Die Schwalbe

28 problem(s) found in 5720 milliseconds (displaying 28 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT K='Exzelsior Weiß' AND K='symmetrisches Spiel'] [download as LaTeX]

1 - P0002476
Werner Kuntsche
1777v Problem 73-78 06/1961
P0002476
(5+7) cooked
h#3 AP
Einheitslösung!
1) 1. cxd3ep Ta5 2. Sf5 0-0 3. Sd4 Txe5#
2) 1. gxf3ep Th5 2. Sd5 0-0-0 3. Sf4 Txe5#
play all play one stop play next play all
Cook: 707 cooks which do not begin with e.p., e.g. 1.Sg3-e2 Ra1-a2 2.Ke4-d3 Rh1-h3 3.e5-e4 Ra2-d2 #
What is the obscure intent behind "Einheitslösung!"? (= "One size fits all solution"?)
Mario Richter: Im Nachdruck in problem 144-147 steht nur auf e5 ein sB (also keiner auf e3). Allerdings gibt es in allen drei Varianten (sBe5+e3, nur sBe5, nur sBe3) jede Menge NL, die ohne Rochade und e.p.-Key auskommen - am wenigsten dann, wenn nur auf e3 ein sB steht. (2010-10-10)
VL: Cf. P0002475. (2012-08-26)
A.Buchanan: Possibly "Einheitlösung!" is a request to unify retro implications derived across separate parts of the PRA solution. But cooked chessically irrespective of these philosophical issues, which still wait to be resolved 60 years on. (2022-02-16)
comment
Keywords: a posteriori (AP) (Type Petrovic - ccee), En passant as key (2), Castling (wb), Symmetrical position, Symmetrical solution, Superseded by (P1401449,P1399112)
Genre: h#, Retro
Computer test: C- Forward play cooked by Popeye v4.87. However the basic idea is good, if a suitable theoretical framework can be found.
FEN: 8/8/8/4p3/2pPkPp1/2n1p1n1/8/R3K2R
Reprints: (66) Problem 144, p. 52, 12/1971
Die Schwalbe 99 06/1986
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-05-24 more...
2 - P1000172
Andrey Frolkin
Andrej N. Kornilow

