Die Schwalbe

16 problem(s) found in 6119 milliseconds (displaying 16 problem(s)). [COMMENTDATE>=20200919 AND NOT S='Vart Land' AND A='Petrovic, Tomislav'] [download as LaTeX]

1 - P0003287
Tomislav Petrovic
(VIII) Problem 37-40 09/1956
P0003287
(5+9) C+
h#2
1. fxg3ep h8=S 2. Sg4 Sxg6#
play all play one stop play next play all
A.Buchanan: The point I think is that the en passant is a tempo move. Otherwise wBf2 serves no purpose. How about sBh5 instead of sT? (2021-10-19)
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Keywords: En passant as key, Promotion (S), Tempo Move
Genre: h#, Retro
Computer test: HC+ Popeye v4.61 & trivial retro-logic
FEN: 8/7P/6pP/6pr/5pPk/4np1n/5P1p/7K
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-19 more...
2 - P0003335
Tomislav Petrovic
(XXI) Problem 37-40 09/1956
P0003335
(5+9) cooked
h#9
1. dxc3ep dxc3+ 2. Ka5 c4 3. d2 c5 4. d1=L c6 5. Lg4 hxg4 6. Kb6 g5 7. Ka7 g6 8. Kb8 g7 9. Kc8 g8=D/T#
play all play one stop play next play all
Cook: 1. b2 c5 2. b1=S c6 3. Sc3 dxc3+ 4. Ka5 cxd4 5. Kb6 d5 6. Ka7 d6 7. Kb8 dxc7+ 8. Ka7 c8=D 9. a5 Db7#
paul: See P0003212 as version. (2011-08-06)
Anton Baumann: C+?? Die Aufgabe ist eindeutig inkorrekt! (2021-01-27)
James Malcom: Fixed. (2021-01-27)
comment
Keywords: En passant as key, Promotion (D), konsekutive Umwandlungen 2 (L, D/T), En passant, Kindergarten Problem
Genre: h#, Retro
FEN: 8/2p5/p7/8/1kPp3p/1p1p2pP/3P2Pp/7K
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-01-27 more...
3 - P0003430
Tomislav Petrovic
(XIII) Problem 37-40 09/1956
P0003430
(4+15) cooked
h#3
1. dxe3ep Td1? 2. Le4 Txd6 3. Sg4 Tf6# usual AP try
1. dxe3ep 0-0-0! 2. Le4 Txd6 3. Sg4 Tf6#
play all play one stop play next play all
Cook: 1. dxe3ep 0-0-0 2. Lf5 Txd6 3. Sf3 Td4#
not
1. dxe3ep Td1? 2. Lf5 Txd6 3. Sf3+ ?? usual AP try and also check Bl 3rd move
Henrik Juel: The missing black man is dark-squared, so last move was not fxe4. In the solution Td6 should read Txd6. There seems to be a 'variation': 0... dxe3ep 1.0-0-0 Le4 2.Txd6 Sg4 3.Tf6#, so maybe the stipulation should have 1.1;2.1;1.1 added. (2004-09-23)
A.Buchanan: Well spotted Henrik. Your kindness is legendary, but in the harsh world of helpmates, this counts as a cooked I believe. In fact, it's the 2.Lf5/3.Sf3 version which is the cook. Yours is the actual solution! This is because 3.Sf3 would check if White hadn't castled, and we want the castling to be because of the AP condition only, not for 2 reasons, which one might term a "logical dual". The problem can be trivially fixed by sticking sSe5 on f6. I have no idea whether it's a typo or a cook: WinChloe has the same diagram, and the same confusion between cook & intended solution. The fact that AP does not appear in the stipulation might be a factor. WinChloe as far as I can see has no concept of AP as a keyword, and just picks it up based on a substring of the stipulation. In other compositions, T.Petrovic wasn't shy of flashing the AP acronym in the stipulation, but as usual the detective work peters out in the absence of primary records. (2020-12-08)
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Keywords: En passant as key, Castling (wg), a posteriori (AP) (Type Petrovic), Superseded by (P1382802)
Genre: h#, Retro
Computer test: Popeye v4.85 + retro thinking
FEN: 1n1r4/p1B4p/1p1p4/p3n1p1/3pPk2/3b4/pr5q/R3K3
Reprints: (60) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-02-16 more...
