474 problem(s) found in 5190 milliseconds (displaying 100 problem(s)). [COMMENTDATE>=20220810 AND G='h#' AND NOT S='Problemist Ukrainy' AND CPLUS ] [download as LaTeX]
a) 1. ... exf6ep 2. 0-0-0 Lxf4 3. Td7 a8=D#
b) 1. ... Kxf4 2. Te7 e6 3. Tb8 axb8=D,T#
b) 1. ... Kxf4 2. Te7 e6 3. Tb8 axb8=D,T#
Keywords: En passant as key, Castling (sg), Cant Castler, Valladao Task
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & basic retro thinking
FEN: r3k3/P7/b3r1pP/4PpBP/3nnpKR/5PRB/5PP1/7N
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-16 more...
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & basic retro thinking
FEN: r3k3/P7/b3r1pP/4PpBP/3nnpKR/5PRB/5PP1/7N
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-16 more...
* 1. ... dxc5 2. Dxh3 0-0-0#
1. Db2 Le2+ 2. Kc2 Ld1#
1. Db2 Le2+ 2. Kc2 Ld1#
Henrik Juel: the five missing black men were captured by white pawns (exfxgxh, fxgxj), so with Black to move last move was with Ta1 or Ke1, and White may not castle
C+ Popeye 4.61 (2022-11-26)
A.Buchanan: Pleasant White tempo play in both phases (2022-11-27)
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C+ Popeye 4.61 (2022-11-26)
A.Buchanan: Pleasant White tempo play in both phases (2022-11-27)
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Keywords: Cant Castler (wl), Castling (wl)
Genre: Retro, h#
Computer test: HC+ Popeye 4.61 with simple retro logic
FEN: 8/7p/7P/2pr2pP/2bP2Pb/2pk1BRP/6qN/R3KNrn
Reprints: 553 FIDE Album 1959-1961 1966
157 Europe Echecs 90 07/1966
(10) diagrammes 112 01-03/1995
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-27 more...
Genre: Retro, h#
Computer test: HC+ Popeye 4.61 with simple retro logic
FEN: 8/7p/7P/2pr2pP/2bP2Pb/2pk1BRP/6qN/R3KNrn
Reprints: 553 FIDE Album 1959-1961 1966
157 Europe Echecs 90 07/1966
(10) diagrammes 112 01-03/1995
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-27 more...
1. ... cxd6ep 2. 0-0-0 0-0-0 3. Kd7 Sa7#
1. De7 c6 2. Th8 c7 3. Tf8 Sd6#
White pawn caps: axb,dxe,gxf,hxg.
Black: fxg,bxc,cxb.
wPb4 came from b3 to release wBa3, so bPb3 captured to reach that square.
All pcs accounted for means bPd never captured.
In the set play, there are 13 retro tries in which one or both players do not castle. The intention is that both castling rights are needed in order to imply the pawn double hop.
1. De7 c6 2. Th8 c7 3. Tf8 Sd6#
White pawn caps: axb,dxe,gxf,hxg.
Black: fxg,bxc,cxb.
wPb4 came from b3 to release wBa3, so bPb3 captured to reach that square.
All pcs accounted for means bPd never captured.
In the set play, there are 13 retro tries in which one or both players do not castle. The intention is that both castling rights are needed in order to imply the pawn double hop.
A.Buchanan: White pawn caps: axb,dxe,gxf,hxg definite.
Black: fxg and two to resolve c-file. But that may be c&d cross-capture, so in set play last move might have been c6xd5. So I think this problem is cooked. What am I missing? (2022-03-21)
Mario Richter: If Black's last move was c6xd5, how do you get white Bishop a3 out of his cage? (In that case, black pawn b7 never left the b-file). (2022-03-21)
A.Buchanan: I agree Mario thanks (2022-03-21)
Hans-Jürgen Manthey: beide Rochaden und im Satz ep. ist möglich:
R.: 1. ... d7-d5 2. Sa7-b5 b5xTc4 3. Tg4-c4 Dd8-h4 4. c4-c5 Th8-h3 5. c2-c4 c4xDb3 6. Dd3-b3 h3-h2 7. Dd1-d3 h4-h3 8. Sc8-a7 h5-h4 9. Th4-g4 c5-c4 10. Th1-h4 h7-h5 11. h2xSg3 Sf5-g3 12. b3-b4 Sh6-f5 13. Lb4-a3 c7-c5 14. Ld2-b4 g3-g2 15. Lc1-d2 a3-a2 16. a2xSb3 Sc5-b3 17. Lb3-a4 Sa6-c5 18. Lc4-b3 Sb8-a6 19. d2xLe3 Lc5-e3 20. Ld3-c4 Lf8-c5 21. Lf5-d3 a4-a3 22. Lh3-f5 a5-a4 23. Lf1-h3 g4-g3 24. g2xLf3 Lb7-f3 25. Sb6-c8 Lc8-b7 26. Sa4-b6 a7-a5 27. Sc3-a4 b7-b5 28. Sb1-c3 f5xSg4 29. Se5-g4 Sg8-h6 30. Sf3-e5 e7-e6 31. Sg5-f3 f6-f5 32. Sh3-g5 f7-f6 33. Sg1-h3 (2023-02-23)
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Black: fxg and two to resolve c-file. But that may be c&d cross-capture, so in set play last move might have been c6xd5. So I think this problem is cooked. What am I missing? (2022-03-21)
Mario Richter: If Black's last move was c6xd5, how do you get white Bishop a3 out of his cage? (In that case, black pawn b7 never left the b-file). (2022-03-21)
A.Buchanan: I agree Mario thanks (2022-03-21)
Hans-Jürgen Manthey: beide Rochaden und im Satz ep. ist möglich:
R.: 1. ... d7-d5 2. Sa7-b5 b5xTc4 3. Tg4-c4 Dd8-h4 4. c4-c5 Th8-h3 5. c2-c4 c4xDb3 6. Dd3-b3 h3-h2 7. Dd1-d3 h4-h3 8. Sc8-a7 h5-h4 9. Th4-g4 c5-c4 10. Th1-h4 h7-h5 11. h2xSg3 Sf5-g3 12. b3-b4 Sh6-f5 13. Lb4-a3 c7-c5 14. Ld2-b4 g3-g2 15. Lc1-d2 a3-a2 16. a2xSb3 Sc5-b3 17. Lb3-a4 Sa6-c5 18. Lc4-b3 Sb8-a6 19. d2xLe3 Lc5-e3 20. Ld3-c4 Lf8-c5 21. Lf5-d3 a4-a3 22. Lh3-f5 a5-a4 23. Lf1-h3 g4-g3 24. g2xLf3 Lb7-f3 25. Sb6-c8 Lc8-b7 26. Sa4-b6 a7-a5 27. Sc3-a4 b7-b5 28. Sb1-c3 f5xSg4 29. Se5-g4 Sg8-h6 30. Sf3-e5 e7-e6 31. Sg5-f3 f6-f5 32. Sh3-g5 f7-f6 33. Sg1-h3 (2023-02-23)
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Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wgsg)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & retro-logic.
FEN: r3k3/6p1/4p3/1NPp4/BPp4q/Bp2PPPr/pP2PPpp/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & retro-logic.
FEN: r3k3/6p1/4p3/1NPp4/BPp4q/Bp2PPPr/pP2PPpp/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-21 more...
1. exd3ep Lxg4 2. f3 Le6#
Klären: Quelle = Schachmatt? - Felber, Volker: SCHACH ist korrekt, 6/1969, Seite 191 (2010-10-09)
Eliminierung von 4 Steinen zwischen sK und wT im h#2 (mit Hilfe von ep-Schlag)!
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Eliminierung von 4 Steinen zwischen sK und wT im h#2 (mit Hilfe von ep-Schlag)!
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Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: 8/8/8/1pn4b/2kPpppR/2q1rB1p/1p4r1/3K4
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-01-09 more...
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: 8/8/8/1pn4b/2kPpppR/2q1rB1p/1p4r1/3K4
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-01-09 more...
a) 1. Sg3 Kxh4 2. Le4 hxg3#
b) 1. hxg3ep Kh4 2. Lf5 hxg3#
b) 1. hxg3ep Kh4 2. Lf5 hxg3#
Henrik Juel: in a) last move could be Kg2-h3
in b) last move must be g2-g4 (2024-01-14)
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in b) last move must be g2-g4 (2024-01-14)
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Keywords: En passant as key, Zeroposition
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 & trivial retro-logic
FEN: 8/7b/8/4pn2/4pkPp/4pp1K/7P/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-01-15 more...
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 & trivial retro-logic
FEN: 8/7b/8/4pn2/4pkPp/4pp1K/7P/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-01-15 more...
a) 1. Sxb4 Sxc3 2. Ka5 Sxc4#
b) 1. cxb3ep Sc4 2. Sb4 Sxc3#
b) 1. cxb3ep Sc4 2. Sb4 Sxc3#
1. cxd3ep? bxc3 2. Lxf4 Lxg2# Last move not d2-d4
1. gxf3ep! bxc3 2. Lf4 Lf5# Last move f2-f4
White's last move was certainly one of the two double pawn hops. The last move couldn't be d2-d4 because Black's pawns had already captured 10 of White's pieces, and playing d2-d4 would have resulted in wBc1 being White's 17th piece. So, the only solution is 1.gxf3 e.p.
1. gxf3ep! bxc3 2. Lf4 Lf5# Last move f2-f4
White's last move was certainly one of the two double pawn hops. The last move couldn't be d2-d4 because Black's pawns had already captured 10 of White's pieces, and playing d2-d4 would have resulted in wBc1 being White's 17th piece. So, the only solution is 1.gxf3 e.p.
Viktoras Paliulionis: The last move couldn't be d2-d4 because Black's pawns had already captured 10 of White's pieces, and playing d2-d4 would have resulted in wBc1 being White's 17th piece. So, the only solution is 1.gxf3 e.p. (2023-12-30)
A.Buchanan: Yes that's right! (2023-12-31)
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A.Buchanan: Yes that's right! (2023-12-31)
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Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye C-Version 4.87 & trivial retro-logic
FEN: 2n1q3/5prp/5K1b/3b4/2pPkPp1/2p1p1pB/1P4pP/8
Reprints: 546 FIDE Album 1962-1964 1968
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-31 more...
Genre: h#, Retro
Computer test: HC+ Popeye C-Version 4.87 & trivial retro-logic
FEN: 2n1q3/5prp/5K1b/3b4/2pPkPp1/2p1p1pB/1P4pP/8
Reprints: 546 FIDE Album 1962-1964 1968
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-31 more...
1. exf3ep c3 2. Df7 Ke4 3. Dh5 exf3#
A.Buchanan: Can shift bQd5 to c4, while replacing bRg5 with bP to reach Meredith status. bBh4 can also be downgraded to bP. But probably even more economy is possible by shifting pieces one file to the right, keeping the ep, White tempo & model mate, which seem to be the main features (2022-11-30)
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Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: 8/8/8/3q2r1/2p1pPkb/4K1pp/2PrP3/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-30 more...
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: 8/8/8/3q2r1/2p1pPkb/4K1pp/2PrP3/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-11-30 more...
a) 1. f3 Lxa7 2. Lg5 Lxf2#
b) 1. fxg3ep Lxc7 2. Lh5 Ld8#
b) 1. fxg3ep Lxc7 2. Lh5 Ld8#
Henrik Juel: a) C+ Popeye 4.61
b) the ep capture is unjustified, last move could be Ke2-f1 or f3xg4 (2023-08-06)
A.Buchanan: There was an error in the stipulation: "b) sLe3 nach h2 (-wSh2)" is completely incorrect. However "b) sLe3 nach f3" leads to a very nice problem which matches the solution already present. This problem is not in WinChloe, but I am sure this is the resolution of the mystery (2023-08-07)
Henrik Juel: You are probably right, Andrew; maybe there was a misprint in the source
Now part b) is C+ Popeye 4.61 after very simple analysis (2023-08-07)
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b) the ep capture is unjustified, last move could be Ke2-f1 or f3xg4 (2023-08-06)
A.Buchanan: There was an error in the stipulation: "b) sLe3 nach h2 (-wSh2)" is completely incorrect. However "b) sLe3 nach f3" leads to a very nice problem which matches the solution already present. This problem is not in WinChloe, but I am sure this is the resolution of the mystery (2023-08-07)
Henrik Juel: You are probably right, Andrew; maybe there was a misprint in the source
Now part b) is C+ Popeye 4.61 after very simple analysis (2023-08-07)
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Keywords: En passant as key
Genre: h#, Retro
Computer test: HC+ Popeye v4.61 & simple retro-logic for b)
FEN: 1B6/npp5/8/8/5pPk/4b2p/3p1p1N/5Kn1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-08-07 more...
Genre: h#, Retro
Computer test: HC+ Popeye v4.61 & simple retro-logic for b)
FEN: 1B6/npp5/8/8/5pPk/4b2p/3p1p1N/5Kn1
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-08-07 more...
1. ... exf6ep 2. Sf5 f7#
White captured fxg and promoted [Pd2] on d8
Black captured axbxa2-a1=Y, b7xc6, d5xe4, and gxf
White cannot have moved last, and in fact Black's last move can only have been f7-f5 in order to give White a prior move. R: 1... d5-e4 would have retro-blocked wPd marching to its promotion.
So the retroplay was R: 1... f7-f5 2.f5xYg6
Numerous retro tries but none distinct.
White captured fxg and promoted [Pd2] on d8
Black captured axbxa2-a1=Y, b7xc6, d5xe4, and gxf
White cannot have moved last, and in fact Black's last move can only have been f7-f5 in order to give White a prior move. R: 1... d5-e4 would have retro-blocked wPd marching to its promotion.
So the retroplay was R: 1... f7-f5 2.f5xYg6
Numerous retro tries but none distinct.
"Autor Ing. Rudolf Buljan, Zagreb"
AB: Have therefore marked him in the author table as Croatian. Yugoslavia has been removed from the PDB country list, I see.
A.Buchanan: Any ideas how to distinguish usage of “whose move?” and “no legal last move for white” (or black) keywords (2020-10-01)
Henrik Juel: This problem is clearly the latter
I would use 'Whose move?' in retro problems where a deeper analysis is required to determine the move, often with stipulations like '#1 (who?)' (2020-10-01)
A.Buchanan: I think "Whose move?" is where there is no forward stip, or where we have to determine if the forward stip should be interpreted as orthodox or as half-duplex. "no legal last move for..." is where the mater/stalemater/etc is the usual one, but we add or remove a single move at the beginning of the forward stip. I guess a third possibility is "last move?" where in a Type A position we also have to figure out who moved last.
With respect, I don't think the level of analysis can be relevant. (2023-12-06)
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AB: Have therefore marked him in the author table as Croatian. Yugoslavia has been removed from the PDB country list, I see.
A.Buchanan: Any ideas how to distinguish usage of “whose move?” and “no legal last move for white” (or black) keywords (2020-10-01)
Henrik Juel: This problem is clearly the latter
I would use 'Whose move?' in retro problems where a deeper analysis is required to determine the move, often with stipulations like '#1 (who?)' (2020-10-01)
A.Buchanan: I think "Whose move?" is where there is no forward stip, or where we have to determine if the forward stip should be interpreted as orthodox or as half-duplex. "no legal last move for..." is where the mater/stalemater/etc is the usual one, but we add or remove a single move at the beginning of the forward stip. I guess a third possibility is "last move?" where in a Type A position we also have to figure out who moved last.
With respect, I don't think the level of analysis can be relevant. (2023-12-06)
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Keywords: En passant as key, No legal last move for White
Genre: h#, Retro
Computer test: Popeye 4.61
FEN: 5nkb/1qp1p1n1/2p3PQ/4PpKb/4prRp/P4prB/1PP3PP/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-06 more...
Genre: h#, Retro
Computer test: Popeye 4.61
FEN: 5nkb/1qp1p1n1/2p3PQ/4PpKb/4prRp/P4prB/1PP3PP/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-06 more...
1. Kb3 Kd2 2. Ka4 Kc3 3. a2 Txa2#
Nicht 1. Kb3 0-0-0?? 2. Ka2 Td3 3. Ka1 Txa3#, da Weiß zuletzt mit K oder T gezogen hat
Nicht 1. Kb3 0-0-0?? 2. Ka2 Td3 3. Ka1 Txa3#, da Weiß zuletzt mit K oder T gezogen hat
1. ... Sf5? 2. 0-0-0?? Sd6# - aber die s0-0-0 ist illegal, den zuletzt muß Schwarz mit K oder T gezogen haben.
