Die Schwalbe

14 problem(s) found in 3417 milliseconds (displaying 14 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND NOT S='harmonie' AND S='Eigenartige Schachprobleme'] [download as LaTeX]

1 - P0000758
Gerd Rinder
1033 Die Schwalbe 21 06/1973
1. Preis
P0000758
(7+11)
Remis (AP)
Weiß ist patt. 1. cxb6ep ist nur zulässig, wenn Schwarz diese a posteriori durch die Rochade rechtfertigt. Weiß kann aber so spielen, daß Schwarz nicht rochieren kann, z.B. 1. ... Lxc7 2. bxc7
play all play one stop play next play all
Guus Rol: This is an incorrect interpretation of the AP-convention. Rules outrank goals in the definition of all GAMES. Therefore the legitimacy of a move cannot be restricted by the desire to achieve the goal (in this case: Remis). The proper way to view AP is that executing e.p. invalidates the legitimacy of all lines of future play that do not contain 0-0-0! In that sense black and white are forced to cooperate. In whatever freedom remains they can compete for the prize promised in the stipulation. By the way, this understanding of AP is not only more logical, it is also much more interesting as a playing field for AP-composition. (2005-09-21)
mri: citeWeiß kann aber so spielen, daß Schwarz nicht rochieren kann, z.B. 1. ... Lxc7 2. bxc7
/cite
How does white prevent black from castling after 1. cxb6 e.p. Ba7xb6+?
E.g. 2.Kxb6 a1=R 3.a7 Rxa7, or 2.Ka4 Bd8xc7 3.a7 Bb8. (2005-09-22)
VL: 1.c5xb6ep(??) a7xb6+ 2.Kxb6 a1R 3.Kb7 R1xa6 4.Rc8! (R6a7#?? illegal).
This study is correct under the generally accepted understanding of AP
a la' N.Petrovic'. Antiform (looking possibly somewhat strange):
Black's unsuccessful try. (2005-10-03)
Guus Rol: Generally accepted, true. Generally acceptable, false. Freedom of interpretation ceases for a concept once its polar concept (a priori validation) has been defined. "Goal induced AP" however, might be a passable stipulation for this type of problem. To keep this place from turning into a discussion forum I will discontinue comments on this issue. (2005-10-03)
paul: Author intention is: If black still can castle, his last move must have been b7-b5. However, to prove this, he has to castle (A Posteriori condition). So: 1.cxb6 e.p. axb6+ 2.Kxb6 a1R! (2...a1Q? 3.Kb7 Qxa6 mate obviously doesn`t prove b7-b5 as the last move) 3.Kb7 R1xa6 4.Rc8! and white has prevented black from castling. So black can`t prove the last move is b7-b5 and therefor is already stalemated in the initial position! (2011-07-12)
A.Buchanan: Isn't Guus' idea just AP-Prioritat? And even if it were "more logical" or "more interesting", it doesn't follow that other forms is AP are "incorrect" (2023-07-31)
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comment
Keywords: En passant as key, Castling (sg), a posteriori (AP)
Genre: Retro, Studies
FEN: r2bk3/p1Rpp3/P1p2p2/KpP2P2/1P2p3/1P6/p7/8
Reprints: (4) Problem 161-164 11/1973
317 Europe Echecs 217 01/1977
(A) Die Schwalbe 80 04/1983
408 Eigenartige Schachprobleme 2010
M36 mpk-Blätter 12/2011
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-07-31 more...
2 - P0000933
Luigi Ceriani
Sahovski vjesnik 12/1951
1. Preis
P0000933
(2+11) C+
Letzter Zug?
R: 1. Kg8xDh8
Solved in YouTubex httx//www. youtube. com/watch?v=Do_rkLQnrpk
play all play one stop play next play all
Compare P0000490 with equivalent material but 30 years later.
A.Buchanan: Solved in YouTube: https://www.youtube.com/watch?v=Do_rkLQnrpk (2022-02-17)
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comment
Keywords: Type A, Last Move? (KxD), Economy record (Last Move? Type A), Type B (a fortiori), Economy record (Last Move? Type B), Minimal
Genre: Retro
Computer test: Solved in YouTube: https://www.youtube.com/watch?v=Do_rkLQnrpk
FEN: 3bkN1K/pppprp1p/4p1p1/8/8/8/8/8
Reprints: 1372 FEENSCHACH 08-09/1952
Problem 10-12 12/1952
1.2A Eigenartige Schachprobleme , p. 172, 2010
1.2B Eigenartige Schachprobleme , p. 172, 2010
YouTube 13/02/2022
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-01 more...
