48 problem(s) found in 3724 milliseconds (displaying 48 problem(s)). [COMMENTDATE>=20200919 AND NOT K='Hilfsrückzüger' AND S='The Problem' AND K='Umwandlung'] [download as LaTeX]
1. b3 h5 2. La3 h4 3. Dc1 h3 4. Kd1 hxg2 5. h4 e5 6. h5 e4 7. h6 e3 8. h7 exf2 9. e4 f5 10. Se2 g1=L 11. Lg2 f1=L 12. e5 Lb6 13. d4 Lfc5 14. dxc5 f4 15. cxb6 f3 16. Df4 f2 17. Sc1 La6 18. Lc5 f1=L 19. a3 Lfb5 20. c4 Se7 21. cxb5 Tg8 22. hxg8=L g5 23. Lc4 d5 24. bxa6 Lf5 25. e6 Sc8 26. e7 Kf7 27. e8=L+ Kg8 28. Leb5 c6 29. Ta2 cxb5 30. Tc2 Sc6 31. Sa2 dxc4+
Keywords: Ceriani-Frolkin Theme (lllLL), Unique Proof Game, Promotion (lllLL)
Genre: Retro
Computer test: Computerprüfung: C+ Stelvio 1.11 65:30:51 Stunden. (hh:mm:ss) Keine Lösung: BP 30.0, BP 30.5.
FEN: r1nq2k1/pp6/PPn5/1pB2bp1/2p2Q2/PP6/N1R3B1/1N1K3R
Reprints: 580 Ukrainisches Album 1986-1990
26 Shortest Proof Games 11/1991
H25 FIDE Album 1986-1988 1995
(H25) Die Schwalbe 156, p. 237, 12/1995
feenschach 141 06/2001
Thema Danicum 105 2002
(C) Quartz 22 10-12/2002
H2 The Problemist 07/2010
(18) Die Schwalbe 250A 08/2011
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-08 more...
Genre: Retro
Computer test: Computerprüfung: C+ Stelvio 1.11 65:30:51 Stunden. (hh:mm:ss) Keine Lösung: BP 30.0, BP 30.5.
FEN: r1nq2k1/pp6/PPn5/1pB2bp1/2p2Q2/PP6/N1R3B1/1N1K3R
Reprints: 580 Ukrainisches Album 1986-1990
26 Shortest Proof Games 11/1991
H25 FIDE Album 1986-1988 1995
(H25) Die Schwalbe 156, p. 237, 12/1995
feenschach 141 06/2001
Thema Danicum 105 2002
(C) Quartz 22 10-12/2002
H2 The Problemist 07/2010
(18) Die Schwalbe 250A 08/2011
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-05-08 more...
1. dxe3ep 2. fxg1=L 3. 0-0 Tg4#
1. dxe3ep 2. Ke7? 3. Kd6 Sf5# doesn't pay AP debt
1. dxe3ep 2. Ke7? 3. Kd6 Sf5# doesn't pay AP debt
Henrik Juel: If Black may castle, his latest move must have been e3xf2, so last move was e2-e4. (Orig. wPg2 promoted on g8, so g7xh6 happened early). 1.dxe3 e.p. 2.fxg1=B 3.0-0 Tg4# (2003-03-21)
James Malcom: Is this the only know one-sided Valladao in a regular series-mover helpmate? Also, can wPh2 be shifted to h4, and the White king moved as well to h2, so that the solution must have 2. fxg1=S? (2020-12-08)
James Malcom: Well, the only known one that is in minimum form, i.e. 3 moves, I mean. (2020-12-08)
A.Buchanan: This is nice. I don't know of any other AP ser-h#3 with Valladao, but there could be. Just been cleansing PDB data today. Yes I think wKh3 and wBh2 can be transposed, and then promote to S instead of L. (2020-12-08)
A.Buchanan: The legality of intermediate positions in seriesmovers is of course irrelevant. However, each proof game that leads to the diagram position with BTM can be appended with a black move and then a "flip" that changes the player to move. We can repeat this process, and then the fact that Black retains castling rights implies that they had castling rights in the diagram position. I think this is the right formal way to handle AP with seriesmovers. (2022-03-21)
comment
James Malcom: Is this the only know one-sided Valladao in a regular series-mover helpmate? Also, can wPh2 be shifted to h4, and the White king moved as well to h2, so that the solution must have 2. fxg1=S? (2020-12-08)
James Malcom: Well, the only known one that is in minimum form, i.e. 3 moves, I mean. (2020-12-08)
A.Buchanan: This is nice. I don't know of any other AP ser-h#3 with Valladao, but there could be. Just been cleansing PDB data today. Yes I think wKh3 and wBh2 can be transposed, and then promote to S instead of L. (2020-12-08)
A.Buchanan: The legality of intermediate positions in seriesmovers is of course irrelevant. However, each proof game that leads to the diagram position with BTM can be appended with a black move and then a "flip" that changes the player to move. We can repeat this process, and then the fact that Black retains castling rights implies that they had castling rights in the diagram position. I think this is the right formal way to handle AP with seriesmovers. (2022-03-21)
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (sk), Seriesmover, Promotion, Valladao Task
Genre: Retro, Fairies
Computer test: C+ Popeye v4.85 + thinking
FEN: 4k2r/1pp2p1p/1N5p/3P4/2RpP2N/P2P1P1K/p1BP1p1P/B3b1R1
Reprints: Die Schwalbe 143 10/1993
Rex Multiplex 45-46 05/1994
(XII) Quartz 5 1997
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
Genre: Retro, Fairies
Computer test: C+ Popeye v4.85 + thinking
FEN: 4k2r/1pp2p1p/1N5p/3P4/2RpP2N/P2P1P1K/p1BP1p1P/B3b1R1
Reprints: Die Schwalbe 143 10/1993
Rex Multiplex 45-46 05/1994
(XII) Quartz 5 1997
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
3 - P0003417
John Frederick Keeble
2206 The Problemist Fairy Chess Supplement 16, p. 173, 02/1936
(4+5) C+
h#2.5 (AP)
John Frederick Keeble
2206 The Problemist Fairy Chess Supplement 16, p. 173, 02/1936
(4+5) C+
h#2.5 (AP)
1. ... exd6ep 2. 0-0-0 dxe7+ 3. Tf8 exf8=T,D#
H.Juel: If Black may castle, last move was not made by Ke8 or Ta8, but by Pd5, so it was d7-d5, and hence White may capture en passant. 1... exd6ep 2.0-0-0 dxe7 3.Tf8 exf8=D,T# where the castling (belatedly) justifies the e.p. capture.
Not 1... exd6ep 2.Kd8? dxe7 3.Kc8 e8=D,T
AB: Another 120 retro tries (=60x2 due to tolerated dual promotion) of general form 1. exd6ep 2. T~ dxc7 3. T~ c8=D,T.
No set play
H.Juel: If Black may castle, last move was not made by Ke8 or Ta8, but by Pd5, so it was d7-d5, and hence White may capture en passant. 1... exd6ep 2.0-0-0 dxe7 3.Tf8 exf8=D,T# where the castling (belatedly) justifies the e.p. capture.
Not 1... exd6ep 2.Kd8? dxe7 3.Kc8 e8=D,T
AB: Another 120 retro tries (=60x2 due to tolerated dual promotion) of general form 1. exd6ep 2. T~ dxc7 3. T~ c8=D,T.
No set play
Nachdruck in "Die Schwalbe" 33 mit Diagrammfehler (wBe6 fehlt).
VL: The first AP-problem! Thematic illegal try:
1. ... exd6ep 2.Kd8? dxe7+ 3.Kc8 e8=T(D)#?? (2007-02-11)
Mario Richter: 46 years between this Problem and P1366663 - perhaps this was not Keeble's first AP-Problem?! (2019-08-29)
Ladislav Packa: Of course I know the idea a posteriori. But let my heresy be forgiven - I do not consider it logical. In this particular example, I consider e.p. for proof that black can castling - not vice versa. (2019-08-29)
A.Buchanan: Hi Ladislav. If ep is ok, then Black just moved a pawn with double hop. That doesn't stop Black having e.g. moved bK right at the beginning of the game. So you can't prove that Black definitely can castle this way. What am I missing here? (2019-08-29)
Ladislav Packa: Your statement is perfectly fine. However, the AP condition is usually interpreted as castling is evidence of e.p. However, the second party does not have to do castling - the possibility has already been demonstrated by the existence of e.p. (2019-08-29)
A.Buchanan: Hi again Ladislav. Please try again, I am obviously being very stupid. I don't understand how 1. exd6ep is any more indicative that Black can castle than 1. K~. (2019-08-30)
Ladislav Packa: Hi, Andre!
e.p. is just a result of the d7-d5 move. Black can castle only if it was the last move of black (even without wPe5). Therefore, it does not have the logic of joining the e.p. with castling. For example, ask yourself if black is allowed to castle in the position without wPe5. (2019-08-30)
A.Buchanan: @Ladislav: ep is not "proof that black can castle", rather it is a *necessary* condition for Black to be able to castle. The logical implication is the other way round. We can castle because of the optimistic convention, and because sPd might just have moved. Without wPe, there is no solution, but whatever White plays, Black can castle (2020-12-11)
Hans-Jürgen Manthey: was heißt hier Thematisch Illegal ??
Mir völlig wurscht ob ep möglich oder nicht, nach dem weißen Zug ist natürlich Kd8 möglich !!
also ist auch 1. ... exd6ep 2. Kd8 dxe7+ 3. Kc8 e8DT# eine Lösung, sonst müßte auf die erzwungende Rochade in der Aufgabenstellung hingewiesen werden ! (2020-12-11)
A.Buchanan: Can one tolerate “tolerated dual promotion” in Valladao? Well Valladao himself did, so it must be ok (2022-03-26)
more ...
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VL: The first AP-problem! Thematic illegal try:
1. ... exd6ep 2.Kd8? dxe7+ 3.Kc8 e8=T(D)#?? (2007-02-11)
Mario Richter: 46 years between this Problem and P1366663 - perhaps this was not Keeble's first AP-Problem?! (2019-08-29)
Ladislav Packa: Of course I know the idea a posteriori. But let my heresy be forgiven - I do not consider it logical. In this particular example, I consider e.p. for proof that black can castling - not vice versa. (2019-08-29)
A.Buchanan: Hi Ladislav. If ep is ok, then Black just moved a pawn with double hop. That doesn't stop Black having e.g. moved bK right at the beginning of the game. So you can't prove that Black definitely can castle this way. What am I missing here? (2019-08-29)
Ladislav Packa: Your statement is perfectly fine. However, the AP condition is usually interpreted as castling is evidence of e.p. However, the second party does not have to do castling - the possibility has already been demonstrated by the existence of e.p. (2019-08-29)
A.Buchanan: Hi again Ladislav. Please try again, I am obviously being very stupid. I don't understand how 1. exd6ep is any more indicative that Black can castle than 1. K~. (2019-08-30)
Ladislav Packa: Hi, Andre!
e.p. is just a result of the d7-d5 move. Black can castle only if it was the last move of black (even without wPe5). Therefore, it does not have the logic of joining the e.p. with castling. For example, ask yourself if black is allowed to castle in the position without wPe5. (2019-08-30)
A.Buchanan: @Ladislav: ep is not "proof that black can castle", rather it is a *necessary* condition for Black to be able to castle. The logical implication is the other way round. We can castle because of the optimistic convention, and because sPd might just have moved. Without wPe, there is no solution, but whatever White plays, Black can castle (2020-12-11)
Hans-Jürgen Manthey: was heißt hier Thematisch Illegal ??