1. ... Sg8! 2. Td8 Sc7#
1. ... Sg8! 2. Td8 Sc7#
Mario Richter: Luboš Kekely (Slovakia) correctly points out that 1. ... Sf5! 2. 0-0-0 Sd6# is only a try and not a solution (last black move must have been by King or Rook, so the queenside castling is illegal).
I have changed the solution accordingly. (2023-03-10)
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I have changed the solution accordingly. (2023-03-10)
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*) 1. ... 0-0#
1) 1. Dc5 Tf1+ 2. Df2 Txf2#
1) 1. Dc5 Tf1+ 2. Df2 Txf2#
a) 1. Ta6! Lxc3 2. Ta2 0-0#
b) 1. Ta5! Kd1 2. Ta2 Kc2#
b) 1. Ta5! Kd1 2. Ta2 Kc2#
Henrik Juel: In b) White may not castle, because last move was done by Ke1 or Th1 (2023-12-02)
A.Buchanan: Cute. Do wPe2 & bPe3 serve any purpose, however? (2023-12-03)
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A.Buchanan: Cute. Do wPe2 & bPe3 serve any purpose, however? (2023-12-03)
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Keywords: Cant Castler, Castling (wk), Superseded by (P1413924)
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 & simple retro logic
FEN: 5n1q/6B1/5r2/7r/5p2/2p1p3/1P2P3/k3K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-05 more...
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 & simple retro logic
FEN: 5n1q/6B1/5r2/7r/5p2/2p1p3/1P2P3/k3K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-05 more...
a) 1. 0-0 Tcg3 2. Sh8 Txg7#
b) 1. 0-0-0 Tgc4 2. Sb8 Txc7#
b) 1. 0-0-0 Tgc4 2. Sb8 Txc7#
Keywords: Castling, Cant Castler, Obvious promotion (T), Twin
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: r3k2r/1pp3pp/2n3n1/8/6R1/2R4P/4P1P1/5B1K
Input: Gerd Wilts, 1995-06-03
Last update: Gunter Jordan, 2022-12-01 more...
Genre: h#, Retro
Computer test: HC+ Popeye 4.61
FEN: r3k2r/1pp3pp/2n3n1/8/6R1/2R4P/4P1P1/5B1K
Input: Gerd Wilts, 1995-06-03
Last update: Gunter Jordan, 2022-12-01 more...
a) 1. fxg1=S Dxe3 2. Sd2 Df2#
b) 1. ... Dxe3 2. c1=S Dc3#
a) R: 1. d2xc3
b) WTM, so solution in a) can't work here.
b) 1. ... Dxe3 2. c1=S Dc3#
a) R: 1. d2xc3
b) WTM, so solution in a) can't work here.
Retro
b) Weiß am Zug
Adrian Storisteanu: Two knight promotions differently motivated.
The technical challenge was in averting the short second solution in a) as set play, in order to keep the two phases nicely apart, and also, of course, preventing black tempi and potential white retro moves. (2000-11-20)
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b) Weiß am Zug
Adrian Storisteanu: Two knight promotions differently motivated.
The technical challenge was in averting the short second solution in a) as set play, in order to keep the two phases nicely apart, and also, of course, preventing black tempi and potential white retro moves. (2000-11-20)
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Keywords: No legal last move for White, Promotion (s,s)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & simple retro logic
FEN: 8/8/8/8/8/2P1p1P1/ppp1ppRP/bqQbknRK
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-06 more...
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & simple retro logic
FEN: 8/8/8/8/8/2P1p1P1/ppp1ppRP/bqQbknRK
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-06 more...
1. ... e5 2. g4 Le4#
1. Lxf4 e5 2. Lh2 Le4#
1. Lxf4 e5 2. Lh2 Le4#
A.Buchanan: Setplay doesn't care whether the position is legal. (2023-12-06)
A.Buchanan: So is this a retro problem? I think not. (2023-12-06)
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A.Buchanan: So is this a retro problem? I think not. (2023-12-06)
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Keywords: No legal last move for Black (setplay doesn't care), Tempo Move
Genre: h#
Computer test: HC+ Popeye v4.87 & trivial retro-logic
FEN: 8/8/5PBP/6pP/4PP2/8/5K1b/7k
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-06 more...
Genre: h#
Computer test: HC+ Popeye v4.87 & trivial retro-logic
FEN: 8/8/5PBP/6pP/4PP2/8/5K1b/7k
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-06 more...
1. fxe3ep d8=S 2. Kxd5 0-0-0# (Td1#?)
White has made 6 pawn captures with one missing black piece unaccounted for, that by parity can only have been captured by an officer. White's last move cannot have been a pawn capture. If R: 1.f2-f3, then sLg1 was promoted, implying 7 captures by black pawns - one too many. So if White can prove they retain castling rights, then the ep is on. Hence AP Petrovic is valid.
White has made 6 pawn captures with one missing black piece unaccounted for, that by parity can only have been captured by an officer. White's last move cannot have been a pawn capture. If R: 1.f2-f3, then sLg1 was promoted, implying 7 captures by black pawns - one too many. So if White can prove they retain castling rights, then the ep is on. Hence AP Petrovic is valid.
Henrik Juel: 0... fxe3ep 1.d8S Kxd5 2.0-0-0#. Not -1.f2? and Lg1 is caught. (2004-09-16)
Vaclav Kotesovec: Similar problems should not be labeled as "C+". Such a designation is only acceptable if the entire analysis was performed by a computer program. (2023-08-03)
Henrik Juel: In principle I agree, Vaclav
But PDB does not (yet) allow HC+, so I find it acceptable to use the C+ label, when you also tell the whole story after 'Computer test:' below (2023-08-03)
A.Buchanan: Hopefully Gerd will have more time at some point, and can expand the functionality in this and other areas. In the meantime, engine solving of conventional retros including AP, is in its infancy. Retractor 2 has some effectiveness, but is still basic. And there is nothing that yet grasps the intricacies of castling/ep etc. However AP problems do often contain considerable forward chess, and the C+ tag is very useful to filter out those that have already been solved forwardly, without pretending that these are in any sense fully solved (2023-08-04)
Ladislav Packa: I know the definition of AP, but I don't understand the logic behind it. The move 1.fxe3 e.p. proves that White CAN castling. But the solution (2. ...Rd1#?) claims that castling is MANDATORY. From my point of view, AP is correct when only castling is necessary for the solution and the Rook move would be a dual. (2023-08-04)
A.Buchanan: @Ladislav: I am not sure how to help you. Maybe you can read this page from Retro Corner: https://www.janko.at/Retros/Glossary/APosteriori.htm (2023-08-05)
Ladislav Packa: Andrew, what should the article help me with? I quote the final sentence:
Some people still oppose this rule and argue that it should certainly not be the default convention. (2023-08-05)
Henrik Juel: You could view it this way, Ladislav
h#2 means that it is Black to move, so White made last move
What was last move? A little analysis shows just three possibilities: f2-f4, move by Ta1, or move by Ke1
So normally we cannot assume that last move was f2-f4
But if White can castle, then the last move was f2-f4
So if we could start with 0... 0-0-0, then 1.fxe3ep would be legitimate
AP says that you are allowed to reverse the sequence of events; first do the ep capture, then later legitimize it by castling
Was this helpful? (2023-08-05)
Ladislav Packa: Henrik, you don't have to explain that to me. I've done a few AP issues myself, like P1348357. But that doesn't mean I agree with AP's logic. I already wrote it - the term "you can castle" is applied as "you must castle". But these are only problems where, in addition to castling, the Rook move can also be used, I consider that a dual.
From that point of view, the P1000662 issue is perfectly fine for me. (2023-08-05)
Joost de Heer: AP: By castling, you prove a posteriori that the ep-capture was not just a try but the actual solution. Without castling, the ep-solution just is that: a try.
So: Try 1. fe3 ep e8=S 2. Kd5 Rd1 - but ep capture not allowed, as there is no proof that f2-f4 must've been the last move.
Solution 1. fe3 ep e8=S 2. Kd5 OOO - Now the ep capture was justified because white castled, thereby proving that the last move before the diagram position indeed was f2-f4. (2023-08-06)
Joost de Heer: See e.g. P1052919 : The try is an ep capture which is unjustified. (2023-08-06)
A.Buchanan: OK Ladislav: I think I get your point. If one solution with castling justifies the e.p., then based on that certainty, why shouldn't an alternative solution with no castling *then* be allowed as well? There are problems in which one twin shows 0-0-0 and the other shows 0-0. Each is based on the other in a similar way, so the idea of dependency is not new. Why are we not allowed to add other "parasitic" solutions as well? Why can we only have the "paying" solutions? We can't say that we are restricted to one solution: that's not the way chess problems operate! And this is just in the help world - in the adversarial world it might get even more complicated. Is this your issue, Ladislav? (2023-08-07)
Ladislav Packa: I don't want to unnecessarily prolong this discussion. However, I will add one more note: in this position, white castling is also possible without e.p. in Black's 1st move. If B1 were an indifferent move, then white can 1...0-0-0! The Codex of Chess Composition writes about it in Article 16 (1):
Castling convention. Casting is permitted unless it can be proven that it is not permissible.
In our case, 0-0-0 is possible because White's last move exists - e2-e4! It does not matter if it is this move or some a2-a3, both moves are equivalent. EP does not prove the possibility of casting, it would be legal even without it. (2023-08-07)
A.Buchanan: Ladislav was what I wrote your issue pls? Y/N :-) (2023-08-07)
Ladislav Packa: I have no problem, I'm just expressing my own opinion about the AP convention. (2023-08-07)
A.Buchanan: OK cos I think the point I raised is a real one that should be addressed by theory some day. Clearly from the nice problem that you composed Ladislav you understand the mechanics very well. From a justification perspective it's all a bit iffy, but that's why it's controversial. Under RS it's really the only way one can end up actually eping, and it's proved compositionally fertile. So that's enough to justify (2023-08-08)
Ladislav Packa: No need to apologize. This is a normal discussion with different views on the issue. Maybe it will come to some conclusion.
I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p. (2023-08-08)
Joost de Heer: "I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p."
You misinterpret AP. The e.p. capture does not authorize castling, castling provides a justification later on (hence the 'a posteriori') for the legality of ep.
Usually, for ep justification you need to examine all game trees that lead to the diagram, and only if all game trees end with the double-step, then ep is allowed.
With AP, you examine all the game trees including the actual play. If all those game trees have as last move before the diagram position the double step, then ep is possible.
In this case, if white doesn't castle, then there are game trees which don't have as last move the double step, and therefore AP logic dictates that the ep capture was illegal. However, all game trees which lead to the diagram and which have castling in the actual play have as last move before the diagram position the double step, hence AP dictates that the ep capture is legal. (2023-08-09)
Ladislav Packa: Joost: A simple question - is white allowed to castle after any 1st move by black (except e.p.)? (2023-08-09)
Joost de Heer: Of course he is. AP only is used to combine the ep justification with castling, not the castling right per se. (2023-08-09)
more ...
comment
Vaclav Kotesovec: Similar problems should not be labeled as "C+". Such a designation is only acceptable if the entire analysis was performed by a computer program. (2023-08-03)
Henrik Juel: In principle I agree, Vaclav
But PDB does not (yet) allow HC+, so I find it acceptable to use the C+ label, when you also tell the whole story after 'Computer test:' below (2023-08-03)
A.Buchanan: Hopefully Gerd will have more time at some point, and can expand the functionality in this and other areas. In the meantime, engine solving of conventional retros including AP, is in its infancy. Retractor 2 has some effectiveness, but is still basic. And there is nothing that yet grasps the intricacies of castling/ep etc. However AP problems do often contain considerable forward chess, and the C+ tag is very useful to filter out those that have already been solved forwardly, without pretending that these are in any sense fully solved (2023-08-04)
Ladislav Packa: I know the definition of AP, but I don't understand the logic behind it. The move 1.fxe3 e.p. proves that White CAN castling. But the solution (2. ...Rd1#?) claims that castling is MANDATORY. From my point of view, AP is correct when only castling is necessary for the solution and the Rook move would be a dual. (2023-08-04)
A.Buchanan: @Ladislav: I am not sure how to help you. Maybe you can read this page from Retro Corner: https://www.janko.at/Retros/Glossary/APosteriori.htm (2023-08-05)
Ladislav Packa: Andrew, what should the article help me with? I quote the final sentence:
Some people still oppose this rule and argue that it should certainly not be the default convention. (2023-08-05)
Henrik Juel: You could view it this way, Ladislav
h#2 means that it is Black to move, so White made last move
What was last move? A little analysis shows just three possibilities: f2-f4, move by Ta1, or move by Ke1
So normally we cannot assume that last move was f2-f4
But if White can castle, then the last move was f2-f4
So if we could start with 0... 0-0-0, then 1.fxe3ep would be legitimate
AP says that you are allowed to reverse the sequence of events; first do the ep capture, then later legitimize it by castling
Was this helpful? (2023-08-05)
Ladislav Packa: Henrik, you don't have to explain that to me. I've done a few AP issues myself, like P1348357. But that doesn't mean I agree with AP's logic. I already wrote it - the term "you can castle" is applied as "you must castle". But these are only problems where, in addition to castling, the Rook move can also be used, I consider that a dual.
From that point of view, the P1000662 issue is perfectly fine for me. (2023-08-05)
Joost de Heer: AP: By castling, you prove a posteriori that the ep-capture was not just a try but the actual solution. Without castling, the ep-solution just is that: a try.
So: Try 1. fe3 ep e8=S 2. Kd5 Rd1 - but ep capture not allowed, as there is no proof that f2-f4 must've been the last move.
Solution 1. fe3 ep e8=S 2. Kd5 OOO - Now the ep capture was justified because white castled, thereby proving that the last move before the diagram position indeed was f2-f4. (2023-08-06)
Joost de Heer: See e.g. P1052919 : The try is an ep capture which is unjustified. (2023-08-06)
A.Buchanan: OK Ladislav: I think I get your point. If one solution with castling justifies the e.p., then based on that certainty, why shouldn't an alternative solution with no castling *then* be allowed as well? There are problems in which one twin shows 0-0-0 and the other shows 0-0. Each is based on the other in a similar way, so the idea of dependency is not new. Why are we not allowed to add other "parasitic" solutions as well? Why can we only have the "paying" solutions? We can't say that we are restricted to one solution: that's not the way chess problems operate! And this is just in the help world - in the adversarial world it might get even more complicated. Is this your issue, Ladislav? (2023-08-07)
Ladislav Packa: I don't want to unnecessarily prolong this discussion. However, I will add one more note: in this position, white castling is also possible without e.p. in Black's 1st move. If B1 were an indifferent move, then white can 1...0-0-0! The Codex of Chess Composition writes about it in Article 16 (1):
Castling convention. Casting is permitted unless it can be proven that it is not permissible.
In our case, 0-0-0 is possible because White's last move exists - e2-e4! It does not matter if it is this move or some a2-a3, both moves are equivalent. EP does not prove the possibility of casting, it would be legal even without it. (2023-08-07)
A.Buchanan: Ladislav was what I wrote your issue pls? Y/N :-) (2023-08-07)
Ladislav Packa: I have no problem, I'm just expressing my own opinion about the AP convention. (2023-08-07)
A.Buchanan: OK cos I think the point I raised is a real one that should be addressed by theory some day. Clearly from the nice problem that you composed Ladislav you understand the mechanics very well. From a justification perspective it's all a bit iffy, but that's why it's controversial. Under RS it's really the only way one can end up actually eping, and it's proved compositionally fertile. So that's enough to justify (2023-08-08)
Ladislav Packa: No need to apologize. This is a normal discussion with different views on the issue. Maybe it will come to some conclusion.
I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p. (2023-08-08)
Joost de Heer: "I just want to point out the fact that it is not the e.p. that authorizes castling, because according to the Codex castling is possible regardless of the e.p. It's the exact opposite: castling authorizes the possibility of e.p."
You misinterpret AP. The e.p. capture does not authorize castling, castling provides a justification later on (hence the 'a posteriori') for the legality of ep.
Usually, for ep justification you need to examine all game trees that lead to the diagram, and only if all game trees end with the double-step, then ep is allowed.
With AP, you examine all the game trees including the actual play. If all those game trees have as last move before the diagram position the double step, then ep is possible.
In this case, if white doesn't castle, then there are game trees which don't have as last move the double step, and therefore AP logic dictates that the ep capture was illegal. However, all game trees which lead to the diagram and which have castling in the actual play have as last move before the diagram position the double step, hence AP dictates that the ep capture is legal. (2023-08-09)
Ladislav Packa: Joost: A simple question - is white allowed to castle after any 1st move by black (except e.p.)? (2023-08-09)
Joost de Heer: Of course he is. AP only is used to combine the ep justification with castling, not the castling right per se. (2023-08-09)
more ...
comment
Keywords: a posteriori (AP) (Type Petrovic), En passant as key, Castling (wg), Promotion (S), Valladao Task
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 + simple retro-logic
FEN: 8/3P2p1/2PP4/1ppPp3/2pkPp2/5PP1/6Pp/R3K1b1
Input: Gerd Wilts, 1999-02-27
Last update: A.Buchanan, 2023-09-11 more...
