.Bxf2 Kxf2 3.Tb7 c7xLb8~ 4.KxLb8 ax/cxb7=
1. Lxa7,c7 Lxf2,h2 2.gxLf2,h2 bxLa7,c7 3.Tb8 axTb8L=
auch mit vielen Dualen
gar in schon 3 Zügen:
1. Txa7 Lxf2,h2 2. g3xLf2,h2 cxLb8L 3.Tc7 bx/LxTc7=
1...cxb8L 2.Tc7 Lxf2,xh2 3.Bg3xLf2,h2 b6x/Lxc7=
1.Lb8xa7 Lxf2,xh2 2.Bg3xLf2,xh2 bxLa7 3.Tb8 axTb8L=
2.Tb8 bxLa7 3.g3xLf2,h2 axb8L=
1...bxLa7 2.Tb8 Lxf2,h2 3.gxLf2,h2 a7xb8L=
1.Lxc7 Lg1xf2,h2 2.Bg3Lxf2,h2 bxLc7 3.Tb8 axTb8L=
2.Tb8 bxLc7 3.gxLf2,h2 axTb8L=
2...axTb8L 3.gxLf2,h2 bx/LxLc7=
1...bxc7 2.Tb8 Lxf2,h2 3.gxLf2,h2 axTb8L= (2020-12-31)
SCHRECKE: Hans-Jürgen, die Forderung lautet h==5 (nicht h=5!) (2020-12-31)
Hans-Jürgen Manthey: OHHH Im so Sorry (2021-01-02)
comment
Keywords: Promotion (LlTt), Symmetrical position, Symmetrical solution
Genre: Fairies
Computer test: %Popeye UNIX32-Version 3.56
FEN: rbk5/P1P5/PPP5/8/8/5ppp/5p1p/5KBR
Input: Erich Bartel, 2012-09-23
Last update: A.Buchanan, 2020-12-31 more...
Genre: Fairies
Computer test: %Popeye UNIX32-Version 3.56
FEN: rbk5/P1P5/PPP5/8/8/5ppp/5p1p/5KBR
Input: Erich Bartel, 2012-09-23
Last update: A.Buchanan, 2020-12-31 more...
52 - P1256398
Arnold Beine
15063 Die Schwalbe 252 12/2011
Martin Minski und Michael Schlosser gewidmet
(4+2)
h#14
b) alles ein Feld nach rechts (a1 = b1)
Doppellängstzüger; KöKo; Circe Rex incl.
Arnold Beine
15063 Die Schwalbe 252 12/2011
Martin Minski und Michael Schlosser gewidmet
(4+2)
h#14
b) alles ein Feld nach rechts (a1 = b1)
Doppellängstzüger; KöKo; Circe Rex incl.
a) 1. Nf3 Kf6 2. Nb5 g6 3. Nf7 Ke7 4. Nb5 Kd6 5. Nf3 Kd5 6. Nb5 Ke6 7. Nf7 gxf7[+sNf1] 8. Nxe3[+wBe2] Kf5 9. Nf1 e4 10. Nd5 Ke6 11. Ne7 Kd7 12. Nd5 Ke8 13. Nb4 f8=D 14. Nf6 Dd6#
b) 1. Ne3 Ke6 2. Nxd5[+wBd2] d4 3. Nf6 Kf7 4. Ng4 fxg4[+sNg1] 5. Ne5 gxf5[+sKe8] 6. Ng6 hxg6[+sNg1] 7. Ne5 Ke6 8. Nf7 gxf7[+sNf1] 9. Nd5 Kd7+ 10. Kf8 Ke8 11. Nf4 f6 12. Nd8 Kd7 13. Nc6 Ke8 14. Ng8 fxg8=D[+sNg1]#
b) 1. Ne3 Ke6 2. Nxd5[+wBd2] d4 3. Nf6 Kf7 4. Ng4 fxg4[+sNg1] 5. Ne5 gxf5[+sKe8] 6. Ng6 hxg6[+sNg1] 7. Ne5 Ke6 8. Nf7 gxf7[+sNf1] 9. Nd5 Kd7+ 10. Kf8 Ke8 11. Nf4 f6 12. Nd8 Kd7 13. Nc6 Ke8 14. Ng8 fxg8=D[+sNg1]#
Keywords: Circe, Köko, Maximummer (Doppel-), Symmetrical position, Asymmetrical solution
Pieces: = Nightrider (N)
Genre: Fairies
FEN: 8/4K3/8/2P1k1P1/8/4P3/8/4*2n3
Input: Gerd Wilts, 2012-12-13
Last update: Arnold Beine, 2022-12-18 more...
Pieces: = Nightrider (N)
Genre: Fairies
FEN: 8/4K3/8/2P1k1P1/8/4P3/8/4*2n3
Input: Gerd Wilts, 2012-12-13
Last update: Arnold Beine, 2022-12-18 more...
1. Kc6 Kb8 2. Kb6 Sd6 3. Db4 Sc8+ 4. Kc6+ Sb6 5. Dxb6+ Kc8 6. Dc7#
5. ... Ka8 6. Db7#
1. ... Ka7 2. Kc7 Sc5 3. De7 usw.
5. ... Ka8 6. Db7#
1. ... Ka7 2. Kc7 Sc5 3. De7 usw.
Keywords: Aristocrat, Minimal, Symmetrical position, Symmetrical solution, Oneliner
Genre: n#
FEN: k7/1n6/8/3K4/4Q3/5n2/8/8
Input: Frank Müller, 2013-01-20
Last update: Felber, Volker, 2013-05-24 more...
Genre: n#
FEN: k7/1n6/8/3K4/4Q3/5n2/8/8
Input: Frank Müller, 2013-01-20
Last update: Felber, Volker, 2013-05-24 more...
1. Td6? Da2!
1. Th6! droht 2. Tf6#
1. ... gxh4 2. Th5+ Sg5+ 3. Txg5+ Kxg5 4. Txe5#
1. Th6! droht 2. Tf6#
1. ... gxh4 2. Th5+ Sg5+ 3. Txg5+ Kxg5 4. Txe5#
Keywords: Symmetrical position
Genre: n#
FEN: 5B2/5K2/8/3RpkpR/3P1p1P/3P1n1P/5q2/8
Input: Felber, Volker, 2013-02-21
Last update: Dieter Berlin, 2021-12-09 more...
Genre: n#
FEN: 5B2/5K2/8/3RpkpR/3P1p1P/3P1n1P/5q2/8
Input: Felber, Volker, 2013-02-21
Last update: Dieter Berlin, 2021-12-09 more...
1. Dh1! g8=T 2. Kg1 Tf8 3. g2 Txf2=
Keywords: Symmetrical position, Asymmetrical solution
Genre: Fairies
FEN: 8/6P1/6K1/8/6N1/6p1/5pkp/6q1
Input: Alfred Pfeiffer, 2013-06-29
Last update: Alfred Pfeiffer, 2014-11-07 more...
Genre: Fairies
FEN: 8/6P1/6K1/8/6N1/6p1/5pkp/6q1
Input: Alfred Pfeiffer, 2013-06-29
Last update: Alfred Pfeiffer, 2014-11-07 more...
1. Le3! Kb2 2. Kc4 Ka3 3. Sd3 Ka4 4. Ld2 Ka3 5. Lb4+ Ka2 6. Kc3 Kb1 7. Kb3 Ka1 8. Kc2 Ka2 9. Sc1+ Ka1 10. Lc3#
Keywords: Aristocrat, Oneliner, Symmetrical position
Genre: n#
FEN: 8/8/1B6/1K6/1N6/8/8/1k6
Input: Rainer Staudte, 2013-08-22
Last update: Alfred Pfeiffer, 2013-08-22 more...
Genre: n#
FEN: 8/8/1B6/1K6/1N6/8/8/1k6
Input: Rainer Staudte, 2013-08-22
Last update: Alfred Pfeiffer, 2013-08-22 more...
1. ... bxa6 La7 a5,Ka5 2. Tc5#
1. ... bxc6 La7 c5 2. Tb6+ Ka5 3. Sc6#
1. Ta5#?
1. Tc5#?
Schwarz beginnt, da er keinen letzten Zug hat.
1. ... bxc6 La7 c5 2. Tb6+ Ka5 3. Sc6#
1. Ta5#?
1. Tc5#?
Schwarz beginnt, da er keinen letzten Zug hat.
A.Buchanan: What's going on here? (2021-10-06)
Henrik Juel: Maybe Pb4 should be removed (2021-10-06)
A.Buchanan: WinChloe has the same diagram, and the solution given here (with incorrect move counting) assumes sBb4 is present. Without it, there is a cook: 1. ... bxc6 2. Kc3 c5 3. Ld8,Lc7 c4 4. Ta5# (2021-10-07)
comment
Henrik Juel: Maybe Pb4 should be removed (2021-10-06)
A.Buchanan: WinChloe has the same diagram, and the solution given here (with incorrect move counting) assumes sBb4 is present. Without it, there is a cook: 1. ... bxc6 2. Kc3 c5 3. Ld8,Lc7 c4 4. Ta5# (2021-10-07)
comment
Keywords: Symmetrical position, Superseded by (P1394575), Symbol problem (Kreuz)
Genre: 3#, Retro
Computer test: %Popeye Windows-32Bit v4.61
FEN: 1N6/1p6/RBR5/1k6/1p6/1K6/8/8
Reprints: V46 Bulletin Michael Schlosser-60-Jubiläumsturnier , p. 38, 2016
Input: Erich Bartel, 2013-09-20
Last update: Gunter Jordan, 2023-07-21 more...
