Die Schwalbe

14 problem(s) found in 2570 milliseconds (displaying 14 problem(s)). [COMMENTDATE>=20220810 AND NOT S='Akademische Monatshefte für Schach' AND K='Letzte Züge?'] [download as LaTeX]

1 - P0000254
Leonid M. Borodatow
7642 Die Schwalbe 133 02/1992
P0000254
(16+10)
Welches waren die letzten 7 Einzelzüge, wenn dabei keine Zugwiederholungen vorkamen?
R: 1. 0-0-0# Ke4-d4 2. e5xf6ep+ f7-f5 3. Tg6-b6+ Kf5-e4 4. c7-c8=L
play all play one stop play next play all
Die von einigen Lösern angeführte Abweichung 2. f5-f6+ Kd4-e4 3. Lh6-g7+ (und mehrdeutig weiter) ließe sich durch die Erweiterung '... keine Zugwiederholungen und keine Pendelzüge ...' (mühsam) kitten. Beim Autor hieß es bei dieser ich-weiß-nicht-wie-vielten Fassung nur 'letzte 9 (!) Einzelzüge ohne Wiederholung).
HHS meint ohnehin, daß es das ganze auch ohne die einengende Zusatzbedingung schon gibt.
Das von einem Löser angegebene 1. Ld3-h7# Th1-h8 2. Lh8-g7 Tg1-h1 3. Se1-g3 g2-g1=T 4. Th7-h8=L scheitert allerdings an der Schlagbilanz.
Anton Baumann: Neufassung vergl. P0006288 (2023-01-06)
comment
Keywords: En passant, Last Moves?, Non-standard material, Castling (wl), Promotion (L), Valladao Task (WWW)
Genre: Retro
FEN: qrB2brr/Bp2p1BB/pR3P2/1Q6/2Pk1P2/B1p2R2/2P3N1/2KR1N2
Input: Gerd Wilts, 1995-06-03
Last update: Rainer Staudte, 2019-08-11 more...
2 - P0000545
Andrej N. Kornilow
Andrey Frolkin

3460 Die Schwalbe 68 04/1981
P0000545
(9+12)
Welches waren die letzten 8 Einzelzüge?
R: 1. f7-f8=D# Kd7-e7 2. e7-e8=L+ Kc6-d7 3. d7-d8=S+ Ld8-c7 4. c7-c8=T+ Tc8-b8
play all play one stop play next play all
James Malcom: (Shortest) proof of legality: 1. d4 Nh6 2. Bxh6 gxh6 3. g4 Rg8 4. g5 Rg6 5. Nh3 Rf6 6. Nf4 Nc6 7. g6 Nb4 8. g7 Rg6 9. Nxg6 fxg6 10. Bh3 Nd5 11. Be6 dxe6 12. f4 Kd7 13. f5 Kc6 14. f6 Bd7 15. Rf1 Be8 16. a4 Bf7 17. a5 Bg8 18. f7 Qd6 19. Rf6 exf6 20. e4 Be7 21. e5 Bd8 22. exd6 Ne7 23. dxe7 Rc8 24. d5+ Kb5 25. d6 Kc6 26. d7 Kb5 27. Qd6 cxd6 28. a6 Kc6 29. c4 Kb6 30. c5+ Kb5 31. c6 Kc5 32. c7 Kb5 33. Na3+ Kc6 34. Nc4 Kb5 35. Nb6
axb6 36. Ra5+ Kb4 37. Rc5 bxc5 38. a7 Kb5 39. b4 Kc4 40. b5 Kd4 41. b6 Ke4 42. Kd2 Ke5 43. Kc3 Kd5 44. a8=B Kc6 45. Kc4 Rb8 46. c8=R+ Bc7 47. d8=N+ Kd7 48. e8=B+ Ke7 49. f8=Q#

Took me a bit to figure out the trick for maneuvering the Black bishops. (2022-08-28)
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Keywords: Last Moves? (8), Allumwandlung
Genre: Retro
FEN: BrRNBQb1/1pb1k1Pp/1P1ppppp/2p5/2K5/8/7P/8
Input: Gerd Wilts, 1995-06-03
3 - P0001970
Thomas R. Dawson
26 Schachkongress Teplitz-Schönau im Oktober 1922 1923
P0001970
(13+13)
h#1
1. exf3ep Lc2#
R: 1. f2-f4 f5xTe4 2. Tg4-e4 & e.g. f6-f5 3. Tg1-g4 f7-f6 4. Le4-h7 h5-h4 5. Lg2-e4 h6-h5 6. Lf1-g2 h7-h6 7. g2xh3
play all play one stop play next play all
1.exf3e.p. Bc2# is the only possible solution, but this necessitates R: 1.f2-f4. Can we prove this?