Genre: Retro, h#
Computer test: HC+ Popeye v4.87 + simple retro-logic
FEN: 8/3P2p1/2PP4/1ppPp3/2pkPp2/5PP1/6Pp/R3K1b1
Input: Gerd Wilts, 1999-02-27
Last update: A.Buchanan, 2023-09-11 more...
19 - P0500385
Zdravko Maslar
3371 Die Schwalbe 67, p. 209, 02/1981
2. ehrende Erwähnung
(6+9) C+
h#3
Zdravko Maslar
3371 Die Schwalbe 67, p. 209, 02/1981
2. ehrende Erwähnung
(6+9) C+
h#3
1. Sf3 Th1 2. Dxh1+ Kxg3 3. Da1 d4#
zunächst für die 3. ehrende Erwähnung vorgesehen, wegen Disqualifikation von P0532932 hochgerutscht (vergl. 'Die Schwalbe' 08/1984 S.308)
Anton Baumann: Nachträglich zur 2. ehrenden Erwähnung aufgerückt (vergl. 'Die Schwalbe' 08/1984 S.308) (2022-12-23)
comment
Anton Baumann: Nachträglich zur 2. ehrenden Erwähnung aufgerückt (vergl. 'Die Schwalbe' 08/1984 S.308) (2022-12-23)
comment
Keywords: Sacrifice of white pieces
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/5p2/3P1kpp/6pq/p2P2p1/P1B3Kn/R7
Reprints: 773 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1996-06-06
Last update: Mario Richter, 2022-12-23 more...
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/5p2/3P1kpp/6pq/p2P2p1/P1B3Kn/R7
Reprints: 773 FIDE Album 1980-1982 1988
Input: Gerd Wilts, 1996-06-06
Last update: Mario Richter, 2022-12-23 more...
1) 1. ... g4 2. e6 g5 3. Ke7 g6 4. Td8 gxf7 5. Td7 f8=D#
2) 1. ... g3 2. Kd7 g4 3. Td8 g5 4. Ke8 g6 5. Sd7 gxf7#
Numerous retro tries but none distinct
2) 1. ... g3 2. Kd7 g4 3. Td8 g5 4. Ke8 g6 5. Sd7 gxf7#
Numerous retro tries but none distinct
Keywords: Promotion in the mating move, Excelsior white (auto key), No legal last move for White, Minimal
Genre: h#, Retro
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 4k2r/4ppK1/5n1p/8/8/8/6P1/8
Reprints: 365 Minimalkunst im Schach 2006
Input: Gerd Wilts, 1996-06-06
Last update: A.Buchanan, 2023-12-08 more...
Genre: h#, Retro
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 4k2r/4ppK1/5n1p/8/8/8/6P1/8
Reprints: 365 Minimalkunst im Schach 2006
Input: Gerd Wilts, 1996-06-06
Last update: A.Buchanan, 2023-12-08 more...
1. f1=S Kf4 2. Se3 dxe3 3. d2 e4 4. d1=S e5 5. Se3 e6 6. Sf5 e7 7. Sg7 exf8=S#
Unterverwandlung!Springer!3-fach
Yuri Bilokin: more economical bNh6-f6(-bPf6), bPh5-d5, then a1=b1 6n1/6b1/6nk/4p3/8/4p1K1/4P1p1/8 (2+7) h#7
1.g1=S Kg4 2.Sf3 exf3 3.e2 f4 4.e1=S f5 5.Sf3 f6 6.Sg5 f7 7.Sh7 fxg8=S# (MM)
Slow Excelsior. Active sacrifice (black). Annihilation.
Excelsior (white). Long-trip (bS, promoted, 3) Phoenix. Promotion (Sss, 1, 2)
Model mate × 1 (2023-05-10)
more ...
comment
Yuri Bilokin: more economical bNh6-f6(-bPf6), bPh5-d5, then a1=b1 6n1/6b1/6nk/4p3/8/4p1K1/4P1p1/8 (2+7) h#7
1.g1=S Kg4 2.Sf3 exf3 3.e2 f4 4.e1=S f5 5.Sf3 f6 6.Sg5 f7 7.Sh7 fxg8=S# (MM)
Slow Excelsior. Active sacrifice (black). Annihilation.
Excelsior (white). Long-trip (bS, promoted, 3) Phoenix. Promotion (Sss, 1, 2)
Model mate × 1 (2023-05-10)
more ...
comment
Keywords: Excelsior white (auto key), under-promotion
Genre: h#
Computer test: C+ PY V3.52.--
FEN: 5n2/5p2/5pkn/7p/8/3p1K2/3P1p2/8
Reprints: 198 Ideal-Mate Encyclopedia Vol.1 1999
Input: Gerd Wilts, 1996-06-06
Last update: Erich Bartel, 2011-07-06 more...
Genre: h#
Computer test: C+ PY V3.52.--
FEN: 5n2/5p2/5pkn/7p/8/3p1K2/3P1p2/8
Reprints: 198 Ideal-Mate Encyclopedia Vol.1 1999
Input: Gerd Wilts, 1996-06-06
Last update: Erich Bartel, 2011-07-06 more...
1) 1. Lc3 Df6 2. Td4 Df1 3. Dc4 Db1#
2) 1. Lf7+ Kh7 2. Dc3 Kh6 3. Lc4 Df5#
2) 1. Lf7+ Kh7 2. Dc3 Kh6 3. Lc4 Df5#
Grimshaw
Yuri Bilokin: more economical bPg2-f3, bRd8-g2, bBg8-h5(-bNh5), -bPb5 7K/2qr4/8/4Q2b/3b4/3kpp2/3pn1r1/8 (2+10) 2.1…
1.Bc3 Qf6 2.Rd4 Qb6 3.Qc4 Qb1# (MM)
1.Bf7 Kh7 2.Qc3 Kh6 3.Bc4 Qf5# (MM)
Amazon theme. Blocking piece replacement (bB-bR)
Check prevention (W-W). Hideaway maneuver (wK, 2)
Long-trip (wQ, 3). Pelle move (white)
Play on the same square (B3, 2)
Model mate × 2 (2024-02-09)
comment
Yuri Bilokin: more economical bPg2-f3, bRd8-g2, bBg8-h5(-bNh5), -bPb5 7K/2qr4/8/4Q2b/3b4/3kpp2/3pn1r1/8 (2+10) 2.1…
1.Bc3 Qf6 2.Rd4 Qb6 3.Qc4 Qb1# (MM)
1.Bf7 Kh7 2.Qc3 Kh6 3.Bc4 Qf5# (MM)
Amazon theme. Blocking piece replacement (bB-bR)
Check prevention (W-W). Hideaway maneuver (wK, 2)
Long-trip (wQ, 3). Pelle move (white)
Play on the same square (B3, 2)
Model mate × 2 (2024-02-09)
comment
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 3r2bK/2qr4/8/1p2Q2n/3b4/3kp3/3pn1p1/8
Input: Gerd Wilts, 1996-06-06
Last update: hpr, 1999-05-20 more...
23 - P0501066
Henry Olof Axel Forsberg
599-603 Revista Romana de Sah 01/1935
1. Preis
Pauly Gedenkturnier 1935
(3+2) C+
h#2
b) sTa6 statt sDa6
c) sLa6 statt sDa6
d) sSa6 statt sDa6
e) sBa6 statt sDa6
Henry Olof Axel Forsberg
599-603 Revista Romana de Sah 01/1935
1. Preis
Pauly Gedenkturnier 1935
(3+2) C+
h#2
b) sTa6 statt sDa6
c) sLa6 statt sDa6
d) sSa6 statt sDa6
e) sBa6 statt sDa6
a) 1. Df6 Sc5 2. Db2 Ta4#
b) 1. Tb6 Tb1 2. Tb3 Ta1#
c) 1. Lc4 Se1 2. La2 Sc2#
d) 1. Sc5 Sc1 2. Sa4 Tb3#
e) 1. a5 Tb3+ 2. Ka4 Sc5#
b) 1. Tb6 Tb1 2. Tb3 Ta1#
c) 1. Lc4 Se1 2. La2 Sc2#
d) 1. Sc5 Sc1 2. Sa4 Tb3#
e) 1. a5 Tb3+ 2. Ka4 Sc5#
Das namensgebende [Stamm-]Problem für dieses Thema (=Forsberg-Zwilling).
Erich Bartel: weitere Nachdrucke:
13) 197 moving on 2008.---
14) Naef:Endspielstudien Hilfmattprobleme und Märchenschachaufgaben 1998,S.72.--- (2008-10-01)
Jacques Rotenberg: 5982, CHM 1995, G. Lestriguel
p.1315, Le Guide des Echecs 1993
5 p.8, The Modern Helpmate in Two, Z. Janevski & N. Stolev 1989
XIII p.151, Thèmes-64 10 (avr. 58)
XII bis p.38, Rex Multiplex 2 (avr. 82)
285, Svenska Miniatyrer I, A.Uddgren & A. Hildebrand 1996
p.76, Im Wunderland des Schachproblems, E. Ramin 1958
E-1 p.236, StrateGems 12 (oct. 00)
I33 p.1333, Phénix 14 (sept. 91)
3 p.219, Le Genre Aidé Supplément diagrammes 15 (juin 75)
161 p.241, Echecs, N. Ramini 1985
E p.14, Best Problems 21 (jan. 02)
259 p.238, Chess Problems : Introduction to an Art, M. Lipton, R.C.O. Matthews, J. Rice 1963
139, Skakopgaven 1942
135 p.31, Album FIDE 1914-44/III
9 p.403, feenschach 26 (déc. 74)
40 p.61, Europe Echecs 330 (juin 86)
p.185, feenschach 47 (juil. 79)
in WinChloe, you find also :
A p.5, Springaren 17 (mars 84)
p.50, feenschach 73 (jan. 85)
M p.171, The Problemist (sept. 81)
p.415, feenschach 97 (nov. 90)
133 p.104, Solving in Style, J. Nunn 1985
E-I p.43, Probleemblad 58/1 (jan. 00)
E-1 p.102, Probleemblad 58/3 (mai 00)
p.136, Springaren 70 (août 97)
4 p.4424, diagrammes 159 (oct. 06)
p.37, Problem-Forum 36 (déc. 08) (2012-03-10)
A.Buchanan: The position is unique (except for left-right reflection). In particular, it cannot be shifted up or down without breaking (b) and only the current location of wK makes (b) sound and (a)&(d) solvable. (2017-01-27)
Anton Baumann: in Revista de Sah 1936 soll Henry Forsberg eine weitere Möglichkeit gezeigt haben:
f) wSa6 statt sDa6: 1.Ka2 Sac5 2.Ka3 Ta4# (C+)
Ferner mit Märchenschachfiguren: vergl. P1349128 (2022-12-28)
more ...
comment
Erich Bartel: weitere Nachdrucke:
13) 197 moving on 2008.---
14) Naef:Endspielstudien Hilfmattprobleme und Märchenschachaufgaben 1998,S.72.--- (2008-10-01)
Jacques Rotenberg: 5982, CHM 1995, G. Lestriguel
p.1315, Le Guide des Echecs 1993
5 p.8, The Modern Helpmate in Two, Z. Janevski & N. Stolev 1989
XIII p.151, Thèmes-64 10 (avr. 58)
XII bis p.38, Rex Multiplex 2 (avr. 82)
285, Svenska Miniatyrer I, A.Uddgren & A. Hildebrand 1996
p.76, Im Wunderland des Schachproblems, E. Ramin 1958
E-1 p.236, StrateGems 12 (oct. 00)
I33 p.1333, Phénix 14 (sept. 91)
3 p.219, Le Genre Aidé Supplément diagrammes 15 (juin 75)
161 p.241, Echecs, N. Ramini 1985
E p.14, Best Problems 21 (jan. 02)
259 p.238, Chess Problems : Introduction to an Art, M. Lipton, R.C.O. Matthews, J. Rice 1963
139, Skakopgaven 1942
135 p.31, Album FIDE 1914-44/III
9 p.403, feenschach 26 (déc. 74)
40 p.61, Europe Echecs 330 (juin 86)
p.185, feenschach 47 (juil. 79)
in WinChloe, you find also :
A p.5, Springaren 17 (mars 84)
p.50, feenschach 73 (jan. 85)
M p.171, The Problemist (sept. 81)
p.415, feenschach 97 (nov. 90)
133 p.104, Solving in Style, J. Nunn 1985
E-I p.43, Probleemblad 58/1 (jan. 00)
E-1 p.102, Probleemblad 58/3 (mai 00)
p.136, Springaren 70 (août 97)
4 p.4424, diagrammes 159 (oct. 06)
p.37, Problem-Forum 36 (déc. 08) (2012-03-10)
A.Buchanan: The position is unique (except for left-right reflection). In particular, it cannot be shifted up or down without breaking (b) and only the current location of wK makes (b) sound and (a)&(d) solvable. (2017-01-27)
Anton Baumann: in Revista de Sah 1936 soll Henry Forsberg eine weitere Möglichkeit gezeigt haben:
f) wSa6 statt sDa6: 1.Ka2 Sac5 2.Ka3 Ta4# (C+)
Ferner mit Märchenschachfiguren: vergl. P1349128 (2022-12-28)
more ...
comment
Keywords: Forsberg Twins, Aristocrat, Model mate
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/q7/8/1R4K1/k2N4/8/8
Reprints: 6 The Chess Review , p. 25, 12/1945
141 Zwillinge und Mehrlinge 1952
Schach-Echo Vol.11, p. 151, 1953
5 The Problemist 01/1962
761 Szachy 06/1965
Problemschach [Sidler] , p. 140, 1968
Problem 127-132, p. 95, 09/1969
9) feenschach 26, p. 403, 12/1974
135 FIDE Album 1914-1944/III 1975
83 Schach ohne Partner [Grasemann] 1977
feenschach 47, p. 185, 07-09/1979
XII Rex Multiplex 2, p. 38, 04-06/1982
67 100 Classics of the Chessboard 1983
Belfort , p. 75, 1994
Tim Krabbé's Website (57) 2000
E-I Probleemblad 01-02/2000
harmonie 63 09/2000
König & Turm 4, p. 13, 03/2001
986 Minimalkunst im Schach 2006
Problemkiste 163 02/2006
633 Encyclopedia of Chess Problems 2012
Input: Gerd Wilts, 1996-06-06
Last update: Dieter Berlin, 2022-02-09 more...
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/q7/8/1R4K1/k2N4/8/8
Reprints: 6 The Chess Review , p. 25, 12/1945
141 Zwillinge und Mehrlinge 1952
Schach-Echo Vol.11, p. 151, 1953
5 The Problemist 01/1962
761 Szachy 06/1965
Problemschach [Sidler] , p. 140, 1968
Problem 127-132, p. 95, 09/1969
9) feenschach 26, p. 403, 12/1974
135 FIDE Album 1914-1944/III 1975
83 Schach ohne Partner [Grasemann] 1977
feenschach 47, p. 185, 07-09/1979
XII Rex Multiplex 2, p. 38, 04-06/1982
67 100 Classics of the Chessboard 1983
Belfort , p. 75, 1994
Tim Krabbé's Website (57) 2000
E-I Probleemblad 01-02/2000
harmonie 63 09/2000
König & Turm 4, p. 13, 03/2001
986 Minimalkunst im Schach 2006
Problemkiste 163 02/2006
633 Encyclopedia of Chess Problems 2012
Input: Gerd Wilts, 1996-06-06
Last update: Dieter Berlin, 2022-02-09 more...
1) 1. Kc3+ Sc4 2. Sb4 Sxe3 3. Kb3 Sf1 4. Tc3 Sd2#
2) 1. Tc3 Sf1 2. Kc4 Sxe3+ 3. Kb3+ Sc4 4. Sb4 Sd2#
2) 1. Tc3 Sf1 2. Kc4 Sxe3+ 3. Kb3+ Sc4 4. Sb4 Sd2#
Keywords: Pure Round Trip (S,S), Tempo Move (k,k)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/2n5/2r5/rk4K1/p3p3/pppNp3/3b4
Reprints: E226 FIDE Album 1989-1991 1997
Input: Gerd Wilts, 1996-06-06
Last update: Marcin Banaszek, 2018-02-13 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/2n5/2r5/rk4K1/p3p3/pppNp3/3b4
Reprints: E226 FIDE Album 1989-1991 1997
Input: Gerd Wilts, 1996-06-06
Last update: Marcin Banaszek, 2018-02-13 more...