9 Die Schwalbe 169, p. 342, 02/1998
3. Preis
P1000172
(14+14) cooked
KBP?
1. a4 h5 2. a5 h4 3. a6 h3 4. axb7 hxg2 5. h4 a5 6. h5 a4 7. h6 a3 8. h7 a2 9. Th6 Ta3 10. Sh3 Sa6 11. b8=D g1=D 12. Db4 Dg5 13. Dh4 Da5 14. b4 g5 15. 15. b5 g4 16. b6 g3 17. b7 g2 18. b8=D g1=D 19. Dbb4 Dgg5 20. Dbg4 Dgb5 21. c4 f5 22. Tf6 Tc3 23. dxc3 exf6 24. Le3 Ld6 25. Sd2 Se7 26. Tb1 Tg8 27. h8=S a1=S 28. Sg6 Sb3 29. Sgf4 Sbc5 30. Sg2 Sb7 31. f4 c5 32. Lg1 Lb8 33. e3 d6 34. Le2 Ld7 35. Sf1 Sc8 36. Dd2 De7 37. Kd1
play all play one stop play next play all
Cook: NL
1. d3 a5 2. Le3 a4 3. Sd2 a3 4. g4 Ta4 5. g5 Tc4 6. dxc4 b5 7. g6 b4 8. gxh7 b3 9. h4 bxa2 10. b4 e6 11. b5 g5 12. b6 g4 13. b7 g3 14. h5 g2 15. h6 Sa6 16. Th5 f6 17. Tb1 a1=S 18. Sh3 g1=D 19. b8=D Dg5 20. c3 Db5 21. Tf5 c5 22. Df4 Ld6 23. Dg4 Lb8 24. f4 Se7 25. Lg1 a2 26. e3 Sb3 27. Le2 a1=D 28. Sf1 Sa5 29. Dd2 Sb7 30. Kd1 Tg8 31. h8=S Da5 32. Sg6 exf5 33. Sh4 d6 34. Sg2 Ld7 35. h7 Sc8 36. h8=D De7 37. Dh8-h4 (Henrik Juel)
Moldenhauer: Computerprüfung: Cooked Stelvio 1.31 00:06:21 Minuten. (hh:mm:ss)
Keine Lösung: BP 36.0.
Beispiel Stelvio: 1.c3 a5 2.d3 a4 3.Le3 a3 4.Sd2 Ta4 5.Tb1 Tc4 6.dxc4 Sa6 7.g4 b5
8.g5 b4 9.g6 b3 10.gxh7 bxa2 11.b4 a1=S 12.b5 a2 13.b6 Sb3 14.h4 g5 15.h5 g4
16.h6 g3 17.Th5 g2 18.Sh3 g1=D 19.b7 Dg5 20.b8=D Db5 21.Tf5 c5 22.Df4 a1=D 23.Dg4 Sa5
24.f4 Sb7 25.Lg1 Daa5 26.e3 e6 27.Le2 Ld6 28.Sf1 Lb8 29.Dd2 Se7 30.Kd1 Tg8
31.h8=S d6 32.Sg6 Ld7 33.Sh4 Sc8 34.Sg2 De7 35.h7 f6 36.h8=D exf5 37.Dhh4 (2023-06-20)
more ...
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Keywords: Unique Proof Game, Symmetrical position, Non-standard material, Symmetrical solution
Genre: Retro
FEN: 1bn1k1r1/1n1bq3/n2p1p2/qqp2p2/2P2PQQ/2P1P2N/3QB1N1/1R1K1NB1
Reprints: feenschach 141 06/2001
Input: Gerd Wilts, 2000-08-01
Last update: Alfred Pfeiffer, 2018-12-19 more...
3 - P1099694
William A. Shinkman
284 American Chess Magazine 09/1898
P1099694
(12+3) C+
s#5
1. Dd6! Sac3,Sb6 2. Dd5+ Sxd5 3. Se5+ Kd4 4. Sf3+ Kc4 5. Se3+ Sxe3#
1. ... Sac5,Sb2 2. Dd3+ Sxd3 3. Se3+ Kd4 4. Sf5+ Kc4 5. Se5+ Sxe5#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force (2021-09-24)
comment
Keywords: Symmetrical solution
Genre: s#
FEN: 8/3N4/2B5/7P/nBk1nRKP/P6P/2PQ4/3N4
Reprints: 3840 Deutsches Wochenschach 02/04/1899
Input: Frank Müller, 2010-02-06
Last update: Marcin Banaszek, 2021-09-24 more...
4 - P1110764
Peter Hoffmann
2275 Schach-Aktiv 06/1999
P1110764
(11+16) C+
s#6
1. Lg7! droht 2. Txc2+ Ke3 3. Lh6+ f4 4. Tc3+ Kd4 5. Txb3+ Kxc5 6. Lf8+ d6#
1. ... Lb1 2. Txb3+ Kxc5 3. Lf8+ d6 4. Tc3+ Kd4 5. Txc2+ Ke3 6. Lh6+ f4#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force (2021-01-12)
more ...
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Keywords: Batterie Typ Rehm, half-battery, black, Symmetrical solution
Genre: s#
Computer test: Gustav 4.1d, Brute Force
FEN: 1nqn4/1rrp1p2/1Pp4B/N1P1pp2/3k3P/1pR3pK/bQp1P1Bb/5R2