4 - P0003431
Tomislav Petrovic
(XIV) Problem 37-40 09/1952
P0003431
(8+14) cooked
h#3
1. cxb3ep+ c3 2. Ld3 Tg4+ 3. Kh1 0-0-0#
play all play one stop play next play all
paul: White captures was axb and g2xh3, so the retro move c3xb4 is not possible. If b3-b4, the retro check is not justified. So last move was b2-b4 (preceded by Rc3-a3). (2011-08-06)
A.Buchanan: There's a lot to unpack here. Firstly, the intended solution has a definite transposition dual in the order of Black's 2nd & 3rd moves. Second, the pawn capture count is wrong. What happened to the original wBh, given sBh2 never left the h-file? Thirdly, and not a showstopper, White's only solution involves castling: so that's a logical dual. (2020-12-08)
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Keywords: En passant as key, Castling
Genre: h#, Retro
Computer test: Popeye v4.85 + retro thinking
FEN: 3r3n/p7/pp6/bP1q4/RPp5/r3p2P/p1P1P1kp/Rb2K3
Reprints: (61) Problem 144-147 12/1971
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-05-02 more...
5 - P0004192
Tomislav Petrovic
(IX) Problem 37-40 09/1956
P0004192
(14+8) C+
h#2*
1. ... dxc6ep 2. dxc3 Lxb6#
1. dxe3 Sd4 2. e2 Sc6#
play all play one stop play next play all
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Keywords: En passant as key, Interchange (Sb)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & trivial retro-logic
FEN: B5Rr/k4pPp/1p3P1p/1KpPP2N/2Pp4/2PPB3/2P1N3/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2021-10-23 more...
6 - P0009121
Tomislav Petrovic
2949 Phénix 69 12/1998
P0009121
(10+9) C+
h#2 (AP)
1. fxe3ep d8=S 2. Kxd5 0-0-0# (Td1#?)
play all play one stop play next play all
White has made 6 pawn captures with one missing black piece unaccounted for, that by parity can only have been captured by an officer. White's last move cannot have been a pawn capture. If R: 1.f2-f3, then sLg1 was promoted, implying 7 captures by black pawns - one too many. So if White can prove they retain castling rights, then the ep is on. Hence AP Petrovic is valid.
Henrik Juel: 0... fxe3ep 1.d8S Kxd5 2.0-0-0#. Not -1.f2? and Lg1 is caught. (2004-09-16)
Vaclav Kotesovec: Similar problems should not be labeled as "C+". Such a designation is only acceptable if the entire analysis was performed by a computer program. (2023-08-03)
Henrik Juel: In principle I agree, Vaclav
But PDB does not (yet) allow HC+, so I find it acceptable to use the C+ label, when you also tell the whole story after 'Computer test:' below (2023-08-03)
A.Buchanan: Hopefully Gerd will have more time at some point, and can expand the functionality in this and other areas. In the meantime, engine solving of conventional retros including AP, is in its infancy. Retractor 2 has some effectiveness, but is still basic. And there is nothing that yet grasps the intricacies of castling/ep etc. However AP problems do often contain considerable forward chess, and the C+ tag is very useful to filter out those that have already been solved forwardly, without pretending that these are in any sense fully solved (2023-08-04)
Ladislav Packa: I know the definition of AP, but I don't understand the logic behind it. The move 1.fxe3 e.p. proves that White CAN castling. But the solution (2. ...Rd1#?) claims that castling is MANDATORY. From my point of view, AP is correct when only castling is necessary for the solution and the Rook move would be a dual. (2023-08-04)
A.Buchanan: @Ladislav: I am not sure how to help you. Maybe you can read this page from Retro Corner: https://www.janko.at/Retros/Glossary/APosteriori.htm (2023-08-05)
Ladislav Packa: Andrew, what should the article help me with? I quote the final sentence:
Some people still oppose this rule and argue that it should certainly not be the default convention. (2023-08-05)
Henrik Juel: You could view it this way, Ladislav
h#2 means that it is Black to move, so White made last move
What was last move? A little analysis shows just three possibilities: f2-f4, move by Ta1, or move by Ke1
So normally we cannot assume that last move was f2-f4
But if White can castle, then the last move was f2-f4
So if we could start with 0... 0-0-0, then 1.fxe3ep would be legitimate
AP says that you are allowed to reverse the sequence of events; first do the ep capture, then later legitimize it by castling
Was this helpful? (2023-08-05)
Ladislav Packa: Henrik, you don't have to explain that to me. I've done a few AP issues myself, like P1348357. But that doesn't mean I agree with AP's logic. I already wrote it - the term "you can castle" is applied as "you must castle". But these are only problems where, in addition to castling, the Rook move can also be used, I consider that a dual.
