Die Schwalbe

1350 problem(s) found in 3870 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT G='Fairies' AND COOKED ] [download as LaTeX]

1 - P0000101
Leonid M. Borodatow
Evgeny V. Kharichev

6209v Die Schwalbe 110 04/1988
P0000101
(12+10) cooked
h#3
b) sBh5 nach h6
a) 1. 0-0-0 Sxc7 2. hxg3 Sd5 3. g2 Se7#

Beispielauflösung mri:
R: 1. Kf1-e1 Ta2-a1 2. Kg2-f1 Tb2-a2 3. La2-b1 Tb1-b2 4. Kf3-g2 Tf1-b1 5. Ke3-f3 g5xDh4 6. Lh2-g1 Tg1-f1 7. Dd4-h4 Tg2-g1 8. Lg1-h2 Th2-g2 9. Kd3-e3 Tg2-h2 10. Kc3-d3 Th2-g2 11. Kb2-c3 Tg2-h2 12. Kc1-b2 Th2-g2 13. Kd1-c1 Tg2-h2 14. Ke1-d1 Th2-g2 15. Da1-d4 Tg2-h2 16. Dd1-a1 d6xLc5 17. La3-c5 Th2-g2 18. Lc1-a3 Tg2-h2 19. b2-b3 Th2-g2 20. Ld5-a2 Tg2-h2 21. Sc5-a6 Th2-g2 22. Lg2-d5 h6-h5 23. Lf1-g2 Tg2-h2 24. Lh2-g1 Tg1-g2 25. Sa4-c5 g2-g1=T 26. Sb6-a4 f3xTg2 27. Tg1-g2 f4-f3 28. g2-g3 f5-f4 29. Le5-h2 h7-h6 30. Lg7-e5 f6-f5 31. Lf8-g7 f7-f6 32. e7xLf8=L Lg7-f8 33. e6-e7 Lf8-g7 34. d5xTe6 Tg6-e6 35. Sc8-b6 Tg8-g6 36. Sb6xLc8 g6-g5 37. c4xDd5 Dg5-d5 38. Sd5-b6 Dd8-g5 39. Sg3-h1 e7xTd6 40. Ta6-d6 Th8-g8 41. Ta1-a6 g7-g6 42. b3xSc4 Sa5-c4 43. a2xSb3 Sd4-b3 44. Sc3-d5 Sc6-a5 45. Sb1-c3 Sb8-c6 46. Th1-g1 Sf5-d4 47. Se4-g3 Sh6-f5 48. Sg5-e4 Sg8-h6 49. Sf3-g5 Sh6-g8 50. Sg1-f3 Sg8-h6 51. h2-h3


b) 1. Kf7 f4 2. Kg6 c3,c4+ 3. Kh5 g4#
play all play one stop play next play all
in b) fehlt Schwarz ein Retrotempo zur Aufrechterhaltung des Rochaderechts, es kann maximal eine Stellung wie z.B. r3kB2/pppp1p1p/3p2p1/8/8/7P/1PPPPPP1/1NBQKBRN erreicht werden, in der entweder sTh8 oder sLf8 nicht als Schlagobjekt für die notwendigen weißen Bauernschläge zur Verfügung stand.

Der Dual 2. ... c3+,c4+ in b) war von den Autoren in Kauf genommen worden., die (schon bei der Lösungsveröffentlichung bekannten) NLs aber natürlich nicht. Ein Schwalbe-Löser ("PS") kritisierte den "völlig unnötigen Vorwärtsballast" und schlug implizit vor, das Vorwärtsspiel komplett wegzulassen und stattdessen direkt zu fragen: "Ist die 0-0-0 erlaubt?"
Cook: a) 1. hxg3 Sxg3 2. c6 Sf5 3. 0-0-0 Sd6#
b) 1. Kf7 f4 2. Kg6 c4+ 3. Kh5 g4#
Neufassung 5949.
A.Buchanan: It would be great if someone can retrieve 6209v from Die Schwalbe, please, to confirm the diagram and intended solution. If castling right remains, then sBf must promote on g1=T. There is then some jiggling around because Tg1-h2 to unpin Lg1 and let it go b1. In (a) this is doable, but in (b), Black runs out of tempi however there is an alternative no-castling mate with sKh5. However that's just a rough sketch, and I don't want to spend more time until the actual published form is confirmed (2022-01-08)
Ladislav Packa: Is everything allright here? Because solution a) is not a solution - after 3 .... Se7 # ?? 4.Kc7 / b8! (2022-01-09)
Mario Richter: Indeed, the given solution only works with wLh2 instead of g1. I only have access to the solution, but not to original diagram. Perhaps someoe with access to it can give us the correct details? (2022-01-10)
A.Buchanan: Yes I didn't check the solution to a) matches one of the actual ones. With wLh2, it's still cooked, as is b) in any case. Possible to rearrange the free pieces to make b) sound, but I don't see how to fix a) at the same time. (2022-01-10)
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Keywords: Castling (sg), Cant Castler (sg)
Genre: h#, Retro
FEN: r3k3/pppp4/N7/2p4p/7p/1P4PP/2PPPP2/rB2K1BN
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2022-01-10 more...
2 - P0000112
Dmitri W. Pronkin
Andrey Frolkin

6386v Die Schwalbe 113 10/1988
P0000112
(14+14) cooked
BP in 45.0
1. f4 g5 2. f5 g4 3. f6 g3 4. fxe7 gxh2 5. g4 d5 6. g5 d4 7. g6 d3 8. g7 dxc2 9. d4 f5 10. Lf4 c1=T 11. Lg3 Tc6 12. Dd3 Tg6 13. Da6 Sf6 14. g8=L c5 15. Lb3 c4 16. d5 Kf7 17. e8=T c3 18. Te4 c2 19. Ta4 c1=L 20. e4 Lf4 21. Sd2 h5 22. 0-0-0 h4 23. Te1 h3 24. Ld1 Th4 25. d6 L8h6 26. d7 Dh8 27. d8=T Le6 28. Tc8 S8d7 29. Tc2 Kg8 30. e5 Lf7 31. e6 Tf8 32. e7 Lb8 33. e8=S f4 34. Te7 f3 35. Se2 f2 36. Tg1 h1=S 37. b4 h2 38. Lh3 f1=S 39. b5 Sf2 40. b6 h1=L 41. bxa7 b6 42. a8=L Lb7 43. Th1 Lc8 44. Lag2 Se3 45. Lf1 S6e4
play all play one stop play next play all
Cook: 1. b4 c5 2. b5 c4 3. b6 c3 4. bxa7 d5 5. e4 d4 6. f4 d3 7. f5 dxc2 8. d4 g5 9. Lf4 c1=L 10. d5 g4 11. f6 g3 12. fxe7 gxh2 13. g4 c2 14. Lg3 Lf4 15. g5 c1=T 16. g6 Tc6 17. Dd3 f5 18. Sd2 h5 19. g7 Tg6 20. 0-0-0 Sf6 21. Te1 h4 22. d6 h3 23. g8=L Th4 24. Lb3 L8h6 25. Ld1 Kf7 26. d7 Dh8 27. d8=T Le6 28. Td4 Sbd7 29. e5 Tf8 30. e8=T Kg8 31. Tc8 Lf7 32. e6 b6 33. e7 Lb8 34. e8=S f4 35. Te7 f3 36. Se2 f2 37. Tg1 h1=S 38. Da6 h2 39. Lh3 f1=S 40. Ta4 Sf2 41. Tc2 h1=L
Michel Caillaud: cooked by Stelvio 0.93 :
1.b4 c5 2.b5 c4 3.b6 c3 4.bxa7 d5 5.e4 d4 6.f4 d3 7.f5 dxc2 8.d4 g5 9.Lf4 c1=L 10.d5 g4 11.f6 g3 12.fxe7 gxh2 13.g4 c2 14.Lg3 Lf4 15.g5 c1=T 16.g6 Tc6 17.Dd3 f5 18.Sd2 h5 19.g7 Tg6 20.0-0-0 Sf6 21.Te1 h4 22.d6 h3 23.g8=L Th4 24.Lb3 L8h6 25.Ld1 Kf7 26.d7 Dh8 27.d8=T Le6 28.Td4 Sbd7 29.e5 Tf8 30.e8=T Kg8 31.Tc8 Lf7 32.e6 b6 33.e7 Lb8 34.e8=S f4 35.Te7 f3 36.Se2 f2 37.Tg1 h1=S 38.Da6 h2 39.Lh3 f1=S 40.Ta4 Sf2 41.Tc2 h1=L... (2022-12-20)
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Keywords: Unique Proof Game, Move Length Record, Non-standard material, Castling, Promotion (tLTlTSsslL)
Genre: Retro
FEN: 1bb1Nrkq/3nRb2/Qp4rb/8/R3n2r/4n1BB/P1RNNn2/2KB1B1R
Reprints: 583 Ukrainisches Album 1986-1990
80 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Silvio Baier, 2023-03-02 more...
3 - P0000172
Dmitri W. Pronkin
6991v Die Schwalbe 123 06/1990
P0000172
(13+13) cooked
BP in 24.5
1. Sc3 Sf6 2. Se4 Sd5 3. Sg5 Sc3 4. Sxh7 Sb1 5. Sxf8 Th5 6. h4 Tg5 7. hxg5 Kxf8 8. Th6 Kg8 9. Tb6 Kh7 10. g6+ Kh6 11. e4 Kg5 12. Lb5 Kf4 13. Ke2 Ke5 14. Kf3 Kd4 15. Kf4 Kc5 16. b4+ Kxb4+ 17. La3+ Kxa3 18. Df3+ Kb2 19. a4 Kc1 20. Se2+ Kd1 21. Sc1+ Ke1 22. Sd3+ Kf1 23. Sb2+ Kg1 24. Lf1 Kh1 25. Dd3
play all play one stop play next play all
Cook: 1. Sg1-f3 Sg8-f6 2. Sf3-g5 Sf6-d5 3. Sg5xh7 Sd5-c3 4. Sh7xf8 Th8-h5 5. Sf8-e6 Th5-g5 6. Se6-c5 Ke8-f8 7. b2-b4 Kf8-g8 8. e2-e4 Kg8-h7 9. Dd1-g4 Kh7-g6 10. h2-h4 Kg6-f6 11. h4xg5+ Kf6-e5 12. Dg4-g3+ Ke5-d4 13. Th1-h6 Sc3xb1 14. Ke1-e2 Kd4-c4 15. Ke2-e3+ Kc4xb4 16. Lc1-a3+ Kb4xa3 17. Ke3-f4+ Ka3-b2 18. Th6-b6+ Kb2-c1 19. Lf1-a6 Kc1-d1 20. a2-a4 Kd1-e1 21. Sc5-d3+ Ke1-e2 22. g5-g6 Ke2-f1 23. Sd3-b2+ Kf1-g1 24. La6-f1 Kg1-h1 25. Dg3-d3 (Stelvio v0.93, RA)
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Keywords: Unique Proof Game, Promenade (k)
Genre: Retro
FEN: rnbq4/ppppppp1/1R4P1/8/P3PK2/3Q4/1NPP1PP1/Rn3B1k
Reprints: 579 Ukrainisches Album 1986-1990
113 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2022-12-17 more...
4 - P0000411
Andrey Frolkin
4429 Die Schwalbe 82 08/1983
2. Lob
P0000411
(9+13) cooked
BP in 40,0
1. d4 e5 2. d5 f5 3. d6 Le7 4. dxe7 d5 5. e4 d4 6. Dg4 fxg4 7. c4 d3 8. c5 Dd6 9. b4 Kd7 10. cxd6 c5 11. b5 c4 12. b6 Sc6 13. e8=T d2+ 14. Ke2 c3 15. Kd3 d1=L 16. Sd2 Sd4 17. Tf8 Kc6 18. Tf4 exf4 19. e5 h5 20. e6 Lb3 21. e7 Lf7 22. bxa7 b5 23. e8=T b4 24. Te6 b3 25. Th6 gxh6 26. d7 b2 27. d8=T Lce6 28. Td5 Te8 29. Kc4 b1=L 30. a8=T Lh7 31. Ta3 c2 32. Tg3 Se7 33. a4 Thf8 34. a5 Sg6 35. a6 Sh8 36. a7 fxg3 37. a8=T gxh2 38. T8a3 Lhg8 39. Th3 gxh3 40. Se4 Lxd5+
play all play one stop play next play all
Cook: 1. b4 e5 2. d4 Le7 3. d5 f5 4. d6 h5 5. dxe7 d5 6. b5 Dd6 7. b6 Kd7 8. bxa7 b5 9. c4 b4 10. c5 d4 11. cxd6 c5 12. e8=T Sc6 13. Tf8 c4 14. e4 d3 15. Dg4 d2+ 16. Ke2 c3 17. Kd3 d1=L 18. Sd2 fxg4 19. Tf4 exf4 20. e5 Sd4 21. e6+ Kc6 22. e7 b3 23. e8=T b2 24. Te6 Lb3 25. Th6 Lf7 26. d7+ gxh6 27. d8=T Lce6 28. Td5 Te8 29. Kc4 b1=L 30. a8=T Lh7 31. Ta3 c2 32. Tg3 Se7 33. a4 Thf8 34. a5 Sg6 35. a6 Sh8 36. a7 fxg3 37. a8=T gxh2
38. T8a3 Lhg8 39. Th3 gxh3 40. Se4 Lxd5+
Moldenhauer: Computerprüfung: Cooked Stelvio 1.6 29:20:32 Stunden. (hh:mm:ss)
Da NUPG C+
Notation: 1.b4 e5 2.d4 Le7 3.d5 f5 4.d6 h5 5.dxe7 d5 6.b5 Dd6 7.b6 Kd7 8.bxa7 b5
9.c4 b4 10.c5 d4 11.cxd6 c5 12.e8=T Sc6 13.Tf8 c4 14.e4 d3 15.Dg4 d2+ 16.Ke2 c3
17.Kd3 d1=L 18.Sd2 fxg4 19.Tf4 exf4 20.e5 Sd4 21.e6+ Kc6 22.e7 b3 23.e8=T b2
24.Te6 Lb3 25.Th6 Lf7 26.d7+ gxh6 27.d8=T Lce6 28.Td5 Te8 29.Kc4 b1=L 30.a8=T Lh7
31.Ta3 c2 32.Tg3 Se7 33.a4 Thf8 34.a5 Sg6 35.a6 Sh8 36.a7 fxg3 37.a8=T gxh2
38.T8a3 Lhg8 39.Th3 gxh3 40.Se4 Lxd5+
3 schwarze Läufer stehen zum Schluss auf den weißen Felder d5, f7, g8. (2023-09-21)
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Keywords: Non-Unique Proof Game, Ceriani-Frolkin Theme (TTTTT), Non-standard material (ll), Promotion (TlTTlTT)
Genre: Retro
FEN: 4rrbn/5b2/2k4p/3b3p/2KnN3/7p/2p2PPp/R1B2BNR
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2023-09-22 more...
5 - P0000541
Tivadar Kardos
3398 Die Schwalbe 67 02/1981
P0000541
(13+12) cooked
BP in 6,0
1. Sf3 e5 2. Sxe5 Se7 3. Sxd7 Sec6 4. Sxb8 Dxd2 5. Dxd2 Sxb8 6. Dd8+ Kxd8
play all play one stop play next play all
Cook: 1. Sh3 d5 2. Sf4 Sf6 3. Sxd5 Se4 4. Sxe7 Sxd2 5. Dxd2 Kxe7 6. Dxd8 Kxd8
(Can transpose B1&B2)
HHS ('Schwalbe' Heft 71, Oktober 1981, S. 349): "ein schwarzer Schuft - lässt seinen Zwillingsbruder von einem weissen Söldner killen, um dessen Platz einzunehmen: ein regelrechter Krimi."
Als Vergleichsaufgaben sind in der 'Schwalbe' angegeben: G. Schweig (P0002287), Mortimer (P1394750), W. Naef & H. Klüver (P0002832)
A.Buchanan: It's curious that if we shift sK to e8 (i.e. make the position fully homebase) then it is sound as BP in 6.0! The magic of homebase! :) I don't know if it was a typo - maybe someone can check the magazine archive? (2021-10-19)
A.Buchanan: WinChloe & YACPDB don't know this composition. (2021-10-20)
Mario Richter: No typo, the position with black Kd8 was intended, the cook was found by the 'Schwalbe'-solvers (Heft 71, Oktober 1981, p. 349) (2021-10-21)
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Keywords: Unique Proof Game, Homebase (W), Impostor (s), Superseded by (P1394733)
Genre: Retro
FEN: rnbk1b1r/ppp2ppp/8/8/8/8/PPP1PPPP/RNB1KB1R
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2021-10-21 more...
6 - P0000548
Alexander Kislyak
3463 Die Schwalbe 68 04/1981
Dr. L. Ceriani zum Gedenken
P0000548
(10+13) cooked
BP in 46,0
AL: 1. d4 a5 2. c4 a4 3. b4 a3 4. Lb2 axb2 5. a4 c5 6. a5 b5 7. a6 Lb7 8. a7 Da5 9. bxa5 Sc6 10. a6 0-0-0 11. a8=S Sa5 12. Sc7 b4 13. a7 b3 14. a8=S Sf6 15. Sb6 Kb8 16. Se6 dxe6 17. Sd7 Ka8 18. Sxf8 Td5 19. cxd5 c4 20. d6 c3 21. d7 c2 22. d5 c1=L 23. d6 Ld5 24. Ta4 Se8 25. Tf4 f6 26. Sc3 b1=L 27. d8=S b2 28. d7 Lg6 29. Sb7 b1=L 30. d8=S Lf7 31. Sg6 Lf5 32. Sd6 Lg4 33. Sf5 hxg6 34. Sb7 gxf5 35. Sc5 Th4 36. S5e4 fxe4 37. e3 Lf5 38. Ke2 Tg4 39. h4 Sb3 40. h5 Sa1 41. h6 Ld2 42. h7 Le1 43. h8=S Sc7 44. Sg6 Sb5 45. Sh4 Sa3 46. S4f3 exf3+
play all play one stop play next play all
Korrektur siehe 3463v
James Malcom: How in the world can a non-unique PG be cooked? I'm unmarking it, for now. (2021-01-25)
A.Buchanan: Maybe the intended theme was not forced? Haven’t looked at this problem though (2021-01-26)
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Keywords: Non-Unique Proof Game, Ceriani-Frolkin Theme, Non-standard material (ll), Castling, konsekutive Umwandlungen 8, Promotion, Superseded by (P0000582)
Genre: Retro
FEN: k7/4pbp1/4pp2/3b1b2/5Rr1/n1N1Pp2/4KPP1/n2QbBNR
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-01-26 more...
7 - P0000582
Alexander Kislyak
3463v Die Schwalbe 72 12/1981
Dr. L. Ceriani zum Gedenken
P0000582
(10+13) cooked
BP in 46,0
AL: 1. b4 a5 2. c4 a4 3. d4 a3 4. Lb2 axb2 5. a4 b5 6. a5 c5 7. a6 Da5 8. a7 Sc6 9. bxa5 Lb7 10. a6 0-0-0 11. a8=S b4 12. Sc7 Sa7 13. Se6 Sb5 14. Sxf8 Sh6 15. a7 f6 16. a8=S Sf7 17. Sc7 b3 18. Sce6 dxe6 19. Ta4 Td5 20. cxd5 c4 21. d6 c3 22. d5 c2 23. Sc3 Sg5 24. d7+ Kb8 25. d6 c1=L 26. d8=S b1=L 27. d7 b2 28. Sf7 Lf5 29. Sd6 Lh3 30. d8=S b1=L 31. S8f7 Lg6 32. Sh6 Lf7 33. Sg6 hxg6 34. Shf5 Th4 35. Tf4 gxf5 36. Sde4 fxe4 37. e3 Lf5 38. Ke2 Tg4 39. h4 Sa3 40. h5 Sb1 41. h6 Ka8 42. h7 Ld5 43. h8=S Ld2 44. Sg6 Le1 45. Sh4 Sh3 46. Shf3 exf3+
play all play one stop play next play all
Cook: NL: 1. b4 a5 2. c4 a4 3. d4 a3 4. Lb2 axb2 5. a4 b5 6. a5 c5 7. a6 Sc6 8. a7 Lb7 9. Ta6 Da5 10. bxa5 0-0-0 11. a8=S b4 12. Sc7 b3 13. Se6 Sb4 14. Sxf8 Sf6 15. Te6 dxe6 16. a6 Td5 17. cxd5 c4 18. a7 c3 19. a8=S c2 20. Sc3 c1=L 21. Sb6+ Kb8 22. Sc8 b1=L 23. d6 Lg6 24. d7 b2 25. d8=D b1=L 26. Da5 Lbf5 27. d5 Se4 28. d6 f6 29. d7 Lf7 30. Sg6 hxg6 31. d8=T Lh3 32. Td4 Th4 33. Df5 gxf5 34. Sd6 Sg5 35. Tf4 Ka8 36. S6e4 fxe4 37. e3 Lf5 38. Ke2 Tg4 39. h4 Sc2 40. h5 Sa3 41. h6 Sb1 42. h7 Ld5 43. h8=S Sh3 44. Sg6 Ld2 45. Sh4 Le1 46. Shf3 exf3+
James Malcom: Again, how is this cooked? (2021-01-25)
A.Buchanan: The AL has 5 Wh S promotions in 46.0 moves but the cook shows this is not necessary. (2021-01-26)
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Keywords: Non-Unique Proof Game, Ceriani-Frolkin Theme (SSSSS), Non-standard material (ll), Castling, Promotion, konsekutive Umwandlungen 8
Genre: Retro
FEN: k7/4pbp1/4pp2/3b1b2/5Rr1/2N1Pp1n/4KPP1/1n1QbBNR
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-01-26 more...
8 - P0000615
Andrey Lobusov
4088 Die Schwalbe 77 10/1982
14.Lob
P0000615
(15+6) cooked
h#2* (AP)
1. ... Kg5 2. 0-0?? Se7#
1. ... Txh7 2. Kf8 Txh8#