Input: Frank Müller, 2010-07-16
Last update: Marcin Banaszek, 2021-01-13 more...
5 - P1148947
Godehard Murkisch
23c Schachkomponist Günther Jahn 04/2005
P1148947
(3+3) C+
#4
1. e8=D+ Tde6 2. Db8+ Td6 3. Db5+ Ke6 4. De8#
3. ... Td5 4. Dxd5#
1. ... Tfe6 2. Dh8+ Tf6 3. Dh5+ Ke6 4. De8#
3. ... Tf5 4. Dxf5
play all play one stop play next play all
mm Schema
more ...
comment
Keywords: Miniature Collection (0349521), Checking key, Echo, Epaulettenmatt, Switchback, Symmetrical position, Promotion (D), Symmetrical solution, Symmetrical end position, Miniature
Genre: n#
Computer test: Gustav 4.2a, Brute Force
FEN: 8/4P3/3r1r2/4k3/4P3/4K3/8/8
Input: Zuncke/Bruder, 2010-09-12
Last update: Rainer Staudte, 2023-10-06 more...
6 - P1152303
Christoph Johannessohn
4 Schach-Echo 1942
P1152303
(4+2) C+
#4
1. Tg1 Ke3 2. Tg2 Kd4 3. Tg3 e3 4. Tg4#
2. ... Kf4 3. Tc3 e3 4. Tc4#
play all play one stop play next play all
B5T e458
more ...
comment
Keywords: Miniature Collection (0292494), Minimal, Miniature, Symmetrical solution
Genre: n#
Computer test: Gustav 4.1d
FEN: 8/8/4K3/8/3kp3/8/2R1P3/4R3
Input: Felber, Volker, 2010-09-12
Last update: Arnold Beine, 2021-06-05 more...
7 - P1214309
Edward Boswell
2559 Springaren 06-07/1954
P1214309
(11+12) C+
s#2
1. Dh4+! Lc4 2. Txc7 Sxc7#
1. ... Lg4 2. Txg7 Sxg7#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61 (2022-03-08)
comment
Keywords: Symmetrical solution, Checking key
Genre: s#
FEN: 4n1n1/2pPpPp1/B1RpKpRp/p2N1N1P/k7/1p6/1P2b3/4Q3
Input: Frank Müller, 2011-10-11
Last update: Marcin Banaszek, 2022-03-10 more...
8 - P1217923
Heinrich Friedrich Ludwig Meyer
181 Brüderschaft 43, p. 197, 23/10/1886
P1217923
(7+5) C+
#2
1. e8=S! Kf5 2. Sxd6#
1. ... Kd5 2. Sxf6#
1. ... d5 2. Sd6#
1. ... f5 2. Sf6#
play all play one stop play next play all
more ...
comment
Keywords: under-promotion key (S), Symmetrical position, Zugzwang-Goal, Symmetrical solution
Genre: 2#
Computer test: Juel: Popeye 4.61
FEN: 8/4P3/3ppp2/1P2p2P/4k3/1P2B2P/4K3/8
Input: Felber, Volker, 2011-11-08
Last update: Dieter Berlin, 2024-03-11 more...
9 - P1228928
Hieronymus Fischer
7066v Deutsches Wochenschach 26/08/1906
P1228928
(8+4) cooked
s#6
Korrektur in DWS 11.11.1906
1. Dg2 Kd3 2. Tc2 Ke3 3. Dd5 Kd3 4. Td1+ Ke3 5. Le6 fxe6 6. Sxe6 Sf7#
1. Dg2 Kc4 2. Tb3 Kc5 3. De4 Kc4 4. Ta4+ Kc5 5. Lf5 gxf5 6. Sxf5 Sg6#
play all play one stop play next play all
SCHRECKE: viele Duale, z.B.:
1. ... Kd3 2.Tc1 Ke3 3.Tc6 Kd3 4.Dd5 Ke3 5.Se6 f:e6 6.T:e6 Sf7#
1. ... Kc4 2.Ta3 Kc5 3.De4 Kc4 4.Tf3 Kc5 5.Sf5 g:f5 6.T:f5 Sg6# (2021-02-21)
comment
Keywords: Echo, Symmetrical solution
Genre: s#
FEN: 7n/5p2/5Pp1/4K1P1/3N2B1/2k5/1R2Q3/R7
Input: Frank Müller, 2011-12-30
Last update: James Malcom, 2021-02-23 more...
10 - P1242745
Joachim Reiners
936 Freie Presse (Chemnitz) 28/03/1969
P1242745
(6+6) C+
#2
1. De6+? Txe6!
1. Da3? Lb4!
1. Dg3?,Dh2? Lf4!
1. Dh6? Lxh6!
1. Dh7? Lc1,L~

