Die Schwalbe

48 problem(s) found in 3828 milliseconds (displaying 48 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND S='The Problem']

1 - P0003417
John Frederick Keeble
2206 The Problemist FCS 16, p. 173, 02/1936
P0003417
(4+5) C+
h#3
Weiß zieht an
1. ... exd6ep 2. 0-0-0 dxe7+ 3. Tf8 exf8=T,D#
play all play one stop play next play all
H.Juel: If Black may castle, last move was not made by Ke8 or Ta8, but by Pd5, so it was d7-d5, and hence White may capture en passant. 1... exd6ep 2.0-0-0 dxe7 3.Tf8 exf8=DT# where the castling (belatedly) justifies the e.p. capture.
Not 1... exd6ep 2.Kd8? dxe7 3.Kc8 e8=DT
C+ by Popeye 4.61, except for the promotion mate dual, which was considered acceptable in the old days.
Nachdruck in "Die Schwalbe" 33 mit Diagrammfehler (wBe6 fehlt).
VL: The first AP-problem! Thematic illegal try:
1. ... exd6ep 2.Kd8? dxe7+ 3.Kc8 e8=T(D)#?? (2007-02-11)
Mario Richter: 46 years between this Problem and P1366663 - perhaps this was not Keeble's first AP-Problem?! (2019-08-29)
Ladislav Packa: Of course I know the idea a posteriori. But let my heresy be forgiven - I do not consider it logical. In this particular example, I consider e.p. for proof that black can castling - not vice versa. (2019-08-29)
A.Buchanan: Hi Ladislav. If ep is ok, then Black just moved a pawn with double hop. That doesn't stop Black having e.g. moved bK right at the beginning of the game. So you can't prove that Black definitely can castle this way. What am I missing here? (2019-08-29)
Ladislav Packa: Your statement is perfectly fine. However, the AP condition is usually interpreted as castling is evidence of e.p. However, the second party does not have to do castling - the possibility has already been demonstrated by the existence of e.p. (2019-08-29)
A.Buchanan: Hi again Ladislav. Please try again, I am obviously being very stupid. I don't understand how 1. exd6ep is any more indicative that Black can castle than 1. K~. (2019-08-30)
Ladislav Packa: Hi, Andre!
e.p. is just a result of the d7-d5 move. Black can castle only if it was the last move of black (even without wPe5). Therefore, it does not have the logic of joining the e.p. with castling. For example, ask yourself if black is allowed to castle in the position without wPe5. (2019-08-30)
A.Buchanan: Hi Ladislav, I still don't understand you. Heresies must be explained extraordinarily carefully :-)
Following the conventions:
(1) Black retains castling rights because we cannot prove that bK or bR ever moved.
(2) If e.p. is now played, then we still require the same castling convention, as bK or bR might have moved earlier in the game.
(3) So the actual execution of the e.p. does not prove anything new about castling.
(4) Hence it is incorrect to say "e.p. [is] proof that black can [castle]".
Which step do you disagree with?
Yes by the convention, Black could castle in the position without wPe5. What does that prove? (2020-10-03)
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comment
Keywords: a posteriori (AP), En passant as key, Castling (sg), Promotion (T), Valladao Task
Genre: h#, Retro
Computer test: Popeye 4.61
FEN: r3k3/2p1p3/2P1P3/2KpP3/8/8/8/8
Reprints: V. Die Schwalbe 33, p. 323, 06/1975
2001 CHM Themes 12/2000
3 Die Schwalbe 215, p. 240, 10/2005
A1 Problemkiste 169 02/2007
14 Die Schwalbe 241, p. 374, 02/2010
Input: Gerd Wilts, 1995-06-03
Last update: Alfred Pfeiffer, 2018-01-03 more...
2 - P0004141
Karl Fabel
1071 The Problemist 12/1933
P0004141
(8+1)
#1
1. ... ... 2. 0-0?
1. ... Kxg2 2. e5#
1. ... Kxf4 2. Df6#
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61 with analysis (2020-11-30)
comment
Keywords: Castling (wk), No legal last move for Black, Castling in the forward play, Fabel-Opus (82)
Genre: Retro
FEN: 8/8/2Q5/8/4PBN1/3P1k2/6R1/4K2R
Reprints: (IV) Problem 17-18 08/1952
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-11-30 more...
3 - P0570670
Colin Peter Sydenham
The Problemist 15/6 11/1995
4. Platz
P0570670
(6+6)
ser-h#4
Duplex
s) 1. La3 2. Sb5 3. Tc3 4. Kb4 Sd3#
w) 1. Tg5 2. Se6 3. Lf4 4. Kf6 Sd5#
play all play one stop play next play all
ANDROMEDA FAIRY CHESS MATCH GREAT BRITAIN v HUNGARY 1993-95
SECTION 1 (Serieshelpmates in 4-8 moves)
Anton Baumann: mit +sBh7 geht die Autorabsicht
Computerprüfung mit sBh7 C+ Gustav 4.1d (2020-11-17)
Mario Richter: Es fehlte ein wBg6! (2020-11-18)
Henrik Juel: Now C+ Popeye 4.61 (2020-11-18)
comment
Keywords: Series mover
Genre: Fairies
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/6K1/6Pn/p7/k4NR1/2n2r2/1bPB4/8
Input: Torsten Linss, 1999-04-07
Last update: Mario Richter, 2020-11-18 more...
4 - P0577226
Jonathan Levitt
B) The Problemist (2), p. 32, 03/1995
P0577226
(6+4) cooked
ser-h#30
1. Kb2 2. Kc3 3. Kd4 4. Kxe5 5. Kf6 6. e5 7. e4 8. e3 9. e2 10. e1=L 11. Lxh4 12. Lg5 13. Lxh6 14. Kg7 15. Kh8 16. Lg7 17. h5 18. h4 19. h3 20. h2 21. h1=L 22. Lxd5 23. Lg8 24. d5 25. d4 26. d3 27. d2 28. d1=T 29. Th1 30. Th7 Sg6#
play all play one stop play next play all
Erich Bartel: im Problemist ist hierzu vermerkt:
Jonathan's Artikel has already apeared, in translation,in the
March 1995 issue of Rochade-Europa, and these originals
should compete in the informal tourney of that magazine.
--------
Die Frage ist nun welches Magazin als Erstqueelle gelten soll. (2011-11-28)
Anton Baumann: NL: 1.d6 2.dxe5 .. 6.e1=D .. 8.Dg8 .. 13.e1=L 14.Lxh4 15.Lg5 16.Lxh6 .. 23.Kh8 24.Lg7 .. 29.h1=T 30.Th7 Sg6# (2020-11-21)
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comment
Keywords: Series mover, corner to corner (sKa1h8), Excelsior (3-fach), under-promotion, konsekutive Umwandlungen 3 (llt)
Genre: Fairies
FEN: 8/3pp2p/7P/1K1PP3/5N1P/8/8/k7
Reprints: Rochade Europa 03/1995
Input: Felber, Volker, 2000-01-06
Last update: Olaf Jenkner, 2020-11-23 more...
5 - P1017980
Lionel Sharples Penrose
London Observer 1921
1. Preis
P1017980
(9+9) C+
#2
1. ... Tg2 2.Lf3#
1. ... Lg2 2. Dxe3#
1. ... e2 2. Sd2#

