Compare P0000490 with equivalent material but 30 years later.
A.Buchanan: Solved in YouTube: https://www.youtube.com/watch?v=Do_rkLQnrpk (2022-02-17)
A.Buchanan: Solved in YouTube video: https://www.youtube.com/watch?v=Do_rkLQnrpk&list=PLYeOP7z8XTGTAF6LYk15wZgqD6-ZXgbM2&index=2 (2022-02-17, hidden)
A.Buchanan: Compare P0000490 with equivalent material but 30 years later. (2023-05-31, hidden) more ...
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Henrik Juel: This problem demonstrates an advantage of type Høeg over type Proca:
another way of generating variations
2.0-0 cannot be an uncapture, of course
2.Te7-f7 and 2.Dc5-c8 etc. could be uncaptures, but no matter what Black supplements, he is mated (2023-04-08)
A.Buchanan: Thanks Henrik: is an alternative for White R: 1. Kg1-h1 Lb8xDa7+ 2. Dc5-a7/Da3-a7, dann 1. Df8# (2023-04-08)
Henrik Juel: No Andrew, when White moves his uncaptured queen back to c5 or a3, Black supplements a queen or bishop on a7, preventing the mate on f8 (2023-04-08)
A.Buchanan: Thanks! (2023-04-08)
Henrik Juel: -1.Kg1:S Sf2:0 -2.0-0, 1.Rh8#; -1.. Bb8:S -2.Re7, 1.Sc6#; -1.. cSb6,dSb6,Se3:Q -2.Qc5, 1.Qf8#. Duplicated by P0006277 (2003-10-09, hidden) more ...
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Adrian Storisteanu: See twin P1216951. Another possible twin (see Thomas Brand's Retroblog 11/2019):
wKc7->.h5
- 1.Kg4xRh5 Re3xQb3 & 1.Re5 Qc4# (2024-03-19)
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A.Buchanan: Setplay doesn't care whether the position is legal. (2023-12-06)
A.Buchanan: So is this a retro problem? I think not. (2023-12-06)
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Bernd Schwarzkopf: zurück: 1.Kg4xBg3 Kd3-c2 2.Kg5-g4 Ke4-d3 3.Kh5xBg5 Kf5-e4; vor: 1.g3-g4# (2024-03-29)
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siehe 9200
mri: Mehrere NL, z.B. R: Kc6xLd6 Lc5xDd6 V: 1.Ka5-a6 Dd6xc5 oder R: Kc5xTd6 Tb6xDd6 V: 1.Tb6-c6 Dd6xc6 (2007-10-25)
Mario Richter: s. P0005054 (2009-12-31)
A.Buchanan: Reasonable to suppose that P0005054 is the correction (2024-01-15)
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{ NL}
klären AL
SCHRECKE: Geplant war wohl:
1. Kd6 Lh2+ 2. e5 dxe6 e.p. 3. Ke7 Sd5#
Nebenlösungen, z.B.:
1. Df6 Kb4 2. De6 fxe6 3. Kd6 Lh2#
1. Kd7 Lh2 2. Sc7 Sc4 3. De8 Sb6# (2023-09-20)
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{ NL}
klären AL
SCHRECKE: Satz:
1. ... c8=T+ 2. Kd7 Le6#
Es lösen:
1) 1. Ld8 cxd8=T+ 2. Ke7 Lh4#
2) 1. Kd7 cxb8=D 2. Kc6 Dc7#
3) 1. Ld6 c8=D+ 2. Ke7 Lh4#
4) 1. Kf8 Lf4 2. De8 Lh6# (2023-09-20)
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Yuri Bilokin: correction wKa7-b1, +bNd1 7k/5p1b/3p4/8/8/8/1Pn5/1K1n4 (2+6) h#7

1.f5 b4 2.f4 b5 3.f3 b6 4.f2 b7 5.f1=B b8=B 6.Bc4 Bxd6 7.Bcg8 Be5# (MM)