1. Dd7+! Tcxd7 2. Sc8#
1. ... Texd7 2. Se8#
1. ... Scxd7 2. Se4#
1. ... Sexd7 2. Sc4#
play all play one stop play next play all
SCHRECKE: C+, popeye 4.87 (2022-01-21)
comment
Keywords: Symmetrical solution
Genre: 2#
Computer test: popeye 4.87
FEN: 3B4/2r1r3/1N1k1N2/2nPn3/8/7Q/3b4/3K4
Reprints: Die Schwalbe 59, p. 476, 10/1979
Input: Felber, Volker, 2012-06-22
Last update: Dieter Berlin, 2022-01-21 more...
11 - P1242933
Jacob Schumer
10246 Deutsches Wochenschach 23/07/1911
P1242933
(11+8) C+
s#4
1. Kd6! c5 2. Ke5 cxd4 3. Sa3+ Kxe3 4. Sxc4+ Sxc4#
1. ... e5 2. Kc5 exd4 3. Sg3+ Kxc3 4. Sxe4+ Sxe4#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.2a, Brute Force (2022-03-21)
comment
Keywords: Symmetrical solution
Genre: s#
FEN: 8/1p1K1p2/1Pp1pR2/8/2pPp3/2PkP3/2NnN3/1Q1R1B2
Input: Frank Müller, 2012-06-23
Last update: Marcin Banaszek, 2022-03-25 more...
12 - P1243461
Adolph Decker
8764 Deutsches Wochenschach 23/05/1909
P1243461
(9+4) cooked
s#6
1. Da2 Ke3 2. Ke5 Kf3 3. Dh2 Ke3,Kg4 4. f5 Kf3 5. Dg2+ Ke3 6. Sd6 exd6#
1. Da2 Kg3 2. Kg5 Kf3 3. Dd2 Kg3,Ke4 4. f5 Kf3 5. De2+ Kg3 6. Sh6 gxh6#
play all play one stop play next play all
SCHRECKE: Nebenlösung
1.Ke5 Kg3 2.Dg1+ Kf3 3.Dh2 Ke3,Kg4 4.f5 Kf3 5.Dg2+ Ke3 6.Sd6 e:d6#
2. ... Kh4 3.Dh2+ Kg4 4.f5 ...
1. ... Kg4 2.Df2 K:h5 3.f5 Kg4 4.Dh2 Kf3 5.Dg2+ Ke3 6.Sd6 e:d6# (2021-02-15)
comment
Keywords: Echo-Manöver, Symmetrical solution, Quasi-symmetrical position
Genre: s#
FEN: 5b2/Q3pNp1/4P1P1/3P1K1P/5P2/5k2/8/5B2
Input: Frank Müller, 2012-06-30
Last update: A.Buchanan, 2021-02-15 more...
13 - P1249790
Michel Olausson
Springaren (69) 05/1997
P1249790
(8+8) cooked
h==5
1. hxg1=L axb8=L 2. Ta7 Th2 3. gxh2 bxa7 4. h1=T a8=T 5. h2 a7==
play all play one stop play next play all
Cook: 1. hxg1=L Th2 2. gxh2 axb8=L 3. Ta7 bxa7 4. h1=T a8=T 5. h2 a7==
t/Figuren-Kranz 3×3 2-fach a6c8 und f1h3
Bernd Schwarzkopf: Popeye 4.79 findet eine Zugumstellung:
1.hxg1=L Th2 2.gxh2 axb8=L 3.Ta7 bxa7 4.h1=T a8=T 5.h2 a7==
1.hxg1=L axb8=L 2.Ta7 Th2 3.gxh2 bxa7 4.h1=T a8=T 5.h2 a7==
(Auch Lösungsprogramme lernen dazu!) (2018-09-06)
Henrik Juel: Popeye 4.61 also found the cook (in a couple of minutes)
Maybe the original C+ label is just an error; I see no reason why Popeye 3.56 should be different in this respect (2018-09-06)
James Malcom: Fixed. (2020-12-31)
