Die Schwalbe

10 problem(s) found in 2847 milliseconds (displaying 10 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT G='Retro' AND K='En passant als Schlüssel'] [download as LaTeX]

1 - P1020144
Josef Kling
23 The Chess Euclid 1849
P1020144
(6+6)
#2
1. axb6ep+ Kb1 2. 0-0#
1. ... Da7 2. Kf2#
play all play one stop play next play all
in 'Le Pion' fälschlich wBa4 ("1 - R 1 R ... 5 - P 4 TD ...")

Nach heutigen Konventionen ist der Ep-Schlag unzulässig, man beachte aber:
Kling im 'Chess Euclid' zur Intention dieser Aufgabe: "This problem I have compossed expressly to shew the error the modern composers of problems have committed, in introducing the system of castling in the ends of games. In this problem I consider I have as good a reason to say that Black has just moved his Q. Kt. P. [b5] two squares as that White has not moved his K. R. or K."
James Malcom: I found this hidden ancient, another that rode the rails of the unjustified en passant key. (2020-12-28)
SP: Unsound in its own terms, as, whatever Black plays (Kb1/Qa7),
castling is never forced due to 2.Kf2#
I use the keyword "non-analytic en passant key" for such problems. (2023-08-21)
A.Buchanan: The composer's stated intention seems to be that (1) ep is ok (2) castling is not ok. In these terms, the problem is sound (2023-08-22)
comment
Keywords: Brian Stephenson Collection (4985), En passant as key, Castling (wk), En passant, Castling as mating move, Golden Age
Genre: 2#
FEN: R7/7q/7r/Pp6/5p1r/7P/4Q3/k3K2R
Reprints: 458 Dubuque Chess Journal 35 01/1873
P10 Le Pion 01/05/1873
Input: Brian Stephenson, 2004-08-12
Last update: A.Buchanan, 2023-08-22 more...
2 - P1237298
Alain Brobecker
5912 diagrammes 159 10-12/2006
P1237298
(10+6) C+
s#6
b) -wBe6 = s#5
c) -wBc3 = s#4
a) 1. cxb6ep+ Lc5 2. e8=D fxe6 3. Dcxe6+ Ld6 4. Dc4+ Lc5 5. Dg6+ d6 6. Dge6 cxb6#
b) 1. cxb6ep+ Lc5 2. e8=D f6 3. exf6 Kd6 4. e5+ Kc6 5. f7 cxb6#
c) 1. cxb6ep+ Lc5 2. e8=D f6 3. exd7 f5 4. exf5 cxb6#, 3. ... fxe5 4. De7 cxb6#
play all play one stop play next play all
Anton Baumann: C+ Gustav 4.2a (2022-05-20)
comment
Keywords: En passant as key
Genre: s#
FEN: 8/2ppPp2/P1kbP3/KpP1P3/P1Q1P3/2P5/8/8
Input: Frank Müller, 2012-04-22
Last update: Marcin Banaszek, 2022-05-25 more...
3 - P1255845
Bernd Schwarzkopf
13750 Die Schwalbe 231 06/2008
P1255845
(2+3)
#6
Längstzüger
1. cxd6ep! g5 2. d7 Kg7 3. d8=D Kh6 4. Kg4 Kg7 5. Kf5 Kh6 6. Dh8#
play all play one stop play next play all
Anton Baumann: Retro: Unter der Annahme, dass die Längstzügerregel auch für den der Diagrammstellung vorangegangenen Zug gilt, kann der letzte Zug nur d7-d5 gewesen sein! Daher die Lösung:
1.cxd6 e.p.! g5 2.d7 Kg7 3.d8=D Kh6 4.Kg4 Kg7 5.Kf5 Kh6 6.Dh8# (2022-09-14)
comment
Keywords: Maximummer, Kindergarten Problem, Minimal, Miniature, En passant as key
Genre: Fairies
FEN: 7k/6p1/8/2Pp4/8/6K1/8/8
Input: Gerd Wilts, 2012-12-13
Last update: Mario Richter, 2022-09-14 more...
4 - P1260009
Miomir Nedeljkovic
500 Mat Plus 1998
Informalturnier 1998/99
Speziallob
P1260009
(8+5) C+
s#2
1. fxg6ep! e6 2. Dd6 hxg6#
1. ... e5 2. Dxd7 hxg6#
1. ... d6 2. Le6 hxg6#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61
It is obvious that last move was g7-g5 (2022-02-14)
comment
Keywords: En passant as key
Genre: s#
FEN: 6B1/3pp2p/5k1P/3Q1PpK/4R1PP/8/8/8
Input: Frank Müller, 2013-01-18
Last update: Marcin Banaszek, 2022-02-16 more...
5 - P1272046
Gianni Donati
The Ural's Problemist 04-06/2004
2. Thematurnier
1. Preis
P1272046
(15+7)
s#6
1. cxb6ep+ Kxd6 2. d8=T+ Ke5 3. e8=D+ Kxf6 4. gxh8=L+ Kg6 5. f8=S+ Kxh6 6. Dxc6+ Lxc6#
play all play one stop play next play all
Anton Baumann: gemäss Diagramm unlösbar, da als letzter Zug auch c3xTb2 in Frage kommt;
mit letztem Zug b7-b5 geht kurz: 1.cxb6ep+ Kxd6 2.d8=D+ Ke5 3.e8=D+ Lxe8#
Korrektur: es fehlt sBc6(15+8)! So gilt: Mehr als 1 schwarzer Schlag geht nicht, d.h. letzter Zug c3xb2 ist nicht möglich; also letzter Zug eindeutig b7-b5; und die Kurzlösung ist auch eliminiert.
Computerprüfung mit sBc6: C+ Gustav 4.1d (2021-05-21)
comment
Keywords: Allumwandlung (TDLS), En passant as key, konsekutive Umwandlungen 4
Genre: s#
FEN: Q6b/2kPPPP1/B2R1P1N/KpP5/bP6/qP5N/rp6/B7
Input: Frank Müller, 2013-06-08
Last update: Frank Müller, 2013-06-08 more...
6 - P1380523
Nels H. Nelson
760 Los Angeles Times , p. 30, 28/3/1937
"April Fool Joke"
P1380523
(9+5)
#3
1. gxh6ep+! Kxf7 2. 0-0xg1! Sf6 3. e8=sS#!
play all play one stop play next play all
28/3/1937-https://www.newspapers.com/clip/25408700/chess-by-herman-steiner/