3 - P0000957
Theophilus Harding Willcocks
Die Schwalbe 1959
Willcocks 1959, version
P0000957
(4+8)
Letzter Zug?
R: 1. a7xTb8=L
play all play one stop play next play all
See P1409984.
Yoav Ben-Zvi: WBd8 can be replaced with a BN after moving BPg7 to f7 and BPh5 to h6. (2018-08-08)
A.Buchanan: Yes after all these years, I found this a few months ago, but when I told Thomas Brand, he said that Werner Keym had found it - one of a series of modifications through seeking to avoid non-standard material. (2018-08-12)
Henrik Juel: Werner's improvement can be found in his 'Eigenartige Schachprobleme' from 2010, p.196, dia 1.68 (2018-08-12)
A.Buchanan: I thought it was more recent (2018-08-12)
A.Buchanan: In fact Werner was not trying to avoid non-standard material, but to prefer "cheaper" knights over bishops. But this is not the canonical ordering, which regards knights and bishops as equivalent. So the older record will win out in classical terms. (2019-10-04)
A.Buchanan: And non-standard material is no defect, according to the 1977 grading criteria, so old Theophilus reigns supreme (2019-10-04)
Henrik Juel: The further retroplay is
-1... h6 -2.a6 and e.g. -2... Ka7 -3.a5 Ta8 -4.Tb8 Ka6 -5.Kc8
and wK out via g6 (2019-10-04)
A.Buchanan: I don't know if a bishop is more expensive than a knight for these economy records. If modifying the criteria, I personally would prefer to minimize non-standard material. But more generally, how to handle a later version of economy record, with similar force? In some cases, the change is trivial, just transforming one unit which might as well be a dummy. At the other extreme, the matrix is completely different. In "Eigenartige Schachprobleme", Werner Keym stoically prefers the earlier record. Even the original composer(s) of a record problem are forbidden from making any artistic improvement to a published economy record! Over the years, the only change to the grading criteria is that Type C problem now needs to contain a check. Any old check-free Type C would a fortiori have been a Type B economy record at least. Here in PDB, I've tagged some cases of "ex-aequo" (search k='economy:eq') but I fear that Werner would not approve of this. What should we do? (2022-03-31)
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comment
Keywords: Type A, Last Move? (BxT=L), Promotion (L), Non-standard material (L)
Genre: Retro
FEN: kBRB4/1pKpp1p1/1pp5/7p/8/8/8/8
Reprints: 1.49A Eigenartige Schachprobleme , p. 190, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-06-02 more...
4 - P0001030
Jan R. Mortensen
Werner Keym

Die Schwalbe 1984
P0001030
(3+6)
Welches war der letzte Zug?
Schwarz am Zug
R: 1. f7xLg8=T
play all play one stop play next play all
siehe auch P0001031
Henrik Juel: Source is almost surely Caissa 1979 (CA stopped in 1930) (2020-12-17)
A.Buchanan: According to Werner Keym in ES, the original source is JM+WK Die Schwalbe 1984. That probably means that Werner modified P0001031 to tackle the different task here. I will adjust the source & authors accordingly. For these task problems, no-one tracks versioning, or afters. We just lump together all the composers who lent a hand. (2020-12-18)
Henrik Juel: OK, fine
Of course, this is also an example of First move by promoted Tg8, but not an economy record in this genre (2020-12-18)
A.Buchanan: Any last move which is promotion is implicitly a zero move for a the promoted unit. So I feel probably not worth adding the keyword of first move except for those which were intended as first move records. What do you think? (2020-12-19)
Henrik Juel: The same position with wSg8 was similar, but it was a double economy record, I think
The position with wTg8 is a last move record, but not a first move record, as removing Th7 and moving Ph6 to h7 is more economical
The first move problems with a zero move are not very impressive, so your approach is fine (2020-12-19)
comment
Keywords: Last Move? (BxL=T), Type B, Promotion (T), Economy record (Last Move? Type B)
Genre: Retro
FEN: k4bRK/4p1pR/5p1p/8/8/8/8/8
Reprints: 1.45B Eigenartige Schachprobleme , p. 188, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-30 more...