1. cxb3ep Txh7 2. Kf8?? Txh8#
1. cxb3ep Kg5 2. 0-0! Se7#
play all play one stop play next play all
Wh captured 10 by pawns (including hxPg-g8) but not on the last move. wPa3 came from a2: wPa5 captured bPa.
Bl took only b3xa2.
In set play, Bl has no last move except for K or R.
For the main play, the intention is that if Bl retains castling rights, last moves were R: 1. b2-b4 b3xa2 e.g. 2. Bg1-d4 b4-b3 3. d4xc5 etc. However there are retro cooks e.g. R: 1. Bg1-d4 b3xa2 2. d4xc5 etc, with wPa5 the original wPb. wPb4 & wPb5 come from further East.
Cook: Retro logic for main play is unsound.
A.Buchanan: Not trivial to fix as shifting wPa5 to b6 leads to promotion cooks. Adding black material must be carefully done to avoid disrupting uniqueness of e.p. as tempo. (2022-03-11)
A.Buchanan: OK just to say I have found a form of this idea that works. This one was the very devil to fix - the final form includes different mates and retro logic, so becomes an "after" rather than a "correction", and I will find somewhere else to publish first. (2022-03-19)
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Keywords: Castling (sk), a posteriori (AP) (Type Petrovic), En passant as key, Tempo Move, Superseded by (P1409841)
Genre: h#, Retro
Computer test: Popeye v4.87 & simple retro-logic
FEN: 4k2r/5p1p/5K1R/PPP2N2/1PpB4/P1P5/p1RNB1P1/Q7
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-20 more...
9 - P0000653
Eliahu Fasher
2311 Die Schwalbe 48 12/1977
P0000653
(12+14) cooked
h#2 (wer?)
Kees: possible fix: Lb1=Sb1 -De1 +Ld1
White begins: 1.Kxb7 Lxe2 2.Kc8 La6#
(1.Txd8+ Kxd8 2.Kf8 Th8# illegal for white has no last move) (2023-06-07)
A.Buchanan: Your fix is good, Kees. It removes the cook, and sLd1 denies R: 1. c2xb3 as well as sLb1 did. Note R: 1 Sc6-d8 0-0+? as black castling rights were lost to let wK enter the back rank. (2023-06-08)
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Genre: h#, Retro
FEN: 1bKN1rk1/1ppn1r1R/5p1P/4pP1p/3p1p2/1PP3P1/PP2P3/Rb2q3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-08 more...
10 - P0000674
Leonid M. Borodatow
2475 Die Schwalbe 51 06/1978
P0000674
(12+11) cooked
h#3
1. ... Kgxf4 2. Tf6 e6 3. Tf8 Sg7#
play all play one stop play next play all
Cook: 1. ... exf6ep 2. 0-0-0 gxf4 3. Td7 a8=D
Failed try, as Bg4xBh5 allows bRh8 to have escaped the cage prior to ep.
Anton Baumann: Sollte eine Verbesserung von P0000777 sein.
Autorabsicht: "letzter Zug f7-f5 sonst retropatt! Jetzt ist aber die Rochade illegal, da der sTh8 nur über e8 aus seiner Ecke kommt. Daher Verführung 1. ... exf6 e.p. 2.0-0-0? Lxf4 3.Td7 a8=D#. Lösung: 1. ... Kxf4 2.Tf6 e6 3.Tf8 sg7#"
Aber: Der s h-Bauer kann auch auf h5 geschlagen worden sein; so konnte der sT über h6 aus seiner Ecke entkommen. Die vermeintliche Verführung ist also NL! (2022-12-14)
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Keywords: Castling (sg), Superseded by (P0000058)
Genre: h#, Retro
FEN: r3k3/P7/p1r3pP/4PpBN/3ppnKn/6P1/1PP2PPq/7N
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-16 more...
11 - P0000684
Simo Ylikarjula
2531 Die Schwalbe 52 08/1978
P0000684
(15+15) cooked
BP in 18,0
NL: 1. d4 d6 2. Kd2 Le6 3. g4 f5 4. g5 Lf7 5. g6 Sd7 6. e4 Db8 7. gxf7+ Kd8 8. Kc3 g5 9. Kc4 g4 10. Kd5 Lg7 11. Ke6 Kc8 12. f8=L g3 13. Kf7 g2 14. Ke8 gxf1=L 15. e5 Lg2 16. Se2 d5 17. Lg5 Lh3 18. e6
Die Autorlösung wurde nie publiziert und ist unbekannt.
play all play one stop play next play all
Moldenhauer: Computerprüfung: C+ NUPG cooked Stelvio 1.11 in 1 Sekunde.
Keine Lösung: BP 17.0. BP 17.5 cooked.
Beispiel BP 18.0: 1.d4 Sa6 2.Kd2 Sb8 3.Kc3 d6 4.e4 Le6 5.Se2 Sd7 6.e5 Db8 7.g4 Kd8
8.g5 f5 9.g6 Lf7 10.gxf7 Kc8 11.Kc4 g5 12.Kd5 Lg7 13.Ke6 d5 14.f8L g4 15.Kf7 g3
16.Ke8 g2 17.Lg5 gxf1L 18.e6 Lh3
Beispiel BP 17.5: 1.d4 Sa6 2.Kd2 Sc5 3.Ke3 d5 4.Kf4 Le6 5.Ke5 Kd7 6.e4 Db8
7.g4 Kc8 8.g5 f5 9.g6 Lf7 10.gxf7 Sd7+ 11.Ke6 g5 12.Se2 Lg7 13.e5 g4 14.Lg5 g3
15.f8L g2 16.Kf7 gxf1L 17.Ke8 Lh3 18.e6 (2023-05-07)
comment
Keywords: Non-Unique Proof Game, Non-standard material
Genre: Retro
FEN: rqk1KBnr/pppnp1bp/4P3/3p1pB1/3P4/7b/PPP1NP1P/RN1Q3R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2014-05-20 more...
12 - P0000759
Luis Alberto Garaza
1034 Die Schwalbe 21 06/1973
P0000759
(9+9) cooked
Schwarz am Zug, Weiß gewinnt
1. ... fxg3ep 2. hxg3+ Kh5 3. f4 Kh6 4. h8=T+! Kg7
play all play one stop play next play all
Cook: Intended a Posteriori combo of castling and ep rights retro-locks wTh in cage, contradicting pawn capture balance
hans: only black move is fxg3e.p.
1. fxg3+ Kh5 2. h8D/T#
Why the keyword 'castling'?
Castling is illegal, for there are 7 black captures, and because white's last move is g2-g4, needs the wK let pass Rh1 (2012-05-18)
Anton Baumann: g2-g4 war nicht zwingend der letzte Zug! Schwarz ist patt, also unlösbar!
Korrektur in 'die Schwalbe' 12/2074 S.264: "wTa1 nach h1. Nun gewinnt nach 1. - fxg3 Weiss mit 2.hxg3+ Kh5 3.f4 Kh6 4.h8=T+! Kg7 und der umgewandelte Turm holt die störenden sBB ab, sodass Weiss rochieren kann und beweist, dass Schwarz nicht patt war. Schwarz versucht die Rochade zu verhindern, ist aber machtlos." (2022-12-06)
A.Buchanan: The forward play is more complicated, as Black can play more aggressively than 3. … Kh6 (2022-12-07)
Anton Baumann: Wenn Schwarz nicht 3.-Kh6! zieht, holt sich Weiss auf h8 die Dame, mit einfacherer Fortsetzung.
3.-g4? 4.f5 Kg5 (4.-g5 5.f6 ~ 6.h8=D) 5.h8=D Kxf5 6.De8 +_
3.-Kg4? 4.h8=D Kf3 5.Dxh3 g4 6.Dh2 Ke4 7.Dg2+ +_ (2022-12-09)
more ...
comment
Keywords: Castling (wl), a posteriori (AP) (Type Petrovic), En passant as key
Genre: Retro, Studies
FEN: 8/7P/6p1/2p3p1/2p2pPk/2Pp1P1p/3PpP1P/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-07 more...
13 - P0000777
Leonid M. Borodatow
1424 Die Schwalbe 30 12/1974
P0000777
(12+10) cooked
h#2.5
1. ... exf6ep 2. 0-0-0? Lxf4 3. Td7 a8=D# try
1. ... Kxf4 2. Tf6 e6 3. Tf8 Sg7# solution
play all play one stop play next play all
Cook: 1. ... Kxf4 2. Te7 e6 3. Tb8 axb8=D,T#
See P0000674
Henrik Juel: The stipulation should probably read h#2.5: 1.exf6ep 0-0-0 2.Bxf4 Rd7 3.a8Q# (2003-08-18)
Anton Baumann: Letzter Zug war f7-f5, sonst retropatt. Die weissen Bauern haben 6x geschlagen. Der s a-Bauer wurde so ebenfalls als Schlagopfer benötigt und musste 2x schlagen, um sich umwandeln zu können. Weiss hat also auf h6 den s Bauern geschlagen. Unabhängig davon ob der sTe6 ein Umwandlungsturm ist oder nicht, muss der sTh8 über e8 aus der Ecke gekommen sein. Also ist die Rochade illegal!
Autorabsicht: 1. ... exf6 e.p. 2.0-0-0 Lxf4 3.Td7 a8=D# ist die Verführung!
Lösung: 1. ... Kxf4 2.Tf6 e6 3.Tf8 Sg7#
leider geht auch: 1. ... Kxf4 2.Te7 e6 3.Tb8 axb8=D,T# (2022-12-13)
A.Buchanan: I agree Anton. I suggest as a fix -bBa6 +bDc2. I think retro, solution and try all work correctly now. Do you folks agree? (2022-12-13)
Anton Baumann: Der Vorschlag von Andrew ergibt eine korrekte Lösung, aber nicht im Sinne des Autors: ohne einen s Stein auf a6 ist f6-f5+ als letzter Zug möglich, d.h. kein Retropatt weil Weiss a6-a7 zurücknehmen kann! 1. ... exf6 e.p. ist deshalb nicht zulässig. LB wollte aber dass f7-f5 der letzte Zug war, damit aber die Rochade illegal ist! (2022-12-14)
Anton Baumann: Mögliche Korrektur: a6=sL, g2=sD (2022-12-15)
A.Buchanan: Yes I agree. I had overlooked the unmove of wPa7 (2022-12-15)
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comment
Keywords: Castling (sg), Valladao Task, Superseded by (P0000058)
Genre: h#, Retro
FEN: r3k3/P7/p3r1pP/4PpBN/3nnpKP/6PB/1P2PPb1/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-16 more...
14 - P0000899
Giuseppe Brogi
743 Die Schwalbe 06/1972
P0000899
(8+15) cooked
h#2
b) wSa1
a) 1. T2xh3 Txh3 2. 0-0 Th8#
b) 1. La4 0-0 2. Tf8 Te1#
play all play one stop play next play all
a) White cannot cross-capture, so because of sTh2, w0-0 impossible.
wBe captured sD, either to be captured on f-file or to promote without disrupting sKe8.
b) sTh2 can return to a8 only via e8 as Black cannot cross-capture, so s0-0 is impossible.
wBe was waylaid or promoted after disrupting sKe8.
Cook: 1. T2xh3 Lb4 2. Txg3 Txh8#
1. Sd2 Lf6 2. Tf8 Sd6#
(cooked by MR)
See P0003736 a companion problem.
milan: [-bPa7b6wPg3bSa1+bPg3bBa5-b4 bPc6-d6] h#2 1.2...bRh2? illegal move? M.Frelih (2023-03-30)
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comment
Keywords: Cant Castler, Castling (wksk), Cross-capture (s,w), Superseded by (P1399805)
Genre: h#, Retro
Computer test: Popeye v4.87
FEN: B3k2r/pN1p1p2/1pp3p1/bb3p2/8/p1B3PP/5P1r/nn2K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-16 more...
15 - P0000914
Vladimir Archakov
852 Die Schwalbe 17 11/1972
P0000914
(14+3) cooked
#2*
Set Play
1. ... Kxh1 2. Kf2#
1. ... Kxh3 2. Sf4#
1. ... Kxf3 2. Lb7#
BTM
1. ... hxg5 2. Sc3
2. ... Kxh1 3. Kf2#
2. ... Kxh3 3. Lf1#
2. ... Kxf3 3. 0-0#
play all play one stop play next play all
Cook: 1. ... hxg5 2. Kd2 Kxh3 3. Df1# 2. ... Kxf3 3. Lb7#
A.Buchanan: We can +wBd2, but then need to e.g. transpose wLg7 & wBg5, otherwise the wBB are impossibly concentrated in corner. Then I think it's sound. (2021-10-08)
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comment
Keywords: Castling (wk), No legal last move for Black, Superseded by (P1394496)
Genre: Retro
Computer test: C- Popeye v4.87
FEN: 8/6BR/B6p/6PP/3P2Np/5P1P/4N1kP/Q3K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-12 more...
16 - P0001569
Andrey Frolkin
439v Europe Echecs 310 10/1984
Lob
P0001569
(12+14) cooked
BP in 27,0
1. f4 h5 2. f5 h4 3. f6 h3 4. fxe7 f5 5. d4 Kf7 6. e8=T Kg6 7. Te6+ Kh5 8. Ta6 bxa6 9. Dd2 Lb7 10. e4 Lc6 11. e5 La4 12. e6 Sc6 13. e7 Db8 14. e8=T Db3 15. Te5 Te8 16. d5 Te6 17. dxe6 Lb4 18. Ta5 Lc3 19. Lb5 f4 20. e7 f3 21. e8=T f2+ 22. Ke2 f1=S 23. Tb8 Sxh2 24. Tb6 cxb6 25. Sf3 bxa5 26. Se5 Sf3 27. Sg4 Sfd4+
play all play one stop play next play all
Cook: 1. f4 h5 2. f5 h4 3. f6 h3 4. fxe7 f5 5. e4 Kf7 6. e8=T f4 7. Te6 f3 8. Ta6 bxa6 9. e5 Kg6 10. e6 Lb7 11. e7 Lc6 12. e8=T La4 13. Te5 Sc6 14. Ta5 Db8 15. d4 Db3 16. Lb5 f2 17. Ke2 f1=S 18. Sf3 Te8 19. Se5 Kh5 20. d5 Te6 21. dxe6 Sxh2 22. e7 Sf3 23. e8=T Lb4 24. Tb8 Lc3 25. Tb6 cxb6 26. Sg4 bxa5 27. Dd2 Sd4
more ...
comment
Keywords: Ceriani-Frolkin Theme (TTT), Unique Proof Game, Non-standard material, Promotion (s)
Genre: Retro
Computer test: Computerprüfung: Cooked Stelvio 1.11 1 Sekunde. Keine Lösung: BP 26.0, BP 26.5.
FEN: 6nr/p2p2p1/p1n5/pB5k/b2n2N1/1qb4p/PPPQK1P1/RNB4R
Reprints: 21 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-08 more...
17 - P0001580
Dmitri W. Pronkin
450 Europe Echecs 319/320 07-08/1985
P0001580
(12+11) cooked
BP in 31,5
1. b4 h5 2. Lb2 h4 3. Dc1 h3 4. Kd1 hxg2 5. h4 e5 6. h5 e4 7. h6 e3 8. h7 exf2 9. e4 f5 10. Se2 g1=L 11. Lg2 f1=L 12. e5 Lb6 13. d4 Lfc5 14. dxc5 f4 15. cxb6 f3 16. Df4 f2 17. Sc1 La6 18. Sd2 f1=L 19. Tb1 Lfb5 20. c4 Se7 21. cxb5 Tg8 22. hxg8=L g5 23. Lc4 d5 24. bxa6 Lf5 25. e6 Sc8 26. e7 Kf7 27. e8=L+ Kg8 28. Leb5 c6 29. Tf1 cxb5 30. Tf2 Sc6 31. Sf1 dxc4+ 32. Ld5+
play all play one stop play next play all
Cook: 1. b4 e5 2. Lb2 e4 3. Dc1 e3 4. Kd1 exf2 5. g4 Ld6 6. g5 Lxh2 7. g6 Kf8 8. gxf7 g5 9. Lg2 f1=L 10. e4 Lb5 11. Se2 Lg1 12. Th4 h5 13. e5 Kg7 14. c4 Th6 15. cxb5 Ta6 16. Tc4 Lc5 17. d4 h4 18. e6 h3 19. e7 h2 20. e8=D d5 21. bxa6 Se7 22. Db5 c6 23. Sd2 cxb5 24. Sf1 h1=D 25. f8=T Dh6 26. Tf2 Db6 27. Df4 Lf5 28. Tb1 Kg8 29. dxc5 Sc8 30. cxb6 Sc6 31. Sc1 dxc4+ 32. Ld5+
Paulo Roque: obs: Cook: 26...D6b6 (2008-12-24)
paul: See P0001634 as correction. (2010-09-25)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.6 in 31:54:04 Stunden. (hh:mm:ss).
1 Lösung mit 20 cooks. (2024-01-07)
comment
Keywords: Ceriani-Frolkin Theme (lllLL), Unique Proof Game, Promotion (lllLL)
Genre: Retro
FEN: r1nq2k1/pp6/PPn5/1p1B1bp1/1Pp2Q2/8/PB3R2/1RNK1N2
Reprints: 26 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-04-06 more...
18 - P0001600
Pascal Wassong
470 Europe Echecs 334 10/1986
P0001600
(13+14) cooked
BP in 20,0
1. b4 c5 2. b5 Sc6 3. bxc6 b5 4. c7 La6 5. c8=L d6 6. Lf5 Tc8 7. d4 Tc6 8. d5 Db8 9. dxc6 e6 10. c7 Le7 11. c8=S Ld8 12. Se7 Lb6 13. Sg6 hxg6 14. h4 Ke7 15. h5 Kf6 16. h6 Se7 17. h7 Te8 18. h8=T gxf5 19. Th4 Sg6 20. Te4 fxe4
play all play one stop play next play all
Cook: 1. b4 c5 2. b5 Sc6 3. bxc6 b5 4. d4 La6 5. d5 Tc8 6. d6 Tc7 7. dxc7 Db8 8. c8=L d6 9. Lf5 e6 10. h4 Ke7 11. h5 Kf6 12. c7 Le7 13. c8=S Ld8 14. Se7 Lb6 15. Sg6 Se7 16. h6 hxg6 17. h7 Te8 18. h8=T gxf5 19. Th4 Sg6 20. Te4 fxe4
Henrik Juel: Dual: ... 4.d4 La6 5.d5 Tc8 6.d6 Tc7 7.dxc7 Db8 8.c8L d6 9.Lf5 ... (2004-02-12)
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comment
Keywords: Ceriani-Frolkin Theme (TLS), Unique Proof Game, Homebase (W), Promotion
Genre: Retro
Computer test: Ergänzung Stelvio 1.2. Keine Lösung BP 19.0, BP 19.5.
FEN: 1q2r3/p4pp1/bb1ppkn1/1pp5/4p3/8/P1P1PPP1/RNBQKBNR
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-21 more...
19 - P0001617
Michel Caillaud
487 Europe Echecs 346 10/1987
P0001617
(9+7) cooked
#1 vor 12
VRZ, Typ Proca
paul: Cooked in 4: 1.Ke5-e6! b2×Ba1=B+ -2.Kf4×Pe5 e6-e5+ -3.Rc2×Sg2 Se1-g2+ -4.Re2×Pc2 & 1.Rxe1# (2023-06-14)
comment
Keywords: En passant, Defensive Retractor, Type Proca
Genre: Retro
FEN: 8/4p3/3PK1P1/8/1B5p/1P1qPP1p/P5Rp/b2k4
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2004-08-28 more...
20 - P0001640
A. d'Ales
509 Europe Echecs 367/368 07/1989
P0001640
(15+16) cooked
KBP in 25,0
NL: 1. b4 a5 2. h4 d6 3. Th3 g6 4. Te3 Lg7 5. g3 Lc3 6. Lh3 Ta6 7. Kf1 Tc6 8. Kg2 b6 9. Kf3 Dd7 10. Ke4 Tc4+ 11. Kd5 Dxh3 12. Sf3 Lg4 13. Sd4 Sd7 14. Sb3 Td4+ 15. Kc6 Se5+ 16. Kb7 Kd7 17. Dh1 Ke6 18. Kc8 Lh5 19. Da8 Kf5 20. g4+ Kf4 21. f3 Kg3 22. Kd8 Kf2 23. Ke8 Ke1
AL wurde nie veröffentlicht.
play all play one stop play next play all
Moldenhauer: Computerprüfung: Cooked Stelvio 1.6 01:00:21 Stunde. (hh:mm:ss)
1.Sf3 a5 2.b4 g6 3.h4 Lg7 4.Th3 Lc3 5.Sd4 Ta6 6.Te3 Tc6 7.g3 Tc4 8.Lh3 d6 9.Kf1 Dd7
10.Kg2 Dxh3+ 11.Kf3 Lg4+ 12.Ke4 Sd7 13.Kd5 b6 14.Sb3 Td4+ 15.Kc6 Se5+ 16.Kb7 Kd7
17.Dh1 Ke6 18.Kc8 Kf5 19.Da8 Lh5 20.g4+ Kf4 21.f3 Kg3 22.Kd8 Kf2 23.Ke8 Ke1
Keine Lösung: BP 22.5.
Wenn die Forderung KBP 25.0 richtig ist dann Cooked. (2023-09-28)
comment
Keywords: Interchange, Non-Unique Proof Game, Non-Unique Proof Game
Genre: Retro
FEN: Q3K1nr/2p1pp1p/1p1p2p1/p3n2b/1P1r2PP/1Nb1RP1q/P1PPP3/RNB1k3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2014-05-21 more...
21 - P0001641
Francois Brassaud
510 Europe Echecs 367/368 07/1989
A. Hazebrouck gewidmet
P0001641
(13+14) cooked
KBP?
1. h4 e5 2. h5 Ke7 3. h6 Kd6 4. hxg7 Kc5 5. Th6 Kb4 6. Tc6 h5 7. e4 h4 8. Ke2 h3 9. Kf3 Th4 10. Le2 Sh6 11. g8=L f6 12. Lb3 h2 13. c4 h1=S 14. Dc2 Sg3 15. fxg3 a5 16. g4 a4 17. g5 axb3 18. g6 bxc2 19. g7 cxb1=T 20. g8=D
play all play one stop play next play all
Cook: 1. c2-c4 a7-a6 2. e2-e4 e7-e6 3. f2-f4 h7-h5 4. Dd1xh5 Ke8-e7 5. Dh5-b5 Th8-h4 6. Ke1-e2 Th4-g4 7. h2-h4 a6xb5 8. h4-h5 b5-b4 9. h5-h6 Ke7-d6 10. h6-h7 Kd6-c5 11. Th1-h6 Tg4-h4 12. h7-h8=D g7-g6 13. Dh8-c3 b4xc3 14. Ke2-f3 c3-c2 15. f4-f5 c2xb1=T 16. f5xg6 Kc5-b4 17. g6-g7 e6-e5 18. Th6-c6 f7-f6 19. Lf1-e2 Sg8-h6 20. g7-g8=D (H. Juel)
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comment
Keywords: Allumwandlung, Ceriani-Frolkin Theme (Ls), Unique Proof Game, Non-standard material
Genre: Retro
Computer test: Euclide 1.01 Moldenhauer: Computerprüfung: Cooked Stelvio 1.11 2 Sekunden. Keine Lösung: BP 18.5, BP 19.0. KBP = 19.5.
FEN: rnbq1bQ1/1ppp4/2R2p1n/4p3/1kP1P2r/5K2/PP1PB1P1/RrB3N1
Reprints: 135 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-04-15 more...
22 - P0001657
Philippe Leroy
526 Europe Echecs 376 04/1990
P0001657
(13+11) cooked
BP in 37,0
1. h4 d5 2. h5 d4 3. h6 d3 4. hxg7 h5 5. g4 h4 6. g5 h3 7. e4 h2 8. Sh3 Th6 9. Tg1 h1=D 10. e5 Dc6 11. Lg2 Dc3 12. dxc3 Tc6 13. e6 Sh6 14. g8=L Lg7 15. exf7 Kf8 16. Sd2 e5 17. Sf3 e4 18. Sh4 d2 19. Ke2 e3 20. Kf3 e2 21. g6 e1=D 22. Tb1 Dee7 23. De1 d1=T 24. Lg5 Da3 25. bxa3 Td4 26. Tb3 Tb4 27. cxb4 Lb2 28. Le7 Kg7 29. f8=S Sa6 30. Lc4 Sf7 31. Sd7 Kh6 32. Sb6 cxb6 33. g7 Sc7 34. La6 bxa6 35. g8=T Lb7 36. Tg5 Tc8 37. Ta5 bxa5
play all play one stop play next play all
Cook: 1. h4 d5 2. h5 e5 3. h6 f5 4. hxg7 h5 5. Sa3 h4 6. Sc4 h3 7. Sb6 h2 8. e4 Th3 9. exf5 Ta3 10. Sh3 Sa6 11. Tg1 h1=D 12. g4 Df3 13. f6 Dc3 14. dxc3 cxb6 15. Tb1 Sc7 16. La6 bxa6 17. bxa3 Lb4 18. cxb4 Sh6 19. g8=L d4 20. Ld5 Kf8 21. Lg2 e4 22. Ke2 e3 23. Kf3 e2 24. f7 Kg7 25. f8=S e1=L 26. Sg6 Lc3 27. Sh4 d3 28. g5 d2 29. De1 d1=T 30. g6 Td6 31. Lg5 Tc6 32. Le7 Sf7 33. Tb3 Kh6 34. g7 Lb2 35. g8=T Lb7 36. Tg5 Tc8 37. Ta5 bxa5
A.Buchanan: The unsoundness in this non-unique PG is that 6 promotions (apparently intended) are not forced (2023-05-11)
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comment
Keywords: Ceriani-Frolkin Theme (dLdtST), Promotion, Non-Unique Proof Game, konsekutive Umwandlungen 6
Genre: Retro
Computer test: Computerprüfung: many solutions Stelvio 1.11 48 Sekunden. Keine Lösung: BP 36.0, BP 36.5.
FEN: 2rq4/pbn1Bn2/p1r4k/p7/1P5N/PR3K1N/PbP2PB1/4Q1R1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-11 more...
23 - P0001762
Ivan Arandjelovic
2123 diagrammes 90 07-09/1989
P0001762
(16+16) cooked
BP in 16,0
1. e3 Sc6 2. La6 b5 3. Lb7 Tb8 4. La8 La6 5. a4 Tb7 6. Ta3 Db8 7. Td3 Kd8 8. Td6 Kc8 9. d3 Sd8 10. Tb6 c6 11. Ld2 Kc7 12. Lc3 Kd6 13. Lf6 Kc5 14. Sc3 Kb4 15. Dg4+ Ka5 16. Sce2 De5
play all play one stop play next play all
Cook: 1. d3 b5 2. Lg5 La6 3. e3 Sc6 4. Dg4 Db8 5. Le2 Db6 6. Lf3 0-0-0 7. a4 Kb7 8. Ta3 Dc5 9. Sc3 De5 10. Sce2 Kb6 11. Tc3 Tb8 12. Lf6 Sd8 13. La8 Tb7 14. Tc6+ Ka5 15. Tb6 c6
Moldenhauer: Ergänzung: Stelvio 1.2. Keine Lösung: BP 14.0, BP 14.5.
BP 15.0 und BP 15.5 cooked.
Notation BP 15.0: 1.Sc3 Sc6 2.a4 b5 3.Ta3 La6 4.d3 Db8 5.Lg5 Db6 6.Lf6 0–0–0
7.e3 Kb7 8.Dg4 Dc5 9.Le2 Kb6 10.Lf3 Ka5 11.Sce2 Tb8 12.Tc3 Sd8 13.La8 De5
14.Tc6 Tb7 15.Tb6 c6
Notation BP 15.5: 1.Sc3 Sc6 2.a4 b5 3.Ta2 La6 4.Ta3 Db8 5.d3 Db6 6.Lg5 0–0–0
7.e3 Kb7 8.Dg4 Dc5 9.Le2 Kb6 10.Lf3 Ka5 11.Sce2 Tb8 12.Tc3 Sd8 13.La8 De5
14.Tc6 Tb7 15.Tb6 c6 16.Lf6.
Alles schlagfrei und ohne Umwandlung. (2023-05-20)
comment
Keywords: Unique Proof Game, Capture-free
Genre: Retro
FEN: B2n1bnr/pr1ppppp/bRp2B2/kp2q3/P5Q1/3PP3/1PP1NPPP/4K1NR
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2014-05-23 more...
24 - P0001765
Kostas Prentos
26 Phénix 1 05/1988
P0001765
(11+15) cooked
BP in 18,5
1. Sf3 f5 2. Sd4 Kf7 3. Sb5 Kg6 4. Sd6 exd6 5. e4 Le7 6. e5 Lh4 7. e6 Df6 8. e7 Dxb2 9. e8=S Se7 10. Lc4 Tf8 11. 0-0 Tf6 12. f3 Kh5 13. Te1 Th6 14. Lf7+ Sg6 15. Te7 Dxc1 16. De1 Dxd2 17. De6 dxe6 18. Td7 Dg5 19. Sxg7#
play all play one stop play next play all
Cook: 1. d4 g5 2. Sf3 Lg7 3. e4 Lxd4 4. e5 Lxb2 5. Dd6 exd6 6. e6 f5 7. e7 Kf7 8. e8=S Se7 9. Sxg5+ Kg6 10. Lc4 Kh5 11. 0-0 Tg8 12. Te1 Tg6 13. f3 Th6 14. Lf7+ Sg6 15. Te7 Lf6 16. Se6 dxe6 17. Td7 Lh4 18. Lg5 Dxg5 19. Sg7#
Kostas Prentos: A correction was published in Phenix, 2009 (No.186/Pg.7979)
Solution:
1. Sf3 f5 2. Sd4 Kf7 3. Sb5 Kg6 4. Sd6 exd6 5. e4 Le7 6. e5 Lh4 7. e6 Dg5 8. e7 Dg3 9. e8=T Se7 10. Lc4 Tf8 11. 0-0 Tf6 12. f3 Kh5 13. Te1 Th6 14. Lf7+ Sg6 15. T1e6 dxe6 16. Txc8 Sd7 17. Th8 Txh8 18. Le8 (2022-12-08)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.2 00:33:56 Minuten. (hh:mm:ss)
Keine Lösung: BP 17.5, BP 18.0.
Beispiel: 1.Sf3 f5 2.d4 Kf7 3.e4 g5 4.Lc4+ Kg6 5.e5 Lg7 6.e6 Lxd4
7.0–0 Lxb2 8.Dd6 exd6 9.e7 Kh5 10.e8S Se7 11.Te1 Tf8 12.Sxg5 Tf6
13.f3 Th6 14.Lf7+ Sg6 15.Te7 Lf6 16.Se6 dxe6 17.Td7 Lh4 18.Lg5 Dxg5
19.Sg7# (2023-05-30)
comment
Keywords: Unique Proof Game, Castling, Promotion
Genre: Retro
FEN: rnb5/pppR1BNp/3pp1nr/5pqk/7b/5P2/P1P3PP/RN4K1
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2006-10-15 more...
25 - P0002257
Ulrich Ring
5674 feenschach 93 11-12/1989
P0002257
(13+15) cooked
BP in 23,5
1. e4 h5 2. Dg4 hxg4 3. d4 Th3 4. d5 Tb3 5. Le3 b5 6. Lb6 axb6 7. h4 Ta4 8. h5 La6 9. h6 Dc8 10. h7 Db7 11. Th6 Da7 12. Tc6 dxc6 13. e5 Kd7 14. e6+ Kd6 15. exf7 Kc5 16. d6 e5 17. d7 e4 18. d8=D e3 19. Dd1 Ld6 20. f8=L g6 21. Lh6 e2 22. Lc1 Tf4 23. h8=T Kb4 24. Th1
play all play one stop play next play all
Cook: 1. e4 h5 2. Dg4 hxg4 3. d4 Th3 4. d5 Tb3 5. Le3 b5 6. Lb6 axb6 7. h4 Ta4 8. h5 La6 9. h6 Dc8 10. h7 Db7 11. Th6 Da7 12. Tc6 dxc6 13. e5 Kd7 14. e6+ Kd6 15. exf7 Kc5 16. d6 e5 17. d7 e4 18. d8=D g6 19. Dd1 Ld6 20. f8=L e3 21. Lh6 e2 22. Lc1 Tf4 23. h8=T Kb4 24. Th1
Alfred Pfeiffer: Die Korrekturfassung 5674v mit gleicher Forderung (fs-99, S.38): 1ss5/d1b5/lbb1b1b1/1bl5/k2t2b1/2t5/BBB2BB1/TSLDKLST soll die Duale der Urfassung (4-fach mögliches Ziehen von g7-g6) nicht mehr enthalten. (2014-11-06)
Henrik Juel: The correction mentioned by Alfred is still cooked, acc. to Euclide 1.01 (2017-11-24)
Joost de Heer: For correction see P1067393. (2023-08-18)
comment
Keywords: Unique Proof Game, Homebase (W), Pronkin Theme (DTL)
Genre: Retro
FEN: 1n4n1/q1p5/bppb2p1/1p6/1k3rp1/1r6/PPP1pPP1/RNBQKBNR
Reprints: 42 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2014-11-06 more...
26 - P0002312
Kostas Prentos
5673 feenschach 93 11-12/1989
P0002312
(14+11) cooked
BP in 17,5
1. e3 b5 2. Ld3 b4 3. Lg6 b3 4. axb3 hxg6 5. Ta5 Th3 6. Tb5 Tg3 7. hxg3 a5 8. Th8 a4 9. Dh5 a3 10. Se2 Ta4 11. bxa4 gxh5 12. b3 g6 13. Lb2 Lh6 14. Lg7 Lg5 15. Lh6 Lh4 16. gxh4 a2 17. Sg3 a1=T 18. Txg8#
play all play one stop play next play all
Cook: 1. h4 b6 2. Th3 La6 3. Ta3 h5 4. e3 Lxf1 5. Se2 a6 6. Sg3 Le2 7. Txa6 b5 8. Th6 Ta3 9. Txh8 Tc3 10. a4 Lxd1 11. Ta3 Lf3 12. Tb3 Lb7 13. Txb5 Ta3 14. b3 g6 15. Lb2 Lg7 16. Lxg7 Ta1 17. Lh6 Lc8 18. Txg8#
s. Version P0007474
HHS: "Die Auflösung erscheint zunächst nicht übermäßig schwierig - die TTT schlängeln sich durch die BB hindurch, dabei geht geht der Tg8 über a6, um einen der sB dort wiedererstehen zu lassen. Im 'Gegenzug' vollbringt der Lc8 ein Husarenstück - Dd1 und Lf1 gehen auf sein Konto - aber es funktioniert nicht: Der L kommt nicht über b5 hinweg, denn weder der wT noch der sB (der dort entsteht) haben Zeit, ihm Platz zu machen. Also muß man sich was anderes ausdenken: Die sBB kann man zu einem Überkreuzschlagen der wBBa- und b- ausnutzen: Das erleichtert die Rückführung der linken Türme. Aber das genügt noch nicht: Jetzt braucht Schwarz zuviel Züge. Man muß den Gedanken an den L-Streich aufgeben. Dann können die wFiguren ein analoges Spiel der sB oben rechts ermöglichen. Schwarz schafft die Zugzahl spielend, aber Weiß braucht genau 18 Züge, und das auch nur dann, wenn Tg8 direkt nach g3 kann. Aber was sollte dann der erste wRückzug sein? Bis jetzt hat man die sFiguren problemlos einfach in der NO-Ecke wiedererstehen lassen - man muß auch da einen komplizierteren Modus wählen und darf den wBh- nicht einfach zurückgehen lassen, sondern man muß ihm die Möglichkeit geben, ebenso wie sein sGegenüber den wT auf der h-Linie durchzulassen. Das ist kompliziert und knifflig, aber so und nur so klappt es [dies Wort in Gottes Ohr! HG]. Bestechend ist der Einbau der Verführungen, die immer nur um Haaresbreite scheitern." "Gefällt mir!" (WD als Prüfer) Diese ausgekochten und tollen Kreuzschlagmanöver fand aber leider nur HHS, da es doch eine NL gibt.
Henrik Juel: The content is concealed pawn captures
Despite no visible captures White captured a2xPb3xTa4 to open the a-line for [Ta1,Pa7], and h2xTg3xLh4 with black h7xLg6xDh5 to open the h-line for [Th1,Th8]
This makes life difficult for the human solver and for Natch 3.1, who tested the first 15.0 moves correct in 40 sec.
Testing the entire proof game would need more than a couple of hours by Natch (2018-12-08)
paul: See P0007474 as a version. (2020-11-03)
comment
Keywords: Unique Proof Game, Promotion (t)
Genre: Retro
FEN: 1nbqk1R1/2pppp2/6pB/1R5p/P6P/1P2P1N1/2PP1PP1/rN2K3
Reprints: 143 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-11-04 more...
27 - P0002325
Andrey Frolkin
166 Shortest Proof Games 11/1991
P0002325
(16+14) cooked
BP in 15,5
Is this KBP correct?
1. d3 Sh6 2. Kd2 Sf5 3. Kc3 Sd4 4. Kb4 Sb3 5. axb3 Tg8 6. Ta6 Th8 7. Th6 f6 8. e4 Kf7 9. Dh5+ Kg8 10. Le2 De8 11. Dd5+ Df7 12. Lh5 De6 13. Sf3 Df7 14. Te1 De6 15. Te3 Df7 16. Lxf7#
play all play one stop play next play all
Cook: 1. e4 Sh6 2. d3 Sf5 3. Kd2 Sd4 4. Kc3 Sb3 5. axb3 Sc6 6. Ta6 Sb8 7. Th6 f6 8. Kb4 Kf7 9. Dh5+ Kg8 10. Le2 De8 11. Dd5+ Df7 12. Lh5 De6 13. Sf3 Df7 14. Te1 De6 15. Te3 Df7 16. Lxf7
This is an tutorial example of a PG deliberately including a cook.
more ...
comment
Keywords: Unique Proof Game, Pendulum (td x2 x2)
Genre: Retro
Computer test: Computerprüfung: Cooked Stelvio 1.11 13 Sekunden. Keine Lösung: BP 14.0 bis 15.0 und 16.0.
FEN: rnb2bkr/pppppBpp/5p1R/3Q4/1K2P3/1P1PRN2/1PP2PPP/1NB5
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-08 more...
28 - P0002327
Jasper van Atten
The Problemist 1985-1986
3. Preis
P0002327
(16+14) cooked
BP in 20,0
1. a4 Sf6 2. Ta3 Sh5 3. Td3 f6 4. Td6 Kf7 5. d3 Kg6 6. Le3 Kf5 7. Ld4 Kg5 8. e3 Kg6 9. Dg4+ Kf7 10. De6+ Ke8 11. g4 Sc6 12. Lg2 Sa5 13. Lxb7 Tb8 14. Lxc8 Tb3 15. Ke2 Ta3 16. Kf3 Ta1 17. Sa3 Td1 18. Se2 Td2 19. Tb1 a6 20. Sc1 Te2
play all play one stop play next play all
Cook: 1. d3 b5 2. Le3 b4 3. Ld4 b3 4. axb3 Sf6 5. Ta6 Sh5 6. Td6 Sc6 7. e3 Sa5 8. Dg4 Tb8 9. De6 Tb4 10. g4 Ta4 11. Ke2 Ta1 12. Sa3 Td1 13. Lg2 La6 14. Lb7 Lc4 15. Lc8 Lb5 16. Kf3 La4 17. bxa4 Td2 18. Se2 f6 19. Tb1 a6 20. Sc1 Te2