1. Kh5! (Zugzwang)
1. ... Tg2 2. Df3#
1. ... Lg2 2. Dg4#
1. ... e2 2. Dxd3#
1. ... Txf1 2. Dg4#
1. ... Txg3 2. Sxg3#
1. ... Lf3+ 2. Dxf3#
1. ... d2 2. Lc2#
1. ... Kxf5 2. Df4#
play all play one stop play next play all
BS Problemid: 2813
Authors: Penrose, Lionel Sharples
Sources: The Problemist 2001
Het Belgisch Schaakbord (L'Echiquier Belge) 1947
Mate in Two Moves 1931
Simple Two-move Themes 1924
Years: 1920
more ...
comment
Keywords: Brian Stephenson Collection (2813)
Genre: 2#
Computer test: SCHRECKE: C+, popeye 4.85 (2020-11-17)
FEN: 8/2Np4/3P1p1B/3RpP2/4k1K1/3pp1Q1/5p2/3B1Nrb
Reprints: 32B Simple Two-move Themes 1924
Neues Wiener Tagblatt 16/07/1944
Het Belgisch Schaakbord 1947
The Problemist 2001
Input: Brian Stephenson, 2004-08-12
Last update: Erich Bartel, 2020-11-17 more...
6 - P1025292
C. G. Sathya Narayanan
The Problemist 1991
3. Preis
P1025292
(11+7)
#2
1. La1,Lc~? droht 2. Tc3#
1. ... Sd6 2. Dd4#
1. ... Dxb5 2. De5#, aber 1. ... De4!
1. Ld4!? droht 2. Tc3,Tc~#
1. ... Dxb5 2. De5#, aber 1. ... Sd6!
1. Le5!!? droht 2. Tc3#
1. ... Sd6 2. Sxe3#, aber 1. ... Dxb5!
1. Lf6! droht 2. Tc3#
1. ... De4 2. Db7#
1. ... Sd6 2. Txd6#
1. ... Dxb5 2. Df7#
play all play one stop play next play all
BS Problemid: 10170
Authors: Narayanan, Chithathuz Gopatan Sathya
Sources:
Years: 1991
SCHRECKE: C+, popeye 4.85 (2020-10-30)
comment
Keywords: Brian Stephenson Collection (10170), White correction, Changed mates, Batteriematt diagonal, discovered checkmate
Genre: 2#
FEN: r3q3/6Q1/1R5r/pPPk1nN1/2R2P2/1BB1p3/K1N5/8
Input: Brian Stephenson, 2004-08-12
Last update: Gunter Jordan, 2020-10-30 more...
7 - P1033263
Josef Retter
The Problemist 1985
2. Preis
P1033263
(9+7)
#2

BS Problemid: 18174
Authors: Retter, Yosef
Sources: FIDE Album (1983-1985) 1992
Years: 1985
SCHRECKE: C+, popeye 4.85
1.Ld1! (2.Lb3#)
1. ... D:f4+ 2.S:f4#
1. ... D:d3 2.Df5#
1. ... Db6 2.D:e4#
1. ... Dc5 2.De5#
1. ... Dd4 2.Df7# (2020-11-23)
comment
Keywords: Brian Stephenson Collection (18174)
Genre: 2#
FEN: 8/2p5/R1P4K/3k4/R3pQBp/B2Nq2N/3p4/6b1
Input: Brian Stephenson, 2004-08-12
Last update: Roland Ott, 2020-11-23 more...
8 - P1038125
Denis M. Saunders
Juan Kloostra

C7426 The Problemist 09/1987
P1038125
(13+6) C+
#4
1. Tf7! Tf4, T~ 2. La2+ Kxc2 3. Txf4, ~xT Kd3 4. 0-0-0#
1. ... Tg5 2. Lxg5 h4 3. Txf3 h3, exf3 4. Se2#, e4#
play all play one stop play next play all
BS Problemid: 23075
Authors: Saunders, Denis M
Kloostra, Juan
Sources: The Wizard of Oz 1999
Years: 1987
Im 'Problemist' ist der zweite Autor als "Jan Kloostra" angegeben
more ...
comment
Keywords: Brian Stephenson Collection (23075), Belen Theme
Genre: n#
Computer test: Gustav 4.1d, Brute Force
FEN: 8/7R/1P6/2P2r1p/N2Pp2B/2p1Pp2/2P2P2/RBk1K1N1
Input: Brian Stephenson, 2004-08-12
Last update: Mario Richter, 2020-09-23 more...
9 - P1059762
Aleksandr Kuzovkov
Shakhmaty v SSSR 1985
P1059762
(8+10)
#2

BS Problemid: 44831
Authors: Kuzovkov, Aleksandr
Sources: The Problemist 2002
FIDE Album (1983-1985) 1992
Years: 1985
SCHRECKE: C+, popeye 4.85
1.Sb4! (2.Dd5#)
1. ... L:e4 2.D:c5#
1. ... d:e6 2.Sc6#
1. ... Th5 2.S:c2#
1. ... Se5 2.D:e5#
1.. .. Sf4,Se7 2.De5# (2020-11-23)
comment
Keywords: Brian Stephenson Collection (44831)
Genre: 2#
FEN: 8/3p2p1/p2KP1n1/N1pN1Q2/2PkP3/b1p3R1/2b4r/8
Reprints: The Problemist 1985
Input: Brian Stephenson, 2004-08-12
Last update: Roland Ott, 2020-11-23 more...
10 - P1064675
C. G. Sathya Narayanan
The Problemist 1989
P1064675
(9+12)
#2
1. Sc2,Sd~? droht 2. Tc5#
1. ... Sxf2 2. Dh5#
1. ... e3 2. Df3#, aber 1. ... Dxc4!
1. Sf5!? droht 2. Tc5#
1. ... Dxc4 2. Sfe7#, aber 1. ... Sxf2!
1. Sf3!!? droht 2. Tc5#
1. ... Dxc4 2. Sge7#
1. ... Sxf2 2. Sxf4#, aber 1. ... e3!
1. Se2! droht 2. Tc5#
1. ... Dxc4 2. Sc3#
1. ... Sxf2 2. Sexf4#
1. ... e3 2. Dxd3#
play all play one stop play next play all
BS Problemid: 49766
Authors: Narayanan, Chithathuz Gopatan Sathya
Sources: Chess Wizardry: The New ABC of Chess Problems 1996
Years: 1989
Henrik Juel: Slightly damaged by the double threat 2.Tc5,Txb4# (2020-10-31)
comment
Keywords: Brian Stephenson Collection (49766), White correction
Genre: 2#
FEN: 4n3/3p4/R5Np/pP1k4/rqRNpp2/1B1p3n/5B1K/3Q1b2
Input: Brian Stephenson, 2004-08-12
Last update: Gunter Jordan, 2020-10-30 more...
11 - P1081611
Hans Peter Rehm
S1028v The Problemist 05/1985
1. Preis
P1081611
(6+8) cooked
s#8
1. Lc7? droht 2. Db5+ Sxb5#
1. ... d3 2. Le5 c2!

