743 problem(s) found in 3723 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT S='Klassik pur! [Böhringer]' AND K='Serienzüger'] [download as LaTeX]
1 - P0000250
Nikita M. Plaksin
Valery Liskovets
7577v Die Schwalbe 132 12/1991
(5+14)
ser-h#5 (AP)
Typ Tauber/Caillaud
Nikita M. Plaksin
Valery Liskovets
7577v Die Schwalbe 132 12/1991
(5+14)
ser-h#5 (AP)
Typ Tauber/Caillaud
1. Kd4 2. bxc3ep (zuletzt nur K,T-Zug oder c2-c4) 3. e5! (nicht 4. Tb4? weil zuletzt K,T-Zug und 0-0-0 nicht mehr möglich) 4. Tb4 (zuletzt e7xLd8=S möglich) 5. Tc4 & 1. 0-0-0# nicht 1. Td1#? wegen fehlender AP-Legalisierung
Keywords: Castling (wl), a posteriori (AP), Promotion (S), Seriesmover, Consequent, En passant
Genre: Retro, Fairies
FEN: 1N6/1ppppppn/n7/1Pq1k3/1pP1r3/4p3/1r6/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-29 more...
Genre: Retro, Fairies
FEN: 1N6/1ppppppn/n7/1Pq1k3/1pP1r3/4p3/1r6/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-29 more...
1. Lf1 2. Kh3 3. Kh4 4. Lh3 5. fxg3ep 6. Kh5 7. Kg6 8. Kf7 9. Ke8 10. 0-0-0 11. Td7 a8=D#
The cluster of tries: Kh2-g1-f1-e1-d2-...-e8 0-0-0 Td7 is 12 moves: just too long.
In the diagram, e.p. is not permitted because last move might be g3-g4. So first shift sK to h4. Following the e.p., check that wK does now have prior move: Kf4-f3. Now sK scampers to e8 where through consequent forgetfulness it recovers castling rights.
The cluster of tries: Kh2-g1-f1-e1-d2-...-e8 0-0-0 Td7 is 12 moves: just too long.
In the diagram, e.p. is not permitted because last move might be g3-g4. So first shift sK to h4. Following the e.p., check that wK does now have prior move: Kf4-f3. Now sK scampers to e8 where through consequent forgetfulness it recovers castling rights.
Keywords: En passant, Castling (sg), Seriesmover, Consequent, Valladao Task, Promotion in the mating move (D), Switchback (l), Promotion (D), Königswanderung
Genre: Retro, Fairies
FEN: r7/P1p5/pp6/5pp1/5pP1/5K1b/4rp1k/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-09-14 more...
Genre: Retro, Fairies
FEN: r7/P1p5/pp6/5pp1/5pP1/5K1b/4rp1k/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-09-14 more...
1. dxc3ep 2. Kxb5 3. Kxc6 4. Kd7 5. Ke8 6. 0-0 Th8#
Aber es geht auch R: 1. Kb2-a1!?
Aber es geht auch R: 1. Kb2-a1!?
Henrik Juel: The intention may be 1.dxc3ep 2.Kxb5xc6-d7-e8 6.0-0 Rh8#, but -1.Kb2 seems possible. Should bBc1 be moved to a3? (2003-04-28)
GW: Yes, that's the solution, and the problem seems indeed to be cooked. I don't know if it has been corrected. (2003-04-28)
James Malcom: I believe that the intent was that the sLc1 must be the orginal one, and thus an impediment to wK foreplay, as the wBc6 "must" have captured the e7 Black pawn on its way from f2. The problem is that it can take the alternative path fxsLf3xDe3xTc5-c6, and there are enough White pieces to capture for the Black b pawn to make it d2 and for the d pawn to make it to c2. (2021-09-14)
James Malcom: It turns out this problem actually was corrected a long time later: P1012052 (2021-09-14)
comment
GW: Yes, that's the solution, and the problem seems indeed to be cooked. I don't know if it has been corrected. (2003-04-28)
James Malcom: I believe that the intent was that the sLc1 must be the orginal one, and thus an impediment to wK foreplay, as the wBc6 "must" have captured the e7 Black pawn on its way from f2. The problem is that it can take the alternative path fxsLf3xDe3xTc5-c6, and there are enough White pieces to capture for the Black b pawn to make it d2 and for the d pawn to make it to c2. (2021-09-14)
James Malcom: It turns out this problem actually was corrected a long time later: P1012052 (2021-09-14)
comment
Keywords: En passant, Castling (sk), Seriesmover, Consequent, Non-standard material (sLb1), Valladao Task, Promotion in the retro play (sLb1), Obvious promotion ((sLb1)), Superseded by (P1012052)
Genre: Retro, Fairies
FEN: 7r/5pnR/2P3pR/pPpn3p/1kPp4/3P4/P2pP3/Kbb5
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-09-14 more...
Genre: Retro, Fairies
FEN: 7r/5pnR/2P3pR/pPpn3p/1kPp4/3P4/P2pP3/Kbb5
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-09-14 more...
1. dxe3ep 2. fxg1=L 3. 0-0 Tg4#
1. dxe3ep 2. Ke7? 3. Kd6 Sf5# doesn't pay AP debt
1. dxe3ep 2. Ke7? 3. Kd6 Sf5# doesn't pay AP debt
Henrik Juel: If Black may castle, his latest move must have been e3xf2, so last move was e2-e4. (Orig. wPg2 promoted on g8, so g7xh6 happened early). 1.dxe3 e.p. 2.fxg1=B 3.0-0 Tg4# (2003-03-21)
James Malcom: Is this the only know one-sided Valladao in a regular series-mover helpmate? Also, can wPh2 be shifted to h4, and the White king moved as well to h2, so that the solution must have 2. fxg1=S? (2020-12-08)
James Malcom: Well, the only known one that is in minimum form, i.e. 3 moves, I mean. (2020-12-08)
A.Buchanan: This is nice. I don't know of any other AP ser-h#3 with Valladao, but there could be. Just been cleansing PDB data today. Yes I think wKh3 and wBh2 can be transposed, and then promote to S instead of L. (2020-12-08)
A.Buchanan: The legality of intermediate positions in seriesmovers is of course irrelevant. However, each proof game that leads to the diagram position with BTM can be appended with a black move and then a "flip" that changes the player to move. We can repeat this process, and then the fact that Black retains castling rights implies that they had castling rights in the diagram position. I think this is the right formal way to handle AP with seriesmovers. (2022-03-21)
comment
James Malcom: Is this the only know one-sided Valladao in a regular series-mover helpmate? Also, can wPh2 be shifted to h4, and the White king moved as well to h2, so that the solution must have 2. fxg1=S? (2020-12-08)
James Malcom: Well, the only known one that is in minimum form, i.e. 3 moves, I mean. (2020-12-08)
A.Buchanan: This is nice. I don't know of any other AP ser-h#3 with Valladao, but there could be. Just been cleansing PDB data today. Yes I think wKh3 and wBh2 can be transposed, and then promote to S instead of L. (2020-12-08)
A.Buchanan: The legality of intermediate positions in seriesmovers is of course irrelevant. However, each proof game that leads to the diagram position with BTM can be appended with a black move and then a "flip" that changes the player to move. We can repeat this process, and then the fact that Black retains castling rights implies that they had castling rights in the diagram position. I think this is the right formal way to handle AP with seriesmovers. (2022-03-21)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (sk), Seriesmover, Promotion, Valladao Task
Genre: Retro, Fairies
Computer test: C+ Popeye v4.85 + thinking
FEN: 4k2r/1pp2p1p/1N5p/3P4/2RpP2N/P2P1P1K/p1BP1p1P/B3b1R1
Reprints: Die Schwalbe 143 10/1993
Rex Multiplex 45-46 05/1994
(XII) Quartz 5 1997
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
Genre: Retro, Fairies
Computer test: C+ Popeye v4.85 + thinking
FEN: 4k2r/1pp2p1p/1N5p/3P4/2RpP2N/P2P1P1K/p1BP1p1P/B3b1R1
Reprints: Die Schwalbe 143 10/1993
Rex Multiplex 45-46 05/1994
(XII) Quartz 5 1997
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
1. Kf8 2. Ke8 3. 0-0 4. Kh8 5. Tg8 Sf7#
Version Bernd Schwarzkopf
Henrik Juel: Not 1.Kf8 2.Tg8 3.Tg7 4.Kg8 5.Kh8 6.Tg8, one move too many (2021-01-18)
comment
Henrik Juel: Not 1.Kf8 2.Tg8 3.Tg7 4.Kg8 5.Kh8 6.Tg8, one move too many (2021-01-18)
comment
Keywords: Seriesmover, Consequent, Castling
Genre: Retro, Fairies
FEN: 6kr/7p/7K/6N1/8/8/8/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-09-14 more...
Genre: Retro, Fairies
FEN: 6kr/7p/7K/6N1/8/8/8/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-09-14 more...
1. Df2 2. Db6 3. Kd4 4. bxc3ep 5. Dg6 6. De4 Lb6
Cook: 1. Kd4 2. Kc3 3. Db2 4. d2 5. Ld3 6. d4 Lxb4#
Cook: 1. Kd4 2. Kc3 3. Db2 4. d2 5. Ld3 6. d4 Lxb4#
Keywords: Seriesmover, Consequent, En passant
Genre: Retro, Fairies
FEN: 8/8/p7/B2pp3/KpP1k3/Np1p4/q7/1b6
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-09-14 more...
Genre: Retro, Fairies
FEN: 8/8/p7/B2pp3/KpP1k3/Np1p4/q7/1b6
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-09-14 more...
7 - P0003925
Ivan Skoba
1009 diagrammes 47 09-10/1980
(6+7) C+
a) ser-h#6 (AP)
b) nach dem Schlüssel von a): ser-h#5
Ivan Skoba
1009 diagrammes 47 09-10/1980
(6+7) C+
a) ser-h#6 (AP)
b) nach dem Schlüssel von a): ser-h#5
a)
1. dxc3ep 2. Kc4? 3. Tb5 4. Td5 5. Dc5 6. Kd4 Th4#
2. Tb2! 3. Kb3 4. Kc2 5. Kc1 6. c2 0-0#
b)
1. Tb2? 2. Kb3 3. Kc2 4. Kc1 5. c2 0-0#
1. Kc4! 2. Tb5 3. Td5 4. Dc5 5. Kd4 Th4#
There are basically two candidate solutions ending Th4# and 0-0#. In (a), the initial ep can only be justified by 0-0#. On the other hand in the diagram position in (b), White's last move must have been with wK or wR, so 0-0# is disrupted. Nice and paradoxical.
1. dxc3ep 2. Kc4? 3. Tb5 4. Td5 5. Dc5 6. Kd4 Th4#
2. Tb2! 3. Kb3 4. Kc2 5. Kc1 6. c2 0-0#
b)
1. Tb2? 2. Kb3 3. Kc2 4. Kc1 5. c2 0-0#
1. Kc4! 2. Tb5 3. Td5 4. Dc5 5. Kd4 Th4#
There are basically two candidate solutions ending Th4# and 0-0#. In (a), the initial ep can only be justified by 0-0#. On the other hand in the diagram position in (b), White's last move must have been with wK or wR, so 0-0# is disrupted. Nice and paradoxical.
Keywords: Seriesmover, Castling (wk), Cant Castler, a posteriori (AP) (Type Petrovic), En passant as key
Genre: Retro, Fairies
Computer test: HC+ Popeye v4.87 & simple retro-logic
FEN: 8/8/8/8/bkPp4/pr1pq3/3PRP2/4K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-29 more...
Genre: Retro, Fairies
Computer test: HC+ Popeye v4.87 & simple retro-logic
FEN: 8/8/8/8/bkPp4/pr1pq3/3PRP2/4K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-29 more...
1. a1=S 2. fxg3ep 3. Kxh5 4. Kxg6 5. Kf7 6. Ke8 7. 0-0-0 a8=D#
8. TT
Henrik Juel: Solution: 1.a1S 2.fxg3ep 3.Kxh5xg6-f7-e8 7.0-0-0 a8Q#. Nice problem with open and hidden ep capture (exf3ep). (2003-04-28)
James Malcom: How is the key here justified? (2021-01-18)
James Malcom: I am still pondering. (2021-09-14)
Henrik Juel: James, I have forgotten all about this weird stipulation during the time since my last comment, and I don't know what I meant so say...
The definition of shc in the PDB is not complete; here is the Schwalbe definition:
Konsequenter Serienzüger: Ein Serienzüger, bei dem nach jedem Zug die Retroanalyse der Stellung neu durchgeführt wird (also ohne Kenntnis früherer Züge und Analysen). Beispielsweise wird eine Rochade wieder möglich, wenn König und Rochadeturm auf ihre entsprechenden Felder ziehen (weil in der neuen Analyse "vergessen" ist, dass beide bereits gezogen haben).
In english, something like
After each move the analysis of the position is done afresh, without knowledge of previous moves;
for instance, castling is possible when king and rook reach their original squares (e8 and a8), because it is 'forgotten' that they have already moved (2021-09-14)
Henrik Juel: You ask for a justification of the key, James; there is no need for justification, Black can do whatever he likes
In the position after 1.a1=S last move must have been g2-g4, so the ep capture 2.fxg3ep is legitimized
In the position after 2.fxg3ep last move must have been Ke3xPf3, with the double check being explained by exf3ep++; this is the 'hidden ep capture' I mentioned in my youthful comment (2021-09-14)
James Malcom: Thanks Henri! While the definition is incomplete, the reset each time is deducible from looking over shc problems. The justification here, however, was a level above me somehow. (2021-09-14)
comment
Henrik Juel: Solution: 1.a1S 2.fxg3ep 3.Kxh5xg6-f7-e8 7.0-0-0 a8Q#. Nice problem with open and hidden ep capture (exf3ep). (2003-04-28)
James Malcom: How is the key here justified? (2021-01-18)
James Malcom: I am still pondering. (2021-09-14)
Henrik Juel: James, I have forgotten all about this weird stipulation during the time since my last comment, and I don't know what I meant so say...
The definition of shc in the PDB is not complete; here is the Schwalbe definition:
Konsequenter Serienzüger: Ein Serienzüger, bei dem nach jedem Zug die Retroanalyse der Stellung neu durchgeführt wird (also ohne Kenntnis früherer Züge und Analysen). Beispielsweise wird eine Rochade wieder möglich, wenn König und Rochadeturm auf ihre entsprechenden Felder ziehen (weil in der neuen Analyse "vergessen" ist, dass beide bereits gezogen haben).
In english, something like
After each move the analysis of the position is done afresh, without knowledge of previous moves;
for instance, castling is possible when king and rook reach their original squares (e8 and a8), because it is 'forgotten' that they have already moved (2021-09-14)
Henrik Juel: You ask for a justification of the key, James; there is no need for justification, Black can do whatever he likes
In the position after 1.a1=S last move must have been g2-g4, so the ep capture 2.fxg3ep is legitimized
In the position after 2.fxg3ep last move must have been Ke3xPf3, with the double check being explained by exf3ep++; this is the 'hidden ep capture' I mentioned in my youthful comment (2021-09-14)
James Malcom: Thanks Henri! While the definition is incomplete, the reset each time is deducible from looking over shc problems. The justification here, however, was a level above me somehow. (2021-09-14)
comment
Keywords: Seriesmover, Consequent, En passant, Promotion (sD x2), Valladao Task, Castling, Promotion in the mating move
Genre: Retro, Fairies
FEN: r7/P1pp4/pp3pP1/4rpbP/5pPk/3n1K1b/p6q/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-09-14 more...
Genre: Retro, Fairies
FEN: r7/P1pp4/pp3pP1/4rpbP/5pPk/3n1K1b/p6q/8
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-09-14 more...
* 1. ... Lxd2#
1. dxe3ep 2. Txf2 3. Txg2 4. Th2 5. Th3 0-0#
1. dxe3ep 2. Txf2 3. Txg2 4. Th2 5. Th3 0-0#
Keywords: Castling (wk), Seriesmover, En passant as key, a posteriori (AP) (Type Petrovic)
Genre: Retro, Fairies
Computer test: HC+ Popeye 4.61 after analysis
FEN: 8/8/8/4pPp1/1p1pPkpb/1P1P2p1/pPpr1PP1/rbB1K2R
Reprints: 103 Bilten 1970 1971
(70) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-07-20 more...
Genre: Retro, Fairies
Computer test: HC+ Popeye 4.61 after analysis
FEN: 8/8/8/4pPp1/1p1pPkpb/1P1P2p1/pPpr1PP1/rbB1K2R
Reprints: 103 Bilten 1970 1971
(70) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-07-20 more...
10 - P0004481
Matjaz Zigman
Länderkampf Mazedonien-Slowenien 1969
7. Platz
(13+10) cooked
ser-h#6** AP
Matjaz Zigman
Länderkampf Mazedonien-Slowenien 1969
7. Platz
(13+10) cooked
ser-h#6** AP
* 1. ... Sb5#
* 1. ... dxc3#
1. fxe3ep 2. e2 3. exf1=S 4. Se3? 5. Sd5 Sb5# (must castle for AP)
1. fxe3ep 2. e2 3. exf1=S 4. Sxd2 5. Sxb1 6. Sxa3 0-0-0!#
Luckily, illegal diagram can be fixed by removal of bPa4.
Then if White castling rights remain, ep is on. One ser-h#5 & 18 ser-h#6 tries exist, in which White does not bother to castle.
We don't know if this was a transcription error or a counting mistake by the composer.
Cook: Too many pawn captures required. For retro problem, illegal position implies unsound
* 1. ... dxc3#
1. fxe3ep 2. e2 3. exf1=S 4. Se3? 5. Sd5 Sb5# (must castle for AP)
1. fxe3ep 2. e2 3. exf1=S 4. Sxd2 5. Sxb1 6. Sxa3 0-0-0!#
Luckily, illegal diagram can be fixed by removal of bPa4.
Then if White castling rights remain, ep is on. One ser-h#5 & 18 ser-h#6 tries exist, in which White does not bother to castle.
We don't know if this was a transcription error or a counting mistake by the composer.
Cook: Too many pawn captures required. For retro problem, illegal position implies unsound
Mike Neumeier: The solution appears to be 1.fxe4 e.p. 2.e2 3.exf1=L 4.Ld3 5.Le4 6.Ld5 dxc3#. Was that the intention? (2013-02-18)
Arno Tüngler: There would even be a solution in 5 moves by 3.exf1=S 5.Sd5 Sb5#
However, in order to justify the e.p.-key there must be an AP prove that e2-e4 (and not a move by the wK or wRa1) was played as White's last move. Thus the only solution giving this in 6 moves is 1.fxe3 e.p. 2.e2 3.exf1=S 4.Sxd2 5.Sxb1 6.Sxa3 0-0-0!# (2013-02-18)
Mike Neumeier: It struck me as odd there was no solution listed. (2013-02-18)
Mike Neumeier: And, if we let black be the idle side, there is 1.Txg1 2.Lxh1 3.Kd1 4.Kc1 hxg1T#. What does the asterisk(*) mean? (2013-02-18)
Henrik Juel: The asterisk means that there is also a white mate if he had the move, in this case two mates, so maybe the stipulation should be ser-h#6**:
1.dxc3,Sb5# (2013-02-18)
Ladislav Packa: It is clear that e.p. is possible only when the wK and wRa1 done neither move.
What convention is used here for the right to castling? (2013-02-18)
Henrik Juel: White may castle, unless you can show that he has lost the right to castle. In this problem there is a major difficulty, I think: the position seems illegal.
White pawns captured b2xc3xd4xe5xf6, g2xf3, and axb, promoting on b8; Black captured bxc, dxc, and g3xh2. We cannot explain the destiny of [Ph7].
Reversing wPh3 and bPh2 seems to handle the illegality, but then the problem can be solved in 5 moves (2013-02-18)
Mike Neumeier: Thanks, Henrik. Maybe the stipulation was a typo. Considering all comments together, perhaps the stip should have been ser-h#5**, with the one solution being the 5-mover Arno gave. I do not think it can be proven, except by a stipulation of ser-h#5 that en passant is possible. Which leads to the question of convention. Can the existence of a unique solution as implied only by the stipulation be used to determine that en passant is permissible? Whether there is castling or not here seems immaterial. It is just another 6-move solution. There are 19 6-movers (Popeye) with one queenside castling among them. But only the one 5-mover. (2013-02-18)
Henrik Juel: By convention, an en passant capture as first move is not permitted, unless the pawn double step can be shown by some kind of retro analysis.
(Conversely, a castling is permitted, unless it can be shown by retro analysis that the right to castle has been lost, i.e., that king and/or rook has moved) (2013-02-18)
A.Buchanan: Suggested repair: Remove bPa4. Add AP to stipulation.
As Henrik points out, the diagram as it stands is illegal. We can't swap wPh3 & bPh2, because that allows 2 h#1 cooks.
Suppose we remove bPa4 instead. Then we still at least 5 White pawn captures: bxcxdxexf6 & gxf3. But wPh3 did still move from h2, so there are 3 Black pawn captures bxc, dxc & gxh2. So [bhP] died without capturing or promoting. [waP] must have promoted - so either [baP] was captured to clear the way, or [waP] captured to promote, and later [baP] promoted. Either way, all the numbers add up, and the position is legal. wPe4 cannot have just come from d3. So AP is triggered. Forward logic works just as before without bPa4. There is 1 5-move try, and 18 6-move tries, but AP eliminates them all because of need for castling to retrospectively justify the ep. (2013-02-23)
A.Buchanan: Mike asked: "Can the existence of a unique solution as implied only by the stipulation be used to determine that en passant is permissible?"
