44 problem(s) found in 3341 milliseconds (displaying 44 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT K='Funktionswechsel' AND K='Letzter Zug?'] [download as LaTeX]
R: 1. Kg8xDh8
Solved in YouTubex httx//www. youtube. com/watch?v=Do_rkLQnrpk
Solved in YouTubex httx//www. youtube. com/watch?v=Do_rkLQnrpk
Keywords: Type A, Last Move? (KxD), Economy record (Last Move? Type A), Type B (a fortiori), Economy record (Last Move? Type B), Minimal
Genre: Retro
Computer test: Solved in YouTube: https://www.youtube.com/watch?v=Do_rkLQnrpk
FEN: 3bkN1K/pppprp1p/4p1p1/8/8/8/8/8
Reprints: 1372 FEENSCHACH 08-09/1952
Problem 10-12 12/1952
1.2A Eigenartige Schachprobleme , p. 172, 2010
1.2B Eigenartige Schachprobleme , p. 172, 2010
YouTube 13/02/2022
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-01 more...
Genre: Retro
Computer test: Solved in YouTube: https://www.youtube.com/watch?v=Do_rkLQnrpk
FEN: 3bkN1K/pppprp1p/4p1p1/8/8/8/8/8
Reprints: 1372 FEENSCHACH 08-09/1952
Problem 10-12 12/1952
1.2A Eigenartige Schachprobleme , p. 172, 2010
1.2B Eigenartige Schachprobleme , p. 172, 2010
YouTube 13/02/2022
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-01 more...
2 - P0000957
Theophilus Harding Willcocks
Die Schwalbe 1959
Willcocks 1959, version
(4+8)
Letzter Zug?
Theophilus Harding Willcocks
Die Schwalbe 1959
Willcocks 1959, version
(4+8)
Letzter Zug?
R: 1. a7xTb8=L
See P1409984.
Yoav Ben-Zvi: WBd8 can be replaced with a BN after moving BPg7 to f7 and BPh5 to h6. (2018-08-08)
A.Buchanan: Yes after all these years, I found this a few months ago, but when I told Thomas Brand, he said that Werner Keym had found it - one of a series of modifications through seeking to avoid non-standard material. (2018-08-12)
Henrik Juel: Werner's improvement can be found in his 'Eigenartige Schachprobleme' from 2010, p.196, dia 1.68 (2018-08-12)
A.Buchanan: I thought it was more recent (2018-08-12)
A.Buchanan: In fact Werner was not trying to avoid non-standard material, but to prefer "cheaper" knights over bishops. But this is not the canonical ordering, which regards knights and bishops as equivalent. So the older record will win out in classical terms. (2019-10-04)
A.Buchanan: And non-standard material is no defect, according to the 1977 grading criteria, so old Theophilus reigns supreme (2019-10-04)
Henrik Juel: The further retroplay is
-1... h6 -2.a6 and e.g. -2... Ka7 -3.a5 Ta8 -4.Tb8 Ka6 -5.Kc8
and wK out via g6 (2019-10-04)
A.Buchanan: I don't know if a bishop is more expensive than a knight for these economy records. If modifying the criteria, I personally would prefer to minimize non-standard material. But more generally, how to handle a later version of economy record, with similar force? In some cases, the change is trivial, just transforming one unit which might as well be a dummy. At the other extreme, the matrix is completely different. In "Eigenartige Schachprobleme", Werner Keym stoically prefers the earlier record. Even the original composer(s) of a record problem are forbidden from making any artistic improvement to a published economy record! Over the years, the only change to the grading criteria is that Type C problem now needs to contain a check. Any old check-free Type C would a fortiori have been a Type B economy record at least. Here in PDB, I've tagged some cases of "ex-aequo" (search k='economy:eq') but I fear that Werner would not approve of this. What should we do? (2022-03-31)
more ...
comment
Yoav Ben-Zvi: WBd8 can be replaced with a BN after moving BPg7 to f7 and BPh5 to h6. (2018-08-08)
A.Buchanan: Yes after all these years, I found this a few months ago, but when I told Thomas Brand, he said that Werner Keym had found it - one of a series of modifications through seeking to avoid non-standard material. (2018-08-12)
Henrik Juel: Werner's improvement can be found in his 'Eigenartige Schachprobleme' from 2010, p.196, dia 1.68 (2018-08-12)
A.Buchanan: I thought it was more recent (2018-08-12)
A.Buchanan: In fact Werner was not trying to avoid non-standard material, but to prefer "cheaper" knights over bishops. But this is not the canonical ordering, which regards knights and bishops as equivalent. So the older record will win out in classical terms. (2019-10-04)
A.Buchanan: And non-standard material is no defect, according to the 1977 grading criteria, so old Theophilus reigns supreme (2019-10-04)
Henrik Juel: The further retroplay is
-1... h6 -2.a6 and e.g. -2... Ka7 -3.a5 Ta8 -4.Tb8 Ka6 -5.Kc8
and wK out via g6 (2019-10-04)
A.Buchanan: I don't know if a bishop is more expensive than a knight for these economy records. If modifying the criteria, I personally would prefer to minimize non-standard material. But more generally, how to handle a later version of economy record, with similar force? In some cases, the change is trivial, just transforming one unit which might as well be a dummy. At the other extreme, the matrix is completely different. In "Eigenartige Schachprobleme", Werner Keym stoically prefers the earlier record. Even the original composer(s) of a record problem are forbidden from making any artistic improvement to a published economy record! Over the years, the only change to the grading criteria is that Type C problem now needs to contain a check. Any old check-free Type C would a fortiori have been a Type B economy record at least. Here in PDB, I've tagged some cases of "ex-aequo" (search k='economy:eq') but I fear that Werner would not approve of this. What should we do? (2022-03-31)
more ...
comment
Keywords: Type A, Last Move? (BxT=L), Promotion (L), Non-standard material (L)
Genre: Retro
FEN: kBRB4/1pKpp1p1/1pp5/7p/8/8/8/8
Reprints: 1.49A Eigenartige Schachprobleme , p. 190, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-02 more...
Genre: Retro
FEN: kBRB4/1pKpp1p1/1pp5/7p/8/8/8/8
Reprints: 1.49A Eigenartige Schachprobleme , p. 190, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-02 more...
3 - P0001030
Jan R. Mortensen
Werner Keym
Die Schwalbe 1984
(3+6)
Welches war der letzte Zug?
Schwarz am Zug
Jan R. Mortensen
Werner Keym
Die Schwalbe 1984
(3+6)
Welches war der letzte Zug?
Schwarz am Zug
R: 1. f7xLg8=T
siehe auch P0001031
Henrik Juel: Source is almost surely Caissa 1979 (CA stopped in 1930) (2020-12-17)
A.Buchanan: According to Werner Keym in ES, the original source is JM+WK Die Schwalbe 1984. That probably means that Werner modified P0001031 to tackle the different task here. I will adjust the source & authors accordingly. For these task problems, no-one tracks versioning, or afters. We just lump together all the composers who lent a hand. (2020-12-18)
Henrik Juel: OK, fine
Of course, this is also an example of First move by promoted Tg8, but not an economy record in this genre (2020-12-18)
A.Buchanan: Any last move which is promotion is implicitly a zero move for a the promoted unit. So I feel probably not worth adding the keyword of first move except for those which were intended as first move records. What do you think? (2020-12-19)
Henrik Juel: The same position with wSg8 was similar, but it was a double economy record, I think
The position with wTg8 is a last move record, but not a first move record, as removing Th7 and moving Ph6 to h7 is more economical
The first move problems with a zero move are not very impressive, so your approach is fine (2020-12-19)
comment
Henrik Juel: Source is almost surely Caissa 1979 (CA stopped in 1930) (2020-12-17)
A.Buchanan: According to Werner Keym in ES, the original source is JM+WK Die Schwalbe 1984. That probably means that Werner modified P0001031 to tackle the different task here. I will adjust the source & authors accordingly. For these task problems, no-one tracks versioning, or afters. We just lump together all the composers who lent a hand. (2020-12-18)
Henrik Juel: OK, fine
Of course, this is also an example of First move by promoted Tg8, but not an economy record in this genre (2020-12-18)
A.Buchanan: Any last move which is promotion is implicitly a zero move for a the promoted unit. So I feel probably not worth adding the keyword of first move except for those which were intended as first move records. What do you think? (2020-12-19)
Henrik Juel: The same position with wSg8 was similar, but it was a double economy record, I think
The position with wTg8 is a last move record, but not a first move record, as removing Th7 and moving Ph6 to h7 is more economical
The first move problems with a zero move are not very impressive, so your approach is fine (2020-12-19)
comment
Keywords: Last Move? (BxL=T), Type B, Promotion (T), Economy record (Last Move? Type B)
Genre: Retro
FEN: k4bRK/4p1pR/5p1p/8/8/8/8/8
Reprints: 1.45B Eigenartige Schachprobleme , p. 188, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-30 more...
Genre: Retro
FEN: k4bRK/4p1pR/5p1p/8/8/8/8/8
Reprints: 1.45B Eigenartige Schachprobleme , p. 188, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-30 more...
4 - P0001031
Jan R. Mortensen
Deutsche Schachrundschau Caissa 1979
(3+6)
Welches war der letzte Zug?
Schwarz am Zug
(Erster Zug des wUWS?)
Jan R. Mortensen
Deutsche Schachrundschau Caissa 1979
(3+6)
Welches war der letzte Zug?
Schwarz am Zug
(Erster Zug des wUWS?)
R: 1. f7xLg8=S
Henrik Juel: Not R: 1.f7xSg8=S,
because the black knight can be extracted only by retracting f7-f6, trapping white king (2020-12-13)
A.Buchanan: Some brave person should sort out the keywords for record retros properly. Here's a good example. The last move is Type B, but the first move question is Type A. The original stipulation (which I think is just about the first move?) should stand. The first move question is a *deemed* stipulation (new terminology) and allows us to leverage an existing problem, without creating a new version or editing the prior stipulation. This is particularly true here, since the problems are of different type. (2020-12-14)
Hans-Jürgen Manthey: mögliche Retro-Zugfolge:
1.f7xLg8S Ka7-a8 2. e6xSf7 Sd6-f7+ 3. e5-e6 Le6-g8 4. Kg8-h8 Lc8-e6+ 5. Th8-h7 Ka8-a7 6. Kh7-g8 Kb7-a8 7. Kg6-h7 Kc7-b7 8. h7-h8T Kd8-c7 9. d4xSe5 Sd7-e5+ 10. Kf5-g6 Sf7-d6+ 11. g6xTh7 Th8-h7 12. g5-g6 h7-h6 13. Ke6-f5 Sh6-f7 14. g4-g5 Sg8-h6 15. e3xTd4 Ta4xSd4 16. f2xDe3 Dd2-e3+ 17. g2-g4 Ke8-d8 18. Kf5-e6 De2xd2 19. Ke4-f5 Dd1xe2+ 20. Kd3-e4 Df1xTd1 21. Sf3-d4 Dh1xLf1 22. Kc2-d3 Sb8-d7 23. Kc1-c2 Dh2xTh1 24. O-O-O Dc7xh2 25. Sg1-f3 Ta8xDa4 26. Dd1-a4+ Dc2-c7 27. Se6-c7+ Dc1xc2 28. Sc5-e6 Db2xLc1 29. Sd7-c5 Da2xb2 30. Se5xd7 Da5xa2 31. Sc6-e5 f7-f6 32. a7xc6 Dd8-a5 33. Sb5xa7 c7-c6 34. Sc3xb5 b7-b5 35. Sb1-c3 (2020-12-17)
Henrik Juel: 'The Chess Amateur 1979' must be wrong, as this magazine stopped in 1930 (2020-12-17)
Henrik Juel: .. and Eigenartige Schachprobleme just says Caissa 1979 (2020-12-17)
A.Buchanan: WinChloe does not have this problem at all! I am inclined to go with Eigenartige Schachprobleme. I suspect that Gerd was entering hundreds of compositions at scale, and a copy-paste error would be easy (2020-12-17)
A.Buchanan: Also P0001030 (2020-12-17)
A.Buchanan: Have removed "The Chess Amateur" as original source here. (2020-12-18)
comment
because the black knight can be extracted only by retracting f7-f6, trapping white king (2020-12-13)
A.Buchanan: Some brave person should sort out the keywords for record retros properly. Here's a good example. The last move is Type B, but the first move question is Type A. The original stipulation (which I think is just about the first move?) should stand. The first move question is a *deemed* stipulation (new terminology) and allows us to leverage an existing problem, without creating a new version or editing the prior stipulation. This is particularly true here, since the problems are of different type. (2020-12-14)
Hans-Jürgen Manthey: mögliche Retro-Zugfolge:
1.f7xLg8S Ka7-a8 2. e6xSf7 Sd6-f7+ 3. e5-e6 Le6-g8 4. Kg8-h8 Lc8-e6+ 5. Th8-h7 Ka8-a7 6. Kh7-g8 Kb7-a8 7. Kg6-h7 Kc7-b7 8. h7-h8T Kd8-c7 9. d4xSe5 Sd7-e5+ 10. Kf5-g6 Sf7-d6+ 11. g6xTh7 Th8-h7 12. g5-g6 h7-h6 13. Ke6-f5 Sh6-f7 14. g4-g5 Sg8-h6 15. e3xTd4 Ta4xSd4 16. f2xDe3 Dd2-e3+ 17. g2-g4 Ke8-d8 18. Kf5-e6 De2xd2 19. Ke4-f5 Dd1xe2+ 20. Kd3-e4 Df1xTd1 21. Sf3-d4 Dh1xLf1 22. Kc2-d3 Sb8-d7 23. Kc1-c2 Dh2xTh1 24. O-O-O Dc7xh2 25. Sg1-f3 Ta8xDa4 26. Dd1-a4+ Dc2-c7 27. Se6-c7+ Dc1xc2 28. Sc5-e6 Db2xLc1 29. Sd7-c5 Da2xb2 30. Se5xd7 Da5xa2 31. Sc6-e5 f7-f6 32. a7xc6 Dd8-a5 33. Sb5xa7 c7-c6 34. Sc3xb5 b7-b5 35. Sb1-c3 (2020-12-17)
Henrik Juel: 'The Chess Amateur 1979' must be wrong, as this magazine stopped in 1930 (2020-12-17)
Henrik Juel: .. and Eigenartige Schachprobleme just says Caissa 1979 (2020-12-17)
A.Buchanan: WinChloe does not have this problem at all! I am inclined to go with Eigenartige Schachprobleme. I suspect that Gerd was entering hundreds of compositions at scale, and a copy-paste error would be easy (2020-12-17)
A.Buchanan: Also P0001030 (2020-12-17)
A.Buchanan: Have removed "The Chess Amateur" as original source here. (2020-12-18)
comment
Keywords: Last Move? (BxL=S), Type B, Promotion (S), Economy record (Last move? Type B), First Move? (US0), Type A, Economy record (First move? Type A)
Genre: Retro
Computer test: RSP 1.2
FEN: k4bNK/4p1pR/5p1p/8/8/8/8/8
Reprints: The Chess Amateur 1979
1.55B Eigenartige Schachprobleme , p. 192, 2010
2.51 Eigenartige Schachprobleme , p. 202, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-30 more...
Genre: Retro
Computer test: RSP 1.2
FEN: k4bNK/4p1pR/5p1p/8/8/8/8/8
Reprints: The Chess Amateur 1979
1.55B Eigenartige Schachprobleme , p. 192, 2010
2.51 Eigenartige Schachprobleme , p. 202, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-30 more...
5 - P0001086
Peter Kahl
Jan R. Mortensen
Sveto Stambuk
Problem 5-6, p. 92, 12/1951
6. ehrende Erwähnung
(4+1)
Welches war der letzte Zug?
Peter Kahl
Jan R. Mortensen
Sveto Stambuk
Problem 5-6, p. 92, 12/1951
6. ehrende Erwähnung
(4+1)
Welches war der letzte Zug?
R: 1. Dh3xSh2+
im Original ist als Dritter Autor D. Suboticanec angegeben, habe entsprechend geändert.
