Die Schwalbe

25 problem(s) found in 5571 milliseconds (displaying 25 problem(s)). [COMMENTDATE>=20220810 AND NOT K='Allumwandlung' AND K='bessere Version'] [download as LaTeX]

1 - P0000029
Walter Wittstock
5463 Die Schwalbe 98 04/1986
P0000029
(3+2) cooked
-1w -1s, dann h=1
R: 1. b2xBc3 b4xc3ep, dann bxa6 b3=
play all play one stop play next play all
Cook: R: 1. b2xDc3 Da3xSc3, dann 1. bxa6 bxa3=
Adrian Storisteanu: Possible fix: +bPc5. (2015-06-10)
Miguel Ambrona: The fix proposed by Adrian works.
Verified with Deadpos v.2.2. (2024-01-12)
comment
Keywords: En passant in the retro play, Help retractor, Kindergarten Problem, Minimal, Miniature, Ideal stalemate, Superseded by (P1360139)
Genre: Retro, Fairies
Computer test: cooked by Deadpos v2.3 14-Jan-2024
FEN: 8/1pK5/P7/k7/8/2P5/8/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-01-18 more...
2 - P0000136
Dmitri W. Pronkin
Andrey Frolkin

6631v Die Schwalbe 117 06/1989
Preis
P0000136
(14+14)
BP in 57.5
1. a4 h5 2. a5 h4 3. a6 h3 4. axb7 hxg2 5. h4 d5 6. h5 d4 7. h6 d3 8. h7 dxc2 9. d4 a5 10. Lh6 c1=T 11. e4 Tc5 12. Se2 Th5 13. e5 c5 14. e6 Sc6 15. b8=T a4 16. Tb4 a3 17. Ta4 c4 18. b4 c3 19. b5 c2 20. b6 c1=T 21. b7 Tc4 22. b8=T Da5+ 23. Tbb4 Lb7 24. S1c3 0-0-0 25. exf7 e5 26. Tc1 Lc5 27. f8=T a2 28. Tf3 a1=T 29. Sa2 g1=T 30. Tfa3 Tg6 31. f4 Te6 32. f5 g5 33. f6 g4 34. f7 g3 35. f8=T g2 36. Tf5 g1=T 37. Lf8 Tg7 38. Sg3 e4 39. Ld3 e3 40. 0-0 e2 41. Tcc3 e1=T 42. Lc2 T1e3 43. d5 Tdd7 44. d6 Tdf7 45. d7+ Kb8 46. Dd6+ Ka8 47. Dc7 Sge7 48. d8=T+ Sc8 49. Tdd3 Thg8 50. h8=T Tae1 51. Th6 T1e2 52. T1f2 Tce4 53. Kf1 Ld4 54. Tfc5 Se5 55. Sf5 Sc4 56. Sd6 Sb2 57. Tbc4 Sb6 58. Db8+
play all play one stop play next play all
Der absolute KBP-Längenrekord.
See P1338946 cooked.
paul: Compare with P0002278 & P0002279 (2010-04-30)
Mu-Tsun Tsai: This one is by far the toughest retro I've ever solved. Very little certain information can be determined by structural consideration alone, even with long and complicated argument. It took me five days to complete solving this. (2012-07-22)
A.Buchanan: @Mu-Tsun: that's an interesting data point - thanks for posting. (2017-09-07)
Henrik Juel: The current record is 58.5 moves in a proof game problem by the authors + Keym, Die Schwalbe 2017 (2017-09-07)
Henrik Juel: I just learned that the 58.5 move proof game has been cooked... (2017-09-07)
A.Buchanan: In retrospect, my earlier comment about "interesting data point" is a bit weak. It's actually great that for such an extreme problem, someone took substantial time to independently validate it. It's like doing science: people want to do their own new stuff, and are unwilling to take the time to validate what's already been claimed. This one has survived 30+ years, and maybe the use of constraints e.g. in Jacobi can eventually allow it to be HC+. (2021-05-29)
Olaf Jenkner: This problem is the current record, because P1338946 (58.5 moves) has been cooked. (2021-11-25)
Reto: This is C+ up to 51.0 moves with Stelvio 2.0. This ties the record for partial testing of an SPG. Took 1200 CPU hours of strategy seeking (finding 378 0+0 strategies) and another 13h of strategy playing these strategies. If this can ever be completely solved, then it needs to be the case that all strategies have 0+0 free moves, otherwise playing is utterly hopeless.
@Andrew: There is absolutely no way a brute-force based program like Jacobi ever stands a chance at solving something like this, no matter how many conditions you add. (2023-12-14)
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Keywords: Unique Proof Game, Move Length Record, Non-standard material (TTTTTTtttttt), Castling, Aristocrat, Superseded by (P1397486)
Genre: Retro
FEN: kQ3Br1/1b3rr1/1n1Nr2R/q1R4r/R1Rbr3/R1RRr3/NnB1rR2/5K2
Reprints: 584 Ukrainisches Album 1986-1990
86 Shortest Proof Games 11/1991
(6) diagrammes 103 10-12/1992
H18 FIDE Album 1989-1991 1997
feenschach 137, p. 368, 08-09/2000
Input: Gerd Wilts, 1995-06-03
Last update: James Malcom, 2021-12-25 more...
3 - P0000674
Leonid M. Borodatow
2475 Die Schwalbe 51 06/1978
P0000674
(12+11) cooked
h#3
1. ... Kgxf4 2. Tf6 e6 3. Tf8 Sg7#
play all play one stop play next play all
Cook: 1. ... exf6ep 2. 0-0-0 gxf4 3. Td7 a8=D
Failed try, as Bg4xBh5 allows bRh8 to have escaped the cage prior to ep.
Anton Baumann: Sollte eine Verbesserung von P0000777 sein.
Autorabsicht: "letzter Zug f7-f5 sonst retropatt! Jetzt ist aber die Rochade illegal, da der sTh8 nur über e8 aus seiner Ecke kommt. Daher Verführung 1. ... exf6 e.p. 2.0-0-0? Lxf4 3.Td7 a8=D#. Lösung: 1. ... Kxf4 2.Tf6 e6 3.Tf8 sg7#"
Aber: Der s h-Bauer kann auch auf h5 geschlagen worden sein; so konnte der sT über h6 aus seiner Ecke entkommen. Die vermeintliche Verführung ist also NL! (2022-12-14)
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Keywords: Castling (sg), Superseded by (P0000058)
Genre: h#, Retro
FEN: r3k3/P7/p1r3pP/4PpBN/3ppnKn/6P1/1PP2PPq/7N
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-16 more...