Answer: No. The stipulation does imply a default player to move, but otherwise cannot be used as a premise to determine game state (castling, en passant). (2022-03-21)
A.Buchanan: WinChloe & Yacpdb have the same cooked diagram as PDB, so I think this cook was in the design. I would like to post a sound version with bPa4 removed, and I think it would just be “Zigman correction” with no one else’s name mentioned in the credits. Is everyone ok with this? (2022-05-30)
Mario Richter: 'Bilten 1970' (printed 1971) contains on pp. 62-81 a complete report on the "Problem Duel Slovenia - Macedonia 1969", the problem here can be found on page 79 and is printed there exactly as given here.
Andrew's handling of the suggested correction (remove black pawn a4) is o.k. for me. (2022-05-31)
more ...
comment
Arno Tüngler: There would even be a solution in 5 moves by 3.exf1=S 5.Sd5 Sb5#
However, in order to justify the e.p.-key there must be an AP prove that e2-e4 (and not a move by the wK or wRa1) was played as White's last move. Thus the only solution giving this in 6 moves is 1.fxe3 e.p. 2.e2 3.exf1=S 4.Sxd2 5.Sxb1 6.Sxa3 0-0-0!# (2013-02-18)
Mike Neumeier: It struck me as odd there was no solution listed. (2013-02-18)
Mike Neumeier: And, if we let black be the idle side, there is 1.Txg1 2.Lxh1 3.Kd1 4.Kc1 hxg1T#. What does the asterisk(*) mean? (2013-02-18)
Henrik Juel: The asterisk means that there is also a white mate if he had the move, in this case two mates, so maybe the stipulation should be ser-h#6**:
1.dxc3,Sb5# (2013-02-18)
Ladislav Packa: It is clear that e.p. is possible only when the wK and wRa1 done neither move.
What convention is used here for the right to castling? (2013-02-18)
Henrik Juel: White may castle, unless you can show that he has lost the right to castle. In this problem there is a major difficulty, I think: the position seems illegal.
White pawns captured b2xc3xd4xe5xf6, g2xf3, and axb, promoting on b8; Black captured bxc, dxc, and g3xh2. We cannot explain the destiny of [Ph7].
Reversing wPh3 and bPh2 seems to handle the illegality, but then the problem can be solved in 5 moves (2013-02-18)
Mike Neumeier: Thanks, Henrik. Maybe the stipulation was a typo. Considering all comments together, perhaps the stip should have been ser-h#5**, with the one solution being the 5-mover Arno gave. I do not think it can be proven, except by a stipulation of ser-h#5 that en passant is possible. Which leads to the question of convention. Can the existence of a unique solution as implied only by the stipulation be used to determine that en passant is permissible? Whether there is castling or not here seems immaterial. It is just another 6-move solution. There are 19 6-movers (Popeye) with one queenside castling among them. But only the one 5-mover. (2013-02-18)
Henrik Juel: By convention, an en passant capture as first move is not permitted, unless the pawn double step can be shown by some kind of retro analysis.
(Conversely, a castling is permitted, unless it can be shown by retro analysis that the right to castle has been lost, i.e., that king and/or rook has moved) (2013-02-18)
A.Buchanan: Suggested repair: Remove bPa4. Add AP to stipulation.
As Henrik points out, the diagram as it stands is illegal. We can't swap wPh3 & bPh2, because that allows 2 h#1 cooks.
Suppose we remove bPa4 instead. Then we still at least 5 White pawn captures: bxcxdxexf6 & gxf3. But wPh3 did still move from h2, so there are 3 Black pawn captures bxc, dxc & gxh2. So [bhP] died without capturing or promoting. [waP] must have promoted - so either [baP] was captured to clear the way, or [waP] captured to promote, and later [baP] promoted. Either way, all the numbers add up, and the position is legal. wPe4 cannot have just come from d3. So AP is triggered. Forward logic works just as before without bPa4. There is 1 5-move try, and 18 6-move tries, but AP eliminates them all because of need for castling to retrospectively justify the ep. (2013-02-23)
A.Buchanan: Mike asked: "Can the existence of a unique solution as implied only by the stipulation be used to determine that en passant is permissible?"
Answer: No. The stipulation does imply a default player to move, but otherwise cannot be used as a premise to determine game state (castling, en passant). (2022-03-21)
A.Buchanan: WinChloe & Yacpdb have the same cooked diagram as PDB, so I think this cook was in the design. I would like to post a sound version with bPa4 removed, and I think it would just be “Zigman correction” with no one else’s name mentioned in the credits. Is everyone ok with this? (2022-05-30)
Mario Richter: 'Bilten 1970' (printed 1971) contains on pp. 62-81 a complete report on the "Problem Duel Slovenia - Macedonia 1969", the problem here can be found on page 79 and is printed there exactly as given here.
Andrew's handling of the suggested correction (remove black pawn a4) is o.k. for me. (2022-05-31)
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Keywords: Castling (wg), Seriesmover, a posteriori (AP) (Type Petrovic), Illegal position, En passant as key, Promotion (s), Valladao Task, Superseded by (P1401546)
Genre: Retro, Fairies
Computer test: Popeye v4.87 but simple retro-logic shows illegality
FEN: 8/8/5P2/2p1p3/p1pkPp2/N1p2P1P/2PP1PBp/RN2KRbr
Reprints: 104 Bilten 1970 1971
(72) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-01 more...
Genre: Retro, Fairies
Computer test: Popeye v4.87 but simple retro-logic shows illegality
FEN: 8/8/5P2/2p1p3/p1pkPp2/N1p2P1P/2PP1PBp/RN2KRbr
Reprints: 104 Bilten 1970 1971
(72) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-01 more...
1. ... hxg6ep#, 1. gxh4 2. h3 3. h2 4. h1=L 5. Lc6 6. Le8 7. Lxh5 g5#
Keywords: En passant as key, Seriesmover, Promotion in forward play
Genre: Retro
FEN: 8/7p/4NP1k/5KpP/6PR/8/8/8
Input: Gerd Wilts, 1996-07-24
Last update: James Malcom, 2021-01-29 more...
Genre: Retro
FEN: 8/7p/4NP1k/5KpP/6PR/8/8/8
Input: Gerd Wilts, 1996-07-24
Last update: James Malcom, 2021-01-29 more...
1. Sc8 2. Sxb6 3. Sxa4 4. Sb2 5. Sd3 6. Se1 7. Sf3 8. exd3ep 9. Kd4 10. Ke4 11. Sd4 12. gxf3ep 13. Kf4 14. Kg4 15. f4 16. Sf5 exf3#
NL. Verbesserung 1998 erschienen: P1000933
Cook: 1. Lf7 2. Txe5 3. Kd5 4. Ke6 5. Kf6 6. Sg7 7. Se6 8. Tg6 9. Dh7 10. Dg7 dxe5#
außerdem Dual in der AL
1. Sc8 2. Sxb6 3. Sxa4 4. Sc5
NL. Verbesserung 1998 erschienen: P1000933
Cook: 1. Lf7 2. Txe5 3. Kd5 4. Ke6 5. Kf6 6. Sg7 7. Se6 8. Tg6 9. Dh7 10. Dg7 dxe5#
außerdem Dual in der AL
1. Sc8 2. Sxb6 3. Sxa4 4. Sc5
Keywords: Seriesmover, Consequent, En passant (x2)
Genre: Retro, Fairies
FEN: 8/4n3/1P2b3/3rPprn/P1kPpPpq/2p1p1p1/4P1Pb/7K
Input: Gerd Wilts, 1998-06-26
Last update: Mario Richter, 2021-09-16 more...
Genre: Retro, Fairies
FEN: 8/4n3/1P2b3/3rPprn/P1kPpPpq/2p1p1p1/4P1Pb/7K
Input: Gerd Wilts, 1998-06-26
Last update: Mario Richter, 2021-09-16 more...
1. gxf3ep 2. Dg4 3. 0-0-0 4. Te8 5. Kd8 6. Dxh5 0-0-0#
Henrik Juel: 1.gxf3ep 2.Qg4 3.000 4.Re8 5.Kd8 6.Qxh5 000#. Both castlings are necessary to legitimize the en passant capture. (2003-09-29)
A.Buchanan: I don't think this is consequent series mover, under which every position would considered afresh from the perspective of legality i.e. possible histories. Instead, this is regular series mover where one player is simply saying "pass". It's hard to imagine how AP might operate in a consequent context. I will change the keyword suitably. (2021-11-08)
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A.Buchanan: I don't think this is consequent series mover, under which every position would considered afresh from the perspective of legality i.e. possible histories. Instead, this is regular series mover where one player is simply saying "pass". It's hard to imagine how AP might operate in a consequent context. I will change the keyword suitably. (2021-11-08)
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Keywords: a posteriori (AP), Seriesmover, Castling, En passant as key
Genre: Retro, Fairies
FEN: r3k3/ppp1p3/2p5/6PP/5Ppq/1P4nB/PrP1P1p1/R3K1nb
Input: Gerd Wilts, 1998-06-26
Last update: A.Buchanan, 2021-11-08 more...
Genre: Retro, Fairies
FEN: r3k3/ppp1p3/2p5/6PP/5Ppq/1P4nB/PrP1P1p1/R3K1nb
Input: Gerd Wilts, 1998-06-26
Last update: A.Buchanan, 2021-11-08 more...
1. c5 2. c4 3. c3 4. c2 5. c1=S 6. Kf7 7. Kg6 8. Kh5 9. Kxh4 10. h5 g3#
Vor Kf7-e8 geschah Bg6xh7, deshalb muß zuerst einer der sB durch Umwandlung eliminiert werden.
In der Diagrammstellung haben die Bauern jeweils alle fehlenden gegnerischen Steine geschlagen:
W: Bdxexfxgxh, Baxbxa (oder Bcxbxa)
S: Bfxg, Bdxcxb, Bexdxcxb, Bbxa
Nach 1. Kf7? oder 1. Kf8 2. Kg7 3. Kg6 hätte W jeweils keinen letzten Zug. (R: h3-h4 sperrt den Th1 aus, der aber auch zu den Schlagopfern der sBB gehörte).
Also muß im Vorwärtsspiel zunächst eine Stellung mit geänderter Schlagbilanz erreicht werden.
Der Versuch 1. Kf8 2.Kg8 3. Kxh7 4. Kg6 5. Kh5 6. Kxh4? - aber nun hat W keinen letzten Zug - zeigt, daß der wBh7 erhalten bleiben muß, also muß die virtuelle Rücknahme h2,h3-h4 ermöglicht werden. Dies geschieht durch "Elimination" des Bc7, indem dieser auf c1 umwandelt. Bei einem sUW-Lc1 würden weiterhin 7 sBB-Schläge erforderlich sein, sUW-Dc1 oder sUW-Tc1 böten Schach, sodaß nur ein sUW-Sc1 übrig bleibt.
Nach 1. c5 2. c4 3. c3 4. c2 5. c1=S 6. Kf7 hat W nun h2,h3-h4 als Rücknahmemöglichkeit, weil nun der wTh1 nicht mehr notwendig als Schlagobjekt benötigt wird.
Vor Kf7-e8 geschah Bg6xh7, deshalb muß zuerst einer der sB durch Umwandlung eliminiert werden.
In der Diagrammstellung haben die Bauern jeweils alle fehlenden gegnerischen Steine geschlagen:
W: Bdxexfxgxh, Baxbxa (oder Bcxbxa)
S: Bfxg, Bdxcxb, Bexdxcxb, Bbxa
Nach 1. Kf7? oder 1. Kf8 2. Kg7 3. Kg6 hätte W jeweils keinen letzten Zug. (R: h3-h4 sperrt den Th1 aus, der aber auch zu den Schlagopfern der sBB gehörte).
Also muß im Vorwärtsspiel zunächst eine Stellung mit geänderter Schlagbilanz erreicht werden.
Der Versuch 1. Kf8 2.Kg8 3. Kxh7 4. Kg6 5. Kh5 6. Kxh4? - aber nun hat W keinen letzten Zug - zeigt, daß der wBh7 erhalten bleiben muß, also muß die virtuelle Rücknahme h2,h3-h4 ermöglicht werden. Dies geschieht durch "Elimination" des Bc7, indem dieser auf c1 umwandelt. Bei einem sUW-Lc1 würden weiterhin 7 sBB-Schläge erforderlich sein, sUW-Dc1 oder sUW-Tc1 böten Schach, sodaß nur ein sUW-Sc1 übrig bleibt.
Nach 1. c5 2. c4 3. c3 4. c2 5. c1=S 6. Kf7 hat W nun h2,h3-h4 als Rücknahmemöglichkeit, weil nun der wTh1 nicht mehr notwendig als Schlagobjekt benötigt wird.
Henrik Juel (PDB 2021-09-15): This is one of the few shc#'s without ep capture and/or castling
Henrik Juel: I don't agree entirely with you comment, James; this seems clearer:
1.Kf7? does not work, because now White has no last move ([Th1] was captured by a pawn)
1.Kf8 2.Kg7 3.Kg6? fails for the same reason
After 5.c1=S 6.Kf7 last move was h3-h4 or h2-h4
This is one of the few shc#'s without ep capture and/or castling (2021-09-15)
James Malcom: Henrik, what comment of mine? I merely edit swapped some text. (2021-09-15)
Henrik Juel: OK, so it was probably Gerd who wrote it in 1998; the early updates are no longer available, when you click on 'more...'
The german text roughly translates to:
Pg6xh7 happened before Kf7-e8, so first one of the black pawns must be eliminated by promotion.
I still like my comment better... (2021-09-15)
comment
Henrik Juel: I don't agree entirely with you comment, James; this seems clearer:
1.Kf7? does not work, because now White has no last move ([Th1] was captured by a pawn)
1.Kf8 2.Kg7 3.Kg6? fails for the same reason
After 5.c1=S 6.Kf7 last move was h3-h4 or h2-h4
This is one of the few shc#'s without ep capture and/or castling (2021-09-15)
James Malcom: Henrik, what comment of mine? I merely edit swapped some text. (2021-09-15)
Henrik Juel: OK, so it was probably Gerd who wrote it in 1998; the early updates are no longer available, when you click on 'more...'
The german text roughly translates to:
Pg6xh7 happened before Kf7-e8, so first one of the black pawns must be eliminated by promotion.
I still like my comment better... (2021-09-15)
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Keywords: Seriesmover, Consequent, Promotion (s), Excelsior
Genre: Retro, Fairies
FEN: 4k3/2p4P/7p/P5p1/pp4pP/bp6/pP2PPP1/K4B2
Input: Gerd Wilts, 1998-06-26
Last update: Mario Richter, 2021-09-16 more...
Genre: Retro, Fairies
FEN: 4k3/2p4P/7p/P5p1/pp4pP/bp6/pP2PPP1/K4B2
Input: Gerd Wilts, 1998-06-26
Last update: Mario Richter, 2021-09-16 more...
15 - P0501008
Karl Pohlheim
5883 Schach 12/1968
Ein Sylversterscherz
(1+8) cooked
ser-h=16
b) sGh8 nach h2
sDU=Grashüpfer
Karl Pohlheim
5883 Schach 12/1968
Ein Sylversterscherz
(1+8) cooked
ser-h=16
b) sGh8 nach h2
sDU=Grashüpfer
a) 1. Kg3 2. Kh2 3. Gh1 4. Kg2 5. Gg1 6. Kf2 7. Gf1 8. Ke2 9. Ge1 10. Kd2 11. Gd1 12. Kc2 13. Gc1 14. Kb2 15. Gb1 16. Ka1 Ka3=
b) 1. Kg5 2. Kh6 3. Gh7 4. Kg7 5. Gg6 6. Kf6 7. Gf5 8. Ke5 9. Ke4 10. Kd4 11. Gd3 12. Kc3 13. Gc2 14. Kb2 15. Gb1 16. Ka1 Ka3=
Cook: in b) 1. Ke5 2. Ke6 3. Gd5 4. Kf5 5. Gg4 6. Ke4 7. Ge3 8. Kd3 9. Kc2 10. Kb2 11. Ga8 12. Gb1 13. Ka1 14. Ga3 Kxa3=
b) 1. Kg5 2. Kh6 3. Gh7 4. Kg7 5. Gg6 6. Kf6 7. Gf5 8. Ke5 9. Ke4 10. Kd4 11. Gd3 12. Kc3 13. Gc2 14. Kb2 15. Gb1 16. Ka1 Ka3=
Cook: in b) 1. Ke5 2. Ke6 3. Gd5 4. Kf5 5. Gg4 6. Ke4 7. Ge3 8. Kd3 9. Kc2 10. Kb2 11. Ga8 12. Gb1 13. Ka1 14. Ga3 Kxa3=
HBae: Korrekturvorschlag b) sKf4 nach h7
1.Kh6 2.Gh5 3.Gh7 4.Kg7 ... usw. Eine Prüfung mit Popeye habe ich nach nach 13 Std. abgebrochen. (2021-06-06)
HBae: Mit sKh7 auch NL: 1.Ga8 2.Ga3 3.Kg6 4.Gg5 5.Kf5 6.Ke4 7.Gh4 8.Gh3 9.Gd4 10.Ke3 11.Ge2 12.Kd3 13.Kc3 14.Kb2 15.Gb1 16.Ka1 Kxa3= (2021-06-06)
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1.Kh6 2.Gh5 3.Gh7 4.Kg7 ... usw. Eine Prüfung mit Popeye habe ich nach nach 13 Std. abgebrochen. (2021-06-06)
HBae: Mit sKh7 auch NL: 1.Ga8 2.Ga3 3.Kg6 4.Gg5 5.Kf5 6.Ke4 7.Gh4 8.Gh3 9.Gd4 10.Ke3 11.Ge2 12.Kd3 13.Kc3 14.Kb2 15.Gb1 16.Ka1 Kxa3= (2021-06-06)
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Keywords: Seriesmover
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: 1*2q*2q*2q*2q*2q*2q*2q/8/8/8/K4k2/8/8/8
Input: Gerd Wilts, 1996-06-06
Last update: Vaclav Kotesovec, 2020-07-01 more...
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: 1*2q*2q*2q*2q*2q*2q*2q/8/8/8/K4k2/8/8/8
Input: Gerd Wilts, 1996-06-06
Last update: Vaclav Kotesovec, 2020-07-01 more...
1. Da8 2. Kb7 3. Kc6 4. Kd5 5. Ke4 6. Kf3 7. Kg2 8. Kg1 9. Dh1 10. g2 11. Lh2 12. g3 13. Lh3 14. g4 Ke2=
paul: This problem could be done as an ser-auto-stalemate (with inverted colors). (2013-04-30)
Olaf Jenkner: It's not a good idea to add another fairy condition. (2021-03-26)
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Olaf Jenkner: It's not a good idea to add another fairy condition. (2021-03-26)
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Keywords: Seriesmover, Homebase
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 2k5/2bb4/8/6p1/6p1/5qp1/8/4K3
Input: Gerd Wilts, 1996-06-06
Last update: Arnold Beine, 2022-09-14 more...
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 2k5/2bb4/8/6p1/6p1/5qp1/8/4K3
Input: Gerd Wilts, 1996-06-06
Last update: Arnold Beine, 2022-09-14 more...
1. b1=D 2. Db4 3. De1 4. b4 5. b3 6. b2 7. b1=D 8. Db6 9. Dbg1 10. b5 11. b4 12. b3 13. b2 14. b1=D 15. Db8 16. c1=D 17. Dcf4 18. Dff1 19. Tf2 20. f5 21. f4 22. f3 23. Sh1 24. Dbh2 25. Tg3 26. Lh3 27. Dfg2 28. Def1 29. Ke1 Kc2 =
Cook: NL (s.PK137):
von George P.~Sphicas wird folgende von
Mike Neumeier gefundene NL mitgeteilt: 1.Tf2 2.b1\prom{S} 3.Sd2
4.Sf3 5.Sg1 6.b4 9.b1\prom{L} 10.La2 11.Lad5 12.Lf1 13.L5g2 14.b5
18.b1\prom{D} 19.Db4 20.De1 21.f5 23.f3 24.Sh1 25.Tg3 26.Lh3
27.L1g2 28.Df1 29.Ke1 K×c2=
Cook: NL (s.PK137):
von George P.~Sphicas wird folgende von
Mike Neumeier gefundene NL mitgeteilt: 1.Tf2 2.b1\prom{S} 3.Sd2
4.Sf3 5.Sg1 6.b4 9.b1\prom{L} 10.La2 11.Lad5 12.Lf1 13.L5g2 14.b5
18.b1\prom{D} 19.Db4 20.De1 21.f5 23.f3 24.Sh1 25.Tg3 26.Lh3
27.L1g2 28.Df1 29.Ke1 K×c2=
Erich Bartel: Nachdrucke:
1) G29 Fide-Album 1989-1991
2) 975 Minimalkunst im Schach 2006 (2013-03-07)
paul: See P1330761 as correction. (2022-07-10)
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1) G29 Fide-Album 1989-1991
2) 975 Minimalkunst im Schach 2006 (2013-03-07)
paul: See P1330761 as correction. (2022-07-10)
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Keywords: Promotion (dddd), Rex solus (w), Seriesmover
Genre: Fairies
FEN: 8/1p3p2/5r2/1p6/6p1/3K2nr/1pp1p1b1/3k4
Input: Gerd Wilts, 1996-06-06
Last update: Alfred Pfeiffer, 2013-07-17 more...
Genre: Fairies
FEN: 8/1p3p2/5r2/1p6/6p1/3K2nr/1pp1p1b1/3k4
Input: Gerd Wilts, 1996-06-06
Last update: Alfred Pfeiffer, 2013-07-17 more...
