24 problem(s) found in 3611 milliseconds (displaying 24 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT G='h#' AND S='Best Problems'] [download as LaTeX]
1 - P0002321
Samuel Loyd
Le Sphinx 1866
(16+16)
Welches ist die kürzeste Partie, die mit Patt endet?
Samuel Loyd
Le Sphinx 1866
(16+16)
Welches ist die kürzeste Partie, die mit Patt endet?
1. e3 a5 2. Dh5 Ta6 3. Dxa5 h5 4. Dxc7 Tah6 5. h4 f6 6. Dxd7+ Kf7 7. Dxb7 Dd3 8. Dxb8 Dh7 9. Dxc8 Kg6 10. De6= pat
Keywords: Construction task, Non-Unique Proof Game, Homebase
Genre: Retro
FEN: rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR
Reprints: The American Chess Journal , p. 18, 15/06/1876
335 Chess Strategy (Loyd) , p. 174, 1878
Ruy Lopez 3 03/1897
61-IV Sam Loyd and his Chess Problems , p. 58, 1913
61/IV Sam Loyd und seine Schachaufgaben 1926
132 Ultimate Themes 1938
6-5 De Waag 03/10/1941
R424 feenschach 21 04/1974
162 Shortest Proof Games 11/1991
Best Problems 45 2008
idee & form 159, p. 5395, 07/2023
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-08-09 more...
Genre: Retro
FEN: rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR
Reprints: The American Chess Journal , p. 18, 15/06/1876
335 Chess Strategy (Loyd) , p. 174, 1878
Ruy Lopez 3 03/1897
61-IV Sam Loyd and his Chess Problems , p. 58, 1913
61/IV Sam Loyd und seine Schachaufgaben 1926
132 Ultimate Themes 1938
6-5 De Waag 03/10/1941
R424 feenschach 21 04/1974
162 Shortest Proof Games 11/1991
Best Problems 45 2008
idee & form 159, p. 5395, 07/2023
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-08-09 more...
1. h4 f5 2. Th3 f4 3. Tb3 f3 4. Tb6 axb6 5. h5 Ta3 6. h6 Td3 7. a4 gxh6 8. a5 bxa5 9. Ta4 b6 10. Td4 Lb7 11. Td6 exd6 12. e3 Se7 13. De2 Sc8 14. Kd1 Le7 15. De1 0-0 16. Le2 Kh8 17. Df1 fxe2+ 18. Ke1 Tf3 19. Sa3 Th3 20. g3 Lh1 21. Dg2 Dg8 22. Dc6 Db3 23. cxb3 Ld8 24. Dc2 c6 25. Dd1 Lc7
7zügiges Tempoverlustmanöver der wD, die kompliziert auf dem Königsflügel freigeschleust werden muss.
7zügiges Tempoverlustmanöver der wD, die kompliziert auf dem Königsflügel freigeschleust werden muss.
Keywords: Unique Proof Game, Tempo Loss, Pure Round Trip (D), Switchback (K), Castling
Genre: Retro
Computer test: Stelvio 1.0
FEN: 1nn4k/2bp3p/1ppp3p/p7/8/NP1rP1Pr/1P1PpP2/2BQK1Nb
Reprints: Best Problems 47 07/2008
Input: Gerd Wilts, 2002-04-05
Last update: A.Buchanan, 2023-05-14 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: 1nn4k/2bp3p/1ppp3p/p7/8/NP1rP1Pr/1P1PpP2/2BQK1Nb
Reprints: Best Problems 47 07/2008
Input: Gerd Wilts, 2002-04-05
Last update: A.Buchanan, 2023-05-14 more...
1. d4 e5 2. Lh6 Dh4 3. Dd2 g5 4. Da5 Lxh6 5. Sc3 Kf8 6. 0-0-0 g4+ 7. f4 gxf3ep+ 8. Td2 fxe2 9. Sf3 e1=L 10. Kd1 Lg3 11. Tf2 Lc1 12. Ld3 h6 13. Lh7 e4 14. Ke1
paul: Theme Valladao (2013-09-12)
James Malcom: An excellent Valladao with a castling paradox and Anti-Pronkin! (2021-01-23)
A.Buchanan: Normally, castling paradox would employ *both* K&R heading back home after the dalliance. There's non-standard material which to me seems a defect in a Valladao. No-one here was able to agree on what Anti-Pronkin is, so the term has been retired. I guess it covers everything which is not a Pronkin: from Allumwandlung to Zilahi :-) (2021-05-19)
Michel Caillaud: Anti-Pronkin (from FIDE Album "Theme definitions") :
A promoted piece is captured. The corresponding piece of the same colour from the game-array moves onto the promotion-square.
So 1) it doesn't cover everything which is not a Pronkin 2) it is not present in this problem (2021-05-21)
A.Buchanan: I was confusing the term with "Anti-Phoenix" oops.
As Michel says, this problem does *not* show Anti-Pronkin as per Michel's FIDE definition. The promoted piece is never captured.
The "Pronkin" theme in the V&V Encyclopaedia wisely does not requires that the original unit is captured. There has to be some credit for a unit reaching a thematic target square at all, irrespective of the fate of the unit. In the current problem, we could still imagine a Prenix after Lc1 for example to regularize the material: why couldn't that still class as Anti-Pronkin?
Unit quests & regularization of material should be keyworded separately. And there should be a proper symmetry between Pronkin & Anti-Pronkin themes, imho. (2021-07-31)
more ...
comment
James Malcom: An excellent Valladao with a castling paradox and Anti-Pronkin! (2021-01-23)
A.Buchanan: Normally, castling paradox would employ *both* K&R heading back home after the dalliance. There's non-standard material which to me seems a defect in a Valladao. No-one here was able to agree on what Anti-Pronkin is, so the term has been retired. I guess it covers everything which is not a Pronkin: from Allumwandlung to Zilahi :-) (2021-05-19)
Michel Caillaud: Anti-Pronkin (from FIDE Album "Theme definitions") :
A promoted piece is captured. The corresponding piece of the same colour from the game-array moves onto the promotion-square.
So 1) it doesn't cover everything which is not a Pronkin 2) it is not present in this problem (2021-05-21)
A.Buchanan: I was confusing the term with "Anti-Phoenix" oops.
As Michel says, this problem does *not* show Anti-Pronkin as per Michel's FIDE definition. The promoted piece is never captured.
The "Pronkin" theme in the V&V Encyclopaedia wisely does not requires that the original unit is captured. There has to be some credit for a unit reaching a thematic target square at all, irrespective of the fate of the unit. In the current problem, we could still imagine a Prenix after Lc1 for example to regularize the material: why couldn't that still class as Anti-Pronkin?
Unit quests & regularization of material should be keyworded separately. And there should be a proper symmetry between Pronkin & Anti-Pronkin themes, imho. (2021-07-31)
more ...
comment
Keywords: Unique Proof Game, Valladao Task (slwwg), En passant, Promotion (l), Castling, Non-standard material (l)
Genre: Retro
FEN: rnb2knr/pppp1p1B/7p/Q7/3Pp2q/2N2Nb1/PPP2RPP/2b1K2R
Input: Gerd Wilts, 2010-06-04
Last update: A.Buchanan, 2021-07-31 more...
Genre: Retro
FEN: rnb2knr/pppp1p1B/7p/Q7/3Pp2q/2N2Nb1/PPP2RPP/2b1K2R
Input: Gerd Wilts, 2010-06-04
Last update: A.Buchanan, 2021-07-31 more...