5 - P0001031
Jan R. Mortensen
Deutsche Schachrundschau Caissa 1979
P0001031
(3+6)
Welches war der letzte Zug?
Schwarz am Zug
(Erster Zug des wUWS?)
R: 1. f7xLg8=S
play all play one stop play next play all
Henrik Juel: Not R: 1.f7xSg8=S,
because the black knight can be extracted only by retracting f7-f6, trapping white king (2020-12-13)
A.Buchanan: Some brave person should sort out the keywords for record retros properly. Here's a good example. The last move is Type B, but the first move question is Type A. The original stipulation (which I think is just about the first move?) should stand. The first move question is a *deemed* stipulation (new terminology) and allows us to leverage an existing problem, without creating a new version or editing the prior stipulation. This is particularly true here, since the problems are of different type. (2020-12-14)
Hans-Jürgen Manthey: mögliche Retro-Zugfolge:
1.f7xLg8S Ka7-a8 2. e6xSf7 Sd6-f7+ 3. e5-e6 Le6-g8 4. Kg8-h8 Lc8-e6+ 5. Th8-h7 Ka8-a7 6. Kh7-g8 Kb7-a8 7. Kg6-h7 Kc7-b7 8. h7-h8T Kd8-c7 9. d4xSe5 Sd7-e5+ 10. Kf5-g6 Sf7-d6+ 11. g6xTh7 Th8-h7 12. g5-g6 h7-h6 13. Ke6-f5 Sh6-f7 14. g4-g5 Sg8-h6 15. e3xTd4 Ta4xSd4 16. f2xDe3 Dd2-e3+ 17. g2-g4 Ke8-d8 18. Kf5-e6 De2xd2 19. Ke4-f5 Dd1xe2+ 20. Kd3-e4 Df1xTd1 21. Sf3-d4 Dh1xLf1 22. Kc2-d3 Sb8-d7 23. Kc1-c2 Dh2xTh1 24. O-O-O Dc7xh2 25. Sg1-f3 Ta8xDa4 26. Dd1-a4+ Dc2-c7 27. Se6-c7+ Dc1xc2 28. Sc5-e6 Db2xLc1 29. Sd7-c5 Da2xb2 30. Se5xd7 Da5xa2 31. Sc6-e5 f7-f6 32. a7xc6 Dd8-a5 33. Sb5xa7 c7-c6 34. Sc3xb5 b7-b5 35. Sb1-c3 (2020-12-17)
Henrik Juel: 'The Chess Amateur 1979' must be wrong, as this magazine stopped in 1930 (2020-12-17)
Henrik Juel: .. and Eigenartige Schachprobleme just says Caissa 1979 (2020-12-17)
A.Buchanan: WinChloe does not have this problem at all! I am inclined to go with Eigenartige Schachprobleme. I suspect that Gerd was entering hundreds of compositions at scale, and a copy-paste error would be easy (2020-12-17)
A.Buchanan: Also P0001030 (2020-12-17)
A.Buchanan: Have removed "The Chess Amateur" as original source here. (2020-12-18)
comment
Keywords: Last Move? (BxL=S), Type B, Promotion (S), Economy record (Last move? Type B), First Move? (US0), Type A, Economy record (First move? Type A)
Genre: Retro
Computer test: RSP 1.2
FEN: k4bNK/4p1pR/5p1p/8/8/8/8/8
Reprints: The Chess Amateur 1979
1.55B Eigenartige Schachprobleme , p. 192, 2010
2.51 Eigenartige Schachprobleme , p. 202, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-30 more...
6 - P0001086
Peter Kahl
Jan R. Mortensen
Sveto Stambuk

Problem 5-6, p. 92, 12/1951
6. ehrende Erwähnung
P0001086
(4+1)
Welches war der letzte Zug?
R: 1. Dh3xSh2+
play all play one stop play next play all
im Original ist als Dritter Autor D. Suboticanec angegeben, habe entsprechend geändert.