4 - P0000777
Leonid M. Borodatow
1424 Die Schwalbe 30 12/1974
P0000777
(12+10) cooked
h#2.5
1. ... exf6ep 2. 0-0-0? Lxf4 3. Td7 a8=D# try
1. ... Kxf4 2. Tf6 e6 3. Tf8 Sg7# solution
play all play one stop play next play all
Cook: 1. ... Kxf4 2. Te7 e6 3. Tb8 axb8=D,T#
See P0000674
Henrik Juel: The stipulation should probably read h#2.5: 1.exf6ep 0-0-0 2.Bxf4 Rd7 3.a8Q# (2003-08-18)
Anton Baumann: Letzter Zug war f7-f5, sonst retropatt. Die weissen Bauern haben 6x geschlagen. Der s a-Bauer wurde so ebenfalls als Schlagopfer benötigt und musste 2x schlagen, um sich umwandeln zu können. Weiss hat also auf h6 den s Bauern geschlagen. Unabhängig davon ob der sTe6 ein Umwandlungsturm ist oder nicht, muss der sTh8 über e8 aus der Ecke gekommen sein. Also ist die Rochade illegal!
Autorabsicht: 1. ... exf6 e.p. 2.0-0-0 Lxf4 3.Td7 a8=D# ist die Verführung!
Lösung: 1. ... Kxf4 2.Tf6 e6 3.Tf8 Sg7#
leider geht auch: 1. ... Kxf4 2.Te7 e6 3.Tb8 axb8=D,T# (2022-12-13)
A.Buchanan: I agree Anton. I suggest as a fix -bBa6 +bDc2. I think retro, solution and try all work correctly now. Do you folks agree? (2022-12-13)
Anton Baumann: Der Vorschlag von Andrew ergibt eine korrekte Lösung, aber nicht im Sinne des Autors: ohne einen s Stein auf a6 ist f6-f5+ als letzter Zug möglich, d.h. kein Retropatt weil Weiss a6-a7 zurücknehmen kann! 1. ... exf6 e.p. ist deshalb nicht zulässig. LB wollte aber dass f7-f5 der letzte Zug war, damit aber die Rochade illegal ist! (2022-12-14)
Anton Baumann: Mögliche Korrektur: a6=sL, g2=sD (2022-12-15)
A.Buchanan: Yes I agree. I had overlooked the unmove of wPa7 (2022-12-15)
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Keywords: Castling (sg), Valladao Task, Superseded by (P0000058)
Genre: h#, Retro
FEN: r3k3/P7/p3r1pP/4PpBN/3nnpKP/6PB/1P2PPb1/8
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-12-16 more...
5 - P0000899
Giuseppe Brogi
743 Die Schwalbe 06/1972
P0000899
(8+15) cooked
h#2
b) wSa1
a) 1. T2xh3 Txh3 2. 0-0 Th8#
b) 1. La4 0-0 2. Tf8 Te1#
play all play one stop play next play all
a) White cannot cross-capture, so because of sTh2, w0-0 impossible.
wBe captured sD, either to be captured on f-file or to promote without disrupting sKe8.
b) sTh2 can return to a8 only via e8 as Black cannot cross-capture, so s0-0 is impossible.
wBe was waylaid or promoted after disrupting sKe8.
Cook: 1. T2xh3 Lb4 2. Txg3 Txh8#
1. Sd2 Lf6 2. Tf8 Sd6#
(cooked by MR)
See P0003736 a companion problem.
milan: [-bPa7b6wPg3bSa1+bPg3bBa5-b4 bPc6-d6] h#2 1.2...bRh2? illegal move? M.Frelih (2023-03-30)
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Keywords: Cant Castler, Castling (wksk), Cross-capture (s,w), Superseded by (P1399805)
Genre: h#, Retro
Computer test: Popeye v4.87
FEN: B3k2r/pN1p1p2/1pp3p1/bb3p2/8/p1B3PP/5P1r/nn2K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2022-03-16 more...
6 - P0003365
Gyula Bebesi
41 Problemas 04-06/1962
P0003365
(8+14) cooked
h#2
1) 1. axb3ep bxc6+ 2. b5 cxb6ep#
2) 1. exd3ep g8=D,L+ 2. d5 cxd6ep#
play all play one stop play next play all
PRA: 1 solution with 2 parts
Henrik Juel: White captured [sLc8] on c8 and axb, so last move was either b2-b4 or d2-d4
C+ Popeye 4.61, except for the promotion dual (2020-08-03)
A.Buchanan: There's no keyword for an untolerated dual promotion! (2020-08-03)
Henrik Juel: Yes and no, Andrew
What about the cooked label? (2020-08-03)
A.Buchanan: Hi Henrik: this is obviously intentional. I tried to replace the pawn promotion with wDh8-h7+ but I ran out of pieces. I guess that Bebesi had the same difficulty. The word "cooked" seems too strong to me, but it's obviously a significant defect though (2020-08-04)
A.Buchanan: The bar is higher for helpmates than other problems, and this is unsound. However it’s not cooked but dualled. Yet all we have is “cooked” so I suppose it is in PDB-speak. I’ve added that and removed the 2.1… (2023-08-07)
Joost de Heer: Is there an 'unsound' keyword? (2023-08-07)
A.Buchanan: Hi Joost: no there isn't. It can be added, the challenge for any new common keyword would be populating it for more than a few values. (2023-08-07)
A.Buchanan: This time round, I've managed to find a fix. Bebesi's correction in WinChloe 66992 has non-standard wL. I have a feeling I've seen a similar one by Andrey Frolkin & someone else recently with a different matrix, and also non-standard wL. I've sent my effort to Joaquim Crusats at Problemas for his assessment (2023-08-08)
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Keywords: En passant as key (2), Partial Retro Analysis (PRA), En passant as mating move (2), Superseded by (P1411659, P1413906)
Genre: h#, Retro
FEN: 3qn3/1p1p2P1/B1r3p1/1PP1Kp2/pPkPp3/p1p4n/N7/2b5
Reprints: 233 Ungarische Schachproblem Anthologie , p. 188, 1983
1 Problemas 44, p. 1456, 10/2023
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-04 more...
7 - P0003659
Maurice Jago
8202v Die Schwalbe , p. 148, 10/1980
version of cooked 8202 Die Schwalbe 08/1977
P0003659
(12+14) cooked
h#2
b) sBb4->b5
a) 1. Sf2 Dxf2+ 2. Kh1 0-0-0#
b) 1. Sb1 Ta4 2. Sxg3 Th4#
play all play one stop play next play all
Cook: 1. Txg3 0-0-0 2. La2/Lb3/Lc4 Dxh1#
1. La2/Lb3/Lc4 0-0-0 2. Txg3 Dxh1#
See P0000642
Mario Richter: Hier stimmt was nicht: In der Schwalbe 08/1977 erschien als Nr. 2202 die folgende Aufgabe: 8/Pp2p1p1/Bq1p3p/4p3/1p6/n4pP1/1PPPPr1k/R3KQ1n/; h#2, b) sBb4 nach b5 und der AL a) 1.Tf2-g2 0-0-0 2.Tg2xg3 Df1xh1#; b) 1.Sa3-b1 Ta1-a4 2.Sh1xg3 Ta4-h4#, die aber in a) und b) durch 1.f3xe2 La6xb7 2.Tf2-g2 Df1xg2# nebenlösig war.