4 - P1114202
Zoltan Laborczi
György Bakcsi
2402 Best Problems 01/2010
Informalturnier 2010/11
2. ehrende Erwähnung
(5+7)
s#16
Ultraschachzwang
Zoltan Laborczi
György Bakcsi
2402 Best Problems 01/2010
Informalturnier 2010/11
2. ehrende Erwähnung
(5+7)
s#16
Ultraschachzwang
1. Kb2 d1=S+ 2. Ka2 Sc3+ 3. Kb3 a4+ 4. Kxc3 exd4+ 5. Kxd4 c5+ 6. Ke4 d5+ 7. Kd3 dxc4+ 8. Kxc4 b5 9. Kd3 c4+ 10. Kd2 c3+ 11. Kd1 c2+ 12. Ke2 c1=S+ 13. Kd2 Sb3+ 14. Kc3 b4+ 15. Kb2 a3+ 16. Ka2 Sc1#
Ultraschachzwang = Schachzwang (?)
Ultraschachzwang = Schachzwang (?)
SCHRECKE: C+, popeye 4.87 (2022-05-06)
Henrik Juel: The Märchenschachlexicon is not absolutely clear, but it seems that
Schachzwang: Black must check, if he can
Ultraschachzwang: Black must check
so these conditions are different (2022-05-06)
comment
Henrik Juel: The Märchenschachlexicon is not absolutely clear, but it seems that
Schachzwang: Black must check, if he can
Ultraschachzwang: Black must check
so these conditions are different (2022-05-06)
comment
Keywords: Pure Round Trip (K), Black check, Ultraschachzwang
Genre: Fairies
FEN: 4k3/1ppp4/8/p3p3/2PP4/8/K2p4/BN6
Input: Frank Müller, 2010-09-01
Last update: Frank Müller, 2012-06-27 more...
Genre: Fairies
FEN: 4k3/1ppp4/8/p3p3/2PP4/8/K2p4/BN6
Input: Frank Müller, 2010-09-01
Last update: Frank Müller, 2012-06-27 more...
a) 1. Lb3;
b) 1. Sd8
b) 1. Sd8
B12D
SCHRECKE: a)+b): C+, popeye 4.85
a) 1.Lb3! d3/d5 2.Df2/Da3#
b) 1.Sd8! d3/d5 2.Se6/Sb7# (2021-01-08)
comment
SCHRECKE: a)+b): C+, popeye 4.85
a) 1.Lb3! d3/d5 2.Df2/Da3#
b) 1.Sd8! d3/d5 2.Se6/Sb7# (2021-01-08)
comment
Keywords: Miniature Collection (0320502), Multiple publication
Genre: 2#
FEN: 8/8/2pp4/K1k5/3p4/8/Q7/3B4
Reprints: 2517 Best Problems 56, p. 362, 10/2010
Input: Felber, Volker, 2010-09-11
Last update: Felber, Volker, 2021-01-08 more...
Genre: 2#
FEN: 8/8/2pp4/K1k5/3p4/8/Q7/3B4
Reprints: 2517 Best Problems 56, p. 362, 10/2010
Input: Felber, Volker, 2010-09-11
Last update: Felber, Volker, 2021-01-08 more...
R: 1. Bb7xTa8=T (zuvor) 1. ... Ta1-a8
Mario Richter: Reprinted in 'Best Problems' in the announcement of "Marco Bonavoglia Memorial Tournament" (s. http://www.bestproblems.it/bppdf/BP105.pdf bzw. http://www.bestproblems.it/bppdf/Marco%20Bonavoglia%20MT%20-%20Announcement.pdf) (2022-12-30)
Ladislav Packa: Why not 1.Ra1-a8? Because in that case black's last move is missing. Richer content than it seems at first sight. (2022-12-31)
comment
Ladislav Packa: Why not 1.Ra1-a8? Because in that case black's last move is missing. Richer content than it seems at first sight. (2022-12-31)
comment
Keywords: Last Move?, Sentinels, Aristocrat, Minimal, Miniature
Genre: Fairies
FEN: Rb6/8/8/8/8/2K2k2/8/8
Reprints: Best Problems 105, p. 589, 01/2023
Input: Hans Gruber, 2011-10-09
Last update: Mario Richter, 2022-12-30 more...
Genre: Fairies
FEN: Rb6/8/8/8/8/2K2k2/8/8
Reprints: Best Problems 105, p. 589, 01/2023
Input: Hans Gruber, 2011-10-09
Last update: Mario Richter, 2022-12-30 more...
SCHRECKE: C+, popeye 4.87
1. Kc8 2. Kb8 3. Ka7 4. Ka6 5. Kb5 6. Kc4 7. Kd3 8. Kxe2 9. Kd3 10. Kc4 11. Kb5 12. Ka6 13. Ka7 14. Kb8 15. Kc8 16. Kd8 17. Kxe8 18. Kd8 19. Kc8 20. Kb8 21. Ka7 22. Ka6 23. Kb5 24. Kc4 25. Kd3 26. Ke2 27. Kf2 28. Kg3 29. Kh4 30. Kh5 31. Kxg6 32. Kh5 33. Kh4 34. Kg3 35. Kf2 36. Ke2 37. Kd3 38. Kc4 39. Kb5 40. Ka6 41. Ka7 42. Kb8 43. Kc8 44. Kd8 45. Ke8 46. Kf8 47. Kxg8 48. Kf8 49. Ke8 50. Kd8 51. Kc8 52. Kb8 53. Ka7 54. Ka6 55. Kb5 56. Kc4 57. Kd3 58. Ke2 59. Kf2 60. Kg3 61. Kh4 62. Kh5 63. Kg6 64. Kxf6 65. Kg7 66. Kh8 67. h5 68. h4 69. h3 70. h2 71. h1=L 72. Lxf3 73. Ld5 74. Lg8 Lb2# (2023-09-20)
comment
1. Kc8 2. Kb8 3. Ka7 4. Ka6 5. Kb5 6. Kc4 7. Kd3 8. Kxe2 9. Kd3 10. Kc4 11. Kb5 12. Ka6 13. Ka7 14. Kb8 15. Kc8 16. Kd8 17. Kxe8 18. Kd8 19. Kc8 20. Kb8 21. Ka7 22. Ka6 23. Kb5 24. Kc4 25. Kd3 26. Ke2 27. Kf2 28. Kg3 29. Kh4 30. Kh5 31. Kxg6 32. Kh5 33. Kh4 34. Kg3 35. Kf2 36. Ke2 37. Kd3 38. Kc4 39. Kb5 40. Ka6 41. Ka7 42. Kb8 43. Kc8 44. Kd8 45. Ke8 46. Kf8 47. Kxg8 48. Kf8 49. Ke8 50. Kd8 51. Kc8 52. Kb8 53. Ka7 54. Ka6 55. Kb5 56. Kc4 57. Kd3 58. Ke2 59. Kf2 60. Kg3 61. Kh4 62. Kh5 63. Kg6 64. Kxf6 65. Kg7 66. Kh8 67. h5 68. h4 69. h3 70. h2 71. h1=L 72. Lxf3 73. Ld5 74. Lg8 Lb2# (2023-09-20)
comment
Keywords: Alphabetic Chess, Seriesmover
Genre: Fairies
FEN: 3kB1N1/7p/2PK1PR1/2P3N1/8/5P2/4R3/2B5
Input: Frank Müller, 2012-10-04
Last update: Frank Müller, 2012-10-04 more...