(13+13) with 1+2 pawn captures. Bf8 captured at home, so to satisfy White appetite, the missing Black pawn (a or b) must have promoted via c2 on c1. Two more White units must be captured to allow this.

The kings cage can only be unlocked by retracting WPc2. But the clock is ticking as there are only 6 black moves which can be retracted.

The promoted piece was captured on e3 or h3. If either capture is undone, then a White bishop square is cut off, so WB must be replaced prior to this.

Now the order of the early moves is: WdP moves, WQB & WQR escape, BP promotes on c1 to X (capturing WR at some point), X captured by WP.

So the first White capture must be dxNe3 and the second White capture releases gxXh3. The second White capture releases WKB & WKR. WKR captured by original BfP.

The clock starts ticking with gxh3. Black has 6 pawn moves. WKB has 3 moves to reach h7. WR has 3 if it goes via d file, or 2 if it starts on g1 (in which case WfP or WQB must also move once). So certainly at least 6 White moves. Last move was therefore White (even if the stipulation didn't tell us), and it can only have been WfP coming from f3 or f4. If it had been coming from f3 it would have blocked WKB in its progress, so the last White move was indeed R: 1.f2-f4.

WKR did therefore move from g1-g4-e4, and R: 1. ... fxRe5 2. Rg4-e4. Prior to that, move order not unique, but counting still exact.

Note that WN loitering on b4, pretending to be part of the cage, is present on the board just to make up the numbers.
Jeliss: "Obstruction of passage square f3 to Bishop of same colour."

"Version 'Pittsburgh Leader' 08.06.1913"
Yoav Ben-Zvi: Appears as the first problem (D445) in the booklet on Dawson's RA problems by G.P. Jellis. The obstruction that occurs in the Try -1.Pf3-f4?, by WP of WB, is described as "obstruction of passage square". It is not considered by Dawson and his disciples to be a Retro opposition. Dawson's conception of RO was quite broad, it included cases where the interference was not by occupation of the target square, so the only valid reason that I can see to exclude this case is that the 2 pieces involved are both of the same color. Fabel's definition explicitly excludes "Monochrome RO". I conclude that it would be preferrable to interpret RO as a bi-chromatic interference. The keyword Retro opposition should be removed. (2018-04-07)
A.Buchanan: To my mind, RO involves some kind of parity-tempo issue between the sides, not just some kind of race-tempo. If it was just about "bi-chromatic interference", one might say that bPe4 blocks wBh7 from an immediate retreat, so it has to be wPf4 that retreats first, legitimizing the ep key. So I agree this is not RO. (2024-01-06)
more ...
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Keywords: Last Moves?, En passant as key
Genre: h#, Retro
FEN: nqb5/1rrpp1pB/KRp5/1p4B1/kN2pP1p/2P1P2P/PP2P2P/8
Reprints: D445 Retro-Opposition & Other Retro-Analytical Chess Problems 1989
Input: Gerd Wilts, 1995-06-03
Last update: A.Buchanan, 2024-01-06 more...
4 - P0008219
Jozsef Korponai
6690 Probleemblad 09-10/1969
1. ehrende Erwähnung
P0008219
(12+7)
a) h#2
b) Last two single moves?
a) 1. Kxc5 h8=D 2. a1=T De5#
b) R: 1. a7-a8=S+ h2-h1=L
play all play one stop play next play all
Erich Bartel: Auszeichnung: 1.ehrende Erwähnung.--
Nachdruck: 1) Jaarboek 1970.-- (2006-11-26)
Henrik Juel: Something is wrong: De5 does not mate. And the intention certainly was not -1.S=a7 L=h2, 0... Kxc5 1.h8DL Kb6 2.DLd4#. (2006-11-27)
Erich Bartel: Ich habe die Aufgabe aus dem Jaarboek 1970 übernommen, wo
sie wie angegeben im Diagramm und Lösung so steht. Es
scheint also bereits hier ein Fehler vorzuliegen. Zur Klärung
ist es wohl notwendig in der Ur-Quelle Probleemblad -die ich
nicht besitze- nachzusehen. (2006-11-27)
Siegfried Hornecker: No matter how the position is changed, there can be no line where the king, coming from b6, is not allowed to return to b6 when the queen checks on e5. Also, there would be no reason to not play again 2.h2-h1~ as a waiting move.