18 - P0501043
Theodor Steudel
AHK-Memorial 1983-1985
2. Preis
(1+4) C+
ser-h#5
magischer Kb8
b) wKb8 nach g8
Theodor Steudel
AHK-Memorial 1983-1985
2. Preis
(1+4) C+
ser-h#5
magischer Kb8
b) wKb8 nach g8
a) 1. Th7 2. Kh2 3. La8(w) 4. Tb7(w) 5. Kh1 Th7# b) 1. Le4 2. Kg2 3. Th8(w) 4. Lh7(w) 5. Kh1 Le4#
Keywords: Seriesmover, Aristocrat, Miniature, Aristocrat
Genre: Fairies
Computer test: popeye 4.87
FEN: 1K6/8/8/8/8/8/6br/6nk
Input: Gerd Wilts, 1996-06-06
Last update: Arnold Beine, 2022-09-14 more...
Genre: Fairies
Computer test: popeye 4.87
FEN: 1K6/8/8/8/8/8/6br/6nk
Input: Gerd Wilts, 1996-06-06
Last update: Arnold Beine, 2022-09-14 more...
s) 1. La3 2. Sb5 3. Tc3 4. Kb4 Sd3#
w) 1. ... Tg5 2. Se6 3. Lf4 4. Kf6 Sd5#
w) 1. ... Tg5 2. Se6 3. Lf4 4. Kf6 Sd5#
ANDROMEDA FAIRY CHESS MATCH GREAT BRITAIN v HUNGARY 1993-95
SECTION 1 (Serieshelpmates in 4-8 moves)
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SECTION 1 (Serieshelpmates in 4-8 moves)
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Keywords: Seriesmover
Genre: Fairies
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/6K1/6Pn/p7/k4NR1/2n2r2/1bPB4/8
Input: Torsten Linss, 1999-04-07
Last update: Arnold Beine, 2022-09-14 more...
Genre: Fairies
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/6K1/6Pn/p7/k4NR1/2n2r2/1bPB4/8
Input: Torsten Linss, 1999-04-07
Last update: Arnold Beine, 2022-09-14 more...
20 - P0574405
Tivadar Kardos
Pavlos N. Moutecidis
Feladvanykedvelök Lapja 1970
5. ehrende Erwähnung
(2+5) cooked
ser-h=20
Tivadar Kardos
Pavlos N. Moutecidis
Feladvanykedvelök Lapja 1970
5. ehrende Erwähnung
(2+5) cooked
ser-h=20
Erich Bartel (2008-01-25):
1. Kb2 2. Ka3 3. Kb4 4. Kc4 5. Kd3 6. Ke3 7. Kf2 8. Kf1 9. h1=D 10. Dh8 11. Kf2 12. Ke3 13. Kd3 14. Kc4 15. Kb4 16. Ka3 17. Kb2 18. Kb1 19. Da1 20. b2 Sd4=
Cook: Anton Baumann (2020-11-20):
1. a1=L 2. Ld4 3. Lg1 4. h1=T 5. Th8 6. Le3 7. Lc1 8. Kb2 9. Ta8 10. Ta1 11. Tb1 12. Ka1 13. b2 14. d4 15. d3 16. d2 Sc3=
1. Kb2 2. Ka3 3. Kb4 4. Kc4 5. Kd3 6. Ke3 7. Kf2 8. Kf1 9. h1=D 10. Dh8 11. Kf2 12. Ke3 13. Kd3 14. Kc4 15. Kb4 16. Ka3 17. Kb2 18. Kb1 19. Da1 20. b2 Sd4=
Cook: Anton Baumann (2020-11-20):
1. a1=L 2. Ld4 3. Lg1 4. h1=T 5. Th8 6. Le3 7. Lc1 8. Kb2 9. Ta8 10. Ta1 11. Tb1 12. Ka1 13. b2 14. d4 15. d3 16. d2 Sc3=
Anton Baumann: kürzer, wenn eine Umwandlungsfigur rechts abschirmt:
1.a1=L 3.Lg1 4.h1=T 6.Ta8 8.Lc1 9.Kb2 11.Tb1 12.Ka1 13.b2 16.d2 Sc3= (2020-11-20)
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1.a1=L 3.Lg1 4.h1=T 6.Ta8 8.Lc1 9.Kb2 11.Tb1 12.Ka1 13.b2 16.d2 Sc3= (2020-11-20)
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Keywords: Seriesmover
Genre: Fairies
FEN: 8/8/8/3p4/8/1p6/p3N2p/1k1K4
Input: Felber, Volker, 1999-12-20
Last update: Mario Richter, 2020-11-20 more...
Genre: Fairies
FEN: 8/8/8/3p4/8/1p6/p3N2p/1k1K4
Input: Felber, Volker, 1999-12-20
Last update: Mario Richter, 2020-11-20 more...
1. c1=T 2. Tc4 3. Th4 4. c4 5. c3 6. c2 7. c1=T 8. Tcc4 9. Tcf4 10. Ke4 11. d5 12. d4 13. d3 14. d2 15. d1=T 16. Td3 17. Tdf3 18. g1=T 19. Tg5 20. Tgh5 21. g5 22. g4 23. g3 24. g2 25. g1=T 26. T1g5 27. Lg4 28. Tgf5 29. Lg5 30. h6 The8=
Erstdarstellung der fünffachen Turmumwandlung im Ser.H=, vollständig
schlagfrei, auch im weißen Schlußzug. -eb-
Erich Bartel: t/GUW, u/ttttt.---
Nachdrucke:
1) 1064 Ajedrez Magico (28) VII 1971.---
2) feenschach (150) I-III 2003,S.44.--- (2008-07-06)
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schlagfrei, auch im weißen Schlußzug. -eb-
Erich Bartel: t/GUW, u/ttttt.---
Nachdrucke:
1) 1064 Ajedrez Magico (28) VII 1971.---
2) feenschach (150) I-III 2003,S.44.--- (2008-07-06)
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Keywords: Seriesmover, Promotion (konsekutiv ttttt)
Genre: Fairies
FEN: 1KbR3R/3p3p/5ppb/2pkn3/8/7p/2p2PpP/7B
Input: Felber, Volker, 1999-12-20
Last update: Arnold Beine, 2022-09-14 more...
Genre: Fairies
FEN: 1KbR3R/3p3p/5ppb/2pkn3/8/7p/2p2PpP/7B
Input: Felber, Volker, 1999-12-20
Last update: Arnold Beine, 2022-09-14 more...
22 - P0574436
Endre Szentai
Feladvanykedvelök Lapja 1970
1.-2. Preis
(5+1) C+
ser-h=32
b) sKf1 nach h6, +wTg1, ser-h=36
Endre Szentai
Feladvanykedvelök Lapja 1970
1.-2. Preis
(5+1) C+
ser-h=32
b) sKf1 nach h6, +wTg1, ser-h=36
a) 1. Kg1 2. Kh2 3. Kh3 4. Kh4 5. Kg5 6. Kf6 7. Kf7 8. Ke8 9. Kd8 10. Kc7 11. Kb8 12. Ka7 13. Ka6 14. Kb5 15. Kxb4 16. Kb5 17. Ka6 18. Ka7 19. Kb8 20. Kc7 21. Kd8 22. Ke7 23. Kf6 24. Kg5 25. Kh4 26. Kh3 27. Kh2 28. Kg1 29. Kf1 30. Ke1 31. Kd1 32. Kc1 Ke2=
b) 1. Kh5 2. Kh4 3. Kh3 4. Kh2 5. Kxg1 6. Kh2 7. Kh3 8. Kh4 9. Kg5 10. Kf6 11. Kf7 12. Ke8 13. Kd8 14. Kc7 15. Kb8 16. Ka7 17. Ka6 18. Kb5 19. Kxb4 20. Kb5 21. Ka6 22. Ka7 23. Kb8 24. Kc7 25. Kd8 26. Ke7 27. Kf6 28. Kg5 29. Kh4 30. Kh3 31. Kh2 32. Kg1 33. Kf1 34. Ke1 35. Kd1 36. Kc1 Ke2=
b) 1. Kh5 2. Kh4 3. Kh3 4. Kh2 5. Kxg1 6. Kh2 7. Kh3 8. Kh4 9. Kg5 10. Kf6 11. Kf7 12. Ke8 13. Kd8 14. Kc7 15. Kb8 16. Ka7 17. Ka6 18. Kb5 19. Kxb4 20. Kb5 21. Ka6 22. Ka7 23. Kb8 24. Kc7 25. Kd8 26. Ke7 27. Kf6 28. Kg5 29. Kh4 30. Kh3 31. Kh2 32. Kg1 33. Kf1 34. Ke1 35. Kd1 36. Kc1 Ke2=
Keywords: Seriesmover, Aristocrat, Miniature, Aristocrat
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 8/8/1N6/8/1BN1B3/5K2/8/5k2
Input: Felber, Volker, 1999-12-20
Last update: Arnold Beine, 2022-09-15 more...
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 8/8/1N6/8/1BN1B3/5K2/8/5k2
Input: Felber, Volker, 1999-12-20
Last update: Arnold Beine, 2022-09-15 more...
a) 1. Th7 ... 2. Kg7 ... 3. Kh8 ... 4. T1g7 Le5=
b) 1. ... Txh4 h5 2. Kxh3 Th6 3. Txh5 T6h7 4. Th6 Txh6#
b) 1. ... Txh4 h5 2. Kxh3 Th6 3. Txh5 T6h7 4. Th6 Txh6#
Keywords: Twinning by continuation, Stipulation change, Seriesmover
Genre: Fairies, s#
Computer test: Gustav 4.2a
FEN: 1B3kB1/4N1r1/7p/7R/7p/7p/7K/6r1
Input: Felber, Volker, 1999-12-26
Last update: Arnold Beine, 2022-08-17 more...
Genre: Fairies, s#
Computer test: Gustav 4.2a
FEN: 1B3kB1/4N1r1/7p/7R/7p/7p/7K/6r1
Input: Felber, Volker, 1999-12-26
Last update: Arnold Beine, 2022-08-17 more...
1. Kf5 2. Sd3 3. Sf4 4. Kg4 5. Kf3 6. Sd5 7. Se3 8. Ke2 9. Kd3 10. Sf5 11. Sd4 12. Kxc4 13. Kd5 14. Sf3 15. Se5 16. Ke6 Se3=
Keywords: Seriesmover, Pure Round Trip (k)
Genre: Fairies
Computer test: Alybadix
FEN: 4N3/4p3/p1P1k1P1/rp2n3/pPP1R3/K7/6N1/8
Reprints: FIDE Album 1965-1967
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-15 more...
Genre: Fairies
Computer test: Alybadix
FEN: 4N3/4p3/p1P1k1P1/rp2n3/pPP1R3/K7/6N1/8
Reprints: FIDE Album 1965-1967
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-15 more...
1. d2 2. d1=D 3. Dxa4 4. Dc4 5. a4 6. a3 7. a2 8. a1=D 9. Dg1 10. Dxg6 11. De8 12. g5 13. g4 14. g3 15. gxh2 16. h1=D 17. Dh3 18. Dhe6 19. h3 20. h2 21. h1=D 22. Dh4 23. Dhd8 24. h4 25. h3 26. h2 27. h1=D 28. Dhh4 29. Dhe7 30. Dc6+ bxc6#
Keywords: Seriesmover, Promotions to queens, konsekutive Umwandlungen 5, Kindergarten Problem
Genre: Fairies
Computer test: Alybadix
FEN: 8/1K1k2p1/3p2Pp/pP5p/P3P2p/2Pp4/7P/8
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-15 more...
Genre: Fairies
Computer test: Alybadix
FEN: 8/1K1k2p1/3p2Pp/pP5p/P3P2p/2Pp4/7P/8
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-15 more...
1. f1=S 2. Sxh2 3. Sg4 4. h2 5. h1=T 6. Th5 7. Tg5 8. h5 9. h4 10. h3 11. h2 12. h1=T 13. Th6 14. Thg6 15. h5 16. h4 17. h3 18. h2 19. h1=T 20. Th8 21. Tb8 22. Txb7 23. Kb8 24. Kc8 25. Kd8 26. Ke7 27. Kf6 28. Kxf5 29. Df6 30. c3 31. c2 32. c1=L 33. Lxb2 34. Le5 35. b2 36. b1=L 37. La2 38. Le6 39. dxc5 40. c4 41. c3 42. c2 43. c1=L 44. Lcf4 e4#
Erich Bartel: Nachdruck:
1) Umwandlungsrekorde I 1985.---:w (2008-01-27)
Anton Baumann: C+ Gustav 4.2a (2023-09-16)
Vaclav Kotesovec: Anton, this is an incredible result. Was your test "brute force" ? Can you also add an elapsed time ? (2023-09-16)
Vaclav Kotesovec: 4 hours later... Since I couldn't believe this fantastic result at first, I tested the problem myself and Gustav tested it in less than 4 hours. Thank you Olaf for the great improvement! (2023-09-16)
comment
1) Umwandlungsrekorde I 1985.---:w (2008-01-27)
Anton Baumann: C+ Gustav 4.2a (2023-09-16)
Vaclav Kotesovec: Anton, this is an incredible result. Was your test "brute force" ? Can you also add an elapsed time ? (2023-09-16)
Vaclav Kotesovec: 4 hours later... Since I couldn't believe this fantastic result at first, I tested the problem myself and Gustav tested it in less than 4 hours. Thank you Olaf for the great improvement! (2023-09-16)
comment
Keywords: Seriesmover
Genre: Fairies
Computer test: Anton Baumann: Gustav 4.2a, V. Kotesovec: Gustav 4.2e (Lösezeit: 03 : 55 : 44,97 h, Hashtables: 100000 MB)
FEN: b7/kNp4p/2Kp3p/1PP2P2/2p5/PpqP3p/1P2Pp1P/8
Reprints: 632 FIDE Album 1977-1979 , p. 126,
Input: Felber, Volker, 1999-12-27
Last update: Vaclav Kotesovec, 2023-09-16 more...
Genre: Fairies
Computer test: Anton Baumann: Gustav 4.2a, V. Kotesovec: Gustav 4.2e (Lösezeit: 03 : 55 : 44,97 h, Hashtables: 100000 MB)
FEN: b7/kNp4p/2Kp3p/1PP2P2/2p5/PpqP3p/1P2Pp1P/8
Reprints: 632 FIDE Album 1977-1979 , p. 126,
Input: Felber, Volker, 1999-12-27
Last update: Vaclav Kotesovec, 2023-09-16 more...
*) 1. d3 2. Lg1 3. Df2 4. Da7 5. Lb6 6. Tc1 7. Tc6 bxc6#
1) 1. ... b6, dann Tc8 2. Kb8 3. Lg2 4. Df3 5. Da8 6. Lb7 7. Tc7+ bxc7#
1) 1. ... b6, dann Tc8 2. Kb8 3. Lg2 4. Df3 5. Da8 6. Lb7 7. Tc7+ bxc7#
Keywords: Seriesmover, Minimal, Turton, Räumung and Bahnung
Genre: Fairies
Computer test: Jacobi
FEN: br6/bk1K4/p3p3/1P6/3p4/8/8/5q1r
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-17 more...
Genre: Fairies
Computer test: Jacobi
FEN: br6/bk1K4/p3p3/1P6/3p4/8/8/5q1r
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-17 more...
28 - P0575717
Emiliano F. Ruth
harmonie 46 06/1996
2. Preis, Abt. A, 8. harmonie-TT 1995/96
(7+3) cooked
1w->ser-h=34
Circe
Kürzestzüger
Emiliano F. Ruth
harmonie 46 06/1996
2. Preis, Abt. A, 8. harmonie-TT 1995/96
(7+3) cooked
1w->ser-h=34
Circe
Kürzestzüger
1. ... Lg1, dann Kg5 2. Kg6 3. Kxf6[+wBf2] 4. Ke6 5. Kd6 6. Kc6 7. Kc5 8. Kb5 9. Kb4 10. Kb3 11. Kb2 12. Kb1 13. Kc1 14. Kd1 15. Ke1 16. Kf1 17. Kxg1[+wLc1] 18. Kf1 19. Ke1 20. Kd1 21. Kxc1 22. Kb1 23. Kb2 24. Kb3 25. Kb4 26. Kb5 27. Kxb6[+wSg1] 28. Kc6 29. Kd6 30. Ke6 31. Kf6 32. Kg6 33. Kg5 34. Kg4 h4=
Cook: 1. ... Sa8, dann g1=T 2. Th1 3. Txh2 4. Th3 5. Th4 6. Kxg3[+wBg2] 7. Kg4 8. Kg5 9. Tg4 10. Tf4 11. Txe4[+wBe2] 12. Tf4 13. Kg6 14. Kxf6[+wBf2] 15. Ke6 16. Ke5 17. Kd5 18. Kxc5[+wLc1] 19. Kd5 20. Ke5 21. Kf5 22. Kg5 23. Kg4 24. Kh4 25. Tf3+ exf3=
Cook: 1. ... Sa8, dann g1=T 2. Th1 3. Txh2 4. Th3 5. Th4 6. Kxg3[+wBg2] 7. Kg4 8. Kg5 9. Tg4 10. Tf4 11. Txe4[+wBe2] 12. Tf4 13. Kg6 14. Kxf6[+wBf2] 15. Ke6 16. Ke5 17. Kd5 18. Kxc5[+wLc1] 19. Kd5 20. Ke5 21. Kf5 22. Kg5 23. Kg4 24. Kh4 25. Tf3+ exf3=
Arnold Beine: Kurzlösung in 25 Zügen:
1.Sa8! (besetzt das Wiedergeburtsfeld des sT, s. letzten Zug), dann g1=T 2.Th1 3.Txh2 4.Th3 5.Th4 6.Kxg3[+wBg2] 7.Kg4 8.Kg5 9.Tg4 10.Tf4 11.Txe4[+wBe2] 12.Tf4 13.Kg6 14.Kxf6[+wBf2] 15.Ke6 16.Ke5 17.Kd5 18.Kxc5[+wLc1] 19.Kd5 20.Ke5 21.Kf5 22.Kg5 23.Kg4 24.Kh4 25.Tf3+ exf3=
Mit dem Zusatz "exakt" in der Forderung wäre die Aufgabe korrekt (C+, Jacobi). (2022-09-20)
comment
1.Sa8! (besetzt das Wiedergeburtsfeld des sT, s. letzten Zug), dann g1=T 2.Th1 3.Txh2 4.Th3 5.Th4 6.Kxg3[+wBg2] 7.Kg4 8.Kg5 9.Tg4 10.Tf4 11.Txe4[+wBe2] 12.Tf4 13.Kg6 14.Kxf6[+wBf2] 15.Ke6 16.Ke5 17.Kd5 18.Kxc5[+wLc1] 19.Kd5 20.Ke5 21.Kf5 22.Kg5 23.Kg4 24.Kh4 25.Tf3+ exf3=
Mit dem Zusatz "exakt" in der Forderung wäre die Aufgabe korrekt (C+, Jacobi). (2022-09-20)
comment
Keywords: Seriesmover, Circe, Minimummer
Genre: Fairies
FEN: 8/8/1N3P2/2B4p/4P1k1/3K2P1/6pP/8
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-20 more...
Genre: Fairies
FEN: 8/8/1N3P2/2B4p/4P1k1/3K2P1/6pP/8
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-20 more...
29 - P0575718
Hans Ott
Hans Peter Rehm
harmonie 46 06/1996
Lob, Abt. A, 8. harmonie-TT 1995/96
(4+8) C+
1w->ser-h#7
2 Lösungen
Hans Ott
Hans Peter Rehm
harmonie 46 06/1996
Lob, Abt. A, 8. harmonie-TT 1995/96
(4+8) C+
1w->ser-h#7
2 Lösungen
1) 1. ... Se8, dann Sxd6 2. Se4 3. Ke3 4. Kf4 5. Kf5 6. Sg5 7. Df4 Sg7#
2) 1. ... Sh5, dann Lf7 2. Kd4 3. Kc5 4. Kxd6 5. Ke6 6. De7 7. Sd6 Sg7#
2) 1. ... Sh5, dann Lf7 2. Kd4 3. Kc5 4. Kxd6 5. Ke6 6. De7 7. Sd6 Sg7#
Keywords: Seriesmover
Genre: Fairies
Computer test: Popeye 4.61
FEN: 8/3p2N1/3P1pb1/4p3/1qn5/3k1B2/1p6/1K6
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-15 more...
Genre: Fairies
Computer test: Popeye 4.61
FEN: 8/3p2N1/3P1pb1/4p3/1qn5/3k1B2/1p6/1K6
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-15 more...
30 - P0575724
Theodor Steudel
harmonie 46 06/1996
3. ehrende Erwähnung, Abt. B, 8. harmonie-TT 1995/96
(6+13)
1w->ser-h=13*
Theodor Steudel
harmonie 46 06/1996
3. ehrende Erwähnung, Abt. B, 8. harmonie-TT 1995/96
(6+13)
1w->ser-h=13*
*) 1. f2 Ta1=
1) 1. ... Ta1, dann Tg2 2. Tde2 3. Kd2 4. Sa2 5. Sb4 6. Sxc6 7. Sb4 8. Sa2 9. Sc1 10. Kd1 11. Td2 12. Tge2 13. f2 c6=
1) 1. ... Ta1, dann Tg2 2. Tde2 3. Kd2 4. Sa2 5. Sb4 6. Sxc6 7. Sb4 8. Sa2 9. Sc1 10. Kd1 11. Td2 12. Tge2 13. f2 c6=
PR Torsten Linß zur 2. ehrenden Erwähnung (P0575722) und dieser Aufgabe: "Im Satz wird ein schwarzes `Eigenpatt' mit einem weißen Tempozug beantwortet. In der Lösung ist Weiß genötigt, sich im Vorschaltzug dieses Tempos zu berauben. Mit langzügigen Manövern stellt Schwarz einen anderen Tempozug bereit. Dabei kommt es zu Rückkehren von 2 bzw. 4 schwarzen Steinen. Die doppelte Rückkehr ist trotz `halben' Inhaltes wegen ihrer Eleganz und Subtilität besser. Der Unterschied, den ein Tempo ausmachen kann, ist gut herausgearbeitet, allerdings hätte mir ein Wechsel im Spiel (z. B. anderes Pattbild) noch mehr zugesagt."
paul: Probably a white Pawn b2 is missing. (2013-05-06)
Anton Baumann: mit wBb2 C+ Gustav 4.2a (Test für alle Züge 1w) (2022-05-30)
Mario Richter: in der mir vorliegenden Version des Preisberichtes (31. Januar 1997) steht im Diagramm kein wB auf b2 (2022-05-31)
comment
paul: Probably a white Pawn b2 is missing. (2013-05-06)
Anton Baumann: mit wBb2 C+ Gustav 4.2a (Test für alle Züge 1w) (2022-05-30)
Mario Richter: in der mir vorliegenden Version des Preisberichtes (31. Januar 1997) steht im Diagramm kein wB auf b2 (2022-05-31)
comment
Keywords: Seriesmover
Genre: Fairies
FEN: 8/2p5/2P5/2P5/6p1/1p1pppPp/2prr2P/1RnkbK2
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-15 more...