Zu P. Kahl heißt es ergänzend: [aus] Osterholz-Scharmbeck
HBae: Ist "Klaus Peter Kahl" identisch zu "Peter Kahl" ? (2010-09-22)
Henrik Juel: Yes, probably
I know that 'Jan Robert Mortensen' is identical to 'Jan Mortensen'; he never used his middle name (2017-03-08)
A.Buchanan: It’s possible to put the middle name into the “addition” field in the author table, rather than have two names in the “first name” field. Then in overview list the middle name won’t appear, but it will still appear above each composition as here. Curiously the addition field is common across all four languages (German, English, French, Unicode) supported by the author table. There is no comment field to allow for random extra info to be stored, unlike the source table. So if we drop Robert, we lose it completely. (2022-03-31)
Henrik Juel: Thanks for the info, Andrew
I guess we will have to live with it
For Jan, there is really no risk of confusion
But for Knud Hannemann (son of the less illustrious composer Harald Hannemann) it is annoying to see him cast as Knud Harald Hannemann, just because it was a custom in his family that the sons were given the father's first name
They still use this custom in Russia, but with 'son of' added, e.g., Vladimir Vladimirovitch Putin (2022-03-31)
Henrik Juel: A chess problem example is Nikita Michaelovitch Plaksin
But the rendering of his name in the PBD also gives an obvious partial solution to my problem
Change the middle name of the two danish composers to the corresponding initial:
Jan R. Mortensen and Knud H. Hannemann (2022-03-31)
Henrik Juel: Thanks for the 'initialization', Andrew (2022-03-31)
A.Buchanan: OK fixed those, Henrik. HBae's original question concerned "Klaus Peter Kahl" vs "Peter Kahl". The former only has 2 problems here, and "both" collaborated with Jan Mortensen, so surely this is one person? (2022-03-31)
A.Buchanan: Kahls unified (2022-04-01)
Henrik Juel: I hear no protests from Osterholz-Scharmbeck, so that seems fine (2022-04-01)
comment
Zu P. Kahl heißt es ergänzend: [aus] Osterholz-Scharmbeck
HBae: Ist "Klaus Peter Kahl" identisch zu "Peter Kahl" ? (2010-09-22)
Henrik Juel: Yes, probably
I know that 'Jan Robert Mortensen' is identical to 'Jan Mortensen'; he never used his middle name (2017-03-08)
A.Buchanan: It’s possible to put the middle name into the “addition” field in the author table, rather than have two names in the “first name” field. Then in overview list the middle name won’t appear, but it will still appear above each composition as here. Curiously the addition field is common across all four languages (German, English, French, Unicode) supported by the author table. There is no comment field to allow for random extra info to be stored, unlike the source table. So if we drop Robert, we lose it completely. (2022-03-31)
Henrik Juel: Thanks for the info, Andrew
I guess we will have to live with it
For Jan, there is really no risk of confusion
But for Knud Hannemann (son of the less illustrious composer Harald Hannemann) it is annoying to see him cast as Knud Harald Hannemann, just because it was a custom in his family that the sons were given the father's first name
They still use this custom in Russia, but with 'son of' added, e.g., Vladimir Vladimirovitch Putin (2022-03-31)
Henrik Juel: A chess problem example is Nikita Michaelovitch Plaksin
But the rendering of his name in the PBD also gives an obvious partial solution to my problem
Change the middle name of the two danish composers to the corresponding initial:
Jan R. Mortensen and Knud H. Hannemann (2022-03-31)
Henrik Juel: Thanks for the 'initialization', Andrew (2022-03-31)
A.Buchanan: OK fixed those, Henrik. HBae's original question concerned "Klaus Peter Kahl" vs "Peter Kahl". The former only has 2 problems here, and "both" collaborated with Jan Mortensen, so surely this is one person? (2022-03-31)
A.Buchanan: Kahls unified (2022-04-01)
Henrik Juel: I hear no protests from Osterholz-Scharmbeck, so that seems fine (2022-04-01)
comment
Keywords: Type C, Last Move? (DxS), Economy record (Last Move? Type C)
Genre: Retro
FEN: 8/8/8/8/7P/6P1/5K1Q/7k
Reprints: 1375 FEENSCHACH 08-09/1952
(C10) feenschach 160 07-08/2005
1.11C Eigenartige Schachprobleme , p. 176, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-04-01 more...
Genre: Retro
FEN: 8/8/8/8/7P/6P1/5K1Q/7k
Reprints: 1375 FEENSCHACH 08-09/1952
(C10) feenschach 160 07-08/2005
1.11C Eigenartige Schachprobleme , p. 176, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-04-01 more...
6 - P0001185
Zdravko Maslar
(291) Problem 45-48 11/1957
16. TEMATSKOG TURNIRA "PROBLEMA" 1.-2. Preis e.a.
(4+9)
Welches war der letzte Zug?
Zdravko Maslar
(291) Problem 45-48 11/1957
16. TEMATSKOG TURNIRA "PROBLEMA" 1.-2. Preis e.a.
(4+9)
Welches war der letzte Zug?
R: 1. Tc8xDb8
Keywords: Last Move? (TxD), Type B (a fortiori), Type A
Genre: Retro
FEN: BR1rk3/1pKppRp1/1pp2p2/8/8/8/8/8
Reprints: 58 Europe Echecs 36 08/1961
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-22 more...
Genre: Retro
FEN: BR1rk3/1pKppRp1/1pp2p2/8/8/8/8/8
Reprints: 58 Europe Echecs 36 08/1961
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-22 more...
R: 1. 0-0-0
Deemed stipulation: "Erster Zug des wTd1?"
Henrik Juel: White pawns captured all 13 missing black men
Retracting the castling is the only way to give Black a retraction, e.g. Kc2-b3 (2020-12-01)
comment
Henrik Juel: White pawns captured all 13 missing black men
Retracting the castling is the only way to give Black a retraction, e.g. Kc2-b3 (2020-12-01)
comment
Keywords: Type A, Last Move? (0-0-0), Castling (wl), Economy record (Last Move? Type A), First Move? (T0), Economy record (First move)
Genre: Retro
FEN: 8/P1p5/PN6/1P6/P1N5/Pk6/pP6/2KR4
Reprints: 342 Europe Echecs 241 01/1979
1.57A Eigenartige Schachprobleme , p. 194, 2010
1 Die Schwalbe 360-1, p. 737, 12/2020
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-28 more...
Genre: Retro
FEN: 8/P1p5/PN6/1P6/P1N5/Pk6/pP6/2KR4
Reprints: 342 Europe Echecs 241 01/1979
1.57A Eigenartige Schachprobleme , p. 194, 2010
1 Die Schwalbe 360-1, p. 737, 12/2020
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-28 more...
8 - P0001785
Andrey Frolkin
Andrej N. Kornilow
1 Rex Multiplex 27 08/1989
(16+0)
Färbe die Steine!
Welches war der letzte Zug?
Schwarz am Zug
Andrey Frolkin
Andrej N. Kornilow
1 Rex Multiplex 27 08/1989
(16+0)
Färbe die Steine!
Welches war der letzte Zug?
Schwarz am Zug
a) R: 1. Kh4-h3
Keywords: Colouring problem, Kindergarten Problem, Last Move? (K-), Type B, Economy record (Last Move? Type B Co)
Genre: Retro
FEN: 8/8/7K/6PP/4PPP1/3PPPPK/3PPPPP/8
Reprints: (A) feenschach 130 10-12/1998
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-13 more...
Genre: Retro
FEN: 8/8/7K/6PP/4PPP1/3PPPPK/3PPPPP/8
Reprints: (A) feenschach 130 10-12/1998
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-13 more...
9 - P0005279
Yehuda Veisberg
7135 The Fairy Chess Review 105 02/1947
(10+10)
Weiß am Zug. Letzter Zug?
Yehuda Veisberg
7135 The Fairy Chess Review 105 02/1947
(10+10)
Weiß am Zug. Letzter Zug?
R: 1. ... Sd8-e6! 2. b6xLa7 Lb8-a7 3. c5xSb6 Lf4-b8 4. d4xTc5 Lh6-f4 5. e3xTd4 Lf8-h6 6. f2xDe3 g7xLf6 7. Lg5-f6 Df3-e3 8. Lc1-g5 Kc4-b3 9. d2-d3+ ...
Zvi Mendlowitz: This is a *great* problem!
Solution: Sd8-e6 (2004-12-07)
hans: R: -1. … Sd8-e6 -2. b6xLa7 Lb8-a7 -3. c5xSb6 Lf4-b8 -4. d4xTc5 Lh6-f4 -5. e3xTd4 Lf8-h6 -6. f2xDe3 g7xLf6 -7. Lg5-f6 Df3-e3 -8. Lc1-g5 Kc4-b3 -9. d2-d3+ etc.
Other captures: black h7xg6xf5xe4xd3xc2 Captured pieces are random.
It’s *great* that d8 is only square for S. (2013-01-30)
Henrik Juel: Another try, d7-d5 as last move, fails, not because the access for [Lc8] is cut off ([Lc8] could have been captured on c8), but because following -2.b6xLa7 [Ta8] cannot get home when g7xLf6 is retracted (2013-01-30)
Yoav Ben-Zvi: The cage locking element in the try noted above is made thematic through 5-fold Echo
Tries:
-1.Pd7-d5 -- NW cage prevents escape of BRa8 to be captured by WPf2
-1.BPg7xBf6 -- Cage prevents escape of BBf8 to be captured by WPf2
-1.Nc5(d4)-e6 -- Blocks path of White Pa7 to f2
-1… Pb6xBa7 -2.Ne6-c5(d4) Pc5xb6 -3.Bb8-a7 Pd4xc5 -4.Bf4-b8 Pe3xd4 -5.Bh6-f4 Pf2xe3 -6.Bf8-h6
-6…Pd2-d3 -- Cage prevents escape of WBc1 to be captured by BPg7
-6…Pa3-a4 -- SW cage prevents escape of WRa1 to be captured by BPh7
-6…Ph3-h4 -- SE cage prevents escape of WRh1 to be captured by BPh7
Two other Retros by Yehuda Veisberg were printed in "The Israel Problemist" (1964) one from FCR and the other from "The Palestine Post" (2013-01-31)
Mario Richter: For -1.Pd7-d5 and …Pa3-a4 more precisely the reason for the illegality consists in a conflict between the uncapture of a bishop and a rook. (2013-02-01)
A.Buchanan: A satisfyingly unified little problem with precise tempo. WQR cannot be captured on c2 inside the White cage, since c2 is surrounded by dark-squared White units prior to Pd2-d3. BQR cannot be captured on a7 inside the Black cage, since BKB is too slow to reach any square for capture apart from a7 right at the end of the line. (2013-02-03)
Henrik Juel: It is nice to review this fine retro (although it would be even better, if it had not been necessary to stipulate that it is White to move)
The last three single moves are determined (2018-01-12)
Alfred Pfeiffer: Deleted "White to move", because this was not a part of the stipulation in the original. (2018-01-12)
Henrik Juel: Please undelete this again, Alfred
Without the knowledge that Black must start the retroplay, we can start with -1.b6xLa7 Lb8 etc., and the surprising intended solution -1... Sd8! vanishes (2018-01-12)
Alfred Pfeiffer: OK, but "White to move" is usually the standard in problems (except help problems). (2018-01-12)
Henrik Juel: Yes, Alfred; but there is no forward stipulation (like #2) in this retro problem (2018-01-12)
Yoav Ben-Zvi: Apparently Dawson considered the stipulation "What was Black's last move" as indicating that Black was the last to move and therefore equivalent to "White to move. Last move". An alternative could be "Last move. a)Black to move b)White to move". (2018-01-14)
Mario Richter: For 'Last Movers' we also have the "Type A", "Type B" etc. categories ... (2018-01-16)
Hans-Jürgen Manthey: Klasse ! mögliche Zugfolge:
1. Sh3 a6 2. Sf4 d5 3. Sg6 hxSg6 4. a4 Th4 5. Ta3 Td4 6. Td3 Dd6 7. Sa3 Lf5 8. c3 Kd7 9. Sc2 Kc6 10. Se3 Kc5 11. SxLf5 Kc4 12. h4 Sc6 13. Th3 Td8 14. The3 Dg3 15. Te4 Td6 16. Dc2 Sd8 17. Db1 Tb6 18. Da1 Sf6 19. Kd1 Sd7 20. Kc2 Sc5 21. Kb1 gxSf5 22. Ka2 fxTe4 23. Db1 exTd3 24. Ka1 c6 25. Dc2 dxDc2 26. d3+ Kb3 27. Lg5 De3 28. Lf6 gxLf6 29. fxDe3 Lh6 30. exTd4 Lf4 31. dxSc5 Lb8 32. cxTb6 La7 33. bxLa7 Se6 (2021-02-20)
more ...
comment
Solution: Sd8-e6 (2004-12-07)
hans: R: -1. … Sd8-e6 -2. b6xLa7 Lb8-a7 -3. c5xSb6 Lf4-b8 -4. d4xTc5 Lh6-f4 -5. e3xTd4 Lf8-h6 -6. f2xDe3 g7xLf6 -7. Lg5-f6 Df3-e3 -8. Lc1-g5 Kc4-b3 -9. d2-d3+ etc.
Other captures: black h7xg6xf5xe4xd3xc2 Captured pieces are random.
It’s *great* that d8 is only square for S. (2013-01-30)
Henrik Juel: Another try, d7-d5 as last move, fails, not because the access for [Lc8] is cut off ([Lc8] could have been captured on c8), but because following -2.b6xLa7 [Ta8] cannot get home when g7xLf6 is retracted (2013-01-30)
Yoav Ben-Zvi: The cage locking element in the try noted above is made thematic through 5-fold Echo
Tries:
-1.Pd7-d5 -- NW cage prevents escape of BRa8 to be captured by WPf2
-1.BPg7xBf6 -- Cage prevents escape of BBf8 to be captured by WPf2
-1.Nc5(d4)-e6 -- Blocks path of White Pa7 to f2
-1… Pb6xBa7 -2.Ne6-c5(d4) Pc5xb6 -3.Bb8-a7 Pd4xc5 -4.Bf4-b8 Pe3xd4 -5.Bh6-f4 Pf2xe3 -6.Bf8-h6
-6…Pd2-d3 -- Cage prevents escape of WBc1 to be captured by BPg7
-6…Pa3-a4 -- SW cage prevents escape of WRa1 to be captured by BPh7
-6…Ph3-h4 -- SE cage prevents escape of WRh1 to be captured by BPh7
Two other Retros by Yehuda Veisberg were printed in "The Israel Problemist" (1964) one from FCR and the other from "The Palestine Post" (2013-01-31)
Mario Richter: For -1.Pd7-d5 and …Pa3-a4 more precisely the reason for the illegality consists in a conflict between the uncapture of a bishop and a rook. (2013-02-01)
A.Buchanan: A satisfyingly unified little problem with precise tempo. WQR cannot be captured on c2 inside the White cage, since c2 is surrounded by dark-squared White units prior to Pd2-d3. BQR cannot be captured on a7 inside the Black cage, since BKB is too slow to reach any square for capture apart from a7 right at the end of the line. (2013-02-03)
Henrik Juel: It is nice to review this fine retro (although it would be even better, if it had not been necessary to stipulate that it is White to move)
The last three single moves are determined (2018-01-12)
Alfred Pfeiffer: Deleted "White to move", because this was not a part of the stipulation in the original. (2018-01-12)
Henrik Juel: Please undelete this again, Alfred
Without the knowledge that Black must start the retroplay, we can start with -1.b6xLa7 Lb8 etc., and the surprising intended solution -1... Sd8! vanishes (2018-01-12)
Alfred Pfeiffer: OK, but "White to move" is usually the standard in problems (except help problems). (2018-01-12)
Henrik Juel: Yes, Alfred; but there is no forward stipulation (like #2) in this retro problem (2018-01-12)
Yoav Ben-Zvi: Apparently Dawson considered the stipulation "What was Black's last move" as indicating that Black was the last to move and therefore equivalent to "White to move. Last move". An alternative could be "Last move. a)Black to move b)White to move". (2018-01-14)
Mario Richter: For 'Last Movers' we also have the "Type A", "Type B" etc. categories ... (2018-01-16)
Hans-Jürgen Manthey: Klasse ! mögliche Zugfolge:
1. Sh3 a6 2. Sf4 d5 3. Sg6 hxSg6 4. a4 Th4 5. Ta3 Td4 6. Td3 Dd6 7. Sa3 Lf5 8. c3 Kd7 9. Sc2 Kc6 10. Se3 Kc5 11. SxLf5 Kc4 12. h4 Sc6 13. Th3 Td8 14. The3 Dg3 15. Te4 Td6 16. Dc2 Sd8 17. Db1 Tb6 18. Da1 Sf6 19. Kd1 Sd7 20. Kc2 Sc5 21. Kb1 gxSf5 22. Ka2 fxTe4 23. Db1 exTd3 24. Ka1 c6 25. Dc2 dxDc2 26. d3+ Kb3 27. Lg5 De3 28. Lf6 gxLf6 29. fxDe3 Lh6 30. exTd4 Lf4 31. dxSc5 Lb8 32. cxTb6 La7 33. bxLa7 Se6 (2021-02-20)
more ...
comment
Keywords: Last Move?, Type B, Volet Pawn (x2)
Genre: Retro
FEN: 8/Pp2pp2/p1p1np2/3p4/P6P/1kPP4/1Pp1P1P1/K4B2
Reprints: 18 L'Echiquier de France 01/1957
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-02-19 more...