1. De7+! Kc6 2. Ld7+ Kd5 3. De6+ Kc5 4. Lc7 Sd2 5. De7+ Kd5 6. Le6+ Kc6 7. Dd7+ Kc5 8. Db5+ Sxb5#
play all play one stop play next play all
Original (ohne sBa7) mit NL in 6 Zügen.
Korrektur des Autors (+sBa7) in 11/1985, Seite 106.
Cook: NL 1. Lf6! droht 2. Db5+ Kd6 3. Dd5+ Kc7 4. Le5+ Kb6 5. Db7+ Kc5 6. Db5+ Sxb5#
1. ... Kb6? 2. Db7+ Kc5 3. Le5 ... 4. Db5+ Sxb5#
Rolf Wiehagen: Valery Kirillov points out that the problem can be corrected by wBd8--a5, C+. (2020-10-01)
Gerald Ettl: In meiner Datenbank steht als Verbesserung sBa7 nach g7. Allerdings weiss ich nicht, ob das C+ ist. (2020-10-02)
Rolf Wiehagen: Valery Kirillov points out that bPa7 to g7 is cooked, in 7 moves:
1.De7+ Kc6 2.Ld7+ Kd5 3.De6+ Kc5 4.Lc7 Sd2 5.Db6+ Kd5 6.Db7+ Kc5 7.Db5+ Sxb5# (2020-10-26)
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comment
Keywords: Interchange (DL)
Genre: s#
FEN: 3B4/p2Q4/P3B3/2k5/K2pp3/nPp5/8/rn6
Reprints: 595 FIDE Album 1983-1985 1992
Input: HBae, 2009-02-06
Last update: Marcin Banaszek, 2020-10-01 more...
12 - P1098397
Josef Kupper
S1876 The Problemist 07/2001
P1098397
(8+2) C+
s#5
1. Sf4 gxf4 2. Tc3 f3 3. Da4 Ke2 4. Dd1+ Kf2 5. Tg2+ fxg2#
1. Sf4 g4 2. Sh3+ gxh3 3. Da5 Ke2 4. Tf1 Kxf1 5. Tg2 hxg2#
play all play one stop play next play all
more ...
comment

Genre: s#
Computer test: A. Baumann: Gustav 4.1 d
FEN: 8/8/Q2P4/6p1/8/P5R1/4Nk1P/6RK
Input: Frank Müller, 2010-01-22
Last update: Olaf Jenkner, 2020-11-23 more...
13 - P1098417
Angel D. Zlatanov
S1896 The Problemist 11/2001
P1098417
(16+6) C+
s#7
1. e8=L! Se3 2. Db4+ Sc4 3. Lh6 gxh6 4. Lb7 h5 5. Kc8 h4 6. Td8 h3 7. Db6+ Sxb6#
1. ... Sc3 2. Dxf4+ Se4 3. Lh6 gxh6 4. Lf7 h5 5. Ke8 h4 6. Td8 h3 7. Df6+ Sxf6#
1. ... Sxf2 2. Se5+ Sd3 3. Lh6 gxh6 4. c7 h5 5. e3+ fxe3 6. Db4+ Sxb4 7. Sc6 Sxc6#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-11-13)
comment
Keywords: Echo-Manöver
Genre: s#
FEN: 2BK4/3RP1p1/2Pb2P1/R5B1/3k1p2/1P1N1P2/1pPQPP2/1N1n4
Input: Frank Müller, 2010-01-22
Last update: Marcin Banaszek, 2020-11-18 more...
14 - P1107377
Jorma Pitkänen
Aleksandr Chistyakov

S1930 The Problemist 09/2002
P1107377
(9+4) C+
s#6
1. Sb3 c5 2. Le6 c4 3. Sh3+ Ke4 4. Te3+ Sxe3 5. Df3+ Sxf3 6. d3+ cxd3#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-11-12)
comment

Genre: s#
FEN: 5Q2/2B5/2p5/2N1nnN1/2B2k2/6R1/3PKP2/8
Input: Frank Müller, 2010-06-07
Last update: Marcin Banaszek, 2020-11-12 more...
15 - P1133898
Karl Fabel
846 The Problemist 03/1933
1. ehrende Erwähnung
20. Thematurnier BCPS
P1133898
(4+2)
#3
1. Lc6! droht 2. Sf3+ Ke6 3. Ld5#
1. ... Ke6 2. Ld5+ Ke5 3. Sf3#
1. ... Le2 2. Ld5 ... 3. Sc4#,Sf3#
1. ... Lb7 2. Ld7 Le4 3. Sc4#
1. Ld7? Ld3!
play all play one stop play next play all
'The Problemist': " Clever bishop play, but most of the other pieces rather passive."

Block-Römer, Auswahl [he]. Da nur Ld7 und Lc6 mit der ungedeckten Satzflucht fertig werden, drängt sich dem Löser freilich eher eine Auswahl-Interpretation auf [EZ].
ROa-L
Sally: 1. ehr. Erw. im 20. Turnier der British Chess Problem Society 1933.
1.Lc6! Droht 2.Sf3# Ke6 3.Ld5#. - Ke6, 2. Ld5+ - Ke5,3.Sf3#.
1. - Le2, 2. Ld5 - L bel, 3. Sc4# bzw. Sf3#. 1. - Lb7, 2. Ld7 - Le4, 3. Sc4#. 1. - Ld7? Ld3!; nach der Vorolanlenkung (1. Lc6) Lb7 bewirkt die analoge Verteidigung des sL. (2. - Le4) einen block: ein L - Blockrömer mit reichhaltigem Ne-
benspiel (wobei nach 1. - Le2, der sL. durch2. Ld5 im eine Brennpunktstellung verbracht wird). Die im Verführungsspiel und der lösung bedeutsamen Feldera6/d3/e4/und b7 bilden die
Ecken eines "römischen Rechtecks", dass man in ähnlicher Form in vielen Römern wiederfindet. Nr. 122 Perlen der S.
Komposition ( Speckmann 1985) Nr. 60 K. Fabel Einführung in
das Prbl. Schach 1976). (2011-11-28)
Henrik Juel: Slightly damaged by mate dual after 1... Le2 (2020-11-30)
comment
Keywords: Miniature Collection (0047234), Fabel-Opus (54)
Genre: 3#
FEN: 4B3/5R2/b7/2K1k3/8/8/3N4/8
Reprints: 60 Einiges über Schachaufgaben [Fabel] 1950
60 Einführung in das Problemschach [Fabel] 1976
122 Perlen der Schachkomposition 1985
Input: Felber, Volker, 2010-09-11
Last update: Mario Richter, 2020-11-30 more...
16 - P1186125
Josef Kupper
S2212 The Problemist 03/2008
Lob
P1186125
(9+8) C+
s#12
1. Sd4? Tb1!
1. Ld4+ Kd5,d6 2. Lb2+ Kc5 3. Sd4 Kd5,d6 4. Sf5+ Kc5 5. Ld4+ Kd5 6. Lxg1+ Ke5 7. Ld4+ Kd5 8. Lf6+ Kc5 9. Sd4 Kd5,d6 10. Se2+ Kc5 11. Sc1 b2 12. Sb3+ Sxb3#
play all play one stop play next play all
Anton Baumann: C+ Gustav 4.1d (2020-11-17)
comment
Keywords: Beseitigung hinderlicher Kraft, Logik - Multiple Rückkehr
Genre: s#
FEN: 8/2p5/P1N1pB2/KBk5/P4pP1/1p3P2/2pR4/n5r1
Input: Frank Müller, 2011-01-29
Last update: Marcin Banaszek, 2020-11-18 more...
17 - P1190508
Jorma Pitkänen
The Problemist 01/2009
Neujahrsgruß
P1190508
(7+5) C+
s#7
1. Ta7 Kb5 2. Sd6+ Ka5 3. Se4 Kb5 4. Sc3+ Ka5 5. Tc4 Txa7 6. Tc5+ Ka6 7. Db7+ Txb7#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-20)
comment