A.Buchanan: "Under"-promotion is meaningless - except of course for direct mates and endgame studies. I always remove it if I have the time (2020-12-31)
Hans-Jürgen Manthey: Total Kaputt, jeder der 12 möglichen Züge ist eine Lösung:
1. fxLg1D,T,L,S Tx~g1 2. h1L cxLb8L 3. g2+ Kf2 4. Txa7 Lh2 5. Tc7 bxTc7=
2. h1S Tg2 3. f2 axLb8D,T,L,S 4. Tx~b8 a7 5. h2 axTb8S,L=
2. f2 Th1 3. Txa7 cxLb8L 4. T~7 Lxg3 5. Tc7 bxTc7=
1. hxg1D,T,L,S Tx~g1 2. g2+ Kxf2 3. h2 Kxf3 4. h1L axLb8S 5. Txa6 SxTa6=
1. g2+ Kxf2 2. gxTh1D Lxh2 3. Da1 axLb8S 4. Dxa6 SxDa6 5. Ta7 bxTa7=
1. Txa7 Lxf2 2. gxLf2 Kxf2 3. Txa6 Txh2 4. Ta7 cxLb8 5. Tc7 LxTc7=
1. Lxa7 Lxf2 2. g2+ Ke1 3. g1L bxLa7 4. Lxf2+ Kxf2 5. Tb8 aXTb8L=
1. Lxc7 Lxf2 2. gxLf2 Kxf2 3. Lg3+ Kxf3 4. Lc7 bxLc7 5. Tb8 axTb8L=
mit sehr vielen Dualen
Kürzer zB: in 4 Zügen:
1. fxLg1L cxLb8L 2. f2 Lxg3 3. Tb8 Lc7 4.Txb6 LxTb6=
1. hxLg1L cxLb8L 2. Lh2 Lxg3 3. Txa7 LxLh2 4.Ta7-c7 bxc7=
1. Bg2+ Kxf2 2.Txa7 Txh2 3.Tb7 c7xLb8~ 4.KxLb8 ax/cxb7=
1. Txa7 Lxf2 2.Bxf2 Kxf2 3.Tb7 c7xLb8~ 4.KxLb8 ax/cxb7=
1. Lxa7,c7 Lxf2,h2 2.gxLf2,h2 bxLa7,c7 3.Tb8 axTb8L=
auch mit vielen Dualen
gar in schon 3 Zügen:
1. Txa7 Lxf2,h2 2. g3xLf2,h2 cxLb8L 3.Tc7 bx/LxTc7=
1...cxb8L 2.Tc7 Lxf2,xh2 3.Bg3xLf2,h2 b6x/Lxc7=
1.Lb8xa7 Lxf2,xh2 2.Bg3xLf2,xh2 bxLa7 3.Tb8 axTb8L=
2.Tb8 bxLa7 3.g3xLf2,h2 axb8L=
1...bxLa7 2.Tb8 Lxf2,h2 3.gxLf2,h2 a7xb8L=
1.Lxc7 Lg1xf2,h2 2.Bg3Lxf2,h2 bxLc7 3.Tb8 axTb8L=
2.Tb8 bxLc7 3.gxLf2,h2 axTb8L=
2...axTb8L 3.gxLf2,h2 bx/LxLc7=
1...bxc7 2.Tb8 Lxf2,h2 3.gxLf2,h2 axTb8L= (2020-12-31)
SCHRECKE: Hans-Jürgen, die Forderung lautet h==5 (nicht h=5!) (2020-12-31)
Hans-Jürgen Manthey: OHHH Im so Sorry (2021-01-02)
comment
Keywords: Promotion (LlTt), Symmetrical position, Symmetrical solution
Genre: Fairies
Computer test: %Popeye UNIX32-Version 3.56
FEN: rbk5/P1P5/PPP5/8/8/5ppp/5p1p/5KBR
Input: Erich Bartel, 2012-09-23
Last update: A.Buchanan, 2020-12-31 more...
14 - P1260390
Anatoly N. Skripnik
C11016 The Problemist 05/2012
P1260390
(2+3)
#6
1. Kc6 Kb8 2. Kb6 Sd6 3. Db4 Sc8+ 4. Kc6+ Sb6 5. Dxb6+ Kc8 6. Dc7#
5. ... Ka8 6. Db7#
1. ... Ka7 2. Kc7 Sc5 3. De7 usw.
play all play one stop play next play all
Anton Baumann: C+ Gustav 4.2a (2023-02-21)
comment
Keywords: Aristocrat, Minimal, Symmetrical position, Symmetrical solution, Oneliner
Genre: n#
FEN: k7/1n6/8/3K4/4Q3/5n2/8/8
Input: Frank Müller, 2013-01-20
Last update: Felber, Volker, 2013-05-24 more...
15 - P1318027
Virgil Nestorescu