1. d3 Sc6 2. Le3 Tb8 3. Ld4 Sf6 4. e3 Sh5 5. Dg4 b5 6. Ke2 La6 7. De6 b4 8. g4 Lb5 9. Lg2 b3 10. axb3 f6 11. Ta6 La4 12. bxa4 Sa5 13. Td6 Tb3 14. Lb7 Ta3 15. Kf3 Ta1 16. Sa3 Td1 17. Se2 Td2 18. Tb1 a6 19. Sc1 Te2 20. Lc8
more ...
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: Moldenhauer: Cooked Stelvio 1.11:13 Keine Lösung BP 19.0, BP 19.5 Cooked
FEN: 2Bqkb1r/2ppp1pp/p2RQp2/n6n/P2B2P1/N2PPK2/1PP1rP1P/1RN5
Reprints: 168 Shortest Proof Games 11/1991
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-03-06 more...
29 - P0002372
Alexander Kislyak
Die Schwalbe 136 08/1992
P0002372
(15+10) cooked
BP in 10,5
1. Sf3 e6 2. Se5 Df6 3. Sxd7 Sxd7 4. a4 Sb6 5. a5 Ld7 6. axb6 0-0-0 7. Txa7 La4 8. Txa4 Td4 9. Txd4 Kb8 10. bxc7+ Ka8 11. Ta4#
play all play one stop play next play all
Cook: 1. Sf3 e6 2. Se5 Df6 3. Sxd7 Kd8 4. Sxb8 Ld7 5. a4 Lb5 6. axb5 Kc8 7. Txa7 Kxb8 8. Ta3 c6 9. bxc6 Ta4 10. c7 Ka8 11. Txa4
Moldenhauer: Computerprüfung: Cooked Stellung Stelvio 1.11 1 Sekunde.
Keine Lösung: BP 9.5, BP 10.0.
Eine Notation von Stelvio:
1.Sf3 e6 2.Se5 Df6 3.Sxd7 Kd8 4.Sxb8 Ld7 5.Sc6+ Kc8 6.Sxa7+ Kb8
7.a4 Lb5 8.axb5 Txa7 9.b6 Ka8 10.bxc7 Ta4 11.Txa4#
Schlüsselwort Rochade? (2023-05-02)
comment
Keywords: Unique Proof Game, Castling
Genre: Retro
FEN: k4bnr/1pP2ppp/4pq2/8/R7/8/1PPPPPPP/1NBQKB1R
Input: Gerd Wilts, 1995-06-03
Last update: Gerd Wilts, 2006-10-15 more...
30 - P0002476
Werner Kuntsche
1777v Problem 73-78 06/1961
P0002476
(5+7) cooked
h#3 AP
Einheitslösung!
1) 1. cxd3ep Ta5 2. Sf5 0-0 3. Sd4 Txe5#
2) 1. gxf3ep Th5 2. Sd5 0-0-0 3. Sf4 Txe5#
play all play one stop play next play all
Cook: 707 cooks which do not begin with e.p., e.g. 1.Sg3-e2 Ra1-a2 2.Ke4-d3 Rh1-h3 3.e5-e4 Ra2-d2 #
What is the obscure intent behind "Einheitslösung!"? (= "One size fits all solution"?)
Mario Richter: Im Nachdruck in problem 144-147 steht nur auf e5 ein sB (also keiner auf e3). Allerdings gibt es in allen drei Varianten (sBe5+e3, nur sBe5, nur sBe3) jede Menge NL, die ohne Rochade und e.p.-Key auskommen - am wenigsten dann, wenn nur auf e3 ein sB steht. (2010-10-10)
VL: Cf. P0002475. (2012-08-26)
A.Buchanan: Possibly "Einheitlösung!" is a request to unify retro implications derived across separate parts of the PRA solution. But cooked chessically irrespective of these philosophical issues, which still wait to be resolved 60 years on. (2022-02-16)
comment
Keywords: a posteriori (AP) (Type Petrovic - ccee), En passant as key (2), Castling (wb), Symmetrical position, Symmetrical solution, Superseded by (P1401449,P1399112)
Genre: h#, Retro
Computer test: C- Forward play cooked by Popeye v4.87. However the basic idea is good, if a suitable theoretical framework can be found.
FEN: 8/8/8/4p3/2pPkPp1/2n1p1n1/8/R3K2R
Reprints: (66) Problem 144, p. 52, 12/1971
Die Schwalbe 99 06/1986
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-24 more...
31 - P0002554
Unto Heinonen
Probleemblad 1991
1. Preis
P0002554
(16+16) cooked
BP in 43.0
1. h4 a5 2. Th3 Ta6 3. Tf3 Tg6 4. Sh3 Tg3 5. Sf4 Th3 6. g3 Th2 7. Lh3 Sh6 8. Le6 Sf5 9. Lc4 d5 10. Kf1 Th1+ 11. Kg2 Tg1+ 12. Kh3 Kd7 13. Kg4 h5+ 14. Kg5 Th6 15. a4 Tb6 16. T1a3 Kc6 17. Tac3 Tb3 18. Sg6 Ta3 19. b3 Ta2 20. La3 Dd6 21. Lc5 Sd7 22. La7 Sb6 23. Sh8 Kc5 24. La6+ Kb4 25. Tc5 g6 26. Sc3 Lg7 27. Se4 Lc3 28. Da1 Sd4 29. Kh6 Ld7 30. Kg7 Lb5 31. Kf8 Ld3 32. Ke8 Dc6+ 33. Kd8 Sc4 34. Kc8 Ka3 35. Kb8 Lb4 36. Ka8 De8+ 37. Lb8 Sb6+ 38. Ka7 Sa8 39. c4 Sc2 40. Df6 Sa1 41. Db6 Kb2 42. Sf6 Ta3 43. Sd7 Ka2
play all play one stop play next play all
Cook: NL
1. h4 a5 2. Th3 Ta6 3. Tf3 Te6 4. g3 Te3 5. Lh3 Sh6 6. Le6 Sf5 7. Lc4 d5 8. Kf1 Dd6 9. Kg2 Da6 10. Kh3 Kd7 11. Kg4 h5+ 12. Kg5 Th6 13. a4 Tb6 14. Ta3 Kc6 15. Tc3 Tb3 16. Sh3 Ta3 17. b3 Ta2 18. La3 Sd4 19. Lc5 Lf5 20. La7 Db6 21. Sf4 Kc5 22. Sg6 Kb4 23. Sh8 g6 24. La6 Lg7 25. Tc5 Db5 26. c4 Sc2 27. Sc3 Ka3 28. Se4 Lc3 29. Da1 Lb4 30. Df6 Tc3 31. Kh6 Kb2 32. Kg7 Ta3 33. Kf8 Sd7+ 34. Ke8 Ka2 35. Kd8 Sa1 36. Kc8 Sf8+ 37. Kb8 Sd7+ 38. Ka8 Tc1 39. Lb8 Sb6+ 40. Ka7 Sa8 41. Db6 Tg1 42. Sf6 De8 43. Sd7 Ld3 (Sebastian Natschke)
Henrik Juel: Very good, Sebastian (although not for the author...) (2019-06-17)
paul: Probably the cook of the year, because the problem is well known. Which is now the length record for a capture free proof game? (2019-07-16)
paul: The length record for a capture-free PG is now 40.5 moves by Th. le Gleuher (Phenix50/1997) (2019-07-16)
Mario Richter: The problem Paul was referring to is P0006623. So far it has resisted all my and rawbats' attempts to cook it, and I think that chances are high that it is indeed correct ... (2019-07-17)
James Malcom: See the correction P1386520 (2021-02-15)
more ...
comment
Keywords: Unique Proof Game, Move Length Record, Capture-free, Superseded by (P1386520)
Genre: Retro
FEN: nB2q2N/KppNpp2/BQ4p1/p1Rp3p/PbP4P/rP1b1RP1/k2PPP2/n5r1
Reprints: H17 FIDE Album 1989-1991 1997
feenschach 137 08-09/2000
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-28 more...
32 - P0003009
Luigi Ceriani
117 La Genesi delle Posizioni 1961
P0003009
(13+12) cooked
Welches war der erste Zug der sD und des sK?
AL in der Version von "hans" (PDB 2012-07-26):
R: 1. ... Ld8xLc7 2. Lb6-c7 Kc8-b8 3. Lc7-b6 Kb7-c8 4. Lb6-c7 Lc7-d8 5. Lg1-b6 Lb8-c7 6. Lb6-g1 Kc8-b7 7. Ld8-b6 Kb7-c8 8. d7-d8=L Lh7-g8 9. e6xSd7 Sc5-d7 10. Sc3-a4 Sa4-c5 11. Sd1-c3 d7-d6 12. Sc3-d1 Le5-b8 13. Se4-c3 Lg7-e5 14. Sf6-e4 c7-c6 15. Sg8-f6 Lh6-g7 16. g7-g8=S Kc8-b7 17. f6xTg7 Tg8-g7 18. e5-e6 Td8-g8 19. e4-e5 0-0-0 20. e3-e4 Lf8-h6 21. f5-f6 g7-g6 22. f4-f5 Le4-h7 23. f3-f4 Lb7-e4 24. f2-f3 Lc8-b7 25. Kb5-a5 b7xSa6 26. Kc4-b5 Sc5-a4 27. Kd3-c4 Se4-c5 28. Ke2-d3 Ta5-a3 29. Ta4-a2 Sf6-e4 30. La2-b1 Sg8-f6 31. Tb1-b2 Tf5-a5 32. Lb2-c1 Tf6-f5 33. Th1-b1 Tg6-f6 34. Ke1-e2 Th6-g6 35. Dd1-a1 Th7-h6 36. Lc1-b2 Th8-h7 37. b2-b3 Th7-h8 38. Lc4-a2 Th6-h7 39. Lf1-c4 Th7-h6 40. Ta1-a4 Th8-h7 41. Sc5-a6 h6xSg5 42. Se6-g5 h7-h6 43. a3xSb4 Sa6-b4 44. Sd8-e6 Sb8-a6 45. Se6xDd8 Sh6-g8 46. Sf4-e6 Sg8-h6 47. Sh3-f4 Sh6-g8 48. Sa4-c5 Sg8-h6 49. Sc3-a4 Sh6-g8 50. a2-a3 Sg8-h6 51. Sb1-c3 Sh6-g8 52. e2-e3 Sg8-h6 53. Sg1-h3
play all play one stop play next play all
Cook: (Mario Richter, PDB 2023-06-30)
R: 1. ... Ld8xLc7 2. Lb6-c7 Kc8-b8 3. Lc7-b6 Lh7-g8 4. Lb6-c7 Lc7-d8 5. Ld4-b6 Lb8-c7 6. Lb6-d4 Kb7-c8 7. Ld8-b6 Kc7-b7 8. d7-d8=L Kd8-c7 9. e6xSd7 Sb6-d7 10. Sc5-a4 Sa4-b6 11. Se4-c5 d7-d6 12. Sf6-e4 Ke8-d8 13. Sg8-f6 Le5-b8 14. Sh6-g8 Lg7-e5 15. Sg8-h6 Lf8-g7 16. g7-g8=S c7-c6 17. f6xDg7 Dh6-g7 18. f5-f6 g7-g6 19. e5-e6 Dc6-h6 20. e4-e5 Da8-c6 21. e3-e4 Dd8-a8 22. f4-f5 Le4-h7 23. f3-f4 Lb7-e4 24. f2-f3 Lc8-b7 25. Kb5-a5 b7xSa6 26. Sb8-a6 Sc5-a4 27. Sc6xTb8 Se4-c5 28. Se5-c6 Sf6-e4 29. Kc4-b5 Ta6-a3 30. Kd3-c4 Sg8-f6 31. Ta4-a2 Tb6-a6 32. La2-b1 Tc6-b6 33. Tb1-b2 Te6-c6 34. Lb2-c1 Tf6-e6 35. Th1-b1 Tg6-f6 36. Dd1-a1 Th6-g6 37. Ke2-d3 Th5-h6 38. Ke1-e2 Th6-h5 39. Lc1-b2 Th7-h6 40. b2-b3 Th8-h7 41. Lc4-a2 Th7-h8 42. Lf1-c4 Th8-h7 43. Sc4-e5 Th7-h8 44. Ta1-a4 Th6-h7 45. Sa3-c4 Ta8-b8 46. Sb1-a3 Th8-h6 47. a3xSb4 h6xSg5 48. Sf3-g5 h7-h6 49. Sg1-f3 Sa6-b4 50. e2-e3 Sb8-a6 51. a2-a3
s.a. 32Pe1A