Zu P. Kahl heißt es ergänzend: [aus] Osterholz-Scharmbeck
HBae: Ist "Klaus Peter Kahl" identisch zu "Peter Kahl" ? (2010-09-22)
Henrik Juel: Yes, probably
I know that 'Jan Robert Mortensen' is identical to 'Jan Mortensen'; he never used his middle name (2017-03-08)
A.Buchanan: It’s possible to put the middle name into the “addition” field in the author table, rather than have two names in the “first name” field. Then in overview list the middle name won’t appear, but it will still appear above each composition as here. Curiously the addition field is common across all four languages (German, English, French, Unicode) supported by the author table. There is no comment field to allow for random extra info to be stored, unlike the source table. So if we drop Robert, we lose it completely. (2022-03-31)
Henrik Juel: Thanks for the info, Andrew
I guess we will have to live with it
For Jan, there is really no risk of confusion
But for Knud Hannemann (son of the less illustrious composer Harald Hannemann) it is annoying to see him cast as Knud Harald Hannemann, just because it was a custom in his family that the sons were given the father's first name
They still use this custom in Russia, but with 'son of' added, e.g., Vladimir Vladimirovitch Putin (2022-03-31)
Henrik Juel: A chess problem example is Nikita Michaelovitch Plaksin
But the rendering of his name in the PBD also gives an obvious partial solution to my problem
Change the middle name of the two danish composers to the corresponding initial:
Jan R. Mortensen and Knud H. Hannemann (2022-03-31)
Henrik Juel: Thanks for the 'initialization', Andrew (2022-03-31)
A.Buchanan: OK fixed those, Henrik. HBae's original question concerned "Klaus Peter Kahl" vs "Peter Kahl". The former only has 2 problems here, and "both" collaborated with Jan Mortensen, so surely this is one person? (2022-03-31)
A.Buchanan: Kahls unified (2022-04-01)
Henrik Juel: I hear no protests from Osterholz-Scharmbeck, so that seems fine (2022-04-01)
comment
Keywords: Type C, Last Move? (DxS), Economy record (Last Move? Type C)
Genre: Retro
FEN: 8/8/8/8/7P/6P1/5K1Q/7k
Reprints: 1375 FEENSCHACH 08-09/1952
(C10) feenschach 160 07-08/2005
1.11C Eigenartige Schachprobleme , p. 176, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-04-01 more...
7 - P0001136
Edgar Fielder
The Fairy Chess Review 1941
P0001136
(13+10)
Darf Schwarz rochieren?
Schwarz hat bereits rochiert!
play all play one stop play next play all
See P1398939
Henrik Juel: Black captured b7xLc6 and axbxc; White captured [Lf8], e2xd3, and fxexdxc6xb7-b8=D.
Ke8 to b7, Th8 to b8, Kb7 to g8, Tb8 to f8, Da4 to b8 for unpromotion, -22.c6xDb7 Da8 -23.d5xLc6 Dd8 -24.d4 Lb7 -25.e3xTd4 Lc8 -26.f2xSe3 c6 -27.h5 b7xLc6, Lc6 to f1, f2xSe3 etc.
Black may not castle, because he already did.
It is not possible to avoid the early castling:
-11... Ka7 -12.Db4 Ka6 -13.Db8 Ka7 -14.D=b7 Kb8 -15.c6xDb7 Kc8 -16.d5xLc6 Kd8 -17.d4 Ke8 -18.e3xTd4 Da8 -19.f2xSe3 Dd8 -20.h5 Lb7 -21.h4 Lc8 and two white pawn retractions are missing (2012-07-23)
Yoav Ben-Zvi: The solution does not require a full analysis since if Black King and Rook never moved then Black is almost immediately in retro-stalemate. An alternative stipulation is "First move of Black King?". (2014-06-03)
A.Buchanan: Maybe there is intentional irony? (2014-06-03)
Henrik Juel: Nowadays composers are not afraid to use the real stipulation in this type of resolution retro, like 'Release the position'.
Formerly a formal stipulation was popular, like 'Mate in 1', with the real stipulation understood but not mentioned.
