16 problem(s) found in 6830 milliseconds (displaying 16 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT K='Überholt' AND K='Fressbauer'] [download as LaTeX]
a) 1. gxf3ep g4 2. Kd5 gxf5 3. Kc6 fxe6 4. Kb7 exd7 5. Ka8 dxc8=D#
1. Le3+ Kb5 2. Da5+ Kc4 3. Dc5+ Kd3 4. Dc3+ Ke2 5. Dd2+ Kf1 6. Lb6 bxc6 7. Lc5 cxd5 8. Ld4 dxe4 9. Le3 exf3 10. Lf2 fxg2#
bessere Neufassung zu Nr. 1854, Blatt 152
bessere Neufassung zu Nr. 1854, Blatt 152
1. Db6+ Ka4 2. Db5+ Ka3 3. Ta2+ Kxa2 4. Db3+ Ka1 5. Tf1+ Se1 6. Lb6 bxc6 7. Lc5 cxd5 8. Ld4 dxe4 9. Le3 exf3 10. Lf2 fxg2#
1. e7+ Kc8 2. d7+ Kb8 3. c7+ Ka8 4. b7+ Ka7 5. b8=D+ Kxa6 6. c8=D+ Ka5 7. d8=D+ Ka4 8. e8=D+ Ka3 9. f8=D+ Ka2 10. Db3+ Ka1 11. Dff6+ gxf6 12. De5+ fxe5 13. Dd4+ exd4 14. Dcc3+ dxc3 15. Db2+ cxb2#
Keywords: Pac-Man, Promotions to queens, konsekutive Umwandlungen 5 (DDDDD), Kindergarten Problem
Genre: s#
FEN: 3k4/5Pp1/PPPPP3/8/8/8/2PPp3/2K5
Input: Frank Müller, 2009-06-29
Last update: Marcin Banaszek, 2022-07-30 more...
Genre: s#
FEN: 3k4/5Pp1/PPPPP3/8/8/8/2PPp3/2K5
Input: Frank Müller, 2009-06-29
Last update: Marcin Banaszek, 2022-07-30 more...
1. Lb6 bxc6 2. Lc5 cxd5 3. Ld4 dxe4 4. Le3 exf3 5. Lf2 fxg2#
Keywords: Alleinunterhalter, Pac-Man, Round Trip (L)
Genre: s#
FEN: 8/1p6/2P5/3P4/4P2p/5P1k/5BRp/7K
Input: Frank Müller, 2009-10-03
Last update: Frank Müller, 2009-10-03 more...
Genre: s#
FEN: 8/1p6/2P5/3P4/4P2p/5P1k/5BRp/7K
Input: Frank Müller, 2009-10-03
Last update: Frank Müller, 2009-10-03 more...
1. b8=L!
1. ... dxe6 2. Le5 exd5 3. Ld4 dxe4 4. Le3 exd3 5. Ld2 dxc2#
1. ... d6 2. e5 dxe5 3. La7 e4 4. Le3 exd3 5. Ld2 dxc2#
1. ... dxe6 2. Le5 exd5 3. Ld4 dxe4 4. Le3 exd3 5. Ld2 dxc2#
1. ... d6 2. e5 dxe5 3. La7 e4 4. Le3 exd3 5. Ld2 dxc2#
Keywords: Pac-Man, Promotion key
Genre: s#
Computer test: Gustav 4.1d, Brute Force
FEN: 8/1P1p4/4P3/3P4/4P3/3N4/PpP3R1/bK1k4
Input: Frank Müller, 2010-11-06
Last update: Rainer Staudte, 2023-01-19 more...
Genre: s#
Computer test: Gustav 4.1d, Brute Force
FEN: 8/1P1p4/4P3/3P4/4P3/3N4/PpP3R1/bK1k4
Input: Frank Müller, 2010-11-06
Last update: Rainer Staudte, 2023-01-19 more...