Genre: Retro
FEN: 8/Pp2pp2/p1p1np2/3p4/P6P/1kPP4/1Pp1P1P1/K4B2
Reprints: 18 L'Echiquier de France 01/1957
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-02-19 more...
10 - P0006899
Gideon Husserl
Israel Ring Tourney 1966-1971
Preis
(9+0)
Färbe die Steine!
Welches war der letzte Zug?
Gideon Husserl
Israel Ring Tourney 1966-1971
Preis
(9+0)
Färbe die Steine!
Welches war der letzte Zug?
sKc8,sBb7
R: 1. c7xSd8=T++
R: 1. c7xSd8=T++
Henrik Juel: Black: Kc8, Pb7 (7+2). -1.R=c7:S. Duplicated by P0007375 (2003-11-17)
Alain Brobecker: P1397480 is inspired by this one! (2021-12-25)
comment
Alain Brobecker: P1397480 is inspired by this one! (2021-12-25)
comment
Keywords: Colouring problem, Last Move?
Genre: Retro
Computer test: rawbats
FEN: B1KRN3/PP6/2QK1R2/8/8/8/8/8
Reprints: feenschach 21, p. 255, 04/1974
(C) feenschach 39 07-10/1977
Input: Gerd Wilts, 1996-08-11
Last update: A.Buchanan, 2023-06-06 more...
Genre: Retro
Computer test: rawbats
FEN: B1KRN3/PP6/2QK1R2/8/8/8/8/8
Reprints: feenschach 21, p. 255, 04/1974
(C) feenschach 39 07-10/1977
Input: Gerd Wilts, 1996-08-11
Last update: A.Buchanan, 2023-06-06 more...
11 - P0006953
Josef Haas
feenschach 21, p. 258, 04/1974
(6+1) cooked
Welches war der letzte Zug?
Circe
Josef Haas
feenschach 21, p. 258, 04/1974
(6+1) cooked
Welches war der letzte Zug?
Circe
R: 1. 0-0
Cook: R: 1. Kf2-g1 Kh2xBh3[+wBh2]
Cook: R: 1. Kf2-g1 Kh2xBh3[+wBh2]
HBae: cook siehe feenschach-25, 10/1974, S. 372 (2015-12-02)
A.Buchanan: Bh2->L (2015-12-03)
A.Buchanan: A number of these problems by Haas were cooked. HBae gives a teasing link to an article which possibly includes some corrections. Has anyone got access to this article, please? (2021-05-13)
HBae: Hello Andrew, link to feenschach 10/1974 (website Kotesovec):
http://problem64.beda.cz/silo/feenschach25_1974.pdf (2021-05-13)
A.Buchanan: Thanks HBae! (2021-05-13)
A.Buchanan: In this one B-=D seems to be Type C, not type A?
In WinChloe there are a batch more from a few years later 34 p.143, feenschach 47 (juil. 79). If we're uploading anything, should maybe skip to the end? (2021-05-13)
comment
A.Buchanan: Bh2->L (2015-12-03)
A.Buchanan: A number of these problems by Haas were cooked. HBae gives a teasing link to an article which possibly includes some corrections. Has anyone got access to this article, please? (2021-05-13)
HBae: Hello Andrew, link to feenschach 10/1974 (website Kotesovec):
http://problem64.beda.cz/silo/feenschach25_1974.pdf (2021-05-13)
A.Buchanan: Thanks HBae! (2021-05-13)
A.Buchanan: In this one B-=D seems to be Type C, not type A?
In WinChloe there are a batch more from a few years later 34 p.143, feenschach 47 (juil. 79). If we're uploading anything, should maybe skip to the end? (2021-05-13)
comment
R: 1. Kg1xSh2#
Keywords: Last Move? (KxS), Checkless, Miniature
Genre: Retro, Fairies
FEN: 8/8/8/8/8/7P/2Q3PK/4k2R
Input: Gerd Wilts, 1996-08-18
Last update: A.Buchanan, 2023-05-15 more...
Genre: Retro, Fairies
FEN: 8/8/8/8/8/7P/2Q3PK/4k2R
Input: Gerd Wilts, 1996-08-18
Last update: A.Buchanan, 2023-05-15 more...
13 - P0007435
Adamas
(47) feenschach 40 11-12/1977
(1+3) cooked
Welches war der letzte Zug?
Längstzüger
Adamas
(47) feenschach 40 11-12/1977
(1+3) cooked
Welches war der letzte Zug?
Längstzüger
R: 1. Bd2xDe1=L+
Cook: R: 1. Bd2xDc1=L+,d2xT/L/Sc1=L+
Cook: R: 1. Bd2xDc1=L+,d2xT/L/Sc1=L+
Mario Richter: Position is as given in 'feenschach'. It seems that R: 1. d3xDc1+,d3xT/L/Sc1+ also works and that adding a black pawn on the 7th rank (e.g. h7) would prevent the cook.
Can somebody confirm my observation? (2022-01-10)
Mario Richter: small typo: It seems that R: 1. d2xDc1+,d2xT/L/Sc1+ also works (2022-01-10)
Henrik Juel: Your observation, with last moves d2xDTLDc1=L+, seems correct (2022-01-10)
comment
Can somebody confirm my observation? (2022-01-10)
Mario Richter: small typo: It seems that R: 1. d2xDc1+,d2xT/L/Sc1+ also works (2022-01-10)
Henrik Juel: Your observation, with last moves d2xDTLDc1=L+, seems correct (2022-01-10)
comment
Keywords: Maximummer, Last Move? (BxD=L), Aristocrat, Miniature
Genre: Retro, Fairies
FEN: 8/8/8/8/8/4K1k1/8/2b1b3
Input: Gerd Wilts, 1996-08-21
Last update: Mario Richter, 2022-01-10 more...
Genre: Retro, Fairies
FEN: 8/8/8/8/8/4K1k1/8/2b1b3
Input: Gerd Wilts, 1996-08-21
Last update: Mario Richter, 2022-01-10 more...
14 - P0007436
Adamas
(48) feenschach 40 11-12/1977
(1+3) cooked
Welches war der letzte Zug?
Längstzüger
Adamas
(48) feenschach 40 11-12/1977
(1+3) cooked
Welches war der letzte Zug?
Längstzüger
R: 1. Bg2xTh1=L+
Cook: R: 1. Bg2xDf1=S+,Bg2xTf1=S+,Bg2xLf1=S+,Bg2xSf1=S+,
Cook: R: 1. Bg2xDf1=S+,Bg2xTf1=S+,Bg2xLf1=S+,Bg2xSf1=S+,
Henrik Juel: What is the other last move, Andrew? (2022-01-08)
A.Buchanan: I didn’t analyse these problems, just corrected the genre when I saw that it was incomplete. Here how about e.g. R: 1. Bc6-h8+ Kb7-a8 2. Bh8xPc6 (2022-01-09)
Mario Richter: R: 1. ... Bc6-h1+? is illegal - it leaves the wK in check!
The cooks are the discovered checks by 1. ... g2xYf1+ (2022-01-09)
comment
A.Buchanan: I didn’t analyse these problems, just corrected the genre when I saw that it was incomplete. Here how about e.g. R: 1. Bc6-h8+ Kb7-a8 2. Bh8xPc6 (2022-01-09)
Mario Richter: R: 1. ... Bc6-h1+? is illegal - it leaves the wK in check!
The cooks are the discovered checks by 1. ... g2xYf1+ (2022-01-09)
comment
Keywords: Maximummer, Last Move? (BxT=L), Aristocrat, Miniature
Genre: Retro, Fairies
FEN: K7/8/8/8/8/8/7k/5n1b
Input: Gerd Wilts, 1996-08-21
Last update: Mario Richter, 2022-01-09 more...
Genre: Retro, Fairies
FEN: K7/8/8/8/8/8/7k/5n1b
Input: Gerd Wilts, 1996-08-21
Last update: Mario Richter, 2022-01-09 more...
15 - P0007437
Ewald Reichel
(49) feenschach 40 11-12/1977
(4+8) cooked
Welches war der letzte Zug?
Längstzüger
Ewald Reichel
(49) feenschach 40 11-12/1977
(4+8) cooked
Welches war der letzte Zug?
Längstzüger
R: 1. Ba2xLb1=L+
Cook: R: 1. a2xSb1=L+
Cook: R: 1. a2xSb1=L+
Henrik Juel: What is the other last move, Andrew? (2022-01-08)
Henrik Juel: Well, maybe 1.Pa2xSb1=L+ also works (2022-01-08)
comment
Henrik Juel: Well, maybe 1.Pa2xSb1=L+ also works (2022-01-08)
comment
Keywords: Maximummer, Last Move? (BxL=L)
Genre: Retro, Fairies
FEN: 8/8/8/3p4/p2p4/R1pK4/1k1PP3/rbb5
Input: Gerd Wilts, 1996-08-21
Last update: Mario Richter, 2022-01-09 more...
Genre: Retro, Fairies
FEN: 8/8/8/3p4/p2p4/R1pK4/1k1PP3/rbb5
Input: Gerd Wilts, 1996-08-21
Last update: Mario Richter, 2022-01-09 more...
R: 1. Bf7xTg8=T
Keywords: Last Move? (BxT=T), Type A, Promotion (TT)
Genre: Retro
FEN: kNR2bR1/ppppp1pp/5p2/8/3K4/8/8/8
Reprints: feenschach 41 01-03/1978
Input: Gerd Wilts, 1996-08-31
Last update: A.Buchanan, 2021-04-21 more...
Genre: Retro
FEN: kNR2bR1/ppppp1pp/5p2/8/3K4/8/8/8
Reprints: feenschach 41 01-03/1978
Input: Gerd Wilts, 1996-08-31
Last update: A.Buchanan, 2021-04-21 more...
17 - P0007612
Hans Gruber
2802 feenschach 47 07-09/1979
(12+13)
Welches war der letzte schwarze Zug?
b) sTa8 statt La8
Es gelten die üblichen Zugkonventionen auch für das Retrospiel (Schwarz nimmt zuerst zurück, wenn er kann)
Hans Gruber
2802 feenschach 47 07-09/1979
(12+13)
Welches war der letzte schwarze Zug?
b) sTa8 statt La8
Es gelten die üblichen Zugkonventionen auch für das Retrospiel (Schwarz nimmt zuerst zurück, wenn er kann)
a) Bd7-d6
b) Sb3-a1
b) Sb3-a1
Hans-Jürgen Manthey: a) R: 1. d7-d6 Sd6-c8 2. Kc8-b8 Sc4-d6+ 3. Sd6-e8 Sa3-c4 4. Dd8-f8 Sb5-a3 5. Se8-d6 Kg8-h7 6. Tb8-b7 Kf8-g8 7. Kb7-c8 Kg8-f8 8. Kc6-b7 Sc3-b5 9. Kd6-c6 Sb1-c3 10. Dc8-d8 Sc3-b1 11. Lf3-a8 Sd5-c3 12. Db7-c8 Sb4-d5 13. Dd5-b7 Sa6-b4 14. Ta8-b8 Sb8-a6 15. Dh5-d5 Kf8-g8 16. Sf6-e8 Ke8-f8 17. Sd5-f6+ Kd8-e8 18. Le4-f3 Kc8-d8 19. Lf3-e4 Kb7xTc8 20. Le4-f3 Sa6-b8 21. Th8-c8 Sc5-a6 22. Lf3-e4 Ka6-b7 23. Le4-f3 Kb5-a6 24. Sb4-d5 Ka6-b5 25. Sc6-b4+ Kb5-a6 26. Sb8-c6 Kc4-b5 27. Kc6-d6 Sa4-c5 28. Kb7-c6 Kd4-c4 29. Kc8-b7 Sc3-a4 30. Kd8-c8 Ke3-d4 31. Ke8-d8 Kf4-e3 32. Dd5-h5 Kg3-f4 33. Db7-d5 Kh2-g3 34. Dc8-b7 Kg1-h2 35. Dd8-c8 Kf1-g1 36. Lb7-e4 Ke1-f1 37. Lc8-b7 Kd1-e1 38. h7xSg6 Ke1xSd1 39. Se3xDd1 Sb1-c3 40. Sf1-e3 Sf8-g6 41. Sg3xLf1 Sg6xLf8 42. Sh1-g3 Se5-g6 43. Sg3xTh1 Sf3-e5 44. Sh5-g3 h2-h3 45. Sf6-h5 Sg5-f3 46. Sg8-f6 Sh3-g5 47. b7-b6 Sg1-h3
b) R: 1... Tb1xa1 (da Schwarz keinen Zug zurück nehmen kann) 2. Sb3-a1 (der letzte Zug von Schwarz) 2... Ta1-b1 3. Sd4-b3 Tb1-a1 4. Sf5-d4 Ta1-b1 5. Sh6-f5 Tb1-a1 6. Sg8-h6 Kh8-h7 7. Sf6-e8 Ta1-b1 8. Sd5-f6 Tb1-a1 9. De8-f8 Ta1-b1 10. Da4-e8 Tb1-a1 11. Sf6-g8 Ta1-b1 12. Sg4-f6 Kg8-h8 13. Sc3-d5 Kf8-g8 14. Sb5-c3 Ke8-f8 15. Se3-g4 Kd7-e8 16. Sd1-e3 Kc6-d7 17. Da6-a4 Kd5-c6 18. d7-d6 Sd6-c8 19. h7xSg6 Sc4-d6 20. Kc8-b8 Ke5-d5 21. Tb8-b7 Sa3-c4 22. Kb7-c8 Ke4-e5 23. Th8-b8 Sf8-g6 24. Kc8-b7 Sg6XLf8 25. Kd8-c8 Se5-g6 26. Ke8-d8 Sc4-e5 27. Dc8-a6 Kf4-e4 28. Dd8-c8 Kg3-f4 29. Dd8-c8 Kh2-g3 30. b7-b6 Sb6-c4 31. Sd4-b5 Kg1-h2 32. Sc6-d4 Kf1-g1 33. Sb8-c6 Ke1-f1 34. Se3xDd1 Sc8-b6 35. Sf1-e3 Sb6xLc8 36. Sg3xLf1 Sc4-b6 37. Sh1-g3 Se5-c4 38. Sg3xTh1 Sf3-e5 39. Se4-g3 Sb1-a3 40. Sf6-e4 Sg1-f3 41. Sg8-f6 h2-h3 (2020-12-31)
comment
b) R: 1... Tb1xa1 (da Schwarz keinen Zug zurück nehmen kann) 2. Sb3-a1 (der letzte Zug von Schwarz) 2... Ta1-b1 3. Sd4-b3 Tb1-a1 4. Sf5-d4 Ta1-b1 5. Sh6-f5 Tb1-a1 6. Sg8-h6 Kh8-h7 7. Sf6-e8 Ta1-b1 8. Sd5-f6 Tb1-a1 9. De8-f8 Ta1-b1 10. Da4-e8 Tb1-a1 11. Sf6-g8 Ta1-b1 12. Sg4-f6 Kg8-h8 13. Sc3-d5 Kf8-g8 14. Sb5-c3 Ke8-f8 15. Se3-g4 Kd7-e8 16. Sd1-e3 Kc6-d7 17. Da6-a4 Kd5-c6 18. d7-d6 Sd6-c8 19. h7xSg6 Sc4-d6 20. Kc8-b8 Ke5-d5 21. Tb8-b7 Sa3-c4 22. Kb7-c8 Ke4-e5 23. Th8-b8 Sf8-g6 24. Kc8-b7 Sg6XLf8 25. Kd8-c8 Se5-g6 26. Ke8-d8 Sc4-e5 27. Dc8-a6 Kf4-e4 28. Dd8-c8 Kg3-f4 29. Dd8-c8 Kh2-g3 30. b7-b6 Sb6-c4 31. Sd4-b5 Kg1-h2 32. Sc6-d4 Kf1-g1 33. Sb8-c6 Ke1-f1 34. Se3xDd1 Sc8-b6 35. Sf1-e3 Sb6xLc8 36. Sg3xLf1 Sc4-b6 37. Sh1-g3 Se5-c4 38. Sg3xTh1 Sf3-e5 39. Se4-g3 Sb1-a3 40. Sf6-e4 Sg1-f3 41. Sg8-f6 h2-h3 (2020-12-31)
comment
Keywords: Last Move?