Here, the stipulation question may well be ironic, but you will get no solution points, if you just answer 'No'; you still need to explain how the position arose (2014-06-03)
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comment
Keywords: Castling (sk), Castling Paradox (sk hidden)
Genre: Retro
FEN: 4k2r/2pppppp/7P/2p5/Q1P5/PPRP4/RBpP2P1/N1K5
Reprints: 71 32 personaggi e 1 autore 1955
12 Europe Echecs 12 08/1959
222 FIDE Album 1914-1944/III 1975
341 Eigenartige Schachprobleme , p. 110, 2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-02-23 more...
8 - P0001468
Oskar E. Vinje
The Fairy Chess Review 1938
P0001468
(10+3)
Letzter Zug?
R: 1. 0-0-0
play all play one stop play next play all
Deemed stipulation: "Erster Zug des wTd1?"
Henrik Juel: White pawns captured all 13 missing black men
Retracting the castling is the only way to give Black a retraction, e.g. Kc2-b3 (2020-12-01)
comment
Keywords: Type A, Last Move? (0-0-0), Castling (wl), Economy record (Last Move? Type A), First Move? (T0), Economy record (First move)
Genre: Retro
FEN: 8/P1p5/PN6/1P6/P1N5/Pk6/pP6/2KR4
Reprints: 342 Europe Echecs 241 01/1979
1.57A Eigenartige Schachprobleme , p. 194, 2010
1 Die Schwalbe 360-1, p. 737, 12/2020
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-28 more...
9 - P0003417
John Frederick Keeble
2206 The Problemist Fairy Chess Supplement 16, p. 173, 02/1936
P0003417
(4+5) C+
h#2.5 (AP)
1. ... exd6ep 2. 0-0-0 dxe7+ 3. Tf8 exf8=T,D#
play all play one stop play next play all
H.Juel: If Black may castle, last move was not made by Ke8 or Ta8, but by Pd5, so it was d7-d5, and hence White may capture en passant. 1... exd6ep 2.0-0-0 dxe7 3.Tf8 exf8=D,T# where the castling (belatedly) justifies the e.p. capture.
Not 1... exd6ep 2.Kd8? dxe7 3.Kc8 e8=D,T
AB: Another 120 retro tries (=60x2 due to tolerated dual promotion) of general form 1. exd6ep 2. T~ dxc7 3. T~ c8=D,T.
No set play
Nachdruck in "Die Schwalbe" 33 mit Diagrammfehler (wBe6 fehlt).
VL: The first AP-problem! Thematic illegal try:
1. ... exd6ep 2.Kd8? dxe7+ 3.Kc8 e8=T(D)#?? (2007-02-11)
Mario Richter: 46 years between this Problem and P1366663 - perhaps this was not Keeble's first AP-Problem?! (2019-08-29)
Ladislav Packa: Of course I know the idea a posteriori. But let my heresy be forgiven - I do not consider it logical. In this particular example, I consider e.p. for proof that black can castling - not vice versa. (2019-08-29)
A.Buchanan: Hi Ladislav. If ep is ok, then Black just moved a pawn with double hop. That doesn't stop Black having e.g. moved bK right at the beginning of the game. So you can't prove that Black definitely can castle this way. What am I missing here? (2019-08-29)
Ladislav Packa: Your statement is perfectly fine. However, the AP condition is usually interpreted as castling is evidence of e.p. However, the second party does not have to do castling - the possibility has already been demonstrated by the existence of e.p. (2019-08-29)
A.Buchanan: Hi again Ladislav. Please try again, I am obviously being very stupid. I don't understand how 1. exd6ep is any more indicative that Black can castle than 1. K~. (2019-08-30)
Ladislav Packa: Hi, Andre!
e.p. is just a result of the d7-d5 move. Black can castle only if it was the last move of black (even without wPe5). Therefore, it does not have the logic of joining the e.p. with castling. For example, ask yourself if black is allowed to castle in the position without wPe5. (2019-08-30)
A.Buchanan: @Ladislav: ep is not "proof that black can castle", rather it is a *necessary* condition for Black to be able to castle. The logical implication is the other way round. We can castle because of the optimistic convention, and because sPd might just have moved. Without wPe, there is no solution, but whatever White plays, Black can castle (2020-12-11)
Hans-Jürgen Manthey: was heißt hier Thematisch Illegal ??