Genre: s#
FEN: 1KN5/1RQ5/rnR1p3/k3P3/p7/P7/8/8
Input: Frank Müller, 2011-03-20
Last update: Marcin Banaszek, 2020-10-23 more...
18 - P1190536
Stephan Dietrich
S2288 The Problemist 11/2009
P1190536
(9+2) C+
s#8
1. Dg7 Kd6 2. Sb7+ Kc6 3. Lf7 Kd7 4. Lg8+ Kc6 5. Ta6+ Kb5 6. Tb6+ Ka4 7. Dd4+ Ka3 8. Ta6+ Sxa6#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-21)
comment
Keywords: Stalemate dissolution
Genre: s#
FEN: NKR5/P1n5/2k5/R1N5/2BQ4/8/P7/8
Input: Frank Müller, 2011-03-20
Last update: Marcin Banaszek, 2020-10-23 more...
19 - P1226261
Karl Fabel
1190 The Problemist FCS 02/1934
P1226261
(8+5)
#3
1. Ld3 Kc1 2. Se2+ Kb1 3. 0-0#
play all play one stop play next play all
"smallwares"

Rochade aus weißer Homebase [he]. < [EZ].
SCHRECKE: C+, popeye 4.85 (2020-11-30)
comment
Keywords: Castling (wk), Fabel-Opus (84), Homebase (w)
Genre: 3#
FEN: 8/8/8/8/8/8/pppP1PPP/bk2KBNR
Reprints: 23 Kurioses Schach 1975
Input: Mario Richter, 2011-12-03
Last update: Mario Richter, 2020-11-30 more...
20 - P1233639
Stephan Dietrich
S2298 The Problemist 01/2010
P1233639
(10+4) C+
s#8
1. Le4 fxe4 2. T4f3 exf3 3. Dh5 Kf8 4. e7+ Kg8 5. e8=L Kf8 6. Df5+ Kg8 7. Lg6 hxg6 8. Df7+ Kxf7#
play all play one stop play next play all
more ...
comment

Genre: s#
Computer test: M. Schreckenbach: Gustav 4.1 d
FEN: 3K2kr/2PP3p/4P2P/2QB1p2/5R2/4P3/5R2/8
Input: Frank Müller, 2012-03-04
Last update: Olaf Jenkner, 2020-11-23 more...
21 - P1233651
Stephan Dietrich
S2312 The Problemist 05/2010
P1233651
(9+2) C+
s#7
1. Ld8 Ke6 2. Sf8+ Kf7 3. c7 Ke8 4. Sd6+ Txd6 5. Sg6+ Kd7 6. Se5+ Kc8 7. La6+ Txa6#
play all play one stop play next play all
more ...
comment

Genre: s#
Computer test: Gustav 4.1d, Brute Force
FEN: K1N3R1/3N1k2/2P2B2/3r2R1/2BP4/8/8/8
Input: Frank Müller, 2012-03-04
Last update: James Malcom, 2020-10-01 more...
22 - P1238798
Stephan Dietrich
S2367 The Problemist 07/2011
P1238798
(9+2) C+
s#10
1. g4 Kf4 2. g5 Ke4 3. g6 Kf4 4. g7 Ke4 5. g8=L Kf4 6. Le5+ Ke4 7. Ld5+ Kf5 8. e4+ Kg6 9. Ldf7+ Kh6 10. Lg7+ Lxg7#
play all play one stop play next play all
SCHRECKE: C+, Gustav 4.1d, Brute Force
Umwandlungsläufer wLe6! (2020-10-29)
comment
Keywords: Excelsior
Genre: s#
FEN: 7K/8/4BB2/8/R2bk3/5N1P/4PPP1/8
Input: Frank Müller, 2012-05-11
Last update: Marcin Banaszek, 2020-10-29 more...
23 - P1252999
William Edmund Frank Fillery
S848 The Problemist 05/1982
P1252999
(10+4) C+
s#6
1. Tah5! a5 2. Tb5 h5 3. g4 hxg4 4. Tb1 g3 5. Thb4 axb4 6. Sab2 b3#
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SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-11-07)
comment

Genre: s#
FEN: k7/2Q5/p6p/R7/N6R/5rP1/2KP2B1/2BN4
Input: Frank Müller, 2012-11-04
Last update: Marcin Banaszek, 2020-11-07 more...
24 - P1262803
Mark Kirtley
S1065v The Problemist 01/1986
P1262803
(11+8) C+
s#4
Korrektur in 09/1986, Seite 205
1. Sde7 Lb1 2. Sxe3+ Kh4 3. S7f5+ Kg5 4. Sd5+ Sxd2#
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The note "Korrectur in 09/1986 seite 205" the author assumes means that a correction can be found there, but he has no record of what that correction is.
The author tested wBf3 to g4 and wPg2 to h3, same solution, Popeye+
Olaf Jenkner: The author was wrong with his correction attempts. Finally (2020) he added pawn h3. (2020-10-28)
comment
Keywords: Platzwechsel im Mattbild (SS)
Genre: s#
Computer test: O. Jenkner: Gustav 4.1 d
FEN: 8/8/1p5p/1PpNQNkP/2Kp4/1n1PrB1P/b2B2P1/8
Input: Frank Müller, 2013-02-18
Last update: Olaf Jenkner, 2020-10-28 more...
25 - P1267131
Camillo Gamnitzer
The Problemist 1994
4. Ehrende Erwähnung
P1267131
(10+11) C+
s#6
1. Lc5! droht 2. Se5+ Kxc5 3. Sd7+ Kc4 4. d3+ Txd3#
1. ... gxf6 2. Lf8 droht 3. Se5+ fxe5 4. d3+ Txd3#
2. ... f5 3. Lg7 fxe4 4. Dc7+ Sxc7 5. Tc6+ Kd5 6. Sb4+ Txb4#
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SCHRECKE: C+, Gustav 4.1d, Brute Force
1.Lc5! (2.Se5+ K:c5 3.Sd7+ Kc4 4.d3+ T:d3#) g:f6 2.Lf8 (3.Se5+ f:e5 4.d3+ T:d3#) f5 3.Lg7 f:e4 4.Dc7+ S:c7 5.Tc6+ Kd5 6.Sb4+ T:b4# (2020-11-07)
comment

Genre: s#
FEN: 8/5Qpr/1R1B1P2/1p1n3p/b1kpP3/Pr1N4/1pKP4/bB6
Input: Mario Richter, 2013-04-12
Last update: Marcin Banaszek, 2020-11-07 more...
26 - P1270832
Josef Kupper
S2143v The Problemist 11/2006
P1270832
(7+7)
s#8
Korrektur in 05/2007, Seite 117.
1. Dh3 Lb1 2. Dh8+ Td8 3. b7+ Kd7,c7+ 4. b8=T+ Kc6 5. Se5+ Kd6 6. Df6+ e6,exf6 7. Sc4+ Kc6 8. Tc8+ Txc8#
1. Dh3 b2 2. Dh8+ Td8 3. b7+ Kd7,c7+ 4. b8=T+ Kc6 5. Dc3+ Lc4 6. Se5+ Kd6 7. Sxc4+ Kc6 8. Tc8+ Txc8#
1. Dh3 e6,e5 2. Dh8+ Td8 3. b7+ Kd7,c7+ 4. b8=T+ Kc6 5. Se5+ Kd6 6. Df8+ Txf8 7. Sc4+ Kc6 8. Tc8+ Txc8#
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SCHRECKE: Nach 1. ... e5 gibt es einen Dual:
2.Td5 Lb1,~ 3.b7+ Kc7 4.b8D+ Kc6 5.Db7+ T:b7 6.De6+ Kc7 7.Dd6+ Kc8 8.Db8+ T:b8# (2020-10-11)
comment