Korrekturversuch zu P0005036
hans: Good motivation to capture Qd8 on the spot, to make long castling possible, which is needed to retrack the captured bRg7 just on time. Also a minor-promotion. I like this one, and I think the stipulation asks for which move black queen makes.
R: -1. …Ld8xLc7+ -2. Lb6c7+ Kc8b8 -3. Lc7b6 Kb7c8 -4. Lb6c7 Lc7d8 -5. Lg1b6 Lb8c7+ -6.Lb6g1 Kc8b7 -7. Ld8b6 Kb7c8 -8. d7d8=L Lh7g8 -9. e6xSd7 Sc5d7 -10. Sc3a4 Sa4c5+ -11.Sd1c3 d7d6 -12.Sc3d1 Le5b8 -13.Se4c3 Lg7e5 -14.Sf6e4 c7c6 -15.Sg8f6 Lh6g7 -16.g7g8=S Kc8b7 -17.f6xTg7 Tg8g7 -18.e5e6 Td8g8 -19.e4e5 0-0-0!! -20.e3e4 Lf8h6 -21.f6f5 g7g6 -21.f4f5 Le4h7 -22.f3f4 Lb7e4 -23.f2f3 Lc8b7 -24. Kb5a5 b7xSa6 and cage can be undone while black plays only with Ta3 and Sa4.
captures white axSb, SxDd8, exSd7, fxTg7, black hxSg, bxSa6, LxLc7 (2012-07-26)
Henrik Juel: Very similar to P0005036 and with identical stipulation question:
What was the first move by black queen and by black king.
Ceriani's abbreviations for move, queen, king, black, (and white) are t., D, R, n, (and b); in his ortho reconstruction problems the color abbreviations are capitalized, e.g. N=11 meaning 11 black moves (2012-07-26)
Thomas Volet: This composition appears on p.197 of Ceriani's 1961 book as his correction of P0005036 (which appeared in his earlier book). On that page, he discusses the clever cook in P0005036 ("ma questa bella posizione e demolita") with the WhP unpromoting at h8, uncapturing to the g file, and uncapturing back to the h file. (2012-08-02)
Mario Richter: I'm sorry to say this, but Ceriani's correction attempt still leaves room for cooks ... (2023-06-30)
comment
Keywords: First Move? (kd), Castling in the retro play (sg)
Genre: Retro
FEN: 1k4b1/p1b1pp2/p1pp2p1/K5p1/NP6/rP6/RRPP2PP/QBB5
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2023-07-02 more...
33 - P0003189
Tivadar Kardos
2144 Diagramme und Figuren 19/09/1967
P0003189
(7+15) cooked
h#2
1. bxc3ep Lxe2 2. Sa3 0-0-0#
play all play one stop play next play all
Cook: 2. ... Td1#
Sally: Der letzte Zug war: Bc2 - c4!
Nr.138 200 Ausgewählte S .Probleme T. Kardos(W. Fentze1983) (2010-09-30)
A.Buchanan: All 9+1 captures are visible by pawns. Note R: 1. Kd1-e1 d3xe2 is illegal because it costs 2 more captures for Black. So e.p. is unconditionally legal, requiring no AP justification. I see no reason why White has lost castling rights. Indeed someone might make a demo game ending with c2-c4. So this one seems cooked. Neither WinChloe nor yacpdb contains this problem. (2022-01-08)
A.Buchanan: If this is AP, it will be rendered sound by removing wPa2. But is this the intention? Does anyone have access to the collection of selected Kardos problems mentioned? (2024-01-25)
more ...
comment
Keywords: En passant as key, Castling (wg)
Genre: h#, Retro
FEN: 8/8/3pp3/2ppp3/1pPkrq2/4pb1P/P3p1rP/Rn2KBb1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-01-08 more...
34 - P0003211
Tivadar Kardos
6476 Skakbladet 10/1957
P0003211
(7+14) cooked
h#3
1. dxe3ep+ Kxc4 2. Lc3 Sxc2 3. Da5 axb3#
play all play one stop play next play all
See the correction P1396159
Cook: 1. dxe3ep+ Kxc4 2. Td5 Sxc2 3. Ta5 axb3#
A.Buchanan: Easy enough to eliminate what I suppose is the intended solution (sL unblocking sD and blocking sT) by e.g. just removing sDf5. However I don't see a way to say goodbye to the cook instead. (2021-11-23)
James Malcom: I believe I may have a fix Andrew. If we substitute the Black queen with a Black rook, the same theme is kept even is if considered watered down.

h#3 8/3p4/3p1p2/3Kbr2/k1ppPp2/1n1r3P/P1p4P/N3nq1b (2021-11-24)
A.Buchanan: Hi James, hurray cool I thought I couldn't get through that way: I was confused in my mind about wPe2 blocking that line, but with the freshness of a new day, I can look at it again. The precise diagram that you propose doesn't quite work because R: 1. e3-e4 Sf3*e1+,Sg2*e1+,g2xf1=Q+,g2xh1=Q+, but this is all fixable with +bPd2,-bSe1. Now Popeye 4.87 says the forward solution is works uniquely, and Retractor 2.0 says R: 1. e2-e4 Rf3-d3+ 2. Ke4-d5 are unique. So for full C+ we only need some demo game that results in the position prior to Ke4-d5.
I don't see any "watering down" here: I think we have faithfully represented Tivadar's idea. Let's post it here as TK, corr JM&AB? (2021-11-24)
A.Buchanan: I have made an unedifying demo game with lichess, so our correction is fully C+. (2021-11-24)
James Malcom: "TK, corr JM&AB" sounds good to me. (2021-11-24)
more ...
comment
Keywords: En passant as key, Superseded by (P1396159)
Genre: h#, Retro
Computer test: Popeye C-Version 4.87 & trivial retro-logic
FEN: 8/3p4/3p1p2/3KbqP1/k1ppPpp1/1n1r3P/P1p4P/N6b
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-24 more...
35 - P0003269
Tivadar Kardos
149 British Chess Magazine 10/1956
P0003269
(5+17) cooked
h#3
1. exf3ep e3 2. 0-0-0 Tb4 3. Tg4 Tb8#
I think that this cooked problem is an early A osteriori. I can see ways that it might be made sound, but I would like to see the published version. San anyone help please? Thanks.
play all play one stop play next play all
Cook: 17 Black pawns, retro cook and numerous forward cooks
klären wK im Schach, vielleicht wBb2?
Alfred Pfeiffer: 9 schwarze Bauern! (2012-02-07)
Ladislav Packa: Auch mit wBb2 NL, z.B. 1.exf3 e.p. Txg5 2.0-0-0 Tb5 3.Tg~ Tb8# (2012-02-07)
A.Buchanan: And adding to earlier comments, if we do swap sBb2 for wB, the retraction is still not unique with R: 1. f3-f4 Lh6xg5+ (2021-11-26)
A.Buchanan: I think that this cooked problem is an early A Posteriori. I can see ways that it might be made sound, but I would like to see the published version. Can anyone help please? Thanks. (2022-04-25)
Gerald Ettl: Verbesserungsvorschlag: -sBa2, -sBb2, -sSg7, +sBg7
r3k3/3b2p1/5p2/6b1/4pPRp/2pq2rp/2p1P1pB/2K3n1/ (2022-04-25)
Gerald Ettl: und +sSg8 (wegen exf4 Vermeidung) (2022-04-25)
Gerald Ettl: +sSa4 nicht g8 (2022-04-25)
A.Buchanan: Hi Gerald. Thanks for this. Your final proposed version is r3k3/3b2p1/5p2/6b1/n3pPRp/2pq2rp/2p1P1pB/2K3n1, yes? There are 16 candidate solutions, all using castling. But wPa cannot leave the a-file, and is required for capture balance, so Black cannot castle. Five of the candidates begin with e.p.: play might have just been R: 1. Kb1-c1 b3xPc2+, so e.p. is not permitted in any case. What am I missing? (2022-04-25)
Gerald Ettl: Hi Andrew,
Those were 2 mistakes I made. I improved it again.
r3k3/3b4/4pp2/6b1/4pPRp/n1pq2rp/PPp1P1pB/2K3n1/
(den wBa2 habe ich auf das Brett gestellt, da sonst wieder Lh6xXg5 geht.) (2022-04-26)
A.Buchanan: Hi Gerald: Deine Retro-Logik ist gut. Aber es gibt 18 Lösungsvorschläge für die Zukunft. Ich habe heute im Discord meinen eigenen Vorschlag zur AP-Korrektur von Kardos veröffentlicht. Ich werde ihn hier im PDB hinzufügen. (2022-04-26)
comment
Keywords: En passant as key, Castling
Genre: h#, Retro
FEN: r3k3/3b2n1/5p2/6b1/4pPRp/2pq2rp/ppp1P1pB/2K3n1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-11-26 more...
36 - P0003335
Tomislav Petrovic
(XXI) Problem 37-40 09/1956
P0003335
(5+9) cooked
h#9
1. dxc3ep dxc3+ 2. Ka5 c4 3. d2 c5 4. d1=L c6 5. Lg4 hxg4 6. Kb6 g5 7. Ka7 g6 8. Kb8 g7 9. Kc8 g8=D/T#
play all play one stop play next play all
Cook: 1. b2 c5 2. b1=S c6 3. Sc3 dxc3+ 4. Ka5 cxd4 5. Kb6 d5 6. Ka7 d6 7. Kb8 dxc7+ 8. Ka7 c8=D 9. a5 Db7#
paul: See P0003212 as version. (2011-08-06)
Anton Baumann: C+?? Die Aufgabe ist eindeutig inkorrekt! (2021-01-27)
James Malcom: Fixed. (2021-01-27)
comment
Keywords: En passant as key, Promotion (D), konsekutive Umwandlungen 2 (L, D/T), En passant, Kindergarten Problem
Genre: h#, Retro
FEN: 8/2p5/p7/8/1kPp3p/1p1p2pP/3P2Pp/7K
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-01-27 more...
37 - P0003339
Tivadar Kardos
2519 Revista Romana de Sah 01/1948
2. Preis
P0003339
(10+15) cooked
h# in wieviel?
1. ... cxd6ep 2. Tc8 dxe7 3. Tf8 exf8=S#
play all play one stop play next play all
AL ('Revista Romana de Sah', 06/1948, S.225-226):
Bekanntlich beginnt im Hilfsmatt Schwarz, also hat in der Diagrammstellung Weiß den letzten Zug gemacht. Man findet aber, wenn man die Position analysiert, daß Weiß den letzten Zug nicht gemacht haben kann.
Der weiße Doppelbauer auf der d-Linie läßt sich nur durch Schlagen des einzig fehlenden schwarzen Steines, des sBa7, erklären. Dieser konnte aber erst nach Umwandlung geschlagen werden. Dazu mußte er zunächst bis a3 vorrücken, dann nach b2 schlagen, und dann umwandeln.
Also kann Weiß nicht zuletzt b2-b3 gezogen haben.
Die anderen schwarzen Bauern haben mindestens 5 Schläge gemacht, um die Position im Diagramm zu erreichen (man beachte, daß der sBh7 zweimal schlagen mußte, um den wBh2 durchzulassen)
also kann auch g2-g3 nicht der letzte Zug gewesen sein, denn sonst hätte der wLf1 nicht von einem sB geschlagen worden sein können.
Für alle anderen weißen Steine ist leicht zu sehen, daß sie den letzten Zug nicht gemacht haben können.
Es stellt sich heraus, dass der letzte Zug von Schwarz gemacht wurde, und eine einfache Analyse zeigt, daß dies nur möglich ist durch d7-d5 (sonst wäre es unmöglich, daß die weißen Steine ihre Position im Diagramm erreichen könnten).
In diesem Fall Weiß kann 1. ... c5:d6(e.p.) spielen, gefolgt von 2. Tc8 d:e7 3. Tf8 e:f8C matt!
Das kürzeste Hilfsmatt wird also in 2,5 Zügen erreicht!
Cook: 1. ... Txg5+ 2. Kxg5 f3 3. Lg6 gxf4#
1. ... Kxd5 2. Kf6 e4 3. Tg6,Dg6 e5#
A.Buchanan: Popeye v.487. WinChloe has the same diagram, and although it just claims 1 solution, it's C? Yet WinChloe engine gives the cooks right away (2021-10-27)
Mario Richter: Shouldn't this problem get the Label "No legal last move for White"?
(White pawn d2 has captured the missing black piece (Pdxe), so black pawn a7 had to promote to get to the capture square. This requires one capture (Pa3xb2), together with bxc,cxd,hxg,gxh,gxh this accounts for all missing white pieces.)

Btw. "for me, "C?" stands for "Not yet computer-tested or computer test didn't come to a conlusion" ... (2021-10-28)
A.Buchanan: Hi Mario, thank you.
(1) The stipulation is non-standard. I think this is why the WinChloe database doesn't include a solution, and just marks it as "C?" However if I run the WinChloe solving engine manually it (like Popeye) gives 121 h#3 solutions and 4 h#2.5 solutions. I think you, me and Christian would all agree on the meaning of "C?"
(2) The problem does not rely on Article 15 to eliminate the first single move, but implicitly requests the shortest. Currently the PDB usage of "No legal last move..." is to indicate that Codex Article 15 applies, so I did not add it. But I'm ok if you want me to add the keyword. In my correction, I shift the stipulation to h#3 so it's clear that Article 15 and not any desire for brevity which push the problem to h#2.5.
(3) However the PDB usage is confused. Ideallly think the two "No legal..." keywords should be replaced by "Retro-stalemate", while two new keywords "Article 15" & "Whose mate?" indicate the choice of implications of the retropat for forward play. "Board rotation" and other jokes are also implications of retropat (and of illegal diagram).
(4) But this is complicated to implement, requiring either database-level access or screen-scraping. The latter is quite practical for some future time when I have more leisure.
(5) https://www.stere.ro/biblioteca-digitala/reviste/revista-romana-de-sah/ is an excellent archive of Revista Romana de Sah. My sincere compliments and thanks to whoever prepared it. And the magazines themselves contain thorough annual indices. p225-6 of 6/1948, contains the solution to Kardos. I haven't translated it, nor have I found time to locate the prize announcement.
Comments welcome! (2021-10-29)
Mario Richter: I still believe, that the label "No legal last move for White" is justified here, because this is exactly what the author wanted to show.
(And this is too, what the reprint in 'Problem (Zagreb)' 37-40 09/1956 is all about - it appears there inside asn article

Btw., I wouldn't call the presentation of the solution in 'Revista Romana de Sah', p.225, 06/1948, a "reprint" - it lacks the presentation of the position ... (2021-10-30)
A.Buchanan: Added the keyword.
Yes I know that's the usage of "reprint", but then there should be a field for the location of the solution :-) It's idiotic that if I want to say where the solution is contained, I have to embed it in text like this: 2519 Revista Romana de Sah , p. 225-6, 06/1948 (2021-10-30)
more ...
comment
Keywords: En passant as key, Promotion (S), Superseded by (P1394978), No legal last move for White
Genre: h#, Retro
Computer test: Popeye v4.87 & WinChloe both say cooked
FEN: 7b/4p1nP/2r1P1kq/1nPpKbrp/2pp1pRp/1P4P1/P3PP2/8
Reprints: (III) Problem 37-40 09/1956
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-30 more...
38 - P0003343
Yaakov Mintz
344 Canadian Chess Chat 11-12/1980
P0003343
(4+15) cooked
h#4
1. hxg3ep Lxb1 2. Kf5 fxe4 3. Kg6 e5+ 4. f5 exf6ep#
play all play one stop play next play all
Cook: NL:
1. hxg3ep fxe4 2. f6 e5 3. Kf5 exf6 4. Kg6 Lxb1# uvm
YM: The correct mechanism is in P1109109 (2010-07-13)
YM: Correction option: P1229434 (2021-06-28)
comment
Keywords: En passant as key, Superseded by (P1109109)
Genre: h#, Retro
FEN: q2r4/4Kp2/3r3b/3p2pp/4nkPp/1n3P2/B4p1p/1b6
Reprints: 805 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-06-28 more...
39 - P0003365
Gyula Bebesi
41 Problemas 04-06/1962
P0003365
(8+14) cooked
h#2
1) 1. axb3ep bxc6+ 2. b5 cxb6ep#
2) 1. exd3ep g8=D,L+ 2. d5 cxd6ep#
play all play one stop play next play all
PRA: 1 solution with 2 parts
Henrik Juel: White captured [sLc8] on c8 and axb, so last move was either b2-b4 or d2-d4
C+ Popeye 4.61, except for the promotion dual (2020-08-03)
A.Buchanan: There's no keyword for an untolerated dual promotion! (2020-08-03)
Henrik Juel: Yes and no, Andrew
What about the cooked label? (2020-08-03)
A.Buchanan: Hi Henrik: this is obviously intentional. I tried to replace the pawn promotion with wDh8-h7+ but I ran out of pieces. I guess that Bebesi had the same difficulty. The word "cooked" seems too strong to me, but it's obviously a significant defect though (2020-08-04)
A.Buchanan: The bar is higher for helpmates than other problems, and this is unsound. However it’s not cooked but dualled. Yet all we have is “cooked” so I suppose it is in PDB-speak. I’ve added that and removed the 2.1… (2023-08-07)
Joost de Heer: Is there an 'unsound' keyword? (2023-08-07)
A.Buchanan: Hi Joost: no there isn't. It can be added, the challenge for any new common keyword would be populating it for more than a few values. (2023-08-07)
A.Buchanan: This time round, I've managed to find a fix. Bebesi's correction in WinChloe 66992 has non-standard wL. I have a feeling I've seen a similar one by Andrey Frolkin & someone else recently with a different matrix, and also non-standard wL. I've sent my effort to Joaquim Crusats at Problemas for his assessment (2023-08-08)
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comment
Keywords: En passant as key (2), Partial Retro Analysis (PRA), En passant as mating move (2), Superseded by (P1411659, P1413906)
Genre: h#, Retro
FEN: 3qn3/1p1p2P1/B1r3p1/1PP1Kp2/pPkPp3/p1p4n/N7/2b5
Reprints: 233 Ungarische Schachproblem Anthologie , p. 188, 1983
1 Problemas 44, p. 1456, 10/2023
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-04 more...
40 - P0003430
Tomislav Petrovic
(XIII) Problem 37-40 09/1956
P0003430
(4+15) cooked
h#3
1. dxe3ep Td1? 2. Le4 Txd6 3. Sg4 Tf6# usual AP try
1. dxe3ep 0-0-0! 2. Le4 Txd6 3. Sg4 Tf6#
play all play one stop play next play all
Cook: 1. dxe3ep 0-0-0 2. Lf5 Txd6 3. Sf3 Td4#
not
1. dxe3ep Td1? 2. Lf5 Txd6 3. Sf3+ ?? usual AP try and also check Bl 3rd move
Henrik Juel: The missing black man is dark-squared, so last move was not fxe4. In the solution Td6 should read Txd6. There seems to be a 'variation': 0... dxe3ep 1.0-0-0 Le4 2.Txd6 Sg4 3.Tf6#, so maybe the stipulation should have 1.1;2.1;1.1 added. (2004-09-23)
A.Buchanan: Well spotted Henrik. Your kindness is legendary, but in the harsh world of helpmates, this counts as a cooked I believe. In fact, it's the 2.Lf5/3.Sf3 version which is the cook. Yours is the actual solution! This is because 3.Sf3 would check if White hadn't castled, and we want the castling to be because of the AP condition only, not for 2 reasons, which one might term a "logical dual". The problem can be trivially fixed by sticking sSe5 on f6. I have no idea whether it's a typo or a cook: WinChloe has the same diagram, and the same confusion between cook & intended solution. The fact that AP does not appear in the stipulation might be a factor. WinChloe as far as I can see has no concept of AP as a keyword, and just picks it up based on a substring of the stipulation. In other compositions, T.Petrovic wasn't shy of flashing the AP acronym in the stipulation, but as usual the detective work peters out in the absence of primary records. (2020-12-08)
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comment
Keywords: En passant as key, Castling (wg), a posteriori (AP) (Type Petrovic), Superseded by (P1382802)
Genre: h#, Retro
Computer test: Popeye v4.85 + retro thinking
FEN: 1n1r4/p1B4p/1p1p4/p3n1p1/3pPk2/3b4/pr5q/R3K3
Reprints: (60) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-02-16 more...
41 - P0003431
Tomislav Petrovic
(XIV) Problem 37-40 09/1952
P0003431
(8+14) cooked
h#3
1. cxb3ep+ c3 2. Ld3 Tg4+ 3. Kh1 0-0-0#
play all play one stop play next play all
paul: White captures was axb and g2xh3, so the retro move c3xb4 is not possible. If b3-b4, the retro check is not justified. So last move was b2-b4 (preceded by Rc3-a3). (2011-08-06)
A.Buchanan: There's a lot to unpack here. Firstly, the intended solution has a definite transposition dual in the order of Black's 2nd & 3rd moves. Second, the pawn capture count is wrong. What happened to the original wBh, given sBh2 never left the h-file? Thirdly, and not a showstopper, White's only solution involves castling: so that's a logical dual. (2020-12-08)
more ...
comment
Keywords: En passant as key, Castling
Genre: h#, Retro
Computer test: Popeye v4.85 + retro thinking
FEN: 3r3n/p7/pp6/bP1q4/RPp5/r3p2P/p1P1P1kp/Rb2K3
Reprints: (61) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-05-02 more...
42 - P0003444
Janko Furman
Miroslav Stosic

7273 Schach-Echo 11/1972
P0003444
(8+14) cooked
h#2
b) Gespiegelt (a1<->h1) & wKd1->e1
a) 1. dxe3ep 0-0 2. Te4 Txf3#
b) 1. exd3ep 0-0-0 2. dxe2 Ld5#
play all play one stop play next play all
Cook: a) 1. Kg3 Kf1 2. Df4 Th3#
1. Kg3 0-0 2. Dh4 Txf3#
A.Buchanan: This is a very heavy position to prevent the possibility of R: 1. c2xb3. I'm not sure why this was done. A much lighter position 8/8/8/5np1/1r1pPkr1/2Bp1p2/1p1P2P1/4K2R with 7 less units achieves the mates soundly. Am I missing something? (2022-02-16)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wk,wg), Superseded by (P1399967), Twinning by board reflection
Genre: h#, Retro
FEN: 8/1p1pp1p1/8/5nq1/1r1pPkr1/1PBp1p2/Pp1P2P1/2n1K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-23 more...
43 - P0003451
Knud H. Hannemann
3823 Stella Polaris 03/1971
P0003451
(6+8) cooked
h#2 AP
1) 1. gxf3ep 0-0-0 2. Te7 Th4#
2) 1. cxd3ep 0-0 2. Da4 Txa4#
play all play one stop play next play all
AB: I think this is cooked. I don't see how AP castling can justify earlier ep here.
1. Kf3 Bf5 2. Kg2 Be4#
1. Kf3 Bxd7 2. Kg2 Bc6#
1. cxd3 Rf1 2. Qa4 Rxa4#
1. gxf3ep Ra5 2. Kf4 Rh4#
1. gxf3ep Rd1 2. Re7 Rh4#
Also, second solution given has typos 1. *c*xd3ep & 2. Q*a*4. (2002-03-21)
V.Liskovets: Indeed this problem is cooked, and I
failed to correct it preserving symmetry.
Here is a possible correction:
W: Ke1 Ra1 Rh1 Be6 Pd4 Pf4
B: Ke4 Qd7 Rf7 Pc3 Pc4 Pe3 Pg3 Pg4 Bh7 Rb2 Pb3