Mir völlig wurscht ob ep möglich oder nicht, nach dem weißen Zug ist natürlich Kd8 möglich !!
also ist auch 1. ... exd6ep 2. Kd8 dxe7+ 3. Kc8 e8DT# eine Lösung, sonst müßte auf die erzwungende Rochade in der Aufgabenstellung hingewiesen werden ! (2020-12-11)
A.Buchanan: Can one tolerate “tolerated dual promotion” in Valladao? Well Valladao himself did, so it must be ok (2022-03-26)
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comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (sg), Promotion (D/T), Tolerated dual promotion (D/T), Valladao Task, Retro Strategy (RS)
Genre: h#, Retro
Computer test: Popeye 4.61
FEN: r3k3/2p1p3/2P1P3/2KpP3/8/8/8/8
Reprints: V. Die Schwalbe 33, p. 323, 06/1975
2001 CHM Themes 12/2000
3 Die Schwalbe 215, p. 240, 10/2005
A1 Problemkiste 169 02/2007
402 Eigenartige Schachprobleme , p. 130, 2010
14 Die Schwalbe 241, p. 374, 02/2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-10 more...
10 - P0007827
Bernd Schwarzkopf
(23) feenschach 55, p. 124, 07/1981
P0007827
(11+6)
Welches war der erste Zug?
a) oben: des wUWTb8?
b) unten: der wDd1?
c) unten +wDd1: des wKe1?
a) 0 Züge
b) 0 Züge
c) 0 Züge
play all play one stop play next play all
Bernd Schwarzkopf: Nur Forderung a (b und c gehören zu einem anderen Problem);
Lösung: UW-Tb8 zog nie (2015-03-13)
Mario Richter: In fs55 sind die verschiedenen Stellungén in einem Diagramm zusammengefaßt. Ich sehe zwei Möglichkeiten, wie wir das in der PDB behandeln:
1. So wie aktuell eingegeben (nahe an der historischen Wahrheit, aber schlecht visuell wahrnehmbar - der Nutzer muß wissen, daß er auf die Lösungen zu b) bzw. c) klicken muß, um die entsprechenden Diagramme zu sehen).
2. Aufsplitten in zwei separate Aufgaben.
Was wird gewünscht/präferiert? (2015-03-14)
Henrik Juel: I prefer your second option, Mario (2015-03-14)
Thomas Brieden: Hätte ich obigen Text nicht gelesen, hätte ich auch nicht gewusst, dass man auf entsprechende Lösungen klicken muss. Ich bevorzuge daher auch den zweiten Vorschlag. (2015-03-14)
Alfred Pfeiffer: Diagramm (als Zeroposition) und Forderung so klarer? (2015-03-15)
Olaf Jenkner: So gefällt es mir. (2015-03-15)
A.Buchanan: In the zero diagram, one might also put in a line between ranks 4 & 5. This separator is used in PDB for grid chess etc, but could be helpful here. What do you think? (2020-11-11)
Olaf Jenkner: If I was asked, good idea.
Maybe there's an issue because the line doesn't vanish in a), b) and c) (2020-11-12)
comment
Keywords: First Move? (UT0 / D0 / K0), Type A, Economy record (First move)
Genre: Retro
FEN: KRb1k3/pp1p4/8/8/4k3/8/1PPPPPP1/2B1KB2
Reprints: 2.38 Eigenartige Schachprobleme , p. 200, 2010
2.8 Eigenartige Schachprobleme , p. 198, 2010
2.1 Eigenartige Schachprobleme , p. 198, 2010
Input: Gerd Wilts, 1996-09-03
Last update: A.Buchanan, 2020-12-01 more...