Mir völlig wurscht ob ep möglich oder nicht, nach dem weißen Zug ist natürlich Kd8 möglich !!
also ist auch 1. ... exd6ep 2. Kd8 dxe7+ 3. Kc8 e8DT# eine Lösung, sonst müßte auf die erzwungende Rochade in der Aufgabenstellung hingewiesen werden ! (2020-12-11)
A.Buchanan: Can one tolerate “tolerated dual promotion” in Valladao? Well Valladao himself did, so it must be ok (2022-03-26)
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (sg), Promotion (D/T), Tolerated dual promotion (D/T), Valladao Task, Retro Strategy (RS)
Genre: h#, Retro
Computer test: Popeye 4.61
FEN: r3k3/2p1p3/2P1P3/2KpP3/8/8/8/8
Reprints: V. Die Schwalbe 33, p. 323, 06/1975
2001 CHM Themes 12/2000
3 Die Schwalbe 215, p. 240, 10/2005
A1 Problemkiste 169 02/2007
402 Eigenartige Schachprobleme , p. 130, 2010
14 Die Schwalbe 241, p. 374, 02/2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-10 more...
Genre: h#, Retro
Computer test: Popeye 4.61
FEN: r3k3/2p1p3/2P1P3/2KpP3/8/8/8/8
Reprints: V. Die Schwalbe 33, p. 323, 06/1975
2001 CHM Themes 12/2000
3 Die Schwalbe 215, p. 240, 10/2005
A1 Problemkiste 169 02/2007
402 Eigenartige Schachprobleme , p. 130, 2010
14 Die Schwalbe 241, p. 374, 02/2010
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-06-10 more...
1. La7 Kxa7 2. c8=T Ka6 3. Ta8#
Max J. Meyer in 'Brighton and Hove Society', 1904: "It will be seen that the ideas of these two problems [dieses und P1143870] are the same. The addition of the White B. enables Mr. Mackenzie to get a much better key for this position, a point in which Steinweg's problem does not excel; but, of course, the use of an extra piece renders the miniature less remarkable from the point of view of smallness in size."
Paulo Roque: .
Solution:
1) 1. La7 KxLa7 2. c8=T! Ka6 3. Ta8#
2) Proof da legality of the answer:
Retro: 0... Ka7-a8 -1. b7-b8=L etc (2009-09-06)
Sally: Der letzte weiße Zug von Weiß kann nur Ba7xb8L gewesen sein, demgemäß enthält die Aufgabe 2 Bauernumwandlungen
in verschiedenen Figuren: in der lösung in einem turm und retrospektiv in einen Läufer.
406 Mattaufgaben mit 3 und 4 Steinen (Teil 1) Speckmann 1976 (2016-08-30)
Henrik Juel: There is even a third promotion in the threat 2.c8=D+
C+ by Popeye 4.61 (2016-08-30)
A.Buchanan: Here the threat play (1) is sound & (2) can never occur as Black has no neutral move. But if threat play is *unsound* yet can never occur, can it be safely ignored or will some directmate purists regard that as a defect? (2022-04-02)
Henrik Juel: I think not, Andrew
When I test problems, I ignore plays that do not occur (2022-04-02)
comment
Paulo Roque: .
Solution:
1) 1. La7 KxLa7 2. c8=T! Ka6 3. Ta8#
2) Proof da legality of the answer:
Retro: 0... Ka7-a8 -1. b7-b8=L etc (2009-09-06)
Sally: Der letzte weiße Zug von Weiß kann nur Ba7xb8L gewesen sein, demgemäß enthält die Aufgabe 2 Bauernumwandlungen
in verschiedenen Figuren: in der lösung in einem turm und retrospektiv in einen Läufer.
406 Mattaufgaben mit 3 und 4 Steinen (Teil 1) Speckmann 1976 (2016-08-30)
Henrik Juel: There is even a third promotion in the threat 2.c8=D+
C+ by Popeye 4.61 (2016-08-30)
A.Buchanan: Here the threat play (1) is sound & (2) can never occur as Black has no neutral move. But if threat play is *unsound* yet can never occur, can it be safely ignored or will some directmate purists regard that as a defect? (2022-04-02)
Henrik Juel: I think not, Andrew
When I test problems, I ignore plays that do not occur (2022-04-02)
comment
Keywords: under-promotion (T), Stalemate avoidance, Promotion in the retro play (L)
Genre: 3#, Retro
Computer test: Popeye 4.61
FEN: kB6/2P5/2K5/8/8/8/8/8
Reprints: 64 Chess Lyrics , p. 100, 1905
1359 Wiener Hausfrauen-Zeitung 5, p. 77, 29/01/1905
5 Vliegend Blaadje 22/07/1911
Szachy 01/1958
The Problemist (20) 03/1969
406 Mattaufgaben mit drei und vier Steinen 1976
diagrammes 64 01-02/1984
(1) diagrammes 15 07-09/1994
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-02-26 more...
Genre: 3#, Retro
Computer test: Popeye 4.61
FEN: kB6/2P5/2K5/8/8/8/8/8
Reprints: 64 Chess Lyrics , p. 100, 1905
1359 Wiener Hausfrauen-Zeitung 5, p. 77, 29/01/1905
5 Vliegend Blaadje 22/07/1911
Szachy 01/1958
The Problemist (20) 03/1969
406 Mattaufgaben mit drei und vier Steinen 1976
diagrammes 64 01-02/1984
(1) diagrammes 15 07-09/1994
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2020-02-26 more...
1. h4 g5 2. hxg5 a5 3. b4 axb4 4. Th4 Ta3 5. Sf3 Te3 6. a4 Sf6 7. gxf6 e5 8. Tc4 h5 9. a5 h4 10. a6 h3 11. a7 h2 12. a8=L h1=L 13. Ta6 Th6 14. dxe3 Le7 15. Te6 fxe6 16. La3 b3 17. Lc5 Sc6 18. Sd4 exd4 19. Sc3 dxc3 20. g4 Se5 21. Lg2 b6 22. Lac6 dxc6 23. fxe7 Dd3 24. Ld5 exd5 25. cxd3 Lf5 26. gxf5 Te6 27. fxe6 Le4 28. dxe4 bxc5 29. f4 dxc4 30. Dc2 bxc2 31. fxe5
Juha Saukkola:: Solution not unique! (2000-09-29)
Moldenhauer: Computerprüfung: C+ NUPG Stelvio 1.11 00:02:12 Minuten. (hh:mm:ss)
Keine Lösung: BP 29.5, BP 30.0. (2023-04-24)
Moldenhauer: Beispiel Stelvio 1.11: 1.Sc3 Sc6 2.b3 Sf6 3.La3 a5 4.g4 a4 5.Lg2 Ta5 6.h4 Tf5
7.Lc5 axb3 8.Ld5 b6 9.a4 bxc5 10.gxf5 g5 11.hxg5 e5 12.Th4 h5 13.Tc4 h4
14.a5 h3 15.a6 h2 16.a7 h1D 17.Ta6 De4 18.Sf3 Le7 19.Sd4 exd4 20.a8D Se5
21.Te6 dxc3 22.Dc6 dxc6 23.d4 fxe6 24.dxe5 exd5 25.gxf6 Le6
26.fxe6 dxc4 27.fxe7 Ddd3 28.cxd3 Th3 29.Dc2 Te3 30.dxe4 bxc2 31.fxe3 (2023-04-24)
comment
Moldenhauer: Computerprüfung: C+ NUPG Stelvio 1.11 00:02:12 Minuten. (hh:mm:ss)
Keine Lösung: BP 29.5, BP 30.0. (2023-04-24)
Moldenhauer: Beispiel Stelvio 1.11: 1.Sc3 Sc6 2.b3 Sf6 3.La3 a5 4.g4 a4 5.Lg2 Ta5 6.h4 Tf5
7.Lc5 axb3 8.Ld5 b6 9.a4 bxc5 10.gxf5 g5 11.hxg5 e5 12.Th4 h5 13.Tc4 h4
14.a5 h3 15.a6 h2 16.a7 h1D 17.Ta6 De4 18.Sf3 Le7 19.Sd4 exd4 20.a8D Se5
21.Te6 dxc3 22.Dc6 dxc6 23.d4 fxe6 24.dxe5 exd5 25.gxf6 Le6
26.fxe6 dxc4 27.fxe7 Ddd3 28.cxd3 Th3 29.Dc2 Te3 30.dxe4 bxc2 31.fxe3 (2023-04-24)
comment
Keywords: Non-Unique Proof Game, Promotion
Genre: Retro
FEN: 4k3/2p1P3/2p1P3/2p1P3/2p1P3/2p1P3/2p1P3/4K3
Reprints: The Problemist 11/1993
Input: Gerd Wilts, 1995-06-26
Last update: A.Buchanan, 2012-04-10 more...
Genre: Retro
FEN: 4k3/2p1P3/2p1P3/2p1P3/2p1P3/2p1P3/2p1P3/4K3
Reprints: The Problemist 11/1993
Input: Gerd Wilts, 1995-06-26
Last update: A.Buchanan, 2012-04-10 more...
1. Kb7 Lh3 2. Kc6 Lg4 3. Kd5 Lh3 4. Kc4 d3+ 5. Kxd3 Lg4 6. Kc3 Lh3 7. d3 Lg4 8. d2 Lh3 9. d1=L Lg4 10. Lb3 Lh3 11. Le6 fxe6 12. Kxb4 e7 13. Ka5 e8=D 14. Ka6 Da8#
Keywords: Pure Round Trip (k), Promotion
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/kp3p1p/1p3P1P/1P1p1pB1/5Pp1/3P2Pp/7K
Input: hpr, 1996-09-23
Last update: hpr, 1999-06-13 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/kp3p1p/1p3P1P/1P1p1pB1/5Pp1/3P2Pp/7K
Input: hpr, 1996-09-23
Last update: hpr, 1999-06-13 more...
s) * 1. ... b8=S 2. f6 Sc6#
1. Td4 b8=D 2. Kd5 Db5#
w) * 1. ... ... Lc8 2. b8=T Ta5#
1. ... b8=L Tb5 2. La7 Ld5#
1. Td4 b8=D 2. Kd5 Db5#
w) * 1. ... ... Lc8 2. b8=T Ta5#
1. ... b8=L Tb5 2. La7 Ld5#
Allumwandlung!weiße, Kegel!motiv
t/Allumwandlung, t/Minimal-B,, u/61105, u/TL-SD
Allumwandlung!eines Bauern
paul: In 1944, Bo was 17 years old. (2022-07-04)
more ...
comment
t/Allumwandlung, t/Minimal-B,, u/61105, u/TL-SD
Allumwandlung!eines Bauern
paul: In 1944, Bo was 17 years old. (2022-07-04)
more ...
comment
Keywords: Allumwandlung, Promotion
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: K7/1P3p2/3pb3/3rkp2/4pp2/8/8/8
Reprints: 1983 100 Classics of the Chessboard
4 varianter med 1 bonde 1972
143 FIDE Album 1914-1944/III 1975
The Problemist , p. 71, 10-12/1976
The Problemist , p. 171, 09/1981
(20) idee & form 47, p. 1293, 07/1995
Mat Plus 06-07/1995
080 Kegelschach [Ebert u. Wolfenter] 1997
305 Minimalkunst im Schach 2006
Input: Hans-Jürgen Schäfer, 1999-02-22
Last update: Alfred Pfeiffer, 2016-02-12 more...
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: K7/1P3p2/3pb3/3rkp2/4pp2/8/8/8
Reprints: 1983 100 Classics of the Chessboard
4 varianter med 1 bonde 1972
143 FIDE Album 1914-1944/III 1975
The Problemist , p. 71, 10-12/1976
The Problemist , p. 171, 09/1981
(20) idee & form 47, p. 1293, 07/1995
Mat Plus 06-07/1995
080 Kegelschach [Ebert u. Wolfenter] 1997
305 Minimalkunst im Schach 2006
Input: Hans-Jürgen Schäfer, 1999-02-22
Last update: Alfred Pfeiffer, 2016-02-12 more...