From that point of view, the P1000662 issue is perfectly fine for me. (2023-08-05)
Joost de Heer: AP: By castling, you prove a posteriori that the ep-capture was not just a try but the actual solution. Without castling, the ep-solution just is that: a try.
So: Try 1. fe3 ep e8=S 2. Kd5 Rd1 - but ep capture not allowed, as there is no proof that f2-f4 must've been the last move.
Solution 1. fe3 ep e8=S 2. Kd5 OOO - Now the ep capture was justified because white castled, thereby proving that the last move before the diagram position indeed was f2-f4. (2023-08-06)
Joost de Heer: See e.g. P1052919 : The try is an ep capture which is unjustified. (2023-08-06)
A.Buchanan: OK Ladislav: I think I get your point. If one solution with castling justifies the e.p., then based on that certainty, why shouldn't an alternative solution with no castling *then* be allowed as well? There are problems in which one twin shows 0-0-0 and the other shows 0-0. Each is based on the other in a similar way, so the idea of dependency is not new. Why are we not allowed to add other "parasitic" solutions as well? Why can we only have the "paying" solutions? We can't say that we are restricted to one solution: that's not the way chess problems operate! And this is just in the help world - in the adversarial world it might get even more complicated. Is this your issue, Ladislav? (2023-08-07)
Ladislav Packa: I don't want to unnecessarily prolong this discussion. However, I will add one more note: in this position, white castling is also possible without e.p. in Black's 1st move. If B1 were an indifferent move, then white can 1...0-0-0! The Codex of Chess Composition writes about it in Article 16 (1):
Castling convention. Casting is permitted unless it can be proven that it is not permissible.
In our case, 0-0-0 is possible because White's last move exists - e2-e4! It does not matter if it is this move or some a2-a3, both moves are equivalent. EP does not prove the possibility of casting, it would be legal even without it. (2023-08-07)
A.Buchanan: Ladislav was what I wrote your issue pls? Y/N :-) (2023-08-07)
Ladislav Packa: I have no problem, I'm just expressing my own opinion about the AP convention. (2023-08-07)
A.Buchanan: OK cos I think the point I raised is a real one that should be addressed by theory some day. Clearly from the nice problem that you composed Ladislav you understand the mechanics very well. From a justification perspective it's all a bit iffy, but that's why it's controversial. Under RS it's really the only way one can end up actually eping, and it's proved compositionally fertile. So that's enough to justify (2023-08-08)
Ladislav Packa: No need to apologize. This is a normal discussion with different views on the issue. Maybe it will come to some conclusion.
I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p. (2023-08-08)
Joost de Heer: "I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p."
You misinterpret AP. The e.p. capture does not authorize castling, castling provides a justification later on (hence the 'a posteriori') for the legality of ep.
Usually, for ep justification you need to examine all game trees that lead to the diagram, and only if all game trees end with the double-step, then ep is allowed.
With AP, you examine all the game trees including the actual play. If all those game trees have as last move before the diagram position the double step, then ep is possible.
In this case, if white doesn't castle, then there are game trees which don't have as last move the double step, and therefore AP logic dictates that the ep capture was illegal. However, all game trees which lead to the diagram and which have castling in the actual play have as last move before the diagram position the double step, hence AP dictates that the ep capture is legal. (2023-08-09)
Ladislav Packa: Joost: A simple question - is white allowed to castle after any 1st move by black (except e.p.)? (2023-08-09)
Joost de Heer: Of course he is. AP only is used to combine the ep justification with castling, not the castling right per se. (2023-08-09)
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Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg), Promotion (S), Valladao Task
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 + simple retro-logic
FEN: 8/3P2p1/2PP4/1ppPp3/2pkPp2/5PP1/6Pp/R3K1b1
Input: Gerd Wilts, 1999-02-27
Last update: A.Buchanan, 2023-09-11 more...