Ferner ist in nebenstehendem Diagramm sowohl in a) als auch in b) sehr wohl die w0-0-0 möglich
(Weiß hat als letzten Zug Sc7-a8, Schwarz entwandelt auf b1 und h1, Weiß auf f8); und selbst unter der Annahme, daß die w0-0-0 nur mit sBb4 möglich sei, wäre die Aufgabe mehrfach nebenlösig, z.B. durch 1.Ld5-c4 0-0-0 2.Bd6-d5 Df1xh1# (2010-05-29)
A.Buchanan: Here, the source was incorrectly given as "8202v Die Schwalbe 08/1977". No, that was where the original problem appeared, with a "v" added. So when, as here, we suspect the diagram has a typo, we would have to look through many back issues of Die Schwalbe! It turns out that this correction (itself cooked) was published (as text) in p.148 Die Schwalbe 65 10/1980. I have corrected the source. The reference to the earlier buggy problem can then cleanly be put in the "after" field. The actual typo was missing bPc7. (2024-03-06)
A.Buchanan: With the typo fixed, I think the retro-logic works ok, but there is a single cook family, fortunately repairable (2024-03-06)
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Keywords: Cant Castler, Castling (wg), Superseded by (P1415606)
Genre: h#, Retro
Computer test: both twins cooked by Popeye v4.87
FEN: NBr5/N1p3p1/1qPpp3/2bb4/1p6/n1pP1rP1/1PP1P2k/R3KQ1n
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-03-06 more...
8 - P0003666
Johannes Jacob Burbach
Alain C. White

392 Probleemblad 03/1947
P0003666
(5+8) C+
h#2
b) +sBh6
a) 1. Ta6! Lxc3 2. Ta2 0-0#
b) 1. Ta5! Kd1 2. Ta2 Kc2#
play all play one stop play next play all
Henrik Juel: In b) White may not castle, because last move was done by Ke1 or Th1 (2023-12-02)
A.Buchanan: Cute. Do wPe2 & bPe3 serve any purpose, however? (2023-12-03)
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Keywords: Cant Castler, Castling (wk), Superseded by (P1413924)
Genre: h#, Retro
Computer test: HC+ Popeye 4.61 & simple retro logic
FEN: 5n1q/6B1/5r2/7r/5p2/2p1p3/1P2P3/k3K2R
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-05 more...
9 - P0003736
Giuseppe Brogi
1249 Sinfonie Scacchistiche 07-09/1972
P0003736
(12+12) cooked
h#2
b) wSa5
a) 1. f5 Le5 2. 0-0 Th8#
b) 1. Kd8 0-0-0 2. Te8 Lf8#
play all play one stop play next play all
Try to deduce the diagram error, as we do have the intended solutions!
a) wRh7 is original, but cannot have escaped from cage by white cross-capture as there are too many captures needed. On the other hand, Black only has to make 4 captures so the cross-capture is ok.
b) changing the colour of Sa5 shifts the capture balance: now White can cross-capture but not Black, so White but not Black can castle.
Thus the retro-logic works with the diagram as it is, but the forward logic does not. How can we repair the diagram?
See P0000899 a companion problem.
A.Buchanan: Something odd going on here. There are numerous h#2 in both a&b. PRA not normally found in a problem with single solution for each twin. White has 8 pawns so trivially wRh7 must be original. (2018-10-13)
A.Buchanan: There are three similar problems by Brogi which are all twinned RS rather than PRA, but don't have diagram error. P0003743, P0003746 & P0003747. (2018-10-13)
VL: Nothing to do with Retro Strategy (nor with PRA). One definite castling is legal in every case. (2021-02-09)
Ladislav Packa: Cooked a) and b):
1...b8S and 2...R:h8# (2021-02-10)
A.Buchanan: I think the composer simply forgot that wPb7 can promote. Most of the cooks come from S promotions, but it's also possible to have QR. I've fixed it, rejigging the captures to make them still add up. I've posted in Discord, as I did with the partner composition, and will create entries for them here. (2022-03-15)
milan: +sLb8 sBa7=sT M.Frelih (2023-12-02)
A.Buchanan: Hi Milan - I don't think your suggestion quite works for b). In a) there are 0+2 spare captures, so Black can certainly cross-capture. But in b) there is 1+1 so neither side can cross-capture, so there is no solution. Please compare with P1399806, in which there are 1+2 & 2+1 spare captures, so both twins are sound. (2023-12-03)
milan: Hi Andrew my correction works only with 2.1... solutions, black or white knights on a5. are not important. (2023-12-03)
A.Buchanan: Hi Milan not really clear what you are doing, but if as well as the piece changes you proposed, you also change the stipulation to 2.1... then there is still only one solution. Even if you remove Sa5 entirely as well, there is no White cross-capture possible. (2023-12-04)
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Keywords: Castling (wgsk), Cant Castler (wgsk), Cross-capture (s,w), Superseded by (P1399806)
Genre: h#, Retro
Computer test: Popeye v4.87
FEN: 4k2r/pPp2p1R/n1pB1ppp/npP5/1P6/5PPP/2P2P2/R3K3
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2023-12-03 more...
10 - P0005036
Luigi Ceriani
36 32 personaggi e 1 autore 1955
P0005036
(14+12) cooked
Welches war der erste Zug der sD und des sK?