25 - P0501209
Hilmar Ebert
Hans Gruber
Denis Blondel
12173v British Chess Magazine 1985
1. ehrende Erwähnung
(2+13) C+
h#4
Hilmar Ebert
Hans Gruber
Denis Blondel
12173v British Chess Magazine 1985
1. ehrende Erwähnung
(2+13) C+
h#4
1. Tc4 Txa2 2. Tb4 Txb2 3. Ta2 Txb1 4. Ta1 Txa1#
Yuri Bilokin: you can see
1...Rxb1 2.a1=Q Rxa1 3.b1=Q+ Rxb1 4.Ra1 Rxa1#
1...Rxb1 2.a1=Q Rxa1 3.b1=R Rxb1 4.Ra1 Rxa1#
1...Rxb1 2.a1=Q Rxa1 3.b1=B+ Rxb1 4.Ra1 Rxa1#
1...Rxb1 2.a1=Q Rxa1 3.b1=S Rxb1 4.Ra1 Rxa1# (2023-05-08)
more ...
comment
1...Rxb1 2.a1=Q Rxa1 3.b1=Q+ Rxb1 4.Ra1 Rxa1#
1...Rxb1 2.a1=Q Rxa1 3.b1=R Rxb1 4.Ra1 Rxa1#
1...Rxb1 2.a1=Q Rxa1 3.b1=B+ Rxb1 4.Ra1 Rxa1#
1...Rxb1 2.a1=Q Rxa1 3.b1=S Rxb1 4.Ra1 Rxa1# (2023-05-08)
more ...
comment
Keywords: Pure Round Trip (T), Tempo Move (ttt), Switchback (t), Minimal (T)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: b7/1n6/8/pp2p3/kr1pK3/rp6/pp6/Rn6
Reprints: 12173v British Chess Magazine 01/1986
Input: Gerd Wilts, 1996-06-06
Last update: A.Buchanan, 2017-03-20 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: b7/1n6/8/pp2p3/kr1pK3/rp6/pp6/Rn6
Reprints: 12173v British Chess Magazine 01/1986
Input: Gerd Wilts, 1996-06-06
Last update: A.Buchanan, 2017-03-20 more...
1. e1=L Txh3 2. f1=T Txh2 3. Kf2 Txh1 4. g1=S Th2#
Unterverwandlung!Springer, Unterverwandlung!Läufer, Unterverwandlung!Turm, Umwandlungswechsel!3-fach
Adrian Storisteanu: See also slight variation P0577817. (2015-09-12)
Gunter Jordan: Dies ist kein Umwandlungswechsel, dazu müssten die UW auf dem selben Feld erfolgen. (2023-01-11)
A.Buchanan: Why would we talk of helpmate promotions (particularly black ones) as underpromotions. Is a knight ever an under-promotion? And we still with all this under-promotion effort don’t know what the pieces are: it might be rook or bishop. Just label them as promotion:lts and be done (2023-01-12)
more ...
comment
Adrian Storisteanu: See also slight variation P0577817. (2015-09-12)
Gunter Jordan: Dies ist kein Umwandlungswechsel, dazu müssten die UW auf dem selben Feld erfolgen. (2023-01-11)
A.Buchanan: Why would we talk of helpmate promotions (particularly black ones) as underpromotions. Is a knight ever an under-promotion? And we still with all this under-promotion effort don’t know what the pieces are: it might be rook or bishop. Just label them as promotion:lts and be done (2023-01-12)
more ...
comment
Keywords: under-promotion, Minimal
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/5p1R/4pp2/2ppbrnn/4pppr/1K4kb
Input: Gerd Wilts, 1996-06-06
Last update: SBD, 2012-12-26 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/5p1R/4pp2/2ppbrnn/4pppr/1K4kb
Input: Gerd Wilts, 1996-06-06
Last update: SBD, 2012-12-26 more...
1. Kc2! Lh1 2. Kxd3 Kg2 3. Ke4 Sc5#
Keywords: Cheney-Loyd (LK)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/4N3/8/2P1BBP1/1k1P4/4N2K/8
Reprints: 4 Problemschach-Jahrbuch 1993 D , p. 10, 1993
(1) Die Schwalbe , p. 498, 08/1994
Input: hpr, 1996-07-14
Last update: Dieter Berlin, 2023-05-12 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/4N3/8/2P1BBP1/1k1P4/4N2K/8
Reprints: 4 Problemschach-Jahrbuch 1993 D , p. 10, 1993
(1) Die Schwalbe , p. 498, 08/1994
Input: hpr, 1996-07-14
Last update: Dieter Berlin, 2023-05-12 more...
1. Tg8 h8=D 2. Kg6 Df6+ 3. Kh7 Dxf8 4. Kh8 Dh6#
29 - P0502798
Achim Schöneberg
3849 Die Schwalbe 74 04/1982
3. Preis
(3+12) C+
h#4
b) sSe4 tauschen mit sLh5
Achim Schöneberg
3849 Die Schwalbe 74 04/1982
3. Preis
(3+12) C+
h#4
b) sSe4 tauschen mit sLh5
a) 1. Sxc5 Sxf5 2. Te4 Sd4 3. Ke3 Kg3 4. Sd3 Sc2#
b) 1. Kd4 Sxh5 2. Ld3 Kg3 3. Te4 Sg7 4. Ke3 Sxf5#
b) 1. Kd4 Sxh5 2. Ld3 Kg3 3. Te4 Sg7 4. Ke3 Sxf5#
klären Datum
Erich Bartel: die erste Zeile stimmt.Dort steht die Aufgabe auf Seite 459
als Urdruck. (2007-10-12)
Achim Schöneberg: Siehe P0502915 (2022-10-05)
comment
Erich Bartel: die erste Zeile stimmt.Dort steht die Aufgabe auf Seite 459
als Urdruck. (2007-10-12)
Achim Schöneberg: Siehe P0502915 (2022-10-05)
comment
Keywords: Interchange (kts,kls)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/2p4q/r1P2p1b/4n3/3krpNK/3pp3/6b1
Reprints: 3849 Die Schwalbe 06/1982
Input: hpr, 1996-07-28
Last update: hpr, 1999-06-05 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/2p4q/r1P2p1b/4n3/3krpNK/3pp3/6b1
Reprints: 3849 Die Schwalbe 06/1982
Input: hpr, 1996-07-28
Last update: hpr, 1999-06-05 more...
a) 1. Sb3 Se3 2. Td4 Sd5 3. Kc4 Kc2 4. Sc5 Sb6#
b) 1. Kd5 Se1 2. Lc5 Sg2 3. Td4 Kc2 4. Kc4 Se3#
b) 1. Kd5 Se1 2. Lc5 Sg2 3. Td4 Kc2 4. Kc4 Se3#
Keywords: Interchange (kts,kls), Minimal
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/4p3/1pk5/1prn4/8/2N5/1Kb5
Input: hpr, 1996-08-28
Last update: Achim Schöneberg, 2021-12-09 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/4p3/1pk5/1prn4/8/2N5/1Kb5
Input: hpr, 1996-08-28
Last update: Achim Schöneberg, 2021-12-09 more...
31 - P0503025
Norman Alasdair Macleod
R. Tony Lewis
diagrammes 03-04/1982
2. Preis
6. Thematurnier
(3+5) C+
h#2
4.1...
Norman Alasdair Macleod
R. Tony Lewis
diagrammes 03-04/1982
2. Preis
6. Thematurnier
(3+5) C+
h#2
4.1...
1) 1. Kc7 e8=D 2. Db6 Dfe7#
2) 1. Kb7 e8=L 2. Ka8 Lc6#
3) 1. Kd7 e8=T 2. Dc6 De7#
4) 1. Dc4 e8=S 2. Kd5 Dd6#
2) 1. Kb7 e8=L 2. Ka8 Lc6#
3) 1. Kd7 e8=T 2. Dc6 De7#
4) 1. Dc4 e8=S 2. Kd5 Dd6#
(KSp)
t/Allumwandlung, u/61103, t/sK-Korrespondenz
A.Buchanan: A pity that 1 & 3 both end with 2...Dfe7# (2023-03-14)
more ...
comment
t/Allumwandlung, u/61103, t/sK-Korrespondenz
A.Buchanan: A pity that 1 & 3 both end with 2...Dfe7# (2023-03-14)
more ...
comment
Keywords: Allumwandlung, Figurenspiel
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 5Q2/n3P3/2k1q3/7b/4p3/K7/8/8
Reprints: feenschach 61 08/1982
13 The Modern Helpmate in two 1989
Input: Erich Bartel, 1996-09-03
Last update: A.Buchanan, 2023-03-14 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 5Q2/n3P3/2k1q3/7b/4p3/K7/8/8
Reprints: feenschach 61 08/1982
13 The Modern Helpmate in two 1989
Input: Erich Bartel, 1996-09-03
Last update: A.Buchanan, 2023-03-14 more...
1. Db6 Td7 2. Ld6 Ta7 3. Kd5 Ta5+ 4. Kc6 d5#
teilweiser Rundlauf T
Yuri Bilokin: Long-trip (wR, 3)
Umnov mate (bK-wP)
Ideal mate
Epaulette mate (2023-05-08)
comment
Yuri Bilokin: Long-trip (wR, 3)
Umnov mate (bK-wP)
Ideal mate
Epaulette mate (2023-05-08)
comment
Keywords: Pure Round Trip
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 2K5/8/3R4/4b3/3Pk3/1q6/8/8
Input: hpr, 1996-09-05
Last update: hpr, 1999-06-06 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 2K5/8/3R4/4b3/3Pk3/1q6/8/8
Input: hpr, 1996-09-05
Last update: hpr, 1999-06-06 more...
1. Tc2 Th1 2. Kb2 Th8 3. Kc1 Txa8 4. Sb2 Ta1#
Erich Bartel: Nachdruck:
1) V35) Problemkiste (125) X 1999.--- (2007-07-18)
Yuri Bilokin: Areal cycle (wR, with captures, 4)
Corner-to-corner (wR) × 4
Four corners (wR (2023-05-08)
comment
1) V35) Problemkiste (125) X 1999.--- (2007-07-18)
Yuri Bilokin: Areal cycle (wR, with captures, 4)
Corner-to-corner (wR) × 4
Four corners (wR (2023-05-08)
comment
Keywords: Pure Round Trip (D)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: r7/6K1/8/5q2/n3b3/1k6/r2p4/R7
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-13 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: r7/6K1/8/5q2/n3b3/1k6/r2p4/R7
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-13 more...
34 - P0503616
Johann Christoffel van Gool
Jacobus Theodorus Sanderse
876b The Problemist 01/1983
(4+5) C+
h#4
2.1...
Johann Christoffel van Gool
Jacobus Theodorus Sanderse
876b The Problemist 01/1983
(4+5) C+
h#4
2.1...
1) 1. Sc3 Th1 2. Kc2 Th3 3. Kd1 Txc3 4. Ke1 Tc1#
2) 1. Kxb3 Ta1 2. Kc2 Txa2+ 3. Kd1 Tc2 4. Ke1 Tc1#
2) 1. Kxb3 Ta1 2. Kc2 Txa2+ 3. Kd1 Tc2 4. Ke1 Tc1#
Keywords: Pure Round Trip (T)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/1p6/1P6/nk1npPK1/2R5
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-13 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/1p6/1P6/nk1npPK1/2R5
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-13 more...
35 - P0503644
Peter Kniest
3650v Deutsche Schachzeitung 11/1976
(3+11) C+
h#4
b) wBb3 nach c2, sBb4 nach c3
Peter Kniest
3650v Deutsche Schachzeitung 11/1976
(3+11) C+
h#4
b) wBb3 nach c2, sBb4 nach c3
a) 1. Dg4+ Lg2 2. De6 Lf1 3. Kd5 La6 4. c5 Lb7#
b) 1. De4 Ld5 2. c6 La2 3. Sb3 cxb3 4. Kd5 b4#
b) 1. De4 Ld5 2. c6 La2 3. Sb3 cxb3 4. Kd5 b4#
Keywords: Hilfsmatt-Inder (LB), Pure Round Trip (L)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/1Bp5/3p1p2/2k1r3/1p1p3q/1P5r/3n4/3n2K1
Input: hpr, 1996-09-23
Last update: hpr, 1999-06-13 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/1Bp5/3p1p2/2k1r3/1p1p3q/1P5r/3n4/3n2K1
Input: hpr, 1996-09-23
Last update: hpr, 1999-06-13 more...
1. Kc5 Ta2 2. Kb5 Kd5 3. Kb4 Kc6 4. Kc4 Ta4#
Keywords: Pure Round Trip (k)
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/8/8/2k1K3/2p5/1RP5/8
Reprints: Problemkiste 99 06/1995
1936 Ideal-Mate Encyclopedia Vol.1 1999
Problemkiste 121 02/1999
r628 Mirador 06/2002
153) Hobelspäne (2) 28/05/2017
Input: hpr, 1996-09-23
Last update: Alfred Pfeiffer, 2019-05-15 more...
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/8/8/2k1K3/2p5/1RP5/8
Reprints: Problemkiste 99 06/1995
1936 Ideal-Mate Encyclopedia Vol.1 1999
Problemkiste 121 02/1999
r628 Mirador 06/2002
153) Hobelspäne (2) 28/05/2017
Input: hpr, 1996-09-23
Last update: Alfred Pfeiffer, 2019-05-15 more...
1. Kf3 Td4 2. Kxe3 Txd3+ 3. Kxf4 Te3 4. Kg4 Te4#
Yuri Bilokin: Areal cycle (bK, with captures, 4)
Areal cycle (wR, with captures, 4) (2023-05-08)
comment
Areal cycle (wR, with captures, 4) (2023-05-08)
comment
Keywords: Pure Round Trip
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/7p/1p3n1p/bp2RPkP/pR1pP3/q2p4/rrnK4
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-20 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/7p/1p3n1p/bp2RPkP/pR1pP3/q2p4/rrnK4
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-20 more...
1. Kd2 Lxb6 2. Kxc3 Lc7 3. Kxd4 Lxd6 4. Ke3 Lc5#
Yuri Bilokin: Areal cycle (bK, with captures, 4)
Areal cycle (wB, with captures, 4) (2023-05-08)
comment
Areal cycle (wB, with captures, 4) (2023-05-08)
comment
Keywords: Pure Round Trip
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 2b5/1p1R4/1p1p4/1PB4p/1PpP1p1P/2P1kPpK/2P3P1/3B4
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-20 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 2b5/1p1R4/1p1p4/1PB4p/1PpP1p1P/2P1kPpK/2P3P1/3B4
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-20 more...
1) 1. Ke4 Txc4+ 2. Kxe5 Txc5+ 3. Kd4 Tb5 4. e5 Tb4#
2) 1. Kxe5 Tb5 2. Kd4 Txc5 3. Lb5+ Txb5 4. e5 Tb4#
2) 1. Kxe5 Tb5 2. Kd4 Txc5 3. Lb5+ Txb5 4. e5 Tb4#
Keywords: Pure Round Trip
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/p3p3/p1K1p3/P1p1P3/1Rbk4/2npp3/8/8
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-20 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/p3p3/p1K1p3/P1p1P3/1Rbk4/2npp3/8/8
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 1999-06-20 more...
1) 1. Lc6 De8 2. Kb7 Dxc6+ 3. Ka6 Da8#
2) 1. Ld5 Dd8+ 2. Kb7 Dxd5+ 3. Ka6 Da8#
3) 1. Le4 Da4 2. Kb7 Dxe4+ 3. Ka6 Da8#
4) 1. Lf3 Df8 2. Kb7 Dxf3+ 3. Ka6 Da8#
5) 1. Lg2 Dg8 2. Kb7 Dxg2+ 3. Ka6 Da8#
6) 1. e5 Dh8 2. Kb7 Dxh1+ 3. Ka6 Da8#
2) 1. Ld5 Dd8+ 2. Kb7 Dxd5+ 3. Ka6 Da8#
3) 1. Le4 Da4 2. Kb7 Dxe4+ 3. Ka6 Da8#
4) 1. Lf3 Df8 2. Kb7 Dxf3+ 3. Ka6 Da8#
5) 1. Lg2 Dg8 2. Kb7 Dxg2+ 3. Ka6 Da8#
6) 1. e5 Dh8 2. Kb7 Dxh1+ 3. Ka6 Da8#
Keywords: Pure Round Trip (D,D,D,D,D)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: Q7/2k5/1p2p3/1p6/8/K7/8/7b
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 2004-09-30 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: Q7/2k5/1p2p3/1p6/8/K7/8/7b
Input: Hans-Jürgen Schäfer, 1996-09-23
Last update: hpr, 2004-09-30 more...
