Die Schwalbe

6 problem(s) found in 2700 milliseconds (displaying 6 problem(s)). [COMMENTDATE>=20220810 AND G='Retro' AND NOT K='Beamtenschach' AND A='Oudot, Jean'] [download as LaTeX]

1 - P0001285
Jean Oudot
370 Die Schwalbe 07/1960
R. Bédoni gewidmet
P0001285
(11+11) C+
h#2*
* 1. ... dxc5 2. Dxh3 0-0-0#
1. Db2 Le2+ 2. Kc2 Ld1#
play all play one stop play next play all
Henrik Juel: the five missing black men were captured by white pawns (exfxgxh, fxgxj), so with Black to move last move was with Ta1 or Ke1, and White may not castle
C+ Popeye 4.61 (2022-11-26)
A.Buchanan: Pleasant White tempo play in both phases (2022-11-27)
comment
Keywords: Cant Castler (wl), Castling (wl)
Genre: Retro, h#
Computer test: HC+ Popeye 4.61 with simple retro logic
FEN: 8/7p/7P/2pr2pP/2bP2Pb/2pk1BRP/6qN/R3KNrn
Reprints: 553 FIDE Album 1959-1961 1966
157 Europe Echecs 90 07/1966
(10) diagrammes 112 01-03/1995
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-27 more...
2 - P0001349
Jean Oudot
Echiquier de France 1957
P0001349
(14+7)
#2
Rosalie Fay: White has lost only the bishops. So the pawn on c5 is not [Pa7] (because that entails 2 White units captured on black squares). White has played axbxcxdxe7, dxe, fxe, hxg, gxfxe. Black has 7 units, so white pawns have captured all missing Black units, but none on the a or h files.

Black has 2 pawns on the c-file, so one has captured. Thus [bPa7] and [bPh7] pawns have collectively captured no more than once. So at least one of them must have promoted, in order to either get to a file where White made a capture, or replace a captured unit; it didn't capture en route to promotion, so it displaced a white rook and thus spoilt one White castling right.