Another story, justifying its contents (e.p.).
In my opinion, all published treatments are
insatisfactory (the same concerns P0004295
(corrected) by Werner Kuntsche as well).
There is a way to make it sound under the
sophisticated HYBRID stipulation 'AP, pRA':
2 partial solutions legalized JOINTLY by
both castlings (details to be published). (2002-04-02)
VL: Sorry, Andrew, I see no issues with my version (excepting the mentioned special retro-convention/genre for justifying its soundness, of course!). h#2 (pRA&AP). The full solution consists of 2 partial AP-based ones: I 1.gxf3 e.p.(!?) 0-0-0! 2.Te7 Th4#; II 1.cxd3 e.p.(!?) 0-0! 2.Da4 Txa4#.
C+(popeye): h#2 & two h#1.5 after the keys (added Tb2 & Lh7 are cookstoppers).
The main features of the corresponding suitable AP-genre ("consolidated")are rather clear. However, not all subtle aspects have been analyzed thoroughly yet. I have got only a draft manuscript with few examples, still. (2022-02-15)
A.Buchanan: Yes Valery I think your correction is technically sound. Theological debate is something else, heh. Have posted it as separate entry. Please tell me if it was original here, or appeared somewhere else (2022-05-29)
Henrik Juel: I looked in Stella Polaris 1971 p.202-203, where the problem is given without AP under the diagram
It turns out that both the author and the editor (Jan Knöppel) consider the problem correct
After explaining the AP convention the latter writes [my translation]:
The author has elegantly applied the AP conventionn in combination with partial analysis. If we assume that last move was not f2-f4 or T-h1, the possibilities d2-d4, K-e1, and T-a1 remain, but the two latter disappear by 1... 0-0. The other assumption (last move was not d2-d4 or T-a1) is analogous.
So something like Valery's HYBRID stipulation was the intention, and the problem was considered correct in 1971; later developments do not change this fact (2022-05-29)
Henrik Juel: Of course, the obvious cooks 1.Kf3 etc. remain (2022-05-29)
A.Buchanan: I agree. Basic AP Petrovic does not allow multiple ep, nor does RS, so some alignment of AP with PRA is required. I would like to see this codified though. (2022-05-29)
more ...
comment
Keywords: Castling (wb), En passant as key (2), a posteriori (AP) (Type Petrovic), Superseded by (P1401508, P1399178), Quasi-symmetrical position, Partial Retro Analysis (PRA)
Genre: h#, Retro
Computer test: C- Forward play cooked by Popeye v4.87. However the basic idea is good, if a suitable theoretical framework can be found.
FEN: 8/3q1r2/4B3/8/2pPkPp1/2p1p1p1/8/R3K2R
Reprints: (65) Problem 144-147 12/1971
(8) StrateGems SG19, p. 156, 07/2002
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-29 more...
44 - P0003659
Maurice Jago
8202v Die Schwalbe , p. 148, 10/1980
version of cooked 8202 Die Schwalbe 08/1977
P0003659
(12+14) cooked
h#2
b) sBb4->b5
a) 1. Sf2 Dxf2+ 2. Kh1 0-0-0#
b) 1. Sb1 Ta4 2. Sxg3 Th4#
play all play one stop play next play all
Cook: 1. Txg3 0-0-0 2. La2/Lb3/Lc4 Dxh1#
1. La2/Lb3/Lc4 0-0-0 2. Txg3 Dxh1#
See P0000642
Mario Richter: Hier stimmt was nicht: In der Schwalbe 08/1977 erschien als Nr. 2202 die folgende Aufgabe: 8/Pp2p1p1/Bq1p3p/4p3/1p6/n4pP1/1PPPPr1k/R3KQ1n/; h#2, b) sBb4 nach b5 und der AL a) 1.Tf2-g2 0-0-0 2.Tg2xg3 Df1xh1#; b) 1.Sa3-b1 Ta1-a4 2.Sh1xg3 Ta4-h4#, die aber in a) und b) durch 1.f3xe2 La6xb7 2.Tf2-g2 Df1xg2# nebenlösig war.
Ferner ist in nebenstehendem Diagramm sowohl in a) als auch in b) sehr wohl die w0-0-0 möglich
(Weiß hat als letzten Zug Sc7-a8, Schwarz entwandelt auf b1 und h1, Weiß auf f8); und selbst unter der Annahme, daß die w0-0-0 nur mit sBb4 möglich sei, wäre die Aufgabe mehrfach nebenlösig, z.B. durch 1.Ld5-c4 0-0-0 2.Bd6-d5 Df1xh1# (2010-05-29)
A.Buchanan: Here, the source was incorrectly given as "8202v Die Schwalbe 08/1977". No, that was where the original problem appeared, with a "v" added. So when, as here, we suspect the diagram has a typo, we would have to look through many back issues of Die Schwalbe! It turns out that this correction (itself cooked) was published (as text) in p.148 Die Schwalbe 65 10/1980. I have corrected the source. The reference to the earlier buggy problem can then cleanly be put in the "after" field. The actual typo was missing bPc7. (2024-03-06)
A.Buchanan: With the typo fixed, I think the retro-logic works ok, but there is a single cook family, fortunately repairable (2024-03-06)
more ...
comment
Keywords: Cant Castler, Castling (wg), Superseded by (P1415606)
Genre: h#, Retro
Computer test: both twins cooked by Popeye v4.87
FEN: NBr5/N1p3p1/1qPpp3/2bb4/1p6/n1pP1rP1/1PP1P2k/R3KQ1n
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-03-06 more...
45 - P0003736
Giuseppe Brogi
1249 Sinfonie Scacchistiche 07-09/1972
P0003736
(12+12) cooked
h#2
b) wSa5
a) 1. f5 Le5 2. 0-0 Th8#
b) 1. Kd8 0-0-0 2. Te8 Lf8#
play all play one stop play next play all
Try to deduce the diagram error, as we do have the intended solutions!
a) wRh7 is original, but cannot have escaped from cage by white cross-capture as there are too many captures needed. On the other hand, Black only has to make 4 captures so the cross-capture is ok.
b) changing the colour of Sa5 shifts the capture balance: now White can cross-capture but not Black, so White but not Black can castle.
Thus the retro-logic works with the diagram as it is, but the forward logic does not. How can we repair the diagram?
See P0000899 a companion problem.
A.Buchanan: Something odd going on here. There are numerous h#2 in both a&b. PRA not normally found in a problem with single solution for each twin. White has 8 pawns so trivially wRh7 must be original. (2018-10-13)
A.Buchanan: There are three similar problems by Brogi which are all twinned RS rather than PRA, but don't have diagram error. P0003743, P0003746 & P0003747. (2018-10-13)
VL: Nothing to do with Retro Strategy (nor with PRA). One definite castling is legal in every case. (2021-02-09)
Ladislav Packa: Cooked a) and b):
1...b8S and 2...R:h8# (2021-02-10)
A.Buchanan: I think the composer simply forgot that wPb7 can promote. Most of the cooks come from S promotions, but it's also possible to have QR. I've fixed it, rejigging the captures to make them still add up. I've posted in Discord, as I did with the partner composition, and will create entries for them here. (2022-03-15)
milan: +sLb8 sBa7=sT M.Frelih (2023-12-02)
A.Buchanan: Hi Milan - I don't think your suggestion quite works for b). In a) there are 0+2 spare captures, so Black can certainly cross-capture. But in b) there is 1+1 so neither side can cross-capture, so there is no solution. Please compare with P1399806, in which there are 1+2 & 2+1 spare captures, so both twins are sound. (2023-12-03)
milan: Hi Andrew my correction works only with 2.1... solutions, black or white knights on a5. are not important. (2023-12-03)
A.Buchanan: Hi Milan not really clear what you are doing, but if as well as the piece changes you proposed, you also change the stipulation to 2.1... then there is still only one solution. Even if you remove Sa5 entirely as well, there is no White cross-capture possible. (2023-12-04)
more ...
comment
Keywords: Castling (wgsk), Cant Castler (wgsk), Cross-capture (s,w), Superseded by (P1399806)
Genre: h#, Retro
Computer test: Popeye v4.87
FEN: 4k2r/pPp2p1R/n1pB1ppp/npP5/1P6/5PPP/2P2P2/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-03 more...
46 - P0003781
Imre Sztankovszky
(IX) Problem 29-30 05/1955
P0003781
(5+14) cooked
h#3*
1. ... b6 2. Le7 Lxg2+ 3. Kd6 Sxc4#
play all play one stop play next play all
Cook: Popeye V4.87
1. ... Sxc4 2. Da1 Kxb3 3. Le5 Lxg2#
1. ... bxa5 2. Le5 Kb4 3. d6 Lxg2#
1. ... Sxd1,Sxd3 2. Le5 Sb2,Sf2 3. d6 Lxg2#
1. ... Sxc4 2. Le5 Sb2,Sd2 3. d6 Lxg2#
WinChloe has same diagram, also says is cooked.
Henrik Juel: Black is missing [Lc8], which was captured on c8, and a rook
Last move was not c3xTb4, because sTc4's check is impossible, so White has the move (2020-10-01)
A.Buchanan: Shifting sLd6 to c5 removes the cooks. What's the artistic intent here though? (2021-10-16)
Henrik Juel: Maybe the unique h#2 try plays a role: 1.Le5 b6 2.d6 Lxg2# (2021-10-16)
A.Buchanan: In the h#2 try, b5-b6 is cool as the sole tempo move available to White. However there are plenty of *pairs* of White moves e.g. Sxd1-f2, which lose two tempi. These lead directly to h#2.5 cooks, and I see no way to eliminate these without losing the h#2 try. (2021-10-17)
comment
Keywords: No legal last move for White
Genre: h#, Retro
FEN: 8/1p1p4/3br3/pP1k4/KPbp4/pn1p4/qN4p1/3n3B
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-07 more...
47 - P0004199
Werner Frangen
Problem 41-44, p. 52, 03/1957
P0004199
(14+10) cooked
#5
1. axb6ep+ Kb5 2. bxc7+ Tb6 3. 0-0-0 ...
play all play one stop play next play all
K. Fabel: "Von Interesse ist, dass diese strittige Idee [Beweis des e.p.-Schlagrechts durch spätere Ausführung der Rochade] auch im direkten Mattproblem dargestellt werden kann, vergl. das Diagramm [diese Aufgabe P0004199]. (Vielleicht ist diese Aufgabe noch nicht korrekt doch es wird nicht schwer sein, sie zu verbessern). Falls Schwarz zuletzt Bb6-b5, Tb6-c6 oder Lb6-c7 gezogen hat, ergibt sich, dass Weiss im letzten oder vorletzten Zug den K oder T bewegt haben muss. Falls jedoch K und T noch nicht gezogen haben, muss b7-b5 der letzte Zug gewesen sein. Weiss spielt daher 1. ab6e.p.+ Kb5 2. bc7+ Tb6. Jetzt könnte Weiss mit Dxb6 sofort mattsetzen, aber er muss ja den e.p.-Schlag noch legalisieren. Daher 3. 0-0-0! und Matt erst im 5. Zuge."
Cook: 1. Sxc7+!
1. Lxc7!
Innerhalb des 2. Teils einer Artikelserie "Die Konventionen im Problemschach" von Karl Fabel.
A.Buchanan: The retro logic is fine, but forward play is savagely cooked. I wonder about changing wSc8 to sS. The retro stuff still works OK, indeed sSc8 is a fourth thematic unit to retract in the try. Ignoring proof of ep legality, there is a unique #4 beginning with ep, and no #5. Promising: but when can we interpolate w000? Any solution must begin 1. axb6ep+ Kb5. There are now numerous #4, but none include w000, so I think we must stick with the still unique line beginning 2. Dxc8 thr 3. 0-0-0. There are 3 black defenses to refute this. 2. ... Txb6,axb3,d5. So maybe #6 needed for White to prevail? (2022-03-28)
A.Buchanan: But if we shift to #6 then 1. Sxc7!,Qxc8+! mate without ep. Can anyone retrieve the original diagram for this one, please? (2022-03-28)
Mario Richter: The position here is identical to the original diagram, but it should be regarded more as a schematic example than a "real problem". Fabel in his quote above: "... perhaps the problem is still not correct, but it should be easy to improve it ..." (2022-03-28)
Henrik Juel: unfortunately K. Fabel forgot to give the easy correction... (2022-03-28)
A.Buchanan: Thanks for this. Valery Liskovetz, an AP expert, was kind enough to send a pdf of the relevant Problem issue, so I can confirm. It's easy enough to remove the two cooks (e.g. sTc8) but the difficulty is in validation of the intended solution. Is there any "exact" option in Popeye that forces the solution to include a waiting move? The actual solution might be expected to be included in that set. (2022-03-29)
Henrik Juel: Yes, Andrew
'stip exact-#5' would disregard #4 as a solution, I believe (2022-03-29)
A.Buchanan: Even with the "exact", it's still very complicated to investigate. I think this kind of problem requires an engine feature to disallow any mate or pat if the specified castling has not been executed. Gazing at the 20,000 lines of output, I don't think sTc8 works as 1. axb6ep+ Kb5 2. Qb7 bxa3! threatens axb2+ after castling. I wonder if the board might be flipped left-right except for wK, but I haven't explored this. (2022-05-31)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg), Non-standard material (TLL)
Genre: Retro, n#
FEN: NQNB4/B1brpp2/k1rp4/Ppp5/Rp6/BP6/RPP5/R3K3
Reprints: (8) Problem 101-102 09/1966
(52) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-29 more...
48 - P0004296
Luis Alberto Garaza
1809 Problem 73-78 06/1961
P0004296
(16+13) cooked
h#1? h#2?
1. fxe3ep? Dxa8# No justification for the ep, so just retro try.
play all play one stop play next play all
White pcs: dxexf5,hxBg. Black none. Assume that Black can still castle. White can't have just played h4xg5 as sBh2 would be blocked. White might apparently just have moved D,Se5,Td4,Tc3,g4-g5,a5-a6,e3-e4 or e2-e4 but what might Black have played before? Only the last allows a move sDf1-e1. So set up for AP Type Petrovic is OK.
Cook: 446 candidate h#2
However 27 have no ep, while 59 have both ep & castling.
So a total of 86 viable solutions, 85 of which must be cooks.
s.a. Version P0004341
more ...
comment
Keywords: Castling (sg), En passant as key, a posteriori (AP) (Type Petrovic), Superseded by (P0004341)
Genre: h#, Retro
Computer test: Popeye v4.87 indicates cook
FEN: r3k3/p1ppp3/Pp6/4NPP1/2PRPp2/2RK2PN/1PBn1PQp/2Brq1b1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-22 more...
49 - P0004341
Luis Alberto Garaza
(9) Problem 101-102 09/1966
P0004341
(15+12) cooked
h#1 oder h#2
1. fxe3ep Dxa8#? because no AP justification for ep

1. 0-0-0 g7 2. Tf8 gxf8=D#
play all play one stop play next play all
62 apparent h#2, so seems cooked.
Cook: 415 candidate solutions for h#2. 401 begin with ep, of which 48 contain 0-0-0 to justify. There are also 14 solutions without ep, of which 13 begin with 0-0-0. The odd one is 1. Kd8 Sc6+ 2. Kc8 Sge7#
Version zu P0004296

Autor: "In Nr.9, I intended to do something similiar to No. 8 [P0004199], but with a different key: the solution 1. PxP "e.p.", Qxa8 checkmate will not go, for if blackside does not castle, the "en-passant" capture cannot be justified. Though, well considering, there is the demolition 1. PxP "e.p." -any 2. 0-0-0! Qb7 or a8 checkmate.
A.Buchanan: Thanks Mario for retrieving the author's intent with this. So he knew it was cooked! Assume s000 rights remain. R: 1. b5xa6? as sBb promoted on b1. R: 1. h4xg5? as sBh retro-blocked. R: 1. Ke3-d3? impossible check from sBf4. R. 1. K~-d3 d3-d2? illegal check. I like these! So by elimination, R: 1. e2-e4 e3xTd2 2. T~d2 L~e1. So must have sLe1. (2022-03-22)
more ...
comment
Keywords: Castling (sg), En passant as key, a posteriori (AP) (Type Petrovic), Superseded by (P0004342)
Genre: h#, Retro
Computer test: Popeye v4.87 & simple retro-logic
FEN: r3k1N1/p1pp4/P5P1/4PPp1/2PNPprB/3K1QRp/P2p1PB1/4b2n
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-22 more...
50 - P0004342
Luis Alberto Garaza
(10) Problem 101-102 09/1966
P0004342
(15+11) cooked
h#2
1. bxc3ep Dg8#? (thematic try)
1. bxc3ep Dd5 2. 0-0-0 Db7#
play all play one stop play next play all
Cook: 1. bxc3ep Ld6 2. 0-0-0 Dc4#
Author: "From the former [d.h. P0004341], the No. 10 was born, something similar to No. 8 [P0004199] but with Black-castling for it is a help-mate. The mating move 1. ... Qg8? will not go."
more ...
comment
Keywords: Castling (sg), En passant as key, a posteriori (AP) (Type Petrovic), Superseded by (P1399966)
Genre: h#, Retro
Computer test: Popeye v4.87 & simple retro-logic
FEN: r3k3/p2p4/8/NP6/BpPPN1PP/B2K1Ppp/QP1p1pP1/Rrb5
Reprints: (55) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-23 more...
51 - P0004657
Mato Prikril
(27) Problem 206-210 07/1981
1. ehrende Erwähnung
P0004657
(5+7) cooked
h#2*
*) 1. ... Ta4 2. Kxg4 Txf4#
1. fxg3ep Ta4#? (no proof of ep right)
1. fxg3ep 0-0-0! 2. g2 Td4#
play all play one stop play next play all
A short retro try h#1 and 16 h#2 tries. B2 is unique tempo move
Cook: 1. Kxg4 Ta5 2. h4 Tg5#
1. Kxg4 Ta4 2. Kh4 Txf4#
61. TT (Pavlovic Memorial), Gruppe A
more ...
comment
Keywords: Castling (wg), En passant as key, a posteriori (AP) (Type Petrovic), Tempo Move
Genre: h#, Retro
Computer test: Popeye v4.87 & simple retro-logic
FEN: 8/6p1/6pB/7p/5pPk/5p1p/5P2/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-04-06 more...
52 - P0005036
Luigi Ceriani
36 32 personaggi e 1 autore 1955
P0005036
(14+12) cooked
Welches war der erste Zug der sD und des sK?
R: 1. ... Ld8xLc7 2. Lb6-c7 Kb7-b8 3. Lc7-b6 Kc8-b7 4. Lb6-c7 Lc7-d8 5. Lc5-b6 Lb8-c7 6. Lb6-c5 Kb7-c8 7. Ld8-b6 Kc7-b7 8. d7-d8=L Kd8-c7 9. e6xSd7 Sb6-d7 10. Sc5-a4 Sa4-b6 11. Se4-c5 d7-d6 12. Sf6-e4 Lh7-g8 13. Sg8-f6 Lf4-b8 14. Sf6-g8 Lh6-f4 15. Sg8-f6 c7-c6 16. g7-g8=S Kc8-d8 17. f6xTg7 Tg8-g7 18. e5-e6 Td8-g8 19. e4-e5 0-0-0 20. e3-e4 Lf8-h6 21. f5-f6 g7-g6 22. f4-f5 Le4-h7 23. f3-f4 Lb7-e4 24. f2-f3 Lc8-b7 25. Kb5-a5 b7xSa6
play all play one stop play next play all
alternative Auflösung (Mu-Tsun Tsai, PDB 2012-07-22, leicht gekürzt)
R: 1. ... Ld8xSc7+ 2. Sd5-c7 Kc7-b8 3. Sb6-d5 Kb7-c7 4. f2xSg3 Lc7-d8 5. Sd5-b6 Lb8-c7 6. Sf4-d5 Se4-g3 7. Se6-f4 Sc5-e4 8. Sb6-a4 Sa4-c5 9. Sc4-b6 Kc8-b7 10. Sd8-e6 Kc7-c8 11. d7-d8=S Kd8-c7 12. e6xTd7 Tb7-d7 13. Se3-c4 d7-d6 14. Sf5-e3 Le5-b8 15. Sg3-f5 Lg7-e5 16. Sf5-g3 Lf8-g7 17. Sh4-f5 g7-g6 18. Sf3-h4 Sg6-h8 19. Sh4-f3 Se5-g6 20. Sg6-h4 Lh7-g8 21. Sh8-g6 Le4-h7 22. Sg6-h8 Ke8-d8 23. Sh8-g6 Sf3-e5 24. h7-h8=S Ld5-e4 25. g6xDh7 Dh2-h7 26. g5-g6 Db8-h2 27. g4-g5 c7-c6 28. g3-g4 Dd8-b8 29. e5-e6 Tb8-b7 30. e4-e5 Lb7-d5 31. e3-e4 Lc8-b7 32. Kb5-a5 b7xSa6 33. Kc4-b5 Sd4-f3 34. Kd3-c4 Sc6-d4 35. Sc5-a6 Ta8-b8 36. Se4-c5 Sb8-c6 37. Ke2-d3 Sc5-a4 38. Ke1-e2 Da6-a3 39. Sg5-e4 Dh6-a6 40. Ta3-b3 Se4-c5 41. Db3-b2 Sf6-e4 42. Tb2-c2 Sg8-f6 43. Dd1-b3 Sf6-g8 44. Sf3-g5 Sg8-f6 45. Sg1-f3 Dh1-h6 46. Ld3-b1 h2-h1=D 47. Ta4-a3 h3-h2 48. Tb1-b2 h4-h3 49. b2-b4 h5-h4 50. Th4-a4 Sf6-g8 51. Th1-h4 Sg8-f6 52. h2xTg3 Tg6-g3 53. Lf1-d3 Th6-g6 54. e2-e3 Th7-h6 55. Sc2-a1 Th6-h7 56. Sa3-c2 Th7-h6 57. Ta1-b1 Th8-h7 58. Sb1-a3 h7-h5 59. c2-c3
Korrekturversuch s. P0003009
Henrik Juel: If you want a great solving challenge, this is the retro for you.
If you need a hint:
[Dd8] never moved, and Black castled (as you may have guessed).
If you need another hint:
Last move was Ld8xLc7+.
I gave up, but Nikolai told me the solution:
-1... Ld8xLc7 -2.Lb6 Kb7 -3.Lc7 Kc8 -4.Lb6 Lc7 -5.Lc5 Lb8 -6.Lb6 Kb7 -7.Ld8 Kc7 -8.L=d7 Kd8 -9.e6xSd7 Sb6 -10.Sc5 Sa4 -11.Sd4 d7 -12.Sf6 Lh7 -13.Sg8 Lf4 -14.Sf6 Lh6 -15.Sg8 c7 -16.S=g7 Kc8 -17.f6xTg7 Tg8 -18.e5 Td8 -19.e4 0-0-0 -20.e3 Lf8 -21.f5 g7 -22.f4 Le4 -23.f3 Lb7 -24.f2 Lc8 -25.Kb5 b7xSa6 etc. (2012-07-22)
Mu-Tsun Tsai: Once I heard "great challenge" I started working. But I came to a complete different conclusion. Not only [Qd8] can move, but the first move of the black king need not be castling. Here's the proof game. After playing
1.c3 h5 2.b4 Rh6 3.Na3 Rg6 4.Nc2 Rg3 5.hxg3 Nf6 6.Rb1 Ng8 7.Na1 Nf6 8.e3 Ng8 9.Bd3 Nf6 10.Rb2 Ng8 11.Bb1 Nf6 12.Qb3 Ng8 13.Rc2 Nf6 14.Qb2 Ng8 15.Rh4 Nf6 16.Rd4 h4 17.Rd5 h3 18.Ra5 h2 19.Ra3 h1=Q 20.Rb3 Qh5 21.Nf3 Qa5 22.Ke2 Qa3 23.Kd3 Na6 24.Kc4 Nc5 25.Kb5 Na4 26.Ne5 Nh5 27.Nd3 Nf4 28.Nc5 Nd3 29.Na6 bxa6+ 30.Ka5 Bb7 31.e4 Qb8 32.e5 Bc8 33.e6 Qb7 34.g4 Qf3 35.g5 Qh3 36.g6 Qh7 37.gxh7 Nf4 38.h8=N Bb7 39.Ng6 Be4 40.Ne5 Bh7 41.Nc4 Bg8 42.Ne3 Ng6 43.Nc4 Nh8 44.Ne3 g6 45.Nc4 Bg7 46.Ne3 Be5 47.Nc4 c6 48.Ne3,
you could either play
48...O-O-O 49.Nc4 Bb8 50.Ne3 d6 51.Nc4 Rd7 52.exd7+ Kb7 53.d8=N+ Kc7 54.Ne6+ Kb7 55.Nb6 Nc5+ 56.Na4 Ne4 57.Nc5+ Kc7 58.Nd7 Kb7 59.Nb6 Ng3 60.Nd5 Bc7+ 61.Nb6 Bd8 62.fxg3 Kc7 63.Nd5+ Kb8+ 64.Nc7 Bxc7+,
which is castling version, or,
48...Kd8 49.Nc4 Kc7 50.Ne3 Rd8 51.Nc4 Kc8 52.Ne3 Bb8 53.Nc4 d6 54.Ne3 Rd7 55.exd7+ Kb7 56.d8=N+ Kc7 57.Ne6+ Kb7 58.Nc4 Bh7 59.Nb6 Nc5+ 60.Na4 Ne4 61.Nd4 Kc7 62.Ne6+ Kc8 63.Nd4 Kb7 64.Ne6 Bg8 65.Nc5+ Kc7 66.Nd7 Kb7 67.Nb6 Ng3 68.Nd5 Bc7+ 69.Nb6 Bd8 70.fxg3 Kc7 71.Nd5+ Kb8+ 72.Nc7 Bxc7+
which is none castling version. Both reach the diagram position.
Why am I feeling cooking Ceriani's problems too much lately? (2012-07-22)
Mu-Tsun Tsai: Also in your retraction, -11.Nd4 should be -11.Ne4 I believe? It seems like your retraction also works just fine, and looks like it should be the intended solution. (2012-07-22)
Henrik Juel: Yes, the intended solution should have -11.Se4, and it can be shortened a bit.
I am impressed by your cook, Mu-Tsun, with two white pawn captures on g3 and promotion on h8, but it is also a little sad that a seemingly fine problem has been rendered worthless.
Probably several more Ceriani problems will be cooked, because they were not scrutinized well enough by testers and solvers in the old days; now, when I finally have cracked a Ceriani nut, I have no energy left to search for errors (2012-07-23)
Mu-Tsun Tsai: I've been thinking about how this problem might be fixed, but unfortunately I cannot come up with anything other than adding extra assumptions in the stipulation, for example "g3 pawn came from h2". The structure of this one is good, and either method of releasing the position (mine or the intended one) is quite subtle, so I feel sad about have to cook this one as well. (2012-07-23)
Thomas Volet: In his 1961 book Ceriani discusses the cook with the WhP unpromoting on h8 and uncapturing to the g file and back to the h file, and gives P0003009 as the corrected diagram position. (2012-08-02)
Mu-Tsun Tsai: This is a really late comment, but I do think this will make a great problem by changing the stip to "You don't know the first move of the black queen nor the black king"! (2023-06-29)
comment
Keywords: First Move? (kd), Superseded by (P0003009)
Genre: Retro
FEN: 1k4bn/p1b1pp2/p1pp2p1/K7/NP6/qRP3P1/PQRP2P1/NBB5
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2023-07-02 more...
53 - P0005275
Otto Kerekes
Tivadar Kardos