1. ehrende Erwähnung
Czerniak Memorial 1986
P1318027
(3+4)
Gewinn
b) sSa2->b3
a) 1. b5! Kb3 2. Te2 Sb4 3. Te3+ Ka4 4. Kc4 Sc2 5. Txe4 Sa3+ 6. Kc3+ Ka5 7. Kb3 Sxb5 8. Ta4#
3. Txe4? Sc2+ 4. Kd5 Sb4+ 5. Kd6 Ka4 6. Te5 Ka5 7. Kc7 Sc2 8. Kb7 Sb4 remis
2. ... Sc1 3. Te1! Sd3 4. Txe4 Sc5 5. Te1 Ka4 6. Tb1 gewinnt

b) 1. Kc3? b5! Zugzwang 2. Te2 Sc1 3. Te3 Sd3! 4. Txe4 Sb2 remis
2. Tb2 Sc1 3. Kc2 Sd3 4. Tb3+ Ka4 5. Kc3 Sc1 6. Tb2 Ka3 remis

1. Kc4! b5+ 2. Kc3 e3 3. Te2 Sc1 4. Txe3 Sa2+ 5. Kc2+ Ka4 6. Kb2 Sxb4 7. Ta3#
3. ... Sd2 4. Txe3 Sb1+ 5. Kc2+ usw.
4. ... Sc4 5. Te1!
play all play one stop play next play all
Anton Baumann: NL in b): 1.Kc3! b5 2.Te2 Sc1 3.Te3 Sd3 4.Kc2!! (fesselt den Springer) K~ 5.Txe4 +- nach Nalimov
zB. 4. ...Ka2 5.Txe4 Sb2 6.Te3 Sc4 7.Th3 Sb6 8.Th5 Sc4 9.Kc3 Sd6 10.Te5 Kb1(Sc4?) 11.Kb3 Kc1 12.Tc5+ Kd2 13.Td5+ +- (2022-04-09)
comment
Keywords: Chameleon Echo, Reciprocal Zugzwang, Symmetrical solution
Genre: Studies
FEN: 8/8/1p6/8/1P1Kp3/k7/n1R5/8
Input: Rainer Staudte, 2016-03-06
Last update: Alfred Pfeiffer, 2019-07-18 more...
16 - P1334387
Reinhardt Fiebig
18524 Schach , p. 79, 02/2017
P1334387
(3+12) C+
h#2
6.1...
1) 1. Kc4 Ta8 2. Kb3 Da2#
2) 1. Ke4 Tg8 2. Kf3 Dg2#
3) 1. Lb5 Txd6+ 2. Kc5 Dxd4
4) 1. Lf5 Txd6+ 2. Ke5 Dxd4#
5) 1. Kc6 Da2 2. Kb7 Da8#
6) 1. Ke6 Dg2 2. Kf7 Dg8#
play all play one stop play next play all
Stefan Felber: Schlüsselwort muß 'Königsstern' lauten. (2021-05-04)
comment
Keywords: Symmetrical position, Symmetrical solution, Echo, Königskreuz
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 3R4/2pbp3/1p1n1p2/3k4/1p1n1p2/2p1p3/3Q4/3K4
Input: Felber, Volker, 2017-05-29
Last update: Felber, Volker, 2017-05-29 more...
17 - P1358607
Eberhard Schulze
88b Amberger Zeitung 10/01/2015
P1358607
(5+1) C+
#4
b) wKf6->c3
a) 1. Tf1+! Kh2 2. Tgg1 Kh3 3. Tf2 Kh4 4. Th2#
b) 1. Th3+! Kg1 2. Tfh2 Kf1 3. Tg3 Ke1 4. Tg1#
play all play one stop play next play all
Optisch mag das eine Spiegelung sein. Von mir ist das aber nicht beabsichtigt, wie mein Lösungsverlauf deutlich zeigt. Also ist mir hier dieses Schlüsselwort nicht passend.ES
more ...
comment
Keywords: Rex solus (s), Symmetrical solution, Checking key, Stalemate dissolution, Miniature
Genre: n#
Computer test: a)+b): C+, Gustav 4.1d, Brute Force
FEN: 8/8/5K2/8/6P1/6R1/4PR2/7k
Input: Rainer Staudte, 2018-12-10
Last update: Felber, Volker, 2023-06-30 more...
18 - P1380996
Otto Oppenheimer
8 Aufbau (New York) 18/06/1943
P1380996
(5+2) C+
#2
1. Dg7! (Zugzwang)
1. ... Kd4 2. Dxf6#
1. ... Kxf4 2. Dg3#
1. ... Kxd6 2. Dc7#
play all play one stop play next play all
more ...
comment
Keywords: Symmetrical position, Symmetrical solution, Aristocrat
Genre: 2#
Computer test: popeye 4.85
FEN: 7Q/8/3N1r2/4k3/5N2/2R5/8/K7
Input: Mario Richter, 2020-10-16
Last update: Alfred Pfeiffer, 2020-10-16 more...
19 - P1389654
Otto Trinks
20 Bote von der Ybbs 07/03/1930
nach W.J. Baird
P1389654
(5+1) C+
#3
2 Lösungen
1) 1. Se7! droht 2. Te1#
1. ... Ke5 2. Tb6 Ke4 3. Te6#

2) 1. Sh4! droht 2. Tb4#
1. ... Kf4 2. Tg1 Ke4 3. Tg4#
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bei der Bairdschen Vorlage handelt es sich vermutlich um P1144237

Beim Abdruck im 'Boten von der Ybbs' Forderung nur "Matt in drei Zügen", bei den Lösungen (21.03.1930): "Beabsichtigte Doppellösung (sogenannter 'Zweispänner') 1. Sc6-e7 und 1. Sg2-h4." (Die Aufgabe war Teil eines Lösewettbewerbs, bei dem es für gefundene NLs Extrapunkte gab, die "beabsichtigten" 2 Lösungen waren also evtl. ein Test für die Löser)
Henrik Juel: No asymmetry... (2021-05-16)
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comment
Keywords: Rex solus (s), Aristocrat, Symmetrical position, Miniature, Flight giving and taking key, Symmetrical solution
Genre: 3#
Computer test: C+ Popeye 4.61
FEN: 8/8/2N5/8/4k3/3R4/2K3N1/1R6
Input: Mario Richter, 2021-05-16
Last update: Alfred Pfeiffer, 2021-08-17 more...
20 - P1398982
Werner Keym
Die Zeit 2020
P1398982
(5+1)
#2
1. De5? Kxd7,Kxf7 2. e8=D#
aber Schwarz hatte zuletzt keinen Zug, also
0) 1. ... Kxd7,Kxf7! e8=D+ 2. Kd6,Kf6 D2e5#
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Letztform eines symmetrischen Sechssteiners mit schwarzem Anzug.
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comment
Keywords: Miniature, Homebase, Rex solus (s), Promotion (D), Symmetrical position, Symmetrical solution
Genre: 2#
Computer test: C+ Popeye 4.61 (it is obvious that Black has the move)
FEN: 4k3/3RPR2/8/8/8/8/4Q3/4K3
Input: Alfred Pfeiffer, 2022-02-09
Last update: A.Buchanan, 2022-02-10 more...
21 - P1399112
Werner Kuntsche
Valery Liskovets
Andrew Buchanan

