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2 problem(s) found in 4265 milliseconds (displaying 2 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND S='Dubuque Chess Journal' AND A='Wheeler, Charles Henry'] [download as LaTeX]

1 - P1260207
Charles Henry Wheeler
892 Dubuque Chess Journal 05/1874
P1260207
(4+7)
s# in wieviel Zügen?
1) R: 1. ... 0-0-0, dann 1. Txg6#
2) R: 1. ... 0-0-0, dann 1. Df7#
play all play one stop play next play all
Weiß kann Selbstmatt ohne einen eigenen Zug erzwingen.
Schwarz rochierte im letzten Zug, obwohl er im Schachstand und ignorierte dabei auch das Schach auf d8. Beides ist illegal. Er muss diesen Zug zurücknehmen und statt dessen Df7# oder Txg6# spielen.
A.Buchanan: No retro analysis to show that last move was in fact castling. Position is not illegal. (2019-10-21)
James Malcom: Perhaps that's why it labeled as a joke then. Andrew. (2020-10-20)
A.Buchanan: Yes it’s a joke but there is an existing species of problem where the position Is illegal. This is kind of like Conan Doyle vs Agatha Christie: here we are only told the key clue after the fact. I am sadly interested in classifying the main families of jokes, identifying which ones are fairies as well etc. This one is not fairy I think. In constraint promotion into foreign units can be joke depending on stipulation, but is definitely fairy (2020-10-21)
comment
Keywords: Joke, Retract illegal move (castling)
Genre: s#, Retro
FEN: 2kr1b2/p3p3/4K1Br/B3R3/8/5q2/8/8
Input: Frank Müller, 2013-01-19
Last update: Alfred Pfeiffer, 2019-10-22 more...
2 - P1260210
Charles Henry Wheeler
953 Dubuque Chess Journal 08/1874
P1260210
(11+12)
#7 Duplex
b) s#7 Duplex
s) 1. ... Dxf8+ 2. Kd7 Dc8+ 3. Kd6 Tc6+ 4. Kd5 De6+ 5. Kd4 Dc4+ 6. Ke3 Te6+ 7. Le5 Txe5#
w) 1. Dc1+ Kf2 2. Dg1+ Kxf3 3. fxg7+ Ke4 4. Te8+ Se7 5. Txe7+ Kd5 6. Dg2,Dh1+ Te4 7. Dxe4#
s) 1. ... Dxf8+ 2. Kd7 Dc8+ 3. Kd6 Tc6+ 4. Kd5 De6+ 5. Kd4 Tc4+ 6. Kxd3 Df5+ 7. Ke3 c1=D+ 8. Dxc1#
w) 1. Dc1+ Kf2 2. Dg1+ Kxf3 3. Dg3+ Ke4 4. Df4+ Kd5 5. De5+ Kc6 6. De6+ Kb7 7. Dc8+ Txc8#
play all play one stop play next play all
Anton Baumann: NL in as) 1.d2 Lg3+ 2.Kf1 Da1+ 3.d1=D+ Dxd1+ 4.c(e)xd1=D+ Ld6 5.Db7 nebst 6.Tc8# (2021-01-11)
A.Buchanan: Is that the only one cooked, Anton? (2021-01-11)
Anton Baumann: aw) hat die oben erwähnten (im 19. Jahrhundert oft akzeptierten) Duale.
bw) ist C+ und bs) ist abgesehen vom Umwandlungsdual ebenfalls korrekt. (2021-01-12)
comment
Keywords: Stipulation change
Genre: n#, s#
FEN: 3K1Rn1/p5qb/5Pp1/Pp4Pp/1Pr5/Q1Pp1P1P/2p1p2B/4k3
Input: Frank Müller, 2013-01-19
Last update: Marcin Banaszek, 2021-01-13 more...
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Frank Müller (2)