Genre: 3#, Retro
Computer test: %Popeye Windows-32Bit v4.61
FEN: 1N6/1p6/RBR5/1k6/1p6/1K6/8/8
Reprints: V46 Bulletin Michael Schlosser-60-Jubiläumsturnier , p. 38, 2016
Input: Erich Bartel, 2013-09-20
Last update: Gunter Jordan, 2023-07-21 more...
1. Dg1! droht 2. Dg8#
1. ... d5 2. Da7 ... 3. Dd7#,Db6#
1. ... d5 2. Da7 ... 3. Dd7#,Db6#
Keywords: Symmetrical position
Genre: 3#
FEN: 4K3/4b3/3pkp2/4p3/4P3/3p1p2/8/4Q3
Reprints: 3a Allgemeine Zeitung Chemnitz 02/12/1928
9 Bote von der Ybbs 08/11/1929
Input: Felber, Volker, 2014-11-29
Last update: Mario Richter, 2021-05-14 more...
Genre: 3#
FEN: 4K3/4b3/3pkp2/4p3/4P3/3p1p2/8/4Q3
Reprints: 3a Allgemeine Zeitung Chemnitz 02/12/1928
9 Bote von der Ybbs 08/11/1929
Input: Felber, Volker, 2014-11-29
Last update: Mario Richter, 2021-05-14 more...
1. Kd6 Df6+ 2. Ke5 Sc3 3. d2 d4#
Wechsel der Symmetrieachse
Wechsel der Symmetrieachse
Keywords: Grid Chess, Symmetrical end position, Symmetrical position
Genre: Fairies
FEN: 8/3k4/8/3-N4/3-Q4/3-P4/8/8
Input: Frank Müller, 2015-01-18
Last update: Alfred Pfeiffer, 2015-01-19 more...
Genre: Fairies
FEN: 8/3k4/8/3-N4/3-Q4/3-P4/8/8
Input: Frank Müller, 2015-01-18
Last update: Alfred Pfeiffer, 2015-01-19 more...
60 - P1322874
Jean Louis Preti
IV-2 Recueil d'Études Progressives [Preti] 1856
(4+3)
Gewinn, Schwarz am Zug
Jean Louis Preti
IV-2 Recueil d'Études Progressives [Preti] 1856
(4+3)
Gewinn, Schwarz am Zug
1. ... Kc6 2. e4 dxe4+ 3. Kxe4 Kd6 4. c4 Ke6 5. d5+ Kd6 6. Kd4 Ke7 7. Kc5 +-
Originalforderung: "Les blancs gagnent même sans le trait"
Anton Baumann: Dual (1 Zug schneller am Ziel): 4.Kf5! Kd5 5.Kf6 Kc4 6.Ke7 d5 7.Ke6,Kd6 Kxc3 8.Kxd5 Kd3 9.Ke5 +- (2022-06-17)
comment
Anton Baumann: Dual (1 Zug schneller am Ziel): 4.Kf5! Kd5 5.Kf6 Kc4 6.Ke7 d5 7.Ke6,Kd6 Kxc3 8.Kxd5 Kd3 9.Ke5 +- (2022-06-17)
comment
Keywords: Symmetrical position, Kindergarten Problem
Genre: Studies
FEN: 8/3p4/3k4/3p4/3P4/2PKP3/8/8
Reprints: E44 Spirit of the Times 27/01/1866
Input: Mario Richter, 2016-07-30
Last update: Alfred Pfeiffer, 2016-07-30 more...
Genre: Studies
FEN: 8/3p4/3k4/3p4/3P4/2PKP3/8/8
Reprints: E44 Spirit of the Times 27/01/1866
Input: Mario Richter, 2016-07-30
Last update: Alfred Pfeiffer, 2016-07-30 more...
1. Tg3+! Kh7 2. Df7+ Kh6 3. Th3+ Kg5 4. Dh5+ Kf4 5. Tf3+ Ke4 6. Df5+ Kxd4 7. Td3+ Kc4 8. Dd5+ Kb4 9. Td4+ Ka3 10. Db7 c2 11. Td3+ Ka4 12. Ta3+ Kxa3 13. Db3+ Kxb3=
Anton Baumann: symmetrischer Versuch:
1.Tc7+? Kg8 2.Dg6+ Kf8 3.Tc8+ Ke7 4.De8+ Kd6 5.Tc6+ Kd5 6.De6+ Kxd4 7.Td6 Kc5 8.Td5+ Kb4(Kc4) 9.De4+ Ka3? 10.Ta5+ Kb3 11.Ta3+ Kxa3 12.Dc4 c2 13.Db3+ Kxb3=
aber 9. ... Kb3! 10.Tb5+ Ka3 11.Ta5+ Kb3 12.Ta3+ ist zu langsam
C+ Gustav 4.2a (2023-05-23)
comment
1.Tc7+? Kg8 2.Dg6+ Kf8 3.Tc8+ Ke7 4.De8+ Kd6 5.Tc6+ Kd5 6.De6+ Kxd4 7.Td6 Kc5 8.Td5+ Kb4(Kc4) 9.De4+ Ka3? 10.Ta5+ Kb3 11.Ta3+ Kxa3 12.Dc4 c2 13.Db3+ Kxb3=
aber 9. ... Kb3! 10.Tb5+ Ka3 11.Ta5+ Kb3 12.Ta3+ ist zu langsam
C+ Gustav 4.2a (2023-05-23)
comment
Keywords: Oneliner, Symmetrical position, Asymmetrical solution
Genre: Fairies
FEN: 7k/6R1/5Q2/8/3B4/2p5/8/K7
Input: Felber, Volker, 2016-10-22
Last update: Felber, Volker, 2016-10-22 more...
Genre: Fairies
FEN: 7k/6R1/5Q2/8/3B4/2p5/8/K7
Input: Felber, Volker, 2016-10-22
Last update: Felber, Volker, 2016-10-22 more...
62 - P1346361
Teppo Mänttä
B14 Problemkiste (159-160) 07/2005
(1+1+8)
r#6
Circe
Längstzüger
nDL=Känguruh
Teppo Mänttä
B14 Problemkiste (159-160) 07/2005
(1+1+8)
r#6
Circe
Längstzüger
nDL=Känguruh
1. KÄd1 KÄa4 2. KÄa5 KÄd1 3. KÄa1 KÄa6 4. KÄc4 KÄ6d3 5. KÄc5 KÄa6 6. KÄb4 Kxb4[+nKÄb8]#
Arnold Beine: Unlösbar! ... 7.Ka1,Kb1,Kc1! (2018-02-01)
Alfred Pfeiffer: Vermutlich fehlt die Bedingung 'Köko'. (2018-02-01)
Arnold Beine: In der Originalquelle fehlt die Angabe "Köko", aber dann wäre die Aufgabe C+. (2018-02-01)
Teppo Mänttä: I confirm that is a KöKo problem. (Everything else would be crazy). (2021-04-25)
comment
Alfred Pfeiffer: Vermutlich fehlt die Bedingung 'Köko'. (2018-02-01)
Arnold Beine: In der Originalquelle fehlt die Angabe "Köko", aber dann wäre die Aufgabe C+. (2018-02-01)
Teppo Mänttä: I confirm that is a KöKo problem. (Everything else would be crazy). (2021-04-25)
comment
Keywords: Skittles setup, Circe, Maximummer, Symmetrical position, Asymmetrical solution, Aristocrat
Pieces: = Kangaroo (KÄ)
Genre: Fairies
FEN: 8/8/8/1k6/8/-*3Q-*3Q-*3Q5/-*3QK-*3Q5/-*3Q-*3Q-*3Q5
Input: Erich Bartel, 2018-01-31
Last update: Alfred Pfeiffer, 2018-02-01 more...
Pieces: = Kangaroo (KÄ)
Genre: Fairies
FEN: 8/8/8/1k6/8/-*3Q-*3Q-*3Q5/-*3QK-*3Q5/-*3Q-*3Q-*3Q5
Input: Erich Bartel, 2018-01-31
Last update: Alfred Pfeiffer, 2018-02-01 more...
1. Sf5! f2 2. Dh1+ f3 3. Dh4+ Df4 4. Td8 Sc6 5. Sd6+ Ke3 6. Sc4+ Ke4 7. Dh7+ Df5+ 8. Dxf5#
Keywords: Symmetrical position, Asymmetrical solution
Genre: n#
FEN: 4R3/4N3/4K3/4n3/3pkp2/3pqp2/4b3/4Q3
Input: Felber, Volker, 2018-12-18
Last update: Felber, Volker, 2018-12-18 more...
Genre: n#
FEN: 4R3/4N3/4K3/4n3/3pkp2/3pqp2/4b3/4Q3
Input: Felber, Volker, 2018-12-18
Last update: Felber, Volker, 2018-12-18 more...