"NELS NELSON

We have heretofore published many of Nelson's fine problems and should like to show any readers the more humorous side of his talent. This winter our distinguished friend is spending his vacation in Los Angles. It is with his kind permission that we are publishing this story and problem.

Nels Nelson, born in Denmark in 1871, emigrated to the United States when 12 years of age. He learned the moves of chess in Denmark and began solving and composing problems in 1894. He was chess editor of the Minneapolis State Chess Asccostion, 1911-1912, president of the Minnesota State Chess Asccostion, 19229-1930, and lives at Hopkins, Minn., a suburb of Minneapolis.

AN APRIL FOOL JOKE

A certain celebrated chess master, who we will designate as Mr. "X," while on in the provinces happened into a tavern which was the mecca of the village chess players. Mr. "X," very fond of practical jokes, conceived a plan of springing on one of the unsuspecting natives. Professing ignorance of the game, the champion of the club offered to teach Mr. "X" its intricacies. After showing Mr. "X' all of the moves with the exception of pawn promotion, pawn takes pawn, etc., and castling, the champion said the following: ""I have purposely omitted three of the maneuvers in chess, which to the beginner are somewhat difficult to grasp. They are pawn promotion-when a pawn reaches the eight rank it ceases to be a pawn but may but it may be converted to any piece on the board and assumes its function at once. It is thus theoretically possible to have as many as nine queens on the board at once, and so on down the line." The champion then went to explain the castling on the king and queen side and emphasized the importance of moving the king first. The act of pawn takes pawn "en passant" was then thoroughly explained and the actual game started with the champion giving odds of queen to Mr. "X," who proved to be a very apt pupil! Mr. "X" lost the first game in short order-walking boldly into a mating net. In the second game he gave the champion quite the battle and won the approbation of that was worthy. In the third game, the champion managed to trap Mr. "X's" queen but had to give up two pieces for it and saw that he had a lost game but continued on in the hope that his experienced opponent would make some mistake. When the game has reached the position in the diagram the champion was dumbfounded to hear Mr. "X" announce mate in three moves. "Impossible!" exclaimed the champion. "You should win, of course, but mate in three cant be done." "Well, if you have interpreted the move and rules correctly, I am certain I see a mate in three," said Mr. "X." "Of course I have interpreted the rules correctly, exclaimed the now irate champion: and I will lay you a wager of dinner for the members of the club that you fail to mate in three moves." "Done!" cried Mr. "X." By this time nearly every member in the club was watching the game with interest. Now, who won this wager? It will be shown in the solution April 11."