1) 1. gxh4 a8=L 2. h3 Lxg2 3. Dxg2 f8=D 4. Dg7 Dh8 5. Dxb2 Dxb2#
2) 1. gxf4 f8=D 2. f3 Db4 3. f2 Dxb3 4. Kxb3 a8=L 5. Ka2 Ld5#
2) 1. gxf4 f8=D 2. f3 Db4 3. f2 Dxb3 4. Kxb3 a8=L 5. Ka2 Ld5#
Anton Baumann: C+ Gustav 4.1d (2020-06-09)
Teppo Mänttä: reprint: Tehtäväniekka n:o 3, page 142, 14/09/2016. Published in Kari Valtonen's article about Hungarian themes and composers. (2021-04-28)
comment
Teppo Mänttä: reprint: Tehtäväniekka n:o 3, page 142, 14/09/2016. Published in Kari Valtonen's article about Hungarian themes and composers. (2021-04-28)
comment
Keywords: Capture key, Promotion (D), under-promotion (L), konsekutive Umwandlungen 2 (LD, DL), Square vacation, Opferbahnung (in 1), Model mate (in 2)
Genre: h#
FEN: 8/P4P2/4P3/1P4p1/5P1P/1p1p4/kPp3pp/rnK2nrq
Reprints: 5) idee & form 154, p. 5223, 04/2022
Input: hpr, 2002-03-02
Last update: Gunter Jordan, 2023-01-23 more...
Genre: h#
FEN: 8/P4P2/4P3/1P4p1/5P1P/1p1p4/kPp3pp/rnK2nrq
Reprints: 5) idee & form 154, p. 5223, 04/2022
Input: hpr, 2002-03-02
Last update: Gunter Jordan, 2023-01-23 more...
9 - P1012460
Andrey Frolkin
Sergey A. Komarov
The Problemist 1/1990
2. ehrende Erwähnung
(11+7)
shc#7
Vertikaler Zylinder
Andrey Frolkin
Sergey A. Komarov
The Problemist 1/1990
2. ehrende Erwähnung
(11+7)
shc#7
Vertikaler Zylinder
1. a5 2. a4 3. a3 4. a2 5. a1=T 6. Ta8 7. 0-0 (castling with a queenside rook!) Tg3#
The interest here is in the try 5. h1=T? 6. Th8, when, in a game to that position, the sK or sT must have moved to let out Ta8 to be captured (0-0?). The solution is a surprise, involving castling round the cylinder instead.
The interest here is in the try 5. h1=T? 6. Th8, when, in a game to that position, the sK or sT must have moved to let out Ta8 to be captured (0-0?). The solution is a surprise, involving castling round the cylinder instead.
No. 2142 HN
James Malcom: Due to the implementation of odds castling, the castling animation is off here. Is there any possible fix or circumvention? (2021-09-14)
comment
James Malcom: Due to the implementation of odds castling, the castling animation is off here. Is there any possible fix or circumvention? (2021-09-14)
comment
Keywords: Seriesmover, Consequent, Vertical Cylinder (Vertikaler), Homebase (s), Castling, Excelsior, Promotion (t)
Genre: Retro, Fairies
FEN: 4k3/pppp1p1p/1N3B2/4P3/4PK2/5R2/1PPPPP2/8
Input: Henri Nouguier, 2004-01-11
Last update: James Malcom, 2021-09-14 more...
Genre: Retro, Fairies
FEN: 4k3/pppp1p1p/1N3B2/4P3/4PK2/5R2/1PPPPP2/8
Input: Henri Nouguier, 2004-01-11
Last update: James Malcom, 2021-09-14 more...
1. Kc4! droht 2. Sd5#
1. ... Sb2+ 2. Kd5 Sa4 3. Sc4#
1. ... Sc3 2. d7 Kxc7 3. d8=D# 2. ... Sa4 3. Sd5#
1. ... Sb2+ 2. Kd5 Sa4 3. Sc4#
1. ... Sc3 2. d7 Kxc7 3. d8=D# 2. ... Sa4 3. Sd5#
Keywords: Brian Stephenson Collection (32937), Drag-in sacrifice, Promotion in the mating move (wD)
Genre: 3#
Computer test: SCHRECKE: popeye 4.89
FEN: R7/1pN5/1k1P4/N7/n2K4/8/8/8
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-12-23 more...
Genre: 3#
Computer test: SCHRECKE: popeye 4.89
FEN: R7/1pN5/1k1P4/N7/n2K4/8/8/8
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2023-12-23 more...
1. e8=D? droht 2. Dg6# 1. ... exd5 2. Tf4# 1. ... exd4 2. Dxe6# 1. ... Sf8!
1. Da8? droht 2. Txd6# 1. ... exd5 2. Dxd5# 1. ... exd4 2. Te5# 1. ... Sf6!
1. De1? droht 2. Dh1# 1. ... exd5 2. Sf5# 1. ... exd4 2. Tf4# 1. ... Sg5!
1. Db4! droht 2. Lc5# 1. ... exd5 2. Lf5# 1. ... exd4 2. Dxd4#
1. Da8? droht 2. Txd6# 1. ... exd5 2. Dxd5# 1. ... exd4 2. Te5# 1. ... Sf6!
1. De1? droht 2. Dh1# 1. ... exd5 2. Sf5# 1. ... exd4 2. Tf4# 1. ... Sg5!
1. Db4! droht 2. Lc5# 1. ... exd5 2. Lf5# 1. ... exd4 2. Dxd4#
Keywords: Brian Stephenson Collection (45633), Zagoruiko (4x2), Battery creation (dreifach), Promotion key (wD in Verführung), Rook sacrifice, Knight sacrifice
Genre: 2#
Computer test: SCHRECKE: popeye 4.87
FEN: 1b6/3BP2n/1P1pp3/Qp1Rp3/3Bk3/3NN3/P1K2R2/8
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2022-07-30 more...
Genre: 2#
Computer test: SCHRECKE: popeye 4.87
FEN: 1b6/3BP2n/1P1pp3/Qp1Rp3/3Bk3/3NN3/P1K2R2/8
Input: Brian Stephenson, 2004-08-12
Last update: Dieter Berlin, 2022-07-30 more...
1. g4 d5 2. g5 Lf5 3. g6 hxg6 4. Sc3 Th3 5. Se4 Tb3 6. axb3 Dd7 7. Ta6 Da4 8. Tf6 Sa6 9. h4 Td8 10. h5 Td6 11. h6 Tc6 12. h7 Tc3 13. dxc3 gxf6 14. Le3 Lh6 15. Lb6 Lc1 16. e3 d4 17. Lc4 d3 18. Dh5 d2+ 19. Ke2 d1=T 20. Sf3 Td8 21. Td1 Ta8 22. Td6 Lc8 23. Da5 Dd7 24. Se5 Dd8 25. Sd7 Sb8
Henrik Juel: Natch 3.1 did nothing in half an hour
Hard to see that Ta8 is promoted (2018-12-20)
paul: Stelvio found the solution. Then I skipped the strategies with d1=Q and d1=B. HC+ (2023-02-05)
ras@bsiag.com: In fact C+ with Stelvio 1.0 in 25min (2023-02-06)
comment
Hard to see that Ta8 is promoted (2018-12-20)
paul: Stelvio found the solution. Then I skipped the strategies with d1=Q and d1=B. HC+ (2023-02-05)
ras@bsiag.com: In fact C+ with Stelvio 1.0 in 25min (2023-02-06)
comment
Keywords: Unique Proof Game, Pronkin Theme (t), Promotion (t)
Genre: Retro
Computer test: Stelvio 1.0
FEN: rnbqk1n1/pppNpp1P/1B1R1pp1/Q7/2B1N3/1PP1P3/1PP1KP2/2b5
Reprints: (E) Quartz 25 07-09/2004
Input: Gerd Wilts, 2005-01-01
Last update: Silvio Baier, 2023-03-03 more...
Genre: Retro
Computer test: Stelvio 1.0
FEN: rnbqk1n1/pppNpp1P/1B1R1pp1/Q7/2B1N3/1PP1P3/1PP1KP2/2b5
Reprints: (E) Quartz 25 07-09/2004
Input: Gerd Wilts, 2005-01-01
Last update: Silvio Baier, 2023-03-03 more...
1. a4 e5 2. a5 Dg5 3. a6 Sf6 4. axb7 Sa6 5. b8=S Lb7 6. Sc6 dxc6 7. h4 0-0-0 8. hxg5 Td3 9. exd3 Se4 10. Dg4+ f5 11. gxf6ep+
Keywords: Unique Proof Game, En passant, Ceriani-Frolkin Theme (s), Valladao Task (wws), Promotion (S), Castling (sg)
Genre: Retro
Computer test: Euclide 0.93
FEN: 2k2b1r/pbp3pp/n1p2P2/4p3/4n1Q1/3P4/1PPP1PP1/RNB1KBNR
Input: Gerd Wilts, 2007-01-07
Last update: A.Buchanan, 2021-05-26 more...
Genre: Retro
Computer test: Euclide 0.93
FEN: 2k2b1r/pbp3pp/n1p2P2/4p3/4n1Q1/3P4/1PPP1PP1/RNB1KBNR
Input: Gerd Wilts, 2007-01-07
Last update: A.Buchanan, 2021-05-26 more...
1. a8=D+ Sf3 2. Dxf3+ Kg1 3. Lh2+ Kxh2 4. Kb4 Kg1 5. Kxc3 Kh2 6. Kd4 Kg1 7. Ke5 Kh2 8. Kf6 Kg1 9. Kg7 Kh2 10. Kh8 Kg1 11. Se2+ Kh2 12. Dg3+ Kh1 13. Sf4 c1=D,c1=~ 14. Dg2+ Txg2#
Moldenhauer: Computerprüfung: C+ Gustav 4.1d 4 Tage 6 Std. 38 Min.
Gustav hat nur im 13. Zug Se2-f4 c2-c1D. Warum nicht c2-c1T? (2022-12-15)
Olaf Jenkner: Weil es schöner aussieht.
Man sieht alle Varianten, wenn "Züge nicht zusammenfassen" aktiviert ist. (2022-12-16)
Moldenhauer: Danke!! Ein Gutes Neues auch von mir!! (2022-12-16)
more ...
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Gustav hat nur im 13. Zug Se2-f4 c2-c1D. Warum nicht c2-c1T? (2022-12-15)
Olaf Jenkner: Weil es schöner aussieht.
Man sieht alle Varianten, wenn "Züge nicht zusammenfassen" aktiviert ist. (2022-12-16)
Moldenhauer: Danke!! Ein Gutes Neues auch von mir!! (2022-12-16)
more ...
comment
Keywords: Königswanderung, Schlüssel = Eckzug, Promotion key, Promotion (D), discovered checkmate, Corner mate, Batteriematt diagonal
Genre: s#
FEN: 1B6/P7/8/8/8/Kpp5/prp5/bbN3nk
Reprints: 12) idee & form 154, p. 5215, 04/2022
Input: Frank Müller, 2010-01-22
Last update: Olaf Jenkner, 2022-12-16 more...
Genre: s#
FEN: 1B6/P7/8/8/8/Kpp5/prp5/bbN3nk
Reprints: 12) idee & form 154, p. 5215, 04/2022
Input: Frank Müller, 2010-01-22
Last update: Olaf Jenkner, 2022-12-16 more...
15 - P1101422
Erwin Moritz Herbert Guttmann
v Neue Leipziger Zeitung 04/1933
1. Preis
Monatsinformal
(6+6) C+
#5
Erwin Moritz Herbert Guttmann
v Neue Leipziger Zeitung 04/1933
1. Preis
Monatsinformal
(6+6) C+
#5
1. Tb8? d1=D!
1. Tc8? d1=S 2. Tb8 e1=D+!
1. Tf8? h1=D!
1. Tg8! h1=S 2. Tf8 e1=S 3. Tc8 d1=S 4. Tb8 ... 5. Tb3#
1. Tc8? d1=S 2. Tb8 e1=D+!
1. Tf8? h1=D!
1. Tg8! h1=S 2. Tf8 e1=S 3. Tc8 d1=S 4. Tb8 ... 5. Tb3#
Alfred Pfeiffer: Der Autor schlägt eine Version mit etwas weniger Material auf einem 12x6-Brett vor.
(1120 "The Problemist Fairy Chess Supplement" 4, 02/1934) (2014-10-09)
more ...