Genre: Retro
FEN: bkN1nq2/prp1pppK/1p1p2p1/8/8/7P/PPPPPPP1/R1B5
Input: Gerd Wilts, 1996-09-01
Last update: Gerd Wilts, 2005-12-03 more...
Genre: Retro
FEN: bkN1nq2/prp1pppK/1p1p2p1/8/8/7P/PPPPPPP1/R1B5
Input: Gerd Wilts, 1996-09-01
Last update: Gerd Wilts, 2005-12-03 more...
18 - P0007676
Wolfgang Dittmann
(B) feenschach 50 04-06/1980
(13+1)
Welches war der letzte Zug?
Kamikaze
Wolfgang Dittmann
(B) feenschach 50 04-06/1980
(13+1)
Welches war der letzte Zug?
Kamikaze
R: 1. Dd1-f1 ... 2. Se1-d3+
A.Buchanan: Last move sure, but prior to that could be Kg1-h2, Kh1-h2 or even Kg1xTh2. wSa1 needs to be present so it wasn’t uncaptured on h2, but I think it can replace wLb2, which cannot I think be uncaptured on h2. Am I missing sth? (2022-07-15)
Mario Richter: Does the Kamikaze-rule only apply to Black's moves? Otherwise, how can the diagram position be reached from the initial game array?
If Kamikaze applies to White too, I think, wSa1 also prevents Tg1xSh1[-wTh1] as an alternative last move ... (2022-07-15)
A.Buchanan: Hi Mario: thanks for this. Kamikaze applies to both sides. By default it’s Rex exclusive so kings can go round mopping up odd pieces. Black used three of Pacg BQSS to capture wBRR inside the cage. I now see wSSBQ must remain on the board of else there may just have been a capture outside the cage. If there was just a Kamikaze capture inside the cage, it can only have been Q&R or S&R (or vice versa). e.g. bSf3xRg1(-bSg1). Since a1 is occupied, can’t get bK past wR to retract via b2. (2022-07-15)
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Mario Richter: Does the Kamikaze-rule only apply to Black's moves? Otherwise, how can the diagram position be reached from the initial game array?
If Kamikaze applies to White too, I think, wSa1 also prevents Tg1xSh1[-wTh1] as an alternative last move ... (2022-07-15)
A.Buchanan: Hi Mario: thanks for this. Kamikaze applies to both sides. By default it’s Rex exclusive so kings can go round mopping up odd pieces. Black used three of Pacg BQSS to capture wBRR inside the cage. I now see wSSBQ must remain on the board of else there may just have been a capture outside the cage. If there was just a Kamikaze capture inside the cage, it can only have been Q&R or S&R (or vice versa). e.g. bSf3xRg1(-bSg1). Since a1 is occupied, can’t get bK past wR to retract via b2. (2022-07-15)
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Keywords: Kamikaze, Last Move? (D), Type A
Genre: Retro, Fairies
FEN: 8/8/8/8/8/1P1N3P/PBPPPPPk/N1K2Q2
Input: Gerd Wilts, 1996-09-02
Last update: A.Buchanan, 2022-07-15 more...
Genre: Retro, Fairies
FEN: 8/8/8/8/8/1P1N3P/PBPPPPPk/N1K2Q2
Input: Gerd Wilts, 1996-09-02
Last update: A.Buchanan, 2022-07-15 more...
19 - P0008784
Niels Høeg
The Chess Amateur 07/1926
(1+1)
Längste BP ohne Schach. Welches war der letzte Zug?
Niels Høeg
The Chess Amateur 07/1926
(1+1)
Längste BP ohne Schach. Welches war der letzte Zug?
R: 5899. Kg2xTh1
The game ends after 50 consecutive moves without captures or pawn moves (loss of castling right is not included here), or when there is not enough material to mate (say K-K or K-KS). There are 30 captures and 96 pawn moves (including 8 pawn captures) available, so the longest game seems to last (30+96-8)x50=5900 moves. This cannot be achieved because of the move-loss when the draw-preventing move shifts between white and black. Niels Høeg believed that 2 moves were lost and stated the solution as 5898.- Kb7xTa8. Karl Fabel later showed that only 1.5 moves need be lost.
Since 1926, there have been some relevant innovations to rules and conventions
(1) 50 move rule applies only to retro compositions, and will trigger automatically (no issue with writing down the move). (Codex 1953?)
(2) Removal of rules about draw by insufficient material (Laws 1997)
(3) Dead position rule introduced (Laws 1997)
(4) 75 move rule introduced (Laws 2014)
(5) Dead position rule applies only to retro compositions (Codex 2015)
(6) Articles 9.2 & 9.3 apply to chess problems - this includes 50 move rule and excludes 75 move rule (Codex 2019)
This is certainly a composition rather than a question about over the board chess. And it is certainly a retro composition. So the 50 move rule will dominate the 75 rule. The standard interpretation of interaction between 50 move rule and Dead Position in compositions is that Dead Position assessment *is* aware of looming automatic draw by 50 moves. (Note there is a similar assessment for interaction between Dead Position and Draw by Repetition.)
So we can argue that the game cannot last to 5898.5 moves, because the final move leads to a mandatory draw: either the king captures the last officer, or the king avoids the capture and the game ends in draw under the 50 move rule. So the position is dead at 5898.0. But even 5898.0 is too long for the diagram position with the kings so far apart. In the alternate reality if the last capture of a rook does not take place, there must be sufficient moves left for the kings to come together so that the rook can deliver checkmate. This will take at least 6.0 moves.
There is also still an ambiguity in the rules as to whether checkmate overrides draw by 50 moves. This is explicitly mentioned in the 75 move rule, but not in 50 move rule. I assume that checkmate *does* take priority.
Or does a valid problem only exist in the context of the rules and conventions that pertained at the time of its composition? The Codex does not opine on this general point.
Compare P1331022
The game ends after 50 consecutive moves without captures or pawn moves (loss of castling right is not included here), or when there is not enough material to mate (say K-K or K-KS). There are 30 captures and 96 pawn moves (including 8 pawn captures) available, so the longest game seems to last (30+96-8)x50=5900 moves. This cannot be achieved because of the move-loss when the draw-preventing move shifts between white and black. Niels Høeg believed that 2 moves were lost and stated the solution as 5898.- Kb7xTa8. Karl Fabel later showed that only 1.5 moves need be lost.
Since 1926, there have been some relevant innovations to rules and conventions
(1) 50 move rule applies only to retro compositions, and will trigger automatically (no issue with writing down the move). (Codex 1953?)
(2) Removal of rules about draw by insufficient material (Laws 1997)
(3) Dead position rule introduced (Laws 1997)
(4) 75 move rule introduced (Laws 2014)
(5) Dead position rule applies only to retro compositions (Codex 2015)
(6) Articles 9.2 & 9.3 apply to chess problems - this includes 50 move rule and excludes 75 move rule (Codex 2019)
This is certainly a composition rather than a question about over the board chess. And it is certainly a retro composition. So the 50 move rule will dominate the 75 rule. The standard interpretation of interaction between 50 move rule and Dead Position in compositions is that Dead Position assessment *is* aware of looming automatic draw by 50 moves. (Note there is a similar assessment for interaction between Dead Position and Draw by Repetition.)
So we can argue that the game cannot last to 5898.5 moves, because the final move leads to a mandatory draw: either the king captures the last officer, or the king avoids the capture and the game ends in draw under the 50 move rule. So the position is dead at 5898.0. But even 5898.0 is too long for the diagram position with the kings so far apart. In the alternate reality if the last capture of a rook does not take place, there must be sufficient moves left for the kings to come together so that the rook can deliver checkmate. This will take at least 6.0 moves.
There is also still an ambiguity in the rules as to whether checkmate overrides draw by 50 moves. This is explicitly mentioned in the 75 move rule, but not in 50 move rule. I assume that checkmate *does* take priority.
Or does a valid problem only exist in the context of the rules and conventions that pertained at the time of its composition? The Codex does not opine on this general point.
Compare P1331022
Duplicate Diagram: P1101148, P1189676, P1191185, P1304589
A.Buchanan: There's a question whether DP rule has visibility of 3Rep & 50M state. The current consensus among most of the tiny group who might care is that for retros, it does have visibility, but for purely forward problems, it does not. This align with the idea that by default 50M & DP rules apply only to retros (2023-09-06)
A.Buchanan: The old intended interpretation is protected under the Golden Age principle. Suppose we do apply modern rules, codex & clarifications. If Black just played Kb7xRa8, then the alternative leading to mate takes 7.0 moves, so this must have been Black's 5892nd move at the latest. If White just moved, then it was White's 5892nd at latest. So to maximize the length of the game, Black moved last. (2023-09-06) edit (2023-09-06)
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A.Buchanan: The old intended interpretation is protected under the Golden Age principle. Suppose we do apply modern rules, codex & clarifications. If Black just played Kb7xRa8, then the alternative leading to mate takes 7.0 moves, so this must have been Black's 5892nd move at the latest. If White just moved, then it was White's 5892nd at latest. So to maximize the length of the game, Black moved last. (2023-09-06) edit (2023-09-06)
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Keywords: Longest Proof Game, Last Move?, only Kings, Non-Unique Proof Game, Dead Position, 50 move rule, Constrained problem, Type A, Miniature, Golden Age (pre-dead), Aristocrat
Genre: Mathematics, Retro
FEN: k7/8/8/8/8/8/8/7K
Reprints: Schackproblemet 1928
Schach und Zahl 1966
Input: Gerd Wilts, 1997-06-20
Last update: A.Buchanan, 2024-01-18 more...
Genre: Mathematics, Retro
FEN: k7/8/8/8/8/8/8/7K
Reprints: Schackproblemet 1928
Schach und Zahl 1966
Input: Gerd Wilts, 1997-06-20
Last update: A.Buchanan, 2024-01-18 more...
20 - P1000069
Henrik Juel
7019 Thema Danicum 86 04/1997
2. Preis
(8+9)
Ergänze einen Stein!
Letzter Zug?
Henrik Juel
7019 Thema Danicum 86 04/1997
2. Preis
(8+9)
Ergänze einen Stein!
Letzter Zug?
+sLf8
R: 1. ... g7xSf6 2. Sg4-f6+ Kd8-e8 3. Se5-g4 Kd7-d8 4. Sc6-e5+ Kc8-d7 5. Sd8-c6 Kb8-c8 6. d7-d8=S Kc8-b8 7. c6xTd7+ Td8-d7 8. b5xLc6 0-0-0 9. a4xTb5 Ld7-c6 10. a3-a4 Lc8-d7 11. c3xDd4 Dd8-d4 12. a2-a3 d7xLe6
There is some choice in the retro path, but in the shortest resolution, the sK round trip is uniquely defined: e8-c8(castling)-b8-c8(switchback)-d7-d8-e8. Note that wTa, still stuck in its cage, was captured on c2.
R: 1. ... g7xSf6 2. Sg4-f6+ Kd8-e8 3. Se5-g4 Kd7-d8 4. Sc6-e5+ Kc8-d7 5. Sd8-c6 Kb8-c8 6. d7-d8=S Kc8-b8 7. c6xTd7+ Td8-d7 8. b5xLc6 0-0-0 9. a4xTb5 Ld7-c6 10. a3-a4 Lc8-d7 11. c3xDd4 Dd8-d4 12. a2-a3 d7xLe6
There is some choice in the retro path, but in the shortest resolution, the sK round trip is uniquely defined: e8-c8(castling)-b8-c8(switchback)-d7-d8-e8. Note that wTa, still stuck in its cage, was captured on c2.
Mu-Tsun Tsai: Can't believe that this one didn't get the 1st prize. The design is really brilliant! (2011-04-17)
Henrik Juel: Thanks for your nice words, Mu-Tsun. In 1997 there were few retro problems in Thema Danicum, and they were judged together with fairy problems, so the competition was stiff. (2011-04-17)
Henrik Juel: Thanks for posting the solution, Andrew
Two minor points:
The uncheck plusses should be R: 1. ... g7xSf6 2. Sg4-f6+ Kd8-e8 3. Se5-g4 Kd7-d8 4. Sc6-e5+ Kc8-d7 5. Sd8-c6 Kb8-c8 6. d7-d8=S Kc8-b8 7. c6xTd7+
sK could wander around on the queen side while wS pendulates on, say, g4 and h2; but in the shortest resolution the sK round trip is unique (2021-01-17)
A.Buchanan: welcome Henrik - also added the famous sLf8 to the animation (2021-01-18)
Henrik Juel: Six of the pawn captures happen to be uniquely determined, namely
b5xLc6xTd7, c3xDd4
d3xTc2, d7xLe6, g7xSf6 (2021-01-18)
A.Buchanan: An earlier sequence where timing was important: dxTc2+ Kc1 Td3/Sd3+ exd3 (2021-01-18)
A.Buchanan: Solved in YouTube: https://www.youtube.com/watch?v=sKi8ahju9Mc (2022-02-17)
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Henrik Juel: Thanks for your nice words, Mu-Tsun. In 1997 there were few retro problems in Thema Danicum, and they were judged together with fairy problems, so the competition was stiff. (2011-04-17)
Henrik Juel: Thanks for posting the solution, Andrew
Two minor points:
The uncheck plusses should be R: 1. ... g7xSf6 2. Sg4-f6+ Kd8-e8 3. Se5-g4 Kd7-d8 4. Sc6-e5+ Kc8-d7 5. Sd8-c6 Kb8-c8 6. d7-d8=S Kc8-b8 7. c6xTd7+
sK could wander around on the queen side while wS pendulates on, say, g4 and h2; but in the shortest resolution the sK round trip is unique (2021-01-17)
A.Buchanan: welcome Henrik - also added the famous sLf8 to the animation (2021-01-18)
Henrik Juel: Six of the pawn captures happen to be uniquely determined, namely
b5xLc6xTd7, c3xDd4
d3xTc2, d7xLe6, g7xSf6 (2021-01-18)
A.Buchanan: An earlier sequence where timing was important: dxTc2+ Kc1 Td3/Sd3+ exd3 (2021-01-18)
A.Buchanan: Solved in YouTube: https://www.youtube.com/watch?v=sKi8ahju9Mc (2022-02-17)
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Keywords: Add pieces (l), Last Move?, Type A, Kindergarten Problem, Volet Pawn, Ceriani-Frolkin Theme (S), Castling, Round Trip (k6)
Genre: Retro
FEN: 4k3/ppp1pp2/4pp2/8/3P4/3P2P1/1PpP1PP1/2K5
Reprints: I) Economy Records in Add Unit(s) Problems , p. 8, 03/2011
YouTube 17/02/2022
Input: Gerd Wilts, 2000-07-31
Last update: A.Buchanan, 2022-02-18 more...
Genre: Retro
FEN: 4k3/ppp1pp2/4pp2/8/3P4/3P2P1/1PpP1PP1/2K5
Reprints: I) Economy Records in Add Unit(s) Problems , p. 8, 03/2011
YouTube 17/02/2022
Input: Gerd Wilts, 2000-07-31
Last update: A.Buchanan, 2022-02-18 more...
1. 0-0 Kxe2 2. Te1#
R: 1. Ke4-e3
Die vorherige Stellung war noch nicht tot, wenn Weiß noch rochieren darf.
R: 1. Ke4-e3
Die vorherige Stellung war noch nicht tot, wenn Weiß noch rochieren darf.
AB: First proof of "can castle", without recourse to conventions. (2009-11-22)
A.Buchanan: deadpos doesn't understand about retro logic yet, so does not eliminate R: 1. Ke4xLSBe3? (2022-11-13)
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A.Buchanan: deadpos doesn't understand about retro logic yet, so does not eliminate R: 1. Ke4xLSBe3? (2022-11-13)
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Keywords: Dead Position, Castling, Rex solus (s), Obvious promotion (L), Last Move?, Type B
Genre: Retro, 2#
Computer test: HC+ Forward Popeye 4.79 DP deadpos
FEN: 8/7Q/8/4BB2/2PP1P2/3NkN2/PP2P1P1/4K2R
Reprints: 13 idee & form 156, p. 5284, 10/2022
Input: Gerd Wilts, 2001-01-25
Last update: A.Buchanan, 2023-12-27 more...
Genre: Retro, 2#
Computer test: HC+ Forward Popeye 4.79 DP deadpos
FEN: 8/7Q/8/4BB2/2PP1P2/3NkN2/PP2P1P1/4K2R
Reprints: 13 idee & form 156, p. 5284, 10/2022
Input: Gerd Wilts, 2001-01-25
Last update: A.Buchanan, 2023-12-27 more...
22 - P1011875
Andrej N. Kornilow
Andrey Frolkin
12111 Die Schwalbe 204 12/2003
3. Preis
(13+12)
Ergänze einen weißen Stein auf der h-Linie!
a) Letzter Zug?
b) Letzter Zug des wK?