The retroanalytics say that the last move must(!) have been 1.a7-a8S+ h2-h1L so I think the correct stipulation is:
a) Last move (w+s)
b) h#2

I have no source for this but if you think about it, the whole thing makes sense! The last move was 1.a8=S+ after 1.h1=L and from the diagram position the h#2 runs 2. Kxc5 h8=D 3. a1=T De5#. That's what I think. (2006-12-12)
Jan Hein Verduin: I got the Jaarboek too, and mr. Hornecker is right. The stipulation there is "h#2; what where the last w+b moves?" The way the solution then is given (the retro moves are given first) probably caused the confusion. (2007-01-26)
Adrian Storisteanu: Then, ceci n'est pas un ... retractor!? (2024-03-17)
Henrik Juel: Right, Adrian
The Help retractor keyword should be deleted (2024-03-17)
comment
Keywords: Allumwandlung, Last Moves? (2), Type C
Genre: Retro, h#
FEN: N7/1Bp4P/pkP5/p1R5/P7/P5P1/p1KNPPp1/7b
Input: Gerd Wilts, 1996-09-14
Last update: A.Buchanan, 2024-03-18 more...
5 - P0008275
Wladimir Lewschinski
Shakhmaty v SSSR 1980
3. Preis
P0008275
(12+9)
#1
1. Sxb2#
R: 1. ... a3xDb2 2. Sa2-b4 b4xLa3 3. c4-c5 c5xSb4 4. Da1-b2 d6xTc5 5. Lc1-a3 Ka3-a4 6. Tb2-b3++! Ka4-a3 7. Lb1-c2 Ka3-a4
play all play one stop play next play all
1. N:b2# Black's last move was a3:b2. White's balance equals 12 in the diagram) + 4 (captures d:c:b4:a3:52) = 16 - including the pawns e2, 12, g2 and h2, which were promoted. Black's balance: 9 (in the diagram) + 7 (captures e:d7-d8, f:e7-e8, g:f:e7-e8, h:g:f:e7-e8) = 16. Retroplay: 1. ... a3:Qb2 (necessarily a Queen!) 2. Na2-b4! b4:Ba3 (necessarily a Bishop) 3. c4-c5 c5:Nb4 (necessarily a Knight) 4. Qal-b2 d6:Rc5 (necessarily a Rook) 5. Bcl-a3 Ka36. Rb2-b3++! Ka4-a3 7. Bb1-c2+, etc. Had Black uncaptured a Rook on b2, then the retromove 4. Rb1-b2 instead of Qal-b2) would have oscillations of the black King on the squares a3-a4 and the white Rook on b2-b3 would have gone on forever... This is the first-ever rendition of uncapture differentiation under the pressure of perpetual retro motion!

Sourced from a comment by Shoopi: https://www.chess.com/blog/Rocky64/the-allumwandlung-theme-in-endgame-studies#comment-71850163
Henrik Juel: 1.Sxb2#. -1... a3xDb2 -2.Sa2 b4xLa3 -3.c4 c5xSb4 -4.Da1 d6xTc5 -5.Lc1 Ka3 -6.Tb2 Ka4 -7.Lb1 Ka3 etc. All-uncapture. (2004-01-02)
James Malcom: Shortest possible proof game: 1. c4 c6 2. a4 Qc7 3. h4 Qh2 4. Nh3 Kd8 5. Ra2 Kc7 6. e4 Kb6 7. Nc3 Kc5 8. a5 Qg3 9. b4+ Kd4 10. b5 Kc5 11. Qa4 Qd3 12. g4 Qc2 13. Rb2 Qb3 14. Qa1 Kb4 15. Na2+ Ka3 16. Ke2 Qd1+ 17. Ke3 Qf3+ 18. Kd4 Na6 19. Bd3 Nc5 20. Bb1 Nd3 21. Nf4 Ne5 22. Kc5 Qh3 23. Nd3 a6 24. f4 Nf3 25. Kb6 Ng5 26. hxg5 d6 27. e5 Bd7 28. e6 Re8 29. exd7 e6 30. f5 Be7 31. f6 Rc8 32. fxe7 Nf6 33. e8=N Ng8 34. d8=B Qh4 35. Bf6 Qh5 36. Bc3 Qh6 37. Nf6 Qg6 38. Nd5 Nf6 39. gxf6 Rce8 40. N5b4 Re7 41. fxe7 Rf8 42. e8=R Rg8 43. Rd8 Rf8 44. Rh5 Re8 45. Rc5 Re7 46. g5 Qf6 47. gxf6 Ka4 48. fxe7 Ka3 49. e8=Q Ka4 50. Rd7 Ka3 51. Qe7 Ka4 52. Bc2+ Ka3 53. Rb3+ Ka4 54. Ba3 dxc5 55. Qb2 cxb4 56. c5 bxa3 57. Nab4 axb2 (2023-02-05)
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Keywords: Last Moves?
Genre: Retro
FEN: 8/1p1RQppp/pKp1p3/PPP5/kN6/1RBN4/1pBP4/8
Input: Gerd Wilts, 1996-09-16
Last update: James Malcom, 2022-08-29 more...
6 - P0008879
Arpad Molnar
R259 The Problemist 01/1997
P0008879
(10+9) cooked
Welches waren die letzten 16 Einzelzüge?