R: 1. ... Ld8xLc7 2. Lb6-c7 Kb7-b8 3. Lc7-b6 Kc8-b7 4. Lb6-c7 Lc7-d8 5. Lc5-b6 Lb8-c7 6. Lb6-c5 Kb7-c8 7. Ld8-b6 Kc7-b7 8. d7-d8=L Kd8-c7 9. e6xSd7 Sb6-d7 10. Sc5-a4 Sa4-b6 11. Se4-c5 d7-d6 12. Sf6-e4 Lh7-g8 13. Sg8-f6 Lf4-b8 14. Sf6-g8 Lh6-f4 15. Sg8-f6 c7-c6 16. g7-g8=S Kc8-d8 17. f6xTg7 Tg8-g7 18. e5-e6 Td8-g8 19. e4-e5 0-0-0 20. e3-e4 Lf8-h6 21. f5-f6 g7-g6 22. f4-f5 Le4-h7 23. f3-f4 Lb7-e4 24. f2-f3 Lc8-b7 25. Kb5-a5 b7xSa6
play all play one stop play next play all
alternative Auflösung (Mu-Tsun Tsai, PDB 2012-07-22, leicht gekürzt)
R: 1. ... Ld8xSc7+ 2. Sd5-c7 Kc7-b8 3. Sb6-d5 Kb7-c7 4. f2xSg3 Lc7-d8 5. Sd5-b6 Lb8-c7 6. Sf4-d5 Se4-g3 7. Se6-f4 Sc5-e4 8. Sb6-a4 Sa4-c5 9. Sc4-b6 Kc8-b7 10. Sd8-e6 Kc7-c8 11. d7-d8=S Kd8-c7 12. e6xTd7 Tb7-d7 13. Se3-c4 d7-d6 14. Sf5-e3 Le5-b8 15. Sg3-f5 Lg7-e5 16. Sf5-g3 Lf8-g7 17. Sh4-f5 g7-g6 18. Sf3-h4 Sg6-h8 19. Sh4-f3 Se5-g6 20. Sg6-h4 Lh7-g8 21. Sh8-g6 Le4-h7 22. Sg6-h8 Ke8-d8 23. Sh8-g6 Sf3-e5 24. h7-h8=S Ld5-e4 25. g6xDh7 Dh2-h7 26. g5-g6 Db8-h2 27. g4-g5 c7-c6 28. g3-g4 Dd8-b8 29. e5-e6 Tb8-b7 30. e4-e5 Lb7-d5 31. e3-e4 Lc8-b7 32. Kb5-a5 b7xSa6 33. Kc4-b5 Sd4-f3 34. Kd3-c4 Sc6-d4 35. Sc5-a6 Ta8-b8 36. Se4-c5 Sb8-c6 37. Ke2-d3 Sc5-a4 38. Ke1-e2 Da6-a3 39. Sg5-e4 Dh6-a6 40. Ta3-b3 Se4-c5 41. Db3-b2 Sf6-e4 42. Tb2-c2 Sg8-f6 43. Dd1-b3 Sf6-g8 44. Sf3-g5 Sg8-f6 45. Sg1-f3 Dh1-h6 46. Ld3-b1 h2-h1=D 47. Ta4-a3 h3-h2 48. Tb1-b2 h4-h3 49. b2-b4 h5-h4 50. Th4-a4 Sf6-g8 51. Th1-h4 Sg8-f6 52. h2xTg3 Tg6-g3 53. Lf1-d3 Th6-g6 54. e2-e3 Th7-h6 55. Sc2-a1 Th6-h7 56. Sa3-c2 Th7-h6 57. Ta1-b1 Th8-h7 58. Sb1-a3 h7-h5 59. c2-c3
Korrekturversuch s. P0003009
Henrik Juel: If you want a great solving challenge, this is the retro for you.
If you need a hint:
[Dd8] never moved, and Black castled (as you may have guessed).
If you need another hint:
Last move was Ld8xLc7+.
I gave up, but Nikolai told me the solution:
-1... Ld8xLc7 -2.Lb6 Kb7 -3.Lc7 Kc8 -4.Lb6 Lc7 -5.Lc5 Lb8 -6.Lb6 Kb7 -7.Ld8 Kc7 -8.L=d7 Kd8 -9.e6xSd7 Sb6 -10.Sc5 Sa4 -11.Sd4 d7 -12.Sf6 Lh7 -13.Sg8 Lf4 -14.Sf6 Lh6 -15.Sg8 c7 -16.S=g7 Kc8 -17.f6xTg7 Tg8 -18.e5 Td8 -19.e4 0-0-0 -20.e3 Lf8 -21.f5 g7 -22.f4 Le4 -23.f3 Lb7 -24.f2 Lc8 -25.Kb5 b7xSa6 etc. (2012-07-22)
Mu-Tsun Tsai: Once I heard "great challenge" I started working. But I came to a complete different conclusion. Not only [Qd8] can move, but the first move of the black king need not be castling. Here's the proof game. After playing
1.c3 h5 2.b4 Rh6 3.Na3 Rg6 4.Nc2 Rg3 5.hxg3 Nf6 6.Rb1 Ng8 7.Na1 Nf6 8.e3 Ng8 9.Bd3 Nf6 10.Rb2 Ng8 11.Bb1 Nf6 12.Qb3 Ng8 13.Rc2 Nf6 14.Qb2 Ng8 15.Rh4 Nf6 16.Rd4 h4 17.Rd5 h3 18.Ra5 h2 19.Ra3 h1=Q 20.Rb3 Qh5 21.Nf3 Qa5 22.Ke2 Qa3 23.Kd3 Na6 24.Kc4 Nc5 25.Kb5 Na4 26.Ne5 Nh5 27.Nd3 Nf4 28.Nc5 Nd3 29.Na6 bxa6+ 30.Ka5 Bb7 31.e4 Qb8 32.e5 Bc8 33.e6 Qb7 34.g4 Qf3 35.g5 Qh3 36.g6 Qh7 37.gxh7 Nf4 38.h8=N Bb7 39.Ng6 Be4 40.Ne5 Bh7 41.Nc4 Bg8 42.Ne3 Ng6 43.Nc4 Nh8 44.Ne3 g6 45.Nc4 Bg7 46.Ne3 Be5 47.Nc4 c6 48.Ne3,
you could either play
48...O-O-O 49.Nc4 Bb8 50.Ne3 d6 51.Nc4 Rd7 52.exd7+ Kb7 53.d8=N+ Kc7 54.Ne6+ Kb7 55.Nb6 Nc5+ 56.Na4 Ne4 57.Nc5+ Kc7 58.Nd7 Kb7 59.Nb6 Ng3 60.Nd5 Bc7+ 61.Nb6 Bd8 62.fxg3 Kc7 63.Nd5+ Kb8+ 64.Nc7 Bxc7+,
which is castling version, or,
48...Kd8 49.Nc4 Kc7 50.Ne3 Rd8 51.Nc4 Kc8 52.Ne3 Bb8 53.Nc4 d6 54.Ne3 Rd7 55.exd7+ Kb7 56.d8=N+ Kc7 57.Ne6+ Kb7 58.Nc4 Bh7 59.Nb6 Nc5+ 60.Na4 Ne4 61.Nd4 Kc7 62.Ne6+ Kc8 63.Nd4 Kb7 64.Ne6 Bg8 65.Nc5+ Kc7 66.Nd7 Kb7 67.Nb6 Ng3 68.Nd5 Bc7+ 69.Nb6 Bd8 70.fxg3 Kc7 71.Nd5+ Kb8+ 72.Nc7 Bxc7+
which is none castling version. Both reach the diagram position.
Why am I feeling cooking Ceriani's problems too much lately? (2012-07-22)
Mu-Tsun Tsai: Also in your retraction, -11.Nd4 should be -11.Ne4 I believe? It seems like your retraction also works just fine, and looks like it should be the intended solution. (2012-07-22)
Henrik Juel: Yes, the intended solution should have -11.Se4, and it can be shortened a bit.
I am impressed by your cook, Mu-Tsun, with two white pawn captures on g3 and promotion on h8, but it is also a little sad that a seemingly fine problem has been rendered worthless.