1. Lb6 bxc6 2. Lc5 cxd5 3. Ld4 dxe4 4. Le3 exf3 5. Lf2 fxg2#
Beitrag eines Schülerkompositionsturnieres
Beitrag eines Schülerkompositionsturnieres
1. Lf5 f6 2. Le5 fxe5 3. Le4 exd4 4. Ld3 dxc3 5. Lc2 cxb2#
1. Lg6? gxf6 2. Lf5 fxe5 3. Le4 exd4 4. Ld3 Ka4!
1. Dg6! gxf6 2. Df5 fxe5 3. De4 exd4 4. Dxc6 dxc3 5. Lc2 cxb2#
1. Dg6! gxf6 2. Df5 fxe5 3. De4 exd4 4. Dxc6 dxc3 5. Lc2 cxb2#
1. b2 Kxa2[+sBa7] 2. b1=L+ Kxb1[+sLc8] 3. Lh3 gxh3[+sLc8] 4. Lg4 hxg4[+sLc8] 5. Lf5+ gxf5[+sLc8] 6. Le6 fxe6[+sLc8] 7. Ld7 exd7[+sLc8] 8. Ka8 dxc8=D#
1. d8=S! droht 2. Se6+
1. ... Lc3 2. dxe3 droht 3. Se6+
2. ... Ld4 3. exf4 droht 4. Se6+
3. ... Le5 4. fxg5 Lf6 5. gxh6 Lxd8 6. hxg7+ Dxg7#
1. ... Lc3 2. dxe3 droht 3. Se6+
2. ... Ld4 3. exf4 droht 4. Se6+
3. ... Le5 4. fxg5 Lf6 5. gxh6 Lxd8 6. hxg7+ Dxg7#
1. Sg6! f6 2. Se5 fxe5 3. Tc3 exd4 4. Ld3 dxc3 5. Lc2 cxb2#
1. ... fxg6 2. Tc3 g5 3. Lc2 g4 4. Lg3 bxc3 5. b4 cxb2#
2. ... gxf5 3. Lc2 f4 4. Lxf4 bxc3 5. b4 cxb2#
Jaremska-Iliescu gibt in ihrem Herland-Buch Deutsche Schachzeitung 1906 als Quelle an.
1. ... fxg6 2. Tc3 g5 3. Lc2 g4 4. Lg3 bxc3 5. b4 cxb2#
2. ... gxf5 3. Lc2 f4 4. Lxf4 bxc3 5. b4 cxb2#
Jaremska-Iliescu gibt in ihrem Herland-Buch Deutsche Schachzeitung 1906 als Quelle an.
1. f8=S! g5 2. Sg6 g4 3. c8=L gxh3 4. Sdf6 h2,gxf6 5. Lf5 gxf6,h2 6. Se5 fxe5 7. Lg4 exd4 8. Sc3 dxc3 9. Db2+ cxb2#
1. Kd6! dxe6 2. Ke5 exd5 3. Kd4 dxe4 4. Ke3 exd3 5. Kd2 dxe2 6. Lb6+ axb6 7. Ke1 b5 8. Sc3 bxc3 9. Lc2 b4 10. Sf5 Kg2#
1. Lb6+? Td4? 2. Tg5+ Sg3 3. De2 usw. wie in der Lösung, aber
1. ... Sd4!
1. Tg5+! Sg3 2. Lb6+ Td4 3. De2! gxh5 4. Kd2 g6,h4 5. Kc3 h4,g6 6. Kb4 h3 7. a6! bxa6 8. Ka5 axb5 9. Kb4 bxc4 10. Kc3 cxd3 11. Kd2 dxe2+ 12. Ke1 Kg2#
1. ... Sd4!