play all play one stop play next play all
Cook: R: 1. a4xSb3+ Lb8-c7 2. d6xSc5 Ld8-b6 3. b6xSa5 e7xTd8=L
Gerald Ettl: Weiss jemand wie die Autorloesung geplant war? (2023-09-28)
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Keywords: Last Moves? (16), Non-standard material
Genre: Retro
FEN: 8/p1Bp1ppp/RBR5/pBpP4/1kP5/Rp6/1PK5/8
Input: Gerd Wilts, 1998-06-26
Last update: Gerd Wilts, 2006-10-08 more...
7 - P1004179
Arpad Molnar
R275 The Problemist 05/1998
4. ehrende Erwähnung
P1004179
(11+10) cooked
Letzte 12 Einzelzüge?
R: 1. a4xSb3+ Dd8-b6 2. b6xSa5 Tc8-c6 3. c7xSb6 Lc6-b5 4. b5xSa4 Sa8-b6 5. b6-b5 Lb7-c6 6. Kb5-b4 c3-c4+
play all play one stop play next play all
Gerald Ettl: Wie lautet der Cook? (2023-09-28)
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Keywords: Ceriani-Frolkin Theme (SSSS), Last Moves? (12)
Genre: Retro
FEN: 1N6/p2p1ppp/RQRp4/pBNP4/1kP5/bp6/PPK5/8
Reprints: (1) Quartz 18 10-12/2001
Input: Gerd Wilts, 2002-09-05
Last update: Gerd Wilts, 2004-08-28 more...
8 - P1011798
Thierry Le Gleuher
R210 Probleemblad 09-10/2003
Lob
PR Hans Gruber
P1011798
(14+13)
Letzte 42 Einzelzüge?
R: 1. ... 0-0-0+ 2. Kg7-h8 f7-f6 3. Kf6-g7 e4-e3 4. Kf5-f6 e5-e4 5. Ke4-f5 e6-e5 6. Kd3-e4 e7-e6 7. Te6-e2 e2-e1=L 8. Db2-a1 e3-e2 9. Ke2-d3 e4-e3 10. Dc1-b2 e5-e4 11. Dd1-c1 d6xLe5 12. Lb2-e5 c6-c5 13. Lc1-b2 c7-c6 14. b2-b4 b3xTa2 15. Ta1-a2 b4-b3 16. La2-b1 b5-b4 17. Lb3-a2 b6-b5 18. La4-b3 b7-b6 19. Lb5xBa4 a5-a4 20. Ke1-e2 a6-a5 21. Lf1-b5 a7-a6 22. e2xSf3 ...
play all play one stop play next play all
hans: all black pawn-moves
Henrik Juel: Commendation
(awarded by Hans Gruber, PB no.1 2005 p.4) (2019-03-07)
Joost de Heer: @Hans: First retraction move isn't a pawn move. (2024-02-01)
more ...
comment
Keywords: Last Moves?, Castling in the retro play
Genre: Retro
FEN: 2kr3K/3N3p/5p2/2p3p1/1P4P1/P3pPrb/p1PPRPPq/QB2b1bN
Reprints: H11-5 WCCI 2001-2004
Input: Gerd Wilts, 2003-10-20
Last update: Alfred Pfeiffer, 2019-03-08 more...
9 - P1017610
Michel Caillaud
Kevin James Begley