11 - P1080382
Werner Keym
13879 Die Schwalbe 233 10/2008
1. Preis
P1080382
(13+12)
#3
Henrik Juel: 1.0-0 thr. 2.Dxc6+,Td1 (2023-07-18)
A.Buchanan: I don't think it's as straightforward as this. Under PRA, there are 2 parts: a) wK & sD rights ok b) wD & sK ok. We tackle each separately. a) 1. 0-0? 0-0-0! 1. Td1! b) 1. 0-0-0? 0-0! 1. Tf1! The forward play is messy, and there are three promoted units, but the amazing paradox is that White wins by not castling. This is not a case of mutual exclusion. This is why it got first prize, I think. (2023-07-18)
Mu-Tsun Tsai: Yeah, on second thought I indeed got it the wrong way; it is in fact possible that Kq castling are both valid (I have the proof game in fact), and I take your word that the other side is also true. (2023-07-19)
A.Buchanan: For complete retro proof, need both retro logic & non-unique proof games. For the latter, maybe can show the legality of rn2k1nr/ppp1p1pp/4P2B/4p3/2P1Q3/2P5/PP2P1PP/R1b1KB1R. From here, can branch to the two ways of getting the two rook promotions: (a1+h8 vs h1+h8) (2023-07-19)
Henrik Juel: If Andrew's analysis holds, the keys are correct by Popeye 4.61
But there are duals in each part (2023-07-20)
more ...
comment
Keywords: Partial Retro Analysis (PRA), Castling
Genre: Retro, 3#
FEN: r3k2r/bRp1p1p1/1pn1P2B/rB2p3/n1P1Q3/2P1P3/1P4P1/R3K2R
Reprints: 172 Eigenartige Schachprobleme 2010
(8) Die Schwalbe 241 02/2010
A Die Schwalbe 283, p. 9, 02/2017
Input: Gerd Wilts, 2009-01-03
Last update: Mu-Tsun Tsai, 2023-07-19 more...
12 - P1384455
Werner Keym
Allgemeine Zeitung Mainz 1963
Dr. Ernst Bachl gewidmet
P1384455
(9+3) C+
#3
1. Ta8? b5xa4!
1. Lxb5+? Kxd8!
1. Sb6+? Kxe8!
1. Scd6? b5xa4!
1. Sed6? Kxd8!
1. a5xb6ep+! Kxd8 2. b7 g6 3. Td6#
1. ... Kxc8 2. Ta8+ Kb7 3. Lc6#
play all play one stop play next play all
Die letzten Züge waren b7-b5 Tc6xXa6+. Also ist der En-passant-Schlag erlaubt.
more ...
comment
Keywords: En passant as key
Genre: 3#, Retro
Computer test: Popeye 4.61
FEN: 2NBN3/3k2p1/R7/Pp1K2P1/B7/1P6/8/8
Reprints: 299 Eigenartige Schachprobleme , p. 97, 2010
288 Chess Problems Out of the Box , p. 87, 2018
Input: Alfred Pfeiffer, 2020-12-30
Last update: Alfred Pfeiffer, 2020-12-31 more...
13 - P1409983
Andrey Frolkin
Werner Keym

1.67 Eigenartige Schachprobleme , p. 196, 2010
P1409983
(10+2)
Letzter Zug?
R: 1. g3xBh4 h5-h4 and e.g. 2. Kf4-g5 Kh4-h3
play all play one stop play next play all
Compare P0000999 with more non-standard material
more ...
comment
Keywords: Economy record (Last Move? Type A), Last Move? (BxB), Non-standard material (L), Type A, Type B (a fortiori), Economy record (Last Move? Type B), Minimal
Genre: Retro
FEN: 8/1p5P/6PP/5BK1/6PP/5B1k/6NP/8
Input: A.Buchanan, 2023-05-28
Last update: A.Buchanan, 2023-05-31 more...
14 - P1409984
Theophilus Harding Willcocks
1.68 Eigenartige Schachprobleme , p. 196, 2010
P1409984
(3+9)
Letzter Zug?
R: 1. a7xTb8=L h7-h6 2. a6-a7 Ka7-a8 3. a5-a6 and e.g. 3. ... Ta8-b8 4. Tb8-c8
play all play one stop play next play all
Compare P0000957 with non-standard material.
more ...
comment
Keywords: Economy record (Last Move? Type A), Type A, Last Move? (BxT=L), Promotion (L)
Genre: Retro
FEN: kBRn4/1pKppp2/1pp4p/8/8/8/8/8
Input: A.Buchanan, 2023-05-28
Last update: A.Buchanan, 2023-05-31 more...
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The problems of this query have been registered by the following contributors:

Gerd Wilts (11)
Alfred Pfeiffer (1)
A.Buchanan (2)