5 problem(s) found in 2801 milliseconds (displaying 5 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND S='Problem Paradise' AND K='Umwandlung'] [download as LaTeX]
1 - P0009165
Michel Caillaud
PR17 Problem Paradise 12 01-03/1999
3. ehrende Erwähnung
(15+13) C+
BP in 22,5
Michel Caillaud
PR17 Problem Paradise 12 01-03/1999
3. ehrende Erwähnung
(15+13) C+
BP in 22,5
1. f4 Sc6 2. f5 Tb8 3. f6 exf6 4. a4 Lb4 5. a5 Lc3 6. dxc3 De7 7. Le3 De5 8. Lxa7 b6 9. a6 Tb7 10. Lb8 Sge7 11. a7 Tg8 12. a8=L Ta7 13. Lb7 Ta8 14. h4 Sa7 15. Le4 d5 16. Lxh7 g6 17. h5 Tg7 18. h6 Dh5 19. Lg8 Lf5 20. h7 Sec8 21. h8=D Th7 22. Dg7 Th8 23. Dh7
Rundlauf der sTT a8 und h8.
Rundlauf der sTT a8 und h8.
Keywords: Unique Proof Game, Pure Round Trip (tt), Promotion
Genre: Retro
Computer test: Stelvio 1.0
FEN: rBn1k1Br/n1p2p1Q/1p3pp1/3p1b1q/8/2P5/1PP1P1P1/RN1QKBNR
Input: Gerd Wilts, 1999-02-27
Last update: Silvio Baier, 2023-03-03 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: rBn1k1Br/n1p2p1Q/1p3pp1/3p1b1q/8/2P5/1PP1P1P1/RN1QKBNR
Input: Gerd Wilts, 1999-02-27
Last update: Silvio Baier, 2023-03-03 more...
1. d5 2. d4 3. d3 4. d2 5. d1=L 6. Lb3 7. Lxa2 8. Lc4 9. Lf1 10. Lg2 11. Lh1 12. fxg3ep fxg3#
Aber nach 11. Lh1 kann Weiß auch g2xLh3 zurücknehmen!
Cook: gxsLh3!
Aber nach 11. Lh1 kann Weiß auch g2xLh3 zurücknehmen!
Cook: gxsLh3!
Henrik Juel: 1.d5-d4-d3-d2-d1B-b3xa2-c4-f1 10.Bg2-h1 12.fxg3ep+?? fxg3# seems to fail, because after 11.Bh1 last move could be g2xh3. So what is the solution? (2003-04-28)
Thierry LE GLEUHER: After 11.Bh1, the last move can't be g2xh3 because of the promoted Bishop h1 imcompatible with the bP structure! (2005-09-25)
Henrik Juel: Why couldn't Black have a promoted bishop at this point in time (where wPa2 and bPd7 are no longer present)? 12 captures by black pawns seem to match the 12 missing white men. (2005-09-26)
Joost de Heer: Besides, after g2-g4, the black bishop must've been promoted too. (2005-09-30)
James Malcom: Henrik, gxh3 is indeed impossible. The last move sequence must go something like 1. Kfg8 Se2+ 2. Kh2 Sg1. There cannot be a knight on h3, cutting off g8, or a queen/rook, cutting off h2. Thus, gxh3 has already been played and g2-g4 is the last move. (2021-09-14)
Mario Richter: Position after 11. Lh1 is 8/5p2/8/5ppp/5pPk/5p1P/5P1K/6nb.
It can be easily shown, that in this position g2xLh3! is indeed a legal retraction.
So the ep-capture is not justified and the problem is cooked!