R0083 StrateGems 15 07-09/2001
2. ehrende Erwähnung
P1017610
(15+5)
Welches waren die letzten 7 Einzelzüge?
Circe Parrain
R: 1. 0-0[+wBc4]+ sBd4x[Dc3,Bc4]c3ep 2. c2-c4[+wDc3]+ b2xDc1=S[+sLb4] 3. Sb7xLa5[+wBc2] e5xBd4[+sLa5]+ 4. a5xLb6
play all play one stop play next play all
Michel Caillaud: cooked by Dmitry Baibikov :
3.Sb7xLa5(+wBa3) Kb4xPb5(+sLa5)+ -4.Ta5xLa4(+wSd3)+ e5xSd4 (2022-07-19)
Kevin Begley: correction: P1404688 (2022-09-27)
more ...
comment
Keywords: Circe (Parrain), Last Moves? (7), Valladao Task
Genre: Retro, Fairies
FEN: 8/8/PPp5/NkP5/RbP5/PBpN4/P4PP1/B1n2RK1
Input: Gerd Wilts, 2004-07-03
Last update: Kevin Begley, 2022-09-27 more...
10 - P1084663
Andrey Frolkin
1027 Mat Plus 30 04-06/2008
Lob
P1084663
(13+14)
Letzte 7 Einzelzüge?
Herkunft der sTb8 und des sTd1?
R: 1. Sf8-h7+ f4-f5 2. Th1-d1 f3-f4 3. Kg1-h2 f2-f3 4. Th7-h1 Sh5-g7 5. Tg7-h7+ Sf4-h5 6. Ta8-b8 ... 7. Ta3-a8 ... 8. Th3-a3 ... 9. Th1-h3 ... 10. h2-h1=T ... 11. h3-h2 ... 12. h4-h3 ... 13. h5-h4 ... 14. h6-h5 h5xSg6, dann a7-a8=D, Ba7-a4, Tg7-a8, a7xBb6, BcxTb6 (dieser entschlagene Turm kommt von h8).
Der Tb8 kommt von h1 (Pronkin), der Td1 kommt von a8 (Antipronkin, da er über h1 zieht.).
play all play one stop play next play all
Hans-Jürgen Manthey: Umwandlung h1T-b8 (h2-h1T-h3-a3-a8-b8)
Td1 kommt von a8 (Ta8-b8-a8-a3-f3-f7-g7-h7-h1-d1)
Th8 wird geopfert (Th8-e8-e6-b6/c5xb6)
7 Einzelzüge: R.: 1. Sf8-h7+ f4-f5 2. Th1-d1 f3-f4 3. Kg1-h2 f2-f3 4. Th7-h1 ... weiter: 4... Sh5-g7 5. Tg7-h7+ Sf4-h5 6. Ta8-b8 Sd5-f4 7. Ta3-a8 Sb4-d5 8. Th3-a3 Sc2-b4 9. Th1-h3 Sa3-c2 10. h2-h1T Sb1-a3 11. h3-h2 Sc3-b1 12. h4-h3 Sd5-c3 13. h5-h4 Sf4-d5 14. h6-h5 h5xSg6 15. Sh4-g6 Sd3-f4 16. g6-g5 Sb4-d3 17. h7-h6 Kg5-f6 18. Kf1-g1 Tf3-f7 19. Tf7-g7 Ta3-f3 20. Tf3-f7 Ta1-a3 21. Ta3-f3 Tg7-g8 22. Ta8-a3 Tf7-g7 23. Ke1-f1 Kg4-g5 24. Sf5-h4 Kh3-g4 25. Kd1-e1 Kh3-h2 26. Lf6-h8 Sd5-e7 27. Le7-f6 Sa2-b4 28. Kc2-d1 Kg1-h2 29. Kb3-c2 Kf1-g1 30. Kc4-b3 Ke1-f1 31. Sg3-f5 Tf3-f7 32. Sf1-g3 Th3-f3 33. Sg3xLf1 Th1-h3 34. f7xDe6 h4-h5 35. Kd4-c4 h2-h4 36. Ke4-d4 Dc6-e6 37. Kf5-e4 Da4-c6 38. Tb8-a8 Da8-a4 39. Lf6-e7 a7-a8D 40. Lg7-f6 a6-a7 41. Se6-f8 Df8-e8 42. a7xb6 c5xTb6 43. Sd4-e6 Sb4-d5 44. Te6-b6 c4-c5 45. Te8-e6 Sd3-b4 46. Kf6-f5 Da3-f8 47. Th8-e8 Db3-a3 48. Sc6-d4 Dd1-b3 49. Ta8-b8 Sc3-a2 50. Sb8-c6 Sf4-d3 51. Ke7-f6 Sh3-f4 52. Ke8-e7 Sg1-h3 53. Sh5-g3 Sb1-c3 54. e7-e5 a5-a6 55. Lf8-g7 a4-a5 56. Sf6-h5 a2-a4 57. Sg8-f6 c3-c4 58. g7-g6 c2-c3 (2023-03-12)
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Keywords: Last Moves?, Pronkin Theme (t), Anti-Pronkin (t)
Genre: Retro
FEN: 1rbqQ1Rb/1pppNRNn/1p2pKP1/4pPp1/8/8/1P1PP1Pk/2Br4
Input: Gerd Wilts, 2009-05-24
Last update: Gerd Wilts, 2010-08-16 more...
11 - P1240697
Dmitri Baibikow
C22 Length Records in Last Single Moves? 11/2009
P1240697
(12+10) cooked
Last 46 single moves?
R: 1. Tc3xDc2 h5xSg4 2. Se5-g4 h6-h5 3. Sf3-e5 h7-h6 4. Se1-f3 Dd1-c2 5. Sc2-e1 Df1-d1 6. g5-g6 f2-f1=D 7. g4-g5 f3-f2 8. g3-g4 g4xSf3 9. Se5-f3 g5-g4 10. Sd7-e5 g6-g5 11. Sc5-d7 g7-g6 12. Sa4-c5 Sd1-b2 13. Sb2-a4 Sf2-d1 14. f5-f6 Sh3-f2 15. f4-f5 Sg1-h3 16. f3-f4 g2-g1=S 17. f2-f3 f3xDg2 18. Dh3-g2 f4-f3 19. Dc8-h3 f5-f4 20. Da8-c8 f6-f5 21. a7-a8=D f7-f6 22. a6-a7 a7xDb6 23. Kc5-b5 La5-b4