White would mate by 1 Rd1 & 2 Rd6 or 1 Rf1 & 2 Rf6, except that Black threatens Qxe2+. So either 1 0-0 or 1 0-0-0, though it's impossible to say which is legal. (2022-11-24)
Henrik Juel: one solution, but in two parts
if Ta1 has moved, 1.0-0 thr. 2.Dc8,Tf6#
if Th1 has moved, 1.0-0-0 thr. 2.Dg8,Td6# (2022-11-25)
Hans-Jürgen Manthey: nach der möglichen Zugfolge: 1. Sb1-c3 c7-c6 2. Sc3-d5 Dd8-b6 3. Sg1-f3 Db6-b3 4. a2xDb3 a7-a5 5. Sd5-b4 a5-a4 6. Sb4-a2 e7-e5 7. Sf3-h4 Lf8-c5 8. Sh4-g6 f7-f5 9. Sg6-f4 g7-g5 10. Sf4-g6 Lc5-e3 11. d2xLe3 f5-f4 12. g2-g3 Ta8-a5 13. g3xf4 g5-g4 14. f4xe5 g4-g3 15. h2xg3 h7-h5 16. Lf1-g2 h5-h4 17. Lc1-d2 h4-h3 18. Ld2-b4 Th8-h4 19. c2-c3 Th4-c4 20. Sa2-c1 a4-a3 21. Lb4-c5 a3-a2 22. Dd1-d4 Sb8-a6 23. Dd4-h4 Sa6-c7 24. Dh4-d8+ Ke8-f7 25. b3xTc4 Sc7-d5 26. c4xSd5 Sg8-e7 27. d5-d6 Ta5-b5 28. d6xSe7 d7-d6 --- folgt nun
29. Lg2-e4 Lc8-e6 30. Le4-b1 a2xLb1D 31. Th1-g1 Db1-d3 32. Sc1-b3 Le6-c4 33. Th1-g1 h3-h2 34. Dd8-e8+ Kf7-e6 35. Tg1-h1 Tb5-b6 36. Th1-g1 Le6-c4 37. Tg1-h1 h3-h2 38. Th1-g1 h2-h1D 39. Sc1-b3 Dh1-e4 40. f2-f3 Lc4-a6 41. f3xDe4 d6xLc5 42. Dd8-e8+ Kf7-e6 43. Tg1-h1 Dd3-b5 matt in 2:
1. OOO droht 2. De8-g8/Td1-d6# - 1. ... Db5-d3 2. Sb3xc5# oder:
29. Sc1-b3 h3xLg2 30. Sb3-d2 g2-g1D+ 31. Sd2-f1 Dg1-g2 32. Sf1-d2 Dg2-e4 33. f2-f3 Tb5-b6 34. f3xDe4 d6xLc5 35. Sd2-b3 Lc8-e6 36. Ta1-b1 Le6-c4 37. Ta1-b1 Kf7-e6 38. Tb1-a1 Lc4-a6 39. Ta1-b1 a2-a1D 40. Dd8-e8 Da1-a4 41. Tb1-a1 Da4-b5 matt in 2: 1. OO bel. 2. De8-c8/Tf1-f6# (2023-02-22)
more ...
comment
Keywords: Partial Retro Analysis (PRA), Castling (wb)
Genre: Retro, 2#
FEN: 4Q3/1p2P3/brp1k1N1/1qp1P3/4P3/1NP1P1P1/1P2P3/R3K2R
Reprints: 223 Europe Echecs 130 09/1969
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-26 more...
3 - P0003630
Jean Oudot
652 Themes-64 10-12/1962
P0003630
(9+6) C+
h#2*
*) 1. ... 0-0#
1) 1. Dc5 Tf1+ 2. Df2 Txf2#
play all play one stop play next play all
A.Buchanan: White must cover g2. If not by check, then by rook. However Rf1 is check, so both Black's moves are forced to shield bK (2022-11-27)
more ...
comment
Keywords: Cant Castler, Castling (wk)
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: b7/7P/6p1/6qP/6Pb/3p1kNP/3P3P/4K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-27 more...
4 - P0003815
Jean Oudot
Nation Belge 1956
P0003815
(5+11) C+
#2
Kann der sTh3 durch einen sB ersetzt werden?
1. Ld8
1. ... Sf2/Sc3~ 2. De3#
1. ... Sa2/Sd1~ 2. Se2#
1. ... Kxf4 2. Lxc7#
1. ... g5 2. Sh5#
play all play one stop play next play all
Henrik Juel: with a black pawn on h3, we have all eight black pawns on the board, but none of them could come from a7 (2022-11-26)
comment

Genre: Retro, 2#
Computer test: C+ Popeye v4.87
FEN: 8/2p3p1/2p3p1/2Q3B1/5Npp/2n3kr/7p/K2n3B
Reprints: RA13 diagrammes 15 06/1975
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-27 more...
5 - P0003816
Jean Oudot
Nation Belge 1956
P0003816
(6+2) C+
#3
1. ... h6 2. La4 Kxa2 3. Tf3 Ka1 4. Ta3#
retro try: 1. Lg8?? h6 2. Tf7 Kxa2 3. Ta7#
play all play one stop play next play all
more ...
comment
Keywords: No legal last move for Black, Minimal
Genre: Retro, 3#
Computer test: C+ Popeye 4.61
FEN: 8/7p/8/7P/8/1B6/P1P2R2/k1K5
Reprints: RA14 diagrammes 15 06/1975
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-27 more...
6 - P0003817
Jean Oudot
Nation Belge 1956
P0003817
(14+12) C+
#2
1. cxd6ep
play all play one stop play next play all
paul: Since the wB couldnt leave c1, the captured piece on b6 is the promoted wPh2. If last black move was f7-f5, then h-Pawn captured four pieces to promote on d8, among which bRh8, impossible. Thus, the h-Pawn could only have been promoted from f7 and therefore d7-d5 remains as the last move. (2011-07-02)
more ...
comment
Keywords: En passant as key
Genre: Retro, 2#
Computer test: C+ Popeye 4.61
FEN: qrRNkb2/PpQ1p1pp/1pp1R3/2PpKpP1/6N1/7B/1P1PPP2/8
Reprints: RA15 diagrammes 15 06/1975
(51) Mat Plus 12 10-12/2009
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-27 more...
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