Genre: s#
FEN: K1k5/R2rpN2/1P2Q1p1/R5N1/5p2/1p6/b7/8
Input: Frank Müller, 2013-05-25
Last update: Olaf Jenkner, 2013-05-25 more...
27 - P1282454
Stephan Dietrich
S2458 The Problemist 07/2013
P1282454
(11+2) C+
s#10
1. Da7 Dxf4 2. Tcd7+ Kc6 3. Tf6+ Dd6 4. Te6 Dxe6 5. d5+ Dxd5 6. Td8+ Dd7 7. Tc8+ Kd6 8. Dd4+ Ke7 9. g8=S+ Kf8 10. Dg7+ Dxg7#
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SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-23)
comment

Genre: s#
FEN: 4B2K/1QR2RP1/3k4/4qPP1/2PP1B2/8/8/8
Input: Frank Müller, 2014-01-21
Last update: Marcin Banaszek, 2020-10-23 more...
28 - P1282593
William Edward Lester
1223 The Problemist FCS 02/1934
P1282593
(2+6) C+
s#6
Längstzüger;
sDu= Grashüpfer;
1. g4! Gg3 2. g5 Gh2 3. g6 Ga2 4. g7 Gh8 5. g8=G Gb8 6. Gg2 Gh2#
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Wehrlos muss Schwarz dazuhelfen, dass sich Weiß durch seinen Exzelsior und die anschließende Rückkehr des Minimalexzelsiorbauern nach Umwandlung auf sein Startfeld das Selbstmatt gräbt
more ...
comment
Keywords: Maximummer, Excelsior, Promotion (Märchen-)
Pieces: du = Grasshopper (G)
Genre: Fairies
Computer test: SCHRECKE: C+, popeye 4.85 (2020-10-25)
FEN: 1*2qk2*2q*2q1/1p6/8/8/8/8/1*2q4P1/7K
Input: Erich Bartel, 2014-01-28
Last update: Erich Bartel, 2020-10-26 more...
29 - P1301071
Ljubomir Ugren
F3085 The Problemist 11/2013
P1301071
(9+12)
ser-h#35
1. Da2xb1 2. Db1-a2 3. Da2xa3 4. Da3-c5 5. Ta4-b4 6. Ta5-a2 7. Ka6-a5 8. Ka5-a4 9. Ka4-a3 10. Tb4-a4 11. Ta4-a6 12. Ka3-a4 13. Ka4-a5 14. Ta2-a4 15. Ta4-b4 16. Ka5-a4 17. Ka4-a3 18. Ka3-a2 19. Ka2-b1 20. Ta6-a2 21. a7-a5 22. a5-a4 23. a4-a3 24. Tb4-a4 25. Ta4-a8 26. Ta8-d8 27. Td8xd2 28. Kb1xc1 29. Kc1-d1 30. Kd1-e2 31. Ke2-f3 32. Kf3-g4 33. Kg4-h5 34. Kh5-h6 35. Dc5-h5 g7-g8=S#
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Henrik Juel: The position is illegal, as black pawns have captured nine times, but only seven white men are missing.
What is the intended solution? (2015-04-07)
Mario Richter: I do not know the intended solution, but the following line of play does the job:
1. Qa2xb1 2. Qb1-a2 3. Qa2xa3 4. Qa3-c5 5. Ra4-b4 6. Ra5-a2 7. Ka6-a5 8. Ka5-a4 9. Ka4-a3 10. Rb4-a4 11. Ra4-a6 12. Ka3-a4 13. Ka4-a5 14. Ra2-a4 15. Ra4-b4 16. Ka5-a4 17. Ka4-a3 18. Ka3-a2 19. Ka2-b1 20. Ra6-a2 21. Pa7-a5 22. Pa5-a4 23. Pa4-a3 24. Rb4-a4 25. Ra4-a8 26. Ra8-d8 27. Rd8xd2 28. Kb1xc1 29. Kc1-d1 30. Kd1-e2 31. Ke2-f3 32. Kf3-g4 33. Kg4-h5 34. Kh5-h6 35. Qc5-h5 Pg7-g8=N# (2015-04-08)
Henrik Juel: Thanks, Mario, for the nice solution, which certainly looks intended (2015-04-08)
Anton Baumann: C+ Alybadix (2020-12-01)
comment
Keywords: Series mover, Illegal position
Genre: Fairies
FEN: 5N2/pp4P1/kp3P2/rp6/r1p1N3/PpK5/qn1Q4/bBB5
Input: Frank Müller, 2015-04-07
Last update: Alfred Pfeiffer, 2015-04-09 more...
30 - P1338746
Stephen J. G. Taylor
H4062 The Problemist 26-4, p. 151, 07/2017
P1338746
(4+7) C+
h#5
2 solutions
Henrik Juel: C+ Popeye 4.61
1.Bg4-h3 Be4-g2 2.Kh5-g4 Bg2*h3 + 3.Kg4-f3 d2*e3 4.Sf4*d3 + Kc1-d2 5.Kf3-e4 Bh3-g2 #
1.Sf4-e6 d3-d4 2.Be3-g5 Be4-b1 3.f5-f4 d2-d3 4.Kh5-g6 d4*e5 5.Kg6-f5 d3-d4 # (2020-11-21)
comment

Genre: h#
FEN: 8/8/8/4rp1k/4Bnb1/1p1Pb3/3P4/2K5
Input: A.Buchanan, 2017-09-05
Last update: Olaf Jenkner, 2020-11-23 more...
31 - P1344147
Jasper van Atten
F644 The Problemist , p. 255, 07/1982
P1344147
(2+12) cooked
ser-h#10
wDU=Grashüpfer
1. Lf5 2. Te4 3. Ld4 4. Sc3 5. Kd5 6. Sc4 7. Ge5 8. Dc5 9. Td6 10. Le6 Gxd3#
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Cook: 1. d2 2. d1=T 3. e2 4. Sb4 5. Kd5 6. Tc4 7. T1d4 Gb3# (H. Juel)
t/zyklischer Platzwechse 9-fach,
Alfred Pfeiffer: Kein schwarzer G im Diagramm. Auch 10... Gc3 nicht ausführbar. (2017-12-08)
Erich Bartel: Vielen Dank für den Hinweis.Mein Eingavefehler.Habe korrigiert. (2017-12-08)
Marcin Banaszek: In der Rochade Europa 03/1999 s. 54 wird andere Fassung der Aufgabe gezeigt: wGh3 nach d1 +sBd2 (2020-11-26)
more ...
comment
Keywords: Series mover, Interchange (zyklisch), Skittles setup
Pieces: du = Grasshopper (G)
Genre: Fairies
FEN: 8/8/2pqr3/2*2qnn2K/2krb3/2bpp2*2Q/8/8
Input: Erich Bartel, 2017-12-08
Last update: Arnold Beine, 2017-12-09 more...
32 - P1356154
Mirko Degenkolbe
Steven B. Dowd