10 L'Echiquier de France 11/1956
P0005275
(11+15) cooked
h#2
b) sBg2 statt wBg2
a) 1. cxd4 Lxc4 2. Dd5 Ld3#

b)
play all play one stop play next play all
Paulo Roque: Illegale Stellung. Diagrammfehler? (2009-11-17)
Alfred Pfeiffer: außerdem in b) 9 schwarze Bauern. (2010-01-13)
A.Buchanan: Twin a) is also illegal, as too many Bl captures (2021-11-24)
more ...
comment
Keywords: En passant as key, Castling, Illegal position, Superseded by (P1400824)
Genre: h#, Retro
FEN: 8/p1p2p1b/1B3pp1/q1p1b3/r1pPk3/1Bp3P1/PPP2PPr/3n1RK1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-04-23 more...
54 - P0005310
Karlheinz Bachmann
8761 Die Schwalbe 151 02/1995
P0005310
(16+16) cooked
BP in 34,0
1. Sa3 Sa6 2. Sc4 Sc5 3. Se5 Se4 4. c4 c5 5. Da4 Da5 6. b3 b6 7. Lb2 Lb7 8. Tc1 Tc8 9. Tc3 Tc6 10. Th3 Th6 11. e3 e6 12. Le2 Le7 13. Lh5 Lh4 14. Sgf3 Sgf6 15. 0-0 0-0 16. Tc1 Tc8 17. Tc3 Tc6 18. Td3 Td6 19. Td4 Td5 20. d3 d6 21. Dd7 Dd2 22. De7 De2 23. Sd7 Sd2 24. Tg4 Tg5 25. Le5 Le4 26. Lf4 Lf5 27. Sfe5 Sfe4 28. f3 f6 29. Le8 Le1 30. Lg3 Lg6 31. Lf2 Lf7 32. Thg3 Thg6 33. h3 h6 34. Kh2 Kh7
play all play one stop play next play all
Cook: 1. Sa3 Sa6 2. Sc4 Sc5 3. Se5 Se4 4. c4 c5 5. Da4 Da5 6. b3 b6 7. Lb2 Lb7 8. Tc1 Tc8 9. Tc3 Tc6 10. Th3 Th6 11. e3 e6 12. Le2 Le7 13. Lh5 Lh4 14. Sgf3 Sgf6 15. 0-0 0-0 16. Tc1 Tc8 17. Tc3 Tc6 18. Td3 Td6 19. Td4 Td5 20. d3 d6 21. Dd7 Dd2 22. De7 De2 23. Sd7 Sd2 24. Tg4 Tg5 25. Le5 Le4 26. Lf4 Lf5 27. Sfe5 Sfe4 28. f3 Le1 29. Lg3 f6 30. Le8 Lg6 31. Lf2 Lf7 32. Thg3 Thg6 33. h3 h6 34. Kh2 Kh7
more ...
comment
Keywords: Unique Proof Game, Castling, Symmetrical position, Capture-free
Genre: Retro
FEN: 4B3/p2NQbpk/1p1ppprp/2p1N1r1/2P1n1R1/1P1PPPRP/P2nqBPK/4b3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-05-13 more...
55 - P0005336
Dezsö Elekes
4336 The Fairy Chess Review 3 28/11/1939
P0005336
(14+12) cooked
KBP?
1. g4 h5 2. gxh5 d5 3. h6 Dd6 4. hxg7 Dxh2 5. gxh8=T Dxh1 6. Txh1
play all play one stop play next play all
Duale sind möglich
"These promoted piece games are anticipated in general idea by CMF" (TRD)
Moldenhauer: Computerprüfung: C+ KBP 5.5 cooked in 1 Sekunde.
Keine Lösung: vor BP 5.5.
Beispiellösung:1.g4 d5 2.g5 h6 3.gxh6 Dd6 4.hxg7 Ddxh2
5.gxh8=T Dxh1 6.Txh1 (2023-03-22)
comment
Keywords: Non-Unique Proof Game, Pronkin Theme (T), Homebase (w)
Genre: Retro
Computer test: Computerprüfung: C+ KBP 5.5 cooked in 1 Sekunde. Keine Lösung: vor BP 5.5. Beispiellösung:1.g4 d5 2.g5 h6 3.gxh6 Dd6 4.hxg7 Ddxh2 5.gxh8=T Dxh1 6.Txh1
FEN: rnb1kbn1/ppp1pp2/8/3p4/8/8/PPPPPP2/RNBQKBNR
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-03-06 more...
56 - P0005581
Leonid M. Borodatow
5647v Die Schwalbe 105 06/1987
Günter Lauinger gewidmet
P0005581
(11+13) cooked
Wie oft stand der wK mindestens auf c7?
R: 1. ... De5-b8+ 2. Kc7xSc8 Sd6-c8+ 3. Kc8-c7 Sc4-d6+ 4. Kc7xSc8 Sd6xLc4+
play all play one stop play next play all
Cook: R: 1. ... Dd6:Sb8+ 2. Kc7-c8 ...
Nikolai Beluhov: Diagram is now correct (missing wRe8 and bBf8 restored). (2011-05-05)
Nikolai Beluhov: This problem seems to be cooked by 1. ... Qd6:Nb8+ 2. Kc7-c8 Q~d6+ ...
Fortunately, this flaw is very easy to fix: just relocate bQb8 to c7, as in
L. Borodatov (correction)
k1KRRb2/P1qpp1p1/rpp5/p7/5p2/3PP3/P1Pp1PP1/4Bb2
(http://www.janko.at/Retros/d.php?ff=k1KRRb2/P1qpp1p1/rpp5/p7/5p2/3PP3/P1Pp1PP1/4Bb2)
(11 + 13) How often did the wK visit c7 at least? (2011-05-06)
Henrik Juel: The wK visited c7 at least four times, twice as shown in the indicated retroplay, and twice to let wK pass the two white rooks en route to f7, with Le1 screening on b8. (2011-05-06)
Anton Baumann: Informalturnier 1986 (PB in 'Die Schwalbe' 06/2011 S.124)
Auszeichnung: 2.Lob; ausgezeichnete Fassung: mit sDc7 statt b8 (2023-01-04)
comment

Genre: Retro
FEN: kqKRRb2/P2pp1p1/rpp5/p7/5p2/3PP3/P1Pp1PP1/4Bb2
Input: Gerd Wilts, 1995-06-04
Last update: Nikolai Beluhov, 2011-05-06 more...
57 - P0005637
Osmo Ilmari Kaila
Hannu Harkola

(D) Die Schwalbe 48 12/1977
P0005637
(6+1) cooked
#3
AP
WTM: ???
BTM: 1. ... Kxf3 2. 0-0+! Ke3 3. Td1 Kf3 4. Td3#
not 2. Kd2? Kg2 3. Sf4+ Kf2,Kf3 4. Tf1#
play all play one stop play next play all
Cook: 1.Tf1,Se2+,Sf2 all lead to mate in 3, and none require castling
A.Buchanan: I don't get the regular part of this. White can mate in 3 in various ways: 1.Tf1,Se2+,Sf2. Black just played R: 1.Kh2g2 Td~h1+, so White can't castle but doesn't need to. What's going on? (2022-02-15)
comment
Keywords: a posteriori (AP) (Type Keym), Castling, Rex solus, Miniature
Genre: Retro, 3#
FEN: 8/8/6R1/8/8/5PNN/6k1/4K2R
Input: Gerd Wilts, 1995-06-06
Last update: A.Buchanan, 2023-07-30 more...
58 - P0005911
Unto Heinonen
2375 U.S. Problem Bulletin 01-02/1992
P0005911
(13+16) cooked
BP in 34,5
1. Sc3 h5 2. Se4 h4 3. Sg3 hxg3 4. h4 Th5 5. Th2 gxh2 6. Tb1 hxg1=S 7. Ta1 Sh3 8. Tb1 Sf4 9. Ta1 Sd5 10. Tb1 Sb4 11. Ta1 Td5 12. Tb1 g5 13. Ta1 Lg7 14. Tb1 Ld4 15. Ta1 Lb6 16. Tb1 c5 17. Ta1 Dc7 18. Tb1 De5 19. Ta1 Ld8 20. Tb1 b6 21. Ta1 La6 22. Tb1 Lc4 23. Ta1 a6 24. Tb1 Ta7 25. Ta1 Tc7 26. Tb1 Tc6 27. Ta1 Tf6 28. Tb1 d6 29. Ta1 Kd7 30. Tb1 Ke6 31. Ta1 Kf5 32. Tb1 Kg4 33. Ta1 Tf5 34. Tb1 Sf6 35. Ta1
play all play one stop play next play all
Korrektur siehe P0008426.
James Malcom: What is the cook? (2023-05-02)
more ...
comment
Keywords: Unique Proof Game, Non-standard material, Pendulum (T x30), Superseded by (P0008426)
Genre: Retro
FEN: 1n1b4/4pp2/pp1p1n2/2prqrp1/1nb3kP/8/PPPPPPP1/R1BQKB2
Reprints: (12) feenschach 117 11/1995
Input: Gerd Wilts, 1995-06-26
Last update: James Malcom, 2023-05-02 more...
59 - P0006428
Andrey Frolkin
9133v Die Schwalbe 157, p. 283, 02/1996
P0006428
(13+12) cooked
BP in 20.0
May White castle?
Weiß darf noch rochieren: 1. h4 Sa6 2. h5 Sc5 3. h6 a6 4. hxg7 h5 5. f4 h4 6. f5 h3 7. f6 h2 8. fxe7 Sf6 9. g8=L Lh6 10. Lxf7 Kxf7 11. e8=T Kg6 12. Te6 Dg8 13. Tc6 Db3 14. axb3 dxc6 15. Ta4 Lh3 16. Te4 Tag8 17. Te8 hxg1=D 18. e4 Dd4 19. Lc4 Tg7 20. Lg8 Dd8
Ohne die Bedingung, daß Weiß rochieren darf, gibt es andere BPs: 1. f4 Sa6 2. f5 Sc5 3. f6 a6 4. fxe7 f5 5. e4 f4 6. Lb5 f3 7. Lc6 f2+ 8. Ke2 fxg1=D 9. h4 dxc6 10. h5 Lf5 11. h6 Sf6 12. hxg7 Dd5 13. g8=L Db3 14. Lxh7 Kf7 15. axb3 Lh6 16. Ta4 Tag8 17. Td4 Dxd4 18. e8=T Tg7 19. Lg8+ Kg6 20. Ke1 Dd8
play all play one stop play next play all
SH: Cooked?:
1. e4 f5 2. Ne2 f4 3. h4 f3 4. h5 fxe2 5. f4 exf1B 6. f5 Bc4 7. f6 Bb3 8. axb3 Na6 9. fxe7 Nc5 10. Ra6 Nf6 11. Rc6 dxc6 12. h6 Bh3 13. hxg7 Qd7 14. g8B Bh6 15. Bxh7 Kf7 16. Qf3 Rag8 17. Qe2 Rg7 18. Bg8+ Kg6 19. Qd1 a6 20. e8R Qd8 (2005-06-20)
Henrik Juel: The stipulation question was probably intended as an implicit condition; when answered affirmatively, there should be a unique solution
But SH's solution shows that the problem is cooked (2018-12-09)
more ...
comment
Keywords: Anti-Pronkin, Constrained problem, Unique Proof Game, Castling
Genre: Retro
FEN: 3qR1Br/1pp3r1/p1p2nkb/2n5/4P3/1P5b/1PPP2P1/1NBQK2R
Input: Gerd Wilts, 1996-06-12
Last update: James Malcom, 2022-02-08 more...
60 - P0006623
Thierry Le Gleuher
1853v Phénix 50 03/1997
3. ehrende Erwähnung
P0006623
(16+16) cooked
BP in 40.5
1. a4 h5 2. Ta3 Th6 3. Tc3 Tb6 4. Tc4 Tb3 5. Sc3 Ta3 6. b3 Ta1 7. La3 d5 8. Db1 Lf5 9. Kd1 Lh7 10. Kc1 g6 11. Kb2 Lh6 12. Da2 Tc1 13. Sb1 Le3 14. Kc3 Lb6 15. Kd3 c5 16. Ke3 Sc6 17. Kf4 Dc7+ 18. Kg5 0-0-0 19. h4 Td6 20. Th3 Tf6 21. Te3 Tf3 22. Te6 Sf6 23. Kh6 Th3 24. Kg7 Th1 25. Kf8 Dh2 26. g3 Se5 27. Tc6+ Kd7 28. Tc8 Ke6 29. Lg2 Kf5 30. Le4+ Kg4 31. Sf3 Kh3 32. Lf5+ Kg2 33. Tg4 Lg8 34. Sd4 Sh7+ 35. Ke8 Sf3 36. Kd7 Kf1 37. Te8 Ke1 38. Kc8 Kd1 39. Kb8 Te1 40. Lc8 Sg1 41. f3
play all play one stop play next play all
Yoav Ben-Zvi: The cook found in P0002554 re-opens the question of the current length record for unique capture-free SPG. A search in PDB finds this problem, assuming it is sound, to be the record holder, until Unto Heinonen publishes a correction (expected very soon). Prior to publication of this problem the record was 38.5, in Michel Caillaud's P0002187. (2019-07-10)
Michel Caillaud: cooked (testing last moves with Jacobi 0.7.5 and constraints) :
16...Sd7 17.h4 Tc8 18.Th3 Tc6 19.Kf4 Te6 20.Tf3 Te3 21.Kg5 Db8 22.Tf6 Th3 23.Tc6 Sgf6 24.Kh6 Th1 25.Kg7 Dh2 26.g3 Se5 27.Lg2 Kd7 28.Tc8 Ke6 29.Kf8... (2021-02-13)
James Malcom: And thus, another giant falls. (2021-02-13)
A.Buchanan: Did Unto find a fix? (2021-02-14)
Michel Caillaud: Unto published a correction of P0002554 in StrateGems (42,5 moves, january 2020), not C+ of course... (2021-02-14)
James Malcom: May you input it into PDB please, Michel? (2021-02-14)
James Malcom: Thanks for the email, Michel. Unto's correction can now be seen in the database: P1386520 (2021-02-15)
more ...
comment
Keywords: Unique Proof Game, Capture-free, Move Length Record
Genre: Retro
FEN: 1KB1R1b1/pp2pp1n/1b4p1/2pp3p/P2N2RP/BP3PP1/Q1PPP2q/1Nrkr1n1
Reprints: H34 FIDE Album 1995-1997 2004
Input: Gerd Wilts, 1996-07-07
Last update: James Malcom, 2021-02-16 more...
61 - P0006972
Tivadar Kardos
1357 feenschach 24 08/1974
P0006972
(11+12) cooked
h#3
1. Lxa2 Txa2 2. 0-0-0 Txa7 3. Td7 Ta8#
1. Lxa2 0-0-0? 2. Dxg2 Tg1 3. 0-0 Txg2# but White can't castle
play all play one stop play next play all
Cook: 1. Lxa2 Lf6 2. Lb1 Txa7 3. Kf8 Txa8#
1. Lxa2 Lf6 2. Lxb3 Txa7 3. Kf8 Txa8#
1. Dxg2 Txb1 2. Dxf2+ Kxf2 3. 0-0 Tg1#
1. Dg3 Txb1 2. Dxb3 Txb3 3. 0-0 Tg3#
paul: White Rook h1 left the S-E camp, so the white castle is no more possible.
Intention: 1.L×a2 T×a2 2.0-0-0 T×a7 3.Td7 Ta8#
1.L×a2 0-0-0 2.D×g2 Tg1 3.0-0 T×g2#
Cooked by 1.L×a2 Lf6 2.Lb1 T×a7 3.Rf8 T×a8# or
1.D×g2 T×b1 2.D×f2+ K×f2 3.0-0 Tg1# (2011-09-15)
milan: wBe5-f4 M.Frelih (2021-12-01)
A.Buchanan: @Milan: that removes all 4 cooks, and alas the intended try also. (2021-12-01)
comment
Keywords: Cant Castler, Obvious promotion (l), Superseded by (P1396304)
Genre: Retro
FEN: r3k1qr/pp3p1p/2p5/3pB2p/8/1P6/P1PPPPPP/Rb2K3
Input: Gerd Wilts, 1996-08-11
Last update: A.Buchanan, 2021-12-01 more...
62 - P0007029
Philippe Leroy
623 Europe Echecs 447 07/1996
P0007029
(12+13) cooked
BP in 32,0
1. h4 Sf6 2. h5 Se4 3. h6 Sg5 4. hxg7 h5 5. a4 h4 6. a5 h3 7. a6 h2 8. axb7 hxg1=S 9. Ta6 Th2 10. Tg6 fxg6 11. e4 Kf7 12. Dh5 gxh5 13. e5 Kg6 14. e6 Kh6 15. exd7 e5 16. c4 e4 17. c5 e3 18. c6 Lc5 19. Sa3 Dg8 20. d8=S e2 21. Se6 exf1=L 22. Sf4 Le6 23. Sh3 Sd7 24. b8=D La2 25. Db3 Tb8 26. Dd1 Tb3 27. f4 Tf3 28. Sc2 Db3 29. g8=L Lb5 30. Lc4 a6 31. Lf1 Se2 32. Sg1 Lf2+
play all play one stop play next play all
paul: Correction of P0005875. (2011-06-02)
paul: Dans une version ultérieure, Mr.Leroy a remplacé 30.-a6 avec 30.-a5. Dans un e-mail, il m'a expliqué: La version de ce problème avec 30...a6 a été démolie par Thierry le Gleuher, d'une manière presque plus compliquée que la solution
de l'auteur. En résumé de sa démolition, le PN en a6 peut n'avoir joué qu'un seul coup, mais par b7xa6!
La version avec le PN en a5 est donc une correction de ce grave défaut.
Donc, Thierry, quel était cette démolition explicitement? (2011-06-09)
paul: Démoli(T. le Gleuher) : 1.c4 g5 2.Da4 g4 3.D×a7 g3 4.f4 g×h2 5.Df2 Ta3 6.Rd1 Tf3 7.a4 e5 8.a5 e4 9.a6 e3 10.Ta5 e×f2 11.Ch3 Cf6 12.Tg1 h×g1=C 13.Th5 Ce4 14.c5 Cg5 15.c6 Fc5 16.e4 0-0 17.Fc4 f1=F 18.F×f7+ Rg7 19.e5 Fb5 20.Fc4 Tf6 21.Ff1 Ce2 22.Cg1 Dg8 23.e6 Th6 24.Th1 Th2 25.e×d7 h5 26.d8=D Fe6 27.Dd3 Fa2 28.Dc2 Db3 29.Re1 Rh6 30.Dd1 b×a6 31.Ca3 Cd7 32.Cc2 Ff2?
La correction avec 30.-a5 a été publié dans Europe-Échecs 452/1997. (2011-06-12)
Joost de Heer: The position with a5 is also cooked:
1. h4 Nf6 2. h5 Ne4 3. h6 Ng5 4. hxg7 h5 5. a4 h4 6. a5 h3 7. a6 h2 8. axb7 hxg1=N 9. Ra6 Rh2 10. Rg6 a5 11. e4 fxg6 12. Qh5 Kf7 13. e5 gxh5 14. e6+ Kg6 15. exd7 e5 16. Na3 e4 17. c4 e3 18. c5 e2 19. c6 Bc5 20. f4 Qg8 21. d8=N Be6 22. Nf7 Nd7 23. b8=Q Ba2 24. Qb3 exf1=B 25. Ne5+ Kh6 26. Qd1 Qb3 27. g8=B Bb5 28. Bc4 Re8 29. Bf1 Ne2 30. Nf3 Re3 31. Ng1 Rf3 32. Nc2 Bf2# (2023-07-26)
comment
Keywords: Unique Proof Game, Pronkin Theme (DLS)
Genre: Retro
FEN: 8/2pn4/p1P4k/1b4np/5P2/1q3r2/bPNPnbPr/2BQKBNR
Input: Gerd Wilts, 1996-08-12
Last update: Gerd Wilts, 2004-08-29 more...
63 - P0007474
Kostas Prentos
5673v feenschach 1989
1. ehrende Erwähnung
P0007474
(11+14) cooked
BP in 15,0
1. a4 e6 2. Ta3 Ld6 3. Tb3 Lg3 4. Tb6 axb6 5. hxg3 Txa4 6. Th6 Ta1 7. Tg6 hxg6 8. Sa3 Th1 9. Sc4 Dh4 10. Sa5 bxa5 11. gxh4 b6 12. g3 Lb7 13. Lh3 Lg2 14. Lg4 Lh3 15. Lh5 gxh5
play all play one stop play next play all
Version zur inkorrekten P0002312
Cook: 1. a3 e6 2. h4 Lxa3 3. Sxa3 h5 4. Sb5 Th6 5. Ta6 Tf6 6. Tb6 Tf3 7. Sd4 Th3 8. Sc6 Txh1 9. Sxd8 axb6 10. Sc6 Ta1 11. Sa5 bxa5 12. g3 b6 13. Lg2 Lb7 14. Kf1 Lxg2+ 15. Ke1 Lh3
Kostas Prentos: Here is a computer tested correction: PG 12,5

1. a4 e6 2. Ta3 Ld6 3. Tb3 Lg3 4. Tb6 axb6 5. hxg3 Txa4 6. Th6 Ta1 7. Tg6 hxg6 8. Sa3 Th1 9. Sc4 Dh4 10. Sa5 bxa5 11. e3 b6 12. Dh5 gxh5 13. gxh4

C+ Euclide v1.11 (42 h 2 min 37 sec} (2022-12-08)
more ...
comment
Keywords: Unique Proof Game
Genre: Retro
Computer test: cooked by Stelvio 0.92
FEN: 1n2k1n1/2pp1pp1/1p2p3/p6p/7P/6Pb/1PPPPP2/r1BQK1Nr
Reprints: feenschach 115 01-09/1995
Input: Gerd Wilts, 1996-08-31
Last update: A.Buchanan, 2022-12-04 more...
64 - P0007482
Alexander Kislyak
6848v feenschach 116 10/1995
Peter Kniest zum Gedenken
P0007482
(12+11) cooked
BP in 13.5

Autor: "Reines Epaulettenmatt durch Rochade (vgl. mit f-111/6634)."
Moldenhauer: Computerprüfung: C+ Stelvio 1.2 03:15:11 Stunden. (hh:mm:ss)
C+ Euclide 1.11 01:00:47 Stunde.
Stelvio und Euclide finden nur 1 Lösung! Warum cooked?
Keine Lösung: BP12.5, BP 13.0.
Notation: 1.a4 Sf6 2.a5 Tg8 3.a6 bxa6 4.Txa6 Lb7 5.Txf6 a5 6.Txf7 Sa6
7.Txf8+ Kxf8 8.h4 De8 9.h5 Dxh5 10.f3 Dxf3 11.Sh3 Da3 12.e3 Te8
13.Lxa6 Lc8 14.0–0+#
Epaulettenmatt durch Rochade ist OK. (2023-05-28)
comment
Keywords: Unique Proof Game, Castling
Genre: Retro
FEN: 2b1rkr1/2ppp1pp/B7/p7/8/q3P2N/1PPP2P1/1NBQ1RK1
Reprints: (2) Die Schwalbe 164 04/1997
Input: Gerd Wilts, 1996-08-31
Last update: James Malcom, 2021-01-24 more...
65 - P0007858
Bernd Schwarzkopf
(16) feenschach 56 10/1981
P0007858
(13+12) cooked
Für 3 DD ist der erste Zug eindeutig (sie zogen nie).