Genre: Fairies
FEN: 3kB1N1/7p/2PK1PR1/2P3N1/8/5P2/4R3/2B5
Input: Frank Müller, 2012-10-04
Last update: Frank Müller, 2012-10-04 more...
8 - P1288722
Arnold Beine
Best Problems 2005
3. Preis
L. Vitale Memorial
(3+11)
h#19
Doppellängstzüger
Arnold Beine
Best Problems 2005
3. Preis
L. Vitale Memorial
(3+11)
h#19
Doppellängstzüger
1. a5 d4 2. c5 dxc6ep 3. Db6 cxb7 4. Dh6 bxc8=S 5. Dc1+ Ka2 6. Dh6 Sd6+ 7. Dxd6 Kb1 8. Dh2 Ka1 9. Db8 d5 10. Dh2 d6 11. Da2+ Kxa2 12. 0-0-0 dxe7 13. d5 Kb3 14. Td6 Ka4 15. Th6 Kb5 16. Ta6 Kxa6 17. g5 Kb5 18. Lh6 Kc6 19. Lf8 exf8=D,T (UW-Dual)
Keywords: Valladao Task, En passant, Castling, Maximummer (Doppel-)
Genre: Fairies
FEN: r1bqkb2/ppppp1p1/8/3P4/8/8/3P4/K7
Reprints: A4387 Phénix (178), p. 7731, 11/2008
Input: Erich Bartel, 2014-09-30
Last update: Alfred Pfeiffer, 2014-09-30 more...
Genre: Fairies
FEN: r1bqkb2/ppppp1p1/8/3P4/8/8/3P4/K7
Reprints: A4387 Phénix (178), p. 7731, 11/2008
Input: Erich Bartel, 2014-09-30
Last update: Alfred Pfeiffer, 2014-09-30 more...
9 - P1291761
Ralf Chris Handloser
3160 Best Problems 69 01/2014
1. Preis
JT Rodolfo Riva 60
2012-2013
(9+10) C+
#2*
Ralf Chris Handloser
3160 Best Problems 69 01/2014
1. Preis
JT Rodolfo Riva 60
2012-2013
(9+10) C+
#2*
* 1. ... Lc1 2. Sc3#,Tdxd4#
* 1. ... Tf8 2. Dxc5#,Db7#
1. Sg2? droht 2. Sxf4#
1. ... Lc1 2. Tdxd4#
1. ... Tf8 2. Db7#
1. ... Sxd6!
1. Sd3! droht 2. Sxf4#
1. ... Lc1 2. Sc3#
1. ... Tf8 2. Dxc5#
1. ... Sxb5 2. Lxe4#
* 1. ... Tf8 2. Dxc5#,Db7#
1. Sg2? droht 2. Sxf4#
1. ... Lc1 2. Tdxd4#
1. ... Tf8 2. Db7#
1. ... Sxd6!
1. Sd3! droht 2. Sxf4#
1. ... Lc1 2. Sc3#
1. ... Tf8 2. Dxc5#
1. ... Sxb5 2. Lxe4#
Keywords: Ellerman-Mäkihovi
Genre: 2#
Computer test: C+ Popeye 4.61
FEN: 2r5/6p1/3Bp1K1/1QpkP3/rR1nnp2/8/1b6/1N1RN2B
Reprints: 7 idee & form 124, p. 4167, 10/2014
Input: Felber, Volker, 2014-11-30
Last update: A.Buchanan, 2021-04-07 more...
Genre: 2#
Computer test: C+ Popeye 4.61
FEN: 2r5/6p1/3Bp1K1/1QpkP3/rR1nnp2/8/1b6/1N1RN2B
Reprints: 7 idee & form 124, p. 4167, 10/2014
Input: Felber, Volker, 2014-11-30
Last update: A.Buchanan, 2021-04-07 more...
10 - P1344219
Marco Travasoni
594 Best Problems 01-03/2002
Informalturnier 1996-2002
3. Lob
(5+6) C+
s#11
Marco Travasoni
594 Best Problems 01-03/2002
Informalturnier 1996-2002
3. Lob
(5+6) C+
s#11
1. Lg3+ Kg1 2. Dh2+ Kf1 3. Dh1+ Ke2 4. Tb2+ Ke3 5. De1+ Kd4 6. Tb4+ Kc5 7. Dc3+ Kb6 8. Lxd3+ Ka5 9. Tb2+ Ka4 10. Lc2+ Lxc2 11. Da3+ Txa3#
Genre: s#
Computer test: Gustav 4.1d
FEN: 8/p7/8/1B1p4/1R2b3/3p1r1Q/K6B/7k
Input: Frank Müller, 2017-12-10
Last update: Marcin Banaszek, 2021-01-31 more...
1. Td2? (Z) d5? 2. Td3 d4 3. E4g2 hxg2#, aber 1. ... d6!
1. Td4! (Z) d6 2. Te3 d5 3. E8g2 hxg2#
1. ... d5 2. Td3 d4 3. E4g2 hxg2#
1. Td4! (Z) d6 2. Te3 d5 3. E8g2 hxg2#
1. ... d5 2. Td3 d4 3. E4g2 hxg2#
Keywords: Pawn mate, Corner mate, Model mate, Pawn step variations
Pieces: = Equihopper (E)
Genre: Fairies
Computer test: Popeye Windows-64Bit v4.75 (1024 MB)
FEN: *1Q3R3/3p4/3R4/8/*1Q7/7p/5p1P/5k1K
Input: Gunter Jordan, 2018-04-12
Last update: James Malcom, 2020-09-28 more...
Pieces: = Equihopper (E)
Genre: Fairies
Computer test: Popeye Windows-64Bit v4.75 (1024 MB)
FEN: *1Q3R3/3p4/3R4/8/*1Q7/7p/5p1P/5k1K
Input: Gunter Jordan, 2018-04-12
Last update: James Malcom, 2020-09-28 more...
a) 1. Th8+! Kxh8 2. Txh3+ Kg8 3. Th8+ Kxh8 4. Txh2+ Kg8 5. Th8+ Kxh8 6. Th1+ Kg8 7. Th8+ Kxh8 8. Th1+ Kg8 9. Th8+ Kxh8 10. Th1+ Kg8 11. Th8+ Kxh8 12. Th1+ Kg8 13. Th8+ Kxh8 14. Th1+ Kg8 15. Th8+ Kxh8 16. Th1+ Kg8 17. Th8+ Kxh8 18. Dh1+ Kg8 19. Dh7+ Kf8 20. Dh8+ Ke7 21. Dxg7+ Kd6,Kd8 22. Dc7#
b) 1. Th8+! Kxh8 2. Txh3+ Kg8 3. Th8+ Kxh8 4. Txh2+ Kg8 5. Th8+ Kxh8 6. Th1+ Kg8 7. Th8+ Kxh8 8. Th1+ Kg8 9. Th8+ Kxh8 10. Th1+ Kg8 11. Th8+ Kxh8 12. Th1+ Kg8 13. Th8+ Kxh8 14. Th1+ Kg8 15. Th8+ Kxh8 16. Th1+ Kg8 17. Th8+ Kxh8 18. Dh1+ Kg8 19. Dh7+ Kf8 20. Dh8+ Ke7 21. Dxg7+ Kd6,Kd8 22. Dc7+ Lxc7#
http://www.bestproblems.it/bppdf/BP2019(complete).pdf
"... details are everything ..."
b) 1. Th8+! Kxh8 2. Txh3+ Kg8 3. Th8+ Kxh8 4. Txh2+ Kg8 5. Th8+ Kxh8 6. Th1+ Kg8 7. Th8+ Kxh8 8. Th1+ Kg8 9. Th8+ Kxh8 10. Th1+ Kg8 11. Th8+ Kxh8 12. Th1+ Kg8 13. Th8+ Kxh8 14. Th1+ Kg8 15. Th8+ Kxh8 16. Th1+ Kg8 17. Th8+ Kxh8 18. Dh1+ Kg8 19. Dh7+ Kf8 20. Dh8+ Ke7 21. Dxg7+ Kd6,Kd8 22. Dc7+ Lxc7#
http://www.bestproblems.it/bppdf/BP2019(complete).pdf
"... details are everything ..."