Genre: Fairies
FEN: 8/2p5/2P5/2P5/6p1/1p1pppPp/2prr2P/1RnkbK2
Input: Felber, Volker, 1999-12-27
Last update: Arnold Beine, 2022-09-15 more...
17. Kxf8 35. Kxd8 50. Kxe6 51. Kd7 56. e1=T 58. Tg8 fxg8=D=
Kr4Bzzz: NL: 51. Kf5 56. e1=T 57. Te8 fxe8=D= (2010-04-15)
Mario Richter: Wenn die Forderung lautete "ser-h=57", dann gäbe es genau eine Lösung. (2010-04-28)
Anton Baumann: als ser-h=57 C+ (Gustav 4.2a) (2023-10-30)
SCHRECKE: Ohne den wBh3 geht nur die AL! (2023-10-30)
comment
Mario Richter: Wenn die Forderung lautete "ser-h=57", dann gäbe es genau eine Lösung. (2010-04-28)
Anton Baumann: als ser-h=57 C+ (Gustav 4.2a) (2023-10-30)
SCHRECKE: Ohne den wBh3 geht nur die AL! (2023-10-30)
comment
Keywords: Seriesmover
Genre: Fairies
FEN: 2kN1R2/2p1pP2/2p1P3/2P5/2PP3B/2K3PP/6P1/8
Input: Felber, Volker, 2000-01-03
Last update: hpr, 2000-03-04 more...
Genre: Fairies
FEN: 2kN1R2/2p1pP2/2p1P3/2P5/2PP3B/2K3PP/6P1/8
Input: Felber, Volker, 2000-01-03
Last update: hpr, 2000-03-04 more...
1. Kh2 2. Kg3 3. Kxf3 4. Ke4 5. Kd5 6. Kc6 7. Kb7 8. Kxa8 9. Kb7 10. Kc6 11. Kc5 12. Kb4 13. Kxb3 14. Ka2 15. Kxa1 16. Kb1 17. Kc2 18. Kd3 19. Ke4 20. Kxf4 21. Kg5 22. Kxh6 23. Kg7 24. Kxh8 25. Kg7 26. Kh6 27. Kxh5 28. Kh4 29. Kxh3 30. Kh2 31. Kh1 h8=D/T#
Keywords: Seriesmover, Tolerated dual promotion, Rex solus (s)
Genre: Fairies
Computer test: Gustav 4.1d
FEN: R6N/7P/1P5P/7P/P1N2P2/1B3P1P/8/B4K1k
Reprints: V34 Problemkiste 125) 10/1999
Input: Felber, Volker, 2000-01-03
Last update: Gunter Jordan, 2023-07-21 more...
Genre: Fairies
Computer test: Gustav 4.1d
FEN: R6N/7P/1P5P/7P/P1N2P2/1B3P1P/8/B4K1k
Reprints: V34 Problemkiste 125) 10/1999
Input: Felber, Volker, 2000-01-03
Last update: Gunter Jordan, 2023-07-21 more...
1. Ke5 2. Kd4 3. Kxd3 4. Kc2 5. Kxb1 6. Kc2 7. b1=L 8. Da1 9. b2 10. b3 11. b4 12. Ta5 13. Ta2 14. T5a5 15. T5a3 16. La4 17. b5 18. La5 19. b6 Ke2=
Kurzlösung in 18 Zügen
Cook: 1. Txd3 2. Th3 3. Kd5 4. Kc4 5. Le5 6. Lf5 7. Lxb1 8. La2 9. b1=L 10. Da1 11. Kd3 12. Tc2 13. Lb2 14. La3 15. Tb2 16. Kc2 17. Th2 18. Te2+ Kxe2=
Kurzlösung in 18 Zügen
Cook: 1. Txd3 2. Th3 3. Kd5 4. Kc4 5. Le5 6. Lf5 7. Lxb1 8. La2 9. b1=L 10. Da1 11. Kd3 12. Tc2 13. Lb2 14. La3 15. Tb2 16. Kc2 17. Th2 18. Te2+ Kxe2=
Joshua Green: I've been testing some modifications to Popeye with the goal of improving its performance against seriesmovers. Unfortunately, my improved -- assuming there are no bugs -- Popeye cooked this problem, offering:
1. Txd3 2. Th3 3. Kd5 4. Kc4 5. Le5 6. Lf5 7. Lxb1 8. La2 9. b1L 10. Da1 11. Kd3 12. Tc2 13. Lb2 14. La3 15. Tb2 16. Kc2 17. Th2 18. Te2+ Kxe2= (2022-09-13)
comment
1. Txd3 2. Th3 3. Kd5 4. Kc4 5. Le5 6. Lf5 7. Lxb1 8. La2 9. b1L 10. Da1 11. Kd3 12. Tc2 13. Lb2 14. La3 15. Tb2 16. Kc2 17. Th2 18. Te2+ Kxe2= (2022-09-13)
comment
Keywords: Seriesmover
Genre: Fairies
FEN: 8/1pbb4/1p2k3/1prr4/1p6/1pqP4/1p1B4/1N2K3
Reprints: B21 Shift of groups of pawns in chess problems 28/04/2005
Input: Felber, Volker, 2000-01-03
Last update: Arnold Beine, 2022-09-13 more...
Genre: Fairies
FEN: 8/1pbb4/1p2k3/1prr4/1p6/1pqP4/1p1B4/1N2K3
Reprints: B21 Shift of groups of pawns in chess problems 28/04/2005
Input: Felber, Volker, 2000-01-03
Last update: Arnold Beine, 2022-09-13 more...
34 - P0576961
Laszlo Zoltan
György Bakcsi
D The Problemist , p. 312, 03/1994
4. ehrende Erwähnung, Sherlock Holmes Turnier 1994
(2+3) C+
ser-h#3
b) -wDa1, -sLc2: ser-r#4
c) -wDa1, -sTh7: ser-r=5
d) -sLc2, -sTh7: ser-h=4
Laszlo Zoltan
György Bakcsi
D The Problemist , p. 312, 03/1994
4. ehrende Erwähnung, Sherlock Holmes Turnier 1994
(2+3) C+
ser-h#3
b) -wDa1, -sLc2: ser-r#4
c) -wDa1, -sTh7: ser-r=5
d) -sLc2, -sTh7: ser-h=4
a) 1. Th3 2. Tc3 3. Ld3 Da4#
b) 1. ... Kc6 2. Kb6 3. Ka5 4. Ka4 Ta7#
c) 1. ... Ke5 2. Kf4 3. Ke3 4. Kd2 5. Kc1 Kc3=
d) 1. Kb5 2. Kb6 3. Kb7 4. Kb8 Da6=
b) 1. ... Kc6 2. Kb6 3. Ka5 4. Ka4 Ta7#
c) 1. ... Ke5 2. Kf4 3. Ke3 4. Kd2 5. Kc1 Kc3=
d) 1. Kb5 2. Kb6 3. Kb7 4. Kb8 Da6=
Thema des TT ('The Problemist' 09/1992, S. 88): "... composers are required to combine 2 (or more) problems to make a distinct third."
(Im 'Problemist' haben die Teilaufgaben a),b),c) und d) die Labels: D,A,B und C.
PR Barry Barnes vermutet in seinem Kommentar zu diesem Problem, daß ein Computer bei der Erstellung geholfen haben könnte: "Essentially disparate parts (A),(B) and (C) come together as something quite new in (D). But note a minimal record: 5 pieces, cyclic absence of 2 of the pieces, 4 different series-demands, and only ideal mates! Was Holmes right in thinking that a later model of Prof Babbage's "engine" (Cambridge,1834) determined the solving conditions and lengths?"
Anton Baumann: a)-d): C+ Alybadix (2022-02-25)
comment
(Im 'Problemist' haben die Teilaufgaben a),b),c) und d) die Labels: D,A,B und C.
PR Barry Barnes vermutet in seinem Kommentar zu diesem Problem, daß ein Computer bei der Erstellung geholfen haben könnte: "Essentially disparate parts (A),(B) and (C) come together as something quite new in (D). But note a minimal record: 5 pieces, cyclic absence of 2 of the pieces, 4 different series-demands, and only ideal mates! Was Holmes right in thinking that a later model of Prof Babbage's "engine" (Cambridge,1834) determined the solving conditions and lengths?"
Anton Baumann: a)-d): C+ Alybadix (2022-02-25)
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Keywords: Seriesmover, Aristocrat, Minimal, Miniature, Aristocrat, Aristocrat, Aristocrat
Genre: Fairies
Computer test: Anton Baumann (2022-02-25): a)-d): C+ Alybadix
FEN: 8/7r/3K4/8/2k5/8/2b5/Q7
Input: Felber, Volker, 2000-01-03
Last update: Mario Richter, 2022-02-27 more...
Genre: Fairies
Computer test: Anton Baumann (2022-02-25): a)-d): C+ Alybadix
FEN: 8/7r/3K4/8/2k5/8/2b5/Q7
Input: Felber, Volker, 2000-01-03
Last update: Mario Richter, 2022-02-27 more...
1. h1=D 2. Dxh4 3. Dg5 4. h4 5. h3 6. h2 7. h1=T 8. Txh6 9. Tg6 10. h5 11. h4 12. h3 13. h2 14. h1=S 15. Sg3 16. Sxe2 17. Sf4 18. e2 19. e1=D 20. Dxa5 21. Dxa6 22. Daf6 23. a5 24. a4 25. a3 26. a2 27. a1=L 28. Lxb2 29. Le5 30. b2 31. b1=L 32. La2 33. Le6 dxe4#
Erich Bartel: Nachdrucke:
1) feenschach VIII-IX 1975,S.124.---
2) Mat plus (6-7) 1995,S.237.---
3) MAT V 1979.---
4) Serienzugrekorde 1978-1984.---
5) 893 Kings & Pawns 1996.---
6) The Problemist V 1998,S.370.--- (2007-02-18)
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1) feenschach VIII-IX 1975,S.124.---
2) Mat plus (6-7) 1995,S.237.---
3) MAT V 1979.---
4) Serienzugrekorde 1978-1984.---
5) 893 Kings & Pawns 1996.---
6) The Problemist V 1998,S.370.--- (2007-02-18)
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Keywords: Seriesmover, Kindergarten Problem, Allumwandlung
Genre: Fairies
Computer test: Alybadix
FEN: 4K3/p6p/P6P/P4k1p/4p2P/1p1PpP2/1P2P2p/8
Input: Felber, Volker, 2000-01-04
Last update: Arnold Beine, 2022-09-19 more...
Genre: Fairies
Computer test: Alybadix
FEN: 4K3/p6p/P6P/P4k1p/4p2P/1p1PpP2/1P2P2p/8
Input: Felber, Volker, 2000-01-04
Last update: Arnold Beine, 2022-09-19 more...
36 - P0577047
Yves Cheylan
F1353 The Problemist 03/1993
2. ehrende Erwähnung
(4+8) C+
ser-h=8
Anticirce Cheylan
Yves Cheylan
F1353 The Problemist 03/1993
2. ehrende Erwähnung
(4+8) C+
ser-h=8
Anticirce Cheylan
1. Tcg1 2. Sc1 3. Ld1 4. Ta4 5. Ta1 6. Kd8 7. De4 8. De1 Ke8=
Gerald Ettl: Grundlinie-Einmauerung, sogar mit wK-Effekt. Mehr scheint wohl nicht zu gehen. (2009-02-10)
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Keywords: Circe (Anti-), Seriesmover
Genre: Fairies
Computer test: Alybadix
FEN: 2k2K2/2P2p2/1N3P2/8/b5r1/1n6/3p4/1qr5
Input: Felber, Volker, 2000-01-04
Last update: Arnold Beine, 2022-09-22 more...
Genre: Fairies
Computer test: Alybadix
FEN: 2k2K2/2P2p2/1N3P2/8/b5r1/1n6/3p4/1qr5
Input: Felber, Volker, 2000-01-04
Last update: Arnold Beine, 2022-09-22 more...
37 - P0577050
Franz Pachl
F1402 The Problemist 1993
4.-6. ehrende Erwähnung
(5+13) C+
ser-h#5
b) wKh6 nach b8
Franz Pachl
F1402 The Problemist 1993
4.-6. ehrende Erwähnung
(5+13) C+
ser-h#5
b) wKh6 nach b8
a) 1. Tb6 2. Se6 3. c5 4. c4 5. Sc7 Lxb6#
b) 1. Df4 2. Sd6 3. e4 4. e3 5. Sf5 Dxf4#
b) 1. Df4 2. Sd6 3. e4 4. e3 5. Sf5 Dxf4#
Anton Baumann: vermutlich Diagramm nicht korrekt:
a) unlösbar b) mehrere Lösungen (2020-12-08)
SCHRECKE: Der wBc2 muss offenbar auf b2 stehen!
Dann gibt es die Lösungen:
a) 1.Tb6 2.Se6 3.c5 4.c4 5.Sc7 L:b6#
b) 1.Df4 2.Sd6 3.e4 4.e3 5.Sf5 D:f4# (2020-12-08)
Mario Richter: Im Originaldiagramm wBb2 statt wBc2 - Stellung entsprechend korrigiert. (2020-12-09)
comment
a) unlösbar b) mehrere Lösungen (2020-12-08)
SCHRECKE: Der wBc2 muss offenbar auf b2 stehen!
Dann gibt es die Lösungen:
a) 1.Tb6 2.Se6 3.c5 4.c4 5.Sc7 L:b6#
b) 1.Df4 2.Sd6 3.e4 4.e3 5.Sf5 D:f4# (2020-12-08)
Mario Richter: Im Originaldiagramm wBb2 statt wBc2 - Stellung entsprechend korrigiert. (2020-12-09)
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Keywords: Seriesmover
Genre: Fairies
Computer test: Popeye Windows-64Bit v4.67
FEN: 3b4/B4r2/r1p4K/p1npp2p/3kn2Q/7p/1P2P2q/8
Input: Felber, Volker, 2000-01-04
Last update: Mario Richter, 2020-12-09 more...
Genre: Fairies
Computer test: Popeye Windows-64Bit v4.67
FEN: 3b4/B4r2/r1p4K/p1npp2p/3kn2Q/7p/1P2P2q/8
Input: Felber, Volker, 2000-01-04
Last update: Mario Richter, 2020-12-09 more...
38 - P0577107
Ian Shanahan
3168 U.S. Problem Bulletin 104 11/1994
G. Foster gewidmet
2. Preis
(4+11)
ser-h=18
b) sDh3 nach h2
Ian Shanahan
3168 U.S. Problem Bulletin 104 11/1994
G. Foster gewidmet
2. Preis
(4+11)
ser-h=18
b) sDh3 nach h2
a) 1. Th2 2. Lh1 3. Tfg2 4. Lf2 5. Tg1 6. Lg2 7. Tgh1 8. Kg1 9. Lf1 10. Tg2 11. Kh2 12. Lg1 13. Tf2 14. Dg2 15. Kh3 16. Th2 17. Dh1 18. g2 Sf5=
b) 1. Lh3 2. Dg2 3. Th2 4. Dh1 5. Lg2 6. Th3 7. Lh2 8. Kg1 9. Lf1 10. Dg2 11. Kh1 12. Lg1 13. Kh2 14. Dh1 15. g2 16. Kg3 17. Th2 18. Kh3 Sf5=
b) 1. Lh3 2. Dg2 3. Th2 4. Dh1 5. Lg2 6. Th3 7. Lh2 8. Kg1 9. Lf1 10. Dg2 11. Kh1 12. Lg1 13. Kh2 14. Dh1 15. g2 16. Kg3 17. Th2 18. Kh3 Sf5=
paul: a) 1.Rh2 2.Bh1 3.Rfg2 4.Bf2 5.Rg1 6.Bg2 7.Rgh1 8.Kg1 9.Bf1 10.Rg2 11.Kh2 12.Bg1 13.Rf2 14.Qg2 15.Kh3 16.Rh2 17.Qh1 18.g2 Sf5=
b) 1.Bh3 2.Qg2 3.Rh2 4.Qh1 5.Bg2 6.Rh3 7.Bh2 8.Kg1 9.Bf1 10.Qg2 11.Kh1 12.Bg1 13.Kh2 14.Qh1 15.g2 16.Kg3 17.Rh2 18.Kh3 Sf5=
The judge was H.P.Rehm. (2013-05-06)
Joshua Green: This is C+ according to a special version of Popeye that I've modified to improve performance on ser-h= and ser-h# problems (hopefully without introducing any bugs). (2022-09-15)
A.Buchanan: Hi Joshua: great stuff, thanks! I guess you’ve been working with a test set of previously validated compositions? Do you plan to merge your branch with the main Popeye version? (2022-09-16)
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b) 1.Bh3 2.Qg2 3.Rh2 4.Qh1 5.Bg2 6.Rh3 7.Bh2 8.Kg1 9.Bf1 10.Qg2 11.Kh1 12.Bg1 13.Kh2 14.Qh1 15.g2 16.Kg3 17.Rh2 18.Kh3 Sf5=
The judge was H.P.Rehm. (2013-05-06)
Joshua Green: This is C+ according to a special version of Popeye that I've modified to improve performance on ser-h= and ser-h# problems (hopefully without introducing any bugs). (2022-09-15)
A.Buchanan: Hi Joshua: great stuff, thanks! I guess you’ve been working with a test set of previously validated compositions? Do you plan to merge your branch with the main Popeye version? (2022-09-16)
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Keywords: Seriesmover
Genre: Fairies
FEN: 8/8/7p/7K/6PN/4pppq/4prb1/4Bkbr
Reprints: FIDE Album 1992-1994 2001
Input: Felber, Volker, 2000-01-04
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
FEN: 8/8/7p/7K/6PN/4pppq/4prb1/4Bkbr
Reprints: FIDE Album 1992-1994 2001
Input: Felber, Volker, 2000-01-04
Last update: Arnold Beine, 2022-10-31 more...
1. h1=D 2. Dh3 3. De6 4. h3 5. h2 6. h1=D 7. Dh4 8. Dd8 9. h4 10. h3 11. h2 12. h1=D 13. Dhh4 14. Dhe7 Lc6#
Keywords: Seriesmover (konsekutiv ddd), Minimal
Genre: Fairies
Computer test: (Popeye WINDOWS-32Bit-Version 3.65 (2048 KB))
FEN: 8/1K1k3p/3p4/7p/4B2p/8/7p/8
Input: Felber, Volker, 2000-01-06
Last update: James Malcom, 2022-06-21 more...
Genre: Fairies
Computer test: (Popeye WINDOWS-32Bit-Version 3.65 (2048 KB))
FEN: 8/1K1k3p/3p4/7p/4B2p/8/7p/8
Input: Felber, Volker, 2000-01-06
Last update: James Malcom, 2022-06-21 more...
1. Kb1 2. Sc2 3. Da1 4. Tb2 5. La2 6. b3 Le4=
Keywords: Seriesmover
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 8/8/7B/8/1p6/1b6/rqk3BK/n7
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 8/8/7B/8/1p6/1b6/rqk3BK/n7
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-10-31 more...
41 - P0577141
Rudolf Queck
721 Europa-Rochade 06/1989
Hans Klüver zum Gedenken
(4+2)
ser-h#3
2.1...
Platzwechselcirce
Rudolf Queck
721 Europa-Rochade 06/1989
Hans Klüver zum Gedenken
(4+2)
ser-h#3
2.1...
Platzwechselcirce
1) 1. Te5 2. Txc5[+wBe5] 3. Tc3 Lc5#
2) 1. Tg3 2. Txa3[+wBg3] 3. Te3 Le5#
2) 1. Tg3 2. Txa3[+wBg3] 3. Te3 Le5#
Keywords: Circe (Platzwechsel-), Seriesmover
Genre: Fairies
FEN: 8/8/1N6/2P5/3k4/B3r3/5N2/8
Input: Felber, Volker, 2000-01-06
Last update: Alfred Pfeiffer, 2014-03-07 more...
Genre: Fairies
FEN: 8/8/1N6/2P5/3k4/B3r3/5N2/8
Input: Felber, Volker, 2000-01-06
Last update: Alfred Pfeiffer, 2014-03-07 more...
1. Kb2 2. Kc3 3. Kd4 4. Kxe5 5. Kf6 6. e5 7. e4 8. e3 9. e2 10. e1=L 11. Lxh4 12. Lg5 13. Lxh6 14. Kg7 15. Kh8 16. Lg7 17. h5 18. h4 19. h3 20. h2 21. h1=L 22. Lxd5 23. Lg8 24. d5 25. d4 26. d3 27. d2 28. d1=T 29. Th1 30. Th7 Sg6#
Erich Bartel: im Problemist ist hierzu vermerkt:
Jonathan's Artikel has already apeared, in translation,in the
March 1995 issue of Rochade-Europa, and these originals
should compete in the informal tourney of that magazine.