11/4/1937-https://www.newspapers.com/clip/25408721/chess-by-herman-steiner/

"SOLUTION TO PROBLEM 760 by N. Nelson: "April Fool Joke."

White: K. on K1 R. on Q7, and KR1: Kt. on KB7 and KB8: B, on QB5: P. on K7, KKt5, and KKt2, Black: K. on KKt2: R. on KKt1: Kt. on K1: B. on KKt8: P. on KR4. (Wh. 9: BL. 5.)

Many members of the club were very fine players and felt their champion would win. Curiously, most of them were pulling for Mr. "X," as the champion was somewhat of a braggard and if he won they felt they would be hearing about it for a long time. They were, therefore, keenly alert when Mr. "X" started to proceed the game. "My first move is pawn takes en passant," said the smiling Mr. "x." "Of course, I anticipated that move," replied the champion, "and I shall meet it with king takes knight." Oh well then I shall make for my second move, castle: taking the bishop," continued Mr. "X." "This move is according to your definition of castling, perfectly legitimate, as the king moves first, and the bishop being on the knight square, certainly is subject to capture." "Well," replied the champion, "I must say your interpretation is far fetched, but I will grant you even this point as I fail to see how you mate on the next move: you evidently overlook the fact that when you promote the pawn the king will be able to capture it. Of course, I am forced to interpose my knight and it is pinned, but the king will still be able to take care of that promoted pawn. " Well," smiled Mr. "X," "I shall, however, mate you by pawn to king eight, discovering check, as I shall claim a black knight for the promoted pawn, which, according to your interpretation of pawn promotion, is perfectly legitimate. You stated I might choose any piece on the board and, of course, as the black knight is the only piece that will mate, I naturally selected it."
Exit champion.

We are publishing the best solution sent in my Ladderite L. A. Post, incidentally only two others solved this April Fool Problem.

Problem 760 to complete the tale that Mr. Nelson started to what I believe to be the logical solution according to the rules given by the local champion.
1. White: Pawn takes pawn "en passant" check.
The local champion then captured the white knight reposing on his "bishop two."
1. Black: king takes knight.
"Now," continued Mr. "X" "I understand to quote you, the king moves firstl in castling."
"That is correct," agreed the champion.
Thereupon Mr. "X" executed the move in the prescribed manner by first moving his king to his king knight square and removing the champion's bishop and then setting his rook down on his king bishop square calling check.
The champion was nonplussed, for in stating the rules for "castling" he had failed to forsee a circumstance of this kind. He was forced to admit that, according to his own statement, such a move was possible But seeing in spite of this that it was still impossible to checkmate on the next move, he conceded the point and interposed his knight.
2. Black: Knight to king bishop three.
"Did you not say," resumed Mr. "X," "that in 'pawn promotion' you could reclaim to any piece on the board?"
"That is correct," conceded the champion, "but since you insist on taking me literally I might add that there is no "queen' on the board you may claim in one."
"In that case," stated Mr. "X," "I will be equally generous and present you with a 'knight.'"Whereupon Mr. "X" removed the pawn at king seven and placed a black 'knight' at king eight discovering checkmate to the champion's "king."
"Such a thing is impossible !" cried the outraged champion.
"Not at all," replied Mr. "X," "for according to your statement that "upon reaching the eight rank a pawn be converted to any piece on the board and assumes its function at once.'"
To this the other members agreed. So the champion held a dinner in honor of Mr. "X," the most apt pupil he had ever taught.