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(1120 "The Problemist Fairy Chess Supplement" 4, 02/1934) (2014-10-09)
more ...
comment
Keywords: Holst promotion, Promotion, konsekutive Umwandlungen 3 (sss)
Genre: n#
Computer test: C+, Gustav 4.1d, Brute Force
FEN: R7/8/8/K7/P7/k6p/Pp1ppP1p/1B6
Reprints: 17527 Deutsche Schachzeitung 09/1933
1119 The Problemist Fairy Chess Supplement 4, p. 32, 02/1934
36 Deutsche Schachblätter 6, p. 94, 15/03/1934
5336 Schweizerische Schachzeitung 04/1934
79 Comoedia 19/08/1934
VII Die Schwalbe 05-06/1942
1273 Schachmatt 12/09/1948
Schach-Express 1949
XVIII. Die Schwalbe 4, p. 91, 04/1970
Input: Frank Müller, 2010-03-21
Last update: Dieter Berlin, 2023-09-26 more...
Genre: n#
Computer test: C+, Gustav 4.1d, Brute Force
FEN: R7/8/8/K7/P7/k6p/Pp1ppP1p/1B6
Reprints: 17527 Deutsche Schachzeitung 09/1933
1119 The Problemist Fairy Chess Supplement 4, p. 32, 02/1934
36 Deutsche Schachblätter 6, p. 94, 15/03/1934
5336 Schweizerische Schachzeitung 04/1934
79 Comoedia 19/08/1934
VII Die Schwalbe 05-06/1942
1273 Schachmatt 12/09/1948
Schach-Express 1949
XVIII. Die Schwalbe 4, p. 91, 04/1970
Input: Frank Müller, 2010-03-21
Last update: Dieter Berlin, 2023-09-26 more...
1. Te6! Sf6 2. b7+ Kxb7 3. Txf6 gxf6 4. h4 f5 5. h5 f4 6. h6 f3 7. Ke3 f2 8. Kxf2 Kc7 9. h7 Le4 10. h8=D
17 - P1110582
George P. Sphicas
7997 Die Schwalbe 139 02/1993
3. ehrende Erwähnung
Inf. T.
PR Bernd Ellinghoven + Hans Gruber
(8+11)
ser-s#28
George P. Sphicas
7997 Die Schwalbe 139 02/1993
3. ehrende Erwähnung
Inf. T.
PR Bernd Ellinghoven + Hans Gruber
(8+11)
ser-s#28
1. f8=L 2. Lxd6 3. La3 4. d6 5. d7 6. d8=L 7. Lxc7 8. Lxe5 9. c7 10. c8=L 11. Lxg4 12. Lxh5 13. Ld1 14. Lxb3 15. Ka2 16. La1 17. e5 18. e6 19. e7 20. e8=L 21. Lxg6 22. Lb1 23. g6 24. g7 25. gxh8=L 26. Lhb2 27. h8=L 28. Lhc3 axb3/cxb3#
paul: Pawn h5 is not necessary, I believe. (2022-06-19)
paul: Just have seen, without Ph5 we have an alternative promotion: 1.f8=B 2.Bxd6 3.Ba3 4.d6 5.d7 6.d8=B 7.Bxc7 8.Bxe5 9.c7 10.c8=Q 11.Qxg4 12.Qgg3 13.Qxb3 14.Ka2 15.Ba1 etc (2022-06-19)
comment
paul: Just have seen, without Ph5 we have an alternative promotion: 1.f8=B 2.Bxd6 3.Ba3 4.d6 5.d7 6.d8=B 7.Bxc7 8.Bxe5 9.c7 10.c8=Q 11.Qxg4 12.Qgg3 13.Qxb3 14.Ka2 15.Ba1 etc (2022-06-19)
comment
Keywords: Seriesmover, Promotions to bishops (6-fach), konsekutive Umwandlungen 6 (LLLLLL)
Genre: Fairies
FEN: 7n/2r2P1P/2Pp2p1/3Pp1Pp/p1p1P1p1/1p6/1K3Q2/7k
Reprints: XV The Problemist 11/2012
Input: HBae, 2010-07-15
Last update: Gunter Jordan, 2023-01-14 more...
Genre: Fairies
FEN: 7n/2r2P1P/2Pp2p1/3Pp1Pp/p1p1P1p1/1p6/1K3Q2/7k
Reprints: XV The Problemist 11/2012
Input: HBae, 2010-07-15
Last update: Gunter Jordan, 2023-01-14 more...
1. a1=D+ Kb4 2. b1=D+ Kxc4 3. Dba2+ Kd3 4. f1=D+ Ke3 5. Db5 Kf3 6. Df6 Kxg3 7. Dbe5+ Kf3 8. Dae6 g4#
Keywords: Maximummer (Weisser), Promotions to queens, konsekutive Umwandlungen 3 (ddd), Oudot Theme, Minimal
Genre: Fairies
Computer test: Popeye 4.87, option intelligent
FEN: 8/6p1/3p2b1/K4kp1/2p5/6p1/pp3pP1/8
Input: HBae, 2010-07-16
Last update: James Malcom, 2022-01-31 more...
Genre: Fairies
Computer test: Popeye 4.87, option intelligent
FEN: 8/6p1/3p2b1/K4kp1/2p5/6p1/pp3pP1/8
Input: HBae, 2010-07-16
Last update: James Malcom, 2022-01-31 more...
1. b1=L 2. La2 3. Lc4 4. L4a6 5. b5 6. Tcb6 7. c5 8. c4 9. Sdc5 10. d3 11. d2 12. d1=L 13. Lxf3 14. La8 15. f3 16. f2 17. f1=L 18. Lfxg2 19. Lgb7 20. g2 21. gxh1=L 22. Lhc6 23. h1=L 24. Lhd5 25. Se4 26. Kg6 g8=L=
5 schwarze und 1 weiße Läufer-UW
5 schwarze und 1 weiße Läufer-UW
paul: Cook: 1.b1=B 2.Ba2 3.Sdc5 4.d3 5.d2 6.d1=B 7.Bxf3 8.Bxg2 9.f3 10.f2 11.f1=B 12.Bfa6 13.b5 14.Rcb6 15.Ba8 16.g2 17.gxh1=B 18.Bhb7 19.h1=B 20.Bhd5 21.Se4 22.c5 23.Bdc6 24.Bad5 25.c4 26.Kg6 (2022-06-03)
comment
comment
Keywords: Seriesmover, Promotions to bishops
Genre: Fairies
FEN: 1rb5/K1pp1kP1/1prRn3/8/1N1p1pP1/2Bn1Pp1/1pB3Rp/2Q4N
Reprints: 711 Chess Problems: Tasks and Records 1995
Input: HBae, 2010-08-30
Last update: Alfred Pfeiffer, 2017-01-27 more...
Genre: Fairies
FEN: 1rb5/K1pp1kP1/1prRn3/8/1N1p1pP1/2Bn1Pp1/1pB3Rp/2Q4N
Reprints: 711 Chess Problems: Tasks and Records 1995
Input: HBae, 2010-08-30
Last update: Alfred Pfeiffer, 2017-01-27 more...
1. Ka1! a4 2. Lb1 a3 3. La2 Kh7 4. Lxf7 a2 5. Lf8 Kh8
6. Lg6 Kg8 7. Lh6 Kh8 8. Kxa2 Kg8 9. f7+ Kh8 10. f8=D,T#
6. Lg6 Kg8 7. Lh6 Kh8 8. Kxa2 Kg8 9. f7+ Kh8 10. f8=D,T#
1. d7! droht 2. dxe8=D#,dxe8=L#,d8=S#
1. ... Kc7 2. dxe8=D#
1. ... Lxd7 2. Dc5#
1. ... Lh5,Lg6,Lf7 2. d8=S#
1. ... Sb6,Sc7 d8=S#
1. ... Kc7 2. dxe8=D#
1. ... Lxd7 2. Dc5#
1. ... Lh5,Lg6,Lf7 2. d8=S#
1. ... Sb6,Sc7 d8=S#
Keywords: Miniature Collection (0016215), under-promotion in mating move (S), discovered checkmate, Promotion (D), Miniature
Genre: 2#
Computer test: Juel: Popeye 4.61
FEN: n3b3/4Q3/2kP4/8/3K4/1R6/8/8
Reprints: The Problemist 1953
13 Schachminiaturen Zweizüger , p. 14, 1965
24 Elementary Electronics 05-06/1970
Input: Felber, Volker, 2010-09-11
Last update: Dieter Berlin, 2023-01-12 more...
Genre: 2#
Computer test: Juel: Popeye 4.61
FEN: n3b3/4Q3/2kP4/8/3K4/1R6/8/8
Reprints: The Problemist 1953
13 Schachminiaturen Zweizüger , p. 14, 1965
24 Elementary Electronics 05-06/1970
Input: Felber, Volker, 2010-09-11
Last update: Dieter Berlin, 2023-01-12 more...
22 - P1150117
Nils Adrian Bakke
XXXIV The Problemist 6 Special, p. 268, 11/1997
BJM-60 1. Lob ex aequo
(5+1) C+
#3
b) wLh4->d4
Nils Adrian Bakke
XXXIV The Problemist 6 Special, p. 268, 11/1997
BJM-60 1. Lob ex aequo
(5+1) C+
#3
b) wLh4->d4
a) 1. e8=L Kd6 2. c8=T Ke6 3. Tc6#;
b) 1. e8=D+ Kd6 2. c8=S+ Kc7 3. Le5#
b) 1. e8=D+ Kd6 2. c8=S+ Kc7 3. Le5#
Keywords: Miniature Collection (0053113), Promotion key (L,D), konsekutive Umwandlungen 2 (LT,DS), Allumwandlung (LT,DS), Miniature
Genre: 3#
Computer test: SCHRECKE: popeye 4.87
FEN: 8/2P1P3/P3k3/8/4K2B/8/8/8
Input: Felber, Volker, 2010-09-12
Last update: Dieter Berlin, 2023-02-08 more...
Genre: 3#
Computer test: SCHRECKE: popeye 4.87
FEN: 8/2P1P3/P3k3/8/4K2B/8/8/8
Input: Felber, Volker, 2010-09-12
Last update: Dieter Berlin, 2023-02-08 more...
1. Dc3+! Kb1 2. b4 Ka2 3. b5 Kb1 4. b6 Ka2 5. b7 Kb1 6. b8=D+ Ka2 7. Dbb2#
1. Dc3+! Ka2 2. Kg6 Kb1 3. Kf5 Ka2 4. Ke4 Kb1 5. Kd3 Ka2 6. Kc2 Ka3 7. Da5#
1. Dc3+! Ka2 2. Kg6 Kb1 3. Kf5 Ka2 4. Ke4 Kb1 5. Kd3 Ka2 6. Kc2 Ka3 7. Da5#
vf: wBe2->d2, -sBe3, gleiche Quellenangaben
Henrik Juel: C+ Popeye 4.61, except for the promotion dual 6.b8=DT+ and some mate duals (2022-03-08)
comment
Henrik Juel: C+ Popeye 4.61, except for the promotion dual 6.b8=DT+ and some mate duals (2022-03-08)
comment
Keywords: Miniature Collection (0088040), Promotion (wD), Minimal, Miniature
Genre: n#
Computer test: Popeye 4.61
FEN: 8/7K/8/8/8/1P2p3/2Q1P3/k7
Reprints: Die Schwalbe 103, p. 194, 02/1987
12 The Problemist 23-6, p. 229, 11/2011
Input: Felber, Volker, 2010-09-12
Last update: Dieter Berlin, 2022-03-08 more...
Genre: n#
Computer test: Popeye 4.61
FEN: 8/7K/8/8/8/1P2p3/2Q1P3/k7
Reprints: Die Schwalbe 103, p. 194, 02/1987
12 The Problemist 23-6, p. 229, 11/2011
Input: Felber, Volker, 2010-09-12
Last update: Dieter Berlin, 2022-03-08 more...