play all play one stop play next play all
Cook: alternative Auflösung (mri, PDB 03.07.2023)
R: 1. Tc3xDc2 g5-g4 2. f5-f6 f6xSg5 3. Sf3-g5 f7-f6 4. Se1-f3 Dd1-c2 5. Sc2-e1 Dg1-d1 6. g5-g6 g2-g1=D 7. g4-g5 h3xDg2 8. Dg3-g2 h4-h3 9. Db8-g3 h5-h4 10. Da8-b8 h6-h5 11. a7-a8=D h7-h6 12. a6-a7 a7xSb6 13. Kc5-b5 La5-b4 14. Kd5-c5 Da4-b3 15. Ke5-d5 Sd6-c4 16. Kf4-e5 Se8-d6 17. Kg3-f4 Lb5-d3 18. Le7-a3 Sd3-b2 19. Ta3-c3 Kb2-c1 20. Td1-d2 Sc1-d3 21. Th1-d1 Sd2-b1 22. Kg2-g3 Sf1-d2 23. Se1-c2 Sf6-e8 24. g3-g4 f2-f1=S 25. Sf3-e1 c2-c1=S 26. d2xTe3 Tc3-e3 27. Sg1-f3 Tc8-c3 28. Kf1-g2 Ld7-b5 29. Le6-a2 Th8-c8 30. Ta1-a3 Sg8-f6 31. f4-f5 f3-f2 32. c3xBd4 Kb3-b2 33. Lh3-e6 g4xDf3 34. La3-e7 g5-g4 35. Lc1-a3 g7-g5 36. b2xTc3 Tc8-c3 37. Df2-f3 Ta8-c8 38. De1-f2 Lc8-d7 39. d3xBe4 c3-c2 40. f3-f4 Kb4-b3 41. c2xSd3 Dd7-a4 42. Dd1-e1 Kc5-b4 43. Sc4-b6 Kd6-c5 44. Sa3-c4 Ke7-d6 45. Sb1-a3 Ke8-e7 46. Ke1-f1 Sc5-d3 47. Lf1-h3 Lb4-a5 48. a5-a6 Sa6-c5 49. a4-a5 Sb8-a6 50. g2-g3 Dd8-d7 51. f2-f3 c4-c3 52. Sf3-g1 Lf8-b4 53. Sg1-f3 e5-e4 54. Sf3-g1 d5-d4 55. Sg1-f3 c5-c4 56. Sf3-g1 e7-e5 57. Sg1-f3 d7-d5 58. a3-a4 c7-c5 59. a2-a3
Gerald Ettl: Die Stellung ist falsch. wTc2 auf c3 und +sDc2 (2023-07-02)
Gerald Ettl: Bzw. vielleicht ist die Stellung richtig, aber dann stimmt die Lösungsangabe und Forderung nicht. (2023-07-02)
Mario Richter: Hallo Gerald, Type C heißt: ein K muß im Schach stehen, also ist das Diagramm wohl richtig. Die Originalforderung war "Last 46 single moves?" (nicht ... 45 ...) - da hat wohl jemand den einleitenden schachbietenden Zug vergessen. (2023-07-03)
more ...
comment
Keywords: Last Moves? (45), Non-standard material (s), Type C, Superseded by (P1353149)
Genre: Retro
FEN: 8/1p6/1p3PP1/1K6/1bnPP1p1/Bq1bP3/BnRRP2P/1nk5
Input: Gerd Wilts, 2012-06-04
Last update: A.Buchanan, 2023-07-05 more...
12 - P1371439
Thierry Le Gleuher
R546 The Problemist 27-6, p. 229, 11/2019
P1371439
(13+12)
Last 102 single moves?
Duplex
BTM: R: 1. Lc2-b1 Kg1-f1 2. Lb1-c2 Tf1-f2 3. Lc2-b1 Tf2-f3 4. Lb1-c2 Tf3-g3 5. Lc2-b1 Tg3-h3 6. Th3-h2 Th2-h1 7. Lb1-c2 Kh1-g1 8. Lc2-b1 Tg1-f1 9. Lb1-c2 Tf1-f2 10. Lc2-b1 Tf2-f3 11. Lb1-c2 Tf3-g3 12. Tg3-h3 Th3-h2 13. Lc2-b1 Kh2-h1 14. Lb1-c2 Th1-g1 15. Lc2-b1 Kg1-h2 16. Lb1-c2 Th2-h1 17. Lc2-b1 Kh1-g1 18. Lb1-c2 Tg1-f1 19. Lc2-b1 Tf1-f2 20. Lb1-c2 Tf2-f3 21. Tf3-g3 Tg3-h3 22. Lc2-b1 Th3-h2 23. Lb1-c2 Kh2-h1 24. Lc2-b1 Th1-g1 25. Lb1-c2 Kg1-h2 26. Lc2-b1 Th2-h1 27. Lb1-c2 Kh1-g1 28. Lc2-b1 Tg1-f1 29. Lb1-c2 Tf1-f2 30. Tf2-f3 Tf3-g3 31. Lc2-b1 Tg3-h3 32. Lb1-c2 Th3-h2 33. Lc2-b1 Kh2-h1 34. Lb1-c2 Th1-g1 35. Lc2-b1 Tg1-f1 36. Tf1-f2 Lf2-e1 37. Te1-f1 Tf1-g1 38. Lb1-c2 Tg1-h1 39. Lc2-b1 Kh1-h2 40. Lb1-c2 Th2-h3 41. Lc2-b1 Th3-g3 42. Lb1-c2 Lg3-f2 43. Lc2-b1 Tf2-f1 44. Lb1-c2 Tf1-g1 45. Lc2-b1 Kg1-h1 46. Lb1-c2 Th1-h2 47. Lc2-b1 Kh2-g1 48. Lb1-c2 Tg1-h1 49. Lc2-b1 Kh1-h2 50. Lb1-c2 Th2-h3 51. h3-h4 Lh4-g3 52. Lc2-b1
52. ... Tg3-f3 53. Lb1-c2 Tf3-f2 54. Lc2-b1 Tf2-f1 55. Lb1-c2 Tf1-g1 56. Lc2-b1 Kg1-h1 57. Lb1-c2 Th1-h2 58. h2-h3 Th3-g3 59. Lc2-b1 Lg3-h4 60. Lb1-c2 Th8-h3