Respectfully yours,

L.A. Post
Seaman, First Class, U.S. Navy,
U.S..S Texas, San Pedro, Cal."
Henrik Juel: Some help is needed here, James
At least for me (2020-10-01)
A.Buchanan: Hi Henrik I am guessing it’s a cheatyface Valladao:
1. gxh6ep+ Kxf7 2. 0-0+ Sf6 3. f8=sS#
No proof for the ep, castling with capture and promotion to black officer (2020-10-02)
James Malcom: Bingo Andrew! (2020-10-02)
Henrik Juel: Even though I ought to stand by my fellow danish author:
This is a most crude 'joke' problem, especially the 'castling' with capture (2020-10-02)
A.Buchanan: It's kind of a running gag: three silly jokettes which do combine relatively harmoniously (2020-10-02)
A.Buchanan: 1. ... Kf6 allows a short mate, robbing White of the Valladao. 4nNbn/3RP1kN/8/6Pp/8/8/8/4K1bR is the best I can find, fixing the problem, and with less material (2020-10-02)
A.Buchanan: I was hoping that someone would spot that I have shifted a unit to h7 - i.e. the e.p. is even more Foolish :-) I claim it "improves" the problem because currently the e.p. *might* be legal :-) If this is too crude for some, then 4nNr1/3RP1k1/6N1/4P1Pp/8/8/8/4K1bR works. Note you need sTg8 to prevent 2. Sh8#, but wSg6 is blocking g-file, so wBg2 is still free to find other duties on e5. (2020-10-03)
James Malcom: Excellent improvements, Andrew! (2020-10-06)
A.Buchanan: Thanks James: do you think the one with Sh7 is excessively silly? (2020-10-06)
James Malcom: Yes, 'd say a bit too silly. (2020-10-16)
more ...
comment
Keywords: Joke, Valladao Task, Joke promotion (s), En passant as key, Castling, Checking key, under-promotion (s)
Genre: 3#
FEN: 4nNr1/3RPNk1/8/2B3Pp/8/8/6P1/4K1bR
Reprints: Los Angeles Times , p. 13, 11/4/1937
Input: James Malcom, 2020-10-01
Last update: James Malcom, 2021-02-23 more...
7 - P1380892
Courtnay Lemon
343 American Chess Magazine Volume 2, p. 284, 12/1898
P1380892
(7+6)
#3
1. bxc6ep+! Kc7 2. 0-0-0 Dxb4 3. a8=S#
play all play one stop play next play all
Solution text from the 2/1899 issue: "A clever rendering of this "triple idea." It will be seen that Black cannot play simply 2.R-Q sq on account of 3. Q x Q ch."
zum Autor heißt es im 'ACM': Courtenay Lemon, New York
James Malcom: I found this most excellent early Valladao while ago, but only today did I finally find it again. This is the second one that I've found, i.e. P1380523

Is this the second oldest known Valladao after the 1867 P1360420 found by Keym?

The mainline should be C+, with the "legitimate" ep key, but with many dualed sidelines. (2020-10-14)
Henrik Juel: Something seems missing, James
There is no mate 3... Kc8,Kxc6 (2020-10-14)
Henrik Juel: Adding wSe7 would help (2020-10-14)
James Malcom: Henrik, Mario-many thanks!-has now fixed the position. I had missed the wSe7 when entering! (2020-10-14)
comment
Keywords: Joke (e.p.), En passant as key, Castling, under-promotion in mating move (S), Valladao Task
Genre: 3#
FEN: 1b6/Pk2N3/1q6/1Pp5/1Q6/4p1p1/2P5/R3K3
Input: James Malcom, 2020-10-14
Last update: Mario Richter, 2020-10-14 more...
8 - P1381271
I. I. Lyon
No. 9 American Chess Review Vol. 1, p. 27, 8/1886
P1381271
(6+4)
#2
1. exf6ep! droht 2. Sc6,Se6#
1. ... Sd6,gxf4 2. Se6#
1. ... Sc7,Sxf6,Sg7 2. Sc6#
play all play one stop play next play all
https://books.google.com/books?id=y6uBo98GjoUC
Henrik Juel: The ep key is unjustified (2020-10-24)
more ...
comment
Keywords: En passant, En passant as key, Joke
Genre: 2#
FEN: 3kn3/8/1N6/4PppB/3N1B2/8/3K4/8
Input: James Malcom, 2020-10-24
Last update: A.Buchanan, 2020-10-25 more...
9 - P1395488
Thomas R. Dawson
Tidskrift för Schack 1923
P1395488
(15+9) cooked
#2
1. axb6ep+! Kxe3 2. De2#
play all play one stop play next play all
Cooked by the possibility of e2-e1=S!