1) 1. Lf3 Le4+ 2. Kh1 Tb1#
2) 1. Tf3 Tb3 2. Kh3 Lf5#
Die Rollen der fesselnden und gefesselten Figur werden umgedreht. Grimshaw auf f3 und Funktionswechsel von T und L
2) 1. Tf3 Tb3 2. Kh3 Lf5#
Die Rollen der fesselnden und gefesselten Figur werden umgedreht. Grimshaw auf f3 und Funktionswechsel von T und L
Sally: Markant ist der Grimshaw auf "f3" (überraschend auf einem "Eck-Feld" des w. Königs), wobei die dennoch notwendige Fesselung prägend ist. [Eine der ersten Aufgaben des Erfolgsduos].
41 Mehr als ein Hobby ( F. Pachl 2011). (2016-12-07)
Achim Schöneberg: Knapper Vorgänger siehe P1413421 (2023-11-08)
comment
41 Mehr als ein Hobby ( F. Pachl 2011). (2016-12-07)
Achim Schöneberg: Knapper Vorgänger siehe P1413421 (2023-11-08)
comment
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: 8/8/8/7p/KR3r1p/8/R1B3kP/3b4
Reprints: 41 Mehr als 1 Hobby [Pachl] 2011
Input: Markus Manhart, 1996-10-07
Last update: Alfred Pfeiffer, 2016-12-07 more...
1. Tg3 Tf3 2. Te3 hxg3 3. Ld3 Tf4#
43 - P0506014
Vladimir Korolkov
Lev Loshinsky
1806 Revista de Sah 11/1964
3. Preis
(8+7) C+
h#2
4.1...
Vladimir Korolkov
Lev Loshinsky
1806 Revista de Sah 11/1964
3. Preis
(8+7) C+
h#2
4.1...
1) 1. b5 Td7 2. bxc4 Tb7#
2) 1. b6 Txe4 2. b5 c5#
3) 1. bxa6 Sc5 2. a5 Sa6#
4) 1. bxc6 Sa5 2. c5 Sc6#
2) 1. b6 Txe4 2. b5 c5#
3) 1. bxa6 Sc5 2. a5 Sa6#
4) 1. bxc6 Sa5 2. c5 Sc6#
BSp
spiegelverkehrt von R.Senkus in Chess in Australia veröffentlicht
Yuri Bilokin: you can see 1...Rxe4 2.b5 c5# (2024-04-02)
comment
spiegelverkehrt von R.Senkus in Chess in Australia veröffentlicht
Yuri Bilokin: you can see 1...Rxe4 2.b5 c5# (2024-04-02)
comment
Keywords: Figurenspiel
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 3K4/1p6/P1P5/4p3/pkPRp3/pNp1P3/2P5/8
Reprints: 183 Chess in Australia 1992
Input: hpr, 1996-12-31
Last update: hpr, 2011-03-06 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 3K4/1p6/P1P5/4p3/pkPRp3/pNp1P3/2P5/8
Reprints: 183 Chess in Australia 1992
Input: hpr, 1996-12-31
Last update: hpr, 2011-03-06 more...
1) 1. e5 d7 2. e4 d8=D 3. d2+ Dxd2#
2) 1. exf6 d7 2. f5 d8=D 3. f4 Dxd3#
3) 1. e6 f7 2. e5 f8=D 3. e4 Df2#
4) 1. exd6 f7 2. d5 f8=D 3. d4 Df3#
2) 1. exf6 d7 2. f5 d8=D 3. f4 Dxd3#
3) 1. e6 f7 2. e5 f8=D 3. e4 Df2#
4) 1. exd6 f7 2. d5 f8=D 3. d4 Df3#
Keywords: Figurenspiel, Kindergarten Problem
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/4p3/3P1P2/8/8/3pk3/4P3/4K3
Input: hpr, 1996-12-31
Last update: Erich Bartel, 2012-05-24 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/4p3/3P1P2/8/8/3pk3/4P3/4K3
Input: hpr, 1996-12-31
Last update: Erich Bartel, 2012-05-24 more...
1) 1. e6 d7 2. e5 d8=D 3. e4 Dd2#
2) 1. exf6 d7 2. f5 d8=D 3. f4 Dd3#
3) 1. e5 f7 2. e4 f8=D 3. f2+ Dxf2#
4) 1. exd6 f7 2. d5 f8=D 3. d4 Dxf3#
2) 1. exf6 d7 2. f5 d8=D 3. f4 Dd3#
3) 1. e5 f7 2. e4 f8=D 3. f2+ Dxf2#
4) 1. exd6 f7 2. d5 f8=D 3. d4 Dxf3#
Keywords: Figurenspiel
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/4p3/3P1P2/8/8/4kp2/4P3/4K3
Input: hpr, 1996-12-31
Last update: hpr, 1999-08-29 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/4p3/3P1P2/8/8/4kp2/4P3/4K3
Input: hpr, 1996-12-31
Last update: hpr, 1999-08-29 more...
46 - P0506144
Felix Alexander Sonnenfeld
Ricardo de Mattos Vieira
1895 diagrammes 85 04-06/1988
(4+5) C+
h#2
3.1...
Felix Alexander Sonnenfeld
Ricardo de Mattos Vieira
1895 diagrammes 85 04-06/1988
(4+5) C+
h#2
3.1...
1) 1. Sb5 Sd5+ 2. Kf5 Se7#
2) 1. Sc6 Sc4+ 2. Kf5 Sd6#
3) 1. Sc8 Sc2+ 2. Kf5 Sd4#
2) 1. Sc6 Sc4+ 2. Kf5 Sd6#
3) 1. Sc8 Sc2+ 2. Kf5 Sd4#
Yuri Bilokin: you can see 1...Sc2+ 2.Kf5 Sd4#
1...Sc4+ 2.Kf5 Sd6#
1...Sd5+ 2.Kf5 Se7# (2023-06-26)
comment
1...Sc4+ 2.Kf5 Sd6#
1...Sd5+ 2.Kf5 Se7# (2023-06-26)
comment
Keywords: Dual avoidance, Tempo Move
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/n7/4p1p1/4P3/4kb1K/4N3/8/4R3
Input: Markus Manhart, 1997-01-06
Last update: hpr, 1999-08-29 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/n7/4p1p1/4P3/4kb1K/4N3/8/4R3
Input: Markus Manhart, 1997-01-06
Last update: hpr, 1999-08-29 more...
47 - P0506889
Claude Goumondy
3779 Die Schwalbe 73 02/1982
(5+7) C+
h#2
b) wSe8 nach g7
c) wSe8 nach e3
d) wLg5 nach g6
Claude Goumondy
3779 Die Schwalbe 73 02/1982
(5+7) C+
h#2
b) wSe8 nach g7
c) wSe8 nach e3
d) wLg5 nach g6
a) 1. Td4 Td5+ 2. Ke4 Sf6#
b) 1. Td5 Td6 2. Ld4 Te6#
c) 1. Td6 Td7 2. Ke6 Te7#
d) 1. Td3 Td4 2. Sd5 Te4#
b) 1. Td5 Td6 2. Ld4 Te6#
c) 1. Td6 Td7 2. Ke6 Te7#
d) 1. Td3 Td4 2. Sd5 Te4#
klären Jahr?
Anton Baumann: Korrektur in 'Die Schwalbe' 06/1983 S.87: +sDa5 zur Verhinderung der NL in c) (2022-12-21)
comment
Anton Baumann: Korrektur in 'Die Schwalbe' 06/1983 S.87: +sDa5 zur Verhinderung der NL in c) (2022-12-21)
comment
*) 1. ... f8=S 2. f1=L Le3#
1) 1. f1=T f8=D 2. Tf6 Dxg7#
1) 1. f1=T f8=D 2. Tf6 Dxg7#
t/Allumwandlung, u/61112, u/SDlt
Vorläufer: A.C.White,1930, s.Nr.1056
s. A. C. White 364v L'Echiquier 07-08/1930
Anton Baumann: Die Aufgabe stammt gem. 'Die Schwalbe' 05/1963 von André Simonet, Brüssel
Vorgänger vergl. P0542142 (2022-11-16)
comment
Vorläufer: A.C.White,1930, s.Nr.1056
s. A. C. White 364v L'Echiquier 07-08/1930
Anton Baumann: Die Aufgabe stammt gem. 'Die Schwalbe' 05/1963 von André Simonet, Brüssel
Vorgänger vergl. P0542142 (2022-11-16)
comment
Keywords: Allumwandlung, Promotion
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 4N3/5Pp1/6Pk/7p/4P2P/pp6/pqpp1p2/bbrr2BK
Input: Erich Bartel, 1997-05-23
Last update: hpr, 1999-10-16 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 4N3/5Pp1/6Pk/7p/4P2P/pp6/pqpp1p2/bbrr2BK
Input: Erich Bartel, 1997-05-23
Last update: hpr, 1999-10-16 more...
1) 1. cxb1=S g8=D 2. Sc3 Db3#
2) 1. cxb1=L g8=T 2. Ka2 Ta8#
2) 1. cxb1=L g8=T 2. Ka2 Ta8#
t/Allumwandlung, u/61113, u/DTsl
Yuri Bilokin: you can see 1...g8=Q 2.cxb1=B Qb3#
1...g8=Q 2.cxb1=S Qb3#
1...Bxc2 2.Ka2 Ra4# (2024-02-29)
comment
Yuri Bilokin: you can see 1...g8=Q 2.cxb1=B Qb3#
1...g8=Q 2.cxb1=S Qb3#
1...Bxc2 2.Ka2 Ra4# (2024-02-29)
comment
Keywords: Allumwandlung, Sacrifice of white pieces, Promotion
Genre: h#
Computer test: (Popeye C-Version 3. 47 (1024 KB))
FEN: 8/6P1/8/8/1R6/k2p4/2p5/1BK5
Input: Erich Bartel, 1997-05-23
Last update: hpr, 1999-10-16 more...
Genre: h#
Computer test: (Popeye C-Version 3. 47 (1024 KB))
FEN: 8/6P1/8/8/1R6/k2p4/2p5/1BK5
Input: Erich Bartel, 1997-05-23
Last update: hpr, 1999-10-16 more...
1. Ka3 Sf6 2. Da8+ Se4 3. Dxa4 Sc5 4. Lb2 Txa4#
Autor klären
Felber, Volker: Ich gehe davon aus, dass hier die Korrektur zu P1406481 vorliegt. Dort ist im Original von SCHACH "Eduard Walzinsch" angegeben. In der PDB gibt es beide Schreibweisen für denselben Autor. (2022-12-07)
comment
Felber, Volker: Ich gehe davon aus, dass hier die Korrektur zu P1406481 vorliegt. Dort ist im Original von SCHACH "Eduard Walzinsch" angegeben. In der PDB gibt es beide Schreibweisen für denselben Autor. (2022-12-07)
comment
Keywords: Check Protection
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 6Nq/6b1/6p1/1n6/P6R/8/1k6/5b1K
Input: Markus Manhart, 1997-06-26
Last update: hpr, 1999-10-19 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 6Nq/6b1/6p1/1n6/P6R/8/1k6/5b1K
Input: Markus Manhart, 1997-06-26
Last update: hpr, 1999-10-19 more...
a) 1. Tc5 Sb2 2. Td5 Kf4 3. Tc3 Se6#
b) 1. Kd3 Sb6 2. Ke3 Kh4 3. Kf4 Sd5#
b) 1. Kd3 Sb6 2. Ke3 Kh4 3. Kf4 Sd5#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/4rrN1/2Nk4/6K1/8/8
Reprints: 2602 Revista de Sah 01/1970
Input: Markus Manhart, 1997-09-30
Last update: hpr, 1999-02-15 more...
1) 1. Lh2 Kc6 2. Lf4 Lc3#
2) 1. Lh4 Kc4 2. Lf6 Lg3#
3) 1. Kd4 Kb4 2. Le5 Lf2#
2) 1. Lh4 Kc4 2. Lf6 Lg3#
3) 1. Kd4 Kb4 2. Le5 Lf2#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/1KN1k3/4P3/6b1/8/4B3
Input: Markus Manhart, 1997-09-30
Last update: A.Buchanan, 2023-06-06 more...
1. ... Sf2 2. Kg1 g3 3. Kh2 Sg4+ 4. Kh3 Lg2#
Jean Marc Loustau: The setting is not legal, but it is without impotance here... Let us say it is "fairy" (2003-05-08)
A.Buchanan: Legality/illegality is orthogonal to fairy. Let us say here it is "not fairy". (2023-07-09)
Adrian Storisteanu: Add, say, "circe" under the diagram, and all is pretty cool. Even cooler, "chess960". (2023-07-10)
paul: cond einstein
stip h#2.5 forsyth 8/8/8/7k/8/5K1B/3R2P1/8
Two solutions (2023-07-10)
comment
A.Buchanan: Legality/illegality is orthogonal to fairy. Let us say here it is "not fairy". (2023-07-09)
Adrian Storisteanu: Add, say, "circe" under the diagram, and all is pretty cool. Even cooler, "chess960". (2023-07-10)
paul: cond einstein
stip h#2.5 forsyth 8/8/8/7k/8/5K1B/3R2P1/8
Two solutions (2023-07-10)
comment
Keywords: Illegal position (wLh1), Miniature, Symmetrical constellation
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/8/5K1N/6P1/5k1B
Reprints: 1683 Ideal-Mate Encyclopedia Vol.1 1999
Input: Markus Manhart, 1997-09-30
Last update: A.Buchanan, 2023-07-09 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/8/5K1N/6P1/5k1B
Reprints: 1683 Ideal-Mate Encyclopedia Vol.1 1999
Input: Markus Manhart, 1997-09-30
Last update: A.Buchanan, 2023-07-09 more...
1. Dh8 0-0 2. Da1 Lxf7#
Eric Huber: Anticipated by 'P0534152' Erkki Heinonen, 3. Makuc-Moder-Gedenkturnier 1971-1973, 4. ehrende Erwähnung. (2008-10-01)
Viktoras Paliulionis: This problem shows paradoxical idea - two mutually exclusive tempo moves (B1 & B2). P0534152 has only one tempo move. (2023-10-09)
more ...
comment
Viktoras Paliulionis: This problem shows paradoxical idea - two mutually exclusive tempo moves (B1 & B2). P0534152 has only one tempo move. (2023-10-09)
more ...
comment
Keywords: Castling (wk), Tempo Move (dd)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 6B1/5n1n/8/8/N7/b7/kq5r/4K2R
Input: Markus Manhart, 1998-02-10
Last update: Gerd Wilts, 2008-10-02 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 6B1/5n1n/8/8/N7/b7/kq5r/4K2R
Input: Markus Manhart, 1998-02-10
Last update: Gerd Wilts, 2008-10-02 more...
1. Kd2 e4+ 2. Kd1 e5 3. Ke1 e6 4. Kd1 e7 5. Ke1 e8=D+ 6. Kd1 De2#
Yuri Bilokin: you can see 1...e4 2.Kd1 e5 3.Ke1 e6 4.Kd1 e7 5.Ke1 e8=Q+ 6.Kd1 Qe2# (2023-01-14)
comment
comment
Keywords: Excelsior white (auto key), Round Trip, Pure Round Trip (k), Tempo Move (kkk)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/8/p1p5/PpP1PR2/1K2k3
Input: Markus Manhart, 1998-02-10
Last update: hpr, 2000-10-11 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/8/p1p5/PpP1PR2/1K2k3
Input: Markus Manhart, 1998-02-10
Last update: hpr, 2000-10-11 more...
56 - P0523513
Eduard A. Enkin
Mykola Nagnibida
1529 Feladvanykedvelök Lapja 11-12/1974
(9+8) C+
h#2
b) sBf3 nach e3
Eduard A. Enkin
Mykola Nagnibida
1529 Feladvanykedvelök Lapja 11-12/1974
(9+8) C+
h#2
b) sBf3 nach e3
a) 1. Thg1 Ta8 2. Tgf1 Da7#
b) 1. Thf1 Lg8 2. Tg1 Df7#
b) 1. Thf1 Lg8 2. Tg1 Df7#
Keywords: Bahnung, Tempo Move (t t)
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 2K5/3p4/3P4/1P6/RP6/1B3pp1/QPR1qkp1/4r2r
Input: Markus Manhart, 1998-02-10
Last update: hpr, 1999-11-02 more...
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 2K5/3p4/3P4/1P6/RP6/1B3pp1/QPR1qkp1/4r2r
Input: Markus Manhart, 1998-02-10
Last update: hpr, 1999-11-02 more...