7 - P0519781
Tomislav Petrovic
Problem 41-44 03/1957
4. Platz
BiH - Macedonien
P0519781
(14+10) C+
h#2*
*) 1. ... dxc6ep 2. dxc3 Lxb6#
1) 1. dxe3 Dxg7 2. Kxb7 Dxd7#
2) 1. Lxb7 Sc6+ 2. Ka8 Sc7#
play all play one stop play next play all
pawns history:
Bl: axb,exd,f=
Wh: hxgxh,gxh,fxgxh,cxd,a=,e=
All accounted for.
Bl can't uncapture axb or exd else block promotion.
If WTM, Bl just played c7-c5 so ep is on
A.Buchanan: WinChloe doesn't think this problem is cooked at all. It says there are two full solutions, with "Echange de place de pièces noires entre les positions finales" i.e. Kb7 La8 vs Ka8 Lb7. WinChloe does not cover the (single) set play. Must the number of set plays normally match the number of full solutions? I will mark this problem HC+ uncooked. (2021-10-31)
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Keywords: En passant as key, Sacrifice of white pieces
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 + simple retro logic.
FEN: bN6/kB1p2p1/Np1P4/1KpP3P/1prp3P/1PQRB2P/2R4p/8
Input: Hans-Jürgen Schäfer, 1997-10-11
Last update: A.Buchanan, 2021-10-31 more...
8 - P1000901
Tomislav Petrovic
3 feenschach 137, p. 340, 08-09/2000
Zdravko Maslar gewidmet
P1000901
(14+8) C+
s#2
1. dxc6ep!
1. ... dxc6+ 2. Lxc6 Sc7#
1. ... d6 2. d5 Sc7#
1. ... d5 2. exd5 Sc7#
1. ... dxe6 2. e5 Sc7#
1. ... gxf6 2. Sf5 Sc7#
1. ... g6 2. Lxg6 Sc7#
1. ... g5 2. Sg4 Sc7#
1. ... gxh6 2. Lh5 Sc7#
play all play one stop play next play all
James Malcom: This is a most excellent problem! En passant as the key and a double pickaninny in a short s#2 is surely no easy feat, I'd say. Now, question: Why can't dxc5 be Black's last move? The illegal retraction od b6-b7 is already quite obvious. (2020-10-24)
A.Buchanan: R: 1. cxb6/dxc5? both imply 3 pawn captures by Bl (2020-10-24)
A.Buchanan: I agree this is a beautifully integrated composition (2020-10-24)
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Keywords: En passant, Pickaninny (2x), En passant as key, Grab
Genre: Retro, s#
Computer test: C+ Popeye 4.61 after retro-analysis shows that last move was c7-c5
FEN: n2RB3/k2p2pR/Pp2PP1N/bKpP4/PpNPP3/1P6/8/8
Input: Gerd Wilts, 2000-10-08
Last update: A.Buchanan, 2020-10-25 more...
9 - P1066741
Tomislav Petrovic
R033 Probleemblad 11-12/1998
Ing. R. Tomasevic gewidmet
P1066741
(14+10) C+
h#2 (AP)
1. gxf3ep 0-0-0 2. gxh1=T gxh4#
play all play one stop play next play all
White PCs: axb=, bxc=, dxexf, cxdxe
Black PCs: fxg2. wRh was captured by officer in cage, and since wK didn’t move wRg5 is promoted
A.Buchanan: Suppose White: dxexf,cxdxe,bxc=,a| Black: fxg. This means there is one capture by white unaccounted for. So can’t White have just played e.g. QxS? What am I missing? (2022-03-22)
Mario Richter: Regarding the "can’t White have just played e.g. QxS?-question", the following considerations may be helpful:
1. black Pawn f3 x Yg2 can only be retracted after wPf2 has returned home.
2. If at this moment the black K is still on g1, Y cannot be a white rook.
3. Assuming that W can still castle, wRg5 must be a promoted Piece, since wKe1+wPf2+wPg3+wPh2 form a cage from which the originalwRh1 could not escape ...

I think the same considerations can also be useful by answering the question about +sBc6 ... (2022-03-22)
A.Buchanan: Hi Mario, thanks I agree (2022-03-22)
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Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg), Valladao Task, Promotion (t)
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 & retro-logic
FEN: 1B6/p2p4/1p4Q1/5PRN/4PPpb/3Np1Pp/4P1pP/R3KbkB
Input: Gerd Wilts, 2004-09-16
Last update: A.Buchanan, 2023-09-11 more...