play all play one stop play next play all
Editor's comment: Do not be put off by the length of R546: there is a repeated sequence of moves.
James Malcom: Solution? Also, is this an Othoreconstrution? (2023-05-30)
Henrik Juel: Here is the solution from the May 2020 issue (from www.theproblemist.org , which is a treasure of info, althoug I find it hard to navigate)
R546 (Le Gleuher): Retroanalysis: The wPs captured the 4 missing black units.
Thus, wPb4 comes from b2, and (Pa2) promoted to the extra wR on a8 with (Pa7)
letting it pass by switching to the b file (first capture of the 3 missing white units).
(Pb7) must have promoted to a rook on a1 or c1 (second capture). (Ph7) must
have moved onto the g file (third and final capture) in order to be captured. Thus
(Pc7) and (Pe7) promoted to rooks on the c and e files, respectively. It is not
possible to immediately take back a4xb3 or c2xd3. The retro-move e4xf5 is
forbidden since then the bP which promoted on e1 cannot retract to e5. Black can
only move in the southeast cage, while White’s bishop is free to oscillate between
c2 and b1.
Black to move: back 1.Bc2-b1 Kg1-f1 2.Bb1-c2 Rf1-f2 3.Bc2-b1 Rf2-f3
4.Bb1-c2 Rf3-g3 5.Bc2-b1 Rg3-h3 6.Rh3-h2 Rh2-h1 7.Bb1-c2 Kh1-g1 8.Bc2-b1
Rg1-f1 9.Bb1-c2 Rf1-f2 10.Bc2-b1 Rf2-f3 11.Bb1-c2 Rf3-g3 12.Rg3-h3 Rh3-h2
13.Bc2-b1 Kh2-h1 14.Bb1-c2 Rh1-g1 15.Bc2-b1 Kg1-h2 16.Bb1-c2 Rh2-h1
17.Bc2-b1 Kh1-g1 18.Bb1-c2 Rg1-f1 19.Bc2-b1 Rf1-f2 20.Bb1-c2 Rf2-f3
21.Rf3-g3 Rg3-h3 22.Bc2-b1 Rh3-h2 23.Bb1-c2 Kh2-h1 24.Bc2-b1 Rh1-g1
25.Bb1-c2 Kg1-h2 26.Bc2-b1 Rh2-h1 27.Bb1-c2 Kh1-g1 28.Bc2-b1 Rg1-f1
29.Bb1-c2 Rf1-f2 30.Rf2-f3 Rf3-g3 31.Bc2-b1 Rg3-h3 32.Bb1-c2 Rh3-h2
33.Bc2-b1 Kh2-h1 34.Bb1-c2 Rh1-g1 35.Bc2-b1 Rg1-f1 36.Rf1-f2 Bf2-e1
37.Re1-f1 Rf1-g1 38.Bb1-c2 Rg1-h1 39.Bc2-b1 Kh1-h2 40.Bb1-c2 Rh2-h3
41.Bc2-b1 Rh3-g3 42.Bb1-c2 Bg3-f2 43.Bc2-b1 Rf2-f1 44.Bb1-c2 Rf1-g1
45.Bc2-b1 Kg1-h1 46.Bb1-c2 Rh1-h2 47.Bc2-b1 Kh2-g1 48.Bb1-c2 Rg1-h1
49.Bc2-b1 Kh1-h2 50.Bb1-c2 Rh2-h3 51.h3-h4 Bh4-g3 52.Bc2-b1
then 52…Rg3-f3 (or 52...Bg3-h4 53.Bb1-c2 Bh4-g3…) 53.Bb1-c2 Rf3-f2 54.Bc2-b1 Rf2-f1 55.Bb1-c2
Rf1-g1 56.Bc2-b1 Kg1-h1 57.Bb1-c2 Rh1-h2 58.h2-h3 Rh3-g3 59.Bc2-b1 Bg3-h4 60.Bb1-c2 Rh8-h3 etc…
The diagram position is a draw and the last 103 single moves are determined.
White to move: back 1…Kg1-f1 …
51.h3-h4 Bh4-g3 52.Bc2-b1 then the same… Here, there are 99 single moves between the diagram position and the retro-move h3-h4. Of course, trying to insert another manoeuvre in the solution would lead to an overshoot of the 101 single moves, which would be incompatible with the 50 moves rule. Here only 102 last single moves are determined.
So, we have a D25/102, a new record for last single moves for ‘D’ type (Duplex) with 25 pieces (It is also
the overall record for Duplex). With black to move, the same diagram is also a record with 25 pieces (B25/103) (2023-05-30)
comment
Keywords: Last Moves?, Non-standard material, 50 move rule
Genre: Retro
FEN: 8/6p1/8/5PP1/1P3pRP/1p1PPrrr/n2pRrPR/1BNKbk1r
Input: A.Buchanan, 2020-01-05
Last update: Mario Richter, 2023-05-30 more...
13 - P1410903
Mu-Tsun Tsai
Dream Yeh