play all play one stop play next play all
Cook: (alternative Auflösung mri)
R: 1. a5-a6 Ka8-b8 2. Ta6xTa7 Kb8-a8 3. Tb6-a6 Ta8-a7 4. Tb3-b6 Ka7-b8 5. Th3-b3 Kb6-a7 6. a4-a5 Kc6-b6 7. Dh5-e8 Kd6-c6 8. Df3-h5 Ke6-d6 9. Th1-h3 Kf7-e6 10. Dd3-f3 Ke8-f7 11. De4-d3 Kd8-e8 12. Dd3-e4 f7-f6 13. Sf6-g8 Dg8-h8 14. De3-d3 Th8-h7 15. Se4-f6 Dh7-g8 16. Sc3-e4 Ke8-d8 17. Sb1-c3 Dd3-h7 18. De4-e3 Tg8-h8 19. Dh7-e4 Da3-d3 20. Dh8-h7 Da1-a3 21. h7-h8=D Th8-g8 22. g6xSh7 a2-a1=D 23. g5-g6 b3xTa2 24. Ta1-a2 b4-b3 25. g4-g5 Sf6-h7 26. h3xSg4 a5xSb4 27. Sc6-b4 Se3-g4 28. Sd8-c6 Sd1-e3 29. Se6xDd8 Sc3xDd1 30. Sf4-e6 Sb5-c3 31. h2-h3 h7-h6 32. Sh3-f4 Sg8-f6 33. Sg1-h3 Sa7-b5 34. Ta2-a1 Sc6-a7 35. Ta1-a2 Sb8-c6 36. a3-a4 a7-a5 37. a2-a3
vgl. P0007857
Hans-Jürgen Manthey: die Vorgabe ist nicht nötig. 2 Damen zogen nie, die dritte konnte über a2 oder a3 usw. gezogen haben !
R: 1. f7xSe8=D Sd6-e8 g6xSf7 Se5-f7 h5xTg6 Tg5-g6 a5-a6 Sc6-e5 a4-a5 Se4-d6 Ta6-a7 Ta5-g5 Tb6-a6 Ta8-a5 Tb3-b6 Ka7-b8 Th3-b3 Kb6-a7 Th4-h3 Kc5-b6 Th3-h4 Kd6-c5 Th2-h3 Ke6-d6 Th1-h2 Kf7-e6 h4-h5 Ke8-f7 h3-h4 Kd8-e8 h2-h3 f7-f6 Sf6-g8 Sc3-e4 Se4-f6 Sd1-c3 Sc5-e4 Ke8-d8 Se6-c5 Sc3xDd1 Sd8-e6 Dg8-h8 Se6xDd8 Th8-h7 Sg5-e6 Dh7-g8 Sf3-g5 Dd3-h7 Sg1-f3 Sd5-c3 Sh3-g1 Da3-d3 Sg5-h3 Da1-a3 Sf3-g5 a2-a1=D Sg1-f3 b3xTa2 Ta3-a2 b4-b3 Ta2-a3 a5xSb4 Ta1-a2 Sf6-d5 Sd5-b4 h7-h6 Sc3-d5 Sg8-f6 a3-a4 a7-a5 a2-a3 Sb8-c6 Sb1-c3 (2021-07-26)
Mario Richter: Geplant war ein First-Move-Rekord, bei dem hier für 3 Damen der erste Zug eindeutig ist (wOriginal-Dd1, sOriginal-Dd8 und wUW-De8 zogen nie).
Leider läßt sich die Stellung auch beginnend mit R: 1. a5-a6 Ka8-b8 2. Ta6xTa7+ auflösen, so daß diese Aufgabe wohl "cooked" ist.
vgl. P0007857 (2021-07-27)
comment
Keywords: First Move?
Genre: Retro
FEN: 1kb1QbNq/Rpppp1pr/P4p1p/8/8/8/1PPPPPP1/2B1KB2
Input: Gerd Wilts, 1996-09-03
Last update: Mario Richter, 2021-07-28 more...
66 - P0008459
Jasper van Atten
972 Probleemblad 2 1985
P0008459
(13+15) cooked
BP in 25,0

play all play one stop play next play all
Cook: 1. a4 Sc6 2. a5 Se5 3. a6 Sc4 4. axb7 a5 5. b8=S a4 6. Sc6 dxc6 7. g4 Dd4 8. g5 Dh4 9. d4 Lf5 10. Dd2 Sf6 11. g6 Sd5 12. Dh6 gxh6 13. g7 Lg6 14. g8=S f5 15. Sf6+ exf6 16. b4 Se7 17. d5 Kd7 18. d6 Ke6 19. d7 Tg8 20. d8=D Lg7 21. Dd1 Lh8 22. b5 Tg7 23. b6 Tf8 24. b7 Tff7 25. b8=D Sg8
Moldenhauer: Die hier genannte Lösung Cook: hat am Ende die schwarze Dame auf h4
und den schwarzen Springer auf e7. Die FEN sind anders. Bitte löschen.
Autorenlösung? FEN?
Computerprüfung: FEN:1Q4nb/2p2rrp/2p1kpbp/5p1q/p1n5/8/2P1PP1P/RNBQKBNR
Cooked Stelvio 1.4 nach 3 Sekunden. Keine Lösung: BP 24.5.
Stelvio Beispiel: 1.a4 Sc6 2.d4 Sa5 3.d5 Sc4 4.d6 a5 5.g4 b5 6.axb5 a4
7.b6 f5 8.b7 Kf7 9.b8=S Ke6 10.Sc6 De8 11.g5 dxc6 12.d7 Dh5 13.d8=D Ld7
14.g6 Le8 15.D8d2 Sf6 16.Dh6 gxh6 17.g7 Lg6 18.g8=T Lg7 19.Tf8 Tg8
20.b4 Lh8 21.b5 Tg7 22.b6 Sg8 23.Tf6+ exf6 24.b7 Tf8 25.b8D Tff7 (2023-07-29)
comment
Keywords: Unique Proof Game
Genre: Retro
FEN: 1Q4nb/2p2rrp/2p1kpbp/5p1q/p1n5/8/2P1PP1P/RNBQKBNR
Input: Gerd Wilts, 1996-10-19
Last update: Gerd Wilts, 2004-08-11 more...
67 - P0008465
Thomas Volet
9375 Die Schwalbe 161 10/1996
Nikita Plaksin gewidmet
P0008465
(14+9) cooked
Die Partie ist beendet. Weshalb?
Thomas Volet: Problem P0008465 is faulty. (2000-11-27)
James Malcom: What is the author's solution and the cook? (2022-01-21)
Mario Richter: I do not the "official cook", but the following should work:
R: 1. Th1-g1 Kf5-e4 2. Th4-h1 Kg6-f5 3. Td4-h4 Kh6-g6 4. Td1-d4 Kg6-h6 5. Ta1-d1 Kh6-g6 6. Ta3-a1 Kg6-h6 7. Tb3-a3 Kh6-g6 8. Tb5-b3 Kg6-h6 9. Ta5-b5 Kh6-g6 10. Lb8-a7 Kg6-h6 11. Ta7-a5 Kh6-g6 12. Tb7-a7 Kg6-h6 13. La7-b8 Kh6-g6 14. Kg8-f8 Kg6-h6 15. Tb8-b7 Kh6-g6 16. Tf8-b8 Te8-e7 17. Lb8-a7 Tc8-e8 18. La7-b8 Tb8-c8 19. Te8-f8 Tb7-b8 20. Lb8-a7 Ta7-b7 21. Kf8-g8 Ta5-a7 22. Ke7-f8 Tb5-a5 23. Kd8-e7 Tb4-b5 24. Kc8-d8 Th4-b4 25. Kb7-c8 Th5-h4 26. Ka6-b7 Tg5-h5 27. Kb5-a6 Tf5-g5 28. Kc4-b5 Te5-f5 29. Kb3-c4 Te4-e5 30. Ka2-b3 Tb4-e4 31. Kb1-a2 Tb5-b4 32. Te7-e8 Ta5-b5 33. Kc1-b1 Ta7-a5 34. Kd1-c1 Tb7-a7 35. La7-b8 Tb8-b7 36. Ke1-d1 Th8-b8 37. Te8-e7 Kg5-h6 38. Tb8-e8 Tg8-h8 39. Tb7-b8 Th8-g8 40. Lb8-a7 Tg8-h8 41. Ta7-b7 Th8-g8 42. Ta5-a7 Tg8-h8 43. Tb5-a5 Th8-g8 44. Tb4-b5 Tg8-h8 45. Th4-b4 Tf8-g8 46. Th1-h4 Th8-f8 47. h2xLg3 (2022-01-23)
Thomas Volet: Mario, I do appreciate your tactfully lengthy unwind, but this effort at economy is hugely flawed. (2022-01-23)
comment
Keywords: 50 move rule
Genre: Retro
FEN: N4K2/B1pprPpp/1p2p3/2p5/N3k3/2P3P1/1PP1PPP1/5BR1
Input: Gerd Wilts, 1996-10-26
Last update: A.Buchanan, 2017-03-22 more...
68 - P0008788
Noam D. Elkies
FIDE Kongress 39 Tel Aviv 1996
1. Preis
P0008788
(12+16) cooked
BP in 23,0
1. c3 c6 2. Db3 Db6 3. Kd1 Dxf2 4. Db6 axb6 5. h4 Ta3 6. Th3 Tb3 7. a4 Ta3 8. Tg3 Ta2 9. Tg6 hxg6 10. Sh3 Th5 11. Sf4 Tb5 12. h5 Tb3 13. h6 Tba3 14. b3 Tb2 15. h7 Taa2 16. Sa3 Tb1 17. h8=T Tab2 18. Ta2 Ta1 19. Th3 Tbb1 20. Tc2 Tb2 21. Sb1 Tba2 22. La3 Tb2 23. Tg3 Dxf1#
play all play one stop play next play all
Cook: 1. a4 Sa6 2. Ta3 Sb8 3. Tg3 c6 4. Tg6 hxg6 5. Sh3 Th4 6. Sf4 Tg4 7. h4 Tg3 8. Th3 Ta3 9. h5 Ta1 10. Ta3 Da5 11. c3 Db4 12. Db3 Dc5 13. Db6 axb6 14. Kd1 Ta5 15. Ta2 Tb5 16. h6 Tb3 17. h7 Ta3 18. b3 Dxf2 19. Tc2 T3a2 20. h8=T Tb2 21. Th3 ...
Michel Caillaud: cooked by Stelvio 0.93 :
1.a4 Sa6 2.Ta3 Sb8 3.Tg3 c6 4.Tg6 hxg6 5.Sh3 Th4 6.Sf4 Tg4 7.h4 Tg3 8.Th3 Ta3 9.h5 Ta1 10.Ta3 Da5 11.c3 Db4 12.Db3 Dc5 13.Db6 axb6 14.Kd1 Ta5 15.Ta2 Tb5 16.h6 Tb3 17.h7 Ta3 18.b3 Dxf2 19.Tc2 T3a2 20.h8=T Tb2 21.Th3… (2022-12-19)
comment
Keywords: Unique Proof Game
Genre: Retro
FEN: 1nb1kbn1/1p1pppp1/1pp3p1/8/P4N2/BPP3R1/1rRPP1P1/rN1K1q2
Input: Gerd Wilts, 1997-06-21
Last update: Silvio Baier, 2023-03-02 more...
69 - P0008879
Arpad Molnar
R259 The Problemist 01/1997
P0008879
(10+9) cooked
Welches waren die letzten 16 Einzelzüge?

play all play one stop play next play all
Cook: R: 1. a4xSb3+ Lb8-c7 2. d6xSc5 Ld8-b6 3. b6xSa5 e7xTd8=L
Gerald Ettl: Weiss jemand wie die Autorloesung geplant war? (2023-09-28)
comment
Keywords: Last Moves? (16), Non-standard material
Genre: Retro
FEN: 8/p1Bp1ppp/RBR5/pBpP4/1kP5/Rp6/1PK5/8
Input: Gerd Wilts, 1998-06-26
Last update: Gerd Wilts, 2006-10-08 more...
70 - P0500165
Gino Mentasti
1721v Die Schwalbe 33-34, p. 561, 09-10/1964
Lob
P0500165
(3+8) cooked
h#4
1. Lf2 e3 2. Kf3 Txf7 3. Kg3+ Tb7 4. Tf3 Tg7#
play all play one stop play next play all
Cook: NL:
1. Kg4 Kg2 2. f5 Kf1 3. Kg3 Tb5 4. f4 Tg5#
1. Kf2 e4 2. Ke1 Kg2 3. Tf3 Kxf3 4. Kf1 Tb1#
Korrektur Timo Koistinen: +sDa2, +sBh6h7, ST 2001, p.179
Yuri Bilokin: Correction: bBd4-g1, bPh3 b4r2/1R3p2/8/8/7p/6kp/4P2p/6bK (3+8) (2022-04-21)
comment

Genre: h#
FEN: b4r2/1R3p2/8/8/3b3p/6kr/4P2p/7K
Reprints: 584 FIDE Album 1965-1967
Input: Gerd Wilts, 1996-06-06
Last update: Marcin Banaszek, 2016-01-22 more...
71 - P0500421
Reto List
(5) Die Schwalbe 84 12/1983
3. ehrende Erwähnung
P0500421
(4+12) cooked
h#2
b) wSg2 nach h6
a) 1. Sh5 Tf4 2. Tg3 Txh4#
b) 1. Sf5 Lf3 2. Lg3 Lg4#
play all play one stop play next play all
Cook: NL a)
1. La1 Ka7 2. Lg4 Sf4#
1. Lg4+ Ka7 2. Lf4 Sxf4#
Kees: possible fix: +wBa7 +sSa5 (2023-06-07)
A.Buchanan: This fix certainly removes the cooks, but the twinning in the original problem feels clumsy. (2023-06-08)
comment

Genre: h#
FEN: K1b4q/6pr/3p1pp1/4b3/7p/3r2nk/5RN1/7B
Input: Gerd Wilts, 1996-06-06
Last update: Alfred Pfeiffer, 2019-04-26 more...
72 - P0501318
Peter Kniest
feenschach 12/1973
5. Lob
27. Thematurnier
P0501318
(3+4) cooked
h#4
1. Df8 Lf1 2. Le6 Se3 3. Dc5+ Sc4+ 4. Kd5 Lg2#

NL:
1. Df4 Lf1 2. Le6 Se1 3. Kd5 Sd3 4. Dd6 Lg2#
play all play one stop play next play all
Yuri Bilokin: correction bQf1-c1, then a1=b1 8/8/4k3/8/3B3p/2bK4/7N/2q5 (3+4) h#4

1.Qg5 Bg1 2.Bf6 Sf3 3.Qd5+ Sd4+ 4.Ke5 Bh2# (MM) (2023-05-24)
comment
Keywords: Interchange (LS (20))
Genre: h#
FEN: 8/8/8/4k3/2B3p1/1bK5/6N1/5q2
Input: hpr, 1996-06-14
Last update: hpr, 1999-05-22 more...
73 - P0501392
Michael Schlosser
Karl Pohlheim

0-0 1981
2. -3. Lob
P0501392
(3+4) cooked
h#4*
*) 1. ... f4 2. Se7 f5 3. 0-0 f6 4. Kh8 f7#
1) 1. Se7 f4 2. 0-0 f5 3. Te8 f6 4. Kh8 f7#

NL:
*) 1. ... f4 2. Sh6 f5 3. 0-0 f6 4. Kh8 f7#
play all play one stop play next play all
Yuri Bilokin: +bSh6 4k1nr/K6p/7n/8/8/8/1B3P2/8 (3+5) (2021-06-11)
comment
Keywords: Interchange (kt (9)), Castling (sk)
Genre: h#
FEN: 4k1nr/K6p/8/8/8/8/1B3P2/8
Input: hpr, 1996-07-01
Last update: Alfred Pfeiffer, 2013-08-21 more...
74 - P0501419
Stanko Milenkovic
101 Problemas 04-06/1964
P0501419
(3+8) cooked
h#4
1. f2 Tb1 2. Sf3 Tb2 3. Ke1 Txc2 4. Sd2 Tc1#
play all play one stop play next play all
Cook: NL
1. Sg2 Th1 2. f2 Th8 3. Ke1 Th2 4. Kf1 Th1#
Adrian Storisteanu: Possible fix:
Kh1 Rb1 / Kc2 Sd1 ppb2 d2 e3 g3 h2 h3 (2+8) h#4
1.e2 Ra1 2.Se3 Ra2 3.Kd1 Rxb2 4.Sc2 Rb1# (2015-07-24)
milan: milan frelih: i've found key solution,your move? (2015-07-24)
milan: Milan Frelih:[Ka1 h1,+bBb1,wPe3=bPe4] (2015-08-31)
Yuri Bilokin: Correction: wKa1-h1, wRc1-b1, bKd2-c2, bPc2-b2, bNe1-d1, bPe2-d2, bPf3-e3, -bPb3, -bPd3, -wPe3, -bPe4, +bQg3 8/8/8/8/8/4p1q1/1pkp4/1R1n3K (2+6) h#4 1.e2 Ra1 2.Se3 Ra2 3.Kd1 Rxb2 4.Sc2 Rb1# (MM) (2022-04-21)
comment
Keywords: Interchange (ks (2)), Pure Round Trip (T)
Genre: h#
FEN: 8/8/8/8/4p3/1pp1Pp2/2pkp3/K1R1n3
Input: hpr, 1996-07-01
Last update: Alfred Pfeiffer, 2015-07-24 more...
75 - P0501467
Fritz Hoffmann
7030v Schach 09/1972
P0501467
(3+7) cooked
h#4
1. Db6 b5 2. Ld8 bxc6 3. Ke7 c7 4. Df6 c8=S#

NL:
1. Da5 b5 2. Ld8 bxc6 3. Ke7 c7 4. f6 c8=S# ua
play all play one stop play next play all
Yuri Bilokin: Correction: -bPf7, +bRe1 3qb1K1/3n4/2pk1b2/5P2/1P6/8/8/4r3 (3+7) (2022-05-02)
comment
Keywords: Interchange (dl (8))
Genre: h#
FEN: 3qb1K1/3n1p2/2pk1b2/5P2/1P6/8/8/8
Input: hpr, 1996-07-01
Last update: hpr, 1999-04-06 more...
76 - P0501534
Jean-Michel Trillon
feenschach 7, p. 194, 01/1972
7. ehrende Erwähnung
P0501534
(6+11) cooked
h#5
1. Sf3+ Se1 2. Se5 f3 3. Lg1 d4 4. Sc4 Sd3 5. Sb6 Sc5#

NL:
1. Ld4 Se3 2. Lxb2 Kxb2 3. Kb6 Sc4+ 4. Kc5 Kc3 5. d5 d4#
1. Lc5 Sd4 2. La3 bxa3 3. b2 Kc2 4. b1=T Se6 5. Tb6 Sc5#
play all play one stop play next play all
Yuri Bilokin: Correction: wNc2-g2, bPb2, +bRa2, +bPa3 8/q2p4/kbp5/p7/P4p2/pp6/rp1P1PNp/1K4nr (5+14) (2020-11-29)
comment
Keywords: interchange in mating position (ls (50)), Checking key, Line opening, Line closing
Genre: h#
FEN: 8/q2p4/kbp5/p7/P4p2/1p6/1PNP1P1p/1K4nr
Input: hpr, 1996-07-01
Last update: Gunter Jordan, 2021-05-18 more...
77 - P0501535
Günter Glaß
feenschach 01/1972
6. ehrende Erwähnung
25. Thematurnier
P0501535
(7+12) cooked
h#5
1. Sd7 Le5 2. Sf6 Lxg3 3. Sxg4 Le1 4. Lb8 La5 5. Sh2 Lxe6#

NL:
1. Kd8 Lf6 2. Ke8 Lxg5 3. Kf7 Lf4+ 4. Kf6 Ld6 5. Kg5 Lxe7#
uvm
play all play one stop play next play all
Yuri Bilokin: Correction: wKd1-h1 nnk5/1p2p3/4p2p/2p3pP/6P1/4p1pB/4P1Pb/B6K (7+12) (2020-11-28)
comment
Keywords: Interchange (ls (72))
Genre: h#
FEN: nnk5/1p2p3/4p2p/2p3pP/4p1P1/4P1pB/6Pb/B2K4
Input: hpr, 1996-07-01
Last update: hpr, 1999-05-23 more...
78 - P0501885
Mykola Nagnibida
2582 Gazeta Czestochowska 16/05/1979
P0501885
(3+9) cooked
h#3
1. Df5 Td4 2. Se6 Lc4 3. Df4 Td5#

NL:
1. Td4 Le4 2. Td6 Lg6 3. Sd5 Te4#
1. Dg8 Txe4+ 2. Kf5 Te8 3. Dg5 Le4#
play all play one stop play next play all
Yuri Bilokin: correction wKa4-b4, bPb7-f7, bPb6-e3, bPg4-f3, bPf4(-bSf4), -bBa7, then rotate 90 8/8/1pr1pp2/2qkrp2/3B4/4R3/4K3/8 (3+8) h#3
1.Qd6 Re4 2.Rc5 Be3 3.Qc6 Rd4# (MM)

Blocking piece replacement (bQ-bR)
Blocking piece replacement (bR-bQ)
Pelle move (white)
Place exchange (bQ/bR)
Place exchange (wR/wB)
Model mate × 1 (2023-05-19)
comment
Keywords: Interchange (TL ds)
Genre: h#
FEN: 8/bp6/1p2qr2/3Bk3/K1R1rnp1/8/8/8
Input: hpr, 1996-07-12
Last update: hpr, 1999-06-04 more...
79 - P0502003
Charles Wermelinger
1536 Europe Echecs 02/1970
P0502003
(3+6) cooked
h#4
1. Sg3 Ld3 2. Kg2 Lf2 3. Tg1 Le1 4. Sf1 Le4#
play all play one stop play next play all
Cook: NL
1. Tg2 Lc5 2. Sg3 Kd4 3. Kg1 Le2 4. Kf2 Kd3#
Adrian Storisteanu: Possible fix: +bPd4. (2015-07-25)
Yuri Bilokin: Correction: -bPe6, +bQd7 8/3q4/8/8/2K1n3/7n/7r/4rBBk (3+6)
Consecutive Umnov (mixed, BrB, 2), Place exchange (wB/bR), Place exchange (wB/bS) (2021-11-20)
comment
Keywords: Interchange (Lt Ls)
Genre: h#
FEN: 8/8/4p3/8/2K1n3/7n/7r/4rBBk
Input: hpr, 1996-07-15
Last update: Alfred Pfeiffer, 2015-07-25 more...
80 - P0502398
John Niemann
883 Feladvanykedvelök Lapja 07/1972
P0502398
(3+6) cooked
h#3
1. Db8 c7 2. Sb4 cxb8=S 3. Sa6 Sc6#

NL:
1. Dd2 c7 2. Sd7+ Ka3 3. Sdb8 c8=S#
1. Tb8 c7 2. Le4 c8=D 3. Ka8 Dxa6#
play all play one stop play next play all
Yuri Bilokin: correction bBa8, wKb3-e6, wPe2-c3, +bPc4 n7/kr6/npP1K3/8/2p2q2/2P5/8/8 (3+7) (2022-06-05)
Yuri Bilokin: sorry bNa8, bPb6 (2022-06-05)
comment

Genre: h#
FEN: b7/kr6/nnP5/8/5q2/1K6/4P3/8
Input: hpr, 1996-07-23
Last update: A.Buchanan, 2022-06-06 more...
81 - P0502612
John Niemann
1259 FEENSCHACH 102 05/1952
3. Preis
P0502612
(8+6) cooked
h#4
Autorabsicht: 1. Lh2 Th1 2. Lg1 Th8 3. Lh2 Th1 4. Lg1 T1h7#
play all play one stop play next play all
Cook: Viele NL, zB: 1. Sh4 Txg1 2. Sf3 gxf3 3. Kh6 Txg3 4. Kh5 Th1#
klären Autorlösung
Anton Baumann: Autorabsicht: 1.Lg2 Th1 2.Lg1 Th8 3.Lh2 Th1 4.Lg1 Th7#
Korrektur Version A. Bulawka: -sSg6, sKg7 nach f7, +sBe6, +sBf5, +sBg6 (vergl. yacpdb 320494) (2020-07-15)
Ladislav Packa: The modified version has an illegal position. (2020-07-15)
A.Buchanan: A good, sound, economical version is 320495 in YACPDB (2020-07-15)
A.Buchanan: Bulawka's correction 320494 is sound and legal (6 sB captures + 2 wL died at home). But Smirnov made a much lighter sound version 320495. (2021-05-16)
more ...
comment
Keywords: Superseded by (P1389613)
Genre: h#
FEN: 8/6k1/5pn1/8/8/6p1/PPKPPpP1/RR4b1
Input: hpr, 1996-07-23
Last update: A.Buchanan, 2021-05-16 more...
82 - P0502815
Shergil Sukhitashvili
1656 Gazeta Czestochowska 05/03/1974
P0502815
(9+12) cooked
h#2
4.1...
1) 1. Ld3 e3 2. Le2 e4#
2) 1. Se3 g3 2. Sg2 g4#
3) 1. Sg5 Lg8 2. Sf7 Lh7#
4) 1. Sf8 Txd6 2. Sg6 Lxe6#

NL:
1. Dg3 dxe5 2. Df4 Sg7#
1. Th1 dxe5 2. Sxe5 g4#
1. Ld3 exd3 2. De4 dxe4#
play all play one stop play next play all
Kees: I don't know how to send a diagram, but I fixed this one with a whole different position, but with the 4 thematic solutions I can send a FEN-notation with the 4 solutions