Probably several more Ceriani problems will be cooked, because they were not scrutinized well enough by testers and solvers in the old days; now, when I finally have cracked a Ceriani nut, I have no energy left to search for errors (2012-07-23)
Mu-Tsun Tsai: I've been thinking about how this problem might be fixed, but unfortunately I cannot come up with anything other than adding extra assumptions in the stipulation, for example "g3 pawn came from h2". The structure of this one is good, and either method of releasing the position (mine or the intended one) is quite subtle, so I feel sad about have to cook this one as well. (2012-07-23)
Thomas Volet: In his 1961 book Ceriani discusses the cook with the WhP unpromoting on h8 and uncapturing to the g file and back to the h file, and gives P0003009 as the corrected diagram position. (2012-08-02)
Mu-Tsun Tsai: This is a really late comment, but I do think this will make a great problem by changing the stip to "You don't know the first move of the black queen nor the black king"! (2023-06-29)
comment
Keywords: First Move? (kd), Superseded by (P0003009)
Genre: Retro
FEN: 1k4bn/p1b1pp2/p1pp2p1/K7/NP6/qRP3P1/PQRP2P1/NBB5
Input: Gerd Wilts, 1995-06-03
Last update: Mario Richter, 2023-07-02 more...
11 - P0005911
Unto Heinonen
2375 U.S. Problem Bulletin 01-02/1992
P0005911
(13+16) cooked
BP in 34,5
1. Sc3 h5 2. Se4 h4 3. Sg3 hxg3 4. h4 Th5 5. Th2 gxh2 6. Tb1 hxg1=S 7. Ta1 Sh3 8. Tb1 Sf4 9. Ta1 Sd5 10. Tb1 Sb4 11. Ta1 Td5 12. Tb1 g5 13. Ta1 Lg7 14. Tb1 Ld4 15. Ta1 Lb6 16. Tb1 c5 17. Ta1 Dc7 18. Tb1 De5 19. Ta1 Ld8 20. Tb1 b6 21. Ta1 La6 22. Tb1 Lc4 23. Ta1 a6 24. Tb1 Ta7 25. Ta1 Tc7 26. Tb1 Tc6 27. Ta1 Tf6 28. Tb1 d6 29. Ta1 Kd7 30. Tb1 Ke6 31. Ta1 Kf5 32. Tb1 Kg4 33. Ta1 Tf5 34. Tb1 Sf6 35. Ta1
play all play one stop play next play all
Korrektur siehe P0008426.
James Malcom: What is the cook? (2023-05-02)
more ...
comment
Keywords: Unique Proof Game, Non-standard material, Pendulum (T x30), Superseded by (P0008426)
Genre: Retro
FEN: 1n1b4/4pp2/pp1p1n2/2prqrp1/1nb3kP/8/PPPPPPP1/R1BQKB2
Reprints: (12) feenschach 117 11/1995
Input: Gerd Wilts, 1995-06-26
Last update: James Malcom, 2023-05-02 more...
12 - P0006339
Yosif Krikheli
8945 FEENSCHACH 09-10/1968
P0006339
(1+1) cooked
-1w -1s, dann h=1
2 Lösungen
1) R: 1. Kc5xDd6 Dd7xDd6, dann 1. Dc6 Dxc6=
2) R: 1. Kc5xBd6 c7xDd6, dann 1. c6 Dxc6#
play all play one stop play next play all
siehe 9200
mri: Mehrere NL, z.B. R: Kc6xLd6 Lc5xDd6 V: 1.Ka5-a6 Dd6xc5 oder R: Kc5xTd6 Tb6xDd6 V: 1.Tb6-c6 Dd6xc6 (2007-10-25)
Mario Richter: s. P0005054 (2009-12-31)
A.Buchanan: Reasonable to suppose that P0005054 is the correction (2024-01-15)
comment
Keywords: Help retractor, only Kings, Aristocrat, Miniature, Superseded by (P0005054)
Genre: Retro, Fairies
Computer test: C- Deadpos v2.3 14-Jan-2024
FEN: 8/8/3K4/k7/8/8/8/8
Input: Gerd Wilts, 1995-09-10
Last update: A.Buchanan, 2024-01-18 more...
13 - P0515072
Thomas R. Dawson
4056 Stratford Express 18/09/1937
P0515072
(4+5) cooked
h#2
1. d4 Sh6 2. Tg5 Ta6#
play all play one stop play next play all
Cook: NL:
1. d4 Kg8 2. Tf5 Ta6#
Adrian Storisteanu: Possible fix (a bit rough, but the wK is still employed):
Kg7 Ra1 Se6 Sf5 / Ke5 Rb4 Rd2 Sh8 pc4 pd3 (4+6)
1.c3 Sg5 2.Rf4 Ra5#. (2019-10-12)
A.Buchanan: Pushing wS to f8 & h6 seems to fix the cook. Maybe that's where they were meant to be all along: hard to imagine old TRD making such an error. WinChloe hasn't got this one, so can't confirm. (2019-10-14)
Adrian Storisteanu: Nice workaround, Andrew! Dawson had his share of cooks... (2019-10-14)
Yuri Bilokin: possibly wNf7-f5, bRe2-f2, -bPe4 7K/8/5kN1/1r1p1N2/8/8/5r2/R7 (4+4) (2022-12-16)
comment
Keywords: Symmetrical position, Asymmetrical solution, Superseded by (P1389169)
Genre: h#
FEN: 7K/5N2/5kN1/1r1p4/4p3/8/4r3/R7
Input: Hans-Jürgen Schäfer, 1997-09-01
Last update: A.Buchanan, 2021-05-02 more...
14 - P0582614
Branko Koludrovic
Mat (Belgrade) 1984
P0582614
(5+15) cooked
h#3
1. fxg1=S c8=S 2. Sh3 hxg8=S 3. b1=S Txe1#

NL:
1. Ke5 c8=D 2. Dd6 Dc1 3. f6 De3#
1. Se7 Kh3 2. Sf6 Lh2 3. Td8 cxd8=S#
play all play one stop play next play all
milan: i've tested by Linux 4.87 128 MB C+ M.Frelih (2022-12-11)
A.Buchanan: what's your suggested position, Milan? (2022-12-11)
milan: my purpose was to show difference beetwen gustav program and linux.i've solved with linux and found intended solution in 30 sec. Gustav found cooks? M.Frelih (2022-12-12)
A.Buchanan: When you say Linux, do you mean Popeye? When I solve with helpmate analyser, it finds a lot of cooks e.g. those shown here already (2022-12-13)
Ulrich Voigt: Just for the record, Popeye on Linux does find those cooks (11 solutions in total). (2022-12-14)
milan: i've tested in YACPDB site C+ M.Frelih (2022-12-17)
more ...
comment
Keywords: Superseded by (P0559785)
Genre: h#
FEN: 4n1nr/2Pb1p1P/2q1k3/3p1p2/8/8/pp3ppK/r3b1BR
Input: hpr, 2001-03-25
Last update: A.Buchanan, 2022-12-13 more...