1. Db7! bxc1=L 2. g8=S+ Kxh8 3. Se7+ Kh7 4. Sd5+ Kg6 5. Sf4+ Lxf4#
1. ... bxc1=S 2. g8=L+ Kxh8 3. Lf7+ Kh7 4. Lc4+ Kg6 5. Ld3+ Sxd3#
1. ... c5 2. g6+ Kxh6 3. Sf7+ Kxg6 4. g8=D+ Kf5 5. Tf1+ Txf1#
1. ... bxc1=S 2. g8=L+ Kxh8 3. Lf7+ Kh7 4. Lc4+ Kg6 5. Ld3+ Sxd3#
1. ... c5 2. g6+ Kxh6 3. Sf7+ Kxg6 4. g8=D+ Kf5 5. Tf1+ Txf1#
Keywords: Batterie Typ Siers, Battery play, Exchange of Promotions, under-promotion B/S
Genre: s#
FEN: 4R2N/5QPk/2p2P1N/4P1Pp/7P/1p4p1/1p4P1/brR4K
Input: Frank Müller, 2011-05-07
Last update: Marcin Banaszek, 2021-07-29 more...
Genre: s#
FEN: 4R2N/5QPk/2p2P1N/4P1Pp/7P/1p4p1/1p4P1/brR4K
Input: Frank Müller, 2011-05-07
Last update: Marcin Banaszek, 2021-07-29 more...
1. a8=G+! Kb3 2. b8=G+ Kc3 3. c8=G+ Kd2 4. d8=G+ Ke2 5. e8=G+ Kf2 6. f8=G+ Kxg1 7. g8=G+ Kh1 8. h8=G#
Duplicate Diagram: P0574294
Keywords: Promotion (GGGGGGGG), konsekutive Umwandlungen 8 (GGGGGGGG), Promotion key, Checking key, Perpetual check, Promotion to fairy pieces
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: 8/PPPPPPPP/8/8/ppp5/k2ppp2/6pp/1K1*2Qr1*2Q1
Input: Hans Gruber, 2011-10-09
Last update: Achim Schöneberg, 2024-03-19 more...
Pieces: = Grasshopper (G)
Genre: Fairies
FEN: 8/PPPPPPPP/8/8/ppp5/k2ppp2/6pp/1K1*2Qr1*2Q1
Input: Hans Gruber, 2011-10-09
Last update: Achim Schöneberg, 2024-03-19 more...
1) 1. Sb6+ axb6 2. Lc7 bxc7 3. Td8 cxd8=D 4. e5 Dd3#
2) 1. Lb6 a6 2. Le3 a7 3. c5 a8=D 4. Ld5+ Dxd5#
2) 1. Lb6 a6 2. Le3 a7 3. c5 a8=D 4. Ld5+ Dxd5#
1. f7 Txg6 2. Lxd5+ Kxd7 3. Lc6+ Ke6 4. Dd5+ Kf6 5. De5+ Kxf7 6. Sxh6+ Thxh6#
6. ... Tgxh6#
1. ... Txf5 2. b8=S+ Kxd6 3. c8=S+ Kxe6 4. d8=S+ Kf6 5. e8=S+ Kxg6 6. f8=S+ Txf8#
Cook: Dual: 3. d8=D+ Kxe6 4. Dd7+ Kf6 5. e8=S+ Kxg6 6. f8=S+ Txf8#
6. ... Tgxh6#
1. ... Txf5 2. b8=S+ Kxd6 3. c8=S+ Kxe6 4. d8=S+ Kf6 5. e8=S+ Kxg6 6. f8=S+ Txf8#
Cook: Dual: 3. d8=D+ Kxe6 4. Dd7+ Kf6 5. e8=S+ Kxg6 6. f8=S+ Txf8#
SCHRECKE: Dual nach 1.f7! T:f5 2.b8S+ K:d6
Es geht auch 3.d8D+ K:e6 4.Dd7+ Kf6 5.e8S+ K:g6 6.f8S+ T:f8# (2021-03-25)
comment
Es geht auch 3.d8D+ K:e6 4.Dd7+ Kf6 5.e8S+ K:g6 6.f8S+ T:f8# (2021-03-25)
comment
Keywords: Promotions to Knights, konsekutive Umwandlungen 5 (SSSSS)
Genre: s#
FEN: N6K/1PPPP3/2kBBPPp/2pp1Nrr/1RR2Ppb/6p1/6Q1/8
Input: Frank Müller, 2013-02-16
Last update: Rainer Staudte, 2021-03-26 more...
Genre: s#
FEN: N6K/1PPPP3/2kBBPPp/2pp1Nrr/1RR2Ppb/6p1/6Q1/8
Input: Frank Müller, 2013-02-16
Last update: Rainer Staudte, 2021-03-26 more...
28 - P1282593
William Edward Lester
1223 The Problemist FCS 02/1934
(2+6) C+
s#6
Längstzüger;
sDu= Grashüpfer;
William Edward Lester
1223 The Problemist FCS 02/1934
(2+6) C+
s#6
Längstzüger;
sDu= Grashüpfer;
1. g4! Gg3 2. g5 Gh2 3. g6 Ga2 4. g7 Gh8 5. g8=G Gb8 6. Gg2 Gh2#
Wehrlos muss Schwarz dazuhelfen, dass sich Weiß durch seinen Exzelsior und die anschließende Rückkehr des Minimalexzelsiorbauern nach Umwandlung auf sein Startfeld das Selbstmatt gräbt
more ...
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more ...
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Keywords: Maximummer, Excelsior, Promotion (Märchen-)
Pieces: = Grasshopper (G)
Genre: Fairies
Computer test: SCHRECKE: C+, popeye 4.85 (2020-10-25)
FEN: 1*2qk2*2q*2q1/1p6/8/8/8/8/1*2q4P1/7K
Input: Erich Bartel, 2014-01-28
Last update: Erich Bartel, 2020-10-26 more...
Pieces: = Grasshopper (G)
Genre: Fairies
Computer test: SCHRECKE: C+, popeye 4.85 (2020-10-25)
FEN: 1*2qk2*2q*2q1/1p6/8/8/8/8/1*2q4P1/7K
Input: Erich Bartel, 2014-01-28
Last update: Erich Bartel, 2020-10-26 more...
a) 1. e8=L+ Kd8 2. Lf7+ Kd7 3. Sg4 e5 4. Lg6+ Ke6 5. Ld3 e4 6. Se3 exd3 7. Lxb3+ Sxb3#
b) 1. e8=S+ Kd8 2. Sg7+ Kd7 3. Sf4 e5 4. Sfd3 e4 5. Sf5+ Ke6 6. Se3 exd3 7. Lxb3+ Sxb3#
Korrektur in 11/1997, Seite 205.
Cook: NL
b) 1. e8=S+ Kd8 2. Sg7+ Kd7 3. Sf4 e5 4. Sfd3 e4 5. Sf5+ Ke6 6. Se3 exd3 7. Lxb3+ Sxb3#
Korrektur in 11/1997, Seite 205.
Cook: NL
Anton Baumann: Diagramm korrekt?
a) sowie b) haben beide 8 NL in 6 Zügen!?
zB. a),b): 1.Dc8+ Kd6 2.Lxc6 e5 3.Dd7+ Kc5 4.Dd5+ Kxb4 5.Lc3+ Kxc3 6.De4 b2# (2022-03-08)
comment
a) sowie b) haben beide 8 NL in 6 Zügen!?
zB. a),b): 1.Dc8+ Kd6 2.Lxc6 e5 3.Dd7+ Kc5 4.Dd5+ Kxb4 5.Lc3+ Kxc3 6.De4 b2# (2022-03-08)
comment
Keywords: Exchange of Promotions
Genre: s#
FEN: 5Q2/1PpkP2R/R1n1p2N/8/BN6/1p6/1Bp5/n1K5
Input: Frank Müller, 2015-02-08
Last update: Marcin Banaszek, 2022-03-10 more...
Genre: s#
FEN: 5Q2/1PpkP2R/R1n1p2N/8/BN6/1p6/1Bp5/n1K5
Input: Frank Müller, 2015-02-08
Last update: Marcin Banaszek, 2022-03-10 more...
1. b8=D+! Kd7 2. e8=T c5 3. Dd8+ Kc6 4. a8=D+ Kb5 5. Ddb8+ Kc4 6. Te1 Kd4 7. h8=L+ Kc4 8. Kd1 Kd3 9. Df4 c4 10. Lb2 c3 11. Lc1 c2#
Keywords: Kindergarten Problem, konsekutive Umwandlungen 4 (DTDL), Pawn mate, under-promotion, Minimal (s), Miniature, Selfblock, Model mate, Checking key, Promotion key, Flight taking
Genre: s#
FEN: 8/PPk1P2P/2p5/8/8/8/2K5/8
Reprints: 14) idee & form 143, p. 4843, 07/2019
Input: Frank Müller, 2015-04-11
Last update: Rainer Staudte, 2023-01-19 more...
Genre: s#
FEN: 8/PPk1P2P/2p5/8/8/8/2K5/8
Reprints: 14) idee & form 143, p. 4843, 07/2019
Input: Frank Müller, 2015-04-11
Last update: Rainer Staudte, 2023-01-19 more...
a) 1. e5 d3 2. e4 dxe4 3. Sb7 e5 4. 0-0-0 e6 5. Kb8 e7 6. Ka8 e8=S 7. Tb8 Sc7#
b) 1. Sb6 d3 2. Sc4 dxc4 3. d3 c5 4. d2 c6 5. d1=T c7 6. Tf1 c8=D 7. Tf8 Dxe6#
b) 1. Sb6 d3 2. Sc4 dxc4 3. d3 c5 4. d2 c6 5. d1=T c7 6. Tf1 c8=D 7. Tf8 Dxe6#
32 - P1341579
Michel Olausson
PS224 The Problemist Supplement 12 05/1994
(3+3) C+
h#2
Circe
Umwandlung auch
b) wSUc1 statt wTLc1
wSU,sSU=Nachtreiter
wTL=Pao
Michel Olausson
PS224 The Problemist Supplement 12 05/1994
(3+3) C+
h#2
Circe
Umwandlung auch
b) wSUc1 statt wTLc1
wSU,sSU=Nachtreiter
wTL=Pao
a) 1. b1=N d8=D 2. Nd5 Dxd5[+sNd1]#
b) 1. bxc1=PA[+wNc8] d8=N 2. PAg1 Nf2#
Laut Begleittext ist in b) Umwandlung in PAO erlaubt
b) 1. bxc1=PA[+wNc8] d8=N 2. PAg1 Nf2#
Laut Begleittext ist in b) Umwandlung in PAO erlaubt
Keywords: Circe, Forsberg Twins, Promotion
Pieces: = Nightrider (N), = Pao (PA)
Genre: Fairies
Computer test: Henrik Juel: C+ Popeye 4.61 (2021-02-26)
FEN: 6K1/3P4/8/8/8/8/1p5*2n/2*3R4k
Input: HBae, 2017-10-12
Last update: James Malcom, 2021-02-27 more...
Pieces: = Nightrider (N), = Pao (PA)
Genre: Fairies
Computer test: Henrik Juel: C+ Popeye 4.61 (2021-02-26)
FEN: 6K1/3P4/8/8/8/8/1p5*2n/2*3R4k
Input: HBae, 2017-10-12
Last update: James Malcom, 2021-02-27 more...
33 - P1356154
Mirko Degenkolbe
Steven B. Dowd
H3382v The Problemist 26-8, p. 318, 03/2018
(11+9)
h#24
Mirko Degenkolbe
Steven B. Dowd
H3382v The Problemist 26-8, p. 318, 03/2018
(11+9)
h#24
1. Kxb5 La2 2. Kc6 Lb1 3. Kc7 La2 4. Kd8 Lb1 5. Ke8 La2 6. Kf8 Lb1 7. Kg7 La2 8. Kh6 g5+ 9. Kh5 Lb1 10. Kg4 La2 11. Kf3 Lb1 12. Kxe4 La2 13. Kxe3 Lb1 14. Kd2 La2 15. Kc1 Lb1 16. Kb2 La2 17. Kxa1 Lb1 18. Kb2 La2 19. Kxc2 Lb1 20. Kxb3 Lxg6 21. Kc4 Lh7 22. Kd5 g6 23. Kxe6 g7 24. Kf7 g8=D#
vergleiche P1110452
[MD 1315]
Autoren:
Verbesserung von Aufgabe H3382 „THE PROBLEMIST“ Juli 2010
Wir sehen in dieser Aufgabe folgenden Inhalt:
1) Erhalt weißer Masse (wBg4).