Andrej N. Kornilow
Andrey Frolkin
12111 Die Schwalbe 204 12/2003
3. Preis
(13+12)
Ergänze einen weißen Stein auf der h-Linie!
a) Letzter Zug?
b) Letzter Zug des wK?
a) +wSh8 R: 1. Sg6xTh8 Th7-h8 2. Sc3-d1 Th8-h7 3. Sb5-c3 Th7-h8 4. Sd4-b5 Th8-h7 5. Sc6-d4 Th7-h8 6. Sb8-c6 Th8-h7 7. b7-b8=S Th7-h8 8. b6-b7 Th8-h7 9. b5-b6 Th7-h8 10. b4-b5 Th8-h7 11. Sh2-f1 Th7-h8 12. Sf3-h2 Th8-h7 13. Sd4-f3 Th7-h8 14. Sc6-d4 Th8-h7 15. Sb8-c6 Th7-h8 16. b7-b8=S Th8-h7 17. b6-b7 Th7-h8 18. b5-b6 Th8-h7 19. a4xBb5 Th7-h8 20. Dh8-g8 b6-b5 21. Kg8xSf8 Te8-e7 22. a3-a4 Le7-d8 23. a2-a3 Lc5-e7 24. b3-b4 e7-e6 25.
Das Schach, in dem der sK steht, kann nur durch einen wSh8 oder einen wLh7 aufgehoben werden. Damit Schwarz vor dem Schach gezogen haben kann, muß die weiße Figur eine schwarze Figur entschlagen. Die beiden anderen fehlenden weißen Steine wurden von den sBBg und h geschlagen, d.h. die beiden wBa2b2 müssen sich beide auf b8 umgewandelt haben. Im letzten weißen Zug wurde auf der h-Linie ein sT entschlagen, da ein sL oder sS vorher nicht gezogen haben konnten und eine sD die Umwandlung des sBb7 auf b1 in eine D erfordert hätte, was unmöglich ist, da dann der wB mit zwei Schlägen um den sBb herumgeschlagen haben müßte, was aber insgesamt 5 weiße Schläge erfordert hätte. Als letzter Zug von Weiß ist also Sg6xTh8 oder Lg6xTh7 denkbar.
Um die Stellung aufzulösen, muß die wD nach h8 und der wK nach g8 ausweichen und ein Stein auf f8 gestellt werden, damit der sTe8 nach e7 kann. Da dazu einige weiße und schwarze Tempozüge benötigt werden kann dies nur wie folgt erreicht werden:
Das Schach, in dem der sK steht, kann nur durch einen wSh8 oder einen wLh7 aufgehoben werden. Damit Schwarz vor dem Schach gezogen haben kann, muß die weiße Figur eine schwarze Figur entschlagen. Die beiden anderen fehlenden weißen Steine wurden von den sBBg und h geschlagen, d.h. die beiden wBa2b2 müssen sich beide auf b8 umgewandelt haben. Im letzten weißen Zug wurde auf der h-Linie ein sT entschlagen, da ein sL oder sS vorher nicht gezogen haben konnten und eine sD die Umwandlung des sBb7 auf b1 in eine D erfordert hätte, was unmöglich ist, da dann der wB mit zwei Schlägen um den sBb herumgeschlagen haben müßte, was aber insgesamt 5 weiße Schläge erfordert hätte. Als letzter Zug von Weiß ist also Sg6xTh8 oder Lg6xTh7 denkbar.
Um die Stellung aufzulösen, muß die wD nach h8 und der wK nach g8 ausweichen und ein Stein auf f8 gestellt werden, damit der sTe8 nach e7 kann. Da dazu einige weiße und schwarze Tempozüge benötigt werden kann dies nur wie folgt erreicht werden:
Keywords: Uncapture of pieces by pieces, Add pieces, Last move of a specific piece?, Last Move?
Genre: Retro
FEN: 3b1KQ1/p1pprp2/4pR1k/5pRq/6PB/4P1pb/2PP1PP1/3N1N2
Reprints: feenschach 155 2004
A3855 Phénix 147 01/2006
(8) Die Schwalbe 240 12/2009
Input: Gerd Wilts, 2003-12-30
Last update: A.Buchanan, 2024-01-15 more...
Genre: Retro
FEN: 3b1KQ1/p1pprp2/4pR1k/5pRq/6PB/4P1pb/2PP1PP1/3N1N2
Reprints: feenschach 155 2004
A3855 Phénix 147 01/2006
(8) Die Schwalbe 240 12/2009
Input: Gerd Wilts, 2003-12-30
Last update: A.Buchanan, 2024-01-15 more...
(a) l. g2-glB+ by Black.
(b) 1. Kh3-h2 by White. This is the only way we can get back without having 2 consecutive moves from any man e.g. Kh3-h2, g2-g1B, h2xSg3, Se4-g3, Kh4-h3, h3xBg2, Bfl-g2 Sg3xRh1, g2xRf3 etc.
Fuddled Men is a recent Fairy form invented by John Beasley, in which all men (including Kings) are unable to make 2 moves in succession. This is a Fairy form with great potential both on its own, and combined with other Fairy rules.
(b) 1. Kh3-h2 by White. This is the only way we can get back without having 2 consecutive moves from any man e.g. Kh3-h2, g2-g1B, h2xSg3, Se4-g3, Kh4-h3, h3xBg2, Bfl-g2 Sg3xRh1, g2xRf3 etc.
Fuddled Men is a recent Fairy form invented by John Beasley, in which all men (including Kings) are unable to make 2 moves in succession. This is a Fairy form with great potential both on its own, and combined with other Fairy rules.
No. 2184 HN
Walter Lindenthal: Why not (b) as follows:
(b) 1. wKg2-h2 by White (provided bBg1 is 'fuddled' at that moment).
The wBf1 was captured possibly by a bS before (or the wK gave way for its capture), it need not have been ... Bfl-g2 h3xBg2 ...
So, the last moves: ... bPh3-h2 wKf1-g2 ... bPx?g1=B wKg2-h2
Yes, this will result in an 'automatic' Mate after black's next move, but it seems fully legal under Fuddled Men rules! (2021-01-17)
A.Buchanan: @Walter if "bPh3-h2 wKf1-g2 ... bPx?g1=B wKg2-h2" tHen what moves can be in the "..."? There are no spare black pieces to be uncaptured, as S&R are captured by wPg & wPh. (2021-01-17)
Walter Lindenthal: Oh yes, agreed. Thanks! (2021-01-18)
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Walter Lindenthal: Why not (b) as follows:
(b) 1. wKg2-h2 by White (provided bBg1 is 'fuddled' at that moment).
The wBf1 was captured possibly by a bS before (or the wK gave way for its capture), it need not have been ... Bfl-g2 h3xBg2 ...
So, the last moves: ... bPh3-h2 wKf1-g2 ... bPx?g1=B wKg2-h2
Yes, this will result in an 'automatic' Mate after black's next move, but it seems fully legal under Fuddled Men rules! (2021-01-17)
A.Buchanan: @Walter if "bPh3-h2 wKf1-g2 ... bPx?g1=B wKg2-h2" tHen what moves can be in the "..."? There are no spare black pieces to be uncaptured, as S&R are captured by wPg & wPh. (2021-01-17)
Walter Lindenthal: Oh yes, agreed. Thanks! (2021-01-18)
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Keywords: Fuddled Men, Last Move?
Genre: Retro, Fairies
FEN: 2bqkb2/ppppppp1/8/8/8/5PP1/4PP1K/6bn
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2016-09-23 more...
Genre: Retro, Fairies
FEN: 2bqkb2/ppppppp1/8/8/8/5PP1/4PP1K/6bn
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2016-09-23 more...
24 - P1012896
Helmut Pönitz
Die Schwalbe 1935
(16+15)
Stellung nach dem 9. Zug von Weiß. Welches war der letzte Zug?
Helmut Pönitz
Die Schwalbe 1935
(16+15)
Stellung nach dem 9. Zug von Weiß. Welches war der letzte Zug?
1. f4 Sa6 2. f5 Sc5 3. g4 Sa4 4. Lh3 Sc3 5. dxc3 a5 6. Lh6 Ta6 7. g5 Tc6 8. Lg4 Tg6 9. f6 is one of 210 possible proof games
No. 790 HN
Kees: 1. f4 Na6 2. f5 Nc5 3. g4 Na4 4. Bh3 Nc3 5. dxc3 a5 6. Bh6 Ra6 7. g5 Rc6 8.
Bg4 Rg6 9. f6 * (2022-02-12)
Henrik Juel: We are told that White made last move, so the type is really B
But it also seems correct as a type A problem (2022-02-12)
A.Buchanan: Whatever the stipulation that we have ended up with here in PDB, it's clear that effort was expended by the composer to ensure that the problem functions as a Type A, so let's credit him with that :-) (2022-02-13)
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Kees: 1. f4 Na6 2. f5 Nc5 3. g4 Na4 4. Bh3 Nc3 5. dxc3 a5 6. Bh6 Ra6 7. g5 Rc6 8.
Bg4 Rg6 9. f6 * (2022-02-12)
Henrik Juel: We are told that White made last move, so the type is really B
But it also seems correct as a type A problem (2022-02-12)
A.Buchanan: Whatever the stipulation that we have ended up with here in PDB, it's clear that effort was expended by the composer to ensure that the problem functions as a Type A, so let's credit him with that :-) (2022-02-13)
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Keywords: Non-Unique Proof Game, Last Move?, Type A
Genre: Retro
FEN: 2bqkbnr/1ppppppp/5PrB/p5P1/6B1/2P5/PPP1P2P/RN1QK1NR
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2022-02-13 more...
Genre: Retro
FEN: 2bqkbnr/1ppppppp/5PrB/p5P1/6B1/2P5/PPP1P2P/RN1QK1NR
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2022-02-13 more...
25 - P1012897
Thomas R. Dawson
Die Schwalbe 1935
(16+15)
Stellung nach dem 10. Zug von Schwarz. Mit Weiss am zug, welches war der letzte Zug?
Thomas R. Dawson
Die Schwalbe 1935
(16+15)
Stellung nach dem 10. Zug von Schwarz. Mit Weiss am zug, welches war der letzte Zug?
Beispielauflösung:
R: 1. ... f7-f5 2. Ke4-e5 Sg6-h8 3. Lf1-a6 Sh4-g6 4. Kd3-e4 Sf5-h4 5. Ke2-d3 Sh6-f5 6. h4xTg5 Tg6-g5 7. e5-e6 Sg8-h6 8. e4-e5 Th6-g6 9. Ke1-e2 Th8-h6 10. e2-e4 h7-h5 11. h2-h4
zuletzt kann nur R: 1. ... f7-f5 geschehen sein, nicht R: 1. ... h6-h5,h7-h5??, denn dann hätte der sTh8, der auf g3,g4 oder g5 vom wBh2 geschlagen wurde, nicht auf das Schlagfeld gelangen können.
R: 1. ... f7-f5 2. Ke4-e5 Sg6-h8 3. Lf1-a6 Sh4-g6 4. Kd3-e4 Sf5-h4 5. Ke2-d3 Sh6-f5 6. h4xTg5 Tg6-g5 7. e5-e6 Sg8-h6 8. e4-e5 Th6-g6 9. Ke1-e2 Th8-h6 10. e2-e4 h7-h5 11. h2-h4
zuletzt kann nur R: 1. ... f7-f5 geschehen sein, nicht R: 1. ... h6-h5,h7-h5??, denn dann hätte der sTh8, der auf g3,g4 oder g5 vom wBh2 geschlagen wurde, nicht auf das Schlagfeld gelangen können.
No. 791 HN
Kees: 1. h4 h5 2. e4 Rh6 3. e5 Rg6 4. e6 Rg5 5. hxg5 Nh6 6. Ke2 Ng4 7. Kf3 Ne5+
8. Ke4 Ng6 9. Ba6 Nh8 10. Ke5 f5 * (2022-02-12)
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Kees: 1. h4 h5 2. e4 Rh6 3. e5 Rg6 4. e6 Rg5 5. hxg5 Nh6 6. Ke2 Ng4 7. Kf3 Ne5+
8. Ke4 Ng6 9. Ba6 Nh8 10. Ke5 f5 * (2022-02-12)
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Keywords: Last Move?, Non-Unique Proof Game, Type B
Genre: Retro
FEN: rnbqkb1n/ppppp1p1/B3P3/4KpPp/8/8/PPPP1PP1/RNBQ2NR
Input: Henri Nouguier, 2004-01-11
Last update: Mario Richter, 2022-02-13 more...
Genre: Retro
FEN: rnbqkb1n/ppppp1p1/B3P3/4KpPp/8/8/PPPP1PP1/RNBQ2NR
Input: Henri Nouguier, 2004-01-11
Last update: Mario Richter, 2022-02-13 more...
26 - P1012898
Helmut Pönitz
Die Schwalbe 1935
(15+15) C+
(a) Welches war der letzte Zug? Weiss am Zug (b) KBP im 4,0
Helmut Pönitz
Die Schwalbe 1935
(15+15) C+
(a) Welches war der letzte Zug? Weiss am Zug (b) KBP im 4,0
b) 1. d4 Sc6 2. Lh6 Sxd4 3. Dxd4 Tb8 4. Df6 Ta8
a) R: 1. Tb8-a8
a) R: 1. Tb8-a8
Keywords: Unique Proof Game, Last Move?, Type B, Homebase (s), Switchback (t)
Genre: Retro
Computer test: HC+ Retractor 2.0 Last move? (+ manual elimination of 1 try) C+ Natch 2.3 SPG
FEN: r1bqkbnr/pppppppp/5Q1B/8/8/8/PPP1PPPP/RN2KBNR
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2021-04-14 more...
Genre: Retro
Computer test: HC+ Retractor 2.0 Last move? (+ manual elimination of 1 try) C+ Natch 2.3 SPG
FEN: r1bqkbnr/pppppppp/5Q1B/8/8/8/PPP1PPPP/RN2KBNR
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2021-04-14 more...
R: 1. b5xa6ep!
Mario Richter: Can somebody please provide an explanation? It's clear that Black didn't move last, but why not e.g. R: 1. Ke6xTf7 or even R: 1. b5xTa6 Ta3xDa6 2. Dc8-a6+ (2022-01-10)
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Keywords: En passant, Maximummer, Last Move?, Type A (BxB ep.)
Genre: Fairies, Retro
FEN: n7/2p2K1p/Pk6/7p/7p/8/PP1PPnPP/2B2BB1
Input: Hans Gruber, 2004-05-01
Last update: Erich Bartel, 2014-09-14 more...
Genre: Fairies, Retro
FEN: n7/2p2K1p/Pk6/7p/7p/8/PP1PPnPP/2B2BB1
Input: Hans Gruber, 2004-05-01
Last update: Erich Bartel, 2014-09-14 more...
s) R: 1. b3xBa2 f6xBg7
w) R: 1. ... f6xBg7 2. b3xBa2
All captures are accounted for by hungry pawns, wBf1 died at home, & bPh waylaid. wPa & bPg can only have been captured on their home squares. bPc6 & bPd6 can't have just moved as they would close off bB homes. Most interestingly, wPd4 must have captured light-squared bB, but did not do so recently, as wPf3 would lock the south-east cage. Need Ng1 to shield wKh1, allowing bKg3. So the two last single moves are clear, and may have occurred in either order.
w) R: 1. ... f6xBg7 2. b3xBa2
All captures are accounted for by hungry pawns, wBf1 died at home, & bPh waylaid. wPa & bPg can only have been captured on their home squares. bPc6 & bPd6 can't have just moved as they would close off bB homes. Most interestingly, wPd4 must have captured light-squared bB, but did not do so recently, as wPf3 would lock the south-east cage. Need Ng1 to shield wKh1, allowing bKg3. So the two last single moves are clear, and may have occurred in either order.
Keywords: Last Move? (BxB,BxB), Type D (DD), Economy record (Last Move? Type DD), Volet Pawn (2), waylaid (sBh)
Genre: Retro
FEN: 8/ppp3P1/2pp4/8/4P3/7P/p1PPPkPK/4bq2
Input: Gerd Wilts, 2009-06-08
Last update: A.Buchanan, 2024-02-19 more...
Genre: Retro
FEN: 8/ppp3P1/2pp4/8/4P3/7P/p1PPPkPK/4bq2
Input: Gerd Wilts, 2009-06-08
Last update: A.Buchanan, 2024-02-19 more...
29 - P1100901
Michael Grushko
MG/15 feenschach 173, p. 272, 07-09/2008
(3+2)
Letzter Zug?