H3382v The Problemist 26-8, p. 318, 03/2018
P1356154
(11+9)
h#24
1. Kxb5 La2 2. Kc6 Lb1 3. Kc7 La2 4. Kd8 Lb1 5. Ke8 La2 6. Kf8 Lb1 7. Kg7 La2 8. Kh6 g5+ 9. Kh5 Lb1 10. Kg4 La2 11. Kf3 Lb1 12. Kxe4 La2 13. Kxe3 Lb1 14. Kd2 La2 15. Kc1 Lb1 16. Kb2 La2 17. Kxa1 Lb1 18. Kb2 La2 19. Kxc2 Lb1 20. Kxb3 Lxg6 21. Kc4 Lh7 22. Kd5 g6 23. Kxe6 g7 24. Kf7 g8=D#
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vergleiche P1110452

[MD 1315]

Autoren:
Verbesserung von Aufgabe H3382 „THE PROBLEMIST“ Juli 2010

Wir sehen in dieser Aufgabe folgenden Inhalt:
1) Erhalt weißer Masse (wBg4).
2) Beseitigung hinderlicher weißer Masse (wBe3 & wBe4)
3) Das Matt mit sKa4 ist nicht möglich, weil Weiß für das Mattbild einen Zug zu viel benötigen würde.

Des Weiteren enthält diese Aufgabe meines Erachtens, wie schon erwähnt, sage und schreibe DREI Weltrekorde.
Also:

Rekord Nummer eins:
Längster schwarzer Königsmarsch am Stück in einem orthodoxem Hilfsmatt = 24 Züge.

Rekord Nummer zwei:
Zuglängste Darstellung eines schwarzen Durbars in einem orthodoxem Hilfsmatt = 24 Züge.

Rekord Nummer drei:
Zuglängster Rundlauf des schwarzen Königs in einem orthodoxem Hilfsmatt = 21 Züge.

Die beiden ersten Rekorde befinden sich schon in der Originalversion, die 2010 veröffentlicht wurde. Der dritte Rekord (längster Rundlauf des schwarzen Königs im orthodoxen Hilfsmatt) ist nun auch noch hinzugekommen.

Wahrscheinlich ist diese Aufgabe auch schwer zu lösen, weil der Löser versucht, den Quadrupelbauern abzuräumen, damit sich Schwarz einen Springer erwandeln kann, vergebens …

Christopher J. A. Jones brachte die verbesserte Version als Einleitung der Hilfsmatt-Urdruck-Serie im März-Heft 2018, sehr ordentlich besprochen, in Englisch.
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-28)
comment
Keywords: Round Trip (maximal, 21 Züge), Durbar Theme (schwarz), Promotion in the mating move (D)
Genre: h#
FEN: 8/4p3/1p2P1p1/1P2P3/1pk1P1P1/1Pp1P1p1/2P3p1/NB4Kb
Input: Felber, Volker, 2018-10-10
Last update: Felber, Volker, 2020-10-28 more...
33 - P1358618
Jorma Pitkänen
11696 feenschach 227 11-12/2017
Version
P1358618
(9+5) C+
s#9
1. d8=S! g5 2. b5 g4 3. b7 Ka7 4. b8=T g3 5. Se6 fxe6 6. f7 e5 7. d5 e4 8. f8=D e3 9. Df2 exf2,gxf2#
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Version zu P1343954
Gunter Jordan: Lt. Hans Gruber erschien diese Aufgabe in feenschach 227 (2017), tatsächlich erschienen im März 2018. Somit ist feenschach die Erstquelle (sofern die Aufgabe nicht noch irgendwo drittveröffentlicht wurde). Ich habe hier die Erstquelle auf feenschach geändert. Die ursprüngliche 'Erstquelle' The Problemist habe ich als Reprint eingegeben. [GJ] (2020-10-30)
comment
Keywords: Kindergarten Problem, under-promotion (S,T), Promotion (D), under-promotion in the key (S), Multiple publication, Pawn mate, Antiphönix, Pinning, Flight taking
Genre: s#
Computer test: Gustav 4.0c
FEN: k7/2PP1p2/1P3Pp1/8/1P1P4/3p4/3Pp1P1/4K3
Reprints: S2678c The Problemist 26-9, p. 363, 05/2018
Input: Felber, Volker, 2018-12-11
Last update: Gunter Jordan, 2020-10-30 more...
34 - P1375751
Manfred Ernst
S2785 The Problemist 27-7, p. 272, 01/2020
P1375751
(9+5) C+
s#3
1. Dg7-h6!
1. ... Le1-a5 2. Sf6-d5+ Ke6-d7 3. Sd5-b6+ La5xb6#
1. ... Le1-b4 2. Sf6-e4+ Ke6-d7 3. Se4-c5+ Lb4xc5#
1. ... Le1-c3 2. Se7-c6+ Ke6-f5 3. Sc6-d4+ Lc3xd4#
1. ... Le1-d2 2. Se7-d5+ Ke6-f5 3. Sd5-e3+ Ld2xe3#
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Iwan Soroka: Siehe P1088945 von I.Soroka (2020-09-20)
comment

Genre: s#
Computer test: Popeye 4.83
FEN: 4R3/4N1Q1/3PkN2/4P2B/5P2/6p1/6p1/4b1Kb
Input: Marcin Banaszek, 2020-05-10
Last update: Felber, Volker, 2020-11-20 more...
35 - P1375822
Manfred Ernst
S2794 The Problemist 27-8, p. 308, 03/2020
P1375822
(7+5) C+
s#9
1. Ta6-c6! a5-a4 2. Lf3-h5 f4-f3 3. Lh6-c1 f3-f2 4. Dd5-f3+ Le5-f4 5. Df3-g4+ Kf5-e5 6. Lc1-b2+ Ke5-d5 7. Dg4-d7+ Lf4-d6 8. Tc6-c5 Kd5xc5 9. Dd7-b5+ Kc5xb5#
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more ...
comment

Genre: s#
Computer test: Gustav 4.1d, Brute Force
FEN: 5R2/5b2/R6B/p2Qbk2/5p2/K2P1B2/8/8
Input: Marcin Banaszek, 2020-05-11
Last update: Felber, Volker, 2020-11-23 more...
36 - P1375825
Marcin Banaszek
S2796 The Problemist 27-8, p. 308, 03/2020
P1375825
(11+3) C+
s#10
1. Le4!
1. ... e1=D 2. Tb3+ Ka4 3. Lc6+ Ka5 4. Dc7+ Kxa6 5. Db7+ Ka5 6. Tb5+ Ka4 7. Da7+ Da5 8. Dd4+ Db4 9. Tc5+ Ka3 10. Db2+ Dxb2#
1. ... e1=L 2. Tc4+ Lb4 3. Tc3+ Ka4 4. Td4! Ka5 5. Dc7+ Kxa6 6. Db7+ Ka5 7. Sb3+ Ka4 8. Lb1! Ka3 9. Sc5+ Lxc3+ 10. Db2+ Lxb2#
1. ... e1=S 2. Tb1+ Ka4 3. Dd7+ Ka5 4. Sb3+ Kxa6,Kb6 5. Dc6+ Ka7 6. Dc7+ Ka6 7. Td6+ Kb5 8. Sd4+ Ka4 9. Lc6+ Ka3 10. Sc2+ Sxc2#
1. ... e1=T 2. Tb3+ Ka4 3. Ta3+ Kb5 4. Db7+ Kc4 5. Td4+ Kxd4 6. Ta4+ Kc3 7. Db3+ Kd2 8. Td4+ Kxc1 9. De3+ Txe3 10. La3+ Txa3#
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Nebenuntervarianten nach 1. ... e1=L 2. Tc4+ Lb4 3. Tc3+ Ka4 4. Td4! Ka5 5. Dc7+
5. ... Kb5 6. Db7+ Ka4 7. Sb3 Ka3 8. Lb1 Lc5 9. Db4+ Lxb4 10. Sc5+ Lxc3#
6. ... Ka4 7. Sb3 Ka3 8. Lb1 Lc5,L~ 9. Db4+ Lxb4 10. Sc5+ Lxc3#
oder 7. Lb1 Ka5 8. Sb3+ Ka4 9. Dc6+,Dd7+ Ka3 10. Sc5+ Lxc3#
5. ... Ka4 6. Db7 Ka5 7. Sb3+ etc. =Hauptvariante, oder 6. Lb1 Kb5 7. Db7+ Ka4 8. Sb3 etc. =Hauptvariante oder
7. ... Ka5 8. Sb3+ Ka4 9. Dc6+,Dd7+ Ka3 10.Sc5+ Lxc3#
Nach 4. ... Kb5 5. Db7+ Ka4 6. Lb1 Ka5 7. Sb3+ Ka4 8. Dc6+ Ka3 9. Sc5+ Lxc3#