15 - P1094839
Vladislav Nefyodov
Rashid Usmanov

Shakhmatnaya Poeziya 42 2008
5th Honourable Mention
P1094839
(3+12) cooked
h#3
b) sBg2 nach h2
a) 1. Txh7+ Kxh7 2. Kh2 Txg4 3. Sg3 Th4#
b) 1. Lxg7+ Kxg7 2. Kg2 Lxf5 3. g3 Le4#

NL:
a) 1. Txh7+ Kxh7 2. Kh2 Tg5 3. g3 Th5#
b) 1. Txh7+ Kxh7 2. Kh4 Kg6 3. Tg3 Th7#
play all play one stop play next play all
Yuri Bilokin: correction bBe6-f7 7K/5bRB/8/5p2/6p1/4n1kr/q4pp1/b4nr1 (3+12) (2023-05-22)
A.Buchanan: This exact correction was made by the authors in 2009, see P1094987. (2023-05-22)
comment
Keywords: Superseded by (P1094987)
Genre: h#
Computer test: Popeye Windows-32Bit v4.51 (100000 KB)
FEN: 7K/6RB/4b3/5p2/6p1/4n1kr/q4pp1/b4nr1
Input: hpr, 2009-11-21
Last update: A.Buchanan, 2023-05-22 more...
16 - P1185584
Mrs. W. J. Baird
La Strategie
P1185584
(3+3) cooked
-1w,-1s, dann h#1, keine Damen
R: 1. Sc5xTe6 h7xTg6, dann 1. Te6-d6 Tg6-g5#
play all play one stop play next play all
Cook: R: 1. Sc5-e6 (oder Sc5xTe6) Kc4xTd5, dann 1. Kc4-b5 Sc5-d3# (oder Sa6#)
Motto: "Our play"
Originalforderung 1.White played last, retract his move 2.Black retracts his last move 3.Black plays so as to enable-- 4.White to mate 5.No Queens
A.Buchanan: The issue is that wPb3 covers a4. Rotate the board clockwise by 90 deg & shift wPc7 to c5 gives unique queenless solution R: 1. Se6xTf4 g3xTf2, dann 1. Tf5 Te2#, together with 68 queeny tries. (2022-11-13)
Adrian Storisteanu: The wQ is, unfortunately, extremely deadly. In your suggested position, there are still cooks, e.g.,
- 1.Kg6xPg7 g3xQf2 & 1.g3-g2 Qf2-e3#
- 1.Sg2xRf4 e3xQf2 & 1.Rf4-e4 Qf2-f6# (2022-11-13)
A.Buchanan: Yes I make no attempt to remove the "keine Damen" constraint, which is a kind of thematic aid that Baird employs quite often. deadpos identifies 69 solutions in the rotated position 8/6K1/8/2Ppk3/5N2/8/5p2/8, of which 68 require a queen (2022-11-13)
Adrian Storisteanu: The "no queens" constraint seems here almost thematic, as the intended solution works just as fine with a wQ uncapture: - 1.Sc5xRe6 h7xQg6 & 1.Re6-d6 Qg6-g5#... (2022-11-13)
Adrian Storisteanu: (What is "deadpos"?) (2022-11-13)
Adrian Storisteanu: A quick fix along your intention is also -wPb3,+bPc4 (90 queeny tries). (2022-11-13)
A.Buchanan: deadpos is a software engine that determines very efficiently whether a position is dead or not, and allows stipulations such as h=, hdp, h#. Simple retractions are also important for DP last move problems, and since no-one who's written help retractor functionality has ever made it public, this is of use for testing neglected problems such as Mrs Baird's, which have little to do with DP rule. A broader name for this engine will probably emerge at some point.
Your fix -wPb3, + bPc4 also works! (2022-11-13)
comment
Keywords: Help retractor, Miniature, Constrained problem, Superseded by (P1414378)
Genre: Retro
Computer test: C- deadpos v1.0: 1 solution + 2x2 cooks
FEN: 8/1K6/4N1p1/3k4/3p4/1P6/8/8
Reprints: 66 Twentieth Century Retractor 1907
Input: Mario Richter, 2011-01-23
Last update: A.Buchanan, 2024-01-08 more...
17 - P1240697
Dmitri Baibikow
C22 Length Records in Last Single Moves? 11/2009
P1240697
(12+10) cooked
Last 46 single moves?
R: 1. Tc3xDc2 h5xSg4 2. Se5-g4 h6-h5 3. Sf3-e5 h7-h6 4. Se1-f3 Dd1-c2 5. Sc2-e1 Df1-d1 6. g5-g6 f2-f1=D 7. g4-g5 f3-f2 8. g3-g4 g4xSf3 9. Se5-f3 g5-g4 10. Sd7-e5 g6-g5 11. Sc5-d7 g7-g6 12. Sa4-c5 Sd1-b2 13. Sb2-a4 Sf2-d1 14. f5-f6 Sh3-f2 15. f4-f5 Sg1-h3 16. f3-f4 g2-g1=S 17. f2-f3 f3xDg2 18. Dh3-g2 f4-f3 19. Dc8-h3 f5-f4 20. Da8-c8 f6-f5 21. a7-a8=D f7-f6 22. a6-a7 a7xDb6 23. Kc5-b5 La5-b4
play all play one stop play next play all
Cook: alternative Auflösung (mri, PDB 03.07.2023)
R: 1. Tc3xDc2 g5-g4 2. f5-f6 f6xSg5 3. Sf3-g5 f7-f6 4. Se1-f3 Dd1-c2 5. Sc2-e1 Dg1-d1 6. g5-g6 g2-g1=D 7. g4-g5 h3xDg2 8. Dg3-g2 h4-h3 9. Db8-g3 h5-h4 10. Da8-b8 h6-h5 11. a7-a8=D h7-h6 12. a6-a7 a7xSb6 13. Kc5-b5 La5-b4 14. Kd5-c5 Da4-b3 15. Ke5-d5 Sd6-c4 16. Kf4-e5 Se8-d6 17. Kg3-f4 Lb5-d3 18. Le7-a3 Sd3-b2 19. Ta3-c3 Kb2-c1 20. Td1-d2 Sc1-d3 21. Th1-d1 Sd2-b1 22. Kg2-g3 Sf1-d2 23. Se1-c2 Sf6-e8 24. g3-g4 f2-f1=S 25. Sf3-e1 c2-c1=S 26. d2xTe3 Tc3-e3 27. Sg1-f3 Tc8-c3 28. Kf1-g2 Ld7-b5 29. Le6-a2 Th8-c8 30. Ta1-a3 Sg8-f6 31. f4-f5 f3-f2 32. c3xBd4 Kb3-b2 33. Lh3-e6 g4xDf3 34. La3-e7 g5-g4 35. Lc1-a3 g7-g5 36. b2xTc3 Tc8-c3 37. Df2-f3 Ta8-c8 38. De1-f2 Lc8-d7 39. d3xBe4 c3-c2 40. f3-f4 Kb4-b3 41. c2xSd3 Dd7-a4 42. Dd1-e1 Kc5-b4 43. Sc4-b6 Kd6-c5 44. Sa3-c4 Ke7-d6 45. Sb1-a3 Ke8-e7 46. Ke1-f1 Sc5-d3 47. Lf1-h3 Lb4-a5 48. a5-a6 Sa6-c5 49. a4-a5 Sb8-a6 50. g2-g3 Dd8-d7 51. f2-f3 c4-c3 52. Sf3-g1 Lf8-b4 53. Sg1-f3 e5-e4 54. Sf3-g1 d5-d4 55. Sg1-f3 c5-c4 56. Sf3-g1 e7-e5 57. Sg1-f3 d7-d5 58. a3-a4 c7-c5 59. a2-a3
Gerald Ettl: Die Stellung ist falsch. wTc2 auf c3 und +sDc2 (2023-07-02)
Gerald Ettl: Bzw. vielleicht ist die Stellung richtig, aber dann stimmt die Lösungsangabe und Forderung nicht. (2023-07-02)
Mario Richter: Hallo Gerald, Type C heißt: ein K muß im Schach stehen, also ist das Diagramm wohl richtig. Die Originalforderung war "Last 46 single moves?" (nicht ... 45 ...) - da hat wohl jemand den einleitenden schachbietenden Zug vergessen. (2023-07-03)
more ...