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Die Frage ist nun welches Magazin als Erstqueelle gelten soll. (2011-11-28)
Anton Baumann: NL: 1.d6 2.dxe5 .. 6.e1=D .. 8.Dg8 .. 13.e1=L 14.Lxh4 15.Lg5 16.Lxh6 .. 23.Kh8 24.Lg7 .. 29.h1=T 30.Th7 Sg6# (2020-11-21)
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Jonathan's Artikel has already apeared, in translation,in the
March 1995 issue of Rochade-Europa, and these originals
should compete in the informal tourney of that magazine.
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Die Frage ist nun welches Magazin als Erstqueelle gelten soll. (2011-11-28)
Anton Baumann: NL: 1.d6 2.dxe5 .. 6.e1=D .. 8.Dg8 .. 13.e1=L 14.Lxh4 15.Lg5 16.Lxh6 .. 23.Kh8 24.Lg7 .. 29.h1=T 30.Th7 Sg6# (2020-11-21)
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Keywords: Seriesmover, corner to corner (sKa1h8), Excelsior (3-fach), under-promotion, konsekutive Umwandlungen 3 (llt)
Genre: Fairies
FEN: 8/3pp2p/7P/1K1PP3/5N1P/8/8/k7
Reprints: Rochade Europa 03/1995
Input: Felber, Volker, 2000-01-06
Last update: Olaf Jenkner, 2020-11-23 more...
Genre: Fairies
FEN: 8/3pp2p/7P/1K1PP3/5N1P/8/8/k7
Reprints: Rochade Europa 03/1995
Input: Felber, Volker, 2000-01-06
Last update: Olaf Jenkner, 2020-11-23 more...
a) 1. Kd3 2. Kc2 3. Kb1 4. Dc2 0-0#
b) 1. Kf3 2. Kf2 3. Kg1 4. Df2 0-0-0#
b) 1. Kf3 2. Kf2 3. Kg1 4. Df2 0-0-0#
SCHRECKE: Braucht Weiß einen letzten Zug? Dann kann den nur der wTurm ausgeführt haben! (2023-01-25)
Henrik Juel: Good point, Michael
If this were a retro problem, there would be no solutions
But here you can also view it as a sequence of black moves, ending with DxPf5, say (2023-01-25)
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Henrik Juel: Good point, Michael
If this were a retro problem, there would be no solutions
But here you can also view it as a sequence of black moves, ending with DxPf5, say (2023-01-25)
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Keywords: Seriesmover, Grid Chess, Castling, Minimal (d)
Genre: Fairies
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/8/5q2/8/8/3Pk3/4K2R
Input: Felber, Volker, 2000-01-06
Last update: Achim Schöneberg, 2023-01-24 more...
Genre: Fairies
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/8/5q2/8/8/3Pk3/4K2R
Input: Felber, Volker, 2000-01-06
Last update: Achim Schöneberg, 2023-01-24 more...
1. c1=L 2. f1=T 3. Txf4 4. La3 5. Ta4 6. f4 7. f3 8. f2 9. f1=S 10. Sxd2 11. Lc1#, 11. Ta7 c8=D#
Duplicate Diagram: P1007654
Erich Bartel: C+ PY V4.41 .---
Genaue Quelle: 8943 Die Schwalbe VIII 1995.---
Erste Darstellung einer AUW dieses Genres im Serienzüger?!.--
Nachdrucke:
1) A) Rochade Europa IV 1996,S.60.---
2) Infoblatt 15.Ausgabe V 1996.---
3) Thema Danicum (85) I 1997,S.119.--- (2008-03-01)
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Genaue Quelle: 8943 Die Schwalbe VIII 1995.---
Erste Darstellung einer AUW dieses Genres im Serienzüger?!.--
Nachdrucke:
1) A) Rochade Europa IV 1996,S.60.---
2) Infoblatt 15.Ausgabe V 1996.---
3) Thema Danicum (85) I 1997,S.119.--- (2008-03-01)
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Keywords: Seriesmover, Grazer Helpmate, Allumwandlung
Genre: Fairies
Computer test: PY V4.41
FEN: k7/2P5/8/5p2/5P2/8/2pR1p2/K7
Reprints: A) Rochade Europa , p. 60, 04/1996
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-09-15 more...
Genre: Fairies
Computer test: PY V4.41
FEN: k7/2P5/8/5p2/5P2/8/2pR1p2/K7
Reprints: A) Rochade Europa , p. 60, 04/1996
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-09-15 more...
1. f1=L 2. g1=T 3. Tg3 4. Te3 5. g3 6. g2 7. g1=D 8. Dg4 9. Lg2 10. Ld5 11. Ke4 12. Df5 13. g4 14. g3 15. g2 16. g1=S 17. Sf3 Sc5#
paul: With bPd3 to c4, the checkmate looks better. (2022-03-30)
A.Buchanan: I guess the smothered mate is thematic, at the cost of the more common model mate (2022-03-31)
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A.Buchanan: I guess the smothered mate is thematic, at the cost of the more common model mate (2022-03-31)
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Keywords: Allumwandlung, black, Seriesmover, under-promotion key (l), Smothered mate, Model mate, Check Protection, Minimal (S)
Genre: Fairies
Computer test: Gustav 4.1d, Brute Force
FEN: 8/8/N7/4pkp1/3p1pp1/3p4/5pp1/2K5
Reprints: Suomen Tehtäväniekat 01/11/1994
Phénix 32 08/1995
072 Kegelschach [Ebert u. Wolfenter] 1997
Rochade Europa , p. 59, 05/1998
846 Minimalkunst im Schach 2006
Input: Felber, Volker, 2000-01-06
Last update: Gunter Jordan, 2022-03-31 more...
Genre: Fairies
Computer test: Gustav 4.1d, Brute Force
FEN: 8/8/N7/4pkp1/3p1pp1/3p4/5pp1/2K5
Reprints: Suomen Tehtäväniekat 01/11/1994
Phénix 32 08/1995
072 Kegelschach [Ebert u. Wolfenter] 1997
Rochade Europa , p. 59, 05/1998
846 Minimalkunst im Schach 2006
Input: Felber, Volker, 2000-01-06
Last update: Gunter Jordan, 2022-03-31 more...
1. Kb6 2. Ka5 3. Ka4 4. Kxa3 5. Kxa2 6. Kxa1 7. Kb2 8. Kc3 9. Kd4 19. Ke5 11. Kf6 12. Kg7 13. Kxh8 14. Kg7 15. Kf6 16. Ke5 17. Kxd6 18. Kxc7 19. Kb8 20. Kxa8 21. Kb7 22. Kc6 23. Kd5 24. Ke4 25. Kf3 26. Kg2 27. Kxh1 28. Lxf2+ Kxf2=
Keywords: Seriesmover
Genre: Fairies
Computer test: Gustav 4.1d
FEN: B6R/k1N5/3P4/8/8/P7/P4P1p/B3K1bR
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: Gustav 4.1d
FEN: B6R/k1N5/3P4/8/8/P7/P4P1p/B3K1bR
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-10-31 more...
47 - P0577311
Satoshi Hashimoto
F1708v The Problemist 07/1997
5. ehrende Erwähnung
(8+3)
ser-h=11
Platzwechselcirce
Satoshi Hashimoto
F1708v The Problemist 07/1997
5. ehrende Erwähnung
(8+3)
ser-h=11
Platzwechselcirce
1. Dxd7[+wSd8] 2. Dxd8[+wSd7] 3. Dxe7[+wSd8] 4. Df8 5. Dxg7[+wSf8] 6. Dh8 7. Dxf6[+wSh8] 8. De7 9. Dxf8[+wSe7] 10. Dxf7[+wSf8] 11. De8 Shf7=
Urversion NL mit wKe4!
Kevin Begley: Correction of 'P0577029' (was this actually published)? (2011-05-18)
paul: Cook: 1.Q×e7(Sd8) 2.K×d8(Sc7) 3.Qf8 4.S×c7(Sa8) 5.Se8 6.Q×g7(Qf8) 7.Qh8 8.Q×f6(Qh8) 9.Qe7 Qf6= (2024-02-28)
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Kevin Begley: Correction of 'P0577029' (was this actually published)? (2011-05-18)
paul: Cook: 1.Q×e7(Sd8) 2.K×d8(Sc7) 3.Qf8 4.S×c7(Sa8) 5.Se8 6.Q×g7(Qf8) 7.Qh8 8.Q×f6(Qh8) 9.Qe7 Qf6= (2024-02-28)
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Keywords: Circe (Platzwechsel-), Seriesmover
Genre: Fairies
FEN: n2q4/2kPPPP1/1N2PP2/8/4K3/8/8/8
Input: Felber, Volker, 2000-01-06
Last update: Kevin Begley, 2011-09-12 more...
Genre: Fairies
FEN: n2q4/2kPPPP1/1N2PP2/8/4K3/8/8/8
Input: Felber, Volker, 2000-01-06
Last update: Kevin Begley, 2011-09-12 more...
48 - P0577314
Peter Fayers
F1715 The Problemist 07/1997
(5+5)
ser-h#3
Iceberg
Andernach
b) wSa1 statt sSa1
c) wTb1 statt sTb1
d) wLc1 statt sLc1
Peter Fayers
F1715 The Problemist 07/1997
(5+5)
ser-h#3
Iceberg
Andernach
b) wSa1 statt sSa1
c) wTb1 statt sTb1
d) wLc1 statt sLc1
a) 1. Ta1 2. (TS)c1 3. (TSL)xg5=w (TSB)e4#
b) 1. Tc1 2. (TL)c4 3. (TL)xe6=w Sb3#
c) 1. Lb2 2. La1 3. (LS)xe5=w Tb5#
d) 1. Ta1 2. (TS)b1 3. (TS)xb6=w Le3#
b) 1. Tc1 2. (TL)c4 3. (TL)xe6=w Sb3#
c) 1. Lb2 2. La1 3. (LS)xe5=w Tb5#
d) 1. Ta1 2. (TS)b1 3. (TS)xb6=w Le3#
Alfred Pfeiffer: Was ist "Iceberg"? Ist das eine Art Augsburger Schach? (2010-09-29)
Alfred Pfeiffer: "Iceberg" ist Peter Fayers' Version des Augsburger Schachs, bei folgenden drei Unterschiede gelten (Quelle: "http://www.bcvs.ukf.net/augsb.htm"):
E1: Pieces may combine, but not kings, and NOT PAWNS either (not even when moving to promote).
E2: The game-array queen is not separable, and Qs are distinct from (R+B)s.
E3: A pawn may promote to any combination seen in the diagram, or generated during play. (2010-10-11)
A.Buchanan: Link is now at https://www.mayhematics.com/s/augsb.htm. Piece images to make up the diagrams have been lost, but you can get a clue what the diagrams were by clicking in the html. (2019-02-04)
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Alfred Pfeiffer: "Iceberg" ist Peter Fayers' Version des Augsburger Schachs, bei folgenden drei Unterschiede gelten (Quelle: "http://www.bcvs.ukf.net/augsb.htm"):
E1: Pieces may combine, but not kings, and NOT PAWNS either (not even when moving to promote).
E2: The game-array queen is not separable, and Qs are distinct from (R+B)s.
E3: A pawn may promote to any combination seen in the diagram, or generated during play. (2010-10-11)
A.Buchanan: Link is now at https://www.mayhematics.com/s/augsb.htm. Piece images to make up the diagrams have been lost, but you can get a clue what the diagrams were by clicking in the html. (2019-02-04)
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Keywords: Seriesmover, Andernach Chess, Augsburg Chess (Iceberg)
Genre: Fairies
FEN: 8/8/1P2P3/K1k1P1P1/8/p7/8/nrb5
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-09-19 more...
Genre: Fairies
FEN: 8/8/1P2P3/K1k1P1P1/8/p7/8/nrb5
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-09-19 more...
1. Kh7 2. Kh6 3. Kh5 4. Kh4 5. Kh3 6. Kh2 7. Kxg1[+sKe8] 8. Ke7 9. Ke6 10. Ke5 11. Kxe4[+sKe8] 12. Ke7 13. Ke6 14. Ke5 15. Ke4 16. Kxe3[+sKe8] 17. Ke7 18. Ke6 19. Ke5 20. Ke4 21. Ke3 22. Kxd2[+sKe8] 23. Ke7 24. Ke6 25. Ke5 26. Ke4 27. Ke3 28. Kd2 29. Kc2 30. Kxb2[+sKe8] 31. Ke7 32. Ke6 33. Ke5 34. Ke4 35. Ke3 36. Kd2 37. Kc2 38. Kb2 39. Kxa3[+sKe8] 40. Ke7 41. Ke6 42. Ke5 43. Ke4 44. Ke3 45. Kd2 46. Kc2 47. Kb2 48. Ka3 49. Kxa4[+sKe8] 50. Ke7 51. Ke6 52. Ke5 53. Ke4 54. Ke3 55. Kd2 56. Kc2 57. Kb2 58. Ka3 59. Ka4 60. Kxa5[+sKe8] 61. Ke7 62. Ke6 63. Ke5 64. Ke4 65. Ke3 66. Kd2 67. Kc2 68. Kb2 69. Ka3 70. Kxb4[+sKe8] 71. Ke7 72. Ke6 73. Ke5 74. Ke4 75. Ke3 76. Kd2 77. Kc2 78. Kxb1[+sKe8] 79. Ke7 80. Ke6 81. Ke5 82. Ke4 83. Ke3 84. Kd2 85. Kc2 86. Kb2 87. Ka3 88. Ka4 Ta1#
Gerald Ettl: Man muss bevor man den wSb4 schlaegt, den wLa5 beseitigen, sonst kommt der sK nicht nach d2. Den wLb1 darf man erst nehmen, wenn der wSb4 weg ist, sonst kommt der sK nicht nach c2. (2009-02-10)
Anton Baumann: C+ Alybadix (2021-02-08)
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Anton Baumann: C+ Alybadix (2021-02-08)
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Keywords: Seriesmover, Circe (Anti-)
Genre: Fairies
Computer test: Anton Baumann: C+ Alybadix (2021-02-08) C+ Alybadix
FEN: 7k/1N1p4/3p4/B7/PNK1P3/P3P3/1P1PP3/1B3RR1
Input: Felber, Volker, 2000-01-06
Last update: Erich Bartel, 2021-02-09 more...
Genre: Fairies
Computer test: Anton Baumann: C+ Alybadix (2021-02-08) C+ Alybadix
FEN: 7k/1N1p4/3p4/B7/PNK1P3/P3P3/1P1PP3/1B3RR1
Input: Felber, Volker, 2000-01-06
Last update: Erich Bartel, 2021-02-09 more...
1. Kg8 2. Kxh8[+sKe8] 3. Kd8 4. Kc8 5. Kb8 6. Kxa8[+sKe8] 7. Kd8 8. Kc8 9. Kb8 10. Ka7 11. Kb6 12. Kc5 13. Kc4 14. Kd3 15. Kc2 16. Kb1 17. Kxa1[+sKe8] 18. Kd8 19. Kc8 20. Kb8 21. Ka7 22. Kb6 23. Kc5 24. Kd4 25. Ke3 26. Kf2 27. Kg1 28. Kxh1[+sKe8] Th8#
Gerald Ettl: Der sK muss alle Eckfiguren abraeumen. (GE) (2009-02-10)
K?vanç Çefle: Why 17. Th8 is not mate? After 17...Kd8(or f8) 18. Txd8(or f8)[+wTa1] seems legal to me... (2022-05-13)
SCHRECKE: 17.K:a1[+sKe8] 18.Th8= (Patt) (2022-05-13)
SCHRECKE: without 18. (2022-05-13)
Kivanç Çefle: So, 18. Th8 is not a checking move? That is strange... (2022-05-13)
paul: To Kivanç Çefle: 17... Th8 is not check because the square h1 is occupied. (2022-05-14)
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K?vanç Çefle: Why 17. Th8 is not mate? After 17...Kd8(or f8) 18. Txd8(or f8)[+wTa1] seems legal to me... (2022-05-13)
SCHRECKE: 17.K:a1[+sKe8] 18.Th8= (Patt) (2022-05-13)
SCHRECKE: without 18. (2022-05-13)
Kivanç Çefle: So, 18. Th8 is not a checking move? That is strange... (2022-05-13)
paul: To Kivanç Çefle: 17... Th8 is not check because the square h1 is occupied. (2022-05-14)
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Keywords: Seriesmover, Four corners (k), Circe (Anti-), Switchback (k), Model mate
Genre: Fairies
Computer test: Popeye 4.61
FEN: N4k1N/8/P2PP2R/7P/K7/8/8/B6B
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-09-22 more...
Genre: Fairies
Computer test: Popeye 4.61
FEN: N4k1N/8/P2PP2R/7P/K7/8/8/B6B
Input: Felber, Volker, 2000-01-06
Last update: Arnold Beine, 2022-09-22 more...
1. f4 2. f3 3. f2 4. Kf7 5. Kg7 6. Kh8 7. f1=T 8. Tc1 9. Dd1 10. h5 11. h4 12. h3 13. h2 14. h1=T 15. Tg1 g7=
Gerald Ettl: Und nicht 14.h1D 15.Dg1 wegen Dxg7[Dd8] nette Rundlinien-Einmauerung(GE) (2009-02-10)
Ladislav Packa: Anticirce Cheylan (2023-02-28)
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Ladislav Packa: Anticirce Cheylan (2023-02-28)
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Keywords: Seriesmover, Miniature, Circe (Anticirce Cheylan)
Genre: Fairies
Computer test: PY V4.45
FEN: 8/8/4kNPp/5p1q/8/8/8/K7
Input: Felber, Volker, 2000-01-06
Last update: A.Buchanan, 2023-03-01 more...
Genre: Fairies
Computer test: PY V4.45
FEN: 8/8/4kNPp/5p1q/8/8/8/K7
Input: Felber, Volker, 2000-01-06
Last update: A.Buchanan, 2023-03-01 more...
1. gxf3ep? Weiß hat keinen letzten Zug!
1. Le6 2. Tdf5 3. Lxa2 4. Lxb1 5. gxf3ep 6. Kf4 7. Kg4 8. Df4 h3#
1. Le6 2. Tdf5 3. Lxa2 4. Lxb1 5. gxf3ep 6. Kf4 7. Kg4 8. Df4 h3#
Keywords: En passant, Seriesmover, Consequent
Genre: Retro, Fairies
FEN: 8/8/p7/P2r1brp/pp2kPpb/p3q1p1/P1P1P1PP/KN6
Input: Gerd Wilts, 2000-10-15
Last update: James Malcom, 2021-09-14 more...
Genre: Retro, Fairies
FEN: 8/8/p7/P2r1brp/pp2kPpb/p3q1p1/P1P1P1PP/KN6
Input: Gerd Wilts, 2000-10-15
Last update: James Malcom, 2021-09-14 more...
1. d5 2. d4 3. d3 4. d2 5. d1=L 6. Lb3 7. Lxa2 8. Lc4 9. Lf1 10. Lg2 11. Lh1 12. fxg3ep fxg3#
Aber nach 11. Lh1 kann Weiß auch g2xLh3 zurücknehmen!
Cook: gxsLh3!
Aber nach 11. Lh1 kann Weiß auch g2xLh3 zurücknehmen!
Cook: gxsLh3!
Henrik Juel: 1.d5-d4-d3-d2-d1B-b3xa2-c4-f1 10.Bg2-h1 12.fxg3ep+?? fxg3# seems to fail, because after 11.Bh1 last move could be g2xh3. So what is the solution? (2003-04-28)
Thierry LE GLEUHER: After 11.Bh1, the last move can't be g2xh3 because of the promoted Bishop h1 imcompatible with the bP structure! (2005-09-25)
Henrik Juel: Why couldn't Black have a promoted bishop at this point in time (where wPa2 and bPd7 are no longer present)? 12 captures by black pawns seem to match the 12 missing white men. (2005-09-26)
Joost de Heer: Besides, after g2-g4, the black bishop must've been promoted too. (2005-09-30)
James Malcom: Henrik, gxh3 is indeed impossible. The last move sequence must go something like 1. Kfg8 Se2+ 2. Kh2 Sg1. There cannot be a knight on h3, cutting off g8, or a queen/rook, cutting off h2. Thus, gxh3 has already been played and g2-g4 is the last move. (2021-09-14)
Mario Richter: Position after 11. Lh1 is 8/5p2/8/5ppp/5pPk/5p1P/5P1K/6nb.
It can be easily shown, that in this position g2xLh3! is indeed a legal retraction.
So the ep-capture is not justified and the problem is cooked!