Excelsior (black)
Excelsior (white)
Promotion (Bb, 1, 1)
Model mate × 1 (2023-05-10)
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Yuri Bilokin: you can see 1...e4 2.Kd1 e5 3.Ke1 e6 4.Kd1 e7 5.Ke1 e8=Q+ 6.Kd1 Qe2# (2023-01-14)
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klären Zwilling
Ladislav Packa: Lösung b) 1.kBa3-a2 kBc2-c4 2.kBa2-a1=kS! Le1-c3# (2023-02-25)
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Yuri Bilokin: correction wKg4-f4, -bBa6, +bRe7, then a1=c1 6N1/5Pr1/4k3/8/2P4K/8/8/8 (4+2) h#2*

1...f8=Q 2.Rd7 Qf6#
1.Rg5 f8=Q 2.Rf5 Qe7#

Echo mates (mirrored diagonally, 0, 0)
Promotion (QQ, 2)
Echo (2023-06-04)
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Yuri Bilokin: possibly wKg8-h8 7K/4p3/7k/6p1/8/5p2/6P1/8 (2+4) (2023-02-01)
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Erich Bartel: Nachdruck:
Die Schwalbe (2) XII 1969 (2013-02-22)
Yuri Bilokin: possibly wKb3-a2 7k/1p4pn/8/8/8/8/K4P2/8 (2+4) h#7
1.b5 f4 2.b4 f5 3.b3+ Ka3 4.b2 f6 5.b1=B f7 6.Ba2 f8=S 7.Bg8 Sg6# (MM) (2023-02-01)
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0218
SCHRECKE: C+, popeye 4.87 (2022-09-12)
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0505 und 0862
SCHRECKE: C+, popeye 4.87 (2022-09-12)
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0457
SCHRECKE: C+, popeye 4.87 (2023-09-30)
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T12T IM
vf: sBh4->h5, Sergej Radtschenko, 08.1990, Ceskoslovensky Sach, #7793
SCHRECKE: C+, popeye 4.87 (2023-03-16)
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SCHRECKE: Unlösbar (2023-07-14)
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Anton Baumann: C+ Alybadix (2023-03-29)
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Steen Christensen: Anticipated by / identical to Nixon (P0575588):
Turn the board 90 degrees anticlockwise. {wKb3,sKb5} becomes {wKf2,sKd2}. (2023-10-01)
Henrik Juel: 1... Kf3 2. Ke1 Ke2=
1. Ke1 Ke3 2. Kd1 Kd2=
C+ by Popeye 4.69 (2015-03-11, hidden) more ...
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Gunter Jordan: a) und letztlich auch c) sind vorweggenommen durch Nixon 1953 (P0575588) und auch durch Steudel 1958 (P1207519). (2015-03-09)
Steen Christensen: I do not see similarities between Nixon (P0575588) and a), except for the obvious ones: Identical material, stipulation and stale mate position. The problem is correctly not assigned the keyword “anticipated”, but “vgl. Nixon 1953” might be added as a comment. (2023-10-01)
Henrik Juel: a) and b) are C+ by Popeye 4.69
The first solution in part b) should have 2. Ka6, not Kc8
What does the stipulation in part c) mean? (2015-03-09, hidden)
Henrik Juel: Thanks for the clarification, Alfred
Part c) is also C+ by Popeye 4.69 using 'bed git hor' (2015-03-09, hidden) more ...
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prüfen?
SCHRECKE: Auf a7 muss offenbar ein wBauer stehen. (2024-03-24)
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SCHRECKE: Forderung: Grazer h=7 (2023-07-25)
Henrik Juel: C+ Popeye 4.61
(Popeye stipulation: reci-h=7) (2023-07-25)
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SCHRECKE: C+, Gustav 4.2e, Brute Force (2023-08-11)
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Anton Baumann: C+ Alybadix (2023-03-31)
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Klären ob Originalforderung h#2
Alfred Pfeiffer: Originalforderung war h#2. In der Lösungsbesprechung (fs-1, 01/1971, S.17) steht: "Korrekterweise sollte bei Aufgaben dieser Art ein Hinweis gegeben werden, daß sie Retroanalyse erfordern!".
Bei der Scheinlösung hat weiß keinen letzten Zug. (2017-11-23)
Henrik Juel: Giving a hint about retro analysis would spoil the fun (2017-11-23)
A.Buchanan: Quite right Henrik. Solvers should always be on their toes (2023-12-07)
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