1) 1. cxb1=T+ Lc1 2. Dh8 Ta7#
2) 1. cxb1=L Tc2 2. Da8 Lg7#
2) 1. cxb1=L Tc2 2. Da8 Lg7#
Keywords: Sacrifice of white pieces, Tempo Move (d d)
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 8/2R5/7B/8/8/1P6/2p5/kN3Knq
Reprints: 528 FIDE Album 1965-1967
Input: Markus Manhart, 1998-02-10
Last update: Marcin Banaszek, 2016-01-21 more...
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 8/2R5/7B/8/8/1P6/2p5/kN3Knq
Reprints: 528 FIDE Album 1965-1967
Input: Markus Manhart, 1998-02-10
Last update: Marcin Banaszek, 2016-01-21 more...
58 - P0524038
Yosi Retter
4220 Probleemblad 05-06/1961
1. Preis
107. Thematurnier
(6+14) C+
h#2
3.1...
Yosi Retter
4220 Probleemblad 05-06/1961
1. Preis
107. Thematurnier
(6+14) C+
h#2
3.1...
1) 1. Sa6 Sd1 2. c3 Sxe5#
2) 1. Sc6 Sa4 2. Dc3 Sc5#
3) 1. Sd7 Sxa2 2. Tc3 Sb4#
2) 1. Sc6 Sa4 2. Dc3 Sc5#
3) 1. Sd7 Sxa2 2. Tc3 Sb4#
Yuri Bilokin: you can see 1...Sd1 2.c3 Sxe5#
1...Sxa2 2.Rc3 Sb4#
1...Sa4 2.Qc3 Sc5# (2022-09-11)
comment
1...Sxa2 2.Rc3 Sb4#
1...Sa4 2.Qc3 Sc5# (2022-09-11)
comment
Keywords: Tempo Move (s s s)
Genre: h#
Computer test: Popeye C-Version 3.47 (1024 KB)
FEN: 1n6/8/8/3PpK2/2p1P1N1/ppNkP3/pqrpr3/nbb5
Reprints: 528 FIDE Album 1959-1961 1966
(11) idee & form 58, p. 1653, 04/1998
Input: Markus Manhart, 1998-02-10
Last update: Felber, Volker, 2022-09-06 more...
Genre: h#
Computer test: Popeye C-Version 3.47 (1024 KB)
FEN: 1n6/8/8/3PpK2/2p1P1N1/ppNkP3/pqrpr3/nbb5
Reprints: 528 FIDE Album 1959-1961 1966
(11) idee & form 58, p. 1653, 04/1998
Input: Markus Manhart, 1998-02-10
Last update: Felber, Volker, 2022-09-06 more...
1) 1. 0-0 Lf6 2. Tf7 Th8#
2) 1. Tf8 Td7 2. Tf7 Td8#
3) 1. Tg8 Kc7 2. Tf8 Te7#
2) 1. Tf8 Td7 2. Tf7 Td8#
3) 1. Tg8 Kc7 2. Tf8 Te7#
in Vratnica von Datiaschwili/Gatseciladse steingetreu nachempfunden
Yuri Bilokin: you can see *) 1...Kc7 2.Rf8 Re7# (2022-09-11)
comment
Yuri Bilokin: you can see *) 1...Kc7 2.Rf8 Re7# (2022-09-11)
comment
Keywords: Echo, Castling (sk), Aristocrat
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 4k2r/7R/1K6/8/7B/8/8/8
Reprints: 87 Vratnica-64 3 07-09/2001
Input: Markus Manhart, 1998-02-16
Last update: Erich Bartel, 2022-09-12 more...
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 4k2r/7R/1K6/8/7B/8/8/8
Reprints: 87 Vratnica-64 3 07-09/2001
Input: Markus Manhart, 1998-02-16
Last update: Erich Bartel, 2022-09-12 more...
1) 1. Ke5 Kd3 2. Ld6 Tf5#
2) 1. Ke3 Tf2 2. Lf4 Te2#
3) 1. Lf4 Tf6 2. Ke5 Te6#
2) 1. Ke3 Tf2 2. Lf4 Te2#
3) 1. Lf4 Tf6 2. Ke5 Te6#
Keywords: Echo
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 1b3R2/8/8/8/2KNk3/8/8/8
Input: Markus Manhart, 1998-02-16
Last update: hpr, 1999-11-04 more...
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 1b3R2/8/8/8/2KNk3/8/8/8
Input: Markus Manhart, 1998-02-16
Last update: hpr, 1999-11-04 more...
1) 1. Sg1 0-0-0 2. Sf3 Sc2 3. Sxe5 Txd4#
2) 1. Sf4 Td6 2. Sd5 Sc6 3. Se3 Txd4#
2) 1. Sf4 Td6 2. Sd5 Sc6 3. Se3 Txd4#
Yuri Bilokin: more economical -wPf6, -wPg4, -bPa4, bBg6-f5, bPf7-d7 8/4p3/2R1p1p1/2P1Pb2/1Nppk3/2p3p1/rr2n1P1/R3K3 (7+12) h#3 2.1…
1.Sg1 0-0-0 2.Sf3 Sc2 3.Sxe5 Rxd4#
1.Sf4 Rd6 2.Sd5 Sc6 3.Se3 Rxd4#
AntiZielElement (B2, line obstruction)
Castling (white, long). Check prevention (W-W)
Exchange of functions (wRa1/wRc6, Mate / Passive)
Long-trip (bS, 3) × 2.Play on the same square (W3, 2)
Mates on the same square × 2 (2023-08-23)
comment
1.Sg1 0-0-0 2.Sf3 Sc2 3.Sxe5 Rxd4#
1.Sf4 Rd6 2.Sd5 Sc6 3.Se3 Rxd4#
AntiZielElement (B2, line obstruction)
Castling (white, long). Check prevention (W-W)
Exchange of functions (wRa1/wRc6, Mate / Passive)
Long-trip (bS, 3) × 2.Play on the same square (W3, 2)
Mates on the same square × 2 (2023-08-23)
comment
1) 1. T1b6 Sxg7 2. Lb3 Sc6#
2) 1. T8b2 Sxg6 2. Sb3 Sd4#
2) 1. T8b2 Sxg6 2. Sb3 Sd4#
Jean Haymann: Not simply "Fesselungsspiel" but Goethard. There are
some better presentations of that basic shema but not
presented as "after A.Uddgren". (2007-01-02)
Yuri Bilokin: more economical bQh8-g6(-bPg6) 1r6/K4pp1/R3Nkq1/4N3/7P/8/8/Brnb4 (6+8) (2023-01-03)
comment
some better presentations of that basic shema but not
presented as "after A.Uddgren". (2007-01-02)
Yuri Bilokin: more economical bQh8-g6(-bPg6) 1r6/K4pp1/R3Nkq1/4N3/7P/8/8/Brnb4 (6+8) (2023-01-03)
comment
Keywords: Fesselungsspiel (Dualvermeidung), Sacrifice of white pieces
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 1r5q/K4pp1/R3Nkp1/4N3/7P/8/8/Brnb4
Reprints: 536 FIDE Album 1965-1967
Input: Markus Manhart, 1998-03-01
Last update: Marcin Banaszek, 2016-01-21 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 1r5q/K4pp1/R3Nkp1/4N3/7P/8/8/Brnb4
Reprints: 536 FIDE Album 1965-1967
Input: Markus Manhart, 1998-03-01
Last update: Marcin Banaszek, 2016-01-21 more...
1) 1. Te1 Txe7 2. Te4 Td7#
2) 1. Td2 Sf6 2. Td3 Te4#
3) 1. Txf2 Sxf2 2. e5 Td3#
4) 1. e5 Txe2 2. e4 Td2#
5) 1. e6 Txe6 2. Te4 Td6#
2) 1. Td2 Sf6 2. Td3 Te4#
3) 1. Txf2 Sxf2 2. e5 Td3#
4) 1. e5 Txe2 2. e4 Td2#
5) 1. e6 Txe6 2. Te4 Td6#
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 8/4p3/8/8/1K1k2N1/4R3/4rP2/8
Input: hpr, 1998-03-23
Last update: hpr, 1999-11-06 more...
*) 1. ... Sf3#
1) 1. fxe1=L Tf3 2. Kd2 Td3#
1) 1. fxe1=L Tf3 2. Kd2 Td3#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/8/2p5/2P1np2/1K1kNR2
Input: Ralf Krätschmer, 1998-03-30
Last update: hpr, 1999-02-10 more...
*) 1. ... g4#
1) 1. Sxg3 Kxg3 2. g4 Tf5#
1) 1. Sxg3 Kxg3 2. g4 Tf5#
Yuri Bilokin: 1. ... g4#, white rook extra (2023-06-24)
Ladislav Packa: There is one interesting possibility, wRg3 instead of wPg3. The set play is then replaced by the second solution. Zilahi theme, C+ by Popeye v4.63
1.Sh1xg3 Kh3xg3 2.g5-g4 Rf2-f5#
1.Sh1xf2 + Kh3-g2 2.Sf2-g4 Rg3-h3# (2023-06-24)
Yuri Bilokin: Ladislav, in the proposed edition can be seen 1...Rh2 2.Sxg3 Kxg3#. There is a better implementation of the Zilahi theme for this white material P0527728 (2023-06-26)
Ladislav Packa: Zilahi is just one part of the theme, besides it contains multiple tempo play.
1. ...Rh2 (thr. 2.Kg2#) 2.Sxg3 Kxg3#
1.g4+? Rxg4 (thr. 2.Rf5#) but 2.Sxg3, Sxf2+
1.Sxg3 Kxg3 (thr. 2.Rh2#) 2.g4 Rh5#
1.Sxf2+ Kg2 2.Sg4 Rh3# (2023-06-27)
comment
Ladislav Packa: There is one interesting possibility, wRg3 instead of wPg3. The set play is then replaced by the second solution. Zilahi theme, C+ by Popeye v4.63
1.Sh1xg3 Kh3xg3 2.g5-g4 Rf2-f5#
1.Sh1xf2 + Kh3-g2 2.Sf2-g4 Rg3-h3# (2023-06-24)
Yuri Bilokin: Ladislav, in the proposed edition can be seen 1...Rh2 2.Sxg3 Kxg3#. There is a better implementation of the Zilahi theme for this white material P0527728 (2023-06-26)
Ladislav Packa: Zilahi is just one part of the theme, besides it contains multiple tempo play.
1. ...Rh2 (thr. 2.Kg2#) 2.Sxg3 Kxg3#
1.g4+? Rxg4 (thr. 2.Rf5#) but 2.Sxg3, Sxf2+
1.Sxg3 Kxg3 (thr. 2.Rh2#) 2.g4 Rh5#
1.Sxf2+ Kg2 2.Sg4 Rh3# (2023-06-27)
comment
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 7N/8/7p/6pk/8/6PK/5R2/7n
Input: Ralf Krätschmer, 1998-03-30
Last update: Rainer Staudte, 2013-01-05 more...
1) 1. Sf4 Te3 2. Scd3 Te4#
2) 1. Se6 Le7 2. Sdc5 Lf6#
2) 1. Se6 Le7 2. Sdc5 Lf6#
zunächst für die 2. ehrende Erwähnung vorgesehen, wegen Vorgänger (P0565488) Auszeichnung aberkannt (vergl. 'Die Schwalbe' 08/1984 S.308)
Anton Baumann: wegen Vorgänger (P0565488) Auszeichnung aberkannt (vergl. 'Die Schwalbe' 08/1984 S.308) (2022-12-23)
Yuri Bilokin: Model mats, other finals. The task has the main reward, it is published. (2022-12-25)
comment
Anton Baumann: wegen Vorgänger (P0565488) Auszeichnung aberkannt (vergl. 'Die Schwalbe' 08/1984 S.308) (2022-12-23)
Yuri Bilokin: Model mats, other finals. The task has the main reward, it is published. (2022-12-25)
comment
Keywords: Fesselungsspiel (224 220 220)
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 5b2/8/1r6/2n3N1/1BPk3r/K1Rn3q/8/8
Input: Markus Manhart, 1998-03-28
Last update: Mario Richter, 2022-12-23 more...
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 5b2/8/1r6/2n3N1/1BPk3r/K1Rn3q/8/8
Input: Markus Manhart, 1998-03-28
Last update: Mario Richter, 2022-12-23 more...
1. Se7 La5 2. Sb5+ Kb6 3. 0-0-0 Kxb5 4. Te8 Kb6 5. Kd8 Kb7#
Yuri Bilokin: you can see 1...Bh4 2.Se7 Be1 3.0-0-0 Ba5 4.Re8 Kb6 5.Kd8 Kb7#
1...Bh4 2.Se7 Be1 3.0-0-0 Kb6 4.Re8 Ba5 5.Kd8 Kb7#
1...Bh4 2.Se7 Kb6 3.0-0-0 Be1 4.Re8 Ba5 5.Kd8 Kb7#
1...Ba5 2.Se7 Be1 3.0-0-0 Ba5 4.Re8 Kb6 5.Kd8 Kb7# (2024-04-03)
comment
1...Bh4 2.Se7 Be1 3.0-0-0 Kb6 4.Re8 Ba5 5.Kd8 Kb7#
1...Bh4 2.Se7 Kb6 3.0-0-0 Be1 4.Re8 Ba5 5.Kd8 Kb7#
1...Ba5 2.Se7 Be1 3.0-0-0 Ba5 4.Re8 Kb6 5.Kd8 Kb7# (2024-04-03)
comment
1) 1. Lc8 Tb7 2. Ld7 Lf4 3. 0-0-0 Tb8#
2) 1. Ld4 Lf4 2. 0-0-0 Txb7 3. Td7 Tb8#
3) 1. 0-0-0+ Td7 2. Sb5 Lxf6 3. Sc7 Txd8#
2) 1. Ld4 Lf4 2. 0-0-0 Txb7 3. Td7 Tb8#
3) 1. 0-0-0+ Td7 2. Sb5 Lxf6 3. Sc7 Txd8#
klären autor?
Yuri Bilokin: author Yuri Bilikin
Castling (black, long) × 3 (2024-03-18)
Yuri Bilokin: slip of the pen, author Yuri Bilokin (2024-03-21)
comment
Yuri Bilokin: author Yuri Bilikin
Castling (black, long) × 3 (2024-03-18)
Yuri Bilokin: slip of the pen, author Yuri Bilokin (2024-03-21)
comment
a) 1. Dd6 Dh1 2. Kd5 Tf5#
b) 1. Ld5 Dh8 2. Kd4 Se6#
b) 1. Ld5 Dh8 2. Kd4 Se6#
Anton Baumann: Informalturnier 1991: 2. ehrende Erwähnung
PB in 'Die Schwalbe' Heft 171A (06/1998 S.489) (2023-01-21)
comment
PB in 'Die Schwalbe' Heft 171A (06/1998 S.489) (2023-01-21)
comment
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 3R4/2p3N1/2p2qr1/2k3pQ/4b3/2pPPR2/8/3n2K1
Reprints: E118 FIDE Album 1989-1991 1997
Input: Michal Dragoun, 1998-04-06
Last update: Marcin Banaszek, 2018-02-09 more...
1) 1. Le5 Sc5+ 2. Kd4 Sb3#
2) 1. Lc5 Sd8+ 2. Kd4 Sc6#
2) 1. Lc5 Sd8+ 2. Kd4 Sc6#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/5B2/4N3/3k4/3bp3/8/3K4/8
Input: Michal Dragoun, 1998-04-06
Last update: hpr, 1999-01-31 more...
1) 1. Td3 Lc4 2. Te3 Dg4#
2) 1. Td6 Dg4+ 2. Kd5 Dc4#
3) 1. Kf5 Le8 2. Tf4 Dg6#
4) 1. Tf5 Le2 2. Tf4 De6#
2) 1. Td6 Dg4+ 2. Kd5 Dc4#
3) 1. Kf5 Le8 2. Tf4 Dg6#
4) 1. Tf5 Le2 2. Tf4 De6#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 2K3Q1/8/8/1B2r3/3rk3/8/8/8
Input: Michal Dragoun, 1998-04-07
Last update: hpr, 1999-01-31 more...
1) 1. Sb4 Lc6 2. Tb6 Da8#
2) 1. Kxb7 Dc8+ 2. Ka8 Dxa6#
3) 1. Ta8 Lc8 2. Sb8 Dg1#
2) 1. Kxb7 Dc8+ 2. Ka8 Dxa6#
3) 1. Ta8 Lc8 2. Sb8 Dg1#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 1r4Q1/kB2p3/n3K3/8/8/8/8/8
Input: Michal Dragoun, 1998-04-07
Last update: hpr, 1999-01-31 more...