Typ C
Andernacher Circe
Michael Grushko
MG/15 feenschach 173, p. 272, 07-09/2008
(3+2)
Letzter Zug?
Typ C
Andernacher Circe
R: 1. wLg1xsTf1=s[+wTa1]#
Walter Lindenthal: Da sollte ein Tippfehler mit sTf1 vorliegen, es müsste heißen: R: 1. wLg1xsTf2=s[+wTa1]# (2024-02-17)
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Keywords: Last Move? (LxT), Type M, Circe (Andernacher), Andernach Chess, Type C
Genre: Retro, Fairies
FEN: 8/8/8/8/8/3K4/5b2/R3k2R
Input: Gerd Wilts, 2010-03-01
Last update: A.Buchanan, 2023-06-03 more...
Genre: Retro, Fairies
FEN: 8/8/8/8/8/3K4/5b2/R3k2R
Input: Gerd Wilts, 2010-03-01
Last update: A.Buchanan, 2023-06-03 more...
30 - P1108099
Nikolai Beluchow
Henrik Juel
Andrey Frolkin
14506 Die Schwalbe 243 06/2010
2. Preis
(14+12)
Letzter Zug?
Nikolai Beluchow
Henrik Juel
Andrey Frolkin
14506 Die Schwalbe 243 06/2010
2. Preis
(14+12)
Letzter Zug?
R: 1. Tg4-g1+ Tb1-c1 2. Sf1-e3 a2-a1=L 3. Se3-f1 a3-a2 4. Sf1-e3 a4-a3 5. Sg3-f1 Ta1-b1 6. Lf1-h3 Ta3-a1 7. Dh3-h4 Tb3-a3 8. Dh4-h5 Th5-h6 9. Te4-g4 Tb6-b3 10. Te8-e4 Te6-b6 11. Te7-e8 Te4-e6 12. Te8-e7 Tg4-e4 13. Te4-e8 Th6-h5 14. Dh5-h4 a5-a4 15. Dh4-h3 a6-a5 16. Sh1-g3 Tg2-g4 17. Tg4-e4+ Tg1-g2 18. Sg3-h1 g2-g1=T 19. Sh1-g3 g3-g2 20. Dh3-h4 a7-a6 21. Dh4-h5 Th5-h6 22. Te4-g4 g4-g3 23. Sg3-h1+ h6xLg5 24. Lc1-g5 g5-g4+ 25. d2xTc3 Tc8-c3 26. Te6-e4 c3-c2 27. Ta6-e6 c4-c3 28. c3xLd4 Lb6-d4 29. Ta1-a6 c5-c4 30. Db4-h4 etc. (D unpromote on b8 and L unpromote on e8)
PR Thierry Le Gleuher: "Noch ein bemerkenswertes Problem, anscheinend von Nikolai initiiert und dann von den beiden anderen Autoren korrigiert und verbessert. Die Zusammenarbeit bringt schließlich ein wegen seines Retrospiels außergewöhnliches Problem hervor, das eine originelle Idee zeigt und wahrscheinlich ein Task ist: 7 Retroschilde wTg4/wDh5, wSg3/wDh4, sTg4/wDh5, wTg4/wDh5, sBg3/wDh3, Sg3/wDh3, sBg5/sTh5, aber auch 3 Retroablösungen sTg4, sBg3, wLg5 Tempo sTg4-g2-g1, sBh7-h6-h5, 6 Switchbacks wSg3-h1-g3 (2×), wDh4-h3-h4, wDh5-h4-h5, sTh6-h5-h6, wTe4-g4-e4, 1 Rundlauf wTg4-e4-...-e4-g4, 1 Phönix sT."
hans: R: 1. Tg4-g1+ Tb1-c1 2. Sf1-e3 a2-a1=L 3. Se3-f1 a3-a2 4. Sf1-e3 a4-a3 5. Sg3-f1 Ta1-b1 6. Lf1-h3 Ta3-a1 7. Dh3-h4 Tb3-a3 8. Dh4-h5 Th5-h6 9. Te4-g4 Tb6-b3 10. Te8-e4 Te6-b6 11. Te7-e8 Te4-e6 12. Te8-e7 Tg4-e4 13. Te4-e8 Th6-h5 14. Dh5-h4 a5-a4 15. Dh4-h3 a6-a5 16. Sh1-g3 Tg2-g4 17. Tg4-e4+ Tg1-g2 18. Sg3-h1 g2-g1=T 19. Sh1-g3 g3-g2 20. Dh3-h4 a7-a6 21. Dh4-h5 Th5-h6 22. Te4-g4 g4-g3 23. Pg3-h1+ h6xLg5 24. Lc1-g5 g5-g4+ 25. d2xTc3 Tc8-c3 26. Te6-e4 c3-c2 27. Ta6-e6 c4-c3 28. c3xLd4 Lb6-d4 29. Ta1-a6 c5-c4 30. Db4-h4 etc. (D unpromote on b8 and L unpromote on e8)
Nice work of those three composers. Just for curiosity, how come this problem into existence? (2011-02-07)
Henrik Juel: I only saw your question today, Hans.
Nikolai made the original version of the problem and sent it to Andrej and later to me for comments. We suggested some corrections and improvements (I do not recall the details), not expecting any public acknowledgement; but Nikolai wanted the problem published with three authors (2012-07-13)
Henrik Juel: The retroplay can be shortened by a couple of moves
R: 1. Tg4-g1+ a2-a1=L 2. Sf1-e3 a3-a2 3. Sg3-f1 a4-a3 4. Lf1-h3 Ta1-c1 5. Dh3-h4 Ta3-a1 6. Dh4-h5 Th5-h6 7. Te4-g4 Tb5-b3 8. Te6-e4 Te5-b5 9. Te7-e6 Te4-e5 10. Te5-e7 Tg4-e4 11.Te4-e5 Th6-h5 12. Dh5-h4 a5-a4 13. Dh4-h3 a6-a5 14. Sh1-g3 Tg2-g4! 15. Tg4-e4+ Tg1-g2 16. Sg3-h1 g2-g1=T 17. Sh1-g3 g3-g4 18. Dh3-h4 a7-a6 19. Dh4-h5 Th5-h6 20. Te4-g4 g4-g3 21. Sg3-h1+ h6xLg5 22. Lc1-g5 g5-g4+ 23. d2xTc3 etc. (2021-04-28)
Henrik Juel: sorry, retractions 7-10 should read
7. Te4-g4 Tb6-b3 8. Te7-e4 Te6-b6 9. Te8-e7 Te4-e6 10. Te5-e8 Tg4-e4
The black rook must not check, of course (2021-04-28)
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hans: R: 1. Tg4-g1+ Tb1-c1 2. Sf1-e3 a2-a1=L 3. Se3-f1 a3-a2 4. Sf1-e3 a4-a3 5. Sg3-f1 Ta1-b1 6. Lf1-h3 Ta3-a1 7. Dh3-h4 Tb3-a3 8. Dh4-h5 Th5-h6 9. Te4-g4 Tb6-b3 10. Te8-e4 Te6-b6 11. Te7-e8 Te4-e6 12. Te8-e7 Tg4-e4 13. Te4-e8 Th6-h5 14. Dh5-h4 a5-a4 15. Dh4-h3 a6-a5 16. Sh1-g3 Tg2-g4 17. Tg4-e4+ Tg1-g2 18. Sg3-h1 g2-g1=T 19. Sh1-g3 g3-g2 20. Dh3-h4 a7-a6 21. Dh4-h5 Th5-h6 22. Te4-g4 g4-g3 23. Pg3-h1+ h6xLg5 24. Lc1-g5 g5-g4+ 25. d2xTc3 Tc8-c3 26. Te6-e4 c3-c2 27. Ta6-e6 c4-c3 28. c3xLd4 Lb6-d4 29. Ta1-a6 c5-c4 30. Db4-h4 etc. (D unpromote on b8 and L unpromote on e8)
Nice work of those three composers. Just for curiosity, how come this problem into existence? (2011-02-07)
Henrik Juel: I only saw your question today, Hans.
Nikolai made the original version of the problem and sent it to Andrej and later to me for comments. We suggested some corrections and improvements (I do not recall the details), not expecting any public acknowledgement; but Nikolai wanted the problem published with three authors (2012-07-13)
Henrik Juel: The retroplay can be shortened by a couple of moves
R: 1. Tg4-g1+ a2-a1=L 2. Sf1-e3 a3-a2 3. Sg3-f1 a4-a3 4. Lf1-h3 Ta1-c1 5. Dh3-h4 Ta3-a1 6. Dh4-h5 Th5-h6 7. Te4-g4 Tb5-b3 8. Te6-e4 Te5-b5 9. Te7-e6 Te4-e5 10. Te5-e7 Tg4-e4 11.Te4-e5 Th6-h5 12. Dh5-h4 a5-a4 13. Dh4-h3 a6-a5 14. Sh1-g3 Tg2-g4! 15. Tg4-e4+ Tg1-g2 16. Sg3-h1 g2-g1=T 17. Sh1-g3 g3-g4 18. Dh3-h4 a7-a6 19. Dh4-h5 Th5-h6 20. Te4-g4 g4-g3 21. Sg3-h1+ h6xLg5 22. Lc1-g5 g5-g4+ 23. d2xTc3 etc. (2021-04-28)
Henrik Juel: sorry, retractions 7-10 should read
7. Te4-g4 Tb6-b3 8. Te7-e4 Te6-b6 9. Te8-e7 Te4-e6 10. Te5-e8 Tg4-e4
The black rook must not check, of course (2021-04-28)
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Keywords: Last Move?, Promotion in the retro play (lt)
Genre: Retro
FEN: 6n1/3p1P1b/5pnr/5KpQ/3P3Q/2PpNk1B/1Pp1RP1P/b1rB2R1
Reprints: FIDE Album 2010-2012 , p. 560,
Input: Gerd Wilts, 2010-06-20
Last update: Mario Richter, 2020-05-06 more...
Genre: Retro
FEN: 6n1/3p1P1b/5pnr/5KpQ/3P3Q/2PpNk1B/1Pp1RP1P/b1rB2R1
Reprints: FIDE Album 2010-2012 , p. 560,
Input: Gerd Wilts, 2010-06-20
Last update: Mario Richter, 2020-05-06 more...
R: 1. Bb7xTa8=T (zuvor) 1. ... Ta1-a8
Mario Richter: Reprinted in 'Best Problems' in the announcement of "Marco Bonavoglia Memorial Tournament" (s. http://www.bestproblems.it/bppdf/BP105.pdf bzw. http://www.bestproblems.it/bppdf/Marco%20Bonavoglia%20MT%20-%20Announcement.pdf) (2022-12-30)
Ladislav Packa: Why not 1.Ra1-a8? Because in that case black's last move is missing. Richer content than it seems at first sight. (2022-12-31)
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Ladislav Packa: Why not 1.Ra1-a8? Because in that case black's last move is missing. Richer content than it seems at first sight. (2022-12-31)
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Keywords: Last Move?, Sentinels, Aristocrat, Minimal, Miniature
Genre: Fairies
FEN: Rb6/8/8/8/8/2K2k2/8/8
Reprints: Best Problems 105, p. 589, 01/2023
Input: Hans Gruber, 2011-10-09
Last update: Mario Richter, 2022-12-30 more...
Genre: Fairies
FEN: Rb6/8/8/8/8/2K2k2/8/8
Reprints: Best Problems 105, p. 589, 01/2023
Input: Hans Gruber, 2011-10-09
Last update: Mario Richter, 2022-12-30 more...
R: 1. 0-0 dann 1. Dc4 Kg2 2. Df1# z.B.
BTM the game is stalemate, WTM the game is dead.
If Black moved last it was R: 0. Kh4-h3 g2-g3+ retropat. So White moved last.
All missing pieces were captured by wP, and none can be undone immediately, even wPb3 & wPh7. However there is a try R: 0. Be8(f7)-h5? Kh4-h3 1. g2-g3+ Kh5-h4 2. B~-e8+. But then 0. ... Kh4-h3 was mandatory into DP, as White can't relieve the looming stalemate. The only solution is R: 0. ... 0-0 1. Kg2-h3, with many alternatives: basically anything but Kf1, Rg1 or Ne3, as Black must be allowed to respond Kg2. There is unique shortest “ghost play” h#1.5 living alternative to castling.
BTM the game is stalemate, WTM the game is dead.
If Black moved last it was R: 0. Kh4-h3 g2-g3+ retropat. So White moved last.
All missing pieces were captured by wP, and none can be undone immediately, even wPb3 & wPh7. However there is a try R: 0. Be8(f7)-h5? Kh4-h3 1. g2-g3+ Kh5-h4 2. B~-e8+. But then 0. ... Kh4-h3 was mandatory into DP, as White can't relieve the looming stalemate. The only solution is R: 0. ... 0-0 1. Kg2-h3, with many alternatives: basically anything but Kf1, Rg1 or Ne3, as Black must be allowed to respond Kg2. There is unique shortest “ghost play” h#1.5 living alternative to castling.
Objective: Type A Last move with uncastling
Henrik Juel: I see that retracting a2xb3 or g6xPh7 is no good
But R: 0.Le8-h5 Kh4-h3 1.g2-g3+ Kh5-h4 2.Sf7-e5+ Kh4-h5 3.e5xDf6 seems OK
Where is 'the looming stalemate'? (2022-04-09)
A.Buchanan: Retracting 1. Le8-h5 Kh4-h3 puts us in a position where Black’s move is mandatory and whatever White then plays, the position is stalemated (2022-04-10)
A.Buchanan: So in this line, the initial dead position was two single moves ago. One single move from dead position would suffice to show that Le8-h5 is not possible. (2022-04-10)
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Henrik Juel: I see that retracting a2xb3 or g6xPh7 is no good
But R: 0.Le8-h5 Kh4-h3 1.g2-g3+ Kh5-h4 2.Sf7-e5+ Kh4-h5 3.e5xDf6 seems OK
Where is 'the looming stalemate'? (2022-04-09)
A.Buchanan: Retracting 1. Le8-h5 Kh4-h3 puts us in a position where Black’s move is mandatory and whatever White then plays, the position is stalemated (2022-04-10)
A.Buchanan: So in this line, the initial dead position was two single moves ago. One single move from dead position would suffice to show that Le8-h5 is not possible. (2022-04-10)
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Keywords: Dead Position, Castling, Last Move?, Type A, Rex solus (S)
Genre: Retro
FEN: 7B/6PP/5P2/4N1PB/5QN1/1P3RPk/5P1P/5RK1
Reprints: 40 The Puzzling Side of Chess 145, p. 3, 07/04/2018
Input: A.Buchanan, 2013-02-02
Last update: A.Buchanan, 2022-04-09 more...
Genre: Retro
FEN: 7B/6PP/5P2/4N1PB/5QN1/1P3RPk/5P1P/5RK1
Reprints: 40 The Puzzling Side of Chess 145, p. 3, 07/04/2018
Input: A.Buchanan, 2013-02-02
Last update: A.Buchanan, 2022-04-09 more...
R: 1. Kb8xSa8
Compare P0001033.
