1 problem(s) found in 1250 milliseconds (displaying 1 problem(s)).

1 - P1243719

**Andrew Buchanan**

Richard Stanley

8574 feenschach 144 11-12/2001

(a: 6+10)

(a: 6+9)

Weiß am Zug. A nach B in

(1) 5,5

(2) 6,0

(3) 6,5

(4) 7,0

(5) 7,5 etc...

A-nach-B-Schach

Richard Stanley

8574 feenschach 144 11-12/2001

(a: 6+10)

(a: 6+9)

Weiß am Zug. A nach B in

(1) 5,5

(2) 6,0

(3) 6,5

(4) 7,0

(5) 7,5 etc...

A-nach-B-Schach

(1,5,9...) 1. g3+ Kh5 2. g4+ Kh6 3. g5+ Kh7 4. fxg6+ Kg8! 5. f5 b1=L+ 6. Kd1!

(2,6,10...) 1. g3+ Kh5 2. g4+ Kh6 3. g5+ Kh7 4. fxg6+ Kh8! 5. f5 b1=L+ 6. Kd1! Kg8

(3,7,11...) 1. g3+ Kh5 2. g4+ Kh6 3. g5+ Kh7 4. fxg6+ Kh8! 5. f5 b1=L+ 6. Kc1! Kg8 7. Kd1

(4,8,12...) 1. g3+ Kh5 2. g4+ Kh6 3. g5+ Kh7 4. fxg6+ Kg8! 5. f5 b1=L+ 6. Kc1! Kh8 7. Kd1 Kg8 etc.

The point of the above problem is that it has infinitely many stipulations! Moreover, they are of the form A->B in k single moves, k + 1 single moves, k + 2 single moves... There was an attempt to make k as large as possible (with no solution in less than k single moves). This has the paradoxical effect that it is harder to make a problem which has a smaller set of valid stipulations!

It is much also easier to compose such a problem if the required

number of moves is always the same mod 2: k, k + 2, k + 4...

(2,6,10...) 1. g3+ Kh5 2. g4+ Kh6 3. g5+ Kh7 4. fxg6+ Kh8! 5. f5 b1=L+ 6. Kd1! Kg8

(3,7,11...) 1. g3+ Kh5 2. g4+ Kh6 3. g5+ Kh7 4. fxg6+ Kh8! 5. f5 b1=L+ 6. Kc1! Kg8 7. Kd1

(4,8,12...) 1. g3+ Kh5 2. g4+ Kh6 3. g5+ Kh7 4. fxg6+ Kg8! 5. f5 b1=L+ 6. Kc1! Kh8 7. Kd1 Kg8 etc.

The point of the above problem is that it has infinitely many stipulations! Moreover, they are of the form A->B in k single moves, k + 1 single moves, k + 2 single moves... There was an attempt to make k as large as possible (with no solution in less than k single moves). This has the paradoxical effect that it is harder to make a problem which has a smaller set of valid stipulations!

It is much also easier to compose such a problem if the required

number of moves is always the same mod 2: k, k + 2, k + 4...

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The problems of this query have been registered by the following contributors:

A.Buchanan (1)
A.Buchanan: Thanks Francois. I have no idea how to change the diagrams for these A-B problems. There isn't a little pencil to click on in edit mode... (2017-9-12)Alfred Pfeiffer: Andrew, there is a trick to do this:1) Go into the edit mode with any other problem;

2) Replace in the command line of the browser the actual probid by that of the A=B-problem

(eg "http://pdb.dieschwalbe.de/edit.jsp?id=P1224189&positions=true" becomes to

"http://pdb.dieschwalbe.de/edit.jsp?id=P1243719&positions=true"), then click ENTER;

3) Edit the position as usual. (2017-9-13)

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