1) 1. Txb4 Le5 2. Ke4 Te1#
2) 1. Lxb4 Tc1 2. Kd2 Lf4#
2) 1. Lxb4 Tc1 2. Kd2 Lf4#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/1pKp4/bB1P4/rQ4P1/p3k1B1/P5P1/7R
Input: Michal Dragoun, 1998-04-07
Last update: Felber, Volker, 2022-09-06 more...
74 - P0539968
Unto Heinonen
470 Suomen Tehtäväniekat 1994
3. ehrende Erwähnung
(5+9) C+
h#2
b) Circe
c) Platzwechselcirce
d) Madrasi
Unto Heinonen
470 Suomen Tehtäväniekat 1994
3. ehrende Erwähnung
(5+9) C+
h#2
b) Circe
c) Platzwechselcirce
d) Madrasi
a) 1. Kd1 Le4 2. Le1 Lxf3#
b) 1. Txg6[+wLf1] d4 2. Txc6[+wTh1] Ld3#
c) 1. fxg6[+wLf7] Ta6 2. Txa6[+wTa1] Lxb3[+sSf7]#
d) 1. Ld1 Tc4 2. Le1 d4#
b) 1. Txg6[+wLf1] d4 2. Txc6[+wTh1] Ld3#
c) 1. fxg6[+wLf7] Ta6 2. Txa6[+wTa1] Lxb3[+sSf7]#
d) 1. Ld1 Tc4 2. Le1 d4#
1) 1. Td6 Df3 2. Le6 Lf6#
2) 1. g4 Dg6 2. Ld5 Ld6#
3) 1. Lh7 Lxg5 2. Le4 Lf4#
2) 1. g4 Dg6 2. Ld5 Ld6#
3) 1. Lh7 Lxg5 2. Le4 Lf4#
Keywords: Echo-Kombinationen
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 6b1/4BQ2/8/4k1p1/3r4/8/8/4K3
Input: Michal Dragoun, 1998-04-09
Last update: hpr, 1999-11-09 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 6b1/4BQ2/8/4k1p1/3r4/8/8/4K3
Input: Michal Dragoun, 1998-04-09
Last update: hpr, 1999-11-09 more...
1) 1. Ke5 Kd3 2. Ld6 Tf5#
2) 1. Ke3 Tf2 2. Lf4 Te2#
3) 1. Lf4 Tf6 2. Ke5 Te6#
2) 1. Ke3 Tf2 2. Lf4 Te2#
3) 1. Lf4 Tf6 2. Ke5 Te6#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/2b2R2/8/8/2KNk3/8/8/8
Input: Michal Dragoun, 1998-04-09
Last update: hpr, 2010-06-04 more...
s) 1. Te4 f4 2. Lg6 Th2#
w) 1. ... La2 Te4 2. Tb2 Te1#
w) 1. ... La2 Te4 2. Tb2 Te1#
A. Luxemburg-Gedenkturnier
Entfeßlung!indirekt, Mustermatts
Felber, Volker: Korrektur zu P1405949 (2022-11-16)
comment
Entfeßlung!indirekt, Mustermatts
Felber, Volker: Korrektur zu P1405949 (2022-11-16)
comment
Keywords: Fesselungsspiel (212 000 211)
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 8/8/4B3/5b1k/3P3r/8/2R2P2/1K6
Input: Markus Manhart, 1998-04-17
Last update: Felber, Volker, 2022-11-16 more...
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 8/8/4B3/5b1k/3P3r/8/2R2P2/1K6
Input: Markus Manhart, 1998-04-17
Last update: Felber, Volker, 2022-11-16 more...
a) 1. f6 Sc4 2. Kb5 Tb6#
b) 1. Tf6 Tb6+ 2. Ka5 Sc4#
b) 1. Tf6 Tb6+ 2. Ka5 Sc4#
Yuri Bilokin: possibly Exchange bQa4-bBg8 6qb/1p3p2/R7/4N3/bk1K4/5r2/8/8 (3+7) h#2 2.1…
1.f6 Sc4 2.Kb5 Rb6# (MM)
1.Rf6 Rb6+ 2.Ka5 Sc4# (MM) (2022-12-17)
comment
1.f6 Sc4 2.Kb5 Rb6# (MM)
1.Rf6 Rb6+ 2.Ka5 Sc4# (MM) (2022-12-17)
comment
Keywords: Fesselungsspiel (212 000 220)
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 6bb/1p3p2/R7/4N3/qk1K4/5r2/8/8
Input: Markus Manhart, 1998-04-17
Last update: hpr, 1999-01-30 more...
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 6bb/1p3p2/R7/4N3/qk1K4/5r2/8/8
Input: Markus Manhart, 1998-04-17
Last update: hpr, 1999-01-30 more...
1. Sd2+ Lc2 2. Sxe4+ Td3 3. Sf6 Td5#
Keywords: Sacrifice of white pieces
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/3r4/1p2b3/1p3k2/q3Nbp1/Rn1B1p2/8/3K4
Input: HBae, 1998-03-06
Last update: Felber, Volker, 2023-02-08 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/3r4/1p2b3/1p3k2/q3Nbp1/Rn1B1p2/8/3K4
Input: HBae, 1998-03-06
Last update: Felber, Volker, 2023-02-08 more...
1) 1. exd4 Tc6 2. Ke5 Txe6+ 3. Kd5 Lc4#
2) 1. Kxd4 Tc7 2. Kd5 Lb5 3. Kd6 Td7#
2) 1. Kxd4 Tc7 2. Kd5 Lb5 3. Kd6 Td7#
Tempozug
Yuri Bilokin: you can see 1...Rc6 2.exd4 Rxe6+ 3.Kd5 Bc4#
1...Rc6 2.Kd5 Rxe6 3.exd4 Bc4#
1...Rc7 2.Kd5 Bb5 3.e4 Rd7#
1...Rc7 2.Kd5 Kb5 3.e4 Rd7# (2024-03-09)
comment
Yuri Bilokin: you can see 1...Rc6 2.exd4 Rxe6+ 3.Kd5 Bc4#
1...Rc6 2.Kd5 Rxe6 3.exd4 Bc4#
1...Rc7 2.Kd5 Bb5 3.e4 Rd7#
1...Rc7 2.Kd5 Kb5 3.e4 Rd7# (2024-03-09)
comment
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/4p3/2R1p3/1K1Pk3/8/8/5B2
Input: Thomas Maeder, 1998-05-26
Last update: hpr, 1999-11-11 more...
a) 1. Ke3 Kc5 2. Kd3 Kb4 3. Kc2 Ka3 4. Kb1 Lf5#
b) 1. Kd3 Sxd4 2. Kc4 Sc6 3. Kb5 Kc7 4. Ka6 Lf1#
b) 1. Kd3 Sxd4 2. Kc4 Sc6 3. Kb5 Kc7 4. Ka6 Lf1#
Yuri Bilokin: you can see in a) 1...Kc5 2.Kd3 Kb4 3.Kc2 Ka3 4.Kb1 Bf5# Gracefully and more meaningfully done later P1005864 (2022-12-12)
comment
comment
Keywords: Punkt-Echo
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/3K4/8/2p1k3/1N5B/8/8
Input: Ronald Schäfer, 1997-10-29
Last update: Felber, Volker, 2022-12-11 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/3K4/8/2p1k3/1N5B/8/8
Input: Ronald Schäfer, 1997-10-29
Last update: Felber, Volker, 2022-12-11 more...
82 - P0550041
Jacobus Theodorus Sanderse
8711 feenschach 03/1968
(2+5) C+
h#6
b) -sBe7
c) sKg1 nach f2
Jacobus Theodorus Sanderse
8711 feenschach 03/1968
(2+5) C+
h#6
b) -sBe7
c) sKg1 nach f2
a) 1. Dh5 d4 2. g5 d5 3. g4 d6 4. g3 dxe7 5. g2 e8=D 6. Dh2 De1#
b) 1. Kh2 d4 2. Dg1 d5 3. g5 d6 4. g4 d7 5. g3 d8=D 6. g2 Dh4#
c) 1. Kg3 d4 2. Kh4 d5 3. Dg3 d6 4. g5 dxe7 5. Lf8 exf8=D 6. g4 Dh6#
b) 1. Kh2 d4 2. Dg1 d5 3. g5 d6 4. g4 d7 5. g3 d8=D 6. g2 Dh4#
c) 1. Kg3 d4 2. Kh4 d5 3. Dg3 d6 4. g5 dxe7 5. Lf8 exf8=D 6. g4 Dh6#
Keywords: Echo-Kombinationen, Excelsior white (auto key), Minimal (B), Obvious promotion (l)
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/4p1p1/6qb/8/8/8/K2P4/6k1
Input: Ronald Schäfer, 1997-12-16
Last update: A.Buchanan, 2023-07-25 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/4p1p1/6qb/8/8/8/K2P4/6k1
Input: Ronald Schäfer, 1997-12-16
Last update: A.Buchanan, 2023-07-25 more...
1) 1. Kb2 Lb4 2. Kc1 Lxc3 3. Kd1 Te1#
2) 1. Ld3 Te3 2. Lb5 Txc3+ 3. Ka4 Ta3#
3) 1. Ka4 Lb4 2. Lb3 Lxc3 3. Sc2 Ta5#
2) 1. Ld3 Te3 2. Lb5 Txc3+ 3. Ka4 Ta3#
3) 1. Ka4 Lb4 2. Lb3 Lxc3 3. Sc2 Ta5#
Keywords: Echo-Kombinationen
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/2B1R2K/3P4/1kp5/2b5/n7
Input: Ronald Schäfer, 1998-01-02
Last update: hpr, 1999-01-09 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/2B1R2K/3P4/1kp5/2b5/n7
Input: Ronald Schäfer, 1998-01-02
Last update: hpr, 1999-01-09 more...
1) 1. Td3 Lg4 2. Ke3 Ke5 3. h5 Te2#
2) 1. Te4 Lh5 2. Ke3 Txc3+ 3. Kf4 Tf3#
3) 1. Kd3 Ld1 2. Ke4 Tg2 3. Kf4 Tg4#
4) 1. h5 Kg5 2. Te6 Td2+ 3. Ke5 Td5#
2) 1. Te4 Lh5 2. Ke3 Txc3+ 3. Kf4 Tf3#
3) 1. Kd3 Ld1 2. Ke4 Tg2 3. Kf4 Tg4#
4) 1. h5 Kg5 2. Te6 Td2+ 3. Ke5 Td5#
Sally: Miniatur mit viermaliger Abwandlung von Turmblocks. Alle Lösungen enden zwar mattrein, sin aber alles andere als offensichtlich. (2018-10-25)
Yuri Bilokin: you can see 1...Bd1 2.Ke4 Rg2 3.Kf4 Rg4# (2023-06-07)
comment
Yuri Bilokin: you can see 1...Bd1 2.Ke4 Rg2 3.Kf4 Rg4# (2023-06-07)
comment
Keywords: Echo-Kombinationen
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/5K1p/8/3k4/2p1rB2/2R5/8
Input: Ronald Schäfer, 1998-01-03
Last update: hpr, 1999-01-09 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/5K1p/8/3k4/2p1rB2/2R5/8
Input: Ronald Schäfer, 1998-01-03
Last update: hpr, 1999-01-09 more...
85 - P0550452
Carel Johan Robert Sammelius
Shakhmatna Misl 10/1979
3. Lob
Bulgaria 100 JT
(4+4) C+
h#3
5.1...
Carel Johan Robert Sammelius
Shakhmatna Misl 10/1979
3. Lob
Bulgaria 100 JT
(4+4) C+
h#3
5.1...
1) 1. Lh3 Te1 2. Kxf2 Le7 3. Lg2 Lh4#
2) 1. Ld3+ Kxb6 2. Le2 Tg1+ 3. Kxf2 Lc5#
3) 1. Le4 Td1 2. Kxf2 Td2+ 3. Ke3 Lh6#
4) 1. Lg4 Th1 2. Kxf2 Th2+ 3. Kg3 Ld6#
5) 1. Kh2 Le7 2. Kh3 Th1+ 3. Kg4 Th4#
2) 1. Ld3+ Kxb6 2. Le2 Tg1+ 3. Kxf2 Lc5#
3) 1. Le4 Td1 2. Kxf2 Td2+ 3. Ke3 Lh6#
4) 1. Lg4 Th1 2. Kxf2 Th2+ 3. Kg3 Ld6#
5) 1. Kh2 Le7 2. Kh3 Th1+ 3. Kg4 Th4#
Keywords: Echo-Kombinationen
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 5B2/8/1p6/1K3b2/8/5p2/5Pk1/5R2
Input: Ronald Schäfer, 1998-02-21
Last update: Marcin Banaszek, 2020-06-13 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 5B2/8/1p6/1K3b2/8/5p2/5Pk1/5R2
Input: Ronald Schäfer, 1998-02-21
Last update: Marcin Banaszek, 2020-06-13 more...
86 - P0551651
Tibor Florian
1117/8 Revista Romana de Sah 11/1936
1. ehrende Erwähnung
(6+4) C+
h#2
b) sLh6 nach g5
Tibor Florian
1117/8 Revista Romana de Sah 11/1936
1. ehrende Erwähnung
(6+4) C+
h#2
b) sLh6 nach g5
a) 1. Sxf5 Sc3 2. Kd4 Lf6#
b) 1. Sxd5 Sg3 2. Kf4 Ld6#
b) 1. Sxd5 Sg3 2. Kf4 Ld6#
Rainer Staudte: Autor: Tibor Flórián (Feldmann war sein Pseudonym) (2008-06-07)
SP: Most certainly not a pseudonym but his real name.
Like most Jews and others whose name was not sufficiently
Magyar, he was forcibly renamed by the Hungarian Nazis. (2023-03-24)
comment
SP: Most certainly not a pseudonym but his real name.
Like most Jews and others whose name was not sufficiently
Magyar, he was forcibly renamed by the Hungarian Nazis. (2023-03-24)
comment
Keywords: Echo, Sacrifice of white pieces
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 8/4B3/7b/2pNkN2/8/1P2n2P/4K3/8
Input: Hans-Jürgen Schäfer, 1997-10-11
Last update: Gerd Wilts, 2008-08-26 more...
Genre: h#
Computer test: (Popeye C-Version 3.47 (1024 KB))
FEN: 8/4B3/7b/2pNkN2/8/1P2n2P/4K3/8
Input: Hans-Jürgen Schäfer, 1997-10-11
Last update: Gerd Wilts, 2008-08-26 more...
87 - P0552248
Pal Benko
6234 Schach-Echo 19, p. 303, 10/1970
3. ehrende Erwähnung
(4+4) C+
h#2
b) wLc1 nach f1
Pal Benko
6234 Schach-Echo 19, p. 303, 10/1970
3. ehrende Erwähnung
(4+4) C+
h#2
b) wLc1 nach f1
a) 1. Sxd6 Kd3 2. Ke5 Lb2#
b) 1. Dxd6+ Sd5+ 2. Ke6 Lh3#
b) 1. Dxd6+ Sd5+ 2. Ke6 Lh3#
Benkö in 'My Life': "Creating a double Queen sacrifice like this is quite an achievement, yet the judge in the Schach Echo helpmate contest didn't appreciate it and only awarded the problem an honorable mention. Later, this problem became one of the most popular examples of the bad judging that is so common in publications."
TLi: a) There are no sacrifices, only captures.
b) The wQ can be omitted without changing the solutions.
Bad judging, indeed! (2023-02-16)
comment
TLi: a) There are no sacrifices, only captures.
b) The wQ can be omitted without changing the solutions.
Bad judging, indeed! (2023-02-16)
comment
Keywords: Sacrifice of white pieces, Aristocrat
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/4Nn2/3Qqk2/8/3K1b2/8/8/2B5
Reprints: 245 My life, games and compositions 2003
Input: Hans-Jürgen Schäfer, 1998-01-20
Last update: Mario Richter, 2016-06-25 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/4Nn2/3Qqk2/8/3K1b2/8/8/2B5
Reprints: 245 My life, games and compositions 2003
Input: Hans-Jürgen Schäfer, 1998-01-20
Last update: Mario Richter, 2016-06-25 more...
1) 1. T1b6 Sxg7 2. Sb4 Sc6#
2) 1. T8b2 Sxg6 2. Sb3 Sd4#
2) 1. T8b2 Sxg6 2. Sb3 Sd4#
Keywords: Sacrifice of white pieces
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 1r6/K4pp1/R3Nkp1/p1n1N3/7P/8/2n5/Br6
Input: Hans-Jürgen Schäfer, 1998-07-01
Last update: hpr, 1999-02-02 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 1r6/K4pp1/R3Nkp1/p1n1N3/7P/8/2n5/Br6
Input: Hans-Jürgen Schäfer, 1998-07-01
Last update: hpr, 1999-02-02 more...