Gerald Ettl: steht der sLh5 vielleicht auf h2 ?? (2023-07-02)
SCHRECKE: Why not R: Kb8xLa8? (2023-07-03)
Mario Richter: Wie "SCHRECKE" mit seiner Frage schon illustriert hat: mit dem sL auf h2 wäre das Problem inkorrekt, da neben R: 1. Kb8xSa8 auch R: 1. Kb8xLa8 als letzter Zug möglich gewesen wäre. Grund sind die etwas verwirrenden Dead-Reckoning-Regeln: mit sLh5 kann zuletzt nicht Kb8xLa8 geschehen sein, da in der Stellung wKb8 - sKb6 sLh5 sLa8 wegen der unzureichendes-Material-zum-Mattsetzen-Regel das Spiel schon in dieser Position beendet gewesen wäre, der wK als gar nicht mehr zur Ausführung eines Zuges geommen wäre ... (2023-07-03)
Mario Richter: Dear James, I suggest that you undo last change and put the black bishop back on h5! (2023-07-03)
A.Buchanan: There are 17 valid squares for the wB. Got to be on a light square for reasons given. Also it can't occupy or attack c8. And can't be attacking a8 because BTM. I think h5 selection was random, but could argue for any. (2023-07-04)
A.Buchanan: Or maybe bBa4, with which White by his last move avoided a completely sound #12. (2023-07-04)
Gerald Ettl: Dann waere es vielleicht ganz sinnvoll man schreibt die Bedingung unter das Diagramm. (2023-07-04)
A.Buchanan: Hi Gerald, it's not a condition, it's a FIDE rule since 1997, invented by a problemist who is also a rules committee member (Igor Vereschchagin) and approved by the rules committee (headed by FIDE Head International Arbiter Stewart Reuben), backed up by a WFCC convention since 2015 (Kjell Widlert & Michel Caillaud, responding to a request from some endgame studiers who understood that it was a real thing. Like 50M rule, it applies by default for retro problems. And the PDB keywords here give the game away anyway. If it was a forward stipulation, then I would indeed add a stipulation, e.g. P1208623. Please enjoy the madness that is DP rule :) P.S. I have found recently that it was really invented by Shakespeare. (2023-07-04)
Gerald Ettl: Ich spiele nicht nach den FIDE-Regel. (2023-07-04)
Olaf Jenkner: Allright.
https://www.skat-online.com/regeln-hilfe/regelwerk/internationale-skatordnung.html (2023-07-05)
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Gerald Ettl: steht der sLh5 vielleicht auf h2 ?? (2023-07-02)
SCHRECKE: Why not R: Kb8xLa8? (2023-07-03)
Mario Richter: Wie "SCHRECKE" mit seiner Frage schon illustriert hat: mit dem sL auf h2 wäre das Problem inkorrekt, da neben R: 1. Kb8xSa8 auch R: 1. Kb8xLa8 als letzter Zug möglich gewesen wäre. Grund sind die etwas verwirrenden Dead-Reckoning-Regeln: mit sLh5 kann zuletzt nicht Kb8xLa8 geschehen sein, da in der Stellung wKb8 - sKb6 sLh5 sLa8 wegen der unzureichendes-Material-zum-Mattsetzen-Regel das Spiel schon in dieser Position beendet gewesen wäre, der wK als gar nicht mehr zur Ausführung eines Zuges geommen wäre ... (2023-07-03)
Mario Richter: Dear James, I suggest that you undo last change and put the black bishop back on h5! (2023-07-03)
A.Buchanan: There are 17 valid squares for the wB. Got to be on a light square for reasons given. Also it can't occupy or attack c8. And can't be attacking a8 because BTM. I think h5 selection was random, but could argue for any. (2023-07-04)
A.Buchanan: Or maybe bBa4, with which White by his last move avoided a completely sound #12. (2023-07-04)
Gerald Ettl: Dann waere es vielleicht ganz sinnvoll man schreibt die Bedingung unter das Diagramm. (2023-07-04)
A.Buchanan: Hi Gerald, it's not a condition, it's a FIDE rule since 1997, invented by a problemist who is also a rules committee member (Igor Vereschchagin) and approved by the rules committee (headed by FIDE Head International Arbiter Stewart Reuben), backed up by a WFCC convention since 2015 (Kjell Widlert & Michel Caillaud, responding to a request from some endgame studiers who understood that it was a real thing. Like 50M rule, it applies by default for retro problems. And the PDB keywords here give the game away anyway. If it was a forward stipulation, then I would indeed add a stipulation, e.g. P1208623. Please enjoy the madness that is DP rule :) P.S. I have found recently that it was really invented by Shakespeare. (2023-07-04)
Gerald Ettl: Ich spiele nicht nach den FIDE-Regel. (2023-07-04)
Olaf Jenkner: Allright.
https://www.skat-online.com/regeln-hilfe/regelwerk/internationale-skatordnung.html (2023-07-05)
comment
Keywords: Type B, Last Move? (KxS), Dead Position, Economy record (Last Move? Type B), Rex solus (W), Aristocrat, Miniature, Minimal
Genre: Retro
FEN: K7/8/1k6/7b/8/8/8/8
Reprints: Retros mailing list 20/02/2007
Input: A.Buchanan, 2015-01-07
Last update: James Malcom, 2023-07-03 more...
Genre: Retro
FEN: K7/8/1k6/7b/8/8/8/8
Reprints: Retros mailing list 20/02/2007
Input: A.Buchanan, 2015-01-07
Last update: James Malcom, 2023-07-03 more...
34 - P1323914
Andrew Buchanan
PDB Website 14/08/2016
(16+15) C+
a) White to move. Last move?
b) KBP in 4.0
Andrew Buchanan
PDB Website 14/08/2016
(16+15) C+
a) White to move. Last move?
b) KBP in 4.0
b) 1. f4 Sc6 2. Kf2 Se5 3. Kg3 Sg4 4. Kxg4 Tb8
a) R: 1. Ta8-b8
a) R: 1. Ta8-b8
See also: P1012898 & P1388527
Henrik Juel: Even though obvious, the a) solution should be included
a) Ta8-b8 (2016-08-15)
A.Buchanan: Can't get both solutions to be animated here, due to hidden interactions with stipulation text (2021-04-14)
more ...
comment
Henrik Juel: Even though obvious, the a) solution should be included
a) Ta8-b8 (2016-08-15)
A.Buchanan: Can't get both solutions to be animated here, due to hidden interactions with stipulation text (2021-04-14)
more ...
comment
Keywords: Unique Proof Game, Last Move?, Type B
Genre: Retro
Computer test: C+ Retractor 2.0 Last move? C+ Euclide 1.01 SPG
FEN: 1rbqkbnr/pppppppp/8/8/5PK1/8/PPPPP1PP/RNBQ1BNR
Input: A.Buchanan, 2016-08-13
Last update: A.Buchanan, 2021-04-14 more...
Genre: Retro
Computer test: C+ Retractor 2.0 Last move? C+ Euclide 1.01 SPG
FEN: 1rbqkbnr/pppppppp/8/8/5PK1/8/PPPPP1PP/RNBQ1BNR
Input: A.Buchanan, 2016-08-13
Last update: A.Buchanan, 2021-04-14 more...
35 - P1386540
Thomas Volet
18228v Die Schwalbe 303 06/2020
Mario Richter gewidmet
(13+13)
Letzter Zug?
Thomas Volet
18228v Die Schwalbe 303 06/2020
Mario Richter gewidmet
(13+13)
Letzter Zug?
Beispielauflösung mri:
R: 1. ... Tc4-c6 2. Dc6-b6 Tc5-c4 3. Df3-c6 Td5-c5 4. Df8-f3 Tc5-d5 5. f7-f8=D Td5-c5 6. f6-f7 Te5-d5 7. f5-f6 Td5-e5 8. f4-f5 Tc5-d5 9. f2-f4 f3xSe2 10. Sf4-e2 Td5-c5 11. Sg6-f4 Tc5-d5 12. Se5-g6 Td5-c5 13. Sc4-e5 Sa3-b5 14. Sb6-c4 Tb5-d5 15. Sa4-b6 Sc4-a3 16. Sc5-a4 Sa5-c4 17. Tb6-b7 Sb7-a5 18. Se6-c5 Tf5-b5 19. Tc6-b6 Tf8-f5 20. Tc5-c6 Th8-f8 21. Ta5-c5 Th1-h8 22. Sc5-e6 h2-h1=T 23. Sa4-c5 h3-h2 24. Sb6-a4 h4-h3 25. Ta1-a5 h5-h4 26. h4xDg5 Dd5-g5 27. Ta5-a1 Dc6-d5 28. Sc4-b6 Da4-c6 29. Sb6-c4 Da1-a4 30. Ta3-a5 Db1-a1 31. Ta1-a3 f4-f3 32. Sa4-b6 Da2-b1 33. Tb1-a1 Da1-a2 34. Sc5-a4 a2-a1=D 35. Se6-c5 a3-a2 36. a2xSb3 Kc4-b4 37. Sg5-e6 Kd5-c4 38. Kb5-a6 Ke6-d5 39. Sf3-g5 Kf7-e6 40. Sg1-f3 Sc5-b3 41. Kc4-b5 Se4-c5 42. Ta5-a7 Sf6-e4 43. Tg5-a5 Sc5-b7 44. Lf3-a8 Lb7-c8 45. Le2-f3 Dd8-b8 46. Lf1-e2 Lc8-b7 47. e2-e3 Te3-d3 48. Ta1-b1 b3xSc2 49. Tg3-g5 a4-a3 50. Sa3-c2 Te8-e3 51. Kd3-c4 Sa6-c5 52. Kc2-d3 b4-b3 53. Kd1-c2 Th8-e8 54. d3-d4 Sg8-f6 55. Th3-g3 Lf6-c3 56. Th1-h3 Le7-f6 57. Ke1-d1 Lf8-e7 58. Sb1-a3 e7xDd6 59. Dc6-d6 Sb8-a6 60. Dc2-c6 Ke8-f7 61. Dd1-c2 h7-h5 62. c2xTd3 Td6-d3 63. Sh3-g1 Ta6-d6 64. Sg1-h3 Ta8-a6 65. Sh3-g1 f5-f4 66. Sg1-h3 b5-b4 67. Sh3-g1 a5-a4 68. Sg1-h3 f7-f5 69. Sh3-g1 b7-b5 70. Sg1-h3 a7-a5 71. h2-h4
Die wesentlichen Ereignisse im Retrospiel:
5. f7-f8=D!
9. ... f3xSe2!
14. ... Tb5-d5!
17. Tb6-b7! Sb7-a5!
26. h4xDg5!
27. Ta5-a1 Dc6-d5 28. Sc4-b6 Da4-c6
33. Tb1-a1 Da1-a2
34. ... a2-a1=D
36. a2xS/Tb3
R: 1. ... Tc4-c6 2. Dc6-b6 Tc5-c4 3. Df3-c6 Td5-c5 4. Df8-f3 Tc5-d5 5. f7-f8=D Td5-c5 6. f6-f7 Te5-d5 7. f5-f6 Td5-e5 8. f4-f5 Tc5-d5 9. f2-f4 f3xSe2 10. Sf4-e2 Td5-c5 11. Sg6-f4 Tc5-d5 12. Se5-g6 Td5-c5 13. Sc4-e5 Sa3-b5 14. Sb6-c4 Tb5-d5 15. Sa4-b6 Sc4-a3 16. Sc5-a4 Sa5-c4 17. Tb6-b7 Sb7-a5 18. Se6-c5 Tf5-b5 19. Tc6-b6 Tf8-f5 20. Tc5-c6 Th8-f8 21. Ta5-c5 Th1-h8 22. Sc5-e6 h2-h1=T 23. Sa4-c5 h3-h2 24. Sb6-a4 h4-h3 25. Ta1-a5 h5-h4 26. h4xDg5 Dd5-g5 27. Ta5-a1 Dc6-d5 28. Sc4-b6 Da4-c6 29. Sb6-c4 Da1-a4 30. Ta3-a5 Db1-a1 31. Ta1-a3 f4-f3 32. Sa4-b6 Da2-b1 33. Tb1-a1 Da1-a2 34. Sc5-a4 a2-a1=D 35. Se6-c5 a3-a2 36. a2xSb3 Kc4-b4 37. Sg5-e6 Kd5-c4 38. Kb5-a6 Ke6-d5 39. Sf3-g5 Kf7-e6 40. Sg1-f3 Sc5-b3 41. Kc4-b5 Se4-c5 42. Ta5-a7 Sf6-e4 43. Tg5-a5 Sc5-b7 44. Lf3-a8 Lb7-c8 45. Le2-f3 Dd8-b8 46. Lf1-e2 Lc8-b7 47. e2-e3 Te3-d3 48. Ta1-b1 b3xSc2 49. Tg3-g5 a4-a3 50. Sa3-c2 Te8-e3 51. Kd3-c4 Sa6-c5 52. Kc2-d3 b4-b3 53. Kd1-c2 Th8-e8 54. d3-d4 Sg8-f6 55. Th3-g3 Lf6-c3 56. Th1-h3 Le7-f6 57. Ke1-d1 Lf8-e7 58. Sb1-a3 e7xDd6 59. Dc6-d6 Sb8-a6 60. Dc2-c6 Ke8-f7 61. Dd1-c2 h7-h5 62. c2xTd3 Td6-d3 63. Sh3-g1 Ta6-d6 64. Sg1-h3 Ta8-a6 65. Sh3-g1 f5-f4 66. Sg1-h3 b5-b4 67. Sh3-g1 a5-a4 68. Sg1-h3 f7-f5 69. Sh3-g1 b7-b5 70. Sg1-h3 a7-a5 71. h2-h4
Die wesentlichen Ereignisse im Retrospiel:
5. f7-f8=D!
9. ... f3xSe2!
14. ... Tb5-d5!
17. Tb6-b7! Sb7-a5!
26. h4xDg5!
27. Ta5-a1 Dc6-d5 28. Sc4-b6 Da4-c6
33. Tb1-a1 Da1-a2
34. ... a2-a1=D
36. a2xS/Tb3
Korrektur zu P1383314, veröffentlicht in der 'Schwalbe', Heft 307 (02/2021), S.58 mit folgenden Worten: "Der Autor korrigiert (siehe Heft 306-1, S. 773) und hält die neue Fassung für definitiv besser. Weiß schlug Ba2:b3, Bc:d, Bh:g; Schwarz schlug Be7:d6, Bb:c, Bf3:e2; Weiß wandelte auf f8 um, Schwarz auf a1 und h1. Die Knoten im Westen kann nur durch Ba2:Xb3 aufgelöst werden."
Henrik Juel: Very good correction by Tom
Thanks for posting it, Mario, and for providing a complete retroplay
Why do you omit the check plus, when an uncheck occurs in the retroplay, like 34.Sc5-a4 a2-a1=D+ ? (2021-02-16)
Mario Richter: Henrik, we talked about the missing check signs already on the occasion of problem P1189314, the explanation is the same here: I do not use a physical chess board, instead I'm using chessbase light for forward play, and the GUI of 'retractor' as my chessboard for retroplay. 'retractor' has an option for output as text file, this are the retromove-sequences I use for input into the PDB. Unfortunately 'retractor' does not "produce" check signs, so I would have to add them by hand - and this is the question: spending my limited time to "beautify" the solution text, which makes it look a little bit nicer, but doesn't have any influence on the animation engine, or to use it for e.g. adding other problems to the PDB ... (2021-02-16)
Henrik Juel: I do not recall our previous talk, but I fully understand your reasoning (2021-02-16)
comment
Henrik Juel: Very good correction by Tom
Thanks for posting it, Mario, and for providing a complete retroplay
Why do you omit the check plus, when an uncheck occurs in the retroplay, like 34.Sc5-a4 a2-a1=D+ ? (2021-02-16)
Mario Richter: Henrik, we talked about the missing check signs already on the occasion of problem P1189314, the explanation is the same here: I do not use a physical chess board, instead I'm using chessbase light for forward play, and the GUI of 'retractor' as my chessboard for retroplay. 'retractor' has an option for output as text file, this are the retromove-sequences I use for input into the PDB. Unfortunately 'retractor' does not "produce" check signs, so I would have to add them by hand - and this is the question: spending my limited time to "beautify" the solution text, which makes it look a little bit nicer, but doesn't have any influence on the animation engine, or to use it for e.g. adding other problems to the PDB ... (2021-02-16)
Henrik Juel: I do not recall our previous talk, but I fully understand your reasoning (2021-02-16)
comment
Keywords: Last Move?
Genre: Retro
FEN: Bqb5/RRpp2p1/KQrp4/1n4P1/1k1P4/1PbrP3/1PpPp1P1/2B5
Input: Mario Richter, 2021-02-16
Last update: Mario Richter, 2021-02-16 more...
Genre: Retro
FEN: Bqb5/RRpp2p1/KQrp4/1n4P1/1k1P4/1PbrP3/1PpPp1P1/2B5
Input: Mario Richter, 2021-02-16
Last update: Mario Richter, 2021-02-16 more...
36 - P1387362
Manfred Zucker
Freie Presse (Chemnitz) 24/06/1977
(1+1)
Wie viele verschiedene letzte Züge sind möglich?
Manfred Zucker
Freie Presse (Chemnitz) 24/06/1977
(1+1)
Wie viele verschiedene letzte Züge sind möglich?
29 Lösungen
Gefragt war natürlich nach dem letzten Einzelzug. Nun kann zuletzt sowohl der weiße als auch der der schwarze König gezogen haben. Der weiße König kann von drei verschiedenen Feldern (a2,b1,b2) gekommen sein, und er kann auf a1 eine schwarze Dame, einen schwarzen Turm, einen schwarzen Läufer, einen schwarzen Springer oder nichts geschlagen haben, das sind 3x5=15 Möglichkeiten. Dasselbe trifft auf den schwarzen König zu, insgesamt ergeben sich so 30 Möglichkeiten für den letzten Zug - und doch ist diese Lösung nicht richtig! Die Stellung wKb2-sLa1 ist partiemöglich (letzte Züge: 1. ... a2-a2=L+! 2. Kxa1), die Stellung sKg2-wLh1 jedoch nicht, denn der weiße Läufer kann (bei schwarzer Königsstellung auf g2) auf keine Weise nach h1 gekommen sein! Diese partieunmögliche Stellung war also zu subtrahieren, das richtige Ergebnis mußte "29" lauten.