Henrik Juel: Popeye 4.61 with 'opt thr 0' found no flaws in part a (2020-11-12)
Henrik Juel: ... and with 'opt thr 0 non 0 1' no flaws in part b (2020-11-12)
comment
Henrik Juel: ... and with 'opt thr 0 non 0 1' no flaws in part b (2020-11-12)
comment
Keywords: Task (Construction), Non-standard material, Räumung and Bahnung, Checking key
Genre: n#
FEN: q3r1k1/6p1/1K2p1P1/3rp3/7R/b4pRn/5R1p/QRRRRRR1
Input: James Malcom, 2020-11-12
Last update: Rainer Staudte, 2020-11-12 more...
Genre: n#
FEN: q3r1k1/6p1/1K2p1P1/3rp3/7R/b4pRn/5R1p/QRRRRRR1
Input: James Malcom, 2020-11-12
Last update: Rainer Staudte, 2020-11-12 more...
1. c4 d5 2. Db3 Lh3 3. gxh3 f5 4. Dxb7 Kf7 5. Dxa7 Kg6 6. f3 c5 7. Dxe7 Txa2 8. Kf2 Txb2 9. Dxg7+ Kh5 10. Dxg8 Txb1 11. Txb1 Kh4 12. Dxh8 h5 13. Dh6 Lxh6 14. Txb8 Le3+ 15. dxe3 Dxb8 16. Kg2 Df4 17. exf4 d4 18. Le3 dxe3=
Record for the shortest possible double-stalemate
https://timkr.home.xs4all.nl/chess2/diary19txt.htm
Record for the shortest possible double-stalemate
https://timkr.home.xs4all.nl/chess2/diary19txt.htm
Quelle: L'Unita, s. http://cerca.unita.it/ARCHIVE/xml/240000/235026.xml (14.05.2022: toter Link)
Alternativ: https://archivio.unita.news/assets/main/2007/08/14/page_019.pdf (14.05.2022 geprüft)
In 'L'Unita' ohne konkrete Forderung als Ergebnis einer Rekordkonstruktion mit dem Ziel "Doppelpatt in möglichst wenigen Zügen" veröffentlicht.
Henrik Juel: This non-unique proof game is probably the shortest to reach the diagram position (2020-11-17)
Mario Richter: For a detailed history of the hunt for the shortest PG see Enzo's interesting article "Nuovo record nello stallo reciproco" in 'Best Problems" Nr. 44 (issue 04/2007).
Btw., most sources call this a "double-stalemate" (not "mutual") ... (2020-11-18)
Mario Richter: s. http://www.bestproblems.it/bppdf/BP044.pdf (2020-11-18)
A.Buchanan: That is probably very difficult to find and unlikely that many unique proof games can exist of that form (2020-11-19)
James Malcom: I'm unaware of any unique PGS that end in a mutual stalemate, but surely it must be possible, who the genius may be. (2020-11-19)
A.Buchanan: We’re missing some keywords for stalemate and mutual stalemate objectives. Also what are construction task and record and what’s the difference? (2020-11-19)
Henrik Juel: Euclide 1.01 found no solutions in 17.5 moves (30 hours), so it is extremely likely that all shortest proof games last 18.0 moves (2020-12-01)
comment
Alternativ: https://archivio.unita.news/assets/main/2007/08/14/page_019.pdf (14.05.2022 geprüft)
In 'L'Unita' ohne konkrete Forderung als Ergebnis einer Rekordkonstruktion mit dem Ziel "Doppelpatt in möglichst wenigen Zügen" veröffentlicht.
Henrik Juel: This non-unique proof game is probably the shortest to reach the diagram position (2020-11-17)
Mario Richter: For a detailed history of the hunt for the shortest PG see Enzo's interesting article "Nuovo record nello stallo reciproco" in 'Best Problems" Nr. 44 (issue 04/2007).
Btw., most sources call this a "double-stalemate" (not "mutual") ... (2020-11-18)
Mario Richter: s. http://www.bestproblems.it/bppdf/BP044.pdf (2020-11-18)
A.Buchanan: That is probably very difficult to find and unlikely that many unique proof games can exist of that form (2020-11-19)
James Malcom: I'm unaware of any unique PGS that end in a mutual stalemate, but surely it must be possible, who the genius may be. (2020-11-19)
A.Buchanan: We’re missing some keywords for stalemate and mutual stalemate objectives. Also what are construction task and record and what’s the difference? (2020-11-19)
Henrik Juel: Euclide 1.01 found no solutions in 17.5 moves (30 hours), so it is extremely likely that all shortest proof games last 18.0 moves (2020-12-01)
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Keywords: Construction task, Construction record, Non-Unique Proof Game
Genre: Retro
FEN: 8/8/8/2p2p1p/2P2P1k/4pP1P/4P1KP/5BNR
Reprints: 5 Best Problems 44, p. 95, 2007
61 Tim Krabbé's Website 16/08/2007
Input: James Malcom, 2020-11-17
Last update: Mario Richter, 2022-05-14 more...
Genre: Retro
FEN: 8/8/8/2p2p1p/2P2P1k/4pP1P/4P1KP/5BNR
Reprints: 5 Best Problems 44, p. 95, 2007
61 Tim Krabbé's Website 16/08/2007
Input: James Malcom, 2020-11-17
Last update: Mario Richter, 2022-05-14 more...
AL: 1. e4 d5 2. e5 d4 3. c3 f6 4. Df3 Kf7 5. Dxb7 Dd5 6. Kd1 Dxg2 7. Kc2 Dxf1 8. Dxc8 Dxg1 9. Dxb8 Txb8 10. Txg1 Tb3 11. Tg6 Ta3 12. Th6 gxh6 13. bxa3 Kg7 14. Kb2 d3 15. e6 a5 16. h4 a4 17. h5 c5 18. f4 c4 19. f5==
faster solution (Henrik Juel): 1. c3 a5 2. e4 a4 3. Dg4 Ta5 4. Kd1 b5 5. Lc4 d5 6. Dxc8 bxc4 7. Dxc7 f6 8. Dxb8 Dxb8 9. Kc2 Dxh2 10. f4 Dxg1 11. g4 Dc5 12. Th6 Da3 13. bxa3 d4 14. Kb2 Th5 15.
e5 d3 16. f5 Kf7 17. gxh5 gxh6 18. e6+ Kg7==
The fastest known symmetrical, mutual stalemate
faster solution (Henrik Juel): 1. c3 a5 2. e4 a4 3. Dg4 Ta5 4. Kd1 b5 5. Lc4 d5 6. Dxc8 bxc4 7. Dxc7 f6 8. Dxb8 Dxb8 9. Kc2 Dxh2 10. f4 Dxg1 11. g4 Dc5 12. Th6 Da3 13. bxa3 d4 14. Kb2 Th5 15.
e5 d3 16. f5 Kf7 17. gxh5 gxh6 18. e6+ Kg7==
The fastest known symmetrical, mutual stalemate
Henrik Juel: The position can be reached in 18.0 moves, e.g.