comment
Keywords: Last Moves? (45), Non-standard material (s), Type C, Superseded by (P1353149)
Genre: Retro
FEN: 8/1p6/1p3PP1/1K6/1bnPP1p1/Bq1bP3/BnRRP2P/1nk5
Input: Gerd Wilts, 2012-06-04
Last update: A.Buchanan, 2023-07-05 more...
18 - P1386064
James Malcom
SuperProblem (Website) 15/01/2020
P1386064
(8+11) C+
#12
1. hxg8=D! a1=D+ 2. Kh2 Dg1+ 3. Kxg1 b1=D+ 4. Kh2 Dg1+ 5. Kxg1 c1=D+ 6. Kh2 Dg1+ 7. Kxg1 d1=D+ 8. Kh2 Dg1+ 9. Kxg1 e1=D+ 10. Kh2 Dg1+ 11. Kxg1 Sf4 12. f8=D#
play all play one stop play next play all
My first queening record

Record of 2+5 queen promotions

http://superproblem.ru/archive/probl/N/Malcom-12x-2020.gif
more ...
comment
Keywords: Promotion (Dd), Promotion key, Promotion in the mating move, Superseded by (P1378033), Capture key, Pendulum (K), Promotions to queens, konsekutive Umwandlungen 7 (DdddddD)
Genre: n#
Computer test: a. Baumann: Gustav 4.2a
FEN: 2n3r1/3BkP1P/4Pp2/8/8/6BP/pppppPn1/6Kb
Input: James Malcom, 2021-02-01
Last update: Dieter Berlin, 2023-12-08 more...
19 - P1398779
Andrew Buchanan
AA006 The Hopper Magazine I01 24/12/2021
P1398779
(12+5) cooked
h=3*

play all play one stop play next play all
Cook: Set: 1. ... Th1 2. Ka1 Dg1/Tg1 3. Ka2 Df1=/Th1=
Main: 1. Ka1 Th1 2. Ka2 Dg1/Tg1 3. Ka1 Df1=/Th1=
A.Buchanan: Oops! Vlaicu Crisan informed me of a bug in the forward play. Not so easy to fix, but think I've managed. Sent back to Vlaicu, and will republish in The Hopper. (2022-12-03)
comment
Keywords: Draw by repetition, Superseded by (P1408741)
Genre: Retro, Fairies
FEN: 8/p7/8/8/8/P4P1P/kPPPPRPr/2KnrQR1
Input: A.Buchanan, 2022-01-31
Last update: Miguel Ambrona, 2023-07-26 more...
20 - P1401254
Hiroaki Maeshima
PS3693 The Problemist Supplement 173, p. 163, 07/2021
P1401254
(3+8) C+
h#4*
0.1.1...
* 1. ... ... 2. Df2 Kg5 3. d3 cxd3 4. Kf3 Sd4#
1. ... c4 2. Dg4 Sg7 3. Sf4 Se6 4. Df3 Sc5#
play all play one stop play next play all
Yuri Bilokin: More economical -bPh7, then a1=b1 8/6p1/6K1/6N1/4pkq1/5p1p/3P3n/8 (3+7)
1... ... 2.Qg2 Kh5 3.e3 dxe3+ 4.Kg3 Se4# (MM)
1...d4 2.Qh4 Sh7 3.Sg4 Sf6 4.Qg3 Sd5# (MM) (2022-05-18)
Hiroaki Maeshima: Thank you, I added the version (P1404069). (2022-09-06)
comment
Keywords: Superseded by (P1404069)
Genre: h#
Computer test: Popeye WINDOWS98-32Bit-Version 3.77 (8192KB)
FEN: 8/5p1p/5K2/5N2/3pkq2/4p1p1/2P3n1/8
Input: Felber, Volker, 2022-05-11
Last update: A.Buchanan, 2022-09-06 more...
21 - P1404281
Mikhail Mikhaylov
3 Shakhmatna Misl , p. 160, 10/1956
P1404281
(8+6) cooked
#2
1. d8=sS! droht 2. g8=S#
1. ... Sb7 2. Sd7#
1. ... Sc6 2. Te6#
1. ... Se6 2. Se4#
1. ... Sf7 2. Sg4#
play all play one stop play next play all
Cook: (found by Henrik Juel, 2022-09-12)
1. d8=sL! droht 2. g8=S#
1. ... Lc7 2. Sd7#
Henrik Juel: Popeye 4.61 finds no solution (2022-09-11)
Henrik Juel: Joke problem
1.d8=sL?? thr. 2.g8=S#
1... Lc7 2.Sd7# (2022-09-12)
Mario Richter: Does Henrik's answer show that the problem is cooked? (2022-09-12)
Henrik Juel: Yes, Mario (2022-09-12)
A.Buchanan: Could it be that bRb6 is meant to be on a6? (2022-09-13)
A.Buchanan: The point being that with bRa6, 1. d8=sL? La5! (not Lc7/Lb6 2. Sd7#/Te6#) So bishop promotion becomes a thematic try. (2022-09-13)
Mario Richter: I have access to the original issue of 'Shakhmatna Misl', so I can confirm that the black rooks are on a7 and b6. I checked some of the following issues to see, if there was a mentioning a of the cook and/or a correction, but without success.