1. Tg5+! Sg3 2. Lb6+ Td4 3. De2! gxh5 4. Kd2 g6,h4 5. Kc3 h4,g6 6. Kb4 h3 7. a6! bxa6 8. Ka5 axb5 9. Kb4 bxc4 10. Kc3 cxd3 11. Kd2 dxe2+ 12. Ke1 Kg2#
1. c2! b3+ 2. c3 bxc4ep+ 3. d4 cxd5ep+ 4. e5 dxe6ep+ 5. f6 exf7ep#
Not e.g. 1. c3? b4?? 2. Kg7 bxc5 3. Kh8 cxd6 4. Kg7 dxe7 5. Kh8 exf8=D# as wPb2 has lost double move rights
Not 1. c3? bxc3 2. d4 cxd4 3. e5 dxe5 4. f6 exf6 and no h#1 due to bPc5
Not 1. c3? c2 2. cxb2 c3 3. b1=L Lb2 4. La2 La1 5. Lg8 c4#? as 3 bPs can make double move to block the check
Either the current position is a starting position, or White has just played 0. ... b1-b2, from a position with an impossible check which must therefore have been the starting position itself. In either case, none of the Black pawns have ever moved, and so are eligible to make a double move. wPc1 has also never moved. But what of wPb2? We are up in the air as to whether b2-b4 is legal.
Since we can never prove that a position is not a starting position, the default convention is that it is *not* the starting position. Therefore, White has just begun the game with Black in check, and played 0. ... b1-b2, so is not able to play b2-b4 later.
Eventually, when Chess960 becomes played out, we will all be playing Chess4E71, so best to learn it now. There are three diagonals wPb2 may move along, but only one of them works. Rigorous retro reasoning allows all the pawns to make a double move *except* for wPb2. (Author)
Not e.g. 1. c3? b4?? 2. Kg7 bxc5 3. Kh8 cxd6 4. Kg7 dxe7 5. Kh8 exf8=D# as wPb2 has lost double move rights
Not 1. c3? bxc3 2. d4 cxd4 3. e5 dxe5 4. f6 exf6 and no h#1 due to bPc5
Not 1. c3? c2 2. cxb2 c3 3. b1=L Lb2 4. La2 La1 5. Lg8 c4#? as 3 bPs can make double move to block the check
Either the current position is a starting position, or White has just played 0. ... b1-b2, from a position with an impossible check which must therefore have been the starting position itself. In either case, none of the Black pawns have ever moved, and so are eligible to make a double move. wPc1 has also never moved. But what of wPb2? We are up in the air as to whether b2-b4 is legal.
Since we can never prove that a position is not a starting position, the default convention is that it is *not* the starting position. Therefore, White has just begun the game with Black in check, and played 0. ... b1-b2, so is not able to play b2-b4 later.
Eventually, when Chess960 becomes played out, we will all be playing Chess4E71, so best to learn it now. There are three diagonals wPb2 may move along, but only one of them works. Rigorous retro reasoning allows all the pawns to make a double move *except* for wPb2. (Author)
Henrik Juel: No comment (2020-08-30)
James Malcom: I think that the simplest possbility to animate this, if Gerd has time that is, would be to allow a pawn to commence a double step fro anywhere. (2020-08-30)
A.Buchanan: Would also need non-standard e.p. (2020-08-31)
Mario Richter: Henrik walking in the footsteps of Epimenides: a comment saying "No comment" :-) (2020-09-20)
A.Buchanan: This is basically the simplest set of rules & conventions to allow chess with any starting arrangement of the orthodox pieces (2020-09-21)
comment
James Malcom: I think that the simplest possbility to animate this, if Gerd has time that is, would be to allow a pawn to commence a double step fro anywhere. (2020-08-30)
A.Buchanan: Would also need non-standard e.p. (2020-08-31)
Mario Richter: Henrik walking in the footsteps of Epimenides: a comment saying "No comment" :-) (2020-09-20)
A.Buchanan: This is basically the simplest set of rules & conventions to allow chess with any starting arrangement of the orthodox pieces (2020-09-21)
comment
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The problems of this query have been registered by the following contributors:
Gerd Wilts (1)HBae (2)
Frank Müller (10)
Erich Bartel (1)
Rainer Staudte (1)
A.Buchanan (1)
Henrik Juel: Popeye 4.61 with 'opt var int enp f3' works fine
Maybe you just have to change f2f3f4 to f3, Andrew (2021-11-23)
A.Buchanan: Thanks for the suggestion, Henrik, but even without the "intelligent", opti vari enpa f3 fails with v4.87. I think that the syntax has been rendered more complicated since v4.61 in order to support fancy fairy en passants. (2021-11-23)
comment