AL: 1. e4 d5 2. e5 d4 3. c3 f6 4. Df3 Kf7 5. Dxb7 Dd5 6. Kd1 Dxg2 7. Kc2 Dxf1 8. Dxc8 Dxg1 9. Dxb8 Txb8 10. Txg1 Tb3 11. Tg6 Ta3 12. Th6 gxh6 13. bxa3 Kg7 14. Kb2 d3 15. e6 a5 16. h4 a4 17. h5 c5 18. f4 c4 19. f5==
faster solution (Henrik Juel): 1. c3 a5 2. e4 a4 3. Dg4 Ta5 4. Kd1 b5 5. Lc4 d5 6. Dxc8 bxc4 7. Dxc7 f6 8. Dxb8 Dxb8 9. Kc2 Dxh2 10. f4 Dxg1 11. g4 Dc5 12. Th6 Da3 13. bxa3 d4 14. Kb2 Th5 15.
e5 d3 16. f5 Kf7 17. gxh5 gxh6 18. e6+ Kg7==
The fastest known symmetrical, mutual stalemate
faster solution (Henrik Juel): 1. c3 a5 2. e4 a4 3. Dg4 Ta5 4. Kd1 b5 5. Lc4 d5 6. Dxc8 bxc4 7. Dxc7 f6 8. Dxb8 Dxb8 9. Kc2 Dxh2 10. f4 Dxg1 11. g4 Dc5 12. Th6 Da3 13. bxa3 d4 14. Kb2 Th5 15.
e5 d3 16. f5 Kf7 17. gxh5 gxh6 18. e6+ Kg7==
The fastest known symmetrical, mutual stalemate
Henrik Juel: The position can be reached in 18.0 moves, e.g.
1. Bc2-c3 Ba7-a5 2. Be2-e4 Ba5-a4 3. Dd1-g4 Ta8-a5
4. Ke1-d1 Bb7-b5 5. Lf1-c4 Bd7-d5 6. Dg4xc8 Bb5xc4
7. Dc8xc7 Bf7-f6 8. Dc7xb8 Dd8xb8 9. Kd1-c2 Db8xh2
10. Bf2-f4 Dh2xg1 11. Bg2-g4 Dg1-c5 12. Th1-h6 Dc5-a3
13. Bb2xa3 Bd5-d4 14. Kc2-b2 Ta5-h5 15. Be4-e5 Bd4-d3
16. Bf4-f5 Ke8-f7 17. Bg4xh5 Bg7xh6 18. Be5-e6 Kf7-g7 (2020-11-29)
Henrik Juel: ... but not in 17.5 moves, according to Euclide 1.01 (2020-11-29)
James Malcom: In other notatiom: 1. c3 a5 2. e4 a4 3. Qg4 Ra5 4. Kd1 b5 5. Bc4 d5 6. Qxc8 bxc4 7. Qxc7 f6 8. Qxb8
Qxb8 9. Kc2 Qxh2 10. f4 Qxg1 11. g4 Qc5 12. Rh6 Qa3 13. bxa3 d4 14. Kb2 Rh5 15.
e5 d3 16. f5 Kf7 17. gxh5 gxh6 18. e6+ Kg7
And by crikey! This is big news! This means that Gik actually had the record all along, and Minerva only tied it with his P1382027! (2020-11-29)
Henrik Juel: Gik's position is the record, but neither he nor Minerva knew this (2020-11-30)
James Malcom: This is an exciting development in the story of the mutual stalemate! (2020-11-30)
A.Buchanan: They will have to change the "Mr Robot" TV series: https://www.ozproblems.com/walkabout/walkabout2021/feb27 (2021-02-28)
A.Buchanan: Flipping left-right is again achievable in 18.0 not 17.5 - not entirely unexpected, as bK has further to walk, but was worth checking (2021-02-28)
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1. Bc2-c3 Ba7-a5 2. Be2-e4 Ba5-a4 3. Dd1-g4 Ta8-a5
4. Ke1-d1 Bb7-b5 5. Lf1-c4 Bd7-d5 6. Dg4xc8 Bb5xc4
7. Dc8xc7 Bf7-f6 8. Dc7xb8 Dd8xb8 9. Kd1-c2 Db8xh2
10. Bf2-f4 Dh2xg1 11. Bg2-g4 Dg1-c5 12. Th1-h6 Dc5-a3
13. Bb2xa3 Bd5-d4 14. Kc2-b2 Ta5-h5 15. Be4-e5 Bd4-d3
16. Bf4-f5 Ke8-f7 17. Bg4xh5 Bg7xh6 18. Be5-e6 Kf7-g7 (2020-11-29)
Henrik Juel: ... but not in 17.5 moves, according to Euclide 1.01 (2020-11-29)
James Malcom: In other notatiom: 1. c3 a5 2. e4 a4 3. Qg4 Ra5 4. Kd1 b5 5. Bc4 d5 6. Qxc8 bxc4 7. Qxc7 f6 8. Qxb8
Qxb8 9. Kc2 Qxh2 10. f4 Qxg1 11. g4 Qc5 12. Rh6 Qa3 13. bxa3 d4 14. Kb2 Rh5 15.
e5 d3 16. f5 Kf7 17. gxh5 gxh6 18. e6+ Kg7
And by crikey! This is big news! This means that Gik actually had the record all along, and Minerva only tied it with his P1382027! (2020-11-29)
Henrik Juel: Gik's position is the record, but neither he nor Minerva knew this (2020-11-30)
James Malcom: This is an exciting development in the story of the mutual stalemate! (2020-11-30)
A.Buchanan: They will have to change the "Mr Robot" TV series: https://www.ozproblems.com/walkabout/walkabout2021/feb27 (2021-02-28)
A.Buchanan: Flipping left-right is again achievable in 18.0 not 17.5 - not entirely unexpected, as bK has further to walk, but was worth checking (2021-02-28)
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Keywords: Non-Unique Proof Game, Symmetrical position
Genre: Retro
FEN: 5bnr/4p1kp/4Pp1p/5P1P/p1p5/P1Pp4/PK1P4/RNB5
Reprints: 5 Best Problems 4, p. 94, 2007
61 Tim Krabbé's Website 16/08/2007
Input: James Malcom, 2020-11-29
Last update: A.Buchanan, 2021-02-28 more...
Genre: Retro
FEN: 5bnr/4p1kp/4Pp1p/5P1P/p1p5/P1Pp4/PK1P4/RNB5
Reprints: 5 Best Problems 4, p. 94, 2007
61 Tim Krabbé's Website 16/08/2007
Input: James Malcom, 2020-11-29
Last update: A.Buchanan, 2021-02-28 more...
65 - P1384831
Lion Xray
Facebook 31/12/2020
(9+9)
In how many ways can you add a White Queen and a Black Queen to this diagram to obtain a legal position?
Lion Xray
Facebook 31/12/2020
(9+9)
In how many ways can you add a White Queen and a Black Queen to this diagram to obtain a legal position?
2021 solutions
A.Buchanan: beautiful! (2021-01-01)
Henrik Juel: Yes, beautiful simplicity; finally one I can handle...
There are 64-9-9 = 46 empty squares, so the queens can be added in 46x45 = 2070 ways
The only illegality is that both kings are in check, which happens in 7x7 = 49 ways
Answer: 2070-49 = 2021 (2021-01-01)
A.Buchanan: Oh the other two today aren't hard, Henrik. But this one is a real gift from the Gods (2021-01-01)
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Henrik Juel: Yes, beautiful simplicity; finally one I can handle...
There are 64-9-9 = 46 empty squares, so the queens can be added in 46x45 = 2070 ways
The only illegality is that both kings are in check, which happens in 7x7 = 49 ways
Answer: 2070-49 = 2021 (2021-01-01)
A.Buchanan: Oh the other two today aren't hard, Henrik. But this one is a real gift from the Gods (2021-01-01)
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Keywords: Add pieces (Dd), Symmetrical position, Kindergarten Problem
Genre: Retro, Mathematics
FEN: 4k3/3ppp2/ppp3pp/8/8/PPP3PP/3PPP2/4K3
Reprints: Retros mailing list 01/01/2021
Input: A.Buchanan, 2021-01-01
Last update: A.Buchanan, 2021-01-01 more...
Genre: Retro, Mathematics
FEN: 4k3/3ppp2/ppp3pp/8/8/PPP3PP/3PPP2/4K3
Reprints: Retros mailing list 01/01/2021
Input: A.Buchanan, 2021-01-01
Last update: A.Buchanan, 2021-01-01 more...
66 - P1385832
Kurt Keller
4585 idee & form 149, p. 5047, 01/2021
Weihnachts- und Neujahrsgruss
(10+2)
#5
b) -wBd4
c) ferner -wBb5
Kurt Keller
4585 idee & form 149, p. 5047, 01/2021
Weihnachts- und Neujahrsgruss
(10+2)
#5
b) -wBd4
c) ferner -wBb5
a) 1. d6? cxd6 2. b6 d5 3. Lb7 Kb5 4. Kc7 Kc4 5. La6#
4. ... Ka4! 5. Lc6+ Ka3
1. b6! cxb6 2. Kc7 b5 3. Ld7 Kxd5 4. Lf5 Kc4 5. Le6#
b) 1. b6? cxb6!
1. d6! cxd6 2. b6 d5 3. b7 d4 4. b8=D droht 5. Db5#
5. ... dxc3 5. Df4#
c) 1. b5? Kc5!