PDB Website 14/02/2022
WK, correction AB
P1399112
(5+8) C+
h#3 AP

No solutions except for those beginning with e.p.
297 candidate solutions begin 1.gxf3ep, but only one includes castling. Queenside 2. ... 0-0-0
22 candidate solutions begin 1.fcxd3ep, but only one includes castling. Kingside 2. ... 0-0
In some way, these are trying to be combined so that from AP perspective, White's last move can only have been double hop with wBd or wBf.
We need a clear delineation of the precise PRA-AP algorithm to be followed.

The point: if this problem is "sound", then surely P1382808 is "unsound", because there only one of the two parts needs to prove that White castling rights remain, so there are 4 cooks.
This is an important schema for AP. Previous cooked problems P0002476 & P0004295 (together with versions of each lacking sBe3) had multiple chess cooks that do not involve e.p. as key. This chessically sound composition allows us to focus on the fundamental theoretical issue of AP.

The double e.p. idea cannot work as an AP retro strategy problem, because one can never prove that one double pawn hop rather than the other occurred. PRA+AP seems potentially feasible, but I see no clear statement of how the normal PRA method should be extended to this case. All prescriptive suggestions are welcome.

In WinChloe, I found a correction from 2002 by Valery Liskovitz, just posted in PDB as P1401449. However it used three extra pawns, rather than 2, so the current version still has merit, but I will add Valery as co-corrector.

See also P1399178.
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comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key (2), Symmetrical position, Symmetrical solution, Castling (wb)
Genre: h#, Retro
Computer test: HC+ Forward play proved by Popeye v4.87 AP logic requires some framework but I think we know we want this cool idea to end up being sound.
FEN: 8/8/2p3p1/8/2pPkPp1/2n1p1n1/8/R3K2R
Input: A.Buchanan, 2022-02-14
Last update: A.Buchanan, 2022-05-24 more...
22 - P1403724
Claus Grupen
1628 Kieler Nachrichten 1971
P1403724
(7+6)
#2
1. c4! dxc4 2. Sxc4#
1. ... dxe4 2. Sxe4#
1. ... b5 2. c5#
1. ... c5 2. Sb5#
1. ... e5 2. Sf5#
1. ... f5 2. e5#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61 also (2022-08-19)
comment
Keywords: Pawn mate, Symmetrical position (nach Schlüssel), Symmetrical solution
Genre: 2#
Computer test: Gustav 4.1 a
FEN: 3K4/3B4/1ppkpp2/3p4/3BP3/N5N1/2P5/8
Input: Gunter Jordan, 2022-08-18
Last update: Gunter Jordan, 2022-08-18 more...
23 - P1406913
Miroslav Svitek
Zhiguliovskiye zori 2011
Lob
P1406913
(3+2)
#3
1. De5! Kg8 2. De8+ Kh7 3. Dg6#
2. ... Kg7 3. Dg6#,Df7#
1. ... Kh7 2. Dh5+ Kg8 3. Df7#
2. ... Kg7 3. Df7#,Dg6#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61, except for two mate duals (2022-12-29)
comment
Keywords: Symmetrical position, Symmetrical solution, Minimal (l), Aristocrat, Oneliner
Genre: 3#
FEN: 7b/6k1/5R2/8/3Q4/8/8/K7
Input: Rainer Staudte, 2022-12-29
Last update: Gunter Jordan, 2022-12-29 more...
24 - P1407350
Ivar Godal
207 Østlendingen 05/01/1960
P1407350
(3+2)
#3
1. e4 Kd8 2. Tc1 Ke8 3. Tc8#
1. ... Kf8 2. Tg1 Ke8 3. Tg8#
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SCHRECKE: Forderung: #3 / Genre: 3#
C+, popeye 4.87 (2023-01-20)
comment
Keywords: Symmetrical position, Symmetrical solution, Oneliner, Minimal (b), Miniature
Genre: 3#
FEN: 4k3/8/4K3/4p3/8/8/4P3/4R3
Input: Rainer Staudte, 2023-01-20
Last update: Rainer Staudte, 2023-01-20 more...
25 - P1407363
Albert Goetze
722 Dresdner Volkszeitung 02/11/1932
P1407363
(4+4)
#3
1. De7! Kd4 2. Dc5+ Ke4 3. De3#
1. ... Kf4 2. Dg5+ Ke4 3. De3#
1. ... d4 2. Db7+ Kf4 3. Df3#
1. ... f4 2. Dh7+ Kd4 3. Dd3#
play all play one stop play next play all
SCHRECKE: C+, popeye 4.87 (2023-01-21)
comment
Keywords: Symmetrical position, Symmetrical solution
Genre: 3#
FEN: 4Q3/8/8/3ppp2/1P2k2P/8/4K3/8
Input: Rainer Staudte, 2023-01-21
Last update: Rainer Staudte, 2023-01-21 more...
26 - P1408728
Dieter Müller
Tribüne
P1408728
(4+4)
#2
* 1. ... Kc5 2. Da5#
1. ... Ke5 2. Dg5#