1. Bc2-c3 Ba7-a5 2. Be2-e4 Ba5-a4 3. Dd1-g4 Ta8-a5
4. Ke1-d1 Bb7-b5 5. Lf1-c4 Bd7-d5 6. Dg4xc8 Bb5xc4
7. Dc8xc7 Bf7-f6 8. Dc7xb8 Dd8xb8 9. Kd1-c2 Db8xh2
10. Bf2-f4 Dh2xg1 11. Bg2-g4 Dg1-c5 12. Th1-h6 Dc5-a3
13. Bb2xa3 Bd5-d4 14. Kc2-b2 Ta5-h5 15. Be4-e5 Bd4-d3
16. Bf4-f5 Ke8-f7 17. Bg4xh5 Bg7xh6 18. Be5-e6 Kf7-g7 (2020-11-29)
Henrik Juel: ... but not in 17.5 moves, according to Euclide 1.01 (2020-11-29)
James Malcom: In other notatiom: 1. c3 a5 2. e4 a4 3. Qg4 Ra5 4. Kd1 b5 5. Bc4 d5 6. Qxc8 bxc4 7. Qxc7 f6 8. Qxb8
Qxb8 9. Kc2 Qxh2 10. f4 Qxg1 11. g4 Qc5 12. Rh6 Qa3 13. bxa3 d4 14. Kb2 Rh5 15.
e5 d3 16. f5 Kf7 17. gxh5 gxh6 18. e6+ Kg7
And by crikey! This is big news! This means that Gik actually had the record all along, and Minerva only tied it with his P1382027! (2020-11-29)
Henrik Juel: Gik's position is the record, but neither he nor Minerva knew this (2020-11-30)
James Malcom: This is an exciting development in the story of the mutual stalemate! (2020-11-30)
A.Buchanan: They will have to change the "Mr Robot" TV series: https://www.ozproblems.com/walkabout/walkabout2021/feb27 (2021-02-28)
A.Buchanan: Flipping left-right is again achievable in 18.0 not 17.5 - not entirely unexpected, as bK has further to walk, but was worth checking (2021-02-28)
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1. Bc2-c3 Ba7-a5 2. Be2-e4 Ba5-a4 3. Dd1-g4 Ta8-a5
4. Ke1-d1 Bb7-b5 5. Lf1-c4 Bd7-d5 6. Dg4xc8 Bb5xc4
7. Dc8xc7 Bf7-f6 8. Dc7xb8 Dd8xb8 9. Kd1-c2 Db8xh2
10. Bf2-f4 Dh2xg1 11. Bg2-g4 Dg1-c5 12. Th1-h6 Dc5-a3
13. Bb2xa3 Bd5-d4 14. Kc2-b2 Ta5-h5 15. Be4-e5 Bd4-d3
16. Bf4-f5 Ke8-f7 17. Bg4xh5 Bg7xh6 18. Be5-e6 Kf7-g7 (2020-11-29)
Henrik Juel: ... but not in 17.5 moves, according to Euclide 1.01 (2020-11-29)
James Malcom: In other notatiom: 1. c3 a5 2. e4 a4 3. Qg4 Ra5 4. Kd1 b5 5. Bc4 d5 6. Qxc8 bxc4 7. Qxc7 f6 8. Qxb8
Qxb8 9. Kc2 Qxh2 10. f4 Qxg1 11. g4 Qc5 12. Rh6 Qa3 13. bxa3 d4 14. Kb2 Rh5 15.
e5 d3 16. f5 Kf7 17. gxh5 gxh6 18. e6+ Kg7
And by crikey! This is big news! This means that Gik actually had the record all along, and Minerva only tied it with his P1382027! (2020-11-29)
Henrik Juel: Gik's position is the record, but neither he nor Minerva knew this (2020-11-30)
James Malcom: This is an exciting development in the story of the mutual stalemate! (2020-11-30)
A.Buchanan: They will have to change the "Mr Robot" TV series: https://www.ozproblems.com/walkabout/walkabout2021/feb27 (2021-02-28)
A.Buchanan: Flipping left-right is again achievable in 18.0 not 17.5 - not entirely unexpected, as bK has further to walk, but was worth checking (2021-02-28)
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Keywords: Non-Unique Proof Game, Symmetrical position
Genre: Retro
FEN: 5bnr/4p1kp/4Pp1p/5P1P/p1p5/P1Pp4/PK1P4/RNB5
Reprints: 5 Best Problems 4, p. 94, 2007
61 Tim Krabbé's Website 16/08/2007
Input: James Malcom, 2020-11-29
Last update: A.Buchanan, 2021-02-28 more...
Genre: Retro
FEN: 5bnr/4p1kp/4Pp1p/5P1P/p1p5/P1Pp4/PK1P4/RNB5
Reprints: 5 Best Problems 4, p. 94, 2007
61 Tim Krabbé's Website 16/08/2007
Input: James Malcom, 2020-11-29
Last update: A.Buchanan, 2021-02-28 more...
15 - P1383064
Dieter Müller
8987 Best Problems 2018
3. ehrende Erwähnung
PR Antonio Garofalo
(11+9) C+
hs#3
b) wKg6->b5
Dieter Müller
8987 Best Problems 2018
3. ehrende Erwähnung
PR Antonio Garofalo
(11+9) C+
hs#3
b) wKg6->b5
a) 1. Tf7 Txa8 2. T5f6 Tf8 3. Te7+ Sxe7# (De6#)
b) 1. Lg1 f2 2. Txf2 Lxh4 3. Te2+ Dxe2# (Se3#)
b) 1. Lg1 f2 2. Txf2 Lxh4 3. Te2+ Dxe2# (Se3#)
Keywords: white Bristol (in a), Unpinning, Exchange of roles (d-s), Mirror mate (in b), Umnov
Genre: Fairies
FEN: B7/3p2PP/3p1RK1/3n1Rb1/3Pk1qQ/2p2pP1/r1P2B2/8
Reprints: Best Problems 96, p. 363, 10/2020
Input: Gunter Jordan, 2020-12-16
Last update: Gunter Jordan, 2020-12-18 more...
Genre: Fairies
FEN: B7/3p2PP/3p1RK1/3n1Rb1/3Pk1qQ/2p2pP1/r1P2B2/8
Reprints: Best Problems 96, p. 363, 10/2020
Input: Gunter Jordan, 2020-12-16
Last update: Gunter Jordan, 2020-12-18 more...
16 - P1385091
Kurt Keller
Best Problems 97, p. 367, 01/2020
Happy New Year 2021
Šťastný nový rok 2021
С новым годом 2021
Bonne année 2021
(6+4) C+
#3 v
Kurt Keller
Best Problems 97, p. 367, 01/2020
Happy New Year 2021
Šťastný nový rok 2021
С новым годом 2021
Bonne année 2021
(6+4) C+
#3 v
1. Le6+? A Kb4 a 2. Sd3+ B Ka4 b 3. Lb3# C
1. ... Kd4!