1. d6! cxd6 2. Kb7 d5 3. La4 d4 4. Lb3+ Kb5 5. a4#
Nr. 4585, K. Keller [Ulm, Germany]: a) 1.d6? c:d6! 1.b6! c:b6 2.Kc7 b5 3.Ld7 K:d5 4.Lf5 Kc4 5.Le6⧧ b) 1.b6? c:b6! 1.d6! c:d6 2.b6 d5 3.b7 d4 4.b8D (5.Db5⧧) d:c3 5.Df4⧧ c) 1.b5? Kc5! 1.d6! c:d6 2.Kb7 d5 3.La4 d4 4.Lb3+ Kb5 5.a4⧧
(Andreas Nievergelt (Winterthur, Switzerland): informalturnier. Lösungen zu Heft i&f 149, in: idee & form 150, p. 5084, April 2021)
4. ... Ka4! 5. Lc6+ Ka3
1. b6! cxb6 2. Kc7 b5 3. Ld7 Kxd5 4. Lf5 Kc4 5. Le6#
b) 1. b6? cxb6!
1. d6! cxd6 2. b6 d5 3. b7 d4 4. b8=D droht 5. Db5#
5. ... dxc3 5. Df4#
c) 1. b5? Kc5!
1. d6! cxd6 2. Kb7 d5 3. La4 d4 4. Lb3+ Kb5 5. a4#
Nr. 4585, K. Keller [Ulm, Germany]: a) 1.d6? c:d6! 1.b6! c:b6 2.Kc7 b5 3.Ld7 K:d5 4.Lf5 Kc4 5.Le6⧧ b) 1.b6? c:b6! 1.d6! c:d6 2.b6 d5 3.b7 d4 4.b8D (5.Db5⧧) d:c3 5.Df4⧧ c) 1.b5? Kc5! 1.d6! c:d6 2.Kb7 d5 3.La4 d4 4.Lb3+ Kb5 5.a4⧧
(Andreas Nievergelt (Winterthur, Switzerland): informalturnier. Lösungen zu Heft i&f 149, in: idee & form 150, p. 5084, April 2021)
Comments:
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- Author – Kurt Keller (Ulm, Germany)
- Yet Another Chess Problem Database (...)
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Keywords: Symbol problem (Christmas tree), Stalemate dissolution, Sacrifice key, Sacrifice of white pieces, Active sacrifice, Switchback (k), Option key, Promotion, Pawn mate (c), Symmetrical position, Asymmetrical solution, Twin (triplet), Minimal
Genre: n#
Computer test: Popeye Windows-32Bit v4.63 (512 MB)
FEN: 2K5/2p5/2B5/1P1P4/1PkP4/2P5/P3P3/2R5
Input: Kurt Keller, 2021-01-27
Last update: Kurt Keller, 2021-04-28 more...
Genre: n#
Computer test: Popeye Windows-32Bit v4.63 (512 MB)
FEN: 2K5/2p5/2B5/1P1P4/1PkP4/2P5/P3P3/2R5
Input: Kurt Keller, 2021-01-27
Last update: Kurt Keller, 2021-04-28 more...
67 - P1387362
Manfred Zucker
Freie Presse (Chemnitz) 24/06/1977
(1+1)
Wie viele verschiedene letzte Züge sind möglich?
Manfred Zucker
Freie Presse (Chemnitz) 24/06/1977
(1+1)
Wie viele verschiedene letzte Züge sind möglich?
29 Lösungen
Gefragt war natürlich nach dem letzten Einzelzug. Nun kann zuletzt sowohl der weiße als auch der der schwarze König gezogen haben. Der weiße König kann von drei verschiedenen Feldern (a2,b1,b2) gekommen sein, und er kann auf a1 eine schwarze Dame, einen schwarzen Turm, einen schwarzen Läufer, einen schwarzen Springer oder nichts geschlagen haben, das sind 3x5=15 Möglichkeiten. Dasselbe trifft auf den schwarzen König zu, insgesamt ergeben sich so 30 Möglichkeiten für den letzten Zug - und doch ist diese Lösung nicht richtig! Die Stellung wKb2-sLa1 ist partiemöglich (letzte Züge: 1. ... a2-a2=L+! 2. Kxa1), die Stellung sKg2-wLh1 jedoch nicht, denn der weiße Läufer kann (bei schwarzer Königsstellung auf g2) auf keine Weise nach h1 gekommen sein! Diese partieunmögliche Stellung war also zu subtrahieren, das richtige Ergebnis mußte "29" lauten.
Gefragt war natürlich nach dem letzten Einzelzug. Nun kann zuletzt sowohl der weiße als auch der der schwarze König gezogen haben. Der weiße König kann von drei verschiedenen Feldern (a2,b1,b2) gekommen sein, und er kann auf a1 eine schwarze Dame, einen schwarzen Turm, einen schwarzen Läufer, einen schwarzen Springer oder nichts geschlagen haben, das sind 3x5=15 Möglichkeiten. Dasselbe trifft auf den schwarzen König zu, insgesamt ergeben sich so 30 Möglichkeiten für den letzten Zug - und doch ist diese Lösung nicht richtig! Die Stellung wKb2-sLa1 ist partiemöglich (letzte Züge: 1. ... a2-a2=L+! 2. Kxa1), die Stellung sKg2-wLh1 jedoch nicht, denn der weiße Läufer kann (bei schwarzer Königsstellung auf g2) auf keine Weise nach h1 gekommen sein! Diese partieunmögliche Stellung war also zu subtrahieren, das richtige Ergebnis mußte "29" lauten.
Duplicate Diagram: P1207607
Dazu schreibt die FP: "Wie viele verschiedene letzte Züge sind möglich? Noch ein kleiner Hinweis: Beachten Sie beim Zählen bitte auch, daß die Könige zuletzt geschlagen haben können.".
(MZ433)
.
Henrik Juel: solution
2x3x5 - 1 = 29
R: Kg2xLh1 is illegal (2021-03-12)
A.Buchanan: This preceded the DP rule by 20 years, so under “Golden Age” principle, that rule does not apply, although it would be sound either way. Under DP rule there would have been 2x2x3=12 possible last moves, as a rook or queen must have just been captured (2021-03-13)
A.Buchanan: Is an only kings position an aristocrat or a kindergarten? :) Is it a one liner? :) I think the answer should be no, no and no (2021-03-13)
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(MZ433)
.
Henrik Juel: solution
2x3x5 - 1 = 29
R: Kg2xLh1 is illegal (2021-03-12)
A.Buchanan: This preceded the DP rule by 20 years, so under “Golden Age” principle, that rule does not apply, although it would be sound either way. Under DP rule there would have been 2x2x3=12 possible last moves, as a rook or queen must have just been captured (2021-03-13)
A.Buchanan: Is an only kings position an aristocrat or a kindergarten? :) Is it a one liner? :) I think the answer should be no, no and no (2021-03-13)
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Keywords: Aristocrat, Miniature, only Kings, Golden Age, Last Move?, Symmetrical position, Asymmetrical solution
Genre: Retro, Mathematics
FEN: 8/8/8/8/8/8/8/K6k
Input: Felber, Volker, 2021-03-12
Last update: A.Buchanan, 2021-03-13 more...
Genre: Retro, Mathematics
FEN: 8/8/8/8/8/8/8/K6k
Input: Felber, Volker, 2021-03-12
Last update: A.Buchanan, 2021-03-13 more...
1. Ke4xd5[+wWEe4] WEf5-g5 2. Kd5-e6 WEe4-e5+ 3. Ke6-f7 WEe5-e6 4. Kf7xe6[+wWEf7] WEf7-f8 5. Ke6-f6 WEg5-h5 6. Kf6-g7 WEh5-h6 7. Kg7-h8 WEf8-g8#,WEh6-h7# (Mattdual,Verschmerzbar?)
Henrik Juel: The black king goes to h8, on his way helping the white wazirs reach f8 and h6
The mating move dual is very disturbing, I think (2021-04-11)
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The mating move dual is very disturbing, I think (2021-04-11)
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Keywords: Circe (Platzwechsel), Symmetrical position, Asymmetrical solution, Aristocrat, Rex solus (s)
Pieces: = Wazir (WE)
Genre: Fairies
Computer test: %Popeye FreeBSD-9.1-RELEASE-amd64-64Bit v4.59
FEN: 8/8/8/3*2R1*2R2/4k3/8/8/8
Input: Erich Bartel, 2021-04-11
Last update: Alfred Pfeiffer, 2021-04-21 more...
Pieces: = Wazir (WE)
Genre: Fairies
Computer test: %Popeye FreeBSD-9.1-RELEASE-amd64-64Bit v4.59
FEN: 8/8/8/3*2R1*2R2/4k3/8/8/8
Input: Erich Bartel, 2021-04-11
Last update: Alfred Pfeiffer, 2021-04-21 more...
1. g3! (Zugzwang)
1. ... Sc3+ 2. Sxc3#
1. ... Sa3 2. Sc3#
1. ... Sxg3+ 2. Sxg3#
1. ... Sc3+ 2. Sxc3#
1. ... Sa3 2. Sc3#
1. ... Sxg3+ 2. Sxg3#
Keywords: Symmetrical position, Asymmetrical solution
Genre: 2#
Computer test: SCHRECKE: C+, popeye 4.85 (2021-04-29
FEN: 8/8/8/4p3/2P1k1P1/4B3/2PpKpP1/1n1NbN1n
Reprints: 23 Panorama (Leiden) 06/05/1925
70 Asymmetry 1927
Input: Mario Richter, 2021-04-29
Last update: Erich Bartel, 2021-04-29 more...