1. Dd3! Kc5 2. Dc4#
1. ... Ke5 2. De4#
1. ... c5 2. De4#
1. ... e5 2. Dc4#
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Würde Schwarz beginnen mit z. B. 1. ... Ke5/Kc5, stehen die Matts 2. Dg5/Da5 bereit. Nach dem Schlüssel sieht man auf die gleichen Königszüge andere Matts. Auf jeden Fall: immer Symmetrie.
SCHRECKE: C+, popeye 4.87 (2023-04-07)
comment
Keywords: Symmetrical solution, Changed mates
Genre: 2#
FEN: 2N5/8/2pNp1K1/3k4/3b4/8/3Q4/8
Input: Rainer Staudte, 2023-04-06
Last update: Rainer Staudte, 2023-04-07 more...
27 - P1414367
Paul Wenman
104 Two Hundred Assorted Problems , p. 28, 1945
P1414367
(10+8) C+
#2
1. Dd2! dxc2 2. e4#
1. ... dxe2 2. c4#
1. ... e4 2. Dg5#
1. ... c4 2. Da5#
1. ... Sxb6+ 2. Sxb6#
1. ... Sa7 2. Se7#
1. ... Sxf6+ 2. Sxf6#
1. ... Sg7 2. Sc7#
play all play one stop play next play all
more ...
comment
Keywords: Zugzwang-Goal, pin-mate (zweifach), ambush key, Switchback, Symmetrical solution, Epaulettenmatt, Pawn mate, Symmetrical position (nach Schlüssel)
Genre: 2#
Computer test: Juel: Popeye 4.61
FEN: N1n1n1N1/3K4/1P1p1P2/2pkp1Q1/3p4/1P1p1P2/2P1P3/8
Input: Dieter Berlin, 2024-01-07
Last update: Dieter Berlin, 2024-01-07 more...
28 - P1415284
Claus Grupen
2014/63 Schach in Schleswig-Holstein 2014
P1415284
(7+8)
#5
1. Dd3! Kc6 2. Db5+ Kd5 3. Dxb3+ Kc6 4. Sf5 ... 5. Se7#
4. ... c4 5. Db5#
4. ... d5 5. Db5,Db6# (Dual)
1. ... Ke6 2. Df5+ und weiter symmetrisch wie oben
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Henrik Juel: Popeye 4.61 found no solution (2024-02-26)
SCHRECKE: Es fehlen: wBb2+wBf2 (2024-02-26)
Gunter Jordan: ... ja, tatsächlich. Die beiden Bauern fehlen. Danke für den Hinweis - ich habe es korrigiert. (2024-02-27)
Henrik Juel: now C+ Popeye 4.61, except for the mate duals (2024-02-27)
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comment
Keywords: Changed continuation, Switchback (k), Symbol problem (Weihnachtsbaum), Symmetrical position, Symmetrical solution
Genre: n#
FEN: 3B4/3p4/3p4/2pkp3/3b4/Np3pN1/1P1Q1P2/3K4
Input: Gunter Jordan, 2024-02-26
Last update: Gunter Jordan, 2024-02-27 more...
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The problems of this query have been registered by the following contributors:

Gerd Wilts (2)
Frank Müller (7)
Zuncke/Bruder (1)
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