MatPlus.net Forum 14/07/2023
P1410903
(16+2)
What is curious about this position?
R: 1. d5xe6ep# e7-e5 2. d4-d5+
play all play one stop play next play all
Mu-Tsun Tsai: Previous record is P1410861 (2023-07-14)
Mu-Tsun Tsai: Original design was 8/2N5/3PPkPR/rP6/B5PP/8/3PPN2/B2RqQK1, but that leads to a surprising cook: remove both d2 and f2, and retract -1. fxe6ep# e7 -2. Rd4+! (2023-07-14)
comment
Keywords: Economy record, En passant, En passant in the retro play, Last Moves? (3), Minimal
Genre: Retro, Fairies
FEN: 3Q1R2/2N1PP2/5k2/7P/2P4P/6N1/3PPP2/B2BqRK1
Input: James Malcom, 2023-07-14
Last update: James Malcom, 2023-09-09 more...
14 - P1411240
Min Hang Kyaw
SS105 The Hopper Magazine I04 13/07/2023
P1411240
(12+10)
Last 7 single moves?
R: 1. h2xLg3 Lh4-g3 2. h5-h6 Le7-h4 3. h4-h5 Lf8-e7 4. h3-h4 (e7xDTSd6)
play all play one stop play next play all
more ...
comment
Keywords: Last Moves? (7)
Genre: Retro
FEN: Rb6/rp1p1pp1/pK1p3P/p7/1k6/1P1PP1P1/1P1PP3/N1B5
Input: Miguel Ambrona, 2023-07-26
Last update: A.Buchanan, 2023-07-28 more...
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