2) Beseitigung hinderlicher weißer Masse (wBe3 & wBe4)
3) Das Matt mit sKa4 ist nicht möglich, weil Weiß für das Mattbild einen Zug zu viel benötigen würde.
Des Weiteren enthält diese Aufgabe meines Erachtens, wie schon erwähnt, sage und schreibe DREI Weltrekorde.
Also:
Rekord Nummer eins:
Längster schwarzer Königsmarsch am Stück in einem orthodoxem Hilfsmatt = 24 Züge.
Rekord Nummer zwei:
Zuglängste Darstellung eines schwarzen Durbars in einem orthodoxem Hilfsmatt = 24 Züge.
Rekord Nummer drei:
Zuglängster Rundlauf des schwarzen Königs in einem orthodoxem Hilfsmatt = 21 Züge.
Die beiden ersten Rekorde befinden sich schon in der Originalversion, die 2010 veröffentlicht wurde. Der dritte Rekord (längster Rundlauf des schwarzen Königs im orthodoxen Hilfsmatt) ist nun auch noch hinzugekommen.
Wahrscheinlich ist diese Aufgabe auch schwer zu lösen, weil der Löser versucht, den Quadrupelbauern abzuräumen, damit sich Schwarz einen Springer erwandeln kann, vergebens …
Christopher J. A. Jones brachte die verbesserte Version als Einleitung der Hilfsmatt-Urdruck-Serie im März-Heft 2018, sehr ordentlich besprochen, in Englisch.
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-28)
comment
[MD 1315]
Autoren:
Verbesserung von Aufgabe H3382 „THE PROBLEMIST“ Juli 2010
Wir sehen in dieser Aufgabe folgenden Inhalt:
1) Erhalt weißer Masse (wBg4).
2) Beseitigung hinderlicher weißer Masse (wBe3 & wBe4)
3) Das Matt mit sKa4 ist nicht möglich, weil Weiß für das Mattbild einen Zug zu viel benötigen würde.
Des Weiteren enthält diese Aufgabe meines Erachtens, wie schon erwähnt, sage und schreibe DREI Weltrekorde.
Also:
Rekord Nummer eins:
Längster schwarzer Königsmarsch am Stück in einem orthodoxem Hilfsmatt = 24 Züge.
Rekord Nummer zwei:
Zuglängste Darstellung eines schwarzen Durbars in einem orthodoxem Hilfsmatt = 24 Züge.
Rekord Nummer drei:
Zuglängster Rundlauf des schwarzen Königs in einem orthodoxem Hilfsmatt = 21 Züge.
Die beiden ersten Rekorde befinden sich schon in der Originalversion, die 2010 veröffentlicht wurde. Der dritte Rekord (längster Rundlauf des schwarzen Königs im orthodoxen Hilfsmatt) ist nun auch noch hinzugekommen.
Wahrscheinlich ist diese Aufgabe auch schwer zu lösen, weil der Löser versucht, den Quadrupelbauern abzuräumen, damit sich Schwarz einen Springer erwandeln kann, vergebens …
Christopher J. A. Jones brachte die verbesserte Version als Einleitung der Hilfsmatt-Urdruck-Serie im März-Heft 2018, sehr ordentlich besprochen, in Englisch.
SCHRECKE: C+, Gustav 4.1d, Brute Force (2020-10-28)
comment
Keywords: Round Trip (maximal, 21 Züge), Durbar Theme (schwarz), Promotion in the mating move (D)
Genre: h#
FEN: 8/4p3/1p2P1p1/1P2P3/1pk1P1P1/1Pp1P1p1/2P3p1/NB4Kb
Input: Felber, Volker, 2018-10-10
Last update: Felber, Volker, 2020-10-28 more...
Genre: h#
FEN: 8/4p3/1p2P1p1/1P2P3/1pk1P1P1/1Pp1P1p1/2P3p1/NB4Kb
Input: Felber, Volker, 2018-10-10
Last update: Felber, Volker, 2020-10-28 more...
1. d8=S! g5 2. b5 g4 3. b7 Ka7 4. b8=T g3 5. Se6 fxe6 6. f7 e5 7. d5 e4 8. f8=D e3 9. Df2 exf2,gxf2#
Version zu P1343954
Gunter Jordan: Lt. Hans Gruber erschien diese Aufgabe in feenschach 227 (2017), tatsächlich erschienen im März 2018. Somit ist feenschach die Erstquelle (sofern die Aufgabe nicht noch irgendwo drittveröffentlicht wurde). Ich habe hier die Erstquelle auf feenschach geändert. Die ursprüngliche 'Erstquelle' The Problemist habe ich als Reprint eingegeben. [GJ] (2020-10-30)
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Gunter Jordan: Lt. Hans Gruber erschien diese Aufgabe in feenschach 227 (2017), tatsächlich erschienen im März 2018. Somit ist feenschach die Erstquelle (sofern die Aufgabe nicht noch irgendwo drittveröffentlicht wurde). Ich habe hier die Erstquelle auf feenschach geändert. Die ursprüngliche 'Erstquelle' The Problemist habe ich als Reprint eingegeben. [GJ] (2020-10-30)
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Keywords: Kindergarten Problem, under-promotion (S,T), Promotion (D), under-promotion key (S), Multiple publication, Pawn mate, Antiphönix, Pinning, Flight taking
Genre: s#
Computer test: Gustav 4.0c
FEN: k7/2PP1p2/1P3Pp1/8/1P1P4/3p4/3Pp1P1/4K3
Reprints: S2678c The Problemist 26-9, p. 363, 05/2018
Input: Felber, Volker, 2018-12-11
Last update: Gunter Jordan, 2020-10-30 more...
Genre: s#
Computer test: Gustav 4.0c
FEN: k7/2PP1p2/1P3Pp1/8/1P1P4/3p4/3Pp1P1/4K3
Reprints: S2678c The Problemist 26-9, p. 363, 05/2018
Input: Felber, Volker, 2018-12-11
Last update: Gunter Jordan, 2020-10-30 more...
35 - P1366134
Anatoly Stepochkin
S2811 The Problemist 27-10, p. 392, 07/2020
3.-5. Lob
Sektion s#5-n
(5+2) C+
s#9
b) wLa2->h4
Version
Anatoly Stepochkin
S2811 The Problemist 27-10, p. 392, 07/2020
3.-5. Lob
Sektion s#5-n
(5+2) C+
s#9
b) wLa2->h4
Version
a) 1. g7-g8=L+! Kf7-f8 2. d7-d8=D+ Te6-e8 3. Dd8-d6+ Te8-e7 4. Dg5-c1! Kf8-e8 5. Dd6-b8+ Ke8-d7 6. La2-e6+ Te7xe6 7. Db8-c7+ Kd7-e8 8. Lg8-f7+ Ke8-f8 9. Dc1-h6+ Te6xh6#
b) 1. Dg5-h5+! Te6-g6 2. Dh5-d5+ Tg6-e6 3. d7-d8=D Kf7-g6 4. Dd8-g5+ Kg6-f7 5. Dd5-c4! Kf7-e8 6. Dg5-d8+ Ke8-f7 7. g7-g8=S! Kf7-g6 8. Dc4-g4+ Kg6-f7 9. Sg8-h6+ Te6xh6#
Das Problem wurde zuerst mit drittem Zwilling (wDg5>h1) und mit Co-Autor Yuri Paramonov in SuperProblem 04/2019 veröffentlicht.
Aber die Lösung war dualistisch:
c) 1. d7-d8=D! Kf7-g6 2. Dh1-h7+ Kg6-f7 3. Dh7-h3 Kf7-g6 4. g7-g8=T+ Kg6-f7 5. Dd8-d7+ Kf7-f6 6. Dh3-h4+ Ke5,Kf5 7. Tg8-g5+ Kf6 8. Tg5-d5+ Kf6-g6 9. Dd7-e8+ Te6xe8#
und
3. Dd8-d6 Kf7-f6 4. Dd6-f4+ Kf6-e7 5. g7-g8=L+ Ke7-e8 6. Dff7+,Dhf7+ Ke8-d8 7. Df7-c7+ Kd8-e8 8. Lg8-f7+ Ke8-f8 9. Dh6+ Te6xh6#
3. ... Kf7-e8 4. Dh7-h5+ Te6-g6 5. La2-b1 Ke8-f7 6. Lb1-f5 Kf7-e8 7. g7-g8=T+ Ke8-f7 8. Lf5-e6+ Kf7-f6 9. Dh5-h6 Tg6xh6#
Judge Ivan Soroka 07/2023:
"Again two solutions – with black rook pinned in the diagram position and four promotions of two white pawns. Unfortunately, the author failed to achieve Allumwandlung – promotion of pawns to all four possible types of pieces: QRBS."
b) 1. Dg5-h5+! Te6-g6 2. Dh5-d5+ Tg6-e6 3. d7-d8=D Kf7-g6 4. Dd8-g5+ Kg6-f7 5. Dd5-c4! Kf7-e8 6. Dg5-d8+ Ke8-f7 7. g7-g8=S! Kf7-g6 8. Dc4-g4+ Kg6-f7 9. Sg8-h6+ Te6xh6#
Das Problem wurde zuerst mit drittem Zwilling (wDg5>h1) und mit Co-Autor Yuri Paramonov in SuperProblem 04/2019 veröffentlicht.
Aber die Lösung war dualistisch:
c) 1. d7-d8=D! Kf7-g6 2. Dh1-h7+ Kg6-f7 3. Dh7-h3 Kf7-g6 4. g7-g8=T+ Kg6-f7 5. Dd8-d7+ Kf7-f6 6. Dh3-h4+ Ke5,Kf5 7. Tg8-g5+ Kf6 8. Tg5-d5+ Kf6-g6 9. Dd7-e8+ Te6xe8#
und
3. Dd8-d6 Kf7-f6 4. Dd6-f4+ Kf6-e7 5. g7-g8=L+ Ke7-e8 6. Dff7+,Dhf7+ Ke8-d8 7. Df7-c7+ Kd8-e8 8. Lg8-f7+ Ke8-f8 9. Dh6+ Te6xh6#
3. ... Kf7-e8 4. Dh7-h5+ Te6-g6 5. La2-b1 Ke8-f7 6. Lb1-f5 Kf7-e8 7. g7-g8=T+ Ke8-f7 8. Lf5-e6+ Kf7-f6 9. Dh5-h6 Tg6xh6#
Judge Ivan Soroka 07/2023:
"Again two solutions – with black rook pinned in the diagram position and four promotions of two white pawns. Unfortunately, the author failed to achieve Allumwandlung – promotion of pawns to all four possible types of pieces: QRBS."
Felber, Volker: Von Stjopotschkin als Alleinautor unter Weglassung des dualistischen Teils c) in THE PROBLEMIST 07/2020 (2021-02-06)
comment
comment
Keywords: konsekutive Umwandlungen 2 (LD,DS,DT), Allumwandlung, Promotion key, Multiple publication, Minimal, Miniature
Genre: s#
FEN: 7K/3P1kP1/4r3/6Q1/8/8/B7/8
Reprints: F163 SuperProblem (Website) 14/04/2019
Input: Marcin Banaszek, 2019-08-08
Last update: Marcin Banaszek, 2023-07-05 more...
Genre: s#
FEN: 7K/3P1kP1/4r3/6Q1/8/8/B7/8
Reprints: F163 SuperProblem (Website) 14/04/2019
Input: Marcin Banaszek, 2019-08-08
Last update: Marcin Banaszek, 2023-07-05 more...
1. ... e6 2. Lf8 exf7 3. Lc5 f8=D 4. Lb6 c5 5. Lb1 Dxf6#
VL: A hideaway maneuver (bB).