1. La6+! D Kb4 a 2. Sd3+ B Ka4 b 3. Lb5# E
1. ... Kd4 2. Sb3+ Ke4 3. Ld3#
Kurt Keller – (Germania) Christmas card
2B5/2B5/2K5/8/2k5/p1p1p3/P3P3/2N5
≠3 (6+4) C+
1.♗e6+?
1…♔b4 2.♘d3+ ♔a4 3.♗b3‡ but 1…♔d4!
1.♗a6+!
1…♔b4 2.♘d3+ ♔a4 3.♗b5‡
1…♔d4 2.♘b3+ ♔e4 3.♗d3‡
Checking key, 2 model mates.
[...] We thank our colleagues who have sent us greetings from various
countries.
(Antonio Garofalo (Bari, Italy): EDITORIALE, in: BEST PROBLEMS, 2021 - January [BP097.pdf])
1. ... Kd4!
1. La6+! D Kb4 a 2. Sd3+ B Ka4 b 3. Lb5# E
1. ... Kd4 2. Sb3+ Ke4 3. Ld3#
Kurt Keller – (Germania) Christmas card
2B5/2B5/2K5/8/2k5/p1p1p3/P3P3/2N5
≠3 (6+4) C+
1.♗e6+?
1…♔b4 2.♘d3+ ♔a4 3.♗b3‡ but 1…♔d4!
1.♗a6+!
1…♔b4 2.♘d3+ ♔a4 3.♗b5‡
1…♔d4 2.♘b3+ ♔e4 3.♗d3‡
Checking key, 2 model mates.
[...] We thank our colleagues who have sent us greetings from various
countries.
(Antonio Garofalo (Bari, Italy): EDITORIALE, in: BEST PROBLEMS, 2021 - January [BP097.pdf])
Comments:
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- Author – Kurt Keller (Ulm, Germany)
- Yet Another Chess Problem Database (...)
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Keywords: Symbol problem (Christmas tree), Checking key, Model mate, Changed mates, Symmetrical position, Asymmetrical solution, Selfblock, Remote selfblock, interchange in mating position (LS (4))
Genre: 3#
Computer test: Popeye Windows-32Bit v4.63 (512 MB)
FEN: 2B5/2B5/2K5/8/2k5/p1p1p3/P3P3/2N5
Input: Kurt Keller, 2021-01-07
Last update: Kurt Keller, 2021-01-30 more...
Genre: 3#
Computer test: Popeye Windows-32Bit v4.63 (512 MB)
FEN: 2B5/2B5/2K5/8/2k5/p1p1p3/P3P3/2N5
Input: Kurt Keller, 2021-01-07
Last update: Kurt Keller, 2021-01-30 more...
1. Se6! Kxc8 2. Dd8#
1. ... Ke8 2. De7#
1. ... Kxe6 2. Df5#
1. ... Kc6 2. Db5#
1. ... Ke8 2. De7#
1. ... Kxe6 2. Df5#
1. ... Kc6 2. Db5#
18 - P1385132
Steven B. Dowd
2407 Best Problems 53, p. 294, 01/2010
Stefano Spinelli gewidmet
(3+4) C+
s#7
Längstzüger
Steven B. Dowd
2407 Best Problems 53, p. 294, 01/2010
Stefano Spinelli gewidmet
(3+4) C+
s#7
Längstzüger
1. Kc1! Ta5 2. Tc7+ Kg8 3. Lb5 Lb1 4. Tc2 Ta1 5. Lxe2 Ta8 6. Kd1 Ta1 7. Td2 Lh7#
Keywords: Maximummer, ambush, Switchback, Miniature
Genre: Fairies
Computer test: popeye 4.85
FEN: 8/7k/6b1/5r2/8/3B4/2R1p3/1K6
Input: Felber, Volker, 2021-01-07
Last update: Marcin Banaszek, 2021-01-07 more...
Genre: Fairies
Computer test: popeye 4.85
FEN: 8/7k/6b1/5r2/8/3B4/2R1p3/1K6
Input: Felber, Volker, 2021-01-07
Last update: Marcin Banaszek, 2021-01-07 more...
19 - P1385191
Vladimir Kozhakin
Diana Utarova
4064 Best Problems 88, p. 147, 10/2018
(4+3) C+
#3
b) sBc6->c2
Vladimir Kozhakin
Diana Utarova
4064 Best Problems 88, p. 147, 10/2018
(4+3) C+
#3
b) sBc6->c2
a) 1. Dxc6! droht 2. Dc5#
1. ... Kd4 2. Lxe6 Kd3 3. Dc4#
2. ... Ke5 3. Dd5#
1. ... exf5 2. Le3 droht 3. De6#
b) 1. Lxe6! droht 2. Df4#, 2. Dd5#
1. ... Kd6 2. Dc3 c1=D 3. Lf8#
1. ... Kd4 2. Lxe6 Kd3 3. Dc4#
2. ... Ke5 3. Dd5#
1. ... exf5 2. Le3 droht 3. De6#
b) 1. Lxe6! droht 2. Df4#, 2. Dd5#
1. ... Kd6 2. Dc3 c1=D 3. Lf8#
20 - P1391341
Gianni Donati
v Best Problems 50 04/2009
2nd Honourable Mention,
E. Minerva 45 JT
(13+14) C+
BP in 22.0
Gianni Donati
v Best Problems 50 04/2009
2nd Honourable Mention,
E. Minerva 45 JT
(13+14) C+
BP in 22.0
1. h4 a5 2. Th3 a4 3. Tb3 axb3 4. Sc3 bxa2 5. b3 d5 6. La3 Lf5 7. Db1 e6 8. Kd1 Dg5 9. hxg5 c5 10. g6 Sc6 11. gxh7 g5 12. Kc1 Lg6 13. Kb2 f5 14. Dd1 Sf6 15. Sb1 Tg8 16. h8=T 0-0-0 17. Th1 Lh6 18. Kc3 Tg7 19. Kd3 c4 20. Ke3 c3 21. Lc1 g4+ 22. f4 gxf3ep+
HJ: last moves were something like 21... g5-g4+ 22.f2-f4 gxf3ep+
so it suffices to test the position with Pf3 on g5 and a wP added on f2
C++ means C+ plus that no shorter solution can be found.
A.Buchanan: The definition of Pronkin seems over-narrow, in two ways:
(1) The original officer must be captured: why? Standardization of material can be achieved by later Ceriani-Frolkin of the promoted officer, or (if S or T) by capture of another officer. In *any* of these three cases, it's an achievement for the promoted unit to have doing a homecoming.
(2) And this capture must happen *before* the homecoming of promoted officer: again why? This is a similar timing irrelevancy to "Phoenix", where the proper concept is "Nix".
So there are all these other fine scenarios which are completely nameless. Not to moan: how to fix all this? (2021-07-04)
A.Buchanan: @Henrik, I like your concept of "C++" (the well-known programming language). For positions with checks in the final diagram clearly testing n & n-1.0 suffices. Where there is no check in the final diagram, then the testing should be n, n-0.5, n-1.0 & n-1.5. Even though this is a bit of a bore, in most cases the other cases are very quick. This is the minimum set of tests necessary to *guarantee* no shorter PGs exist. To me, it seems worth pushing that extra yard, because otherwise C++ will be tarred with the same subjective incompleteness as C+. (2021-07-04)
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so it suffices to test the position with Pf3 on g5 and a wP added on f2
C++ means C+ plus that no shorter solution can be found.