Erste schwarze Allumwandlung im Selbstmatt in zehn Zügen.
Weiße Batteriespiele (7), weiße Linienverstellungen (4), Mustermatts (3).
Zwischen Varianten 1...e1=D und 1...e1=L ein Spielwechsel nach dem Marsch und Rückkehr des schwarzen Königs (a3-a6-a3), dazu Verstellungswechsel auf c5 und Mattwechsel auf b2.
In der Variante 1...e1=S ein Marsch und Rückkehr des schwarzen Königs (a3-a7-a3) und Linienverstellungen auf d6 und c6.
In der Variante 1...e1T ein Marsch des schwarzen Königs von a3 zu anderem Oppositionsfeld c1 und vier weiße Figurenopfer. (Autor)
First black AUW in a S#10 (Composer).
Marcin also notes: “long bK marches in each variation, three times returning to a3 having visited a6 or a7, and, after 1…e1R, finishing at the echoed opposition square c1”.
Masterly problem! Bravo Marcin! (RL)
A top-level problem! (JP)
SCHRECKE: Nach 1. ... e1L 2.Tc4+ Lb4 3.Tc3+ Ka4 4.Td4 Ka5! 5.Dc7+ geht's aber unsauber zu.
Es existiert das völlig gleichwertige 5. ... Ka4, worauf 6.Db7 Ka5 7.Sb3+ Ka4 8.Lb1 Ka3 9.Sc5+ L:c3+ 10.Db2+ L:b2# geschieht.
Allerdings geht auch dualistisch:
6.Lb1 Kb5 7.Db7+ Ka4 8.Sb3 Ka3 9.Sc5+ L:c3+ 10.Db2+ L:b2#
7. ... Ka5 8.Sb3+ Ka4 9.Dc6+,Dd7+ Ka3 10.Sc5+ L:c3#
Nach 5. ... Kb5 6.Db7+ Ka4 geht auch der ZU-Dual 7.Lb1 Ka5 8.Sb3+ ...
Mir gefallen diese Niedlichkeiten aber nicht - Kodex hin, Kodex her !! (2020-09-20)
comment
Keywords: Allumwandlung, black (10)
Genre: s#
Computer test: O. Jenkner: Gustav 4.1 d
FEN: 3R1B2/7Q/P3p3/4P3/1R3P2/k7/2B1pP2/K1N5
Input: Marcin Banaszek, 2020-05-11
Last update: Felber, Volker, 2020-11-23 more...
37 - P1376593
Kurt Keller
C11834 The Problemist 27-9, p. 347, 05/2020
P1376593
(6+9)
#5
1. Sg3! droht 2. Kc1 ... 3. Le2#
1. ... Kxd2 2. Dxc4 droht 3. Dc1+
2. ... Ke3 3. De2+ Kf4 4. Sxe4 ... 5. Df3#
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Comments:
  • Author – Kurt Keller (Ulm, Germany)
  • Note on publication: C11834 shows a black ‘Lion’s cage’, to compare with the white cage in the last issue – can the en prise wQ be justified?
    (Jim Grevatt (Headly, England): CHAMPIONSHIP ORIGINALS. THREE- and MOREMOVERS, in: THE PROBLEMIST, MAY 2020)
  • Yet Another Chess Problem Database (507767)

Henrik Juel: C+ Popeye 4.61 (2020-11-26)
comment
Keywords: Skittles, Skittles setup (Lion's cage), Sacrifice key, Active sacrifice, Passive sacrifice, Sacrifice of white pieces, Flight giving key
Genre: n#
FEN: 8/8/2ppp3/2pQp2B/P1ppp3/3k4/3P4/1K3N2
Input: Kurt Keller, 2020-06-03
Last update: Felber, Volker, 2020-11-26 more...
38 - P1380192
Maxwell Bukofzer
80 The Problem 09/05/1914
P1380192
(5+2) C+
#3
1. De1! Kc5 2. Da5+ Kd4 3. Dc3#
2. ... Kd6 3. Sc4#
1. ... Ke5 2. Dh4 Kd6 3. De7#
1. ... Kc7 2. Db4 Kc8 3. Db7#
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schwarzer Bauer ergänzt
more ...
comment