10 - P1066823
Tomislav Petrovic
The Ural's Problemist 04-06/2004
2. Thematurnier
4. ehrende Erwähnung
P1066823
(10+4) cooked
s#6
1. hxg6ep Kh5 2. Dg4+ Kh6 3. Dh5+ Kxh5 4. g4+ Kh6 5. f4 fxe6+ 6. dxe6 hxg6#
play all play one stop play next play all
Cook: Retro logic doesn’t work
(As well as major dual)
So unsound
SCHRECKE: Konnte zuletzt nicht auch 0. ... Kg7-h6 geschehen sein? (2021-02-15)
A.Buchanan: I think the diagram must be wrong. Not only does the retro logic fail, but also there is a dual 2. Df3+,Dg4+. It's not in WinChloe. (2021-02-15)
Mario Richter: An additional white Pawn e7 would justify the epkey, but not prevent the mentioned dual. (2021-02-16)
VL: We might shift wPf2 to f3 against the dual. Or exchange Bf6 with Pf2 and add wP on f3 (instead of e7)... (2021-02-16)
A.Buchanan: Shifting wBf2 to f3 leads to short cook solutions 1.Dh2. However I think 8/5p1p/4NB1k/3PPKpP/4P3/8/5PP1/2Q5 fixes the retro issue, and it's C+ by Popeye, with still ideal mate! The composer Tomislav Petrovic is still alive but would be very old (90). Is he still active? (2021-02-17)
A.Buchanan: By the way, if you query for k='foo', that will always return uses of the keyword "foobar". It's just checking for the prefix. If you omit k='foo', then that will also block "foobar". Therefore if we tag with "en passant as key", then we should not tag with "en passant" too. Both keywords should exist, and over time we may refine uses of "en passant" to be more precise.
Because of the sensible way prefixes are handled in PDB, this is a different situation from tagging a problem as both "ceriani-frolkin" and "prentos", which we should do.
On this general subject, when counting instances within a single problem, we should always use Gerd's excellent mechanism of parameters "foo:1" etc, rather than having separate keywords "foo 1", "foo 2" etc. Otherwise the set of keywords becomes unmanageable. (2021-02-17)
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Keywords: En passant as key, Ideal mate, Superseded by (P1386589)
Genre: Retro, s#
FEN: 8/5p1p/4PB1k/3PPKpP/4PQ2/8/5PP1/8
Input: Frank Müller, 2004-11-01
Last update: A.Buchanan, 2021-02-18 more...
11 - P1072281
Werner Keym
Tomislav Petrovic

Hannoversche Allgemeine Zeitung 1999
P1072281
(4+3) C+
h#1.5 (AP)
1. ... cxb6ep 2. 0-0-0 b7#
play all play one stop play next play all
Very elegant representation of AP Type Petrovic. Keym himself established in the Codex that the stipulation should include "AP".
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Keywords: En passant as key, Miniature, a posteriori (AP) (Type Petrovic), Castling
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 together with elementary reflection
FEN: r3k3/8/N1P5/KpP5/8/8/8/8
Reprints: (A2) Problemkiste (169), p. 6, 02/2007
Input: hpr, 2007-03-04
Last update: A.Buchanan, 2023-09-11 more...
12 - P1072354
Tomislav Petrovic
(H17) Problemkiste 165, p. 214, 06/2006
P1072354
(5+1) C+
h#2.5
1. ... c3+ 2. Kxa4 Lb5+ 3. Ka5 b4#
play all play one stop play next play all
Letzter Zug: Ka5-b4
A.Buchanan: A small group of similar problems forces some short Round Trip across past and forward play. The last move is not uniquely defined (it may be a capture) and is not mentioned in the stipulation. However the genre includes retro. This means that an aesthetic criterion (e.g. existence of Round Trip) can define whether a composition is subject to 50 move rule or dead position rule! (2021-10-31)
comment
Keywords: Pure Round Trip (k), Miniature, Rex solus
Genre: h#, Retro
Computer test: (Popeye WINDOWS-32Bit V4.05 (1708292 KB))
FEN: 8/8/2K5/8/PkB5/8/1PP5/8
Input: hpr, 2007-03-14
Last update: A.Buchanan, 2021-10-31 more...