https://timkr.home.xs4all.nl/admag/promo.htm Tim Krabbe writes in "PROMOTIEMOTIVATIE": Een van de mooiste uitspraken in de Nederlandse schaakliteratuur werd gedaan door Johan Barendregt (1924-1982), in een interview met Max Pam: 'Mijn leven is bepaald door de zet e2-e1P.'

Hij doelde daarmee op een ontdekking die hij had gedaan in een stelling die in 1937 aan de lezers van het blad De Schaakwereld ter oplossing was voorgelegd. (Zie diagram.)
Het mat op zich was niet moeilijk, dat kon alleen 1.axb6+ Kxe3 2.De2 mat zijn, maar het ging om het bewijs dat alleen b7-b5 Zwarts laatste zet geweest kon zijn, en niet b6-b5 of Kc4-d3. Toen een paar weken later de oplossing werd gepubliceerd, bleek dat de 13-jarige Barendregt alle oplossers de baas was geweest, omdat hij had aangetoond dat het probleem van de grootheid Dawson incorrect was. Met een bewijspartij van 48 zetten liet hij zien dat ook e2-e1P Zwarts laatste zet geweest kon zijn, wat 1.axb6 illegaal maakte. En passant repareerde hij het probleem ook, door de pion van f5 naar e7 te verplaatsen - dàn moet Zwart zojuist b7-b5 gespeeld hebben.
Dat bewijs laat ik hier voor wat het is - het gaat me om de verrukking die Barendregt moet hebben gevoeld toen hem, temidden van de partijen van Euwe, Aljechin en Keres, lof werd toegezwaaid, maar die hij vooral moet hebben gevoeld bij de ontdekking van e2-e1P zèlf. Dat geluksgevoel bond hem voor de rest van zijn leven aan het schaken - hij was jarenlang een van de sterkste Nederlanders, werd Internationaal Meester toen dat nog iets betekende, en won partijen tegen Botwinnik en Portisch.

In English: One of the most beautiful statements in Dutch chess literature was made by Johan Barendregt (1924-1982), in an interview with Max Pam: 'My life is determined by the move e2-e1P.'