Genre: 3#
Computer test: Henrik Juel: C+ Popeye 4.61 (2020-09-23)
FEN: 4K3/8/3k4/3B4/8/1p2N3/1P6/7Q
Input: Rainer Staudte, 2020-09-23
Last update: Erich Bartel, 2020-09-23 more...
39 - P1380195
Norbert Geissler
The Problemist Supplement 2018
after Andrew Buchanan
P1380195
(10+12)
h#3
1. ... e3 2. Da5 Df3 3. b6 Dxa8#
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The task here is to maximize the number of necessary units in a homebase h#.
Henrik Juel: 1... e3 2.Da5 Df3 3.b6 Dxa8#
White (not Black) has no last move, so he has the move, and the stipulation is really h#2.5 (2020-09-23)
A.Buchanan: Can shift sBd7 to c7 for an entirely different mate, but alas one of sBg7h7 might be removed without losing soundness. (2020-09-24)
comment
Keywords: Homebase (2), No legal last move for White
Genre: h#, Retro
FEN: r2qk1nr/pp1ppppp/8/8/8/8/1PPPPPP1/2BQKB2
Input: A.Buchanan, 2020-09-23
Last update: Alfred Pfeiffer, 2020-09-24 more...
40 - P1380264
Norbert Geissler
3 The Problemist Supplement 154, p. 646, 05/2018
P1380264
(3+7)
h#4
Wie viele Lösungen?
1. Sh6 f4 2. 0-0 f5 3. Kh8 f6 4. Tg8 Txh6# Only one solution!
play all play one stop play next play all
The possible second solution 1. Th7 0-0 2. Td7 Ta1 3. De7 Txa8 4. Kd8 Txb8#
is illegal as white castling is not allowed (last move of white was made by King or Rook)
Henrik Juel: C+ Popeye 4.61 (2020-09-25)
comment
Keywords: Homebase (2)
Genre: h#, Retro
FEN: rn1qk1nr/2p5/8/8/8/8/5P2/4K2R
Input: A.Buchanan, 2020-09-25
Last update: Alfred Pfeiffer, 2020-09-25 more...
41 - P1380878
Gilbert S. Dobbs
155 The Problem 27/06/2014
P1380878
(3+4) C+
#2
1. Df7! droht 2. De2#
1. ... f3,Lf3 2. De6#
1. ... d3,Ke5 2. Ddxf4#
1. ... Kf3 2. Dfxf4#
play all play one stop play next play all
Henrik Juel: Two white queens (2020-10-13)
more ...
comment
Keywords: Non-standard material, Flight giving and taking key
Genre: 2#
Computer test: Popeye 4.61
FEN: 8/K7/5Q2/8/3pkp2/8/3Q4/7b
Input: Rainer Staudte, 2020-10-13
Last update: Alfred Pfeiffer, 2020-10-14 more...
42 - P1380879
Gilbert S. Dobbs
154 The Problem 27/06/2014
dedicated to William E. Rudolph
P1380879
(3+3)
#3
1. De1!
play all play one stop play next play all
Henrik Juel: Ruined by duals after 1... Kd4,Kc2,f6 (2020-10-13)
comment
Keywords: Non-standard material
Genre: 3#
FEN: 4Q3/4Kp2/8/7n/7Q/3k4/8/8
Input: Rainer Staudte, 2020-10-13
Last update: Alfred Pfeiffer, 2020-10-14 more...
43 - P1381175
Bogusz Piliczewski
C11811 The Problemist 27-8, p. 303, 03/2020
P1381175
(4+3) C+
#2
1. Sb4? droht 2. T2d3#
1. ... Le4!
1. Se1? droht 2. T2d3#
1. ... Le4!
1. Sf4? droht 2. Se2#
1. ... Lf3!
1. Sc1? droht 2. Se2#
1. ... Lf3!
1. Sc5? droht 2. Sa4# A
1. ... Lc6! a
1. Se5? droht 2. T4d3# B
1. ... Le4! b
1. Sf2? droht 2. Sd1# C
1. ... Lf3! c

1. Sb2! droht 2. Sa4# A, 2. T4d3# B, 2. Sd1# C
1. ... Lc6 a 2. T4d3# B, 2. Sd1# C
1. ... Le4 b 2. Sd1# C, 2. Sa4# A
1. ... Lf3 c 2. Sa4# A, 2. T4d3# B
play all play one stop play next play all
Henrik Juel: C+ Popeye 4.61, I guess the triple threat and the duals are thematic (2020-10-20)
comment
Keywords: Knight's wheel, Fleck Theme, Hannelius Theme, Barnes theme, duel, White correction, Threat correction
Genre: 2#
Computer test: Popeye 4.61
FEN: b7/8/8/8/3R4/KpkN4/3R4/8
Input: Rainer Staudte, 2020-10-20
Last update: Felber, Volker, 2020-11-22 more...
44 - P1382152
Olivier Schmitt
C11810 The Problemist 27-7, p. 267, 01/2020
P1382152
(6+9) C+
#13
1. Lxd4? Lxd4 2. Sd2 b1=D!
1. Tb5+! Kc6 2. Tb8 Kc5 3. Ka5 Kc6 4. Tb6 Kc5 5. Txb2 Kc6 6. Tb6+ Kc5 7. Tb8 Kc6 8. Ka6 Kc5 9. Tb5+ Kc6 10. Tb6+ Kc5 11. Lxd4+ Lxd4 12. Sd2 ... 13. Sb3#
play all play one stop play next play all
more ...
comment
Keywords: Checking key, Switchback (KT, k), Logical Problem, Rücknahme Schlüsselzug
Genre: n#
Computer test: C+, Gustav 4.1d, Brute Force
FEN: 5n2/3p3r/KR1P4/2kpB3/3p3p/3PbN2/1p6/8
Input: Felber, Volker, 2020-11-19
Last update: A.Buchanan, 2020-11-21 more...
45 - P1382395
Petros Lambrinakos
PS3507 The Problemist Supplement 165, p. 63, 03/2020
P1382395
(4+7)
#4
1. Db2!
play all play one stop play next play all
Henrik Juel: Damaged by some mate duals (2020-11-25)
comment

Genre: n#
FEN: 8/2p4K/2p3N1/2p5/4kpp1/QN4p1/8/8
Input: Felber, Volker, 2020-11-25
Last update: Felber, Volker, 2020-11-25 more...
46 - P1382499
Valery Kirillov
S2805 The Problemist 27-9, p. 354, 05/2020
P1382499
(12+5) C+
s#9*
* 1. ... Kd3 2. De2+ Kxc3 3. Db2+ Kd3 4. Db1+ Kc3 5. Tc2+ Kd3 6. Dd1+ Ke4 7. Te2+ Te3 8. Kc4 Txe2 9. Dc2+ Txc2#
1. Ld4! Kd3 2. Td1+ Ke4 3. Lxg7 Ke3 4. Te1+ Kd3 5. Se5+ Kxc3 6. Dd2+ Kxb3 7. Dd5+ Kc3 8. Sd7+ Tf6 9. Sb6 axb6#
play all play one stop play next play all
SCHRECKE: C+ (auch Satz), Gustav 4.1d, Brute Force (2020-11-28)
comment

Genre: s#
FEN: 8/p5p1/P5N1/pPK5/P3k1P1/1NP2r2/R5Q1/5RB1
Input: Felber, Volker, 2020-11-26
Last update: Marcin Banaszek, 2020-11-30 more...
47 - P1382582
Christopher Max Bazett Tylor
PS3533 The Problemist Supplement 166, p. 79, 05/2020
P1382582
(3+1) C+
h#3
b) Mattposition a) wK<>sK
c) Mattposition b) wK<>sK
a) 1. Ka7 Tb5 2. Ka6 Tb6+ 3. Ka5 Sc4#
b) 1. Ka2 Kb5 2. Kb3 Kc5 3. Ka4 Tb4#
c) 1. Kc6 Sb6 2. Kb7 Sc8 3. Ka6 Tb6#
play all play one stop play next play all
Henrik Juel: Unusual twinning (2020-11-29)
comment
Keywords: Aristocrat
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/8/1k1N4/2R5/8/K7/8/8
Input: Felber, Volker, 2020-11-29
Last update: Felber, Volker, 2020-11-29 more...
48 - P1382584
Reinhardt Fiebig
PS3535 The Problemist Supplement 166, p. 79, 05/2020
P1382584
(2+7) C+
h#5
0.1.1...
1. ... Dh8 2. Ld8 Dxf8 3. Le7 Db8 4. Kg7 Db2+ 5. Kf8 Dh8#
play all play one stop play next play all
Henrik Juel: Roundtrip by Db2 (2020-11-29)
comment
Keywords: Minimal (D)
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 5n2/5p2/3n2k1/b1p4p/8/8/1Q6/K7
Input: Felber, Volker, 2020-11-29
Last update: Felber, Volker, 2020-11-29 more...
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The problems of this query have been registered by the following contributors:

Gerd Wilts (2)
Torsten Linss (1)
Felber, Volker (9)
Brian Stephenson (6)
HBae (1)
Frank Müller (14)
Mario Richter (2)
Erich Bartel (2)
A.Buchanan (3)
Marcin Banaszek (3)
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Rainer Staudte (4)