3K4/1pr1B1p1/s1pp2P1/2Rpk1S1/2Pb1sP1/3pPp2/4P3/3q1r2

1.Fc3 exd3 2.Fd2 d4‡
1.Ch3 exf3 2.Cf2 f4‡
1.Cxg6 Ff8 2.Ce7 Fxg7‡
1.Ch5 Txc6 2.Cf6 Fxd6‡ (2023-06-09)
comment
Keywords: Interchange (Bl,Bs,Ls)
Genre: h#
FEN: 4K3/2pr1B1n/3pp2p/3Rbk1N/3Pb1nP/5P2/4P1P1/4q1r1
Input: hpr, 1996-07-28
Last update: hpr, 1999-06-05 more...
83 - P0502958
Beni Snaider
9194v Tidskrift för Schack 03-04/1947
P0502958
(3+4) cooked
h#4
1. Kb5 Kf5 2. Kb6 Kg6 3. Kc7 Kf7 4. Kd6 Lh2#
play all play one stop play next play all
Cook: NL
1. Ta6 Sg8 2. Td6 Kf4 3. Kd5 Kf5 4. c4 Se7#
(KSp h)
Adrian Storisteanu: See P0502965 (failed correction attempt / self-anticipation). (2015-07-25)
milan: milan frelih:[Ke5 to h4 +bPh6] 1.Kb5 Kh5 2.Kb6 Kg6 3.Kc7 Kf7 4.Kd6 Bh2# (2015-07-26)
Yuri Bilokin: correction b1=a1, then wKd5-h4, -bPf7 8/8/1r2N3/1p6/1k5K/8/8/5B2 (3+3) h#4

1.Ka5 Kg5 2.Ka6 Kf6 3.Kb7 Ke7 4.Kc6 Bg2# (MM) (2023-05-24)
comment
Keywords: Figurenspiel
Genre: h#
FEN: 8/6p1/2r2N2/2p1K3/2k5/8/8/6B1
Input: hpr, 1996-08-30
Last update: Alfred Pfeiffer, 2015-07-25 more...
84 - P0503022
Claude Goumondy
Turnier des Tschechischen Sportbundes 1981-1982
1. Lob
P0503022
(6+6) cooked
h#2
b) wTe1 nach a4
c) sDe5 tauschen mit sSe4
d) sSg6 nach h4
a) 1. Ke6 Lxe4 2. Df6 Ld5#
b) 1. Kc5 Lxe5 2. Sd6 Ld4#
c) 1. Kxc6 Txe4 2. Sd7 Te6#
d) 1. Kd6 Txe5 2. Sc5 Te6#

NL:
d) 1. Ke6 Tf5 2. Sd6 Txe5#
play all play one stop play next play all
KSp
Kees: possible fix: +sLh8

What is KSp ? (2023-06-09)
comment
Keywords: Figurenspiel
Genre: h#
FEN: 8/8/2P3nK/3kq2R/4n1r1/5B1r/7B/4R3
Input: hpr, 1996-09-03
Last update: hpr, 1999-06-06 more...
85 - P0503162
Thomas R. Dawson
2322 Pittsburgh Sun 19/04/1924
P0503162
(5+8) cooked
h#3
1. Th1 Sa1 2. Th4 Sh1 3. Tf4 Sc2#
play all play one stop play next play all
Cook: NL
1. Tf1 Kh8 2. Tf2 Sa1 3. Df4 Sc2#
1. Df4 Sxa1 2. e1=L h6 3. Lf2 Sc2#
teilweiser Rundlauf t
Adrian Storisteanu: Possible fix: bPe4 (instead of the bQ), +wPf5, +bPf6 (6+9). (2015-08-15)
Yuri Bilokin: correction bRd3(-bNd3), bBe4(-bQe4), bPf3(-bBf3) 6K1/8/8/7P/3Pb3/pN1rkpN1/3pp3/r7 (5+8) (2022-12-19)
A.Buchanan: This is very clean Yuri well done. I would shift bPa3 to a5. wK must be exactly on g8, else the problem is cooked (2022-12-20)
comment
Keywords: Pure Round Trip
Genre: h#
FEN: 6K1/8/8/7P/3Pq3/pN1nkbN1/3pp3/r7
Input: hpr, 1996-09-05
Last update: Alfred Pfeiffer, 2015-08-15 more...
86 - P0503402
Laszlo Barna
3. Makuc-Moder-Gedenkturnier 03/1970
2. Preis
P0503402
(4+9) cooked
h#2
b) wSc8 nach c6
c) wSc8 nach e6
d) wSc8 nach e4
a) 1. Tf6 g8=D 2. Kc6 De8#
b) 1. Tc3 g8=L 2. Kc8 Le6#
c) 1. Te5 g8=S 2. Ke8 Sf6#
d) 1. Tc3 g8=T 2. Ke6 Te8#

NL:
1. Dh1 Sf6+ 2. Kd8 g8=D#
uvm
play all play one stop play next play all
KSp Königsstern
t/Allumwandlung, u/61104
Daniel Novomesky: Add bPh5. C+ (2008-03-03)
Yuri Bilokin: correction +bPh5 2N4K/3k2PR/6pq/2rp1rpp/8/8/b7/b7 (4+10)

Allumwandlung (white)
JT Onkoud 50 theme (double)
Promotion (QRBS, 4)
Star (bK)
Mates on the same square × 2 (2023-06-26)
comment
Keywords: Allumwandlung, Figurenspiel
Genre: h#
FEN: 2N4K/3k2PR/6pq/2rp1rp1/8/8/b7/b7
Reprints: feenschach , p. 58, 04/1975
Input: Erich Bartel, 1996-09-17
Last update: hpr, 1999-06-12 more...
87 - P0503578
Thomas R. Dawson
2254v Bolton Football Field 06/07/1912
P0503578
(6+3) cooked
h#3
1. Kc3 De6 2. Kxd4 Dxd6+ 3. Ke4 De5#

NL
1. Kc3 Df5 2. Tf8 Kxd6 3. Kxd4 Dd3#
play all play one stop play next play all
Korrektur Hilmar Ebert: +sSe8 (erhält Quasi-Symmetrie)
Yuri Bilokin: Not all pieces in quasi-symmetry are necessary: the white pawn on h2 is superfluous. It is clear that more than 100 years ago there was such a direction in art, although some authors indulge in technical white pawns in our time. (2022-12-19)
A.Buchanan: The technical term for such a position is "symmetric constellation". "Quasi-symmetry" is where the position is nearly symmetric but not quite (e.g. game array except wPa2 is missing). In a symmetric constellation any redundant piece is a definite defect. A quasi-symmetric position is not an ornament, more of a consequence of the content. For example, a number of last move type DD problems are quasi-symmetric (2022-12-20)
Yuri Bilokin: Thanks for the interpretation (2022-12-20)
comment
Keywords: Pure Round Trip (D)
Genre: h#
FEN: 8/4K3/3p1r2/4Q3/3P1P2/8/1k2P2P/8
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 2001-12-21 more...
88 - P0503649
Peter Kniest
6742v Die Schwalbe 09/1942
P0503649
(3+13) cooked
h#4
b) wBg3 nach g2
a) 1. Dd6 Lxb2 2. e6 Lc1 3. Ke5 Lxh6 4. f5 Lg7#
b) 1. Dd4 Le5 2. f6 Lxh2 3. e6 g3 4. Ke5 g4#

NL:
a) 1. Se6 Kxh7 2. Dc3 Kxh6 3. Lc1+ Kh5 4. Lf4 g4#
b) 1. Ke5 g3 2. Sf5 Kg8 3. e6 Lh6 4. Ld4 Lf4#
play all play one stop play next play all
Korrekturvorschlag HJS Co+:wKh8, wLg7, wBg3, sKf5, sDf6, sTa2a8, sLb2g8, sBd5e4e7f7h4
Yuri Bilokin: Good fix, can be more economical: r5bK/4ppB1/5q2/3p1k2/4p3/1rb3P1/8/8 (3+10) h#3 b) wPg3-g2
a) 1.Qd6 Bxc3 2.e6 Bd2 3.Ke5 Bh6 4.f5 Bg7# (MM)
b) 1.Qd4 Be5 2.f6 Bh2 3.e6 g3 4.Ke5 g4# (MM) (2021-06-14)
comment
Keywords: Hilfsmatt-Inder (LB), Pure Round Trip (L)
Genre: h#
FEN: 5n1K/4ppBp/5q1n/3p1k2/4p2p/6P1/rb5r/8
Input: hpr, 1996-09-23
Last update: hpr, 1999-06-13 more...
89 - P0503768
Thomas R. Dawson
1471v The Chess Amateur 08/1929
P0503768
(8+13) cooked
h#3
1. Dxe5+ Lf5 2. Dxd4 Lc2 3. De4 Lb3#

NL:
1. d1=S Le7 2. Sxb2 Sb3 3. f1=S Sc1#
play all play one stop play next play all
Korrekturvorschlag HJS Co+:wKg5, wLc2f6, wSc5, wBb2d4e5g4, sKa2, sDe4, sTa1h1, sLb1d8, sBb4d5e6f2f7
milan: +wPd6 M.Frelih (2021-12-01)
A.Buchanan: 3b4/5p2/4pB2/2NpP1K1/1p1Pq1P1/8/kPB2p2/rb5r as specified in Korrekturvorschlag HJS is C+ with 2 fewer units (2021-12-02)
comment
Keywords: Pure Round Trip (d)
Genre: h#
FEN: 3b2n1/5p2/4pB2/1pNpP1K1/3Pq1P1/8/kPBp1p1r/rb6
Input: hpr, 1996-09-23
Last update: hpr, 1999-06-19 more...
90 - P0503880
Christer Jonsson
14139v Tidskrift för Schack 02/1982
P0503880
(4+5) cooked
h#4
0.2.1...
1) 1. ... Txb8 2. Kc5 Txe8 3. Lc3 Te5+ 4. Kb4 Tb5#
2) 1. ... Te5 2. Dd6 Txe8 3. Kc5 Tb8 4. Ld4 Tb5#

NL:
1. ... Tb6 2. Kc3 Sb5+ 3. Kb4 Sd6+ 4. Ka5 Sc4#
play all play one stop play next play all
Yuri Bilokin: correction +bNd2 1q2b2b/N7/8/1R6/3k4/pP6/3n4/7K (4+6)

AntiZielElement (W1, line obstruction)
Areal cycle (wR, with captures, 4) × 2
Exchange of moves (W1/W3)
JT Onkoud 50 theme
Long-trip (wR, 4) × 2. Many-ways (wR, 2) × 4
Zalokotsky theme (wR/wR, 3)
Model mate × 2.Mates on the same square × 2 (2023-05-08)
comment
Keywords: Pure Round Trip
Genre: h#
FEN: 1q2b2b/N7/8/1R6/3k4/pP6/8/7K
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-20 more...
91 - P0503926
Claude Goumondy
4104 Deutsche Schachzeitung 01/1980
P0503926
(3+9) cooked
h#4*
0.2.1...
1) 1. ... Lxb7 2. Le5 Lc8 3. Kd5 Lxd7 4. Ke4 Lc6#
2) 1. ... Th3 2. Ld2 Txh4 3. Kd3 Tf4 4. Ke3 Tf3#

NL:
1. ... Tf1 2. Kd3 Tf2 3. Sf3 Lb5+ 4. Ke3 Txe2#
play all play one stop play next play all
Yuri Bilokin: correction +bQg4, +bPa6, -bNh4, -bPh2 8/1b1p4/p1Bn4/8/2kp1bq1/5R2/4p3/7K (3+9) h#4 0.2.1…
1...Rg3 2.Bd2 Rxg4 3.Kd3 Rf4 4.Ke3 Rf3# (MM)
1...Bxb7 2.Be5 Bc8 3.Kd5 Bxd7 4.Ke4 Bc6# (MM)

Areal cycle (wB, with captures, 4)
Areal cycle (wR, with captures, 4)
Exchange of functions (wRf3/wBc6, Mate / Passive guard)
Long-trip (wB, 4). Long-trip (wR, 4)
Model mate × 2 (2023-05-08)
comment
Keywords: Pure Round Trip
Genre: h#
FEN: 8/1b1p4/2Bn4/8/2kp1b1n/5R2/4p2p/7K
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-20 more...
92 - P0503977
Leon Loewenton
H241 FIDE Olympia Turnier 14 Leipzig 1960
5. -9. Lob
P0503977
(6+5) cooked
h#2
5.1...
1) 1. f2 e8=S 2. Ld5 Txf2#
2) 1. Kd6 Tc2 2. Kc7 Le5#
3) 1. Kf6 e8=D 2. Kg7 Th2#
4) 1. Kf4 Th2 2. Kg3 Le5#
5) 1. Kd4 Le6 2. Kc3 Tb3#

NL:
1. Kxf5 e8=D 2. Kf6 Tb5#
play all play one stop play next play all
KSp Königsstern
Kees: Possible fix: +wBb4 -sLh1 (No 5.1... but 4.1... with only KSp Königsstern) (2023-06-05)
A.Buchanan: I agree with +wBb4 for soundness but let's keep sLh1. What's not to like about 5 well differentiated solutions? WinChloe has the same cooked diagram as we do here. (2023-06-06)
Yuri Bilokin: The fifth solution is not necessary, the author has kept it, so after adding the white pawn to the b4 square and without removing the black bishop, we fully preserve the author's intention.
8/4P3/1pP5/4kB2/1P6/4pp2/1R6/B2K3b (7+5) h#2 5.1...

Active sacrifice (black, delayed). BK moves only × 4. Delayed Umnov (bK-wB) × 2
Extended star (bK)
Promotion (QS, 2)
Battery mate × 3. Double-check mate. Mirror mate
Mate from initial bK square × 2 (2023-06-10)
more ...
comment
Keywords: Figurenspiel
Genre: h#
FEN: 8/4P3/1pP5/4kB2/8/4pp2/1R6/B2K3b
Reprints: H241 Schach 19, p. 301, 10/1960
Input: hpr, 1996-10-03
Last update: A.Buchanan, 2023-06-06 more...
93 - P0504564
Leonid Makaronez
1634 Gazeta Czestochowska 22/01/1974
P0504564
(4+7) cooked
h#2
b) wTc1 nach b1
c) wTc1 nach a5
a) 1. Lg6 Tc7 2. e5 Le7#
b) 1. e5 Lf8 2. g5 Tb6#
c) 1. g5 Ld6 2. Lg6 Le5#

NL:
a) 1. e5 Le1 2. Lg6 Lh4#
ua
play all play one stop play next play all
SB- SB- SL
klären: fehlen irgendwelche Figuren?
Daniel Novomesky: Add black Pawns b6,d4. C+ (2007-11-04)
Yuri Bilokin: Currection: bPe2-f2, +bPb6, +bPd2, +bPh6 2B5/4ppp1/Kp3k1p/8/1B6/4p3/2bp1p2/2R5 (4+10) (2021-05-20)
Ladislav Packa: Correction: wKa6?f1, -bPe2, +bPa6, b6, g3 (4+9) C+ (2021-05-20)
Yuri Bilokin: Correction: The author's moves are quiet, without taking. Taking it can be more economical. "The captured girl is good for everyone." wKa6-f1, wBb4-a3, bPe2-b6, +bPa6 8/4ppp1/pp3k2/8/8/B3p2B/2b5/2R2K2 (4+8)
a) 1.Bg6 Rc7 2.e5 Be7# (MM)
b) 1.e5 Bf8 2.g5 Rxb6#
c) 1.g5 Bd6 2.Bg6 Be5# (MM) (2021-05-20)
Yuri Bilokin: It is possible without taking r1B5/1K2ppp1/5k2/8/8/B3p3/2bp4/2R5 (4+8) (2021-05-21)
comment
Keywords: Cycle
Genre: h#
FEN: 8/4ppp1/K4k2/8/1B6/4p2B/2b1p3/2R5
Input: Torsten Linss, 1996-10-09
Last update: hpr, 1999-07-09 more...
94 - P0504742
Julius Dohrn-Lüttgens
5v FEENSCHACH 11/1949
P0504742
(11+7) cooked
h#4
1.Dxa3 Tg1 2. Da8 Ta7 3. Dxg2 Txh7 4. Da8 Txg8#

NL:
1. Kb7 Td1 2. Dc5 dxc5 3. Ka6 Td7 4. Ka5 Ta7#
play all play one stop play next play all
DSp
Adrian Storisteanu: Possible fix: wPd4->d2,+bPd3 (11+8). (2021-09-17)
comment
Keywords: Figurenspiel
Genre: h#
FEN: 1k3qn1/7n/8/1p6/3P4/PpP1P2P/1P3PPp/R3K2R
Input: hpr, 1996-12-25
Last update: hpr, 1999-07-10 more...
95 - P0504934
Henrik Juel
5802 Thema Danicum 73 01/1994
P0504934
(4+2) cooked
h#5
1. f4 h5 2. f3 h6 3. f2 h7 4. f1=T h8=L 5. Tg1 Le5#
play all play one stop play next play all
Cook: 1. Kg3 Kb5 2. Kf2 Kc4 3. f4 Sd3+ 4. Ke2 Kc3 5. Kd1 Lf3#
Henrik Juel: Here's a correction: move the pawns one step ahead, then h#4. (2003-10-16)
Henrik Juel: A stronger correction is needed:
move Ph4 to h6, Pf5 to f2, and change stip to h#2.5
Then C+ Popeye 4.61 with solution
1... h7 2.f1=T h8=L 3.Tg1 Le5# (2021-05-23)
A.Buchanan: Hi Henrik: -wSe1 +wLh1 cheekily repairs the original h#5. Indeed you can push the pawns back to make a h#6, still sound 8/5p2/K7/8/8/7P/6Bk/7B You're welcome! :D (2021-05-23)
Henrik Juel: Back in the old days two light-squared white bishops were unthinkable
And some people considered the knight more economical than the bishop
The problem is from a construction contest: h# with white and black promotion (2021-05-24)
A.Buchanan: In some ways, Henrik, composition is about trying to find the best natural form that a problem is trying to take. I wasn't trying to think the unthinkable, but when I finally thought it as the only way to salvage and indeed amplify your idea here, I started looking forward to reading your response :) If you don't want it, that's absolutely fine - I will claim it as an "after HJ", and try to find some "Salon Des Refuses" in which to exhibit it (2021-05-24)
Adrian Storisteanu: Or you could send it to the "Salon des Fous":
  Kd1 Bg2 Bh1 ph3 / Kh2 pa5 (4+2)
1.a4 h4 2.a3 h5 3.a2 h6 4.a1B h7 5.Bd4 h8B 6.Bg1 Be5# (2021-05-25)
A.Buchanan: :-) Adrian, your bishop line still works with wKa6: why change that? (2021-05-25)
Adrian Storisteanu: Old habit of putting the wK teasingly close to the main stage, while still not causing unnecessary cooks... (2021-05-25)
Henrik Juel: Your suggestion is fine, Andrew
Composing exercise 50 was announced in Thema Danicum no. 72, where the editor Holger Helledie asked for help mate problems with 1 white and 1 black promotion, as long as possible
Theodor Steudel pointed out that problems as short as possible were also relevant, and the submitted problems along with many old ones were shown in TD no. 73, where HH expanded the criteria to
1. As few men as possible (4 was achieved in 1927: Kh8 Pf7 - Ka1 Pb3, h#2)
2. Shortest or longest possible (from h#1.5 to h#10, the latter from 1956: Kc1 Pc2 - Kh7 Pc3e4)
3. Economy of the men
4. Publication date
Four more problems appeared in TD no. 74, where HH announced his resignation as editor
I considered my contributions as one of the many low points in my composing career, such as it is, and initially excluded them from the compilation, I am working on; but now I have changed my mind... (2021-05-25)
milan: wPh4-f4 wKa6-h4 wBg2-h1 bPf5-b5 1.b4 f5 2.b3 f6 3.b2 f7 4.b1=R f8=Q 5.R×h1 Qf2#
or wSe1-e3 bPf5-b5 ...4.b1=R.Q Dual 5.bRg1 Be5#i couldn't find the solution without dual.
M.Frelih (2021-05-25)
comment
Keywords: Minimal, Miniature
Genre: h#
FEN: 8/8/K7/5p2/7P/8/6Bk/4N3
Input: Markus Manhart, 1996-12-25
Last update: Arnold Beine, 2021-05-27 more...
96 - P0505083
Zoltan Zilahi
788v Problemas 09/1955
P0505083
(4+13) cooked
h#5
1. Tc7 a4 2. Sb7 a5 3. Kd5 a6 4. Kc6 a7 5. Dd5 Ta6#

NL:
1. Ke3 h5 2. Kf3 h6 3. Ke2 h7 4. Kf1 h8=D 5. De2 Dh1#
play all play one stop play next play all
Yuri Bilokin: Correction: -bRf2, -wPh4, bBd7, bNe7-c1, bBe5-f4, bPf6-c3 8/r2b4/8/npp5/4kb2/2p5/Pp1q4/RKn5 (3+11) (2020-11-28)
comment
Keywords: Bahnung
Genre: h#
FEN: 8/r2pn3/5p2/npp1b3/4k2P/8/Pp1q1r2/RK1b4
Input: hpr, 1996-12-26
Last update: hpr, 1999-07-11 more...
97 - P0505122
Filip S. Bondarenko
2122 Problemista 98-99 09-10/1969
P0505122
(5+8) cooked
h#2
1. Dh8 Le6 2. Lg7 f5#
play all play one stop play next play all
Cook: NL 1. b5 Lxb2 2. h6 Lb1#
Yuri Bilokin: Correction: wKe7-a7, wBa2-b3, wPf2-g5, bSc7-e2, -bPb6, -bPd7 8/K6p/6k1/6Pp/5P2/1B6/1q2n3/b1B5 (5+6) (2021-05-10)
comment
Keywords: Bahnung
Genre: h#
FEN: 8/2npK2p/1p4k1/7p/5P2/8/Bq3P2/b1B5
Input: hpr, 1996-12-26
Last update: Marcin Banaszek, 2023-12-13 more...
98 - P0505129
Filip S. Bondarenko
501 Biuletyn 07/1962
P0505129
(5+9) cooked
h#3
1. Da1 exf5 2. Lb2 e4 3. c3 Ld4#

NL:
1. Ta1 exf5 2. Dd4 exd4 3. Lxd4 Lxd4#
play all play one stop play next play all
Korrekturvorschlag HJS Co+: -sBc4, +sTc5; ersetzt man einfach sBc4 durch sTc4 dann 2. Lösung 1. Dh4+ gxh4 2. Lb2 Lg3 3. Sd4 Le5#
Yuri Bilokin: Correction: bPc4-d6, bPg4-g5, +bSd5, -wPg3 6bk/6bp/3p1q2/3n1np1/4P3/4P3/r4B1K/8 (4+10) 1.Qa1 exf5 2.Bb2 e4 3.Sc3 Bd4# (MM) (2021-05-14)
comment
Keywords: Bahnung
Genre: h#
FEN: 6bk/6bp/5q2/5n2/2p1P1p1/4P1P1/r4B1K/8
Input: hpr, 1996-12-26
Last update: hpr, 1999-07-16 more...
99 - P0505142
Arturs Keirans
566 Deutsche Märchenschachzeitung 12/1932
P0505142
(3+8) cooked
h#3
1. Lg1 Th8 2. Df2+ Kh1 3. Te3 Txa8#

NL:
1. Lg1 Th8 2. De3 Txe8 3. c5 Txa8#
play all play one stop play next play all
Yuri Bilokin: Correction: bPc7-d5, bBb5-c6, +bPb5, +bRc7 n3r3/qnr5/kbb5/Pp1p4/8/8/6K1/7R (3+10) (2021-06-24)
comment
Keywords: Bahnung
Genre: h#
FEN: n3r3/qnp5/kb6/Pb6/8/8/6K1/7R
Input: hpr, 1996-12-26
Last update: hpr, 1999-07-16 more...
100 - P0505229
Filip S. Bondarenko
531 Aj. Art 03-04/1970
P0505229
(3+6) cooked
h#5
1. Kc3 b4 2. Kc4 b5 3. Kc5 bxa6 4. Kc6 Lg6 5. Tc5 Le8#

NL:
1. Kc3 Kd5 2. Kb4 Lc2 3. Ka5 Kc4 4. Ta1 b4#
play all play one stop play next play all
Yuri Bilokin: Correction: +bPe5, +bPe6, +bRg4, +bQh4 8/2p4B/pp1pp3/4p3/4K3/1P4rq/2k5/2r5 (3+10) (2021-05-15)
comment
Keywords: Bahnung
Genre: h#
FEN: 8/2p4B/pp1p4/8/4K3/1P6/2k5/2r5
Input: hpr, 1996-12-26
Last update: hpr, 1999-07-16 more...
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