Genre: 2#
Computer test: SCHRECKE: C+, popeye 4.85 (2021-04-29
FEN: 8/8/8/4p3/2P1k1P1/4B3/2PpKpP1/1n1NbN1n
Reprints: 23 Panorama (Leiden) 06/05/1925
70 Asymmetry 1927
Input: Mario Richter, 2021-04-29
Last update: Erich Bartel, 2021-04-29 more...
70 - P1390558
Adrian Storisteanu
Discord Chess Problems & Studies Server 02/05/2021
2.-3. Platz
Discord Composition Tourney 1
(4+6)
#1
b) Drehung 90° Uhrzeigersinn
c) Drehung 180°
d) Drehung 270°
Adrian Storisteanu
Discord Chess Problems & Studies Server 02/05/2021
2.-3. Platz
Discord Composition Tourney 1
(4+6)
#1
b) Drehung 90° Uhrzeigersinn
c) Drehung 180°
d) Drehung 270°
a) 1. Sc5#
b) 1. Sf5#
c) 1. Sf6#
d) 1. Sc6#
b) 1. Sf5#
c) 1. Sf6#
d) 1. Sc6#
Keywords: Board Rotation, Symmetrical position, Asymmetrical solution
FEN: 8/3Np3/8/1N1pp3/1p1pk3/5R2/6K1/8
Input: A.Buchanan, 2021-06-08
Last update: Alfred Pfeiffer, 2021-09-30 more...
FEN: 8/3Np3/8/1N1pp3/1p1pk3/5R2/6K1/8
Input: A.Buchanan, 2021-06-08
Last update: Alfred Pfeiffer, 2021-09-30 more...
71 - P1390564
Adrian Storisteanu
Discord Chess Problems & Studies Server 02/05/2021
8. Platz
Discord Composition Tourney 1
(2+6)
#1
Duplex
Adrian Storisteanu
Discord Chess Problems & Studies Server 02/05/2021
8. Platz
Discord Composition Tourney 1
(2+6)
#1
Duplex
w) 1. Da1#
s) 1. ... Da8#
s) 1. ... Da8#
Keywords: Symmetrical position, Asymmetrical solution (2), Minimal, Asymmetrical solution
FEN: 5q2/8/4nQn1/5p2/5p2/5K2/8/5k2
Input: A.Buchanan, 2021-06-08
Last update: Alfred Pfeiffer, 2021-09-30 more...
FEN: 5q2/8/4nQn1/5p2/5p2/5K2/8/5k2
Input: A.Buchanan, 2021-06-08
Last update: Alfred Pfeiffer, 2021-09-30 more...
72 - P1390566
Geir Sune Tallaksen Østmoe
Discord Chess Problems & Studies Server 02/05/2021
10. Platz
Discord Composition Tourney 1
(9+8)
#1
Geir Sune Tallaksen Østmoe
Discord Chess Problems & Studies Server 02/05/2021
10. Platz
Discord Composition Tourney 1
(9+8)
#1
1. bxc6ep#
Author: 1.fxe6 e.p.#? is illegal. Black’s last move can only have been …c7-c5 or …e7-e5. White’s pawns have made 8 captures, which means they captured all of Black’s missing pieces. This includes the dark-squared bishop, which must have moved from f8 in order to be captured by a White pawn. This means the pawn on e7 must have moved or been captured earlier, so Black’s last move can not have been …e7-e5. This leaves …c7-c5 as the only possible last move.
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Keywords: Symmetrical position, Asymmetrical solution, En passant
Genre: Retro
FEN: 2nrn3/p2k2p1/1P1P1P2/1PpKpP2/3P4/3P4/3P4/8
Input: A.Buchanan, 2021-06-08
Last update: Alfred Pfeiffer, 2021-09-30 more...
Genre: Retro
FEN: 2nrn3/p2k2p1/1P1P1P2/1PpKpP2/3P4/3P4/3P4/8
Input: A.Buchanan, 2021-06-08
Last update: Alfred Pfeiffer, 2021-09-30 more...
73 - P1397709
Rainer Staudte
Michael Schlosser
27 Unión Argentina de Problemistas de Ajedrez A1 27/12/2021
(3+2)
Gewinn
b) Kc1->c3
Rainer Staudte
Michael Schlosser
27 Unión Argentina de Problemistas de Ajedrez A1 27/12/2021
(3+2)
Gewinn
b) Kc1->c3
a) 1. Sd7+? Kd6! 2. Sb6 Kc7!
2. Sf6 Ke7! Echo
1. Sa6+! Kb5 2. Sc7+ Ka4 3. Kb2! c5 4. Sd5 c4 5. Sc3+ gewinnt
3. Kc2? Ka3! mit der Drohung, die Remis-Ecke zu erreichen 4. Kb1 c5! 5. Sd5 c4! 6. Sc3 Kb3!
4. ... Kb3? verliert nach 5. Sde6! droht 6. Sc5
5. ... c5 6. Sd5! c4 7. Sd4+,Sc5+ Ka4 8. Sc3+!
1. ... Kb6 2. Sb4! Ka5 3. Sa2!
b) 1. Se6+? Kd6! 2. Sf4 c5! 3. Kc4 Kc7! Springerfang 4. Sa6+ Kb7
1. Sd7+? Kd6! mit Spingerverlust
1. Sa6+ Kb6 2. Sb4 Kc7 3. Sf7 c5 4. Sd5+ Kc6 5. Kc4
3. Se6+? Kd6! 4. Sf4 c5! 5. Sbd3 c4!
2. ... c5 3. Sd5+! Kb5 4. Kc2,Kb2 c4 5. Sc3+
1. ... Kb5 2. Sc7+! Kb6 2. Sb4? c5!
2. Sf6 Ke7! Echo
1. Sa6+! Kb5 2. Sc7+ Ka4 3. Kb2! c5 4. Sd5 c4 5. Sc3+ gewinnt
3. Kc2? Ka3! mit der Drohung, die Remis-Ecke zu erreichen 4. Kb1 c5! 5. Sd5 c4! 6. Sc3 Kb3!
4. ... Kb3? verliert nach 5. Sde6! droht 6. Sc5
5. ... c5 6. Sd5! c4 7. Sd4+,Sc5+ Ka4 8. Sc3+!
1. ... Kb6 2. Sb4! Ka5 3. Sa2!
b) 1. Se6+? Kd6! 2. Sf4 c5! 3. Kc4 Kc7! Springerfang 4. Sa6+ Kb7
1. Sd7+? Kd6! mit Spingerverlust
1. Sa6+ Kb6 2. Sb4 Kc7 3. Sf7 c5 4. Sd5+ Kc6 5. Kc4
3. Se6+? Kd6! 4. Sf4 c5! 5. Sbd3 c4!
2. ... c5 3. Sd5+! Kb5 4. Kc2,Kb2 c4 5. Sc3+
1. ... Kb5 2. Sc7+! Kb6 2. Sb4? c5!
Keywords: Symmetrical position, Asymmetrical solution, Minimal, Miniature, Grab (S), Echo
Genre: Studies
FEN: 1N1N4/8/2p5/2k5/8/8/8/2K5
Input: Rainer Staudte, 2022-01-02
Last update: Rainer Staudte, 2022-06-20 more...
Genre: Studies
FEN: 1N1N4/8/2p5/2k5/8/8/8/2K5
Input: Rainer Staudte, 2022-01-02
Last update: Rainer Staudte, 2022-06-20 more...
1. c1=T a4 2. Th1 a5 3. Kf1 a6 4. Ke1 a7 5. Kd1 a8=D 6. Le1 Dxh1=
Keywords: Antiphönix, Asymmetrical solution, corner to corner (D), Excelsior white, Ideal stalemate, konsekutive Umwandlungen 2 (tD), Miniature, Minimal (B), Oneliner, Symmetrical position, Promotion (D), under-promotion (t), under-promotion key
Genre: Fairies
FEN: 8/8/8/8/8/8/PKpppbk1/8
Input: Gunter Jordan, 2022-01-28
Last update: Gunter Jordan, 2022-01-28 more...
Genre: Fairies
FEN: 8/8/8/8/8/8/PKpppbk1/8
Input: Gunter Jordan, 2022-01-28
Last update: Gunter Jordan, 2022-01-28 more...
1. Lg2 Kd3 2. Lh3 Sg5 3. Le6 Sxe6 4. Kd5 Sd8=
Keywords: Asymmetrical solution, Ideal stalemate, Miniature, Minimal (l), Symmetrical position
Genre: Fairies
FEN: 8/8/2k5/4P3/3PK3/5N2/8/7b
Input: Gunter Jordan, 2022-01-28
Last update: Gunter Jordan, 2022-01-28 more...
Genre: Fairies
FEN: 8/8/2k5/4P3/3PK3/5N2/8/7b
Input: Gunter Jordan, 2022-01-28
Last update: Gunter Jordan, 2022-01-28 more...