Changing the cook 1. d8=sL! into a try would be nice, but I think the purpose of black Tb6 is to prevent the defense 1. ... Db3!, so unless I'm missing something, Andrew's suggestion doesn't work. (2022-09-13)
A.Buchanan: Thanks Mario - I didn't check enough. If further one swaps bQb8 with bRa7, and pushes wK to h2 further out of harms way, then I think the =S solution & =L try are sound: 1r6/q2Pp1P1/r4k1N/2N3R1/5p1P/8/4R2K/8 (2022-09-13)
James Malcom: Nice find, Mario; sweet fix, Andrew. (2022-09-14)
A.Buchanan: Thanks James. r7/q2Pp1P1/r4k1N/2N3R1/7P/8/8/4RK2 further saves a pawn and has better positions for the remote units. I suggest attribution is MM correction HJ,MR,AB. (2022-09-15)
A.Buchanan: Alternatively r7/q2Pp1P1/r4k1N/2N3R1/5p1K/8/8/4R3 economizes a wP rather than a bP. I don't know which version my esteemed co-creators would prefer to record this momentous achievement for posterity. I don't see a way to reach Meredith (2022-09-17)
comment
Keywords: Joke promotion, Joke, Superseded by (P1404422)
Genre: 2#
FEN: 1q6/r2Pp1P1/1r3k1N/2N3R1/5p1P/8/4RK2/8
Input: Mario Richter, 2022-09-11
Last update: A.Buchanan, 2022-09-18 more...
22 - P1405053
Norman L. Guinasso
1662 Los Angeles Times 18/11/1945
P1405053
(5+2) cooked
#3
1. S4b6? axb6 2. c4 b5 3. cxb5#
play all play one stop play next play all
Cook: Schwarz hat keinen letzten Zug, und mit Schwarz am Zug gibt es kein 3#
SCHRECKE: Schwarz hat keinen letzten Zug! (2022-10-10)
Henrik Juel: So it is Black to move, and he is stalemated (2022-10-10)
Rainer Staudte: Eine Korrektur wäre einfach, z. B. durch Verschiebung um eine Reihe nach unten. Aber wäre das Autorabsicht? (2022-10-10)
A.Buchanan: According to the Codex, mere illegality does not cook a problem or even make it unsound. But in the grunting world of PDB data fields, we only have "cooked" to express all degrees of structural displeasure. If I was fixing the problem, I would stick wLa8 on h1 instead. For then we have the tiny satisfaction of knowing that Black's last move was R: 1. Kb7xTa6.
This author is unknown to WinChloe, and only has one other problem in YAC. (I have added it here.) Amazingly, WinChloe has not heard of the LA Times either! (2022-10-11)
A.Buchanan: It's a rare name: https://www.findagrave.com/memorial/62652231/norman-l-guinasso 1920-1978 might fit as a California memorial. There's then a Norman L. Guinasso Jr, whose age might fit as a son, who retired as a Professor of Oceanography in 2015 (2022-10-11)
A.Buchanan: Or replace wLa8 with wBc6. (sBb7 also works, but is still illegal!) (2022-10-11)
more ...
comment
Keywords: Minimal, Miniature, No legal last move for Black (unintended), Superseded by (P1413729)
Genre: 3#
FEN: B1N5/p7/k7/8/1KN5/2P5/8/8
Input: Rainer Staudte, 2022-10-10
Last update: A.Buchanan, 2023-11-28 more...
23 - P1410861
James Malcom
Siegfried Hornecker
Joaquim Crusats
Andrew Buchanan

12 MatPlus.net Forum 25/06/2023
P1410861
(16+4)
What is curious about this position?

Fewest Black pieces requiring all 16 White pieces in a legal checkmate position

https://matplus.net/start.php?px=1689032781&app=forum&act=posts&fid=gen&tid=3043
A.Buchanan: Mu-Tsun Tsai suggests that for construction problems such as this, the stipulation might be "What is curious about this position?" (2023-07-13)
James Malcom: That feels apt. (2023-07-14)
more ...
comment
Keywords: Superseded by (P1410903)
Genre: Retro, Fairies
FEN: B1Qr2RK/3P2N1/1P4RB/1rP5/4kP2/PPP5/q2P4/2N5
Input: James Malcom, 2023-07-11
Last update: A.Buchanan, 2023-07-27 more...
24 - P1411257
James Malcom
Andrew Buchanan

OP029 The Hopper Magazine I03 30/12/2022
P1411257
(8+7) C+
S#2 (-:
1. Tg8! (Zugzwang)
1. ... Txg8 2. hxg8
1. ... Tf8 2. gxf8
1. ... Td8 2. cxd8
play all play one stop play next play all
SCHRECKE: Have a look at this: R4q1k/pPP3R1/rp3PKn/p5PQ/P7/8/8/8
s#2, 1. f7! - 6(!) dummy promotions (2023-07-28)
SCHRECKE: In my work a black rook on f8 is better! (2023-07-28)
A.Buchanan: Yes this is a great improvement. I can't see how one might get a 7th (2023-07-28)
more ...
comment
Keywords: Dummy Pawn, Golden Age (Dummy Pawn), Superseded by (P1411367)
Genre: s#
Computer test: C+, popeye 4.87
FEN: 2b1r2R/1pPpk1PP/1P3pB1/4pK2/4N3/8/8/8
Input: Miguel Ambrona, 2023-07-26
Last update: A.Buchanan, 2023-07-29 more...
25 - P1411659
Gyula Bebesi
v Problemas 1962
P1411659
(8+14) cooked
h#2
1. exd3ep Lg8+ 2. d5 cxd6ep#
1. axb3ep bxc6+ 2. b5 cxb6ep#
play all play one stop play next play all
PRA means one problem two parts
Cook: R: 1. Kf6-e5 Ld6-f8+
see P0003365
Henrik Juel: Intention:
White captured axSb and [Lc8]
If last move was b2-b4: 1.axb3ep bxc6+ 2.b5 cxb6ep#
If last move was d2-d4: 1.exd3ep Lb8+ 2.d5 cxd6ep# (2023-08-08)
Henrik Juel: Cook: last move could also be Kf6-e5
correction, e.g., move Sh3 to h5 (2023-08-08)
A.Buchanan: Good catch Henrik - I should have looked at this one more carefully! Luckily it admits an easy fix, but there is still the non-standard material. (2023-08-08)
Henrik Juel: I should have thought of a better birthday greeting, Andrew, but there you are (2023-08-08)
comment
Keywords: Partial Retro Analysis (PRA), En passant as key (2), En passant as mating move (2), Non-standard material (L), Superseded by (P1413906)
Genre: h#, Retro
Computer test: HC+ Popeye v4.87 & simple retro-logic
FEN: 3r1b2/1p1p3B/B1r3p1/1PP1Kp2/pPkPp3/p1p4n/N7/2q5
Reprints: Schach-Echo , p. 324, 08/1984
23 125 ausgewählte Schachprobleme , p. 10, 1985
2 Problemas 44, p. 1456, 10/2023
Input: A.Buchanan, 2023-08-08
Last update: A.Buchanan, 2023-12-04 more...
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