(Perhaps Thierry forgot, that black pawn d7 "disappeared"? But Joost's argument raises [correctly] the question, why a promoted Bishop on h1 is ok for g2-g4, but not for g2xLh3.) (2021-09-15)
Henrik Juel: So the good guys (Mario, Joost, and me) win over the bad ones (Thierry and James) by 3-2... (2021-09-15)
Henrik Juel: or, less insultingly:
By a majority of 3 to 2 this problem has been deemed cooked (2021-09-15)
James Malcom: Make it 4 to 1: 1. Nc3 Nf6 2. Nd5 Rg8 3. Nxf6+ exf6 4. d4 Ke7 5. Bg5 fxg5 6. Nf3 Kf6 7. Ne5 Bd6 8. Nc6 Bg3 9. hxg3 bxc6 10. Rh4 gxh4 11. b4 Ba6 12. a4 Bd3 13. b5 Bf5 14. b6 h3 15. bxa7 h2 16. a5 Bh3 17. g4 Re8 18. a6 Re5 19. dxe5+ Kg5 20. Qd6 Qe7 21. c4 Qe6 22. Ra3 Qd5 23. cxd5 cxd5 24. Rf3 Nc6 25. e4 Re8 26. a8=Q Nd4 27. a7 cxd6 28. Qxe8 dxe4 29. Qe6 dxe6 30. a8=Q exf3 31. Bd3 Kh4 32. Bf5 exf5 33. Qa5 g5 34. Qd5 h5 35. Qe4 dxe5 36. Qf4 exf4 37. Kf1 h1=B 38. Kg1 Ne2+ 39. Kh2 Ng1 40. gxh3 (2021-09-16)
A.Buchanan: Is it also possible that in the critical position, the last moves were R: 1.gxSh3 exXf345 2.X~? I think I can fix the cook R: 1.gxLh3 nicely. (2021-09-17)
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Thierry LE GLEUHER: After 11.Bh1, the last move can't be g2xh3 because of the promoted Bishop h1 imcompatible with the bP structure! (2005-09-25)
Henrik Juel: Why couldn't Black have a promoted bishop at this point in time (where wPa2 and bPd7 are no longer present)? 12 captures by black pawns seem to match the 12 missing white men. (2005-09-26)
Joost de Heer: Besides, after g2-g4, the black bishop must've been promoted too. (2005-09-30)
James Malcom: Henrik, gxh3 is indeed impossible. The last move sequence must go something like 1. Kfg8 Se2+ 2. Kh2 Sg1. There cannot be a knight on h3, cutting off g8, or a queen/rook, cutting off h2. Thus, gxh3 has already been played and g2-g4 is the last move. (2021-09-14)
Mario Richter: Position after 11. Lh1 is 8/5p2/8/5ppp/5pPk/5p1P/5P1K/6nb.
It can be easily shown, that in this position g2xLh3! is indeed a legal retraction.
So the ep-capture is not justified and the problem is cooked!
(Perhaps Thierry forgot, that black pawn d7 "disappeared"? But Joost's argument raises [correctly] the question, why a promoted Bishop on h1 is ok for g2-g4, but not for g2xLh3.) (2021-09-15)
Henrik Juel: So the good guys (Mario, Joost, and me) win over the bad ones (Thierry and James) by 3-2... (2021-09-15)
Henrik Juel: or, less insultingly:
By a majority of 3 to 2 this problem has been deemed cooked (2021-09-15)
James Malcom: Make it 4 to 1: 1. Nc3 Nf6 2. Nd5 Rg8 3. Nxf6+ exf6 4. d4 Ke7 5. Bg5 fxg5 6. Nf3 Kf6 7. Ne5 Bd6 8. Nc6 Bg3 9. hxg3 bxc6 10. Rh4 gxh4 11. b4 Ba6 12. a4 Bd3 13. b5 Bf5 14. b6 h3 15. bxa7 h2 16. a5 Bh3 17. g4 Re8 18. a6 Re5 19. dxe5+ Kg5 20. Qd6 Qe7 21. c4 Qe6 22. Ra3 Qd5 23. cxd5 cxd5 24. Rf3 Nc6 25. e4 Re8 26. a8=Q Nd4 27. a7 cxd6 28. Qxe8 dxe4 29. Qe6 dxe6 30. a8=Q exf3 31. Bd3 Kh4 32. Bf5 exf5 33. Qa5 g5 34. Qd5 h5 35. Qe4 dxe5 36. Qf4 exf4 37. Kf1 h1=B 38. Kg1 Ne2+ 39. Kh2 Ng1 40. gxh3 (2021-09-16)
A.Buchanan: Is it also possible that in the critical position, the last moves were R: 1.gxSh3 exXf345 2.X~? I think I can fix the cook R: 1.gxLh3 nicely. (2021-09-17)
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Keywords: Seriesmover, Consequent, Excelsior, Promotion (l)
Genre: Retro, Fairies
FEN: 8/3p1p2/8/5ppp/5pPk/5p1P/P4P1K/6n1
Input: Gerd Wilts, 2002-07-27
Last update: A.Buchanan, 2021-09-17 more...
Genre: Retro, Fairies
FEN: 8/3p1p2/8/5ppp/5pPk/5p1P/P4P1K/6n1
Input: Gerd Wilts, 2002-07-27
Last update: A.Buchanan, 2021-09-17 more...