1. De5? Kxd7,Kxf7 2. e8=D#
aber Schwarz hatte zuletzt keinen Zug, also
0) 1. ... Kxd7,Kxf7! e8=D+ 2. Kd6,Kf6 D2e5#
aber Schwarz hatte zuletzt keinen Zug, also
0) 1. ... Kxd7,Kxf7! e8=D+ 2. Kd6,Kf6 D2e5#
Keywords: Miniature, Homebase, Rex solus (s), Promotion (D), Symmetrical position, Symmetrical solution
Genre: 2#
Computer test: C+ Popeye 4.61 (it is obvious that Black has the move)
FEN: 4k3/3RPR2/8/8/8/8/4Q3/4K3
Input: Alfred Pfeiffer, 2022-02-09
Last update: A.Buchanan, 2022-02-10 more...
Genre: 2#
Computer test: C+ Popeye 4.61 (it is obvious that Black has the move)
FEN: 4k3/3RPR2/8/8/8/8/4Q3/4K3
Input: Alfred Pfeiffer, 2022-02-09
Last update: A.Buchanan, 2022-02-10 more...
1. Sf3-g1? droht 2. Tf2-e2# 2. Tf2-f3#
1. ... Lh3-f1 2. Tf2-f3#
1. ... Lh3-g2 2. Tf2-e2#
1. ... Lh3-g4!
1. Sf3-g5? droht 2. Tf4-f3# 2. Tf4-e4#
1. ... Lh3-f5 2. Tf4-f3#
1. ... Lh3-g4 2. Tf4-e4#
1. ... Lh3-g2!
1. Sf3-h4? Lh3-f1 2. Sh4-f5#
1. ... Lh3-g4 2. Sh4-g2#
1. ... Lh3-c8,L~ 2. Sh4-g2#
1. ... b3-b2!
1. Sf3-h2? Lh3-g2 2. Sh2-g4#
1. ... Lh3-f5 2. Sh2-f1#
1. ... Lh3-c8,L~ 2. Sh2-f1#
1. ... b3-b2!
1. Sf3-e5? droht 2. Se5-c4#
1. ... Lh3-f1 2. Se5-g4#
1. ... Lh3-f5 2. Se5-c4#
1. ... Lh3-e6!
1. Sf3-e1? Lh3-g4 2. Se1-g2#
1. ... Lh3-f5 2. Se1-g2#
1. ... Lh3-c8,L~ 2. Se1-g2#
1. ... Lh3-f1!
1. Sf3-d4? droht 2. Tf2-e2# 2. Tf2-f3#
1. ... Lh3-g4!
1. Sf3-d2! droht 2. Sd2-c4# 2. Tf4-f3# 2. Tf4-e4#
1. ... Lh3-g2 2. Sd2-c4#
1. ... Lh3-f1,Le6 2. Tf4-e4# 2. Tf4-f3# 2. Sd2xf1#
1. ... Lh3-f5 2. Tf4-f3# 2. Sd2-f1# 2. Sd2-c4#
1. ... Lh3-g4 2. Sd2-f1# 2. Sd2-c4# 2. Tf4-e4#
1. ... b3-b2 2. Sd2-c4# 2. Tf4-f3# 2. Tf4-e4#
1. ... Lh3-f1 2. Tf2-f3#
1. ... Lh3-g2 2. Tf2-e2#
1. ... Lh3-g4!
1. Sf3-g5? droht 2. Tf4-f3# 2. Tf4-e4#
1. ... Lh3-f5 2. Tf4-f3#
1. ... Lh3-g4 2. Tf4-e4#
1. ... Lh3-g2!
1. Sf3-h4? Lh3-f1 2. Sh4-f5#
1. ... Lh3-g4 2. Sh4-g2#
1. ... Lh3-c8,L~ 2. Sh4-g2#
1. ... b3-b2!
1. Sf3-h2? Lh3-g2 2. Sh2-g4#
1. ... Lh3-f5 2. Sh2-f1#
1. ... Lh3-c8,L~ 2. Sh2-f1#
1. ... b3-b2!
1. Sf3-e5? droht 2. Se5-c4#
1. ... Lh3-f1 2. Se5-g4#
1. ... Lh3-f5 2. Se5-c4#
1. ... Lh3-e6!
1. Sf3-e1? Lh3-g4 2. Se1-g2#
1. ... Lh3-f5 2. Se1-g2#
1. ... Lh3-c8,L~ 2. Se1-g2#
1. ... Lh3-f1!
1. Sf3-d4? droht 2. Tf2-e2# 2. Tf2-f3#
1. ... Lh3-g4!
1. Sf3-d2! droht 2. Sd2-c4# 2. Tf4-f3# 2. Tf4-e4#
1. ... Lh3-g2 2. Sd2-c4#
1. ... Lh3-f1,Le6 2. Tf4-e4# 2. Tf4-f3# 2. Sd2xf1#
1. ... Lh3-f5 2. Tf4-f3# 2. Sd2-f1# 2. Sd2-c4#
1. ... Lh3-g4 2. Sd2-f1# 2. Sd2-c4# 2. Tf4-e4#
1. ... b3-b2 2. Sd2-c4# 2. Tf4-f3# 2. Tf4-e4#
Keywords: Symmetrical position, Asymmetrical solution
Genre: 2#
FEN: 8/8/8/8/5R2/1pK1kNBb/5R2/8
Input: Marcin Banaszek, 2022-07-20
Last update: Marcin Banaszek, 2022-08-04 more...
Genre: 2#
FEN: 8/8/8/8/5R2/1pK1kNBb/5R2/8
Input: Marcin Banaszek, 2022-07-20
Last update: Marcin Banaszek, 2022-08-04 more...
1. c4! dxc4 2. Sxc4#
1. ... dxe4 2. Sxe4#
1. ... b5 2. c5#
1. ... c5 2. Sb5#
1. ... e5 2. Sf5#
1. ... f5 2. e5#
1. ... dxe4 2. Sxe4#
1. ... b5 2. c5#
1. ... c5 2. Sb5#
1. ... e5 2. Sf5#
1. ... f5 2. e5#
Keywords: Pawn mate, Symmetrical position (nach Schlüssel), Symmetrical solution
Genre: 2#
Computer test: Gustav 4.1 a
FEN: 3K4/3B4/1ppkpp2/3p4/3BP3/N5N1/2P5/8
Input: Gunter Jordan, 2022-08-18
Last update: Gunter Jordan, 2022-08-18 more...
Genre: 2#
Computer test: Gustav 4.1 a
FEN: 3K4/3B4/1ppkpp2/3p4/3BP3/N5N1/2P5/8
Input: Gunter Jordan, 2022-08-18
Last update: Gunter Jordan, 2022-08-18 more...
79 - P1406812
Stefan Felber
1763 Augsburger Allgemeine 10/12/2022
(5+7)
#3
b) wLe4->e6:4#
c) wLe4->e8:5#
Stefan Felber
1763 Augsburger Allgemeine 10/12/2022
(5+7)
#3
b) wLe4->e6:4#
c) wLe4->e8:5#
a) 1. Lxd3+! Kxd3 2. Da3 Kc2 3. Db3#
2. ... Ke2 3. Da6#
2. ... Kc4 3. Th4#
b) 1. Lh3! d1=D 2. Lf1 Kd2 3. Db4 Kc2 4. Db2#
1. ... d1=S 2. Lf1 Kd2 3. Da3 Sb2 4. Dxb2#
1. ... d1=L 2. Lf1 Kd2 3. Da3, 3. Db4, 3. Dc5, 3. Dc7
c) 1. La4! f1=S 2. Ld1 Kf2 3. Dh4 Kg2 4. Dh3 Kf2 5. Txf1#, 5. Dxf3#
2. ... Ke2 3. Da6#
2. ... Kc4 3. Th4#
b) 1. Lh3! d1=D 2. Lf1 Kd2 3. Db4 Kc2 4. Db2#
1. ... d1=S 2. Lf1 Kd2 3. Da3 Sb2 4. Dxb2#
1. ... d1=L 2. Lf1 Kd2 3. Da3, 3. Db4, 3. Dc5, 3. Dc7
c) 1. La4! f1=S 2. Ld1 Kf2 3. Dh4 Kg2 4. Dh3 Kf2 5. Txf1#, 5. Dxf3#
Keywords: Symmetrical position, Capture key (in a), Checking key (in a), Asymmetrical solution, Symbol problem (Weihnachtsbaum)
Genre: 3#
FEN: 8/4Q3/8/4K3/4B3/3ppp2/3pkp2/1R2b2R
Input: Felber, Volker, 2022-12-24
Last update: Gunter Jordan, 2022-12-24 more...
Genre: 3#
FEN: 8/4Q3/8/4K3/4B3/3ppp2/3pkp2/1R2b2R
Input: Felber, Volker, 2022-12-24
Last update: Gunter Jordan, 2022-12-24 more...
1. De5! Kg8 2. De8+ Kh7 3. Dg6#
2. ... Kg7 3. Dg6#,Df7#
1. ... Kh7 2. Dh5+ Kg8 3. Df7#
2. ... Kg7 3. Df7#,Dg6#
2. ... Kg7 3. Dg6#,Df7#
1. ... Kh7 2. Dh5+ Kg8 3. Df7#
2. ... Kg7 3. Df7#,Dg6#
Keywords: Symmetrical position, Symmetrical solution, Minimal (l), Aristocrat, Oneliner
Genre: 3#
FEN: 7b/6k1/5R2/8/3Q4/8/8/K7
Input: Rainer Staudte, 2022-12-29
Last update: Gunter Jordan, 2022-12-29 more...