A.Buchanan: The definition of Pronkin seems over-narrow, in two ways:
(1) The original officer must be captured: why? Standardization of material can be achieved by later Ceriani-Frolkin of the promoted officer, or (if S or T) by capture of another officer. In *any* of these three cases, it's an achievement for the promoted unit to have doing a homecoming.
(2) And this capture must happen *before* the homecoming of promoted officer: again why? This is a similar timing irrelevancy to "Phoenix", where the proper concept is "Nix".
So there are all these other fine scenarios which are completely nameless. Not to moan: how to fix all this? (2021-07-04)
A.Buchanan: @Henrik, I like your concept of "C++" (the well-known programming language). For positions with checks in the final diagram clearly testing n & n-1.0 suffices. Where there is no check in the final diagram, then the testing should be n, n-0.5, n-1.0 & n-1.5. Even though this is a bit of a bore, in most cases the other cases are very quick. This is the minimum set of tests necessary to *guarantee* no shorter PGs exist. To me, it seems worth pushing that extra yard, because otherwise C++ will be tarred with the same subjective incompleteness as C+. (2021-07-04)
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Keywords: Unique Proof Game, Valladao Task, Castling (sg), Promotion (T), Phoenix (T), Pronkin Theme (T), Impostor (Th1)
Genre: Retro
Computer test: C++ Euclide 1.01
FEN: 2kr4/1p4r1/2n1pnbb/3p1p2/8/1Pp1Kp2/p1PPP1P1/RNBQ1BNR
Input: A.Buchanan, 2021-07-04
Last update: A.Buchanan, 2021-07-04 more...
Genre: Retro
Computer test: C++ Euclide 1.01
FEN: 2kr4/1p4r1/2n1pnbb/3p1p2/8/1Pp1Kp2/p1PPP1P1/RNBQ1BNR
Input: A.Buchanan, 2021-07-04
Last update: A.Buchanan, 2021-07-04 more...
21 - P1406866
Vaclav Kotesovec
3432 Best Problems 74 2015
1. Preis
(4+1) C+
hs=9
wDU=Grashüpfer
2 Lösungen
Vaclav Kotesovec
3432 Best Problems 74 2015
1. Preis
(4+1) C+
hs=9
wDU=Grashüpfer
2 Lösungen
1) 1. Df5 Kc3 2. Gg4 Kb4 3. Db1+ Ka5 4. Kd7 Ka6 5. Gc8 Ka7 6. Ga8 Ka6 7. Kc7 Ka5 8. Kb8 Ka6 9. Db6+ Kxb6=
2) 1. Db1 Ke2 2. Gf2 Ke3 3. Kf7 Kd4 4. Gf8 Kd5 5. Gd4 Ke5 6. Kg7 Kf4 7. Gh8 Kg5 8. Kg8 Kh6 9. Dg6+ Kxg6=
2) 1. Db1 Ke2 2. Gf2 Ke3 3. Kf7 Kd4 4. Gf8 Kd5 5. Gd4 Ke5 6. Kg7 Kf4 7. Gh8 Kg5 8. Kg8 Kh6 9. Dg6+ Kxg6=
Judge Hans Gruber (Best Problems 105/2023, p.572-576): "This is a miracle! Although the author showed in a number of publications around the year 2000, that hundreds of threefold chameleon echoes exist in problems without twinning, which seriously limits the innovation value of such problems, I consider this problem – with only two echoes – as outstanding. The quality of the moves and the reasons why their order is unique, is fascinating. Why should manoeuvres by the black king and the white queen (!) be unique on an open board, without constraining fairy conditions, and with the need to reach in two solutions two opposing edges of the board? The provision of appropriate hurdles for the grasshoppers is the key feature. The ingenious find is that the move Db1 (played at different moves) constrains the black king to the a-file in the first solution while it offers him the whole board for a virtuoso slalom run in the second solution. A sensational problem in terms of agility, and I do not care that the computer helped to find it. Still, the composer had to discover this gem in an almost infinitely large data base."
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Keywords: Chameleon Echo, Aristocrat, Rex solus (s)
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: 4K3/3*2Q4/8/8/8/8/*2Q2k4/5Q2
Input: Vaclav Kotesovec, 2022-12-27
Last update: Vaclav Kotesovec, 2022-12-27 more...
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: 4K3/3*2Q4/8/8/8/8/*2Q2k4/5Q2
Input: Vaclav Kotesovec, 2022-12-27
Last update: Vaclav Kotesovec, 2022-12-27 more...
1. e3 h5 2. Dxh5[+sBd1=L] Le2 3. Df3 Txh2[+wBh8=D] 4. Dxb7[+sBf3] fxg2[+wBf3] 5. Dxa7[+sBb7] gxh1=D[+wTg2] 6. Dd4 Txa2[+wBa8=T] 7. Ddxg7[+sBd4] dxe3[+wBd4] 8. d5 exf2[+wBe3]+ 9. Kxf2[+sBe1=T] Dxg2[+wTh1]+ 10. Kxe1[+sTf2] Dg6 11. Dxh2[+sTh8] Dxc2[+wBg6] 12. Dxc7[+sBh2] hxg1=S[+wSh2] 13. Dc5 Db6 14. gxf7[+sBg6]+ Kd8 15. fxg8=S[+sSf7] Dbxb2[+wBb6] 16. Sxe7[+sBg8] Ta7 17. bxa7[+sTb6] Tf6 18. axb8=L[+sSa7]
Keywords: Allumwandlung (2-fach), Unique Proof Game, Interchange Circe, Switchback (KTt)
Genre: Retro, Fairies
FEN: RBbk1bpr/np1pNnQ1/5rp1/2QP4/8/4PP2/1qqPbr1N/RNB1KBnR
Input: Gunter Jordan, 2022-12-27
Last update: A.Buchanan, 2024-01-18 more...
Genre: Retro, Fairies
FEN: RBbk1bpr/np1pNnQ1/5rp1/2QP4/8/4PP2/1qqPbr1N/RNB1KBnR
Input: Gunter Jordan, 2022-12-27
Last update: A.Buchanan, 2024-01-18 more...
23 - P1406940
Marco Bonavoglia
Best Problems 105, p. 561, 01/2023
Happy New Year
(13+15) C+
KBP 17.0
Marco Bonavoglia
Best Problems 105, p. 561, 01/2023
Happy New Year
(13+15) C+
KBP 17.0
1. e3 e6 2. Ld3 Le7 3. Lg6 hxg6 4. Dg4 Th5 5. Se2 Tc5 6. 0-0 Tc3 7. bxc3 Lh4 8. La3 Df6 9. Ld6 Se7 10. Lf4 d6 11. Sa3 Ld7 12. Tfb1 Lc6 13. Tb6 axb6 14. Kf1 Ta5 15. Ke1 Th5 16. Sb5 Th8 17. Lh6 gxh6
Sibling (t)
Sibling (t)
Posthum innerhalb eines Nachrufes auf Marco Bonavoglia veröffentlicht. (s.a. Kommentar zu P1406941)
Antonio Garofalo: "Il Bianco non può arroccare, lo ha già fatto. Il Nero non può arroccare perché la yh8 è un impostore, è originaria di 'a8'. Scambio dei sBBhg che nasconde la soluzione. Una bellissima eredità dell'amico Marco." [Weiß kann nicht rochieren, da er es bereits getan hat. Schwarz kann nicht rochieren, weil Th8 ein 'Betrügerturm' ist, er stammt von a8. Kreuzschlag der sBBhg, was die Lösung verschleiert. Ein wunderschönes Erbe von meinem Freund Marco.]