1) 1. Kd6 Lh1 2. Ke6 Tg2 3. Kd5 Tg6#
2) 1. La2 Lxa2 2. Kc6/Kd6 Tb3 3. Kd5 Tb6#
3) 1. Kd6 Lg8 2. Lf7 Tb6+ 3. Kd5 Lxf7#
4) 1. Kd6 La8 2. Ke6 Tb7 3. Kd5 Tb6#
2) 1. La2 Lxa2 2. Kc6/Kd6 Tb3 3. Kd5 Tb6#
3) 1. Kd6 Lg8 2. Lf7 Tb6+ 3. Kd5 Lxf7#
4) 1. Kd6 La8 2. Ke6 Tb7 3. Kd5 Tb6#
Yuri Bilokin: you can see 1...Bh1 2.Kd6 Rg2 3.Kd5 Rg6#
1...Ba8 2.Kd6 Rb7 3.Kd5 Rb6# (2023-01-02)
comment
1...Ba8 2.Kd6 Rb7 3.Kd5 Rb6# (2023-01-02)
comment
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/2kp4/8/3B4/2bP4/4K3/1R6/8
Input: Markus Manhart, 1998-08-23
Last update: hpr, 1999-11-21 more...
1) 1. Sh2 Ta3 2. Kg2 Ta1 3. Kh1 Le4#
2) 1. Sh2 Tf3 2. Kg2 Le4 3. Kh1 Tf1#
3) 1. Kg2 Th8 2. Sg1 Lh7 3. Kh1 Le4#
2) 1. Sh2 Tf3 2. Kg2 Le4 3. Kh1 Tf1#
3) 1. Kg2 Th8 2. Sg1 Lh7 3. Kh1 Le4#
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/2K5/8/8/5n1R/8/1B4k1
Input: Markus Manhart, 1998-08-24
Last update: hpr, 1999-11-21 more...
1. d1=L Kb1 2. Lb3 axb3 3. f1=L b4 4. La6 b5 5. h1=L bxa6 6. Lb7 axb7 7. Kh4 b8=D 8. g5 Dh2#
1. a1=D a8=S 2. Da7 e8=S 3. Db8 cxb8=S#
Branko Koludrovic: This task has been improved, and the new setting has been printed in"Die Schwalbe"Feb 2002:
White: Ke8,Bc7d6e7f6g7(6)
Black:Ke6,Sd5e5 Bc2d7f4f5f7(8) H#3
1.c1D c8S 2.Dc7 g8S 3.Dd8+ exd8S#
Task Type dSSS (2010-04-05)
Anton Baumann: auch oben genannte Version ist C+ (Gustav 4.2a) (2023-02-18)
comment
White: Ke8,Bc7d6e7f6g7(6)
Black:Ke6,Sd5e5 Bc2d7f4f5f7(8) H#3
1.c1D c8S 2.Dc7 g8S 3.Dd8+ exd8S#
Task Type dSSS (2010-04-05)
Anton Baumann: auch oben genannte Version ist C+ (Gustav 4.2a) (2023-02-18)
comment
93 - P0562706
Vaclav Michal
Vratislav Hadac
5442 Schach , p. 126, 04/1967
(5+10) C+
h#2
b) sKh7 nach h8
c) ferner sSd1 nach c2
Vaclav Michal
Vratislav Hadac
5442 Schach , p. 126, 04/1967
(5+10) C+
h#2
b) sKh7 nach h8
c) ferner sSd1 nach c2
a) 1. bxa1=L Se6 2. Lh8 Sf8#
b) 1. g2 Dxb2 2. g1=T Dh2#
c) 1. Sd3 Dxb1 2. Th1 Dxh1#
b) 1. g2 Dxb2 2. g1=T Dh2#
c) 1. Sd3 Dxb1 2. Th1 Dxh1#
Harry Fougiaxis: The composer is Vratislav HADAC (2006-08-11)
Felber, Volker: Schach schreibt "V. Michal-Hadac" (2023-08-04)
Vaclav Kotesovec: The names of the authors are correct: Vratislav Hadac and Dr. Václav Míchal. See also other problem by these authors http://problem64.beda.cz/silo/ceskoslovensky_sach_1968.pdf, p.6 (in PDF). (2023-08-04)
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Felber, Volker: Schach schreibt "V. Michal-Hadac" (2023-08-04)
Vaclav Kotesovec: The names of the authors are correct: Vratislav Hadac and Dr. Václav Míchal. See also other problem by these authors http://problem64.beda.cz/silo/ceskoslovensky_sach_1968.pdf, p.6 (in PDF). (2023-08-04)
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Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/3p2Nk/3K4/5N2/2B3p1/1p4p1/1p6/Qrrnn3
Input: Markus Manhart, 1998-12-27
Last update: Felber, Volker, 2023-08-04 more...
a) 1. Db2 Lb3 2. Ka3 Ld6#
b) 1. Ka3 c3 2. Ta4 Lc1#
c) 1. Kc5 c4 2. Db4 Le3#
b) 1. Ka3 c3 2. Ta4 Lc1#
c) 1. Kc5 c4 2. Db4 Le3#
SP: Published as an original 33 years later:
275 feenschach ix/1971 (p. 141)
A double publication if the source given
in the Niemann collection is right. (2023-02-08)
comment
275 feenschach ix/1971 (p. 141)
A double publication if the source given
in the Niemann collection is right. (2023-02-08)
comment
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/3K4/8/3B4/1k1q1B2/8/2P5/8
Input: Markus Manhart, 1998-12-28
Last update: hpr, 1999-03-05 more...
1) 1. Ta2 Tb2+ 2. Kf1 Tg2 3. Te2 Tg1#
2) 1. Kh2 Tb2+ 2. Kh1 Lf4 3. Tg1 Th2#
3) 1. Kh3 Tb2 2. Tg1 Lf4 3. Tg4 Th2#
2) 1. Kh2 Tb2+ 2. Kh1 Lf4 3. Tg1 Th2#
3) 1. Kh3 Tb2 2. Tg1 Lf4 3. Tg4 Th2#
Keywords: Axis Echo, Aristocrat, Minimal, Miniature
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/8/1K2B3/6k1/rR6
Input: Markus Manhart, 1999-01-31
Last update: Rainer Staudte, 2023-06-13 more...
Genre: h#
Computer test: (Popeye C-Version 3.52 (2048 KB))
FEN: 8/8/8/8/8/1K2B3/6k1/rR6
Input: Markus Manhart, 1999-01-31
Last update: Rainer Staudte, 2023-06-13 more...
1. f3 Dxa2 2. Tb1+ Dxb1 3. b2+ Dxb2 4. Sb3+ Dxb3 5. Sd3+ Kxc2 6. Tb1 Kxd3 7. Kf1 Dxb1#
Yuri Bilokin: you can see 1...Qd5 2.Sf3+ Qd1 3.Re1 Qxe1+ 4.f1=B Qd1 5.Se1 Qd4#
1...Qd5 2.Sf3+ Qd1 3.Re1 Qxe1+ 4.f1=B Qd1 5.Sd4 Qxd4#
1...Qd5 2.Sf3+ Qd1 3.Re1 Qxe1+ 4.f1=B Qd1 5.Sh4 Qd4#
1...Qd5 2.Sf3+ Qd1 3.Re1 Qxe1+ 4.f1=B Qd1 5.Se5 Qd4# (2024-02-09)
milan: wQa8-a7 C+ by PY 4.61 M.Frelih (2024-03-28)
comment
1...Qd5 2.Sf3+ Qd1 3.Re1 Qxe1+ 4.f1=B Qd1 5.Sd4 Qxd4#
1...Qd5 2.Sf3+ Qd1 3.Re1 Qxe1+ 4.f1=B Qd1 5.Sh4 Qd4#
1...Qd5 2.Sf3+ Qd1 3.Re1 Qxe1+ 4.f1=B Qd1 5.Se5 Qd4# (2024-02-09)
milan: wQa8-a7 C+ by PY 4.61 M.Frelih (2024-03-28)
comment
Genre: h#
Computer test: Popeye C-Version 3.52 (2048 KB)
FEN: Q7/8/8/8/5p2/1pp5/prp2ppp/n1K1nrkb
Input: Markus Manhart, 1999-02-25
Last update: Alfred Pfeiffer, 2020-04-29 more...
* 1. ... e7 2. Kf5 e8=L 3. Ke4 Lg6#
* 1. ... e7 2. Kd3 e8=L 3. Ke4 Lg6#
1. e2 e7 2. e1=T e8=L 3. Te3 Lg6#
* 1. ... e7 2. Kd3 e8=L 3. Ke4 Lg6#
1. e2 e7 2. e1=T e8=L 3. Te3 Lg6#
SCHRECKE: Die Inkorrektheit besteht darin, dass im Satz 2. Kf5 und 2. Kd3 geht. (2022-10-23)
HBae: Mögliche Korrektur wSd3 statt wLg3, C+ Popeye v4.37 (2022-10-23)
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HBae: Mögliche Korrektur wSd3 statt wLg3, C+ Popeye v4.37 (2022-10-23)
more ...
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Keywords: under-promotion (sT, wL), Miniature
Genre: h#
Computer test: (Popeye WINDOWS98-32Bit-Version 3.75 (2048 KB))
FEN: 8/8/4P3/2K5/4k3/4ppB1/8/8
Input: Hans-Jürgen Schäfer, 1999-02-22
Last update: Dieter Berlin, 2022-10-23 more...
Genre: h#
Computer test: (Popeye WINDOWS98-32Bit-Version 3.75 (2048 KB))
FEN: 8/8/4P3/2K5/4k3/4ppB1/8/8
Input: Hans-Jürgen Schäfer, 1999-02-22
Last update: Dieter Berlin, 2022-10-23 more...
1. Txa2 Sxa2 2. Kb6 Sc1 3. Kc7 Sa2 4. Kd8 Sc1 5. Ke8 Sa2 6. Kf8 Sc1 7. Kg8 Sa2 8. Kh7 Sc1 9. Kg6 Sa2 10. Kxf6 Sc1 11. Ke7 Sa2 12. f5 Sc1 13. f4 Sa2 14. f3 exf3 15. e2 Kd2 16. Kd8 Sc3 17. Kc7 Sa4 18. Kc6 Tc3#
Keywords: Capture key, Switchback (Sk), Entblockung, Round Trip (k-8), Square vacation
Genre: h#
Computer test: C+, popeye 4.87
FEN: 8/1b1p1p2/k2p1P2/1p1p4/1P1P4/BRKPp3/NPP1P3/r1N5
Input: hpr, 1999-03-30
Last update: Gunter Jordan, 2022-12-01 more...
Genre: h#
Computer test: C+, popeye 4.87
FEN: 8/1b1p1p2/k2p1P2/1p1p4/1P1P4/BRKPp3/NPP1P3/r1N5
Input: hpr, 1999-03-30
Last update: Gunter Jordan, 2022-12-01 more...
1. g4 Lxg4 2. Lg5 Lf3 3. Lh6 ... 4. Lf8 ... 5. Ld6 ... 6. Lc7 ... 7. La5 ... 8. Lb4 ... 9. La3 ... 10. Lc1 ... 11. Ld2 ... 12. Le1 ... 13. Lf2 ... 14. Lxg1 ... 15. Kg5 ... 16. Kh6 ... 17. Kg7 ... 18. Kf8 ... 19. Ke7 ... 20. Kd6 ... 21. Kc7 ... 22. Kb6 ... 23. Ka5 ... 24. Kb4 ... 25. Ka3 ... 26. Kb2 ... 27. Kc1 ... 28. Kd2 ... 29. Ke1 ... 30. Kxf1 ... 31. Ke1 Kxg1 32. Kd1 Kf1 33. Kc1 Ke1 34. Kb2 Kd1 35. Ka3 Kc1 36. Ka4 Kb1 37. Ka5 Ka2 38. Kb6 Ka3 39. Kc6 Ka4 40. Kd6 Kb5 41. Ke7 Kc6 42. Kf8 Kd6 43. Kg7 Ke6 44. Kh8 Kxf6 45. Kg8 Kg6 46. Kh8 f6 47. Kg8 f7+ 48. Kh8 f8=D,T#
James Malcom: I don’t believe that the great Fabel, with his keen eye, would have not seen such a simply cook as the taking of Black’s c5 pawn. I suspect that a Black bishop was on d4 but was forgotten placing the problem in the database, or it was a misprint. I am changing this problem to not cooked for now. However, someone should check the original source in the event I am wrong, which is always a possibility. (2020-03-15)
Mario Richter: Hi, James, there's indeed a black bishop on d4. Original stipluation: "h#48 (nicht exakt!)"
A scan for some issues of 'Schachmatt' is available in the archive at stere.ro, see
www.stere.ro/wp-content/uploads/2014/06/stere_sah_istoria_sahului-1947-1949-Schachmatt1.pdf (2020-03-26)
Joost de Heer: Stupid question, but won't moving Bh3 to g4 add another halfmove? (2023-01-30)
Henrik Juel: Yes, Joost, but this would make the solution even less exact
0... Lf3,Lh3,Lh5 1.g4 Lxg4 etc. (2023-01-30)
Joost de Heer: @Henrik: So? This is an attempt at a non-unique (exact is something else) h# length record, the level of non-uniqueness is irrelevant. And as James pointed out, adding Kg4-f4 will add yet another move.
Only possible cooks are when white starts with 1... Bh5 2. g4 Be8 (so not capturing Pg4) but I don't see how that could lead to a quicker mate. (2023-01-31)
James Malcom: I double-checked that myself, Joost, and found that going around for wPg2 actually takes far longer, which would be required any PxB action to take place, but that takes far longer than the normal solution. I know Olaf's Gustav would check, since it C+ the h#111. (2023-01-31)
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Mario Richter: Hi, James, there's indeed a black bishop on d4. Original stipluation: "h#48 (nicht exakt!)"
A scan for some issues of 'Schachmatt' is available in the archive at stere.ro, see
www.stere.ro/wp-content/uploads/2014/06/stere_sah_istoria_sahului-1947-1949-Schachmatt1.pdf (2020-03-26)
Joost de Heer: Stupid question, but won't moving Bh3 to g4 add another halfmove? (2023-01-30)
Henrik Juel: Yes, Joost, but this would make the solution even less exact
0... Lf3,Lh3,Lh5 1.g4 Lxg4 etc. (2023-01-30)
Joost de Heer: @Henrik: So? This is an attempt at a non-unique (exact is something else) h# length record, the level of non-uniqueness is irrelevant. And as James pointed out, adding Kg4-f4 will add yet another move.
Only possible cooks are when white starts with 1... Bh5 2. g4 Be8 (so not capturing Pg4) but I don't see how that could lead to a quicker mate. (2023-01-31)
James Malcom: I double-checked that myself, Joost, and found that going around for wPg2 actually takes far longer, which would be required any PxB action to take place, but that takes far longer than the normal solution. I know Olaf's Gustav would check, since it C+ the h#111. (2023-01-31)
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Keywords: Non-standard material, Promotion in the mating move
Genre: h#
Computer test: Gustav 4.2 b: Es gibt kein kürzeres Matt
FEN: 8/8/5p2/2p1pPp1/2PbPk1b/2pBp1pB/2P1P1P1/5BRK
Input: hpr, 1999-03-31
Last update: Olaf Jenkner, 2023-01-31 more...
Genre: h#
Computer test: Gustav 4.2 b: Es gibt kein kürzeres Matt
FEN: 8/8/5p2/2p1pPp1/2PbPk1b/2pBp1pB/2P1P1P1/5BRK
Input: hpr, 1999-03-31
Last update: Olaf Jenkner, 2023-01-31 more...
s) 1. 0-0 Ld4 2. Tf7 Th8#
w) 1. ... Kf1 g2+ 2. Kg1 gxh1=D#
w) 1. ... Kf1 g2+ 2. Kg1 gxh1=D#
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The problems of this query have been registered by the following contributors:
Gerd Wilts (26)hpr (15)
Erich Bartel (3)
Hans-Jürgen Schäfer (12)
Markus Manhart (24)
Ralf Krätschmer (2)
Andreas Mokosch (2)
Michal Dragoun (8)
HBae (1)
Thomas Maeder (1)
Ronald Schäfer (5)
Torsten Linss (1)
A.Buchanan: So Borodatow got it all working! In a) Black might have captured hxgxf and axPb. So castling rights might still be maintained with the ep. In b) on the other hand, it must be axb, bxa, exf and wPgxh6, so there was the cage. Promotion to TD is tolerated in the final move, although it may not be puristic, without the convention, too many mates would be excluded (2022-12-16)
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