Tempo-try: 1... exf6/c5? 2.Lf8 c5/exf6 3.Le7 fxe7 4.Lb1 e8=D 5.?? De5# (2020-12-04)
comment
Tempo-try: 1... exf6/c5? 2.Lf8 c5/exf6 3.Le7 fxe7 4.Lb1 e8=D 5.?? De5# (2020-12-04)
comment
Keywords: Promotion (D), Verstecken (l), Corner mate, Model mate
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/p1p2pb1/p1P2p1p/P2BPP1P/1PP1P3/8/b7/k4K2
Input: Felber, Volker, 2020-11-21
Last update: Gunter Jordan, 2020-11-21 more...
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/p1p2pb1/p1P2p1p/P2BPP1P/1PP1P3/8/b7/k4K2
Input: Felber, Volker, 2020-11-21
Last update: Gunter Jordan, 2020-11-21 more...
1. g4 b5 2. g5 b4 3. g6 b3 4. gxh7 bxa2 5. hxg8=S axb1=S 6. Sxe7 Sc3 7. Sd5 Sxe2 8. Sc3 Sxc1 9. Txc1 Sc6 10. Sb1
Scheint ein Selbstplagiat zu sein. Das Stück wurde in Problemas (SEPA), 07/2020, Heft 31, H1, Seite 935 als Original veröffentlicht.
Scheint ein Selbstplagiat zu sein. Das Stück wurde in Problemas (SEPA), 07/2020, Heft 31, H1, Seite 935 als Original veröffentlicht.
Henrik Juel: C+ Euclide 1.01
This is an example of the retro theme of WCCT-11
The thematic square is b1, where Sb1 is not original, but promoted, and where Black promoted, only to have his promoted piece captured later
The fact that the promotions are both to knight is not required by the theme (2021-03-21)
Henrik Juel: The PDB definition of Antiphönix recommends that this keyword should be deleted... (2021-03-21)
comment
This is an example of the retro theme of WCCT-11
The thematic square is b1, where Sb1 is not original, but promoted, and where Black promoted, only to have his promoted piece captured later
The fact that the promotions are both to knight is not required by the theme (2021-03-21)
Henrik Juel: The PDB definition of Antiphönix recommends that this keyword should be deleted... (2021-03-21)
comment
Keywords: blocking of a piece, Excelsior black, Excelsior white, Phoenix, Prentos Theme (s), Pronkin Theme (S), Promotions to Knights, under-promotion (ss)
Genre: Retro
FEN: r1bqkb1r/p1pp1pp1/2n5/8/8/8/1PPP1P1P/1NRQKBNR
Reprints: H Springaren 154, p. 49, 06/2020
H The Problemist , p. 383, 07/2020
Input: Gunter Jordan, 2021-03-21
Last update: Gunter Jordan, 2023-04-03 more...
Genre: Retro
FEN: r1bqkb1r/p1pp1pp1/2n5/8/8/8/1PPP1P1P/1NRQKBNR
Reprints: H Springaren 154, p. 49, 06/2020
H The Problemist , p. 383, 07/2020
Input: Gunter Jordan, 2021-03-21
Last update: Gunter Jordan, 2023-04-03 more...
38 - P1388091
Andrew Buchanan
James Malcom
PS3645 The Problemist Supplement 171, p. 139, 03/2021
(5+9) C+
#10
Andrew Buchanan
James Malcom
PS3645 The Problemist Supplement 171, p. 139, 03/2021
(5+9) C+
#10
1. h7! dxc2 2. h8=S d3 3. Sg6 d4 4. Sf4 d5 5. Sxd3 d6 6. Sxb4 d3 7. Sxd3 d4 8. b4 d5 9. Sc5 d3 10. Sb3#
Henrik Juel: C+ Popeye 4.61
At first sight I thought that 1.h7 Lxc2 2.h8=DL thr. 3.DLxd4# would be a cook
but Black defends better by 1... dxc2!
Very impressive that the main variation is dual-free (2021-04-03)
comment
At first sight I thought that 1.h7 Lxc2 2.h8=DL thr. 3.DLxd4# would be a cook
but Black defends better by 1... dxc2!
Very impressive that the main variation is dual-free (2021-04-03)
comment
1. b4 f5 2. b5 f4 3. b6 f3 4. bxc7 fxg2 5. cxb8=S gxh1=D 6. Sxd7 Dd5 7. Sxf8 Dxd2+ 8. Lxd2 Dxd2+ 9. Sxd2 Kd8 10. Sxh7 Txh7 11. Tc1 Th8 12. Sb1+
Moldenhauer: Computerprüfung: C+ Natch 3.3 in 5 Tage 10 Std. 49 Min. eine Lösung gefunden.
Prüfung BP in 11 u. 12, keine Lösung! (2022-08-30)
A.Buchanan: Since the position is check, the only shorter PG which requires examination is 10.5 (2022-08-30)
Moldenhauer: Computerüberprüfung: BP in 10.5 Natch 3.3 keine Lösung! Zeit 16 Std. 22 Min. (2022-09-01)
more ...
comment
Prüfung BP in 11 u. 12, keine Lösung! (2022-08-30)
A.Buchanan: Since the position is check, the only shorter PG which requires examination is 10.5 (2022-08-30)
Moldenhauer: Computerüberprüfung: BP in 10.5 Natch 3.3 keine Lösung! Zeit 16 Std. 22 Min. (2022-09-01)
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Keywords: Discovered check, Unique Proof Game, Excelsior black, Excelsior white, Prentos Theme (Sd), Switchback (St), Promotion (d), under-promotion (S), x pieces capture on one square (4)
Genre: Retro
Computer test: Computerprüfung: C+ Natch 3.3 in 5 Tage 10 Std. 49 Min. eine Lösung gefunden. Prüfung BP in 11 u. 12, keine Lösung!
FEN: r1bk2nr/pp2p1p1/8/8/8/8/P1P1PP1P/1NRQKBN1
Input: Gunter Jordan, 2021-04-18
Last update: A.Buchanan, 2022-08-30 more...
Genre: Retro
Computer test: Computerprüfung: C+ Natch 3.3 in 5 Tage 10 Std. 49 Min. eine Lösung gefunden. Prüfung BP in 11 u. 12, keine Lösung!
FEN: r1bk2nr/pp2p1p1/8/8/8/8/P1P1PP1P/1NRQKBN1
Input: Gunter Jordan, 2021-04-18
Last update: A.Buchanan, 2022-08-30 more...
1. Da6! droht 2. Txh5#,Tg5#,Tf5#,Te5#,Td5#,Tc5#,Txb2#,Ta3#,Th3#,Tg3#,Tf3#,Te3#,Td3#,Tc3#
1. ... b1=D+ 2. Txb1#
1. ... b1=L+ 2. Txb1#
1. ... Sg3+ 2. Txg3#
1. ... Sec3+ 2. Txc3#
1. ... Tg1+ 2. Tf3#
1. ... Tf2+ 2. Tf3#
1. ... Tgg8+ 2. Tf3#
1. ... Tg7+ 2. Tf3#
1. ... Tg6+ 2. Tf3#
1. ... Tg5+ 2. Tf3#
1. ... Tg4+ 2. Tf3#
1. ... Tg3+ 2. Tf3#
1. ... Th2+ 2. Tf3#
1. ... Sac3+ 2. Txc3#
1. ... Sc5+ 2. Txc5#
1. ... Df3+ 2. Txf3#
1. ... Dg6+ 2. Tf5#
1. ... Dd5+ 2. Txd5#
1. ... De5+ 2. Txe5#
1. ... Df5+ 2. Txf5#
1. ... Dh7+ 2. Tf5#
1. ... d5+ 2. Txd5#
1. ... Lh4+ 2. Te5#
1. ... Lg5+ 2. Te5#
1. ... Lf6+ 2. Te5#
1. ... Lf8+ 2. Te5#
1. ... Ld8+ 2. Te5#
1. ... f5+ 2. Txf5#
1. ... b1=D+ 2. Txb1#
1. ... b1=L+ 2. Txb1#
1. ... Sg3+ 2. Txg3#
1. ... Sec3+ 2. Txc3#
1. ... Tg1+ 2. Tf3#
1. ... Tf2+ 2. Tf3#
1. ... Tgg8+ 2. Tf3#
1. ... Tg7+ 2. Tf3#
1. ... Tg6+ 2. Tf3#
1. ... Tg5+ 2. Tf3#
1. ... Tg4+ 2. Tf3#
1. ... Tg3+ 2. Tf3#
1. ... Th2+ 2. Tf3#
1. ... Sac3+ 2. Txc3#
1. ... Sc5+ 2. Txc5#
1. ... Df3+ 2. Txf3#
1. ... Dg6+ 2. Tf5#
1. ... Dd5+ 2. Txd5#
1. ... De5+ 2. Txe5#
1. ... Df5+ 2. Txf5#
1. ... Dh7+ 2. Tf5#
1. ... d5+ 2. Txd5#
1. ... Lh4+ 2. Te5#
1. ... Lg5+ 2. Te5#
1. ... Lf6+ 2. Te5#
1. ... Lf8+ 2. Te5#
1. ... Ld8+ 2. Te5#
1. ... f5+ 2. Txf5#
'The Problemist' zählt 27 schwarze Schachs (also vermutlich 1. ... b1=D+ und 1. ... b1=L+ nur als ein Schach)
Überboten durch P1054330.
'The Problemist' gibt zur Quelle nur das Urdruckjahr 1922 an, von der Zeit her könnte die Quelle 'Good Companions' sein ...
Henrik Juel: duals after other defenses (2021-07-29)
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Überboten durch P1054330.
'The Problemist' gibt zur Quelle nur das Urdruckjahr 1922 an, von der Zeit her könnte die Quelle 'Good Companions' sein ...
Henrik Juel: duals after other defenses (2021-07-29)
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Keywords: Promotion (d), under-promotion (l)
Genre: 2#
FEN: 4r3/Q3bp2/3p4/PR5q/nBk1Kp2/1R6/Bp2n1r1/7b
Reprints: The Problemist 15, p. 416, 05/1950
Input: Mario Richter, 2021-07-29
Last update: Alfred Pfeiffer, 2022-03-23 more...
Genre: 2#
FEN: 4r3/Q3bp2/3p4/PR5q/nBk1Kp2/1R6/Bp2n1r1/7b
Reprints: The Problemist 15, p. 416, 05/1950
Input: Mario Richter, 2021-07-29
Last update: Alfred Pfeiffer, 2022-03-23 more...
1. e4 Sf6 2. Dg4 Sxe4 3. Dxg7 Lxg7 4. c4 0-0 5. c5 Lh8 6. c6 Kg7 7. cxb7 Kf6 8. bxc8=D Ke5 9. Dxd8 Kd4 10. Se2+ Kd3 11. Dxd7+ Kc2 12. Dg4 Sd7 13. Sg1 Tac8 14. Dd1#
Keywords: Antiphönix, Unique Proof Game, Excelsior white, Homebase (w), Line closing, Phoenix, Pronkin Theme, Castling, Switchback (S), Promotion (D)
Genre: Retro
Computer test: Jacobi v0.7.5
FEN: 2r2r1b/p1pnpp1p/8/8/4n3/8/PPkP1PPP/RNBQKBNR
Input: Gunter Jordan, 2022-01-27
Last update: Gunter Jordan, 2022-01-27 more...
Genre: Retro
Computer test: Jacobi v0.7.5
FEN: 2r2r1b/p1pnpp1p/8/8/4n3/8/PPkP1PPP/RNBQKBNR
Input: Gunter Jordan, 2022-01-27
Last update: Gunter Jordan, 2022-01-27 more...