Genre: 3#
FEN: 7b/6k1/5R2/8/3Q4/8/8/K7
Input: Rainer Staudte, 2022-12-29
Last update: Gunter Jordan, 2022-12-29 more...
1. e4 Kd8 2. Tc1 Ke8 3. Tc8#
1. ... Kf8 2. Tg1 Ke8 3. Tg8#
1. ... Kf8 2. Tg1 Ke8 3. Tg8#
Keywords: Symmetrical position, Symmetrical solution, Oneliner, Minimal (b), Miniature
Genre: 3#
FEN: 4k3/8/4K3/4p3/8/8/4P3/4R3
Input: Rainer Staudte, 2023-01-20
Last update: Rainer Staudte, 2023-01-20 more...
Genre: 3#
FEN: 4k3/8/4K3/4p3/8/8/4P3/4R3
Input: Rainer Staudte, 2023-01-20
Last update: Rainer Staudte, 2023-01-20 more...
1. De7! Kd4 2. Dc5+ Ke4 3. De3#
1. ... Kf4 2. Dg5+ Ke4 3. De3#
1. ... d4 2. Db7+ Kf4 3. Df3#
1. ... f4 2. Dh7+ Kd4 3. Dd3#
1. ... Kf4 2. Dg5+ Ke4 3. De3#
1. ... d4 2. Db7+ Kf4 3. Df3#
1. ... f4 2. Dh7+ Kd4 3. Dd3#
Keywords: Symmetrical position, Symmetrical solution
Genre: 3#
FEN: 4Q3/8/8/3ppp2/1P2k2P/8/4K3/8
Input: Rainer Staudte, 2023-01-21
Last update: Rainer Staudte, 2023-01-21 more...
Genre: 3#
FEN: 4Q3/8/8/3ppp2/1P2k2P/8/4K3/8
Input: Rainer Staudte, 2023-01-21
Last update: Rainer Staudte, 2023-01-21 more...
83 - P1407446
Andrew Buchanan
Discord Chess Problems & Studies Server 25/01/2023
to Siegfried Hornecker
(9+9)
A=>A in exactly 2.0 moves
16 solutions
Andrew Buchanan
Discord Chess Problems & Studies Server 25/01/2023
to Siegfried Hornecker
(9+9)
A=>A in exactly 2.0 moves
16 solutions
Joost de Heer: In the diagram position, all castling rights are present. Each solution leads to a position with different castling rights remaining.
There are 4 different repetitions for white:
* 1. Rb1 2. Ra1 (Only white kingside castling still allowed)
* 1. Rh2 2. Rh1 (Only white queenside castling still allowed)
* 1. Kd2 2. Ke1 (No white castling allowed)
* 1. Sb6 2. Sc8 (All white castling allowed)
Similarly for black: 1. Rb8 2. Ra8 / 1. Rh7 2. Rh8 / 1. Kd7 2. Ke8 / 1. Sb3 2. Sc1
Each combination of these four results in a position with different castling rights, so 4*4=16 solutions.
There's one solution that breaks this pattern: all white castling allowed, no black castling allowed. Following the above scheme would result in the solution 1. Sb6 Kd7 2. Sc8 Ke8, but the first black move is not allowed, so this solution is slightly different: 1. Sd6 Kd7 2. Sc8 Ke8 (2023-02-07)
comment
There are 4 different repetitions for white:
* 1. Rb1 2. Ra1 (Only white kingside castling still allowed)
* 1. Rh2 2. Rh1 (Only white queenside castling still allowed)
* 1. Kd2 2. Ke1 (No white castling allowed)
* 1. Sb6 2. Sc8 (All white castling allowed)
Similarly for black: 1. Rb8 2. Ra8 / 1. Rh7 2. Rh8 / 1. Kd7 2. Ke8 / 1. Sb3 2. Sc1
Each combination of these four results in a position with different castling rights, so 4*4=16 solutions.
There's one solution that breaks this pattern: all white castling allowed, no black castling allowed. Following the above scheme would result in the solution 1. Sb6 Kd7 2. Sc8 Ke8, but the first black move is not allowed, so this solution is slightly different: 1. Sd6 Kd7 2. Sc8 Ke8 (2023-02-07)
comment
Keywords: A to B, Symmetrical position, Asymmetrical solution
Genre: Retro
FEN: r1N1k1Nr/p3Pp2/7p/8/8/7P/P3pP2/R1n1K1nR
Input: A.Buchanan, 2023-01-27
Last update: A.Buchanan, 2023-01-27 more...
Genre: Retro
FEN: r1N1k1Nr/p3Pp2/7p/8/8/7P/P3pP2/R1n1K1nR
Input: A.Buchanan, 2023-01-27
Last update: A.Buchanan, 2023-01-27 more...
1. Df4+! e5+ 2. Sxe5 c5+! 3. Kd3 c4+ 4. Kd4 fxe5+! 5. Dxe5+ Kc6 6. Dxd5#
3. ... d4 4. Dxf6+ Kd5 5. Sc4 ... 6. Sxb6,Dd6#
3. ... f5 4. Dh6+ Kxe5 5. Lc7+ d6 6. Dxd6,Lxd6# (Mattdual)
3. ... d4 4. Dxf6+ Kd5 5. Sc4 ... 6. Sxb6,Dd6#
3. ... f5 4. Dh6+ Kxe5 5. Lc7+ d6 6. Dxd6,Lxd6# (Mattdual)
Keywords: Asymmetrical solution, Cross check, Provoked check, Checking key, Symbol problem (Kreuz), Symmetrical position
Genre: n#
FEN: 3B4/3p4/1ppkpp2/3p4/3K4/3N4/3Q4/8
Input: Gunter Jordan, 2023-07-10
Last update: Gunter Jordan, 2023-07-10 more...
Genre: n#
FEN: 3B4/3p4/1ppkpp2/3p4/3K4/3N4/3Q4/8
Input: Gunter Jordan, 2023-07-10
Last update: Gunter Jordan, 2023-07-10 more...
1. Te8! Kd1,Kd2 2. Tbd8+ Kc1 3. Te1+ Kb2 4. Tb8+ Ka2 5. Tc1 Ka3 6. Ta1#
Keywords: Symmetrical position, Asymmetrical solution, Switchback (Tk), Model mate, Miniature
Genre: n#
FEN: 1R1R4/2K5/8/8/8/2p5/2p5/2k5
Input: Rainer Staudte, 2023-11-17
Last update: Gunter Jordan, 2023-11-17 more...
Genre: n#
FEN: 1R1R4/2K5/8/8/8/2p5/2p5/2k5
Input: Rainer Staudte, 2023-11-17
Last update: Gunter Jordan, 2023-11-17 more...
86 - P1413568
Vladimir Kozhakin
Albert S. Schachnasarjan
908 Kudesnik 63 25/07/2000
Thematurnier
Lob
(5+2)
#4
Vladimir Kozhakin
Albert S. Schachnasarjan
908 Kudesnik 63 25/07/2000
Thematurnier
Lob
(5+2)
#4
1. Sf4! Ke4xf4 2. Dh4+ Sg4 3. Kd3 Ke5 4. Dg5#
1. ... Ke4xd4 2. Db4+ Sc4 3. Kf3 Ke5 4. Dc5#
1. ... Ke4xd4 2. Db4+ Sc4 3. Kf3 Ke5 4. Dc5#
Keywords: Non-standard material (S), Sacrifice key (S,S), Miniature, Minimal (s), Symmetrical position (nach Schlüssel)
Genre: n#
FEN: 4N3/4Q3/8/3Nn3/3Nk3/8/4K3/8
Input: Rainer Staudte, 2023-11-18
Last update: Gunter Jordan, 2023-11-18 more...
Genre: n#
FEN: 4N3/4Q3/8/3Nn3/3Nk3/8/4K3/8
Input: Rainer Staudte, 2023-11-18
Last update: Gunter Jordan, 2023-11-18 more...
1. Sed4! Kc1 2. Kc3 Kd1 3. Le4 Kc1 4. Sb3 Kb1 5. Sb4#
4. ... Kd1 5. Lf3#
2. ... Kb1 3. Sb3 Ka2 4. Sd2#
4. ... Kd1 5. Lf3#
2. ... Kb1 3. Sb3 Ka2 4. Sd2#
Keywords: Echomatt, Symmetrical position, Asymmetrical solution, Aristocrat, Miniature, Rex solus (s)
Genre: n#
FEN: 8/8/8/3B4/8/3K4/2N1N3/3k4
Input: Rainer Staudte, 2023-12-02
Last update: Gunter Jordan, 2023-12-03 more...
Genre: n#
FEN: 8/8/8/3B4/8/3K4/2N1N3/3k4
Input: Rainer Staudte, 2023-12-02
Last update: Gunter Jordan, 2023-12-03 more...