3 - P1080625
Roberto Osorio
Jorge Joaquin Lois
R133 Problem Paradise 01-03/2006
(13+15) C+
BP in 19,5
Roberto Osorio
Jorge Joaquin Lois
R133 Problem Paradise 01-03/2006
(13+15) C+
BP in 19,5
1. d4 Sc6 2. Dd3 Tb8 3. Da6 bxa6 4. Sf3 Tb5 5. Sh4 Th5 6. Sf5 d5 7. Sh6 gxh6 8. g4 Lg7 9. g5 Le5 10. g6 Sf6 11. g7 Sd7 12. g8=S Sdb8 13. Sf6 exf6 14. dxe5 Se7 15. e6 Sg8 16. e7 Kd7 17. e8=D+ Kd6 18. Da4 Ld7 19. c3 Le8 20. Dd1
Keywords: Unique Proof Game, Interchange (ss), Pronkin Theme (D), Ceriani-Frolkin Theme (S), Promotion (SD)
Genre: Retro
Computer test: C+ Natch 3.1 No solution for 19.0 moves
FEN: 1n1qb1nr/p1p2p1p/p2k1p1p/3p3r/8/2P5/PP2PP1P/RNBQKB1R
Input: Gerd Wilts, 2009-01-17
Last update: A.Buchanan, 2021-02-20 more...
Genre: Retro
Computer test: C+ Natch 3.1 No solution for 19.0 moves
FEN: 1n1qb1nr/p1p2p1p/p2k1p1p/3p3r/8/2P5/PP2PP1P/RNBQKB1R
Input: Gerd Wilts, 2009-01-17
Last update: A.Buchanan, 2021-02-20 more...
1. f8=D Thxd8 2. exd8=D[+sTa1] Txd8 3. h8=T Txh8 4. a8=T Txa8 5. g8=S Txg8 6. b8=S Txb8 7. f8=L Txf8 8. c8=L Txc8=
Anton Baumann: es sollte heissen: 1.d8=D Thxd8 ...
aber unlösbar: Schlussstellung ist nicht patt: 9.Kxd1[+sSb1]
mögliche Korrektur: +sBc2 (2023-03-16)
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aber unlösbar: Schlussstellung ist nicht patt: 9.Kxd1[+sSb1]
mögliche Korrektur: +sBc2 (2023-03-16)
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Keywords: Allumwandlung, Promotion (konsekutiv DDTTSSLL), Maximummer, Circe (Spiegel-), Promotion (8-fach), konsekutive Umwandlungen 8
Genre: Fairies
FEN: r6r/PPPPPPPP/8/5p2/1p1pp3/6p1/p2K1k2/3n3n
Input: Erich Bartel, 2015-01-15
Last update: Erich Bartel, 2015-11-04 more...
Genre: Fairies
FEN: r6r/PPPPPPPP/8/5p2/1p1pp3/6p1/p2K1k2/3n3n
Input: Erich Bartel, 2015-01-15
Last update: Erich Bartel, 2015-11-04 more...
1. g2-g3 h7-h5 2. Lf1-g2 h5-h4 3. Lg2-c6 d7xc6 4. d2-d4 Lc8-e6 5. Dd1-d3 Dd8-d7 6. Dd3-b5 c6xb5 7. Lc1-f4 Sb8-c6 8. Ke1-d2 0-0-0 9. Kd2-e3 Dd7-e8 10. Sb1-d2 Td8-d5 11. Ta1-f1 Td5-h5 12. d4-d5 Kc8-b8 13. d5-d6 Le6-d5 14. d6-d7 e7-e5 15. d7-d8=L e5-e4 16. Ld8-f6 g7xf6 17. Lf4-d6 Lf8-h6 18. f2-f4 e4xf3ep+
Keywords: Unique Proof Game, Valladao Task, Castling, En passant, Promotion (L), Ceriani-Frolkin Theme (L)
Genre: Retro
Computer test: Euclide 1.01, no solution in 17.0
FEN: 1k2q1nr/ppp2p2/2nB1p1b/1p1b3r/7p/4KpP1/PPPNP2P/5RNR
Input: A.Buchanan, 2021-07-03
Last update: Alfred Pfeiffer, 2021-11-26 more...
Genre: Retro
Computer test: Euclide 1.01, no solution in 17.0
FEN: 1k2q1nr/ppp2p2/2nB1p1b/1p1b3r/7p/4KpP1/PPPNP2P/5RNR
Input: A.Buchanan, 2021-07-03
Last update: Alfred Pfeiffer, 2021-11-26 more...
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The problems of this query have been registered by the following contributors:
Gerd Wilts (3)Erich Bartel (1)
A.Buchanan (1)
Moldenhauer: Computerprüfung: C+ Stelvio 1.0 27:15:46 Stunden.
Keine Lösung: BP 21.5, BP 22.0. (2023-02-18)
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