(Perhaps Thierry forgot, that black pawn d7 "disappeared"? But Joost's argument raises [correctly] the question, why a promoted Bishop on h1 is ok for g2-g4, but not for g2xLh3.) (2021-09-15)
Henrik Juel: So the good guys (Mario, Joost, and me) win over the bad ones (Thierry and James) by 3-2... (2021-09-15)
Henrik Juel: or, less insultingly:
By a majority of 3 to 2 this problem has been deemed cooked (2021-09-15)
James Malcom: Make it 4 to 1: 1. Nc3 Nf6 2. Nd5 Rg8 3. Nxf6+ exf6 4. d4 Ke7 5. Bg5 fxg5 6. Nf3 Kf6 7. Ne5 Bd6 8. Nc6 Bg3 9. hxg3 bxc6 10. Rh4 gxh4 11. b4 Ba6 12. a4 Bd3 13. b5 Bf5 14. b6 h3 15. bxa7 h2 16. a5 Bh3 17. g4 Re8 18. a6 Re5 19. dxe5+ Kg5 20. Qd6 Qe7 21. c4 Qe6 22. Ra3 Qd5 23. cxd5 cxd5 24. Rf3 Nc6 25. e4 Re8 26. a8=Q Nd4 27. a7 cxd6 28. Qxe8 dxe4 29. Qe6 dxe6 30. a8=Q exf3 31. Bd3 Kh4 32. Bf5 exf5 33. Qa5 g5 34. Qd5 h5 35. Qe4 dxe5 36. Qf4 exf4 37. Kf1 h1=B 38. Kg1 Ne2+ 39. Kh2 Ng1 40. gxh3 (2021-09-16)
A.Buchanan: Is it also possible that in the critical position, the last moves were R: 1.gxSh3 exXf345 2.X~? I think I can fix the cook R: 1.gxLh3 nicely. (2021-09-17)
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Thierry LE GLEUHER: After 11.Bh1, the last move can't be g2xh3 because of the promoted Bishop h1 imcompatible with the bP structure! (2005-09-25)
Henrik Juel: Why couldn't Black have a promoted bishop at this point in time (where wPa2 and bPd7 are no longer present)? 12 captures by black pawns seem to match the 12 missing white men. (2005-09-26)
Joost de Heer: Besides, after g2-g4, the black bishop must've been promoted too. (2005-09-30)
James Malcom: Henrik, gxh3 is indeed impossible. The last move sequence must go something like 1. Kfg8 Se2+ 2. Kh2 Sg1. There cannot be a knight on h3, cutting off g8, or a queen/rook, cutting off h2. Thus, gxh3 has already been played and g2-g4 is the last move. (2021-09-14)
Mario Richter: Position after 11. Lh1 is 8/5p2/8/5ppp/5pPk/5p1P/5P1K/6nb.
It can be easily shown, that in this position g2xLh3! is indeed a legal retraction.
So the ep-capture is not justified and the problem is cooked!
(Perhaps Thierry forgot, that black pawn d7 "disappeared"? But Joost's argument raises [correctly] the question, why a promoted Bishop on h1 is ok for g2-g4, but not for g2xLh3.) (2021-09-15)
Henrik Juel: So the good guys (Mario, Joost, and me) win over the bad ones (Thierry and James) by 3-2... (2021-09-15)
Henrik Juel: or, less insultingly:
By a majority of 3 to 2 this problem has been deemed cooked (2021-09-15)
James Malcom: Make it 4 to 1: 1. Nc3 Nf6 2. Nd5 Rg8 3. Nxf6+ exf6 4. d4 Ke7 5. Bg5 fxg5 6. Nf3 Kf6 7. Ne5 Bd6 8. Nc6 Bg3 9. hxg3 bxc6 10. Rh4 gxh4 11. b4 Ba6 12. a4 Bd3 13. b5 Bf5 14. b6 h3 15. bxa7 h2 16. a5 Bh3 17. g4 Re8 18. a6 Re5 19. dxe5+ Kg5 20. Qd6 Qe7 21. c4 Qe6 22. Ra3 Qd5 23. cxd5 cxd5 24. Rf3 Nc6 25. e4 Re8 26. a8=Q Nd4 27. a7 cxd6 28. Qxe8 dxe4 29. Qe6 dxe6 30. a8=Q exf3 31. Bd3 Kh4 32. Bf5 exf5 33. Qa5 g5 34. Qd5 h5 35. Qe4 dxe5 36. Qf4 exf4 37. Kf1 h1=B 38. Kg1 Ne2+ 39. Kh2 Ng1 40. gxh3 (2021-09-16)
A.Buchanan: Is it also possible that in the critical position, the last moves were R: 1.gxSh3 exXf345 2.X~? I think I can fix the cook R: 1.gxLh3 nicely. (2021-09-17)
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Keywords: Seriesmover, Consequent, Excelsior, Promotion (l)
Genre: Retro, Fairies
FEN: 8/3p1p2/8/5ppp/5pPk/5p1P/P4P1K/6n1
Input: Gerd Wilts, 2002-07-27
Last update: A.Buchanan, 2021-09-17 more...
Genre: Retro, Fairies
FEN: 8/3p1p2/8/5ppp/5pPk/5p1P/P4P1K/6n1
Input: Gerd Wilts, 2002-07-27
Last update: A.Buchanan, 2021-09-17 more...
1. e4 2. Dg4 3. Dxg7 4. Dxg8 5. Dg3 6. Db3 7. g4 8. g5 9. g6 10. g7 11. g8=T 12. Tg7 13. Txf7 14. Tf3 15. Tc3 16. f4 17. f5 18. f6 19. f7#
Keywords: Unique Proof Game, Seriesmover, Promotion (T)
Genre: Retro, Fairies
Computer test: SCHRECKE: C+, Jacobi v0.7.5 (2020-12-07)
FEN: rnbqkb1r/pppppP1p/8/8/4P3/1QR5/PPPP3P/RNB1KBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
Genre: Retro, Fairies
Computer test: SCHRECKE: C+, Jacobi v0.7.5 (2020-12-07)
FEN: rnbqkb1r/pppppP1p/8/8/4P3/1QR5/PPPP3P/RNB1KBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
1. a4 2. Ta3 3. Td3 4. Txd7 5. d4 6. d5 7. Dd4 8. Dxa7 9. Dxb7 10. Db3 11. Da2 12. b4 13. b5 14. b6 15. b7 16. bxc8=T 17. Tcxd8#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rn1Rkbnr/2pRpppp/8/3P4/P7/8/Q1P1PPPP/1NB1KBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
Genre: Retro, Fairies
FEN: rn1Rkbnr/2pRpppp/8/3P4/P7/8/Q1P1PPPP/1NB1KBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
1. d4 2. d5 3. Dd4 4. Dxa7 5. Dxb7 6. Db4 7. Df4 8. b4 9. b5 10. b6 11. b7 12. bxc8=L 13. La6 14. Ld3 15. Lg6 16. Lxf7#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rn1qkbnr/2pppBpp/8/3P4/5Q2/8/P1P1PPPP/RNB1KBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
Genre: Retro, Fairies
FEN: rn1qkbnr/2pppBpp/8/3P4/5Q2/8/P1P1PPPP/RNB1KBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
1. a4 2. Ta3 3. Tc3 4. Txc7 5. Txc8 6. Tc3 7. Te3 8. c4 9. c5 10. c6 11. c7 12. c8=S 13. Sd6#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rn1qkbnr/pp1ppppp/3N4/8/P7/4R3/1P1PPPPP/1NBQKBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
Genre: Retro, Fairies
FEN: rn1qkbnr/pp1ppppp/3N4/8/P7/4R3/1P1PPPPP/1NBQKBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
1. h4 2. Th3 3. Tg3 4. Txg7 5. Txg8 6. Tg3 7. Te3 8. g4 9. g5 10. g6 11. g7 12. g8=S 13. Sf6#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rnbqkb1r/pppppp1p/5N2/8/7P/4R3/PPPPPP2/RNBQKBN1
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
Genre: Retro, Fairies
FEN: rnbqkb1r/pppppp1p/5N2/8/7P/4R3/PPPPPP2/RNBQKBN1
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
1. h4 2. Th3 3. Td3 4. Txd7 5. Td4 6. Te4 7. d4 8. d5 9. d6 10. Dd5 11. Dxb7 12. Dxb8 13. Dxc8 14. d7#
A.Buchanan: Surely can stick wTe4 somewhere else so it doesn’t spoil the pure mate? :-) (2021-02-25)
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Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
Computer test: C+, popeye 4.85
FEN: r1Qqkbnr/p1pPpppp/8/8/4R2P/8/PPP1PPP1/RNB1KBN1
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
Genre: Retro, Fairies
Computer test: C+, popeye 4.85
FEN: r1Qqkbnr/p1pPpppp/8/8/4R2P/8/PPP1PPP1/RNB1KBN1
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
1. h4 2. Th3 3. Tc3 4. e3 5. Df3 6. Dxb7 7. Dxc7 8. Dh2 9. Txc8 10. c4 11. c5 12. c6 13. c7 14. cxd8=T
A.Buchanan: There are being tagged as homebase, which is clearly inappropriate for most series movers. I am guessing that this is something automatic which PDB is applying when another change is made? I will ask Gerd. BTW: I'm trying to standardize on parameters s, w or 2 for homebase. (2021-04-09)
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Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rnRRkbnr/p2ppppp/8/8/7P/4P3/PP1P1PPQ/RNB1KBN1
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
Genre: Retro, Fairies
FEN: rnRRkbnr/p2ppppp/8/8/7P/4P3/PP1P1PPQ/RNB1KBN1
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
1. d4 2. d5 3. Dd4 4. Dxa7 5. Dxb7 6. Db4 7. Df4 8. b4 9. b5 10. b6 11. b7 12. bxa8=T 13. Ta6 14. Tf6 15. Txf7 16. Txf8#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: 1nbqkRnr/2ppp1pp/8/3P4/5Q2/8/P1P1PPPP/RNB1KBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
Genre: Retro, Fairies
FEN: 1nbqkRnr/2ppp1pp/8/3P4/5Q2/8/P1P1PPPP/RNB1KBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
1. a4 2. a5 3. a6 4. axb7 5. Txa7 6. Ta3 7. Tf3 8. d3 9. Lg5 10. Lxe7 11. Lxd8 12. Le7 13. Lxf8 14. bxc8=T#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rnR1kBnr/2pp1ppp/8/8/8/3P1R2/1PP1PPPP/1N1QKBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
Genre: Retro, Fairies
FEN: rnR1kBnr/2pp1ppp/8/8/8/3P1R2/1PP1PPPP/1N1QKBNR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2020-12-07 more...
1. Sh3 2. Sf4 3. Sh5 4. f4 5. Kf2 6. Kg3 7. Kh4 8. g3 9. Lh3 10. Tf1 11. Tf2 12. Dh1 13. De4 14. Dxh7 15. Dxg8 16. Dxh8 17. Sxg7#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rnbqkb1Q/ppppppN1/8/8/5P1K/6PB/PPPPPR1P/RNB5
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
Genre: Retro, Fairies
FEN: rnbqkb1Q/ppppppN1/8/8/5P1K/6PB/PPPPPR1P/RNB5
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
1. Sh3 2. Sf4 3. Sh5 4. f4 5. Kf2 6. Kg3 7. Kh4 8. g3 9. Lh3 10. Dg1 11. Dxa7 12. Dxb7 13. De4 14. Dxh7 15. Dxg8 16. Dxh8 17. Sxg7#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rnbqkb1Q/2ppppN1/8/8/5P1K/6PB/PPPPP2P/RNB4R
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
Genre: Retro, Fairies
FEN: rnbqkb1Q/2ppppN1/8/8/5P1K/6PB/PPPPP2P/RNB4R
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
1. e4 2. Lc4 3. Ld5 4. c4 5. Db3 6. Dxb7 7. b4 8. Lb2 9. Le5! 10. Sc3 11. Tb1 12. Tb3 13. Ta3 14. Ta6 15. Th6! 16. Ld6 17. e5 18. e6 19. exf7#
Keywords: Unique Proof Game, Seriesmover
Genre: Retro, Fairies
FEN: rnbqkbnr/pQpppPpp/3B3R/3B4/1PP5/2N5/P2P1PPP/4K1NR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
Genre: Retro, Fairies
FEN: rnbqkbnr/pQpppPpp/3B3R/3B4/1PP5/2N5/P2P1PPP/4K1NR
Input: Gerd Wilts, 2002-11-01
Last update: A.Buchanan, 2021-04-09 more...
1. f8=S 2. Se6 3. Sg5 4. Le6 5. g8=S 6. Sf6 7. Sfe4 8. Lf6 9. h8=S 10. S8xg6 Se3#
''Die drei S-Unterverwandlungen sind gut motiviert, ebenso die Zugeindeutigkeit; da W sonst Gefahr läuft, selbst # geben zu müssen'' (MS). KHS: ''3xS-Umwandlung zwecks Vermeidung der r#-Gefahren, gut.'' 11L/5+5P
''Die drei S-Unterverwandlungen sind gut motiviert, ebenso die Zugeindeutigkeit; da W sonst Gefahr läuft, selbst # geben zu müssen'' (MS). KHS: ''3xS-Umwandlung zwecks Vermeidung der r#-Gefahren, gut.'' 11L/5+5P
Branko Koludrovic: This Problem was corrected(+sTg6)and the correction was written in a couple of years after,in Die Schwalbe,too. (2007-01-18)
Anton Baumann: C+ Alybadix (2021-02-13)
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Anton Baumann: C+ Alybadix (2021-02-13)
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Keywords: Seriesmover, Promotion, konsekutive Umwandlungen 3 (SSS)
Genre: r#
FEN: 6BB/1p3PPP/1Pkp2r1/2P1pK2/2P5/2P5/2n5/8
Input: Gerd Wilts, 2003-06-29
Last update: James Malcom, 2021-02-13 more...
Genre: r#
FEN: 6BB/1p3PPP/1Pkp2r1/2P1pK2/2P5/2P5/2n5/8
Input: Gerd Wilts, 2003-06-29
Last update: James Malcom, 2021-02-13 more...
a) 1. La6 2. b5 3. Kb6 4. Ka5 5. b6 Sc6#
b) 1. Se6 2. Kg5 3. Kh6 4. Dh5 5. g6 Sf7#
(T. 'Ersek) hat "2 nicht sehr bedeutende Aufgaben fast zusammenhanglos nebeneinander aufs Brett gestellt: So kann man's auch machen, aber..." (HHS) "jeweils 3 Nachtwächter je Lösung (g7, g5, e5 in a, b7, b6, a4 in b) für diese klitzekleine Minimal-Aufgabe, wobei auch noch eine Zwillingsversetzung des sK vorkommt. Wirklich schwach!" (eb) a) 1.La6 2.b5 3.Kb6 4.Ka5 5.b6 Sc6#, b) 1.Se6 2.Kg5 3.Kh6 4.Dh5 5.g6 Sf7# - das war "leicht zu sehen" (KHS). "Lösung b) ist die gehaltvollere! Leider werden die Figuren aus a) in b) nicht benötigt und umgekehrt (Ausnahme: in b) verstellt der sS den Lc4)" (MWa) Abschließender Kommentar von MRi: "Der sK wird von einem zurechzustellenden Mattnetz zum anderen versetzt. Da hilft es auch nicht, daß der L in der b)-Lösung dazu dient, den Räumzug des sS eindeutig zu machen. Einzig die Minimalform genügt minimalen Ansprüchen." 18L/5P
b) 1. Se6 2. Kg5 3. Kh6 4. Dh5 5. g6 Sf7#
(T. 'Ersek) hat "2 nicht sehr bedeutende Aufgaben fast zusammenhanglos nebeneinander aufs Brett gestellt: So kann man's auch machen, aber..." (HHS) "jeweils 3 Nachtwächter je Lösung (g7, g5, e5 in a, b7, b6, a4 in b) für diese klitzekleine Minimal-Aufgabe, wobei auch noch eine Zwillingsversetzung des sK vorkommt. Wirklich schwach!" (eb) a) 1.La6 2.b5 3.Kb6 4.Ka5 5.b6 Sc6#, b) 1.Se6 2.Kg5 3.Kh6 4.Dh5 5.g6 Sf7# - das war "leicht zu sehen" (KHS). "Lösung b) ist die gehaltvollere! Leider werden die Figuren aus a) in b) nicht benötigt und umgekehrt (Ausnahme: in b) verstellt der sS den Lc4)" (MWa) Abschließender Kommentar von MRi: "Der sK wird von einem zurechzustellenden Mattnetz zum anderen versetzt. Da hilft es auch nicht, daß der L in der b)-Lösung dazu dient, den Räumzug des sS eindeutig zu machen. Einzig die Minimalform genügt minimalen Ansprüchen." 18L/5P
Keywords: Seriesmover, Minimal
Genre: Fairies
Computer test: Gustav 4.2a
FEN: 3N3K/1pk3p1/1p6/4q1n1/p1b5/8/8/8
Input: Gerd Wilts, 2003-06-29
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: Gustav 4.2a
FEN: 3N3K/1pk3p1/1p6/4q1n1/p1b5/8/8/8
Input: Gerd Wilts, 2003-06-29
Last update: Arnold Beine, 2022-10-31 more...
(Barani & Lörinc). Die Autoren beschreiben das Thema: Extended Zilahi in a relatively long sh# with two solutions, three blocks and model battery-mates. Und das sieht dann so aus: a) 3.Kc5 4.G:b6 5.Kb5 6.Ga5 7.K:a6 8.Tb5 e7#; b) 1.Th5 2.Kf5 3.Gg5 4.K:e6 5.Kf6 6.Gg7 8.K:h6 b7# EB (stellvertretend für MW und WW): Auf dem Weg zum echoartigen Matt wird die Bauernhalbbatterie mit Opferwechsel geschärft zum Abschuß. Gefällig! RB: Selbsteinkerkerung des sK am linken und rechten Brettrand mit analogen Abzugsmatts durch die B/G, bzw. B/T-Batterie.
Keywords: Seriesmover
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: 1K6/7p/RP2P2*2Q/4*2qr2/pp1*2q1k2/8/8/8
Input: Gerd Wilts, 2003-06-29
Last update: A.Buchanan, 2021-11-08 more...
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: 1K6/7p/RP2P2*2Q/4*2qr2/pp1*2q1k2/8/8/8
Input: Gerd Wilts, 2003-06-29
Last update: A.Buchanan, 2021-11-08 more...
69 - P1008913
Rolf Wiehagen
Achim Schöneberg
10906 Die Schwalbe 185 10/2000
(8+6) C+
ser-h#4
b) +wTb3 (-wLb3)
Rolf Wiehagen
Achim Schöneberg
10906 Die Schwalbe 185 10/2000
(8+6) C+
ser-h#4
b) +wTb3 (-wLb3)
a) 1. Ta4? 2. Txd4 3. Txe4 4. Txe6+ Lxe6+ 5. Lxe6!
1. Lb1! 2. Ld3 3. Lc4 4. Lxe6 Lxe6#
b) 1. Lb1? 2. Ld3 3. Lxe2 4. Lxf3 Txf3+ 5. Txf3!
1. Ta4! 2. Txd4 3. Td3 4. Txf3 Txf3#
Die beiden Autoren machten den Vorschlag, unter das Diagramm das aus dem orthodoxen Bereich bekannte "v" zu setzen. Dies widerstrebte mir dann doch. Ein diesbezüglicher Hinweis im Vorspann mußte genügen.
Autoren: Rehm-Thema, diagonal und orthogonal mit eindeutigen thematischen Verführungen durch den jeweils "falschen" Hinterstein.
AB: Sehr leicht zu durchschauendes Peri-Manöver.
Schwarz-weiße Opferbahnungen nach einleitenden Umschiffungen des jeweiligen wWirkungssteins (HJ).
1. Lb1! 2. Ld3 3. Lc4 4. Lxe6 Lxe6#
b) 1. Lb1? 2. Ld3 3. Lxe2 4. Lxf3 Txf3+ 5. Txf3!
1. Ta4! 2. Txd4 3. Td3 4. Txf3 Txf3#
Die beiden Autoren machten den Vorschlag, unter das Diagramm das aus dem orthodoxen Bereich bekannte "v" zu setzen. Dies widerstrebte mir dann doch. Ein diesbezüglicher Hinweis im Vorspann mußte genügen.
Autoren: Rehm-Thema, diagonal und orthogonal mit eindeutigen thematischen Verführungen durch den jeweils "falschen" Hinterstein.
AB: Sehr leicht zu durchschauendes Peri-Manöver.
Schwarz-weiße Opferbahnungen nach einleitenden Umschiffungen des jeweiligen wWirkungssteins (HJ).
Keywords: Seriesmover, Twin, Rehm Theme, bi-coloured Bristol, Periführung, Entblockung
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 8/8/2K1P3/p6p/3PPQ2/rB3P1k/b3P1n1/8
Input: Gerd Wilts, 2003-07-01
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 8/8/2K1P3/p6p/3PPQ2/rB3P1k/b3P1n1/8
Input: Gerd Wilts, 2003-07-01
Last update: Arnold Beine, 2022-10-31 more...
1. Th3 2. Kxd2 3. Ke2 4. f3 5. Th4 6. Kxd3 7. Ke3 8. f4 9. Th5 10. Kxd4 11. Ke4 12. f5 13. Th6 14. Kxd5 15. Ke5 16. f6 17. Th7 18. Txf7 19. Kxd6 20. Kxc7 21. Kxd8 22. Kxd7 23. Kc6 24. Ta7#
KHS: Langsam, Schritt für Schritt, kriechen der wK, wB und der wT nach oben. Amüsant!
EB: Simpel? Der SB hat recht, wenn er dies auf den Lösungsablauf bezieht, aber zuerst muß man so eine Idee haben und dann muß man sie auch verwirklichen und dann, da bin ich mir sicher, ist und war die Sache nicht simpel. Mir gefallen solche Sachen jedenfalls weit besser als manche schwülstigen Zweizüger mit herbeigeredeten Themata.
EZ: Die Einschätzung der Ankündigung ["eigentlich ganz simpel und doch nett gemacht"] trifft den Nagel auf dem Kopf!
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EB: Simpel? Der SB hat recht, wenn er dies auf den Lösungsablauf bezieht, aber zuerst muß man so eine Idee haben und dann muß man sie auch verwirklichen und dann, da bin ich mir sicher, ist und war die Sache nicht simpel. Mir gefallen solche Sachen jedenfalls weit besser als manche schwülstigen Zweizüger mit herbeigeredeten Themata.
EZ: Die Einschätzung der Ankündigung ["eigentlich ganz simpel und doch nett gemacht"] trifft den Nagel auf dem Kopf!