1. g8=D! Ke4 2. Dg4+ Kd5 3. Dc4+ Kd6 4. Ta6+ Kd7 5. Da4+ Tb5 6. Dg4+ Tf5 7. Ta8 Ke6 8. Tf8 Kd7,Ke6~ 9. Td8+ Ke6 10. Tc6+ Kf7 11. Dh5+ Txh5#
Keywords: Minimal (t), Oneliner, Symmetrical position, Promotion (D), Promotion key, Asymmetrical solution, Corner mate, Model mate, Queen sacrifice, Antiphönix
Genre: s#
FEN: 7K/6P1/5B2/4r3/3k4/2R5/1P6/R7
Input: Felber, Volker, 2023-12-14
Last update: Gunter Jordan, 2023-12-14 more...
Genre: s#
FEN: 7K/6P1/5B2/4r3/3k4/2R5/1P6/R7
Input: Felber, Volker, 2023-12-14
Last update: Gunter Jordan, 2023-12-14 more...
1. c8=D? Ke5+! 2. Ke8 Dd5 3. Dc3+ Kd6! 4. Df6+ Kc7! 5. Df4+ Kc8 6. Kf8 Dc5! 7. Kf7 Dh5+! 8. Kf8
6. Dg4+ Kc7! 5. Kf8 Dc5!
3. Kf8 Df3+! oder
2. ... Kf6 3. Dc6+,Da6+ Kg7!
1. e8=D! Kc5+ 2. Kc8! Dd5 3. De3+! Kd6 4. Db6+ Ke7 5. Db4+ Ke8 6. Kb8 De5 7. Kb7 Dd5+ 8. Kb6 De6+ 9. Ka7! Kd7 10. Db7! Da2+ 11. Kb8! Dh2 12. Dd5+ gewinnt, zum Beispiel Ke7 13. Dd4 Dg3 14. Dc5+ Ke8 15. Kb7 Dg7 16. Db5+ Kf8 17. Dd5 Db2+ 18. Kc6 Ke7 19. Dc5+ Kf7 20. c8=D
2. ... Dc3 3. Dg8
2. ... Kb6 3. De6+ Ka7 4. Db3,Dc4 Dg2 5. Da4+ Kb6 6. Dd4+ Kc6 7. Kb8 Dh2 8. Dc3+ Kb5 9. Db3+ Ka5 10. Db7 Ka4 11. Ka8
6. ... Ka6 7. Kd7 Dh3+ 8. Kd8 Kb7 9. Db4+
4. ... Ka6 5. Db7+ Ka5 6. Kb8 Df4 7. Ka8
6. Dg4+ Kc7! 5. Kf8 Dc5!
3. Kf8 Df3+! oder
2. ... Kf6 3. Dc6+,Da6+ Kg7!
1. e8=D! Kc5+ 2. Kc8! Dd5 3. De3+! Kd6 4. Db6+ Ke7 5. Db4+ Ke8 6. Kb8 De5 7. Kb7 Dd5+ 8. Kb6 De6+ 9. Ka7! Kd7 10. Db7! Da2+ 11. Kb8! Dh2 12. Dd5+ gewinnt, zum Beispiel Ke7 13. Dd4 Dg3 14. Dc5+ Ke8 15. Kb7 Dg7 16. Db5+ Kf8 17. Dd5 Db2+ 18. Kc6 Ke7 19. Dc5+ Kf7 20. c8=D
2. ... Dc3 3. Dg8
2. ... Kb6 3. De6+ Ka7 4. Db3,Dc4 Dg2 5. Da4+ Kb6 6. Dd4+ Kc6 7. Kb8 Dh2 8. Dc3+ Kb5 9. Db3+ Ka5 10. Db7 Ka4 11. Ka8
6. ... Ka6 7. Kd7 Dh3+ 8. Kd8 Kb7 9. Db4+
4. ... Ka6 5. Db7+ Ka5 6. Kb8 Df4 7. Ka8
Anton Baumann: 15.Ka7 führt etwas schneller zur 2.Dame:
15.Ka7 Dg7 16.Db5+ Kf8 17.Db8+ Kf7 18.c8=D +_ (2024-01-09)
comment
15.Ka7 Dg7 16.Db5+ Kf8 17.Db8+ Kf7 18.c8=D +_ (2024-01-09)
comment
Keywords: Symmetrical position, Asymmetrical solution, Minimal (d), Miniature, Promotion key, Promotion (D), Discovered check
Genre: Studies
FEN: 8/2PKP3/8/3k4/8/8/3q4/8
Input: Rainer Staudte, 2024-01-08
Last update: Rainer Staudte, 2024-01-12 more...
Genre: Studies
FEN: 8/2PKP3/8/3k4/8/8/3q4/8
Input: Rainer Staudte, 2024-01-08
Last update: Rainer Staudte, 2024-01-12 more...
1) 1. Kb6[Ig1]! Kb8[Ih1] 2. g3[Ih2] Ka8[Ig2] 3. Kc5[Ih1]=
2) 1. g4[Ih3]! Ka7[Ih2] 2. Kc5[Ih1] Ka8[Ih2] 3. Kc4[Ih1]=
2) 1. g4[Ih3]! Ka7[Ih2] 2. Kc5[Ih1] Ka8[Ih2] 3. Kc4[Ih1]=
Keywords: Asymmetrical solution, Pawn step variations, Minimal (B), Oneliner, Rex solus (s), Symmetrical position, Corner mate (-patt), Kindergarten Problem, Miniature, Aristocrat, Aristocrat
Pieces: = Imitator (I)
Genre: Fairies
Computer test: Popeye Windows-64Bit v4.85 (4096 KB)
FEN: k7/8/2K5/8/8/8/6P1/8
Input: Gunter Jordan, 2024-01-21
Last update: Gunter Jordan, 2024-01-21 more...
Pieces: = Imitator (I)
Genre: Fairies
Computer test: Popeye Windows-64Bit v4.85 (4096 KB)
FEN: k7/8/2K5/8/8/8/6P1/8
Input: Gunter Jordan, 2024-01-21
Last update: Gunter Jordan, 2024-01-21 more...
1. a5! Kb5 2. Db6+ Ka4 3. Db4#
2. ... Kc4 3. Db4#
1. ... Kc5 2. Kb3 Kb5 3. Db6#
2. ... Kc4 3. Db4#
1. ... Kc5 2. Kb3 Kb5 3. Db6#
Keywords: Miniature, Rex solus (s), Symbol problem (weihnachtsbaum), Asymmetrical solution, Symmetrical position
Genre: 3#
FEN: 8/2Q5/2P5/8/P1k1P3/2P5/2K5/8
Input: Rainer Staudte, 2024-02-13
Last update: Gunter Jordan, 2024-02-13 more...
Genre: 3#
FEN: 8/2Q5/2P5/8/P1k1P3/2P5/2K5/8
Input: Rainer Staudte, 2024-02-13
Last update: Gunter Jordan, 2024-02-13 more...
1. Dd3! Kc6 2. Db5+ Kd5 3. Dxb3+ Kc6 4. Sf5 ... 5. Se7#
4. ... c4 5. Db5#
4. ... d5 5. Db5,Db6# (Dual)
1. ... Ke6 2. Df5+ und weiter symmetrisch wie oben
4. ... c4 5. Db5#
4. ... d5 5. Db5,Db6# (Dual)
1. ... Ke6 2. Df5+ und weiter symmetrisch wie oben
Henrik Juel: Popeye 4.61 found no solution (2024-02-26)
SCHRECKE: Es fehlen: wBb2+wBf2 (2024-02-26)
Gunter Jordan: ... ja, tatsächlich. Die beiden Bauern fehlen. Danke für den Hinweis - ich habe es korrigiert. (2024-02-27)
Henrik Juel: now C+ Popeye 4.61, except for the mate duals (2024-02-27)
more ...
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SCHRECKE: Es fehlen: wBb2+wBf2 (2024-02-26)
Gunter Jordan: ... ja, tatsächlich. Die beiden Bauern fehlen. Danke für den Hinweis - ich habe es korrigiert. (2024-02-27)
Henrik Juel: now C+ Popeye 4.61, except for the mate duals (2024-02-27)
more ...
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Keywords: Changed continuation, Switchback (k), Symbol problem (Weihnachtsbaum), Symmetrical position, Symmetrical solution
Genre: n#
FEN: 3B4/3p4/3p4/2pkp3/3b4/Np3pN1/1P1Q1P2/3K4
Input: Gunter Jordan, 2024-02-26
Last update: Gunter Jordan, 2024-02-27 more...
Genre: n#
FEN: 3B4/3p4/3p4/2pkp3/3b4/Np3pN1/1P1Q1P2/3K4
Input: Gunter Jordan, 2024-02-26
Last update: Gunter Jordan, 2024-02-27 more...
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The problems of this query have been registered by the following contributors:
Gerd Wilts (6)hpr (1)
Hans-Jürgen Schäfer (11)
Ralf Krätschmer (1)
Hans Gruber (2)
Valery Liskovets (1)
Brian Stephenson (3)
Frank Müller (4)
Felber, Volker (19)
Zuncke/Bruder (9)
Gunter Jordan (7)
Mario Richter (4)
Erich Bartel (4)
Alfred Pfeiffer (2)
Rainer Staudte (10)
James Malcom (1)
A.Buchanan (5)
Kurt Keller (1)
Marcin Banaszek (1)
VL: Cf. P0002475. (2012-08-26)
A.Buchanan: Possibly "Einheitlösung!" is a request to unify retro implications derived across separate parts of the PRA solution. But cooked chessically irrespective of these philosophical issues, which still wait to be resolved 60 years on. (2022-02-16)
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