Henrik Juel: Euclide 1.01 did little in an hour. Stopped at pos. 19 (2022-12-30)
Henrik Juel: The first 16.5 moves are C+ Euclide 1.01 (35 minutes) (2022-12-30)
Joost de Heer: C+ in less than a minute with Stelvio 1.11 (2023-04-04)
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Antonio Garofalo: "Il Bianco non può arroccare, lo ha già fatto. Il Nero non può arroccare perché la yh8 è un impostore, è originaria di 'a8'. Scambio dei sBBhg che nasconde la soluzione. Una bellissima eredità dell'amico Marco." [Weiß kann nicht rochieren, da er es bereits getan hat. Schwarz kann nicht rochieren, weil Th8 ein 'Betrügerturm' ist, er stammt von a8. Kreuzschlag der sBBhg, was die Lösung verschleiert. Ein wunderschönes Erbe von meinem Freund Marco.]
Henrik Juel: Euclide 1.01 did little in an hour. Stopped at pos. 19 (2022-12-30)
Henrik Juel: The first 16.5 moves are C+ Euclide 1.01 (35 minutes) (2022-12-30)
Joost de Heer: C+ in less than a minute with Stelvio 1.11 (2023-04-04)
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Keywords: Unique Proof Game, Castling, black Bristol, Switchback (K)
Genre: Retro
Computer test: laut 'Best Problems' C+, aber Prüfprogramm nicht angegeben
FEN: 1n2k2r/1pp1np2/1pbppqpp/1N6/6Qb/2P1P3/P1PPNPPP/R3K3
Input: Mario Richter, 2022-12-30
Last update: Gunter Jordan, 2022-12-30 more...
Genre: Retro
Computer test: laut 'Best Problems' C+, aber Prüfprogramm nicht angegeben
FEN: 1n2k2r/1pp1np2/1pbppqpp/1N6/6Qb/2P1P3/P1PPNPPP/R3K3
Input: Mario Richter, 2022-12-30
Last update: Gunter Jordan, 2022-12-30 more...
1. Ld4! Kh6 2. Dxg7+ Kg5 3. Df6+ Kh6 4. Kh4 Kh7 5. Df7+ Kh6 6. g3 g5#
Comments:
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- Author – Kurt Keller (Ulm, Germany)
- Original problem with solution on http://www.bestproblems.it (BP106.pdf)
- Set of three Easter problems (hs#,s#,h#) with P1408698 and P1408700
- The size of the symbols decreases by one square each in the order 2-1-3.
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Keywords: Symbol problem (Osterkreuz - 2), Symbol problem (Petruskreuz), Symbol problem (Osterkerze)
Genre: Fairies
Computer test: Gustav 4.1 d. Henrik Juel: C+ Popeye 4.61 also (2023-04-05)
FEN: 6Q1/6p1/6p1/6k1/6P1/5PKP/6P1/6B1
Input: Kurt Keller, 2023-04-05
Last update: Kurt Keller, 2023-04-05 more...
Genre: Fairies
Computer test: Gustav 4.1 d. Henrik Juel: C+ Popeye 4.61 also (2023-04-05)
FEN: 6Q1/6p1/6p1/6k1/6P1/5PKP/6P1/6B1
Input: Kurt Keller, 2023-04-05
Last update: Kurt Keller, 2023-04-05 more...
Show statistic for complete result. Show search result faster by using ids.
https://pdb.dieschwalbe.de/search.jsp?expression=COMMENTDATE%3E%3D20200919+AND+NOT+K%3D%27Hilfsr%C3%BCckz%C3%BCger%27+AND+NOT+G%3D%27h%23%27+AND+S%3D%27Best+Problems%27
The problems of this query have been registered by the following contributors:
Gerd Wilts (3)Frank Müller (3)
Felber, Volker (5)
Hans Gruber (1)
Erich Bartel (1)
Gunter Jordan (3)
James Malcom (3)
Kurt Keller (2)
A.Buchanan (1)
Vaclav Kotesovec (1)
Mario Richter (1)
in 'Ruy Lopez' abgedruckt in der Rubrik "Partidas de fantasia"
AB: Not quite unique alas. 4 Dxc7 & 5 h4 can be transposed. (2001-10-17)
Kostas Prentos: Besides the minor transposition, there's another totally different solution:
1.c4 d5 2.Db3 Lf5 3.Dxb7 h5 4.Dxa7 Lh7 5.Dxb8 Ta6 6.h4 Th6 7.Dxc7 f6 8.Dxd8+ Kf7 9.Dxd5+ Kg6 10.De6= with many duals, too (2002-07-03)
AB: Yes, I was referring to uniqueness of proof game to reach the diagram position. KP responds to the task which appears here as the stipulation. (2002-07-07)
Yoav Ben-Zvi: What is the most simple stipulation that makes the solution unique?
My candidate: "Shortest game ending in Stalemate, given that White has not moved a Pawn after his fourth move"
I would add the length of the composer's solution as a courtesy to solvers: "Game in less than 10.0 moves ending in Stalemate, given that White has not moved a Pawn after his fourth move" (2012-08-27)
A.Buchanan: Hi YBZ: the proof game that Kostas gave 5bnr/4p1pb/4Qpkr/7p/7P/2P5/PP1PPPP1/RNB1KBNR has 12 solutions. 1.c3 gives another 12 solutions. And there's 2 solutions for Loyd. Out of these 26 indeed only one has the property that Wh gets all pawn moves out of the way before 4th move. But it's just occurred to me that there's a variant of Loyd which begins 1.c3 and wQ develops via a4 & a5, ending with 5bnr/4p1pq/4Qpkr/7p/7P/2P5/PP1PPPP1/RNB1KBNR this has 15 solutions, and in 6 of these, Wh plays both pawn moves as moves 1 or 2. Similarly if 1.c4. This only differs from Prentos' solution in the occupant of h7. So the suggested stipulation alas wouldn't work. I am pretty sure i have seen a longer version which is sound as a PG. (2020-05-28)
A.Buchanan: See P1004131 for a longer sound PG. (2020-05-28)
Yoav Ben-Zvi: The cook noted above means that a more elaborate secondary condition is needed. My suggestion:
"PG that is shortest to end in Stalemate (less than 10.0 moves) and White plays 2 consecutive captures that are each longer than 2 squares".
An alternative is to accept the transposition:
"PG that is shortest to end in stalemate (less than 10.0 moves) and wPc2 does not move, 2 variants". (2020-06-07)
A.Buchanan: Is it known that there are no h=n.5 (or h=n half-duplex) from the game array for n9? (2022-07-13)
A.Buchanan: I read Loyd’s stipulation more as a hard task for composers than a fair ask of solvers. Loyd was a genius so of course he came up with a great answer. Adding a latter-day secondary condition to give an arbitrary uniqueness is no help to solvers, and has an aesthetic price. I imagine that Loyd’s withering reaction - as he generally favoured conceptual elegance over rigorous dual elimination. Non-unique PGs are a bit old-fashioned, but they still have their place and James Malcom proves a master at their efficient construction. I wish that YBZ was still with us to possibly contest my point, RIP. (2022-07-13)
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