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Keywords: Madrasi, Seriesmover
Genre: Fairies
Computer test: Alybadix
FEN: 3r4/2rr1p2/3r4/k2r4/1p1r4/3r4/3r1P1R/4K3
Input: Gerd Wilts, 2003-07-01
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: Alybadix
FEN: 3r4/2rr1p2/3r4/k2r4/1p1r4/3r4/3r1P1R/4K3
Input: Gerd Wilts, 2003-07-01
Last update: Arnold Beine, 2022-10-31 more...
71 - P1009022
Unto Heinonen
11094 Die Schwalbe 188 04/2001
(2+11)
1w, dann ser-h#5
b) sBc3 nach g4
c) sDf4 nach f6
d) sLg5 nach e7
Unto Heinonen
11094 Die Schwalbe 188 04/2001
(2+11)
1w, dann ser-h#5
b) sBc3 nach g4
c) sDf4 nach f6
d) sLg5 nach e7
a) 1. ... f8=S!, dann Lc4 2. d3 3. Kd4 4. De4 5. Le3 Se6#
b) 1. ... f8=L!, dann Df3 2. Kf4 3. Lf5 4. e4 5. Se3 Lxd6#
c) 1. ... f8=T!, dann Kf5 2. Kg6 3. Kh6 4. g6 5. Sg7 Th8#
d) 1. ... f8=D!, dann Df6 2. Kf5 3. Ke6 4. Lg6 5. Lf7 Dc8#
b) 1. ... f8=L!, dann Df3 2. Kf4 3. Lf5 4. e4 5. Se3 Lxd6#
c) 1. ... f8=T!, dann Kf5 2. Kg6 3. Kh6 4. g6 5. Sg7 Th8#
d) 1. ... f8=D!, dann Df6 2. Kf5 3. Ke6 4. Lg6 5. Lf7 Dc8#
paul: Jacobi+
For example, the input for d is:
stip ~1
stip ser-h#5
pieces white Ka8 Pf7 black Ke4 Qf4 Bd3e7 Sd5h5 Pc3d4e5d6g7 (2022-08-13)
comment
For example, the input for d is:
stip ~1
stip ser-h#5
pieces white Ka8 Pf7 black Ke4 Qf4 Bd3e7 Sd5h5 Pc3d4e5d6g7 (2022-08-13)
comment
Keywords: Seriesmover, Allumwandlung, Minimal
Genre: Fairies
FEN: K7/5Pp1/3p4/3np1bn/3pkq2/2pb4/8/8
Reprints: 817 Minimalkunst im Schach 2006
Input: Gerd Wilts, 2003-07-01
Last update: Alfred Pfeiffer, 2015-04-16 more...
Genre: Fairies
FEN: K7/5Pp1/3p4/3np1bn/3pkq2/2pb4/8/8
Reprints: 817 Minimalkunst im Schach 2006
Input: Gerd Wilts, 2003-07-01
Last update: Alfred Pfeiffer, 2015-04-16 more...
1) 1. Dxf1 2. Lh1 3. Tg2 4. Lf2 Sf3#
2) 1. Kh1 2. Dg1 3. Txh2 4. Lg2 Sg3#
Echomatts; gute "Aufwärmübung" (MW).
EB: Opferwechsel; dass der sLa7 in einem Spiel überflüssig ist, stört doch den guten Gesamteindruck.
Ähnlich KHS: Chamäleon-Echomatt, der nicht benötigte wS wird geschlagen; in einer Lösung nachtwächtert leider der sLa7.
PH: Zweifach Opferminimal und zweifach Mattwechsel sowie Farbwechselecho. Gut gemacht!
LV: very elegant!
Zilahi mit Umgruppierung der sSteine - leicht vom Blatt zu lösen (AB).
2) 1. Kh1 2. Dg1 3. Txh2 4. Lg2 Sg3#
Echomatts; gute "Aufwärmübung" (MW).
EB: Opferwechsel; dass der sLa7 in einem Spiel überflüssig ist, stört doch den guten Gesamteindruck.
Ähnlich KHS: Chamäleon-Echomatt, der nicht benötigte wS wird geschlagen; in einer Lösung nachtwächtert leider der sLa7.
PH: Zweifach Opferminimal und zweifach Mattwechsel sowie Farbwechselecho. Gut gemacht!
LV: very elegant!
Zilahi mit Umgruppierung der sSteine - leicht vom Blatt zu lösen (AB).
Keywords: Aristocrat, Seriesmover
Genre: Fairies
Computer test: Gustav 4.1d
FEN: b7/b7/8/K7/8/8/5rqN/5Nk1
Input: Gerd Wilts, 2003-07-01
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: Gustav 4.1d
FEN: b7/b7/8/K7/8/8/5rqN/5Nk1
Input: Gerd Wilts, 2003-07-01
Last update: Arnold Beine, 2022-10-31 more...
73 - P1009206
Daniel Novomesky
11402 Die Schwalbe 193 02/2002
(2+3)
ser-h#7
3 Lösungen
Schwarz im Schach
sTL=Turmhüpfer
Daniel Novomesky
11402 Die Schwalbe 193 02/2002
(2+3)
ser-h#7
3 Lösungen
Schwarz im Schach
sTL=Turmhüpfer
1) 1. Kc3 2. TPb3 3. TPd3 4. Kd2 5. TPd1 6. TPc1 7. TPe1 Db2#
2) 1. Kc4 2. TPf4 3. TPf5 4. TPd4 5. TPb4 6. Kc5 7. TPb5 Dc7#
3) 1. Kc2 2. Kd1 3. TPc1 4. TPe1 5. Ke2 6. Kf2 7. TPf1 Dh2#
An dem wSchachgebot in der Ausgangsstellung hat sich berechtigterweise keiner gestört!
EB: Dreifaches Idealmatt-Echo in Mehrlingsform. Grandios! Ich liebe solche Aufgaben! (ähnlich MW und AB).
KHS: Lustige und nicht allzu schwere Hüpferei.
EH: Die je ersten K-Züge, und im Grunde auch die Mattzüge, verstehen sich von selbst, aber das spricht nur für das Problem, das mit Minimalaufwand die Gangart des Turmhüpfers ausnutzt.
2) 1. Kc4 2. TPf4 3. TPf5 4. TPd4 5. TPb4 6. Kc5 7. TPb5 Dc7#
3) 1. Kc2 2. Kd1 3. TPc1 4. TPe1 5. Ke2 6. Kf2 7. TPf1 Dh2#
An dem wSchachgebot in der Ausgangsstellung hat sich berechtigterweise keiner gestört!
EB: Dreifaches Idealmatt-Echo in Mehrlingsform. Grandios! Ich liebe solche Aufgaben! (ähnlich MW und AB).
KHS: Lustige und nicht allzu schwere Hüpferei.
EH: Die je ersten K-Züge, und im Grunde auch die Mattzüge, verstehen sich von selbst, aber das spricht nur für das Problem, das mit Minimalaufwand die Gangart des Turmhüpfers ausnutzt.
Keywords: Seriesmover
Pieces: = Rookhopper (TP)
Genre: Fairies
FEN: 1Q6/8/8/8/4K3/1k3*3r2/8/5*3r2
Input: Gerd Wilts, 2003-07-01
Last update: Alfred Pfeiffer, 2015-04-22 more...
Pieces: = Rookhopper (TP)
Genre: Fairies
FEN: 1Q6/8/8/8/4K3/1k3*3r2/8/5*3r2
Input: Gerd Wilts, 2003-07-01
Last update: Alfred Pfeiffer, 2015-04-22 more...
1. Lxd4! 2. Lxc5! 3. Lxb4! 4. c5! 5. c6 6. c7 7. c8=L 8. Lxf5 9. d7! 10. d8=D 11. Dc8! 12. Lg4 13. Lh5 14. Dh3 g5#
WW und MW: Hier steht eigentlich das wReflexmatt im Mittelpunkt: nämlich, warum man es verhindern muss.
KHS: Dass das Reflexmatt durch Bg5# geschehen muss und die beiden Fluchtfelder des wK h3 und h5 von Weiß selbst geblockt werden müssen, war schnell klar; der Weg zur Lösung dauerte aber etwas länger.
AB: Auf die Bd3/d4 kann man verzichten [Stimmt! GES]!
HJ: Gefällig, wie unter Reflexmattbedingungen u.a. sonst mögliche Duale vermieden werden!
WW und MW: Hier steht eigentlich das wReflexmatt im Mittelpunkt: nämlich, warum man es verhindern muss.
KHS: Dass das Reflexmatt durch Bg5# geschehen muss und die beiden Fluchtfelder des wK h3 und h5 von Weiß selbst geblockt werden müssen, war schnell klar; der Weg zur Lösung dauerte aber etwas länger.
AB: Auf die Bd3/d4 kann man verzichten [Stimmt! GES]!
HJ: Gefällig, wie unter Reflexmattbedingungen u.a. sonst mögliche Duale vermieden werden!
Anton Baumann: C+ Alybadix (2021-01-27)
Zoltán Laborczi: Verführungen:
1.d7? (verstellt Lxf5)
1.d7? 2.d8=D 3.Lxd4 4.Dd6/c7/b8#
1.d7? 2.d8=D 3.Dc8 (versellt c8=L)
2.Lb2/Lc3/Lf6? 3.d4 4.Lc1/Ld2/Lg5#
2.La1/Lg7/Lh8? 3.d4 4.dxc5 5.c6 6.c7 7.c8=L 8.Lxf5 9.d7 10.d8=D 11.Dg5#
2.Lf2/Lg1? 3.d4 4.dxc5 5.c6 6.c7 7.c8=L 8.Lxf5 9.d7 10.d8=D 11.Dc8 12.Lg5 Db8/Dc7#
3.La7/Lb6/Ld4/Lf2/Lg1? (wie oben)
4.d7? 5.d8=D 6.Dd4#
9.Lg4? 10.d7 11.d8=D 12.Dd4#
9.Lg4? 10.Lh5 11.d7 12.d8=D 12.Dg5#
11.Dd7? 12.Lg5 Dd4#
Der wBd3 hat eine Rolle nur in den Verführungen. (2021-03-22)
comment
Zoltán Laborczi: Verführungen:
1.d7? (verstellt Lxf5)
1.d7? 2.d8=D 3.Lxd4 4.Dd6/c7/b8#
1.d7? 2.d8=D 3.Dc8 (versellt c8=L)
2.Lb2/Lc3/Lf6? 3.d4 4.Lc1/Ld2/Lg5#
2.La1/Lg7/Lh8? 3.d4 4.dxc5 5.c6 6.c7 7.c8=L 8.Lxf5 9.d7 10.d8=D 11.Dg5#
2.Lf2/Lg1? 3.d4 4.dxc5 5.c6 6.c7 7.c8=L 8.Lxf5 9.d7 10.d8=D 11.Dc8 12.Lg5 Db8/Dc7#
3.La7/Lb6/Ld4/Lf2/Lg1? (wie oben)
4.d7? 5.d8=D 6.Dd4#
9.Lg4? 10.d7 11.d8=D 12.Dd4#
9.Lg4? 10.Lh5 11.d7 12.d8=D 12.Dg5#
11.Dd7? 12.Lg5 Dd4#
Der wBd3 hat eine Rolle nur in den Verführungen. (2021-03-22)
comment
Keywords: Seriesmover
Genre: Fairies
FEN: 8/8/3P2p1/2p2p2/1pPp1k1K/3P1P2/1B4P1/8
Input: Gerd Wilts, 2003-07-01
Last update: James Malcom, 2021-01-27 more...
Genre: Fairies
FEN: 8/8/3P2p1/2p2p2/1pPp1k1K/3P1P2/1B4P1/8
Input: Gerd Wilts, 2003-07-01
Last update: James Malcom, 2021-01-27 more...
1. g4 2. gxh5 3. h6 4. h7 5. h8=T 6. Ta8 7. Txa4 8. Kc3 9. Txh4 10. a4 11. a5 12. a6 13. a7 14. a8=S 15. Sb6 16. Sc4 17. Sd2 18. Tc4 19. h4 20. h5 21. h6 22. h7 23. h8=D 24. Dh7 25. Dxc2 26. Td3 27. f4 28. f5 29. f6 30. f7 31. f8=L 32. Lb4 33. Db2+ Lxb2#
Cook: 1. Tb3 2. Tb2 3. a3 4. Kb4 5. g4 6. g5 7. g6 8. g7 9. g8=L 10. La2 11. f4 12. f5 13. f6 14. f7 15. f8=T 16. Kb3 17. Th8 18. Txh5 19. Txh4 20. Tb4 21. h4 22. h5 23. h6 24. h7 25. h8=S 26. Sf7 27. Sd6 28. Sc4 29. Tb1+ cxb1=D# (cxb1=~#)
Cook: 1. Tb3 2. Tb2 3. a3 4. Kb4 5. g4 6. g5 7. g6 8. g7 9. g8=L 10. La2 11. f4 12. f5 13. f6 14. f7 15. f8=T 16. Kb3 17. Th8 18. Txh5 19. Txh4 20. Tb4 21. h4 22. h5 23. h6 24. h7 25. h8=S 26. Sf7 27. Sd6 28. Sc4 29. Tb1+ cxb1=D# (cxb1=~#)
Die obige Kurzlösung wurde innerhalb der Lösungsbesprechung in Heft 201, 06/2003, S. 154 angegeben.
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Keywords: Seriesmover, Allumwandlung, konsekutive Umwandlungen 4 (TSDL), Excelsior (4x)
Genre: Fairies
FEN: 8/8/8/7p/n1K4p/5R2/P1p2PPP/k1bb4
Input: Gerd Wilts, 2003-07-01
Last update: Arnold Beine, 2022-09-07 more...
Genre: Fairies
FEN: 8/8/8/7p/n1K4p/5R2/P1p2PPP/k1bb4
Input: Gerd Wilts, 2003-07-01
Last update: Arnold Beine, 2022-09-07 more...
1. exd3ep 2. Td5 3. Lc5 4. Lb4 5. Dc5 6. Sd4 exd3#
No. 1126 HN
A.Buchanan: Consequential series movers were invented in 1979. (2015-11-11)
A.Buchanan: Although there is trivial retro consideration at the beginning, this is not a consequent problem. After Black's first four series moves, the position has no last move for White, which violates the consequent condition. This is just a regular seriesmover, with ep convention in the diagram, contrary to the initial post in 2004. (2020-12-10)
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A.Buchanan: Consequential series movers were invented in 1979. (2015-11-11)
A.Buchanan: Although there is trivial retro consideration at the beginning, this is not a consequent problem. After Black's first four series moves, the position has no last move for White, which violates the consequent condition. This is just a regular seriesmover, with ep convention in the diagram, contrary to the initial post in 2004. (2020-12-10)
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Keywords: En passant as key, Seriesmover
Genre: Retro
Computer test: C+ Gustav 4.1d & minimal retro logic
FEN: 8/8/8/1pr5/2kPp3/2p1bn1p/2P1Pq1P/7K
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2020-12-10 more...
Genre: Retro
Computer test: C+ Gustav 4.1d & minimal retro logic
FEN: 8/8/8/1pr5/2kPp3/2p1bn1p/2P1Pq1P/7K
Input: Henri Nouguier, 2004-01-11
Last update: A.Buchanan, 2020-12-10 more...
1. dxc3ep 2. Kxb5 3. Kc6 4. Kd7 5. Ke8 6. 0-0 Txg7#
Un des PNd a pris 1 pièce blanche. pour venir de e7. Donc les PB b, c et d ne peuvent se croiser. Le PBg6 ne peut venir de f5 car il faudrait 2 prises noires! Seule reste le dernier coup blanc 0... c2-c4 Ceci implique que le FNb1 est issue de promtion ! C'est le PNb7, il aurait pris 2 pièces blanches. Les PNg5 et h5 ont pris 2 pièces blanches.
Un des PNd a pris 1 pièce blanche. pour venir de e7. Donc les PB b, c et d ne peuvent se croiser. Le PBg6 ne peut venir de f5 car il faudrait 2 prises noires! Seule reste le dernier coup blanc 0... c2-c4 Ceci implique que le FNb1 est issue de promtion ! C'est le PNb7, il aurait pris 2 pièces blanches. Les PNg5 et h5 ont pris 2 pièces blanches.
No. 11661 HN
A.Buchanan: “Obvious promotion” is intended to refer to something visible in the initial diagram position, not what is reached during series play (2022-09-14)
A.Buchanan: Similarly “non-standard material (2022-09-14)
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A.Buchanan: “Obvious promotion” is intended to refer to something visible in the initial diagram position, not what is reached during series play (2022-09-14)
A.Buchanan: Similarly “non-standard material (2022-09-14)
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Keywords: Seriesmover, Consequent, En passant as key, Promotion in the retro play (sLb1), Castling, Valladao Task
Genre: Retro, Fairies
FEN: 7r/5pnR/5PnR/1Pp2ppq/1kPp4/p2P4/P2pP3/Kbb4r
Input: Henri Nouguier, 2004-01-11
Last update: Mario Richter, 2022-09-14 more...
Genre: Retro, Fairies
FEN: 7r/5pnR/5PnR/1Pp2ppq/1kPp4/p2P4/P2pP3/Kbb4r
Input: Henri Nouguier, 2004-01-11
Last update: Mario Richter, 2022-09-14 more...
1. Td2 2. Tb2 3. bxc3ep 4. Th2 5. Th8 6. Kxb5 7. Kc6 8. Kd7 9. Ke8 10. 0-0 Lxb3#
Following the ep, b4-b5 is the legitimate last move.
Following the ep, b4-b5 is the legitimate last move.
No. 1304 HN
A.Buchanan: Made changes, and checked that all moves comply with the condition. Following the e.p., b4-b5 is legitimate last move. (2021-01-19)
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A.Buchanan: Made changes, and checked that all moves comply with the condition. Following the e.p., b4-b5 is legitimate last move. (2021-01-19)
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Keywords: Seriesmover, Consequent, En passant, Castling, Grid Chess
Genre: Retro, Fairies
FEN: 8/8/8/1P6/kpP5/Kp1r4/B7/8
Input: Henri Nouguier, 2004-01-11
Last update: James Malcom, 2021-09-14 more...
Genre: Retro, Fairies
FEN: 8/8/8/1P6/kpP5/Kp1r4/B7/8
Input: Henri Nouguier, 2004-01-11
Last update: James Malcom, 2021-09-14 more...
1. Kd2 2. Ke3! 3. Kd4 4. Ke5 5. Kd6 6. Kd7 7. Ke8 8. 0-0 9. bxc3ep Lxb3#
1. Kd2 2. Kd3? - W hat keinen letzten Zug
1. Kd2 2. Kd3? - W hat keinen letzten Zug
No. 1857 HN
Original ohne wBb2, mit wKb1 und sLa3 veröffentlicht, dann aber NL 1. bxc3ep, weil danach W als letzten Zug Kc2-b1 hatte.
In der korrigierten Stellung (03/1988, S.400) hat W nach bxc3ep nie einen letzten Zug, so daß dieser ep-Schlag erst am Ende der Lösung gespielt werden darf.
Außerdem bietet der Autor noch einen Zwilling an: Ks a5/a4, zusätzlich Monchromes Schach, shc#6
('The Problemist' (03/1988, S.400): "Composer's Mono-chromatic setting (1.bc ep.) saves another unit, but has less interest."
paul: Or directly 1.bxc3ep etc. (2011-10-24)
James Malcom: Is this cooked, as paul's comment seems to indicate? (2021-09-14)
Henrik Juel: No, I don't think so, James
After 1.bxc3ep White has no previous move (2021-09-15)
Mario Richter: Paul's comment was obviously referring to the origial position, not to the one now presented in the diagram.
(The germsn comment above reads: Originally published without white pawn b2, with wKb1 and black Bishop a3. But then cooked by 1. bxc3ep, because W has Kc2-b1 as last move [preceeded by c4xb3+]) (2021-09-16)
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Original ohne wBb2, mit wKb1 und sLa3 veröffentlicht, dann aber NL 1. bxc3ep, weil danach W als letzten Zug Kc2-b1 hatte.
In der korrigierten Stellung (03/1988, S.400) hat W nach bxc3ep nie einen letzten Zug, so daß dieser ep-Schlag erst am Ende der Lösung gespielt werden darf.
Außerdem bietet der Autor noch einen Zwilling an: Ks a5/a4, zusätzlich Monchromes Schach, shc#6
('The Problemist' (03/1988, S.400): "Composer's Mono-chromatic setting (1.bc ep.) saves another unit, but has less interest."
paul: Or directly 1.bxc3ep etc. (2011-10-24)
James Malcom: Is this cooked, as paul's comment seems to indicate? (2021-09-14)
Henrik Juel: No, I don't think so, James
After 1.bxc3ep White has no previous move (2021-09-15)
Mario Richter: Paul's comment was obviously referring to the origial position, not to the one now presented in the diagram.
(The germsn comment above reads: Originally published without white pawn b2, with wKb1 and black Bishop a3. But then cooked by 1. bxc3ep, because W has Kc2-b1 as last move [preceeded by c4xb3+]) (2021-09-16)
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Keywords: En passant, Grid Chess, Seriesmover, Consequent, Castling
Genre: Retro, Fairies
FEN: 7r/8/8/8/1pP5/Kp6/BP6/4k3
Input: Henri Nouguier, 2004-01-11
Last update: Mario Richter, 2021-09-15 more...
Genre: Retro, Fairies
FEN: 7r/8/8/8/1pP5/Kp6/BP6/4k3
Input: Henri Nouguier, 2004-01-11
Last update: Mario Richter, 2021-09-15 more...