Gefragt war natürlich nach dem letzten Einzelzug. Nun kann zuletzt sowohl der weiße als auch der der schwarze König gezogen haben. Der weiße König kann von drei verschiedenen Feldern (a2,b1,b2) gekommen sein, und er kann auf a1 eine schwarze Dame, einen schwarzen Turm, einen schwarzen Läufer, einen schwarzen Springer oder nichts geschlagen haben, das sind 3x5=15 Möglichkeiten. Dasselbe trifft auf den schwarzen König zu, insgesamt ergeben sich so 30 Möglichkeiten für den letzten Zug - und doch ist diese Lösung nicht richtig! Die Stellung wKb2-sLa1 ist partiemöglich (letzte Züge: 1. ... a2-a2=L+! 2. Kxa1), die Stellung sKg2-wLh1 jedoch nicht, denn der weiße Läufer kann (bei schwarzer Königsstellung auf g2) auf keine Weise nach h1 gekommen sein! Diese partieunmögliche Stellung war also zu subtrahieren, das richtige Ergebnis mußte "29" lauten.
Duplicate Diagram: P1207607
Dazu schreibt die FP: "Wie viele verschiedene letzte Züge sind möglich? Noch ein kleiner Hinweis: Beachten Sie beim Zählen bitte auch, daß die Könige zuletzt geschlagen haben können.".
(MZ433)
.
Henrik Juel: solution
2x3x5 - 1 = 29
R: Kg2xLh1 is illegal (2021-03-12)
A.Buchanan: This preceded the DP rule by 20 years, so under “Golden Age” principle, that rule does not apply, although it would be sound either way. Under DP rule there would have been 2x2x3=12 possible last moves, as a rook or queen must have just been captured (2021-03-13)
A.Buchanan: Is an only kings position an aristocrat or a kindergarten? :) Is it a one liner? :) I think the answer should be no, no and no (2021-03-13)
comment
(MZ433)
.
Henrik Juel: solution
2x3x5 - 1 = 29
R: Kg2xLh1 is illegal (2021-03-12)
A.Buchanan: This preceded the DP rule by 20 years, so under “Golden Age” principle, that rule does not apply, although it would be sound either way. Under DP rule there would have been 2x2x3=12 possible last moves, as a rook or queen must have just been captured (2021-03-13)
A.Buchanan: Is an only kings position an aristocrat or a kindergarten? :) Is it a one liner? :) I think the answer should be no, no and no (2021-03-13)
comment
Keywords: Aristocrat, Miniature, only Kings, Golden Age, Last Move?, Symmetrical position, Asymmetrical solution
Genre: Retro, Mathematics
FEN: 8/8/8/8/8/8/8/K6k
Input: Felber, Volker, 2021-03-12
Last update: A.Buchanan, 2021-03-13 more...
Genre: Retro, Mathematics
FEN: 8/8/8/8/8/8/8/K6k
Input: Felber, Volker, 2021-03-12
Last update: A.Buchanan, 2021-03-13 more...
37 - P1388527
Andrew Buchanan
Retros mailing list 14/04/2021
dedicated to Theodore Hwa
(16+14) C+
a) White to move. Last move?
b) KBP in 4.0
Andrew Buchanan
Retros mailing list 14/04/2021
dedicated to Theodore Hwa
(16+14) C+
a) White to move. Last move?
b) KBP in 4.0
b) 1. e4 Sa6 2. Lxa6 f6 3. Lc4 a6 4. Lxg8 Ta7
a) R: 1. ... Ta8.a7
a) R: 1. ... Ta8.a7
See also: P1012898 & P1323914
Henrik Juel: C+ Euclide 1.01
1. Be2-e4 Sb8-a6 2. Lf1xa6 Bf7-f6 3. La6-c4 Ba7-a6 4. Lc4xg8 Ta8-a7
With White to move, last move could not be f7-f6, so it was Ta8-a7 (2021-04-14)
A.Buchanan: That was quick, Henrik! This is the first PDB problem validated by Retractor 2.0! Note that Black could also not have just played Kf7-e8. (2021-04-14)
Henrik Juel: Actually, I solved part a) by hand, but now it has been verified by Retractor 2.0, so your Computer test stuff is correct, Andrew (2021-04-14)
A.Buchanan: In principle, one could chain the output of an SPG engine into Retractor, to see if any other compositions with this stipulation can exist. Beyond trivial pawn nudges, maybe 3 is the lot? (2021-04-15)
more ...
comment
Henrik Juel: C+ Euclide 1.01
1. Be2-e4 Sb8-a6 2. Lf1xa6 Bf7-f6 3. La6-c4 Ba7-a6 4. Lc4xg8 Ta8-a7
With White to move, last move could not be f7-f6, so it was Ta8-a7 (2021-04-14)
A.Buchanan: That was quick, Henrik! This is the first PDB problem validated by Retractor 2.0! Note that Black could also not have just played Kf7-e8. (2021-04-14)
Henrik Juel: Actually, I solved part a) by hand, but now it has been verified by Retractor 2.0, so your Computer test stuff is correct, Andrew (2021-04-14)
A.Buchanan: In principle, one could chain the output of an SPG engine into Retractor, to see if any other compositions with this stipulation can exist. Beyond trivial pawn nudges, maybe 3 is the lot? (2021-04-15)
more ...
comment
Keywords: Unique Proof Game, Last Move?, Type B
Genre: Retro
Computer test: C+ Retractor 2.0 Last move? C+ Euclide 1.01 SPG
FEN: 2bqkbBr/rpppp1pp/p4p2/8/4P3/8/PPPP1PPP/RNBQK1NR
Input: A.Buchanan, 2021-04-14
Last update: Alfred Pfeiffer, 2021-04-29 more...
Genre: Retro
Computer test: C+ Retractor 2.0 Last move? C+ Euclide 1.01 SPG
FEN: 2bqkbBr/rpppp1pp/p4p2/8/4P3/8/PPPP1PPP/RNBQK1NR
Input: A.Buchanan, 2021-04-14
Last update: Alfred Pfeiffer, 2021-04-29 more...
38 - P1388688
Andrew Buchanan
Retros mailing list 16/04/2021
(16+15) C+
(a) Last move?
(b) KBP in 3.5
Andrew Buchanan
Retros mailing list 16/04/2021
(16+15) C+
(a) Last move?
(b) KBP in 3.5
b) 1. c3 f5 2. Db3 Sf6 3. Dg8 f4 4. Dxf8+
a) R: 1. ... Dg8xLf8+
a) R: 1. ... Dg8xLf8+
Henrik Juel: Part a)
Last move was Dg8xLf8+
Part b) C+ Euclide 1.01
1.c3 f5 2.Db3 Sf6 3.Dg8 f4 4.Dxf8+
Little solver challenge (2021-04-17)
comment
Last move was Dg8xLf8+
Part b) C+ Euclide 1.01
1.c3 f5 2.Db3 Sf6 3.Dg8 f4 4.Dxf8+
Little solver challenge (2021-04-17)
comment
Keywords: Unique Proof Game, Last Move?, Type C
Genre: Retro
Computer test: a) Retractor 2.0 b) C+ Euclide 1.01
FEN: rnbqkQ1r/ppppp1pp/5n2/8/5p2/2P5/PP1PPPPP/RNB1KBNR
Input: A.Buchanan, 2021-04-17
Last update: A.Buchanan, 2021-04-17 more...
Genre: Retro
Computer test: a) Retractor 2.0 b) C+ Euclide 1.01
FEN: rnbqkQ1r/ppppp1pp/5n2/8/5p2/2P5/PP1PPPPP/RNB1KBNR
Input: A.Buchanan, 2021-04-17
Last update: A.Buchanan, 2021-04-17 more...
39 - P1388893
18364 Die Schwalbe 305 10/2020
Thomas Brand gewidmet
(6+8)
Letzter Zug?
make&take
b) wBf5 nach h5
DL=Mulehopper
18364 Die Schwalbe 305 10/2020
Thomas Brand gewidmet
(6+8)
Letzter Zug?
make&take
b) wBf5 nach h5
DL=Mulehopper
a) wMHf8-h8(sLg8-f8)+
b) R 1.wMUg6-f8\x sSh8(sLg8?f8)+
b) R 1.wMUg6-f8\x sSh8(sLg8?f8)+
LaTeX-import:
Author not uniquely identified: Lindenthal, Walter
Keyword not uniquely identified: make&take
Henrik Juel: from the Schwalble Märchenlexikon:
Mulehopper: Zieht wie ein Grashüpfer, kann also auf seinem Zielfeld auch schlagen, schlägt aber zusätzlich als Teil des Zuges nach hinten (wie ein Maultier) aus und befördert auf diese Weise den Sprungbock auf das Startfeld des Mulehopperzuges zurück. (2021-04-21)
comment
Author not uniquely identified: Lindenthal, Walter
Keyword not uniquely identified: make&take
Henrik Juel: from the Schwalble Märchenlexikon:
Mulehopper: Zieht wie ein Grashüpfer, kann also auf seinem Zielfeld auch schlagen, schlägt aber zusätzlich als Teil des Zuges nach hinten (wie ein Maultier) aus und befördert auf diese Weise den Sprungbock auf das Startfeld des Mulehopperzuges zurück. (2021-04-21)
comment
Keywords: Last Move?, make&take
Pieces:
= Mulehopper (MH)
Genre: Retro, Fairies
FEN: 3bkb1*3Q/2Kpppp*3q/4PP1P/5P2/8/8/8/8
Input: Schwalbe, 2021-04-21
Last update: A.Buchanan, 2023-06-02 more...
Pieces:
= Mulehopper (MH)
Genre: Retro, Fairies
FEN: 3bkb1*3Q/2Kpppp*3q/4PP1P/5P2/8/8/8/8
Input: Schwalbe, 2021-04-21
Last update: A.Buchanan, 2023-06-02 more...
40 - P1401678
Daniele Gatti
SS015 The Hopper Magazine I01 24/12/2021
(9+4)
Show that White castled.
Last move?
Daniele Gatti
SS015 The Hopper Magazine I01 24/12/2021
(9+4)
Show that White castled.
Last move?
Henrik Juel: Black captured [Lc1,Lf1] with officers and the remaining missing white men with, e.g., a4xb3xTa2-a1=T and c4xb3xa2xTb1=T+, as the white rooks fell below the pawns
The only way to bring [Th1] to b1 is by castling (Ke1 could get out via a1, but after the black promotions he could not get back to e1)
Last move was a2xTb1=T+
Nice retro (2022-06-08)
comment
The only way to bring [Th1] to b1 is by castling (Ke1 could get out via a1, but after the black promotions he could not get back to e1)
Last move was a2xTb1=T+
Nice retro (2022-06-08)
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Keywords: Last Move?
Genre: Retro
FEN: 7k/8/8/8/1p6/P7/1PPPPPPP/rr2K3
Input: A.Buchanan, 2022-06-08
Last update: Miguel Ambrona, 2023-07-26 more...
Genre: Retro
FEN: 7k/8/8/8/1p6/P7/1PPPPPPP/rr2K3
Input: A.Buchanan, 2022-06-08
Last update: Miguel Ambrona, 2023-07-26 more...
41 - P1409983
Andrey Frolkin
Werner Keym
1.67 Eigenartige Schachprobleme , p. 196, 2010
(10+2)
Letzter Zug?
Andrey Frolkin
Werner Keym
1.67 Eigenartige Schachprobleme , p. 196, 2010
(10+2)
Letzter Zug?
R: 1. g3xBh4 h5-h4 and e.g. 2. Kf4-g5 Kh4-h3
Keywords: Economy record (Last Move? Type A), Last Move? (BxB), Non-standard material (L), Type A, Type B (a fortiori), Economy record (Last Move? Type B), Minimal
Genre: Retro
FEN: 8/1p5P/6PP/5BK1/6PP/5B1k/6NP/8
Input: A.Buchanan, 2023-05-28
Last update: A.Buchanan, 2023-05-31 more...
Genre: Retro
FEN: 8/1p5P/6PP/5BK1/6PP/5B1k/6NP/8
Input: A.Buchanan, 2023-05-28
Last update: A.Buchanan, 2023-05-31 more...
42 - P1409984
Theophilus Harding Willcocks
1.68 Eigenartige Schachprobleme , p. 196, 2010
(3+9)
Letzter Zug?
Theophilus Harding Willcocks
1.68 Eigenartige Schachprobleme , p. 196, 2010
(3+9)
Letzter Zug?
R: 1. a7xTb8=L h7-h6 2. a6-a7 Ka7-a8 3. a5-a6 and e.g. 3. ... Ta8-b8 4. Tb8-c8
Keywords: Economy record (Last Move? Type A), Type A, Last Move? (BxT=L), Promotion (L)
Genre: Retro
FEN: kBRn4/1pKppp2/1pp4p/8/8/8/8/8
Input: A.Buchanan, 2023-05-28
Last update: A.Buchanan, 2023-05-31 more...
Genre: Retro
FEN: kBRn4/1pKppp2/1pp4p/8/8/8/8/8
Input: A.Buchanan, 2023-05-28
Last update: A.Buchanan, 2023-05-31 more...
R: 1. Ke8xDf7#
Version of Die Schwalbe 1990, see P0000180
SCHRECKE: vergleiche: P0000180 (2023-07-25)
more ...
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SCHRECKE: vergleiche: P0000180 (2023-07-25)
more ...
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Keywords: Last Move? (KxD), Type C, Type M
Genre: Retro
FEN: nBk2Rn1/pp1ppKp1/1p3p1p/8/8/8/8/8
Input: Miguel Ambrona, 2023-07-25
Last update: A.Buchanan, 2023-07-27 more...
Genre: Retro
FEN: nBk2Rn1/pp1ppKp1/1p3p1p/8/8/8/8/8
Input: Miguel Ambrona, 2023-07-25
Last update: A.Buchanan, 2023-07-27 more...
1. ... d8=S 2. a1=T gxh8=D#
R: 1. b2-b1=L
R: 1. b2-b1=L
Yuri Bilokin: more economical -wBg5, -wSh7, -wPa3, bQh8(-bRh8) 6kq/3P1NP1/8/8/8/1K6/p1P5/1b6 (5+4) H#1.5
1...d8=S 2.a1=R gxh8=Q# (MM)
Tempo promotion
Promotion (QSr, 2, 1)
Tempo move (bP, waiting, type 1)
Model mate × 1 (2023-08-04)
Henrik Juel: C+ Popeye 4.61 (2023-08-04)
A.Buchanan: heh Yuri the 4th promotion is in the retraction: R: 1. b2-b1=L. The other pieces serve to force retro-uniqueness. (2023-08-04)
Olaf Jenkner: Vergleiche mit P1190770 oder P1190771 (2023-08-04)
A.Buchanan: Very nice! These remind me of my own P1408845. (2023-08-05)
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1...d8=S 2.a1=R gxh8=Q# (MM)
Tempo promotion
Promotion (QSr, 2, 1)
Tempo move (bP, waiting, type 1)
Model mate × 1 (2023-08-04)
Henrik Juel: C+ Popeye 4.61 (2023-08-04)
A.Buchanan: heh Yuri the 4th promotion is in the retraction: R: 1. b2-b1=L. The other pieces serve to force retro-uniqueness. (2023-08-04)
Olaf Jenkner: Vergleiche mit P1190770 oder P1190771 (2023-08-04)
A.Buchanan: Very nice! These remind me of my own P1408845. (2023-08-05)
comment
Keywords: Allumwandlung, Last Move?
Genre: h#, Retro
Computer test: HC+ forward popeye v4.61 retro thinking
FEN: 6kr/3P1NPN/8/6B1/8/PK6/p1P5/1b6
Input: Miguel Ambrona, 2023-07-27
Last update: A.Buchanan, 2023-08-04 more...
Genre: h#, Retro
Computer test: HC+ forward popeye v4.61 retro thinking
FEN: 6kr/3P1NPN/8/6B1/8/PK6/p1P5/1b6
Input: Miguel Ambrona, 2023-07-27
Last update: A.Buchanan, 2023-08-04 more...
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The problems of this query have been registered by the following contributors:
Gerd Wilts (25)Henri Nouguier (4)
Hans Gruber (2)
A.Buchanan (8)
Mario Richter (1)
Felber, Volker (1)
Schwalbe (1)
Miguel Ambrona (2)
A.Buchanan: Solved in YouTube: https://www.youtube.com/watch?v=Do_rkLQnrpk (2022-02-17)
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