1) 1. Lg8 c4 2. Ld5 cxd5 3. Kg5 dxc6 4. Kf4 c7 5. Ke5 c8=D 6. Kd4 Dc5#
2) 1. e1=T c4 2. Td1 c5 3. Td6 cxd6 4. g2 d7 5. g1=T d8=S 6. Tg6 Sf7#
2) 1. e1=T c4 2. Td1 c5 3. Td6 cxd6 4. g2 d7 5. g1=T d8=S 6. Tg6 Sf7#
Yuri Bilokin: more economicai -wPc3, -bPe3
8/6bb/2p2p1k/5p1p/1K2p3/6p1/2P1p3/8 (2+10) h#6 2.1…
1.Bg8 c4 2.Bd5 cxd5 3.Kg5 dxc6 4.Kf4 c7 5.Ke3 c8=Q 6.Kd3 Qc3#
1.e1=R c4 2.Rd1 c5 3.Rd6 cxd6 4.g2 d7 5.g1=R d8=S 6.Rg6 Sf7# (MM)
Excelsior (white) × 2
Exchange of functions (bPe2/bBh7, Active sacrifice / Passive self-block) (2022-07-18)
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8/6bb/2p2p1k/5p1p/1K2p3/6p1/2P1p3/8 (2+10) h#6 2.1…
1.Bg8 c4 2.Bd5 cxd5 3.Kg5 dxc6 4.Kf4 c7 5.Ke3 c8=Q 6.Kd3 Qc3#
1.e1=R c4 2.Rd1 c5 3.Rd6 cxd6 4.g2 d7 5.g1=R d8=S 6.Rg6 Sf7# (MM)
Excelsior (white) × 2
Exchange of functions (bPe2/bBh7, Active sacrifice / Passive self-block) (2022-07-18)
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Keywords: under-promotion key (in 2), Promotions to rooks (in 2), konsekutive Umwandlungen 3 (ttS in 2), Promotion (D in 1), Allumwandlung, Selfblock (in 2), Entblockung (in 1)
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/6bb/2p2p1k/5p1p/1K2p3/2P1p1p1/2P1p3/8
Input: Felber, Volker, 2022-07-13
Last update: Gunter Jordan, 2023-03-09 more...
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/6bb/2p2p1k/5p1p/1K2p3/2P1p1p1/2P1p3/8
Input: Felber, Volker, 2022-07-13
Last update: Gunter Jordan, 2023-03-09 more...
43 - P1403727
George P. Sphicas
F3272 The Problemist 01/2016
Dedicated to my son Phil
(8+8)
ser-s#33
George P. Sphicas
F3272 The Problemist 01/2016
Dedicated to my son Phil
(8+8)
ser-s#33
1. b8=D 2. Dxd6 3. Dxd5 4. De4 5. b6 6. d8=D 7. Ddxd3 8. De2 9. d4 10. d5 11. d6 12. d7 13. d8=D 14. Ddd3 15. b7 16. b8=D 17. Dxh8 18. Dhd4 19. h8=D 20. Dhxh5 21. Dhf3 22. h5 23. h6 24. h7 25. h8=D 26. Dh4 27. Dhf2 28. h4 29. h5 30. h6 31. h7 32. h8=D 33. Dhe5+ Sd5#
'The Problemist' 07/2016, p. 420: "Plausible tries 1.d8R?, 1.b6? – the Pb5 shields both horizontally and diagonally. An alternative setting with Pb7 on b6 (in 34 moves) would include the try 1.d8Q? (Composer). Really wonderful, with wPb5 timing its moves exquisitely to shield bK – surely a prizewinner in due course (CCL [aka C.C. Lytton] – whose credentials to comment include previously holding the record at 4 queens)."
'The Problemist' 07/2016, p. 420: "Plausible tries 1.d8R?, 1.b6? – the Pb5 shields both horizontally and diagonally. An alternative setting with Pb7 on b6 (in 34 moves) would include the try 1.d8Q? (Composer). Really wonderful, with wPb5 timing its moves exquisitely to shield bK – surely a prizewinner in due course (CCL [aka C.C. Lytton] – whose credentials to comment include previously holding the record at 4 queens)."
Stephen Emmerson in 'The Problemist': "George’s F3272 is a formidable promotion task for which the only hint I’ll give is that the wK does not move."
Henrik Juel: A most impressive task (2022-08-19)
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Henrik Juel: A most impressive task (2022-08-19)
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Keywords: Seriesmover, Task (Construction), Promotion (DDDDDDD), konsekutive Umwandlungen 7 (DDDDDDD)
Genre: Fairies
FEN: 7n/1P1P3P/3p4/kP1p2bp/5n1P/3pK3/3P3P/8
Input: Mario Richter, 2022-08-19
Last update: Rainer Staudte, 2022-08-19 more...
Genre: Fairies
FEN: 7n/1P1P3P/3p4/kP1p2bp/5n1P/3pK3/3P3P/8
Input: Mario Richter, 2022-08-19
Last update: Rainer Staudte, 2022-08-19 more...
1. c1=S Kb1 2. Sb3 axb3 3. Se4 b4 4. d2 b5 5. d1=S b6 6. Se3 b7 7. S3f5 b8=S 8. Sg5 Sd7#
Turnier-Thema: h#8, one solution, with wS(s) + bS(s).
Turnier-Thema: h#8, one solution, with wS(s) + bS(s).
Keywords: Entblockung, Excelsior white, konsekutive Umwandlungen 3 (ssS), Liniensperrung, Model mate, Check Protection, Selfblock, Promotions to Knights, under-promotion (Sss), under-promotion key, Minimal (B)
Genre: h#
FEN: 8/4nqb1/4pkb1/8/8/p2p4/P1p2n2/K7
Reprints: 4 The Problemist 283 01/2022
Input: Gunter Jordan, 2023-02-09
Last update: Gunter Jordan, 2023-02-09 more...
Genre: h#
FEN: 8/4nqb1/4pkb1/8/8/p2p4/P1p2n2/K7
Reprints: 4 The Problemist 283 01/2022
Input: Gunter Jordan, 2023-02-09
Last update: Gunter Jordan, 2023-02-09 more...
1. f2 Ka3 2. f1=S Ka4 3. Sg3 hxg3 4. Lf5 g4 5. h2 gxf5 6. h1=D fxe6 7. Dh2 e7 8. Dd6 exd8=S#
Turnier-Thema: h#8, one solution, with wS(s) + bS(s).
Turnier-Thema: h#8, one solution, with wS(s) + bS(s).
Keywords: Antiphönix, Entblockung, Excelsior white, konsekutive Umwandlungen 3 (sdS), Model mate, Phoenix, Rückkehr nach Umwandlung (b/d), Selfblock, Promotion (d), Promotions to Knights, under-promotion (Ss), under-promotion in mating move, Minimal (B)
Genre: h#
FEN: 3b4/2nn4/1rk1p3/2pp4/6bp/5p1p/K6P/8
Reprints: 9 The Problemist , p. 306, 01/2022
Input: Gunter Jordan, 2023-02-09
Last update: Gunter Jordan, 2023-02-09 more...
Genre: h#
FEN: 3b4/2nn4/1rk1p3/2pp4/6bp/5p1p/K6P/8
Reprints: 9 The Problemist , p. 306, 01/2022
Input: Gunter Jordan, 2023-02-09
Last update: Gunter Jordan, 2023-02-09 more...
1) 1. ... b8=D+ 2. Kg4+ Df4+ 3. Kh5 Dd2 4. Le3 fxe3 5. Kg4 Dd1 6. Kg3 Dg1#
2) 1. ... b8=T 2. b2+ Txb2 3. d2+ Kxc2 4. d1=S Kd3 5. Se3 Te2 6. Sf5 Te4#
2) 1. ... b8=T 2. b2+ Txb2 3. d2+ Kxc2 4. d1=S Kd3 5. Se3 Te2 6. Sf5 Te4#
Yuri Bilokin: you can see 1.h2 b8=Q+ 2.Kg4+ Qf4+ 3.Kh3 Qe3 4.Bf6 Qxf3#
1.h2 b8=Q+ 2.Kg4+ Qf4+ 3.Kh3 Qe3 4.Be7 Qxf3#
1.h2 b8=Q+ 2.Kg4+ Qf4+ 3.Kh3 Qe3 4.Bd8 Qxf3#
1.Bf6 b8=Q+ 2.Kg4 Qxb3 3.h2 Qd5 4.Kh3 Qxf3# (2024-02-29)
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1.h2 b8=Q+ 2.Kg4+ Qf4+ 3.Kh3 Qe3 4.Be7 Qxf3#
1.h2 b8=Q+ 2.Kg4+ Qf4+ 3.Kh3 Qe3 4.Bd8 Qxf3#
1.Bf6 b8=Q+ 2.Kg4 Qxb3 3.h2 Qd5 4.Kh3 Qxf3# (2024-02-29)
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Keywords: Checking key (in 1), Promotion key (in 1), under-promotion key (in 2), under-promotion (ts in 2), konsekutive Umwandlungen 2 (ts in 2), bi-coloured Bristol (in 1), Cross check (in 1), Discovered check (in 1), selfpinning (in 1), Unpinning (in 1), Switchback (k in 1), Model mate (in 1), Exchange of Promotions
Genre: h#
FEN: 5n1n/1P6/8/6b1/5k1p/pppp1p1p/2p2P2/2K5
Input: Gunter Jordan, 2023-04-10
Last update: Felber, Volker, 2023-10-15 more...
Genre: h#
FEN: 5n1n/1P6/8/6b1/5k1p/pppp1p1p/2p2P2/2K5
Input: Gunter Jordan, 2023-04-10
Last update: Felber, Volker, 2023-10-15 more...
1. g8=S+! Txg8 2. Lg7+ Txg7 3. Th8+ Th7 4. Dg4 Txh8 5. Dg5+ Kh7 6. f8=S+ Txf8#
Henrik Juel: Popeye 4.61 with 'opt non 0 1' found no flaws (2023-06-08)
SCHRECKE: C+, Gustav 4.2c, Brute Force (2023-06-08)
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SCHRECKE: C+, Gustav 4.2c, Brute Force (2023-06-08)
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Keywords: konsekutive Umwandlungen 2 (SS), Promotion key (S), Minimal
Genre: s#
FEN: 4Rr1B/4NPP1/4PK1k/4PQ2/8/8/8/8
Input: Rainer Staudte, 2023-06-08
Last update: Rainer Staudte, 2023-06-08 more...
Genre: s#
FEN: 4Rr1B/4NPP1/4PK1k/4PQ2/8/8/8/8
Input: Rainer Staudte, 2023-06-08
Last update: Rainer Staudte, 2023-06-08 more...
1) 1. Kxc2 d4 2. Lc1 d5 3. Te6 dxe6 4. Lb2 e7 5. Kc1 e8=D 6. c2 De1#
2) 1. Lc5+ Kxc3 2. Te5 Kb3 3. Kd2 Kb2 4. Ke3 Kc1 5. Kd4 Kd2 6. d5 c3#
2) 1. Lc5+ Kxc3 2. Te5 Kb3 3. Kd2 Kb2 4. Ke3 Kc1 5. Kd4 Kd2 6. d5 c3#
Keywords: Capture key (in 1), Entblockung, Promotion (D), Selfblock, Square vacation, Switchback (k), Klasinc theme (k-l), Model mate (in 1), Checking key (in 2), Ideal mate (in 2), Remote selfblock (in 2), Tschumakow Theme, Pawn mate (in 2)
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/8/3p4/8/1K6/2pPb3/2P5/2k1r3
Input: Felber, Volker, 2023-11-29
Last update: Gunter Jordan, 2024-03-26 more...
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/8/3p4/8/1K6/2pPb3/2P5/2k1r3
Input: Felber, Volker, 2023-11-29
Last update: Gunter Jordan, 2024-03-26 more...
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The problems of this query have been registered by the following contributors:
Gerd Wilts (7)hpr (2)
Hans-Jürgen Schäfer (1)
Henri Nouguier (1)
Brian Stephenson (2)
Frank Müller (6)
YM (1)
HBae (4)
Felber, Volker (11)
Hans Gruber (1)
Erich Bartel (1)
Marcin Banaszek (1)
Gunter Jordan (6)
A.Buchanan (1)
Mario Richter (2)
Rainer Staudte (1)
Silvio Baier: Mit 30....dc+ ist das C+ (Euclide 0.98, Retractor für den letzten Zug) (2011-07-08)
James Malcom: So this is fully C+? (2021-01-27)
Henrik Juel: No, another problem in 30.0 moves ending with 30. Tc2 dxc4+ is tested OK (2021-01-27)
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