He was referring to a discovery he had made in a proposition that had been submitted to the readers of the magazine De Schaakwereld in 1937 for a solution. ( See diagram. )
The mate itself was not difficult, only 1.axb6+ Kxe3 2.De2 ??mate but it was to prove that only b7-b5 could have been Black's last move, and not b6-b5 or Kc4-d3. When the solution was published a few weeks later, it turned out that 13-year-old Barendregt had beaten all the solvers because he had shown that the problem of the great Dawson was incorrect. With a proof game of 48 moves, he showed that e2-e1P could also have been Black's last move, making 1.axb6 illegal. In the meantime, he also solved the problem by moving the pawn from f5 to e7 - then Black must have just played b7-b5.
I will leave that proof for what it is here - I am concerned with the delight that Barendregt must have felt when he was praised among the parties of Euwe, Aljechin and Keres, but which he must have felt above all when he discovered e2-e1P itself. That happiness tied him to playing chess for the rest of his life - for years he was one of the strongest Dutchmen, became an International Master when it still meant something, and won games against Botvinnik and Portisch.
Cook: Possible proof game by James Malcom in 42.0 moves: 1. b4 a5 2. bxa5 g5 3. Lb2 g4 4. Sc3 g3 5. hxg3 Sf6 6. Th6 Se4 7. Sd5 Sc3 8. Tc1 Sb1 9. Ta6 e5 10. Sf6+ Ke7 11. e4 d5 12. c3 d4 13. Tc2 d3 14. Ta7 dxc2 15. Sh3 Sa6 16. d4 c6 17. d5 Sc7 18. La6 Kd6 19. Dd3 Kc5 20. d6 Lh6 21. Ke2 Ld2 22. dxc7 h5 23. Sg5 Dd5 24. exd5 e4 25. a3 e3 26. Kf3 h4 27. De2 Lf5 28. Kf4 Tae8 29. Ta8 h3 30. Tc8 h2 31. d6 h1=T 32. Sd5 Tc1 33. f3 Le4 34. fxe4 b5 35. Dd1 Th4+ 36. Kf5 Tf4+ 37. gxf4 Kc4 38. Sh7 Kd3 39. Kg5 f5 40. Shf6 e2 41. Se3 Te5 42. fxe5 e1=S
means e.p. convention won't fire
Henrik Juel: James, when I played your game I did not reach the diagram position
Is the diagram or your game wrong? (2021-11-06)
James Malcom: Gahhhhh, I got myself again Henrik. I garbled some pawns, which should be fixed now. (2021-11-06)
Henrik Juel: Thanks
The intended retroplay was
R: 1... b7-b5! 2.Sc4-d3+ Ke3-d3+ 3.Sb6-c4+ d3xTc2 (2021-11-07)
Henrik Juel: The cooking last move e2-e1=S is rather obvious
I would have thought that it was found by the TfS solvers and corrected by TRD
Can anyone check in TfS 1923-24? (2021-11-07)
Henrik Juel: Never mind...
The problem appeared in October 1923, and there is no mention of e2-e1=S in the solution in the March 1924 issue (2021-11-07)
comment
Keywords: En passant as key, Superseded by (P1395505)
Computer test: Popeye v4.87 & simple retro-logic & demonstrative proof game
FEN: 2R5/2P5/B1pP1N2/Pp2PpK1/4P3/P1PkN3/1Bpb2P1/1nrQn3
Reprints: De Schaakwereld 1937
Tim Krabbé's Website 2001
MatPlus.net Forum 2021
Input: James Malcom, 2021-11-06
Last update: A.Buchanan, 2021-11-07 more...
10 - P1410414
O. Kirnberger
17 Grafinger Zeitung 03/07/1932
P1410414
(7+8)
#4
1. gxh6ep+! Kf7 2. 0-0+ Df4 3. Txf4+ Ke6 4. Tf6#
3. ... Kg8 4. Sdf6#
Co-Dual 2. Tf1+ Df4 3. Txf4+ Ke6 4. Tf6#
3. ... Kg8 4. Sdf6#
play all play one stop play next play all
Originaldiagramm war verdruckt, Korrektur 17.07.1932

'Grafinger Zeitung': "... eine Aufgabe aus unserm Leserkreise, die sich Schachgebote zum Motto wählte.
Jägerlatein.
Der Bauer auf dem fünften Feld,
Das ist in diesem Kampf der Held!"

Der ep-Schlüssel ist retroanalytisch nicht begründbar.
Henrik Juel: So the problem is incorrect, I think (2023-06-18)
comment
Keywords: En passant as key
Genre: n#
FEN: rq2bb1n/6k1/2P3p1/3N2Pp/6N1/1B6/8/4K2R
Input: Mario Richter, 2023-06-18
Last update: Mario Richter, 2023-06-18 more...
Show statistic for complete result. Show search result faster by using ids.

https://pdb.dieschwalbe.de/search.jsp?expression=COMMENTDATE%3E%3D20200919+AND+NOT+K%3D%27Hilfsr%C3%BCckz%C3%BCger%27+AND+NOT+G%3D%27Retro%27+AND+K%3D%27En+passant+als+Schl%C3%BCssel%27

The problems of this query have been registered by the following contributors:

Brian Stephenson (1)
Frank Müller (3)
Gerd Wilts (1)
James Malcom (4)
Mario Richter (1)