13 - P1189828
Tomislav Petrovic
H2957 The Problemist 03/2006
4. Lob
P1189828
(2+5) C+
h#5
1. d1=L La6 2. Lg4 Lxc4 3. Ld7 Kb6 4. 0-0-0 Ld5 5. Sb8 Lb7#
play all play one stop play next play all
Yuri Bilokin: Compare P1189828 (2024-04-03)
comment

Genre: h#
Computer test: Popeye Windows-32Bit v4.51 (100000 KB)
FEN: r3k3/1BK5/2n5/8/2n5/8/3p4/8
Input: hpr, 2011-03-10
Last update: hpr, 2011-03-10 more...
14 - P1199302
Tomislav Petrovic
4334 Problemkiste (110) 04/1997
P1199302
(2+9) C+
ser-PW in 30
1. Kg1 2. Kf1 3. Ke1 4. Kd1 5. Kc1 6. Kb1 7. Ka2 8. Ka3 9. Kb4 19. Kc5 11. Kd6 12. Ke7 13. Kxf6 14. Kg7 15. Kxh7 16. Kh6 17. Kxh5 18. Kh4 19. Kxh3 20. Kh4 21. Kg5 22. h4 23. h5 24. h6 25. h7 26. h8=T 27. Th1 28. Kh4 29. Kh3 30. Kh2 PW
play all play one stop play next play all
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Keywords: Excelsior, Interchange (K-B), Kindergarten Problem, Seriesmover, Minimal
Genre: Fairies
Computer test: popeye 4.87
FEN: 8/5p1p/5p2/7p/2p5/2pp1k1p/7P/7K
Input: Erich Bartel, 2011-07-22
Last update: Arnold Beine, 2022-10-23 more...
15 - P1201821
Tomislav Petrovic
Problemkiste 1989
P1201821
(3+6) C+
ser-s#46
1. Kf2 2. Ke3 3. Kf4 4. Kg5 5. Kh4 6. Kh3 7. Kxh2 8. Kh3 9. Kh4 10. Kg5 11. Kf4 12. Kxf3 13. Kg4 14. Kh5 15. g4 16. g5 17. g6 18. Kh6 19. Kg7 20. Kf8 21. g7 22. g8=D 23. De6 24. Kf7 25. Kf6 26. Ke5 27. Dd5 28. Kd4 29. Kc5 30. Dc6 31. Kb6 32. Kb7 33. Kb8 34. a8=D 35. Dab7 36. Ka7 37. Kb6 38. Kc5 39. Dd5 40. Kd4 41. Ke5 42. De6 43. Kf6 44. Kf7 45. Kf8 46. Df6+ Txf6#
play all play one stop play next play all
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Keywords: Seriesmover, Move Length Record, Promotion (DD)
Genre: Fairies
Computer test: Gustav 4.2a
FEN: 3k4/P2p4/3r4/8/8/5bP1/7n/4K1r1
Reprints: 187 398 Zuglängenrekorde im Serienzüger 2003
Input: Frank Müller, 2011-09-03
Last update: Arnold Beine, 2022-10-23 more...
16 - P1346371
Tomislav Petrovic
H3 Problemkiste (159-160) 07/2005
P1346371
(9+4)
h#0,5
3 Lösungen
1) 0,5 ... -sBb5# (Teil von axb6ep)
2) 0,5 ... -sBf5# (Teil von gxf6ep)
3) 0,5 ... Tad1# (2. Teil von 0-0-0)
play all play one stop play next play all
A.Buchanan: This is definitely not h#0.5 rather it's h#0.25 or #0.5.
This is retro joke not fairy, imho (2022-03-03)
comment
Keywords: Half-moves, Castling, En passant, Complete an unfinished move, Joke
Genre: Retro
FEN: 8/7Q/BP3P2/1p2Rp2/3p4/1P1k4/1P6/R1K5
Input: Erich Bartel, 2018-01-31
Last update: A.Buchanan, 2022-03-03 more...
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The problems of this query have been registered by the following contributors:

Gerd Wilts (8)
Hans-Jürgen Schäfer (1)
Frank Müller (2)
hpr (3)
Erich Bartel (2)