80 - P1012460
Andrey Frolkin
Sergey A. Komarov
The Problemist 1/1990
2. ehrende Erwähnung
(11+7)
shc#7
Vertikaler Zylinder
Andrey Frolkin
Sergey A. Komarov
The Problemist 1/1990
2. ehrende Erwähnung
(11+7)
shc#7
Vertikaler Zylinder
1. a5 2. a4 3. a3 4. a2 5. a1=T 6. Ta8 7. 0-0 (castling with a queenside rook!) Tg3#
The interest here is in the try 5. h1=T? 6. Th8, when, in a game to that position, the sK or sT must have moved to let out Ta8 to be captured (0-0?). The solution is a surprise, involving castling round the cylinder instead.
The interest here is in the try 5. h1=T? 6. Th8, when, in a game to that position, the sK or sT must have moved to let out Ta8 to be captured (0-0?). The solution is a surprise, involving castling round the cylinder instead.
No. 2142 HN
James Malcom: Due to the implementation of odds castling, the castling animation is off here. Is there any possible fix or circumvention? (2021-09-14)
comment
James Malcom: Due to the implementation of odds castling, the castling animation is off here. Is there any possible fix or circumvention? (2021-09-14)
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Keywords: Seriesmover, Consequent, Vertical Cylinder (Vertikaler), Homebase (s), Castling, Excelsior, Promotion (t)
Genre: Retro, Fairies
FEN: 4k3/pppp1p1p/1N3B2/4P3/4PK2/5R2/1PPPPP2/8
Input: Henri Nouguier, 2004-01-11
Last update: James Malcom, 2021-09-14 more...
Genre: Retro, Fairies
FEN: 4k3/pppp1p1p/1N3B2/4P3/4PK2/5R2/1PPPPP2/8
Input: Henri Nouguier, 2004-01-11
Last update: James Malcom, 2021-09-14 more...
1. Kg3? 2. Dd1#
1. Dg3? 2. Dxf2#
1. Dg5,Dg6,Dg7? 2. Dc1,Db1,Da1#
1. Dg8! 2. Kg3 3. Kh2 4. Kh1 5. Dg1+ fxg1=D#
1. Dg3? 2. Dxf2#
1. Dg5,Dg6,Dg7? 2. Dc1,Db1,Da1#
1. Dg8! 2. Kg3 3. Kh2 4. Kh1 5. Dg1+ fxg1=D#
Keywords: Seriesmover, Minimal, Miniature
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/8/6Q1/5K2/5p2/5k2
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/8/6Q1/5K2/5p2/5k2
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
1. d4 2. d5 3. d6 4. d7 5. d8=T 6. Td3 7. Tf3+ Sxf3=
5. d8=D? 6. Dxd2=
5. d8=D? 6. Dxd2=
Keywords: Seriesmover, Minimal, Miniature
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/8/8/3P4/3n4/5k1K
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/8/8/3P4/3n4/5k1K
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
1. Th2! 2. Tg2 3. Kh2 4. Kh1 5. Tg1+ fxg1=L=
1. Kh2? 2. Te3=
1. Kh2? 2. Te3=
Keywords: Seriesmover, Minimal, Miniature
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/8/8/6KR/5p2/5k2
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/8/8/6KR/5p2/5k2
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
84 - P1013274
Bernd Schwarzkopf
Hans Gruber
158 feenschach 47, p. 146, 07-09/1979
(1+0)
ser-s=26/0 genau
Haaner Schach
Weißer Längstzüger
Bernd Schwarzkopf
Hans Gruber
158 feenschach 47, p. 146, 07-09/1979
(1+0)
ser-s=26/0 genau
Haaner Schach
Weißer Längstzüger
1. La5 2. Ld2 3. Lh6 4. Le3 5. La7 6. Ld4 7. Lh8 8. Le5 9. Lb8 10. Ld6 11. La3 12. Lc1 13. Lb2 14. Lc3 15. Lb4 16. Lc5 17. Lb6 18. Ld8 19. Lh4 20. Le7 21. Lg5 22. Lf4 23. Lh2 24. Lg3 25. Lf2 26. Lg1==
{DL } 9. Lh2 10. Lf4 11. Lg3 12. Lf2 13. Lg1=
{DL } 9. Lh2 10. Lf4 11. Lg3 12. Lf2 13. Lg1=
Keywords: Maximummer, Haaner Chess, Seriesmover
Genre: Fairies
FEN: 8/8/8/8/8/8/8/4B3
Input: Hans Gruber, 2004-05-01
Last update: Alfred Pfeiffer, 2014-04-11 more...
Genre: Fairies
FEN: 8/8/8/8/8/8/8/4B3
Input: Hans Gruber, 2004-05-01
Last update: Alfred Pfeiffer, 2014-04-11 more...
85 - P1013337
Bernd Schwarzkopf
Hans Gruber
7 Die Schwalbe 65, p. 127, 10/1980
(1+0) C+
ser-!=55 genau
Haaner Schach
Längstzüger
Bernd Schwarzkopf
Hans Gruber
7 Die Schwalbe 65, p. 127, 10/1980
(1+0) C+
ser-!=55 genau
Haaner Schach
Längstzüger
1. Tc8 2. Th8 3. Th1 4. Ta1 5. Ta8 6. Ta2 7. Ta7 8. Th7 9. Tb7 10. Tb1 11. Tg1 12. Tg8 13. Tg2 14. Tg7 15. Tg3 16. Ta3 17. Tf3 18. Tf8 19. Tf4 20. Ta4 21. Te4 22. Te8 23. Te5 24. Ta5 25. Td5 26. Td1 27. Td4 28. Tb4 29. Tb2 30. Tb3 31. Te3 32. Te1 33. Tf1 34. Tf2 35. Td2 36. Td3 37. Tc3 38. Tc7 39. Tc4 40. Tc6 41. Th6 42. Th2 43. Th5 44. Th3 45. Th4 46. Tg4 47. Tg6 48. Td6 49. Td8 50. Td7 51. Tf7 52. Tf5 53. Tf6 54. Te6 55. Te7!=
Erich Bartel: richtig,es fehlt der Hinweis "(genau) Typ3, den die Autoren wie folgt bestimmen: die absolut längste mit Patt endende Zugfolge (zugleich die absolut längstmögliche Zugfolge).
[Schwarzkopf/Gruber:Patt-Einsteiner im Haaner-Schach Längstzüger, Die Schwalbe X 1980,S.127.--
Unter diesem Aspekt ist die Aufgabe auch korrekt.--- (2009-07-07)
Joost de Heer: See P1211624 for a longer composition with a nightrider. (2022-08-03)
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[Schwarzkopf/Gruber:Patt-Einsteiner im Haaner-Schach Längstzüger, Die Schwalbe X 1980,S.127.--
Unter diesem Aspekt ist die Aufgabe auch korrekt.--- (2009-07-07)
Joost de Heer: See P1211624 for a longer composition with a nightrider. (2022-08-03)
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Keywords: Maximummer, Haaner Chess, Move Length Record (Typ 3), Seriesmover, Aristocrat
Genre: Fairies
FEN: 8/8/8/8/8/8/2R5/8
Input: Hans Gruber, 2004-05-01
Last update: Alfred Pfeiffer, 2016-08-23 more...
Genre: Fairies
FEN: 8/8/8/8/8/8/2R5/8
Input: Hans Gruber, 2004-05-01
Last update: Alfred Pfeiffer, 2016-08-23 more...
86 - P1013381
Hans Gruber
198v Jugendschach 06/1981
(3+1) C+
ser-h#4
Zwei Lösungen
wSL=Kamel
wLL=Kardinal
Hans Gruber
198v Jugendschach 06/1981
(3+1) C+
ser-h#4
Zwei Lösungen
wSL=Kamel
wLL=Kardinal
1. Ke5 2. Kxf6 3. Ke5 4. Kd4 CDh8#
1. Kc3 2. Kxb2 3. Kc3 4. Kd4 CDa1#
Korr. Problemkiste, IV 1993.
1. Kc3 2. Kxb2 3. Kc3 4. Kd4 CDa1#
Korr. Problemkiste, IV 1993.
Keywords: Seriesmover
Pieces: = Camel (CM), = Cardinal (CD)
Genre: Fairies
Computer test: popeye 4.87
FEN: 8/8/5*3N2/8/3k*3B3/8/1*3N6/8
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
Pieces: = Camel (CM), = Cardinal (CD)
Genre: Fairies
Computer test: popeye 4.87
FEN: 8/8/5*3N2/8/3k*3B3/8/1*3N6/8
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
1. Kc6? 2. b6 3. bxc7=
1. Kc5! 2. b6 3. Kb5 4. Ka6 5. Ka7 6. Ka8 Lxb6=
1. Kc5! 2. b6 3. Kb5 4. Ka6 5. Ka7 6. Ka8 Lxb6=
Keywords: Seriesmover, Minimal, Miniature
Genre: Fairies
Computer test: Alybadix
FEN: 2k5/2b5/3K4/1P6/8/8/8/8
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
Genre: Fairies
Computer test: Alybadix
FEN: 2k5/2b5/3K4/1P6/8/8/8/8
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
88 - P1013535
Hans Gruber
Janos Csak
Arno Tüngler
4073v Die Schwalbe 77 10/1982
(3+5) C+
Kürzestes ser-h#?
Hans Gruber
Janos Csak
Arno Tüngler
4073v Die Schwalbe 77 10/1982
(3+5) C+
Kürzestes ser-h#?
1. a1=S? 2. Sc2 3. Se3 4. Kf3 5. Kg2 6. Kh1 7. Sg2 8. Txe1 9. Tg1 Th3#
1. Td7! 2. Td4 3. Kd5 4. Kc6 5. Kb5 6. Ka4 7. Ka3 8. Ta4 Kc2#
1. Td7! 2. Td4 3. Kd5 4. Kc6 5. Kb5 6. Ka4 7. Ka3 8. Ta4 Kc2#
Keywords: Seriesmover
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 8/4rp2/8/2p5/4k3/2KR4/p7/4B3
Reprints: My problems [Arno Tüngler] , p. 89, 06/2009
Input: Hans Gruber, 2004-05-01
Last update: Arno Tüngler, 2023-12-02 more...
Genre: Fairies
Computer test: Gustav 4.1d
FEN: 8/4rp2/8/2p5/4k3/2KR4/p7/4B3
Reprints: My problems [Arno Tüngler] , p. 89, 06/2009
Input: Hans Gruber, 2004-05-01
Last update: Arno Tüngler, 2023-12-02 more...
1. Kc2 2. Kd3 3. Kxe4 4. Kf3 5. Kg2 6. Kxh1 7. Kg2 8. Kxf2 9. Ke2 10. Kxd2=
A.Buchanan: What's the idea? If it's a length record, can't we shift all the pieces up and put wK on a1 to increase the solution length by one. (2022-03-15)
SCHRECKE: Andrew, it's look like an "A" for "Annemarie". (2022-03-15)
Henrik Juel: This is not the best-looking A, I have seen, so it should not be Keyword'ed Letter problem
Incidentally, the problem can also be tested by Popeye, in a flash (2022-03-15)
A.Buchanan: Thanks all! Letter A must be the concept, although I must admit I didn't see it. It's certainly closer to A than any other letter (excepting the Cyrillic alphabet) to it would be churlish to refuse it the keyword. I hope that, in the unlikely event that Hans ever dedicated a letter problem to me, he would use a less wispy font :) (2022-03-16)
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SCHRECKE: Andrew, it's look like an "A" for "Annemarie". (2022-03-15)
Henrik Juel: This is not the best-looking A, I have seen, so it should not be Keyword'ed Letter problem
Incidentally, the problem can also be tested by Popeye, in a flash (2022-03-15)
A.Buchanan: Thanks all! Letter A must be the concept, although I must admit I didn't see it. It's certainly closer to A than any other letter (excepting the Cyrillic alphabet) to it would be churlish to refuse it the keyword. I hope that, in the unlikely event that Hans ever dedicated a letter problem to me, he would use a less wispy font :) (2022-03-16)
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Keywords: Seriesmover, Rex solus, Illegal position (no sK), Symbol problem (A)
Genre: Fairies
Computer test: C+ Alybadix
FEN: 8/8/8/8/4n3/8/3b1p2/1K5n
Input: Hans Gruber, 2004-05-01
Last update: A.Buchanan, 2022-03-16 more...
Genre: Fairies
Computer test: C+ Alybadix
FEN: 8/8/8/8/4n3/8/3b1p2/1K5n
Input: Hans Gruber, 2004-05-01
Last update: A.Buchanan, 2022-03-16 more...
1. Kc7 2. Kd6 3. Ke5 (3. Ke6? 4. h8=D,T#) 4. Kf6 5. Kg7 6. Kh8 Kf7#
Keywords: Seriesmover, Minimal, Miniature, Homebase
Genre: Fairies
Computer test: Alybadix
FEN: r1K1k3/7P/8/8/8/8/8/8
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
Genre: Fairies
Computer test: Alybadix
FEN: r1K1k3/7P/8/8/8/8/8/8
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
a) 1. Ka3 2. Tc5 (2. Tb2? 3. Txb8=) 3. Tb5 Dxb5=
b) 1. Ka4 (1. Ka3? 2. Txb8=) 2. Tb5 3. Ka3 Dxb5=
b) 1. Ka4 (1. Ka3? 2. Txb8=) 2. Tb5 3. Ka3 Dxb5=
Keywords: Seriesmover, Aristocrat, Minimal, Miniature
Genre: Fairies
Computer test: Alybadix
FEN: 1q6/8/8/8/1K6/8/2R5/k7
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
Genre: Fairies
Computer test: Alybadix
FEN: 1q6/8/8/8/1K6/8/2R5/k7
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
1. Ka3 21. Kxa8[+Sb1] 22. Kb8 38. Kc1 Sc3=
Keywords: Circe, Seriesmover, Aristocrat, Minimal, Miniature
Genre: Fairies
Computer test: popeye 4.85
FEN: N7/8/1K6/8/k7/8/8/8
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
Genre: Fairies
Computer test: popeye 4.85
FEN: N7/8/1K6/8/k7/8/8/8
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-05 more...
* 1. ... GNg5,GNg7,GNb5,GNb7#
1. Kxe6 2. Kf7 3. Ke8 4. Kd8 5. Kc8 6. Kb8 7. Ka8 GNd7#
1. Kxe6 2. Kf7 3. Ke8 4. Kd8 5. Kc8 6. Kb8 7. Ka8 GNd7#
Keywords: Seriesmover
Pieces: = Gnu (GN)
Genre: Fairies
FEN: 8/8/1K1k*3N1*3N1/8/8/8/8/8
Input: Hans Gruber, 2004-05-01
Last update: Alfred Pfeiffer, 2013-08-22 more...
Pieces: = Gnu (GN)
Genre: Fairies
FEN: 8/8/1K1k*3N1*3N1/8/8/8/8/8
Input: Hans Gruber, 2004-05-01
Last update: Alfred Pfeiffer, 2013-08-22 more...
94 - P1013696
Hilmar Ebert
Hans Gruber
682 Ideal-Mate Review 07-08/1984
(1+1)
a) ser-H#4 b) ser-H#5 genau
Hilmar Ebert
Hans Gruber
682 Ideal-Mate Review 07-08/1984
(1+1)
a) ser-H#4 b) ser-H#5 genau
a) 1. kBb1=kS 2. kSa3 3. kSc2 4. kSa1 kPd4#
b) 1. kBb1=kS 2. kSc3 3. kSa4 4. kSb6 5. kSa8 kPd5#
b) 1. kBb1=kS 2. kSc3 3. kSa4 4. kSb6 5. kSa8 kPd5#
95 - P1013709
Joseph Percival Ford
Erich Bartel
Hans Gruber
971 Problemkiste 10/1984
(2+2)
ser-Remis in 4 (ohne Stellungswiederholungsregel)
Joseph Percival Ford
Erich Bartel
Hans Gruber
971 Problemkiste 10/1984
(2+2)
ser-Remis in 4 (ohne Stellungswiederholungsregel)
1. Kd7 2. c4 3. c5 4. c6 and draw by 5. c7!
A.Buchanan: Baffled - what’s going on here? (2023-04-07)
shankar ram: Series Draw in 4 moves (Draw by repetition rule not applicable)! (2023-04-08)
A.Buchanan: Thanks Shankar, I could translate the stipulation. But now the penny has dropped that it means reach a drawing position, not a draw. But normally after ser-goal in n moves, it is formally Black to move. E.g. ser-# in n, or ser-= in n. But here, the rule is broken: it's White to move to sneak a 5th move in. After 4. c6 with Black to move as usual, there is 4. ... Qh3+/Qh7+. So I think it should be ser-draw in 5. I will mark it as a study as well as fairies. (2023-04-08)
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shankar ram: Series Draw in 4 moves (Draw by repetition rule not applicable)! (2023-04-08)
A.Buchanan: Thanks Shankar, I could translate the stipulation. But now the penny has dropped that it means reach a drawing position, not a draw. But normally after ser-goal in n moves, it is formally Black to move. E.g. ser-# in n, or ser-= in n. But here, the rule is broken: it's White to move to sneak a 5th move in. After 4. c6 with Black to move as usual, there is 4. ... Qh3+/Qh7+. So I think it should be ser-draw in 5. I will mark it as a study as well as fairies. (2023-04-08)
comment
Keywords: Draw by repetition (not), Seriesmover
Genre: Fairies, Studies
FEN: 8/8/3K4/8/8/8/2P4q/7k
Input: Hans Gruber, 2004-05-01
Last update: A.Buchanan, 2023-04-08 more...
Genre: Fairies, Studies
FEN: 8/8/3K4/8/8/8/2P4q/7k
Input: Hans Gruber, 2004-05-01
Last update: A.Buchanan, 2023-04-08 more...
* 1. ... Lc2#
1. a2 2. a1=L 3. Lb2 4. La3 Lc2#
1. a2 2. a1=L 3. Lb2 4. La3 Lc2#
Keywords: Seriesmover, Minimal, Miniature
Genre: Fairies
Computer test: popeye 4.87
FEN: 8/8/1Q6/8/k7/p7/8/1B6
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: popeye 4.87
FEN: 8/8/1Q6/8/k7/p7/8/1B6
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-31 more...
1. Lxg3? (2. Kg2 3. Th1 4. Sh3/Lh2 5. Lh2/Sh3 5. Lg1 7. Kh2 Kf3=) 2. Txh5=
1. Txg3! 2. Sh3 3. Tg1 4. Kg2 5. Th1 6. Lg1 7. Kh2 Kf3=
1. Txg3! 2. Sh3 3. Tg1 4. Kg2 5. Th1 6. Lg1 7. Kh2 Kf3=
Keywords: Seriesmover
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/7r/2p1k3/2P3rR/2P2P1B/6NK
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: Alybadix
FEN: 8/8/8/7r/2p1k3/2P3rR/2P2P1B/6NK
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-31 more...
1. Kxb8 2. Kc7 3. Kd6 4. Ke5 5. Kf4 6. Kg3=
Anton Baumann: C+ Gustav 4.2a (2023-04-21)
Ladislav Packa: Ka7-a1 and ser-=12 C+ by Popeye v4.63 (2023-04-21)
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Ladislav Packa: Ka7-a1 and ser-=12 C+ by Popeye v4.63 (2023-04-21)
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1. cxd4 2. dxc3 3. c2 4. c1=L 5. Lf4 6. Lh2 7. Lg1 8. h2 9. h1=T 10. Txh5 11. Th1 12. h5 13. h4 14. h3 15. h2 b5==
Nicht 1. cxb4? ... 15. h2==? Doppelpatt, aber nicht durch Weiß.
Nicht 1. cxb4? ... 15. h2==? Doppelpatt, aber nicht durch Weiß.
Keywords: Seriesmover
Genre: Fairies
Computer test: popeye 4.85
FEN: Bk6/1P6/1P1p3p/2pP3P/1P1P4/2P2p1p/5p2/5K2
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-31 more...
Genre: Fairies
Computer test: popeye 4.85
FEN: Bk6/1P6/1P1p3p/2pP3P/1P1P4/2P2p1p/5p2/5K2
Input: Hans Gruber, 2004-05-01
Last update: Arnold Beine, 2022-10-31 more...
100 - P1013792
Hans Gruber
Theodor Steudel
652 Rex Multiplex 07-09/1986
(3+3) C+
ser-R#7
b) wB d2 nach b5: ser-R=7
Hans Gruber
Theodor Steudel
652 Rex Multiplex 07-09/1986
(3+3) C+
ser-R#7
b) wB d2 nach b5: ser-R=7
a) 1. d4 2. d5 3. d6 4. d7 5. d8=T 6. Tg8 7. Tg1+ fxg1=D#
b) 1. b6 2. b7 3. b8=S 4. Sc6 5. Sd4 6. Se2 7. Sg1 fxg1=L=
b) 1. b6 2. b7 3. b8=S 4. Sc6 5. Sd4 6. Se2 7. Sg1 fxg1=L=
Keywords: Seriesmover, Allumwandlung (Td,Sl), Kindergarten Problem, Miniature
Genre: Fairies, r#
Computer test: C+ Alybadix
FEN: 8/8/8/8/5p2/5P2/3P1p2/5k1K
Input: Hans Gruber, 2004-05-01
Last update: A.Buchanan, 2022-02-28 more...
Genre: Fairies, r#
Computer test: C+ Alybadix
FEN: 8/8/8/8/5p2/5P2/3P1p2/5k1K
Input: Hans Gruber, 2004-05-01
Last update: A.Buchanan, 2022-02-28 more...
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The problems of this query have been registered by the following contributors:
Gerd Wilts (42)Torsten Linss (1)
Felber, Volker (32)
Henri Nouguier (5)
Hans Gruber (20)
A.Buchanan: "By 'type Tauber/Caillaud' it is meant that the individual positions may/should be regarded as a retroanalytic overall complex (otherwise no AP legalization would be possible), although they are independent of each other due to the retroanalytic reassessment after each retraction." (2023-06-29)
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